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| author | Roger Frank <rfrank@pglaf.org> | 2025-10-14 20:05:59 -0700 |
|---|---|---|
| committer | Roger Frank <rfrank@pglaf.org> | 2025-10-14 20:05:59 -0700 |
| commit | 895ecb87799c91af9c80eb824e23639e999145fd (patch) | |
| tree | 49d43eb8fc13f3a9f23b05f7044a921fd9f44abf | |
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| -rw-r--r-- | LICENSE.txt | 11 | ||||
| -rw-r--r-- | README.md | 2 |
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diff --git a/.gitattributes b/.gitattributes new file mode 100644 index 0000000..6833f05 --- /dev/null +++ b/.gitattributes @@ -0,0 +1,3 @@ +* text=auto +*.txt text +*.md text diff --git a/36525-pdf.pdf b/36525-pdf.pdf Binary files differnew file mode 100644 index 0000000..1410a9c --- /dev/null +++ b/36525-pdf.pdf diff --git a/36525-pdf.zip b/36525-pdf.zip Binary files differnew file mode 100644 index 0000000..f6ef694 --- /dev/null +++ b/36525-pdf.zip diff --git a/36525-t.zip b/36525-t.zip Binary files differnew file mode 100644 index 0000000..076a5b7 --- /dev/null +++ b/36525-t.zip diff --git a/36525-t/36525-t.tex b/36525-t/36525-t.tex new file mode 100644 index 0000000..48d812c --- /dev/null +++ b/36525-t/36525-t.tex @@ -0,0 +1,31919 @@ +% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % +% % +% The Project Gutenberg EBook of Notes on Recent Researches in Electricity% +% and Magnetism, by J. J. Thomson % +% % +% This eBook is for the use of anyone anywhere at no cost and with % +% almost no restrictions whatsoever. You may copy it, give it away or % +% re-use it under the terms of the Project Gutenberg License included % +% with this eBook or online at www.gutenberg.net % +% % +% % +% Title: Notes on Recent Researches in Electricity and Magnetism % +% Intended as a Sequel to Professor Clerk-Maxwell\'s Treatise % +% on Electricity and Magnetism % +% % +% Author: J. J. Thomson % +% % +% Release Date: June 27, 2011 [EBook #36525] % +% % +% Language: English % +% % +% Character set encoding: ISO-8859-1 % +% % +% *** START OF THIS PROJECT GUTENBERG EBOOK RECENT RESEARCHES--ELECTRICITY, MAGNETISM *** +% % +% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% % + +\def\ebook{36525} +%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% +%% %% +%% Packages and substitutions: %% +%% %% +%% book: Document class. Required. %% +%% geometry: Enhanced page layout package. Required. %% +%% inputenc: Standard DP encoding. Required. %% +%% amsmath: AMS mathematics enhancements. Required. %% +%% amssymb: AMS symbols e.g. \therefore. Required. %% +%% fancyhdr: Enhanced running headers and footers. Required. %% +%% extramarks: Display article number in header. Required. %% +%% verbatim: For PG license text. Required. %% +%% graphicx: Allows inclusion of images. Required. %% +%% wrapfig: Wrap text around images. Required. %% +%% rotating: For sideways images. Required. %% +%% caption: Provides customised caption format. Required. %% +%% multirow: For table cells spanning several rows. Required. %% +%% makeidx: Allows index creation. Required. %% +%% multicol: Automatically balance index columns. Required. %% +%% calc: Used for length calculations. Required. %% +%% array: Enhancement to arrays. Required. %% +%% mhchem: For chemical formulae. Required. %% +%% indentfirst: Indent after headings. Required. %% +%% ifthen: Logical conditionals. Required. %% +%% longtable Allows multipage tables. Required. %% +%% footmisc: For better footnote handling. Required. %% +%% hyperref: Hypertext embellishments for pdf output. Required. %% +%% %% +%% Things to Check: %% +%% %% +%% Spellcheck: OK %% +%% lacheck: OK %% +%% False positives: %% +%% Complaints from preamble (before line 525) %% +%% Complaints from lprep config and log file (after line 28650) %% +%% Whitespace before punctation mark (many instances) %% +%% possible unwanted space at "{" (many instances) %% +%% punctuation mark should be placed after end of math mode(x2) %% +%% \ldots should be \cdots in "+ \ldots -" (x2) %% +%% Use ` to begin quotation, not ' " 'T" %% +%% %% +%% Lprep: OK, 3 warnings about moving code to preamble %% +%% Gutcheck: OK %% +%% PDF pages: 617 %% +%% PDF page size: 5.5" x 8.25" %% +%% PDF bookmarks: point to preface, contents, chapters, appendix, %% +%% index, PG licensing %% +%% PDF document info: filled in %% +%% PDF Reader displays document title in window title bar %% +%% ToC page numbers: OK %% +%% Images: 144 PNGs (fig01-fig144) located in the images subfolder %% +%% %% +%% Summary of log file: %% +%% No errors or warnings. %% +%% No overfull hboxes. %% +%% 23 underfull hboxes (primarily wrapped text around images) %% +%% %% +%% Command block: %% +%% pdflatex %% +%% makeindex %% +%% pdflatex x2 %% +%% %% +%% Compile History: %% +%% June 2011: windymilla (Nigel Blower) %% +%% MiKTeX 2.9, TeXnicCenter, Windows XP Pro %% +%% Compiled (includes makeindex) three times %% +%% %% +%% %% +%% June 2011: pglatex. %% +%% Compile this project with: %% +%% pdflatex 36525-t.tex %% +%% makeindex 36525-t.idx %% +%% pdflatex 36525-t.tex ..... TWO times %% +%% %% +%% pdfTeXk, Version 3.141592-1.40.3 (Web2C 7.5.6) %% +%% %% +%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% + +\listfiles + +\makeindex + +\makeatletter + +\documentclass[12pt,oneside]{book}[2005/09/16] + +\usepackage[paperwidth=5.5in,paperheight=8.25in, + headsep=0.2in, headheight=0.2in, + top=0.525in, bottom=0.25in, + left=0.125in, right=0.125in]{geometry}[2008/11/13] +\usepackage[latin1]{inputenc}[2006/05/05] + +\usepackage{amsmath}[2000/07/18] +\usepackage{amssymb}[2002/01/22] +\usepackage{fancyhdr}% no date stamp +\usepackage{extramarks}% no date stamp +\usepackage{verbatim}[2003/08/22] +\usepackage{graphicx}[1999/02/16] +\usepackage{wrapfig}[2003/01/31] +\usepackage{rotating}[2009/3/28] +\usepackage[justification=centering, font={footnotesize}]{caption}[2008/08/24] +\usepackage{multirow}% no date stamp +\usepackage{makeidx}[2000/03/29] +\usepackage{multicol}[2006/05/18] +\usepackage{calc}[2005/08/06] +\usepackage{array}[2005/08/23] +\usepackage[version=3]{mhchem}[2007/05/19] +\usepackage{indentfirst}[1995/11/23] +\usepackage{ifthen}[2001/05/26] +\usepackage{longtable}[2004/02/01] +\usepackage[perpage, symbol]{footmisc}[2009/09/15] + +% PDF attributes +\providecommand{\ebook}{00000} +\usepackage[pdftex, + hyperfootnotes=false, + pdftitle={The Project Gutenberg eBook \#\ebook: Notes on Recent Researches in Electricity and Magnetism}, + pdfsubject={Electricity, Magnetism}, + pdfauthor={J. J. Thomson}, + pdfkeywords={Robert Cicconetti, Nigel Blower, Project Gutenberg Online Distributed Proofreading Team}, + pdfpagelayout=SinglePage, + pdfdisplaydoctitle, + pdfpagelabels=true, + bookmarksopen=true, + bookmarksopenlevel=2, + colorlinks=false, + linkcolor=blue]{hyperref}[2008/11/18] + +% redefine hyperref's re-definition +% so that chapter anchor is above chapter title +\AtBeginDocument{% in case hyperref clobbers this +\def\@schapter#1{% + \begingroup + \let\@mkboth\@gobbletwo + \Hy@GlobalStepCount\Hy@linkcounter + \xdef\@currentHref{\Hy@chapapp*.\the\Hy@linkcounter}% + \Hy@raisedlink{% + \hyper@anchorstart{\@currentHref}\hyper@anchorend + }% + \endgroup + \H@old@schapter{#1}% +}} + +% Used to fix typos in the original text +\newboolean{FixTypos} +% Comment the following line to leave typos as in original. Uncomment it to fix them +\setboolean{FixTypos}{true} +\newcommand{\DPtypo}[2]{\ifthenelse{\boolean{FixTypos}}{#2}{#1}} + +\newcommand{\Ditto}{\text{,,}} + +% For sensible insertion of boilerplate/licence, +% Overlong lines will wrap and be indented 0.25in +\def\@xobeysp{~\hfil\discretionary{}{\kern\z@}{}\hfilneg} +\renewcommand\verbatim@processline{\leavevmode + \null\kern-0.25in\the\verbatim@line\par} +\addto@hook\every@verbatim{\@totalleftmargin0.25in\scriptsize} + +% Headers & footers +\pagestyle{fancy} +\renewcommand{\headrulewidth}{0pt} +\setlength\headheight{14.5pt} +\fancyhf{} +\fancyhead[L]{\footnotesize\firstleftmark} +\fancyhead[R]{\footnotesize\thepage} + +% Degree and centered dot symbols +\DeclareInputText{176}{\ifmmode{{}^\circ}\else\textdegree\fi} +\DeclareInputText{183}{\ifmmode\cdot\else\textperiodcentered\fi} + +% command to provide stretchy vertical space in proportion +\newcommand\nbvspace[1][1]{\vspace*{\stretch{#1}}} + +% command to put first word of chapter in small-caps +\newcommand\Firstsc[1]{\textsc{#1}} + +\newlength\TmpLen % for general use + +% For miscellaneous math alignment - usage : \PadTo{Longer Math}{Short Math} +% Will center Short Math in space large enough for Longer Math +% (use optional [l] or [r] for left/right alignment) +\newlength\TmpPadLen % for PadTo +\newcommand{\PadTo}[3][c]{% + \settowidth{\TmpPadLen}{$#2$}% + \makebox[\TmpPadLen][#1]{$#3$}% +} + +% \includegraphicsmid[placement]{graphics filename}{caption} +\newcommand{\includegraphicsmid}[3][!ht]{% + \begin{figure}[#1]% + \centering + \figurelabel{#2}% + \includegraphics{./images/#2.png}% + \ifthenelse{\equal{#3}{}}{}{\caption*{#3}}% + \end{figure}} +% \includegraphicstwo[placement]{graphics filename 1}{caption 1}{graphics filename 2}{caption 2} +\newcommand{\includegraphicstwo}[5][!ht]{% + \begin{figure}[#1]% + \centering% + \figurelabel{#2}% + \hspace*{\stretch{1}}% + \includegraphics{./images/#2.png}% + \hspace*{\stretch{2}} + \figurelabel{#4}% + 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DPalign*, DPgather* and lintertext +\providecommand\shortintertext\intertext +\newcount\DP@lign@no +\newtoks\DP@lignb@dy +\newif\ifDP@cr +\newif\ifbr@ce +\def\f@@zl@bar{\null} +\def\addto@DPbody#1{\global\DP@lignb@dy\@xp{\the\DP@lignb@dy#1}} +\def\parseb@dy#1{\ifx\f@@zl@bar#1\f@@zl@bar + \addto@DPbody{{}}\let\@next\parseb@dy + \else\ifx\end#1% + \let\@next\process@DPb@dy +\ifDP@cr\else\addto@DPbody{\DPh@@kr&\DP@rint}\@xp\addto@DPbody\@xp{\@xp{\the\DP@lign@no}&}\fi + \addto@DPbody{\end}% + \else\ifx\intertext#1% + \def\@next{\eat@command0}% + \else\ifx\shortintertext#1% + \def\@next{\eat@command1}% +\else\ifDP@cr\addto@DPbody{&\DP@lint}\@xp\addto@DPbody\@xp{\@xp{\the\DP@lign@no}&\DPh@@kl}% + \DP@crfalse\fi + \ifx\begin#1\def\begin@stack{b}% + \let\@next\eat@environment + \else\ifx\lintertext#1% + \let\@next\linter@text + \else\ifx\rintertext#1% + \let\@next\rinter@text + \else\ifx\\#1% +\addto@DPbody{\DPh@@kr&\DP@rint}\@xp\addto@DPbody\@xp{\@xp{\the\DP@lign@no}&\\}\DP@crtrue + \global\advance\DP@lign@no\@ne + \let\@next\parse@cr + \else\check@braces#1!Q!Q!Q!\ifbr@ce\addto@DPbody{{#1}}\else + \addto@DPbody{#1}\fi + \let\@next\parseb@dy + \fi\fi\fi\fi\fi\fi\fi\fi\@next} +\def\process@DPb@dy{\let\lintertext\@gobble\let\rintertext\@gobble + \@xp\start@align\@xp\tw@\@xp\st@rredtrue\@xp\m@ne\the\DP@lignb@dy} +\def\linter@text#1{\@xp\DPlint\@xp{\the\DP@lign@no}{#1}\parseb@dy} +\def\rinter@text#1{\@xp\DPrint\@xp{\the\DP@lign@no}{#1}\parseb@dy} +\def\DPlint#1#2{\@xp\def\csname DP@lint:#1\endcsname{\text{#2}}} +\def\DPrint#1#2{\@xp\def\csname DP@rint:#1\endcsname{\text{#2}}} +\def\DP@lint#1{\ifbalancedlrint\@xp\ifx\csname DP@lint:#1\endcsname\relax\phantom + {\csname DP@rint:#1\endcsname}\else\csname DP@lint:#1\endcsname\fi + \else\csname DP@lint:#1\endcsname\fi} +\def\DP@rint#1{\ifbalancedlrint\@xp\ifx\csname DP@rint:#1\endcsname\relax\phantom + {\csname DP@lint:#1\endcsname}\else\csname DP@rint:#1\endcsname\fi + \else\csname DP@rint:#1\endcsname\fi} +\def\eat@command#1#2{\ifcase#1\addto@DPbody{\intertext{#2}}\or + \addto@DPbody{\shortintertext{#2}}\fi\DP@crtrue + \global\advance\DP@lign@no\@ne\parseb@dy} +\def\parse@cr{\new@ifnextchar*{\parse@crst}{\parse@crst{}}} +\def\parse@crst#1{\addto@DPbody{#1}\new@ifnextchar[{\parse@crb}{\parseb@dy}} +\def\parse@crb[#1]{\addto@DPbody{[#1]}\parseb@dy} +\def\check@braces#1#2!Q!Q!Q!{\def\dp@lignt@stm@cro{#2}\ifx + \empty\dp@lignt@stm@cro\br@cefalse\else\br@cetrue\fi} +\def\eat@environment#1{\addto@DPbody{\begin{#1}}\begingroup + \def\@currenvir{#1}\let\@next\digest@env\@next} +\def\digest@env#1\end#2{% + \edef\begin@stack{\push@begins#1\begin\end \@xp\@gobble\begin@stack}% + \ifx\@empty\begin@stack + \@checkend{#2} + \endgroup\let\@next\parseb@dy\fi + \addto@DPbody{#1\end{#2}} + \@next} +\def\lintertext{lint}\def\rintertext{rint} +\newif\ifbalancedlrint +\let\DPh@@kl\empty\let\DPh@@kr\empty +\def\DPg@therl{&\omit\hfil$\displaystyle} +\def\DPg@therr{$\hfil} + +\newenvironment{DPalign*}[1][a]{% + \if m#1\balancedlrintfalse\else\balancedlrinttrue\fi + \global\DP@lign@no\z@\DP@crfalse + \DP@lignb@dy{&\DP@lint0&}\parseb@dy +}{% + \endalign +} +\newenvironment{DPgather*}[1][a]{% + \if m#1\balancedlrintfalse\else\balancedlrinttrue\fi + \global\DP@lign@no\z@\DP@crfalse + \let\DPh@@kl\DPg@therl + \let\DPh@@kr\DPg@therr + \DP@lignb@dy{&\DP@lint0&\DPh@@kl}\parseb@dy +}{% + \endalign +} +\makeatother +%%%%%%%%%%%% end of preamble %%%%%%%%%%%% + +\begin{document} + +% reduce space around displayed maths +\setlength\abovedisplayskip{6pt plus 6pt minus 3pt} +\setlength\belowdisplayskip{\abovedisplayskip} +\setlength\belowdisplayshortskip{\belowdisplayskip} + +%set up page headers +\fancypagestyle{plain}{\fancyhf{}} + +\pagestyle{empty} +\pagenumbering{alph} + +\pdfbookmark[0]{Project Gutenberg Boilerplate}{Project Gutenberg Boilerplate} + +\begin{verbatim} +The Project Gutenberg EBook of Notes on Recent Researches in Electricity +and Magnetism, by J. J. Thomson + +This eBook is for the use of anyone anywhere at no cost and with +almost no restrictions whatsoever. You may copy it, give it away or +re-use it under the terms of the Project Gutenberg License included +with this eBook or online at www.gutenberg.net + + +Title: Notes on Recent Researches in Electricity and Magnetism + Intended as a Sequel to Professor Clerk-Maxwell\'s Treatise + on Electricity and Magnetism + +Author: J. J. Thomson + +Release Date: June 27, 2011 [EBook #36525] + +Language: English + +Character set encoding: ISO-8859-1 + +*** START OF THIS PROJECT GUTENBERG EBOOK RECENT RESEARCHES--ELECTRICITY, MAGNETISM *** +\end{verbatim} + +\clearpage +%% -----File: 001.png----- + +\pagestyle{empty} +\pagenumbering{roman} +\pdfbookmark[0]{Notes on Recent Researches in Electricity and Magnetism}{Notes on Recent Researches in Electricity and Magnetism} + +\begin{center} +\nbvspace[1] +{\large NOTES}\\[2.5ex] +{\scriptsize ON}\\[3ex] +{\large RECENT RESEARCHES IN}\\[4ex] +{\Large ELECTRICITY AND MAGNETISM} + +\nbvspace[1] +{\scriptsize INTENDED AS A SEQUEL TO} + +\nbvspace[1] +PROFESSOR CLERK-MAXWELL'S TREATISE\\[1ex] +ON ELECTRICITY AND MAGNETISM + +\nbvspace[2] +{\scriptsize BY}\\[2ex] +J. J. THOMSON, M.A., F.R.S. + +\textsc{Hon. Sc.D. Dublin} + +{\scriptsize FELLOW OF TRINITY COLLEGE} + +{\scriptsize PROFESSOR OF EXPERIMENTAL PHYSICS IN THE UNIVERSITY OF CAMBRIDGE} + +\nbvspace[3] + +$\mathfrak{Oxford}$\\[1ex] +AT THE CLARENDON PRESS\\[1ex] +1893 +\nbvspace[1] +\end{center} +\clearpage +%% -----File: 002.png----- +% Publisher page +\nbvspace +\begin{center} +$\mathfrak{Oxford}$ + +{\footnotesize PRINTED AT THE CLARENDON PRESS} + +{\tiny BY HORACE HART, PRINTER TO THE UNIVERSITY} +\nbvspace +\end{center} + +\clearpage +\thispagestyle{empty} +\begin{center} +\small +Produced by Robert Cicconetti, Nigel Blower and the Online +Distributed Proofreading Team at http://www.pgdp.net (This +file was produced from images generously made available +by Cornell University Digital Collections) +\end{center} + +\vfill +{% + \setlength{\parindent}{0pt} + \setlength{\parskip}{6pt plus 2pt minus 1pt} + \subsection*{{\normalsize\centering\itshape Transcriber's Notes}} + \small + A small number of minor typographical errors and inconsistencies + have been corrected. See the {\ttfamily\footnotesize DPtypo} command + in the \LaTeX\ source for more information. +} + +\clearpage +%% -----File: 003.png---Folio v------- +\pagestyle{fancy} + +\Chapter{Preface}{} + + +\Firstsc{In} the twenty years which have elapsed since the first +appearance of Maxwell's Treatise on \textit{Electricity and Magnetism} +great progress has been made in these sciences. This progress +has been largely---perhaps it would not be too much to say +mainly---due to the influence of the views set forth in that +Treatise, to the value of which it offers convincing testimony. + +In the following work I have endeavoured to give an account +of some recent electrical researches, experimental as well as +theoretical, in the hope that it may assist students to gain some +acquaintance with the recent progress of Electricity and yet +retain Maxwell's Treatise as the source from which they learn +the great principles of the science. I have adopted exclusively +Maxwell's theory, and have not attempted to discuss the consequences +which would follow from any other view of electrical +action. I have assumed throughout the equations of the Electromagnetic +Field given by Maxwell in the ninth chapter of the +second volume of his Treatise. + +The \chapref{Chapter I.}{first chapter} of this work contains an account of a method +of regarding the Electric Field, which is geometrical and physical +rather than analytical. I have been induced to dwell on this +because I have found that students, especially those who commence +the subject after a long course of mathematical studies, +have a great tendency to regard the whole of Maxwell's theory +as a matter of the solution of certain differential equations, and +to dispense with any attempt to form for themselves a mental +picture of the physical processes which accompany the phenomena +they are investigating. I think that this state of things +is to be regretted, since it retards the progress of the science of +%% -----File: 004.png---Folio vi------- +Electricity and diminishes the value of the mental training +afforded by the study of that science. + +In the first place, though no instrument of research is more +powerful than Mathematical Analysis, which indeed is indispensable +in many departments of Electricity, yet analysis works to +the best advantage when employed in developing the suggestions +afforded by other and more physical methods. One example of +such a method, and one which is very closely connected with the +initiation and development of Maxwell's Theory, is that of the +`tubes of force' used by Faraday. Faraday interpreted all the +laws of Electrostatics in terms of his tubes, which served him in +place of the symbols of the mathematician, while in his hands +the laws according to which these tubes acted on each other +served instead of the differential equations satisfied by such +symbols. The method of the tubes is distinctly physical, that +of the symbols and differential equations is analytical. + +The physical method has all the advantages in vividness which +arise from the use of concrete quantities instead of abstract +symbols to represent the state of the electric field; it is more easily +wielded, and is thus more suitable for obtaining rapidly the main +features of any problem; when, however, the problem has to be +worked out in all its details, the analytical method is necessary. + +In a research in any of the various fields of electricity we shall +be acting in accordance with Bacon's dictum that the best results +are obtained when a research begins with Physics and ends with +Mathematics, if we use the physical theory to, so to speak, make +a general survey of the country, and when this has been done +use the analytical method to lay down firm roads along the line +indicated by the survey. + +The use of a physical theory will help to correct the tendency---which +I think all who have had occasion to examine in Mathematical +Physics will admit is by no means uncommon---to look on +analytical processes as the modern equivalents of the Philosopher's +Machine in the Grand Academy of Lagado, and to regard as the +normal process of investigation in this subject the manipulation +of a large number of symbols in the hope that every now and +then some valuable result may happen to drop out. +%% -----File: 005.png---Folio vii------- + +Then, again, I think that supplementing the mathematical +theory by one of a more physical character makes the study of +electricity more valuable as a mental training for the student. +Analysis is undoubtedly the greatest thought-saving machine +ever invented, but I confess I do not think it necessary or desirable +to use artificial means to prevent students from thinking too +much. It frequently happens that more thought is required, +and a more vivid idea of the essentials of a problem gained, by +a rough solution by a general method, than by a complete +solution arrived at by the most recent improvements in the +higher analysis. + +The method of illustrating the properties of the electric field +which I have given in \chapref{Chapter I.}{Chapter~I} has been devised so as to lead +directly to the distinctive feature in Maxwell's Theory, that +changes in the polarization in a dielectric produce magnetic +effects analogous to those produced by conduction currents. +Other methods of viewing the processes in the Electric Field, +which would be in accordance with Maxwell's Theory, could, I +have no doubt, be devised; the question as to which particular +method the student should adopt is however for many purposes +of secondary importance, provided that he does adopt one, and +acquires the habit of looking at the problems with which he +is occupied as much as possible from a physical point of view. + +It is no doubt true that these physical theories are liable +to imply more than is justified by the analytical theory they +are used to illustrate. This however is not important if we +remember that the object of such theories is suggestion and not +demonstration. Either Experiment or rigorous Analysis must +always be the final Court of Appeal; it is the province of these +physical theories to supply cases to be tried in such a court. + +\chapref{Chapter II.}{Chapter~II} is devoted to the consideration of the discharge of +electricity through gases; \chapref{Chapter III.}{Chapter~III} contains an account of the +application of Schwarz's method of transformation to the solution +of two-dimensional problems in Electrostatics. The rest of +the book is chiefly occupied with the consideration of the properties +of alternating currents; the experiments of Hertz and the +development of electric lighting have made the use of these +%% -----File: 006.png---Folio viii------- +currents, both for experimental and commercial purposes, much +more general than when Maxwell's Treatise was written; and +though the principles which govern the action of these currents +are clearly laid down by Maxwell, they are not developed to the +extent which the present importance of the subject demands. + +\chapref{Chapter IV.}{Chapter~IV} contains an investigation of the theory of such +currents when the conductors in which they flow are cylindrical +or spherical, while in \chapref{Chapter V.}{Chapter~V} an account of Hertz's +experiments on Electromagnetic Waves is given. This Chapter +also contains some investigations on the Electromagnetic Theory +of Light, especially on the scattering of light by small metallic +particles; on reflection from metals; and on the rotation of the +plane of polarization by reflection from a magnet. I regret that +it was only when this volume was passing through the press that +I became acquainted with a valuable paper by Drude (Wiedemann's +\textit{Annalen}, 46, p.~353, 1892) on this subject. + +\chapref{Chapter VI.}{Chapter~VI} mainly consists of an account of Lord Rayleigh's +investigations on the laws according to which alternating +currents distribute themselves among a network of conductors; +while the \chapref{Chapter VII.}{last Chapter} contains a discussion of the equations +which hold when a dielectric is moving in a magnetic field, +and some problems on the distribution of currents in rotating +conductors. + +I have not said anything about recent researches on Magnetic +Induction, as a complete account of these in an easily accessible +form is contained in Professor Ewing's `Treatise on Magnetic +Induction in Iron and other Metals.' + +I have again to thank Mr.~Chree, Fellow of King's College, +Cambridge, for many most valuable suggestions, as well as for +a very careful revision of the proofs. + +\begin{flushright} +J.~J. THOMSON.\qquad\null +\end{flushright} + +%% -----File: 007.png---Folio ix------- + +%% Manually placed "Art./Page" headers using \ToCHead and \ToCHeadPage may need moving if repaginated +%% Lines marked with %%[**manual] may also need adjusting + +\Chapter{Contents}{} + +\TocChapter{CHAPTER I.}{ELECTRIC DISPLACEMENT AND FARADAY TUBES OF FORCE.} + +\ToCHead +\ToCLine{1}{Electric displacement} +\ToCLine{2}{Faraday tubes} +\ToCLine{3}{Unit Faraday tubes} +\ToCLine{4}{Analogy with kinetic theory of gases} +\ToCLine{5}{Reasons for taking tubes of electrostatic induction as the unit} +\ToCLine{6}{Energy in the electric field} +\ToCLine{7}{Behaviour of Faraday tubes in a conductor} +\ToCLine{8}{Connection between electric displacement and Faraday tubes} +\ToCLine[+]{9}{Rate of change of electric polarization expressed in terms of the velocity of Faraday tubes} +\ToCLine{10}{Momentum due to Faraday tubes} +\ToCLine{11}{Electromotive intensity due to induction} +\ToCLine{12}{Velocity of Faraday tubes} +\ToCLine{13}{Systems of tubes moving with different velocities} +\ToCLine{14}{Mechanical forces in the electric field} +\ToCLine{15}{Magnetic force due to alteration in the dielectric polarization} +\ToCLine[+]{16}{Application of Faraday tubes to find the magnetic force due to a moving charged sphere} +\ToCLine{17}{Rotating electrified plates} +\ToCLine{18}{Motion of tubes in a steady magnetic field} +\ToCLine{19}{Induction of currents due to changes in the magnetic field} +\ToCLine{20}{Induction due to the motion of the circuit} +\ToCHeadPage +\ToCLine{21}{Effect of soft iron in the field} +\ToCLine{22}{Permanent magnets} +\ToCLine{23}{Steady current along a straight wire} +\ToCLine{24}{Motion of tubes when the currents are rapidly alternating} +\ToCLine{25}{Discharge of a Leyden jar} +\ToCLine{26}{Induced currents} +\ToCLine{27}{Electromagnetic theory of light} +%% -----File: 008.png---Folio x------- +\ToCLinR{28}{32}{Behaviour of tubes in conductors} +\ToCLine{33}{Galvanic cell} +\ToCLine{34}{Metallic and electrolytic conduction} + +\TocChapter{CHAPTER II.}{PASSAGE OF ELECTRICITY THROUGH GASES.} + +\ToCLine{35}{Introduction} +\ToCLine{36}{Can the molecules of a gas be electrified?} +\ToCLine{37}{Hot gases} +\ToCLine{38}{Electric properties of flames} +\ToCLine{39}{Effect of ultra-violet light on the discharge} +\ToCLine{40}{Electrification by ultra-violet light} +\ToCLine{41}{Disintegration of the negative electrode} +\ToCLine{42}{Discharge of electricity from illuminated metals} +\ToCLine{43}{Discharge of electricity by glowing bodies} +\ToCLine{44}{Volta-potential} +\ToCLine{45}{Electrification by sun-light} +\ToCLine{46}{`Electric Strength' of a gas} +\ToCLine{47}{Effect of the nature of the electrodes on the spark length} +\ToCLine{48}{Effect of curvature of the electrodes on the spark length} +\ToCLine[+]{49}{Baille's experiments on the connection between potential difference and spark length} +\ToCLine{50}{Liebig's on the same subject} +\ToCLine{51}{Potential difference expressed in terms of spark length} +\ToCLinR{52}{53}{Minimum potential difference required to produce a spark} +\ToCLinR{54}{61}{Discharge when the field is not uniform} +\ToCLinR[+]{62}{65}{Peace's experiments on the connection between pressure and spark potential} +\ToCHeadPage +\ToCLinR{66}{68}{Critical pressure} +\ToCLinR{69}{71}{Potential difference required to spark through various\\gases} %%[**manual] +\ToCLinR{72}{76}{Methods of producing electrodeless discharges} +\ToCLine{77}{Appearance of such discharges} +\ToCLinR{78}{80}{Critical pressure for such discharges} +\ToCLine{81}{Difficulty of getting the discharge to pass across from gas to metal} +\ToCLinR{82}{86}{High conductivity of rarefied gases} +\ToCLine{87}{Discharge through a mixture of gases} +\ToCLinR{88}{93}{Action of a magnet on the electrodeless discharges} +\ToCLine{94}{Appearance of discharge when electrodes are used} +\ToCLine{95}{Crookes' theory of the dark space} +%% -----File: 009.png---Folio xi------- +\ToCLine{96}{Length of dark space} +\ToCLinR{97}{98}{Negative glow} +\ToCLinR{99}{103}{Positive column and striations} +\ToCLinR{104}{107}{Velocity of discharge along positive column} +\ToCLinR{108}{116}{Negative rays} +\ToCLine{117}{Mechanical effects produced by negative rays} +\ToCLinR{118}{123}{Shadows cast by negative rays} +\ToCLinR{124}{125}{Relative magnitudes of time quantities in the discharge} +\ToCLinR{126}{128}{Action of a magnet on the discharge} +\ToCLine{129}{Action of a magnet on the negative glow} +\ToCLinR{130}{133}{Action of a magnet on the negative rays} +\ToCLine{134}{Action of a magnet on the positive column} +\ToCLine{135}{Action of a magnet on the negative rays in very high vacua} +\ToCLine{136}{Action of a magnet on the course of the discharge} +\ToCLinR{137}{138}{Action of a magnet on the striations} +\ToCLinR{139}{147}{Potential gradient along the discharge tube} +\ToCLinR{148}{151}{Effect of the strength of the current on the cathode fall} +\ToCLinR[+]{152}{155}{Small potential difference sufficient to maintain current when once started} +\ToCLinR{156}{162}{Warburg's experiments on the cathode fall} +\ToCLinR{163}{165}{Potential gradient along positive column} +\ToCLinR{166}{168}{Discharge between electrodes placed close together} +\ToCLinR{169}{176}{The arc discharge} +\ToCHeadPage +\ToCLinR{177}{178}{Heat produced by the discharge} +\ToCLinR[+]{179}{182}{Difference between effects at positive and negative electrodes} +\ToCLinR{183}{186}{Lichtenberg's and Kundt's dust figures} +\ToCLinR{187}{193}{Mechanical effects due to the discharge} +\ToCLinR{194}{201}{Chemical action of the discharge} +\ToCLine{202}{Phosphorescent glow due to the discharge} +\ToCLinR[+]{203}{206}{Discharge facilitated by rapid changes in the strength of the field} +\ToCLinR{207}{229}{Theory of the discharge} + +\TocChapter{CHAPTER III.}{CONJUGATE FUNCTIONS.} + +\ToCLinR{230}{233}{Schwarz and Christoffel's transformation} +\ToCLine{234}{Method of applying it to electrostatics} +%% -----File: 010.png---Folio xii------- +\ToCLine[+]{235}{Distribution of electricity on a plate placed parallel to an infinite plate} +\ToCLine{236}{Case of a plate between two infinite parallel plates} +\ToCLine{237}{Correction for thickness of plate} +\ToCLine{238}{Case of one cube inside another} +\ToCLinR{239}{240}{Cube over an infinite plate} +\ToCLine{241}{Case of condenser with guard-ring when the slit is shallow} +\ToCLine[+]{242}{Correction when guard-ring is not at the same potential as the plate} +\ToCLine{243}{Case of condenser with guard-ring when the slit is deep} +\ToCLine[+]{244}{Correction when guard-ring is not at the same potential as the plate} +\ToCLine{245}{Application of elliptic functions to problems in electrostatics} +\ToCLine{246}{Capacity of a pile of plates} +\ToCLine{247}{Capacity of a system of radial plates} +\ToCLine{248}{Finite plate at right angles to two infinite ones} +\ToCLine{249}{Two sets of parallel plates} +\ToCLine{250}{Two sets of radial plates} +\ToCLine{251}{Finite strip placed parallel to two infinite plates} +\ToCLine{252}{Two sets of parallel plates} +\ToCHeadPage +\ToCLine{253}{Two sets of radial plates} +\ToCLine{254}{Limitation of problems solved} + +\TocChapter{CHAPTER IV.}{ELECTRICAL WAVES AND OSCILLATIONS.} + +\ToCLine{255}{Scope of the chapter} +\ToCLine{256}{General equations} +\ToCLine{257}{Alternating currents in two dimensions} +\ToCLine{258}{Case when rate of alternation is very rapid} +\ToCLinR{259}{260}{Periodic currents along cylindrical conductors} +\ToCLine[+]{261}{Value of Bessel's functions for very large or very small values of the variable} +\ToCLine{262}{Propagation of electric waves along wires} +\ToCLinR{263}{264}{Slowly alternating currents} +\ToCLine{265}{Expansion of $xJ_0(x) / J_0'(x)$} +\ToCLine{266}{Moderately rapid alternating currents} +\ToCLine{267}{Very rapidly alternating currents} +\ToCLine{268}{Currents confined to a thin skin} +\ToCLine{269}{Magnetic force in dielectric} +\ToCLine{270}{Transmission of disturbances along wires} +%% -----File: 011.png---Folio xiii------- +\ToCLine{271}{Relation between external electromotive force and current} +\ToCLine{272}{Impedance and self-induction} +\ToCLinR{273}{274}{Values of these when alternations are rapid} +\ToCLinR{275}{276}{Flat conductors} +\ToCLine{277}{Mechanical force between flat conductors} +\ToCLine{278}{Propagation of longitudinal magnetic waves along wires} +\ToCLine{279}{Case when the alternations are very rapid} +\ToCLine{280}{Poynting's theorem} +\ToCLine{281}{Expression for rate of heat production in a wire} +\ToCLine{282}{Heat produced by slowly varying current} +\ToCLinR{283}{284}{Heat produced by rapidly varying currents} +\ToCLine[+]{285}{Heat in a transformer due to Foucault currents when the rate of alternation is slow} +\ToCLine{286}{When the rate of alternation is rapid} +\ToCLine{287}{Heat produced in a tube} +\ToCHeadPage +\ToCLine{288}{Vibrations of electrical systems} +\ToCLine{289}{Oscillations on two spheres connected by a wire} +\ToCLine{290}{Condition that electrical system should oscillate} +\ToCLine{291}{Time of oscillation of a condenser} +\ToCLine{292}{Experiments on electrical oscillations} +\ToCLinR[+]{293}{297}{General investigation of time of vibration of a condenser\\\null} %[**manual] +\ToCLinR{298}{299}{Vibrations along wires in multiple arc} +\ToCLine{300}{Time of oscillations on a cylindrical cavity} +\ToCLine{301}{On a metal cylinder surrounded by a dielectric} +\ToCLine{302}{State of the field round the cylinder} +\ToCLine{303}{Decay of currents in a metal cylinder} +\ToCLinR[+]{304}{305}{When the lines of magnetic force are parallel to the axis of the cylinder} +\ToCLinR{306}{307}{When the lines of force are at right angles to the axis} +\ToCLine{308}{Electrical oscillations on spheres} +\ToCLine{309}{Properties of the functions $S$ and $E$} +\ToCLine{310}{General solution} +\ToCLine{311}{Equation giving the periods of vibration} +\ToCLine{312}{Case of the first harmonic distribution} +\ToCLine{313}{Second and third harmonics} +\ToCLine{314}{Field round vibrating sphere} +\ToCLine{315}{Vibration of two concentric spheres} +\ToCLine{316}{When the radii of the spheres are nearly equal} +\ToCLine{317}{Decay of currents in spheres} +\ToCLine{318}{Rate of decay when the currents flow in meridional planes} +%% -----File: 012.png---Folio xiv------- +\ToCLinR{319}{320}{Effect of radial currents in the sphere} +\ToCLine[+]{321}{Currents induced in a sphere by the annihilation of a uniform magnetic field} +\ToCLine[+]{322}{Magnetic effects of these currents when the sphere is not made of iron} +\ToCLine{323}{When the sphere is made of iron} + +\pagebreak +\TocChapter{CHAPTER V.}{ELECTROMAGNETIC WAVES.} + +\ToCHead +\ToCLine{324}{Hertz's experiments} +\ToCLinR{325}{327}{Hertz's vibrator} +\ToCLine{328}{The resonator} +\ToCLine{329}{Effect of altering the position of the air gap} +\ToCLinR{330}{331}{Explanation of these effects} +\ToCLine{332}{Resonance} +\ToCLinR{333}{335}{Rate of decay of the vibrations} +\ToCLinR{336}{339}{Reflection of waves from a metal plate} +\ToCLinR{340}{342}{Sarasin's and De la Rive's experiments} +\ToCLine{343}{Parabolic mirrors} +\ToCLinR{344}{346}{Electric screening} +\ToCLine{347}{Refraction of electromagnetic waves} +\ToCLine{348}{Angle of polarization} +\ToCLinR[+]{349}{350}{Theory of reflection of electromagnetic waves by a dielectric\\\null} %[**manual] +\ToCLine[+]{351}{Reflection of these waves from and transmission through a thin metal plate} +\ToCLinR{352}{354}{Reflection of light from metals} +\ToCLine{355}{Table of refractive indices of metals} +\ToCLine{356}{Inadequacy of the theory of metallic reflection} +\ToCLine{357}{Magnetic properties of iron for light waves} +\ToCLine{358}{Transmission of light through thin films} +\ToCLinR{359}{360}{Reflection of electromagnetic waves from a grating} +\ToCLinR{361}{368}{Scattering of these waves by a wire} +\ToCLine{369}{Scattering of light by metal spheres} +\ToCLine{370}{Lamb's theorem} +\ToCLine{371}{Expressions for magnetic force and electric polarization} +\ToCLine[+]{372}{Polarization in plane wave expressed in terms of spherical harmonics} +\ToCLinR{373}{376}{Scattering of a plane wave by a sphere of any size} +\ToCLine{377}{Scattering by a small sphere} +\ToCLine{378}{Direction in which the scattered light vanishes} +%% -----File: 013.png---Folio xv------- +\ToCLinR{379}{384}{Hertz's experiments on waves along wires} +\ToCHeadPage +\ToCLine{385}{Sarasin's and De la Rive's experiments on waves along wires} +\ToCLinR[+]{390}{392}{Comparison of specific inductive capacity with refractive index} +\ToCLinR[+]{393}{401}{Experiments to determine the velocity of electromagnetic waves through various dielectrics} +\ToCLine{402}{Effects produced by a magnetic field on light} +\ToCLine{403}{Kerr's experiments} +\ToCLine{404}{Oblique reflection from a magnetic pole} +\ToCLine{405}{Reflection from tangentially magnetized iron} +\ToCLine{406}{Kundt's experiments on films} +\ToCLine{407}{Transverse electromotive intensity} +\ToCLine{408}{Hall effect} +\ToCLinR[+]{409}{414}{Theory of rotation of plane of polarization by reflection from a magnet} +\ToCLinR{415}{416}{Passage of light through thin films in a magnetic field} + +\TocChapter{CHAPTER VI.}{DISTRIBUTION OF RAPIDLY ALTERNATING CURRENTS.} + +\ToCLinR[+]{417}{418}{Very rapidly alternating currents distribute themselves so as to make the Kinetic Energy a minimum} +\ToCLine{419}{Experiments to illustrate this} +\ToCLine{420}{Distribution of alternating currents between two wires in parallel} +\ToCLine{421}{Self-induction and impedance of the wires} +\ToCLine{422}{Case of any number of wires in parallel} +\ToCLinR{423}{426}{General case of any number of circuits} +\ToCLinR{427}{428}{Case of co-axial solenoids} +\ToCLine{429}{Wheatstone's bridge with alternating currents} +\ToCLinR{430}{432}{Combination of self-induction and capacity} +\ToCLine{432*}{Effect of two adjacent vibrators on each other's periods} + +\TocChapter{CHAPTER VII.}{ELECTROMOTIVE INTENSITY IN MOVING BODIES.} + +\ToCLine{433}{Equations of electromotive intensity for moving bodies} +\ToCLinR{434}{439}{Sphere rotating in a symmetrical magnetic field} +\ToCLine{440}{Propagation of light through a moving dielectric} +\ToCHeadPage +\ToCLine{441}{Currents induced in a sphere rotating in an unsymmetrical field} +%% -----File: 014.png---Folio xvi------- +\ToCLine{442}{Special case when the field is uniform} +\ToCLine{443}{Case when the rotation is very rapid} +\ToCLine{444}{Magnetic force outside the sphere} +\ToCLine{445}{Couples and Forces on the Rotating Sphere} +\ToCLine{446}{The magnetic force is tangential when the rotation is rapid} +\ToCLine{447}{Force on the sphere} +\ToCLine[+]{448}{Solution of the previous case gives that of a sphere at rest in an alternating field} + +\TocChapter{~}{\textsc{\large Appendix.}} + +\ToCLine{App}{The Electrolysis of Steam} + +\vfill + +\begin{center} +\rule{0.5\textwidth}{0.5pt} +\end{center} + +\vfill + +\Section{ADDITIONS AND CORRECTIONS.} + +\hangindentbox{Page \pageref{add:1}.} For further remarks on electrification by incandescent bodies see +Appendix, p.~\pageref{add:2}. + +\hangindentbox{\Ditto\quad\pageref{add:3}.} E.~Wiedemann and Ebert have shown (\textit{Wied.~Ann.}~46, p.~158, 1892) that +the repulsion between two pencils of negative rays is due to the +influence which the presence of one cathode exerts on the emission of +rays from a neighbouring cathode. + +\hangindentbox{\Ditto\quad\pageref{add:4}.} Dewar (\textit{Proc.~Roy.~Soc}.~33, p.~262, 1882) has shown that the interior of +the gaseous envelope of the electric arc always shows a fixed pressure +amounting to about that due to a millimetre of water above that of +the surrounding atmosphere. + +\hangindentbox{\Ditto\quad\pageref{add:5}.} \textit{For} $90°$\,C. \textit{read} $100°$\,C. + +\vfill +%% -----File: 015.png---Folio 1------- +\clearpage + +\thispagestyle{empty} +\nbvspace +\begin{center}\Large +NOTES ON\\ELECTRICITY AND MAGNETISM. +\end{center} +\nbvspace[2] + +\mainmatter + +\Chapter{Chapter I.}{Electric Displacement and Faraday Tubes of Force.} +\index{Electric displacement}% +\index{Displacement@`Displacement', electric}% + +\Article{1} \Firstsc{The} influence which the notation and ideas of the fluid +theory of electricity have ever since their introduction exerted +over the science of Electricity and Magnetism, is a striking +illustration of the benefits conferred upon this science by a +concrete representation or `\emph{construibar vorstellung}' of the symbols, +which in the Mathematical Theory of Electricity define +the state of the electric field. Indeed the services which the +old fluid theory has rendered to Electricity by providing a language +in which the facts of the science can be clearly and +briefly expressed can hardly be over-rated. A descriptive theory +of this kind does more than serve as a vehicle for the clear expression +of well-known results, it often renders important services +by suggesting the possibility of the existence of new phenomena. + +The descriptive hypothesis, that of displacement in a dielectric, +used by Maxwell to illustrate his mathematical theory, seems +to have been found by many readers neither so simple nor so +easy of comprehension as the old fluid theory; indeed this seems +to have been one of the chief reasons why his views did not +sooner meet with the general acceptance they have since received. +As many students find the conception of `displacement' difficult, +I venture to give an alternative method of regarding the processes +occurring in the electric field, which I have often found +useful and which is, from a mathematical point of view, equivalent +to Maxwell's Theory. +%% -----File: 016.png---Folio 2------- + +\Article{2} This method is based on the conception, introduced by +Faraday, of tubes of electric force, or rather of electrostatic +\index{Tubes of electric force}% +\index{Closed@`Closed' Faraday tubes}% +\index{Faraday, lines of force}% +\index{Faraday, tubes@\subdashone tubes|(}% +induction. Faraday, as is well known, used these tubes +as the language in which to express the phenomena of the +electric field. Thus it was by their tendency to contract, and +the lateral repulsion which similar tubes exert on each other, +that he explained the mechanical forces between electrified +bodies, while the influence of the medium on these tubes was +on his view indicated by the existence of specific inductive +capacity in dielectrics. Although the language which Faraday +used about lines of force leaves the impression that he usually +regarded them as chains of polarized particles in the dielectric, +yet there seem to be indications that he occasionally regarded +them from another aspect; i.e.~as something having an existence +apart from the molecules of the dielectric, though these were +polarized by the tubes when they passed through the dielectric. +Thus, for example, in §~1616 of the \textit{Experimental Researches} he +seems to regard these tubes as stretching across a vacuum. It is +this latter view of the tubes of electrostatic induction which we +shall adopt, we shall regard them as having their seat in the +ether, the polarization of the particles which accompanies their +passage through a dielectric being a secondary phenomenon. +We shall for the sake of brevity call such tubes Faraday +Tubes. + +In addition to the tubes which stretch from positive to negative +electricity, we suppose that there are, in the ether, multitudes +of tubes of similar constitution but which form discrete closed +curves instead of having free ends; we shall call such tubes +`closed' tubes. The difference between the two kinds of tubes is +similar to that between a vortex filament with its ends on the +free surface of a liquid and one forming a closed vortex ring +inside it. These closed tubes which are supposed to be present +in the ether whether electric forces exist or not, impart a fibrous +structure to the ether. + +In his theory of electric and magnetic phenomena Faraday +made use of tubes of magnetic as well as of electrostatic +induction, we shall find however that if we keep to the conception +of tubes of electrostatic induction we can explain the +phenomena of the magnetic field as due to the motion of such +tubes. +%% -----File: 017.png---Folio 3------- + +\Subsection{The Faraday Tubes.} + +\Article{3} As is explained in Art.~82 of Maxwell's \textit{Electricity and +Magnetism}, these tubes start from places where there is positive +and end at places where there is negative electricity, the +quantity of positive electricity at the beginning of the tube +being equal to that of the negative at the end. If we assume +that the tubes in the field are all of the same strength, +the quantity of free positive electricity on any surface will be +proportional to the number of tubes leaving the surface. In the +mathematical theory of electricity there is nothing to indicate +that there is any limit to the extent to which a field of electric +force can be subdivided up into tubes of continually diminishing +strength, the case is however different if we regard these tubes +of force as being no longer merely a form of mathematical expression, +but as real physical quantities having definite sizes +and shapes. If we take this view, we naturally regard the tubes +as being all of the same strength, and we shall see reasons for +believing that this strength is such that when they terminate on +a conductor there is at the end of the tube a charge of negative +electricity equal to that which in the theory of electrolysis we +associate with an atom of a monovalent element such as chlorine. + +This strength of the unit tubes is adopted because the phenomena +of electrolysis show that it is a natural unit, and that +fractional parts of this unit do not exist, at any rate in electricity +that has passed through an electrolyte. We shall assume +in this chapter that in all electrical processes, and not merely in +electrolysis, fractional parts of this unit do not exist. + +The Faraday tubes either form closed circuits or else begin +and end on atoms, all tubes that are not closed being tubes that +stretch in the ether along lines either straight or curved from +one atom to another. When the length of the tube connecting +two atoms is comparable with the distance between the +atoms in a molecule, the atoms are said to be in chemical combination; +when the tube connecting the atoms is very much +longer than this, the atoms are said to be `chemically free'. + +The property of the Faraday tubes of always forming closed +circuits or else having their ends on atoms may be illustrated +by the similar property possessed by tubes of vortex motion in +a frictionless fluid, these tubes either form closed circuits or +%% -----File: 018.png---Folio 4------- +have their ends on the boundary of the liquid in which the +vortex motion takes place. + +The Faraday tubes may be supposed to be scattered throughout +space, and not merely confined to places where there is a +finite electromotive intensity, the absence of this intensity being +due not to the absence of the Faraday tubes, but to the want of +arrangement among such as are present: the electromotive intensity +at any place being thus a measure, not of the whole +number of tubes at that place, but of the excess of the number +pointing in the direction of the electromotive intensity over the +number of those pointing in the opposite direction. + +\Article{4} In this chapter we shall endeavour to show that the various +phenomena of the electromagnetic field may all be interpreted +as due to the motion of the Faraday tubes, or to changes in their +position or shape. Thus, from our point of view, this method +of looking at electrical phenomena may be regarded as forming +a kind of molecular theory of Electricity, the Faraday tubes +taking the place of the molecules in the Kinetic Theory of +Gases: the object of the method being to explain the phenomena +of the electric field as due to the motion of these tubes, +just as it is the object of the Kinetic Theory of Gases to explain +the properties of a gas as due to the motion of its molecules. + +These tubes also resemble the molecules of a gas in another respect, +as we regard them as incapable of destruction or creation. + +\Article{5} It may be asked at the outset, why we have taken the tubes +of electrostatic induction as our molecules, so to speak, rather +than the tubes of magnetic induction? The answer to this question +is, that the evidence afforded by the phenomena which accompany +the passage of electricity through liquids and gases shows +that molecular structure has an exceedingly close connection +with tubes of electrostatic induction, much closer than we have +any reason to believe it has with tubes of magnetic induction. +The choice of the tubes of electrostatic induction as our molecules +seems thus to be the one which affords us the greatest facilities +for explaining those electrical phenomena in which matter as +well as the ether is involved. + +\Article{6} Let us consider for a moment on this view the origin of +the energy in the electrostatic and electromagnetic fields. We +suppose that associated with the Faraday tubes there is a distribution +of velocity of the ether both in the tubes themselves +%% -----File: 019.png---Folio 5------- +and in the space surrounding them. Thus we may have rotation +in the ether inside and around the tubes even when the tubes +themselves have no translatory velocity, the kinetic energy due +to this motion constituting the potential energy of the electrostatic +field: while when the tubes themselves are in motion we +have super-added to this another distribution of velocity whose +energy constitutes that of the magnetic field. + +The energy we have considered so far is in the ether, but when +a tube falls on an atom it may modify the internal motion +of the atom and thus affect its energy. Thus, in addition to +the kinetic energy of the ether arising from the electric +field, there may also be in the atoms some energy arising +from the same cause and due to the alteration of the internal +motion of the atoms produced by the incidence of the Faraday +tubes. If the change in the energy of an atom produced by +the incidence of a Faraday tube is different for atoms of different +substances, if it is not the same, for example, for an atom of +hydrogen as for one of chlorine, then the energy of a number +of molecules of hydrochloric acid would depend upon whether +the Faraday tubes started from the hydrogen and ended on the +chlorine or vice versâ. Since the energy in the molecules thus +depends upon the disposition of the tubes in the molecule, there +will be a tendency to make all the tubes start from the hydrogen +and end on the chlorine or vice versâ, according as the first or +second of these arrangements makes the difference between the +kinetic and potential energies a maximum. In other words, +there will, in the language of the ordinary theory of electricity, +be a tendency for all the atoms of hydrogen to be charged with +electricity of one sign, while all the atoms of chlorine are charged +with equal amounts of electricity of the opposite sign. + +The result of the different effects on the energy of the +atom produced by the incidence of a Faraday tube will be the +same as if the atoms of different substances attracted electricity +with different degrees of intensity: this has been shown +\index{Helmholtz va@Helmholtz, v.\ H., attraction of electricity by different substances}% +by v.~Helmholtz to be sufficient to account for contact and frictional +electricity. It also, as we shall see in \chapref{Chapter II.}{Chapter~II}, accounts +for some of the effects observed when electricity passes from a +gas to a metal or vice versâ. +\index{Faraday, tubes@\subdashone tubes|)}% + +\Article{7} The Faraday tubes when they reach a conductor shrink to +molecular dimensions. We shall consider the processes by which +%% -----File: 020.png---Folio 6------- +this is effected at the end of this chapter, and in the meantime +proceed to discuss the effects produced by these tubes when +moving through a dielectric. + +\Article{8} In order to be able to fix the state of the electric field at any +point of a dielectric, we shall introduce a quantity which we shall +call the `polarization' of the dielectric, and which while mathematically +\index{Polarization}% +\index{Displacement@`Displacement', electric}% +\index{Electric displacement}% +identical with Maxwell's `displacement' has a different +physical interpretation. The `polarization' is defined as follows: +Let $A$~and~$B$ be two neighbouring points in the dielectric, let a +plane whose area is unity be drawn between these points and at +right angles to the line joining them, then the polarization in +the direction~$AB$ is the excess of the number of the Faraday +tubes which pass through the unit area from the side~$A$ to the +side~$B$ over those which pass through the same area from the +side~$B$ to the side~$A$. In a dielectric other than air we imagine +the unit area to be placed in a narrow crevasse cut out of the dielectric, +the sides of the crevasse being perpendicular to~$AB$. +The polarization is evidently a vector quantity and may be +resolved into components in the same way as a force or a velocity; +we shall denote the components parallel to the axes of +$x$,~$y$,~$z$ by the letters $f$,~$g$,~$h$; these are mathematically identical +with the quantities which Maxwell denotes by the same letters, +their physical interpretation however is different. + +\Article{9} We shall now investigate the rate of change of the components +of the polarization in a dielectric. Since the Faraday tubes +in such a medium can neither be created nor destroyed, a change +in the number passing through any fixed area must be due to the +motion or deformation of the tubes. We shall suppose, in the +first place, that the tubes at one place are all moving with the +same velocity. Let $u$,~$v$,~$w$ be the components of the velocities +of these tubes at any point, then the change in~$f$, the number +of tubes passing at the point $x$,~$y$,~$z$, through unit area at right +angles to the axis of~$x$, will be due to three causes. The first of +these is the motion of the tubes from another part of the field +up to the area under consideration; the second is the spreading +out or concentration of the tubes due to their relative motion; +and the third is the alteration in the direction of the tubes due +to the same cause. + +Let $\delta_{1}f$ be the change in~$f$ due to the first cause, then in +consequence of the motion of the tubes, the tubes which at the +%% -----File: 021.png---Folio 7------- +time $t + \delta t$ pass through the unit area will be those which at +the time~$t$ were at the point +\[ +x - u \delta t, \quad y - v \delta t, \quad z - w \delta t, +\] +hence $\delta _{1}f$ will be given by the equation +\[ +\delta_{1} f = - \left(u \frac{df}{dx} + v \frac{df}{dy} + w \frac{df}{dz} \right) \delta t. +\] + +In consequence of the motion of the tubes relatively to one +another, those which at the time~$t$ passed through unit area at +right angles to~$x$ will at the time~$t + \delta t$ be spread over an area +\[ +1 + \delta t \left\{\frac{dv}{dy} + \frac{dw}{dz} \right\}; +\] +thus $\delta_{2}f$, the change in~$f$ due to this cause, will be given by +the equation +\begin{DPalign*} +\delta_{2}f & = \frac{f}{1 + \delta t \left\{\dfrac{dv}{dy} + \dfrac{dw}{dz} \right\}} - f, \\ +\lintertext{or} \delta_{2}f & = -\delta t f \left\{\frac{dv}{dy} + \frac{dw}{dz} \right\}. +\end{DPalign*} + +In consequence of the deflection of the tubes due to the relative +motion of their parts some of those which at the time~$t$ were at +right angles to the axis of~$x$ will at the time~$t + \delta t$ have a +component along it. Thus, for example, the tubes which at the +time~$t$ were parallel to~$y$ will after a time~$\delta t$ has elapsed be +twisted towards the axis of~$x$ through an angle~$\delta t \dfrac{du}{dy}$, similarly +those parallel to~$z$ will be twisted through an angle~$\delta t \dfrac{du}{dz}$ +towards the axis of~$x$ in the time $\delta t$; hence $\delta_{3}f$, the change in~$f$ +due to this cause, will be given by the equation +\[ +\delta_{3}f = \delta t \left\{g \frac{du}{dy} + h \frac{du}{dz} \right\}. +\] + +Hence if $\delta f$ is the total change in~$f$ in the time~$\delta t$, since +\[ +\delta f = \delta_{1}f + \delta_{2}f + \delta_{3}f, +\] +we have +\[ +\delta f = \left[ - \left(u \frac{df}{dx} + v \frac{df}{dy} + w \frac {df}{dz} \right) - f \left(\frac{dv}{dy} + \frac{dw}{dz} \right) + \left(g \frac{du}{dy} + h \frac{du}{dz} \right) \right]\delta t, +\] +which may be written as +\[ +\frac{df}{dt} = \frac{d}{dy} (ug - vf) - \frac{d}{dz} (wf - uh) - u \left(\frac{df}{dx} + \frac{dg}{dy} + \frac{dh}{dz}\right). \Tag{1} +\] +%% -----File: 022.png---Folio 8------- + +If $\rho$ is the density of the free electricity, then since by the +definition of \artref{8}{Art.~8} the surface integral of the normal polarization +taken over any closed surface must be equal to the quantity of +electricity inside that surface, it follows that +\[ +\rho = \frac{df}{dx} + \frac{dg}{dy} + \frac{dh}{dz}, +\] +hence equation~(\eqnref{9}{1}) may be written +\begin{DPalign*} +\lintertext{\raiseboxlint[0.75]{Similarly}} +\left. +\begin{aligned} +\frac{df}{dt} + \PadTo{w}{u}\rho &= \frac{d}{dy} (ug - vf) - \frac{d}{dz} (wf - uh). \\[0.75\baselineskip] +\frac{dg}{dt} + \PadTo{w}{v}\rho &= \frac{d}{dz} (vh - wg) - \frac{d}{dx} (ug - vf), \\ +\frac{dh}{dt} + w\rho &= \frac{d}{dx} (wf - uh) - \frac{d}{dy} (vh - wg). +\end{aligned}\right\} \Tag{2} +\end{DPalign*} + +If $p$,~$q$,~$r$ are the components of the current parallel to $x$,~$y$,~$z$ +respectively, $\alpha$,~$\beta$,~$\gamma$ the components of the magnetic force in the +same directions, then we know +\[ +\left. +\begin{aligned} +4\pi p & = \dfrac{d\gamma}{dy} - \dfrac{d\beta}{dz}, \\ +4\pi q & = \dfrac{d\alpha}{dz} - \dfrac{d\gamma}{dx}, \\ +4\pi r & = \dfrac{d\beta}{dx} - \dfrac{d\alpha}{dy}. +\end{aligned} \right\} \Tag{3} +\] + +Hence, if we regard the current as made up of the convection +current whose components are $u\rho$,~$v\rho$,~$w\rho$ respectively, and the +polarization current whose components are $\dfrac{df}{dt}$,~$\dfrac{dg}{dt}$,~$\dfrac{dh}{dt}$, we +see by comparing equations (\eqnref{9}{2})~and~(\eqnref{9}{3}) that we may regard +the moving Faraday tubes as giving rise to a magnetic force +whose components $\alpha$,~$\beta$,~$\gamma$ are given by the equation +\[ +\left.\begin{aligned} +\alpha & = 4\pi (vh - wg), \\ +\beta & = 4\pi (wf - uh), \\ +\gamma & = 4\pi (ug - vf). +\end{aligned} \right\} \Tag{4} +\] + +Thus a Faraday tube when in motion produces a magnetic +\index{Magnetic force due to the motion of Faraday tubes}% +force at right angles both to itself and to its direction of motion, +whose magnitude is proportional to the component of the velocity +at right angles to the direction of the tube. The magnetic force +%% -----File: 023.png---Folio 9------- +and the rotation from the direction of motion to that of the tube +at any point are related like translation and rotation in a +right-handed screw. + +\Article{10} The motion of these tubes involves kinetic energy, and this +kinetic energy is the energy of the magnetic field. Now if $\mu$~is the +magnetic permeability we know that the energy per unit volume is +\[ +\frac{\mu}{8\pi} (\alpha^2 + \beta^2 + \gamma^2), +\] +or substituting the values of~$\alpha$, $\beta$,~$\gamma$ from equations~(\eqnref{9}{4}), +\[ +2\pi \mu [(hv-gw)^2 + (fw-hu)^2 + (gu-fv)^2]. +\] + +\index{Faradayx tubes, momentum of@\subdashtwo momentum of}% +\index{Momentum of Faraday tubes}% +The momentum per unit volume of the dielectric parallel to~$x$ +is the differential coefficient of this expression with regard to~$u$, +hence if $U$,~$V$,~$W$ are the components of the momentum +parallel to~$x$, $y$,~$z$, we have +\begin{align*} +U &= 4\pi \mu \{g(gu - fv) - h(fw - hu)\} \\ + &= gc - hb, +\end{align*} +if $a$,~$b$,~$c$ are the components of the magnetic induction parallel +to~$x$, $y$,~$z$. +\begin{DPgather*} +\lintertext{\raiseboxlint{\indent Similarly}} \left.\begin{aligned} +V &= ha - fc, \\ +W &= fb - ga. +\end{aligned}\right\} \Tag{5} +\end{DPgather*} + +Thus the momentum per unit volume in the dielectric, which +is due to the motion of the tubes, is at right angles to the +polarization and to the magnetic induction, the magnitude of +the momentum being equal to the product of the polarization +and the component of the magnetic induction at right angles +to it. We may regard each tube as having a momentum +proportional to the intensity of the component of the magnetic +induction at right angles to the direction of the tube. It is +interesting to notice that the components of the momentum +in the field as given by equations~(\eqnref{10}{5}) are proportional to the +amounts of energy transferred in unit time across unit planes +\index{Energy, transfer of}% +\index{Poynting, transfer of energy in electric field}% +at right angles to the axes of $x$,~$y$,~$z$ in Poynting's theory +of the transfer of energy in the electromagnetic field (\textit{Phil.\ +\index{Transfer of energy}% +Trans.}\ 1884, Part~II. p.~343); hence the direction in which the +energy in Poynting's theory is supposed to move is the same +as the direction of the momentum determined by the preceding +investigation. +%% -----File: 024.png---Folio 10------- + +\Article{11} The electromotive intensities parallel to $x$,~$y$,~$z$ due to the +\index{Intensity, electromotive|(}% +motion of the tubes are the differential coefficients of the kinetic +energy with regard to $f$,~$g$,~$h$ respectively, hence we obtain +the following expressions for $X$,~$Y$,~$Z$ the components of the +electromotive intensity, +\index{Electromotive intensity}% +\[ + \left. +\begin{aligned} + X & = wb - vc, \\ + Y & = uc - wa, \\ + Z & = va - ub. +\end{aligned}\right\} \Tag{6} +\] + +Thus the direction of the electromotive intensity due to the +motion of the tubes is at right angles both to the magnetic +induction and to the direction of motion of the tubes. + +From equations~(\eqnref{11}{6}) we get +\begin{multline*} +\frac{dZ}{dy}-\frac{dY}{dz}=v\frac{da}{dy}+w\frac{da}{dz}-u\left(\frac{db}{dy} + \frac{dc}{dz}\right) \\ ++a\left(\frac{dv}{dy}+\frac{dw}{dz}\right)-b\frac{du}{dy}-c\frac{du}{dz}. +\end{multline*} + +But since the equation +\[ +\frac{da}{dx} + \frac{db}{dy} + \frac{dc}{dz} = 0 +\] +holds, as we shall subsequently show, on the view we have taken +of the magnetic force as well as on the ordinary view, we have +\[ +\frac{dZ}{dy} - \frac{dY}{dz} = u \frac{da}{dx} + v \frac{da}{dy} + w \frac{da}{dz} + a\left(\frac{dv}{dy} + \frac{dw}{dz}\right) - b \frac{du}{dy} - c \frac{du}{dz}. +\] + +The right-hand side of this investigation is by the reasoning +given in \artref{9}{Art.~9} equal to~$-\dfrac{da}{dt}$, the rate of diminution in the +number of lines of magnetic induction passing through unit +area at right angles to the axis of~$x$: hence we have +\begin{DPgather*} +\lintertext{Similarly} \left.\begin{aligned} + \frac{dZ}{dy} - \frac{dY}{dz} & = -\frac{da}{dt}. \\ + \frac{dX}{dz} - \frac{dZ}{dx} & = -\frac{db}{dt}, \\ + \frac{dY}{dx} - \frac{dX}{dy} & = -\frac{dc}{dt}. +\end{aligned} \right\} \Tag{7} +\end{DPgather*} + +Now by Stokes' theorem +\index{Stokes, theorem}% +\[ +\tint (X\, dx + Y\, dy + Z\, dz) +\] +%% -----File: 025.png---Folio 11------- +taken round a closed circuit is equal to +\[ +\iint \left\{l\left(\frac{dZ}{dy} - \frac{dY}{dz}\right) + m \left(\frac{dX}{dz} - \frac{dZ}{dx}\right) + n\left(\frac{dY}{dx} - \frac{dX}{dy}\right)\right\}\,dS, +\] +where $l$,~$m$,~$n$ are the direction-cosines of the normal to a surface~$S$ +which is entirely bounded by the closed circuit. Substituting +the preceding values for~$dZ / dy - dY / dz$, \&c., we see that the line +integral of the electromotive intensity round a closed circuit +is equal to the rate of diminution in the number of lines of +magnetic induction passing through the circuit. Hence the preceding +view of the origin of magnetic force leads to Faraday's +rule for the induction of currents by the alteration of the +magnetic field. + +\Article{12} When the electromotive intensity is entirely due to the +motion of the tubes in an isotropic medium whose specific inductive +capacity is~$K$, we have +\begin{align*} +f & = \frac{K}{4\pi} X \\ + & = \frac{K}{4\pi} \{wb - vc\}, +\end{align*} +and since +\begin{DPalign*} +&b = 4\pi \mu \{fw - hu\} , \quad c = 4\pi \mu \{gu - fv\}, \\ +\lintertext{we have} &f = \mu K \{f(u^2 + v^2 + w^2) - u(fu + gv + hw)\}; \\ +\lintertext{similarly} &g = \mu K \{g(u^2 + v^2 + w^2) - v(fu + gv + hw)\}, \\ +&h = \mu K \{h(u^2 + v^2 + w^2) - w(fu + gv + hw)\}, \\ +\lintertext{hence} &fu + gv + hw = 0, \\ +\lintertext{\rlap{and therefore}} +&\PadTo{h = \mu K \{h(u^2 + v^2 + w^2) - w(fu + gv + hw)\},}{u^2 + v^2 + w^2 = \frac{1}{\mu K}.} +\end{DPalign*} + +\index{Faradayx tubes, velocity of@\subdashtwo velocity of}% +\index{Velocity of Faraday tube}% +Hence when the electromotive intensity is entirely due to the +motion of the tubes, the tubes move at right angles to themselves +with the velocity~$1/\sqrt{\mu K}$, which is the velocity with +which light travels through the dielectric. In this case the +momentum is parallel to the direction of motion, and the electromotive +intensity is in the direction of the polarization. In this +case the polarization, the direction of motion and the magnetic +force, are mutually at right angles; their relative disposition is +shown in \figureref{fig01}{Fig.~1}. + +Collecting the preceding results, we see that when a Faraday +tube is in motion it is accompanied by (1)~a magnetic force +%% -----File: 026.png---Folio 12------- +right angles to the tube and to the direction in which it is +moving, (2)~a momentum at right angles to the tube and to +the magnetic induction, (3)~an electromotive intensity at right +angles to the direction of motion and to the magnetic induction; +this always tends to make the tube set itself at right angles +to the direction in which it is moving. Thus in an isotropic +medium in which there is no free electricity and consequently +no electromotive intensities except those which arise from the +motion of the tubes, the tubes set themselves at right angles +to the direction of motion. + +\includegraphicsmid{fig01}{Fig.~1.} + +\Article{13} We have hitherto only considered the case when the tubes +at any one place in a dielectric are moving with a common +velocity. We can however without difficulty extend these results +to the case when we have different sets of tubes moving +with different velocities. + +Let us suppose that we have the tubes $f_{1}$,~$g_{1}$,~$h_{1}$, moving with a +velocity whose components are $u_{1}$,~$v_{1}$,~$w_{1}$, while the tubes $f_{2}$,~$g_{2}$,~$h_{2}$ +move with the velocities $u_{2}$,~$v_{2}$,~$w_{2}$, and so on. Then the rate of +increase in the number of tubes which pass through unit area at +right angles to the axis of~$x$ is, by the same reasoning as before, +\[ +\frac{d}{dy} \tsum (ug - vf) - \frac{d}{dz} \tsum (wf - uh) - \tsum (u\rho). +\] +%% -----File: 027.png---Folio 13------- + +Hence we see as before that the tubes may be regarded as +\index{Magnetic force due to the motion of Faraday tubes}% +producing a magnetic force whose components $\alpha$,~$\beta$,~$\gamma$ are +given by the equations +\[ +\left.\begin{aligned} +\alpha & = 4\pi \tsum (vh - wg), \\ +\beta & = 4\pi \tsum (wf - uh), \\ +\gamma & = 4\pi \tsum (ug - vf). +\end{aligned} \right\} \Tag{8} +\] + +The Kinetic energy per unit volume,~$T$, due to the motion of +\index{Kinetic energy, due to motion of Faraday tubes}% +these tubes is given by the equation +\[ +T = \frac{\mu}{8\pi} \{\alpha^2 + \beta^2 + \gamma^2\}, +\] +or +\[ +T = 2\pi \mu \left[ \left\{\tsum (vh - wg)\right\}^2 + + \left\{\tsum (wf - uh)\right\}^2 + + \left\{\tsum (ug - vf)\right\}^2\right]. +\] + +Thus $dT / du_{1}$, the momentum per unit volume parallel to~$x$ due +to the tube with suffix~$1$, is equal to +\begin{gather*} +4\pi \mu \left\{g_{1} \tsum (ug - vf) - h_{1} \tsum (wf - uh)\right\}, \\ += g_{1} c - h_{1} b, +\end{gather*} +where $a$,~$b$,~$c$ are the components of the magnetic induction. + +Thus $U$,~$V$,~$W$, the components of the momentum per unit +volume parallel to the axes of $x$,~$y$,~$z$ respectively, are given +by the equations +\[ +\left. \begin{aligned} +U &= c \tsum g - b \tsum h, \\ +V &= a \tsum h - c \tsum f, \\ +W &= b \tsum f - a \tsum g. +\end{aligned} \right\} \Tag{9} +\] + +Thus when we have a number of tubes moving about in the +electric field the resultant momentum at any point is perpendicular +both to the resultant magnetic induction and to the +resultant polarization, and is equal to the product of these +two quantities into the sine of the angle between them. + +\index{Electromotive intensity}% +The electromotive intensities $X$,~$Y$,~$Z$ parallel to the axes of +$x$,~$y$,~$z$ respectively are equal to the mean values of~$dT / df$, +$dT / dg$, $dT / dh$, hence we have +\[ +\left.\begin{aligned} +X &= b\bar{w} - c\bar{v}, \\ +Y &= c\bar{u} - a\bar{w}, \\ +Z &= a\bar{v} - b\bar{u}; +\end{aligned}\right\} \Tag{10} +\] +where a bar placed over any quantity indicates that the mean +value of that quantity is to be taken. +\index{Intensity, electromotive|)}% +%% -----File: 028.png---Folio 14------- + +Thus when a system of Faraday tubes is in motion, the +electromotive intensity is at right angles both to the resultant +magnetic induction and to the mean velocity of the tubes, and is +equal in magnitude to the product of these two quantities into +the sine of the angle between them. + +\index{Magnetic force due to the motion of Faraday tubes}% +We see from the preceding equations that there may be a +resultant magnetic force due to the motion of the positive +tubes in one direction and the negative ones in the opposite, +without either resultant momentum or electromotive intensity; +for if there are as many positive as negative tubes passing +through each unit area so that there is no resultant polarization, +there will, by equations~(\eqnref{13}{9}), be no resultant momentum, +while if the number of tubes moving in one direction is the +same as the number moving in the opposite, equations~(\eqnref{13}{10}) show +that there will be no resultant electromotive intensity due to +the motion of the tubes. We thus see that when the magnetic +field is steady the motion of the Faraday tubes in the +field will be a kind of shearing of the positive past the +negative tubes; the positive tubes moving in one direction +and the negative at an equal rate in the opposite. When, +however, the field is not in a steady state this ceases to be +the case, and then the electromotive intensities due to induction +are developed. + +\Subsection{Mechanical Forces in the Field.} +\index{Current, mechanical force on conductor conveying@\subdashone mechanical force on conductor conveying}% +\index{Mechanical force on current@\subdashone force on current}% + +\Article{14} The momentum parallel to~$x$ per unit volume of the +medium, due to the motion of the Faraday tubes, is by equation~(\eqnref{13}{9}) +\[ +c\tsum g - b\tsum h; +\] +thus the momentum parallel to~$x$ which enters a portion of the +medium bounded by the closed surface~$S$ in unit time is equal to +\[ +\tiint \left[c\tsum g(lu + mv + nw) - b \tsum h(lu + mv + nw)\right] dS, +\] +where $dS$~is an element of the surface and $l$,~$m$,~$n$ the direction-cosines +of its inwardly directed normal. + +If the surface~$S$ is so small that the external magnetic field +may be regarded as constant over it, the expression may be +written as +\begin{DPgather*} +c \tiint \tsum g(lu + mv + nw)\,dS - b \tiint \tsum h(lu + mv + nw)\,dS.\\[\abovedisplayskip] +%% -----File: 029.png---Folio 15------- +\lintertext{\rlap{\indent Now}} \tiint \tsum g(lu + mv + nw)\,dS,\\ +\lintertext{\rlap{and}} \tiint \tsum h(lu + mv + nw)\,dS, +\end{DPgather*} +are the number of Faraday tubes parallel to $y$~and~$z$ respectively +which enter the element in unit time, that is, they are the +volume integrals of the components $q$~and~$r$ of the current +parallel to $y$~and~$z$ respectively: if the medium surrounded +by~$S$ is a dielectric this is a polarization current, if it is a conductor +it is a conduction current. Thus the momentum parallel +to~$x$ communicated in unit time to unit volume of the medium, +\index{Force acting on a current}% +in other words the force parallel to~$x$ acting on unit volume of +the medium, is equal to +\[ +cq - br;\hspace{0.9em} +\] +similarly the forces parallel to $y$~and~$z$ are respectively +\begin{DPgather*} +\left. \begin{aligned} +ar &- cp,\\ +bp &- aq. \end{aligned} +\lintertext{\raiseboxlint[-0.5]{and}} +\right\} \Tag{11} +\end{DPgather*} + +When the medium is a conductor these are the ordinary +expressions for the components of the force per unit volume of +the conductor when it is carrying a current in a magnetic +field. + +When, as in the above investigation, we regard the force on a +conductor carrying a current as due to the communication to +the conductor of the momentum of the Faraday tubes which enter +the conductor, the origin of the force between two currents will +be very much the same as that of the attraction between two +\index{Sage, Le, theory of gravitation}% +bodies on Le~Sage's theory of gravitation. Thus, for example, if +we have two parallel currents $A$~and~$B$ flowing in the same +direction, then if $A$~is to the left of~$B$ more tubes will enter~$A$ from +the left than from the right, because some of those which would +have come from the right if $B$~had been absent will be absorbed +by~$B$, thus in unit time the momentum having the direction +left to right which enters~$A$ will exceed that having the opposite +direction; thus $A$~will tend to move towards the right, that +is towards~$B$, while for a similar reason $B$~will tend to move +towards~$A$. + +\Article{15} We have thus seen that the hypothesis of Faraday tubes +in motion explains the properties and leads to the ordinary +equations of the electromagnetic field. This hypothesis has the +advantage of indicating very clearly why polarization and conduction +%% -----File: 030.png---Folio 16------- +currents produce similar mechanical and magnetic effects. +For the mechanical effects and the magnetic forces at any +point in the field are due to the motion of the Faraday tubes at +that point, and any alteration in the polarization involves motion +of these tubes just as much as does an ordinary conduction +current. + +\Article{16} We shall now proceed to illustrate this method of regarding +\index{Electrified sphere@\subdashone sphere, moving}% +electrical phenomena by applying it to the consideration +of some simple cases. We shall begin with the case which +suggested the method; that of a charged sphere moving uniformly +through the dielectric. Let us suppose the charge on +the sphere is~$e$ and that it is moving with velocity~$w$ parallel +to the axis of~$z$. Faraday tubes start from the sphere and are +carried along with it as it moves through the dielectric; since +these tubes are moving they will, as we have seen, produce a +magnetic field. We shall suppose that the system has settled +down into a steady state, so that the sphere and its tubes are +all moving with the same velocity~$w$. Let $f$,~$g$,~$h$ be the components +of the polarization at any point, $\alpha$,~$\beta$,~$\gamma$ those of the +magnetic force. The expressions for $X$,~$Y$,~$Z$, the components +of the electromotive intensity, will consist of two parts, one due +to the motion of the Faraday tubes and given by equations~(\eqnref{11}{6}), +the other due to the distribution of these tubes and derivable +from a potential~$\Psi$; we thus have, if the magnetic permeability +is unity, +\[ +\left.\begin{aligned} +X & = \phantom{-}w\beta - \frac{d\Psi}{dx}, \\ +Y & = -w\alpha - \frac{d\Psi}{dy}, \\ +Z & = -\frac{d\Psi}{dz}. +\end{aligned} \right\} \Tag{12} +\] +By equations~(\eqnref{9}{4}) +\begin{align*} +\alpha & = -4\pi gw, \\ +\beta & = \phantom{-}4\pi fw, \\ +\gamma & = \phantom{-}0. +\end{align*} + +If $K$ is the specific inductive capacity of the medium, we have +\[ +X = \frac{4\pi}{K} f, \quad Y = \frac{4\pi}{K} g, \quad Z = \frac{4\pi}{K} h. +\] +%% -----File: 031.png---Folio 17------- + +Since the magnetic permeability of the dielectric is taken as +unity, we may put $1/K = V^2$, where $V$~is the velocity of light +through the dielectric. + +{\allowdisplaybreaks +Making these substitutions for the magnetic force and the +electromotive intensity, equations~(\eqnref{16}{12}) become +\begin{DPgather*} +\begin{aligned} +&4\pi f(V^2 - w^2) = - \frac{d\Psi}{dx},\\ +&4\pi g(V^2 - w^2) = - \frac{d\Psi}{dy},\\ +&4\pi h\PadTo[l]{(V^2 - w^2)}{V^2} = - \frac{d\Psi}{dz}; +\end{aligned} \\ +\lintertext{and since} \frac{df}{dx} + \frac{dg}{dy} + \frac{dh}{dz} = 0,\\ +\lintertext{we get} +\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{V^2 - w^2}{V^2}\, \frac{d^2\Psi}{dz^2} = 0, \Tag{13}\\ +\lintertext{or putting} z' = \frac{V}{\left\{V^2 - w^2\right\} ^{\frac{1}{2}}} z, +\end{DPgather*} +equation~(\eqnref{16}{13}) becomes +\[ +\frac{d^2\Psi}{dx^2} + \frac{d^2\Psi}{dy^2} + \frac{d^2\Psi}{dz'^2} = 0, +\] +a solution of which is +\begin{align*} +\Psi &= \frac{A}{\left\{x^2+y^2+z'^2 \right\}^{\frac{1}{2}}} \\ +&= \frac{A}{\left\{{x^2+y^2+\dfrac{V^2}{V^2-w^2}z^2}\right\}^{\frac{1}{2}}}.\Tag{14} +\end{align*} +} + +To find $A$ we notice that the normal polarization over any +sphere concentric with the moving one must equal~$e$, the +charge on the sphere; hence if $a$~is the radius of the moving +sphere, +\[ +\iint \left\{\frac{x}{a} f + \frac{y}{a} g + \frac{z}{a} h \right\} dS = e. +\] +%% -----File: 032.png---Folio 18------- + +Substituting for $f$,~$g$,~$h$ their values, we find +\begin{DPalign*} +\frac{Aa}{4\pi (V^2 - w^2)} \iint \frac{dS}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2 \right\}^{\frac{3}{2}}} & = e, \\ +\lintertext{\rlap{\indent\indent or}} \frac{A}{2(V^2 - w^2)} \int_{0}^{\pi} \frac{\sin \theta\,d\theta}{\left\{\sin^2 \theta + \dfrac{V^2}{V^2 - w^2} \cos^2\theta\right\}^{\frac{3}{2}}} & = e. +\end{DPalign*} + +{\allowdisplaybreaks +The integral, if $V > w$, is equal to +\begin{DPgather*} +\frac{2 \{V^2 - w^2\}^{\frac{1}{2}}} {V}; \\ +\lintertext{\rlap{\indent\indent hence}} A = eV\{V^2 - w^2\}^{\frac{1}{2}}, \\ +\lintertext{\raiseboxlint[3.5]{so that}} \left.\begin{aligned} +f & = \frac{e}{4\pi}\, \frac{V}{\{V^2 - w^2\}^{\frac{1}{2}}}\, \frac{x}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2\right\}^{\frac{3}{2}}}, \\ +g & = \frac{e}{4\pi}\, \frac{V}{\{V^2 - w^2\}^{\frac{1}{2}}}\, \frac{y}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2\right\}^{\frac{3}{2}}}, \\ +h & = \frac{e}{4\pi}\, \frac{V}{\{V^2 - w^2\}^{\frac{1}{2}}}\, \frac{z}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2\right\}^{\frac{3}{2}}}. +\end{aligned}\right\}\Tag{15} \\ +\lintertext{\indent Thus} \frac{f}{x} = \frac{g}{y} = \frac{h}{z}. +\end{DPgather*} +} + +The Faraday tubes are radial and the resultant polarization +varies inversely as +\[ +r^2 \left\{1 + \frac{w^2}{V^2 - w^2} \cos^2\theta\right\}^{\frac{3}{2}}, +\] +where $r$ is the distance of the point from the centre, and $\theta$~the +angle which $r$~makes with the direction of motion of the sphere. +We see from this result that the polarization is greatest where~$\theta = \pi / 2$, +least where~$\theta = 0$; the Faraday tubes thus leave the +poles of the sphere and tend to congregate at the equator. This +arises from the tendency of these tubes to set themselves at right +angles to the direction in which they are moving. The surface +density of the electricity on the moving sphere varies inversely +as +\[ +\left\{1 + \frac{w^2}{V^2 - w^2} \cos^2 \theta\right\}^{\frac{3}{2}}, +\] +%% -----File: 033.png---Folio 19------- +it is thus a maximum at the equator and a minimum at the +poles. + +The components $\alpha$,~$\beta$,~$\gamma$ of the magnetic force are given by +the equations +\[ +\left.\begin{aligned} +\alpha &= -4\pi wg = - \frac{eVw}{\{V^2 - w^2\}^{\frac{1}{2}}}\, \frac{y}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2\right\}^{\frac{3}{2}}}, \\ +\beta &= \phantom{-}4\pi wf = \frac{eVw}{\{V^2 - w^2\}^{\frac{1}{2}}}\, \frac{x}{\left\{x^2 + y^2 + \dfrac{V^2}{V^2 - w^2} z^2\right\}^{\frac{3}{2}}}, \\ +\gamma &= 0. +\end{aligned} \right\} \Tag{16} +\] + +These expressions as well as~(\eqnref{16}{15}) were obtained by Mr.\ +Heaviside by another method in the \textit{Phil.\ Mag.}\ for April, +1889. + +Thus the lines of magnetic force are circles with their centres +in and their planes at right angles to the axis of~$z$. When $w$~is +so small that $w^2 / V^2$ may be neglected, the preceding equations +take the simpler forms +\begin{gather*} +f = \frac{e}{4\pi} \frac{x}{r^3}, \quad g = \frac{e}{4\pi} \frac{y}{r^3}, \quad h = \frac{e}{4\pi} \frac{z}{r^3}, \\ +\alpha = -\frac{ewy}{r^3}, \quad \beta = \frac{ewx}{r^3}. +\end{gather*} + +(See J.~J. Thomson `On the Electric and Magnetic Effects +produced by the Motion of Electrified Bodies', \textit{Phil.\ Mag.}\ +April, 1881.) + +\index{Electrified sphere, moving@\subdashtwo moving, magnetic force due to}% +\index{Heaviside, moving electrified sphere}% +\index{Magnetic xfield due to a moving charged sphere@\subdashone field due to a moving charged sphere}% +\index{Sphere, charged moving, magnetic force due to}% +The moving sphere thus produces the same magnetic field as an +element of current at the centre of the sphere parallel to~$z$ whose +moment is equal to~$ew$. When as a limiting case~$V = w$, that is +when the sphere is moving with the velocity of light, we see +from equations (\eqnref{16}{15})~and~(\eqnref{16}{16}) that the polarization and magnetic +force vanish except when $z = 0$ when they are infinite. The +equatorial plane is thus the seat of infinite magnetic force and +polarization, while the rest of the field is absolutely devoid of +either. It ought to be noticed that in this case all the Faraday +tubes have arranged themselves so as to be at right angles to +the direction in which they are moving. + +We shall now consider the momentum in the dielectric due +to the motion of the Faraday tubes. Since the dielectric is +%% -----File: 034.png---Folio 20------- +\index{Electrified sphere, moving@\subdashtwo moving, momentum of}% +\index{Momentum of xa moving electrified sphere@\subdashtwo a moving electrified sphere}% +\index{Sphere, charged moving, momentum of@\subdashone charged moving, momentum of}% +non-magnetic the components $U$,~$V'$,~$W$ of this are by equations~(\eqnref{13}{9}) +given by the following expressions: +\[ +\left.\begin{aligned} +U = \PadTo[l]{-\beta f - \alpha g}{-\beta h} + & = - \frac{e^{2}}{4\pi}\, \frac{V^{2}w}{V^{2} - w^{2}}\, \frac{xz}{\left(x^{2} + y^{2} + \frac{V^{2}}{V^{2} - w^{2}} z^{2}\right)^{3}}, \\ +V' = \PadTo[l]{-\beta f - \alpha g}{\phantom{-}\alpha h} + & = - \frac{e^2}{4\pi}\, \frac{V^2w}{V^2 - w^2}\, \frac{yz}{\left(x^2 + y^2 + \frac{V^2}{V^2 - w^2} z^2\right)^3}, \\ +W = \PadTo[l]{-\beta f - \alpha g}{\phantom{-}\beta f - \alpha g} + & = \phantom{-}\frac{e^2}{4\pi}\, \frac{V^2w}{V^2 - w^2}\, \frac{(x^2 + y^2)}{\left(x^2 + y^2 + \frac{V^2}{V^2 - w^2} z^2\right)^3}. +\end{aligned} \right\} \Tag{17} +\] + +The resultant momentum at any point is thus at right angles +to the radius and to the magnetic force; it is therefore in the +plane through the radius and the direction of motion and at +right angles to the former. The magnitude of the resultant +momentum per unit volume at a point at a distance~$r$ from +the centre of the sphere, and where the radius makes an angle~$\theta$ +with the direction of motion, is +\[ +\frac{e^{2}w}{4\pi} · \frac{V^{2}}{V^{2} - w^{2}}\, \frac{1}{r^{4}}\, \frac{\sin \theta}{\left\{1 + \frac{w^{2}}{V^{2} - w^{2}} \cos^{2} \theta \right\}^{3}}. +\] + +Thus the momentum vanishes along the line of motion of +the sphere, where the Faraday tubes are moving parallel to +themselves, and continually increases towards the equator as the +tubes get to point more and more at right angles to their +direction of motion. + +The resultant momentum in the whole of the dielectric is +evidently parallel to the direction of motion; its magnitude~$I$ +is given by the equation +\begin{align*} +I &= \frac{e^{2}w}{4\pi}\, \frac{V^{2}}{V^{2} - w^{2}} \int_{a}^{\infty} \int_{0}^{\pi} \int_{0}^{2\pi} \frac{\sin^{2} \theta r^{2}\, dr \sin \theta\, d\theta\, d\phi}{r^{4}\left\{1 + \dfrac{w^{2}}{V^{2} - w^{2}} \cos^{2} \theta \right\}^{3}} \\ +&= \frac{e^{2}w}{a}\, \frac{V^2}{V^2 - w^2} \int_0^{1} \frac{\sin^2 \theta\, d(\cos \theta)}{\left\{1 + \dfrac{w^2}{V^2 - w^2} \cos^2 \theta \right\}^3}, +\end{align*} +\begin{DPgather*} +\lintertext{\rlap{or putting}} \frac{w}{\{V^2 - w^2\}^{\frac{1}{2}}} \cos \theta = \tan \psi,\\ +%% -----File: 035.png---Folio 21------- +\intertext{we see that} +I = \frac{e^2 V^2}{a\{V^2 - w^2\}^{\frac{1}{2}}} \int_0^{\tan^{-1} \frac{w}{\{V^2 - w^2\}^{\frac{1}{2}}}} \cos^2 \psi \left(1 - \frac{V^2}{w^2} \sin^2 \psi\right) d\psi; \\ +\lintertext{\rlap{or if}} \tan^{-1} \frac{w}{\{V^2 - w^2\}^{\frac{1}{2}}} = \vartheta, \\ +I = \frac{e^2}{2a}\, \frac{V^2}{\{V^2 - w^2\}^{\frac{1}{2}}} \left\{\vartheta \left(1 - \tfrac{1}{4}\, \frac{V^2}{w^2}\right) + \tfrac{1}{2} \sin 2 \vartheta \left(1 + \tfrac{1}{4}\, \frac{V^2}{w^2} \cos 2 \vartheta\right)\right\}. +\end{DPgather*} + +Thus the momentum of the sphere and dielectric parallel to~$z$ +is~$mw + I$, where $m$~is the mass of the sphere; so that the effect +of the charge will be to increase the apparent mass of the sphere +by~$I/w$ or by +\[ +\tfrac{1}{2}\, \frac{e^2}{a}\, \frac{V^2}{w\{V^2 - w^2\}^{\frac{1}{2}}} +\left\{\vartheta \left(1 - \tfrac{1}{4}\, \frac{V^2}{w^2}\right) + +\tfrac{1}{2} \sin 2 \vartheta \left(1 + \tfrac{1}{4}\, \frac{V^2}{w^2} \cos 2 \vartheta\right) \right\}. +\] + +When the velocity of the sphere is very small compared to +that of light, +\[ +\vartheta = \frac{w}{V} \left(1 + \tfrac{1}{6}\, \frac{w^2}{V^2}\right) +\] +approximately, and the apparent increase in the mass of the +sphere is +\[ +\frac{2}{3}\, \frac{e^2}{a}. +\] + +When in the limit~$w = V$ the increase in mass is infinite, thus +a charged sphere moving with the velocity of light behaves as +if its mass were infinite, its velocity therefore will remain constant, +in other words it is impossible to increase the velocity +of a charged body moving through the dielectric beyond that +of light. + +\index{Electrified sphere, moving@\subdashtwo moving, kinetic energy}% +\index{Kinetic energy, due to moving charged sphere@\subdashtwo due to moving charged sphere}% +\index{Sphere, charged moving, xkinetic energy of@\subdashone charged moving, kinetic energy of}% +The kinetic energy per unit volume of the dielectric is +\[ +\frac{1}{8\pi} (\alpha^2 + \beta^2), +\] +and hence by equations (\eqnref{16}{16})~and~(\eqnref{16}{17}) it is equal to +\[ +\frac{w}{2}\, W; +\] +thus the total kinetic energy in the dielectric is equal to +\[ +\tfrac{1}{2} wI, +\] +%% -----File: 036.png---Folio 22------- +that is to +\[ +\frac{e^2}{4a} w · \frac{V^2}{\{V^2 - w^2\}^{\frac{1}{2}}} +\left\{\vartheta \left(1 - \tfrac{1}{4} \frac{V^2}{w^2}\right) + \tfrac{1}{2} \sin 2 \vartheta +\left(1 + \tfrac{1}{4}\, \frac{V^2}{w^2} \cos 2 \vartheta\right)\right\}. +\] + +\index{Electrified sphere, moving@\subdashtwo moving, force on in a magnetic field}% +\index{Mechanical force on xa moving charged sphere@\subdashtwo a moving charged sphere}% +\index{Sphere, charged moving, yforce acting on@\subdashone charged moving, force acting on}% +We shall now proceed to investigate the mechanical forces +acting on the sphere when it is moving parallel to the axis of~$z$ +in a uniform magnetic field in which the magnetic force is +everywhere parallel to the axis of~$x$ and equal to~$H$. + +If $U$,~$V'$,~$W$ are the components of the momentum, +\begin{align*} +U & = gc - hb, \\ +V' & = ha - fc, \\ +W & = fb - ga. +\end{align*} + +In this case +\[ +c = 0, \qquad b = \beta, \qquad a = \alpha + H, +\] +where $\alpha$~and~$\beta$ have the values given in equations~(\eqnref{16}{16}). + +The momentum transmitted in unit time across the surface of +a sphere concentric with the moving one has for components +\[ +\iint wU \cos \theta\,dS, \qquad \iint wV' \cos \theta\,dS, \qquad \iint wW \cos \theta\,dS, +\] +the integration being extended over the surface of the sphere. +Substituting the values of $U$,~$V'$,~$W$, we see that the first and +third of these expressions vanish, while the second reduces to +\begin{DPgather*} +\frac{e}{4\pi}\, \frac{VHw}{\{V^2 - w^2\}^{\frac{1}{2}}} \iint \frac{\cos^2 \theta\,dS}{r^2\left\{1 + \dfrac{w^2}{V^2 - w^2} \cos^2 \theta\right\}^{\frac{3}{2}}}, \\ +\lintertext{or} \tfrac{1}{2}\, \frac{eVHw}{\{V^2 - w^2\}^{\frac{1}{2}}} \int_0^\pi +\frac{\cos^2 \theta \sin \theta\,d\theta}{\left\{1 + \dfrac{w^2}{V^2 - w^2} \cos^2 \theta \right\}^{\frac{3}{2}}}, +\end{DPgather*} +which is equal to +\begin{DPgather*} +-\frac{eHwV}{\{V^2 - w^2\}^{\frac{1}{2}}} \left\{\frac{(V^2 - w^2)^{\frac{3}{2}}}{Vw^2} - \left(\dfrac{V^2 - w^2}{w^2}\right)^{\frac{3}{2}} +\log \left(\frac{V + w}{V - w}\right)^{\frac{1}{2}} \right\}, \\ +\lintertext{\rlap{or to}} -eH \frac{(V^2 - w^2)}{w} \left\{1 - \tfrac{1}{2} \frac{V}{w} \log \left(\frac{V + w}{V - w}\right)\right\}. +\end{DPgather*} + +When $w/V$ is very small this expression reduces to +\[ +\tfrac{1}{3} eHw. +\] +%% -----File: 037.png---Folio 23------- +This is the rate at which momentum is communicated to +the sphere, in other words it is the force on the sphere; hence +the force on the charged sphere coincides in direction with the +force on an element of current parallel to the axis of~$z$, but the +magnitude of the force on the moving sphere is only one-third +that of the force on an element of current along~$z$ whose moment +is~$ew$. By the moment of an element of current we mean the +product of the intensity of the current and the length of the +element. When~$w=V$, that is when the sphere moves through +the magnetic field with the velocity of light, we see from the +preceding expression that the force acting upon it vanishes. + +We can get a general idea of the origin of the mechanical +force on the moving sphere if we remember that the uniform +magnetic field is (\artref{13}{Art.~13}) due to the motion of Faraday tubes, the +positive tubes moving in one direction, the negative ones in the +opposite, and that in their motion through the field these tubes +have to traverse the sphere. The momentum due to these tubes +when they enter the sphere is proportional to the magnetic +force at the place where they enter the sphere, while their +momentum when they leave the sphere is proportional to the +magnetic force at the place of departure. Now the magnetic +forces at these places will be different, because on one side of +the sphere the magnetic force arising from its own motion will +increase the original magnetic field, while on the other side it +will diminish it. Thus by their passage across the sphere the +tubes will have gained or lost a certain amount of momentum; +this will have been taken from or given to the sphere, which +will thus be subject to a mechanical force. + +\Subsection{Rotating Electrified Plates.} +\index{Rotating electrified plates}% +\index{Electrified plates, rotating|(}% +\index{Himstedt, rotating disc}% +\index{Hutchinson and Rowland, rotating electrified disc}% +\index{Magnetic xfield due to rotating electrified plates@\subdashtwo due to rotating electrified plates}% +\index{Plates, rotating electrified|(}% +\index{Rontgen@Röntgen, rotating disc}% +\index{Rowland, rotating disc}% +\index{Rowlandx@Rowland and Hutchinson, rotating disc|(}% + +\sloppy +\Article{17} The magnetic effects due to electrified bodies in motion +are more conveniently examined experimentally by means of +electrified rotating plates than by moving electrified spheres. The +latter have, as far as I know, not been used in any experiments +on electro-convection, while most interesting experiments with +rotating plates have been made by Rowland (\textit{Berichte d.~Berl.\ Acad.}\ +1876, p.~211), Rowland and Hutchinson (\textit{Phil.\ Mag.}~27, p.~445, +1889), Röntgen (\textit{Wied.\ Ann.}~35, p.~264, 1888; 40,~p.~93, 1890), +Himstedt (\textit{Wied.\ Ann.}~38, p.~560, 1889). The general plan of +%% -----File: 038.png---Folio 24------- +these experiments is as follows: an air condenser with circular +parallel plates is made to rotate about an axis through the +centres of the plates and at right angles to their planes. To +prevent induced currents being produced by the rotation of the +plates in the earth's magnetic field, radial divisions filled with +insulating material are made in the plates. When the plates +are charged and set in rotation a magnetic field is found to +exist in their neighbourhood similar to that which would be +produced by electric currents flowing in concentric circular +paths in the plates of the condenser, the centres of these circles +being the points where the axis of rotation cuts the plates. + +\fussy +Let us now consider how these magnetic forces are produced. +Faraday tubes at right angles to the plates pass from one +plate to the other. We shall suppose when the condenser is +rotating as a rigid body these tubes move as if they were +rigidly connected with it. Then, taking the axis of rotation as +the axis of~$z$, the component velocities of a tube at a point whose +coordinates are $x$,~$y$ are respectively $-\omega y$~and~$\omega x$, where $\omega$~is +the angular velocity with which the plates are rotating. + +If these were the only Faraday tubes in motion the components +$\alpha$,~$\beta$,~$\gamma$ of the magnetic force would by equations~(\eqnref{9}{4}) be +given by the equations +\begin{align*} +\alpha &= 4\pi\sigma\omega x,\\ +\beta &= 4\pi\sigma\omega y, \Tag{18} \\ +\gamma &= 0, +\end{align*} +where $\sigma$ ($=h$) is the surface-density of the electricity on either +plate. These values for the components of the magnetic force +do not however satisfy the relation +\[ +\frac{d \alpha}{dx} + \frac{d \beta}{dy} + \frac{d \gamma}{dz} = 0, +\] +which must be satisfied since the value of +\[ +\frac{1}{8\pi} \iiint (\alpha^2+\beta^2+\gamma^2)\,dx\,dy\,dz +\] +must, in a medium whose magnetic permeability is unity, be +stationary for all values of $\alpha$,~$\beta$,~$\gamma$ which give assigned values to +the currents, that is to +\[ +\frac{d \beta}{dx} - \frac{d\alpha}{dy}, \qquad \frac{d \alpha}{dz} - \frac{d\gamma}{dx}, \qquad \frac{d \gamma}{dy} - \frac{d\beta}{dz}. +\] +%% -----File: 039.png---Folio 25------- + +For let $\alpha_0$,~$\beta_0$,~$\gamma_0$ be any particular values of the components of +the magnetic force which satisfy the assigned conditions, then +the most general values of these components are expressed by +the equations +\begin{align*} +\alpha & = \alpha_0 + \dfrac{d\phi}{dx}, \\ +\beta & = \beta_0 + \dfrac{d\phi}{dy}, \\ +\gamma & = \gamma_0 + \dfrac{d\phi}{dz}, +\end{align*} +where $\phi$~is an arbitrary function of $x$,~$y$,~$z$. + +Then if +\[ +\tiiint (\alpha^2 + \beta^2 + \gamma^2)\,dx\,dy\,dz +\] +is stationary, +\[ +\tiiint (\alpha\, \delta \alpha + \beta\, \delta \beta + \gamma\, \delta \gamma)\,dx\, dy\, dz = 0. \Tag{19} +\] +Let the variations in $\alpha$,~$\beta$,~$\gamma$ be due to the increment of~$\phi$ by +an arbitrary function~$\delta \phi$, then +\[ +\delta \alpha = \frac{d\,\delta \phi}{dx}, \qquad \delta \beta = \frac{d\,\delta \phi}{dy}, \qquad \delta \gamma = \frac{d\,\delta \phi}{dz}. +\] + +Substituting these values for $\delta \alpha$,~$\delta \beta$,~$\delta \gamma$, and integrating by +parts, equation~(\eqnref{17}{19}) becomes +\begin{multline*} +\iint \delta \phi(\alpha\,dy\,dz + \beta\,dz\,dx + \gamma\,dx\,dy) \\ +- \iiint \delta \phi \left\{\frac{d \alpha}{dx} + \frac{d \beta}{dy} + \frac{d \gamma}{dz} \right\} dx\,dy\,dz = 0, +\end{multline*} +and therefore since~$\delta \phi$ is arbitrary +\[ +\frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} = 0. +\] + +The values of $\alpha$,~$\beta$,~$\gamma$ given by equation~(\eqnref{17}{18}) cannot therefore be +the complete expressions for the magnetic force, and since we +regard all magnetic force as due to the motion of Faraday tubes, +it follows that the tubes which connect the positive to the negative +charges on the plates of the condenser cannot be the only +tubes in the field which are in motion; the motion of these +tubes must set in motion the closed tubes which, \artref{2}{Art.~2}, exist +in their neighbourhood. The motion of the closed tubes will +produce a magnetic field in which the forces can be derived from +%% -----File: 040.png---Folio 26------- +a magnetic potential~$\Omega$. When we include the magnetic field +due to the motion of these closed tubes, we have +\begin{align*} +\alpha &= 4\pi \sigma \omega x - \frac{d\Omega}{dx} = \frac{d\Omega'}{dx}, \\ +\beta &= 4\pi \sigma \omega y - \frac{d\Omega}{dy} = \frac{d\Omega'}{dy}, \\ +\gamma &= \phantom{4\pi \sigma \omega y} -\frac{d\Omega}{dz} = \frac{d\Omega'}{dz}, +\end{align*} +if $\Omega' = 2\pi \sigma \omega (x^2 + y^2) - \Omega$; +\begin{DPalign*} +\lintertext{and since} \frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} = 0,& \\ +\lintertext{we have} \frac{d^2 \Omega'}{dx^2} + \frac{d^2 \Omega'}{dy^2} + \frac{d^2 \Omega'}{dz^2} = 0.& +\end{DPalign*} + +The question now arises, does the motion of the tubes which +connect the positive and negative electrifications on the plates +only set those closed tubes in motion which are between the +plates of the condenser, or does it affect the tubes outside as +well? Let us examine the consequences of the first hypothesis. +In this case, since the Faraday tubes outside the condenser are +at rest, the magnetic force will vanish except between the +plates of the condenser; it follows, however, from the properties +of the magnetic potential that it must vanish inside as well, so that +no magnetic force at all would be produced by the rotation of the +plates. As this is contrary to the result of Rowland's experiments, +the Faraday tubes stretching between the plates must by +their rotation set in motion tubes extending far away from the +region between the plates. The motion of these closed tubes +must however be consistent with the condition that the magnetic +force parallel to the plates due to the motion of the tubes must +be continuous. Let us consider for a moment the radial magnetic +force due to the closed tubes: this may arise either from the rotation +round the axis of tubes which pass through the plates, or +from the motion at right angles to the plates of tubes parallel to +them. In the first case, the velocity tangential to the plates of +the tubes must be continuous, otherwise the tubes would break, +and since the tangential velocity is continuous, the radial magnetic +force due to the motion of these tubes will be continuous also. In +the second case, the product of the normal velocity of the tubes +%% -----File: 041.png---Folio 27------- +and their number per unit volume must be the same on the two +sides of a plate, otherwise there would be an accumulation of +these tubes in the plate. The product of the normal velocity +into the number of the tubes is, however, equal to the tangential +magnetic force due to the motion of the closed tubes, so that +this must be continuous. + +The open tubes which stretch from the positive electricity on +one plate to the negative on the other will, however, by their +motion produce a discontinuity in the radial magnetic force, +since these tubes stop at the plates, and do not pass through +them. The radial magnetic force at a point due to these tubes +is~$4\pi\sigma\omega r$, where $r$~is the distance of the point from the axis of rotation. +The conditions to determine the magnetic field are thus, +(1)~that except in the substance of the plates there must be a +magnetic potential satisfying Laplace's equation, and (2)~that +at either plate the discontinuity in the radial magnetic force +must be~$4\pi\sigma\omega r$, where $\sigma$~is the surface-density of the electricity +on the plates. These conditions are, however, exactly those which +determine the magnetic force produced by a system of electric +currents circulating in circles in the plates of the condenser, the +intensity of the currents at a distance~$r$ from the axis of rotation +being $\sigma\omega r$ for the positive and $-\sigma\omega r$ for the negative plate. +Hence the magnetic force due to rotating the plates will be the +same as that produced by this distribution of electric currents. + +This conclusion seems to be confirmed by the results of the +experiments of Rowland and Hutchinson (\textit{Phil.\ Mag.}~27, p.~445, +1889), as using this hypothesis they found a tolerably accurate +value of~`$v$', the ratio of the electromagnetic to the +electrostatic unit of electricity, by means of experiments on a +rotating plate. + +We can see by similar reasoning that if only one of the plates +is rotating, the other being at rest, the magnetic effect will be +the same as that due to a system of electric currents circulating +in the rotating plate, the intensity of the current at a distance~$r$ +from the axis being~$\sigma\omega r$. + +Some interesting experiments have been made by Röntgen +\index{Hutchinson and Rowland, rotating electrified disc}% +\index{Rontgen@Röntgen, rotating disc}% +(\index{Magnetic xfield due to rotating electrified plates@\subdashtwo due to rotating electrified plates}% +\textit{Wied.\ Ann.}\ 35, p.~264, 1888), in which, while the plates of the +condenser were at rest, a glass disc parallel to the plates and +situated between them was set in rapid rotation and was found +to produce a magnetic field. The rotation of the disc must thus +\index{Rowlandx@Rowland and Hutchinson, rotating disc|)}% +%% -----File: 042.png---Folio 28------- +have set in motion the Faraday tubes passing through it, and +these in turn have affected closed tubes extending into the region +beyond the condenser. + +Experiments of this kind seem to open up a field of enquiry +which will throw light upon a question which at present is one +of the most obscure in electricity: that of the relation between +the velocities of the dielectric and of the Faraday tubes passing +through it. This question is one of great importance in the +Electro-magnetic Theory of Light, as but little progress can be +\index{Aberration@\textsc{Aberration}}% +made in the Theory of Aberration until we have got an answer +to it. Another question which we have not touched upon, but +which is very important in this connexion, is whether the +motion of the Faraday tubes through ether devoid of matter +would produce magnetic force, or whether for this purpose it +is necessary that the tubes should pass across ordinary matter +as well as ether. The point may be illustrated by the following +case. Suppose we have a plate of glass between two parallel +charged plates rigidly electrified, whether uniformly or otherwise, +and that the whole system is set in rotation and moves like +a rigid body, then, is or is not the motion of the system +accompanied by magnetic force? Here the Faraday tubes move +through the ether (assuming that the velocity of the ether is not +the same as that of the glass), but do not move relatively to the +glass. + +The motion of the tubes through the \emph{dielectric} will be requisite +for the production of magnetic effects if we suppose that +there are no closed tubes in the electric field, and that all the +tubes connect portions of ordinary matter. The recognition of +closed tubes in the ether seems to be desirable in the present +state of our electrical knowledge, as unless we acknowledge the +existence of such tubes we have to suppose that light being an +electro-magnetic phenomenon cannot traverse a region wholly +devoid of ordinary matter, and further that the existence of +magnetic force depends upon the presence of such matter in the +field. +\index{Electrified plates, rotating|)}% +\index{Plates, rotating electrified|)}% + +\Subsection{A Steady Magnetic Field.} +\index{Faradayx tubes, disposition in a steady magnetic field@\subdashtwo disposition in a steady magnetic field}% +\index{Magnetic xfield, steady@\subdashtwo steady}% + +\Article{18} Magnetic force on the theory we are now discussing is due +to the motion of the Faraday tubes. When the magnetic field is +variable the presence of these tubes is rendered evident by the +%% -----File: 043.png---Folio 29------- +existence of electromotive intensities in the field: when however +the field is steady, we have no direct electrical evidence of the +presence of these tubes, and their disposition and velocities have +to be deduced from the equations developed in the preceding +pages. We shall now proceed to examine this very important +case more in detail. + +In a steady magnetic field in which there is no free electricity +the Faraday tubes must be closed, exception being made of +course of the short tubes which connect together the atoms in +the molecules present in the field. Since in such a field there +is no electromotive intensity, there must pass through each unit +area of the field the same number of positive as of negative tubes, +that is, there must be as many tubes pointing in one direction +as the opposite. These tubes will (\artref{12}{Art.~12}) place themselves +so as to be at right angles both to the direction in which they +are moving and to the magnetic force. The distribution of the +Faraday tubes and the directions in which they are moving +cannot be determined solely from the magnetic force; but for +the purpose of forming a clear conception of the way in +which the magnetic force may be produced, we shall suppose +that the positive tubes are moving with the velocity of light in +one direction, the negative tubes with an equal velocity in +the opposite, and that at any point the direction of a tube, +its velocity, and the magnetic force are mutually at right +angles. + +In a steady magnetic field surfaces of equal potential exist +which cut the lines of magnetic force at right angles, so that +since both the Faraday tubes and the directions in which they are +moving are at right angles to the lines of magnetic force we may +suppose that the Faraday tubes form closed curves on the equipotential +surfaces, a tube always remaining on one equipotential +surface and moving along it at right angles to itself. + +We shall now consider the motion of these tubes in a very +simple magnetic field: that surrounding an infinitely long circular +cylinder whose axis is taken as the axis of~$z$, and which is +uniformly magnetized at right angles to its axis and parallel to +the axis of~$x$. + +The magnetic potential inside the cylinder is equal to +\[ +Hx, +\] +where $H$ is the magnetic force inside the cylinder. +%% -----File: 044.png---Folio 30------- + +The potential outside the cylinder, if $a$~is the radius of the +cylinder, is equal to +\[ +H \frac{a^2\cos\theta}{r}, +\] +where $r$ is the distance from the axis of the cylinder of the point +at which the potential is reckoned, and $\theta$~the azimuth of~$r$ +measured from the direction of magnetization. Thus inside the +cylinder the equipotential surfaces are planes at right angles to the +direction of magnetization, while outside they are a system of circular +cylinders which if prolonged would pass through the axis of +the magnet; the axes of all these cylinders are parallel to the +axis of~$z$ and lie in the plane of~$xz$. The cross sections of the +original cylinder and the equipotential surfaces are represented +in \figureref{fig02}{Fig.~2}. + +\includegraphicsmid{fig02}{Fig.~2.} + +We shall suppose that the Faraday tubes are parallel to the +axis of the cylinder; then we may regard the magnetic field +as produced by such tubes travelling round the equipotential +%% -----File: 045.png---Folio 31------- +surfaces with uniform velocity, the positive tubes moving in one +direction, the negative ones in the opposite. We shall show +that the number of tubes passing through the area bounded +by unit length of the cross-section of any equipotential surface, +the normals and the consecutive equipotential surface will be +constant. For since the magnetic force is at right angles +both to the Faraday tubes and the direction in which they +are moving, the magnetic force due to this distribution of +Faraday tubes will be at right angles to the equipotential +surfaces; and if $N$~is the number of tubes of one sign between two +consecutive equipotential surfaces per unit length of cross section +of one of them, $ds$~the length of a portion of such a cross section, +$d\nu$~the normal distance between two consecutive \DPtypo{equi-potential}{equipotential} +surfaces $\Omega_1$~and~$\Omega_2$, then in the cylinder whose base is~$ds\,d\nu$ +the number of Faraday tubes of one sign will be $N\,ds(\Omega_2-\Omega_1)$; but +since these tubes are distributed over an area~$ds\,d\nu$, the number +of tubes per unit area of the base of the cylinder is $N(\Omega_2-\Omega_1)/d\nu$. +These tubes are however all moving at the same rate, so +that the magnetic force due to them will be proportional to +the number per unit area of the base of the cylinder, that is to +$N(\Omega_2-\Omega_1)/d\nu$, so that since the magnetic force due to these tubes +is proportional to $(\Omega_2-\Omega_1)/d\nu$, $N$~will be constant. Thus the +magnetic force due to the tubes moving in the way we have +described coincides both in magnitude and direction with that +due to the magnetized cylinder. + +We see from \figureref{fig02}{Fig.~2} that the directions of motion of these +tubes change abruptly as they enter the magnetized cylinder. +The principles by which the amount of this bending of the +direction of motion of the tubes may be calculated are as follows. +If $h_1$~and~$h_2$ are the densities of the tubes just inside and outside +the cylinder, $R_1$,~$R_2$ the corresponding velocities of these tubes +along the normal to the cylinder, then since there is no accumulation +of the tubes at the surface of the cylinder we must have +\[ +\tsum R_1h_1=\tsum R_2h_2. +\] +But since $R$ is the radial velocity, $\tsum 4\pi Rh$ is by~(\eqnref{13}{8}), \artref{13}{Art.~13}, the +tangential magnetic force: hence the preceding equation expresses +the continuity +of the tangential magnetic force as we cross the +surface of the cylinder. +\includegraphicsouter{fig03}{Fig.~3.} +Again, when a Faraday tube crosses the +surface of the cylinder, the tangential component of its momentum +will not change; but by equations~(\eqnref{13}{9}) the tangential momentum +%% -----File: 046.png---Folio 32------- +of the tube is proportional to the normal magnetic induction, so +that the continuity of the tangential momentum is equivalent to +that of the normal component of the magnetic induction. We +have thus deduced from this view of the magnetic field the +ordinary boundary conditions (1)~that the tangential component +of the magnetic force is continuous, and (2)~that the normal +component of the magnetic induction is continuous. + +The paths along which the tubes move coincide with the lines +of flow produced by moving the cylinder uniformly at right +angles to the direction of magnetization through an incompressible +fluid. + +\Subsection{Induction of Currents due to Changes in the Magnetic +Field.} +\index{Induction balance, of currents due to changes in the magnetic field@\subdashone of currents due to changes in the magnetic field}% +\index{Magnetic xfield, xinduction of current due to change of@\subdashtwo induction of current due to change of}% + +\Article{19} Let \figureref{fig03}{Fig.~3} represent a section of the magnetized cylinder +and one of its equipotential surfaces, the directions of the magnetic +force round the cylinder being denoted by the dotted lines. +We shall call those Faraday tubes which point upwards from +the plane of the paper positive, +the negative Faraday tubes of +course pointing downwards. +The positive and the negative +tubes circulate round the equipotential +surface in the directions +marked in the figure. Let +\smallsanscap{A}~and~\smallsanscap{B} represent the cross-sections +of the wires of a circuit, +the wires being at right +angles to the plane of the +paper. When the magnetic +field is steady no current will +be produced in this circuit, because +there are as many positive +as negative tubes at any point +in the field. Let us now suppose +that the magnetic field +is suddenly destroyed; we may imagine that this is done by +placing barriers across the equipotential surfaces in the magnetized +cylinder so as to stop the circulation of the Faraday +tubes. The inertia of these tubes will for a short time carry +%% -----File: 047.png---Folio 33------- +them on in the direction in which they were moving when +the barrier was interposed, hence the positive tubes will run +out on the right-hand side of the equipotential surfaces and +accumulate on the left-hand side, while the negative tubes +will leave the left-hand side and accumulate on the right. +The equality which formerly existed between the positive and +negative tubes will now be destroyed: there will be an excess +of positive tubes in the neighbourhood of the conductor~\smallsanscap{A}, +and an excess of negative ones round~\smallsanscap{B}. A current will +therefore be started in the circuit running from~\smallsanscap{A} to~\smallsanscap{B} +above the plane of the paper, and from~\smallsanscap{B} to~\smallsanscap{A} below it. We +see in this way how the inertia of the Faraday tubes accounts +for induced currents arising from variations in the +intensity of the magnetic field. + +\Subsection{Induction due to Motion of the Circuit.} +\index{Induction, of currents due to changes in the magnetic field, due to motion of the circuit@\subdashtwo due to motion of the circuit}% + +\Article{20} We can explain in a similar way the currents induced +when a conductor is moved about in a magnetic field. Suppose +we have a straight conductor moving about in the streams of +Faraday tubes which constitute such a field, the Faraday tubes +being parallel to each other and to the conductor: let the +conductor be moved in the opposite direction to that in which +the positive tubes are moving. This motion of the conductor +will tend to stop the positive tubes in it and just in front of it; +the inertia of the tubes further off will make them continue to +move towards the conductor, and thus the density of the tubes in +front (i.e.~those entering the conductor) will increase, while the +density of the tubes behind (i.e.~those leaving the conductor) +will diminish; the number of positive tubes in the conductor +will thus be greater than the number which would have been +present if the conductor had been at rest. Similar reasoning +will show that there will be a decrease in the number of negative +tubes in the conductor. Thus the positive tubes in the conductor +will now outnumber the negative ones, and there will therefore +be a positive current. The motion of the conductor in the +direction opposite to that in which the positive Faraday tubes +are moving will thus be accompanied by the production of a +positive current. This current is the ordinary induction current +due to the motion of a conductor in the magnetic field. +%% -----File: 048.png---Folio 34------- + +\Subsection{Effect of the Introduction of Soft Iron into a Magnetic Field.} +\index{Faradayx tubes, effect of soft iron on their motion@\subdashtwo effect of soft iron on their motion}% +\index{Iron, effect of, on motion of Faraday tubes}% + +\includegraphicsouter{fig04}{Fig.~4.} + +\Article{21} Another simple magnetic system which we shall briefly +consider is that of an infinite cylinder of soft iron, whose axis is +taken as that of~$z$, placed in what was before its introduction a +uniform magnetic field parallel to the axis of~$x$. Before the +cylinder was introduced into the field, the Faraday tubes, which +we may suppose to be parallel to the axis of~$z$, would all be +moving parallel to the axis of~$y$; as soon however as the +cylinder is placed in the field, the tubes will turn so as to avoid +as much as possible going through it, for since the tangential +momentum is not altered the tangential velocity of the tubes +must be smaller inside the cylinder than it is outside, as +the effective inertia of a tube in a magnetic medium is greater +than in a non-magnetic one +(see \artref{10}{Art.~10}). The lines of flow +of the Faraday tubes will +thus be deflected by the cylinder +in much the same way +as a current of electricity +flowing through a conducting +field would be deflected +by the introduction into +the field of a cylinder made +of a worse conductor than +itself. The Faraday tubes +bend away from the cylinder +in the way shown in +\figureref{fig04}{Figure~4}. The paths of +the Faraday tubes coincide +however with equipotential +surfaces; these surfaces +therefore bend away from +the cylinder, and the lines of magnetic force which are at +right angles to the equipotential surface turn in consequence +towards the cylinder as indicated in \figureref{fig04}{Fig.~4}, in which the dotted +lines represent lines of magnetic force. +%% -----File: 049.png---Folio 35------- + +\includegraphicsmid{fig05}{Fig.~5.} + +\Subsection{Permanent Magnets.} +\index{Magnet, permanent}% +\index{Permanent magnet}% + +\Article{22} In the interior of the magnet as well as in the surrounding +magnetic field there is a shearing of the positive tubes past the +negative ones. The magnet as it moves about carries this +system of moving tubes with it, so that the motion of the +tubes must in some way be maintained by a mechanism connected +with the magnet: this mechanism exerts a fan-like action, driving +the positive tubes in one direction, the negative ones in the +opposite. This effect would be produced if the molecules of the +magnet had the constitution described below and were in rapid +rotation about the lines of magnetic force. Let the molecule~\smallsanscap{ABC} +of a magnet consist of three atoms \smallsanscap{A},~\smallsanscap{B},~\smallsanscap{C}, \figureref{fig05}{Fig.~5}. Let +one short tube go from~\smallsanscap{B} and end on~\smallsanscap{A}, another start from~\smallsanscap{B} +and end on~\smallsanscap{C}, then if the molecule rotates in the direction of the +arrow, about an axis through~\smallsanscap{B} perpendicular to the plane of the +paper, since two like parallel Faraday tubes repel each other the +rotation of the molecule will set the Faraday tubes in the ether +surrounding the molecule in motion, the tubes going from left +to right will move upwards in the plane of the paper, while +those from right to left move downwards. This will produce +a magnetic field in which, since the magnetic force is at right +angles both to the moving tubes and the direction of motion, it +will be at right angles to the plane of the paper and upwards; +thus the magnetic force is parallel to the axis of rotation of the +molecule. We notice that the atoms in the molecule are of +different kinds with respect to the number of tubes incident +upon them; thus \smallsanscap{B}~is the seat of two tubes, \smallsanscap{A}~and~\smallsanscap{C} of one +each; in chemical language this would be expressed by saying +that the valency of the atom~\smallsanscap{B} is twice that of either \smallsanscap{A}~or~\smallsanscap{C}. + + +This illustration is only intended to call attention to the +necessity for some mechanism to be connected with a permanent +%% -----File: 050.png---Folio 36------- +magnet to maintain the motion of the Faraday tubes in the field, +and to point out that the motion of molecular tubes is able to +furnish such a mechanism. + +\Subsection{Steady Current flowing along a Straight Wire.} +\index{Current, motion of Faraday tubes in neighbourhood of steady@\subdashone motion of Faraday tubes in neighbourhood of steady}% +\index{Faradayx tubes, round a wire carrying a steady current@\subdashtwo round a wire carrying a steady current}% + +\Article{23} We shall now proceed to express in terms of the Faraday +tubes the phenomena produced by a steady current flowing along +an infinitely long straight vertical wire. We shall suppose that +the circumstances are such that there is no free electricity on +the surface of the wire, so that the Faraday tubes in its neighbourhood +are parallel to its length. If we take the direction of +the current as the positive direction, the positive tubes parallel +to the wire will be moving in radially to keep up the current, +and this inward radial flow of positive tubes will be accompanied +by an outward radial flow of negative tubes, a positive tube +when entering the wire displacing a negative tube which moves +outward from the wire. This shearing of the positive and +negative tubes past each other will give rise to a magnetic force +which will be at right angles both to the direction of the tubes and +the direction in which they are moving; thus the magnetic force is +tangential to a circle whose plane is horizontal and whose centre +is on the axis of the wire. When the positive tubes enter the +wire they shrink to molecular dimensions in the manner to be +described in \artref{31}{Art.~31}. At a distance~$r$ from the axis of the +wire let $N$~be the number of positive tubes passing through unit +area of a plane at right angles to the wire, $v$~the velocity of +these tubes inwards, let $N'$~be the number of negative tubes per +unit area at the same point, $v'$~their velocity outwards. The +algebraical sum of the number of tubes which cross the circle +whose radius is~$r$ and whose centre is on the axis of the wire is +thus +\[ +(vN + v'N')\, 2\pi r. +\] + +When the field is steady the value of this expression must be +the same at all distances from the wire, because as many tubes +must flow into any region as flow out of it. Hence when the +field is steady this expression must equal the algebraical sum of +the number of positive tubes which enter the wire in unit time; +this number is however equal to~$i$, the current through the wire; +hence we have +\[ +(vN + v'N')\, 2\pi r = i. +\] +%% -----File: 051.png---Folio 37------- +\index{Steady current, motion of Faraday tubes in neighbourhood of}% +But by equations~(\eqnref{9}{4}) +\[ +vN + v'N' = \frac{\gamma }{4\pi}, +\] +where $\gamma$ is the magnetic force at a distance~$r$ from the axis. Substituting +this value for~$vN + v'N'$, we get +\[ +\gamma = \frac{2i}{r}, +\] +the usual expression for the magnetic force outside the wire +produced by a straight current. + +When the field is steady, there will be as many positive as +negative tubes in each unit area, and therefore no electromotive +intensity; if however the intensity of the current changes, this will +no longer hold. To take an extreme case, let us suppose that the +circuit is suddenly broken, then the inertia of the positive tubes +will make them continue to move inwards; and since as the +circuit is broken they can no longer shrink to molecular dimensions +when they enter it, the positive tubes will accumulate in +the region surrounding the wire: the inertia of the negative tubes +carries them out of this region, so that now there will be a preponderance +of positive tubes in the field around the wire. If any +conductor is in this field these positive tubes will give rise to a +positive current, which is the `direct' induced current which +occurs on breaking the circuit. When the field was steady +no current would be produced in this secondary circuit, because +there were as many positive as negative tubes in its +neighbourhood. + +\index{Current, force between two parallel currents@\subdashone force between two parallel currents}% +\index{Force between two parallel currents@\subdashone between two parallel currents}% +The Faraday tubes have momentum which they give up when +they enter the wire. If we consider a single wire where everything +is symmetrical, the wire is bombarded by these tubes on all sides, +so that there is no tendency to make it move off in any definite +direction. Let us suppose, however, that we have \emph{two} parallel +wires conveying currents in the same direction, let \smallsanscap{A}~and~\smallsanscap{B} +denote the cross-sections of these wires, \smallsanscap{B}~being to the right of~\smallsanscap{A}. +Then some of the tubes which if \smallsanscap{B}~were absent would pass +into~\smallsanscap{A} from the region on the right, will when \smallsanscap{B}~is present be +absorbed by it, and so prevented from entering~\smallsanscap{A}. The supply of +positive tubes to~\smallsanscap{A} will thus no longer be symmetrical; more +will now come into~\smallsanscap{A} from the region on its left than from that +on its right; hence since each of the tubes has momentum, more +%% -----File: 052.png---Folio 38------- +momentum will come to~\smallsanscap{A} from the left than from the right; +thus \smallsanscap{A}~will be pushed from left to right or towards~\smallsanscap{B}. There +will thus be an attraction between the parallel currents. + +\Article{24} It will be noticed that the tubes in the preceding case +\index{Polarization}% +move radially in towards the wire, so that the energy which is +converted into heat in the circuit comes from the dielectric sideways +into the wire and is not transmitted longitudinally along +it. This was first pointed out by Poynting in his paper on the +Transfer of Energy in the Electromagnetic Field (\textit{Phil.\ Trans.}\ +1884, Part.~II. p.~343). + +\index{Alternating currents, motion of Faraday tubes round a wire carrying@\subdashtwo motion of Faraday tubes round a wire carrying}% +\index{Faradayx tubes, round a wire carrying an alternating current@\subdashtwo round a wire carrying an alternating current}% +When however the current instead of being constant is +alternating very rapidly, the motion of the tubes in the dielectric +is mainly longitudinal and not transversal. We shall show +in \chapref{Chapter IV.}{Chapter~IV} that if $p$~is the frequency of the current, $\sigma$~the +specific resistance of the wire, $a$~its radius, and $\mu$~its magnetic +permeability, then when $4\pi \mu pa^2 / \sigma$ is a large quantity the electromotive +intensity outside the wire is normal to the wire and +therefore radial. Thus in this case the Faraday tubes will be +radial, and they will move at right angles to themselves parallel +to the wire. There is thus a great contrast between this case +and the previous one in which the tubes are longitudinal and +move radially, while in this the tubes are radial and move +longitudinally. + + +\Subsection{Discharge of a Leyden Jar.} +\index{Faradayx tubes, motion of during the discharge of a Leyden jar@\subdashtwo motion of during the discharge of a Leyden jar}% +\index{Leyden jar, motion of Faraday tubes during discharge of}% + +\includegraphicsouter{fig06}{Fig.~6.} + +\Article{25} We shall now proceed to consider the distribution and +motion of the Faraday tubes during the discharge of a Leyden jar. +We shall take the symmetrical +case in which +the outside coatings of +two Leyden jars \smallsanscap{A}~and~\smallsanscap{B} +(\figureref{fig06}{Fig.~6}) are connected +by a wire, while the inside +coating of~\smallsanscap{A} is connected +to one terminal +of an electrical machine, +the inside coating of~\smallsanscap{B} +to the other. When the +electrical machine is in action the difference of potential between +the inside coatings of the jars increases until a spark +%% -----File: 053.png---Folio 39------- +passes between the terminals of the machine and electrical +oscillations are started in the jars. + +\includegraphicstwo[!t]{fig07}{Fig.~7.}{fig08}{Fig.~8.} +\includegraphicstwo[!b]{fig09}{Fig.~9.}{fig10}{Fig.~10.} +\includegraphicstwo[!t]{fig11}{Fig.~11.}{fig12}{Fig.~12.} + +Just before the passage of the spark the Faraday tubes will +be arranged somewhat as follows. Some tubes will stretch from +one terminal of the electrical machine to the other, others will go +from these terminals to neighbouring conductors, such as the +table on which the machine +is placed, the floors +and walls of the room. The +great majority of the tubes +will however be short +tubes going through the +glass from one coating to +the other of the jars \smallsanscap{A}~and~\smallsanscap{B}. + +Let us consider the behaviour +of two of these +tubes, one from~\smallsanscap{A}, the +other from~\smallsanscap{B}, when a +spark passes between the +terminals of the machine: +while the spark is passing these terminals may be considered to +be connected by a conductor. +The tubes which before the spark passed stretched from one terminal +of the machine to the other, +will as soon as the air space +breaks down shrink to +molecular dimensions; and +since the repulsion which +these tubes exerted on +those surrounding them +is obliterated, the latter +crowd into +the space between +the terminals. The short tubes which, before the spark +passed, went from one coating of a jar to the other will now +occupy some such positions as those shown in \figureref{fig07}{Fig.~7}. These +tubes being of opposite kinds tend to run together, they approach +each other until they meet as in \figureref{fig08}{Fig.~8}, the tubes now break up +as in \figureref{fig09}{Fig.~9}, the upper portion runs into the spark gap where it +%% -----File: 054.png---Folio 40------- +contracts, while the lower portion runs towards the wire connecting +the outside coatings of +the jars, \figureref{fig10}{Fig.~10}. If this +wire is a good conductor the +tubes at their junction with +the wire will be at right +angles to it, and a tube +will move somewhat as in +\figureref{fig11}{Fig.~11}. The inertia of the +tube will carry the two +sides past each other, until +the tubes are arranged as +in \figureref{fig12}{Fig.~12}. The tube with +its ends on the wire will +travel backwards and will approach the positive tube which +was emitted from the air +gap when the negative +tube (\figureref{fig09}{Fig.~9}) entered it. +The tubes then go through +the processes illustrated +in Figs.\ \figureref{fig09}{9},~\figureref{fig08}{8},~\figureref{fig07}{7} in the reverse +order, and the jars +again get charged, but +with electricity of opposite +sign to that with +which they started. After +a time all the original +Faraday tubes will be +replaced by others of opposite sign, and the charges on the jars +will be equal and opposite +to the original charges. +The new charge will then +proceed to get reversed by +similar processes to those +by which the original +charge was reversed, and +thus the charges on the jar +will oscillate from positive +to negative and back again. + + +\Article{26} When a conducting circuit is placed near the wire +%% -----File: 055.png---Folio 41------- +connecting the outer coatings of the jars, the Faraday tubes will +strike against the circuit on their way to and from the wire. +The passage of these tubes across the circuit will, since there is +an excess of tubes of one name, produce a current in this circuit, +which is the ordinary +current in the secondary +due to the variation of +the intensity of the current +in the primary circuit. + +\includegraphicsmid[!t]{fig13}{Fig.~13} + +Some of the tubes as +they rush from the jar to +the wire connecting the +outside coatings of the jar +strike against the secondary +circuit, break up into +two parts, as shown in \figureref{fig13}{Fig.~13}, the ends of these parts run +along this circuit until they meet again, when the tube reunites +and goes off as a single tube. The passage of the tube +across the secondary circuit is thus equivalent to a current in +the direction of rotation of the hands of a watch; this is +opposite to that of the current in the wire connecting the +outside coatings of the jars. The circuit by breaking up the +%% -----File: 056.png---Folio 42------- +tubes falling on it prevents them from moving across its interior, +in other words, it tends to keep the number of lines of magnetic +induction which pass through the circuit constant; this tendency +gives the usual rule for finding the direction of the induced +\index{Induction, of currents due to changes in the magnetic field, due to alternations in the primary circuit@\subdashtwo due to alternations in the primary circuit}% +current. The introduction of magnetic force for the purpose of +finding the currents in one circuit induced by alterations of the +currents in another circuit seems however somewhat artificial. + +\Subsection{Electromagnetic Theory of Light.} +\index{Light, electromagnetic theory of}% +\index{Electromagnetic theory of light}% + +\Article{27} We can by the aid of the Faraday tubes form a mental +picture of the processes which on the Electromagnetic Theory +accompany the propagation of light. Let us consider in the +first place the uninterrupted propagation of a plane wave emitted +from a plane source. Let $z$~be the direction of propagation and +let the wave be one of plane polarized light, the plane of polarization +being that of~$yz$. Then we may suppose that a bundle of +Faraday tubes parallel to~$x$ are emitted from the plane source, +and that either these, or other parallel tubes set in motion +by them, travel at right angles to themselves and parallel to +the axis of~$z$ with the velocity of light. By the principles we +have been considering these tubes produce in the region through +which they are passing a magnetic force whose direction is at +right angles both to the direction of the tubes and that in which +they are moving, the magnetic force is thus parallel to the axis of~$y$. +The magnitude of the magnetic force is by equations~(\eqnref{9}{4}) +equal to~$4\pi v$ times the polarization, where $v$~is the velocity of +light, and since the electromotive intensity is~$4\pi / K$, or, if the +medium is non-magnetic, $4\pi v^2$~times the polarization, we see +that the electromotive intensity is equal to $v$~times the magnetic +force. If there is no reflection the electromotive intensity and +the magnetic force travel with uniform velocity~$v$ outwards +from the plane of disturbance and always bear a constant ratio +to each other. By supposing the number of tubes issuing from +the plane source per unit time to vary harmonically we arrive +at the conception of a divergent wave as a series of Faraday +tubes travelling outwards with the velocity of light. In this +case the places of maximum, zero and minimum electromotive +intensity will correspond respectively to places of maximum, zero +and minimum magnetic force. +%% -----File: 057.png---Folio 43------- + +The case is different, however, when light is reflected from a +metallic surface. We shall suppose this surface plane and at +right angles to the axis of~$z$. In this case since the tangential +electromotive intensity at the metallic surface vanishes, when a +bundle of positive tubes enters the reflecting surface, an equal +number of negative tubes are emitted from it; these travel backwards +towards the source of light, moving in the opposite direction +to the positive tubes. If we have a harmonic emission of tubes +from the source of light we shall evidently also have a harmonic +emission of tubes from the reflecting surface. Thus, at the +various places in the path of the light, we may have positive +tubes moving backwards or forwards accompanied by negative +tubes moving in either direction. The magnetic effects of the +positive tubes moving forwards are the same as those of the +negative tubes moving backwards. Thus, when we have tubes +of opposite signs moving in opposite directions, their magnetic +effects conspire while their electromotive effects conflict; so that +when, as in the case of reflection, we have streams of tubes +moving in opposite directions the magnetic force will no longer +be proportional to the electromotive intensity. In fact the +places where the magnetic force is greatest will be places +where the electromotive intensity vanishes, for such a place +will evidently be one where we have the maximum density of +positive tubes moving in one direction accompanied by the +maximum density of negative tubes moving in the opposite, +and since in this case there are as many positive as negative +tubes the electromotive intensity will vanish. In a similar +way we can see that the places where the electromotive intensity +is a maximum will be places where the magnetic force +vanishes. + +This view of the Electromagnetic Theory of Light has some of +the characteristics of the Newtonian Emission Theory; it is not, +however, open to the objections to which that theory was liable, +as the things emitted are Faraday tubes, having definite positions +at right angles to the direction of propagation of the light. With +such a structure the light can be polarized, while this could not +happen if the things emitted were small symmetrical particles as +on the Newtonian Theory. + +\Article{28} Before proceeding to interpret the production of a current +by a galvanic cell in terms of Faraday tubes it is necessary to +%% -----File: 058.png---Folio 44------- +consider a little more in detail the process by which these tubes +contract when they enter a conductor. + +\Article{29} When a Faraday tube is not closed its ends are places +where electrification exists, and therefore are always situated on +matter. Now the laws of Electrolysis show that the number of +Faraday tubes which can fall on an atom is limited; thus only one +can fall on an atom of a monad element, two on that of a dyad, +and so on. The atoms in the molecule of a compound which is +chemically saturated are already connected by the appropriate +number of tubes, so that no more tubes can fall on such atoms. +Thus on this view the ends of a tube of finite length are on free +atoms as distinct from molecules, the atoms in the molecule being +connected by short tubes whose lengths are of the order of molecular +distances. Thus, on this view, the existence of free electricity, +whether on a metal, an electrolyte, or a gas, always requires the +existence of free atoms. The production of electrification must +be accompanied by chemical dissociation, the disappearance of +electrification by chemical combination; in short, on this view, +changes in electrification are always accompanied by chemical +changes. This was long thought to be a peculiarity attaching to the +passage of electricity through electrolytes, but there is strong evidence +to show that it is also true when electricity passes through +gases. Reasons for this conclusion will be given in \chapref{Chapter II.}{Chap.~II}, it +will be sufficient here to mention one or two of the most striking +instances, the details of which will be found in that chapter. + +\index{Perrot, decomposition of steam}% +Perrot found that when the electric discharge passed through +steam, oxygen came off in excess at the positive and hydrogen +at the negative electrode, and that the excesses of oxygen at the +positive and of hydrogen at the negative electrode were the +same as the quantities of these gases set free in a water voltameter +placed in series with the discharge through the steam. +\index{Grove, chemical action of the discharge}% +Grove found that when the discharge passed between a point +and a silver plate through a mixture of hydrogen and oxygen, +the plate was oxidised when it was the positive electrode, not +when it was the negative. If the plate was oxidised to begin +with, it was reduced by the hydrogen when it was the negative +electrode, not when it was the positive. These and the other +results mentioned in Chap.~II seem to point unmistakably to +the conclusion that the passage of electricity through gases is +necessarily attended by chemical decomposition. +%% -----File: 059.png---Folio 45------- + +\Article{30} Although the evidence that the same is true when electricity +passes through metals is not so direct, it must be borne +in mind that here, from the nature of the case, such evidence is +much more difficult to obtain; there are, however, reasons for +believing that the passage of electricity through metals is accomplished +by much the same means as through gases or electrolytes. +We shall return in \artref{34}{Art.~34} to these reasons after considering the +behaviour of the Faraday tubes when electricity is passing +through an electrolyte, liquid or gaseous. + +\includegraphicsmid{fig14}{Fig.~14} + +\includegraphicsmid{fig15}{Fig.~15} + +\Article{31} To fix our ideas, let us take the case of a condenser discharging +\index{Faradayx tubes, shortening of in a conductor@\subdashtwo shortening of in a conductor|(}% +through the gas between its plates. Let us consider a +Faraday tube which before discharge stretched from an atom~\smallsanscap{O} +(\figureref{fig14}{Fig.~14}) on the positive plate to another atom~\smallsanscap{P} on the negative +one. The molecules \smallsanscap{AB},~\smallsanscap{CD},~\smallsanscap{EF} of the intervening gas will be +polarized by induction, and the Faraday tubes which connect +the atoms in these molecules will point in the opposite direction +to the long tube~\smallsanscap{OP}. The tube in the molecule~\smallsanscap{AB} will lengthen +and bend towards the tube~\smallsanscap{OP} (which is supposed to pass near +to~\smallsanscap{AB}) since these are of opposite signs, until when the field +is sufficiently strong the tube in the molecule~\smallsanscap{AB} runs up +into the long tube~\smallsanscap{OP} as in \figureref{fig15}{Fig.~15}. The long tube then breaks +up into two tubes \smallsanscap{OA}~and~\smallsanscap{BP} as in \figureref{fig16}{Fig.~16}, and the tube~\smallsanscap{OA} +shortens to molecular dimensions. The result of these operations +is that the tube~\smallsanscap{OP} has contracted to the tube~\smallsanscap{BP}, and the +atoms \smallsanscap{O}~and~\textsf{A} have formed a molecule. The process is then +continued, until the tube~\smallsanscap{OP} has contracted into a tube of +molecular dimensions at~\smallsanscap{P}. The above explanation +\includegraphicsmid{fig16}{Fig.~16} +is only +%% -----File: 060.png---Folio 46------- +intended to represent the general nature of the processes by +which the Faraday tubes shorten; we must modify it a little in +order to explain the very great velocity of the discharge along +the positive column (see Chap.~II, \artref{108}{Art.~108}). If the tubes +shortened in the preceding manner, we see that the velocity of the +ends of the tube would only be comparable with the velocity of +translation of the molecules of the gas, but the experiments alluded +to above show that it is enormously greater than this. A very +slight modification of the above process will, however, while +keeping the essential features of the discharge the same, give a +much greater velocity of discharge. Instead of supposing that +the tube~\smallsanscap{OP} jumps from one molecule to the next, we may suppose +that, under the induction in the field, several of the molecules, +say \smallsanscap{AB},~\smallsanscap{CD},~\smallsanscap{EF}, form a chain, and that the tubes in these +molecules instead of being successively affected by the long tube +and by each other are simultaneously affected, so that the tube~\smallsanscap{OP} +instead of merely jumping from one molecule to the next, +moves as in \figureref{fig17}{Fig.~17} from one end of the chain \smallsanscap{AB},~\smallsanscap{CD},~\smallsanscap{EF} to the +%% -----File: 061.png---Folio 47------- +other. In this case the long tube would shorten by the length of +the chain in the same time as on the previous hypothesis it +shortened by the distance between two molecules, so that on this +view the velocity of discharge would be greater than that on the +previous view in the proportion of the length of a chain to the +distance between two molecules. We shall see in Chap.~II that +there is considerable evidence that in the electric field chains +of molecules are formed having a structure much more complex +than that of the molecules recognized in the ordinary Kinetic +Theory of Gases. +\index{Faradayx tubes, shortening of in a conductor@\subdashtwo shortening of in a conductor|)}% + +\includegraphicsmid{fig17}{Fig.~17} + +\Article{32} We can easily express the resistance of a conductor in +\index{Resistance of a conductor}% +\index{Faradayx tubes, duration of in terms of resistance@\subdashtwo duration of in terms of resistance}% +terms of the time the Faraday tubes take to disappear (i.e.~to +contract to molecular dimensions). Let us for the sake of clearness +take the case of a conducting wire, along which $E$~is the +electromotive intensity at any point, while $K$~is the specific inductive +capacity of the material of which the wire is made. +Then the number of Faraday tubes passing through unit area +of the cross-section of the wire is equal to +\[ +\frac{K}{4 \pi}\, E. +\] + +Let $T$ be the average life of a tube in the conductor, then +the number of tubes which disappear from unit area in unit +time is~$KE/4 \pi T$; and since the current~$c$ across unit area is +equal to the number of tubes which disappear from unit area +in unit time, we have +\[ +c = \frac{KE}{4 \pi T}. +\] + +If $\sigma$ be the specific resistance of the conductor measured in +electromagnetic units +\begin{DPalign*} +E & = \sigma c, \\ +\lintertext{hence} \sigma & = \dfrac{4 \pi T}{K}, \\ +\lintertext{or} T & = \frac{K\sigma}{4 \pi}. +\end{DPalign*} +Hence $T$ has the same value as the quantity denoted by the +same symbol in Maxwell's \textit{Electricity and Magnetism} (Art.~325). +\index{Time of `relaxation'}% +It is often called the time of relaxation of the medium. + +If $\{K\}$ be the value of~$K$ in electrostatic units, +%% -----File: 062.png---Folio 48------- +\begin{DPgather*} +\lintertext{then since} \{K\} = \frac{K}{9×10^{20}}, \\ +\lintertext{we have} T = \frac{\{K\}}{4 \pi}\, \frac{\sigma}{9×10^{20}}. +\end{DPgather*} + +The approximate values of $T/\{K\}$ for a few substances are +given in the following table:--- +\begin{center} +\begin{tabular}{l@{}l} + & \multicolumn{1}{c}{$T/\{K\}$} \\ +Silver \wdotfill & $1.5 × 10^{-19}$ \\ +Lead \wdotfill & $1.8 × 10^{-18}$ \\ +Mercury \wdotfill & $8.7 × 10^{-18}$ \\ +Water with $8.3$ per cent of $H_2SO_4$\qquad\null & $3.1 × 10^{-13}$ \\ +Glass at $200°$\,C \wdotfill & $2\phantom{.1} × 10^{-6}$ +\end{tabular} +\end{center} + +Since the values of~$\{K\}$ have not been determined for substances +conducting anything like so well as those in the preceding +\index{Arons and Cohn, specific inductive capacity of water}% +\index{Cohn and Arons, specific inductive capacity}% +list we cannot determine the value of~$T$. Cohn and Arons +have found however that the specific inductive capacity of +distilled water is about~$76$. Cohn and Arons (\textit{Wied.\ Ann.}~33, +p.~13, 1888), and Cohn (\textit{Berl.\ Ber.}\ p.~1037, 1891) found that +the specific inductive capacity of a weak solution differs very +little from that of the solvent, though the difference in the +specific resistance is very great. If we suppose that the~$K$ +for water mixed with sulphuric acid is the same as the~$K$ +for water, we should find~$T$ for this electrolyte about~$2 × 10^{-11}$, +which is about ten thousand times as long as the time of vibration +of sodium light; hence this electrolyte when exposed to +electrical vibration of this period will behave as if $T$~were infinite +or as if it were an insulator, and so will be transparent +to electrical vibrations as rapid as those of light. We see too +that if~$\{K\}$ for the metals were as great as~$\{K\}$ for distilled +water, the values of~$T$ for these substances would not greatly +exceed the time of vibrations of the rays in the visible spectrum: +\index{Metals, opacity of}% +\index{Opacity of metals}% +this result explains Maxwell's observation, that the opacity of +thin metallic films is much less than the value calculated on the +electromagnetic theory, on the assumption that the conductivity +of the metals for the very rapidly alternating currents which +constitute light is as great as that for steady currents. + +\includegraphicsmid{fig18}{Fig.~18} + +\Subsection{Galvanic Cell.} +\index{Galvanic cell}% + +\Article{33} The production of a current by a cell is the reverse process +to the decomposition of an electrolyte by a current; in the latter +%% -----File: 063.png---Folio 49------- +case the chemical processes make a long Faraday tube shrink to +molecular dimensions, in the former they produce a long tube from +short molecular tubes. Let \smallsanscap{A}~and~\smallsanscap{B} (\figureref{fig18}{Fig.~18}) represent two +metal plates immersed in an acid which combines chemically +with~\smallsanscap{A}. Let~$a$ be a positive atom in the plate~\smallsanscap{A} connected by a +Faraday tube with a negative atom~$b$, then if $a$~enters into +chemical combination with a molecule~$cd$ of the acid, after the +combination $a$~and~$c$ will be connected by a Faraday tube, as will +also $b$~and~$d$: it will be seen from the second line in the figure that +the length of the tube~$bd$ has been increased by the chemical action. +If now $d$~enters into combination with another molecule~$ef$, the +result of this will be still further to increase the length of the +tube, and this length will increase as the chemical combination +%% -----File: 064.png---Folio 50------- +progresses through the acid. In this way a long tube is produced, +starting from the metal at which the chemical change occurs. +This tube will rush to the wire connecting the plates, there shrink +to molecular dimensions, and produce a current through the wire. + +\Article{34} The connection between electric conduction and chemical +\index{Conduction of electricity through metals and electrolytes}% +\index{Electrolytes, conduction of electricity through}% +\index{Metals, xconduction through@\subdashone conduction through}% +change is much more evident in the cases of liquid electrolytes +and gases than it is in that of metals. There does not +seem, however, to be sufficient difference between the \emph{laws} of +conduction through metals and electrolytes to make it necessary +to seek an entirely different explanation for metallic conduction. +The chief points in which metallic conduction differs from +electrolytic are:--- + +1. The much greater ease with which electricity passes through +metals than through electrolytes. + +2. The difference of the effects of changes of temperature on the +conductivity in the two cases. An increase of temperature +generally diminishes the conductivity of a metal, while it increases +that of an electrolyte. + +3. The appearance of the products of chemical decomposition +at the electrodes when electricity passes through an electrolyte, +and the existence of polarization, while neither of these effects +has been observed in metallic conduction. + +With regard to the first of these differences, we may remark +that though the conductivities of the best conducting metals are +enormously greater than those of electrolytes, there does not seem +to be any abrupt change in the values of the conductivities when +we pass from cases where the conduction is manifestly electrolytic, +as in fused lead or sodium chlorides, to cases where it is not +recognised as being of this nature, as in tellurium or carbon. +The following table, which contains the relative conductivities +of a few typical substances, is sufficient to show this:--- +\begin{center} +\begin{tabular}{l l} +Silver & $\phantom{8.}63$. \\ +Mercury & $\phantom{8.0}1$. \\ +Gas Carbon & $\phantom{8.}1×10^{-2}$. \\ +Tellurium & $\phantom{8.}4×10^{-4}$. \\ +Fused Lead Chloride & $\phantom{8.}2×10^{-4}$. \\ +Fused Sodium Chloride & $8.6×10^{-5}$. +\end{tabular} +\end{center} + +With regard to the second difference between metallic and +electrolytic conduction, viz.~the effect of temperature on the +%% -----File: 065.png---Folio 51------- +\index{Temperature, effect of, on zconductivity@\subdashone effect of, on conductivity}% +conductivity, though it is true that in most cases the effect of +an increase in temperature is to diminish the conductivity in +one case and increase it in the other, this is a rule which is by no +means without exceptions. There are cases in which, though the +conduction is not recognised as being electrolytic, the conductivity +increases as the temperature increases. Carbon is a +\index{Feussner, temperature coefficient of electrical resistance for alloys}% +striking instance of this, and Feussner\footnote + {\textit{Zeitschrift f.~Instrumentenkunde},~9, p.~233, 1889.} +has lately prepared alloys +of manganese, copper and nickel whose conductivities show the +\index{Sack, temperature coefficients of electrolytes}% +same peculiarity. On the other hand, Sack (\textit{Wied.\ Ann.}~43, p.~212, +1891) has lately shown that above $95°$\,C the conductivity of a +$.5$~per~cent.\ solution of sulphate of copper decreases as the temperature +increases, and in this respect resembles the conductivity +of metals. These exceptions are sufficient to show that increase +of conductivity with temperature is not a sufficient test to +separate electrolytic from metallic conduction. + +With regard to the third and most important point---the +appearance of the products of chemical decomposition at the +electrodes---it is evident that we could not expect to get any +evidence of this in the case of the elementary metals. The case +\index{Roberts-Austen, conduction through alloys}% +of alloys looks more hopeful. Roberts-Austen, however, who examined +several alloys through which a powerful electric current +had been passed, could not detect any difference in the composition +of the alloy round the two electrodes. This result does not however +seem conclusive against the conduction being electrolytic, +for some alloys are little more than mixtures, while others behave +as if they were solutions of one metal in another. In neither +of these cases could we expect to find any separation of the +constituents produced by the passage of the current; we could +only expect to find this effect when the connection between the +constituents was of such a nature that the whole alloy could be +regarded as a chemical compound, in the molecule of which one +metal could be regarded as the positive, the other as the negative +element. The alloys investigated by Roberts-Austen do not +seem to have been of this character. + +\index{Metals, opacity of}% +One important respect in which metallic resembles electrolytic +conduction is the way in which electrolytes and metals behave +to the electrical vibrations which constitute light: an electrolyte, +though a conductor for steady currents, behaves like an insulator +to the rapidly alternating luminous electrical currents, and, as +%% -----File: 066.png---Folio 52------- +Maxwell's experiments on the transparency of their metallic +films show, metals show an analogous effect, for their resistance +for the light vibrations is enormously greater than their resistance +to steady currents. + +The theory of Faraday tubes which we have been considering +is, as far as we have taken it, geometrical rather than dynamical; +we have not attempted any theory of the constitution +of these tubes, though the analogies which exist between their +properties and those of tubes of vortex motion irresistibly suggest +that we should look to a rotatory motion in the ether for +their explanation. + +Taking however these tubes for granted, they afford, I think, +a convenient means of getting a vivid picture of the processes +occurring in the electromagnetic field, and are especially suitable +for expressing the relations which exist between chemical change +and electrical action. +%% -----File: 067.png---Folio 53------ + +\Chapter{Chapter II.}{The Passage of Electricity Through Gases.} +\index{Gases, passage of electricity through|indexetseq}% + +\Article{35} \Firstsc{The} importance which Maxwell attached to the study of +the phenomena attending the passage of electricity through gases, +as well as the fact that there is no summary in English text books +of the very extensive literature on this subject, lead me to think +that a short account of recent researches on this kind of electric +discharge may not be out of place in this volume. + + +\Subsection{Can the \emph{\textbf{Molecule}} of a Gas be charged with Electricity?} + +\Article{36} The fundamental question as to whether a body if charged +to a low potential and surrounded by dust-free air at a low temperature +will lose any of its charge, and the very closely +connected one as to whether it is possible to communicate a +charge of electricity to air \emph{in this condition}, have occasioned +considerable divergence of opinion among physicists. + +Coulomb (\textit{Mémoires de~l'Académie des~Sciences}, 1785, p.~612), +\index{Coulomb, leakage of electricity through air}% +who investigated the loss of electricity from a charged body +suspended by insulating strings, thought that after allowing for +the leakage along the supports there was a balance over, which +he accounted for by a convective discharge through the air; he +supposed that the particles of air when they came in contact +with a charged body received a charge of electricity of the same +sign as that on the body, and that they were then repelled by it. +On this view the molecules of air, just like small pieces of metal, +can be charged with electricity. + +This theory of the loss of electricity from charged bodies has +however not been confirmed by subsequent experiments, as +\index{Nahrwold, leakage of electricity through air}% +\index{Warburg, leakage of electricity through air}% +Warburg (\textit{Pogg.\ Ann.}~145, p.~578, 1872) and Nahrwold (\textit{Wied.\ +Ann.}~31, p.~448, 1887) have shown that the loss can be accounted +%% -----File: 068.png---Folio 54------- +for by the presence of dust in the air surrounding the bodies; +and that it is the particles of dust striking against the bodies +which carry off their electricity, and not the molecules of air. + +\index{Dust figures, given off from electrified metals@\subdashone given off from electrified metals}% +\index{Lenard and Wolf, dust given off under ultra-violet light}% +\index{Wolf and Lenard, action of ultra-violet light}% +This dust may either be present in the air originally, or it may +consist of particles of metal given off from the charged conductors +themselves, for, as Lenard and Wolf (\textit{Wied.\ Ann.}~37, +p.~443, 1889) have shown, metals either free from electrification +or charged with negative electricity give off metallic dust when +exposed to ultra-violet light. When the metals are positively +electrified no dust seems to be given off. + +The experiments of the physicists above mentioned point to +the conclusion that the molecules of a gas at ordinary temperatures +cannot receive a charge of electricity. + +\index{Blake, experiment with mercury vapour}% +This view receives strong support from the results of Blake's +experiments (\textit{Wied.\ Ann.}~19, p.~518, 1883), which have been +\index{Sohncke, electrification by evaporation}% +confirmed by Sohncke (\textit{Wied.\ Ann.}~34, p.~925, 1888), which show +that not only is there no electricity produced by the evaporation +of an unelectrified liquid, but that the vapour arising from an +electrified liquid is not electrified. If the molecules of a vapour +were capable of receiving a charge of electricity under any circumstances +we should expect them to do so in this case. This +experiment is a striking example of the way in which important +researches may be overlooked, for, as the following extract from +\index{Priestley@Priestley's \textit{History of Electricity}}% +Priestley's \textit{History of Electricity}, p.~204, shows, Blake's experiment +was made and the same result obtained more than one +\index{Kinnersley, electrification by evaporation}% +hundred years ago. `Mr.~Kinnersley of Philadelphia, in a letter +dated March~1761, informs his friend and correspondent Dr.~Franklin, +then in England, that he could not electrify anything +by means of steam from electrified boiling water; from whence +he concluded, that, contrary to what had been supposed by himself +and his friend, steam was so far from rising electrified that +it left its share of common electricity behind.' + +There does not seem to be any evidence that an electrified +body can lose any of its charge by radiation through space +without convection of electricity by charged particles. + + +\Subsection{Hot Gases.} +\index{Gases, passage of electricity through hot gases@\subdashone passage of electricity through hot gases|(}% +\index{Hot gases, passage of electricity through|(}% + +\Article{37} It is only at moderate temperatures that a conductor +charged to a low potential retains its charge when surrounded +\index{Becquerel, conductivity of hot gases}% +by a gas, for Becquerel (\textit{Annales de Chimie et de Physique}~[3]~39, +%% -----File: 069.png---Folio 55------- +p.~355, 1853) found that air at a white heat would allow +electricity to pass through it even though the potential difference +was only a few volts. This result has been confirmed by +\index{Blondlot, conductivity of hot gases}% +Blondlot (\textit{Comptes Rendus},~104, p.~283, 1887), who found that +air at a bright red heat was unable to insulate under potential +differences as low as $1/1000$ of a volt. He found, too, that the +conduction through the hot gas did not obey Ohm's law. + +From some experiments of my own (\textit{Phil.\ Mag.}\ [5]~29, +pp.~358,~441, 1890) I have come to the conclusion that hot gases +conduct electricity with very different degrees of facility. Gases +such as air, nitrogen, or hydrogen which do not experience +any chemical change when heated conduct electricity only to +a very small extent when hot, and in this case the conduction, +as Blondlot supposed, appears to be convective. Gases, however, +which dissociate at high temperatures, that is gases such as +iodine, hydriodic acid gas,~\&c., whose molecules split up into +atoms, conduct with very much greater facility, and the conduction +does not exhibit that dependence on the material of +which the electrodes are made which is found when the electricity +is transmitted by convection. + +A large number of gases were examined, and in every case +where the hot gas possessed any considerable conductivity, I +was able to detect by purely chemical means that chemical +decomposition had been produced by the heat. In this connection +it is necessary to distinguish between two classes of dissociation. +The first kind is when the molecule is split up into +atoms, as in iodine, hydriodic acid gas, hydrochloric acid gas +(when the chlorine, though not the hydrogen, remains partly +dissociated), and so on. In all cases when dissociation of this +kind exists, the gas is a good conductor when hot. The second +kind of dissociation consists in the splitting up of the molecules +of the gas into simpler molecules but not into atoms. +This kind of dissociation occurs when a molecule of ammonia +splits up into molecules of nitrogen and hydrogen, or when a +molecule of steam splits up into molecules of hydrogen and +oxygen. In this case the gases only conduct on the very much +lower scale of the non-dissociable gases. + +The first of the following lists contains those gases which only +conduct badly when heated, the second those which conduct +comparatively well: chemical analysis showed that all the gases +%% -----File: 070.png---Folio 56------- +in the second list were decomposed when they were hot enough +to conduct electricity:--- + +(1) Air, Nitrogen, Carbonic Acid, Steam, Ammonia, Sulphuric +Acid gas, Nitric Acid gas, Sulphur (in an atmosphere of nitrogen), +Sulphuretted Hydrogen (in an atmosphere of nitrogen). + +(2) Iodine, Bromine, Chlorine, Hydriodic Acid gas, Hydrobromic +Acid gas, Hydrochloric Acid gas, Potassium Iodide, +Sal-Ammoniac, Sodium Chloride, Potassium Chloride. + +The conductivities of the two classes of gases differ so greatly, +both in amount and in the laws they obey, that the mechanism +by which the discharge is effected is probably different in the +two cases. + +These experiments seem to show that when electricity passes +through a gas otherwise than by convection, free atoms, or +something chemically equivalent to them, must be present. It +should be noticed that on this view the molecules even of a hot +gas do not get charged, it is the \emph{atoms} and not the molecules +which are instrumental in carrying the discharge. + +\index{Metallic vapours, conductivity of}% +I also examined the conductivities of several metallic vapours, +including those of Sodium, Potassium, Thallium, Cadmium, +Bismuth, Lead, Aluminium, Magnesium, Tin, Zinc, Silver, and +Mercury. Of these the vapours of Tin, Mercury, and Thallium +hardly seemed to conduct at all, the vapours of the other metals +conducted well, their conductivities being comparable with +those of the dissociable gases. + +The small amount of conductivity which hot gases, which +are not decomposed by heat, possess, seems to be due to a convective +discharge carried perhaps by dust produced by the decomposition +of the electrodes: in some cases perhaps the electricity +may be carried by atoms produced by the chemical +action of the electrodes on the adjacent gas. + +The temperature of the electrodes seems to exert great influence +upon the passage of the electricity through the gas into which +the electrodes dip. In the experiments described above I found +it impossible to get electricity to pass through the gas, however +hot it might be, unless the electrodes were hot enough to glow. +A current passing through a hot gas was immediately stopped by +placing a large piece of cold platinum foil between the electrodes---though +a strong up-current of the hot gas was maintained to +prevent the gas getting chilled by the cold foil. As soon as the +%% -----File: 071.png---Folio 57------- +foil began to glow, the passage of the electricity through the +gas was re-established. + +This is one among the many instances we shall meet with in +this chapter of the difficulty which electricity has in passing +from a gas to a cold metal. +\index{Gases, passage of electricity through hot gases@\subdashone passage of electricity through hot gases|)}% +\index{Hot gases, passage of electricity through|)}% + +\nbpagebreak +\Subsection{Electric Properties of Flames.} +\index{Flames, electrical properties of}% + +\Article{38} The case in which the passage of electricity through hot +gases has been most studied is that of flames; here the conditions +are far from simple, and the results that have been +obtained are too numerous and intricate for us to do more than +mention their main features. A full account of the experiments +\index{Wiedemann@Wiedemann's \textit{Elektricität}}% +\index{Giese, electrical properties of flames}% +which have been made on this subject will be found in Wiedemann's +\textit{Lehre von~der Elektricität}, vol.~4,~B\footnote + {See also Giese, \textit{Wied.\ Ann.}~38, p.~403, 1889.}. + +A flame such as the oxy-hydrogen flame conducts electricity, +the hotter parts conducting better than the colder: the conductivity +of the flame is improved by putting volatile salts +into it, and the increase in the conductivity is greater when the +salts are placed near the negative electrode than when they +\index{Arrhenius, conductivity of flames}% +are placed near the positive\footnotemark. + \footnotetext{For an investigation on the effect of putting volatile salts in flames published + subsequently to Wiedemann's work, see Arrhenius (\emph{Wied. Ann.}~42, p.~18, 1891).} + +The conduction through the flame exhibits polar properties, for +if the electrodes are of different sizes the flame conducts better +when the larger electrode is negative than when it is positive. + +If wires made of different metals are connected together +and dipped into the flame, there will be an electromotive force +round the circuit formed by the flame and the wire; the +flame apparently behaving in much the same way as the acid +in a one-fluid battery; the electromotive force in some cases +amounts to between three and four volts. + +A current can also be obtained through a bent piece of wire +if the ends of the wire are placed in different parts of the flame. + + +\Subsection{Escape of Electricity from a Conductor at Low Potential +surrounded by Cold Gas.} + +\Article{39} Though it seems to be a well-established fact that a +conductor at a low potential, surrounded by cold air, may retain +its charge for an indefinitely long time, recent researches have +%% -----File: 072.png---Folio 58------- +shown that when the conductor is exposed to certain influences +leakage of the electricity may ensue. + +One of the most striking of these influences is that of ultra-violet +light. The effect of ultra-violet light on the electric +\index{Light, xeffect of ultra@\subdashone effect of ultra-violet on electric discharge}% +\index{Ultra-violet light, effect of, on electric discharge}% +\index{Hertz, effect of ultra-violet light on the discharge}% +discharge seems first to have been noticed by Hertz (\textit{Wied.\ +Ann.}\ 31, p.~983, 1887), who found that the disruptive discharge +between two conductors is facilitated by exposing the air +space, across which the discharge takes place, to the influence +of ultra-violet light. + +\index{Ebert and E. Wiedemann, effect of ultra-violet light}% +\index{Wiedemann, E., and Ebert, effect of ultra-violet light}% +E.~Wiedemann and Ebert (\textit{Wied.\ Ann.}\ 33, p.~241, 1888) subsequently +proved that the seat of this action is at the cathode; +they showed that the light produces no effect when the cathode +is shielded from its influence, however brightly the rest of the +line of discharge may be illuminated. + +They found that if the cathode is surrounded by air the +effect of the ultra-violet light is greatest when the pressure is +about $300$~mm.\ of mercury: when the pressure is so low that +the negative rays (see \artref{108}{Art.~108}) are visible, the effect of the +ultra-violet light is not at all well marked. + +They found also that the magnitude of the effects depends +upon the gas surrounding the cathode; they tried the effect +of immersing the cathode in carbonic acid, hydrogen and air, +and found that for these three gases the effect is greatest in +carbonic acid, least in air. In carbonic acid the effect is not +confined to ultra-violet light, as the luminous rays when they +fall on a cathode also facilitate the discharge. + +Great light was thrown on the nature of this effect by an +\index{Light, xeffect of ultra@\subdashone effect of ultra-violet on electrified metals}% +\index{Lenard and Wolf, dust given off under ultra-violet light}% +\index{Wolf and Lenard, action of ultra-violet light}% +investigation made by Lenard and Wolf (\textit{Wied.\ Ann.}\ 37, p.~443, +1889), in which it was proved that when ultra-violet light falls +on a negatively electrified platinum surface, a steam jet in the +neighbourhood of the surface shows by its change of colour +that the steam in it has been condensed. This condensation +always occurs when the negatively electrified surface on +which the light falls is metallic, or that of a phosphorescent +liquid, such as a solution of fuchsin or methyl violet. They +found also that some, but much smaller, effects are produced +when the surfaces are not electrified, but no effect at all can be +detected when they are charged with positive electricity. + +They attributed this condensation of the jet to dust emitted +from the illuminated surface, the dust, in accordance with +%% -----File: 073.png---Folio 59------- +\index{Aitken, effect of dust}% +Aitken's experiments (\textit{Trans.\ Roy.\ Soc.\ Edinburgh}, 30, p.~337, +1881), producing condensation by forming nuclei round which +the water drops condense. + +The indications of a steam jet are not however free from +\index{Helmholtz vr@Helmholtz, v.\ R., effect of electrification on a steam jet}% +ambiguity, as R.~v.~Helmholtz (\textit{Wied.\ Ann.}\ 32, p.~1, 1887) has +shown that condensation occurs in the jet when chemical reactions +are going on in its neighbourhood, even though no +dust is present. There is thus some doubt as to whether the +condensation observed by Lenard and Wolf is due to disintegration +of the illuminated surface or to chemical action +taking place close to it. Taking however the interpretation +which these observers give to their own experiments, the effects +observed by Hertz, E.~Wiedemann and Ebert can easily be +explained as due to the carrying of the discharge by particles +disintegrated from the metallic surface by the action of the +ultra-violet light. + +\index{Electrification of a metal plate by light}% +\index{Light, xelectrification of a metal plate@\subdashone electrification of a metal plate}% +\Article{40} Closely connected with this effect is the discovery, made +\index{Hallwachs, electrification by light}% +almost simultaneously by Hallwachs (\textit{Phil.\ Mag.}~[5], 26, p.~78, +\index{Righi, electrification by light}% +1888) and Righi (\textit{Phil.\ Mag.}~[5], 25, p.~314, 1888), that a metallic +surface, especially if the metal is zinc and freshly polished, +becomes positively electrified when exposed to the action of +ultra-violet light. + +Lenard and Wolf's experiments suggest that this is probably +due to the disintegration of the surface by the light, the metallic +dust or vapour carrying off the negative electricity and leaving +the positive behind. + +Stoletow (\textit{Phil.\ Mag.}~[5], 30, p.~436, 1890) showed that a kind +\index{Stoletow, electrification by light}% +of voltaic battery might be made by taking two plates of +different metals in metallic connection and exposing one of +them to the action of ultra-violet light; the plate so exposed becoming +the negative electrode of the battery. When ultra-violet +light acts in this way, Stoletow found that, as we should expect, +the light is powerfully absorbed by the surface on which it falls. + +Probably another example of the same effect is the positive +\index{Crookes on discharge through gases}% +electrification observed by Crookes (\textit{Phil.\ Trans.}, Part~II. 1879, +p.~647) on a plate placed inside an exhausted tube in full view of +the negative electrode. We shall see, when we consider the discharges +in such tubes, that something proceeds from the cathode +which resembles ultra-violet light in its power of producing +phosphorescence in bodies on which it falls. Crookes' experiment, +%% -----File: 074.png---Folio 60------- +which was made at Maxwell's suggestion, shows that the +resemblance of the cathode discharge to ultra-violet light extends +to its power of producing a positive charge on a metal +plate exposed to its influence. + +\index{Electrodes, yspluttering of@\subdashone spluttering of}% +\index{Spluttering@`Spluttering' of electrodes}% +\Article{41} A striking instance of the facility with which a negatively +electrified surface disintegrates, whilst a positively electrified +one remains intact, is afforded by the well-known `spluttering' +of the negative electrode in a vacuum tube. In such a tube +the glass round the negative electrode is darkened by the +deposition of a thin film of metal torn from the adjacent +cathode; the glass round the positive electrode is, on the other +hand, quite free from any such deposit. The amount of the +disintegration of the cathode depends greatly upon the metal of +which it is made. Crookes (\textit{Proc.\ Roy.\ Soc.}\ 50, p.~88, 1891) has +given the following table, which expresses the relative loss in +weight in equal times of cathodes of the same size exposed to +similar electrical conditions:--- +\begin{center} +\begin{tabular}{l r} +Palladium &108.00 \\ +Gold &100.\Z\Z \\ +Silver &82.68 \\ +Lead &75.04 \\ +Tin &56.96 \\ +Brass &51.58 \\ +Platinum &44.00 \\ +Copper &40.24 \\ +Cadmium &31.99 \\ +Nickel &10.99 \\ +Indium &10.49 \\ +Iron &5.50 +\end{tabular} +\end{center} + +The loss in weight of magnesium and aluminium electrodes +was too small to be detected. In the same paper Crookes also +describes an experiment which seems to show that the `spluttering' +at the negative electrode exists in water even when surrounded +by air at atmospheric pressure. + +\Article{42} Since a metal surface when exposed to the action of +sunlight emits negative electricity and retains positive, we +should expect positively electrified bodies when exposed to +light to behave differently from negatively electrified ones. This +has been found to be the case. The first observations on this +%% -----File: 075.png---Folio 61------- +subject seem to have been made by Hoor (\textit{Repertorium d.\ +Physik.}~25, p.~105, 1889), who found that freshly prepared surfaces +of zinc, copper, and brass quickly lost a negative charge +when exposed to the action of ultra-violet light, while the same +surfaces retained a positive charge. + +\index{Elster and Geitel, electrification produced by glowing bodies}% +\index{Geitel escape of electricity from illuminated surfaces@\subdashone escape of electricity from illuminated surfaces}% +\index{Hoor, effect of light on charged metals}% +The subject was afterwards taken up by Elster and Geitel +(\textit{Wied.\ Ann.}\ 38, pp.~40, 497, 1889; 41, p.~161, 1890; 42, p.~564, 1891), +who verified Hoor's result for zinc, but could not detect any loss +of negative electricity from freshly prepared surfaces of brass +or copper. They also established the interesting fact that the +effect is most marked in the case of the electro-positive metals, +zinc or amalgamated zinc, aluminium, and magnesium. For the +still more electro-positive metals, potassium and sodium, or +rather for their amalgams, since the pure metals are difficult to +work with on account of the tarnishing of their surfaces, they +found that the effect is so strong that it can readily be +observed even when the amalgams are enclosed in glass tubes, +though glass, as is well known, absorbs most of the ultra-violet +rays. When they succeeded subsequently in working with +surfaces of potassium and sodium instead of their amalgams, +they found that these substances are sensitive not merely to +the ultra-violet rays but even to those emitted by an ordinary +petroleum lamp (\textit{Wied.\ Ann.}\ 43, p.~225, 1891). + +Thus when the surface of some metals is negatively electrified +and exposed to the action of light, and especially of ultra-violet +light, we have an exception to the general rule that a charged +body surrounded by cold air can retain its charge, for an indefinite +time, provided the charge is not large enough to produce a +spark. For as Elster and Geitel proved, the smallest negative +charge rapidly disappears from the illuminated surface. + +The order of sensitiveness of metals to this effect is given by +Elster and Geitel as + +\begin{tabular}{@{\indent}l} +Potassium,\\ +Alloy of Sodium and Potassium,\\ +Sodium,\\ +Amalgams of Rubidium, Potassium, Sodium and Lithium,\\ +Magnesium, Aluminium,\\ +Zinc,\\ +Tin. +\end{tabular} + +It is interesting to note that this is roughly the order of the +%% -----File: 076.png---Folio 62------- +metals in Volta's contact electricity series, as each metal is +positive to the one after it. Elster and Geitel found that the +effect is too small to be measured in Cadmium, Lead, Copper, +Iron, Platinum, Mercury, and Carbon. They also found no clear +indications of it with water. It is well marked, however, in +phosphorescent substances such as Balmain's luminous paint +\index{Elster and Geitel, electrification produced by glowing bodies}% +\index{Geitel and Elster, electrification caused by glowing bodies}% +(sulphide of calcium), and Elster and Geitel (\textit{Wied.\ Ann.}~44, +p.~722, 1891) have quite recently shown that it is exhibited by +Fluor Spar and other phosphorescent minerals. + +Another way of observing this effect is to place the illuminated +body without a charge and in connection with the +earth in the neighbourhood of a charged body, when the latter +will lose its charge if it is positively electrified, while it will +not lose its charge if it is negatively electrified; the positive +charge induces a negative one on the illuminated body, this +negative electricity escapes, travels up to and neutralises the +positive electricity which induced it. When the pressure of the +gas surrounding the body is less than $1$~mm., the escape of the +negative electricity from the illuminated surface is considerably +checked by placing it in a strong magnetic field (Elster and +Geitel, \textit{Wied.\ Ann.}~41, p.~166, 1890). + + +\Subsection{Discharge of Electricity caused by Glowing Bodies.} +\index{Incandescent bodies, discharge of electricity by}% +\index{Incandescent bodies, production of electrification by@\subdashtwo production of electrification by}% + +\Article{43} Somewhat similar differences between the discharge of +positive and negative electricity are observed when the charged +body, instead of being illuminated, is raised to so high a temperature +that it becomes luminous itself. Elster and Geitel (\textit{Wied.\ +Ann.}~38, p.~27, 1889) found that when a platinum wire is heated +to a bright red heat in an atmosphere of air or oxygen at a low +pressure, a cold metal plate in its neighbourhood discharges +negative electricity with much greater ease than positive. If, on +the other hand, a thin platinum wire or carbon-filament is +heated to incandescence in an atmosphere of hydrogen at a low +pressure, the cold plate discharges positive electricity more easily +than negative. Guthrie, who (\textit{Phil.\ Mag.}\ [4]~46, p.~257, 1873) +was the first to call attention to phenomena of this kind, +observed that an iron sphere in air when white hot cannot retain +a charge either of positive or of negative electricity, and +that as it cools it acquires the power of retaining a negative +charge before it can retain a positive one. If the sphere +%% -----File: 077.png---Folio 63------- +is connected to the earth and held near a charged body, then, +when the sphere is white hot, the body soon loses its charge +whether this be positive or negative; when the sphere is +somewhat colder, the body is discharged if negatively electrified +but not if positively. + +\index{Electrification produced near glowing bodies@\subdashone produced near glowing bodies}% +\index{Geitel and Elster, electrification caused by glowing bodies}% +\index{Glowing bodies, discharge of electricity by}% +\index{Glowing bodies, electrification caused by@\subdashone electrification caused by}% +The converse problem of the production of electrification by a +glowing wire has been studied in great detail by Elster and +Geitel, a summary of whose results is given in \textit{Wied.\ Ann.}~37, +p.~315, 1889. The conclusions they have come to are that when +an insulated plate is placed near an incandescent platinum wire, +the plate becomes positively electrified in air and oxygen, negatively +electrified in hydrogen. It thus appears that incandescent +wires discharge most easily the electricity of opposite sign to that +which they produce on plates placed in their neighbourhood. If +the incandescence is continued for a long time, then if the wire +is thin and the pressure low, a plate in the neighbourhood of the +wire receives a negative charge, whatever be the gas by which +it is surrounded. Elster and Geitel seem to ascribe this to +the action of gases driven out of the electrodes. Nahrwold, who +also observed this effect (\textit{Wied.\ Ann.}~35, 107, 1888), regards it +as the normal one, and ascribes the positive electrification observed +when the wire first begins to glow to the action of dust +in the gas. It is noteworthy that hydrogen, which in Elster +and Geitel's experiments behaved with platinum electrodes +oppositely to the other gases, is the only gas in which, according +to Nahrwold, a platinum wire does not disintegrate when +heated. With carbon filaments, Elster and Geitel found that +the neighbouring plate is always negatively electrified, but so +much gas is given off from these filaments that the interpretation +of these results is ambiguous. + +Elster and Geitel have also observed that the ease with which +electricity is produced in a plate near a glowing wire is diminished +if the gas is hydrogen by placing the wire in a magnetic +field, increased if it is oxygen or air. + +\Article{44} The investigations we have just described show clearly +that metallic surfaces have in general a much greater tendency +to attract a positive than a negative charge. Thus, for example, +we have seen that when originally uncharged they become +positively charged when exposed to the action of ultra-violet +light, and if charged to begin with, then under the influence of +%% -----File: 078.png---Folio 64------- +the light they lose a negative charge much more rapidly than a +positive one, indeed there seems no evidence to show that there +is any loss of a small positive charge from this effect. + +The phenomena depending on the action of ultra-violet light and +of incandescent surfaces can be co-ordinated by the conception introduced +\index{Helmholtz va@Helmholtz, v.\ H., attraction of electricity by different substances}% +by v.~Helmholtz (\textit{Erhaltung der~Kraft, Wissenschaftliche +Abhand.}\ vol.~1.\ p.~48), that bodies attract electricity with different +degrees of intensity. This conception was shown by him to be +able to explain electrification by friction, and the difference of +potential produced by the contact of metals. Thus, for example, +the difference of potential produced by the contact of zinc and +copper is explained on this hypothesis by saying that the +positive electricity is attracted more strongly by the zinc than +it is by the copper. + +Instead of considering the specific attraction of different bodies +for electricity directly, it is equivalent in theory and generally +more convenient in practice to regard the potential energy +possessed by a body charged with electricity as consisting of +two parts, (1)~the part calculated by the ordinary rules of electrostatics, +and (2)~a part proportional to the charge and equal to~$\sigma Q$, +where $Q$~is the charge and $\sigma$ a quantity which we shall +\index{Volta@`Volta, potential'}% +call the `Volta potential' of the body, and which varies from one +substance to another. + +To investigate the nature of the effects produced by the presence +of this second term, let us consider the case of two parallel plates +$A$~and~$B$ made of different metals and connected electrically +with each other. + +Let $Q$ be the charge on the plate~$A$, $-Q$~that on the plate~$B$, +$\sigma_A$,~$\sigma_B$ the values of the co-efficient~$\sigma$ for the plates $A$~and~$B$ +respectively, then if $C$~is the capacity of the condenser formed +by the two plates, the potential energy of the system will be +given by the equation +\[ +V =\tfrac{1}{2} \frac{Q^2}{C} + \sigma_{A}Q - \sigma_{B}Q. +\] + +The system will be in equilibrium when the potential energy +is a minimum, i.e.~when $dV/dQ = 0$, or +\[ +\frac{Q}{C} + \sigma_A - \sigma_B = 0. +\] + +Thus, by the contact of the metals the potential of the plate~$A$ +is raised above that of~$B$ by $\sigma_B-\sigma_A$. +%% -----File: 079.png---Folio 65------- + +It is worthy of notice that on this view the medium separating +the plates does not affect the value of the potential difference +between them, however great the value of~$\sigma$ for this medium may +be, provided that, as in the case of cold air, the medium is +incapable of receiving a charge of electricity. + +The idea of the possession by a charged body of a quantity of +energy proportional to the first power of the charge is involved +in the well-used phrase `specific heat of electricity'; for if we +regard electricity as having a specific heat which varies from one +substance to another, a body charged with electricity will in \DPtypo{conquence}{consequence} +of this specific heat possess some energy proportional to +the charge. The electromotive forces which occur in unequally +heated bodies may be explained as due to the tendency of the +electricity to adjust itself so that the potential energy is a +minimum; if the quantity~$\sigma$ is a function of the temperature, +the energy will not be a minimum when the body is devoid of +electrification. + +\index{Electrification xeffect of on surface tension@\subdashone effect of on surface tension}% +The existence of the term~$\sigma Q$ in the expression for the energy +of a charged body, since the electrification is on the surface, +makes the energy per unit area of the surface depend upon +whether the electrification is positive, negative, or zero. Now +since the apparent surface tension of a liquid is equal to the +energy per unit area of surface, it may be objected that if +this view were true the surface tension of such liquids as are +conductors ought to be changed by electrification, the change +being in one direction when the electrification is positive and +in the opposite when it is negative. A short calculation will +show however that this change in the surface tension is so small +that it might easily have escaped detection. We have seen that +$\sigma_B-\sigma_A$ is the potential difference produced by the contact of two +metals $A$~and~$B$, we know from observation that this difference, +and therefore presumably $\sigma_A$~and~$\sigma_B$, is of the order of a volt, or +in electromagnetic units~$10^8$. Now the greatest electrification +which can exist on the surface without discharge when the metal +is surrounded by air at the atmospheric pressure is such as to +produce an electromotive intensity equal approximately to~$10^2$ +in electrostatic measure; thus the greatest surface density is +in electrostatic units about $10^2/4\pi$, or in electromagnetic units +$10^{-8}/12\pi$. Hence~$\sigma Q$, the energy of the kind we are considering, +will at the most be of the order $1/(12\pi)$~ergs per square centimetre. +%% -----File: 080.png---Folio 66------- +\index{Surface tension, effect of electrification on}% +This is so small compared with the energy due to the surface tension +that it would require very careful observations to detect it. + +\Article{45} When a conductor, which does not disintegrate, is surrounded +by air in its normal state, or by some other dielectric +incapable of receiving a charge of electricity, the conductor +cannot get charged, however much the $\sigma$ for the conductor may +differ from that for the dielectric; for the electricity of opposite +sign to that which would be left on the conductor has no +place to which it can go. + +The case is however different when the conductor is exposed to +the action of ultra-violet light, for then, as Lenard and Wolf's +experiments prove, one or both of the following effects must +take place: (1)~disintegration of the conductor, (2)~chemical +changes in the gas in the neighbourhood of the conductor which +put the gas in a state in which it can receive a charge of electricity. +If either of these effects takes place it is possible for the +conductor to be electrified, for the electricity of opposite sign +to that left on the conductor may go to the disintegrated metal +or the gas. The experiments hitherto made leave undecided the +question which of these bodies serves as the refuge of the electricity +discarded from the metal. + +The researches of Hallwachs and Righi on electrification by +ultra-violet light can be explained on either hypothesis, if we +assume that $\sigma_1$, the value of~$\sigma$ for the metallic vapour or for the +dissociated gas, is greater than~$\sigma_2$, the value of~$\sigma$ for the solid +metal. For when negative electricity~$-Q$ escapes from the metal +and positive electricity equal to~$+Q$ remains behind, the diminution +in the part of the potential energy due to the Volta potential +is $\sigma_1 Q - \sigma_2 Q$ or $(\sigma_1 - \sigma_2)Q$. Thus, since $\sigma_1$~is by hypothesis greater +than~$\sigma_2$, the departure of the negative electricity from the metal +will be accompanied by a diminution in the potential energy, +and will therefore go on until the increase in the ordinary +potential energy due to the new distribution of electricity is +sufficient to balance the diminution in the part of the energy +due to the Volta potential. The positive electrification of the +plate produced by ultra-violet light can thus be accounted for. + +Again, if the metal were initially positively electrified it +would not be so likely to lose its charge as if it were initially +charged with negative electricity, for the passage of positive +electricity from the metal to its vapour or to the dissociated gas +%% -----File: 081.png---Folio 67------- +would involve an increase in the energy depending upon the +Volta potential, and so would be much less likely to occur than +an escape of negative electricity, which would produce a diminution +in this energy. We can thus explain the observations of +Elster and Geitel on the difference in the rates of escape of +positive and negative electricity from illuminated surfaces. \nblabel{add:1}The +causes of the electrification by incandescence observed by Elster +and Geitel~(l.c.)\ are more obscure. Thus if we take the case when a +plate receives a positive charge in air owing to the presence of +a neighbouring incandescent platinum wire, the most obvious +interpretation would be that the incandescence produces electrical +separation, the wire getting negatively and the adjacent gas +positively electrified. This view is however open to the very +serious objection that in the other cases of the electrification of a +metal in contact with a gas the metal receives the positive charge +and not the negative one, as it would have to do if the preceding +explanation were correct. + +The plate is exposed to the radiation from the incandescent +wire and may perhaps under the influence of this radiation become +a cathode, i.e.\ give out negative electricity and thus become +positively \DPtypo{electified}{electrified}, just as it would if, as in Hallwach's and +Righi's experiments, it were exposed to the action of ultra-violet +light, or as in Crookes' experiment (\artref{40}{Art.~40}) to the +emanations from a negative electrode. It seems however difficult +to explain the anomalous behaviour of hydrogen on this +view, and Nahrwold's discovery of the absence of `spluttering' +in platinum wires heated to incandescence in an atmosphere of +hydrogen seems to suggest that the charge on the plate may possibly +arise in some such way as the following, even though the first +effect of the incandescence is to produce a positive electrification +over the wire and a negative one over the adjacent gas. When +a metallic wire is heated, disintegration may take place in two +ways, the metal may go off as vapour, or it may be torn off in +solid lumps or dust. Now there seems to be no reason why $\sigma$ +for these lumps should differ from $\sigma$ for the wire, for both the +lump and the wire consist of the same substance in the same +state of aggregation; but if the $\sigma$'s were the same there would +be no separation of electricity between the two. On the contrary, +if the wire were charged with positive electricity, the +lump, when it broke away, would carry positive electricity off +%% -----File: 082.png---Folio 68------- +with it. The case is however different when the metal goes +off as vapour, or when it dissociates the gas in its neighbourhood: +here the wire and the vapour or gas are in different +states of aggregation, for which the values of~$\sigma$ are probably +different, so that there may now be a separation of electricity, the +wire getting the positive and the vapour or gas the negative. + +In air there is such an abundant deposition of platinum on a +glass tube surrounding an incandescent platinum wire that the +latter in all probability gives off dust as well as either dissociating +the surrounding gas or giving off platinum vapour; while +Nahrwold (\textit{Wied.\ Ann.}~35, 107, 1888) has shown that the deposition +of platinum is so small in hydrogen that very little can be +given off as dust in this gas. + +Let us now consider what will happen in air. When the +platinum becomes incandescent there is a separation of electricity, +the positive remaining on the wire, the negative going to the +metallic vapour or dissociated gas. Since the wire has got a +positive charge, any lumps that break away from it will be +positively electrified. If the positive electricity given by these +lumps to the plate, which in Elster and Geitel's experiments was +held above the glowing wire, is greater than the negative charge +given to it by such vapour or gas as may come in contact with +it, the charge on the plate will be positive, as in Elster and +Geitel's experiments. In hydrogen however, where the lumps are +absent, there is nothing to neutralize the negative electricity on +the metallic vapour or dissociated gas, so that the charge on the +plate will, as Elster and Geitel found, be negative. + +\nbpagebreak +\Section{Spark Discharge.} +\index{Spark, discharge|indexetseq}% + +\Subsection{Electric Strength of a Gas.} +\index{Electric strength@\subdashone strength}% + +\Article{46} In \artref{51}{Art.~51} of the first volume of the \textit{Electricity and Magnetism} +Maxwell defines the \emph{electric strength} of a gas as the +greatest electromotive intensity it can sustain without discharge +taking place. This definition suggests that the electric strength +is a definite specific property of a gas, otherwise the introduction +of this term would not be of much value. If discharge through +a gas at a definite pressure and temperature always began when +the electromotive intensity reached a certain value, then this +value, which is what Maxwell calls the electric strength of the +%% -----File: 083.png---Folio 69------- +gas, would have a perfectly definite meaning. The term `electric +strength of the gas' would however be misleading if it were +found to depend on such things, for example, as the materials of +which the electrodes are made, the state of their surface, their +shape, size, or distance apart, or on whether the electric field +was uniform or variable either with regard to time or space. It +has been found that the `electric strength' does depend upon +some, perhaps even upon all, of the preceding conditions. + +\index{Righi, electrification by light}% +\index{Spark, length, effect of nature of electrodes on@\subdashone length, effect of nature of electrodes on}% +\Article{47} Righi (\textit{Nuovo Cimento}, [2]~16, p.~97, 1876) made some +experiments with electrodes of carbon, bismuth, lead, zinc, tin +and copper, but found that the substance of which the electrodes +are made has little effect on the electromotive intensity necessary +\index{Peace, spark potential|(}% +for discharge. Mr.~Peace, who made careful experiments in the +Cavendish Laboratory on this point, could not detect any +difference in the electromotive intensity required to spark across +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +electrodes made of brass and those made of zinc. De~la~Rue and +Hugo Müller (\textit{Phil.\ Trans.}~169, Pt.~1.\ p.~93, 1878) came to the +conclusion that sparks pass more easily between aluminium +terminals than between terminals of other metals, but that with +this exception the nature of the electrodes has no influence upon +the spark length. + +\index{Jaumann, discharge facilitated by rapid changes in the potential}% +Jaumann has shown (\textit{Wien.\ Berichte},~97, p.~765, 1888) that the +spark discharge is very much facilitated by making small but +rapid changes in the potential of one of the electrodes. + +\Article{48} The reduction by Schuster (\textit{Phil.\ Mag.}\ [5]~29, p.~182, 1890) +\index{Spark, length, effect of size of electrode on@\subdashone length, effect of size of electrode on}% +\index{Baille, spark discharge|(}% +\index{Gaugain, spark discharge}% +\index{Paschen, spark discharge}% +of the experiments of Baille, Paschen, and Gaugain on the spark +discharge shows that with spherical electrodes of different sizes +($1$~cm., $.5$~cm., and $.25$~cm.\ in radius respectively) the maximum +electromotive intensity when the spark just passes through air +at atmospheric pressure varies from $142$ to~$372$, the maximum +intensity for small spheres being greater than for large ones. +\index{Schuster, discharge through gases}% +Schuster sums up the conclusions he draws from these experiments +as follows, l.~c.\ p.~192:--- + +(1) `For two similar systems of two equal spheres in which +only the linear dimensions vary, the breaking-stress is greater +the greater the curvature of the spheres.' + +(2) `If the distance between the spheres is increased, the breaking-stress +at first diminishes.' + +(3) `There is a certain distance for which the breaking-stress +is a minimum.' +%% -----File: 084.png---Folio 70------- + +We shall find too when we consider the relation between spark +length and potential difference that the distance between the +electrodes may have an enormous effect on the electromotive +intensity required to produce discharge. + +The `electric strength' as defined by Maxwell seems to depend +upon so many extraneous circumstances that there does not +appear to be any reason for regarding it as an intrinsic property +of the gas. + +\Subsection{Connection between Spark Length and Potential Difference, +when the Field is approximately uniform.} +\index{Spark, length, connection between and potential difference@\subdashone length, connection between and potential difference|indexetseq}% + +\Article{49} This subject has been investigated by a large number of +physicists. We have however only space to consider the most +recent investigations on this subject. Baille (\textit{Annales de Chimie +et de Physique}, [5]~25, p.~486, 1882) has made an elaborate investigation +of the potential difference required to produce in air +at atmospheric pressure sparks of varying lengths, between planes, +cylinders, and spheres of various diameters. The method he +used was to charge the conductors between which the sparks +passed by a Holtz machine, the potential between the electrodes +being measured by an attracted disc electrometer provided with +a guard ring: this method is practically the same as that employed +\index{Kelvin, Lord, spark discharge}% +by Lord Kelvin (\textit{Reprint of Papers on Electrostatics and +Magnetism}, p.~247), who in 1860 made the first measurements +in absolute units of the electromotive intensity required to produce +a spark. + +For very short sparks between two planes Baille (l.c., p.~515) +found the results given in the following table:--- +\begin{center} +\tabletextsize +\begin{tabular}{c|c|c} +\multicolumn{3}{c}{\normalsize\textit{Potential Difference and Spark Length;}} \\ +\multicolumn{3}{c}{\normalsize(\textit{temperature $15°$ to $20°$\,C, pressure $760~\text{mm}$.\smallskip})}\\ +\hline +\settowidth{\TmpLen}{in Centimetres.}% +\parbox[c]{\TmpLen}{\tablespaceup\centering Spark Length\\ in Centimetres.\tablespacedown} & +\settowidth{\TmpLen}{Potential Difference in}% +\parbox[c]{\TmpLen}{\centering Potential Difference in\\ Electrostatic Units.} & +\settowidth{\TmpLen}{Electrostatic Units.}% +\parbox[c]{\TmpLen}{\centering Surface Density in\\ Electrostatic Units.} \\ +\hline +\tablespaceup$.0015$ & $1.42$ & $75.4$ \\ +$.0020$ & $1.62$ & $64.5$ \\ +$.0025$ & $1.90$ & $60.5$ \\ +$.0050$ & $2.51$ & $39.9$ \\ +$.0075$ & $2.81$ & $29.8$ \\ +$.0100$ & $3.15$ & $25.1$ \\ +$.0125$ & $3.48$ & $22.1$ \\ +$.0150$ & $3.80$ & $20.1$\tablespacedown \\ +\hline +\end{tabular} +\end{center} +%% -----File: 085.png---Folio 71------- + +In another series of experiments where the sparks were slightly +longer, Baille, p.~515, found the following results:--- +\setlength{\TmpLen}{0.16\linewidth}% +\begin{center} +\setlength{\tabcolsep}{0pt} +\tabletextsize +\begin{tabular}{c|c|c||c|c|c} +\multicolumn{6}{c}{\normalsize\textit{Potential Difference and Spark Length.\smallskip}}\\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length.} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} \\ +\hline +\tablespaceup$.01$ & $\Z3.17$ & $25.2$ & $.08$ & $12.38$ & $12.3$ \\ +$.02$ & $\Z4.51$ & $17.9$ & $.09$ & $13.44$ & $11.9$ \\ +$.03$ & $\Z6.22$ & $16.5$ & $.10$ & $14.67$ & $11.7$ \\ +$.04$ & $\Z7.32$ & $14.6$ & $.11$ & $15.75$ & $11.4$ \\ +$.05$ & $\Z8.71$ & $13.8$ & $.12$ & $16.84$ & $11.1$ \\ +$.06$ & $\Z9.84$ & $13.2$ & $.13$ & $17.94$ & $11.0$ \\ +$.07$ & $11.20$ & $12.7$ & $.14$ & $19.00$ & $10.8$ \\ + & & & $.15$ & $20.16$ & $10.7$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +For spark lengths between $.025$~cm.\ and $.5$~cm.\ the following +results were obtained, p.~516, in a different series of experiments:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{0pt} +\begin{tabular}{c|c|c||c|c|c} +\multicolumn{6}{c}{\normalsize\textit{Potential Difference and Spark Length.\smallskip}}\\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length.} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} \\ +\hline +\tablespaceup$.025$ & $\Z5.94$ & $18.86$ & $.275$ & $32.69$ & $9.46$ \\ +$.050$ & $\Z8.68$ & $13.76$ & $.300$ & $35.35$ & $9.37$ \\ +$.075$ & $11.87$ & $12.57$ & $.325$ & $37.83$ & $9.25$ \\ +$.100$ & $14.79$ & $11.76$ & $.350$ & $39.95$ & $9.08$ \\ +$.125$ & $17.45$ & $11.06$ & $.375$ & $42.17$ & $8.94$ \\ +$.150$ & $20.29$ & $10.76$ & $.400$ & $44.74$ & $8.90$ \\ +$.175$ & $22.94$ & $10.43$ & $.425$ & $47.30$ & $8.86$ \\ +$.200$ & $25.51$ & $10.15$ & $.450$ & $49.70$ & $8.79$ \\ +$.225$ & $28.17$ & $\Z9.96$ & $.475$ & $52.18$ & $8.75$ \\ +$.250$ & $30.47$ & $\Z9.70$ & $.500$ & $54.48$ & $8.67$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\sloppy +For longer sparks Baille, l.c., p.~517, got the numbers given in +the two following Tables, which represent the results of different +sets of experiments:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{0pt} +\begin{tabular}{c|c|c||c|c|c} +\multicolumn{6}{c}{\normalsize\textit{Potential Difference and Spark Length.\smallskip}} \\ +\multicolumn{6}{c}{TABLE (I).\smallskip}\\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length.} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} \\ +\hline +\tablespaceup$.40$ & $44.80$ & $8.90$ & $.60$ & $63.82$ & $8.47$ \\ +$.45$ & $49.63$ & $8.78$ & $.65$ & $68.75$ & $8.42$ \\ +$.50$ & $54.36$ & $8.65$ & $.70$ & $74.09$ & $8.42$ \\ +$.55$ & $59.09$ & $8.55$ & $.75$ & $79.02$ & $8.39$\tablespacedown \\ +\hline +\end{tabular} +\end{center} +\fussy + +\index{Baille, spark discharge|)}% +%% -----File: 086.png---Folio 72------- +\index{Liebig, spark potential}% +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{0pt} +\begin{tabular}{c|c|c||c|c|c} +\multicolumn{6}{c}{TABLE (II).\smallskip}\\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length.} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Surface\\ Density.} \\ +\hline +\tablespaceup$.70$ & $73.48$ & $8.84$ & $\Z.90$ & $\Z94.72$ & $8.38$ \\ +$.75$ & $80.13$ & $\DPtypo{3.55}{8.55}$ & $\Z.95$ & $100.16$ & $8.38$ \\ +$.80$ & $84.86$ & $8.40$ & $1.00$ & $105.50$ & $8.39$ \\ +$.85$ & $89.89$ & $8.42$ & & &\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\Article{50} We may compare with these results those obtained by +Liebig (\textit{Phil.\ Mag.}\ [5],~24, p.~106, 1887), who used a similar +method, but whose electrodes were segments of spheres $9.76$~cm.\ +in radius. Liebig's results are as follows:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{0pt} +\begin{tabular}{c|c|c||c|c|c} +\multicolumn{6}{c}{\normalsize\textit{Potential Difference and Spark Length.\smallskip}}\\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark Length\\ in centimetres.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Electro- \\motive\\ Intensity.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length.} & +\parbox[c]{\TmpLen}{\centering Potential\\ Difference.} & +\parbox[c]{\TmpLen}{\centering Electro- \\motive\\ Intensity.} \\ +\hline +\tablespaceup$.0066$ & $\Z2.630$ & $398.5$ & $\Z.2398$ & $\Z30.622$ & $127.7$ \\ +$.0105$ & $\Z3.357$ & $319.7$ & $\Z.2800$ & $\Z35.196$ & $125.7$ \\ +$.0143$ & $\Z4.017$ & $280.9$ & $\Z.3245$ & $\Z39.816$ & $122.7$ \\ +$.0194$ & $\Z4.573$ & $235.7$ & $\Z.3920$ & $\Z47.001$ & $119.9$ \\ +$.0245$ & $\Z5.057$ & $206.4$ & $\Z.4715$ & $\Z55.165$ & $117.0$ \\ +$.0348$ & $\Z7.190$ & $206.6$ & $\Z.5588$ & $\Z63.703$ & $114.0$ \\ +$.0438$ & $\Z8.863$ & $195.5$ & $\Z.6226$ & $\Z69.980$ & $112.4$ \\ +$.0604$ & $10.866$ & $179.9$ & $\Z.7405$ & $\Z82.195$ & $111.0$ \\ +$.0841$ & $13.548$ & $161.1$ & $\Z.8830$ & $\Z95.540$ & $108.2$ \\ +$.0903$ & $13.816$ & $153.0$ & $\Z.9576$ & $102.463$ & $107.0$ \\ +$.1000$ & $15.000$ & $150.0$ & $1.0672$ & $110.775$ & $103.8$ \\ +$.1520$ & $20.946$ & $137.8$ & $1.1440$ & $117.489$ & $102.7$ \\ +$.1860$ & $24.775$ & $133.2$ & & &\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +The potential difference and electromotive intensity are measured +in electrostatic units. +\index{Electromotive intensity, required to produce a spark across a thin layer of gas@\subdashtwo required to produce a spark across a thin layer of gas}% + +\bigskip +\quad +\includegraphicssideways[!ht]{fig19}{Fig.~19.} + +Liebig's results for hydrogen, coal gas and carbonic acid as +well as air are exhibited graphically in \figureref{fig19}{Fig.~19}, where the nearly +straight curve represents the relation between potential difference +and spark length, and the other the relation between electromotive +intensity and spark length. The abscissae are the spark +lengths, the ordinates, the potential difference or electromotive +intensity. It will be seen that Liebig's values for the potential difference +required to produce a spark of given length are about $8$~per~cent.\ +higher than Baille's. It also appears from any of the preceding +tables that the electromotive intensity required to spark +across a layer of air varies very greatly with the thickness +%% -----File: 087.png---Folio 73------- +of the layer. Thus from Baille's result we see that the electromotive +intensity required to spark across a layer $.0015$~cm.\ +thick is about nine times that required to spark across a layer +$1$~cm.\ thick. The fact that a greater electromotive intensity +is required to spark across a thin layer of air than a thick one +\index{Kelvin, Lord, spark discharge}% +was discovered by Lord Kelvin~(l.c.) in 1860. + +%% -----File: 088.png---Folio 74------- + +\index{Baille, spark discharge}% +\Article{51} With regard to the relation between the potential difference~$V$ +and spark length~$l$, Baille deduced from his experiments +the relation +\[ +V^2 = 10500 (l + 0.08)l. +\] +\index{Chrystal on spark discharge}% +The agreement between the numbers calculated by this formula +and those found by experiment is not very close, and Chrystal +(\textit{Proc.\ Roy.\ Soc.\ Edin.}\ vol.~11. p.~487, 1882) has shown that for +spark lengths greater than $2$~millimetres the linear relation +\[ +V = 4.997 + 99.593 l +\] +represents Baille's results within experimental errors. This linear +relation is confirmed by Liebig's results, as the curves, \figureref{fig19}{Fig.~19}, +are nearly straight when the spark length is greater than one +millimetre. + +\index{Foster and Pryson, spark potential}% +\index{Pryson and Foster, spark potential}% +Carey Foster and Pryson (\textit{Chemical News},~49, p.~114, 1884) +found that the linear relation $V = \alpha + \beta l$ was the one which represented +best the results of their experiments on the discharge +through air at atmospheric pressure. + +\Article{52} When the spark length in air at atmospheric pressure is +less than about a millimetre, the curve which expresses the relation +between potential difference and spark length gets concave to +the axis along which the spark lengths are measured; that is, for +a given small increase in the spark length the increase in the +corresponding potential difference is greater when the sparks are +short than when they are long. For exceedingly short sparks there +seems to be considerable evidence that when the spark length is +reduced to a certain critical value there is a point of inflexion in +the potential difference curve, and that when the spark length is +reduced below this value the previous concavity is replaced by +convexity, the curve for very small spark lengths taking somewhat +the shape of the one in \figureref{fig20}{Fig.~20}. This indicates that the +potential difference required to produce a spark however short +cannot be less than a certain finite value, which for air at +ordinary temperatures is probably between $300$ and $400$~volts. +If a curve similar to \figureref{fig20}{Fig.~20} represents the relation between +potential difference and spark length, we see that it would be +possible under certain conditions to start a spark by pulling two +plates maintained at a constant potential difference further apart, +and to stop the spark by pushing the plates nearer together. + +\includegraphicsmid{fig20}{Fig.~20.} + +\Article{53} At atmospheric pressure the spark length at which the +potential difference is a minimum must, if such a length exist at +%% -----File: 089.png---Folio 75------- +all, be so small, that it would be very difficult to measure the +spark lengths with sufficient accuracy to investigate this point +completely; when however the air is at a lower pressure the +critical spark length is longer, and the investigation of this +problem easier. The evidence to which I have alluded in \artref{52}{Art.~52} +comes indirectly from an investigation (which we shall have to +consider later) made by Mr.~Peace in the Cavendish Laboratory, +Cambridge. Mr.~Peace's experiments were made with the view +of finding the relation between the potential difference in air and +the pressure when the spark length is kept constant, but as experiments +were made on this relation for sparks of many different +lengths, they furnish material for drawing the curve expressing +the relation between potential difference and spark length at +constant pressure. Such curves are given in \figureref{fig27}{Fig.~27}, and it +will be seen that at lower pressures they exhibit the peculiarities +referred to. The discharge took place between very large electrodes, +one of which was plane and the other a segment of a +sphere about $20$~cm.\ in radius, and as the difference of potential +was produced by a large number of storage cells, the equality of +whose E.~M.~F. was very carefully tested, the measurements of +the potential difference could be made with great accuracy. It +must be remembered, however, that the apparatus used was +designed for the purpose of determining the relation between +%% -----File: 090.png---Folio 76------- +potential difference and pressure for constant spark length, and +not for the relation between potential difference and spark length +for constant pressure, so that its indications on this point are +somewhat indirect. The conclusion that with very short sparks +the potential difference increases as the spark length diminishes +was, however, borne out to some extent by the observation that +when the voltage was just not sufficient (i.e.~was about two +volts too small) to spark across $.002$~of an inch at a pressure of +$20$~mm.\ of mercury, the same voltage would not send a spark +between the plates when the distance was reduced to $.001$ or +even to $.0004$~of an inch. Mr.~Peace also found that when he +removed the electrodes from the apparatus after sparks had +passed between them when they were very close together, the +part of the electrodes most affected by breathing upon them +formed an annulus at some little distance from the centre, indicating +that discharge had taken place most freely at distances +which were slightly greater than the shortest distance between +the electrodes, which was along the line joining their centres. +Mr.~Peace has more recently tested this result directly by placing +two spark gaps in parallel, the electrodes being parallel plane +plates. One pair of these electrodes were separated by a single +thickness of thin pieces of glass such as are used for cover +slips, while the other pair of electrodes were kept at a greater +distance apart by placing between them two or more of the +pieces of glass piled one on the top of the other. At atmospheric +pressure the spark passed across the short gap rather than the +long one, but when the pressure was reduced the reverse effect +took place, the spark going across the longer air gap before +any discharge could be detected across the shorter, and after +the spark had first passed across the longer path it required in +some cases an additional potential difference of more than $100$~volts +to make it go across the shorter as well. When in \artref{170}{Art.~170} +we consider discharge at very low pressures we shall find that +\index{Hittorf, discharge through gases}% +in some experiments of Hittorf's a long spark passed much +more easily than a very much shorter one between the same +electrodes; in this case however the electrodes were wires, and +the field before discharge was not uniform as in the case under +consideration. +\index{Peace, spark potential|)}% +%% -----File: 091.png---Folio 77------- + +\Subsection{Discharge when the Electric Field is not uniform.} + +\Article{54} In the experiments tabulated above the electrodes were so +large that the electric field between them might be considered +as uniform before the spark passed. Baille and Paschen have +however made some very interesting experiments on the potential +differences required to spark between spheres small enough to +make the variations in the electric field considerable. Baille's +results (\textit{Annales de Chimie et de Physique}~(5), 25, p.~531, 1882) +are given in the following table, the potential difference being +measured in absolute electrostatic units:--- +\medskip +\begin{center} +\tabletextsize +\settowidth{\TmpLen}{diameter.} +\setlength{\tabcolsep}{2pt} +\begin{tabular}{c|c|c|c|c|c|c|c} +\multicolumn{8}{c}{\normalsize\textit{Potential Differences: pressure $760$~{\upshape mm.}, + temperature $15°$\,to~$20°$\,{\upshape C}.}\smallskip}\\ +\hline +\parbox[c]{\TmpLen}{\tablespaceup\centering Spark\\Length\\ in cm.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Planes.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $6$~cm.~in \\ diameter.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $3$~cm.~in \\ diameter.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $1$~cm.~in \\ diameter.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.6$~cm.~in \\ diameter.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.35$~cm.~in\\ diameter.} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.1$~cm.~in \\ diameter.} \\ +\hline +$\tablespaceup\Z.05$ & $\Z\Z8.94$ & $\Z\Z8.96$ & $\Z\Z9.18$ & $\Z9.18$ & $\Z9.26$ & $\Z9.30$ & $\Z\mathbf{9.63}$ \\ +$\Z.10$ & $\Z14.70$ & $\Z14.78$ & $\Z14.99$ & $15.25$ & $15.53$ & $16.04$ & $\mathbf{16.10}$ \\ +$\Z.15$ & $\Z20.20$ & $\Z20.31$ & $\Z20.47$ & $21.28$ & $21.24$ & $\mathbf{21.87}$ & $19.58$ \\ +$\Z.20$ & $\Z25.42$ & $\Z25.59$ & $\Z25.95$ & $26.78$ & $26.82$ & $\mathbf{27.13}$ & $21.91$ \\ +$\Z.25$ & $\Z30.38$ & $\Z30.99$ & $\Z31.33$ & $32.10$ & $\mathbf{32.33}$ & $31.96$ & $23.11$ \\ +$\Z.30$ & $\Z35.35$ & $\Z36.12$ & $\Z36.59$ & $37.32$ & $\mathbf{37.38}$ & $36.29$ & $24.12$ \\ +$\Z.35$ & $\Z40.45$ & $\Z41.45$ & $\Z41.47$ & $\mathbf{42.48}$ & $42.16$ & $39.39$ & $25.34$ \\ +$\Z.40$ & $\Z45.28$ & $\Z46.34$ & $\Z46.77$ & $\mathbf{47.62}$ & $46.34$ & $41.77$ & $26.03$ \\ +$\Z.45$ & $\Z50.48$ & $\Z51.46$ & $\Z\mathbf{51.60}$ & $\mathbf{51.56}$ & $50.44$ & $43.76$ & $26.62$\tablespacedown\\ +\hline +$\tablespaceup\Z.40$ & $\Z44.80$ & $\Z45.00$ & $\Z45.00$ & $\mathbf{45.50}$ & $44.80$ & $41.07$ & $26.58$ \\ +$\Z.45$ & $\Z49.63$ & $\Z50.33$ & $\Z49.63$ & $\mathbf{52.04}$ & $48.42$ & $43.29$ & $28.49$ \\ +$\Z.50$ & $\Z54.35$ & $\Z\mathbf{55.06}$ & $\Z\mathbf{54.96}$ & $\mathbf{54.66}$ & $53.25$ & $47.21$ & $30.00$ \\ +$\Z.60$ & $\Z63.82$ & $\Z\mathbf{65.23}$ & $\Z\mathbf{65.23}$ & $\mathbf{65.23}$ & $59.69$ & $53.75$ & $31.51$ \\ +$\Z.70$ & $\Z74.09$ & $\Z\mathbf{75.40}$ & $\Z73.79$ & $72.28$ & $64.22$ & $56.47$ & $32.92$ \\ +$\Z.80$ & $\Z84.83$ & $\Z\mathbf{87.98}$ & $\Z84.76$ & $77.61$ & $67.75$ & $58.79$ & $33.82$ \\ +$\Z.90$ & $\Z94.72$ & $\Z\mathbf{97.44}$ & $\Z94.62$ & $80.13$ & $70.56$ & $59.09$ & $34.93$ \\ +$1.00$ & $105.49$ & $\mathbf{112.94}$ & $104.69$ & $83.05$ & $72.38$ & $59.49$ & $36.24$\tablespacedown\\ +\hline +\end{tabular} +\end{center} + +From this table Baille concludes that for a given length of +spark between two equal spheres, one charged and insulated +and the other put to earth, the potential difference varies with +the diameter of the sphere; starting from the plane the potential +difference at first increases with the curvature, and attains a +maximum when the sphere has a certain diameter. This critical +diameter of the sphere depends upon the spark length, the +shorter the spark the smaller the critical diameter. In the preceding +table the maximum potential differences have been +printed in bolder type. +%% -----File: 092.png---Folio 78------- + +The two parts into which the table is divided by the horizontal +line correspond to two different sets of experiments. + +Paschen's results (\textit{Wied.\ Ann.}~37, p.~79, 1889) are given in the +following table:--- +\begin{center} +\tabletextsize +\settowidth{\TmpLen}{in centimetres.}% +\begin{tabular}{c|c|c|c} +\multicolumn{4}{c}{\normalsize\textit{Potential Difference at first Spark: pressure $756~\text{mm.}$}}\\ +\multicolumn{4}{c}{\normalsize\textit{mean temperature $15°$\,C.}\medskip}\\ +\multicolumn{4}{c}{SHORT SPARKS.}\medskip \\ +\hline +\parbox[c]{\TmpLen}{\tablespaceup\centering Spark Length\\ in centimetres.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $1$~cm.\ radius} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.5$~cm.\ radius} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.25$~cm.\ radius} \\ +\hline +\tablespaceup$.01$ & $\Z3.38$ & $\Z3.42$ & $\Z3.61$ \\ +$.02$ & $\Z5.04$ & $\Z5.18$ & $\Z5.58$ \\ +$.03$ & $\Z6.62$ & $\Z6.87$ & $\Z6.94$ \\ +$.04$ & $\Z8.06$ & $\Z8.22$ & $\Z8.43$ \\ +$.05$ & $\Z9.56$ & $\Z9.75$ & $\Z9.86$ \\ +$.06$ & $10.81$ & $10.87$ & $11.19$ \\ +$.07$ & $11.78$ & $12.14$ & $12.29$ \\ +$.08$ & $13.40$ & $13.59$ & $13.77$ \\ +$.09$ & $14.39$ & $14.70$ & $14.89$ \\ +$.10$ & $15.86$ & $15.97$ & $16.26$ \\ +$.11$ & $16.79$ & $17.08$ & $17.26$ \\ +$.12$ & $18.28$ & $18.42$ & $18.71$ \\ +$.14$ & $20.52$ & $20.78$ & $21.26$\tablespacedown \\ +\hline +\end{tabular} + +\begin{tabular}{c|c|c|c} +\multicolumn{4}{c}{LONG SPARKS.}\medskip \\ +\hline +\parbox[c]{\TmpLen}{\tablespaceup\centering Spark Length\\ in centimetres.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $1$~cm.\ radius} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.5$~cm.\ radius} & +\parbox[c]{\TmpLen}{\centering Spheres\\ $.25$~cm.\ radius} \\ +\hline +\tablespaceup$\Z.10$ & $15.96$ & $16.11$ & $\mathbf{16.45}$ \\ +$\Z.15$ & $21.94$ & $22.17$ & $\mathbf{22.59}$ \\ +$\Z.20$ & $27.59$ & $27.87$ & $\mathbf{28.18}$ \\ +$\Z.25$ & $32.96$ & $33.42$ & $\mathbf{33.60}$ \\ +$\Z.30$ & $38.59$ & $\mathbf{39.00}$ & $38.65$ \\ +$\Z.35$ & $43.93$ & $\mathbf{44.32}$ & $43.28$ \\ +$\Z.40$ & $49.17$ & $\mathbf{49.31}$ & $47.64$ \\ +$\Z.45$ & $\mathbf{54.37}$ & $54.18$ & $51.56$ \\ +$\Z.50$ & $\mathbf{59.71}$ & $59.03$ & $54.67$ \\ +$\Z.55$ & $\mathbf{64.60}$ & $63.35$ & $57.27$ \\ +$\Z.60$ & $\mathbf{69.27}$ & $67.80$ & $59.95$ \\ +$\Z.70$ & $\mathbf{78.51}$ & $75.04$ & $63.14$ \\ +$\Z.80$ & $\mathbf{87.76}$ & $81.95$ & $66.39$ \\ +$\Z.90$ & & & $68.65$ \\ +$1.00$ & & & $70.68$ \\ +$1.20$ & & & $74.94$ \\ +$1.50$ & & & $79.42$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +Here the heavy type again denotes the maximum potential +differences. +%% -----File: 093.png---Folio 79------- + +\medskip +\includegraphicsmid{fig21}{Fig.~21.} + +These results are represented graphically in \figureref{fig21}{Fig.~21}. They +confirm Baille's conclusion that for a spark of given length the +potential difference is a maximum when the spheres have a certain +critical diameter, the critical diameter increasing with the +length of the spark. +%% -----File: 094.png---Folio 80------- +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +\index{Schuster, discharge through gases}% + +\includegraphicsmid{fig22}{Fig.~22.} + +Both Baille's and Paschen's measurements show that when +the spheres are very small, the potential difference required to +produce a spark of given length is, if the spark length is not too +small, much less than the potential difference required to produce +the same length of sparks between parallel plates. When the +spark passes between pointed electrodes the potential differences +are still smaller. This effect is clearly shown in \figureref{fig22}{Fig.~22}, which +is taken from a paper by De~la~Rue and Hugo Müller (\textit{Phil.\ +Trans.}\ 1878, Pt.~1.\ p.~55), and which contains curves representing +the relation between potential difference and spark length when +the electrodes are (i)~two plates, (ii)~two spheres, one $3$~cm.\ in +radius the other $1.5$~cm.\ in diameter, (iii)~two concentric cylinders, +(iv)~a plane and a point, (v)~two points. It will be noticed +that the two points, which give the greatest striking distance +for long sparks, give the least for short sparks. + +\Article{55} If the spark length between parallel plates is taken as +unity, the spark length corresponding to various potential differences +for different kinds of electrodes was found by De~la~Rue +and Müller to be as follows (\textit{Proc.\ Roy.\ Soc.}~36, p.~157, +1883):--- +\begin{center} +\tabletextsize +\settowidth{\TmpLen}{Striking distance for point and plane\quad}% +\begin{tabular}{@{}l@{}cccccc@{}} +\parbox[b]{\TmpLen}{\hangindent=1em Number of cells, each cell having\\ +an E.M.F. of $1.03$~volts\mdotfill} & $1000$ & $3000$ & $6000$ & $9000$ & $12,000$ & $15,000$ \\ +\parbox[c]{\TmpLen}{Striking distance for point and plane\quad} & $.60$ & $2.09$ & $3.82$ & $3.89$ & $3.58$ & $3.30$ \\ +\parbox[c]{\TmpLen}{Striking distance for two points\mdotfill} & $.84$ & $1.94$ & $4.65$ & $4.65$ & $4.18$ & $3.68$ +\end{tabular} +\end{center} + +This table would appear to indicate that the ratio of the +striking distance for pointed electrodes to that of planes attains +a maximum. It must however be remembered that when the +sparks are long the conditions are not the same in the two cases; +in the case of the plates the discharge takes place abruptly, +while when the electrodes are pointed a brush discharge starts +long before the spark passes, and materially modifies the conditions. + +\Article{56} Schuster (\textit{Phil.\ Mag.}\ [5]~29, p.~182, 1890) has, by the aid of +Kirchhoff's solution of the problem of the distribution of electricity +over two spheres, calculated from Baille's and Paschen's +experiments the maximum electromotive intensity in the field +when the spark passed. The results for Baille's experiments +are given in Table~1, for Paschen's in Table~2. +%% -----File: 095.png---Folio 81------- + +\begin{center} +\setlength{\TmpLen}{0.1\linewidth} +\tabletextsize +\setlength{\tabcolsep}{4pt} +\begin{tabular}{c||c|c|c|c|c|c|c} +\multicolumn{8}{c}{TABLE 1.\medskip} \\ +\multicolumn{8}{c}{\normalsize\textit{Value of Maximum Electromotive Intensity in Electrostatic Units.}\medskip} \\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length\\ in cm.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Planes} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $6$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $3$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $1$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $.6$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $.35$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $.1$~cm.} \\ +\hline +$\tablespaceup\Z.05$ & $179$ & $180$ & $186$ & $190$ & $197$ & $206$ & $292$ \\ +$\Z.10$ & $147$ & $149$ & $153$ & $163$ & $176$ & $198$ & $376$ \\ +$\Z.15$ & $135$ & $138$ & $141$ & $157$ & $170$ & $206$ & $425$ \\ +$\Z.20$ & $127$ & $131$ & $137$ & $154$ & $170$ & $219$ & $460$ \\ +$\Z.25$ & $122$ & $127$ & $134$ & $154$ & $180$ & $236$ & $478$ \\ +$\Z.30$ & $118$ & $124$ & $130$ & $156$ & $189$ & $253$ & $494$ \\ +$\Z.35$ & $116$ & $122$ & $129$ & $159$ & $197$ & $263$ & $516$ \\ +$\Z.40$ & $113$ & $122$ & $129$ & $164$ & $204$ & $272$ & $528$ \\ +$\Z.45$ & $112$ & $120$ & $127$ & $166$ & $214$ & $278$ & $540$\tablespacedown \\ +\hline +$\tablespaceup\Z.40$ & $112$ & $118$ & $124$ & $157$ & $197$ & $268$ & $539$ \\ +$\Z.45$ & $110$ & $119$ & $122$ & $167$ & $206$ & $275$ & $578$ \\ +$\Z.50$ & $109$ & $117$ & $125$ & $166$ & $218$ & $296$ & $608$ \\ +$\Z.60$ & $106$ & $116$ & $125$ & $181$ & $233$ & $327$ & $639$ \\ +$\Z.70$ & $106$ & $117$ & $126$ & $188$ & $234$ & $339$ & $667$ \\ +$\Z.80$ & $106$ & $123$ & $130$ & $192$ & $250$ & $349$ & $685$ \\ +$\Z.90$ & $105$ & $120$ & $132$ & $191$ & $255$ & $349$ & $708$ \\ +$1.00$ & $106$ & $128$ & $133$ & $194$ & $258$ & $349$ & $733$\tablespacedown \\ +\hline +\end{tabular} + +\begin{tabular}{c||c|c|c|c|c|c|c} +\multicolumn{8}{c}{TABLE 2.\medskip} \\ +\multicolumn{8}{c}{\normalsize\textit{Maximum Electromotive Intensity in Electrostatic Units.}\medskip} \\ +\hline +\parbox[c]{\TmpLen}{\centering\tablespaceup Spark\\ Length\\ in cm.\tablespacedown} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $2$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $1$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $.5$~cm.} & +\parbox[c]{\TmpLen}{\centering Spark\\ Length\DPtypo{}{\\ in cm}.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $2$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $1$~cm.} & +\parbox[c]{\TmpLen}{\centering Spheres,\\ diameter\\ $.5$~cm.} \\ +\hline +$\tablespaceup.01$ & $336$ & $347$ & $372$ & $\Z.10$ & $166$ & $175$ & $190$ \\ +$.02$ & $258$ & $262$ & $277$ & $\Z.15$ & $155$ & $165$ & $190$ \\ +$.03$ & $224$ & $236$ & $240$ & $\Z.20$ & $148$ & $162$ & $198$ \\ +$.04$ & $206$ & $213$ & $222$ & $\Z.25$ & $145$ & $161$ & $204$ \\ +$.05$ & $194$ & $202$ & $215$ & $\Z.30$ & $143$ & $163$ & $215$ \\ +$.06$ & $184$ & $190$ & $202$ & $\Z.35$ & $143$ & $166$ & $226$ \\ +$.07$ & $175$ & $183$ & $193$ & $\Z.40$ & $142$ & $170$ & $236$ \\ +$.08$ & $172$ & $179$ & $192$ & $\Z.45$ & $142$ & $174$ & $249$ \\ +$.09$ & $165$ & $174$ & $187$ & $\Z.50$ & $144$ & $180$ & $256$ \\ +$.10$ & $164$ & $171$ & $187$ & $\Z.55$ & $145$ & $184$ & $265$ \\ +$.11$ & $160$ & $167$ & $183$ & $\Z.60$ & $145$ & $190$ & $272$ \\ +$.12$ & $159$ & $167$ & $185$ & $\Z.70$ & $148$ & $196$ & $281$ \\ +$.14$ & $154$ & $164$ & $187$ & $\Z.80$ & $151$ & $205$ & $288$ \\ + & & & & $\Z.90$ & & & $293$ \\ + & & & & $1.00$ & & & $301$ \\ + & & & & $1.20$ & & & $312$ \\ + & & & & $1.50$ & & & $327$\tablespacedown \\ +\hline +\end{tabular} +\end{center} +%% -----File: 096.png---Folio 82------- + +\index{Gaugain, spark discharge}% +\Article{57} It will be seen from these tables that the smaller the +spheres, or in other words the more irregular the electric field, +the greater the value of the maximum electromotive intensity. +This is sometimes expressed by saying that the curvature of +the electrodes increases the electric strength of the gas, and +Gaugain (\textit{Annales de Chimie et de Physique}, [iv]~8, p.~75, 1866) +has found that when the spark passes between two coaxial +cylinders, the maximum value~$R$ of the electromotive intensity +can be expressed by an equation of the form +\[ +R = \alpha + \beta r^{-\frac{1}{3}}, +\] +where $\alpha$~and~$\beta$ are constants and $r$~is the radius of the inner +cylinder. + +\Article{58} The variations in the value of the electromotive intensity +are so great that they prove that it is not the value of the +electromotive intensity which primarily determines whether or +not discharge must take place; and it is probable that the use of +this quantity as the measure of the electric strength has retarded +the progress of this subject by withdrawing attention from the +most important cause of the discharge to this which is probably +merely secondary. + +\index{Electromotive intensity, required to produce a spark in a variable field@\subdashtwo required to produce a spark in a variable field}% +\index{Spark, potential difference required to produce in a variable field@\subdashone potential difference required to produce in a variable field}% +\Article{59} The following results taken from Paschen's experiments +show that when the sparks are not too long the variations in +the electromotive intensity are very much greater than the variations +in the potential difference; suggesting that for such +sparks the potential difference is the most important consideration. +\begin{center} +\tabletextsize +\settowidth{\TmpLen}{Radius of Electrodes}% +\begin{tabular}{c|l|l|l|@{\;}l} +\hline +\parbox[c]{\TmpLen}{\tablespaceup\centering Radius of Electrodes\\ in cm.\tablespacedown} & +\PadTo{99.9}{1.} & \PadTo{99.9}{.5} & \PadTo{99.9}{.25} & \\ +\hline +\tablespaceup Potential Difference & $13.4$ & $13.6$ & $13.8$ & \multirow{2}{*}{$\Big\}$ Spark length $.08$~cm.} \\ +Maximum Intensity & $172$ & $179$ & $192$ & \tablespacedown \\ +\tablespaceup Potential Difference & $20.5$ & $20.8$ & $21.3$ & \multirow{2}{*}{$\Big\}$ Spark length $.14$~cm.} \\ +Maximum Intensity & $154$ & $164$ & $187$ & \tablespacedown \\ +\tablespaceup Potential Difference & $49.2$ & $49.3$ & $47.6$ & \multirow{2}{*}{$\Big\}$ Spark length $.40$~cm.} \\ +Maximum Intensity & $142$ & $170$ & $236$ &\tablespacedown \\ +\tablespaceup Potential Difference & $87.8$ & $81.9$ & $66.4$ & \multirow{2}{*}{$\Big\}$ Spark length $.80$~cm.} \\ +Maximum Intensity & $151$ & $2054$ & $288$ &\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\Article{60} We can explain by the following geometrical illustration +the two effects produced by the irregularity of the field---the +diminution in the potential difference, and the increase in the +maximum electromotive intensity. When a discharge is passing +%% -----File: 097.png---Folio 83------- +through gas, we shall see later on, from the consideration of the +discharge at low pressures, reasons for believing that the distribution +of potential during discharge may be approximately +represented by the equation +\[ +V = \alpha + \beta l, +\] +where $\alpha$ and~$\beta$ are constants and $l$~the distance from the +negative electrode. +\includegraphicsouter{fig23}{Fig.~23.} +If the curve representing the distribution +of potential before discharge cuts the curve representing the +distribution after discharge, a spark will pass, while if it does +not cut it, no discharge can take place. + +In \figureref{fig23}{Fig.~23}, \smallsanscap{A},~\smallsanscap{B} represent the electrodes, \smallsanscap{CD}~the distribution +of potential during the discharge. +If the electric field is uniform +the curve which represents +the distribution of potential before +the spark passes is a straight line +such as~\smallsanscap{AE}, as the intensity of the +field increases \smallsanscap{E}~moves higher and +higher, the first point at which it +intersects the curve representing the +distribution of potential after discharge +being~\smallsanscap{D}. In this case the +difference of potential between the +electrodes when the spark passes is~\smallsanscap{BD}, so that the relation +between the potential difference~$V$ and the spark length~$l$ is +\[ +V = \alpha + \beta l. +\] +When however the electric field is not uniform it is possible +for the curve representing the potential before discharge to +intersect the potential curve after discharge, even though the +difference of potential before discharge is less than~\smallsanscap{BD}. +will be evident from \figureref{fig23}{Fig.~23}, where the curved line represents +the distribution of potential in an irregular field. Here we have +a very rapid change in potential in the neighbourhood of one +of the electrodes, followed by a comparatively slow rate of change +midway between them. In this case the curves intersect and a +discharge would take place, though the difference of potential +between the electrodes is less than that required for sparking in +a uniform field. Thus for equal spark lengths the potential +difference may be less when the field is variable than when it is +%% -----File: 098.png---Folio 84------- +uniform. Again, we notice that the slope of this curve in the +neighbourhood of the electrode~\smallsanscap{A} is steeper than that of a line +joining \smallsanscap{A}~and~\smallsanscap{D}, in other words the maximum electromotive +intensity when discharge takes place is greater when the field +is variable than when it is uniform. Both these results are confirmed +by Baille's and Paschen's observations. + +For a theory of the spark discharge the reader is referred to +the discussion at the end of this chapter. + +\Article{61} It is sometimes said that the reason a thin layer of gas is +electrically stronger than a thick one is, that a film of condensed +gas is spread over the surface of the electrodes, and that this film +is electrically stronger than the free gas. This consideration however, +\index{Chrystal on spark discharge}% +as Chrystal (\textit{Proc.\ Roy.\ Soc.\ Edin.},~11, 1881--2, p.~487) +has pointed out, is quite incapable of explaining the variation in +electric strength, for it is evident that if this were all that had to +be taken into account the discharge would pass whenever the +electromotive intensity was great enough to break through this +film of condensed gas, so that this intensity would be constant +when the spark passed whatever the thickness of the layer +of free gas. + +\nbpagebreak +\Subsection{Connection between Spark Potential and the Pressure of the Gas.} + +\index{Pressure, connection between and spark potential@Pressure, connection between and spark potential|indexetseq}% +\index{Spark, potential effect of pressure on@\subdashone potential effect of pressure on|indexetseq}% +\index{Critical pressure@`Critical' pressure}% +\index{Pressure, critical@\subdashone critical}% +\Article{62} The general nature of this connection is as follows: as +the pressure of the gas diminishes the difference of potential required +to produce a spark of given length also diminishes, until +the pressure falls to a critical value depending upon the length +of the spark, the nature of the gas, the shape and size of the +electrodes and of the vessel in which the gas is contained; at +this pressure the potential difference is a minimum, and any +further diminution in the pressure is accompanied by an increase +in the potential difference. The critical pressure varies very +\index{Peace, spark potential|indexetseq}% +greatly with the length of the spark; in Mr.~Peace's experiments, +which we shall consider later, when the spark length was about +$1/100$~of a millimetre, the critical pressure was that due to about +$250$~mm.\ of mercury, while for sparks several millimetres long +the critical pressure was less than that due to $1$~mm.\ of mercury. + +\includegraphicsmid[!b]{fig24}{Fig.~24.} + +\Article{63} At pressures considerably greater than the critical pressure, +the curve which represents the relation between potential +difference and pressure, the spark length being constant, approximates +to a straight line, or more accurately to a slightly curved +%% -----File: 099.png---Folio 85------- +\index{Wolf, effect of pressure on spark potential}% +hyperbola concave with respect to the axis along which the +pressures are measured. Thus Wolf, who has determined (\textit{Wied.\ +Ann.}~37.\ 306, 1889) the potential difference required to produce a +spark through air, hydrogen, carbonic acid, oxygen and nitrogen +at pressures varying from $1$~to~$5$ atmospheres, found that the +electromotive intensity,~$y$, required to produce a spark across a +length of $1$~mm.\ between electrodes $5$~cm.\ in radius when the +pressure was $x$~atmospheres, could be expressed by the following +equations:--- +\begin{center} +\begin{tabular}{p{15em}@{}l} +For hydrogen \wdotfill & $y = 65.09x + 62$. \\ +For oxygen \wdotfill & $y = \PadTo[l]{65.09x}{96.0x} + 44$. \\ +For air \wdotfill & $y = \PadTo[l]{65.09x}{107x} + 39$. \\ +For nitrogen \wdotfill & $y = 120.8x + 50$. \\ +For carbonic acid \wdotfill & $y = 102.2x + 72$. +\end{tabular} +\end{center} + +\includegraphicsmid[!t]{fig25}{Fig.~25.} + +\index{Baille, spark discharge}% +\index{Macfarlane, spark potential}% +\index{Paschen, spark discharge}% +\Article{64} For pressures less than one atmosphere the connection +between spark length and pressure has been investigated by +Baille (\textit{Annales de Chimie et de Physique}, [5]~29, p.~181, 1883), +Macfarlane (\textit{Phil.\ Mag.}\ [5]~10, p.~389, 1880), and Paschen (\textit{Wied.\ +Ann.}~37, p.~69, 1889), who have found that the relation is +graphically represented by very slightly curved portions of a hyperbola. +%% -----File: 100.png---Folio 86------- +Paschen (\textit{l.c.}\ p.~91) made the interesting observation that +as long as the product of the density and spark length is constant +the sparking potential is for a considerable range of pressure +constant for the same gas. This result can also be expressed by +saying that the sparking potential for a gas can be expressed in +terms of the ratio of the spark length to the mean free path of +the molecules of the gas. The curves given in \figureref{fig24}{Fig.~24}, which +represent for air, hydrogen and carbonic acid the relation between +the spark potential in electrostatic units as ordinates, and the +products of the pressure of the gas in centimetres of mercury +and the spark length in centimetres as abscissæ, seem to show +that this relation is approximately a linear one. + +\includegraphicsouter{fig26}{Fig.~26.} + +\Article{65} The preceding experiments were made at pressures much +greater than the critical pressure. A series of very interesting +experiments has lately been made by Mr.~Peace in the +Cavendish Laboratory, Cambridge, on the shape of these curves +in the neighbourhood of the critical pressure. In these experiments +the potential difference could be determined with great +accuracy, as it was produced by a large number of small storage +%% -----File: 101.png---Folio 87------- +cells whose E.~M.~F. could very easily be determined. Mr.~Peace's +curves are represented +in Figs.~\figureref{fig25}{25}, \figureref{fig26}{26}, \figureref{fig27}{27},~\figureref{fig28}{28}. +\figureref{fig25}{Fig.~25} represents +the relation between +potential difference in +air and pressure for +spark lengths varying +from $.0010$~cm.\ to +$.2032$~cm. \figureref{fig26}{Fig.~26} represents +the relation +between electromotive +intensity and +pressure for the same +spark lengths, and +\figureref{fig27}{Fig.~27} the relation +between potential difference +and spark +length for a series of +different pressures: +the curve representing the relation between electromotive +intensity and spark length is given in \figureref{fig28}{Fig.~28}. These curves +%% -----File: 102.png---Folio 88------- +will be seen to present several points of great interest. In the +\index{Critical pressure, effect of spark length on@\subdashtwo effect of spark length on}% +\index{Spark, length, effect of on critical pressure@\subdashone length, effect of on critical pressure}% +first place, \figureref{fig25}{Fig.~25} shows how much the critical pressure depends +upon the spark length; this will also be seen from the following +table:--- +\includegraphicsmid[!t]{fig27}{Fig.~27.} +\begin{center} +\tabletextsize +\begin{tabular}{c|c|c} +\hline +\settowidth{\TmpLen}{Spark Length.}% +\parbox[c]{\TmpLen}{\centering Spark Length.} & +\settowidth{\TmpLen}{Potential Difference.}% +\parbox[c]{\TmpLen}{\tablespaceup\centering Minimum\\ Potential Difference.\tablespacedown} & +\settowidth{\TmpLen}{Critical Pressure.}% +\parbox[c]{\TmpLen}{\centering Critical Pressure.} \\ +\hline +\tablespaceup$.0010$~cm.\Z & $326$~volts. & $250$~mm. \\ +$.00254$~cm. & $330$~volts. & $150$~mm. \\ +$.00508$~cm. & $333$~volts. & $110$~mm. \\ +$.01016$~cm. & $354$~volts. & $\Z55$~mm. \\ +$.02032$~cm. & $370$~volts. & $\Z35$~mm.\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +Thus when the spark length was increased twenty-fold the +critical pressure was reduced from $250$~mm.\ to~$35$~mm. Another +very remarkable feature is the small variation in the minimum +potential difference required to produce the spark. In the preceding +table there is a very considerable range of pressure, but +the variation in the potential difference is comparatively small. +Mr.~Peace too made the interesting observation that he could +not produce a spark however near he put the electrodes together +%% -----File: 103.png---Folio 89------- +or however the pressure was altered, if the potential difference +was less than something over $300$~volts. Gases in this respect +seem to resemble electrolytes which require a finite difference of +potential to produce a steady current through them. This constancy +in the minimum value of the potential required to produce +a spark seems additional evidence that the passage of the +spark is regulated more by the value of the potential difference +than by that of the electromotive intensity. Another thing to +be remarked about the curves in \figureref{fig25}{Fig.~25} is the way in which +they get flatter and flatter as the spark length diminishes: the +flatness of the curve corresponding to the spark length $.0010$~cm., +or $.0004$~inch, is so remarkable that I give the numbers from +which it was drawn:--- +\begin{center} +\tabletextsize +\begin{tabular}{c|c|c} +\multicolumn{3}{c}{\normalsize\textit{Spark Length} $.00101$~cm.\medskip} \\ +\hline +\settowidth{\TmpLen}{Pressure in mm.}% +\parbox[c]{\TmpLen}{\centering\tablespaceup Pressure in mm.\\ of Mercury.\tablespacedown} & +\settowidth{\TmpLen}{Potential Difference.}% +\parbox[c]{\TmpLen}{\centering Potential Difference\\ in Volts.} & +\settowidth{\TmpLen}{Electromotive}% +\parbox[c]{\TmpLen}{\centering Electromotive\\ Intensity.} \\ +\hline +$\tablespaceup\Z20$ & $433$ & $1420$ \\ +$\Z30$ & $398$ & $1310$ \\ +$\Z40$ & $380$ & $1245$ \\ +$\Z50$ & $370$ & $1215$ \\ +$\Z60$ & $357$ & $1170$ \\ +$\Z70$ & $353$ & $1160$ \\ +$\Z80$ & $349$ & $1145$ \\ +$\Z90$ & $346$ & $1135$ \\ +$100$ & $343$ & $1125$ \\ +$120$ & $337$ & $1105$ \\ +$140$ & $332$ & $1090$ \\ +$160$ & $330$ & $1085$ \\ +$180$ & $329$ & $1080$ \\ +$200$ & $328$ & $1075$ \\ +$240$ & $326$ & $1070$ \\ +$280$ & $327$ & $1072$ \\ +$300$ & $328$ & $1075$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\includegraphicsmid{fig28}{Fig.~28.} + +The curves representing the relation between potential difference +and pressure for different lengths of spark cut each other; this +indicates that at a pressure lower than that where the curves cut +it requires a greater potential difference to produce the short +spark than it does the long one. This point has already been +considered in \artref{53}{Art.~53}. + +\Article{66} The connection between the critical pressure and the +spark length proves that the gas at the critical pressure when +conveying the electric discharge has a structure of which the +linear measure of the coarseness is comparable with the spark +length. This spark length is very much greater than the mean +%% -----File: 104.png---Folio 90------- +free path of the molecules, and thus these experiments show that +a gas conveying electrical discharge possesses a much coarser +structure than that recognized by the ordinary Kinetic Theory of +Gases. For the nature of this structure we must refer to the +general theory of the electrical discharge given at the end of this +chapter. + +\Article{67} Although the magnitude of the critical pressure depends, +as we have seen, to a very great extent on the distance between +the electrodes, the actual existence of a critical pressure does not +seem to depend on the presence of electrodes. In \artref{74}{Art.~74} a +method is described by which an endless ring discharge can be +produced in a bulb containing gas at a low pressure; in this case +the discharge is in the gas throughout the whole of its course, +and there are no electrodes. If in such an experiment the bulb +is connected to an air pump it will be found that when the +pressure of the gas in the bulb is high no discharge at all is +visible; as however the pressure is reduced a discharge gradually +appears and increases in brightness until the pressure is reduced +to a small fraction of a millimetre, when the brightness is a +maximum; when the pressure is reduced below this value the +discharge has greater difficulty in passing, it gets dimmer and +dimmer, and finally stops altogether when the exhaustion is very +great. This experiment shows that there is a critical pressure +even when there are no electrodes, but that it is very much lower +than in an ordinary sized tube when electrodes are used. + +\index{Muller@Müller and de la Rue, electric discharge}% +\index{De la Rue and Müller, discharge through gases}% +\Article{68} De~la~Rue and Hugo Müller (\textit{Proc.\ Roy.\ Soc.}~35, p.~292, +1883), using the ordinary discharge with electrodes, found that +the critical pressure depends on the diameter of the tube in +which the rarefied gas is confined, the critical pressure getting +lower as the diameter of the tube is increased. + +\Subsection{Potential Difference required to produce Sparks through +various Gases.} +\index{Faraday, spark potential through different gases@\subdashone spark potential through different gases}% +\index{Potential difference required to produce a spark in different gases@\subdashtwo required to produce a spark in different gases}% +\index{Spark, potential in different gases@\subdashone potential in different gases}% + +\Article{69} The potential difference required to send a spark between +the same electrodes, separated by the same distance, depends, as +Faraday found, on the nature of the gas surrounding the electrodes: +thus, for example, the potential difference required to +produce a spark of given length in hydrogen is much less +than in air. Measurements of the potential differences required +to produce discharge through a series of gases have been made +%% -----File: 105.png---Folio 91------- +\index{Baille, spark discharge}% +\index{Liebig, spark potential}% +\index{Paschen, spark discharge}% +by, among others, Faraday, Baille (\textit{Annales de Chimie et de +Physique}, [5]~29, p.~181, 1883), Liebig (\textit{Phil.\ Mag.}\ [5]~24, p.~106, +1887), Paschen (\textit{Wied.\ Ann.}~37, p.~69, 1889). The results obtained +by different observers seem to differ very largely. This will be +seen from the following table, in which Paschen gives the ratio +of the potential difference required to spark across hydrogen or +carbonic acid, to the potential difference required to spark across +a layer of air of the same thickness, the pressure for all the gases +being $750$~mm.\ of mercury. +\begin{center} +\tabletextsize +\begin{tabular}{c|c|c|c|c|c|c} +\hline +\settowidth{\TmpLen}{Spark length in}% +\multirow{2}{\TmpLen}{\parbox[c]{\TmpLen}{\centering Spark length in\\ centimetres.}} & +\multicolumn{3}{c|}{\tablespaceup Hydrogen.} & \multicolumn{3}{c}{Carbonic Acid.} \\ +\cline{2-7} +&\tablespaceup Baille. & Liebig. & Paschen. & Baille. & Liebig. & Paschen.\tablespacedown \\ +\hline +\tablespaceup$.1$ & $.49$ & $.873$ & $.639$ & $1.67$ & $1.20\Z$ & $1.05\Z$ \\ +$.2$ & $.49$ & $.787$ & $.578$ & $1.24$ & $1.16\Z$ & $\Z.988$ \\ +$.3$ & $.50$ & $.753$ & $.560$ & $\Z.94$ & $1.07\Z$ & $\Z.962$ \\ +$.4$ & $.50$ & $.704$ & $.553$ & $\Z.76$ & $1.03\Z$ & $\Z.930$ \\ +$.5$ & $.50$ & $.670$ & $.548$ & & $\Z.994$ & $\Z.910$ \\ +$.6$ & & $.656$ & $.555$ & & $\Z.974$ & $\Z.940$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +It will be seen that, though the numbers got by different +observers differ very widely, they all agree in making carbonic +acid stronger than air for short sparks and weaker than it for +long. This would indicate that in the formula +\[ +V = \alpha + \beta l, +\] +which gives the spark potential~$V$ in terms of the spark length~$l$, +$\alpha$~for carbonic acid is greater than $\alpha$~for air, while $\beta$~for carbonic +acid is less than $\beta$~for air. + +It will be seen from \figureref{fig24}{Fig.~24}, which contains Paschen's curves +showing the relation between potential difference and pressure +for air, hydrogen and oxygen, that these curves cut each other; +thus the relation between their `electric strengths' depends to +a large extent upon the pressure. Liebig's curves for air, +hydrogen, carbonic oxide and coal gas were given in \figureref{fig19}{Fig.~19}. + +\index{Rontgen, discharge through gases@\subdashone discharge through gases}% +\Article{70} Röntgen (\textit{Göttinger Nachrichten}, 1878, p.~390) arrived at +the conclusion that the potential difference required to produce +a spark of given length in different gases was, approximately, +inversely proportional to the mean free path of the molecules of +the gas. This approximation, if it exists at all, must be exceedingly +rough, for we have seen that the relation between the +potential differences required to spark through different gases +%% -----File: 106.png---Folio 92------- +depends on the spark length and the pressure of the gases. If +the result found by Mr.~Peace for air (\artref{65}{Art.~65}),---that the +minimum potential difference required to produce a spark varied +very little with the spark length,---were to hold for other gases, +there would be much more likelihood of this minimum potential +difference being connected with some physical or chemical +property of the gas, than the potential difference required to +produce a spark of arbitrary length at a pressure chosen at +random being so connected. + +\Article{71} If a permanent gas in a closed vessel be heated up to +\index{Spark, x effect of temperature on@\subdashtwo effect of temperature on}% +\index{Temperature, effect of, on spark potential}% +\index{Cardani, effect of temperature on electric strength of gases}% +$300°$\,C, the discharge potential does not change (see Cardani, +\textit{Rend.\ della R.~Acc.\ dei Lincei},~4, p.~44, 1888; J.~J. Thomson, +\textit{Proc.\ Camb.\ Phil.\ Soc.}, vol.~6, p.~325, 1889): if however the +vessel be open so that the pressure remains constant, there will +be a diminution in the discharge potential due to the diminution +in density. When the temperature gets so high that chemical +changes such as dissociation take place in the gas the discharge +potential may fall to zero. + +\index{Damp air, potential required to spark through}% +A great number of experiments have been made on the +relative `electric strengths' of damp and dry air. The only +observer who seems to have found any difference is Baille, and +in his case the difference was so large as to make it probable +that some of the water vapour had condensed into drops. + + +\Subsection{Phenomena accompanying the Electric Discharge at Low +Pressures.} + +\Article{72} When the discharge passes between metallic electrodes +sealed into a tube filled with gas at a low pressure, the appearance +it presents is very complicated: many of the effects observed +in the tube are however evidently due to the action of the +electrodes, as the phenomena at the anode are very different +from those at the cathode; it therefore appears desirable to begin +the study of the phenomena shown in vacuum tubes by investigating +the discharge when no electrodes are present. + +\index{Discharge electrodeless@\subdashone electrodeless|indexetseq}% +\index{Electrodeless discharge@Electrodeless discharge|indexetseq}% +\Article{73} If we wish to produce the endless discharge in a closed +vessel without electrodes, we must produce in some way or +another round a closed curve in the vessel an electromotive +force large enough to break down the insulation of the gas. +Since, for discharge to take place, the electromotive force round +a closed curve must be finite, it cannot be produced electrostatically, +%% -----File: 107.png---Folio 93------- +we must use the electromotive forces produced by +electromagnetic induction, and make the closed curve in the +exhausted vessel practically the secondary of an induction coil. +As the primary of this induction coil I have used a wire connecting +the inside and outside coatings of a Leyden jar; when +the jar is discharged through the wire enormous currents pass +for a short time backwards and forwards along the wire, the +currents when the wire is short and the jar small reversing their +directions millions of times in a second. We thus have here all +the essentials for producing a very large electromotive force +round the secondary, viz.~a very intense current in the primary +and an exceedingly rapid rate of alternation of this current; +and though the electromotive force only lasts for an exceedingly +short time, it lasts long enough to produce the discharge through +the gas and to enable us to study its appearance. + +\Article{74} Two convenient methods of producing the discharge are +shown in \figureref{fig29}{Fig.~29}: in the one on the right two jars are used, the +outside coatings of which (\smallsanscap{A}~and~\smallsanscap{B}) are connected by a wire in +which a few turns~\smallsanscap{C} are made; \smallsanscap{C}~forms the primary coil. The +inside coatings of these jars are connected, one to one terminal~\smallsanscap{E} +of a Wimshurst electrical machine or of an induction coil, the +other coating to~\smallsanscap{F}, the other terminal of such a machine. If the +tubes in which the discharge is to be observed are spherical bulbs, +they are placed inside the coil~\smallsanscap{C}; if they are endless tubes, they +are placed just outside it. When the difference of potential between +\smallsanscap{E}~and~\smallsanscap{F} becomes great enough to spark across~\smallsanscap{EF}, the +%% -----File: 108.png---Folio 94------- +jars are discharged and electrical oscillations set up in the wire~\smallsanscap{ACB}. +The oscillating currents in the primary produce a large +electromotive intensity in its neighbourhood, sufficient under +favourable conditions to cause a bright discharge to pass through +the rarefied gas in the bulb placed inside the coil. + +\medskip +\includegraphicsmid{fig29}{Fig.~29.} + +We have described in \artref{26}{Art.~26} the way in which the Faraday +tubes, which before the spark took place were mainly in the +glass between the two coatings of the jars, spread through the +region outside the jars, as soon as the discharge passes, keeping +their ends on the wire~\smallsanscap{ACB}. They will pass in their journey +through the bulb in the coil~\smallsanscap{C}, and if they congregate there in +sufficient numbers the electromotive force will be sufficient to +cause a discharge to pass through the gas. Anything which +concentrates the Faraday tubes in the bulb will increase the +brightness of the discharge through it. + +\Article{75} It is necessary to prevent the coil~\smallsanscap{C} getting to a high +potential before the spark passes, otherwise it may induce a +negative electrification on the parts of the inside of the glass bulb +nearest to it and a positive electrification on the parts more +remote: when the potential of the coil suddenly falls in consequence +of the passage of the spark, the positive and negative +electricities will rush together, and in so doing may pass through +the rarefied gas in the bulb and produce luminosity. This +luminosity will spread throughout the bulb and will not be +concentrated in a well-defined ring, as it is when it arises from +the electromotive force due to the alternating currents passing +along the wire~\smallsanscap{ACB}. This effect may explain the difference in +the appearance presented by the discharge in the following experiments, +where the discharge passes as a bright ring, from that observed +\index{Hittorf, discharge through gases}% +by Hittorf (\textit{Wied.\ Ann.}~21, p.~138, 1884), who obtained +the discharge in a tube by twisting round it a wire connecting +the two coatings of a Leyden jar: in Hittorf's experiment the +luminosity seems to have filled the tube and not to have been +concentrated in a bright ring. To prevent these electrostatic +effects, due to causes which operate before the electrical oscillations +in the wires begin, the coil~\smallsanscap{C} is connected to earth, and as +an additional precaution the discharge tube may be separated +from the coil by a screen of blotting paper moistened with dilute +acid. The wet blotting paper is a sufficiently good conductor to +screen off any purely electrostatic effect, but not a good enough +%% -----File: 109.png---Folio 95------- +one to interfere to any appreciable extent with the electromotive +forces arising from the rapidly alternating currents. + +\Article{76} If $C$~is the capacity of the jars, $L$~the coefficient of self-induction +of the discharging circuit, then if the difference +of potential between the terminals of the electric machine is +initially~$V_0$, $\gamma$~the current through the wire at a time~$t$ after +the spark has passed will (Chap.~IV) be given by the equation +\[ +\gamma = \frac{CV_0}{(LC)^{\frac{1}{2}}} \sin \frac{t}{(LC)^{\frac{1}{2}}}\;, +\] +supposing as a very rough approximation that there is no decay +either from resistance or radiation in the vibrations. + +The rate of variation of the current,~$\dot{\gamma}$, is thus given by the +equation +\[ +\dot{\gamma} = \frac{V_0}{L} \cos \frac{t}{(LC)^{\frac{1}{2}}}\;. +\] +Thus if $M$~is the coefficient of mutual induction between the +primary and a secondary circuit, the maximum electromotive +force round the secondary will be~$MV_0/L$, which for a given +spark length is independent of the capacity of the jars. But +though the maximum electromotive force does not depend +upon the capacity of the jars, the oscillations will last longer +when the jars have a large capacity than when they have +a small one, as the energy to begin with is greater; hence, +though it is possible to get the discharge with jars whose +capacity is not more than $70$~or~$80$ in electrostatic measure, it is +not nearly so bright as when larger capacities are used. The best +number of turns to use in the coil is that which makes $M/L$ a +maximum. If~$n$ is the number of turns, then $M$~and~$L$ will be +respectively of the forms~$\beta n$ and $L_0 + \alpha n^2$, where $\alpha$~and~$\beta$ are +constants and $L_0$~the self-induction of the part of the wire~\smallsanscap{ACB} +not included in the coil; thus $M/L$~will be of the form +\[ +\frac{\beta n}{L_0 + \alpha n^2}\;, +\] +and this is a maximum when $L_0 = \alpha n^2$, that is when the self-induction +in the coil is equal to that in the rest of the circuit. +Though the electromotive force is greatest in this case, in +practice it is found to be better to sacrifice a little of the +electromotive force for the sake of prolonging the vibrations; +%% -----File: 110.png---Folio 96------- +this can be done by increasing the self-induction of the coil. +It is thus advisable to use rather more turns in the coil than is +indicated by the preceding rule. + + +\Subsection{Appearance of the Discharge.} + +\Article{77} Let us suppose that a bulb fused on to an air pump is +placed within the coil~\smallsanscap{C}, and that the jars are kept sparking +while the bulb is being exhausted. When the pressure is high, +no discharge at all is to be seen inside the bulb; but when the +exhaustion has proceeded until the pressure of the air has fallen +to a millimetre of mercury or thereabouts, a thin thread of reddish +light is seen going round the bulb in the zone of the coil. As the +exhaustion proceeds still further, the brightness of this thread +rapidly increases as well as its thickness; it also changes its colour, +losing the red tinge and becoming white. Continuing the exhaustion, +the luminosity attains a maximum and the discharge +passes as a very bright and well-defined ring. When the pressure +is still further diminished, the luminosity also diminishes, until +when an exceedingly good vacuum is reached no discharge at +all passes. The pressure at which the luminosity is a maximum +is very much less than the pressure at which the electric +strength is a minimum in a tube provided with electrodes and +comparable in size with the size of the bulb; the former pressure +is in air less than $1/200$~of a millimetre of mercury, while the +latter is about half a millimetre. + +\index{Discharge between electrodes near together, electrodeless, critical pressure for@\subdashtwo critical pressure for}% +\index{Critical pressure, for electrodeless discharges@\subdashtwo for electrodeless discharges}% +\Article{78} We see from this result that the difficulty which is +experienced in getting the discharge to pass through an ordinary +vacuum tube when the pressure is very low is not altogether +due to the difficulty of getting the electricity to pass from the +electrodes into the gas, but that it also occurs in tubes without +electrodes, though in this case the critical pressure is very much +lower. + +\Article{79} The existence of a critical pressure can also be easily +shown by putting some mercury in the bulb, and, when the bulb +has been well exhausted, driving out the remainder of the air by +heating the mercury and filling the bulb with mercury vapour. +After this process has been repeated two or three times, the bulb +should be fused off from the pump when full of mercury vapour. +It will only be found possible to get a discharge through this bulb +within a narrow range of temperature, between about $70°$~and~$160°$\,C; +%% -----File: 111.png---Folio 97------- +when the bulb is colder than this, the pressure of the +mercury vapour is too small to allow the discharge to pass; +when it is hotter, the vapour pressure is too great. + +\index{Discharge between electrodes near together, electrodeless, critical pressure for@\subdashtwo critical pressure for}% +\index{Electrodeless discharge, existence of critical pressure for@\subdashtwo existence of critical pressure for}% +The critical pressure can also be proved by using the principle +that a conductor screens off the electromotive intensities due to +rapidly alternating currents while an insulator does not. For +this purpose we use two glass bulbs one inside the other, the inner +bulb containing gas at such a pressure that the discharge can pass +freely through it. The outer bulb contains nothing but mercury +and mercury vapour, and is prepared in the way just described. +If the primary coil is placed round the outer bulb, then, when +the bulb is cold, the discharge passes through the inner bulb, but +not through the outer, showing that at this low pressure the conductivity +of the vapour in the outer bulb is not great enough for +the vapour to act as an electrical screen to the inner bulb. If, +however, the outer bulb is warmed, the vapour pressure of the +mercury increases, and with it the conductivity; a discharge now +passes through the outer bulb but not through the inner, the +mercury vapour acting as a screen. When the temperature +of the outer bulb is still further increased, the pressure of the +mercury vapour gets so great that it ceases to conduct, and the +discharge, as at first, passes through the inner bulb but not +through the outer. + +\Article{80} These experiments show that after a certain exhaustion +has been passed the difficulty of getting a discharge to pass +through a highly exhausted tube increases as the exhaustion is +increased. This result is in direct opposition to a theory which +has found favour with some physicists, viz.~that a vacuum is a +conductor of electricity. The reason advanced for this belief +is that when the discharge passes through highly exhausted +tubes provided with electrodes, the difficulty which it experiences +in getting through such a tube, though very great, seems to be +almost as great for a short tube as for a long one; from this it has +been concluded that the resistance to the discharge is localised +at the electrodes, and that when once the electricity has succeeded +in escaping from the electrode it has no difficulty in +making its way through the rare gas. But although there is no +doubt that in a highly exhausted tube the rise in potential +close to the cathode is great compared with the rise in unit +length of the gas elsewhere, it does not at all follow that the latter +%% -----File: 112.png---Folio 98------- +vanishes or that it continually diminishes as the pressure is +diminished. The experiment we have just described on the bulb +without electrodes shows that it does not. Numerous other experiments +of very different kinds point to the conclusion that a +\index{Vacuum an insulator}% +\index{Worthington, electric strength of a vacuum}% +vacuum is not a conductor. Thus Worthington (\textit{Nature},~27, p.~434, +1883) showed that electrostatic attraction was exerted across the +best vacuum he could produce, and that a gold-leaf electroscope +\index{Ayrton and Perry, specific inductive capacity of a `vacuum'}% +would work inside it. Ayrton and Perry (\textit{Ayrton's Practical +Electricity}, p.~310) have determined the electrostatic capacity of +a condenser in a vacuum in which they estimated the pressure to +be only $.001$~mm.\ of mercury. If the air at this pressure had +been a good conductor the electrostatic capacity would have been +infinite, instead of being, as they found, less than at atmospheric +pressure. Again, if we accept Maxwell's Electromagnetic Theory +of Light, a vacuum cannot be a conductor or it would be opaque, +and we should not receive any light from the sun or stars. + +\index{Discharge between electrodes near together, electrodeless, difficulty of passing from one medium to another@\subdashtwo difficulty of passing from one medium to another}% +\index{Electrodeless discharge, difficulty of passing from one medium to another@\subdashtwo difficulty of passing from one medium to another}% +\index{Electric discharge, passage of across junction of a metal and a gas}% +\index{Passage of electricity across junction of a metal and a gas}% +\Article{81} The discharge has considerable difficulty in passing across +the junction of a metal and rarefied gas. This can easily be shown +by placing a metal diaphragm across the bulb in which the +discharge takes place, care being taken that the diaphragm extends +right up to the surface of the glass. In this case the +discharge does not cross the metal plate, but forms two separate +closed circuits, one circuit +being on one side of the +diaphragm, the other on +the other. The nature of +the discharge is shown in +\figureref{fig30}{Fig.~30}, in which it is seen +that it travels through a +comparatively long distance +in the +\includegraphicsouter[15]{fig30}{Fig.~30.} +rarefied gas to +avoid the necessity of crossing +a thin plate of a very +good conductor. If the +bulb, instead of merely +being bisected by one diaphragm, +is divided into six +or more regions by a suitable number of diaphragms, it will be +found a matter of great difficulty to get any discharge at all +through it. The metal plate in fact behaves in this case almost +%% -----File: 113.png---Folio 99------- +exactly like a plate of an insulating substance such as mica, +which when continuous also breaks the discharge up into as many +circuits as there are regions formed by the mica diaphragms. When +however small holes are bored through the mica diaphragms +the discharge will not be split up into separate circuits, but will +pass through these holes. By properly choosing the position of +the holes relative to that of the primary coil, we can get an undivided +discharge in part of the circuit branching in the neighbourhood +of the diaphragm into as many separate discharges as +there are holes through either side +of the mica plate. The appearance +presented by the discharge when +there are two holes on each side +of the mica plate is shown in +\figureref{fig31}{Fig.~31}. + +\includegraphicsouter[12]{fig31}{Fig.~31.} + +\Article{82} A rarefied gas is usually regarded +\index{Conductivity of rarefied gases}% +\index{Gases, xhigh conductivity of rarefied@\subdashone high conductivity of rarefied|(}% +as an exceedingly bad +conductor, and the experiments of +many observers, such as those of +\index{Hittorf, discharge through gases}% +Hittorf, De~la~Rue and Hugo +Müller, have shown that when a +tube provided with electrodes in the usual way and filled +with such a gas is placed in a circuit round which there is a +given electromotive force, it produces as great a diminution in +the intensity of the current as a resistance of several million +ohms would produce. This great apparent resistance, when the +pressure of the gas is not too low, is principally due however to +the difficulty which the discharge has in passing from the electrodes +into the gas. If we investigate the amount of current sent +by a given electromotive force round a circuit exclusively confined +to the rarefied gas, we find that, instead of being exceedingly +bad conductors, rarefied gases (at not too low a pressure) are, on +the contrary, surprisingly good ones, having molecular conductivities---that +is specific conductivities divided by the number of +molecules in unit volume---enormously greater than those of any +electrolytes with which we are acquainted. + +\Article{83} We cannot avail ourselves of any of the ordinary methods +of measuring resistances to measure the resistance of rarefied +gases to these electrodeless discharges; but while the +very high frequency of the currents through our primary coil +%% -----File: 114.png---Folio 100------- +makes the ordinary methods of measuring resistances impracticable, +it at the same time makes other methods available which +would be useless if the currents were steady or only varied +slowly. One such method, which is very easily applied, is based +on the way in which plates made of conductors screen off the +action of rapidly alternating currents. If a conducting plate be +placed between a primary circuit conveying a rapidly alternating +current and a secondary coil, the electromagnetic action of the +currents induced in the plate will be opposed to that of the +currents in the primary, so that the interposition of the plate +diminishes the intensity of the currents induced in the secondary. +When we are dealing with currents through the primary with +frequencies as high as those produced by the discharge of a +Leyden jar, the thinnest plate of any metal is sufficient to +entirely screen off the primary from the secondary, and no +currents at all are produced in the latter when a metal plate +is interposed between it and the primary; we could not therefore +use this method conveniently to distinguish between the conductivities +of different metals. If however instead of a metal plate +\index{Electrolytes, conductivity of@\subdashone conductivity of}% +we use a layer of an electrolyte, the conductivity of the electrolyte +is not sufficient to screen off from the secondary the effect of the +primary unless the layer is some millimetres in thickness, and +the worse the conductivity of the electrolyte the thicker will be +the layer of it required to reduce the action of the primary +on the secondary to a given fraction of its undisturbed value. +By comparing the thicknesses of layers of different electrolytes +which produce the same effect when interposed between the +primary and the secondary we can, since this thickness is proportional +to the specific resistance, determine the conductivity +of electrolytes for very rapidly alternating currents (see J.~J. +Thomson, \textit{Proc.\ Roy.\ Soc.}~45, p.~269, 1889). + +\Article{84} The conductivity of a rarefied gas can on this principle +be compared with that of an electrolyte in the following way: +\smallsanscap{A},~\smallsanscap{B},~\smallsanscap{C}, \figureref{fig32}{Fig.~32}, represents the section of a glass vessel shaped +something like a Bunsen's calorimeter; in the inner portion +\smallsanscap{ABC} of this vessel, which is exposed to the air, an exhausted +tube~\smallsanscap{E} is placed. A tube from the outer vessel leads to a +mercury pump which enables us to alter its pressure at will. +The primary coil~\smallsanscap{LM} is wound round the outer tube. When +the air in the outer tube is at atmospheric pressure, a discharge +%% -----File: 115.png---Folio 101------- +caused by the action of the primary passes through the tube~\smallsanscap{E}; +but when the pressure of the gas in the outer tube is reduced +until a discharge passes through it, the discharge in~\smallsanscap{E} stops, +showing that the currents induced in the gas in the outer vessel +have been sufficiently intense to neutralise the direct action of the +primary coil on the tube in~\smallsanscap{E}. + +\includegraphicsouter{fig32}{Fig.~32.} + +In order to compare the intensity of the currents through the +rarefied gas with those produced under similar circumstances in +an electrolyte, the outer vessel~\smallsanscap{ABC}, \figureref{fig32}{Fig.~32}, through which the +discharge has passed is disconnected from +the pump, and the portion which has previously +been occupied by the rarefied gas +is filled with water, to which sulphuric +acid is gradually added. Pure water does +not seem to produce any effect on the +brightness of the discharge in~\smallsanscap{E}, but as +more and more sulphuric acid is added to +the water the discharge in~\smallsanscap{E} gets fainter +and fainter, until when about $25$\footnotemark~per~cent.\ +\footnotetext{The actual percentage depends on the pressure of the gas as well as on what + kind of gas it is; the figures given above refer to an actual experiment.} +by volume of sulphuric acid has been added +the effect produced by the electrolyte seems +to be as nearly as possible the same as that +produced by the rarefied gas. Thus the +currents through the rarefied gas must, since they produced +the same shielding effect, be as intense as those through a +$25$~per~cent.\ solution of sulphuric acid. The conductivity of +the gas must therefore be as great as that of the mixture of +sulphuric acid and water, which is one of the best liquid conductors +we know. This shielding effect can be produced by the +rarefied gas when its pressure is as low as that due to $1/100$~mm.\ +of mercury, while the number of molecules of sulphuric acid in a +$25$~per~cent.\ solution is such as would, if the sulphuric acid were +in a gaseous state, produce a pressure of about $100$~atmospheres. +Thus, comparing the conductivity per molecule of the gas and +of the electrolyte, the molecular conductivity of the gas is about +seven and a-half million times that of sulphuric acid. The +relation which the molecular conductivity of the gas bears to +that of an electrolyte, which produces the same effect in shielding +%% -----File: 116.png---Folio 102------- +off the effects of the primary, depends upon the length of spark +passing between the jars, and so upon the electromotive intensity +acting on the gas: in other words, conduction through these +gases does not obey Ohm's law: the conductivity instead of +being constant increases with the electromotive intensity. This +is what we should expect if we regard the discharge through +the gas as due to the splitting up of its molecules: the greater +the electromotive intensity the greater the number of molecules +which are split up and which take part in the conduction of the +electricity. + +\includegraphicsouter{fig33}{Fig.~33.} + +\Article{85} Another method by which we can prove the great conductivity +of these rarefied gases at the pressures when they +conduct best is by measuring the energy absorbed by a secondary +circuit made of the rarefied gas when placed inside a primary +circuit conveying a rapidly alternating current. We shall see, +\chapref{Chapter IV.}{Chapter~IV}, that when a conductor, whose conductivity is comparable +with that of electrolytes, is placed inside the primary +coil, the amount of energy absorbed per unit time is proportional +to the conductivity of the conductor; so that if we measure +the absorption of energy by equal and similar portions of two +electrolytes we can find the ratio of their conductivities. In +the case of these electrodeless discharges we can easily compare +the absorption of energy by two different secondary circuits +in the following manner. In the primary circuit connecting +the outside coatings of two jars, two loops, +\smallsanscap{A}~and~\smallsanscap{B}, \figureref{fig33}{Fig.~33}, are made, a standard bulb +is placed in~\smallsanscap{A} and the substance to be +examined in~\smallsanscap{B}. When a large amount of +energy is absorbed by the secondary in~\smallsanscap{B}, +the brightness of the discharge through +the bulb placed in~\smallsanscap{A} is diminished, and +by observing the brightness of this discharge +we can estimate whether the absorption +of energy by two different secondaries +placed in~\smallsanscap{B} is the same. If, now, an exhausted bulb be placed +in~\smallsanscap{B}, the brightness of the discharge of the \smallsanscap{A}~bulb is at once +diminished; indeed it is not difficult so to adjust the spark by +which the jars are discharged, that a brilliant discharge passes +in~\smallsanscap{A} when the \smallsanscap{B}~bulb is out of its coil, and no visible discharge +when it is inside the coil. To compare the absorption of energy +%% -----File: 117.png---Folio 103------- +by the rarefied gas with that by an electrolyte we have merely +to fill the bulb with an electrolyte, and alter the strength of +the electrolyte until the bulb when filled with it produces the +same effect as when it contained the rarefied gas. It will be +found that in order to produce as great an absorption of energy +as that due to a comparatively inefficient bulb filled with +rarefied air, a very strong solution of an electrolyte must be +put into the bulb; while a bulb which is exhausted to the +pressure at which it produces its maximum effect absorbs a +greater amount of energy than when filled even with the +best conducting electrolyte we can obtain. We conclude from +these experiments that the very large electromotive intensities +which are produced by the discharge of a Leyden jar can, when +no electrodes are used, send through a rarefied gas when the +pressure is not too low much larger currents than the same +electromotive intensities could send through even the best conducting +mixture of water and sulphuric acid. +\index{Gases, xhigh conductivity of rarefied@\subdashone high conductivity of rarefied|)}% + +The results just quoted show that the conductivity, if estimated +per molecule taking part in the discharge, is much higher for +rare gases than even for metals such as copper or silver. + +\Article{86} The large values of the conductivities of these rarefied +gases when no electrodes are used are in striking contrast +to the almost infinitesimal values which are obtained when +electrodes are present. This illustrates the reluctance which the +discharge has to pass across the junction of a rarefied gas and a +metal: the experiments described in \artref{81}{Art.~81} are a very direct +proof of this peculiarity of the discharge. It seems also to be +indicated, though perhaps not quite so directly, by some experiments +\index{Dewar and Liveing, effects of metallic dust in discharge}% +\index{Liveing and Dewar, dust in electric discharge}% +made by Liveing and Dewar (\textit{Proc.\ Roy.\ Soc.}~48, p.~437, +1890) on the spectrum of the discharge. They found that the +spectrum of a discharge passing through a gas which holds in +suspension a considerable quantity of metallic dust does not show +any of the lines of the metal. This is what we should expect +from the experiments described in \artref{81}{Art.~81}, as these show that +the discharge would take a very round-about course to avoid +passing through the metal. + +\Article{87} There seem some indications that this reluctance of the +discharge to pass from one substance to another extends also +to the case when both substances are in the gaseous state, and +that when the discharge passes through a mixture of two gases +%% -----File: 118.png---Folio 104------- +\smallsanscap{A}~and~\smallsanscap{B}, the discharges through~\smallsanscap{A} and through~\smallsanscap{B} respectively +are in parallel rather than in series: in other words, that the +polarized chains of molecules, which are formed before the discharge +passes, consist some of \smallsanscap{A}~molecules and some of \smallsanscap{B}~molecules, +but that the chains conveying the discharge do not consist +partly of~\smallsanscap{A} and partly of \smallsanscap{B}~molecules. Thus, if the discharge is +passing through a mixture of hydrogen and nitrogen, the chains +in which the molecules split up and along which the electricity +passes may be either hydrogen chains or nitrogen chains, but not +chains containing both hydrogen and nitrogen. This seems to be +indicated by the fact that when the discharge passes through a +mixture of hydrogen and nitrogen, the spectrum of the discharge +may, though a considerable quantity of nitrogen is present, show +nothing but the hydrogen lines. + +\index{Crookes on discharge through gases}% +Crookes' observations on the striations in a mixture of gases +(\textit{Presidential Address to the Society of Telegraph Engineers}, +1891) seem also to point to the conclusion that the discharges +through the different gases in the mixture are separate; for he +found that when several gases are present in the discharge +tube, different sets of striations, \artref{99}{Art.~99}, are found when the +discharge passes through the tube, the spectrum of the bright +portions of the \DPtypo{striae}{striæ} +in one set showing the +lines of one, and only +one, of the gases in the +mixture; the spectrum +of another set showing +the lines of another of +the gases and so on, +indicating that the discharges +through the +components of the mixture +are distinct. + +\includegraphicsouter{fig34}{Fig.~34.} + +\Article{88} When the discharge +can continue in the same medium all the way it can +traverse remarkably long distances, even though the greater +portion of the secondary may be of such a shape as not to +add anything to the electromotive force acting round it. Thus, +for example, the discharge will pass through a very long +secondary, even though the tube of which this secondary is made +%% -----File: 119.png---Folio 105------- +\index{Discharge between electrodes near together, electrodeless, action of magnet on@\subdashtwo action of magnet on}% +is bent up so that the greater part of it is at right angles to the +electromotive intensity acting upon it. By using square coils +with several turns for the primaries, I have succeeded in sending +discharges through tubes of this kind over $12$~feet in length. +On the other hand, there will be no discharge through a rarefied +gas if the shape of the tube in which it is contained is such that +the electromotive force round it is either zero or very small: it +is impossible, for example, to get a discharge of this kind through +a tube shaped like the one shown in \figureref{fig34}{Fig.~34}. + +\Subsection{Action of a Magnet on the Electrodeless Discharge.} +\index{Magnets, action of, on electrodeless discharge}% +\index{Electrodeless discharge, action of magnet on@\subdashtwo action of magnet on}% + +\Article{89} A magnet deflects the discharge through a rarefied gas in +much the same way as it does a flexible wire carrying a current +which flows in the same direction as the one through the gas. As +the electrodeless discharges through the rarefied gas are oscillatory, +they are when under the action of a magnet separated into two +distinct portions, the magnet driving the discharge in one direction +one way and that in the opposite direction the opposite way. +Thus, when a bulb in which the discharge passes as a ring in a +horizontal plane is placed between the poles of an electromagnet +arranged so as to produce a horizontal magnetic field, those parts +of the ring which are at right angles to the lines of magnetic force +are separated into two portions, one being driven upwards, the +other downwards. The displacement of the discharge is not +however the only effect observed when the discharge bulb is +placed in a magnetic field, for the difficulty which the discharge +experiences in getting through the rarefied gas is very much increased +when it has to pass across lines of magnetic force. This +effect, which is very well marked, can perhaps be most readily +shown when the discharge passes as a bright ring through a +spherical bulb. If such a bulb is placed near a strong electromagnet +it is easy to adjust the length of spark in the primary +circuit, so that when the magnet is `off' a brilliant discharge +passes through the bulb, while when the magnet is `on' no +discharge at all can be detected. + +\Article{90} The explanation of this effect would seem to be somewhat +as follows. The discharge through the rarefied gas does not rise +to its full intensity quite suddenly, but, as it were, feels its way. +The gas first breaks down along the line where the electromotive +intensity is a maximum, and a small discharge takes place along +%% -----File: 120.png---Folio 106------- +this line. This discharge produces a supply of dissociated molecules +along which subsequent discharges can pass with greater +ease. The gas is thus in an unstable state with regard to the +discharge, since as soon as any small discharge passes through +it, it becomes electrically weaker and less able to resist subsequent +discharges. When, however, the gas is in a magnetic field, +the magnetic force acting on the discharge produces a mechanical +force which displaces the molecules taking part in the discharge +from the line of maximum electromotive intensity; thus subsequent +discharges will not find it any easier to pass along this line +in consequence of the passage of the previous discharge. There +will not therefore be the same unstability in this case as there is +in the one where the gas is free from the action of the magnetic +force. A confirmation of this view is afforded by the appearance +presented by the discharge when the intensity of the magnetic +field is reduced until the discharge just, but only just, passes when +the magnetic field is on: in this case the discharge instead of +passing as a steady fixed ring, flickers about the tube in a very +undecided way. Unless some displacement of the line of easiest +discharge is produced by the motion of the dissociated molecules +under the action of the magnetic force, it is difficult to understand +why the magnet should displace the discharge at all, +unless the Hall effect in rarefied gases is very large. + +\includegraphicsmid{fig35}{Fig.~35.} + +\Article{91} In the preceding case the discharge was retarded because it +had to flow across the lines of magnetic force, when however +the lines of magnetic force run along the line of discharge the +action of the magnet facilitates the discharge instead of retarding +it. This effect is easily shown by an arrangement of the +following kind. A square tube~\smallsanscap{ABCD}, \figureref{fig35}{Fig.~35}, is placed outside +the primary~\smallsanscap{EFGH}, the lower part of the discharge tube +being situated between the poles \smallsanscap{L},~\smallsanscap{M} of an electromagnet. +By altering the length of the spark between the jars, the +electromotive intensity acting on the secondary circuit can be +adjusted until no discharge passes round the tube~\smallsanscap{ABCD} when +the magnet is off, whilst a bright discharge occurs as long as +the magnet is on. The two effects of the magnet on the discharge, +viz.~the stoppage of the discharge across the lines of +force and the help given to it along these lines, may be prettily +illustrated by placing in this experiment an exhausted bulb~\smallsanscap{N} +inside the primary. The spark length can be adjusted so that +%% -----File: 121.png---Folio 107------- +when the magnet is `off' the discharge passes through the bulb +and not in the square tube; while when the magnet is `on' the +discharge passes in the square tube and not in the bulb. + +\includegraphicsouter{fig36}{Fig.~36.} + +\Article{92} The explanation of the longitudinal effect of magnetic +force is more obscure than that of the transverse effect, it is +possible however that both are due to the same cause. For if +the feeble discharge with which we suppose the total discharge +to begin branches away at all from the main line, these +branches will, when the magnetic force is parallel to the line of +discharge, be brought into this line by the action of the magnetic +force; there will thus be a larger supply of dissociated molecules +along the main line of discharge, and therefore an easier +path for subsequent discharges when the magnetic force is acting +than when it is not. + +This action of the magnet is not confined to this kind of +discharge; in fact I observed it first for a glow discharge, +which took place more easily from the pole of an electromagnet +when the magnet was `on' than when it was `off'. + +\Article{93} Professor Fitzgerald has suggested that this effect of the +\index{Fitzgerald, auroras}% +magnetic field on the discharge may be the cause of the +streamers which are observed in the aurora, the rare air, since +\index{Aurora}% +it is electrically weaker along the lines of magnetic force than +at right angles to them, transmitting brighter discharges along +these lines than in any other direction. +%% -----File: 122.png---Folio 108------- + +\Subsection{Electric discharge through rarefied Gases when Electrodes +are used.} + +\Article{94} When the discharge passes between electrodes through a +\index{Wiedemann, E., on electric discharge}% +rare gas, the appearance of the discharge at the positive and +negative electrodes is so strikingly different that the discharge +loses all appearance of uniformity. \figureref{fig36}{Fig.~36}, which is taken +from a paper by E.~Wiedemann (\textit{Phil.\ Mag.}~[5], 18, +p.~35, 1884), represents the appearance presented +by the discharge when it passes through a gas at +a pressure comparable with that due to half a +millimetre of mercury. Beginning at the negative +electrode~$k$ we meet with the following phenomena. +A velvety glow runs often in irregular patches over +the surface of the negative electrode; a wire placed +inside this glow casts a shadow towards the negative +\index{Schuster, discharge through gases|(}% +electrode (Schuster, \textit{Proc.\ Roy.\ Society},~47, +p.~557, 1890). + +\includegraphicsmid{fig37}{Fig.~37.} + +Next to this there is a comparatively dark region~$lb$, +called sometimes `Crookes' space' and sometimes +\index{Crookes' space}% +the `first dark space;' the length of this region depends +\index{Puluj, dark space}% +\index{Dark space}% +\index{First dark space}% +on the density of the gas, it gets longer as +the density +diminishes. Puluj's experiments (\textit{Wien.\ +Ber.}\ 81~(2), p.~864, 1880) show that the length +does not vary directly as the reciprocal of the +density, in other words, that it is not proportional +to the mean free path of the molecules. + +\includegraphicsmid{fig38}{Fig.~38.} + +The luminous boundary~$b$ of this dark space is +approximately such as could be got by tracing the locus of the +extremities of normals of constant length drawn from the negative +electrode: thus, if the electrode is a disc, the luminous +boundary of the dark space is over a great part of its surface +%% -----File: 123.png---Folio 109------- +nearly plane as in \figureref{fig37}{Fig.~37}, which is given by Crookes; while if it +is a circular ring of wire, the luminous boundary resembles that +\index{De la Rue and Müller, discharge through gases}% +shown in \figureref{fig38}{Fig.~38} (De~la~Rue). The length of the dark space also +depends to some extent on the current passing through the gas, +an increase of current producing (see Schuster, \textit{Proc.\ Roy.\ Society}, +47, p.~556, 1890) a slight increase in the length of the dark space. +Some idea of the length of the dark space at different pressures +may be got from the following table of the results of some experiments +made by Puluj (\textit{Wien.\ Ber.}\ 81~(2), p.~864, 1880) with +a cylindrical discharge tube and disc electrodes:--- +\begin{center} +\begin{tabular}{c|c} +\settowidth{\TmpLen}{Pressure in millimetres}% +\parbox[c]{\TmpLen}{\centering Pressure in millimetres\\ of mercury.\tablespacedown} & +\settowidth{\TmpLen}{Length of dark space}% +\parbox[c]{\TmpLen}{\centering Length of dark space\\ in air in mm.\tablespacedown} \\ +\hline +\tablespaceup$\llap{$1$}.46$ & $\Z2.5$ \\ +$.66$ & $\Z4.5$ \\ +$.51$ & $\Z5.8$ \\ +$.30$ & $\Z7.8$ \\ +$.24$ & $\Z9.5$ \\ +$.16$ & $14.0$ \\ +$.12$ & $15.5$ \\ +$.09$ & $19.5$ \\ +$.06$ & $22.0$ +\end{tabular} +\end{center} + +The mean free path of the molecules is very much smaller than +the length of the dark space; thus at a pressure of $1.46$~mm.\ of +mercury, the mean free path is only $.04$~mm. Crookes found +(\textit{Phil.\ Trans.}\ Part~I, 1879, pp.~138--9) that the dark space is +longer in hydrogen than in air at the same pressure, but that in +carbonic acid it is considerably shorter. + +\index{Crookes on discharge through gases}% +\index{Dark space, Crookes' theory of@\subdashtwo Crookes' theory of}% +\Article{95} Crookes' theory of the dark space is that it is the region +which the negatively electrified particles of gas shot off from +the cathode (see \artref{108}{Art.~108}) traverse before making an appreciable +number of collisions with each other, and that the brightly +luminous boundary of this space is the region where the collisions +occur, these collisions exciting vibrations in the particles and so +%% -----File: 124.png---Folio 110------- +making them luminous. It is an objection, though perhaps not +a fatal one, to this view, that the thickness of the dark space is +very much greater than the mean free path of the molecules. +We shall see later on that if the luminosity is due to gas shot +from the negative electrode, this gas must be in the atomic +and not in the molecular condition; in the former condition its +free path would be greater than the value calculated from the +ordinary data of the Molecular Theory of Gases, though if we +take the ordinary view of what constitutes a collision we +should not expect the difference to be so great as that indicated +by Puluj's experiments. + +\Article{96} The size of the dark space does not seem to be much +affected by the material of which the negative electrode is made, +as long as it is metallic. It is however considerably shorter over +\index{Chree on negative dark space}% +sulphuric acid electrodes than over aluminium ones (Chree, \textit{Proc.\ +\index{Crookes on discharge through gases}% +Camb.\ Phil.\ Soc.}~vii, p.~222, 1891). Crookes (\textit{Phil.\ Trans\DPtypo{}{.}}, 1879, +p.~137) found that if a metallic electrode is partly coated with +lamp black the dark space is longer over the lamp-blacked +portion than over the metallic. Lamp black however absorbs +gases so readily that this effect may be due to a change in the +gas and not to the change in the electrode. The dark space is also, +as Crookes has shown (loc.~cit.), independent of the position of +the positive electrode. When the cathode is a metal wire raised +to a temperature at which it is incandescent, Hittorf (\textit{Wied.\ +Ann.}~21, p.~112, 1884) has shown that the changes in luminosity +which with cold electrodes are observed in the neighbourhood of +the cathode disappear. There is a difference of opinion as to +whether the dark space exists when the discharge passes through +\index{Mercury vapour, discharge through}% +mercury vapour, Crookes maintaining that it does, Schuster +that it does not. + +\Article{97} Adjoining the `dark space' is a luminous space,~$bp$ \figureref{fig36}{Fig.~36}, +called the `negative column,' or sometimes the `negative glow;' the +\index{Column, negative}% +\index{Negative glow@\subdashone glow}% +\index{Negative column}% +length of this is very variable even though the pressure is constant. +The spectrum of this part of the discharge exhibits peculiarities +which are not in general found in that of the other luminous parts +\index{Goldstein, discharge of electricity through gases|(}% +of the discharge. Goldstein (\textit{Wied.\ Ann.}~15, p.~280, 1882) however +has found that when very intense discharges are used, the +peculiarities in the spectrum, which are usually confined to the +negative glow, extend to the other parts of the discharge. + +\includegraphicsmid{fig39}{Fig.~39.} + +\Article{98} The negative glow is independent of the position of the +\index{Schuster, discharge through gases|)}% +%% -----File: 125.png---Folio 111------- +positive electrode; it does not bend round, for example, in a tube +shaped as in \figureref{fig41}{Fig.~41}, but is formed in the part of the tube +away from the positive electrode. This glow is stopped by +any substance, whether a conductor or an insulator, against +which it strikes. The development of the negative glow is +also checked when the space round the negative electrode is +too much restricted by the walls of the discharge tube. Thus +Hittorf (\textit{Pogg.\ Ann.}~136, p.~202, 1869) found that if the discharge +took place in a tube shaped like \figureref{fig39}{Fig.~39}, when the wire~$c$ +in the bulb was made the negative electrode, the negative glow +spread over the whole of its length, while if the wire~$a$ in the +neck was used as the negative electrode the glow only occurred +at its tip. + +\includegraphicsmid[p]{fig40}{Fig.~40.} + +\Article{99} Next after the negative glow comes a second comparatively +non-luminous space,~$ph$ \figureref{fig36}{Fig.~36}, called the `second negative dark +\index{Faraday, space@\subdashone space}% +\index{Negative dark space, second@\subdashone dark space, second}% +space,' or by some writers the `Faraday space;' this is of very variable +length and is sometimes entirely absent. Next after this we +have a luminous column reaching right up to the positive electrode, +this is called the `positive column.' Its luminosity very often +\index{Positive column}% +exhibits remarkable periodic alterations in intensity such as +those shown in \figureref{fig40}{Fig.~40}, which is taken from a paper by +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +De~la~Rue and Hugo Müller (\textit{Phil.\ Trans.}, 1878, Part~I, p.~155); +these are called `striations,' or `\DPtypo{striae}{striæ};' under favourable +\index{Striations}% +\index{Striations, variation of, with density of gas@\subdashone variation of, with density of gas}% +circumstances they are exceedingly regular and constitute the +most striking feature of the discharge. The bright parts of the +striations are slightly concave to the positive electrode. The +distance between the bright parts depends upon the pressure of +the gas and the diameter of the discharge tube. The distance +increases as the density of the gas diminishes. + +According to Goldstein (\textit{Wied.\ Ann.}~15, p.~277, 1882), if $d$~is +the distance between two striations and $\rho$~the density of the +gas, $d$~varies as~$\rho^{-n}$, where $n$~is somewhat less than unity. The +distance between the bright parts of successive striations increases +%% -----File: 126.png---Folio 112------- +\index{Positive column, striations in@\subdashtwo striations in}% +as the diameter of the discharge tube increases, provided +the striations reach to the sides of the tube. Goldstein (l.~c.)\ +found that the ratio of the values of~$d$ at any two given pressures +is the same for all tubes. If the discharge takes place +%% -----File: 127.png---Folio 113------- +in a tube which is wider in some places than in others, the +striations are more closely packed in the narrow parts of +the tube than they are in the wide. + +The striations have very often a motion of translation along +the tube; this motion is quite irregular, being sometimes towards +the positive electrode and sometimes away from it. This can +\index{Spottiswoode, on striations}% +easily be detected by observing, as Spottiswoode did, the discharge +in a rapidly rotating mirror. These movements of the +\DPtypo{striae}{striæ} tend to make the striated appearance somewhat indistinct, +and if the movements are too large may obliterate +it altogether; thus many discharges which show no appearance +of striation when examined in the ordinary way, are seen to +be striated when looked at in a revolving mirror. The difficulty +of detecting whether a discharge is striated or not is, in consequence +of the motion of the \DPtypo{striae}{striæ}, very much greater when the +\DPtypo{striae}{striæ} are near together than when they are far apart, so that it +is quite possible that discharges are striated at pressures much +greater than those at which striations are usually observed. + +Goldstein, using a tube with moveable electrodes, showed +(\textit{Wied.\ Ann.}\ 12, p.~273, 1881) that when the cathode is moved +the \DPtypo{striae}{striæ} move as if they were rigidly connected with it, while +when the anode is moved the position of the \DPtypo{striae}{striæ} is not affected +except in so far as they may be obliterated by the anode moving +past them. + +\Article{100} The striations are not confined to any one particular +method of producing the discharge, they occur equally well +whether the discharge is produced by an induction coil or by a +very large number of galvanic cells. They do not, however, +occur readily in the electrodeless discharge; indeed I have never +observed them when a considerable interval intervened between +consecutive sparks. By using an induction coil large enough to +furnish a supply of electricity sufficient to produce an almost +continuous torrent of sparks between the jars, I have been able +to get striations in exhausted bulbs containing hydrogen or +other gases. + +\Article{101} The striations are influenced by the quantity of current +flowing through the tube; this can easily be shown by putting a +great external resistance in the circuit, such as a wet string. The +changes produced by altering the current are complex and irregular: +there seems to be a certain intensity of current for which the +%% -----File: 128.png---Folio 114------- +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +steadiness of the striations is a maximum (De~la~Rue and +Hugo Müller, \textit{Comptes Rendus},~86, p.~1072, 1878). Crookes has +found (\textit{Presidential Address to the Society of Telegraph Engineers}, +1891) that when the discharge passes through a mixture of different +gases there is a +separate set of striations +for each gas: +the colour of the +striations in each +set being different. +Crookes proved this +by observing the spectra +of the different +\DPtypo{striae}{striæ}. A full account +of the different +coloured striations observed +in air is given +by Goldstein (\textit{Wied.\ +Ann.}~12, p.~274, 1881). +\index{Goldstein, discharge of electricity through gases|)}% + +\Article{102} When we +consider the action +of a magnet on the +striated positive column +we shall see +reasons for thinking +that any portion of +the positive column +between the bright +parts of consecutive +striations constitutes +a separate discharge, +and that the discharges +in the several +portions do not occur +simultaneously, but that the one next the anode begins the +discharge, and the others follow on in order. + +\includegraphicsouter{fig41}{Fig.~41.} + +\Article{103} The positive column bears a very much more important +relation to the discharge than either the negative dark space or +the negative glow. The latter effects are merely local, they do +not depend upon the position of the positive electrode, nor do they +%% -----File: 129.png---Folio 115------- +increase when the length of the discharge tube is increased. The +positive column, on the other hand, takes the shortest route through +the gas to the negative electrode. Thus, if, for example, the discharge +takes place in a tube like \figureref{fig41}{Fig.~41}, the positive column bends +round the corner so as to get to the negative electrode, while the +negative glow goes straight down the vertical tube, and is not +affected by the position of the positive electrode. Again, if the +length of the tube is increased the size of the negative dark +space and of the negative glow is not affected, it is only the +positive column which lengthens out. I have, for example, +obtained the discharge through a tube $50$~feet long, and this +tube, with the exception of a few inches next the cathode, was +entirely filled by the positive column, which was beautifully +striated. These examples show that it is the positive column +which really carries the discharge through the gas, and that the +negative dark space and the negative glow are merely local +effects, depending on the peculiarities of the transference of +electricity from a gas to a cathode. + +\Article{104} By the use of long discharge tubes such as those mentioned +\index{Positive column, velocity of@\subdashtwo velocity of}% +\index{Velocity of positive column@\subdashtwo positive column}% +\index{Wheatstone, velocity of discharge}% +\index{Zahn, von, velocity of molecules in electric discharge}% +above, it is possible to determine the direction in which +the luminosity in the positive column travels and to measure its +rate of progression. The first attempt at this seems to have +been made by Wheatstone, who, in 1835, observed the appearance +presented in a rotating mirror by the discharge through a +vacuum tube $6$~feet long; he concluded from his observations +that the velocity with which the flash went through the tube +could not have been less than $8 × 10^7$~cm.\ per~second. This +great velocity is not accompanied by a correspondingly large +velocity of the luminous molecules, for von~Zahn (\textit{Wied.\ Ann.}~8, +p.~675, 1879) has shown that the lines of the spectrum of +the gas in the discharge tube are not displaced by as much as +$\frac{1}{40}$~of the distance between the D~lines when the line of sight +is in the direction of the discharge. It follows from this by +Döppler's principle, that the particles when emitting light are +not travelling at so great a rate as a mile a second, proving, +at any rate, that the luminous column does not consist of a +wind of luminous particles travelling with the velocity of the +discharge. + +\includegraphicsmid{fig42}{Fig.~42.} + +\Article{105} Wheatstone's observations only give an inferior limit to +the velocity of the discharge; they do not afford any information +%% -----File: 130.png---Folio 116------- +as to whether the luminous column travels from the anode to the +cathode or in the opposite direction. To determine this, as well +as measure the velocity of the luminosity in the positive column, +I made the following experiment. \smallsanscap{ABCDEFG}, \figureref{fig42}{Fig.~42}, is a glass +tube about $15$~metres long and $5$~millimetres in diameter, which, +with the exception of two horizontal pieces of \smallsanscap{BC}~and~\smallsanscap{GH}, is +covered with lamp black; this tube is exhausted until a current +can be sent through it from an induction coil. The light from +the uncovered portions of the tube falls on a rotating mirror~\smallsanscap{MN}, +placed at a distance of about $6$~metres from~\smallsanscap{BC}; the light from~\smallsanscap{GH} +falls on the rotating mirror directly, that from~\smallsanscap{BC} after +reflection from the plane mirror~\smallsanscap{P}. The images of the bright +portions of the tube after reflection from the mirror are viewed +%% -----File: 131.png---Folio 117------- +through a telescope, and the mirrors are so arranged that when +the revolving mirror is stationary the images of the bright portions +\smallsanscap{GH}~and~\smallsanscap{BC} of the tube appear as portions of the same +horizontal straight line. The terminals of the long vacuum +tube are pushed through mercury up the vertical tubes~\smallsanscap{AB~KL}. +This arrangement was adopted because by running sulphuric +acid up these tubes the terminals could easily be changed +from pointed platinum wires to flat liquid surfaces, and the +effect of very different terminals on the velocity and direction +of the discharge readily investigated. The bulbs on the tube +are also useful as receptacles of sulphuric acid, which serves +to dry the gas left in the tube. The rotating mirror was +driven at a speed of from $400$ to $500$ revolutions per~second by a +Gramme machine. It was not found possible to make any +arrangement work well which would break the primary circuit +of the induction coil when the mirror was in such a position +that the images of the luminous portions of the tube would +be reflected by it into the field of view of the telescope. The +method finally adopted was to use an independent slow break +for the coil and look patiently through the telescope at the +rotating mirror until the break happened to occur just at the +right moment. When the observations were made in this way +the observer at the telescope saw, on an average about once in +four minutes, sharp bright images of the portions \smallsanscap{BC}~and~\smallsanscap{GH} +of the tube, not sensibly broadened but no longer quite in the +same straight line. The relative displacement of those images was +reversed when the poles of the coil were reversed, and also when +the direction of rotation of the mirror was reversed. This displacement +of the images of \smallsanscap{BC}~and~\smallsanscap{GH} from the same straight +line is due to the finite velocity with which the luminosity is +propagated: for, if the mirror can turn through an appreciable +angle while the luminosity travels from~\smallsanscap{BC} to~\smallsanscap{GH} or from~\smallsanscap{GH} +to~\smallsanscap{BC}, these images of \smallsanscap{BC}~and~\smallsanscap{GH}, when seen in the telescope +after reflection from the revolving mirror, will no longer be in +the same straight line. If the mirror is turning so that on looking +through the telescope the images seem to come in at the top +and go out at the bottom of the field of view, the image of that +part of the tube at which the luminosity first appears will be +raised above that of the other part. If we know the rate of +rotation of the mirror, the vertical displacement of the images +%% -----File: 132.png---Folio 118------- +and the distance between \smallsanscap{BC}~and~\smallsanscap{GH}, the rate of propagation of +the luminosity may be calculated. The displacement of the +images showed that the luminosity always travelled from the +positive to the negative electrode. When \smallsanscap{AB}~was the negative +electrode, the luminous discharge arrived at~\smallsanscap{GH}, a place about +$25$~feet from the positive electrode, before it reached~\smallsanscap{BC}, which was +only a few inches from the cathode, and as the interval between +its appearance at these places was about the same as when +the current was reversed, we may conclude that when \smallsanscap{AB}~is +the cathode the luminosity at a place~\smallsanscap{BC}, only a few inches +from it, has started from the positive electrode and traversed +a path enormously longer than its distance from the cathode. +The velocity of the discharge through air at the pressure of +about $\frac{1}{2}$~a millimetre of mercury in a tube $5$~millimetres in +diameter was found to be rather more than half the velocity +of light. + +\Article{106} The preceding experiment was repeated with a great +variety of electrodes; the result, however, was the same whether +the electrodes were pointed platinum wires, carbon filaments, flat +surfaces of sulphuric acid, or the one electrode a flat liquid surface +and the other a sharp-pointed wire. The positive luminosity +travels from the positive electrode to the negative, even though +the former is a flat liquid surface and the latter a pointed wire. +The time taken by the luminosity to travel from~\smallsanscap{BC} to~\smallsanscap{GH} was +not affected to an appreciable extent by inserting between~\smallsanscap{BC} +and~\smallsanscap{GH} a number of pellets of mercury, so that the discharge +had to pass from the gas to the mercury several times in its +passage between these places: the intensity of the light was +however very much diminished by the insertion of the mercury. + +\Article{107} The preceding results bear out the conclusion which +\index{Plücker, effect of magnet on discharge}% +Plücker (\textit{Pogg.\ Ann.}~107, p.~89, 1859) arrived at from the consideration +of the action of a magnet on the discharge, viz.~that +the positive column starts from the positive electrode; they also +confirm the result which Spottiswoode and Moulton (\textit{Phil.\ +Trans.}\ 1879, p.~165) deduced from the consideration of what +they have termed `relief' effects, that the time taken by the +negative electricity to leave the cathode is greater than the +time taken by the positive luminosity to travel over the length +of the tube. +%% -----File: 133.png---Folio 119------- + +\Subsection{Negative Rays or Molecular Streams.} +\index{Negative rays@\subdashone rays}% +\index{Molecular streams}% + +\Article{108} Some of the most striking of the phenomena shown by +the discharge through gases are those which are associated with +the negative electrode. These effects are most conspicuous at +\index{Moulton and Spottiswoode, electric discharge}% +\index{Spottiswoode and Moulton, electric discharge}% +low pressures, but Spottiswoode and Moulton's experiments +(\textit{Phil.\ Trans.}\ 1880, pp.~582, 85~\textit{seq.})\ show that they exist over +a wide range of pressure. The sides of the tube exhibit a +brilliant phosphorescence, behaving as if something were shot +out at right angles, or nearly so, to the surface of the cathode, +which had the power of exciting phosphorescence on any substance +on which it fell, provided that this substance is +one which becomes phosphorescent under the action of ultra-violet +light. The portions of the tube enclosed within the +surface formed by the normals to the cathode will, when the +pressure of the gas is low, show a bright green phosphorescence +if the tube is made of German glass, while the phosphorescence +will be blue if the tube is made of lead glass. Perhaps the +easiest way of describing the general features of this effect is +to say that they are in accordance with Mr.~Crookes' theory, that +particles of gas are projected with great velocities at right +angles, or nearly so, to the surface of the cathode, and that these +particles in a highly exhausted tube strike the glass before they +have lost much momentum by collision with other molecules, +and that the bombardment of the glass by these particles is +intense enough to make it phosphoresce. The following extract +\index{Priestley@Priestley's \textit{History of Electricity}}% +from Priestley's \textit{History of Electricity}, p.~294, 1769, is interesting +\index{Beccaria, phosphorescence}% +in connection with this view: `Signior Beccaria observed that +hollow glass vessels, of a certain thinness, exhausted of air, gave +a light when they were broken in the dark. By a beautiful +train of experiments, he found, at length, that the luminous +appearance was not occasioned by the breaking of the glass, but +by the dashing of the external air against the inside, when it +was broke. He covered one of these exhausted vessels with +a receiver, and letting the air suddenly on the outside of it, +observed the very same light. This he calls his \emph{new invented +phosphorous}.' + +\Article{109} If a screen made either of an insulator or a conductor +is placed between the electrode and the walls of the tube, +a shadow of the screen is thrown on the walls of the tube, +%% -----File: 134.png---Folio 120------- +\index{Negative rays, shadows cast by@\subdashtwo shadows cast by}% +\index{Shadows cast by negative rays}% +the shadow of the screen remaining dark while the glass round +the shadow phosphoresces brightly. In this way many very +\index{Crookes on discharge through gases|(}% +beautiful and brilliant effects have been produced by Mr.~Crookes +\index{Goldstein, discharge of electricity through gases}% +and Dr.~Goldstein, the two physicists who have devoted +most attention to this subject. One of Mr.~Crookes' experiments +in which the shadow of a Maltese cross is thrown on the walls +of the tube is illustrated in \figureref{fig43}{Fig.~43}. + +\includegraphicsmid{fig43}{Fig.~43.} + +\Article{110} As we have already mentioned, the colour of the phosphorescence +depends on the nature of the phosphorescing substance; +if this substance is German glass the phosphorescence +is green, if it is lead glass the phosphorescence is blue. Crookes +found that bodies phosphorescing under this action of the +negative electrode give out characteristic band spectra, and he +has developed this observation into a method of the greatest +%% -----File: 135.png---Folio 121------- +importance for the study of the rare earths: for the particulars +of this line of research we must refer the reader to his papers +`On Radiant Matter Spectroscopy,' \textit{Phil.\ Trans.}\ 1883, Pt.~III, +\index{Spectroscopy@`Spectroscopy, Radiant Matter'}% +\index{Radiant matter}% +and~1885, Pt.~II. + +The way the spectrum is produced is represented in \figureref{fig44}{Fig.~44}, +the substance under examination being placed in a high vacuum +in the path of the normals to the cathode. + +\index{Negative rays, phosphorescence due to@\subdashtwo phosphorescence due to}% +\index{Phosphorescence, due to magnetic rays}% +\Article{111} Crookes also found that some substances, when submitted +for long periods to the action of these rays, undergoes +remarkable modifications, which seems to suggest that the phosphorescence +is attended (or caused by?)\ chemical changes slowly +taking place in the phosphorescent body. He also observed +that glass which has been phosphorescing for a considerable +time seems to get tired, and to respond less readily to this +action of the cathode. Thus, for example, if after the experiment +in \figureref{fig44}{Fig.~44} has been proceeding for some time the cross is +shaken down, or a new cathode used whose line of fire does not +cut the cross, the pattern of the cross will still be seen on the +glass, but now it will be brighter than the adjacent parts +instead of darker. The portions outside the pattern of the cross +have got tired by their long phosphorescence, and respond less +vigorously to the stimulus than the portions forming the cross +which were previously shielded. Crookes found this `exhaustion' +of the glass could survive the melting and reblowing of the bulb. + +\includegraphicsmid{fig44}{Fig.~44.} + +By using a curved surface for the negative electrode, such +as a portion of a hollow cylinder or of a spherical shell, this +effect of the negative rays may be concentrated to such an +extent that a platinum wire placed at the centre of the cylinder +or sphere becomes red hot. + +\Article{112} The negative rays are deflected by a magnet in the same +\index{Magnets, action of, on negative rays@\subdashtwo on negative rays}% +\index{Negative rays, action of a magnet on@\subdashtwo action of a magnet on}% +way as they would be if they consisted of particles moving away +from the negative electrode and carrying a charge of negative +electricity. This deflection is made apparent by the movement +of the phosphorescence on the glass when a magnet is brought +near the discharge tube. + +On the other hand they are not deflected when a charged +body is brought near the tube; this does not prove, however, +that the rays do not consist of electrified particles, for we have +seen that gas conveying an electric discharge is an extremely +good conductor, and so would be able to screen the inside of the +%% -----File: 136.png---Folio 122------- +tube from any external electrostatic action. Crookes (\textit{Phil.\ +Trans.}\ 1879, Pt.~II, p.~652) has shown, moreover, that two +\index{Negative rays, repulsion of@\subdashtwo repulsion of}% +\index{Repulsion, of negative rays@\subdashone of negative rays}% +pencils of these rays repel each other, as they would do if +each pencil consisted of particles charged with the same kind +of electricity. The experiment by which this is shown is +represented in \figureref{fig45}{Fig.~45}; $a$,~$b$ are metal discs either or both of +which may be made into cathodes, a diaphragm with two +openings $d$~and~$e$ is placed in front of the disc, and the path +of the rays is traced by the phosphorescence they excite in a +chalked plate inclined at a small angle to their path. When $a$ +is the cathode and $b$ is idle, the rays travel along the path~$df$, +and when $b$ is the cathode and $a$ idle they travel along the path~$ef$, +but when $a$~and~$b$ are cathodes simultaneously the paths of +the rays are $dg$~and~$eh$ respectively, showing that the two +streams have slightly repelled each other.\nblabel{add:3} + +\includegraphicsmid{fig45}{Fig.~45.} + +\Article{113} Crookes (\textit{Phil.\ Trans.}\ 1879, Part~II, p.~647) found that +if a disc connected with an electroscope is placed in the full +line of fire of these rays it receives a charge of \emph{positive} electricity. +This is not, however, a proof that these rays do not +consist of negatively electrified particles, for the experiments +described in \artref{81}{Art.~81} show that electricity does not pass at +all readily from a gas to a metal, and the positive electrification +of the disc may be a secondary effect arising from the same +cause as the positive electrification of a plate when exposed to +the action of ultra-violet light. For since the action of these rays +is the same as that of ultra-violet light in producing phosphorescence +in the bodies upon which they fall, it seems not +unlikely that the rays may resemble ultra-violet light still +further and make any metal plate on which they fall a cathode. +\index{Crookes on discharge through gases|)}% + +\index{Hertz, xnegative rays@\subdashone negative rays}% +Hertz (\textit{Wied.\ Ann.}\ 19, p.~809, 1883) was unable to discover +that these rays produced any magnetic effect. + +\includegraphicsouter{fig46}{Fig.~46.} + +The paths of the negative rays are governed entirely by the +shape and position of the cathode, they are quite independent +%% -----File: 137.png---Folio 123------- +of the shape or position of the anode. Thus, if the cathode +and anode are placed at one end of an exhausted tube, as in +\figureref{fig46}{Fig.~46}, the cathode rays will not bend round to the anode, +but will go straight down the +tube and make the opposite +end phosphoresce. + +Any part of the tube which +is made to phosphoresce by +the action of these rays seems +to acquire the power of sending out such rays itself, or we may +express the same thing by saying that the rays are diffusely +\index{Goldstein, discharge of electricity through gases|(}% +reflected by the phosphorescent body (Goldstein, \textit{Wied.\ Ann.}\ 15, +p.~246, 1882). \figureref{fig47}{Fig.~47} represents the appearance presented by +a bent tube when traversed by such rays, the darkly shaded +places being the parts of the tube which show phosphorescence. + +\includegraphicsmid{fig47}{Fig.~47.} + +\Article{114} These rays seem to be emitted by any negative electrode, +even if this be one made by putting the finger on the glass of +the tube near the anode. This produces a discharge of negative +electricity from the glass just underneath the finger, and the +characteristic green phosphorescence (if the tube is made of +German glass) appears on the opposite wall of the tube; this +phosphorescence is deflected by a magnet in exactly the same +way as if the rays came from a metallic electrode. This experiment +%% -----File: 138.png---Folio 124------- +is sufficient to show the inadequacy of a theory that has +sometimes been advanced to explain the phosphorescence, viz.~that +the particles shot off from the electrode are not gaseous +particles, but bits of metal torn from the cathode; the phosphorescence +being thus due to the disintegration of the negative +electrode, which is a well-known feature of the discharge in +vacuum tubes. The preceding experiment shows that this theory +\index{Crookes on discharge through gases}% +is not adequate, and Mr.~Crookes has still further disproved +it by obtaining the characteristic effects in tubes when the +electrodes were pieces of tinfoil placed \emph{outside} the glass. + +\Article{115} Goldstein (\textit{Wied.\ Ann.}\ 11, p.~838, 1880) found that a +\index{Contraction in discharge-tube produces effects similar to a cathode}% +\index{Negative electrode, quasi, produced by contraction of tube@\subdashone electrode, quasi, produced by contraction of tube}% +sudden contraction in the cross section of the discharge tube +produces on the side towards the anode the same effect as a +cathode. These quasi-cathodes produced by the contraction of +the tube are accompanied by all the effects which are observed +with metallic cathodes, thus we have the dark space, the phosphorescence, +and the characteristic behaviour of the glow in a +magnetic field. + +\Article{116} Spottiswoode and Moulton (\textit{Phil.\ Trans.}\ 1880, pp.~615--622) +\index{Moulton and Spottiswoode, electric discharge}% +\index{Spottiswoode and Moulton, electric discharge}% +\index{Phosphorescence, due to positive column@\subdashtwo to positive column}% +have observed a phosphorescence accompanying the positive +column. They found that in some cases when this strikes the +gas the latter phosphoresces. They ascribe this phosphorescence +to a negative discharge called from the sides of the tube by the +positive electricity in the positive column. + +\Subsection{Mechanical Effects produced by the Negative Rays.} +\index{Mechanical effects due to negative rays}% +\index{Negative rays, mechanical effects produced by@\subdashtwo mechanical effects produced by}% + +\includegraphicsmid[!t]{fig48}{Fig.~48.} + +\includegraphicsmid[!b]{fig49}{Fig.~49.} + +\Article{117} Mr.~Crookes (\textit{Phil.\ Trans.}\ 1879, Pt.~I, p.~152) has shown +that when these rays impinge on vanes mounted like those in a +radiometer the vanes are set in rotation. This can be shown by +making the axle of the vanes run on rails as in \figureref{fig48}{Fig.~48}. When +the discharge passes through the tube, the vanes travel from the +negative to the positive end of the tube. It is not clear, however, +that this is a purely mechanical effect; it may, as suggested by +Hittorf, be due to secondary thermal effects making the vanes act +like those of a radiometer. In another experiment the vanes are +suspended as in \figureref{fig49}{Fig.~49}, and can be screened from the negative +rays by the screen $e$; by tilting the tube the vanes can be +brought wholly or partially out of the shadow of the screen. +When the vanes are completely out of the shade they do +not rotate as the bombardment is symmetrical; when, however, +%% -----File: 139.png---Folio 125------- +they are half in and half out of the shadow, they rotate +in the same direction as they would if exposed to a bombardment +from the negative electrode. The deflection of the negative +rays by a magnet is well illustrated by this apparatus. Thus, if +the vanes are placed wholly within the shadow no rotation +takes place; if, however, the south pole of an electro-magnet is +brought to \smallsanscap{S}, the shadow is deflected from the former position +and a part of the vanes is thus exposed to the action of the +rays; as soon as this takes place the vanes begin to rotate. + +\Article{118} The thinnest layer of a solid substance seems absolutely +\index{Negative rays, opacity of substances to@\subdashtwo opacity of substances to}% +\index{Opacity of substances to the negative rays,@\subdashone of substances to the negative rays}% +opaque to these radiations. Thus Goldstein (\textit{Phil.\ Mag.}\ [5]~10, +p.~177, 1880) found that a thin layer of collodion placed on the +glass gave a perfectly black shadow, and Crookes (\textit{Phil.\ Trans.}\ +\index{Goldstein, discharge of electricity through gases|)}% +%% -----File: 140.png---Folio 126------- +1879, Part~I, p.~151) found that a thin film of quartz, which is +transparent to ultra-violet light, produced the same effect. This +last result is of great importance in connection with a theory +which has received powerful support, viz.~that these `rays' are a +kind of ethereal vibration having their origin at the cathode. If +this view were correct we should not expect to find a thin quartz +plate throwing a perfectly black shadow, as quartz is transparent +to ultra-violet light. To make the theory agree with the facts +we have further to assume that no substance has been discovered +\index{Hertz, xnegative rays@\subdashone negative rays}% +which is appreciably transparent to these vibrations\footnote + {Since the above was written, Hertz (\textit{Wied.\ Ann.}\ 45, p.~28, 1892) has found that + thin films of gold leaf do not cast perfectly dark shadows but allow a certain amount of + phosphorescence to take place behind them, which cannot be explained by the existence + of holes in the film. It seems possible, however, that this is another aspect of + the phenomenon observed by Crookes (\artref{113}{Art.~113}) that a metal plate exposed to the full + force of these rays becomes a cathode; in Hertz's experiments the films may have been + so thin that each side acted like a cathode, and in this case the phosphorescence on + the glass would be caused by the film acting like a cathode on its own account.}. +The sharpness and blackness of these shadows are by far the +strongest arguments in support of the impact theory of the +phosphorescence. + + +\Article{119} Though Crookes' theory that the phosphorescence is due +to the bombardment of the glass by gaseous particles projected +from the negative electrode is not free from difficulties, it seems +to cover the facts better than any other theory hitherto advanced. +On one point, however, it would seem to require a slight modification: +Crookes always speaks of the \emph{molecules} of the gas receiving +a negative charge. We have, however (see \artref{3}{Art.~3}), seen +reasons for thinking that a molecule of a gas is incapable of +receiving a charge of electricity, and that free electricity must +be on the \emph{atoms} as distinct from the molecules. If this view is +right, we must suppose that the gaseous particles projected from +the negative electrode are atoms and not molecules. This does +not introduce any additional difficulty into the theory, for in the +region round the cathode there is a plentiful supply of dissociated +molecules or atoms; of these, those having a negative +charge may under the repulsion of the negative electricity on +the cathode be repelled from it with considerable violence. + +\includegraphicsouter{fig50}{Fig.~50.} + +\Article{120} An experiment which I made in the course of an investigation +on discharge without electrodes seems to afford considerable +evidence that there is such a projection of atoms from the +%% -----File: 141.png---Folio 127------- +cathode. The interpretation of this evidence depends upon the +fact that the presence in a gas of atoms, or the products of a +previous discharge through the gas, greatly facilitates the passage +of a subsequent discharge. The experiment is represented in +\figureref{fig50}{Fig.~50}: the discharge tube~\smallsanscap{A} was fused on to the pump, and +two terminals~$c$ and~$d$ were fused +through the glass at an elbow of the +tube. These terminals were connected +with an induction coil, and +the pressure in the discharge tube +was such that the electrodeless discharge +would not pass. When the +induction coil was turned on in such +a way that $c$ was the negative electrode +the electrodeless discharge at +once passed through the tube, but no +effect at all was produced when $c$ +was positive and $d$ negative. + +\Article{121} Assuming with Mr.~Crookes +that it is the impact of particles driven +out of the region around the negative +electrode which produces the +phosphorescence, it still seems an +open question whether the luminosity is due to the mechanical +effect of the impulse or whether the effect is wholly electrical. +For since these particles are charged, their approach, collision +with the glass, and retreat, will produce much the same electrical +effect as if a body close to the glass were very rapidly +charged with negative electricity and then as rapidly discharged. +Thus the glass in the neighbourhood of the point of impact of +one of these particles is exposed to a very rapidly changing +electric polarization, the effect of which, according to the electromagnetic +theory of light, would be much the same as if light +fell on the glass, in which case we know it would phosphoresce. + +The sharpness of the shadows cast by these rays shows that the +phosphorescence cannot be due to what has been called a `lamp +action' of the particles, each particle acting like a lamp, radiating +light, and causing the glass to phosphoresce by the light it emits. + +\sloppy +\Article{122} The distance which these particles travel before losing +their power of affecting the glass is surprising, amounting to a +%% -----File: 142.png---Folio 128------- +large multiple of the mean free path of the molecules of the gas +when in a molecular condition; it is possible, however, that they +travel together, forming something analogous to the `electrical +wind,' and that their passage through the gas resembles the +passage of a mass of air by convection currents rather than a +process of molecular diffusion. We must remember, too, that +since atoms are smaller than molecules, the mean free path of a +gas in the atomic condition would naturally be greater than +when in the molecular. + +\fussy +\Article{123} Strikingly beautiful as the phenomena connected with +these `negative rays' are, it seems most probable that the rays +are merely a local effect, and play but a small part in carrying the +current through the gas. There are several reasons which lead +us to come to this conclusion: in the first place, we have seen +that the great mass of luminosity in the tube starts from the +anode and travels down the tube with an enormously greater +velocity then we can assign to these particles; again, this discharge +seems quite independent of the anode, so that the rays +may be quite out of the main line of the discharge. The exact +function of these rays in the discharge is doubtful, it seems just +possible that they may constitute a return current of gas by +which the atoms which carry the discharge up to the negative +electrode are prevented from accumulating in its neighbourhood. + +\Article{124} These rays have been used by Spottiswoode and Moulton +\index{Moulton and Spottiswoode, electric discharge}% +(\emph{Phil.\ Trans.}\ 1880, p.~627) to determine a point of fundamental +importance in the theory of the discharge, viz.~the relative magnitudes +of the following times:--- + +(1) The period occupied by a discharge. + +(2) The time occupied by the discharge of the positive electricity +from its terminal. + +(3) The time occupied by the discharge of the negative electricity +from its terminal. + +(4) The time occupied by molecular streams in leaving a +negative terminal. + +(5) The time occupied by positive electricity in passing along +the tube. + +(6) The time occupied by negative electricity in passing along +the tube. + +(7) The time occupied by the particles composing molecular +streams in passing along the tube. +%% -----File: 143.png---Folio 129------- + +(8) The time occupied by electricity in passing along a wire +of the length of the tube. + +\includegraphicsmid[!b]{fig51}{Fig.~51.} + +The phenomenon which was most extensively used by Spottiswoode +\index{Negative rays, repulsion of@\subdashtwo repulsion of}% +\index{Repulsion, of negative rays@\subdashone of negative rays}% +\index{Spottiswoode and Moulton, electric discharge}% +and Moulton in investigating the relative magnitude +of these times was the repulsion of one negative stream by +another in its neighbourhood. This effect may be illustrated in +several ways: thus, if the finger or a piece of tin-foil connected +to earth be placed on the discharge tube, not too far away +from the anode, the portion of the glass tube immediately +underneath the finger becomes by induction a cathode and emits +a negative stream; this stream produces a phosphorescent patch +on the other side of the tube, diametrically opposite to the +finger. If two fingers or two pieces of tin-foil are placed on the +tube two phosphorescent patches appear on the glass, but neither +of these patches occupies quite the position it would if the other +patch were away. Another experiment (see Spottiswoode and +Moulton, \textit{Phil.\ Trans.}\ 1880, Part~II, p.~614) which also illustrates +the same effect is the following. A tube, \figureref{fig51}{Fig.~51}, was taken, in +which there was a flat piece of aluminium containing a small +hole; when the more distant terminal was made negative, a +bright image~\smallsanscap{A} of the hole appeared on the side of the tube in the +midst of the shadow cast by the plate. When the tube was +touched on the side on which this image appeared, but at a +point on the negative side of the image, it was found that the +image was splayed out to~\smallsanscap{B}, part of it moving down the tube +away from the negative terminal. This seems to show that the +negative electrode formed by the finger pushes away from it +the rays forming the image. From this case Spottiswoode and +Moulton reasoned as follows (\textit{Phil.\ Trans.}\ 1880, Part~II, p.~632): +%% -----File: 144.png---Folio 130------- +`This image was \emph{splayed out} by the finger being placed on the +tube. Now a magnet displaced it as a whole without any +splaying out. This then pointed to a variation in the relative +strength of the interfering stream and the stream interfered +with, and such variation must have occurred during the period +that they were encountering one another, and were moving in +the ordinary way of such streams, for it showed itself in a variation +in the extent to which the streams from the negative +terminal were diverted. We may hence conclude that the time +requisite for the molecules to move the length of the tube was +decidedly less than that occupied by the discharge, but was +sufficiently comparable with it to allow the diminution of +intensity of the streams from the sides of the tube to make +itself visible before the streams from the negative terminal experienced +a similar diminution.' + +\Article{125} This may serve as an example of the method used by +\index{Spottiswoode and Moulton, electric discharge}% +\index{Times involved in electric discharge}% +Spottiswoode and Moulton in comparing the time quantities +enumerated in \artref{124}{Art.~124}. We regret that we have not space to +describe the ingenious methods by which they brought other +time quantities into comparison, for these we must refer to their +paper; we can only quote the final result of their investigation. +They arrange (l.~c.\ pp.~641--642) the time quantities in groups +which are in descending order of magnitude, the quantities in +any group are exceedingly small compared with those in any +group above them, while the quantities in the same group are +of the same order of magnitude. +\begin{olist} +\item[A.] The interval between two discharges. +\item[B.] The time occupied by the discharge of the negative electricity +from its terminal. +\begin{ilist} +\item[] The time occupied by negative streams in leaving a negative +terminal. +\item[] The time occupied by the particles composing molecular +streams in passing along the tube. +\end{ilist} +\item[C.] The time occupied by positive electricity in passing along +the tube. +\begin{ilist} +\item[] The time occupied by negative electricity in passing along +the tube. +\end{ilist} +\item[D.] The time occupied by positive discharge. +\begin{ilist} +\item[] The time required for the formation of positive luminosity +at the seat of positive discharge. +%% -----File: 145.png---Folio 131------- +\item[] The time required for the formation of the dark space at +the seat of negative discharge. +\end{ilist} +\item[E.] The time occupied by either electricity in passing along a +wire of the length of the tube. +\end{olist} + +The time of a complete discharge is of the order~B. + +It will be seen that one of the conclusions given above, viz.~that +the time required for the positive luminosity to travel the +length of the tube is very small compared with the time occupied +by the negative discharge, is confirmed by the experiments with +the rotating mirror described in \artref{104}{Art.~104}. According to these +experiments however C~and~E are of the same order. + +\Subsection{Action of a Magnet upon the Discharge when Electrodes +are used.} + +\Article{126} The appearance and path of the discharge in a vacuum +\index{Electric discharge, passage of across junction of a metal and a gas, action of magnet on@\subdashtwo action of magnet on}% +\index{Magnets, action of, on fdischarge with electrodes@\subdashtwo on discharge with electrodes}% +tube are affected to a very great extent by the action of magnetic +force. We may roughly describe the effect produced by +a magnet by saying that the displacement of the discharge is +much the same as that of a perfectly flexible wire conveying a +current in the direction of that through the tube, the position of +the wire coinciding with the part of the luminous discharge +under consideration. This statement, which at first sight seems +to bring the behaviour of the discharge under magnetic force +into close analogy with that of ordinary currents, is apt, however, +to obscure an essential difference between the two cases. A +current through a wire is displaced by a magnetic force because +the wire itself is displaced, and there is no other path open to +the current. If, however, the current were flowing through a +large mass of metal, if, for example, the discharge tube were +filled with mercury instead of with rarefied gas, there would +(excluding the Hall effect) be no displacement of the current +through it. In the case of the rarefied gas, however, we have, +what we do not have in the metal to any appreciable extent, a +displacement of the lines of flow through the conductor---the +rarefied gas. Thus the effects of the magnetic force on currents +through wires, and on the discharge through a rarefied gas, +instead of being, as they seem at first sight, the same, are +apparently opposed to each other. + +\Article{127} The explanation which seems the most probable is that +%% -----File: 146.png---Folio 132------- +by which we explained the effect of a magnet on the discharge +without electrodes: viz.~that when an electric discharge has +passed through a gas, the supply of dissociated molecules, or of +molecules in a peculiar condition, left behind in the line of the +discharge, has made that line so much better a conductor than +the rest of the gas, that when the particles composing it are +displaced by the action of the magnetic force, the discharge +continues to pass through them in their displaced position, and +maintains by its passage the high conductivity of this line of +particles. On this view the case would be very similar to that +of a current along a wire, the line of particles along which the +discharge passes being made by the discharge so much better a +conductor than the rest of the gas, that the case is analogous to +a metal wire surrounded by a dielectric. + +\includegraphicsouter{fig52}{Fig.~52.} + +\Article{128} This view seems to be confirmed by the behaviour of a +\index{Air-blast, effect of on electric discharge}% +\index{Electric discharge, qeffect of air blast on@\subdashtwo effect of air blast on}% +\index{Feddersen, effect of air blast on spark}% +spark between electrodes when a blast of air is blown across it; +the spark is deflected by the blast much as a flexible wire +would be if fastened at the two electrodes. On the preceding +view the explanation of this would be, that by the passage of the +spark through the gas, the electric strength of the gas along the +line of discharge is diminished, partly by the lingering of atoms +produced by the discharge, partly perhaps by the heat produced +by the spark. When a blast of air is blowing across the space +between the electrodes, the electrically weak gas will be carried +with it, so that the next spark, which +\includegraphicsmid{fig53}{Fig.~53.} +will pass through the weak +gas, will be deflected. Feddersen's observations (\textit{Pogg.\ Ann.}\ 103, +p.~69, 1858) on the appearance presented +by a succession of sparks in +a revolving mirror when a blast of +air was directed across the electrodes, +seem to prove conclusively +that this explanation is the true one, +for he found that the first spark was quite straight, while the +successive sparks got, as shown in \figureref{fig52}{Fig.~52}, gradually more +and more bent by the blast. + +\includegraphicstwo{fig54}{Fig.~54.}{fig55}{Fig.~55.} + +\Article{129} The effects produced by a magnet show themselves in +different ways, at different parts of the discharge. Beginning +\index{Magnets, action of, on negative glow@\subdashtwo on negative glow}% +\index{Negative glow, action of magnet on@\subdashtwo action of magnet on}% +\index{Plücker, effect of magnet on discharge}% +with the negative glow, Plücker (\textit{Pogg.\ Ann.}\ 103, p.~88, 1858), +who was the first to observe the behaviour of this part of the +discharge when under the action of a magnet, found that the +%% -----File: 147.png---Folio 133------- +appearance of the glow in the magnetic field could be described +by saying that the negative glow behaved as if it consisted of a +paramagnetic substance, such as iron filings without weight +and with perfect freedom of motion. He found that the bright +boundary of the negative glow coincided with the line of magnetic +force passing through the extremity of the negative electrode. +Figs.~\figureref{fig53}{53}, \figureref{fig54}{54},~\figureref{fig55}{55},~\figureref{fig56}{56}, which are taken +\includegraphicsmid{fig56}{Fig.~56.} +from Plücker's +%% -----File: 148.png---Folio 134------- +\index{Magnets, action of, on negative rays@\subdashtwo on negative rays}% +\index{Negative rays, phosphorescence due to@\subdashtwo phosphorescence due to}% +paper, show the shape taken by the glow when placed in the +magnetic field due to a strong electro-magnet, the tube being +placed in Figs.~\figureref{fig54}{54},~\figureref{fig55}{55} so that the lines of magnetic force are +transverse to the line of discharge; while in Figs.\ \figureref{fig53}{53}~and~\figureref{fig56}{56} +the line of discharge is more or less tangential to the direction +of the magnetic force. + +\includegraphicsmid[!t]{fig57}{Fig.~57.} + +\includegraphicsmid[!b]{fig58}{Fig.~58.} + +\Article{130} Hittorf (\textit{Pogg.\ Ann.}\ 136, p.~213 \textit{et~seq.}, 1869) found that +\index{Hittorf, discharge through gases}% +when the negative rays were subject to the action of magnetic +force, they were twisted into spirals and sometimes into circular +rings. In his experiments the negative electrode was fused into +a small glass tube fused into the discharge tube, the open end of +the small tube projecting beyond the electrode. The negative +rays were by this means limited to those which were approximately +parallel to the axis of the small tube, so that it was easy +to alter the angle which these rays made with the lines of magnetic +force either by moving the discharge tube or altering the +position of the electro-magnet. The discharge tube was shaped +so that the walls of the tube were at a considerable distance from +the negative electrode. Hittorf found +\includegraphicsmid{fig59}{Fig.~59.} +\includegraphicsmid[b]{fig60}{Fig.~60.} +that when the direction +of the negative rays was tangential to the line of magnetic force +passing through the extremity of the cathode, the rays continued +%% -----File: 149.png---Folio 135------- +to travel along this line; that when the rays were initially at +right angles to the lines of magnetic force they curled up into +circular rings; and that when the rays were oblique to the direction +of the magnetic force they were twisted into spirals of which +two or three turns were visible; the axis of the spiral being +parallel to the direction of the magnetic force. These effects are +illustrated in Figs.~\figureref{fig57}{57}, \figureref{fig58}{58},~\figureref{fig59}{59}, and~\figureref{fig60}{60}. +In Figs.\ \figureref{fig57}{57}~and~\figureref{fig58}{58} the +rays are at right angles to the lines of magnetic force, while in +Figs.\ \figureref{fig59}{59}~and~\figureref{fig60}{60} they are oblique to them. + + +\Article{131} This spiral form is the path which would be traversed +by a negatively charged particle moving away from the cathode. +To prove this, let us assume that the magnetic field is uniform, +and that the axis of~$z$ is parallel to the lines of magnetic force. +Let $e$~be the charge on the particle, $v$~its velocity. Then if we +regard the particle as a small conducting sphere, the mechanical +force on it in the magnetic field is, if $v$~is small compared with +the velocity of light, the same (see \artref{16}{Art.~16}) as that which would +be exerted on unit length of a wire carrying a current whose +%% -----File: 150.png---Folio 136------- +components parallel to the axes of $x$,~$y$,~$z$ are respectively +\[ +\tfrac{1}{3} ev \frac{dx}{ds}, \quad \tfrac{1}{3} ev \frac{dy}{ds}, \quad \tfrac{1}{3} ev \frac{dz}{ds}, +\] +where $ds$ is an element of the path of the particle. Thus, if $m$~is +the mass of the particle, $Z$~the magnetic force, the equations of +motion of the particle are +\begin{align*} +m \frac{d^2 x}{dt^2} &= \tfrac{1}{3} ev Z \frac{dy}{ds}, \Tag{1}\\ +m \frac{d^2 y}{dt^2} &= -\tfrac{1}{3} ev Z \frac{dx}{ds}, \Tag{2}\\ +m \frac{d^2 z}{dt^2} &= 0. \Tag{3} +\end{align*} + +Since the force on the particle is at right angles to its direction +of motion, the velocity~$v$ of the particle will be constant, +and since by~(\eqnref{131}{3}) the component of the velocity parallel to the +axis of~$z$ is constant, the direction of motion of the particle must +make a constant angle, $\alpha$~say, with the direction of the magnetic +force. Since $ds/dt$ is constant, equations (\eqnref{131}{1})--(\eqnref{131}{3}) may be written +\begin{align*} +mv^2 \frac{d^2 x}{ds^2} &= \tfrac{1}{3} ev Z \frac{dy}{ds},\\ +mv^2 \frac{d^2 y}{ds^2} &= -\tfrac{1}{3} ev Z \frac{dx}{ds},\\ +mv^2 \frac{d^2 z}{ds^2} &= 0. +\end{align*} + +If $\rho$ is the radius of curvature of the path, $\lambda$,~$\mu$,~$\nu$ its direction +cosines, +\[ +\frac{d^2 x}{ds^2} = \frac{\lambda}{\rho},\quad \frac{d^2 y}{ds^2} = \frac{\mu}{\rho}, \quad \frac{d^2 z}{ds^2} = \frac{\nu}{\rho}. +\] + +Hence from the preceding equations +\begin{align*} +\frac{\lambda}{\rho} &= \tfrac{1}{3} \frac{Ze}{mv}\, \frac{dy}{ds},\\ +\frac{\mu}{\rho} &= -\tfrac{1}{3} \frac{Ze}{mv}\, \frac{dx}{ds},\\ +\frac{\nu}{\rho} &= 0. +\end{align*} + +Squaring and adding, we get +\[ +\frac{1}{\rho^2} = \Bigl(\tfrac{1}{3} \frac{Ze}{mv}\Bigr)^2 \left\{\Bigl(\frac{dx}{ds}\Bigr)^2 + \Bigl(\frac{dy}{ds}\Bigr)^2 \right\}. +\] +%% -----File: 151.png---Folio 137------- + +But +\[ +\Bigl(\frac{dx}{ds}\Bigr)^2 + \Bigl(\frac{dy}{ds}\Bigr)^2 = \sin^2 \alpha. +\] + +So that +\[ +\frac{1}{\rho} = \tfrac{1}{3} \frac{Ze}{mv} \sin \alpha. +\] + +Hence the radius of curvature of the path of the particle is +constant, and since the direction of motion makes a constant +angle with that of the magnetic force, the path of the particle is +a helix of which the axis is parallel to the magnetic force; the +angle of the spiral is the complement of the angle which the +direction of projection makes with the magnetic force. If $a$~is +the radius of the cylinder on which the spiral is wound, +$a = \rho \sin^2 \alpha$, so that +\[ +a = 3 \frac{mv}{Ze} \sin \alpha. +\] + +If $\alpha = \pi/2$, the spiral degenerates into a circle of which the +radius is~$3 mv/Ze$. + +Let the particle be an atom of hydrogen charged with the +quantity of electricity which we find always associated with the +atom of hydrogen in electrolytic phenomena: then since the +electro-chemical equivalent of hydrogen is about~$10^{-4}$, we have, +if $N$~is the number of hydrogen atoms in one gramme of that +substance, $Ne = 10^4$ and $Nm = 1$; hence when the ray is curled up +into a ring of radius~$a$, +\[ +a = 10^{-4}\, 3 \frac{v}{Z}, +\] +or $3v = 10^4 aZ$ in hydrogen. + +\Article{132} In one of Hittorf's experiments, that illustrated in +\figureref{fig60}{Fig.~60}, he estimated the diameter of the ring as less than +$1$~mm.:\ the gas in this case was air, which is not a simple gas; +we shall assume, however, that $m/e$~is the same as for oxygen, +or eight times the value for hydrogen. Putting +\begin{gather*} +a = 5 × 10^{-2}, \text{~and~} m/e = 8 × 10^{-4}, \text{~we get} \\ +v = \frac{5}{24}\, 10^2 Z +\end{gather*} + +The value of~$Z$ is not given in Hittorf's paper; we may be sure, +however, that it was considerably less than~$10^4$, and it follows +that $v$~must have been less than $2 × 10^5$; this superior limit to +%% -----File: 152.png---Folio 138------- +the value of~$v$ is less than six times the velocity of sound. +Hence the velocity of these particles must be infinitesimal in +comparison with that of the positive luminosity which, as we +have seen, is comparable with that of light. + +\Article{133} A magnet affects the disposition of the negative glow +\index{Negative glow, distribution over electrode@\subdashtwo distribution over electrode}% +\index{Magnets, action of, xdistribution of negative glow over electrodes@\subdashtwo distribution of negative glow over electrodes}% +\index{Electrode, effect of magnet on distribution of negative glow over}% +over the surface of the electrode as well as its course through the +gas. Thus Hittorf (\textit{Pogg.\ Ann.}\ 136, p.~221, 1869) found that +when the negative electrode is a flat vertical disc, and the discharge +tube is placed horizontally between the poles of an electromagnet, +with the disc in an axial plane of the electromagnet; +the disc is cleared of glow by the magnetic +force except upon the highest point +on the side most remote from the positive +electrode, or the lowest point on the side +nearest that electrode according to the +direction of the magnetic force. In +another experiment Hittorf, using as a +cathode a metal tube about $1$~cm.\ in +diameter, found that when the discharge +tube is placed so that the axis of the +cathode is at right angles to the line joining +the poles of the electromagnet the +cathode is cleared of glow in the neighbourhood +of the lines where the normals +are at right angles to the magnetic force. +These experiments show that the action +of a magnet on the glow is the same as its +action on a system of perfectly flexible +currents whose ends can slide freely over +the surface of the negative electrode. + +\includegraphicsouter{fig61}{Fig.~61.} + +\Article{134} The positive column is also deflected +\index{Magnets, action of, on positive column@\subdashtwo on positive column}% +\index{Positive column, effect of magnet on@\subdashtwo effect of magnet on}% +by a magnet in the same way as a perfectly flexible wire +carrying a current in the direction of that through the discharge +\index{De la Rive, rotation of electric discharge}% +tube. This is beautifully illustrated by an experiment due to De~la~Rive +in which the discharge through a rarefied gas is set in +continuous rotation by the action of a magnet. The method of +making this experiment is shown in \figureref{fig61}{Fig.~61}; the two terminals +$a$~and~$d$ are metal rings separated from each other by an insulating +tube which fits over a piece of iron resting on one of the +poles of an electromagnet~$M$. This arrangement is placed in an +%% -----File: 153.png---Folio 139------- +egg-shaped vessel from which the air can be exhausted. To +make the experiment successful it is advisable to introduce a +small quantity of the vapour of alcohol or turpentine. The terminals +$a$~and~$d$ are connected with an induction coil, which, +when the pressure in the vessel is sufficiently reduced, produces a +discharge through the gas between the terminals $a$~and~$d$, which +rotates under the magnetic force with considerable velocity. The +rotation of the discharge through the gas is probably due, as we +have seen, to the displacement of the particles through which one +discharge has already passed; the displaced particles form an +easier path for a subsequent discharge than the original line +of discharge along which none of the dissociated molecules +have been left. The new discharge will thus not be along the +same line as the old one, and the luminous column will therefore +rotate. We can easily see why a simple gas like hydrogen +should not show this effect nearly so well as a complicated one +like the vapour of alcohol or turpentine. For the discharges of +the induction coil are intermittent, so that to produce this rotation +the dissociated molecules produced by one discharge must +persist until the arrival of the subsequent one. Now we should +expect to find that when a molecule of a stable gas like hydrogen +is dissociated by the discharge, the recombination of its atoms +will take place in a much shorter time than similar recombination +for a complex gas like turpentine vapour; thus we should +expect the effects of the discharge to be more persistent, and +therefore the rotation more decided in turpentine vapour than in +hydrogen. + +\Article{135} Crookes (\textit{Phil.\ Trans.}\ 1879, Part~II, p.~657) has produced +\index{Crookes on discharge through gases}% +somewhat analogous rotations of the negative rays in a very +highly exhausted tube. The shape of the tube he employed is +shown in \figureref{fig62}{Figure~62}. When the discharge went through this tube, +the neck surrounding the negative pole was covered with two +or three bright patches which rotated when the tube was placed +over an electromagnet. Crookes found that the direction of rotation +was reversed when the magnetic force was reversed, but that +if the magnetic force were not altered the direction of rotation was +not affected by reversing the poles of the discharge tube. This +is what we should expect if we remember that the bright +spots on the glass are due to the negative rays, and that these +will be at right angles to the negative electrode; thus the reversal +%% -----File: 154.png---Folio 140------- +of the poles of the tube does not reverse the direction of +these rays; it merely alters their distance from the pole of the +electromagnet. The curious thing about the rotation was that +it had the \emph{opposite} direction to that +which would have been produced by the +action of a magnet on a current carrying +electricity in the same direction as that +carried by the negative rays, showing +clearly that this rotation is due to some +secondary effect and not to the primary +action of the magnetic force on the current. + +\includegraphicsouter{fig62}{Fig.~62.} + +\Article{136} An experiment due to Goldstein, +\index{Goldstein, discharge of electricity through gases|(}% +which may seem inconsistent with the +view we have taken, viz.~that the deflection +of the discharge is due to the deflection +of the line of least electric strength, should +be mentioned here. Goldstein (\textit{Wied.\ +Ann.}~12, p.~261, 1881) took a large discharge +tube, $4$~cm.\ wide by $20$~long, the +electrodes being at opposite ends of the +tube. A piece of sodium was placed in +the tube which was then quickly filled +with dry nitrogen, the tube was then exhausted +until a discharge passed freely +through the tube, and the sodium heated +until any hydrogen it might have contained +had been driven off. When this +had been done the tube was refilled with +nitrogen and then exhausted until the +positive column filled the tube with a +reddish purple light. The sodium was then slowly heated until +its vapour began to come off, when the discharge in the lower part +of the tube over the sodium became yellow as it passed through +sodium vapour, while the discharge at the top of the tube remained +red as the sodium vapour did not extend all the way +across the tube. The positive discharge was now deflected by +a magnet and driven to the top of the tube out of the region +occupied by the sodium vapour, the discharge was now entirely +red and showed no trace of sodium light. The experiment does +not seem inconsistent with the view we have advocated, as we +%% -----File: 155.png---Folio 141------- +cannot suppose that more than an infinitesimal quantity of +sodium vapour travelled across the tube under the action of the +magnetic force, and it does not follow that because we suppose +the line of discharge to be weakened by the presence of the +dissociated molecules that these molecules are the only ones +affected by the discharge; it seems much more probable that +they serve as nuclei round which the chemical changes which +transmit the discharge take place. + +\Article{137} The striations are affected by magnetic force; in Figs.\ +\figureref{fig53}{53}~and~\figureref{fig56}{56} may be seen the distortion of \DPtypo{striae}{striæ} when the discharge +\index{Magnets, action of, xstriations@\subdashtwo striations}% +\index{Striations, effect of magnetic force on@\subdashone effect of magnetic force on}% +tube is placed in a magnetic field. If the negative +glow is driven away from the line joining the terminals by +magnetic force, the positive column lengthens and fills part of +the space previously occupied by the negative glow; if the positive +column is striated new \DPtypo{striae}{striæ} appear, so that in this case +we have a creation of \DPtypo{striae}{striæ} by the action of magnetic force. +The most remarkable effect of a magnet on the striated discharge, +\index{Spottiswoode and Moulton, electric discharge}% +however, is that discovered by Spottiswoode and Fletcher +Moulton, and Goldstein; Spottiswoode and Moulton (\textit{Phil.\ Trans.}\ +1879, Part~I, p.~205) thus describe the effect: `If a magnet be +applied to a striated column, it will be found that the column is +not simply thrown up or down as a whole, as would be the case +if the discharge passed in direct lines from terminal to terminal, +threading the \DPtypo{striae}{striæ} in its passage. On the contrary, each stria +is subjected to a rotation or deformation of exactly the same +character as would be caused if the stria marked the termination +of flexible currents radiating from the bright head of the stria +behind it and terminating in the hazy inner surface of the stria +in question. An examination of several cases has led the authors +of this paper to conclude that the currents do thus radiate from +the bright head of a stria to the inner surface of the next, and +that there is no direct passage from one terminal of the tube to +the other.' Goldstein (\textit{Wied.\ Ann.}~11, p.~850, 1880) found that +the striated column could by the action of magnetic force be +broken up into a number of bright curves, of the same kind as +those observed by Hittorf in the negative rays (see \artref{130}{Art.~130}), the +number of bright curves being the same as the number of \DPtypo{striae}{striæ} +which had disappeared; each striation was transformed by the +magnetic force into a separate curve, and these curves were +separated from each other by dark spaces. We may conclude +%% -----File: 156.png---Folio 142------- +\index{Potential distribution of along discharge tube,@\subdashone distribution of along discharge tube}% +from these experiments that the positive column does not consist +of a current of electricity traversing the whole of its length +in the way that such a current would traverse a metal cylinder +coincident with the positive column, but that it rather consists +of a number of separate currents, each striation corresponding +to a current which is to a certain extent independent of those +which precede or follow. The discharge along the positive +column might perhaps be roughly illustrated by placing pieces +of wire equal in length to the \DPtypo{striae}{striæ} and separated by very +minute air spaces along the line of discharge. + +\Article{138} Goldstein found that the rolling up of the \DPtypo{striae}{striæ} by the +magnetic force was most marked at the end of the positive +column nearest the negative electrode: the following is a translation +of Goldstein's description of this process (l.c.\ p.~852). The +appearance is very characteristic when in the unmagnetized condition +the negative glow penetrates beyond the first striation into +the positive column. The end of the negative glow is then further +from the cathode than the first striation or, even if the rarefaction +is suitable, than the second or third. Nevertheless the end of the +negative glow rolls itself under the magnetic action up to the +cathode in the magnetic curve which passes through the cathode. +Then separated from this by a dark space follows on the side of +the anode a curve in which all the rays of the first striation are +rolled up, then a similar curve for the second striation, and so on. + +We shall have occasion to refer to these experiments again in +the discussion of the theory of the discharge. + +\Subsection{On the Distribution of Potential along an Exhausted Tube +through which an Electric Discharge is passing.} + +\Article{139} The changes which take place in the potential as we pass +along the discharge tube are extremely interesting, as they +present a remarkable contrast to those which take place along a +metal wire through which a steady uniform current is passing; +in this case the potential-gradient is uniform along the wire, +but changes when the current changes, being by Ohm's law +proportional to the intensity of the current; in the exhausted +tube, on the other hand, the potential-gradient varies greatly in +different parts of the tube, but in the positive column is almost +independent of the intensity of the current passing through the +gas. The potentials measured are those of wires immersed in +\index{Goldstein, discharge of electricity through gases|)}% +%% -----File: 157.png---Folio 143------- +the rarefied gas, and the question arises, whether the potentials +of these wires are constant, as they would be if the wires were +in a steady current, or whether they are variable, the potentials +determined in these experiments being the mean values about +\index{Continuity of current through discharge-tube}% +which the potentials of the wires fluctuate? This question is +the same as, whether the current through the gas is continuous +or intermittent? On this point considerable difference of opinion +has existed among physicists. There is no doubt that by the +aid of a battery consisting of a large number of cells a discharge +can be got, which, if not continuous, has such a high rate of +intermittence that no unsteadiness can be detected when it is +observed in a rotating mirror making $100$~revolutions per +second; this is sufficient to prove that if the intermittence +exists at all it must be exceedingly rapid. As long, however, +as the discharge retains the property of requiring a large potential +difference to exist between the electrodes, this difference +varying continuously with the pressure, while the latter varies +from that of an atmosphere to the pressure in the discharge +tube, we should expect the electrodes to act like condensers +continually being charged and discharged as they are at atmospheric +pressures, in other words we should expect the discharge +to be intermittent. When, however, the discharge passes +as the `arc discharge,' see \artref{169}{Art.~169}, the potential difference falls +to a comparatively small value, and it is probable that this discharge +is much more nearly continuous than the striated one. + +It ought also to be remembered that the current through the +gas may be interrupted even though that through the leads is +continuous. For since the current through the gas does not +obey the same laws as when it goes through a metallic conductor, +the current across a section of the discharge tube need +not at any specified instant be the same as that across the +section of one of the leads. The average current must of course +be the same in the two cases, but only the \emph{average} current +and not that at any particular instant. To quote an illustration +\index{Spottiswoode and Moulton, electric discharge}% +given by Spottiswoode and Moulton, the discharge tube may +act like the air vessel of a fire engine; all the electricity that +goes in comes out again, but no longer with the same pulsation. +The tube may sometimes contain more and sometimes less free +electricity, and may act as an expansible vessel would act if it +formed part of the path of an incompressible fluid. +%% -----File: 158.png---Folio 144------- + +The rapidity of the intermittence can to some extent be tested +by observing whether or not the discharge is deflected by the +approach of a conductor. When the discharge is intermittent +and the interval between the discharges so long that the intermittence +of the discharge can be detected either by the eye or +by a slowly rotating mirror, the discharge is deflected when a +conductor is brought near it; when however the intermittence is +very rapid, the discharge is not affected by the approach of the +conductor. This effect has been very completely investigated +\index{Spottiswoode and Moulton, electric discharge}% +by Spottiswoode and Moulton (\textit{Phil.\ Trans.}\ 1879, Part~I, p.~166; +1880, Part~II, p.~564). + +\Article{140} We shall begin by considering Hittorf's experiments on +\index{Gradient of potential in discharge tube}% +\index{Hittorf, discharge through gases}% +the potential gradient (\textit{Wied.\ Ann.}~20.\ p.~705, 1883). The discharge +tube, \figureref{fig63}{Fig.~63}, which was $5.5$~cm.\ in diameter and $33.7$~cm.\ +long, had aluminium wires $2$~mm.\ in diameter \DPtypo{$f$ used}{fused} into the +ends for electrodes, the anode,~$a$, was $2$~cm.\ long, the cathode,~$c$, +$7$~cm. In addition to the electrodes five aluminium wires,~$b$, $d$,~$e$, +$f$,~$g$, half a millimetre in diameter, were fused into the tube. +The difference of potential between any two of these wires could +be determined by connecting them to the plates of a condenser, +and then discharging the condenser through a galvanometer. +The deflection of the galvanometer was proportional to the +charge in the condenser, which again was proportional to the +difference of potential between the wires. The discharge was +produced by means of a large number of cells of Bunsen's +chromic acid battery, and the intensity of the current was +varied by inserting in the circuit a tube containing a solution of +cadmium iodide, which is a very bad conductor. No intermittence +in the discharge could be detected either by a mirror +rotating $100$~times a second or a telephone. The tube was filled +with nitrogen, as this gas has the advantage of not attacking +the electrodes and of not being absorbed by them so greedily as +%% -----File: 159.png---Folio 145------- +hydrogen. The results of some of the measurements are given +in the following Table, l.~c.\ p.~727:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{4pt} +\settowidth{\TmpLen}{Number fixing the experiment}% +\begin{tabular}{@{}p{\TmpLen}|c|c|c|c|c|c|c|c@{}} +\multicolumn{9}{c}{\normalsize\textit{Pressure of Nitrogen $.6$~mm.}\medskip} \\ +\hline +\tablespaceup Number fixing the experiment & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ +Number of cells \mdotfill & $500$ & $500$ & $500$ & $600$ & $700$ & $800$ & $900$ & $1000$ \\ +\parbox[b]{\TmpLen}{\tabhang Intensity of current in millionths +of an Ampère \mdotfill} + & $244$ & $814$ & $1282$ & $3175$ & $5189$ & $7000$ & $8791$ & $11192$ \\ +\parbox[b]{\TmpLen}{\tabhang Kick of galvanometer due to +the charging of the condenser +to the potential difference +between---} &&&&&&&& \\ +\parbox[c]{\TmpLen}{\hfill $ac$ \mdotfill} & $133$ & $132$ & $133.5$ & $141.5$ & $150$ & $157$ & $165$ & $173$ \\ +\parbox[c]{\TmpLen}{\hfill $ab$ \mdotfill} & $22$ & $22.5$ & $22$ & $21.5$ & $21$ & $21$ & $21$ & $21$ \\ +\parbox[c]{\TmpLen}{\hfill $bd$ \mdotfill} & $14$ & $13$ & $13$ & $12$ & $12.5$ & $12$ & $12$ & $12.25$ \\ +\parbox[c]{\TmpLen}{\hfill $de$ \mdotfill} & $13$ & $13$ & $13$ & $14$ & $14$ & $13.5$ & $12$ & $12.5$ \\ +\parbox[c]{\TmpLen}{\hfill $ae$ \mdotfill} & $52$ & $50$ & $49$ & $47$ & $47$ & $47$ & $47$ & $47$ \\ +\parbox[c]{\TmpLen}{\hfill $fg$ \mdotfill} & --- & $2.25$ & $3$ & $4$ & $3.75$ & $44$ & $3.25$ & $3$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\medskip + +\includegraphicsmid{fig63}{Fig.~63.} + +The difference of potential in volts can be approximately got +by multiplying the galvanometer deflection by~$6$. In experiment~1 +the negative glow covered about $1.5$~cm.\ of the cathode, +and the positive light extended to~$f$. In experiment~2 the negative +glow covered $6$~cm.\ of the cathode, and in~3 and the following +experiments the whole of the cathode. In experiments 1,~2,~3 +the thickness of the negative glow remained the same; in the +later experiments where the negative glow covered the whole of +the cathode its thickness increased as the intensity of the current +increased, and in 7~and~8 it extended to the walls of the tube. +The table shows that no changes in the potential differences occurred +until the negative glow began to increase in thickness. +\index{Positive column, potential gradient in@\subdashtwo potential gradient in}% +\index{Potential gradient in positive column,@\subdashone gradient in positive column}% +We see that by far the greatest fall in the potential occurs in the +immediate neighbourhood of the cathode, the rise in potential +from the negative electrode to the outside of the negative glow +being far greater than the rise in all the rest of the tube; we also +see that the changes which take place when the thickness of the +negative glow alters take place in this part of the tube, and that +the potential differences in the positive column are \emph{independent +of the strength of the current}. The portions $bd$~and~$de$ of the +positive column, which are very nearly equal in length, have +also practically the same potential differences; and these are +each less than that of the portion~$ab$ which contains the anode, +although the latter portion is considerably shorter. The wires +$f$\DPtypo{;}{,}~$g$ were in all these experiments in the dark space between the +%% -----File: 160.png---Folio 146------- +negative glow and the positive column. The small difference of +potential between these wires is very noteworthy. + +\Article{141} Hittorf also investigated the potential differences for lower +\index{Potential xgradient in positive column at low pressures@\subdashtwo at low pressures}% +pressures of the gas than that used in the last experiment; +for this purpose the tube in \figureref{fig63}{Fig.~63} was not suitable, as the +negative glow was very much interfered with by the walls of the +tube, he therefore used a tube shaped like that in \figureref{fig64}{Fig.~64}, which +was purposely made wide in the region round the negative +electrode. The diameter of the positive part of the tube was +$4$~cm., that of the negative $12$~cm. The length of the negative +electrode was $15$~cm., that of the positive $3$~cm. In this case +only two wires, $b$~and~$d$, were inserted in the tube. The results +of experiments with this tube are given in the following +table:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{4pt} +\settowidth{\TmpLen}{Pressure of the nitrogen in millimetres}% +\begin{tabular}{@{}p{\TmpLen}|c|c|c|c|c|c@{}} +\hline +\tablespaceup Number fixing the experiment & 1 & 2 & 3 & 4 & 5 & 6 \\ +\parbox[b]{\TmpLen}{\tabhang Pressure of the nitrogen in +millimetres of mercury\mdotfill} + & $\Z\Z\llap{.}70$ & $\Z\Z\llap{.}35$ & $\Z\llap{.}175$ & $\Z\llap{.}088$ & $\llap{.}044$ & $\llap{.}022$ \\ +\parbox[b]{\TmpLen}{Number of cells\mdotfill} & $\Z600$ & $\Z600$ & $\Z600$ & $\Z600$ & $600$ & $600$ \\ +\parbox[b]{\TmpLen}{\tabhang Strength of current in millionths +of an Ampère\mdotfill} +& $2870$ & $2076$ & $1791$ & $1360$ & $916$ & $488$ \\ +\parbox[c]{\TmpLen}{\tabhang Kick of galvanometer due to +the charging of the condenser +to the potential difference +between---} & & & & & & \\ +\hfill 1 \qquad $ac$\mdotfill & $\Z151\Z$ & $\Z140\Z$ & $\Z145\Z$ & $\Z157\phantom{.0}$ & $\Z168\Z$ & $178\phantom{.00}$ \\ +\hfill 2 \qquad $ab$\mdotfill & $\Z21$ & $\Z15$ & $\Z12$ & $\Z\Z\Z9.5$ & $\Z\Z8$ & $\Z\Z7\phantom{.00}$ \\ +\hfill 3 \qquad $bd$\mdotfill & $\Z30$ & $\Z19$ & $\Z12$ & $\Z\Z\Z8\phantom{.0}$ & $\Z\Z5$ & $\Z\Z4.25$ \\ +\hfill 4 \qquad $ad$\mdotfill & $\Z51$ & $\Z34$ & $\Z24$ & $\Z\Z17.5$ & $\Z13$ & $\Z11.25$\tablespacedown \\ +\hline +\end{tabular} +%% -----File: 161.png---Folio 147------- + +\bigskip +\begin{tabular}{@{}p{\TmpLen}|c|c|c|c|c@{}} +\hline +\tablespaceup Number fixing the experiment & 7 & 8 & 9 & 10 & 11 \\ +\parbox[b]{\TmpLen}{\tabhang Pressure of the nitrogen in +millimetres of mercury\mdotfill} + & $.011$? & $.0055$? & $.0029$? & $.0014$? & $.0007$? \\ +\parbox[b]{\TmpLen}{Number of cells\mdotfill} & $600$ & $800$ & $1000$ & $1200$ & $1400$ \\ +\parbox[b]{\TmpLen}{\tabhang Strength of current in millionths +of an Ampère\mdotfill} + & $326$ & $610$ & $\Z814$ & $\Z814$ & $1100$ \\ +\parbox[b]{\TmpLen}{\tabhang Kick of galvanometer due to +the charging of the condenser +to the potential difference +between---} & & & & & \\ +\hfill 1 \qquad $ac$\mdotfill & $184$ & $242$ & $298$ & $352$ & $422$ \\ +\hfill 2 \qquad $ab$\mdotfill & $\Z\Z7$ & $\Z\Z7$ & $\Z\Z8$ & $\Z8.5$ & $8.75$ \\ +\hfill 3 \qquad $bd$\mdotfill & $\Z\Z4$ & $\Z\Z4$ & $3.75$ & $\Z2.5$ & $2.25$ \\ +\hfill 4 \qquad $ad$\mdotfill & $\Z11$ & $\Z11\rlap{$.5$}$ & $\Z12$ & $11.5$ & $10.5$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\includegraphicsmid{fig64}{Fig.~64.} + +The negative glow in all these experiments covered the cathode, +and in all but the first three it extended to the walls of the tube. +The appearance of the glow at the higher exhaustions is shown +in \figureref{fig64}{Fig.~64}, where the shaded portions represent the bright parts +of the discharge; it will be seen from the figure that the positive +column was striated. + +\Article{142} The table shows that at high exhaustions the potential +difference between the electrodes increases as the density of the +gas diminishes, but that this increase is confined to the neighbourhood +of the cathode; the ratio of the change in potential +near the cathode to that in the rest of the tube increases as +the pressure of the gas diminishes. The potential difference +in the positive light diminishes as the pressure is reduced, but +the diminution in the potential difference is not so rapid as the +diminution in the pressure. The table seems to suggest that +the potential gradient in the positive column tends towards a +constant value which is independent of the density. We must +remember however that Hittorf's experiments do not give the +potential difference required to initiate the discharge through +the gas, but the distribution of potential which accompanies +the passage of electricity through the gas when the discharge +has been established for some time, and where there are a +plentiful supply of dissociated molecules produced by the +passage of previous discharges. Hittorf found that the number +of cells which would maintain a discharge after it was once +started was frequently quite insufficient to initiate it, and +the gas had to be broken through by a discharge from another +source. + +\Article{143} The experiments described in \artref{79}{Art.~79} on the discharge +%% -----File: 162.png---Folio 148------- +without electrodes, when the interval between two discharges +was long enough to give the gas through which the discharge +had passed an opportunity of returning to its normal condition +before the passage of the next discharge, show that even when +no electrodes are used the electromotive intensity required to +start the discharge has a minimum value at a particular pressure, +and that when the pressure is reduced below this value +the electromotive intensity required for discharge increases. + +\Article{144} The supply of dissociated molecules furnished by previous +discharges also explains another peculiarity of these experiments. +It will be seen from the table that at a pressure of $.0007$~mm.\ +of mercury, a potential difference which gave a galvanometer +deflection of~$10.5$, corresponding to about $63$~volts, was all that +occurred in a length of $12$~cm.\ of the positive light; it does not +follow however that a potential gradient of about $5$~volts per +centimetre would be sufficient to \emph{initiate} the discharge even if the +great change in potential at the cathode were absent. In fact +the experiments previously described on the discharge without +electrodes show that it requires a very much greater electromotive +intensity than this even when the cathode is entirely done +away with. + +The table shows that the potential difference between $a$~and~$b$, +a space which includes the anode, has at the higher exhaustions +passed its minimum value and commenced to increase. + +\Article{145} Though the potential differences between wires immersed +in the positive column is independent of the strength of the +current passing through the tube, yet in such a tube as \figureref{fig63}{Fig.~63} +the potential differences between wires in the middle of the +tube may be affected by variations in the current if these variations +are accompanied by changes in the appearance of the discharge. + +Let us suppose, for example, that the tube is filled with nitrogen +at a pressure of from $2$ to $3$~mm.\ of mercury, then when the intensity +of the current is very small the tube will appear to be +dark throughout almost the whole of its length, the positive +column and negative glow being reduced to mere specks in the +neighbourhood of the electrodes; when however the intensity of +the current increases the positive column increases in length, and +if the increase is great enough to make it envelop two wires +which were previously in the dark Faraday space, the difference +%% -----File: 163.png---Folio 149------- +of potential between these wires will be found to be very much +greater than when the gas round them was non-luminous. This +is illustrated for lower pressures by the table in \artref{140}{Art.~140}, which +shows that the potential gradient between $f$~and~$g$, the wires +in the dark space between the positive column and the negative +glow, was very much less than the potential gradient in +the positive column. It is shown however still more clearly +in the following set of experiments made with the tube shown +in \figureref{fig63}{Fig.~63} (l.~c.\ p.~739). + +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{3pt} +\settowidth{\TmpLen}{Kick of the galvano-}% +\begin{tabular} {@{}c|c|c|c|c|c|c|c@{}} +\multicolumn{8}{c}{\normalsize\textit{Pressure of Nitrogen $3.95$~mm.\ of Mercury.}}\\ +\multicolumn{8}{c}{\normalsize\textit{Temperature $12°$\,C.}\medskip} \\ +\hline +\parbox[b]{\TmpLen}{\tablespaceup\tabhang Number fixing the +experiment\mdotfill} & 1 & 2 & 3 & 4 & 5 & 6 & 7\\ +\parbox[b]{\TmpLen}{Number of cells\mdotfill} & $700$ & $700$ & $700$ & $800$ & $900$ & $1000$ & $1200$ \\ +\parbox[b]{\TmpLen}{\tabhang Intensity of the current +in millionths +of an Ampère\mdotfill} & $1465$ & $2035$ & $2391$ & $2483$ & $2830$ & $3541$ & $5820$ \\ +\parbox[b]{\TmpLen}{\tabhang Kick of the galvano\-meter +from the +charge in the condenser +due to the +potential difference +between---} & & & & & & & \\ +\hfill 1 \qquad $ac$\mdotfill & $166$--$168$ & $175$--$168$ & $190$--$188$ & $212$--$208$ & $238$--$232$ & \PadTo{238$--$232}{255} & $292$--$285$ \\ +\hfill 2 \qquad $ab$\mdotfill & --- &--- &--- &--- & $63$ & $\Z60$ & \PadTo[l]{99.9}{79} \\ +\hfill 3 \qquad $bd$\mdotfill & $16.5$ & \PadTo[l]{19.9}{18} & $18.5$ & $25$ & $43$ & $\Z61$ & $56.5$ \\ +\hfill 4 \qquad $de$\mdotfill & $17.5$ & \PadTo[l]{19.9}{18} & \PadTo[l]{19.9}{17} & $18$ & $20$ & $\Z26$ & \PadTo[l]{99.9}{62} \\ +\hfill 5 \qquad $fg$\mdotfill & \PadTo[l]{19.9}{10} & $10.5$ & $11.5$ & $12$ & $13$ & $\Z13$ & $12.5$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\Article{146} In experiments~1--3 the tube was quite dark, except +quite close to the electrodes; the anode had a thin coating of +positive light. The negative glow extended in experiment~1 over +$1$~cm.\ of the cathode, in experiment~2 over $3$~cm., and in experiment~3 +over $3$~cm. In experiment~3 the beginning of a brush +discharge was discernible at the anode. In consequence of the +wires being in the dark Faraday space instead of the positive +column, it will be noticed that the potential difference between +$b$~and~$d$ is very little greater than in the experiments described +in \artref{140}{Art.~140}, though the pressure is more than six times +greater. + +\Article{147} In experiment~4 the positive column reached past~$b$; +it will be seen that the potential difference between $b$~and~$d$ +rose to~$25$, while the differences between $d$~and~$e$ and between +%% -----File: 164.png---Folio 150------- +$f$~and~$g$, which were still in the dark, remained unaltered. In +experiment~5 the positive column reached past the middle of~$bd$; +the potential difference in~$bd$ rose from~$25$ to~$43$, the potential +differences between the wires in the dark still being unaltered. +In experiment~6 the positive light filled the whole space~$ad$; +the potential difference between $b$~and~$d$ rose to~$61$, and that +between $d$~and~$e$ also began to rise as $d$~was now in the positive +column; this difference increased very much in experiment~7, +when the positive column reached to~$e$. + +\Article{148} We now pass on to the effect of an alteration in the +\index{Cathode, potential fall at}% +\index{Potential difference at cathode}% +strength of the current on the potential difference at the cathode. +We have already remarked that if the negative glow does not +spread over the whole of the cathode, the only effect of an increase +in the intensity of the current is to make the negative glow spread +still further over the cathode, without altering the potential difference. +Until the glow has covered the electrode, there is, according +to Hittorf, no considerable increase in temperature at +the cathode: when however the intensity of the current is increased +beyond the point at which the whole of the cathode is +covered by the glow, the temperature of the cathode begins to +increase; when the current through the gas is very strong, the +cathode, and sometimes even the anode, becomes white hot. When +this is the case the character of the discharge changes in a remarkable +way, all luminosity disappears from the gas, which +when examined by the spectroscope does not show any trace of +the lines of its spectrum. The tube with its white hot electrodes +surrounded by the dark gas presents a remarkable appearance, +and it is especially to be noted that the electrodes are raised to +incandescence by a current, which if it passed through them +when they formed part of a metallic circuit, would hardly make +them appreciably hot. + +Hittorf also found (\textit{Wied.\ Ann.}~21.\ p.~121, 1884) that if in +a vacuum tube conveying an ordinary luminous discharge, a +platinum spiral which could be raised by a battery to a white +heat was placed so as to be in the path of the discharge, the +latter lost all luminosity in the neighbourhood of the spiral +when this was white hot. If the spiral was allowed to cool, the +luminosity appeared again before the spiral had cooled below a +bright red heat. + +\Article{149} For experiments of this kind aluminium electrodes melt +%% -----File: 165.png---Folio 151------- +too easily. Hittorf used in most of his experiments iridium +electrodes, which can be raised to a very high temperature without +melting. These were raised to a white heat before any +measurements were made, so as to get rid of any gas they +might have occluded. The length of the electrodes was $48$~mm. +The result of some experiments on nitrogen is given in the +following table (\textit{Wied.\ Ann.}~21, p.~111, 1884); in this, when +the number of cells is given as $600 × x$, it means that $x$~sets +of cells, each containing $600$~elements, were connected up in +parallel. + +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{3pt} +\settowidth{\TmpLen}{Pressure of the nitrogen in millimetres}% +\begin{tabular} {@{}c|c|c|c|c|c@{}} +\multicolumn{6}{c}{\normalsize\textit{Experiments with Nitrogen.}}\\ +\multicolumn{6}{c}{\normalsize\textit{Iridium electrodes at a distance of $15$~mm.}\medskip}\\ +\hline +\parbox[b]{\TmpLen}{\tablespaceup Number fixing the experiment} & 1 & 2 & 3 & 4 & 5 \\ +\parbox[b]{\TmpLen}{\tabhang Pressure of the nitrogen in +millimetres of mercury\mdotfill} & $19.65$ & $31.9$ & $53.1$ & $53.1$ & $52.4$ \\ +\parbox[b]{\TmpLen}{Number of cells\mdotfill} & $600×3$ & $600×3$ & $600×3$ & $600×4$ & $400×6$ \\ +\parbox[b]{\TmpLen}{Strength of current in Ampères} & $.535$ & $1.225$ & $1.4$ & $2.0$ & $2.1$ \\ +\parbox[b]{\TmpLen}{\tabhang Kick of the galvanometer due to the charge in the condenser +produced by the potential difference between +the electrodes\mdotfill} & $75$--$82$ & $25$--$32$ & $25$--$32$ & $15$--$20$ & $17$--$20$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +In the first experiment a reddish-yellow positive column +stretched at first from the anode to an intensely bright patch on +the cathode; the cathode however soon became white hot along +the whole of its length, and then showed no trace of the negative +glow, nor were any nitrogen lines detected when the region round +the cathode was examined by the spectroscope. The tip of the +anode was white hot. + +From the second experiment we see that though the density +of the nitrogen was much greater, the potential difference was +less than half what it was in the first experiment. This is due +to the electrodes being hotter in this experiment than in the preceding +one. In the third experiment only half of the cathode +was white hot, but the length of the anode which was incandescent +was greater than in the preceding experiment. In +the fourth experiment, in which a current of $2$~Ampères passed +through the gas, the end of the anode was hotter than that of the +cathode, in fact with this current the anode, though made of +iridium, began to melt. In the ordinary arc lamp, in which we +%% -----File: 166.png---Folio 152------- +have probably a discharge closely resembling that in this experiment, +the anode is also hotter than the cathode when the +current is intense. + +In this case the gas was quite dark. A very remarkable +feature shown by it is the smallness of the potential difference +between the electrodes, not amounting to more than $100$~volts, +though the gas was at the pressure of $53.1$~millimetres, and the +distance between the electrodes $15$~mm. When the electrodes +were cold, the battery power used, about $1200$~volts, was not +sufficient to break down the gas: the discharge had to be +started by sending a spark from a Leyden jar through the tube. +The conduction through the gas in this case is of the same +character as that described in \artref{169}{Art.~169}. + +\Article{150} Hittorf also made experiments on hydrogen and carbonic +\index{Hittorf, discharge through gases}% +oxide; the results for hydrogen are given in the following table +(\textit{Wied.\ Ann.}~21, p.~113, 1884):--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{3pt} +\settowidth{\TmpLen}{Kick of the galvanometer due}% +\begin{tabular}{@{}c|c|c|c|c|c|c@{}} +\multicolumn{7}{c}{\normalsize\textit{Experiments with Hydrogen.}}\\ +\multicolumn{7}{c}{\normalsize\textit{Distance of the Iridium electrodes $15$~mm.}\medskip}\\ +\hline +\parbox[b]{\TmpLen}{\tablespaceup\tabhang Number fixing the +experiment\mdotfill} & 1 & 2 & 3 & 4 & 5 & 6\\ +\parbox[b]{\TmpLen}{\tabhang Pressure of hydrogen +in millimetres +of~Hg\mdotfill} & $20$ & $33.8$ & $47.05$ & $47.05$ & $47.05$ & $68.55$\\ +\parbox[b]{\TmpLen}{\tabhang Number of cells\mdotfill} & $400×6$ & $400×6$ & $400×6$ & $600×4$ & $800×3$ & $800×3$\\ +\parbox[b]{\TmpLen}{\tabhang Intensity of current +in Ampères\mdotfill} & $.5465$ & $.3415$ & $.3074$ & $.9222$ & $.9905$ & $.8197$\\ +\parbox[b]{\TmpLen}{\tabhang Kick of the galvanometer due to the +charge in the condenser produced by the potential difference between +the electrodes\mdotfill} & $100$ & $107$--$108$ & $110$ & $100$--$110$ & $107$--$110$ & $110$\tablespacedown\\ +\hline +\end{tabular} +\end{center} + +In experiment~1 the pressure and the current were almost the +same as for experiment~1, \artref{149}{Art.~149}, in nitrogen; the potential +difference between the electrodes was however much greater +in hydrogen than in nitrogen, though the potential difference +required to \emph{initiate} a discharge in hydrogen is considerably +less than in nitrogen. In these experiments the potential difference +between the electrodes for this dark discharge seems +almost independent of the current and of the density of the +gas. +%% -----File: 167.png---Folio 153------- + +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{3pt} +\settowidth{\TmpLen}{Kick of the galvanometer due to the charge in the}% +\begin{tabular}{@{}c|c|c|c|c@{}} +\multicolumn{5}{c}{\normalsize\textit{Experiments with Carbonic Oxide Gas.}}\\ +\multicolumn{5}{c}{\normalsize\textit{Distance between Iridium electrodes $15$~mm.}\medskip}\\ +\hline +\parbox[b]{\TmpLen}{\tabhang +\tablespaceup Number fixing the experiment\mdotfill} & 1 & 2 & 3 & 4 \\ +\parbox[b]{\TmpLen}{\tabhang +Pressure of CO in millimetres +of mercury\mdotfill} & $13.1$ & $22.75$ & $51.7$ & $75.85$ \\ +\parbox[b]{\TmpLen}{\tabhang +Number of cells\mdotfill} & $800×3$ & $800×3$ & $800×3$ & $800×3$ \\ +\parbox[b]{\TmpLen}{\tabhang +Intensity of current in Ampères\mdotfill} & $.8880$ & $.9734$ & $1.3662$ & $1.2978$ \\ +\parbox[b]{\TmpLen}{\tabhang +Kick of the galvanometer due +to the charge in the condenser +produced by the potential +difference between +the electrodes\mdotfill} & $92$--$100$ & $89$--$92$ & $40$ & $42$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +The great fall in potential, which occurs between experiments 2~and~3 +\index{Cathode, potential fall at}% +on~CO, was accompanied by a loss of luminosity; in 1~and~2 +there was a little positive blue light at the anode, but in~3 +this had disappeared, and the discharge was quite dark and +showed in the spectroscope no trace of the carbonic oxide bands. + +\includegraphicsouter{fig65}{Fig.~65.} + +\Article{151} When repeating these experiments with carbon electrodes +\index{Hittorf, discharge through gases}% +instead of iridium ones, Hittorf found that +with strong currents and at pressures between $10$~mm.\ +and $2$~mm.\ the discharge through hydrogen took a +very peculiar form, it consisted of ring-shaped \DPtypo{striae}{striæ}, +the insides of which were dark. These rings extended +through the tubes and encircled both the anode and +the cathode, as shown in \figureref{fig65}{Fig.~65}. + +\Article{152} The preceding experiments show that when +the electrodes are white hot, the negative glow disappears, +and the potential difference between the electrodes +when a current is passing through the gas sinks +to a fraction of the value it has when the electrodes +are cold and the negative glow exists. Hittorf (\textit{Wied.\ Ann.}\ 21, +p.~133) has shown by a direct experiment that when the cathode +is white hot a very small electromotive force is sufficient to +maintain the discharge. The arrangement he used is shown in +\figureref{fig66}{Fig.~66}. A thin carbon filament which serves as a cathode is +stretched between two conductors~$mn$, and can be raised to +a white heat by a current passing through it and these conductors; +the anode~$a$ is vertically below the cathode and remains +cold. When the pressure was very low, Hittorf found that $1$~cell +of his battery, equivalent to about $2$~volts, would maintain a +current between the anode and cathode when they were separated +%% -----File: 168.png---Folio 154------- +\index{Potential difference at cathode|indexetseq}% +by $6$~cm.; in this case the discharge was quite dark. When ten or +more cells were used a pale bluish light spread over the anode. +It should be noticed that the single cell does not \emph{start} the current, +it only maintains it: the current +has previously to be started +by the application of a much +greater potential difference. Hittorf +generally started the current +by discharging a Leyden jar +through the tube. No current at +all will pass if the poles are reversed +so that the anode is hot +and the cathode cold. In these +experiments it is necessary for +the cathode to be at a white heat +for an appreciable current to pass +between the electrodes; very little +effect seems to be produced on the +potential difference at the cathode +until the latter is hotter than a +bright red heat. The current +produced by a given electromotive +force is greater at higher +exhaustions than at low ones, but +Hittorf found he could get appreciable +effects at pressures up to $9$~or $10$~mm. + +\Article{153} In considering the results of experiments in which carbon +filaments or platinum wires are raised to incandescence, we must +remember that, as Elster and Geitel have shown (\artref{43}{Art.~43}), electrification +is produced by the incandescent body, the region around +which receives a charge of electricity; though whether the carrier +of this charge is the disintegrated particles of the incandescent +wire, or the dissociated molecules of the gas itself, is not clear. +This electrification often makes the interpretation of experiments +in which incandescent bodies are used ambiguous. Thus for +example, Hittorf in one experiment (\textit{Wied.\ Ann.}\ 21, p.~137, +1884) used a U-shaped discharge tube, in one limb of which a +carbon filament was raised to incandescence; the other limb of +the tube contained a small gold leaf electroscope; when the +pressure of the gas in the tube was very low, Hittorf found that +%% -----File: 169.png---Folio 155------- +the electroscope would retain a charge of negative electricity but +immediately lost a positive charge. This experiment does not +however show conclusively that positive electricity escapes more +easily than negative from a metal into a gas which is in the condition +in which it conducts electricity, because the same effect +would occur if the incandescent carbon filament produced a +negative electrification in the gas around it. + +\includegraphicsouter[22]{fig66}{Fig.~66.} + +\Article{154} The way in which the passage of electricity from metal +to gas, or \emph{vice versâ}, is facilitated by increasing the temperature +of the metal to the point of incandescence is illustrated by an +effect observed in the experiments on hot gases described in +\artref{37}{Art.~37}. It was found that when a current was passing between +electrodes immersed in a platinum tube at a bright yellow heat +and containing some gas, such as iodine, which conducts well, the +current was at once stopped if a large piece of cold platinum foil +was lowered between the electrodes, although there was a strong +up-current of gas in the tube which prevented a cold layer of gas +being formed against the platinum foil: as soon, however, as the +foil became incandescent the current from one or two Leclanché +cells passed freely. It would appear, therefore, that even when +the gas is in the condition in which it conducts electricity freely, +some of the cathode potential difference will remain as long as the +cathode itself is not incandescent. + +\Article{155} The passage of electricity from a gas to a negative electrode +seems, as we shall see later, to require something equivalent +to chemical combination between the charged atoms of the metal +and the atoms of the gas which carry the discharge; and the +reason for the disappearance of the fall in potential at the cathode +when the latter is incandescent is probably due to this combination +taking place under these circumstances much more easily +than when the electrode is cold. + +\Article{156} Warburg (\textit{Wied.\ Ann.}\ 31, p.~545, 1887: 40\DPtypo{.}{,}\ p.~1, 1890) +\index{Negative electrode,x potential fall at@\subdashtwo potential fall at}% +\index{Warburg, potential fall at cathode@\subdashone potential fall at cathode|indexetseq}% +has made a valuable series of experiments on the circumstances +which influence the fall of potential at the cathode. He has investigated +the effect produced on this fall by altering the gas, +the size and material of the electrodes, and the amount of impurity +in the gas. Hittorf, as we have seen, had already shown +that as long as there is room for the negative glow to spread +over the surface of the cathode, the cathode fall in potential is +approximately independent of the intensity of the current. +%% -----File: 170.png---Folio 156------- + +In Warburg's experiments, the fall in potential at the cathode, +by which is meant the potential difference between the cathode +and a wire at the luminous boundary of the negative glow, was +measured by a quadrant electrometer. Warburg found that, so +long as the whole of the cathode was not covered by the negative +glow, the fall in potential at the cathode was nearly independent +of the density of the gas: this is shown by the following table +(l.~c.\ p.~579), in which $E$~represents the potential difference between +the electrodes, which were made of aluminium, $e$~the potential +fall at the cathode, $E$~and~$e$ being measured in volts, $p$~the +pressure of the gas, dry hydrogen, measured in millimetres of mercury, +$i$~the current through the gas in millionths of an Ampère. +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{2em} +\begin{tabular}{c|c|c|c} +\hline +\tablespaceup $p$. & $e$. & $E-e$. & $i$.\tablespacedown\\ +\hline +\tablespaceup $9.5\Z$ & $191$ & $139$ & $6140$ \\ +$6.4\Z$ & $190$ & $103$ & $4740$ \\ +$4.4\Z$ & $190$ & $\Z70$ & $4810$ \\ +$3.0\Z$ & $189$ & $\Z50$ & $2640$ \\ +$1.79$ & $191$ & $\Z40$ & $1730$ \\ +$1.20$ & $192$ & $\Z39$ & $1360$ \\ +$\Z.80$ & $191$ & $\Z39$ & $\Z508$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +This table shows that though the fall in potential in the positive +light decreased as the pressure diminished, the fall in potential at +the cathode remained almost constant. + +\Article{157} In imperfectly dried nitrogen, which contained also a +trace of oxygen, the cathode potential difference depended to some +extent on the metal of which the electrode was made; platinum, +zinc, and iron electrodes had all practically the same potential +fall; for copper electrodes the fall was about $3$~per~cent.\ and for +aluminium electrodes about $15$~per~cent.\ less than for platinum. +In hydrogen which contained a trace of oxygen, the potential fall +for platinum, silver, copper, zinc, and steel was practically the +same, about $300$~volts. In the case of the last three metals, +however, the value of the cathode potential fall at the beginning +of the experiment was much lower than $300$~volts, and it was +not until after long sparking that it rose to its normal value; +Warburg attributed this to the presence at the beginning of +the experiment of a thin film of oxide which gradually got +dissipated by the sparking; he found by direct experiment +that the potential fall of a purposely oxidised steel electrode +was less than the value reached by a bright steel electrode after +%% -----File: 171.png---Folio 157------- +being used for some time. The potential fall for aluminium and +magnesium electrodes was about $180$~volts, and was thus considerably +smaller than for platinum electrodes (cf.\ \artref{47}{Art.~47}); these +metals, however, are easily oxidised; and as, unlike other metals, +they do not disintegrate when used as cathodes, the film of oxide +would not get removed by use. + +\Article{158} The fact that a large number of metals give the same +potential fall, while others give a varying one, seems to indicate +that this potential fall depends upon whether the electrodes do +or do not take part in some chemical change occurring at the +cathode; and the connection between this fall in potential and +the chemical changes which take place near the cathode seems +still more clearly shown by the surprisingly large effects produced +by a small quantity of impurity in the gas. Warburg +found that the fall of potential at the cathode in nitrogen which +contained traces both of moisture and oxygen was $260$~volts, +while the same nitrogen, after being very carefully dried, gave a +cathode fall of $343$~volts: thus, in this case, a mere trace of +moisture had diminished the cathode fall by $25$~per~cent., the +removal of the trace of oxygen produced equally remarkable +effects, see \artref{160}{Art.~160}. This points clearly to the influence exerted +by chemical actions at the cathode on the fall of potential in +that region; since a mere trace of a substance is often sufficient +to start chemical reactions which would be impossible +\index{Pringsheim, combination of hydrogen and chlorine}% +without it: thus, for example, Pringsheim (\textit{Wied.\ Ann.}~32, p.~384, +1887) found that unless traces of moisture were present, hydrogen +and chlorine gas would not combine to form hydro-chloric acid +under the action of sunlight unless it was very intense. + +\Article{159} The fall of potential at the cathode seems to be lowered +as much by a trace of moisture as by a larger quantity, as long +as the total quantity of moisture in the nitrogen remains small; if, +however, the amount of aqueous vapour is considerable, the fall in +potential is greater than for pure nitrogen; thus in a mixture of +nitrogen and aqueous vapour, in which the pressure due to the +nitrogen was $3.9$~mm., that due to the aqueous vapour $2.3$~mm., +Warburg found that the fall in potential was about $396$~volts, as +against about $343$~volts for nitrogen containing a trace of oxygen; +the increase in the fall of potential at the cathode was, however, +not nearly so great comparatively as the increase in the potential +differences along the positive column. +%% -----File: 172.png---Folio 158------- + +In hydrogen, Warburg found that a trace of aqueous vapour +increased the potential difference at the cathode instead of +diminishing it as in nitrogen. + +\Article{160} Warburg (\textit{Wied.\ Ann.}~40, p.~1, 1890) also investigated +the effects produced by removing from the nitrogen or hydrogen +any trace of oxygen that might have been present. This was +done by placing sodium in the discharge tube, and then after the +other gas had been let into the tube, heating up the sodium, +which combined with any oxygen there might be in the tube. +The effect of removing the oxygen from the nitrogen was +very remarkable: thus, in nitrogen free from oxygen, the fall of +potential at the cathode when platinum electrodes were used +was only $232$~volts as against $343$~volts when there was a trace +of oxygen present; when magnesium electrodes were used the +fall in potential was $207$~volts; in hydrogen free from oxygen +the fall of potential was $300$~volts with platinum electrodes, and +$168$~volts with magnesium electrodes; thus with platinum +electrodes the potential fall in hydrogen is greater than in +nitrogen, while with magnesium electrodes it is less. + +\Article{161} Warburg also investigated a case in which the conditions +for chemical change at the cathode were as simple as possible, +one in which the gas was mercury vapour (with possibly a trace +of air) and the cathode a mercury surface; he found that the +negative dark space was present, and that the cathode fall was +very considerable, amounting to about $340$~volts; this, at the +pressures used in these experiments between $3.5$~mm.\ and $14.0$~mm., +was much greater than the potential difference in a portion +of the positive light about half as long again as the piece at the +cathode, for which the potential fall was measured. + +\Article{162} In air free from carbonic acid, but containing a little +moisture, Warburg (\textit{Wied.\ Ann.}~31, p.~559, 1887) found that the +potential fall was about $340$~volts: this is very nearly the value +found by Mr.~Peace for the smallest potential difference which +would send a spark between two parallel plates. When we +consider the theory of the discharge we shall see that there are +reasons for concluding that it is impossible to produce a spark +by a smaller potential difference than the cathode fall of potential +in the gas through which the spark has to pass. + +The researches made by Hittorf on the distribution of potential +along the tube show, as we have seen, \artref{140}{Art.~140}, that the +%% -----File: 173.png---Folio 159------- +potential gradient is by no means constant; to produce the +changes in this gradient which occur in the neighbourhood of +the cathode, there must in that region be a quantity of free +electricity in the tube. Schuster (\textit{Proc.\ Roy.\ Soc.}~47, p.~542, 1890) +\index{Schuster, discharge through gases}% +concludes from his measurements of the potential in the neighbourhood +of the cathode that if $\rho$ is the volume density of the +free positive electricity at a distance~$x$ from the cathode, $\rho$~varies +as~$\epsilon^{-\kappa x}$. + +\Article{163} The measurements of potential along the positive column +have been less numerous than those of the negative dark space. +\index{De la Rue and Müller, discharge through gases}% +Hittorf, De~la Rue and Hugo Müller concur in finding that the +potential gradient close to the anode is, though not comparable +with that at the cathode, greater than that in the middle of the +tube. + +\Article{164} The potential gradient in the positive column is not like +\index{Potential gradient in positive column,@\subdashone gradient in positive column}% +the fall in potential at the cathode approximately independent +of the density, it diminishes as the pressure of the gas diminishes: +but as the pressure of the gas diminishes, the distance between +two consecutive striations increases, and though I can find no +experiments bearing on this point, it would be a matter of great +interest to know whether or not the potential difference along a +length of the positive column equal to the distance between two +striations, where these are regular, is approximately independent +of the density of the gas. + +\Article{165} De~la~Rue and Hugo Müller (\textit{Phil.\ Trans.}\ 1878, Part~I, +p.~159) measured the potential gradients along a tube in which +two wide portions were connected by a piece of capillary tubing, +narrow enough to constrict the \DPtypo{striae}{striæ}; they found the potential +gradient much greater along the capillary portion than along +the wide one. Thus the potential difference along $4.25$~inches of +the positive column in the wide tube, which was about $\frac{15}{16}$~of an +inch in diameter, was, on an arbitrary scale, $75$, while the +potential difference along a portion of the positive column, +which included $2$~inches of the wide tube and $3.75$~inches of the +capillary tube ($\frac{1}{8}$~of an inch in diameter), was~$138$; the potential +gradients along the wide and narrow portions are thus in the +proportion of $1$~to~$1.55$. + +\includegraphicsouter{fig67}{Fig.~67.} + +In this case the cathode was in the wide part of the tube; +when the tube round the cathode is so narrow that it restricts +the negative glow, the increase in the potential difference +%% -----File: 174.png---Folio 160------- +at the cathode produced by this restriction makes it very +much more difficult to get a discharge to pass through the +narrow tube than through a wider one. An experiment due to +Hittorf (\textit{Wied.\ Ann.}~21, p.~93, 1884) illustrates this effect in +a very remarkable way; at a pressure of $.03$~mm.\ of mercury, it +took $1100$~of his cells to force the discharge through a tube $1$~cm.\ +in diameter, while $300$~cells were sufficient to force it between +similar electrodes the same distance apart in a tube $11$~cm.\ in +diameter, filled with the same kind of gas at the same pressure. + +\Article{166} When the electrodes are placed so near together that the +\index{Discharge between electrodes near together|(}% +\index{Electrodes, discharge between two when close together|(}% +dark space round the cathode extends +to the anode, the appearance of +the discharge is completely changed: +this is very well shown in an experiment +\index{Hittorf, discharge through gases}% +due to Hittorf (\textit{Pogg.\ Ann.}\ +136, p.~213, 1869) represented in \figureref{fig67}{Fig.~67}; +the electrodes were parallel to +each other, and the pressure of the +gas in the discharge tube was so low +that the dark space round the cathode +extended beyond the anode; the positive +discharge in this case, instead of +turning towards the cathode, started +from the bend in the anode on the +side furthest away from the cathode, +and then crept along the surface of +the glass until it reached the boundary +of the negative dark space. I observed a similar effect in the +course of some experiments on the discharge between large +parallel plates (\textit{Proc.\ Camb.\ Philos.\ Soc.}~5, p.~395, 1886); when the +pressure of the gas was very small, the positive column, instead +of passing between the plates, went, as in \figureref{fig68}{Fig.~68}, from the under +side of the lower plate which was the positive electrode, and +%% -----File: 175.png---Folio 161------- +after passing between the glass and the plates reached right up +to the negative glow, which was above the negative plate: the +space between the plates was quite dark and free from glow. + +\includegraphicsmid{fig68}{Fig.~68.} + +Lehmann (\textit{Molekularphysik}, bd.~2, p.~295) has observed with a +\index{Lehmann, discharge between electrodes close together}% +microscope the appearance of the discharge passing between +electrodes of different shapes, placed very close together; they +exhibit in a very beautiful way the same peculiarities as those +just described; Lehmann's figures are represented in \figureref{fig69}{Fig.~69}. +%% -----File: 176.png---Folio 162------- + +\includegraphicsmid{fig69}{Fig.~69.} + +When the distance between the electrodes is less than the +thickness of the dark space, it is very difficult to get the discharge +to pass between them; this is very strikingly illustrated +by another experiment of Hittorf's (\textit{Wied.\ Ann.}~21, p.~96, 1884) +\index{Hittorf, discharge through gases}% +which is represented in \figureref{fig70}{Fig.~70}. The two electrodes were only +$1$~mm.\ apart, but the regions surrounding them were connected by +a long spiral tube $3\frac{3}{4}$~m.\ long; in spite of the enormous difference +between the lengths of the two paths, the discharge, when the +pressure was very low, all went round through the spiral, and +\index{Discharge between electrodes near together|)}% +\index{Electrodes, discharge between two when close together|)}% +the space between the electrodes remained quite dark. + +\Article{167} In cases of this kind the potential difference required +to produce discharge between two electrodes must be \emph{diminished} +by increasing the distance between them. For in Hittorf's +experiments, the potential difference between the electrodes +was equal to the potential fall at the cathode, plus the change +in potential due to the $3\frac{3}{4}$~m.\ of positive light in the spiral, +while if the shortest distance between the electrodes had +been increased until it was just greater than the thickness of +the negative dark space, the potential difference between the +electrodes when the discharge passed would only have amounted +to the cathode fall, plus the potential difference due to a short +positive column instead of to one $3\frac{3}{4}$~metres long, so that the +potential difference would have been less than when the electrodes +\index{Peace, spark potential}% +are nearer together. Peace's experiment described in \artref{53}{\DPtypo{Art.~53.}{Art.~53}}\ is +a direct proof of the truth of this statement for higher +pressure, and is free from the objection to which the preceding +deduction from Hittorf's experiment is liable, that the cathode +%% -----File: 177.png---Folio 163------- +fall may not be the same when the discharge starts in the large +vessel when the negative glow is unrestricted, as it is when the +discharge passes through the narrow tubes, the walls of which +constrict the negative glow. + +\includegraphicsmid{fig70}{Fig.~70.} + +\Article{168} These results explain a peculiar effect which is observed +when the discharge passes between slightly curved electrodes +at not too great a distance apart; until the pressure is very +low the discharge passes across the shortest distance between +the electrodes, but after a very low pressure is reached the +discharge leaves the centre of the field, and in order to get a +longer spark length departs further and further from it as the +pressure of the gas is reduced. + +\Subsection{The Arc Discharge.} +\index{Arc discharge}% + +\Article{169} The `arc discharge,' of which the well-known arc lamp is +a familiar example, is characterised by the passage of a large +current and the incandescence of both the terminals, as well as by +the comparatively small potential difference between them; we +considered a case of this discharge in \artref{148}{Art.~148}, the gas was, however, +in that case, at a low pressure; the cases when the gas is at +higher pressures are of special interest, on account of the extensive +use made of this form of discharge for lighting purposes. + +If the current through a vacuum tube with electrodes is gradually +\index{Gassiot on electric discharge}% +increased, the discharge, as Gassiot found in 1863, gradually +changes from the ordinary type of the vacuum tube discharge +with the negative space and a striated positive column to the +arc discharge, in which there is comparatively little difference +between the appearances at the terminals. The terminals are +brilliantly incandescent while the gas remains comparatively +dark, being probably in the state in which it has a large supply +of dissociated molecules by means of which it can transmit the +current even though the potential gradient is small. + +The connection between spark length, potential difference and +current in the arc discharge, has been investigated by many +physicists, who have all found that the potential difference~$V$ +is almost independent of the current and can be expressed by +the formula +\[ +V = a + bl, +\] +where $l$~is the spark length and $a$~and~$b$ are constants. Ayrton +%% -----File: 178.png---Folio 164------- +\index{Ayrton and Perry, xarc discharge@\subdashone arc discharge}% +and Perry (\textit{Phil.\ Mag.}\ [5]~15, p.~346, 1883), using a formula +which is identical with the preceding one if the sparks are not +very short, found that for carbon electrodes $a = 63$~volts and +$b = 21.6$~volts, if $l$~is measured in centimetres. The value of~$a$ +probably depends on the quality of the carbon of which the electrodes +are made, as other observers, who have also used carbon +electrodes, have found considerably smaller values for~$a$. When +more volatile substances than carbon are used the values of~$a$ are +smaller, the more volatile the substance the smaller in general +being the value of~$a$. This is borne out by the following determinations +\index{Lecher, on the arc discharge}% +made by Lecher (\textit{Wied.\ Ann.}~33, p.~625, 1888); the +length~$l$ in these equations is measured in centimetres, and $V$~in +volts:--- +\begin{center} +\begin{tabular}{l@{}l} +Horizontal Carbon Electrodes\mdotfill & $V = 33 + 45l$.\\ +Vertical Carbon Electrodes\mdotfill & $V = 35.5 + 57l$.\\ +Platinum Electrodes, ($.5$ cm.\ in diameter)\quad\mdotfill & $V = 28 + 41l$.\\ +Iron Electrodes, ($.55$ cm.\ in diameter)\mdotfill & $V = 20 + 50l$.\\ +Silver Electrodes, ($.49$ cm.\ in diameter)\mdotfill & $V = 8 + 60l$. +\end{tabular} +\end{center} + +\Article{170} The form of the expression for~$V$ shows that the potential +required to maintain the current between two incandescent +electrodes cannot fall short of a certain minimum value, however +short the arc may be. The preceding measurements for~$a$ show +that this potential difference, though small compared with the +`cathode fall' when the electrodes are cold, is much greater than +that which Hittorf in his experiments (see \artref{152}{Art.~152}) found +necessary to maintain a constant current when the cathode was +incandescent; we must remember, however, that in Lecher's +experiments the gas was at atmospheric pressure, while in +Hittorf's the pressure was very low. + +\Article{171} Lecher (l.~c.)\ investigated the potential gradient in the +arc by inserting a spare carbon electrode, and found that it was +far from uniform: thus when the difference of potential between +the anode and the cathode was $46$~volts, there was a fall of $36$~volts +close to the anode, and a smaller fall of ten volts near the +cathode. The result that the great fall of potential in the arc +discharge occurs close to the anode is confirmed by an experiment +\index{Fleming, arc discharge}% +made by Fleming (\textit{Proc.\ Roy.\ Soc.}~47, p.~123, 1890), in +which a spare carbon electrode was put into the arc; when this +electrode was connected with the anode sufficient current went +%% -----File: 179.png---Folio 165------- +round the new circuit to ring an electric bell, but when it was +connected to the cathode the current which went round the +circuit was not appreciable. + +\includegraphicsouter{fig71}{Fig.~71.} + +\Article{172} The term in the expression for the potential in \artref{169}{Art.~169}, +which is independent of the length of the arc, and which +involves an expenditure of energy when electricity travels across +an infinitesimally small air space, is probably connected with the +work required to disintegrate the electrodes, since the more +volatile are the electrodes the smaller is this term. + +\Article{173} The disintegration of the electrodes is a very marked +feature of the arc discharge, and it is not, as in the case when +small currents pass through +a highly exhausted gas, confined +to the negative electrode; +in fact, when carbon +electrodes are used, the loss +in weight of the anode is +greater than that of the +cathode, the anode getting +hollowed out and taking a +crater-like form. + +\Article{174} Perhaps the most +\index{Arc discharge, with large potential differences@\subdashtwo with large potential differences}% +interesting examples of the +arc discharge are those which +occur when we are able by +means of transformers to produce +a great difference of +potential, say thirty or forty +thousand volts between two +electrodes, and also to transmit +through the arc a very +considerable current. In this +case the arc presents the +appearance illustrated in \figureref{fig71}{Fig.~71}. The discharge, instead of passing +in a straight line between the electrodes, rises from the +electrodes in two columns which unite at the top, where striations +are often seen though these do not appear in the photograph +from which \figureref{fig71}{Fig.~71} was taken. The vertical columns are +sometimes from eighteen inches to two feet in length, they flicker +slowly about and are very easily blown out, a very slight puff of +%% -----File: 180.png---Folio 166------- +air being sufficient to extinguish them. The air blast apparently +breaks the continuity of the belt of dissociated molecules along +which the current passes, and the current is stopped just as a +current through a wire would be stopped if the wire were cut. +The discharge is accompanied by a crackling sound, as if a +number of minute sparks were passing between portions of the +arc temporarily separated by very short intervals of space. + +\Article{175} The relation between the losses of weight of the anode +and the cathode in the arc discharge depends however very much +on the material of which the electrodes are made; thus Matteucci +\index{Matteuchi arc discharge}% +(\textit{Comptes Rendus}, 30, p.~201, 1850) found that for copper, +silver and brass electrodes the cathode lost more than the anode, +while for iron the loss in weight of the anode was greater than +that of the cathode. + +The electrodes in the arc discharge are at an exceedingly high +\index{Arc discharge, connection between loss of weight of electrodes and quantity of electricity passing@\subdashtwo connection between loss of weight of electrodes and quantity of electricity passing}% +temperature, in fact probably the highest temperatures we can +produce are obtained in this way. With carbon electrodes the +anode is much hotter than the cathode (compare \artref{149}{Art.~149}). +Since the temperature of the electrodes is so high, it is probable +that they are disintegrated partly by the direct action of the +heat and not wholly by purely electrical processes such as those +which occur in electrolysis; for this reason, we should not +expect to find any simple relation between the loss in weight of +the electrode and the quantity of electricity which has passed +\index{Grove, on the arc discharge@\subdashone on the arc discharge}% +through the arc. Grove (\textit{Phil.\ Mag.}\ [3]~16, p.~478, 1840), who +used a zinc anode sufficiently large for the temperature not to +rise about its melting point, came to the conclusion that the +amounts of zinc lost and oxygen absorbed by the electrode were +chemically equivalent to the oxygen liberated in a voltameter +\index{Herwig, arc discharge}% +placed in the circuit. On the other hand, Herwig, (\textit{Pogg.\ Ann.}\ +149, p.~521, 1873), who investigated the relation between the loss +of weight of a silver electrode in the arc and the amount of +chemical decomposition in a voltameter placed in the same +circuit, was however unable to find any simple law connecting +the two. The brightness of the light given by carbon electrodes +is much increased by soaking them in a solution of sodium +sulphate. + +\Article{176} The particles projected from the electrodes in the arc +discharge are presumably charged with electricity, since they +are deflected by a magnet; thus some of the electricity passing +%% -----File: 181.png---Folio 167------- +between the electrodes will be carried by these particles. Comparatively +few experiments bearing on this point have, however, +been made on the arc discharge, and we have not the information +which would enable us to estimate how much of the current is +carried by the disintegrated electrodes and how much by the gas. + +Fleming (\textit{Proc.\ Roy.\ Soc.}~47, p.~123, 1890) has suggested that +\index{Fleming, arc discharge}% +\emph{all} the current is carried by particles torn off the electrodes, that +these particles are projected (chiefly from the cathode) with +enormous velocities, and that the incandescence of the electrodes +is due to the heat developed by their bombardment by these +particles; the hollowing out of the anode is on this theory +supposed to be due to a kind of sand blast action exerted by the +particles coming from the negative electrode. + +\longpage +On this theory, if I understand it rightly, the gas by which +the electrodes are enveloped plays no part in the discharge. I +do not think that the theory is consistent with Hittorf's and +Gassiot's observations on the continuity of the arc discharge +with the ordinary striated discharge produced in a vacuum +tube through which only a very small current is passing, nor +does it seem in accordance with what we know about the high +conductivity of gases which are at a high temperature or through +which an electric discharge has recently passed. + + +\Subsection{The Heat produced by the Discharge.} +\index{Heat produced by electric discharge}% +\index{Discharge, heat produced by@\subdashone heat produced by}% +\index{Electric discharge, rheat produced by@\subdashtwo heat produced by}% + +\Article{177} Though the electric discharge is generally accompanied +by intense light, the average temperature of the molecules of the +gas through which it passes is often by no means high. Thus +\index{Wiedemann, E., on electric discharge}% +E.~Wiedemann (\textit{Wied.\ Ann.}~6, p.~298, 1879) has found that the +average temperature of a column of air at a pressure of about +$3$~mm.\ made luminous by the passage of the discharge can be +under $100°$\,C\@. As, however, any instrument which we may use +to measure the temperature of the gas merely measures the +average temperature of molecules filling a considerable space, +the fact that this temperature is low does not preclude the +existence of a small number of molecules moving with velocities +immensely greater than the mean velocity corresponding to the +temperature indicated by the thermometer. + +On the other hand, the fact that the gas is luminous +during the discharge does not afford conclusive evidence of the +%% -----File: 182.png---Folio 168------- +existence of molecules in a state comparable with that of the +majority of the molecules in a gas at a very high temperature, +for mere increase of temperature unaccompanied by chemical +changes seems to have little effect in increasing the luminosity +of a gas; thus in one of Hittorf's experiments already mentioned, +where the temperature of the electrodes was great enough +to melt iridium, the gas surrounding them when examined by +the spectroscope did not show any spectroscopic lines. It +would seem that the interchange of atoms between the molecules +which probably goes on when the discharge passes through +the gas is much more effective in making it luminous than mere +increase in temperature unaccompanied by chemical changes. + +\Article{178} Many experiments have been made by G.~and E.~Wiedemann, +\index{Wiedemann, E., on electric discharge}% +\index{Wiedemann, G. and E., heat produced by electric discharge}% +\index{Hittorf, discharge through gases}% +Hittorf, and others on the distribution along the line of +discharge of the heat produced by the spark. Hittorf's experiments +are the easiest to interpret, since by means of a large +battery he produced through the discharge tube a current which, +if not absolutely continuous, was so nearly so, that no want of +continuity could be detected either by a revolving mirror or +by a telephone; the gas had therefore a much better chance of +getting into a steady state than if intermittent discharges such +as those produced by an induction coil had been used. + +Hittorf (\textit{Wied.\ Ann.}\ 21, p.~128, 1884) inserted three thermometers +in the discharge tube, one close to the cathode, another +in the bright part of the negative glow, and the third in +the positive column. He found, using small currents and low +gaseous pressures, that the temperature of the thermometer next +the cathode was the highest, that of the one in the negative glow +the next, and that of the one in the positive column the lowest. + +The distribution of temperature depends very much upon the +intensity of the current. Hittorf found that when the strength +was increased the difference between the temperatures of his +thermometers increased also. When however the increase in the +current is so great that the discharge becomes an arc discharge, +then, at any rate when carbon electrodes are used, the temperature +at the anode is higher than that of the cathode; with weak +currents we have seen that it is lower. + +E.~Wiedemann (\textit{Wied.\ Ann.}\ 10, p.~225 et~seq., 1880) found that +the distribution of temperature along the discharge depended on +the pressure. In his experiments the temperature at the anode +%% -----File: 183.png---Folio 169------- +was slightly higher than that at the cathode when the pressure +was about $26$~mm.\ of mercury, at lower pressures the cathode +was the hotter, and the difference between the temperatures +of the cathode and the anode increased as the pressure diminished. + + +\Subsection{Differences between the Phenomena at the Positive and +Negative Electrodes.} +\index{Difference between positive and negative discharge}% +\index{Discharge, electric@\subdashone electric, difference between positive and negative}% +\index{Electrodes, xdifference between positive and negative@\subdashone difference between positive and negative}% +\index{Negative qand positive discharges, difference between@\subdashone and positive discharges, difference between}% +\index{Positive and negative discharge, difference between}% + +\Article{179} We have seen already that when the pressure of the gas +is small the two electrodes present very different appearances, +there are however many differences between an anode and a +cathode even at atmospheric pressure. + +\includegraphicsmid{fig72}{Fig.~72.} + +The appearance of the spark discharge at the two electrodes +is different. The following figure is from a photograph of the +spark in air at atmospheric pressure. It will be noticed that +the sparks seem to reach a definite point on the negative electrode, +but to spread over a considerable area of the positive. +Bright dots of light are often to be seen on the positive electrode +but not on the negative, these are still more striking at lower +pressures. When the spark is branched as in \figureref{fig73}{Fig.~73}, the +branches point to the negative electrode. + +\includegraphicsmid{fig73}{Fig.~73.} + +If the electrodes are not of the same size, the spark length +for the same potential difference seems to depend upon whether +the larger or smaller electrode is used as the cathode, though +it is a disputed question whether this difference exists if the +spark is not accompanied by some other form of discharge. +%% -----File: 184.png---Folio 170------- +Thus, if for example the electrodes are spheres of different sizes, +Faraday (\textit{Experimental Researches}, §~1480) found that the spark +\index{Faraday, mdifference between positive and negative discharge@\subdashone difference between positive and negative discharge}% +length was greater when the smaller sphere was positive than +when it was negative. We may express this result by saying +that when the electric field is not uniform the gas does not +break down so easily when the greatest electromotive intensity +is at the cathode as it does when it is at the anode. + +Macfarlane's measurements (\textit{Phil.\ Mag.}\ [5]~10, p.~403, 1880) of +\index{Macfarlane, spark potential}% +the potential difference required to start a discharge between a +ball and a disc are in accordance with this result, as he found +that for a given length of spark the potential difference between +the electrodes was smaller when the ball was positive than when +it was negative. + +\includegraphicstwo{fig74}{Fig.~74.}{fig75}{\hspace*{\stretch{1}}Fig.~75.\hspace*{\stretch{1}}} + +\Article{180} De~la~Rue and Hugo Müller (\textit{Phil.\ Trans.}\ 1878, Part~I, +\index{Muller@Müller and de la Rue, electric discharge}% +\index{De la Rue and Müller, discharge through gases}% +p.~55) observed analogous effects in the experiments they made +with their large chloride of silver battery on the sparking distance +between a point and a disc. They found that for potential differences +between $5000$ and $8000$~volts the sparking distance was +greatest when the point was positive and the disc negative, while +for smaller potential differences they found that the opposite +result was true. The appearance of the discharge at the positive +point they found was different from that at the negative. The +discharge at the negative point is represented in \figureref{fig74}{Fig.~74}, that at +the positive in \figureref{fig75}{Fig.~75}. + +\Article{181} Wesendonck (\textit{Wied.\ Ann.}\ 38, p.~222, 1889), however, +\index{Wesendonck, positive and negative discharge}% +concludes from his experiments that there are no polar differences +of this kind when the discharge passes entirely as a spark, +and that the differences which have been observed are due to the +coexistence of other kinds of discharge such as a brush and glow. + +The existence of this kind of discharge would put the gas +into a condition in which it is electrically weak and thus ill-fitted +%% -----File: 185.png---Folio 171------- +to resist the passage of the spark. This explanation does +not seem inconsistent with Faraday's experiment, for, as we shall +see in the next paragraph, the negative brush is formed more +easily than the positive one. Thus if the sparks in his experiments +only passed when they were preceded by the formation of +brushes at both the electrodes, it might be produced if the +greatest electromotive intensity was at the place where the brush +was formed with the greatest difficulty---the anode---while it +might not be produced if the smallest intensity was at the anode, +thus the gas would be electrically weaker in the first case than +in the second. + +\sloppy +\Article{182} Considerable polar differences seem undoubtedly to occur +\index{Glow, discharge}% +in the brush and glow discharges. Thus Faraday (\textit{Experimental +Researches}, §~1501) found that if two equal spheres were electrified +until they discharged their electricity by a brush discharge +\index{Brush discharge}% +into the air, the discharge occurred at a lower potential for +the negative ball than for the positive; more electricity thus +accumulates on the positive ball than on the negative before the +brush occurs, so that when the positive brush does take place it +is finer than the negative one. + +\includegraphicsmid{fig76}{Fig.~76.} + +\fussy +The brush discharge is also intermittent, and since the positive +brush requires a greater accumulation of electricity than the +negative one, the interval between consecutive discharges is +greater for the positive than for the negative brush. + +The positive and negative brushes are represented in \figureref{fig76}{Fig.~76}, +copied from a figure given by Faraday. + +In the brush discharge the electricity seems to be carried partly +\index{Nahrwold, leakage of electricity through air}% +by particles of metal torn from the electrodes. Nahrwold (\textit{Wied.\ +Ann.}\ 31, p.~473, 1887) has confirmed the conclusion that the +negative brush is more easily formed than the positive. + +Wesendonck (\textit{Wied.\ Ann.}\ 39, p\DPtypo{,}{.}~601, 1890) has shown that when +\index{Wesendonck, positive and negative discharge}% +the discharge passes as a glow discharge from a point into air, +hydrogen, or nitrogen, the potential at which the discharge begins +is less when the point is negative than when it is positive. +%% -----File: 186.png---Folio 172------- + +\Subsection{Lichtenberg's Figures and Kundt's Dust Figures.} +\index{Lichtenberg's figures}% + +\includegraphicsmid[!t]{fig77}{Fig.~77.} + +\includegraphicsouter{fig78}{Fig.~78.} + +\Article{183} Very tangible differences between the discharges from +the positive and negative electrodes at ordinary pressures are +obtained if we allow the discharge from one or other of the +electrodes to pass on to a non-conducting plate covered with +some badly conducting powder. If, for example, we powder +a plate with a mixture of red minium and yellow sulphur and +then cause a discharge from a positively electrified point to pass +to the plate, the sulphur, which by friction against the minium +is negatively electrified, adheres to the positively electrified parts +of the plate, and will be found to be +arranged in a star-like form like that +represented in \figureref{fig77}{Fig.~77}. If, on +the other hand, the discharge is taken +from a negatively electrified body +the appearance of the minium on +the plate is that represented in \figureref{fig78}{Fig.~78}. +These are known as Lichtenberg's +figures; the positive ones are +larger than the negative. + +If the electrodes are made of very +bad conductors, such as wood, there +is no difference between the positive and the negative figures. +%% -----File: 187.png---Folio 173------- + +\Article{184} Very beautiful figures are obtained if a plate of glass +covered with a non-conducting powder, such as lycopodium, is +placed on a metal plate, and two wires connected with the poles +of an induction coil made to touch the powdered surface of the +glass. When the discharge passes the powder arranges itself in +patterns which are finely branched and have a moss-like appearance +at the anode and a more feathery or lichenous appearance at +the cathode. The accompanying figure is from a paper by Joly +\index{Joly, discharge figures}% +(\textit{Proc.\ Roy.\ Soc.}\ 47, p.~84, 1890); the negative electrode is on the +left. + +\includegraphicsmid{fig79}{Fig.~79.} + +\Article{185} As Lehmann has remarked (\textit{Molekularphysik}, \DPtypo{b}{bd}.~11, +\index{Lehmann, xdifference between positive and negative discharge@\subdashone difference between positive and negative discharge}% +p.~303), the differences between the positive and negative figures +are what we should expect if the discharge passed as a brush from +the positive electrode and as a glow from the negative one. He +has verified by direct observation that this is frequently the case. + +A good deal of light is also, I think, thrown on the difference +between the positive and negative figures by \figureref{fig80}{Fig.~80}, which +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +is given by De~la~Rue and Hugo Müller (\textit{Phil.\ Trans.}\ 1878, +Part~I, p.~118) as the discharge produced by $11,000$~of their +%% -----File: 188.png---Folio 174------- +chloride of silver cells in free air. It will be noticed that there +is at the negative electrode a continuous discharge superposed +on the streamers which are the only form of discharge at the +positive, this continuous discharge will fully account for the +comparative want of detail in the negative figure. + +\includegraphicsmid{fig80}{Fig.~80.} + +\Article{186} Kundt's figures are obtained by scattering non-conducting +powders over a horizontal metal plate, instead of, as in +Lichtenberg's figures, over a non-conducting one. If the plate +be shaken after a discharge has passed from a negative point to +the positive plate, it will be found that the powder will fall from +every part of the plate except a small circle under the negative +electrode, where the powder sticks to the plate and forms what +\index{Dust figures}% +\index{Kundt, dust figures}% +is called Kundt's `dust figure.' The dimensions of this circle are +very variable, ranging in Kundt's original experiments (\textit{Pogg.\ +Ann.}\ 136, p.~612, 1869) from $10$ to $200$~mm.\ in diameter. If the +point is positive and the plate negative Kundt's figures are only +formed with great difficulty. + + +\Subsection{Mechanical Effects produced by the Discharge.} +\index{Discharge, mechanical effects produced by@\subdashone mechanical effects produced by}% +\index{Electric discharge, smechanical effects produced by@\subdashtwo mechanical effects produced by}% +\index{Mechanical effects produced by electric discharge@\subdashtwo produced by electric discharge}% + +\Article{187} We have already considered the mechanical effects produced +by the projection of particles from the cathode: many other +such effects are however produced by the electric discharge. \nblabel{add:4}One +of the most interesting of these is that described by De~la~Rue +\index{De la Rue and Müller, discharge through gases}% +\index{Muller@Müller and de la Rue, electric discharge}% +and Hugo Müller (\textit{Phil.\ Trans.}\ 1880, p.~86): they found that when +the discharge from their large chloride of silver battery passed +through air at the pressure of $53$~mm.\ of mercury, the pressure +of the air was increased by about $30$~per~cent., and they proved, +by measuring the temperature, that the increase in pressure +could not be accounted for by the heat produced by the spark. + +This effect can easily be observed if a pressure gauge is +attached to any ordinary discharge tube, the gas inside being +most conveniently at a pressure of from $2$ to $10$~mm.\ of mercury. +At the passage of each spark there is a quick movement of the +liquid in the gauge as if it had been struck by a blow coming +from the tube; immediately after the passage of the spark the +liquid in the gauge springs back to within a short distance of +its position of equilibrium, and then slowly creeps back the +rest of the way. This creeping effect is probably due to the +slow escape of the heat produced by the passage of the spark. +%% -----File: 189.png---Folio 175------- +\index{Electric discharge, texpansion due to@\subdashtwo expansion due to}% +The gauge behaves as if a wave of high pressure rushed through +the tube when the spark passed. + +\Article{188} Meissner, \textit{Abhand.\ der König.\ Gesellschaft, \DPtypo{Gottingen}{Göttingen}}, 16, +\index{Meissner, expansion due to discharge}% +p.~98 et~seq., 1871 (who seems to have been the first to observe +this effect, though in his experiments it was not developed to +such an extent as in De~la~Rue's and Müller's), found that +if a tube provided with a gauge were placed between the plates +of a condenser there was an increase of pressure when the plates +were charged or discharged, and no effect as long as the charge +on the condenser remained constant. In this case there was +no spark between the plates of the condenser, and the effect +must have been due to the passage through the gas of the +electricity which, when it was in equilibrium before the spark +passed, was spread over the glass of the tube. + +Meissner observed this effect when the tube was filled with +oxygen, hydrogen, carbonic acid, and nitrogen, though it was +very small when the tube was filled with hydrogen. + +\includegraphicsmid[!b]{fig81}{Fig.~81.} + +\Article{189} The effect seems too great to be accounted for merely +by the increased statical pressure due to the decomposition +of the molecules of the gas by the discharge, for in De~la~Rue's +experiment, where the gas was contained in a large vessel +and the discharge passed as a narrow thread between the electrodes, +the pressure was increased by about $30$~per~cent. Now +if this increase of pressure was due to the splitting up of the +molecules into atoms it would require about one-third of the +molecules to be so split up by a discharge which only occupied +an infinitesimal fraction of the volume of the gas. + +\Article{190} It would seem more probable that in this case we had +something analogous to the driving off of particles from an +electrified point, as in the ordinary phenomenon of the `electrical +wind,' or that of the projection of particles from the cathode +which occurs when the discharge passes through a gas at a very +low pressure; the difference between this case and the one we +are considering being that in the latter, since the pressure is +greater, the molecules shot off from the cathode communicate +their momentum to the surrounding gas instead of retaining it +until they strike against the walls of the discharge tube. This +would have the effect of diminishing the density of the gas in +the neighbourhood of the line of discharge, and would therefore +increase the density and pressure in other parts of the tube. +%% -----File: 190.png---Folio 176------- + +\includegraphicsmid{fig82}{Fig.~82.} + +\Article{191} Töpler (\textit{Pogg.\ Ann.}\ 134, p.~194, 1868) has investigated by +\index{Topler@Töpler, disturbance produced by spark}% +means of a stroboscopic arrangement the disturbance in the air +produced by the passage of a spark. The following figures taken +from his paper show the regions when the gas is expanded in the +neighbourhood of the spark line at successive small intervals +of time after the passage of the spark. It will be noticed that +these regions show periodic swellings and contractions as if the +centres of greatest disturbance were distributed at regular and +finite intervals along the line of discharge. A similar appearance +\index{Antolik's figures}% +was observed by Antolik (\textit{Pogg.\ Ann.}\ 154, p.~14, 1875) +when the discharge passed over a plate covered with fine powder; +the powder placed itself in ridges at regular intervals along the +line of discharge. + +\Article{192} This effect is also beautifully illustrated in an experiment +\index{Discharge, furrows made by@\subdashone furrows made by}% +\index{Electric discharge, ufurrows made by@\subdashtwo furrows made by}% +\index{Joly, furrows made by discharge@\subdashone furrows made by discharge}% +made by Joly (\textit{Proc.\ Roy.\ Soc.}\ 47, p.~78 et~seq., 1890), in which +the discharge passed from one strip of platinum to another +between plates of glass placed so close together that they showed +Newton's rings; it was only with difficulty that the discharge +could be got through this narrow space at all, it declined to go +through the centre of the rings, and went out of its way to +get through the places where the distance between the plates +was greatest. Where it passed it made furrows on the glass +at right angles to the line of discharge and separated by regular +%% -----File: 191.png---Folio 177------- +intervals; a magnified representation of these is shown in +\figureref{fig82}{Fig.~82}, taken from Joly's paper. When the air between the +plates was replaced by hydrogen these furrows had a tendency +to be more widely separated. + +\Article{193} The explosive effects produced by the spark are well +\index{Hertz, yexplosive effects due to spark@\subdashone explosive effects due to spark}% +illustrated by an experiment due to Hertz (\textit{Wied.\ Ann.}\ 19, +p.~87, 1883), in which the anode was placed at the bottom of +a glass tube with a narrow mouth, while the cathode was placed +outside the tube and close to the open end. The tube and the +electrodes were in a bell jar filled with dry air at a pressure of +$40$--$50$~mm.\ of mercury. When the discharge from a Leyden +jar charged by an induction-coil passed, the glow accompanying +it was blown out of the tube and extended several centimetres +from the open end. In this experiment, as in the well-known +`electric wind,' the explosive effects seem to be more vigorous +at the anode than they are at the cathode. + + +\Subsection{Chemical Action of the Electric Discharge.} +\index{Chemical action of electric discharge}% +\index{Discharge, chemical action of@\subdashone chemical action of}% +\index{Electric discharge, vchemical action of@\subdashtwo chemical action of}% + +\Article{194} When the electric discharge passes through a gas, it +produces in the majority of cases perceptible chemical changes, +though whether these changes are due to the electrical action +of the spark, or whether they are secondary effects due to a +great increase of temperature occurring either at the electrodes +or along the path of the discharge, is very difficult to determine +when the discharge takes the form of a bright spark. +%% -----File: 192.png---Folio 178------- + +\Article{195} For this reason we shall mainly consider the chemical +changes produced by those forms of discharge in which the +thermal effects are as small as possible, though even in these +cases, since we can only measure the average temperature of a +large number of molecules, it is always possible to account for +any chemical effect by supposing that although the average +temperature is not much increased by the discharge, a small +number of molecules have their kinetic energy so much increased +that they can enter into fresh chemical combinations. + +The thermal explanation of the chemical changes requires that +they should be subsequent to, and not contemporaneous with +the passage of the discharge; on the view adopted in this book +chemical changes of some kind are necessary before the discharge +can pass at all, though it by no means follows that the +chemical changes which are instrumental in carrying the current +are those which are finally apparent. When electricity passes +through a liquid electrolyte the substances liberated at the +electrodes are in consequence of secondary chemical actions +frequently different from the ions which carry the current. + +\includegraphicsmid{fig83}{Fig.~83.} + +\Article{196} A very convenient method of producing discharges as free +as possible from great heat is by using a Siemens' ozonizer, represented +\index{Siemens, ozonizer}% +\index{Ozonizer}% +in \figureref{fig83}{Fig.~83}. Two glass tubes are fused together, and the +gas through which the discharge takes place circulates between +them, entering by one of the side tubes and leaving by the other; +the inside of the inner tube and the outside of the outer are +coated with tin-foil, and are connected with the poles of an +%% -----File: 193.png---Folio 179------- +induction-coil. When the coil is working a quiet discharge +passes as a series of luminous threads between the surfaces +of the glass opposed to each other. This form of discharge is +often called the `silent discharge,' and by French writers \emph{l'effluve +electrique}. + +When air or oxygen is sent through a tube of this kind when +the coil is working a considerable amount of ozone is produced. + +Ozone is not produced by the action of a steady electric field +on oxygen or air unless the field is intense enough to produce a +discharge through the gas (see J.~J. Thomson and R.~Threlfall, +\textit{Proc.\ Roy.\ Soc.}\ 40, p.~340, 1886). + +Meissner (\textit{Abhandlungen der König.\ Gesell.\ Göttingen}, 16, +\index{Meissner, expansion due to discharge}% +p.~3, 1871) found that ozone was produced in tubes placed +between the plates of a condenser when the condenser was +charged or discharged, although no sparks passed between the +plates, but that no ozone was produced when the charges on +the plates of the condenser were kept constant. This was probably +due to the passage through the gas of electricity which +had distributed itself over the walls of the tube under the inductive +action of the charged plates of the condenser. + +Bichat and Guntz (\textit{Annales de Chimie et de Physique} [6],~19, +\index{Ozone, production of}% +\index{Bichat and Guntz, formation of ozone}% +\index{Guntz and Bichat on the formation of ozone}% +p.~131, 1890) ascribe the formation of ozone, even by the silent +discharge, to purely thermal causes. They regard the bright +thread-like discharge surrounded by the non-luminous gas as a +column of very hot oxygen surrounded by a cold atmosphere, and +consider the conditions analogous to those which obtain in a St.~Claire +Deville `chaud froid' tube, by the aid of which they state +that Troost and Hautefeuille have produced ozone from oxygen +without the use of the electric discharge. + +\Article{197} By the aid of the silent discharge a great many chemical +changes are produced, of which the following are given by +\index{Lehmann, ychemical action of the discharge@\subdashone chemical action of the discharge}% +Lehmann, \textit{Molekular\-physik}, (bd.~2, p.~328.) Carbonic acid is split +up by the discharge into carbonic oxide, oxygen, and ozone: +water vapour into hydrogen and oxygen: when the discharge +passes through acetylene a solid and a liquid are produced: +phosphoretted hydrogen yields under similar circumstances a +solid: methyl hydride gives marsh gas, hydrogen, and an acid: +nitrous oxide splits up into nitrogen and oxygen: nitric oxide +into nitrous oxide, nitrogen and oxygen. + +A mixture of carbonic acid and marsh gas gives a viscous +%% -----File: 194.png---Folio 180------- +fluid; nitrogen partly combines with ammonia: carbonic oxide +and hydrogen give a solid product: carbonic oxide and marsh +gas a resinous substance: nitrogen and hydrogen ammonia. + +Dextrine, benzine, and sodium absorb nitrogen under the +influence of the discharge, and enter into chemical combination +with it. Hydrogen forms with benzine and turpentine resinous +compounds. + +\Article{198} Berthelot (\textit{Annales de Chimie et de Physique}, [5],~10, +\index{Berthelot, chemical action of electric discharge}% +p.~55, 1877) has shown that the absorption of nitrogen by +dextrine takes place under very small electromotive intensities; +he showed this by connecting the inside and the outside coatings +of the ozonizer to points at different heights above the surface +of the ground, and found that this difference of potential, which +varied in the course of the experiments from $+60$ to $-180$~volts, +was sufficient to produce in the course of a few weeks an appreciable +absorption of nitrogen by a solution of dextrine in contact +with it. The potential differences in these experiments were so +small, and their rate of variation so slow, that it seems improbable +that any discharge could have passed through the +nitrogen, and the experiments suggest that chemical action +between a gas and a substance with which it is in contact can +be produced by the action of a variable electric field without +the passage of electricity through the bulk of the gas. Berthelot +suggests that plants may, under the influence of atmospheric +electricity, absorb nitrogen by an action of this kind. This +suggestion also raises the very important question as to whether +the chemical changes which accompany the growth of plants can +have any influence on the development of atmospheric electricity. + +\Article{199} We must now consider the relation between the quantity +\index{Glow, produced by electrodeless discharge@\subdashone produced by electrodeless discharge|(}% +\index{Phosphorescent glow}% +of electricity which passes through a gas and the amount of +chemical action which takes place in consequence. It is necessary +here to make a distinction, which has been too much +neglected, between the part of this action which occurs at the +electrodes and the part which occurs along the length of the +spark. When a current of electricity passes through a liquid +electrolyte the only evidence of chemical decomposition is to +be found at the electrodes. When, however, the electric discharge +passes through a gas the chemical changes are not confined +to the electrodes but occur along the line of the discharge +as well. This is proved by the fact that when the electrodeless +%% -----File: 195.png---Folio 181------- +discharge passes through oxygen ozone is produced, as is testified +by the existence for several seconds after the discharge has +discharge passes through oxygen ozone is produced, as is testified +by the existence for several seconds after the discharge has +passed of a beautiful phosphorescent glow: the same thing is +also proved by the behaviour of the discharge when it passes +through acetylene; the first two or three sparks are of a beautiful +light green colour, while all subsequent discharges are a kind of +whitish pink, showing that the first two or three sparks have +decomposed the gas. + +\Article{200} Since chemical decomposition is not confined to the electrodes +its amount must depend upon the length of the spark; +\index{Perrot, decomposition of steam|indexetseq}% +\index{Steam, decomposition of by spark}% +this has been proved by Perrot (\textit{Annales de Chimie et de Physique} +[3],~61, p.~161, 1861), who compared the amounts of water +vapour decomposed in the same time in a number of discharge +tubes placed in series, the spark lengths in the tubes ranging +from two millimetres to four centimetres; he found that the +volumes of gas decomposed varied from $2$~c.c.\ to $52$~c.c., and that +neither the longest nor the shortest spark produced the maximum +effect. By placing a voltameter in the circuit Perrot found that +in one of his tubes the amount of water vapour decomposed by +the sparks was about $20$~times the amount of water decomposed +in the voltameter. It is evident from this that if we wish to +arrive at any simple relation between the quantity of electricity +passing through the gas and the amount of chemical decomposition +produced we must separate the part of the latter which +occurs along the length of the spark from that which takes place +at the electrodes. + +\includegraphicsmid{fig84}{Fig.~84.} + +\Article{201} This seems to have been done in a remarkable investigation +made more than thirty years ago by Perrot~(l.c.), which +does not seem to have attracted the attention it merits, and +which would well repay repetition. The apparatus used by +Perrot in his experiments is represented in \figureref{fig84}{Fig.~84} from his +paper. The spark passed between two platinum wires sealed +into glass tubes, $c\,f\,g$,~$d\,f\,g$, which they did not touch except at the +places where they were sealed: the open ends, $c$,~$d$, of these tubes +were about $2$~mm.\ apart, and the wires terminated inside the +tubes at a distance of about $2$~mm.\ from the ends. The other +ends of these tubes were inserted under test tubes~$e\,e$, in which +the gases which passed up the tubes were collected. The air was +exhausted from the vessel~\smallsanscap{A} and the water vapour through which +the discharge passed was obtained by heating the water in the +%% -----File: 196.png---Folio 182------- +vessel to about \nblabel{add:5}$90°$\,C.: special precautions were taken to free this %%correction taken from errata +water from any dissolved gas. The stream of vapour arising +from this water drove up the tubes the gases produced by the +passage of the spark; part of these gases was produced along +the length of the spark, but in this case the hydrogen and +oxygen would be in chemically equivalent proportions; part of +the gases driven up the tubes would however be liberated at the +electrodes, and it is this part only that we could expect to bear +any simple relation to the quantity of electricity which had +passed through the gas. + +When the sparking had ceased, the gases which had collected in +the test tubes $e$~and~$e$ were analysed; in the first place they were +exploded by sending a strong spark through them, this at once +got rid of the hydrogen and oxygen which existed in chemically +equivalent proportions and thus got rid of the gas produced +along the length of the spark. After the explosion the gases +left in the tubes were the hydrogen or oxygen in excess, together +with a small quantity of nitrogen, due to a little air which had +leaked into the vessel in the course of the experiments, or which +had been absorbed by the water. The results of these analyses +showed that there was always an excess of oxygen in the test +tube in connection with the positive electrode, and an excess of +hydrogen in the test tube connected with the negative electrode, +and also that the amounts of oxygen and hydrogen in the +respective tubes were very nearly chemically equivalent to the +amount of copper deposited from a solution of copper sulphate +in a voltameter placed in series with the discharge tube. +%% -----File: 197.png---Folio 183------- + +These results are so important that I shall quote one of Perrot's +experiments in full (l.c.\ pp.~182--3). + +Duration of experiment $4$~hours. $8.5$~milligrammes of copper +deposited in the voltameter from copper sulphate; this amount +of copper is chemically equivalent to $3$~c.c.\ of hydrogen and $1.5$~c.c.\ +of oxygen at atmospheric pressure. + +In the test tube over the negative electrode there were at the +end of the experiment $37.5$~c.c.\ of gas, after the explosion by +the spark this was reduced to $3.1$~c.c., so that by far the greater +part of the gas collected consisted of hydrogen and oxygen in +chemically equivalent proportions, produced not at the electrodes +but along the line of the spark. $5.3$~c.c.\ of oxygen were added +to the original gas, which was again exploded and the contraction +was $4.5$~c.c.; in the original gas in the test tube there was therefore +an excess of $3$~c.c.\ of hydrogen and $.1$~c.c.\ of something besides +hydrogen and oxygen, probably nitrogen. In the test tube over +the positive electrode there were $35.8$~c.c.\ of gas at the end of the +experiment, after the explosion by the spark this was reduced +to $1.6$~c.c. $1.8$~c.c.\ of oxygen were added, but there was no explosion +when the spark passed; $8.7$~c.c.\ of hydrogen were added +and the mixture exploded when the spark passed; the contraction +produced was $9.6$~c.c., showing that the excess of oxygen +originally present was $1.4$~c.c.\ and that $.2$~c.c.\ of nitrogen were +mixed with it. Thus the excesses of hydrogen and oxygen in the +tubes were very nearly chemically equivalent to the amount of +copper deposited in the voltameter. This is also borne out by +the following results of other experiments made by Perrot (l.c.\ +p.~183). + +2nd~experiment. Duration of experiment $4$~hours. Copper +deposited in voltameter $6$~milligrammes, chemically equivalent to +$2.12$~c.c.\ of hydrogen and $1.06$~c.c.\ of oxygen. + +Gas in the test tube over the positive electrode $35.10$~c.c.; +excess of oxygen $.95$~c.c.; nitrogen $.2$~c.c. + +Gas in the test tube over the negative electrode $32.40$~c.c.; +excess of hydrogen $2.10$~c.c.; nitrogen $.1$~c.c. + +4th~experiment. Duration of experiment $3$~hours. Copper +deposited in voltameter $5.5$~milligrammes, chemically equivalent +to $1.94$~c.c.\ of hydrogen and to $.97$~c.c.\ of oxygen. + +Gas in the test tube over the positive electrode $25.10$~c.c.; +excess of oxygen $.85$~c.c.; nitrogen $.15$~c.c. +%% -----File: 198.png---Folio 184------- + +Gas in the test tube over the negative electrode $27.70$~c.c.; +excess of hydrogen $1.8$~c.c.; nitrogen $.21$~c.c. + +6th~experiment. Duration of experiment $3\tfrac{1}{2}$~hours. Copper +deposited in voltameter $6$~milligrammes, chemically equivalent to +$2.12$~c.c.\ of hydrogen and to $1.06$~c.c.\ of oxygen. + +Gas in the test tube over the positive electrode $30.20$~c.c.; +excess of oxygen $.90$~c.c.; nitrogen $.2$~c.c. + +Gas in the test tube over the negative pole $32.50$~c.c.; excess +of hydrogen $2.05$~c.c.; nitrogen $.2$~c.c. + +These results seem to prove conclusively (assuming that the +discharge passed straight between the platinum wires and did +not pass through a layer of moisture on the sides of the tubes) +that the conduction through water vapour is produced by chemical +decomposition, and also that in a molecule of water vapour +the atoms of hydrogen and oxygen are associated with the same +electrical charges as they are in liquid electrolytes. + +\Article{202} \DPtypo{Anotherway}{Another way} in which the chemical changes which accompany +the passage of the spark through a gas manifest themselves +is by the production of a phosphorescent glow, which often lasts +\index{Phosphorescent glow}% +\index{Oxygen, glow produced by discharge in}% +for several seconds after the discharge has ceased. In a great many +gases this glow does not occur, it is however extremely bright in +oxygen. A convenient way of producing the glow is to take a +tube about a metre long filled with oxygen at a low pressure, +and produce an electrodeless discharge at the middle of the tube. +From the bright ring produced by the discharge a phosphorescent +haze will spread through the tube moving sufficiently +slowly for its motion to be followed by the eye. The haze seems +to come from the ozone, and the phosphorescence to be due to the +gradual reconversion of the ozone into oxygen. This view is +borne out by the fact that if the tube is heated the glow is not +formed by the discharge, but as soon as the tube is allowed to +cool down the glow is again produced: thus the glow, like ozone, +cannot exist at a high temperature. + +The spectrum of this glow in oxygen is a continuous one, in +which, however, a few bright lines can be observed if very high +dispersive power is used. The glow is also formed in air, though +not so brightly as in pure oxygen. When electrodes are used it +seems to form most readily over the negative electrode, especially +if this is formed of a flat surface of sulphuric acid. +\index{Glow, produced by electrodeless discharge@\subdashone produced by electrodeless discharge|)}% + +I have experimented with a large number of gases in order to +%% -----File: 199.png---Folio 185------- +see whether or not the glow was formed when the electrodeless +discharge passed through them. I have never detected any +glow in a single gas (as distinct from a mixture) unless that gas +was one which formed polymeric modifications, but all the gases +I examined which do polymerize have shown the after-glow. +The gases in which I have found the glow are oxygen, cyanogen +(in which it is extremely persistent, though not so bright as in +oxygen), acetylene, and vinyl chloride, all of which polymerize. + +A bulb filled with oxygen seems to retain its power of glowing +unimpaired, however much it may be sparked through. In bulbs +filled with the other gases, however, the glow after long sparking +is not so bright as it was originally. This seems to suggest that +the polymeric modification produced by the sparking does not +get completely reconverted into the original form. + +\Subsection{Spark facilitated by rapid changes in the intensity of +the Electric Field.} +\index{Electric discharge, wfacilitated by rapid changes in the electric field@\subdashtwo facilitated by rapid changes in the electric field}% +\index{Jaumann, discharge facilitated by rapid changes in the potential}% +\index{Spark, x effects of rapid alternations in field on@\subdashone effects of rapid alternations in field on}% + +\Article{203} Jaumann (\textit{Sitzb.\ d.~Wien Akad.}\ 97, p.~765, 1888) has made +some interesting experiments on the effect on the spark length of +small but rapid changes in the electrical condition of the electrodes. +The arrangement used for these experiments is represented +in \figureref{fig85}{Fig.~85}, which is taken from Jaumann's paper. + +\includegraphicsmid{fig85}{Fig.~85.} + +The main current from an electrical machine charged the condenser~\smallsanscap{B}, +while a neighbouring condenser~\smallsanscap{C} could be charged +through the air-space~\smallsanscap{F}; \smallsanscap{C}~was a small condenser whose capacity +was only~$.55$ m., while \smallsanscap{B}~was a battery of Leyden Jars whose capacity +was $1000$~times that of~\smallsanscap{C}. Another circuit connected with the +%% -----File: 200.png---Folio 186------- +machine led to a thin wire placed about $5$~mm.\ above a plate~$e$ which +was connected to the earth. A glow discharge passed between the +wire and the plate, and the difference of potential between the inside +and outside coatings of the jar~\smallsanscap{B} was constant and equal to +about $12$~electrostatic units. When the knobs of the air-break~\smallsanscap{F} +were pushed suddenly together a spark about $.5$~mm.\ in length was +produced at~\smallsanscap{F}, and in addition a bright spark $5$~mm.\ long +jumped across the air space at~$e$ where there was previously +only a glow. The passage of the spark at~\smallsanscap{F} put the two +condensers \smallsanscap{B}~and~\smallsanscap{C} into electrical communication, and this was +equivalent to increasing the capacity of~\smallsanscap{B} by about one part in +a thousand; this alteration in the capacity produced a corresponding +diminution in the potential difference between its coatings. +This disturbance of the electrical equilibrium would give rise to +small but very rapid oscillations in the potential difference between +the wire and the plate~$e$, and this variable field seemed able +to send a spark across~$e$, where when the potential was steady +nothing but a glow was to be seen. + +\Article{204} It thus appears that a gas is electrically weaker under +oscillating electric fields than under steady ones, for it is not +apparent why the addition of the capacity of the small condenser +to that of~\smallsanscap{B} should produce any considerable difference in the +electromotive intensity at~$e$. It is true that while the discharge +is oscillating the tubes of electrostatic induction are not distributed +in the same way as they are when the field is steady, and +some concentration of these tubes may very likely take place, but +it does not seem probable that the disturbance produced by so +small a condenser would be sufficient to account for the large +effects observed by Jaumann, unless, as he supposes, the gas is +electrically weaker in variable electric fields. + +Another point which might affect the electromotive intensity +at~$e$ is the following: the comparatively small difference of +potential between the wire and the plate is partly due to the +glowing air-space at~$e$ acting as a conductor, this conductivity +is due to dissociated molecules produced by the discharge, and +it is likely that this would exhibit what are called `unipolar' +properties, that is, that its conductivity for a current in one +direction would not be the same as for one in the opposite. +Even when the change produced in the distribution of electricity +is not so great as that due to an actual reversal of the +%% -----File: 201.png---Folio 187------- +current it is conceivable that the conductivity of the space at~$e$ +might depend upon the way the electricity was distributed over +the wire and plate. Thus when this distribution of electricity was +altered, the air, by becoming a worse conductor, might cause the +electricity to accumulate on the wire and thus increase the electromotive +intensity at~$e$. Since, however, there is a condenser of large +capacity in electrical connection with the wire any increase in +its electrification would be slow, whereas the spark observed by +Jaumann seems to have followed that across~\smallsanscap{F} without the lapse +of any appreciable interval. + +\Article{205} The observations of other physicists seem to afford confirmatory +evidence of the way in which electric discharge is +facilitated by rapid alterations in the electromotive intensity. +Thus Meissner (\textit{Abhand.\ der König.\ Gesell.\ Göttingen}, 16, p.~3, +\index{Meissner, expansion due to discharge}% +1871; see also \artref{196}{Art.~196}) found that ozone was produced in a +tube placed between the plates of a condenser when these were +suddenly charged or discharged, while none was produced when +the charges on the plates were kept constant; the potential difference +in this experiment was not sufficient to cause a spark to +pass between the plates. Again, R.~v.~Helmholtz and Richarz +\index{Helmholtz vr@Helmholtz, v.\ R., effect of electrification on a steam jet}% +\index{Richarz@Richarz and R. v.\ Helmholtz, steam jet}% +(\textit{Wied.\ Ann.}\ 40, p.~161, 1890) using an induction coil that would +give sparks in air about $4$~inches long, found that when the +electrodes were separated by about a foot and encased in wet +linen bags to stop any particles of metal that might be given off +from them, a steam jet some distance away from the electrodes +showed very distinct signs of condensation whenever the current +in the primary of the coil was broken. A steam jet is a very +sensitive detector of chemical decomposition, free atoms producing +condensation of the steam even when no particles of dust are +present. + +\bigskip +\includegraphicsmid{fig86}{Fig.~86.} + +If we suppose that the electric field produces a polarized +arrangement of the molecules of the gas, then considering the +case when the left-hand electrode is the negative one, the right-hand +the positive, there will be between the electrodes a chain +of molecules arranged as in the first line in \figureref{fig86}{Fig.~86}, the +positively charged atoms being denoted by~$A$, the negatively +charged ones by~$B$. If the field is now reversed, the molecules +will be arranged as in the second line in \figureref{fig86}{Fig.~86}. If the reversal +takes place very slowly, the molecules will reverse their polarity +by swinging round, but if the rate of reversal is very rapid the +%% -----File: 202.png---Folio 188------- +resistance offered by the inertia of the molecules to this rotation +will give rise to a tendency to produce the reversal of polarity +of the molecules by chemical decomposition without rotation. +This may be done by the molecules splitting up and rearranging +themselves as in the third line of \figureref{fig86}{Fig.~86}. + +I have observed the effect of the reversal of the electric field +when experimenting on the discharge produced in hydrogen at +low pressures by a battery consisting of a large number of +storage cells. I found that when the electromotive force was +insufficient to produce continuous discharge, a momentary discharge +occurred when the battery was reversed; this discharge +merely flashed out for an instant, and took place when no +discharge could be obtained by merely making or breaking the +circuit without reversing the battery. A momentary discharge, +however, occurred on making the circuit long before the electromotive +force was sufficient to maintain a permanent discharge. + +\Article{206} Jaumann (l.~c.)\ gives some examples of brushes which +\index{Brush discharge}% +are formed at places where the electromotive intensity for steady +charges is not a maximum. He explains these by supposing +that the variations in the density of the electricity are more rapid +%% -----File: 203.png---Folio 189------- +at some parts of the electrodes than at others, and that \textit{ceteris +paribus} the discharge takes place most readily at the places +where the rate of variation of the charge is greatest. Some of +these brushes are represented in \figureref{fig87}{Fig.~87}, taken from Jaumann. + +\bigskip +\includegraphicsmid{fig87}{Fig.~87.} + +\Subsection{Theory of the Electric Discharge.} +\index{Theory of electric discharge}% + +\Article{207} The phenomena attending the electric discharge through +gases are so beautiful and varied that they have attracted the +attention of numerous observers. The attention given to +these phenomena is not, however, due so much to the beauty +of the experiments, as to the wide-spread conviction that +there is perhaps no other branch of physics which affords us so +promising an opportunity of penetrating the secret of electricity; +for while the passage of this agent through a metal or an electrolyte +is invisible, that through a gas is accompanied by the +most brilliantly luminous effects, which in many cases are so +much influenced by changes in the conditions of the discharge +as to give us many opportunities of testing any view we may +take of the nature of electricity, of the electric discharge, and of +the relation between electricity and matter. + +Though the account we have given in this chapter of the discharge +through gases is very far from complete, it will probably +have been sufficient to convince the student that the phenomena +are very complex and very extensive. It is therefore desirable +to find some working hypothesis by which they can be coordinated: +the following method of regarding the discharge +seems to do this to a very considerable extent. + +\Article{208} This view is, that the passage of electricity through a gas +as well as through an electrolyte, and as we hold through a +metal as well, is accompanied and effected by chemical changes; +also that `chemical decomposition is not to be considered merely +as an accidental attendant on the electrical discharge, but as +an essential feature of the discharge without which it could +not occur' (\textit{Phil.\ Mag.}\ [5],~15, p.~432, 1883). The nature of the +chemical changes which accompany the discharge may be roughly +described as similar to those which on Grotthus' theory of +\index{Grotthus' chains}% +electrolysis are supposed to occur in a Grotthus chain. The way +such chemical changes effect the passage of the electricity has +been already described in \artref{31}{Art.~31}, when we considered the way +%% -----File: 204.png---Folio 190------- +in which a tube of electrostatic induction contracted when in +a conductor. The shortening of a tube of electrostatic induction +is equivalent to the passage of electricity through the +conductor. + +In conduction through electrolytes the signs of chemical +change are so apparent both in the deposition on the electrodes +of the constituents of the electrolyte and in the close connection, +expressed by Faraday's Laws, between the quantity of electricity +transferred through the electrolyte and the amount of chemical +change produced, that no one can doubt the importance of the +part played in this case by chemical decomposition in the transmission +of the electric current. + +\Article{209} When electricity passes through gases, though there is +(with the possible exception of Perrot's experiment, see \artref{200}{Art.~200}) +no one phenomenon whose interpretation is so unequivocal as +some in electrolysis, yet the consensus of evidence given by the +very varied phenomena shown by the gaseous discharge seems to +point strongly to the conclusion that here, as in electrolysis, the +discharge is accomplished by chemical agency. + +Perrot, in 1861, seems to have been the first to suggest that +the discharge through gases was of an electrolytic nature. In +\index{Giese, xconduction of electricity through gases@\subdashone conduction of electricity through gases}% +1882 Giese (\textit{Wied.\ Ann.}\ 17, pp.~1, 236,~519) arrived at the same +conclusion from the study of the conductivity of flames. + +Before applying this view to explain in detail the laws governing +the electric discharge through gases, it seems desirable to +mention one or two of the phenomena in which it is most plainly +suggested. + +The experiments bearing most directly on this subject are +\index{Perrot, decomposition of steam}% +those made by Perrot on the decomposition of steam by the discharge +from a Ruhmkorff's coil (see \artref{200}{Art.~200}). Perrot found that +when the discharge passed through steam there was an excess of +oxygen given off at the positive pole and an excess of hydrogen +at the negative, and that these excesses were chemically equivalent +to each other and to the amount of copper deposited from a +voltameter containing copper sulphate placed in series with the +discharge tube. If this result should be confirmed by subsequent +researches, it would be a direct and unmistakeable proof that the +passage of electricity through gases, just as much as through +electrolytes, is effected by chemical means. It would also show +that the charge of electricity associated with an atom of an +%% -----File: 205.png---Folio 191------- +element in a gas is the same as that associated with the same +atom in an electrolyte. + +\Article{210} Again, Grove (\textit{Phil.\ Trans.}\ 1852, Part~I, p.~87) made +\index{Grove, chemical action of the discharge}% +nearly forty years ago some experiments which show that the +chemical action going on at the positive electrode is not the same +as that at the negative. Grove made the discharge from a +Ruhmkorff's coil pass between a steel needle and a silver plate, +the distance between the point of the needle and the plate being +about $2.5$~mm.; the gas through which the discharge passed was a +mixture of hydrogen and oxygen at pressures about $2$~cm.\ of +mercury. When the silver plate was positive and the needle +negative a patch of oxide was formed on the plate, while if the +plate were originally negative no oxidation occurred. When +the silver plate had been oxidised while being used as a positive +electrode, if the current were reversed so that the plate became +the negative electrode, the oxide was reduced by the hydrogen +and the plate became clean. When pure hydrogen was substituted +for the mixture of hydrogen and oxygen no chemical +action could be observed on the plate, which was however a +little roughened by the discharge; if however the plate was +oxidised to begin with, it rapidly deoxidised in the hydrogen, +especially when it was connected with the negative pole of +the coil. Reitlinger and Wächter (\textit{Wied.\ Ann.}\ 12, p.~590, 1881) +found that the oxidation was very dependent upon the quantity +of water vapour present; when the gas was thoroughly dried +very little oxidation took place. The effect may therefore be +due to the decomposition of the water vapour into hydrogen +and oxygen, an excess of oxygen going to the positive and +an excess of hydrogen to the negative pole. + +Ludeking (\textit{Phil.\ Mag.}\ [5],~33, p.~521, 1892) has found that +\index{Ludeking, passage of electricity through steam}% +when the discharge passes through hydriodic acid gas, iodine is +deposited on the positive electrode but not on the negative. + +\Article{211} Again, chemical changes take place in many gases when +the electric discharge passes through them. Perhaps the best +known example of this is the formation of ozone by the silent +discharge through oxygen. There are however a multitude of +other instances, thus ammonia, acetylene, phosphoretted hydrogen, +and indeed most gases of complex chemical constitution are +decomposed by the spark. + +Another fact which also points to the conclusion that the discharge +%% -----File: 206.png---Folio 192------- +is accomplished by chemical means is that mentioned in +\artref{38}{Art.~38}, that the halogens chlorine, bromine, and iodine, which +are dissociated at high temperatures, and which at such temperatures +have already undergone the chemical change which we +regard as preliminary to conduction, have then lost all power of +insulation and allow electricity to pass through them with ease. + +\sloppy +Then, again, we have the very interesting result discovered by +R.~v.~Helmholtz (\textit{Wied.\ Ann.}\ 32, p.~1, 1887), that a gas through +which electricity is passing and one in which chemical changes +are known to be going on both affect a steam jet in the +same way. + +\fussy +\Article{212} Again, one of the most striking features of the discharge +through gases is the way in which one discharge facilitates the +passage of a second; the result is true whether the discharge +passes between electrodes or as an endless ring, as in the experiments +described in \artref{77}{Art.~77}. Closely connected with this effect +is Hittorf's discovery (\textit{Wied.\ Ann.}~7, p.~614, 1879) that a few +galvanic cells are able to send a current through gas which is +conveying the electric discharge. Schuster (\textit{Proceedings Royal +\index{Schuster, discharge through gases}% +Soc.}, 42, p.~371, 1887) describes a somewhat similar effect. A +large discharge tube containing air at a low pressure was +divided into two partitions by a metal plate with openings +round the perimeter, which served to screen off from one compartment +any electrical action occurring in the other, if a +vigorous discharge passed in one of these compartments, the +electromotive force of about one quarter of a volt was sufficient +to send a current through the air in the other. + +\sloppy +Since such electromotive forces would not produce any discharge +through air in its normal state, these experiments suggest +that the chemical state of the gas has been altered by the discharge. + +\fussy +\Article{213} We shall now go on to discuss more in detail the consequences +of the view that dissociation of the molecules of a gas +always accompanies electric discharge through gases. We notice, +in the first place, that the separation of one atom from another in +the molecule of a gas is very unlikely to be produced by the unaided +agency of the external electric field. Let us take the case +of a molecule of hydrogen as an example; we suppose that the +molecule consists of two atoms, one with a positive charge, the +other with an equal negative one. The most obvious assumption, +%% -----File: 207.png---Folio 193------- +which indeed is not an assumption if we accept Perrot's results, +to make about the magnitude of the charges on the atoms is that +each is equal in magnitude to that charge which the laws of electrolysis +show to be associated with an atom of a monovalent +element. We shall denote this charge by~$e$; it is the one +molecule of electricity which Maxwell speaks about in Art.~260 +of the \textit{Electricity and Magnetism}. + +\index{Molecule, electric field required to decompose}% +The electrostatic attraction between the atoms is the molecule +\[ +\frac{e^2}{r^2}, +\] +where $r$ is the distance between them. If the other molecules of +hydrogen present do not help to split up the molecule, the force +tending to pull the atoms apart is +\[ +2Fe, +\] +where $F$ is the external electromotive intensity. + +The ratio of the force tending to separate the atoms, to their +electrostatic attraction, is thus $2 Fr^2/e$; now at atmospheric pressure +discharge will certainly take place through hydrogen if $F$~in +electrostatic units is as large as~$100$, while at lower pressures +a very much smaller value of~$F$ will be all that is required. To +be on the safe side, however, we shall suppose that $F = 10^2$; then, +assuming that the electrochemical equivalent of hydrogen is +$10^{-4}$ and that there are $10^{21}$~molecules per cubic centimetre at +atmospheric pressure, since the mass of a cubic centimetre of +hydrogen is $1/11 × 10^3$ of a gramme, $e$~in electromagnetic units +will be $10^4/11 × 10^{24}$, or $e$~in electrostatic units will be about +$2.7 × 10^{-11}$ and $r$~is of the order~$10^{-8}$, hence $2Fr^2/e$, the ratio +under consideration, will be about $1/1.4 × 10^3$; this is so small +that it shows the separation of the atoms cannot be effected +by the direct action of the electric field upon them when the +molecule is not colliding with other molecules. If the atoms in +a molecule were almost but not quite shaken apart by a collision +with another molecule, the action of the electric field might be +sufficient to complete the separation. + +The electric field, however, by polarizing the molecules of the +gas, may undoubtedly exert a much greater effect than it could +produce by its direct action on a single molecule. When the +gas is not polarized, the forces exerted on one molecule by its +neighbours act some in one direction, others in the opposite, so +%% -----File: 208.png---Folio 194------- +that the resultant effect is very small; when, however, the +medium is polarized, order is introduced into the arrangement of +the molecules, and the inter-molecular forces by all tending in +the same direction may produce very large effects. + +\Article{214} The arrangement of the molecules of a gas in the electric +field and the tendency of the inter-molecular forces may be illustrated +to some extent by the aid of a model consisting of a large +number of similar small magnets suspended by long strings +attached to their centres. The positive and negative atoms in +the molecules of the gas are represented by the poles of the +magnets, and the forces between the molecules by those between +the magnets. The way the molecules tend to arrange themselves +in the electric field is represented by the arrangement +of the magnets in a magnetic field. + +The analogy between the model and the gas, though it may +serve to illustrate the forces between the molecules, is very imperfect, +as the magnets are almost stationary, while the molecules +are moving with great rapidity, and the collisions which occur +in consequence introduce effects which are not represented in the +model. The magnets, for example, would form long chains +similar to those formed by iron filings when placed in the +magnetic field; in the gas, however, though some of the molecules +would form chains, they would be broken up into short lengths +by the bombardment of other molecules. The length of these +chains would depend upon the intensity of the bombardment to +which they were subjected, that is upon the pressure of the gas; +the greater the pressure the more intense the bombardment, and +therefore the shorter the chain. + +We shall call these chains of molecules Grotthus' chains, +because we suppose that when the discharge passes through the +gas it passes by the agency of these chains, and that the same +kind of interchange of atoms goes on amongst the molecules of +these chains as on Grotthus' theory of electrolysis goes on between +the molecules on a Grotthus' chain in an electrolyte. + +The molecules in such a chain tend to pull each other to pieces, +and the force with which the last atom in the chain is attracted +to the next atom will be much smaller than the force between +two atoms in an isolated molecule; this atom will therefore be +much more easily detached from the chain than it would from a +single molecule, and thus chemical change, and therefore electric +%% -----File: 209.png---Folio 195------- +discharge, will take place much more easily than if the chains +were absent. + +\Article{215} As far as the electrical effects go, it does not matter +whether the effect of the electric field is merely to arrange +chains which already exist scattered about in the gas, or +whether it actually produces new chains; we are more concerned +with the presence of such chains than with their method of production. +The existence of a small number of such chains (and it +only requires a most insignificant fraction of the whole number +of molecules to be arranged in chains to enable the gas to convey +the most intense discharge) would have important chemical +results, as it would greatly increase the ability of the gas to enter +into chemical combination. + +\includegraphicsmid{fig88}{Fig.~88.} + +\Article{216} The way in which the electric discharge passes along +such a chain of molecules is similar to the action in an ordinary +Grotthus' chain. Thus, let $A_1B_1$,~$A_2B_2$, $A_3B_3$,~\&c., \figureref{fig88}{Fig.~88}, represent +consecutive molecules in such a chain, the~$A$'s being the +positive atoms and the~$B$'s the negative. Let one atom,~$A_1$, at the +end of the chain be close to the positive electrode. Then when +the chain breaks down the atom~$A_1$ at the end of the chain goes +to the positive electrode, $B_1$~the other atom in this molecule, +combining with the negative atom~$A_2$ in the next molecule, $B_2$~combining +with~$A_3$; the last molecule being left free and serving +as a new electrode from which a new series of recombinations in +a consecutive chain originates. There would thus be along the +line of discharge a series of quasi-electrodes, at any of which the +products of the decomposition of the gas might appear. + +The whole discharge between the electrodes consists on this +view in a series of non-contemporaneous discharges, these discharges +travelling consecutively from one chain to the next. + +The experiment described in \artref{105}{Art.~105} shows that this discharge +starts from the positive electrode and travels to the negative +with a velocity comparable with that of light. The introduction +of these Grotthus' chains enables us to see how the velocity of the +\index{Grotthus' chains}% +discharge can be so great, while the velocity of the individual +molecules is comparatively small. The smallness of the velocity +of these molecules has been proved by spectroscopic observations; +%% -----File: 210.png---Folio 196------- +many experiments have shown that there is no appreciable displacement +in the lines of the spectrum of the gas in the discharge +tube when the discharge is observed end on, while if the molecules +were moving with even a very small fraction of the velocity +of light, Döppler's principle shows that there would be a measurable +displacement of the lines. It does not indeed require spectroscopic +analysis to prove that the molecules cannot be moving +with half the velocity of light; if they did it can easily be shown +that the kinetic energy of the particles carrying the discharge of +a condenser would have to be greater than the potential energy +in the condenser before discharge. + +When, however, we consider the discharge as passing along +these Grotthus' chains, since the recombinations of the different +molecules in the chain go on simultaneously, the electricity will +pass from one end of the chain to the other in the time required +for an atom in one molecule to travel to the oppositely charged +atom in the next molecule in the chain. Thus the velocity of the +discharge will exceed that of the individual atoms in the proportion +of the length of the chain to the distance between two +adjacent atoms in neighbouring molecules. This ratio may be +very large, and we can understand therefore why the velocity +of the electric discharge transcends so enormously that of the +atoms. + +\Article{217} We thus see that the consideration of the smallness of the +electromotive intensity required to produce chemical change or +discharge, as well as of the enormous velocity with which the +discharge travels through the gas, has led us to the conclusion +that a small fraction of the molecules of the gas are held together +in Grotthus' chains, while the consideration of the method by +which the discharge passes along these chains indicates that the +spark through the gas consists of a series of non-contemporaneous +discharges, the discharge travelling along one chain, then waiting +for a moment before it passes through the next, and so on. +It is remarkable that many of the physicists, who have paid the +greatest attention to the passage of electricity through gases, +have been driven by their observations to the conclusion that +the electric discharge is made up of a large number of separate +discharges. The behaviour of \DPtypo{striae}{striæ} under the action of magnetic +force is one of the chief reasons for coming to this conclusion. On +\index{Spottiswoode and Moulton, electric discharge}% +this point Spottiswoode and Moulton (\textit{Phil.\ Trans.}\ 1879, part~1, +%% -----File: 211.png---Folio 197------- +p.~205) say, `If a magnet be applied to a striated column, it will +be found that the column is not simply thrown up or down as a +whole, as would be the case if the discharge passed in direct lines +from terminal to terminal, threading the \DPtypo{striae}{striæ} in its passage. On +the contrary, each stria is subjected to a rotation or deformation +of exactly the same character as would be caused if the stria +marked the termination of flexible currents radiating from the +bright head of the stria behind it and terminating in the hazy +inner surface of the stria in question. An examination of several +cases has led the authors of this paper to conclude that the +currents do thus radiate from the bright head of a stria to the +inner surface of the next, and that there is no direct passage +from one terminal of the tube to the other.' + +With regard to the way the discharge takes place, the same +authors say (\textit{Phil.\ Trans.}\ 1879, part~1, p.~201)---`If, then, we are +right in supposing that the series of artificially produced hollow +shells are analogous in their structures and functions to \DPtypo{striae}{striæ}, it +is not difficult to deduce, from the explanation above given, the +\textit{modus operandi} of an ordinary striated discharge. The passage of +each of the intermittent pulses from the bright surface of a stria +towards the hollow surface of the next may well be supposed, by +its inductive action, to drive from the next stria a similar pulse, +which in its turn drives one from the next stria, and so on\ldots. +The passage of the discharge is due in both cases to an action +consisting of an independent discharge from one stria to the next, +and the idea of this action can perhaps be best illustrated by that +of a line of boys crossing a brook on stepping stones, each boy +stepping on the stone which the boy in front of him has left.' + +Goldstein (\textit{Phil.\ Mag.}\ [5]~10, p.~183, 1880) expresses much the +\index{Goldstein, discharge of electricity through gases}% +same opinion. He says: `By numerous comparisons, and taking +account of all apparently essential phenomena, I have been led to +the following view:--- + +`The kathode-light, each bundle of secondary negative light, +as well as each layer of positive light, represent each a separate +current by itself, which begins at the part of each structure +turned towards the kathode, and ends at the end of the negative +rays or of the stratified structure, without the current flowing in +one structure propagating itself into the next, without the electricity +which flows through one also traversing the rest in +order. +%% -----File: 212.png---Folio 198------- + +`I suspect, then, that as many new points of departure of the +discharge are present in a length of gas between two electrodes +as this shows of secondary negative bundles or layers---that as +according to experiments repeatedly mentioned all the properties +and actions of the discharge at the kathode are found +again at the secondary negative light and with each layer of +positive light, the intimate action is the same with these as it is +with those.' + +\Article{218} Thus, if we regard a stria as a bundle of Grotthus' chains +in parallel rendered visible, the bright parts of the stria corresponding +to the ends of the chain, the dull parts to the middle, the +conclusion of the physicists just quoted are almost identical with +those we arrived at by the consideration of the chains. We +therefore regard the stratification of the discharge as evidence of +the existence of these chains, and suppose that a stria is in fact +a bundle of Grotthus' chains. + +\Article{219} As far as phenomena connected with the electric discharge +are concerned, the Grotthus' chain is the unit rather than the +molecule; now the length of this chain is equal to the length of +a stria, which is very much greater than the diameter of a +molecule, than the average distance between two molecules, +or even than the mean free path of a molecule: thus the structure +of a gas, as far as phenomena connected with the electric discharge +are concerned, is on a very much coarser scale than its +structure with reference to such properties as gaseous diffusion +where the fundamental length is that of the mean free path of +the molecules. + +\Article{220} Peace's discovery that the density---which we shall call +the critical density---at which the `electric strength' of the gas +is a minimum depends upon the distance between the electrodes, +proves that the gas, when in an electric field sufficiently +intense to produce discharge, possesses a structure whose length +scale is comparable with the distance between the electrodes +when these are near enough together to influence the critical +density. As this distance is very much greater than any of the +lengths recognized in the ordinary Kinetic Theory of Gases, the +gas when under the influence of the electric field must have a +structure very much coarser than that recognized by that theory. +In our view this structure consists in the formation of Grotthus' +chains. +%% -----File: 213.png---Folio 199------- + +\Article{221} The striations are only clearly marked within somewhat +narrow limits of pressure. But it is in accordance with the conclusion +which all who have studied the spark have arrived at---that +there is complete continuity between the bright well-defined +spark which occurs at high pressures and the diffused glow +which represents the discharge at high exhaustions---to suppose +that they always exist in the spark discharge, but that at high +pressures they are so close together that the bright and dark +parts cease to be separable by the eye. + +The view we have taken of the action of the Grotthus' chains +in propagating the electric discharge, and the connection between +these chains and the striations, does not require that every discharge +should be visibly striated; on the contrary, since the +striations will only be visible when there is great regularity in +the disposition of these chains, we should expect that it would +only be under somewhat exceptional circumstances that the conditions +would be regular enough to give rise to visible striations. + +\Article{222} We shall now proceed to consider more in detail the +application of the preceding ideas to the phenomena of the +electric discharge. The first case we shall consider is the calculation +of the potential difference required to produce discharge +under various conditions. + +It is perhaps advisable to begin with the caution that in comparing +the potential differences required to \emph{produce} discharge +through a given gas we must be alive to the fact that the condition +of the gas is altered for a time by the passage of the +discharge. Thus, when the discharges follow each other so +rapidly that the interval between two discharges is not sufficiently +long to allow the gas to return to its original condition +before the second discharge passes, this discharge is in reality +passing through a gas whose nature is a function of the electrical +conditions. Thus, though this gas may be called hydrogen or +oxygen, it is by no means identical with the gas which was called +by the same name before the discharge passed through it. When +the discharges follow each other with great rapidity the supply +of dissociated molecules left by preceding discharges may be so +large that the discharge ceases to be disruptive, and is analogous +to that through a very hot gas whose molecules are dissociated +by the heat. + +The measurements of the potential differences required to send +%% -----File: 214.png---Folio 200------- +the first spark through a gas are thus more definite in their +interpretation than measurements of potential gradients along +the path of a nearly continuous discharge. + +The striations on the preceding view of the discharge may, since +they are equivalent to a bundle of Grotthus' chains, be regarded as +forming a series of little electrolytic cells, the beginning and the +end of a stria corresponding to the electrodes of the cell. Let $F$~be +the electromotive intensity of the field, $\lambda$~the length of a stria, +then when unit of electricity passes through the stria the work +done on it by the electric field is~$F\lambda$. The passage of the electricity +through the stria is accompanied just as in the case of +the electrolytic cell, by definite chemical changes, such as the +decomposition of a certain number of molecules of the gas; thus +if $w$~is the increase in the potential energy of the gas due to the +changes which occur when unit of electricity passes through the +stria, then neglecting the heat produced by the current we have +by the Conservation of Energy +\[ +F\lambda = w, +\] +or the difference in potential between the beginning and end of a +stria is equal to~$w$. If the chemical and other changes which +take place in the consecutive \DPtypo{striae}{striæ} are the same, the potential +difference due to each will be the same also. There is however +one stria which is under different conditions from the others, +viz.~that next the negative electrode, i.e.~the negative dark +space. For in the body of the gas, the ions set free at an extremity +of the stria, are set free in close proximity to the ions of opposite +sign at the extremity of an adjacent stria. In the stria next +the electrode the ions at one end are set free against a metallic +surface. The experiments described in the account we have +already given of the discharge show that the chemical changes +which take place at the cathode are abnormal; one reason for +this no doubt is the presence of the metal, which makes many +chemical changes possible which could not take place if there +were nothing but gas present. This stria is thus under exceptional +circumstances and may differ in size and fall of potential +from the other \DPtypo{striae}{striæ}. Hittorf's experiments, \artref{140}{Art.~140}, show that +the fall of potential at the cathode is abnormally great. If we call +this potential fall~$K$ and consider the case of discharge between +two parallel metal plates; the discharge on this view, starting from +the positive electrode, goes consecutively across a number~$n$ of +%% -----File: 215.png---Folio 201------- +similar \DPtypo{striae}{striæ}, one of which reaches up to the positive electrode, +the fall of potential across each of these is~$w$; the discharge +finally crosses the stria in contact with the negative electrode +in which the fall of potential is~$K$; thus~$V$, the total fall of +potential as the discharge goes from the positive to the negative +electrode, is given by the equation +\[ +V = K + nw. \Tag{1} +\] +If $l$~is the distance between the plates, $\lambda_{0}$~the length of the stria +next the cathode, $\lambda$~the length of the other stria, then +\[ +n = \frac{l - \lambda_0}{\lambda}. +\] +Substituting this value for~$n$ in~(\eqnref{222}{1}) we get +\[ +V = \left(K - \frac{w\lambda_0}{\lambda}\right) + \frac{l}{\lambda} w, +\] +which may be written +\[ +V = K' + al. \Tag{2} +\] +According to this equation the curve representing the relation +between potential difference and spark length for constant +pressure is a straight line which does not pass through the +origin. The curves we have given from the papers by Paschen +and Peace show that this is very approximately true. The +curves show that for air $K'$~would at atmospheric pressure be +about $600$~volts from Paschen's experiments and about $400$~volts +from Peace's. + +If $R$~is the electromotive intensity required to produce a spark +of length~$l$ between two parallel infinite plates, then since $R = V/l$ +\[ +R = \frac{K'}{l} + a. \Tag{3} +\] +Since $K'$~is positive, the electromotive intensity required to produce +discharge increases as the length of the spark diminishes; +in other words, the electric strength of a thin layer of gas is +greater than that of a thick layer. The electric strength will +sensibly increase as soon as $K'/l$ \DPtypo{become}{becomes} appreciable in comparison +with~$a$, this will occur as soon as $l$~ceases to be a very large +multiple of the length of a stria. Thus the thickness of the layer +when the `electric strength' begins to vary appreciably is comparable +with the length of a stria at the pressure at which the +discharge takes place; this length is very large when compared +with molecular distances or with the mean free path of the +%% -----File: 216.png---Folio 202------- +molecules of the gas; hence we see why the change in the `electric +strength' of a gas takes place when the spark length is very +large in comparison with lengths usually recognized in the +Kinetic Theory of Gases. + +According to formula~(\eqnref{222}{3}), the curve representing the relation +between electromotive intensity and spark length is a rectangular +hyperbola; this is confirmed by the curves given by Dr.~Liebig +for air, carbonic acid, oxygen and coal gas (see \figureref{fig19}{Fig.~19}), and by +those given by Mr.~Peace for air. + +\Article{223} The preceding formulæ are not applicable when the distance +between the electrodes is less than~$\lambda_0$ the length of the +stria next the cathode. But if the discharge passes through the +gas and is not carried by metal dust torn from the electrodes we +can easily see that the electric strength must increase as the +distance between the electrodes diminishes. For as we have seen, +the molecules which are active in carrying the discharge are not +torn in pieces by the direct action of the electric field but by the +attraction of the neighbouring molecules in the Grotthus' chain. +Now when we push the electrodes so near together that the +distance between them is less than the normal length of the +chain, we take away some of the molecules from the chain +and so make it more difficult for the molecules which remain to +split up any particular molecule into atoms, so that in order to +effect this splitting up we must increase the number of chains in +the field, in other words, we must increase the electromotive +intensity. + +Peace's curves, \figureref{fig27}{Fig.~27}, showing the relation between the +potential difference and spark length are exceedingly flat in the +neighbourhood of the critical spark length. This shows that the +potential difference required to produce discharge increases very +slowly at first as the spark length is shortened to less than the +length of a Grotthus' chain. + +We now proceed to consider the relation between the spark +potential and the pressure. As we have already remarked, the +length of a Grotthus' chain depends upon the density of the +gas; the denser the gas the shorter the chain: this is illustrated +by the way in which the \DPtypo{striae}{striæ} lengthen out when the pressure +is reduced. The experiments which have been made on the +connection between the length of a stria and the density of the +gas are not sufficiently decisive to enable us to formulate the +%% -----File: 217.png---Folio 203------- +exact law connecting these two quantities, we shall assume +however that it is expressed by the equation +\[ +\lambda = \beta\rho^{-k} , +\] +where $\lambda$~is the length of a stria, $\rho$~the density of the gas, and $\beta$,~$k$ +positive \DPtypo{constant}{constants}. + +Equation~(\eqnref{222}{1}) involves $K$~the fall of potential at the cathode +and $w$~the fall along a stria as well as~$\lambda$. Warburg's experiments +(\artref{160}{Art.~160}) show that the cathode fall~$K$ is almost independent +of the pressure, and although no observations have been made +on the influence of a change in the pressure on the value of~$w$, +it is not likely that~$w$ any more than~$K$ depends to any great +extent upon the pressure. If we substitute the preceding value +of~$\lambda$ in equation~(\eqnref{222}{2}) we get +\[ +V = K' + \frac{l}{\beta}\rho^kw. +\] +Both Paschen's and Peace's experiments show that when the +spark length is great enough to include several \DPtypo{striae}{striæ} the curve +representing the relation between the spark potential and density +for a constant spark length, though very nearly straight, is +slightly convex to the axis along which the densities are +measured. This shows that $k$~is slightly, but only slightly, +greater than unity. + +\Article{224} It is interesting to trace the changes which take place +in the conditions of discharge between two electrodes at a fixed +distance apart as the pressure of the gas gradually diminishes. + +When the pressure is great the \DPtypo{striae}{striæ} are very close together, +so that if the distance between the electrodes is a millimetre +or more, a large number of \DPtypo{striae}{striæ} will be crowded in between +them. As the pressure diminishes the \DPtypo{striae}{striæ} widen out, and +fewer and fewer of them can find room to squeeze in between +the electrodes, and as the number of \DPtypo{striae}{striæ} between the electrodes +diminishes, the potential required to produce a spark diminishes +also, each stria that is squeezed out corresponding to a +definite diminution in the spark potential. This diminution +in potential will go on until the \DPtypo{striae}{striæ} have all been eliminated +with the exception of one. There can now be no further +reduction in the number of \DPtypo{striae}{striæ} as the pressure diminishes, +and the Grotthus' chain which is left, and which is required +to split up the molecules to allow the discharge to take place, +%% -----File: 218.png---Folio 204------- +gets curtailed as the pressure falls by a larger and larger +fraction of its natural length, and therefore has greater and +greater difficulty in effecting the decomposition of the molecules, +so that the electric strength of the gas will now increase as the +pressure diminishes. There will thus be a density at which +the electric strength of the gas is a minimum, and that density +will be the one at which the length of the stria next the cathode +is equal or nearly equal to the distance between the electrodes. +Thus the length of a stria at the minimum strength will have +to be very much less when the electrodes are very near together +than when they are far apart, and since the stria-length is less +the density at which the `electric strength' is a minimum will +be very much greater when the electrodes are near together +than when they are far apart. This is most strikingly exemplified +in Mr.~Peace's experiments, for when the distance between the +electrodes was reduced from $1/5$ to $1/100$~of a millimetre the +critical pressure was raised from $30$ to $250$~mm.\ of mercury. +The mean free path of a molecule of air at a pressure of 30~mm.\ +is about $1/400$~of a millimetre. + +\Article{225} The existence of a critical pressure, or pressure at which +the electric strength is a minimum, when the discharge passes +between electrodes can thus be explained if we recognize the +formation of Grotthus' chains in the gas, and the theory leads to +the conclusion which, as we have seen, is in accordance with the +facts, that the critical pressure depends on the spark length. + +\Article{226} We have seen that when the distance between the electrodes +is less than the length of the stria next the negative +electrode, the intensity of the field required to produce discharge +will increase as the distance between the electrodes diminishes. +Peace's observations show that this increase is so rapid that +the potential difference between the electrode when the spark +passes increases when the spark length is diminished, or in other +words, that the electromotive intensity increases more rapidly +than the reciprocal of the length of a Grotthus' chain. This +will explain the remarkable results observed by Hittorf (\artref{170}{Art.~170}) +and Lehmann (\artref{170}{Art.~170}) when the electrodes were placed very +near together in a gas at a somewhat low pressure. In such cases +it was found that the discharge instead of passing in the straight +line between the electrodes took a very roundabout course. To +explain this, suppose that in the experiment shown in \figureref{fig68}{Fig.~68} +%% -----File: 219.png---Folio 205------- +the electrodes are nearer together than the length of the chain +next the electrode, i.e.~the negative dark space; then if the +discharge passed along the shortest path between the plates, the +potential difference required would, by Peace's experiments, considerably +exceed~$K$, the normal cathode potential fall; if however +the discharge passed as in the figure along a line of force, whose +length is greater than the negative dark space, the potential +difference required would be $K$~plus that due to any small positive +column which may exist in the discharge. The latter part of +the potential difference is small compared with~$K$, so that the +potential difference required to produce discharge along this +path will only be a little in excess of~$K$, while that required to +produce discharge along the shortest path would, by Peace's +experiments, be considerably greater than~$K$, the discharge will +therefore pass as in the figure in preference to taking the shortest +path. + +\Article{227} Since a term in the expression~(\eqnref{222}{1}) for the potential difference +required to produce a spark of given length is inversely +proportional to the length of a stria, anything which diminishes +the length of a stria will tend to increase this potential difference. +Now the length of a stria is influenced by the size of the +discharge tube as soon as the length becomes comparable with +the diameter of the tube; the narrower the tube the shorter are +the \DPtypo{striae}{striæ}. Hence we should expect to find that it would require +a greater potential difference to produce at a given pressure a +spark through a narrow tube than through a wide one. This +is confirmed by the experiments made by De~la~Rue and Hugo +Müller, described in \artref{169}{Art.~169}. + +\Article{228} We do not at present know enough about the laws which +govern the passage of electricity from a gas to a solid, or from +a solid to a gas, to enable us to account for the difference +between the appearances presented by the discharge at the cathode +and anode of a vacuum tube; it may, however, be well to consider +one or two points which must doubtless influence the behaviour +of the discharge at the two electrodes. + +We have seen (\artref{108}{Art.~108}) that the positive column in the electric +discharge starts from the positive electrodes, and that with the exception +of the negative rays, no part of the discharge seems to +begin at the cathode; we have also seen that the potential differences +in the neighbourhood of the cathode are much greater than +%% -----File: 220.png---Folio 206------- +those near the anode. These results might at first sight seem inconsistent +with the experiments we have described (\artref{40}{Art.~40}) on the +electrical effect on metal surfaces of ultra-violet light and incandescence. +In these experiments we saw that under such influences +negative electricity escaped with great ease from a metallic +electrode, while, on the other hand, positive electricity had great +difficulty in doing so. In the ordinary discharge through gases it +seems, on the contrary, to be the positive electricity which escapes +with ease, while the negative only escapes with great difficulty. +We must remember, however, that the vehicle conveying the electricity +may not be the same in the two cases. When ultra-violet +light is incident on a metal plate, there seems to be nothing in +the phenomena inconsistent with the hypothesis that the negative +electrification is carried away by the vapour or dust of the +metal. In the case of vacuum tubes, however, the electricity is +doubtless conveyed for the most part by the gas and not by +the metal. In order to get the electricity from the gas into the +metal, or from the metal into the gas, something equivalent to +chemical combination must take place between the metal and +the gas. Some experiments have been made on this point by +\index{Stanton, escape of electricity from hot metals}% +Stanton (\textit{Proc.\ Roy.\ Soc.}~47, p.~559, 1890), who found that a +hot copper or iron rod connected to earth only discharged the +electricity from a positively electrified conductor in its neighbourhood +when chemical action was visibly going on over the +surface of the rod, e.g.~when it was being oxidised in an atmosphere +of oxygen. When it was covered with a film of oxide it +did not discharge the adjacent conductor; if when coated with +oxide it was placed in an atmosphere of hydrogen it discharged +the electricity as long as it was being deoxidised, but as soon as +the deoxidation was complete the leakage of the electricity +stopped. On the other hand, when the conductor was negatively +electrified, it leaked even when no apparent chemical action was +taking place. I have myself observed (\textit{Proc.\ Roy.\ Soc.}~49, p.~97, +1891) that the facility with which electricity passed from a gas +to a metal was much increased when chemical action took place. +If this is the case, the question as to the relative ease with which +the electricity escapes from the two electrodes through a vacuum +tube, depends upon whether a positively or negatively electrified +surface more readily enters into chemical combination with the +adjacent gas, while the sign of the electrification of a metal +%% -----File: 221.png---Folio 207------- +surface under the influence of ultra-violet light may, on the +other hand, depend upon whether the `Volta-potential' (see +\artref{44}{Art.~44}) for the metal in its solid state is less or greater than +for the dust or vapour of the metal. + +\Article{229} In framing any theory of the difference between the positive +and negative electrodes, we must remember that at the electrodes +we have either two different substances or the same substance in +two different states in contact, and it is in accordance with what we +know of the electrical effects produced by the contact of different +substances that the gas in the immediate neighbourhood of the +electrodes should be polarized, that is, that the molecular tubes +of induction in the gas should tend to point in a definite +direction relatively to the outward drawn normals to the +electrode: let us suppose that the polarization is such that the +negative ends of the tubes are the nearest to the electrode: we +may regard the molecules of the gas as being under the influence +of a couple tending to twist them into this position. If now this +electrode is the cathode, then before these molecules are available +for carrying the discharge, they must be twisted right round +against the action of an opposing couple, so that to produce +discharge at this electrode the electric field must be strong +enough to twist the molecules out of their original alignment +into the opposite one, it must therefore be stronger than in the +body of the gas where the opposing couple does not exist: a +polarization of this kind would therefore make the cathode +potential gradient greater than that in the body of the gas. +%% -----File: 222.png---Folio 208------- + + +\Chapter{Chapter III.}{Conjugate Functions.} + +\index{Christoffel's theorem in conjugate functions}% +\index{Kirchhoff, on conjugate functions}% +\index{Love on conjugate functions}% +\index{Michell, xconjugate functions@\subdashone conjugate functions}% +\index{Potier, conjugate functions}% +\index{Schwarz, conjugate functions}% +\index{Schwarz's transformation}% +\index{Transformation, Schwarz's}% +\Article{230} \Firstsc{The} methods given by Maxwell for solving problems in +Electrostatics by means of Conjugate Functions are somewhat +indirect, since there is no rule given for determining the proper +transformation for any particular problem. Success in using +these methods depends chiefly upon good fortune in guessing the +suitable transformation. The use of a general theorem in Transformations +given by Schwarz (\textit{Ueber einige Abbildungsaufgaben}, +Crelle~70, pp.~105--120, 1869), and Christoffel (\textit{Sul problema +delle temperature stazionarie}, Annali di~Matematica,~I. p.~89, +1867), enables us to find by a direct process the proper transformations +for electrostatical problems in two dimensions when +the lines over which the potential is given are straight. We +shall now proceed to the discussion of this method which has +been applied to Electrical problems by Kirchhoff (\textit{Zur Theorie des +Condensators}, Gesammelte Abhandlungen, p.~101), and by Potier +(Appendix to the French translation of Maxwell's \textit{Electricity and +Magnetism}); it has also been applied to Hydrodynamical problems +by Michell (\textit{On the Theory of Free Stream Lines}, Phil.\ +Trans.\ 1890,~A. p.~389), and Love (\textit{Theory of Discontinuous Fluid +Motions in two dimensions}, Proc.\ Camb.\ Phil.\ Soc.~7, p.~175, +1891). + +\Article{231} The theorem of Schwarz and Christoffel is that any +polygon bounded by straight lines in a plane, which we shall +call the $z$~plane, where $z = x + \iota y$, $x$~and~$y$ being the Cartesian +coordinates of a point in this plane, can be transformed into the +axis of~$\xi$ in a plane which we shall call the $t$~plane, where +$t = \xi + \iota \eta$, $\xi$~and~$\eta$ being the Cartesian coordinates of a point in +this plane; and that points inside the polygon in the $z$~plane +%% -----File: 223.png---Folio 209------- +transform into points on one side of the axis of~$\xi$. The transformation +which effects this is represented by the equation +\[ +\frac{dz}{dt} = C(t-t_{1})^{\frac{\alpha_1}{\pi}-1}(t-t_2)^{\frac{\alpha_2}{\pi}-1} \ldots (t-t_r)^{\frac{\alpha_r}{\pi}-1} \ldots (t-t_n)^{\frac{\alpha_n}{\pi}-1}, \Tag{1} +\] +where $\alpha_1, \alpha_2, \ldots \alpha_n$ are the internal angles of the polygon in the +$z$~plane; $t_1, t_2, \ldots t_n$ are real quantities and are the coordinates +of points on the axis of~$\xi$ corresponding to the angular points of +the polygon in the $z$~plane. + +To prove this proposition, we remark that the argument of +$dz/dt$, that is the value of~$\theta$ when $dz/dt$ is expressed in the +form $R\epsilon^{\iota \theta}$ where $R$~is real, remains unchanged as long as $z$ +remains real and does not pass through any one of the values +$t_1, t_2, \ldots t_n$; in other words, the part of the real axis of~$t$ between +the points $t_r$~and~$t_{r+1}$ corresponds to a straight line in +the plane of~$z$. + +We must now investigate what happens when $t$~passes through +one of the points such as~$t_r$ on the axis of~$\xi$. With centre~$t_r$ +describe a small semi-circle~\smallsanscap{BDC} on the positive side of the axis +of~$\xi$, and consider the change in $dz/dt$ as $t$~passes round~\smallsanscap{BDC} +from~\smallsanscap{B} to~\smallsanscap{C}. + +\bigskip +\includegraphicsmid{fig89}{Fig.~89.} + +Since we suppose $\omega$, the radius of this semi-circle, indefinitely +small, if any finite change in $dz/dt$ occurs in passing round this +semi-circle it must arise from the factor $(t-t_r)^{\frac{\alpha_r}{\pi}-1}$. + +Now for a point on the semi-circle~\smallsanscap{BDC} +\begin{gather*} +t - t_r = \omega \epsilon^{\iota \theta},\\ +(t-t_r)^{\frac{\alpha_r}{\pi}-1} = \omega^{\frac{\alpha_r}{\pi}-1} \epsilon^{\iota\left(\frac{\alpha_r}{\pi}-1\right)\theta}, +\end{gather*} +hence, since $\theta$~decreases from~$\pi$ to zero as the point travels +round the semi-circle, the argument of $(t-t_r)^{\frac{\alpha_r}{\pi}-1}$, and therefore +of~$dz/dt$, is increased by $\pi - \alpha_r$, that is the line corresponding +to the portion~$t_r\, t_{r+1}$ of the axis of~$\xi$ makes with the line +corresponding to the portion~$t_{r-1}\, t_r$, the angle $\pi - \alpha_r$; in other +%% -----File: 224.png---Folio 210------- +words, the internal angle of the polygon in the $z$~plane at the +point corresponding to~$t_r$ is~$\alpha_r$. + +If we imagine a point to travel along the axis of~$\xi$ in the +plane of~$t$ from $t = -\infty$ to $t = +\infty$ and then back again from~$+\infty$ +to~$-\infty$ along a semi-circle of infinite radius with its centre +at the origin of coordinates in the $t$~plane, then, as long as the +point is on the axis of~$\xi$, the corresponding point in the plane~$z$ +is on one of the sides of the polygon. To find the path in~$z$ +corresponding to the semi-circle in~$t$ we put +\[ +t = R\epsilon^{\iota\theta}, +\] +where $R$ is very great and is subsequently made infinite: equation~(\eqnref{231}{1}) +then becomes +\[ +\frac{dz}{dt} = CR^{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - n} \epsilon^{\iota {\left\{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - n \right\} \theta}}, \Tag{2} +\] +since $R$~is infinite compared with any of the quantities +$t_1, t_2, \ldots t_n$. + +Since along the semi-circle +\[ +dt = \iota R\epsilon^{\iota\theta}\,d\theta, +\] +equation~(\eqnref{231}{2}) becomes +\begin{DPgather*} +dz = \iota CR^{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - (n-1)} \epsilon^{\iota \left\{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - (n-1) \right\} \theta}\,d\theta, \\ +\lintertext{or} z = CR^{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - (n-1)} \frac{\epsilon^{\iota \left\{\frac{\alpha_1 + \alpha_2 + \DPtypo{}{\ldots} \alpha_n}{\pi} - (n-1) \right\} \theta}}{\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - (n-1)}. +\end{DPgather*} + +Thus the path in the $z$~plane corresponding to the semi-circle +in the plane of~$z$ is a portion of a circle subtending an angle +$\alpha_1 + \alpha_2 + \ldots \alpha_n - (n - 1)\pi$ at the origin, and whose radius is zero or +infinite according as +\[ +\frac{\alpha_1 + \alpha_2 + \ldots \alpha_n}{\pi} - (n-1) +\] +is positive or negative. + +If this quantity is zero, then equation~(\eqnref{231}{2}) becomes +\[ +\frac{dz}{dt} = \frac{C}{R\epsilon^{\iota \theta}} = \frac{C}{t}, +\] +\begin{DPalign*} +\lintertext{hence} z &= C \log t + A \\ + &= C \log R + \iota C\theta + A, +\end{DPalign*} +where $A$ is the constant of integration. +%% -----File: 225.png---Folio 211------- + +Thus as the point in the $t$~plane moves round the semi-circle +the point in the $z$~plane will travel over a length~$C\pi$ of a straight +line parallel to the axis of~$y$ at an infinite distance from the +origin. + +\Article{232} Since by equation~(\eqnref{231}{1}) the value of~$dz/dt$ cannot vanish +or become infinite for values of~$t$ inside the area bounded by the +axis of~$\xi$ and the infinite semi-circle, this area can be conformably +transformed to the area bounded by the polygon in the $z$~plane. + +\Article{233} When we wish to transform any given polygon in the $z$~plane +into the axis of~$\xi$ in the $t$~plane we have the values of +$\alpha_1, \alpha_2, \ldots \alpha_n$ given. As regards the values of $t_1, t_2, \ldots t_n$ some may +be arbitrarily assumed while others will have to be determined +from the dimensions of the polygon. Whatever the values of +$t_1, t_2, \ldots t_n$, the transformation~(\eqnref{231}{1}) will transform the axis of~$\xi$ +into a polygon whose internal angles have the required values. +In order that this polygon should be similar to the given one +we require $n-3$~conditions to be satisfied; hence as regards the +$n$~quantities $t_1, t_2, \ldots t_n$, the values of $3$~of them may be arbitrarily +assumed, while the remaining $n-3$ must be determined +from the dimensions of the polygon in the $z$~plane. + +\Article{234} The method of applying the transformation theorem to +the solution of two dimensional problems in Electrostatics in +which the boundaries of the conductors are planes, is to take the +polygon whose sides are the boundaries of the conductors, which +we shall speak of as the polygon in the $z$~plane, and transform +it by the Schwarzian transformation into the real axis in a +new plane, which we shall call the $t$~plane. If $\psi$~represents the +potential function, $\phi$~the stream function, and $w = \phi + \iota\psi$, the +condition that $\psi$~is constant over the conductors may be represented +by a diagram in the $w$~plane consisting of lines parallel +to the real axis in this plane: we must transform these lines by +the Schwarzian transformation into the real axis in the $t$~plane. +Thus corresponding to a point on the real axis in the $t$~plane we +have a point in the boundary of a conductor in the $z$~plane and +a point along a line of constant potential in the $w$~plane, and +we make this potential correspond to the potential of the conductor +in the electrostatical problem whose solution we require. + +In this way we find +\begin{align*} +x + \iota y &= f(t),\\ +\phi + \iota\psi &= F(t), +\end{align*} +%% -----File: 226.png---Folio 212------- +\index{Capacity of a semi-infinite plate parallel to an infinite one}% +where $f$~and~$F$ are known functions; eliminating~$t$ between these +equations we get +\[ +\phi + \iota\psi = \chi(x + \iota y), +\] +which gives us the solution of our problem. + +\Article{235} We shall now proceed to consider the application of this +method to some special problems. The first case we shall +consider is the one discussed by Maxwell in Art.~202 of the +\textit{Electricity and Magnetism}, in which a plate bounded by a +straight edge and at potential~$V$ is placed above and parallel to +an infinite plate at zero potential. The diagrams in the $z$~and~$w$ +planes are given in Figs.\ \figureref{fig90}{90}~and~\figureref{fig91}{91} respectively. + +\includegraphicsmid{fig90}{Fig.~90.} + +\includegraphicsmid{fig91}{Fig.~91.} + +The boundary of the $z$~diagram consists of the infinite straight +line~\smallsanscap{AB}, the two sides of the line~\smallsanscap{CD}, and an arc of a circle +stretching from $x = -\infty$ on the line~\smallsanscap{AB} to $x = +\infty$ on the line~\smallsanscap{CD}. +We may assume arbitrarily the values of~$t$ corresponding +to three corners of the diagram, we shall thus assume $t = -\infty$ +at the point $x = -\infty$ on the line~\smallsanscap{AB}, $t = -1$ at the point +$x = +\infty$ on the same line, and $t = 0$ at~\smallsanscap{C}. The internal angles +of the polygon are zero at~\smallsanscap{B} and $2\pi$ at~\smallsanscap{C}; hence by equation~(\eqnref{231}{1}), +\artref{231}{Art.~231}, the Schwarzian transformation of the diagram in +the $z$~plane to the real axis of the $t$~plane is +\[ +\frac{dz}{dt} = C \frac{t}{t+1}. \Tag{3} +\] + +The diagram in the $w$~plane consists of two parallel straight +lines; the internal angle at~\smallsanscap{G}, the point corresponding to $t = -1$, +is zero; hence the Schwarzian transformation to the real axis +of~$t$ is +\[ +\frac{dw}{dt} = B \frac{1}{t+1}.\Tag{4} +\] +%% -----File: 227.png---Folio 213------- + +From~(\eqnref{235}{3}) we have +\[ +z = x + \iota y = C \{t- \log (t+1) + \iota\pi \}, \Tag{5} +\] +where the constant has been chosen so as to make $y = 0$ from +$t = -\infty$ to~$-1$. When $t$~passes through the value~$-1$, the +value of~$y$ increases by~$C\pi$, so that if $h$~is the distance between +the plates +\[ +h = C\pi, +\] +hence we have +\[ +x+\iota y = \frac{h}{\pi} \{t- \log (t+1)+\iota\pi\}. \Tag{6} +\] + +From (\eqnref{235}{4}) we have +\[ +w = \phi+\iota\psi = B \{\log (t+1)-\iota\pi\}; +\] +where the constant of integration has been chosen so as to +make $\psi = 0$ from $t = -\infty$ to $t = -1$. As $t$~passes through the +value~$-1$, $\psi$~diminishes by~$B\pi$. Hence, as the infinite plate is +at zero potential and the semi-infinite one at potential~$V$, we +have +\begin{DPgather*} +V = -B\pi, \\ +\lintertext{or} \phi+\iota\psi = -\frac{V}{\pi} \{\log (t+1)-\iota\pi\}. \Tag{7} +\end{DPgather*} + +Eliminating~$t$ from equations (\eqnref{235}{6})~and~(\eqnref{235}{7}), we get +\[ +x + \iota y = \frac{h}{V} \left\{\phi+\iota\psi - \frac{V}{\pi} \left(1 + \epsilon^{-(\phi+\iota\psi) \frac{\pi}{V}}\right)\right\}, +\] +which is the transformation given in Maxwell's \textit{Electricity and +Magnetism}, Art.~202. + +For many purposes, however, it is desirable to retain~$t$ in the +expressions for the coordinates $x$~and~$y$ and for the potential +and current functions $\psi$~and~$\phi$. + +Thus to find the quantity of electricity on a portion of the +underneath side of the semi-infinite plate, we notice that on this +side of the plate $t$~ranges from~$-1$ to~$0$, and that at a distance +from the edge of the plate which is a large multiple of~$h$, $t$~is +approximately~$-1$. In this case we have by~(\eqnref{235}{6}), if $x$~be the +distance from the edge of the plate corresponding to~$t$, +\[ +x = \frac{h}{\pi} \{t-\log(1+t) \}, +\] +%% -----File: 228.png---Folio 214------- +or since $t = -1$ approximately +\[ +\log(t+1) = -\left\{\frac{\pi x}{h} + 1 \right\}. +\] + +The surface density~$\sigma$ of the electricity on a conductor is +equal to +\[ +- \frac{1}{4\pi}\, \frac{d\psi}{d\nu}, +\] +where $d\nu$~is an element of the outward drawn normal to the +conductor. When, as in the present case, the conductors are +parallel to the axis of~$x$, $d\nu = ± dy$, the $+$~or~$-$ sign being +taken according as the outward drawn normal is the positive or +negative direction of~$y$; i.e.~the positive sign is to be taken at +the upper surface of the plates, the negative sign at the lower. +We thus have +\begin{DPgather*} +\sigma = \mp \frac{1}{4\pi}\, \frac{d\psi}{dy} = \mp \frac{1}{4\pi}\, \frac{d\phi}{dx}. \\ +\lintertext{Since} \sigma = - \frac{1}{4\pi}\, \frac{d\psi}{d\nu} \\ +\lintertext{and} \frac{d\psi}{d\nu} = \frac{d\phi}{ds}, +\end{DPgather*} +where $ds$~is an element of the section of the conductor +\begin{align*} +\sigma &= - \frac{1}{4\pi}\, \frac{d\phi}{ds} \\ + &= - \frac{1}{4\pi}\, \frac{d\phi}{dt}\, \frac{dt}{ds}. +\end{align*} +The quantity of electricity on a strip of unit depth (the depth +being measured at right angles to the plane of~$x$,~$y$) is equal to +\begin{align*} +\int \sigma ds &= - \frac{1}{4\pi} \int \frac{d\phi}{dt}\, \dfrac{dt}{ds}\,ds \\ + &= - \frac{1}{4\pi} \{ \phi(t_2)-\phi(t_1) \}, +\end{align*} +where $t_1$,~$t_2$ are the values of~$t$ at the beginning and end of the +strip, $t_2$~being algebraically greater than~$t_1$. + +The quantity of electricity on the strip of breadth~$x$ is +equal to +\[ +\frac{1}{4\pi} \{ \phi_t - \phi_0 \}, +\] +%% -----File: 229.png---Folio 215------- +and this by equation~(\eqnref{235}{7}) is equal to +\begin{gather*} +- \frac{1}{4\pi}\, \frac{V}{\pi} \log (t+1) \\ += \frac{V}{4\pi h} \left\{x+\frac{h}{\pi} \right\}. +\end{gather*} + +Thus the quantity of electricity on the lower side of the +plate is the same as if the density were uniform and equal to +that on an infinite plate, the breadth of the strip being increased +by~$h/\pi$. This, however, only represents the electricity on +the lower side of the plate, there is also a considerable quantity +of electricity on the top of the plate. To find an expression for +the quantity of electricity on a strip of breadth~$x$, we notice +that on the top of the plate $t$~ranges from zero to infinity, and +that when $x$~is a large multiple of~$h$, $t$~is very large; in this +case the solution of the equation +\[ +x = \frac{h}{\pi} \{t-\log (1+t)\} +\] +is approximately +\[ +t = \pi \frac{x}{h} + \log \left\{1+ \frac{\pi x}{h} \right\}, +\] +and the quantity of electricity on a strip of breadth~$x$ is +$\dfrac{1}{4\pi} \{ \phi_0 - \phi_t \}$, and thus by equation~(\eqnref{235}{7}) is equal to +\begin{gather*} +\frac{V}{4\pi^2} \log (t+1) \\ += \frac{V}{4\pi^2} \log \left\{1 + \frac{\pi x}{h} + \log \left(1+ \frac{\pi x}{h}\right) \right\}. +\end{gather*} + +Thus the quantity of electricity on an infinitely long strip is +infinite, though its ratio to the quantity of electricity on the +lower side of the strip is infinitely small. + +The surface density $± d\phi/4\pi\, dx$ of the distribution of electricity +on the semi-infinite plate is by equations (\eqnref{235}{6})~and~(\eqnref{235}{7}) equal to +\[ +\mp \frac{V}{4\pi h}\, \frac{1}{t}. +\] +On the underneath side of the plate $t$~is very nearly equal to~$-1$ +when the distance from the edge of the plate is a large multiple +of~$h$, so that in this case the density soon reaches a constant +%% -----File: 230.png---Folio 216------- +value. On the upper side of the plate, however, when $x$~is a +large multiple of~$h$, $t$~is approximately equal to +\[ +\frac{\pi x}{h}, +\] +so that the density varies inversely as the distance from the edge +of the plate. + +The capacity of a breadth~$x$ of the upper plate, i.e.~the ratio +of the charge on both surfaces to~$V$, is +\[ +\frac{x}{4\pi h} \left[1 + \frac{h}{\pi x} + \frac{h}{\pi x} \log \left\{1 + \frac{\pi x}{h} + \log \left(1+ \frac{\pi x}{h}\right) \right\} \right]. +\] + +We see by the principle of images that the distribution of +electricity on the upper plate is the same as would ensue if, +instead of the infinite plate at zero potential, we had another +semi-infinite parallel plate at potential~$-V$, at a distance~$2h$ +below the upper plate, and therefore that in this case the +capacity of a breadth~$x$, when $x/h$~is large, of either plate is +approximately +\[ +\frac{x}{8\pi h} \left[1 + \frac{h}{\pi x} + \frac{h}{\pi x} \log \left\{1 + \frac{\pi x}{h} + \log \left(1+\frac{\pi x}{h}\right) \right\} \right]. +\] + +\Article{236} The next case we shall consider is the one discussed by +\index{Capacity xof a plate between two infinite plates@\subdashone of a plate between two infinite plates}% +Maxwell in Art.~195, in which a semi-infinite conducting plane is +placed midway between two parallel infinite conducting planes, +maintained at zero potential; we shall suppose that the potential +of the semi-infinite plane is~$V$. The diagrams in the $z$~and~$w$ +planes are given in Figs.\ \figureref{fig92}{92}~and~\figureref{fig93}{93} respectively. + +\medskip +\includegraphicsmid{fig92}{Fig.~92.} + +\includegraphicsmid{fig93}{Fig.~93.} + +The boundary of the $z$~diagram consists of the infinite line~\smallsanscap{AB}, +the two sides of the semi-infinite line~\smallsanscap{CD}, and the infinite +%% -----File: 231.png---Folio 217------- +line~\smallsanscap{EF}. We shall assume $t = 0$ at~\smallsanscap{C}, $t = -\infty$ at the point +$x = -\infty$ on the line~\smallsanscap{AB}, $t = -1$ at the point $x = +\infty$ on the same +line, then by symmetry $t = +1$ at the point $x = +\infty$ on the line~\smallsanscap{EF}, +and $t = +\infty$ at the point $x = -\infty$ on the same line. The +internal angles of the polygon are zero at \smallsanscap{B}~and~\smallsanscap{E}, and $2\pi$ at~\smallsanscap{C}, +hence by equation~(\eqnref{231}{1}) the Schwarzian transformation of the +diagram in the $z$~plane to the real axis in the $t$~plane is +\[ +\frac{dz}{dt} = \frac{Ct}{(t+1)(t-1)}. \Tag{8} +\] + +The diagram in the \textit{w}~plane consists of three parallel lines, or +rather one line and the two sides of another; in \figureref{fig93}{Fig.~93} the upper +side of the lower line corresponds to the conductor~\smallsanscap{EF}, the lower +side to the conductor~\smallsanscap{AB}. The internal angles occur at the +points corresponding to $t = -1$ and to $t = +1$ and are both zero; +hence the transformation which turns the diagram in the $w$~plane +to the real axis in the $t$~plane is +\[ +\frac{dw}{dt} = \frac{B}{(t+1)(t-1)}. \Tag{9} +\] + +From~(\eqnref{236}{8}) we have +\[ +z = x+\iota y = \tfrac{1}{2} C \{ \log \{t^2-1\}- \iota \pi \}, \Tag{10} +\] +where the constant of integration has been determined so +as to make $x = 0$, $y = 0$ at~\smallsanscap{C}. When $t$~passes through the +values~$±1$ the value of~$y$ increases by~$-\frac{1}{2} C\pi$, hence if $h$~is the +distance of the semi-infinite plane from either of the two infinite +ones we have +\begin{DPgather*} +-\tfrac{1}{2} C\pi = h, \\ +\lintertext{or} x + \iota y = \frac{h}{\pi} \{\iota \pi - \log (t^2-1)\}. \Tag{11} +\end{DPgather*} + +From equation~(\eqnref{236}{9}) we have +\[ +w = \phi+\iota\psi = \frac{V}{\pi} \log \frac{t-1}{t+1}. \Tag{12} +\] + +From this equation we get +\[ +t^2 - 1 = \frac{4}{ \left(\epsilon^{\frac{1}{2} {\tfrac{\pi}{V}}(\phi+\iota \psi)}-\epsilon^{- \frac{1}{2} \tfrac{\pi}{V} (\phi+\iota\psi)} \right)^2}. +\] +%% -----File: 232.png---Folio 218------- + +Substituting this value of $t^2 - 1$ in~(\eqnref{236}{11}), we get +\begin{align*} +x + \iota y & = \frac{h}{\pi} \left[\iota \pi - 2 \log 2 + 2 \log \left\{\epsilon^{\frac{1}{2} \frac{\pi}{V} (\phi + \iota\psi)} - \epsilon^{-\frac{1}{2} \frac{\pi}{V} (\phi + \iota\psi)}\right\}\right] \\ +& = \frac{h}{\pi} \left[\iota \pi - 2 \log 2 + \log \left\{\epsilon^{\frac{\pi\phi}{V}} + \epsilon^{-\frac{\pi\phi}{V}} - 2 \cos \frac{\pi\psi}{V} \right\}\right. \\ +& \qquad\qquad \left. {} + 2 \iota \tan^{-1} \left\{\frac{\left(\epsilon^{\frac{1}{2} \frac{\pi\phi}{V}} + \epsilon^{-\frac{1}{2} \frac{\pi\phi}{V}}\right)}{\epsilon^{\frac{1}{2} \frac{\pi\phi}{V}} - \epsilon^{-\frac{1}{2} \frac{\pi\phi}{V}}} \tan \frac{\pi\psi}{2V} \right\} \right], +\end{align*} +which is equivalent to the result given in Maxwell, Art.~195. + +The quantity of electricity on a portion whose length is~\smallsanscap{CP} +and breadth unity of the lower side of the plane~\smallsanscap{CD} is +\[ +\frac{1}{4\pi} \left\{\phi_P - \phi_C\right\}. +\] + +Now $\phi_C = 0$, and when \smallsanscap{CP}~is large compared with~$h$, $t$~is very +nearly equal to~$-1$, hence if $\text{\smallsanscap{CP}} = x$ we have in this case +from~(\eqnref{236}{11}) +\[ +x = -\frac{h}{\pi}\{\log 2 + \log (t+1)\}, +\] +and from~(\eqnref{236}{12}) +\begin{DPalign*} +\phi_P &= \frac{V}{\pi} \{\log 2 - \log (t+1)\}, \\ +\lintertext{hence} \phi_P &= \frac{V}{\pi} \left\{2 \log 2 + \frac{\pi x}{h}\right\}, +\end{DPalign*} +and the quantity of electricity on the strip is +\[ +\frac{V}{4\pi h} x \left\{1 + \frac{2h}{\pi x} \log 2\right\}. +\] + +\index{Capacity xof a plate between two infinite plates@\subdashone of a plate between two infinite plates}% +That is, it is the same as if the distribution were uniform and +the same as for two infinite plates with the breadth of the strip +increased by~$\dfrac{2h}{\pi} \log 2$. + +\medskip +\includegraphicsmid{fig94}{Fig.~94.} + +\Article{237} To find the correction for the thickness of the semi-infinite +plate, we shall solve by the Schwarzian method the problem of +a semi-infinite plate of finite thickness and rectangular section +placed midway between two infinite plates. The two infinite +plates are at zero potential, the semi-infinite one at potential~$V$. +%% -----File: 233.png---Folio 219------- +The diagram in the $z$~plane is represented in \figureref{fig94}{Fig.~94}. The +boundary consists of the infinite line~\smallsanscap{AB}, the semi-infinite line~\smallsanscap{CD}, +the finite line~\smallsanscap{CE}, the semi-infinite line~\smallsanscap{EF} and the infinite +line~\smallsanscap{GH}. We shall assume $t = -\infty$ at the point on the +line~\smallsanscap{AB} where $x$~is equal to~$-\infty, t = -1$ at the point on the +same line where $x = + \infty: t = -a$ at~\smallsanscap{C} $(a < 1)$, $t = +a$ at~\smallsanscap{E}, +$t = + 1$ at the point on the line~\smallsanscap{GH} where $x = + \infty$ and $t = +\infty$ +at the point on the same line where $x = -\infty$. The internal +angles of the polygon are +\[ +0 \text{ when } t = ±1,\ \frac{3\pi}{2} \text{ when } t = ±a, +\] +hence the transformation which transforms the boundary of the +$z$~diagram into the real axis of the $t$~plane is +\begin{align*} +\frac{dz}{dt} &= \frac{C(t+a)^{\frac{1}{2}} (t-a)^{\frac{1}{2}}}{(t+1)(t-1)} \\ + &= \frac{C(t^2-a^2)^{\frac{1}{2}}}{t^2-1} \\ + &= \frac{C}{\{t^2-a^2\}^{\frac{1}{2}}} + \tfrac{1}{2} C (1-a^2) \frac{1}{\{t^2-a^2 \}^{\frac{1}{2}}} \left\{\frac{1}{t-1} - \frac{1}{t+1} \right\}. \Tag{13} +\end{align*} + +The first term on the right-hand side is integrable, and the +second and third become integrable by the substitutions $u = 1/t-1$ +and $u = 1/t+1$ respectively. Integrating~(\eqnref{237}{13}) we find \\ +\begin{align*} +z&=C \log \{t+\sqrt{t^2-a^2}\}-C \log \sqrt{-a^2} \\ +&\qquad {}+ \tfrac{1}{2} (1-a^2)^{\frac{1}{2}} C \log \left[ \frac{(t-a^2-\sqrt{1-a^2} \sqrt{t^2-\DPtypo{a}{a^2}})(t+1)}{(t+a^2+\sqrt{1-a^2} \sqrt{t^2-a^2}) (t-1)} \right] , \Tag{14} +\end{align*} +where the constant has been chosen so as to make both $x$~and~$y$ +vanish when $t = 0$. + +If $2h$~is the thickness of the semi-infinite plate and $2H$~the +distance between the infinite plates, then when $t$~passes through +%% -----File: 234.png---Folio 220------- +the value unity $y$~increases by $H - h$. When $t$~is nearly unity +we may put +\[ +t = 1 + R\DPtypo{\iota}{\epsilon}^{\iota\theta}, +\] +where $R$~is small, and $\theta$~changes from~$\pi$ to zero as $t$~passes through +unity. When $t$~is approximately~$1$, equation~(\eqnref{237}{13}) becomes +\[ +\frac{dz}{dt} = \tfrac{1}{2} C (1 - a^2)^{\frac{1}{2}} \frac{1}{t-1}, +\] +hence the increase in~$z$ as $t$~passes through~$1$ is +\begin{align*} +& \tfrac{1}{2} C (1 - a^2)^{\frac{1}{2}} \left[\log R + \iota\theta \right]_\pi^0 \\ +& = - \frac{\iota\pi}{2} C (1 - a^2)^{\frac{1}{2}}, +\end{align*} +but since the increase in~$z$ when $t$~passes through this value is +$\iota (H - h)$, we have +\[ +H - h = - C \frac{\pi}{2} (1 - a^2)^{\frac{1}{2}}. +\] + +When $t$~changes from~$+ \infty$ to~$- \infty$, $z$~diminishes by~$\iota 2 H$; but +when $t$~is very large, equation~(\eqnref{237}{13}) becomes +\begin{DPalign*} +\frac{dz}{dt} & = \frac{C}{t}, \\ +z & = C \log t. \\ +\lintertext{Now} t & = R \epsilon^{\iota\theta}, +\end{DPalign*} +where $R$~is infinite, and $\theta$~changes from~$0$ to~$\pi$ as $t$~changes from +$+ \infty$ to~$- \infty$; but as $t$~changes from plus to minus infinity, $z$~increases +by +\begin{gather*} +C \left[\log R + \iota\theta\right]_0^\pi \\ += \iota C \pi, +\end{gather*} +and since the \emph{diminution} in~$z$ is~$\iota 2 H$, we have +\begin{DPgather*} +H = -C \frac{\pi}{2}. \\ +\lintertext{Thus} h = H \{1 - \sqrt{1-a^2}\}, \\ +\lintertext{or} a = \sqrt{\frac{h (2H - h)}{H^2}}. +\end{DPgather*} +%% -----File: 235.png---Folio 221------- + +The diagram in the $w$~plane is the same as in \artref{236}{Art.~236}, hence +we have +\[ +\phi+\iota\psi = \frac{V}{\pi} \log\frac{t-1}{t+1}. \Tag{15} +\] + +The quantity of electricity on the portion of the semi-infinite +plate between~$O$, the point midway between $C$~and~$E$, and~$P$ a +point on the upper surface of the boundary, is +\[ +\frac{1}{4\pi} \{\phi_O - \phi_P\}. +\] + +Now at $O$, $t=0$, hence $\phi_O=0$, and if $EP$~is large compared +with~$H$, $t$~at~\DPtypo{\smallbold{P}}{$P$} is approximately equal to~$1$. In this case we +find from~(\eqnref{237}{14}), writing $EP=x$, +\begin{multline*} +x = C \log \left\{\frac{1+\sqrt{1-a^2}}{a}\right\} + \tfrac{1}{2} C \{1-a^2\}^{\frac{1}{2}} \log \frac{a^2}{2(1-a^2)} \\ +{} + \tfrac{1}{2} C \{1-a^2\}^\frac{1}{2} \log{(t-1)}. +\end{multline*} + +Substituting for $C$~and~$a$ their values in terms of $H$~and~$h$ +we get +\begin{multline*} +-\log{(t-1)} = \frac{\pi}{H-h} \left\{x + \frac{H}{\pi} \log \frac{2H-h}{h}\right. \\ +\left.{} + \frac{H-h}{\pi} \log{\frac{h(2H-h)}{2(H-h)^2}}\right\}. \Tag{16} +\end{multline*} + +But from equation~(\eqnref{237}{15}) +\[ +\phi_P = \frac{V}{\pi} \{\log(t-1) - \log2\}, +\] +since $t$~at~$P$ is approximately equal to~$1$. Hence the quantity +of electricity on the strip~$OP$ is +\[ +\frac{V}{4\pi\{H-h\}} \left\{x + \frac{H}{\pi} \log{\frac{2H-h}{h}} + \frac{H-h}{\pi} \log \frac{h(2H-h)}{(H-h)^2} \right\}. +\] +Thus the breadth of the strip, which must be added to allow for +the concentration of the electricity near the boundary, is +\[ +\frac{H}{\pi} \log \frac{2H-h}{h} + \frac{H-h}{\pi} \log \frac{h(2H-h)}{(H-h)^2}. +\] +If $h$~is very small this reduces to +\[ +\frac{2H}{\pi} \log{2}, +\] +which was the result obtained in \artref{236}{Art.~236}. +%% -----File: 236.png---Folio 222------- + +The density of the electricity at the point~$x$ on the top of +the semi-infinite plate is $-\dfrac{1}{4\pi}\, \dfrac{d\phi}{dx}$, now +\begin{align*} +\frac{d\phi}{dx} &= \frac{d\phi}{dt}\, \frac{dt}{dx} \\ + &= \frac{2V}{\pi(t+1)(t-1)} \frac{(t+1)(t-1)}{C(t^2-a^2)^{\frac{1}{2}}} \\ + &= \frac{V}{\pi C}\, \frac{2}{(t^2-a^2)^{\frac{1}{2}}} \\ + &= -\frac{V}{H}\, \frac{1}{(t^2-a^2)^{\frac{1}{2}}}. +\end{align*} +Hence the density of the electricity on the plate is +\[ +\frac{V}{4\pi H}\, \frac{1}{(t^2-a^2)^{\frac{1}{2}}}. +\] + +This is infinite at the edges $C$~and~$E$. When $EP$~is a large +multiple of~$H$, $t=1$ approximately, and the density is +\begin{DPgather*} +\frac{V}{4\pi H}\, \frac{1}{\{1-a^2\}^{\frac{1}{2}}}, \\ +\lintertext{or since} (1-a^2)^{\frac{1}{2}}=\frac{H-h}{H}, +\end{DPgather*} +the density is uniform and equal to +\[ +\frac{1}{4\pi}\, \frac{V}{H-h}. +\] + +\Article{238} Condensers are sometimes made by placing one cube +\index{Capacity xof one cube inside another@\subdashone of one cube inside another}% +inside another; in order to find the capacity of a condenser of +this kind we shall investigate +the distribution of electricity on +a system of conductors such as +that represented in \figureref{fig95}{Fig.~95}, +where \smallsanscap{ABC}~is maintained at zero +potential and \smallsanscap{FED}~at potential~$V$. + +\includegraphicsouter{fig95}{Fig.~95.} + +The diagram in the $z$~plane +is bounded by the lines \smallsanscap{AB},~\smallsanscap{BC}, +\smallsanscap{DE},~\smallsanscap{EF}; we shall assume that +$t=-\infty$ at the point on the line~\smallsanscap{AB} +where $y=+\infty, t=0$ at~\smallsanscap{B}, $t=1$ at the point on~\smallsanscap{BC} where +%% -----File: 237.png---Folio 223------- +$x=+\infty$, and $t=a$ at~\smallsanscap{E}, where $a$~is a quantity greater than unity +which has to be determined by the geometry of the system. The +internal angles of the polygon in the $z$~plane are $\pi/2$ at~\smallsanscap{B}, zero +at~\smallsanscap{C}, $3\pi/2$ at~\smallsanscap{E}. The transformation which turns the boundary +of the $z$~polygon into the real axis in the $t$~plane is by equation~(\eqnref{231}{1}) +expressed by the equation +\[ +\frac{dz}{dt} = \frac{C(a-t)^{\frac{1}{2}}}{t^{\frac{1}{2}} (1-t)}. \Tag{17} +\] + +The diagram in the $w$~plane consists of the real axis and a line +parallel to it. The internal angle of the polygon is at $t=1$ and +is equal to zero, hence the transformation which turns this +diagram into the real axis of~$t$ is +\begin{DPgather*} +\frac{dw}{dt} = \frac{B}{1-t}, \\ +\lintertext{or} \phi + \iota\psi = \iota V - \frac{V}{\pi} \log(1-t), +\end{DPgather*} +since $V$ is the increment in~$\psi$ when $t$~passes through the +value~$1$. + +To integrate~(\eqnref{238}{17}) put +\[ +t = a\, \frac{u^2}{1+u^2}. +\] + +We have then +\begin{align*} +\frac{dz}{du} &= \frac{2Ca}{(1+u^2) \{1-(a-1)u^2\} } \\ + &= 2C\left\{\frac{1}{1+u^2} + \frac{a-1}{1-(a-1)u^2} \right\}. +\end{align*} + +Hence +\begin{align*} +z &= 2C \tan^{-1}u + \sqrt{a-1} C \log \left(\frac{1+\sqrt{a-1}u}{1-\sqrt{a-1} u} \right) \\ + &= 2C \sin^{-1} \sqrt{\frac{t}{a}} + \sqrt{a-1} C \log \left\{\frac{\sqrt{a-t} + \sqrt{a-1} \surd t}{\sqrt{a-t} - \sqrt{a-1} \surd t} \right\}, \Tag{18} +\end{align*} +where the constants have been chosen so as to make $x$~and~$y$ +vanish when $t=0$. + +When $t=a$, we have +\[ +x + \iota y = C\pi + \sqrt{a-1} C\iota \pi. +\] +%% -----File: 238.png---Folio 224------- + +Hence if $h$~and~$k$ are the coordinates of~$E$ referred to the axes +\smallsanscap{BC},~\smallsanscap{AB}, we have +\begin{align*} +h & = C \pi, \\ +k & = C \sqrt{a-1} \pi. +\end{align*} + +We can also deduce these equations from equation~(\eqnref{238}{17}) by the +process used to determine the constants in \artref{237}{Art.~237}. + +We may write~(\eqnref{238}{18}) in the form +\[ +x+\iota y = \frac{2h}{\pi} \sin^{-1} \sqrt{\frac{t}{a}} + \frac{k}{\pi} \log \left\{\frac{(\sqrt{a-t} + \sqrt{a-1} \surd{t})^2}{a(1-t)} \right\}. \Tag{19} +\] + +The quantity of electricity on the strip~\smallsanscap{BP}, where \smallsanscap{P}~is a point +on~\smallsanscap{BC}, is equal to +\begin{gather*} +-\frac{1}{4\pi}\{\phi_P-\phi_B\} \\ +=\frac{1}{4\pi}\, \frac{V}{\pi} \log(1-t_P). +\end{gather*} + +Now if \smallsanscap{BP}~is large compared with~$k$, the value of~$t$ at~$P$ is +approximately unity; from~(\eqnref{238}{19}) we get the more accurate value +\begin{align*} +-\log(1-t) &= \frac{\pi}{k} x - \frac{2h}{k} \sin^{-1} \sqrt{\frac{1}{a}} -2\log \left\{2 \sqrt{\frac{a-1}{a}} \right\}, \\ + &= \pi \frac{x}{k} - \frac{2h}{k} \tan^{-1} \frac{h}{k} - 2\log \frac{2k}{\sqrt{h^2+k^2}}. +\end{align*} + +Hence the quantity of electricity on the strip is +\[ +-\frac{V}{4\pi k} \left\{x - \frac{2h}{\pi} \tan^{-1} \frac{h}{k} + \frac{2k}{\pi} \log \frac{\sqrt{h^2+k^2}}{2k}\right\}. +\] + +Hence the quantity is the same as if the electricity were distributed +with the uniform density $-V/4\pi k$ over a strip whose +breadth was less than~\smallsanscap{BP} by +\[ +\frac{2h}{\pi} \tan^{-1} \frac{h}{k} - \frac{2k}{\pi} \log \frac{\sqrt{h^2+k^2}}{2k}. +\] + +In the important case when $h=k$, this becomes +\[ +\frac{h}{2} + \frac{h}{\pi} \log 2. +\] +%% -----File: 239.png---Folio 225------- + +The surface density of the electricity at any point on~\smallsanscap{BC} or~\smallsanscap{ED} +is +\[ +\mp \frac{V}{4\pi^2C} \sqrt{\frac{t}{a-t}}, +\] +the $-$~or~$+$ sign being taken according as the point is on~\smallsanscap{BC} +or~\smallsanscap{ED}. This expression vanishes at~\smallsanscap{B} and is infinite at~\smallsanscap{E}. + +At~\smallsanscap{P}, a point on~\smallsanscap{BC} at some distance from~\smallsanscap{B}, $t$~is approximately +unity, so that the surface density is +\begin{gather*} +-\frac{V}{4\pi^2C\sqrt{a-1}} \\ += -\frac{V}{4\pi k}. +\end{gather*} + +This result is of course obvious, but it may be regarded as +affording a verification of the preceding solution. + +\includegraphicsmid{fig96}{Fig.~96.} + +\Article{239} Another case of some interest is that represented in +\figureref{fig96}{Fig.~96}, where we have an infinite plane~\smallsanscap{AB} at potential~$V$ in presence +of a conductor at zero potential bounded by two semi-infinite +planes \smallsanscap{CD},~\smallsanscap{DE} at right angles to each other. The diagram in the +$z$~plane is bounded by the lines~\smallsanscap{AB}, \smallsanscap{CD},~\smallsanscap{DE} and a quadrant of a +circle whose radius is infinite. We shall assume $t=-\infty$ at the +point on the line~\smallsanscap{AB} where $x=-\infty$, $t=0$ at the point on the +same line where $x=+\infty$, $t=1$ at~\smallsanscap{D}. The internal angles of the +polygon in the $z$~plane are zero at~\smallsanscap{B} and $3\pi/2$ at~\smallsanscap{D}. The transformation +%% -----File: 240.png---Folio 226------- +which turns the boundary of the $z$~polygon into the +real axis in the $t$~plane is therefore, by equation~(\eqnref{231}{1}), +\[ +\frac{dz}{dt} = \frac{C(1-t)^{\frac{1}{2}}}{t}. \Tag{20} +\] + +The diagram in the $w$~plane consists of two straight lines +parallel to the real axis, the internal angle being zero at the +point~$t=0$; hence we have +\[ +w = \phi + \iota\psi = \frac{V}{\pi} \log t, +\] +since the plane~\smallsanscap{AB} is at potential~$V$ and~\smallsanscap{CDE} at potential zero. + +Integrating equation~(\eqnref{239}{20}), we find when \DPtypo{$t > 0<,1$}{$0 < t < 1$,} +\[ +z=x+\iota y=C\left(2\sqrt{1-t} - \log \frac{1+\sqrt{1-t}}{1-\sqrt{1-t}}\right), \Tag{21} +\] +where no constant of integration is needed if the origin of +coordinates is taken at~\smallsanscap{D} where $t=+1$. If $h$~is the distance +between \smallsanscap{CD}~and~\smallsanscap{AB}, then $z$~increases by~$\iota h$ when $t$~changes sign, +hence we have by equation~(\eqnref{239}{20}), by the process similar to that +by which we deduced the constant in \artref{237}{Art.~\DPtypo{(237)}{237}}, +\[ +h = -C\pi; +\] +so that (\eqnref{239}{21})~becomes, $0<t<1$, +\[ +x+\iota y=\frac{h}{\pi} \left\{\log \frac{1+\sqrt{1-t}}{1-\sqrt{1-t}} - 2\sqrt{1-t} \right\}. \Tag{22} +\] + +The quantity of electricity on a strip~\smallsanscap{DP} where~\smallsanscap{P} is a point +on~\smallsanscap{DC} is +\[ +\frac{V}{4\pi^2} \log t_P, +\] +if $t_P$ is the value of~$t$ at~\smallsanscap{P}. If \smallsanscap{DP}~is large compared with~$h$, +$t_P$~will be very nearly zero; the value of~$\log t_P$ is then readily +got by writing~(\eqnref{239}{22}) in the form +\[ +x+\iota y = \frac{h}{\pi} \{2 \log (1 + \sqrt{1-t})- \log t-2 \sqrt{1-t}\}. +\] + +So that if $x=\text{\smallsanscap{DP}}$, we have approximately, +\begin{align*} +-\log t_P &= \frac{\pi}{h} \left\{x - \frac{2h}{\pi} \log 2 + \frac{2h}{\pi} \right\}, \\ + &= \frac{\pi}{h} \left\{x + \frac{2h}{\pi} (1-\log 2) \right\}. +\end{align*} +%% -----File: 241.png---Folio 227------- + +Thus the quantity of electricity on~\smallsanscap{DP} is +\[ +-\frac{V}{4\pi h} \left\{x + \frac{2h}{\pi}(1- \log 2) \right\}. +\] + +We can prove in a similar way that if \smallsanscap{Q} is a point on~\smallsanscap{DE} the +charge on~\smallsanscap{DQ} is equal to +\[ +\frac{V}{2\pi^2} \log \left(\frac{\pi \smallbold{DQ}}{2h}\right). +\] + +\Article{240} If the angle~\smallsanscap{CDE}, instead of being equal to~$\pi/2$, were +equal to~$\pi/n$, the transformation of the diagram in the $z$~plane to +the real axis of~$t$ could be effected by the relation +\[ +\frac{dz}{dt} = \frac{C(t-1)^{\frac{n-1}{n}}}{t}. +\] + +\Article{241} We shall now proceed to discuss a problem which enables us +\index{Guard-ring, distribution of electricity on}% +to estimate the effect produced by the slit between the guard-ring +and the plate of a condenser on the capacity of the condenser. + +\includegraphicsmid{fig97}{Fig.~97.} + +\includegraphicsmid{fig98}{Fig.~98.} + +When the plate and the guard-ring are of finite thickness the +integration of the differential equation between $z$~and~$t$ involves +the use of Elliptic Functions. In the two limiting cases when the +thickness of the plate is infinitely small or infinitely great, the +necessary integrations can however be effected by simpler means. + +We shall begin with the case where the thickness of the plate +is very small, and consider the distribution of electricity on two +semi-infinite plates separated by a finite interval~$2k$ and placed +parallel to an infinite plane at the distance~$h$ from it. + +We shall suppose that the two semi-infinite plates are at +the same potential~$V$, and that the infinite plate is at potential +zero. The diagrams in the $z$~and $w$~planes are represented in +Figs.\ \figureref{fig97}{97}~and~\figureref{fig98}{98}. +%% -----File: 242.png---Folio 228------- + +The diagram in the $z$~plane is bounded by the infinite straight +line~\smallsanscap{ED}, the two sides \smallsanscap{AB}~and~\smallsanscap{BC} of the semi-infinite line on +the right, the two sides \smallsanscap{FG},~\smallsanscap{GH} of the semi-infinite line on +the left, and a semi-circle of infinite radius. A point traversing +the straight portion of the boundary might start from~\smallsanscap{A} and +travel to~\smallsanscap{B} on the upper side of the line on the right, then from +\smallsanscap{B} to~\smallsanscap{C} along the under side, from~\smallsanscap{D} to~\smallsanscap{E} along the infinite +straight line, from~\smallsanscap{F} to~\smallsanscap{G} on the under side of the line on the +left and from~\smallsanscap{G} to~\smallsanscap{H} on the upper side of this line. We shall +suppose that $t = +\infty$ at~\smallsanscap{A}, $t = +1$ at~\smallsanscap{B}, $t = +a$ ($a<1$) at~\smallsanscap{C}, +$t = -a$ at~\smallsanscap{F}, $t = -1$ at~\smallsanscap{G}, $t = -\infty$ at~\smallsanscap{H}. The internal angles of +the polygon in the $z$~plane are $2\pi$ at~\smallsanscap{B}, zero at~\smallsanscap{C}, zero at~\smallsanscap{F}, and +$2\pi$ at~\smallsanscap{G}; hence the transformation which turns the diagram in +the $z$~plane into the real axis of~$t$ is expressed by the relation +\[ +\frac{dz}{dt} = C \frac{t^2 - 1}{t^2 - a^2}. \Tag{23} +\] + +The diagram in the $w$~plane consists of two straight lines +parallel to the real axis and the potential changes by~$V$ when~$t$ +passes through the values $±a$: hence we easily find +\[ +\phi + \iota\psi = \frac{V}{\pi} \log \frac{t+a}{t-a} + \iota V. \Tag{24} +\] + +We have from equation~(\eqnref{241}{23}) +\[ +z = C \left\{t-\frac{(1-a^2)}{2a} \log \frac{t-a}{t+a} + \frac{(1-a^2)}{2a} \iota\pi \right\}, \Tag{25} +\] +where the constant of integration has been chosen so as to make +$x = 0$, $y = 0$ when $t = 0$. The axis of~$x$ is~\smallsanscap{ED}, the axis of~$y$ +the line at right angles to this passing through the middle +of~\smallsanscap{GB}. + +If $2k$ is the width of the gap and $h$~the vertical distance +between the plates, $x = k$, $y = h$, when $t = 1$, hence we have +by~(\eqnref{241}{25})\ +\begin{align*} +k &= C \left\{1- \frac{(1-a^2)}{2a} \log \frac{1-a}{1+a} \right\}, \\ +h &= C \frac{(1-a^2)}{2a} \pi. +\end{align*} + +Hence $a$ is determined by the equation +\[ +k = \frac{h}{\pi} \left\{\frac{2a}{1-a^2} + \log \frac{1+a}{1-a}\right\}. \Tag{26} +\] +%% -----File: 243.png---Folio 229------- + +The quantity of electricity on the lower side of the semi-infinite +plate between \smallsanscap{B}~and~\smallsanscap{P} is, since $t$~increases from~\smallsanscap{P} to~\smallsanscap{B}, +\[ +\frac{1}{4\pi} \{\phi_P - \phi_B\}, +\] +or by~(\eqnref{241}{24}) +\[ +\frac{V}{4\pi^2} \left\{\log \frac{t_P+a}{t_P-a} - \log \frac{1+a}{1-a}\right\}. +\] + +But by~(\eqnref{241}{25}) if $\text{\smallsanscap{BP}} = x - k$, we have +\[ +x - k = C \left[ t_P - 1 - \frac{1-a^2}{2a} \left\{\log \frac{t_P-a}{t_P+a} - \log \frac{1-a}{1+a} \right\} \right]. +\] + +Hence if $Q$ is the quantity of electricity on the lower side of +the plate between \smallsanscap{B}~and~\smallsanscap{P}, +\begin{gather*} +x - k = C(t_P-1) + \frac{4\pi h}{V} \centerdot Q, \\ +Q = \frac{V}{4\pi h} \{x - k + C(1-t_P)\}, +\end{gather*} +or since $t_P = a$ approximately, if \smallsanscap{P}~is a considerable distance +from~\smallsanscap{B}, we have +\[ +Q = \frac{V}{4\pi h} \{x - k + C(1-a)\}. \Tag{27} +\] + +The quantity of electricity~$Q_1$ on the upper side of the plate, +from~\smallsanscap{A} to~\smallsanscap{B}, is equal to +\[ +\frac{1}{4\pi}(\phi_B - \phi_A), +\] +or since $t = +\infty$ at~\smallsanscap{A}, and therefore $\phi_A$~vanishes, we have +\[ +Q_1 = - \frac{V}{4\pi^2} \log \frac{1-a}{1+a}. \Tag{28} +\] + +We can by equation~(\eqnref{241}{26}) easily express $a$ in terms of~$k/h$, when +this ratio is either very small or very large. We shall begin by +considering the first case, which is the one that most frequently +occurs in practice. + +We see from~(\eqnref{241}{26}) that when $k/h$ is very small, $a$~is very small +and is approximately equal to +\[ +\frac{\pi}{4}\, \frac{k}{h}. +\] +%% -----File: 244.png---Folio 230------- +The corresponding value of~$C$ is~$\frac{1}{2}k$, hence, neglecting~$(k/h)^3$, +\begin{align*} +Q &= \frac{V}{4\pi h} \left\{x - \tfrac{1}{2}k - \frac{\pi}{8}\, \frac{k^2}{h} \right\}, \\ +Q_1 &= \frac{V}{4\pi^2}\, 2a \\ + &= \frac{V}{4\pi h}\, \frac{k}{2}. +\end{align*} + +Hence $Q + Q_1$, the whole quantity of electricity between \smallsanscap{A}~and~\smallsanscap{P}, +is approximately equal to +\[ +\frac{V}{4\pi h} \left\{x - \frac{\pi}{8}\, \frac{k^2}{h} \right\}. +\] + +Hence the quantity of electricity on the plate of the condenser +is to the present degree of approximation the same as if the +electricity were uniformly distributed over the plate with +the density it would have if the slit were absent, provided +that the area of the plate is increased by that of a strip whose +width is +\[ +k - \frac{\pi}{8}\, \frac{k^2}{h}; +\] +thus the breadth of the additional strip is very approximately +half that of the slit. + +We pass on now to the case when $h/k$~is very small. We see +from equation~(\eqnref{241}{26}) that in this case $a$~is very nearly equal to +unity, the approximate values of $a$~and~$C$ being given by the +equations +\begin{align*} +1 - a &= \frac{h}{\pi k}, \\ +C &= k. +\end{align*} + +Hence by equations (\eqnref{241}{27})~and~(\eqnref{241}{28}) we have +\begin{align*} +Q &= \frac{V}{4\pi h} \left\{x - k + \frac{h}{\pi} \right\}, \\ +Q_1 &= \frac{V}{4\pi^2} \log \frac{2\pi k}{h}. +\end{align*} + +So that the total charge $Q + Q_1$ on~\smallsanscap{AP} is equal to +\[ +\frac{V}{4\pi h} \left[ x - k + \frac{h}{\pi} \left\{1 + \log \frac{2\pi k}{h} \right\} \right], +\] +%% -----File: 245.png---Folio 231------- +\index{Guard-ring, distribution of electricity on}% +and thus the width of the additional strip is +\[ +\frac{h}{\pi} \left\{1 + \log {\frac{2\pi k}{h}} \right\}. +\] + +\Article{242} We have hitherto supposed that the potentials of the +plates \smallsanscap{ABC} and~\smallsanscap{FGH} are the same; we can however easily +modify the investigation so as to give the solution of the case +when \smallsanscap{ABC}~is maintained at the potential~$V_1$ and~\smallsanscap{FGH} at the +potential~$V_2$. The relation between $z$~and~$t$ will not be affected +by this change, but the relation between $w$~and~$t$ will now be +represented by the equation +\[ +\phi+ \iota\psi = \frac{V_2}{\pi} \log(t+a) - \frac{V_1}{\pi} \log(t-a) + \iota V_1. +\] + +The quantity of electricity between \smallsanscap{B}~and~\smallsanscap{P}, a point on the +lower side of the plate, is +\[ +\frac{1}{4\pi} \{\phi_P - \phi_B\}. +\] + +Now if \smallsanscap{BP}~is large, $t$~at~\smallsanscap{P} is approximately equal to~$a$, and +\[ +\phi_P = \frac{V_2}{\pi} \log 2a - \frac{V_1}{\pi} \log(t-a); +\] +but by equation~(\eqnref{241}{25}) we have when~$t$ is nearly equal to~$a$, +\begin{DPgather*} +-\log (t-a) = \frac{\pi}{h} (x-Ca) - \log 2a, \\ +\lintertext{hence} \phi_P = \frac{V_2 - V_1}{\pi} \log 2a + \frac{V_1}{h} (x-Ca). +\end{DPgather*} + +When $h/k$ is large $a$~is small and approximately equal to~$\pi k/4h$, +and this equation becomes +\[ +\phi_P = \frac{V_2 - V_1}{\pi} \log \frac{\pi k}{2h} + \frac{V_1}{h}\, x. +\] + +Since $t = 1$ at~\smallsanscap{B} and $a$~is small, we see that $\phi_B$~is approximately +equal to $a(V_1 + V_2)/\pi$ or $(V_1 + V_2)k/4h$, hence the quantity +of electricity between \smallsanscap{B}~and~\smallsanscap{P} is approximately equal to +\[ +\frac{V_1}{4\pi h}\, x - \frac{V_2-V_1}{4\pi^2} \log \frac{2h}{\pi k} - \frac{V_1+V_2}{4\pi h}\, \frac{k}{4}. +\] + +The charge~$Q_1$ on the upper side of the plate~\smallsanscap{ABC} between a +%% -----File: 246.png---Folio 232------- +point~$\text{\smallsanscap{P}}'$ vertically above~\smallsanscap{P} and \smallsanscap{B}~is, since $t$~increases from~\smallsanscap{B} to~$\text{\smallsanscap{P}}'$, +equal to +\begin{DPgather*} +\frac{1}{4\pi}\{\phi_B - \phi_{P'}\}. \\ +\lintertext{Now} \phi_{P'} = \frac{V_2}{\pi}\log (t_{P'}+ a) - \frac{V_1}{\pi}\log (t_{P'}-a), +\end{DPgather*} +which, since $t_{P'}$~is large, may be written as +\[ +\phi_{P'} = \frac{V_2 - V_1}{\pi}\log t_{P'}. +\] + +When $\text{\smallsanscap{BP}}'$~is large, $t_{P'}$~is large also, and by equation~(\eqnref{241}{25}) is +approximately equal to~$x/C$, that is to~$2x/k$, thus +\begin{align*} +\phi_{P'} = \frac{V_2 - V_1}{\pi}\log \frac{2x}{k}, \\ +\phi_B = (V_1 + V_2)\, \frac{k}{4h}; +\end{align*} +and therefore $Q_1$, the charge on the upper part of the plate, is +given by the equation +\[ +Q_1 = \frac{(V_1 + V_2)}{4\pi}\, \frac{k}{4h} - \frac{(V_2 - V_1)}{4\pi^2}\log \frac{2x}{k}; +\] +thus $Q + Q_1$, the sum of the charges on the upper and lower +portions, is given by the equation +\[ +Q+Q_1=\frac{V_1}{4 \pi h}\, x -\frac{(V_2-V_1)}{4 \pi^2}\left\{\log \frac{2h}{\pi k} + \log \frac{2x}{k}\right\}. +\] + +\medskip +\includegraphicsmid{fig99}{Fig.~99.} + +\Article{243} We shall now proceed to discuss the other extreme case +\index{Guard-ring, distribution of electricity on}% +of the guard-ring, that in which the depth of the slit is infinite. +We shall begin with the case when the guard-ring and the condenser +plate are at the same potential. The diagram in the $w$~plane +is the same as that in \artref{239}{Art.~239}, while the diagram in the +$z$~plane is represented in \figureref{fig99}{Fig.~99}. The boundary of this +diagram consists of the semi-infinite lines \smallsanscap{AB},~\smallsanscap{BC} at right +angles to each other, the infinite line~\smallsanscap{DE} parallel to~\smallsanscap{BC}, the +semi-infinite line~\smallsanscap{FG} which is in the same straight line as~\smallsanscap{BC}, +and the semi-infinite line~\smallsanscap{GH} at right angles to~\smallsanscap{FG}. We shall +suppose $t = + \infty$ at~\smallsanscap{A}, $t = +1$ at~\smallsanscap{B}, $t = + a$ ($a < 1$) at~\smallsanscap{C}, $t = -a$ +%% -----File: 247.png---Folio 233------- +at~\smallsanscap{F}, $t = -1$ at~\smallsanscap{G}, and $t = - \infty$ at~\smallsanscap{H}. The internal angles of the +polygon in the $z$~plane are $3\pi/2$ at~\smallsanscap{B} and~\smallsanscap{G} and zero at~\smallsanscap{C} and~\smallsanscap{F}. +Thus the transformation which turns the boundary in the $z$~plane +into the real axis of the $t$~plane is expressed by the equation +\[ +\frac{dz}{dt} = C \frac{(t_2 - 1)^{\frac{1}{2}}}{t^2-a^2}. +\] + +If we are dealing with the portion of the boundary for which +$t$~is less than unity, it is more convenient to write this equation +as +\begin{align*} +\frac{dz}{dt} & = C \iota \frac{(1-t^2)^{\frac{1}{2}}}{t^2-a^2} \\ + & = C \iota \left[\frac{1-a^2}{2a}\, \frac{1}{(1-t^2)^{\frac{1}{2}}} \left\{\frac{1}{t-a} - \frac{1}{t+a}\right\}-\frac{1}{(1-t^2)^{\frac{1}{2}}} \right]. +\end{align*} + +Integrating, we find +\begin{multline*} +z=-C\iota\left[\frac{\sqrt{1-a^2}}{2a}\log\frac{(1-at+\sqrt{1-a^2}\sqrt{1-t^2})}{(1+at+\sqrt{1-a^2}\sqrt{1-t^2})}\, \frac{(t+a)}{(t-a)} +\sin^{-1} t\right]\\ + +C \pi\frac{\sqrt{1-a^2}}{2a}, +\end{multline*} +where the constant of integration has been chosen so as to +make $x = 0$, $y = 0$ when $t = 0$; \smallsanscap{ED}~is the axis of~$x$, and the axis +of~$y$ is midway between \smallsanscap{AB}~and~\smallsanscap{GH}. Writing~$D$ for~$-C\iota$, the +preceding equation takes the form +\begin{multline*} +z=D \sin^{-1}t +D\frac{\sqrt{1-a^2}}{2a}\log \frac{(1-at+\sqrt{1-a^2} \sqrt{1-t^2})}{(1+at+\sqrt{1-a^2} \sqrt{1-t^2})}\, \frac{(t+a)}{(t-a)}\\ + +D\iota\pi\, \frac{\sqrt{1-a^2}}{2a}. +\Tag{29} +\end{multline*} +%% -----File: 248.png---Folio 234------- + +Now if $2k$ is the width of the slit, and $h$ the distance of the +plate of the condenser from the infinite plate, $x = k$, $y = h$ when +$t = 1$, hence from~(\eqnref{243}{29}) +\begin{DPalign*} +k &= D \frac{\pi}{2},\\ +h &= D \frac{\pi}{2}\, \frac{\sqrt{1 - a^2}}{a},\\ +\lintertext{or} a^2 &= \frac{k^2}{h^2 + k^2}. +\end{DPalign*} + +The relation between $w$~and~$t$ is the same as in \artref{239}{Art.~239}, and +we have +\[ +w = \phi + \iota \psi = \frac{V}{\pi}\log(t + a) - \frac{V}{\pi}\log(t - a) + \iota V. +\] + +The quantity of electricity~$Q$ on the plate of the condenser +between $\smallsanscap{A}$~and~$\smallsanscap{P}$, a point on~$\smallsanscap{BC}$ at some considerable distance +from~$\smallsanscap{B}$, is +\[ +\frac{1}{4 \pi} \{\phi_P - \phi_A\}; +\] +since $t$ is infinite at the point corresponding to~$\smallsanscap{A}$, we see that $\phi_A$ +is zero, hence +\begin{align*} +Q &= \frac{1}{4 \pi} \phi_P\\ +&= \frac{V}{4 \pi^2} \log \frac{(t_P + a)}{(t_P - a)}. +\end{align*} +Now the point~\smallsanscap{P} corresponds to a point in the $t$~plane where $t$~is +very nearly equal to~$a$; hence we have approximately by~(\eqnref{243}{29}) +\begin{DPgather*} +\begin{aligned} +\log \frac{t_P + a}{t_P - a} &= \frac{\pi}{h} \left( x - D \sin^{-1} a -\frac{h}{\pi} \log (1 - a^2) \right)\\ +&=\frac{\pi}{h} \left( x - \frac{2k}{\pi} \sin^{-1} \frac{k}{\sqrt{h^2 + k^2}} - \frac{h}{\pi} \log \frac{h^2}{h^2 + k^2} \right). +\end{aligned} \\ +\lintertext{Thus} Q = \frac{V}{4 \pi h} \left\{x - \frac{2k}{\pi} \sin^{-1} \frac{k}{\sqrt{h^2 + k^2}} -\frac{h}{\pi} \log \frac{h^2}{h^2 + k^2} \right\}. +\end{DPgather*} + +In the case which occurs most frequently in practice, that in +which $k$~is small compared with~$h$, we have, neglecting~$(k/h)^2$, +\[ +Q = \frac{V}{4 \pi h}\, x; +\] +%% -----File: 249.png---Folio 235------- +\index{Guard-ring, distribution of electricity on}% +that is, the quantity of electricity on the plate is the same as if +the distribution were uniform and the width of the plate were +increased by half the breadth of the slit. + +The quantity of electricity on the face~\smallsanscap{AB} of the slit is equal to +\[ +\frac{V}{4\pi^2}\log \frac{(1+a)}{(1-a)}, +\] +or, substituting the value for~$a$ previously found, +\[ +\frac{V}{4\pi^2}\log\left\{\frac{1+ \dfrac{k}{\sqrt{h^2+k^2}}}{1-\dfrac{k}{\sqrt{h^2+k^2}}}\right\}, +\] +and this when $k/h$~is small is equal to +\[ +\frac{V}{4\pi h}\, \frac{2k}{\pi}. +\] +Thus $2/\pi$ of the increase in the charge on~\smallsanscap{ABC}, over the value it +would have if the surface density were uniformly~$V/4\pi h$ on~\smallsanscap{BC}, +is on the side~\smallsanscap{AB} of the slit, and $(\pi-2)/\pi$ is on the face of the +plate of the condenser. + +\Article{244} A slight modification of the preceding solution will +enable us to find the distribution of electricity on the conductors +when~\smallsanscap{ABC} and~\smallsanscap{FGH} are no longer at the same potential. If +$V_1$~is the potential of~\smallsanscap{ABC}, $V_2$~that of~\smallsanscap{FGH}, then the relation +between $z$~and~$t$ will remain the same as before, while the +relation between $w$~and~$t$ will now be expressed by the equation +\begin{DPalign*} +w =\phi+\iota\psi &=\frac{V_2}{\pi}\log(t+a)-\frac{V_1}{\pi}\log(t-a)+\iota V_1, \\ +\lintertext{\rlap{or}} \phi+\iota\psi & =\frac{V_2-V_1}{\pi}\log{(t+a)}+\frac{V_1}{\pi} \log(t+a)-\frac{V_1}{\pi}\log(t-a)+\iota V_1\rlap{.} +\end{DPalign*} +Hence the quantity of electricity on~\smallsanscap{QBP} where \smallsanscap{Q}~is a point on~\smallsanscap{AB} +at some distance from~\smallsanscap{B} will exceed the quantity that would +be found from the results of the preceding \artref{243}{Article} by +\[ +\frac{V_2 - V_1}{4\pi^2}\log \frac{t_P + a}{t_Q + a}. +\] + +Since \smallsanscap{P} is a point on~\smallsanscap{BC} at some distance from~\smallsanscap{B}, $t_P$~is approximately +equal to~$a$, and since $a$~is small and $t_Q$~large we may +%% -----File: 250.png---Folio 236------- +replace $t_Q + a$ by~$t_Q$; making these substitutions the preceding expression +becomes +\[ +\frac{V_2 - V_1}{4\pi^2} \log \frac{2a}{t_Q}. \Tag{30} +\] +When $t$ is large, the relation between $z$~and~$t$, which is given by +the equation +\[ +\frac{dz}{dt} = C \frac{(t^2-1)^{\frac{1}{2}}}{t^2-a^2}, +\] +is by integrating this equation found to be +\begin{multline*} +x- k + \iota(y-h) \\ += C \log (t+\sqrt{t^2-1})+\frac{\sqrt{1-a^2}}{2a}\, C\left\{\sin^{-1} \frac{1-at}{t-a} - \sin^{-1}\frac{1+at}{t+a}\right\}, +\end{multline*} +or substituting for~$C$ (the~$\iota D$ of the preceding \artref{243}{Article}) its value +$\iota 2k/\pi$, we have +\begin{multline*} +x-k+ \iota (y-h) \\ += \iota \frac{2k}{\pi}\log(t+\sqrt{t^2-1})+\iota\frac{h}{\pi}\left\{\sin^{-1} \frac{1-at}{t-a} - \sin^{-1} \frac{1+at}{t+a}\right\}. +\end{multline*} +Hence, when $t$~is large we have approximately +\[ +\log 2t = \frac{\pi}{2k}\,(y-h). +\] + +Substituting this value for~$\log t_Q$ in the expression~(\eqnref{244}{30}), we find +that the correction to be applied on account of the difference of +potential between \smallsanscap{ABC}~and~\smallsanscap{FGH} to the expression given by +\artref{243}{Art.~243} for the quantity of electricity on~\smallsanscap{QBP} is +\[ +-\frac{(V_2-V_1)}{4\pi^2}\left\{\log\frac{\sqrt{h^2+k^2}}{4k}+\frac{\pi}{2k}\,(y-h)\right\}, +\] +where $y-h = \text{\smallsanscap{BQ}}$. + +\Article{245} The indirect method given by Maxwell, \textit{Electrostatics}, +Chap.~XII, in which we begin by assuming an arbitrary relation +between $z$~and~$w$ of the form +\[ +x + \iota y = F(\phi + \iota\psi), +\] +and then proceed to find the problems in electrostatics which +can be solved by this relation, leads to some interesting results +when elliptic functions are employed. Thus, let us assume +\[ +x + \iota y = b\sn(\phi + \iota\psi), \Tag{31} +\] +and suppose that $\phi$~is the potential and $\psi$~the stream function. +%% -----File: 251.png---Folio 237------- +Let $k$~be the modulus of the elliptic functions, $2K$~and~$2\iota K'$ the +real and imaginary periods. Let us trace the equipotential +surface for which $\phi = K$; we have +\begin{align*} +x + \iota y & = b \sn(K+\iota\psi) \\ +& = \frac{b}{\dn(\psi,k')}, \Tag{32} +\end{align*} +where $\dn(\psi,k')$ denotes that the modulus of the elliptic function +is~$k'$, that is $\sqrt{1-k^2}$, and not~$k$. From equation~(\eqnref{245}{32}) we see that +$y = 0$, and +\[ +x = \frac{b}{\dn(\psi,k')}. +\] +Now $\dn(\psi,k')$ is always positive, its greatest value is unity +when $\psi = 0$, or an even multiple of~$K'$, its least value is~$k$ when +$\psi$~is an odd multiple of~$K'$, thus the equation +\[ +x + \iota y = \frac{b}{\dn(\psi,k')} +\] +represents the portion of the axis of~$x$ between $x = b$ and +$x = b/k$. + +If we put $\phi = -K$, we have +\begin{align*} +x + \iota y & = b \sn(-K + \iota \psi), \\ +& = - \frac{b}{\dn(\psi,k')}; +\end{align*} +hence the equipotential surface,~$-K$, consists of the portion of +the axis of~$x$ between $x = -b$ and $x = -b/k$. + +\includegraphicsouter{fig100}{Fig.~100.} + +\index{Capacity xof two infinite strips@\subdashone of two infinite strips}% +Thus the transformation~(\eqnref{245}{31}) solves the +case of two infinite plane strips \smallsanscap{AB},~\smallsanscap{CD}, +\figureref{fig100}{Fig.~100}, of finite and equal widths, +$b\, (1 - k)/k$, in one plane placed so that +their sides are parallel to each other. + +In the above investigation the potential difference is~$2K$. +The quantity of electricity on the top of the strip~\smallsanscap{CD} is equal to +the difference in the values of~$\psi$ at~\smallsanscap{C} and~\smallsanscap{D} divided by~$4\pi$. +Now the difference in the values of~$\psi$ at~\smallsanscap{C} and~\smallsanscap{D} is~$K'$, hence the +quantity of electricity on the top of the strip is +\[ +\frac{1}{4\pi}\, K'. +\] +%% -----File: 252.png---Folio 238------- +There is an equal quantity of electricity on the bottom of the +strip, so that the total charge on~\smallsanscap{CD} is +\[ +\frac{1}{4\pi}\, 2K'. +\] +The difference of potential between the strips is~$2K$, hence the +capacity of the strip per unit length measured parallel to~$z$ is +\[ +\frac{1}{4\pi}\, \frac{K'}{K}. +\] +The modulus~$k$ of the elliptic functions is the ratio of \smallsanscap{BC} to~\smallsanscap{AD}, +that is the ratio of the shortest to the longest distance +between points in the lines \smallsanscap{AB}~and~\smallsanscap{CD}. The values of $K$~and~$K'$ +for given values of~$k$ are tabulated in Legendre's \textit{Traité des +Fonctions Elliptiques}: so that with these tables the capacity of +two strips of any width can be readily found. + +When $k$~is small, that is when the breadth of either of the +strips is large compared with the distance between them, $K$~and~$K'$ +are given approximately by the following equations, +\begin{align*} +K & = \frac{\pi}{2}, \\ +K' & = \log(4/k) = \log(4AD/BC). +\end{align*} +Hence in this case the capacity is approximately, +\[ +\frac{1}{2\pi^2}\log(4AD/BC). +\] + +Returning to the general case, if $\sigma$~is the surface density of the +electricity at the point~$P$ on one of the strips~\smallsanscap{AB}, we have +\begin{DPgather*} +\sigma = \frac{1}{4\pi}\, \frac{d\psi}{dx}; \\ +\lintertext{and since} x = - \frac{b}{\dn(\psi,k')},\\ +-\frac{dx}{d\psi} = bk'^2 \sn(\psi,k')\cn(\psi,k')/\dn^2(\psi,k')\\ += \frac{1}{b}\{x^2 - b^2\}^{\frac{1}{2}}\{b^2 - k^2x^2\}^{\frac{1}{2}}\\ += \frac{k}{b}\sqrt{CP \centerdot DP \centerdot AP \centerdot BP}\;;\\ +\lintertext{hence} \sigma = -\frac{b}{4\pi k}\, \frac{1}{\sqrt{CP \centerdot DP \centerdot AP \centerdot BP}}. +\end{DPgather*} +%% -----File: 253.png---Folio 239------- + +The solution of the case of two strips at equal and opposite +potentials, includes that of a strip at potential~$K$ in front of an +infinite plane at potential zero. The solution of this case can be +deduced directly from the transformation +\[ +x + \iota y = b \dn (\phi + \iota\psi), +\] +if $\psi$ be taken as the potential and $\phi$~as the stream function. + +\bigskip +\includegraphicsmid{fig101}{Fig.~101.} + +\Article{246} \emph{Capacity of a Pile of Plates}, \figureref{fig101}{Fig.~101}. If we put +\[ +\epsilon^{\frac{x + \iota y}{b}} = \sn(\phi + \iota\psi), \Tag{33} +\] +then when $\phi = K$ +\[ +\epsilon^{\frac{x + \iota y}{b}} = \sn (K + \iota\psi) = \frac{1}{\dn(\psi,k')}. \Tag{34} +\] + +Thus, since $\dn (\psi,k')$ is always real and positive, +\[ +y = 0,\ y = 2\pi b,\ y = 4\pi b, \text{ \&c.}, +\] +while $x$~varies between the values $x_1$,~$x_2$, where +\[ +\left.\begin{aligned} +\epsilon^{\frac{x_1}{b}} & = 1,\\ +\epsilon^{\frac{x_2}{b}} & = \frac{1}{k}. +\end{aligned}\right\} \Tag{35} +\] + +When $\phi = -K$, +\[ +\epsilon^{\frac{x + \iota y}{b}} = \sn (-K + \iota\psi) = -\frac{1}{\dn(\psi,k')}, +\] +hence, since $\dn (\psi,k')$ is always real and positive, +\[ +y = \pi b,\ y = 3\pi b,\ y = 5\pi b, \text{ \&c.}, +\] +while $x$~varies between the same values as before. Thus, if in +equation~(\eqnref{246}{33}) we take $\phi$ to be the potential and $\psi$~the stream +function, the equation will give the electrical distribution over a +\index{Capacity xof a pile of plates@\subdashone of a pile of plates}% +pile of parallel strips of finite width, $x_2 - x_1$, the distance between +the consecutive strips being~$\pi b$, alternate strips being at the +same potential. The potential of one set of plates is~$K$, that +of the other~$-K$. +%% -----File: 254.png---Folio 240------- + +The quantity of electricity on one side of one of the strips per +unit length parallel to~$z$ is, as in \artref{245}{Art.~245}, equal to $K'/4\pi$, and +since the charge on either side is the same, the total charge on +the strips is~$K'/2\pi$. The potential difference is~$2K$, hence the +capacity of one of the strips per unit length is equal to +\[ +\frac{K'}{4\pi K}. +\] + +We see from equation~(\eqnref{246}{35}) that +\[ +k = \epsilon^{-\frac{(x_2-x_1)}{b}}; +\] +but $x_2-x_1=d$, the breadth of one of the strip, hence +\[ +k = \epsilon^{-\frac{d}{b}}. +\] +Having found~$k$ from this equation, we can by Legendre's Tables +find the values of $K$~and~$K'$, and hence the capacity of the strips. +When the breadth of the strips is large compared with the +distance between them, $d/b$~is large, hence $k$~is small; in this +case we have approximately +\begin{align*} +K &= \frac{\pi}{2},\\ +K' &= \begin{aligned}[t]\log(4/k) &= \log(4\epsilon^{\tfrac{d}{b}})\\ +& = 2 \log 2 + \frac{d}{b}, +\end{aligned} +\end{align*} +so that the capacity of one strip is +\[ +\frac{1}{2\pi^2}\left\{2 \log 2 + \frac{d}{b}\right\}. +\] + +Returning to the general case, the surface density of the +electricity at a point~$P$ on the positive side of one of the strips~\smallsanscap{AB} +is equal to +\[ +\frac{1}{4\pi}\, \frac{d\psi}{dx}. +\] +But by equation~(\eqnref{246}{34}) +\[ +\frac{1}{b}\epsilon^{\frac{x}{b}}\, \frac{dx}{d\psi} = k'^2 \sn(\psi,k') \cn(\psi,k')/\dn^2(\psi,k'). +\] +Substituting the values of +\[ +\sn(\psi,k'), \quad \cn(\psi,k'), \quad \dn(\psi,k') +\] +%% -----File: 255.png---Folio 241------- +in terms of $\epsilon^{\tfrac{x}{b}}$, we get +\[ +\frac{d\psi}{dx} = \frac{1}{b}\, \frac{\epsilon^{\tfrac{(x_2 - x_1)}{2b}}}{ + \Bigl\{ + {(\epsilon^{\tfrac{(x - x_1)}{b}} - \epsilon^{-\tfrac{(x - x_1)}{b}}) + (\epsilon^{\tfrac{(x_2 - x)}{b}} - \epsilon^{\tfrac{-(x_2 - x)}{b}})} + \Bigr\}^{\frac{1}{2}}}. +\] + +Hence the surface density is equal to +\[ +\frac{1}{4 \pi b}\, \frac{\epsilon^{\tfrac{AB}{2b}}}{\Bigl\{ (\epsilon^{\tfrac{AP}{b}} - \epsilon^{-\tfrac{AP}{b}})(\epsilon^{\tfrac{BP}{b}} - \epsilon^{-\tfrac{BP}{b}}) \Bigr\}^{\frac{1}{2}}}. +\] + +The distribution of electricity on any one of the plates is +evidently the same as if the plate were placed midway between +two infinite parallel plates at potential zero, the distance between +the two infinite plates being~$2 \pi b$. + +\Article{247} \emph{Capacity of a system of $2n$~plates arranged radially and +\index{Capacity xof a series of radial plates@\subdashone of a series of radial plates}% +making equal angles with each other, the alternate plates being +at the same potential, the extremities of the plates lying on two +coaxial right circular cylinders.} Let us put +\[ +\left( \frac{x + \iota y}{b} \right)^n = \sn(\phi + \iota \psi), +\] +or, transforming to polar coordinates $r$~and~$\theta$, +\[ +\left( \frac{r}{b} \right)^n \epsilon^{\iota n \theta} = \sn(\phi + \iota \psi). +\] + +Then, as before, we see that when $\phi=K$, $n \theta=0$ or~$2 \pi$, or~$4 \pi$, +and so on, and when $\phi = -K$, $n \theta = \pi$ or~$3 \pi$, or~$5 \pi$,~\&c.; hence +this transformation solves the case of $2n$~plates arranged radially, +making angles~$\pi / n$ with each other, one set of $n$~plates being at +the potential~$K$, the other set at the potential~$-K$. When +$\phi=K$, we have +\[ +\left( \frac{r}{b} \right)^n = \frac{1}{\dn(\psi,k')}. +\] + +Hence if $r_1$~and~$r_2$ are the smallest and greatest distances of +the edges of a plate from the line to which all the plates converge, +we have +\begin{DPalign*} +\left( \frac{r_1}{b} \right)^n &= 1,\\ +\left( \frac{r_2}{b} \right)^n &= \frac{1}{k},\\ +\lintertext{or} k &= \left( \frac{r_1}{r_2} \right)^n. +\end{DPalign*} +%% -----File: 256.png---Folio 242------- + +The total charge on both sides of one of the plates is, as before, +$K'/2\pi$, and since the potential difference is~$2K$ the capacity of +the plate is~$K'/4\pi K$. When $r_1$~is small compared with~$r_2$, $k$~is +small, and we have then approximately +\begin{gather*} +K = \frac{\pi}{2}, \\ +K' = \log (4/k) = \log 4 + n \log (r_2/r_1). +\end{gather*} +Thus the capacity of a plate is in this case approximately +\[ +\frac{1}{2\pi^2} \,\{\log 4 + n \log (r_2/r_1)\}. +\] + +Returning to the general case, the surface density of the +electricity on one side of a plate is equal to +\begin{DPgather*} +\frac{1}{4\pi}\, \frac{d\psi}{dr}; \\ +\lintertext{but since} \left(\frac{r}{b}\right)^n = \frac{1}{\dn(\psi,k')}, \\ +\frac{n}{b}\left(\frac{r}{b}\right)^{n-1} \frac{dr}{d\psi} = k'^2\sn(\psi,k')\cn(\psi,k')/\dn^2(\psi,k'). +\end{DPgather*} + +Substituting for the elliptic functions their values in terms +of~$r$, we find when~$\phi=K$ +\[ +\frac{d\psi}{dr} = \frac{nb^nr^{n-1}}{k\{(r^{2n} - {r_1}^{2n})({r_2}^{2n} - r^{2n})\}^{\frac{1}{2}}}. +\] +Thus the surface density is equal to +\[ +\frac{1}{4\pi} \,\frac{{nr_2}^nr^{n-1}}{\{(r^{2n} - {r_1}^{2n})({r_2}^{2n} - r^{2n})\}^{\frac{1}{2}}}. +\] +When $n=1$, this case coincides with that discussed in \artref{245}{Art.~245}. + +\Article{248} Let us next put +\[ +x+\iota y = b\cn(\phi + \iota\psi), +\] +and take $\psi$~for the potential, and $\phi$~for the stream function. +Then when $\psi=0$, we have +\[ +x + \iota y = b\cn\phi, +\] +hence $y=0$, and $x$~can have any value between~$±b$: thus the +%% -----File: 257.png---Folio 243------- +equipotential surface for which $\psi$~is zero is the portion of the +axis of~$x$ between $x=-b$, and $x=+b$. When $\psi=K'$, +\begin{align*} +x + \iota y &= b \cn(\phi + \iota K')\\ +&= -\frac{b\iota\dn\phi}{k\sn\phi}; +\end{align*} +hence $x=0$, and $y$~ranges from $+bk'/k$ to~$+\infty$ and from $-bk'/k$ +to~$-\infty$. Hence the section of the equipotential surface for +which $\psi=K'$ is the portion of the axis of~$y$ included between +these limits. Thus the section of the conductors over which the +distribution of electricity is given by this transformation is +similar to that represented in \figureref{fig102}{Fig.~102}, where the axis of~$x$ is +\emph{vertical}. + +\includegraphicsouter{fig102}{Fig.~102.} + +To find the quantity of electricity on~\smallsanscap{AB} we notice that $\phi=0$ +at~\smallsanscap{A} and is equal to~$2K$ at~\smallsanscap{B}, +hence the quantity of +electricity on one side of~\smallsanscap{AB} +is equal to~$K/2\pi$, thus the +total charge on~\smallsanscap{AB} is~$K/\pi$. +The difference of potential +between \smallsanscap{AB}~and~\smallsanscap{CD} or~\smallsanscap{EF} is~$K'$, so that the capacity of~\smallsanscap{AB} is +equal to +\[ +\frac{1}{\pi}\, \frac{K}{K'}. +\] +The modulus~$k$ of the elliptic functions is given by the equation +\[ +\frac{k'}{k} = \frac{\{1-k^2\}^{\frac{1}{2}}}{k} = \frac{\smallbold{EC}}{\smallbold{AB}}. +\] +If~\smallsanscap{AB} is very large compared with~\smallsanscap{EC} then $k$~is very nearly +unity, and in this case we have +\begin{align*} +K &= \log (4/k') = \log (4\smallbold{AB}/\smallbold{EC}),\\ +K'&= \frac{\pi}{2}; +\end{align*} +so that the capacity of~\smallsanscap{AB} is +\[ +\frac{2}{\pi^2} \log(4\smallbold{AB}/\smallbold{EC}). +\] + +The surface density of the electricity at a point~$P$ on either +%% -----File: 258.png---Folio 244------- +side of~\smallsanscap{AB} is (without any limitation as to the value of~$k$) +equal to +\[ +\frac{1}{4\pi}\, \frac{d\phi}{dx}, +\] +and since $x = b \cn \phi$, +\begin{align*} +\frac{dx}{d\phi} &= -b \sn \phi \dn \phi\\ +&= -\frac{k}{b} (b^2 - x^2)^{\frac{1}{2}} \left\{\frac{k'^2}{k^2} b^2 + x^2\right\}^{\frac{1}{2}}\\ +&= -\frac{k}{b} \smallbold{CP} \sqrt{\smallbold{AP} \centerdot \smallbold{BP}}; +\end{align*} +hence the surface density is equal to +\[ +- \frac{b}{4\pi k}\, \frac{1}{\smallbold{CP} \sqrt{\smallbold{AP} \centerdot \smallbold{BP}}}. +\] + +\Article{249} We pass on now to consider the transformation +\[ +\epsilon^{\frac{x+\iota y}{b}} = \cn (\phi + \iota\psi), +\] +where $\phi$~is taken as the potential and $\psi$~as the stream function. + +Over the equipotential surface for which $\phi = 0$, we have +\begin{DPgather*} +\begin{aligned} +\epsilon^{\frac{x+\iota y}{b}} &= \cn (\iota \psi)\\ +&= \frac{1}{\cn(\psi,k')}. +\end{aligned} \\ +\lintertext{\indent Hence} y = 0,\quad ±\pi b,\quad ±2\pi b, \ldots; +\end{DPgather*} +while $x$~ranges from $0$ to infinity. + +For the equipotential surface for which $\phi = K$, we have +\begin{DPgather*} +\begin{aligned} +\epsilon^{\frac{x+\iota y}{b}} &= \cn(K + \iota\psi)\\ +&= -\iota k' \frac{\sn(\psi,k')}{\dn(\psi,k')}. +\end{aligned} \\ +\lintertext{\indent Hence} y = ±\tfrac{1}{2} \pi b,\quad ±\tfrac{3}{2} \pi b,\quad ±\tfrac{5}{2} \pi b \ldots, +\end{DPgather*} +while $x$~ranges from minus infinity to a value~$x_1$ given by the +equation +\[ +\epsilon^{\frac{x_1}{b}} = \frac{k'}{k}. +\] + +\includegraphicsmid{fig103}{Fig.~103.} + +Thus this transformation gives the distribution of electricity +%% -----File: 259.png---Folio 245------- +\index{Capacity xof two piles of plates@\subdashone of two piles of plates|(}% +on a pile of semi-infinite parallel plates at equal intervals $\pi b$ +apart, maintained at potential zero when in presence of another +pile of semi-infinite parallel plates at the same distance apart +maintained at potential~$K$, the planes of the second set of plates +being midway between those of the first. The second set of +plates project a distance~$x_1$ into the first set, $x_1$~being given by +the equation~$\epsilon^{x_1/b} = k'/k$. If the edges of the second set of plates +are outside the first set, then $x_1$~is negative and numerically +equal to the distance between the planes containing the ends +of the two sets of plates. The system of conductors is represented +in \figureref{fig103}{Fig.~103}. + +The quantity of electricity on the two sides of one of the +plates is~$K'/2\pi$, hence the capacity of such a plate is +\[ +\frac{K'}{2\pi K}. +\] + +If the ends of the two sets of plates are in the same plane, +then $x_1 = 0$, and therefore $k' = k$, so that $K' = K$; hence the +capacity of each plate is in this case~$1/(2\pi)$. + +When the plates do not penetrate and are separated by a +distance which is large compared with the distance between two +parallel plates, $x_1$~is negative and large compared with~$b$, hence $k'$~is +small, and therefore $k$~nearly equal to unity; in this case +\begin{align*} +K' &= \frac{\pi}{2},\\ +K &= \log(4/k'),\\ +&=\log 4 + \frac{x'}{b}, +\end{align*} +where $x' = -x_1$. + +Thus the capacity of a plate in this case is approximately +equal to +\[ +\frac{b}{4(b\log 4 + x')}. +\] +The surface density at a point on one of the first set of plates at +%% -----File: 260.png---Folio 246------- +a distance~$x$ from the edge is easily shewn by the methods +previously used to be equal, whatever be the value of~$k$, to +\[ +-\frac{1}{4\pi kb}\,\frac{\epsilon^{\frac{x}{b}}}{\sqrt{(\epsilon^{\frac{2x}{b}} - 1)(\epsilon^{\frac{2x}{b}} + \epsilon^{\frac{2x_1}{b}})}}. +\] + +\Article{250} The transformation +\[ +\left(\frac{x + \iota y}{b}\right)^n = \cn(\phi+\iota\psi), +\] +with $\phi$~as the potential and $\psi$~as the stream function, gives the +solution of the case represented in \figureref{fig104}{Fig.~104}; where the $2n$~outer +planes at potential zero are supposed +to extend to infinity, the $2n$~inner +planes at potential~$K$ bisect the angles +between the outer planes, and $\smallsanscap{OA}=b$. + +\includegraphicsouter{fig104}{Fig.~104.} + +\index{Capacity xof two series of radial plates@\subdashone of two series of radial plates|(}% +We can easily prove that in this +case the quantity of electricity on the +outer plates is equal to~$nK'/\pi$, so that +the capacity of the system is equal to +\[ +\frac{n}{\pi}\, \frac{K'}{K}, +\] +when the modulus of the elliptic functions is determined by the +relation +\[ +\left(\frac{\smallbold{OC}}{\smallbold{OA}}\right)^n = \frac{k'}{k}. +\] + +\Article{251} The transformation +\[ +x + \iota y = b\dn(\phi + \iota\psi), +\] +\index{Capacity xof a strip between two plates@\subdashone of a strip between two plates}% +where $\phi$~is the potential and $\psi$~the stream function, gives the +solution of the case represented in \figureref{fig105}{Fig.~105}, in which a finite +plate is placed in the space between two semi-infinite plates. +For when $\phi = 0$, we have +\begin{align*} +x + \iota y &= b\dn\iota\psi\\ +&= b \frac{\dn(\psi,k')}{\cn(\psi,k')}; \Tag{36} +\end{align*} +%% -----File: 261.png---Folio 247------- +hence $y = 0$, and $x$~ranges from $+b$ to~$+\infty$ and from $-b$ to~$-\infty$, +thus giving the portions $\smallsanscap{EF}$,~$\smallsanscap{CD}$ of the figure. + +\includegraphicsmid{fig105}{Fig.~105.} + +When $\phi = K$, we have +\begin{align*} +x + \iota y &= b \dn(K + \iota \psi)\\ +&= bk' \frac{\cn(\psi,k')}{\dn(\psi,k')}; \Tag{37} +\end{align*} +hence $y = 0$, and $x$~ranges between~$±bk'$, thus giving the portion~$\smallsanscap{AB}$ +of the figure. + +The quantity of electricity on the two sides of the plate~$\smallsanscap{AB}$ is +equal to~$K'/\pi$, hence the capacity of this plate is equal to +\[ +\frac{1}{\pi}\, \frac{K'}{K}, +\] +where the modulus~$k$ of the elliptic functions is given by the +equation +\[ +k' = \{ 1 - k^2 \}^{\frac{1}{2}} = \smallbold{OA} / \smallbold{OC}. +\] +When $\smallsanscap{AC}$~is small compared with~$\smallsanscap{AB}$, $k'$~is nearly equal to unity, +and $k$~is therefore small, in this case we have approximately +\begin{align*} +K &= \frac{\pi}{2},\\ +K' &= \log(4/k)\\ +&= \log 4 + \tfrac{1}{2} \log \frac{\smallbold{OC}^2}{\smallbold{AC} \centerdot \smallbold{BC}}; +\end{align*} +so that in this case the capacity of the plate~\smallsanscap{AB} is equal to +\[ +\frac{1}{\pi^2} \left\{\log \frac{\smallbold{OC}^2}{\smallbold{AC} \centerdot \smallbold{BC}} + 2 \log 4 \right\}. +\] + +Returning to the general case, the surface density of the +electricity on one side of the plate~$\smallsanscap{AB}$ at a point~$\smallsanscap{P}$ is equal to +\[ +\frac{1}{4 \pi}\, \frac{d\psi}{dx}. +\] +Using equation~(\eqnref{251}{37}) we find that this is equal to +\[ +\frac{b}{4 \pi}\, \frac{1}{\{(b^2 - x^2)(b^2 k'^2 - x^2) \}^{\frac{1}{2}}}, +\] +which may be written in the form +\[ +\frac{b}{4 \pi}\, \frac{1}{\{ \smallbold{AP} \centerdot \smallbold{BP} \centerdot \smallbold{CP} \centerdot \smallbold{EP}\}^{\frac{1}{2}}}. +\] +%% -----File: 262.png---Folio 248------- + +The surface density at a point~$\smallsanscap{Q}$ on~$\smallsanscap{EF}$ may be shown in a +similar way, using~(\eqnref{251}{36}), to be equal to +\[ +-\frac{b}{4\pi}\,\frac{1}{\{(x^2 - b^2)(x^2 - b^2k'^2)\}^{\frac{1}{2}}}, +\] +which is equal to +\[ +-\frac{b}{4\pi}\,\frac{1}{\{\smallbold{AQ} \centerdot \smallbold{BQ} \centerdot \smallbold{CQ} \centerdot \smallbold{EQ}\}^{\frac{1}{2}}}. +\] + +\Article{252} If we put +\[ +\epsilon^{\frac{x+\iota y}{b}} = \dn(\phi+\iota\psi), +\] +and take as before $\phi$~for the potential and $\psi$~for the stream +function, then since, when $\phi = 0$, +\begin{align*} +\epsilon^{\frac{x+\iota y}{b}} &= \dn(\iota\psi)\\ +&= \frac{\dn(\psi,k')}{\cn(\psi,k')}, +\end{align*} +we have $y = 0$, $y = ±\pi b$, $y = ±2\pi b \ldots$, while $x$~ranges from~$0$ to~$+\infty$. +Thus the equipotential surfaces for which $\phi$~vanishes are +a pile of parallel semi-infinite plates stretching from the axis +of~$y$ to infinity along the positive direction of~$x$, the distance +between two adjacent plates being~$\pi b$. + +When $\phi = K$, we have +\begin{align*} +\epsilon^{\frac{x+\iota y}{b}} &= \dn(K + \iota\psi)\\ +&= k'\frac{\cn(\psi,k')}{\dn(\psi,k')}; +\end{align*} +thus $y = 0$, $y = ±\pi b$, $y = ±2\pi b \ldots$, while $x$~ranges from~$-\infty$ to~$-x_1$, +where $x_1$~is given by the equation +\[ +\epsilon^{-\frac{x_1}{b}} = k'. \Tag{38} +\] +\includegraphicsouter{fig106}{Fig.~106.} +Thus the equipotential surfaces for which $\phi = K$ are a pile of +parallel semi-infinite plates stretching from~$-\infty$ to a distance $x_1$ +from the previous set of plates. The distance between adjacent +plates in this set is again~$\pi b$, and the planes of the plates in this +set are the continuations of those of the plates in the set at +potential zero. This system of conductors is represented in +\figureref{fig106}{Fig.~106}. +%% -----File: 263.png---Folio 249------- + +The quantity of electricity on both sides of one of the plates at +potential zero is~$-K'/2\pi$, +hence the +capacity of such a +plate is +\[ +\frac{1}{2\pi}\, \frac{K'}{K}, +\] +the modulus of the elliptic functions being given by equation~(\eqnref{252}{38}). + +When the distance between the edges of the two sets of +plates is large compared with the distance between two adjacent +parallel plates, then $x_1$~is large compared with~$b$, so that $k'$~is +small; in this case we have approximately +\begin{align*} +K' &= \frac{\pi}{2},\\ +K &= \log(4/k')\\ +&= \log 4 + \frac{x_1}{b}; +\end{align*} +hence the capacity of a plate is equal to +\[ +\frac{b}{4(x_1 + b \log 4)}. +\] + +The surface density of the electricity at a point~$P$ on one of +the planes at potential zero is in the general case easily proved +to be equal to +\[ +-\frac{1}{4\pi b}\,\frac{\epsilon^{\frac{x}{b}}}{\left\{(\epsilon^{\frac{2x}{b}} - 1)(\epsilon^{\frac{2x}{b}} - \epsilon^{-\frac{2x_1}{b}})\right\}^{\frac{1}{2}}}. +\] + +\includegraphicsouter{fig107}{Fig.~107.} + +\Article{253} The transformation +\[ +\left(\frac{x + \iota y}{b}\right)^n = \dn(\phi + \iota \psi), +\] +where $\phi$~is the potential and $\psi$~the stream function and $n$~a +positive integer, gives the solution of the case shown in +\figureref{fig107}{Fig.~107}, when the potential of the outer radial plates is zero +and that of the inner~$K$. The $2n$~outer plates make equal angles +with each other and extend to infinity. + +The quantity of electricity on both sides of one of the outer +\index{Capacity xof two piles of plates@\subdashone of two piles of plates|)}% +\index{Capacity xof two series of radial plates@\subdashone of two series of radial plates|)}% +%% -----File: 264.png---Folio 250------- +plates is $-K' / 2 \pi$; since there are $2n$~of these plates the capacity +of the system is +\[ +\frac{n}{\pi}\, \frac{K'}{K}, +\] +the modulus of the Elliptic Functions being given by the equation +\[ +k' = \{ 1 - k^2 \}^{\frac{1}{2}} = \left( \frac{\smallbold{OA}}{\smallbold{OB}} \right)^n. +\] + +\Article{254} We have only considered those +applications of elliptic function to electrostatics +where the expression for the capacity of the electrical +system proves to be such that it can be readily calculated in any +special case by the aid of Legendre's Tables. There are many +other transformations which are of great interest analytically, +though the want of tables of the special functions involved makes +them of less interest for experimental purposes than those we +have considered. Thus, for example, the transformation +\[ +x + \iota y = Z(\phi + \iota\psi), +\] +where $Z$~is the function introduced by Jacobi and defined by +the equation +\[ +Z(u) = \int^u \dn^2 u\, du - \frac{E}{K}, +\] +if $\psi$~is the potential and $\phi$~the stream function, gives the distribution +of electricity in the important case of a condenser formed +by two parallel and equal plates of finite breadth. +%% -----File: 265.png---Folio 251------- + +\Chapter{Chapter IV.}{Electrical Waves and Oscillations.} + +\Article{255} \Firstsc{The} properties of electrical systems in which the distribution +of electricity varies periodically and with sufficient rapidity +to call into play the effects of electric inertia, are so interesting +and important that they have attracted a very large amount of +attention ever since the principles which govern them were set +forth by Maxwell in his \emph{Electricity and Magnetism}. We shall +in this Chapter consider the theory of such vibrating electrical +systems, while the \chapref{Chapter V.}{following Chapter} will contain an account of +some remarkable experiments by which the properties of such +systems have been exhibited in a very striking way. + +\Article{256} We shall begin by writing down the general equations +which we shall require in discussing the transmission of electric +disturbances through a field in which both insulators and conductors +are present. + +Let $F$,~$G$,~$H$ be the components of the vector potential parallel +to the axes of $x$,~$y$,~$z$ respectively, $P$,~$Q$,~$R$ the components of the +electromotive intensity, and $a$,~$b$,~$c$ those of the magnetic induction +in the same directions, let $\phi$ be the electrostatic potential, +$\sigma$~the specific resistance of the conductor, $\mu$~and~$\mu'$ the magnetic +\DPtypo{permeabilites}{permeabilities} of the conductor and dielectric respectively, and $K$~and~$K'$ +the specific inductive capacities of the conductor and +dielectric respectively, then we have +\[ +\left. \begin{aligned} +P = -\frac{dF}{dt} - \frac{d\phi}{dx},\\ +Q = -\frac{dG}{dt} - \frac{d\phi}{dy},\\ +R = -\frac{dH}{dt} - \frac{d\phi}{dz}. +\end{aligned}\right\} \Tag{1} +\] +%% -----File: 266.png---Folio 252------- + +We have also +\begin{DPalign*} +&\left.\begin{aligned} + \phantom{\frac{da}{dt}}\llap{$a$} &= \frac{dH}{dy} - \frac{dG}{dz}, +\end{aligned}\right.\\ +\lintertext{hence} +&\left.\begin{aligned} + \frac{da}{dt} &= \frac{d}{dy} \frac{dH}{dt} - \frac{d}{dz} \frac{dG}{dt}, +\end{aligned}\right.\\ +\lintertext{\rlap{\raisebox{1.8\baselineskip}{so that }}similarly} +\rintertext{} +&\left.\begin{aligned} + \frac{da}{dt} &= \frac{dQ}{dz} - \frac{dR}{dy};\\ + \frac{db}{dt} &= \frac{dR}{dx} - \frac{dP}{dz},\\ + \frac{dc}{dt} &= \frac{dP}{dy} - \frac{dQ}{dx}. +\end{aligned}\right\} \eqnlabel{\eqnart.2}\tag*{\llap{(2)}} %[TN:Compensate for difference in how DPalign handles tags] +\end{DPalign*} + +If $\alpha$,~$\beta$,~$\gamma$ are the components of the magnetic force, $u$,~$v$,~$w$ +those of the total current, then (Maxwell's \textit{Electricity and Magnetism}, +Art.~607) +\[ +\left. +\begin{aligned} +4 \pi u &= \frac{d \gamma}{dy} - \frac{d \beta}{dz},\\ +4 \pi v &= \frac{d \alpha}{dz} - \frac{d \gamma}{dx},\\ +4 \pi w &= \frac{d \beta}{dx} - \frac{d \alpha}{dy}. +\end{aligned} \Tag{3} +\right\} +\] + +In the metal the total current is the sum of the conduction and +polarization currents; the conduction current parallel to~$x$ is $P / \sigma$, +the polarization current $\dfrac{K}{4 \pi} \dfrac{dP}{dt}$, or if $P$ varies as $\epsilon^{\iota pt}$, the +polarization current is $\dfrac{K}{4 \pi\strut}\iota p \cdot P$. Thus the ratio of the conduction to the +polarization current is $\dfrac{4 \pi}{K \sigma \iota p}$, and since $\sigma$ in electromagnetic +measure is of the order $10^4$ for the commoner metals and $K$ in the +same measure of the order $10^{-21}$, we see that unless the vibrations +are comparable in rapidity with those of light we may +neglect the polarization current in the metal in comparison with +the conduction current. Thus in the conductor we have +\[ +\frac{4 \pi}{\sigma} P = \frac{d\gamma}{dy} - \frac{d\beta}{dz} = \frac{1}{\mu} \left( \frac{dc}{dy} - \frac{db}{dz} \right), +\] +and therefore by (\eqnref{256}{2}) we have, assuming +\[ +\frac{dP}{dx} + \frac{dQ}{dy} + \frac{dR}{dz} = 0, +\] +%% -----File: 267.png---Folio 253------- +\begin{DPalign*} +\lintertext{similarly}\left. +\begin{aligned} +\nabla^2 P &= \frac{4\pi\mu}{\sigma} \frac{dP}{dt};\\ +\nabla^2 Q &= \frac{4\pi\mu}{\sigma} \frac{dQ}{dt},\\ +\nabla^2 R &= \frac{4\pi\mu}{\sigma} \frac{dR}{dt}. +\end{aligned}\right\}\Tag{4} +\end{DPalign*} +It follows from equation~(\eqnref{256}{2}) that $a$,~$b$,~$c$ satisfy equations of the +same form. + +In the dielectric there is only the polarization current, the component +of which parallel to~$x$ is $\dfrac{K'}{4\pi} \dfrac{dP}{dt}$; hence in the dielectric +we have +\[ +K'\frac{dP}{dt} = \frac{d\gamma}{dy} - \frac{d\beta}{dz} = \frac{1}{\mu'}\left(\frac{dc}{dy} - \frac{db}{dz}\right), +\] +and therefore by~(\eqnref{256}{2}) +\begin{DPalign*} +\lintertext{similarly}\left. +\begin{aligned} +\nabla^2 P &= \mu'K'\frac{d^2 P}{dt^2};\\ +\nabla^2 Q &= \mu'K'\frac{d^2 Q}{dt^2},\\ +\nabla^2 R &= \mu'K'\frac{d^2 R}{dt^2}. +\end{aligned}\right\}\Tag{5} +\end{DPalign*} + +We shall suppose that the effects are periodic and of frequency~$p/2\pi$, +so that the components of the electromotive intensity, as +well as of the magnetic induction, will all vary as~$\epsilon^{\iota pt}$ and will +not explicitly involve the time in any other way. We shall also +suppose that the electric waves are travelling parallel to the +axis of~$z$, so that the variables before enumerated will contain +$\epsilon^{\iota mz}$ as a factor, $m$~being a quantity which it is one of the +objects of our investigation to determine. With these assumptions +we see that $d/dt$ may be replaced by~$\iota p$, and $d/dz$ by~$\iota m$. + +\Subsection{Alternating Electric Currents in Two Dimensions.} +\index{Alternating currents, in two dimensions@\subdashtwo in two dimensions}% + +\Article{257} The cases relating to alternating currents which are +of the greatest practical importance are those in which the +currents flow along metallic wires. As the analysis, however, in +these cases is somewhat complicated, we shall begin by considering +the two dimensional problem, as this, though of comparatively +small practical importance, enables us by the aid of +simple analysis to illustrate some important properties possessed +by alternating currents. +%% -----File: 268.png---Folio 254------- + +The case we shall first consider is that of an infinite conducting +plate bounded by the planes $x = h$, $x = -h$, immersed in +a dielectric. We shall suppose that plane waves of electromotive +intensity are advancing through the dielectric, and that these +waves impinge on the plate. We shall suppose also that the +waves fall on both sides of the plate and are symmetrical with +respect to it. These waves when they strike against the plate +will be reflected from it, so that there will on either side of the +plate be systems of direct and reflected waves. + +Let $P$~and~$R$ denote the components of the electromotive +intensity parallel to the axes of $x$~and~$z$ respectively, the component +parallel to the axis of~$y$ vanishing since the case is one +in two dimensions. Then in the dielectric the part of~$R$ due to +the direct wave will be of the form +\[ +B\epsilon^{\iota(mz + lx + pt)}, +\] +while the part due to the reflected wave will be of the form +\[ +C\epsilon^{\iota(mz - lx + pt)}. +\] +Thus in the dielectric on one side of the plate +\[ +R = B\epsilon^{\iota(mz + lx + pt)} + C\epsilon^{\iota(mz - lx + pt)}.\Tag{1} +\] +If $V$ is the velocity with which electromagnetic disturbances +are propagated through the dielectric, we have by equation~(\eqnref{256}{5}), +\artref{256}{Art.~256}, since $\mu'K'= 1/V^2$, +\begin{DPalign*} +\frac{d^2 R}{dx^2} + \frac{d^2 R}{dz^2} &= \frac{1}{V^2} \frac{d^2 R}{dt^2},\\ +\lintertext{hence} l^2 + m^2 &= \frac{p^2}{V^2}. +\end{DPalign*} + +If $\lambda$ is the wave length of the incident wave, $\theta$~the angle +between the normal to the wave front and the axis of~$x$, we +have, since +\begin{gather*} +p = \frac{2\pi}{\lambda} V,\\ +l = \frac{2\pi}{\lambda}\cos \theta, \quad m = \frac{2\pi}{\lambda} \sin \theta. +\end{gather*} + +Since $Q$ vanishes, we have +\[ +\frac{dP}{dx} + \frac{dR}{dz} = 0. +\] +%% -----File: 269.png---Folio 255------- +Substituting the value of $R$ from equation~(\eqnref{257}{1}), we find +\[ +P = -\frac{m}{l} \{B\epsilon^{\iota(mz + lx + pt)} - C\epsilon^{\iota(mz - lx + pt)}\}. \Tag{2} +\] +The resultant electromotive intensity in the incident wave is +\[ +\frac{B}{\cos \theta} \epsilon^{\iota(mz + lx + pt)}, +\] +in the reflected wave +\[ +\frac{C}{\cos \theta} \epsilon^{\iota(mz - lx + pt)}. +\] + +Let us now consider the electromotive intensity in the conducting +plate; in this region we have, by~(\eqnref{256}{4}), \artref{256}{Art.~256}, if $\mu$ is the +magnetic permeability and $\sigma$~the specific resistance of the plate, +\begin{DPgather*} +\frac{d^2 R}{dx^2} + \frac{d^2 R}{dz^2} = \frac{4\pi\mu}{\sigma}\frac{dR}{dt},\\ +\intertext{or, since $R$ varies as $\epsilon^{\iota(mz + pt)}$,}\\ +\frac{d^2 R}{dx^2} = n^2 R,\\ +\lintertext{where} n^2 = m^2 + \frac{4\pi\mu\iota p}{\sigma}. +\end{DPgather*} +The solution of this, since the electromotive intensity is symmetrical +with respect to the plane $x = 0$, is of the form +\begin{DPgather*} +R = A(\epsilon^{nx} + \epsilon^{-nx}) \epsilon^{\iota(mz + pt)}, \Tag{3} \\ +\lintertext{and since} \frac{dP}{dx} + \frac{dR}{dz} = 0,\\ +P = -\frac{\iota m}{n} A(\epsilon^{nx} - \epsilon^{-nx}) \epsilon^{\iota (mz + pt)}. \Tag{4} +\end{DPgather*} + +If $a$,~$b$,~$c$ are the components of magnetic induction, then +\begin{align*} +\frac{da}{dt} &= \frac{dQ}{dz} - \frac{dR}{dy},\\ +\frac{db}{dt} &= \frac{dR}{dx} - \frac{dP}{dz},\\ +\frac{dc}{dt} &= \frac{dP}{dy} - \frac{dQ}{dx}; +\end{align*} +hence $a = 0$, $c = 0$, and +\begin{align*} +b &= \frac{n^2 - m^2}{\iota pn} A(\epsilon^{nx} - \epsilon^{-nx}) \epsilon^{\iota(mz + pt)} \; \text{in the plate},\Tag{5}\\ +b &= \frac{l^2 + m^2}{lp} (B\epsilon^{\iota lx} - C\epsilon^{-\iota lx)} \epsilon^{\iota(mz + pt)} \; \text{in the dielectric}.\Tag{6} +\end{align*} +%% -----File: 270.png---Folio 256------- + +We can get the expression for the magnetic force in the +dielectric very simply by the method given in \artref{9}{Art.~9}. In the +incident wave the resultant electromotive intensity is +\[ +\frac{B}{\cos \theta} \epsilon^{\iota(mz + lx + pt)}, +\] +hence the polarization is +\[ +\frac{K'}{4 \pi} \frac{B}{\cos \theta} \epsilon^{\iota(mz + lx + pt)}, +\] +where $K'$ is the specific inductive capacity of the dielectric. The +Faraday tubes are moving with the velocity~$V$, hence by equations~(\eqnref{9}{4}), \artref{9}{Art.~\DPtypo{(9)}{9}}, +the magnetic force due to their motion is +\[ +VK'\frac{B}{\cos \theta} \epsilon^{\iota(mz + lx + pt)}. +\] +The magnetic induction corresponding to this magnetic force +is equal, since $\mu'K'$ equals $1/V^2$, to +\[ +\frac{B}{V \cos \theta} \epsilon^{\iota(mz + lx + pt)}, +\] +which is the first term on the right in equation~(\eqnref{257}{6}). We may +show in a similar way that the magnetic force due to the motion +of the Faraday tubes in the reflected wave is equal to the second +term on the right in equation~(\eqnref{257}{6}). + +We must now consider the conditions which hold at the +junction of the plate and the dielectric. These may be expressed +in many different ways: they are, however, when the conductors +are at rest, equivalent to the conditions that the tangential +electromotive intensity, and the tangential magnetic force, +are continuous. Thus when $x = h$ we must have both $R$~and~$b/\mu$ +continuous. The first of these conditions gives +\[ +A(\epsilon^{nh} + \epsilon^{-nh}) = B \epsilon^{\iota lh} + C \epsilon^{-\iota lh}, \Tag{7} +\] +the second +\[ +\frac{n^2 - m^2}{\mu n} A(\epsilon^{nh} - \epsilon^{-nh}) = \frac{\iota(l^2 + m^2)}{\mu'l} (B \epsilon^{\iota lh} - C \epsilon^{-\iota lh}). \Tag{8} +\] +\begin{DPalign*} +\lintertext{Since} n^2 - m^2 &= \frac{4 \pi \mu \iota p}{\sigma},\\ +\lintertext{and} \frac{l^2 + m^2}{l} &= \frac{2 \pi}{\lambda \cos \theta}, +\end{DPalign*} +%% -----File: 271.png---Folio 257------- +and for all known dielectrics $\mu'$~may without sensible error be +put equal to unity, equation~(\eqnref{257}{8}) may be written +\[ +\frac{2p}{\sigma n} A(\epsilon^{nh} - \epsilon^{-nh}) = \frac{1}{\lambda \cos \theta} (B \epsilon^{\iota lh} - C\epsilon^{-\iota lh}). \Tag{9} +\] + +From (\eqnref{257}{7}) and (\eqnref{257}{9}) we get +\begin{align*} +A \{ \epsilon^{nh} + \epsilon^{-nh} + \frac{2p \lambda \cos \theta}{\sigma n} (\epsilon^{nh} - \epsilon^{-nh}) \} &= 2B \epsilon^{\iota lh}, \Tag{10}\\ +A \{ \epsilon^{nh} + \epsilon^{-nh} - \frac{2p \lambda \cos \theta}{\sigma n} (\epsilon^{nh} - \epsilon^{-nh}) \} &= 2C \epsilon^{-\iota lh}. \Tag{11} +\end{align*} + +It will be convenient to express $A$,~$B$,~$C$ in terms of the total +current through the plate. If $w$ is the intensity of the current +parallel to~$z$ in the plate, $w = R / \sigma$, hence by~(\eqnref{257}{3}) +\[ +w = \frac{A}{\sigma}(\epsilon^{nx}+\epsilon^{-nx}) \epsilon^{\iota(mz + pt)}. +\] +If $I_0 \epsilon^{\iota(mz + pt)}$ is the total current passing through unit width +measured parallel to~$y$, of the plate, +\begin{DPgather*} +I_0 \epsilon^{\iota(mz + pt)} = \int_{-h}^{+h} w\, dx;\\ +\lintertext{hence} I_0=\frac{2A}{\sigma n}(\epsilon^{nh}-\epsilon^{-nh}), \Tag{12}\\ +\lintertext{so that} w = \tfrac{1}{2 }n I_0 \frac{(\epsilon^{nx} + \epsilon^{-nx})}{(\epsilon^{nh} - \epsilon^{-nh})} \epsilon^{\iota(mz + pt)}. \Tag{13} +\end{DPgather*} + +Let us now suppose that the frequency of the vibrations is so +small that $nh$ is a small quantity, this will be the case if +$h \sqrt{4 \pi \mu p/\sigma}$ is small. When $nh$ and therefore $nx$ is small, +equation~(\eqnref{257}{13}) becomes approximately +\[ +w = \frac{I_0}{2h} \epsilon^{\iota(mz + pt)}; +\] +thus the current in the plate is distributed uniformly across it. +When $nh$ is small, equations~(\eqnref{257}{12}), (\eqnref{257}{10}) and~(\eqnref{257}{11}) become approximately +\begin{gather*} +I_0 = \frac{4Ah}{\sigma},\\ + \begin{aligned} + A (1 + 4 \pi Vh \sigma^{-1} \cos \theta) &= B \epsilon^{\iota lh},\\ + A (1 - 4 \pi Vh \sigma^{-1} \cos \theta) &= C \epsilon^{-\iota lh}. + \end{aligned} +\end{gather*} +%% -----File: 272.png---Folio 258------- +Thus corresponding to the current $I_0 \cos (pt + mz)$ in the plate, +we find +\[ +\left. +\begin{aligned} +R &= \frac{\sigma I_0}{2h} \cos(p t +mz),\\ +P &= \frac{\sigma I_0 mx}{2h} \sin(pt + mz),\\ +b &= 4 \pi \mu I_0 \frac{x}{2h} \cos(pt + mz) +\end{aligned} +\right\} +\text{ in the plate.}\\ +\] +Thus, since $mx$~is exceedingly small, we see that the maximum +electromotive intensity parallel to the boundary of the plate is +exceedingly large compared with the maximum at right angles +to it. + +In the dielectric we have +\begin{multline*} +R = \frac{\sigma I_0}{2h} \cos(pt + mz) \cos l(x - h)\\ +- 2\pi I_0 V \cos \theta \sin(pt + mz)\sin l(x - h), +\end{multline*} +\begin{multline*} +P = \frac{1}{2h} \sigma I_0 \tan \theta \sin(pt + mz) \sin l(x - h)\\ +- 2\pi I_0 V \sin \theta \cos(pt + mz)\cos l(x - h), +\end{multline*} +\begin{multline*} +b = -\frac{\sigma I_0}{2Vh \cos \theta} \sin(pt + mz) \sin l(x - h)\\ ++ 2 \pi I_0 \cos(pt + mz) \cos l(x - h). +\end{multline*} + +Thus at the surface of the plate where $x = h$ +\begin{align*} +R &= \frac{\sigma I_0}{2h} \cos (pt + mz),\\ +P &= -2 \pi I_0 V \sin \theta \cos (pt + mz),\\ +b &= 2 \pi I_0 \cos (pt + mz). +\end{align*} + +Thus at the surface of the plate $P/R = -4 \pi Vh \sigma^{-1} \sin \theta$. If +the plate is metallic this quantity is exceedingly large unless the +plate is excessively thin or $\theta$~very small, so that in the dielectric +the resultant electromotive intensity at the surface of the plate is +along the normal, this is in striking contrast to the effect inside the +plate where $P/R$ is very small. The Faraday tubes in the dielectric +close to the plate are thus at right angles to the plate, while +in the plate they are parallel to it; hence by \artref{10}{Art.~10} the electric +momentum in the dielectric close to the plate is parallel to the +axis of~$z$, or parallel to the plate, while in the plate itself it is +parallel to the axis of~$x$, or in the direction of motion from the +outside of the plate to the inside. If $4 \pi Vh \cos \theta = \sigma$, then +%% -----File: 273.png---Folio 259------- +$C=0$; in this case there is no reflected wave; the wave reflected +from one side of the plate is annulled by the direct wave coming +through the plate from the other side. It is worthy of remark +that the only one of the quantities we have considered whose +value either in the interior of the plate or near to the plate in +the dielectric depends sensibly upon~$\theta$, the direction of motion of +the incident wave, is the normal electromotive intensity in the +dielectric and in the plate. + +\Article{258} We shall now proceed to discuss the case when $nh$~is +large. We shall begin by considering the distribution of current +in the plate. We have by~(\eqnref{257}{13}) +\[ +w=\tfrac{1}{2} I_0 n \frac{(\epsilon^{nx} + \epsilon^{-nx})}{(\epsilon^{nh} + \epsilon^{-nh})}\, \epsilon^{\iota(mz + pt)}, +\] +and since $nh$~is large this equation may be written as +\begin{DPalign*} +w &= \tfrac{1}{2} I_0 n\, \epsilon^{-n(h - x)}\, \epsilon^{\iota(mz + pt)}. \Tag{14}\\ +\lintertext{Now} n^2 &= m^2 + \frac{4 \pi \mu \iota p}{\sigma}\\ +&= \frac{p^2}{V^2} \sin^2 \theta + \frac{4 \pi \mu \iota p}{\sigma}. +\end{DPalign*} +Now $p^2/V^2$ is very small compared with $4 \pi \mu p / \sigma$ if the plate +conducts as well as a metal, unless the vibrations are quicker +than those of light. When the current makes a million vibrations +per second $(p^2/V^2) / (4 \pi \mu p / \sigma)$ is approximately $5 × 10^{-16} (\sigma / \mu)$, +and is thus excessively small unless the resistance is enormously +greater than that of acidulated water; we may therefore without +appreciable error write +\begin{DPgather*} +n^2 = \frac{4 \pi \mu \iota p}{\sigma},\\ +\lintertext{and} n = \sqrt{2 \pi \mu p / \sigma} (1 + \iota) = n_1(1 + \iota) \text{ say, where}\\ +n_1 = \sqrt{2 \pi \mu p/\sigma}. +\end{DPgather*} + +Substituting this value for~$n$, and taking the real part of~(\eqnref{258}{14}), +we have +\[ +w = \sqrt{\pi \mu p / \sigma} I_0 \epsilon^{-n_1(h - x)} \cos \left\{mz - n_1(h - x) + pt +\frac{\pi}{4} \right\}. +\] +The presence of the factor $\epsilon^{-n_1(h - x)}$ in this expression shows +that the current diminishes in geometrical progression as $h - x$ +increases in arithmetical progression, and that it will practically +%% -----File: 274.png---Folio 260------- +\index{Alternating currents, flow to surface of conductors@\subdashtwo flow to surface of conductors}% +\index{Concentration of alternating current on the outside of a conductor}% +\index{Electric skin@\subdashone `skin'}% +\index{Skin@`Skin', electrical}% +vanish as soon as $n_1(h - x)$ is a small multiple of unity. We thus +get the very interesting result that an alternating current does not +distribute itself uniformly over the cross-section of the conductor +through which it is flowing, but concentrates itself towards the +outside of the conductor. When the vibrations are very rapid +the currents are practically confined to a thin skin on the outside +of the conductor. The thickness of this skin will diminish +as $n_1$~increases; we shall take $1/n_1$ as the measure of its +thickness. + +This inequality in the distribution of alternating currents is +explicitly stated in Art.~690 of Maxwell's \textit{Electricity and +Magnetism}, but its importance was not recognised until it was +brought into prominence and its consequences developed by the +\index{Heaviside, xconcentration of current@\subdashone concentration of current}% +\index{Hughes, concentration of alternating current}% +\index{Rayleigh, Lord, concentration of alternating current@\subdashtwo concentration of alternating current}% +investigations of Mr.~Heaviside and Lord Rayleigh, and the experiments +of Professor Hughes. + +The amount of this concentration is very remarkable in the +magnetic metals, even for comparatively slow rates of alternation +of the current. Let us for example take the case of a current +making $100$~vibrations per second, and suppose that the plate +is made of soft iron for which we may put $\mu = 10^3$, $\sigma = 10^4$. In +this case $p = 2 \pi × 10^2$, and $n_1$ or $\{2 \pi \mu p / \sigma \}^{\frac{1}{2}}$ is approximately +equal to~$20$; thus at a depth of half a millimetre from the surface +of such a plate, the maximum intensity of the current will only +be~$1 / \epsilon$ or $.368$~of its value at the surface. At the depth of $1$~millimetre +it will only be~$.135$, at $2$~millimetres $.018$, and at $3$~millimetres +$.0025$, or the $1/400$~part of its value at the exterior. +Thus in such a plate, with the assigned rate of alternations, the +currents will practically cease at the depth of about $2$~mm.\ and will +be reduced to about $1/7$~of their value at the depth of one +millimetre. Thus in this case the currents, and therefore the +magnetic force, are confined to a layer not more than $3$~millimetres +thick. + +The thickness of the `skin' for copper is about $13$~times that +for soft iron. + +The preceding results apply to currents making $100$~vibrations +per second; when we are dealing with such alternating +currents as are produced by the discharge of a Leyden Jar, +where there may be millions of alternations per second, the +thickness of the `skin' in soft iron is often less than the +hundredth part of a millimetre. +%% -----File: 275.png---Folio 261------- + +\index{Momentum of Faraday tubes}% +Returning to the determination of $P$,~$R$, and~$b$ for this case, +we find from equations (\eqnref{257}{3}),~(\eqnref{257}{4}), and~(\eqnref{257}{12}) in the plate +\begin{align*} +R &= \{\pi \mu p \sigma \}^{\frac{1}{2}} I_0 \epsilon^{-n_1(h - x)} \cos \left\{mz + n_1(x - h) + pt + \frac{\pi}{4} \right\},\\ +P &= \tfrac{1}{2} m \sigma I_0 \epsilon^{-n_1(h - x)} \cos \left\{mz + n_1(x - h) + pt - \frac{\pi}{2} \right\},\\ +b &= 2 \pi \mu I_0 \epsilon^{-n_1(h - x)} \cos \left\{mz + n_1(x - h) + pt \right\}. +\end{align*} +Thus we see that in this case, as well as when $nh$~was small, $P/R$ +is in general very small, so that the resultant electromotive +intensity is nearly parallel to the surface of the plate. + +In the dielectric we have by equations (\eqnref{257}{10}),~(\eqnref{257}{11}), and~(\eqnref{257}{12}) +when $nh$~is large; +\begin{multline*} +R = \{\pi \mu p \sigma \}^{\frac{1}{2}} I_0 \cos \left\{mz + pt + \frac{\pi}{4} \right\} \cos l(x - h)\\ +-2 \pi V \cos \theta I_0 \sin(mz + pt) \sin l(x - h), +\end{multline*} +\begin{multline*} +P = \{\pi \mu p \sigma \}^{\frac{1}{2}} \tan \theta I_0 \sin \left\{mz + pt + \frac{\pi}{4} \right\} \sin l(x - h)\\ +-2 \pi V \sin \theta I_0 \cos(mz + pt) \cos l(x - h), +\end{multline*} +\begin{multline*} +b = 2 \pi I_0 \cos(mz + pt) \cos l(x - h)\\ +-\frac{1}{V} \{\pi \mu p \sigma \}^{\frac{1}{2}} \sec \theta I_0 \sin \left( mz + pt + \frac{\pi}{4} \right) \sin l(x - h). +\end{multline*} +At the surface of the plate these become +\begin{align*} +R &= \{\pi \mu p \sigma \}^{\frac{1}{2}} I_0 \cos \left( mz + pt + \frac{\pi}{4} \right),\\ +P &= -2 \pi V \sin \theta I_0 \cos(mz + pt),\\ +b &= 2 \pi I_0 \cos (mz + pt), +\end{align*} +and we see, as before, that in general $P/R$ is very large, so that +the electromotive intensity near the plate in the dielectric is +approximately at right angles to it. + +Thus, as in the case of the slower vibrations, the momentum is +tangential in the dielectric and normal in the plate. + +If we compare the expressions for the components of the +electromotive intensity in the dielectric given above with those +given in the preceding \artref{257}{article}, we see that, except close to the +plate, they are very approximately the same. +%% -----File: 276.png---Folio 262------- + +\Subsection{Periodic Currents in Cylindrical Conductors, and the Rate +of Propagation of Electric Disturbances along them.} +\index{Alternating currents, in wires@\subdashtwo in wires}% + +\Article{259} We shall now proceed to consider the case which is most +easily realized in practice, that in which electrical disturbances +are propagated along long straight cylindrical wires, such for +example as telegraph wires or sub-marine cables. + +A peculiar feature of electrical problems in which infinitely +long straight cylinders play a part, is the effect produced by the +presence of other conductors, even though these are such a long +way off that it might have appeared at first sight that their +influence could have been neglected. This is exemplified by the +well-known formula for the capacity of two coaxial cylinders. +If $\smallbold{a}$~and~$\smallbold{b}$ are the radii of the two cylinders the capacity per +unit length is proportional to~$1/\log(\smallbold{b}/\smallbold{a})$. Thus, even though +the cylinders were so far apart that the radius of the outer +cylinder was $100$~times that of the inner, yet if the distance +were further increased until the outer radius was $10,000$~times +the inner, the capacity of the condenser would be halved, though +similar changes in the distances between concentric spheres +would hardly have affected their capacity to an appreciable extent. +For this reason we shall, though it involves rather more complex +analysis, suppose that our cylinder is surrounded by conductors, +and the results we shall obtain will enable us to determine +when the effects due to the conductors can legitimately be +neglected. + +\Article{260} The case we shall investigate is that of a cylindrical +metallic wire surrounded by a dielectric, while beyond the +dielectric we have another conductor; the dielectric is bounded +by concentric cylinders whose inner and outer radii are $\smallbold{a}$~and~$\smallbold{b}$ +respectively. If $\smallbold{b}/\smallbold{a}$~is a very large quantity, we have a case +approximating to an aerial telegraph wire, while when $\smallbold{b}/\smallbold{a}$~is +not large the case becomes that of a sub-marine cable. + +In the dielectric between the conductors there are convergent +and divergent waves of Faraday tubes, the incidence of which on +the conductors produces the currents through them. + +\Article{261} We shall take the axis of the cylinders as the axis of~$z$, +and suppose that the electric field is symmetrical round this axis; +then if the components of the electric intensity and magnetic +%% -----File: 277.png---Folio 263------- +induction vary as $\epsilon^{\iota(mz + pt)}$, the differential equations by which +these quantities are determined are of the form +\[ +\frac{d^2f}{dr^2} + \frac{1}{r}\, \frac{df}{dr} - n^2f = 0, +\] +where $r$~denotes the distance of a point from the axis of~$z$. The +complete solution of this equation is expressed by +\[ +f = AJ_0(\iota nr) + BK_0(\iota nr)\footnotemark. \Tag{1} +\] + +\footnotetext{Heine, \textit{Kugelfunctionen}, vol.~i.\ p.~189.}% +\index{Bessel's functions, values of, when variable, is small or large}% +\index{Functions, Bessel's}% +Here $J_0(x)$~represents Bessel's function of zero order, and +\[ +K_0(x) = (C + \log 2 - \log x)J_0(x) + 2 \{J_2(x)-\tfrac{1}{2}J_4(x) ++ \tfrac{1}{3}J_6(x) \ldots \}; \Tag{2} +\] +where $C$ is Gauss' constant, and is equal to $.5772157 \ldots \ldots$. + +When the real part of~$\iota n$ is finite, $J_0(\iota nr)$~is infinite when $r$~is +\index{Heine@Heine, \textit{Kügelfunctionen}}% +infinite (Heine, \textit{Kugelfunctionen}, vol.~i.\ p.~248), so that in any +region where $r$~may become infinite we must have $A = 0$ in +equation~(\eqnref{261}{1}). Again, $K_0(\iota nr)$ becomes infinite when $r$~vanishes, +so that in any region in which $r$~can vanish $B = 0$. + +We shall find the following approximate equations very useful +in our subsequent work. + +When $x$~is small +\begin{DPgather*} +J_0(\iota x) = 1,\qquad\qquad J_0'(\iota x) = -\tfrac{1}{2}\iota x.\\ +K_0(\iota x) = \log \frac{2 \gamma}{\iota x},\qquad\qquad K_0'(\iota x) = -\frac{1}{\iota x};\\ +\lintertext{where} \log \gamma = .5772157 \ldots,\\ +\lintertext{\rlap{and $J_0'(\iota x)$ is written for}} +\frac{dJ_0(\iota x)}{d(\iota x)}. +\end{DPgather*} + +When $x$~is very large +\begin{gather*} +J_0(\iota x) = \frac{\epsilon^x}{\sqrt{2 \pi x}}; \qquad\qquad J_0'(\iota x) = -\frac{\iota \epsilon^x}{\sqrt{2 \pi x}}.\\ +K_0(\iota x) = \epsilon^{-x} \sqrt{\frac{\pi}{2x}}; \qquad\qquad K_0'(\iota x)=\iota \epsilon^{-x} \sqrt{\frac{\pi}{2x}}. +\end{gather*} +(See Heine, \textit{Kugelfunctionen}, vol.~i.\ p.~248).\nbpagebreak[1] + +\Article{262} We shall now proceed to apply these results to the investigation +of the propagation of electric disturbances along the +%% -----File: 278.png---Folio 264------- +wire. The axis of the wire is taken as the axis of~$z$; $P$,~$Q$,~$R$ are +the components of the electromotive intensity parallel to the +axes of $x$,~$y$,~$z$ respectively; $a$,~$b$,~$c$ are the components of the +magnetic induction parallel to these axes: $\mu$,~$\sigma$ are respectively +the magnetic permeability and specific resistance of the wire, $\mu'$,~$\sigma'$ +the values of the same quantities for the external conductor, $K$~is +the specific inductive capacity of the dielectric between the +wire and the outer conductor. We shall suppose that the magnetic +permeability of the dielectric is unity, and that $V$~is the +velocity of propagation of electromagnetic action through this +dielectric. We shall begin by considering the equations which +hold in the dielectric: it is from this region that the Faraday +tubes come which produce the currents in the conductor. We +shall assume, as before, that the components of the electromotive +intensity vary as~$\epsilon^{\iota(mz+pt)}$. + +The differential equation satisfied by~$R$, the $z$~component of +the electromotive intensity in the dielectric, is (\artref{256}{Art.~256}) +\[ +\frac{d^2R}{dx^2} + \frac{d^2R}{dy^2} + \frac{d^2R}{dz^2} = \frac{1}{V^2}\, \frac{d^2R}{dt^2}, +\] +or, since $R$~varies as~$\epsilon^{\iota(mz+pt)}$, +\begin{DPgather*} +\Tag{3} \frac{d^2R}{dx^2} + \frac{d^2R}{dy^2} - k^2R = 0,\\ +\lintertext{where } k^2 = m^2 - \frac{p^2}{V^2}. +\end{DPgather*} + +If we introduce cylindrical coordinates $r, \theta, z$, this equation +may be written +\[ +\frac{d^2R}{dr^2} + \frac{1}{r}\, \frac{dR}{dr} + \frac{1}{r^2}\, \frac{d^2R}{d\theta^2} - k^2R = 0; +\] +but since the electric field is symmetrical about the axis of~$z$, $R$~is +independent of~$\theta$, hence this equation becomes +\[ +\frac{d^2R}{dr^2} + \frac{1}{r}\, \frac{dR}{dr} - k^2R = 0, +\] +the solution of which by \artref{261}{Art.~261} is, $C$~and~$D$ being constants, +\[ +\Tag{4} R = \{CJ_0 (\iota kr) + DK_0 (\iota kr)\} \epsilon^{\iota(mz+pt)}. +\] + +Both the $J$~and~$K$ functions have to be included, as $r$~can +neither vanish nor become infinite in the dielectric. This equation +%% -----File: 279.png---Folio 265------- +indicates the presence of converging and diverging waves of +Faraday tubes in the dielectric. If the currents in the wire are +in planes through the axis of~$z$, and if $S$~is the component of the +electromotive intensity along~$r$, then +\[ +P = S \frac{x}{r},\qquad Q = S \frac{y}{r}; +\] +hence, since $S$~is a function of $r$,~$z$, and~$t$, and not of~$\theta$, we may +write +\[ +P = \frac{d\chi}{dx},\qquad Q = \frac{d\chi}{dy}; \Tag{5} +\] +where $\chi$~is a function we proceed to determine. Since $P$~and~$Q$ +satisfy equations of the form +\begin{DPgather*} +\lintertext{\rlap{we have}\rlap{\raisebox{-1.8\baselineskip}{\indent But}}} +\left.\begin{gathered} +\frac{d^2 P}{dx^2} + \frac{d^2 P}{dy^2} - k^2P = 0,\\ +\frac{d^2 \chi}{dx^2} + \frac{d^2 \chi}{dy^2} - k^2 \chi = 0.\\ +\frac{dP}{dx} + \frac{dQ}{dy} + \frac{dR}{dz} = 0, +\end{gathered} +\right\} \Tag{6} +\end{DPgather*} +so that by equations (\eqnref{262}{5})~and~(\eqnref{262}{6}) +\[ +k^2 \chi + \frac{dR}{dz} = 0. +\] +We thus have the following expressions for $P$,~$Q$,~$R$, +\[ +\left. +\begin{aligned} +P &= -\frac{\iota m}{k^2}\, \frac{d}{dx} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)},\\ +Q &= -\frac{\iota m}{k^2}\, \frac{d}{dy} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)},\\ +R &= \phantom{-\frac{\iota m}{k^2}\, \frac{d}{dy}} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)}. +\end{aligned} +\right\} \Tag{7} +\] + +To find $a$,~$b$,~$c$, the components of the magnetic induction, we +have +\begin{align*} +\frac{da}{dt} &= \frac{dQ}{dz} - \frac{dR}{dy},\\ +\frac{db}{dt} &= \frac{dR}{dx} - \frac{dP}{dz},\\ +\frac{dc}{dt} &= \frac{dP}{dy} - \frac{dQ}{dx}. +\end{align*} +%% -----File: 280.png---Folio 266------- + +From these equations we find +\[ +\left. +\begin{aligned} +a &= \frac{(m^2 - k^2)}{\iota pk^2}\, \frac{d}{dy} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)},\\ +b &= - \frac{(m^2 - k^2)}{\iota pk^2}\, \frac{d}{dx} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)},\\ +c &= 0; +\end{aligned} +\right\} \Tag{8} +\] +thus the resultant magnetic induction is equal to +\[ +\frac{m^2 - k^2}{\iota pk^2}\, \frac{d}{dr} \{CJ_0(\iota kr) + DK_0(\iota kr) \} \epsilon^{\iota(mz + pt)}, +\] +and the lines of magnetic force are circles with their centres +along the axis of~$z$ and their planes at right angles to it. + +We now proceed to consider the wire. The differential equation +satisfied by~$R$ in the wire is +\[ +\frac{d^2 R}{dx^2} + \frac{d^2 R}{dy^2} + \frac{d^2 R}{dz^2} = \frac{4 \pi \mu}{\sigma}\, \frac{dR}{dt}. +\] + +Transforming this equation to cylindrical coordinates it becomes, +since $R$~is independent of~$\theta$, +\begin{DPgather*} +\frac{d^2 R}{dr^2} + \frac{1}{r}\, \frac{dR}{dr} - n^2 R = 0,\\ +\lintertext{where, as usual,} n^2 = m^2 + \frac{4 \pi \mu \iota p}{\sigma}. +\end{DPgather*} + +Since $r$~can vanish in the wire, the solution of this equation is +\[ +R = AJ_0 (\iota nr)\epsilon^{\iota(mz + pt)}, +\] +where $A$~is a constant. + +We can deduce the expressions for $P$~and~$Q$ from~$R$ in the +same way as for the dielectric, and we find +\[ +\left. +\begin{aligned} +P &= - \frac{\iota m}{n^2}\, A\, \frac{d}{dx} J_0 (\iota nr)\epsilon^{\iota(mz + pt)},\\ +Q &= - \frac{\iota m}{n^2}\, A\, \frac{d}{dy} J_0 (\iota nr)\epsilon^{\iota(mz + pt)},\\ +R &= \phantom{- \frac{\iota m}{n^2}\,}A\, J_0 (\iota nr)\epsilon^{\iota(mz + pt)}; +\end{aligned} +\right\} \Tag{9} +\] +and also +\[ +\left. +\begin{aligned} +a &= \frac{m^2 - n^2}{\iota pn^2}\, A\, \frac{d}{dy} J_0(\iota nr)\epsilon^{\iota(mz + pt)},\\ +b &= - \frac{m^2 - n^2}{\iota pn^2}\, A\, \frac{d}{dx} J_0(\iota nr)\epsilon^{\iota(mz + pt)}, \\ +c &= 0. +\end{aligned} +\right\} \Tag{10} +\] +%% -----File: 281.png---Folio 267------- + +The resultant magnetic induction is at right angles to $r$~and~$z$ +and equal to +\[ +\frac{m^2-n^2}{\iota pn^2}\, A\, \frac{d}{dr} J_0 (\iota nr)\epsilon^{\iota(mz+pt)}. +\] + +In the outer conductor the differential equations are of the +same form, but their solution will be expressed by the $K$~functions +and not by the~$J$'s, since $r$~can be infinite in the outer conductor. +We find if +\[ +n'^2 = m^2 + \frac{4\pi\mu'\iota p}{\sigma'}, +\] +that in the outer conductor, $E$~being a constant, +\begin{gather*} +\left. \begin{aligned} +P &= -\frac{\iota m}{n'^2}\, E\, \frac{d}{dx} K_0 (\iota n'r)\epsilon^{\iota(mz+pt)},\\ +Q &= -\frac{\iota m}{n'^2}\, E\, \frac{d}{dy} K_0 (\iota n'r)\epsilon^{\iota(mz+pt)}, \\ +R &= E\, K_0 (\iota n'r)\epsilon^{\iota(mz+pt)}; +\end{aligned}\right\} \Tag{11} \\ +% +\left. \begin{aligned} +a &= \frac{m^2-n'^2}{\iota pn'^2}\, E\, \frac{d}{dy} K_0 (\iota n'r)\epsilon^{\iota(mz+pt)}, \\ +b &= -\frac{m^2-n'^2}{\iota pn'^2}\, E\, \frac{d}{dx} K_0 (\iota n'r)\epsilon^{\iota(mz+pt)}, \\ +c &= 0. +\end{aligned}\right\} \Tag{12} +\end{gather*} + +The resultant magnetic induction is equal to +\[ +\frac{m^2-n'^2}{\iota pn'^2}\, E\, \frac{d}{dr} K_0 (\iota n'r)\epsilon^{\iota(mz+pt)}. +\] + +The boundary conditions at the surfaces of separation of the +dielectric and the metals are (1)~that the electromotive intensity +parallel to the surface of separation is continuous, (2)~that the +magnetic \emph{force} parallel to the surface is also continuous. Hence +if $\smallbold{a}$,~$\smallbold{b}$ are respectively the inner and outer radii of the layer of +dielectric, condition~(1) gives +\[ +\left. \begin{aligned} +AJ_0 (\iota n\smallbold{a}) &= CJ_0 (\iota k\smallbold{a}) + DK_0 (\iota k\smallbold{a}),\\ +EK_0 (\iota n'\smallbold{b}) &= CJ_0(\iota k\smallbold{b}) + DK_0 (\iota k\smallbold{b}). +\end{aligned}\right\} \Tag{13} +\] + +\sloppy +Condition~(2) gives, writing $J_0'(x)$ for~$dJ_0(x)/dx$, and $K_0'(x)$ +for~$dK_0(x)/dx$, and substituting for $m^2-n^2$, $m^2-k^2$, $m^2-n'^2$ the +values $-4 \pi\mu\iota p/\sigma$, $p^2/V^2$, $-4\pi\mu'\iota p/\sigma'$ respectively, +\[ +\left. \begin{aligned} +&\frac{4\pi\iota}{\sigma n}\, AJ_0' (\iota n\smallbold{a}) = - \frac{p}{V^2k} \{CJ_0'(\iota k\smallbold{a}) + DK_0' (\iota k\smallbold{a})\},\\ +&\frac{4\pi\iota}{\sigma'n'}\, EK_0' (\iota n'\smallbold{b}) = - \frac{p}{V^2k} \{CJ_0'(\iota k\smallbold{b}) + DK_0' (\iota k\smallbold{b})\}. +\end{aligned}\right\} \Tag{14} +\] +%% -----File: 282.png---Folio 268------- + +\fussy +Eliminating $A$~and~$E$ from equations (\eqnref{262}{13})~and~(\eqnref{262}{14}), we get +\begin{multline*} +C\left(\frac{4\pi\iota}{\sigma n}\, J_0'(\iota n\smallbold{a})\, J_0(\iota k\smallbold{a}) + \frac{p}{V^2k}\, J_0(\iota n\smallbold{a})\, J_0'(\iota k\smallbold{a})\right) \\ + + D\left(\frac{4\pi\iota}{\sigma n}\, J_0'(\iota n\smallbold{a})\, K_0(\iota k\smallbold{a}) + \frac{p}{V^2k}\, J_0(\iota n\smallbold{a})\, K_0'(\iota k\smallbold{a})\right) = 0, +\end{multline*} +\begin{multline*} +C\left(\frac{4\pi\iota}{\sigma'n'}\, K_0'(\iota n'\smallbold{b})\, J_0(\iota k\smallbold{b})\, + \frac{p}{V^2k}\, K_0(\iota n'\smallbold{b})\, J_0'(\iota k\smallbold{b})\right) \\ + + D\left(\frac{4\pi\iota}{\sigma'n'}\, K_0'(\iota n'\smallbold{b})\, K_0(\iota k\smallbold{b})\, + \frac{p}{V^2k}\, K_0(\iota n'\smallbold{b})\, K_0'(\iota k\smallbold{b})\right) = 0. +\end{multline*} +Eliminating $C$~and~$D$ from these equations, we get +\begin{multline*} +\left(\frac{4\pi\iota}{\sigma n}\, J_0'(\iota n\smallbold{a})\, J_0(\iota k\smallbold{a}) + \frac{p}{V^2k}\, J_0(\iota n\smallbold{a})\, J_0'(\iota k\smallbold{a})\right) ×\\ +\left(\frac{4\pi\iota}{\sigma'n'}\, K_0'(\iota n'\smallbold{b})\, K_0(\iota k\smallbold{b}) + \frac{p}{V^2k}\, K_0(\iota n'\smallbold{b})\, K_0'(\iota k\smallbold{b})\right) +\end{multline*} +\begin{multline*} += \left(\frac{4\pi\iota}{\sigma n}\, J_0'(\iota n\smallbold{a})\, K_0(\iota k\smallbold{a}) + \frac{p}{V^2k}\, J_0(\iota n\smallbold{a})\, K_0'(\iota k\smallbold{a})\right) ×\\ + \left(\frac{4\pi\iota}{\sigma'n'}\, K_0'(\iota n'\smallbold{b})\, J_0(\iota k\smallbold{b}) + \frac{p}{V^2k}\, K_0(\iota n'\smallbold{b})\, J_0'(\iota k\smallbold{b})\right). \Tag{15} +\end{multline*} + +This equation gives the relation between the wave length +$2 \pi/m$ along the wire and the frequency $p/2\pi$ of the vibration. To +simplify this equation, we notice that $k\smallbold{a}$,~$k\smallbold{b}$ are both very small +quantities, for, as we shall subsequently find, $k$, when the electrical +waves are very long, is inversely proportional to the wave length, +while when the waves are short $k$~is small compared with the +reciprocal of the wave length; we may therefore assume that +when the waves transmitted along the cable are long compared +with its radii, $k\smallbold{a}$~and~$k\smallbold{b}$ are very small. But in this case we +have approximately, +\begin{gather*} +J_0(\iota k\smallbold{a}) = 1,\quad J_0(\iota k\smallbold{b}) = 1,\\ +J_0'(\iota k\smallbold{a}) = -\tfrac{1}{2}\iota k\smallbold{a},\quad J_0'(\iota k\smallbold{b}) = -\tfrac{1}{2}\iota k\smallbold{b};\\ +K_0(\iota k\smallbold{a}) = \log \frac{2\gamma}{\iota k\smallbold{a}},\quad K_0(\iota k\smallbold{b}) = \log \frac{2\gamma}{\iota k\smallbold{b}},\\ +K_0'(\iota k\smallbold{a}) = -\frac{1}{\iota k\smallbold{a}},\quad K_0'(\iota k\smallbold{b}) = -\frac{1}{\iota k\smallbold{b}}. +\end{gather*} +%% -----File: 283.png---Folio 269------- +Making these substitutions, equation~(\eqnref{262}{15}) reduces to +\begin{align*} +k^2&=-\frac{p}{4\pi V^2}\biggl[\sigma n\Bigl(\frac{1}{\smallbold{a}}+\tfrac{1}{2} k^2 \smallbold{a} \log {\frac{2\gamma}{\iota k\smallbold{b}}}\Bigr)\frac{J_0(\iota n\smallbold{a})}{J'_0(\iota n\smallbold{a})}\\ +&\qquad-\sigma' n'\Bigl(\frac{1}{\smallbold{b}}+\tfrac{1}{2}k^2\smallbold{b} \log {\frac{2\gamma}{\iota k\smallbold{a}}}\Bigr)\frac{K_0(\iota n'\smallbold{b})}{K'_0(\iota n'\smallbold{b})}\\ +&\qquad-\frac{p}{8\pi V^2}\, \frac{\sigma n}{\smallbold{a}}\, \frac{\sigma'n'}{\smallbold{b}}\, (\smallbold{b}^2-\smallbold{a}^2)\, \frac{J_0(\iota n\smallbold{a})K_0(\iota n'\smallbold{b})}{J'_0(\iota n\smallbold{a})K'_0(\iota n'\smallbold{b})}\biggr]\frac{1}{\log(\smallbold{b}/\smallbold{a})}. +\end{align*} + +Now since both $k\smallbold{a}$~and~$k\smallbold{b}$ are very small, +\[ +k^2 \smallbold{a}^2 \log {\frac{2\gamma}{\iota k\smallbold{b}}},\quad k^2 \smallbold{b}^2 \log{\frac{2\gamma}{\iota k\smallbold{a}}} +\] +will be exceedingly small quantities unless $\smallbold{a}$~is so much smaller +than~$\smallbold{b}$ that $\log(2\gamma/\iota k\smallbold{a})$ is comparable with~$1/k^2\smallbold{b}^2$. This would +require such a disproportion between $\smallbold{b}$~and~$\smallbold{a}$ as to be scarcely +realizable in practice on a planet of the size of the earth; we +may therefore write the preceding equation in the form +\begin{align*} +k^2&=-\frac{\iota p^2}{V^2}\biggl[\frac{\mu}{n\smallbold{a}}\, \frac{J_0(\iota n\smallbold{a})}{J'_0(\iota n\smallbold{a})} - \frac{\mu'}{n'\smallbold{b}}\, \frac{K_0(\iota n'\smallbold{b})}{K'_0(\iota n'\smallbold{b})}\\ +&-\tfrac{1}{2} \iota \frac{p^2}{V^2}(\smallbold{b}^2-\smallbold{a}^2)\, \frac{\mu}{n\smallbold{a}}\, \frac{\mu'}{n'\smallbold{b}}\, \frac{J_0(\iota n\smallbold{a})}{J'_0(\iota n\smallbold{a})}\, \frac{K_0(\iota n'\smallbold{b})}{K'_0(\iota n'\smallbold{b})}\biggr] \frac{1}{\log(\smallbold{b}/\smallbold{a})} \cdots, \Tag{16} +\end{align*} +where we have put $n^2 = 4\pi \mu \iota p/\sigma$, $n'^2 = 4\pi \mu' \iota p/\sigma'$. We showed in +\artref{258}{Art.~258} that we were justified in doing this when the electrical +vibrations are not so rapid as to be comparable in frequency +with those of light. + +We see from~(\eqnref{262}{16}) that $k^2$~is given by an equation of the form +\[ +k^2 = - \frac{\iota p^2}{V^2}\left(\xi - \eta - \tfrac{1}{2} \frac{\iota p^2}{V^2} (\smallbold{b}^2-\smallbold{a}^2)\xi \eta\right). \Tag{16*} +\] + +We remark that for all electrical oscillations whose wave lengths +are large compared with the radii of the cable, $p^2 (\smallbold{b}^2-\smallbold{a}^2)/V^2$ is +an exceedingly small quantity, since it is of the order $(\smallbold{b}^2-\smallbold{a}^2)/\lambda^2$, +where $\lambda$~is the length of the electrical wave. + +In equation~(\eqnref{262}{16*}) we see that we can neglect the third term +inside the bracket as long as both $\xi$~and~$\eta$ are small compared +with $2V^2/p^2(\smallbold{b}^2-\smallbold{a}^2)$. +\begin{DPgather*} +\lintertext{\indent Now} \xi = \frac{\mu}{n\smallbold{a}}\, \frac{J_0(\iota n\smallbold{a})}{J'_0(\iota n\smallbold{a})}, +\end{DPgather*} +so that the large values of~$\xi$ occur when $n\smallbold{a}$~is small; and in this +%% -----File: 284.png---Folio 270------- +case, substituting the approximate values for $J_0$~and~$J_0'$, we see +that +\[ +\xi=-\frac{2\mu}{\iota n^2\smallbold{a}^2}=\frac{\sigma}{2\pi p\smallbold{a}^2}=\frac{V^2}{4\pi p^2(\smallbold{b}^2-\smallbold{a}^2)}\, \frac{2\sigma p}{V^2}\, \frac{\smallbold{b}^2-\smallbold{a}^2}{\smallbold{a}^2}. +\] + +Now for cables of practicable dimensions and materials conveying +oscillations slower than those of light $2\sigma p(\smallbold{b}^2-\smallbold{a}^2)/V^2\smallbold{a}^2$ +is an exceedingly small quantity, so that for such cases $\xi$~is very +small compared with $2V^2/p^2(\smallbold{b}^2-\smallbold{a}^2)$. + +\begin{DPgather*} +\lintertext{\indent Again,} \eta = \frac{\mu'}{n'\smallbold{b}}\, \frac{K_0(\iota n'\smallbold{b})}{K_0'(\iota n'\smallbold{b})}; +\end{DPgather*} +the large values of~$\eta$ occur when $n'\smallbold{b}$~is small. Substituting the +approximate values for $K_0$,~$K_0'$ we find +\[ +\eta = -\iota\mu' \log \left( \frac{2\gamma}{\iota n'\smallbold{b}}\right). +\] +This is very small compared with $\mu'/n'\smallbold{b}$, and may, as in the +preceding case, be shown for all practicable cases to be very +small compared with $2 V^2/p^2 (\smallbold{b}^2-\smallbold{a}^2)$. Hence, as both $\xi$~and~$\eta$ +are small compared with this quantity, we may neglect the third +term inside the bracket in equation~(\eqnref{262}{16}), which thus reduces to +\[ +k^2=-\frac{\iota p^2}{V^2}\left\{\frac{\mu}{n\smallbold{a}}\, \frac{J_0(\iota n\smallbold{a})}{J'_0(\iota n\smallbold{a})} - \frac{\mu'}{n'\smallbold{b}}\, \frac{K_0(\iota n'\smallbold{b})}{K'_0(\iota n'\smallbold{b})}\right\} \frac{1}{\log{(\smallbold{b}/\smallbold{a})}}. \Tag{17} +\] + +We shall now proceed to deduce from this equation the +velocity of propagation of electrical oscillations of different +frequencies. + +\Subsection{Slowly Alternating Currents.} + +\Article{263} The first case we shall consider is the one where the +frequency is so small that $n\smallbold{a}$~is a small quantity. In this case, +since we have approximately +\[ +J_0 (\iota n\smallbold{a})/J_0' (\iota n\smallbold{a}) = -2/\iota n\smallbold{a}, +\] +equation~(\eqnref{262}{17}) becomes +\[ +k^2=-\frac{\iota p^2}{V^2}\left\{\frac{2\iota\mu}{n^2\smallbold{a}^2}-\frac{\mu'}{n'\smallbold{b}}\, \frac{K_0(\iota n'\smallbold{b})}{K'_0(\iota n'\smallbold{b})}\right\} \frac{1}{\log{(\smallbold{b}/\smallbold{a})}}. \Tag{18} +\] + +The first term inside the bracket is very large, for it is +equal to $2\iota \mu/n^2\smallbold{a}^2$ and $n\smallbold{a}$~is small; the second term in the +bracket vanishes if $\smallbold{b}$~is infinite, and even if $\smallbold{b}$~is so small that +$n'\smallbold{b}$~is a small quantity, we see, by substituting the values for +$K_0$~and~$K_0'$ when the variable is small, that the ratio of the +%% -----File: 285.png---Folio 271------- +\index{Alternating currents, of long period@\subdashtwo of long period, velocity along a wire}% +\index{Propagation velocity of slowly alternating currents along a wire@\subdashone velocity of slowly alternating currents along a wire}% +\index{Velocity of propagation of slowly alternating currents along wires@\subdashtwo propagation of slowly alternating currents along wires}% +magnitude of the second term inside the bracket to that of the +first is approximately equal to +\[ +\frac{\mu'}{2\mu}\, n^2 \smallbold{a}^2 \log \frac{2\gamma}{\iota n'\smallbold{b}}, +\] +and thus unless $n'\smallbold{b}$~is exceedingly small compared with~$n\smallbold{a}$ the +second term may be neglected. + +Hence, since $n^2 = 4\pi \mu \iota p/\sigma$, we may write~(\eqnref{263}{18}) in the form +\[ +k^2 = -\frac{p}{V^2}\, \frac{\iota\sigma}{2\pi \smallbold{a}^2}\, \frac{1}{\log (\smallbold{b}/\smallbold{a})}, +\] +but $k^2 = m^2 - \dfrac{p^2}{V^2}$, so that +\[ +m^2 = \frac{p^2}{V^2} \left\{1 - \frac{\iota\sigma}{2\pi p\smallbold{a}^2}\, \frac{1}{\log{(\smallbold{b}/\smallbold{a})}} \right\}; +\] +we have seen however that the second term in the bracket is +large compared with unity, so that we have approximately +\[ +m^2 = - \frac{p}{V^2}\, \frac{\iota\sigma}{2\pi \smallbold{a}^2}\, \frac{1}{\log (\smallbold{b}/\smallbold{a})}. +\] + +{\allowdisplaybreaks +If $\smallbold{R}$ is the resistance and $\Gamma$~the capacity in electromagnetic +measure per unit length of the wire, then since +\begin{DPgather*} +\smallbold{R} = \frac{\sigma}{\pi \smallbold{a}^2},\quad \Gamma = \frac{1}{2V^2 \log (\smallbold{b}/\smallbold{a})},\\ +\lintertext{we have} m^2 = -\iota p\smallbold{R}\Gamma, \\ +\lintertext{or} m = -\{p\smallbold{R}\Gamma\}^{\frac{1}{2}} \left\{\frac{1}{\sqrt{2}} - \frac{\iota}{\sqrt{2}}\right\}, +\end{DPgather*} +where the sign has been taken so as to make the real part of~$\iota m$ +negative. The reason for this is as follows: if $m = -\alpha + \iota\beta$, +$\smallbold{R}$,~the electromotive intensity parallel to the axis of the wire, +will be expressed by terms of the form +\[ +\cos(-\alpha z+pt)\, \epsilon^{-\beta z}. +\] +This represents a vibration whose phases propagated with the +velocity~$p/\alpha$ in the positive direction of~$z$, and which dies away +to $1/\epsilon$~of its original value after passing over a distance~$1/\beta$; +if $\beta$ were negative the disturbance would increase indefinitely +as it travelled along the wire. Substituting the value of~$\alpha$, we +see that the velocity of propagation of the phases is +\[ +\left\{\frac{2p}{\smallbold{R}\Gamma} \right\}^{\frac{1}{2}}; +\] +%% -----File: 286.png---Folio 272------- +\index{Alternating currents, of long period@\subdashtwo of long period, rate of decay along a wire}% +thus the velocity of propagation is directly proportional to the +square root of the frequency and inversely proportional to the +square root of the product of the resistance and capacity of +the wire per unit length. +}%end \allowdisplaybreaks + +\index{Distance alternating currents travel along a wire}% +\index{Decay, rate of, of slowly alternating currents along a wire}% +\index{Rate of decay of slowly alternating currents along a wire}% +The distance to which a disturbance travels before falling to +$1/\epsilon$~of its original value is, on substituting the value of~$\beta$, seen +to be +\[ +\left\{\frac{2}{\smallbold{R}\Gamma p}\right\}^{\frac{1}{2}}; +\] +thus the distance to which a disturbance travels is inversely +proportional to the square root of the product of the frequency, +the resistance, and capacity per unit length. + +If we take the case of a cable transmitting telephone messages +of such a kind that~$2\pi/p$, the period of the electrical vibrations, is +$1/100$~of a second, then if the copper core is $4$~millimetres in +diameter and the external radius of the guttapercha covering +about $2.5$~times that of the core, $\smallbold{R}$~is about $1.3 × 10^{-5}$~Ohms, or +in absolute measure $1.3 × 10^4$. $\Gamma$~is about $15 × 10^{-22}$. Substituting +these values for $\smallbold{R}$~and~$\Gamma$, we find that the vibrations will travel +over about $128$~kilometres before falling to $1/\epsilon$~of their initial +value. The velocity of propagation of the phases is about +$80,000$ kilometres per second. If we take an iron telegraph +wire $4$~mm.\ in diameter, $\smallbold{R}$~is about $9.4 × 10^4$; the capacity of +such a wire placed $4$~metres above the ground is stated by +Hagenbach (\textit{Wied. Ann.}~29.\ p.~377, 1886) to be about $10^{-22}$ +per centimetre, hence the distance to which electrical vibrations +making $100$~vibrations per second would travel before falling to +$1/\epsilon$~of their original value would be $\{1.3 × 15/9.4\}^{\frac{1}{2}}$, or $1.43$~times +the distance in the preceding case: thus the messages along the +aerial wire would travel about half as far again as those along +the cable, the increased resistance of the iron telegraph wire +being more than counterbalanced by the smaller electrostatic +capacity. Since vibrations of different frequencies die away at +different rates, a message such as a telephone message which is +made up of vibrations whose frequencies extend over a somewhat +wide range will lose its character as soon as there is any +appreciable decay in the vibrations. We see from this investigation +that the lower the pitch the further will the vibrations +travel, so that when a piece of music is transmitted along a +telephone wire the high notes suffer the most. +%% -----File: 287.png---Folio 273------- + +\Article{264} We shall now proceed to consider the expressions when +$n\smallbold{a}$~is small for the electromotive intensity and magnetic induction +in the wire and dielectric in terms of the total current +flowing through any cross section of the wire. + +We have seen that +\begin{DPgather*} +m = -\{p\smallbold{R}\Gamma\}^{\frac{1}{2}} \left\{\frac{1}{\sqrt{2}} %[TN: surd changed to sqrt for consistency] +- \frac{\iota}{\sqrt{2}}\right\}, \\ +\lintertext{hence if} \alpha = \left\{\tfrac{1}{2} p\smallbold{R}\Gamma\right\}^{\frac{1}{2}}, +\end{DPgather*} +we may suppose that the current through the wire at~$z$ is equal to +\[ +I_0\epsilon^{-\alpha z} \cos{(-\alpha z+pt)}. +\] +\begin{DPgather*} +\lintertext{This is equal to} \int_0^\smallbold{a} \frac{R}{\sigma} 2\pi r\,dr, +\end{DPgather*} +so that in this case we find by equation~(\eqnref{262}{9}), since $J_0(\iota nr)$ can be +replaced by unity as $nr$~is small, +\[ +A = \frac{\sigma I_0}{\pi \smallbold{a}^2}, +\] +so that by~(\eqnref{262}{9}) we have approximately +\[ +R = \frac{\sigma I_0}{\pi \smallbold{a}^2}\, \epsilon^{-\alpha z} \cos{(-\alpha z+pt)}. +\] + +Thus the electromotive intensity, and therefore the current +parallel to~$z$, is uniformly distributed over the cross-section. The +electromotive intensity along the radius, $\{P^2 + Q^2\}^{\frac{1}{2}}$, is easily +found by equation~(\eqnref{262}{9}) to be +\[ +-\frac{\iota m}{2}\, \frac{\sigma I_0}{\pi \smallbold{a}^2}\, r\epsilon^{-\alpha z}\epsilon^{\iota(-\alpha z+pt)}. +\] + +Substituting the value of~$m$ and taking the real part, we see +that it is equal to +\[ +\left\{\frac{p\sigma\Gamma}{\pi \smallbold{a}^2}\right\} \frac{\sigma I_0}{2\pi \smallbold{a}^2}\, r\epsilon^{-\alpha z} \cos{\left(-\alpha z+pt+\frac{\pi}{4}\right)}, +\] +it is thus very small compared with the intensity along the +axis of the wire, so that in the wire the Faraday tubes are +approximately parallel to the axis of the wire. + +The magnetic induction in this case reduces approximately to +\[ +\frac{2\mu I_0}{\smallbold{a}^2}\, r\epsilon^{-\alpha z} \cos{(-\alpha z+pt)}. +\] +%% -----File: 288.png---Folio 274------- +In the dielectric, we have by equations (\eqnref{262}{7}),~(\eqnref{262}{13}), and~(\eqnref{262}{14}), +assuming that $kr$~is small, +\[ +R=\frac{\sigma}{\pi \smallbold{a}^2}\, I_0\left\{1-2V^2\Gamma \log{\frac{r}{\alpha}}\right\}\epsilon^{-\alpha z} \cos{(-\alpha z + pt)}, +\] +since from (\eqnref{262}{13})~and~(\eqnref{262}{14}) $D = 2\Gamma V^2A$. + +The electromotive intensity along the radius, $\{P^2 + Q^2\}^{\frac{1}{2}}$, is +equal to +\[ +2V^2\{\pi \smallbold{a}^2\Gamma /p\sigma\}^{\frac{1}{2}} \frac{\sigma}{\pi \smallbold{a}^2}\, \frac{1}{r}\, I_0\epsilon^{-\alpha z} \cos{\left(-\alpha z + pt - \frac{\pi}{4}\right)}. +\] +In this case the radial electromotive intensity is very large compared +with the tangential intensity, so that in the dielectric the +Faraday tubes are approximately at right angles to the wire. + +The resultant magnetic induction is equal to +\[ +\frac{2I_0}{r}\, \epsilon^{-\alpha z} \cos{(-\alpha z+pt)}. +\] + +\Article{265} The interpretation of~(\eqnref{262}{17}) is easy when $n\smallbold{a}$~is very small, +since in this case the first term inside the bracket is very large +compared with the second; as $n\smallbold{a}$~increases the discussion of the +equation becomes more difficult, since the second term in the +bracket is becoming comparable with the first. It will facilitate +the discussion of the equation if we consider the march of the +function $\iota n\smallbold{a}J_0(\iota n\smallbold{a})/J_0'(\iota n\smallbold{a})$. Perhaps the simplest way to do +this is to expand the function $xJ_0(x)/J_0'(x)$ in powers of~$x$. +Since $J_0(x)$~is a Bessel's function of zero order, we have +\[ +J_0''(x) + \frac{1}{x} J_0'(x) + J_0(x) = 0, +\] +\begin{DPalign*} +\lintertext{so that} \frac{xJ_0(x)}{J_0'(x)} & = -1 - \frac{xJ_0''(x)}{J_0'(x)} \\ + & = -1 - x \frac{d}{dx} \log {J_1(x)}, +\end{DPalign*} +since $J_0'(x) = -J_1(x)$, $J_1(x)$~being Bessel's function of the first +order. + +Let $0, x_1, x_2, x_3 \ldots$ be the positive roots of the equation +\begin{DPgather*} +J_1(x) = 0, \\ +\lintertext{then} J_1(x) = x\left(1-\frac{x^2}{x_1^2}\right)\left(1-\frac{x^2}{x_2^2}\right)\left(1-\frac{x^2}{x_3^2}\right)\ldots +\end{DPgather*} +%% -----File: 289.png---Folio 275------- +so that +\[ +\frac{d}{dx} \log {J_1(x)} = \frac{1}{x} - \frac{2x}{x_1^2\left(1-\dfrac{x^2}{x_1^2}\right)} - \frac{2x}{x_2^2\left(1-\dfrac{x^2}{x_2^2}\right)} - \ldots, +\] +and therefore +\begin{multline*} + x \frac{d}{dx} \log {J_1(x)} = 1 - \frac{2x^2}{x_1^2} \left(1 + \frac{x^2}{x_1^2} + \frac{x^4}{x_1^4} + \ldots\right) \\ + \shoveright{- \frac{2x^2}{x_2^2} \left(1 + \frac{x^2}{x_2^2} + \frac{x^4}{x_2^4} + \ldots\right) + \ldots} \\ +\shoveleft{\phantom{x \frac{d}{dx} \log {J_1(x)}} = 1 - 2x^2 \left(\frac{1}{x_1^2} + \frac{1}{x_2^2} + \frac{1}{x_3^2} + \ldots\right)} \\ + \qquad - 2x^4\left(\frac{1}{x_1^4} + \frac{1}{x_2^4} + \frac{1}{x_3^4} + \ldots\right) - \ldots. +\end{multline*} + +Thus if $S_n$~denotes the sum of the reciprocals of the $n$\textsuperscript{th}~powers +of the roots of the equation +\[ +J_1(x)/x = 0, +\] +we have +\[ +\frac{xJ_0(x)}{J_0'(x)} = -2 + 2S_2x^2 + 2S_4x^4 + 2S_6x^6 + \ldots. +\] + +Now the equation $J_1(x)/x = 0$, when expanded in powers of~$x$ +is, +\[ +1 - \frac{x^2}{2\centerdot4} + \frac{x^4}{2\centerdot4\centerdot4\centerdot6} - \frac{x^6}{2\centerdot4\centerdot4\centerdot6\centerdot6\centerdot8} + \ldots = 0. +\] + +Hence, if we calculate $S_2$,~$S_4$, $S_6$~\&c.\ by Newton's Rule, we find +\begin{gather*} +S_2 = \frac{1}{8}, \quad S_4 = \frac{1}{12×16}, \quad S_6 = \frac{1}{12×16^2}, \\ +S_8 = \frac{1}{12×15×16^2}, \quad S_{10} = \frac{13}{9×15×16^4}; +\end{gather*} +hence +\[ +\frac{xJ_0(x)}{J_0'(x)} = -2 + \frac{x^2}{4} + \frac{x^4}{96} + \frac{x^6}{1536} + \frac{x^8}{23040} + \frac{13x^{10}}{4423680} - \ldots, +\] +so that +\[ +\iota n\smallbold{a}\, \frac{J_0(\iota n\smallbold{a})}{J_0'(\iota n\smallbold{a})} = -2 - \frac{n^2\smallbold{a}^2}{4} + \frac{n^4\smallbold{a}^4}{96} - \frac{n^6\smallbold{a}^6}{1536} + \frac{n^8\smallbold{a}^8}{23040} - \frac{13n^{10}\smallbold{a}^{10}}{4423680}, +\] +%% -----File: 290.png---Folio 276------- +and since $n^2 = 4 \pi \mu \iota p / \sigma$ approximately, we have +\begin{align*} +\iota n \smallbold{a}\, \frac{J_0(\iota n \smallbold{a})}{J_0'(\iota n \smallbold{a})} &= -2 - \frac{1}{96} (4 \pi \mu p \smallbold{a}^2 / \sigma)^2 + \frac{1}{23040} (4 \pi \mu p \smallbold{a}^2 / \sigma)^4 \ldots \\ +&\phantom{-2} -\iota \left\{\frac{1}{4}(4 \pi \mu p \smallbold{a}^2 / \sigma) - \frac{1}{1536}(4 \pi \mu p\smallbold{a}^2 / \sigma)^3\right. \\ +&\phantom{-2 - \frac{1}{96} 4 \pi} + \left. \frac{13}{4423680} (4 \pi \mu p \smallbold{a}^2 / \sigma)^5 \ldots \right\}. \Tag{19} +\end{align*} + +The values of $\iota n \smallbold{a}\, J_0(\iota n \smallbold{a})/J_0'(\iota n \smallbold{a})$ for a few values of $4 \pi \mu p \smallbold{a}^2 / \sigma$ +are given in the following table:--- +\[ +\begin{array}{c@{\quad}||@{\quad}l} +\tablespaceup 4\pi\mu p \smallbold{a}^2/\sigma & +\iota n \smallbold{a} J_0(\iota n \smallbold{a})/J_0'(\iota n \smallbold{a})\tablespacedown\\ +\hline +\tablespaceup \PadTo[r]{9.9}{.5} & -2 \{1.001 + .062 \iota \}\\ + +\PadTo[l]{9.9}{1} & -2 \{1.005 + .125 \iota \}\\ + +1.5 & -2 \{1.012 + .186 \iota \}\\ + +\PadTo[l]{9.9}{2} & -2 \{1.021 + .25 \iota \}\\ + +2.5 & -2 \{1.032 + .31\iota \}\\ + +\PadTo[l]{9.9}{3} & -2 \{1.045 + .37\iota \}\tablespacedown +\end{array} +\] +From this table we see that even when $4 \pi \mu p \smallbold{a}^2 / \sigma$ is as large as +unity, we may still as an approximation put +\[ +\iota n \smallbold{a}\, J_0(\iota n \smallbold{a}) / J_0'(\iota n \smallbold{a}) +\] +equal to~$-2$, and $k^2$~will continue to be given by~(\eqnref{263}{18}). + +\Article{266} We must consider now the relative values of the terms +inside the bracket in~(\eqnref{263}{18}) when $n \smallbold{a}$~is comparable with unity. In +the case of aerial telegraph wires it is conceivable that there may +be cases in which though $n \smallbold{a}$~is not large $n' \smallbold{b}$~may be so; but +when this is the case we have by \artref{261}{Art.~261} +\[ +K_0(\iota n' \smallbold{b}) = -\iota K_0'(\iota n'\DPtypo{b}{\smallbold{b}}), +\] +so that since $n' \smallbold{b}$~is very large the second term inside the bracket +in equation~(\eqnref{263}{18}) will be small compared with the first, hence we +have +\[ +k^2 = -\frac{p}{V^2}\, \frac{\iota \sigma}{2 \pi \smallbold{a}^2}\, \frac{1}{\log(\smallbold{b} / \smallbold{a})}, +\] +which is the same value as in \artref{263}{Art.~263}. + +In all telegraph cables where the external conductor is +water, and in all but very elevated telegraph wires where the +external conductor is wet earth, the value of~$\sigma'$ will so greatly +exceed that of~$\sigma$ that unless $\smallbold{b}$~is more than a thousand times +%% -----File: 291.png---Folio 277------- +\index{Alternating currents, of moderate period@\subdashtwo of moderate period, rate of decay along a wire}% +\index{Decay, rate of, xof moderately rapid currents along a wire\subdashtwo of moderately rapid currents along a wire}% +\index{Rate of decay of tmoderately rapid currents@\subdashtwo of moderately rapid currents}% +as great as~$\smallbold{a}$, $n'\smallbold{b}$~will be very small if the value of~$n\smallbold{a}$ is comparable +with unity. In this case however by \artref{261}{Art.~261}, +\[ +\frac{K_0(\iota n'\smallbold{b})}{K_0'(\iota n'\smallbold{b})} = -\iota n'\smallbold{b} \log \frac{2\gamma}{\iota n'\smallbold{b}}, +\] +so that equation~(\eqnref{263}{18}) becomes +\[ +k^2 = \frac{p^2}{V^2}\, \left\{\frac{2\mu}{n^2\smallbold{a}^2} + \mu' \log \frac{2\gamma}{\iota n'\smallbold{b}}\right\} \frac{1}{\log(\smallbold{b}/\smallbold{a})}. +\] +Since $n'\smallbold{b}$~is very small while $n\smallbold{a}$~is comparable with unity, the +second term inside the brackets will be very large compared +with the first, hence this equation may be written +\begin{DPgather*} +k^2 = \frac{p^2}{V^2} \log {\frac{2\gamma}{\iota n'\smallbold{b}}}\, \frac{\mu'}{\log(\smallbold{b}/\smallbold{a})}; \Tag{20} \\ +\lintertext{or} m^2 = \frac{p^2}{V^2} \left\{1 + \log \frac{2\gamma}{\iota n'\smallbold{b}}\, \frac{\mu'}{\log(\smallbold{b}/\smallbold{a})} \right\}. \\ +\intertext{Thus approximately} +m^2 = \frac{p^2}{V^2} \log \frac{2\gamma}{\iota n'\smallbold{b}}\, \frac{\mu'}{\log(\smallbold{b}/\smallbold{a})}, \\ +\lintertext{and since} n'^2 = 4\pi\mu'\iota p/\sigma', \\ +m^2 = \tfrac{1}{2} \frac{p^2}{V^2} \left\{\log \frac{\sigma'\gamma^2}{\mu'\pi \smallbold{b}^2p} + \frac{\iota\pi}{2} \right\} \frac{\mu'}{\log(\smallbold{b}/\smallbold{a})}, +\end{DPgather*} +hence we have approximately +\[ +m = \frac{1}{\sqrt{2}}\, \frac{p}{V} \left\{\frac{\mu' \log \dfrac{\sigma'\gamma^2}{\mu'\pi \smallbold{b}^2p}}{\log(\smallbold{b}/\smallbold{a})}\right\}^{\frac{1}{2}} \left\{1 + \iota\frac{\pi}{4}\, \frac{1}{\log(\sigma'\gamma^2/\mu'\pi \smallbold{b}^2p)} \right\}, \Tag{21} +\] +where the plus sign has been taken so as to make the real +part of~$\iota m$ negative. This equation corresponds to a vibration +\index{Propagation velocity of xmoderately rapid currents along a wire@\subdashtwo of moderately rapid currents along a wire}% +\index{Velocity of propagation of moderately rapid currents along wires@\subdashtwo propagation of moderately rapid currents along wires}% +\index{Alternating currents, of moderate period@\subdashtwo of moderate period, velocity along a wire}% +whose phases are propagated with the velocity +\[ +V \left\{\frac{\log(\smallbold{b}^2/\smallbold{a}^2)}{\mu'\log(\sigma'\gamma^2/\mu'\pi \smallbold{b}^2p)} \right\}^{\frac{1}{2}}, +\] +and which fades away to $1/\epsilon$~of its original value after passing +over a distance +\index{Distance alternating currents travel along a wire}% +\[ +\frac{4}{\pi}\, \frac{V}{p\mu'^{\frac{1}{2}}} \{\log(\smallbold{b}^2/\smallbold{a}^2) × \log(\sigma'\gamma^2/\mu'\pi \smallbold{b}^2p)\}^{\frac{1}{2}}. +\] + +This case presents many striking peculiarities. In the first +%% -----File: 292.png---Folio 278------- +place we see that to our order of approximation both the velocity +of propagation of the phases and the rate of decay of the +vibrations are independent of the resistance of the wire. These +quantities depend somewhat on the resistance of the external +conductor, but only to a comparatively small extent even on +that, as $\sigma'$ only enters their expressions as a logarithm. The +velocity of propagation of the phases only varies slowly with the +frequency, as $p$ only occurs in its expression as a logarithm. +The rate of decay, \mbox{i.\hspace{0.1em}e.}\ the real part of~$\iota m$, is proportional to +the frequency and thus varies more rapidly with this quantity +than when $n\smallbold{a}$ is small, as in that case the rate of decay is +proportional to the square root of the frequency (\artref{263}{Art.~263}). +We see from the preceding investigation that for sending +periodic disturbances along a cable, the frequency being such as +to make $n'\smallbold{b}$ a very small quantity, we do not gain any appreciable +advantage by making the core of a good conductor +like copper rather than of an inferior one like iron \emph{unless} the +conditions are such as to make $n\smallbold{a}$ small compared with +unity. We see too that the distance to which the disturbance +travels before it falls to $1/\epsilon$~of its original value increases +with the resistance of the external conductor. We shall show +in a subsequent article that the heat produced per second +in the external conductor is very large compared with that +produced in the same time in the wire, thus the dissipation of +energy is controlled by the external conductor and not by the +wire. + +The preceding results will continue true as long as $n'\smallbold{b}$ is +small, even though the frequency of the electrical vibrations gets +so large that $n\smallbold{a}/\mu$ is a very large quantity; for when $n\smallbold{a}$ is large +we have by \artref{261}{Art.~261}, +\[ +J_0'(\iota n\smallbold{a}) = -\iota J_0(\iota n\smallbold{a}), +\] +so that equation~(\eqnref{262}{16}) becomes +\[ +k^2 = \frac{p^2}{V^2} \left\{\frac{\mu}{n\smallbold{a}} + \mu' \log \frac{2\gamma}{\iota n'\smallbold{b}} \right\} \frac{1}{\log(\smallbold{b}/\smallbold{a})}. +\] +Since $n\smallbold{a}/\mu$ is large and $n'\smallbold{b}$ small the second term inside the +bracket is large compared with the first, so that we get the same +value of~$k^2$ as that given by equation~(\eqnref{266}{20}). + +\Article{267} The next case we have to consider is that in which both +%% -----File: 293.png---Folio 279------- +\index{Alternating currents, of short period@\subdashtwo of short period, rate of decay along a wire}% +\index{Alternating currents, of short period@\subdashtwo of short period, velocity of along a wire}% +\index{Decay, rate of, xof very rapid currents along a wire@\subdashtwo of very rapid currents along a wire}% +\index{Distance alternating currents travel along a wire}% +\index{Propagation velocity of yvery rapid currents along a wire@\subdashtwo of very rapid currents along a wire}% +\index{Rate of decay of very rapid currents@\subdashtwo of very rapid currents}% +\index{Velocity of propagation of very rapid currents along wires@\subdashtwo propagation of very rapid currents along wires}% +$n\smallbold{a}$ and $n'\smallbold{b}$ are very large; when this is the case we know by +\artref{261}{Art.~261} that +\[ +J'_0 (\iota n\smallbold{a}) = - \iota J_0 (\iota n\smallbold{a}), \quad K'_0 (\iota n'\smallbold{b}) = \iota K_0 (\iota n'\smallbold{b}). +\] +Making these substitutions, equation~(\eqnref{262}{17}) becomes +\begin{DPgather*} +k^2 = \frac{p^2}{V^2} \left\{\frac{\mu}{n\smallbold{a}} + \frac{\mu'}{n'\smallbold{b}} \right\} \frac{1}{\log(\smallbold{b}/\smallbold{a})}, \Tag{22}\\ +\lintertext{or} +\begin{aligned} + [t]m^2 & = \frac{p^2}{V^2} \left\{1 + \left(\frac{\mu}{n\smallbold{a}} + \frac{\mu'}{n'\smallbold{b}}\right) + \frac{1}{\log(\smallbold{b}/\smallbold{a})} \right\} \\ + & = \frac{p^2}{V^2} \left\{1 - \frac{\iota}{\sqrt {8\pi p}} + \left( \sqrt{\frac{\mu \sigma}{\smallbold{a}^2}} + \sqrt{\frac{\mu'\sigma'}{\smallbold{b}^2}} \right) + \frac{1}{\log(\smallbold{b}/\smallbold{a})} \right\} +\end{aligned} +\end{DPgather*} +approximately. Since the second term inside the bracket is small +compared with unity, extracting the square root we have, +\[ +m = - \frac{p}{V} \left\{1 - \frac{\iota}{\sqrt {32\pi p}} + \left( \sqrt{\frac{\mu\sigma}{\smallbold{a}^2}} + \sqrt{\frac{\mu'\sigma'}{\smallbold{b}^2}} \right) + \frac{1}{\log(\smallbold{b}/\smallbold{a})} \right\}. \Tag{23} +\] + +This represents a vibration travelling approximately with the +velocity~$V$ and dying away to $1/\epsilon$~of its initial value after traversing +a distance +\[ +4V \sqrt\frac{2\pi}{p} \left\{\sqrt\frac{\mu\sigma}{\smallbold{a}^2} + \sqrt\frac{\mu'\sigma'}{\smallbold{b}^2} \right\}^{-1} \log(\smallbold{b}/\smallbold{a}). +\] + +Since the imaginary part of~$m$ is small compared with the real +part, the vibration will travel over many wave lengths before +its amplitude is appreciably reduced. From the expression for +the rate of decay in this case we see that when the wire is +surrounded by a very much worse conductor than itself, as is +practically always the case with cables, the distance to which +these very rapid oscillations will travel will be governed mainly +by the outside conductor, and will be almost independent of the +resistance and permeability of the wire; no appreciable advantage +therefore would in this case be derived by using a well-conducting +but expensive material like copper for the wire. In +aerial wires the decay will be governed by the conductivity of +the earth rather than by that of the wire, unless the height of +the wire above the ground, which we may take to be comparable +with $\smallbold{b}$, is so great that $\mu'\sigma'/\smallbold{b}^2$ is not large compared with $\mu\sigma/\smallbold{a}^2$. + +Experiments which confirm the very important conclusion +that these rapid oscillations travel with the velocity~$V$, that is +%% -----File: 294.png---Folio 280------- +with the velocity of light through the dielectric, will be described +in the \chapref{Chapter V.}{next chapter}. + +\Article{268} As rapidly alternating currents are now very extensively +employed, it will be useful to determine the components of +the electromotive intensity both in the wire and in the dielectric +in terms of the total current passing through the wire. Let this +current at the point~$z$ and time~$t$ be represented by the real +part of $I_0 \epsilon^{\iota(mz+pt)}$. The line integral of the magnetic force +taken round any circuit is equal to $4\pi$~times the current through +that circuit. Now by equation~(\eqnref{262}{10}) the magnetic force at the +surface of the wire is +\[ +\frac{4\pi \iota}{\sigma n} A J_0' (\iota n \smallbold{a}) \epsilon^{\iota(mz+pt)}. +\] +Since the line integral of this round the surface of the wire is +equal to $4 \pi I_0 \epsilon^{\iota(mz+pt)}$, we have +\[ +A = - \frac{\iota\sigma n}{2\pi \smallbold{a}} \frac{I_0}{J'_0(\iota n\smallbold{a})}. +\] +Substituting this value for $A$ in equation~(\eqnref{262}{9}), we find that in the +wire +\[ +R = - \frac{\iota\sigma n}{2\pi \smallbold{a}} \frac{I_0}{J'_0(\iota n\smallbold{a})} J_0(\iota nr)^{\epsilon^{\iota(mz+pt)}}; \Tag{24} +\] +where the real part of the expression on the right-hand side is to +be taken. When $n\smallbold{a}$ and $nr$ are very large, we have by \artref{261}{Art.~261} +\[ +J_0'(\iota n\smallbold{a}) = - \iota \frac{\epsilon^{n\smallbold{a}}}{\sqrt{2\pi n\smallbold{a}}}, + \quad J_0(\iota nr) = \frac{\epsilon^{nr}}{\sqrt{2\pi nr}}; +\] +substituting these values in~(\eqnref{268}{24}), we find +\begin{DPgather*} +R = \left\{\frac{\mu p\sigma}{\pi \smallbold{a}r} \right\}^{\frac{1}{2}} + I_0 \epsilon^{-\{2\pi\mu p/\sigma\}^{\frac{1}{2}} (\smallbold{a}-r)} \cos(\psi), \Tag{25} \\ +\lintertext{where} \psi = mz + pt - (2 \pi\mu p/\sigma)^{\frac{1}{2}} (\smallbold{a}-r) + \frac{\pi}{4}. +\end{DPgather*} + +Similarly, we find by equation~(\eqnref{262}{9}) that the radial electromotive +intensity $(P^2 + Q^2)^{\frac{1}{2}}$ is given by the equation +\[ +\{P^2 + Q^2\}^{\frac{1}{2}} = - \frac{p}{V} \frac{\sigma I_0}{2\pi \sqrt{\smallbold{a}r}} + \epsilon^{-\{2\pi\mu p/\sigma\}^{\frac{1}{2}}(\smallbold{a}-r)} \sin{\left(\psi-\frac{\pi}{4}\right)}. \Tag{26} +\] + +The resultant magnetic force is by equation~(\eqnref{262}{10}) equal to +\[ +\frac{2}{\sqrt{\smallbold{a}r}} I_0\epsilon^{-\{2\pi\mu p/\sigma\}^{\frac{1}{2}}(\smallbold{a}-r)} \cos{\left(\psi-\frac{\pi}{4}\right)}. +\] +%% -----File: 295.png---Folio 281------- + +Since all these expressions contain the factor $\epsilon^{-(2\pi\mu p/\sigma)^{\frac{1}{2}} (\smallbold{a}-r)}$, +\index{Alternating currents, flow to surface of conductors@\subdashtwo flow to surface of conductors}% +\index{Electric skin@\subdashone `skin'}% +\index{Skin@`Skin', electrical}% +we see that the magnitudes of the electromotive intensity and of +the magnetic force must, since $n\smallbold{a}$---and therefore $(2\pi\mu p/\sigma)^{\frac{1}{2}}\smallbold{a}$---is +by hypothesis very large, diminish very rapidly as the distance +from the surface of the wire increases. The maximum values of +these quantities at the distance $(\sigma/2\pi\mu p)^{\frac{1}{2}}$ from the surface are +only $1/\epsilon$~of their values at the boundary, and they diminish +in geometrical progression as the distance from the surface +increases in arithmetical progression. Thus the currents and +magnetic forces are, as in \artref{258}{Art.~258}, practically confined to a skin +on the outside of the wire. We have taken $(\sigma/2\pi\mu p)^{\frac{1}{2}}$ as the +measure of the thickness of this `skin.' For currents making +$100$~vibrations per second, the skin for soft iron having a +magnetic permeability of~$1000$ is about half a millimetre thick, +for copper it is about thirteen times as great. For currents +making a million vibrations per second, such as can be produced +by discharging Leyden jars, the thickness of the skin for soft iron---since +we know that this substance retains its magnetic properties +even in these very rapidly alternating magnetic fields (J.~J. +Thomson, \textit{Phil.\ Mag.}\ Nov.~1891, p.~460)---is about $1/200$~of a +millimetre, for copper it is about $1/15$~of a millimetre. In these +cases there is enormous concentration of the current, and since +the currents produced by the discharge of a Leyden jar, though +they only last for a short time, are very intense whilst they last, +the condition of the outer layers of the wires whilst the discharge +is passing through them is very interesting, as they are conveying +currents of enormously greater density than would be +sufficient to melt them if the currents were permanent instead of +transient. + +This concentration of the current, or `throttling' as it is sometimes +called, produces a great increase in the apparent resistance +of the wire, since it reduces so largely the area which is available +for the passage of the current. If in equation~(\eqnref{268}{25}) we put $r = \smallbold{a}$, +we get maximum value of $R = (\mu p\sigma/\pi \smallbold{a}^2)^{\frac{1}{2}} ×{}$(maximum value of +the current through the wire), thus we may look upon $(\mu p\sigma/\pi \smallbold{a}^2)^{\frac{1}{2}}$ +as the apparent resistance per unit length of the wire to these +alternating currents. This resistance increases indefinitely with +the rate of alternation of the current; we see too that it is +inversely proportional to the circumference of the wire instead +of to the area as for steady currents. This is what we should +%% -----File: 296.png---Folio 282------- +expect, since the currents are concentrated in the region of the +circumference. The resistance of the solid wire to these alternating +currents is the same as that to steady currents of a tube +of the same material, the outside of the tube coinciding with +the outside of the wire, and the thickness of the tube being +$1/\sqrt{2}$~times the thickness of the skin. + +We see by comparing equations (\eqnref{268}{25})~and~(\eqnref{268}{26}) that the electromotive +intensity parallel to the axis of the wire is very large +compared with the radial electromotive intensity in the wire, so +that in the wire the Faraday tubes are approximately parallel +to its axis. + +\Article{269} Let us now consider the expressions for the electromotive +intensities and magnetic force in the dielectric; we find by +equations (\eqnref{262}{8})~and~(\eqnref{268}{24}), assuming~$k\smallbold{a}$ and~$k\smallbold{b}$ small, $n\smallbold{a}$,~$n'\smallbold{b}$ large, +\[ +D = 2\iota V^2 k^2 I_0/p. +\] +Hence, using~(\eqnref{267}{22}), we have in the dielectric when $kr$~is small, +\begin{DPgather*} +R = \left\{\left(\frac{\mu p\sigma}{\pi \smallbold{a}^2}\right)^{\frac{1}{2}} + - \left[ \left(\frac{\mu p\sigma}{\pi \smallbold{a}^2}\right)^{\frac{1}{2}} + + \left(\frac{\smash{\mu'}p\smash{\sigma'}}{\pi \smallbold{b}^2}\right)^{\frac{1}{2}}\right] + \frac{\log r/\smallbold{a}}{\log \smallbold{b}/\smallbold{a}} \right\} I_0 \cos{\phi}, \\ +\lintertext{\rlap{where}} \phi = mz + pt + \frac{\pi}{4}, +\end{DPgather*} +while the radial electromotive intensity is +\[ +\frac{2VI_0}{r} \cos{(mz + pt)}, +\] +and the resultant magnetic force +\[ +\frac{2I_0}{r} \cos{(mz + pt)}. +\] + +\index{Momentum of Faraday tubes}% +We see that the maximum value of the radial electromotive +intensity is very great compared with that of the tangential, so +that in the dielectric the Faraday tubes are approximately radial. +The momentum due to these tubes is, by \artref{12}{Art.~12}, at right +angles both to the tubes and the magnetic force, so that in the +dielectric it is parallel to the axis of the wire, while in the wire +itself it is radial. Thus for these rapidly alternating currents +the momentum in the dielectric follows the wire. The radial +polarization in the dielectric is $K/4\pi$~times the radial electromotive +intensity, and since +\[ +K = 1/V^2, +\] +%% -----File: 297.png---Folio 283------- +it is equal to +\[ +\frac{I_0}{2\pi Vr} \cos{(mz + pt)}. +\] +If the Faraday tubes in the dielectric are moving with velocity~$V$ +at right angles to their length, i.e.~parallel to the wire, the +magnetic force due to these moving tubes is, by \artref{9}{Art.~9}, at right +angles both to the direction of motion, i.e.~to the axis of the +wire, and to the direction of the tubes, i.e.~to the radius, and +the magnitude of the magnetic force being, by~(\eqnref{9}{4}), \artref{9}{Art\DPtypo{}{.}~9}, $4\pi V$~times +the polarization, is +\[ +\frac{2I_0}{r} \cos{(mz + pt)}, +\] +which is the expression we have already found. Hence we may +regard the magnetic force in the field as due to the motion +through it of the radial Faraday tubes, these moving parallel to +the wire with the velocity with which electromagnetic disturbances +are propagated through the dielectric. + +In the outer conductor when $n'r$~is large +\begin{DPgather*} +R = -I_0 \left\{\frac{\mu'p\sigma'}{\pi \smallbold{b}r} \right\}^\frac{1}{2} + \epsilon^{-(2\pi\mu'p/\sigma')^{\frac{1}{2}}(r-\smallbold{b})} \cos{\phi'}, \\ +\lintertext{where} \phi' = mz + pt -(2\pi\mu'p/\sigma')^{\frac{1}{2}} + \frac{\pi}{4}. +\end{DPgather*} +The radial electromotive intensity is +\[ +\frac{1}{2\pi}\, \frac{p}{V}\, \frac{\sigma'I_0}{\sqrt{\smallbold{b}r}} + \epsilon^{-(2\pi\mu'p/\sigma')^{\frac{1}{2}} (r-\smallbold{b})} + \cos{\left(\phi' + \frac{\pi}{4}\right)}. +\] + +The resultant magnetic force is perpendicular to~$r$ and equal to +\[ +\frac{2I_0}{\sqrt{\smallbold{b}r}}\, + \epsilon^{-(2\pi\mu'p/\sigma')^{\frac{1}{2}} (r-\smallbold{b})} + \cos{\left(\phi' - \frac{\pi}{4}\right)}. +\] + +We see from these equations that unless $p\sigma'$ is comparable +with~$V^2$ the tangential electromotive intensity will be large +compared with the radial. + + +\Subsection{Transmission of Arbitrary Disturbances along Wires.} +\index{Disturbance, electric, transmission of along a wire}% + +\Article{270} Since vibrations with different periods travel at different +rates, we cannot without further investigation determine the +rate at which an arbitrary disturbance communicated to a +%% -----File: 298.png---Folio 284------- +limited portion of the wire will travel along it. In order to +deduce an expression which would represent completely the +way in which an arbitrary disturbance is propagated, we should +have to make use of the general relation between $m$~and~$p$ given +by equation~(\eqnref{263}{18}). This relation is however too complicated to +allow of the necessary integrations being effected. The complication +arises from the vibrations whose frequencies are so +great that $2\pi \mu p \smallbold{a}^2 / \sigma$ is no longer a small quantity; such vibrations +however die away more rapidly than the slower ones, +so that when the distance from the origin of disturbance is considerable +the latter are the only vibrations whose effects are felt. +For such vibrations, we have by \artref{263}{Art.~263} +\[ +\iota p = -\frac{m^2}{\smallbold{R}\Gamma}. +\] + +{\allowdisplaybreaks +Hence a term in the expression for~$R$ of the form +\[ +F(\alpha)\, \epsilon^{-\frac{m^2}{\smallbold{R}\Gamma} t} \cos m (z-\alpha), +\] +where $\alpha$ is any constant and $F(\alpha)$~denotes an arbitrary function +of~$\alpha$, will satisfy the electrical conditions. By Fourier's theorem, +however, +\[ +\frac{1}{2\pi} \int_{-\infty}^{+\infty} \int_{-\infty}^{+\infty} + F(\alpha)\, \epsilon^{-\frac{m^2}{\smallbold{R}\Gamma} t} \cos m(z-\alpha)\,dm\,d\alpha, \Tag{27} +\] +is equal to~$F(z)$ when $t = 0$. Hence this integral, since it +satisfies the equations of the electric field, will be the expression +for the disturbance on the wire at~$z$ at the time~$t$ of the disturbance, +which is equal to~$F(z)$ when $t = 0$. When the disturbance +is originally confined to a space close to the origin, $F(\alpha)$~vanishes +unless $\alpha$~is very small; the expression~(\eqnref{270}{27}) becomes in this case +\begin{DPgather*} +\smallbold{F} \int_{-\infty}^{+\infty} \epsilon^{-\frac{m^2}{\smallbold{R}\Gamma} t} \cos mz\,dm, \Tag{28} \\ +\lintertext{where} \smallbold{F} = \int F(\alpha)\,d\alpha. \\ +\lintertext{\indent Since} +\int_{-\infty}^{+\infty} \epsilon^{-\alpha^2x^2} \cos 2\,bx\,dx + = \frac{\sqrt\pi}{\alpha}\, \epsilon^{-\frac{b^2}{\alpha^2}}, +\end{DPgather*} +we see by~(\eqnref{270}{28}) that the disturbance at time~$t$ and place~$z$ will +be equal to +\[ +\smallbold{F}\{\pi \smallbold{R} \Gamma/t\}^{\frac{1}{2}} \epsilon^{-z^2 \smallbold{R}\Gamma/4t^2}. \Tag{29} +\] +}%end \allowdisplaybreaks +%% -----File: 299.png---Folio 285------- + +Thus at a given point on the wire the disturbance will vary as +\[ +\frac{1}{\sqrt{t}}\, \epsilon^{-\frac{c}{t}}, +\] +where $c$ is a constant. The rise and fall of the disturbance with +the time is represented in \figureref{fig108}{Fig.~108}, where the ordinates represent +the intensity of the disturbance and the abscissae the time. It +will be noticed that the disturbance remains very small until $t$ +approaches~$c/4$, when it begins to increase with great rapidity, +reaching its maximum value when $t = 2c$; when $t$~is greater +than this the disturbance diminishes, but fades away from its +maximum value much more slowly than it approached it. + +\includegraphicsmid{fig108}{Fig.~108.} + +Since the disturbance rises suddenly to its maximum value we +may with propriety call~$T$, the time which elapses before this +value is attained at a given point, the time taken by the disturbance +to travel to that point. We see from~(\eqnref{270}{29}) that +\[ +T = \tfrac{1}{2} z^2 \smallbold{R}\Gamma. \Tag{30} +\] +Thus the time taken by the disturbance to travel a distance~$z$ +is proportional to~$z^2$, it is also proportional to the product of +the resistance and capacity per unit length. +%% -----File: 300.png---Folio 286------- + +By dividing $z$ by~$T$ we get the so-called `velocity of the +current along the wire;' this by~(\eqnref{270}{30}) is equal to +\[ +\frac{2}{z \smallbold{R} \Gamma}. \Tag{31} +\] + +The velocity thus varies inversely as the length of the cable, +and for short lengths it may be very great. The preceding formula +would in fact, unless $z$~were greater than $2 / V \smallbold{R} \Gamma$, indicate a +velocity of propagation greater than~$V$. This however is impossible, +and the error arises from our using the equation +$\iota p = -m^2 / \smallbold{R} \Gamma$ instead of the accurate equation~(\eqnref{263}{18}). By our +approximate equation vibrations of infinite frequency travel +with infinite velocity, in reality we have seen (\artref{267}{Art.~267}) that +they travel with the velocity~$V$. These very rapid vibrations +however die away very quickly, and when we get to a distance +equal to a small multiple of $2 / V \smallbold{R} \Gamma$ they will practically have +disappeared, and at such distances we may trust the expressions~(\eqnref{270}{31}). + +A considerable number of experiments have been made on the +time required to transmit messages on both aerial and submarine +cables; the results of some of these, made on aerial telegraph iron +wires $4$~mm.\ in diameter, are given in the accompanying table +\index{Hagenbach, transmission of signals along wires}% +taken from a paper by Hagenbach (\textit{Wied.\ Ann.}~29.\ p.~377):--- +\begin{center} +\tabletextsize +\begin{tabular}{@{}l@{\;}|c|c|c@{}} +\hline +\settowidth{\TmpLen}{Plantamour and Hirsch}% +\parbox[c]{\TmpLen}{\centering Observer.} & +\settowidth{\TmpLen}{Length of line} +\parbox[c]{\TmpLen}{\centering Length of line\\ in kilometers.} & +\settowidth{\TmpLen}{Time taken for message}% +\parbox[c]{\TmpLen}{\centering Time taken for message\\ to travel ($T$.)} & +\settowidth{\TmpLen}{$10^{20} T$/(square of}% +\parbox[c]{\TmpLen}{\tablespaceup\centering $10^{20} T$/(square of\\ +length of line in\\ +centimetres).\tablespacedown}\\ +\hline +\tablespaceup Fizeau and Gounelle\mdotfill & $314$ & $.003085$ & $313$\\ +Walker\mdotfill & $885$ & $.02943\Z$ & $376$\\ +Mitchel\mdotfill & $977$ & $.02128\Z$ & $223$\\ +Gould and Walker\mdotfill & $\llap{$1$}681$ & $.07255\Z$ & $257$\\ +Guillemin \mdotfill & $\llap{$1$}004$ & $.028\Z\Z\Z$ & $278$\\ +Plantamour and Hirsch & $132\rlap{$.6$}$ & $.00895\Z$ & $\llap{$5$}090$\\ +Löwy and Stephan\mdotfill & $863$ & $.024\Z\Z\Z$ & $322$\\ +Albrecht \mdotfill & $\llap{$1$}230$ & $.059\Z\Z\Z$ & $390$\\ +Hagenbach\mdotfill & $284\rlap{$.8$}$ & $.00176\Z$ & $217$\tablespacedown\\ +\hline +\end{tabular} +\end{center} + +Hagenbach proved by making experiments with lines of +different lengths that the time taken by a message to travel +along a line was proportional to the square of the length of the +line. + +If we apply the formula +\[ +T = \tfrac{1}{2} z^2 R \Gamma +\] +%% -----File: 301.png---Folio 287------- +to Hagenbach's experiment in the above table, where +\begin{DPalign*} +z & = 284.8 × 10^5, \\ +R & = \Z\Z9.4 × 10^4, \\ +\lintertext{and (by estimation)} +\Gamma & = 10^{-22}, +\end{DPalign*} +we find $T = .0038$, whereas Hagenbach found~$.0017$. The agreement +is not good, but we must remember that with delicate +receiving instruments it will be possible to detect the disturbance +before it reaches its maximum value, so that we should +expect the observed time to be less than that at which the effect +is a maximum. In Hagenbach's experiment the line was about +$4$~times the length which, according to the formula, would have +made the disturbance travel with the velocity of light, so that +it would seem to have been long enough to warrant the application +of a formula which assumes that the shorter waves +would have become so reduced in amplitude that their effects +might be neglected. + +When the wire is of length~$l$, we know by Fourier's Theorem +that any initial disturbance~$R$ may be represented by the +equation +\begin{multline*} +R = \Bigl(A_1 \sin{\frac{\pi z}{l}} + B_1 \cos{\frac{\pi z}{l}}\Bigr) + + \Bigl(A_2 \sin{\frac{2\pi z}{l}} + B_2 \cos{\frac{2\pi z}{l}}\Bigr) \\ + + \Bigl(A_3 \sin{\frac{3\pi z}{l}} + B_3 \cos{\frac{3\pi z}{l}}\Bigr) + \ldots. +\end{multline*} +\begin{DPgather*} +\lintertext{\indent Since} \iota p = -m^2/\smallbold{R}\Gamma, +\end{DPgather*} +the value of~$R$ after a time~$t$ has elapsed will be represented by +the equation +\begin{multline*} +R = \Bigl(A_1 \sin{\frac{\pi z}{l}} + B_1 \cos{\frac{\pi z}{l}}\Bigr) \epsilon^{-\frac{\pi^2}{l^2}\, \frac{t}{\smallbold{R}\Gamma}} \\ + + \Bigl(A_2 \sin{\frac{2\pi z}{l}} + B_2 \cos{\frac{2\pi z}{l}}\Bigr) \epsilon^{-\frac{4\pi^2}{l^2}\, \frac{t}{\smallbold{R}\Gamma}} + \ldots \\ + \ldots + \Bigl(A_s \sin{\frac{s\pi z}{l}} + B_s \cos{\frac{s\pi z}{l}}\Bigr) \epsilon^{-\frac{s^2\pi^2}{l^2}\, \frac{t}{\smallbold{R}\Gamma}} + \ldots. +\end{multline*} + +For a full discussion of the transmission of signals along +cables the reader is referred to a series of papers by Lord Kelvin +\index{Kelvin, Lord, transmission of an electric disturbance along a wire@\subdashtwo transmission of an electric disturbance along a wire}% +at the beginning of Vol.~II of his Collected Papers. +%% -----File: 302.png---Folio 288------- + +\Subsection{Relation between the External Electromotive Intensity +and the Current.} +\index{Current, connection between and external E.M.F.}% +\index{Electromotive intensity, relation between and current for alternating currents@\subdashtwo relation between and current for alternating currents}% +\index{Force relation between external electromotive force and alternating current@\subdashone relation between external electromotive force and alternating current}% + +\Article{271} We have hitherto only considered the total electromotive +intensity and have not regarded it as made up of two parts, one +due to external causes and the other due to the induction of the +alternating currents in the conductors and dielectric. For some +purposes, however, it is convenient to separate the electromotive +intensity into these two parts, and to find the relation between +the currents and the external electromotive intensity acting on +the system. + +We may conveniently regard the external electromotive +intensity as arising from an electrostatic potential~$\phi$ satisfying +the equation $\nabla^2 \phi = 0$. We suppose that, as in the preceding +investigation, all the variables contain the factor $\epsilon^{\iota(mz+pt)}$. Since +$\phi$~varies as~$\epsilon^{\iota mz}$, the equation $\nabla^2 \phi = 0$ is equivalent to +\[ +\frac{d^2\phi}{dr^2} + \frac{1}{r}\, \frac{d\phi}{dr} - m^2\phi = 0. +\] +The solution of this is, in the wire +\[ +\phi = LJ_0(\iota mr)\, \epsilon^{\iota(mz+pt)}, +\] +in the dielectric +\[ +\phi = \{MJ_0(\iota mr) + NK_0(\iota mr)\}\, \epsilon^{\iota(mz+pt)}, +\] +in the outer conductor +\[ +\phi = SK_0(\iota mr)\, \epsilon^{\iota(mz+pt)}. +\] +If, as before, $\smallbold{a}$~and~$\smallbold{b}$ are the radii of the internal and external +boundaries of the dielectric, we have, since $\phi$~is continuous, +\begin{align*} +LJ_0 (\iota m \smallbold{a}) & = MJ_0 (\iota m \smallbold{a}) + NK_0 (\iota m \smallbold{a}), \\ +SK_0 (\iota m \smallbold{b}) & = MJ_0 (\iota m \smallbold{b}) + NK_0 (\iota m \smallbold{b}). +\end{align*} +The excess of the normal electromotive intensity due to the +electrostatic potential in the dielectric over that in the wire is +equal to +\[ +\iota m \{LJ'_{0}(\iota m \smallbold{a}) + - (MJ'_{0}(\iota m \smallbold{a}) + + NK'_{0}(\iota m \smallbold{a})\DPtypo{}{)}\}\, \epsilon^{\iota(mz+pt)}; +\] +substituting the value for $L-M$ in terms of~$N$ from the preceding +equation, this becomes +\[ +\iota m \frac{N}{J_0(\iota m \smallbold{a})}\, + \{J'_{0}(\iota m \smallbold{a})\, K_0(\iota m \smallbold{a}) + - J_0(\iota m \smallbold{a})\, K'_{0}(\iota m \smallbold{a})\}. +\] +%% -----File: 303.png---Folio 289------- +\begin{DPgather*} +\lintertext{Now} +J'_0 (\iota m \smallbold{a})\, K_0 (\iota m \smallbold{a}) + - J_0 (\iota m \smallbold{a})\, K'_0 (\iota m \smallbold{a}) = \frac{1}{\iota m \smallbold{a}}, \\ +\lintertext{for let} +u = J_0'(x) K_0(x) - J_0(x) K_0'(x), \\ +\lintertext{then} +\frac{du}{dx} = J_0''(x) K_0(x) - J_0(x) K_0''(x), \\ +\lintertext{but} +J_0''(x) + \frac{1}{x} J_0'(x) - J_0(x) = 0, \\ +K_0''(x) + \frac{1}{x} K_0'(x) - K_0(x) = 0; +\end{DPgather*} +substituting the values of $J''_0(x)$, $K''_0(x)$ from these equations, +we find +\begin{DPgather*} +\begin{aligned} +\frac{du}{dx} + &= -\frac{1}{x} \{J_0'(x) K_0(x) - J_0(x) K_0'(x)\} \\ + &= -\frac{u}{x}, +\end{aligned} \\ +\lintertext{hence} u = \frac{C}{x}, +\end{DPgather*} +where $C$~is a constant. Substituting from \artref{261}{Art.~261} the values +for $J_0(x)$, $J_0'(x)$, $K_0(x)$, $K_0'(x)$ when $x$~is very small, we find +that $C$~is equal to unity. + +Thus when $r = \smallbold{a}$, the normal electromotive intensity due to +the electrostatic potential in the dielectric exceeds that in the +wire by +\[ +\frac{N}{\smallbold{a}J_0(\iota m \smallbold{a})}\, \epsilon^{\iota(mz + pt)}. +\] + +Similarly we may show that when $r = \smallbold{b}$ the normal electromotive +intensity in the dielectric exceeds that in the outer +conductor by +\[ +-\frac{M}{\smallbold{b} K_0 (\iota m \smallbold{b})}\, \epsilon^{\iota(mz + pt)}. +\] + +Now the electromotive intensities arising from the induction +of the currents are continuous, so that the discontinuity in the +total normal intensity must be equal to the discontinuity in the +components arising from the electrostatic potential. By equations +(\eqnref{262}{7}),~(\eqnref{262}{9}),~(\eqnref{262}{14}) the total normal intensity in the dielectric +at the surface of separation exceeds that in the wire by +\[ +A \frac{m}{n} J_0' (\iota n \smallbold{a}) + \left\{\frac{n^2 - m^2}{\mu(k^2 - m^2)} - 1 \right\} \epsilon^{\iota (mz + pt)}; +\] +%% -----File: 304.png---Folio 290------- +hence we have +\[ +A \frac{m}{n} J_0'(\iota n \smallbold{a}) + \left\{\frac{n^2-m^2}{\mu(k^2-m^2)} - 1 \right\} + = \frac{N}{\smallbold{a}J_0(\iota m \smallbold{a})}. \Tag{32} +\] +Similarly +\[ +E \frac{m}{n'} K_0'(\iota n' \smallbold{b}) + \left\{\frac{(n'^2-m^2)}{\mu'(k^2-m^2)} - 1 \right\} + = -\frac{M}{\smallbold{b}K_0(\iota m \smallbold{b})}. \Tag{33} +\] + +By equations (\eqnref{262}{10})~and~(\eqnref{262}{12}) +\begin{align*} +& 2\pi \smallbold{a} \frac{n^2-m^2}{\mu p n}\, + AJ_0'(\iota n \smallbold{a})\, \epsilon^{\iota(mz + pt)}, \\ +& 2\pi \smallbold{b} \frac{n'^2-m^2}{\mu' p n'}\, + EK_0'(\iota n' \smallbold{b})\, \epsilon^{\iota(mz + pt)} +\end{align*} +are respectively the line integrals of the magnetic force round +the circumference of the wire and the inner circumference of +the outer conductor, hence they are respectively $4\pi$~times the +current through the wire, and $4\pi$~times the current through +the wire plus that through the dielectric. Unless however the +radius of the outer conductor is enormously greater than that of +the wire, the current through the wire is infinite in comparison +with that through the dielectric: for the electromotive intensity~$R$ +is of the same order in the wire and in the dielectric; the current +density in the wire is~$R/\sigma$, that in the dielectric $(K/4\pi)dR/dt$, +or~$K \iota p R/4\pi$, or~$\iota p R/4\pi V^2$. Now for metals $\sigma$~is of the order~$10^4$; +and since $V^2$~is $9 × 10^{20}$, we see that even if there are a +million alternations per second the intensity of the current in +the wire to that in the dielectric is roughly as $2 × 10^{11}$ is to +unity; thus, unless the area through which the polarization +currents flow exceeds that through which the conduction +currents flow in a ratio which is impracticable in actual experiments, +we may neglect the polarization currents in comparison +with the conduction ones, so that +\[ +\frac{\smallbold{a} (n^2-m^2)}{\mu n}\, AJ_0'(\iota n \smallbold{a}) + = \frac{\smallbold{b} (n'^2-m^2)}{\mu' n'}\, EK_0'(\iota n' \smallbold{b}). \Tag{34} +\] + +Returning to equations (\eqnref{271}{32})~and~(\eqnref{271}{33}), we notice that +\begin{DPgather*} +(m^2-n^2) / \mu(k^2-m^2),\\ +\lintertext{which is equal to} +4 \pi \iota V^2/\sigma p, +\end{DPgather*} +is very large when $\sigma p$~is small compared with~$V^2$. Now $\sigma$ for +%% -----File: 305.png---Folio 291------- +metals is of the order~$10^4$, and $V^2$~is equal to~$9 × 10^{20}$; so that unless +$p$ is of the order~$10^{16}$ at least, that is unless the vibrations are as +rapid as those of light, $(m^2-n^2)/\mu(m^2-k^2)$ is exceedingly large. +Even when the conductivity is no better than that of sea-water, +where $\sigma$ may be taken to be of the order~$10^{10}$, this quantity will +be very large unless there are more than a thousand million +vibrations per second. Hence in equations (\eqnref{271}{32})~and~(\eqnref{271}{33}) we +may neglect the second terms inside the brackets on the left-hand +sides, and write +\[ +\left. \begin{aligned} +A \frac{m}{n} \frac{(n^2-m^2)}{\mu(k^2-m^2)} J_0'(\iota n \smallbold{a}) + & = \frac{N}{\smallbold{a}J_0(\iota m \smallbold{a})}, \\ +E \frac{m}{n'} \frac{(n'^2-m^2)}{\mu'(k^2-m^2)} K_0'(\iota n' \smallbold{b}) + & = - \frac{M}{\smallbold{b}K_0(\iota m \smallbold{b})}; +\end{aligned}\right\} \Tag{35} +\] +hence by~(\eqnref{271}{34}), we have +\[ +\frac{N}{J_0(\iota m \smallbold{a})} = - \frac{M}{K_0(\iota m \smallbold{b})}. \Tag{36} +\] + +Let $\smallbold{E}$ be the external electromotive intensity parallel to the +axis of the wire at its surface, then +\begin{align*} +\smallbold{E} & = -\iota m \{MJ_0(\iota m \smallbold{a}) + NK_0(\iota m \smallbold{a})\} \epsilon^{\iota(mz+pt)}, +\intertext{or by equation~(\eqnref{271}{36})} +& = - \iota mN \{K_0(\iota m \smallbold{a}) - K_0(\iota m \smallbold{b}) \} \epsilon^{\iota(mz+pt)}. +\end{align*} + +Since both $m \smallbold{a}$~and~$m\smallbold{b}$ are very small, we have approximately +by \artref{261}{Art.~261}, +\[ +K_0(\iota m \smallbold{a}) = \log \frac{2\gamma}{\iota m \smallbold{a}}, \quad +K_0(\iota m \smallbold{b}) = \log \frac{2\gamma}{\iota m \smallbold{b}}, +\] +hence we have +\[ +\smallbold{E} = -\iota m N \log(\smallbold{b} / \smallbold{a}) \epsilon^{\iota(mz+pt)}, +\] +or by equation~(\eqnref{271}{35}), since $J_0(\iota m \smallbold{a}) = 1$, +\[ +\smallbold{E} = - \frac{\iota m^2 \smallbold{a}}{n}\, \frac{n^2-m^2}{\mu(k^2-m^2)}\, + J_0'(\iota n \smallbold{a}) \log(\smallbold{b} / \smallbold{a}) A \epsilon^{\iota(mz+pt)}. +\] + +But by \artref{263}{Art.~263} we have, if $I_0 \epsilon^{\iota(mz+pt)}$ is the total current +through the wire, +\[ +I_0 = \frac{2 \pi \smallbold{a} \iota}{\sigma n} A J_0'(\iota n \smallbold{a}), +\] +%% -----File: 306.png---Folio 292------- +\begin{DPalign*} +\lintertext{hence, since} +n^2 - m^2 & = 4 \pi \mu \iota p / \sigma, \\ +m^2 - k^2 & = p^2 / V^2 , +\end{DPalign*} +\[ +\smallbold{E} = 2 \iota p \frac{m^2}{\dfrac{p^2}{V^2}} + \log(\smallbold{b} / \smallbold{a}) \centerdot I_0 \epsilon^{\iota(mz+pt)}. +\] + +But by equation~(\eqnref{263}{18}) +\[ +m^2 = \frac{p^2}{V^2} + \left\{1 - \frac{1}{4 \pi p} + \left( \frac{n \sigma}{\smallbold{a}}\, \frac{J_0(\iota n \smallbold{a})}{J_0'(\iota n \smallbold{a})} + - \frac{n' \sigma'}{\smallbold{b}}\, \frac{K_0 (\iota n' \smallbold{b})}{K_0'(\iota n' \smallbold{b})} \right) + \frac{1}{\log \smallbold{b} / \smallbold{a}}\right\}, +\] +hence +\begin{multline*} +\smallbold{E} + = 2 \iota p \left\{\log \frac{\textbf{b}}{\textbf{a}} + - \frac{1}{4\pi p} \left( \frac{n \sigma}{\smallbold{a}}\, + \frac{J_0(\iota n \smallbold{a})}{J_0'(\iota n \smallbold{a})} \right.\right. \\ + \left. \left. - \frac{n' \sigma'}{\smallbold{b}}\, + \frac{K_0(\iota n' \smallbold{b})}{K_0'(\iota n' \smallbold{b})} \right) \right\} + I_0 \epsilon^{\iota(mz+pt)}.\qquad \Tag{37} +\end{multline*} + +\Article{272} Now, as in \artref{263}{Art.~263}, when both $n \smallbold{a}$~and~$n' \smallbold{b}$ are small, the +last term inside the bracket will be small compared with the +others; so that we may write equation~(\eqnref{271}{37}) in the form +\[ +\smallbold{E} = 2 \iota p \left\{\log \frac{\smallbold{b}}{\smallbold{a}} - \frac{1}{4 \pi p}\, + \frac{n \sigma}{\smallbold{a}}\, + \frac{J_0(\iota n \smallbold{a})}{J_0'(\iota n \smallbold{a})} \right\} I, +\] +where $I$ is the total current through the wire and is equal to +\[ +I_0 \epsilon^{\iota(mz+pt)}. +\] + +From the expressions for $\iota n \smallbold{a} J_0 (\iota n \smallbold{a}) / J_0'(\iota n \smallbold{a})$ given in +\artref{265}{Art.~265}, we see that we may write this equation +\begin{multline*} +\smallbold{E} = 2 \iota p \left\{\log\frac{\smallbold{b}}{\smallbold{a}} + + \frac{\sigma}{2 \pi \iota p \smallbold{a}^2} + \left[ 1 + \frac{1}{12 × 16} (4 \pi \mu p \smallbold{a}^2 / \sigma)^2 \right. \right. \\ + - \frac{1}{12 × 15 × 16^2} (4 \pi \mu p \smallbold{a}^2 / \sigma)^4 + \ldots + + \iota \left( \frac{1}{8} (4 \pi \mu p \smallbold{a}^2 / \sigma) \right. \\ + \left. \left. \left. + - \frac{1}{12 × 16^2} (4 \pi \mu p \smallbold{a}^2 / \sigma)^3 + + \frac{13}{9 × 15 × 16^4} (4 \pi \mu p \smallbold{a}^2 / \sigma)^5 + \ldots\right) \right] \right\} I, +\end{multline*} +\begin{DPgather*} +\lintertext{or} +\smallbold{E} = \iota p \left\{2 \log\frac{\smallbold{b}}{\smallbold{a}} + + \frac{1}{2} \mu - \frac{1}{48}\, \frac{\pi^2 \mu^3 p^2 \smallbold{a}^4}{\sigma^2} + + \frac{13}{8640}\, \frac{\pi^4 \mu^5 p^4 \smallbold{a}^8}{\sigma^4} \ldots\right\} I \\ + + \frac{\sigma}{\pi \smallbold{a}^2} + \left\{1 + \frac{1}{12}\, \frac{\pi^2 p^2 \mu^2 \smallbold{a}^4}{\sigma^2} + - \frac{1}{180}\, \frac{\pi^4 p^4 \mu^4 \smallbold{a}^8}{\sigma^4} \ldots\right\}I. \Tag{38} +\end{DPgather*} +We may write this as +\begin{DPgather*} +\smallbold{E} = \smallbold{P} \iota p I + \smallbold{Q}I, \Tag{39}\\ +%% -----File: 307.png---Folio 293------- +\lintertext{or since} +\iota pI = \frac{dI}{dt},\\ +\lintertext{as} +\smallbold{E} = \smallbold{P} \frac{dI}{dt} + \smallbold{Q}I. +\end{DPgather*} +\index{Alternating currents, expression for self-induction of a single wire@\subdashtwo expression for self-induction of a single wire|(}% +\index{Alternating currents, expression for `impedance' of a single wire@\subdashtwo expression for `impedance' of a single wire|(}% +\index{Heaviside, ximpedance@\subdashone impedance}% +\index{Impedance, expression for@\subdashone expression for|(}% +\index{Induction, self@\subdashone self, expressions for|(}% +\index{Self-induction, expression for, for variable currents}% + +If $L$ is the coefficient of self-induction and $R$~the resistance of +a circuit through which a current~$I$ is flowing, we have +\[ +\text{external electromotive force} = L \frac{dI}{dt} + RI. +\] + +By the analogy of this equation with~(\eqnref{272}{39}) we may call~$\smallbold{P}$ the self-induction +and $\smallbold{Q}$~the resistance of the cable per unit length for +these alternating currents. $\smallbold{Q}$~has been called the `impedance' of +\index{Impedance}% +unit length of the circuit by Mr.~Heaviside, and this term is +preferable to resistance as it enables the latter to be used exclusively +for steady currents. + +By comparing (\eqnref{272}{39})~with~(\eqnref{272}{38}), we see that +\[ +\left. +\begin{aligned} +\smallbold{P} &= 2 \log \frac{\smallbold{b}}{\smallbold{a}} + \frac{1}{2}\mu + - \frac{1}{48}(\mu^3 p^2 \pi^2 \smallbold{a}^4/\sigma^2) + + \frac{13}{8640}(\mu^5 p^4 \pi^4 \smallbold{a}^8 / \sigma^4) - \ldots,\\ +\smallbold{Q} &= \frac{\sigma}{\pi \smallbold{a}^2} + \left\{1 + \frac{1}{12}(\mu^2 p^2 \pi^2 \smallbold{a}^4/\sigma^2) + - \frac{1}{180}(\mu^4 p^4 \pi^4 \smallbold{a}^8/\sigma^4) + \ldots\right\}. +\end{aligned} +\right\}\eqnlabel{\eqnart.40}\nbtag{40} +\] + +These results are the same as those given in equation~(18), +Art.~690, of Maxwell's \textit{Electricity and Magnetism}, with the +exception that $\mu$~is put equal to unity in that equation and in it +$A$~is written instead of~$2 \log (\smallbold{b}/\smallbold{a})$. + +We see from these equations that as the rate of alternation +increases, the impedance increases while the self-induction +diminishes; both these effects are due to the influence of the rate +of alternation on the distribution of the current. As the rate of +alternation increases the current gets more and more concentrated +towards the surface of the wire; the effective area of the +wire is thus diminished and the resistance therefore increased. +On the other hand, the concentration of the current on the surface +of the wire increases the average distance between the portions +of the currents in the wire, and diminishes that between the +currents in the wire and those flowing in the opposite direction +in the outer conductor; both these effects diminish the self-induction +of the system of currents. + +The expression for~$\smallbold{Q}$ does not to our degree of approximation +%% -----File: 308.png---Folio 294------- +involve~$\smallbold{b}$ at all, while $\smallbold{b}$~only enters into the first term +of the expression for~$\smallbold{P}$, which is independent of the frequency; +thus, as long as $n\smallbold{a}$ is very small, the presence of the outer +conductor does not affect the impedance, nor the way in which +the self-induction varies with the frequency. When $p = 0$ the +self-induction per unit length is $2 \log(\smallbold{b}/\smallbold{a}) + \frac{1}{2} \mu$. Since $\mu$~for soft +iron may be as great as~$2000$, the self-induction per unit length +of straight iron wires will be enormously greater than that of +wires made of the \DPtypo{non-metallic}{non-magnetic} metals. + +\sloppy +\Article{273} We shall now pass on to the case when $n\smallbold{a}$~is large and +$n'\smallbold{b}$~small, so that $n\sigma J_0(\iota n\smallbold{a})/p\smallbold{a} J_0'(\iota n\smallbold{a})$ is small compared +with $n'\sigma'K_0(\iota n'\smallbold{b})/p\smallbold{b} K_0'(\iota n'\smallbold{b})$. These conditions are compatible +if the specific resistance of the outer conductor is very +much greater than that of the wire. In this case equation~(\eqnref{271}{37}) +becomes +\[ +\smallbold{E} = 2\iota p \left\{\log \frac{\smallbold{b}}{\smallbold{a}} + + \frac{1}{4\pi p}\, \frac{n'\sigma'}{\smallbold{b}}\, + \frac{K_0(\iota n'\smallbold{b})}{K_0'(\iota n'\smallbold{b})} \right\}I. +\] + +\fussy +Since $n'\smallbold{b}$ is small, we have approximately +\begin{DPgather*} +K_0(\iota n'\smallbold{b}) = \log(2\gamma/\iota n'\smallbold{b}), \quad +K_0'(\iota n'\smallbold{b}) = -1/\iota n'\smallbold{b}; \\ +\lintertext{hence} +\smallbold{E} = 2\iota p \left\{\log \smallbold{b}/\smallbold{a} + + \mu' \log(\gamma/\sqrt{\pi\mu'\smallbold{b}^2 p/\sigma'}) + - \iota 3\mu' \frac{\pi}{4} \right\}. +\end{DPgather*} +Thus the coefficient of self-induction in this case is +\begin{DPgather*} +2 \log(\smallbold{b}/\smallbold{a}) + 2\mu'\log(\gamma/\sqrt{\pi\mu'p\smallbold{b}^2/\sigma')}, \\ +\lintertext{\rlap{and the impedance}} +\tfrac{3}{2} \pi p\mu'. +\end{DPgather*} + +It is worthy of remark that to our order of approximation +neither the impedance nor the self-induction depends upon the +resistance of the wire. This is only what we should expect for +the self-induction, for since $n\smallbold{a}$~is large the currents will all be +on the surface of the wire; the configuration of the currents has +thus reached a limit beyond which it is not affected by the +resistance of the wire. It should be noticed that the conditions +$n\smallbold{a}$~large and $n'\smallbold{b}$~small make the impedance $\frac{3}{2} \pi p\mu'$ large compared +with the resistance $\sigma/\pi \smallbold{a}^2$ for steady currents. +%% -----File: 309.png---Folio 295------- + +\Subsection{Very Rapid Currents.} + +\Article{274} We must now consider the case where the frequency is so +great that $n\smallbold{a}$~and~$n'\smallbold{b}$ are very large; in this case, by \artref{261}{Art.~261}, +\[ +J_0' (\iota n\smallbold{a}) = -\iota J_0(\iota n\smallbold{a}), \quad +K_0' (\iota n'\smallbold{b}) = \iota K_0(\iota n'\smallbold{b}), +\] +so that equation~(\eqnref{271}{37}) becomes +\[ +\smallbold{E} = 2 \iota p \left\{\log \frac{\smallbold{b}}{\smallbold{a}} + + \left[ \Bigl( \frac{\sigma \mu}{4 \pi p \smallbold{a}^2} \Bigr)^{\frac{1}{2}} + + \Bigl( \frac{\sigma' \mu'}{4 \pi p \smallbold{b}^2} \Bigr)^{\frac{1}{2}} \right] + \Bigl( \frac{1}{\surd{2}} - \frac{\iota}{\surd{2}} \Bigr) \right\} I; \Tag{41} +\] +we see from this equation that the self-induction~$\smallbold{P}$ is given by +the equation +\[ +\smallbold{P} = 2 \log(\smallbold{b} / \smallbold{a}) + + (\sigma \mu /2 \pi p \smallbold{a}^2)^{\frac{1}{2}} + + (\sigma'\mu'/2 \pi p \smallbold{b}^2)^{\frac{1}{2}}, \Tag{42} +\] +and the impedance~$\smallbold{Q}$ by +\[ +\smallbold{Q} + = (\sigma \mu p / 2 \pi \smallbold{a}^2)^{\frac{1}{2}} + + (\sigma'\mu'p / 2 \pi \smallbold{b}^2)^{\frac{1}{2}}. \Tag{43} +\] + +In a cable the conductivity of the outer conductor is very +much less than that of the core, so that $\sigma'/\smallbold{b}^2$ will be large compared +with~$\sigma/\smallbold{a}^2$; thus the self-induction and impedance of a cable +are both practically independent of the resistance of the wire +and depend mainly upon that of the outer conductor. The limiting +value of the self-induction when the frequency is indefinitely +increased is $2 \log(\smallbold{b}/\smallbold{a})$; as this does not involve~$\mu$ it is the same +for iron as for copper wires. The difference between the self-induction +per unit length of the cable for infinitely slow and +infinitely rapid vibrations is by equations (\eqnref{272}{40})~and~(\eqnref{274}{42}) equal to~$\mu/2$. +The impedance of the circuit increases indefinitely with +the frequency of the alternations. + +If we trace the changes in the values of the self-induction +and impedance as the frequency~$p$ increases, we see from +Arts.\ \artref{272}{272},~\artref{273}{273},~\artref{274}{274} +that when this is so small that $n\smallbold{a}$~is a small +quantity the self-induction decreases and the impedance increases +by an amount proportional to the square of the +frequency. When the frequency increases so that $n\smallbold{a}$~is considerable +while $n'\smallbold{b}$~is small, the self-induction varies very +slowly with the frequency while the impedance is directly +proportional to it. When the frequency is so great that both +$n\smallbold{a}$~and~$n'\smallbold{b}$ are large the self-induction approaches the limit +$2 \log(\smallbold{b}/\smallbold{a})$, while the impedance is proportional to the square root +of the frequency. +\index{Alternating currents, expression for self-induction of a single wire@\subdashtwo expression for self-induction of a single wire|)}% +\index{Alternating currents, expression for `impedance' of a single wire@\subdashtwo expression for `impedance' of a single wire|)}% +\index{Impedance, expression for@\subdashone expression for|)}% +%% -----File: 310.png---Folio 296------- + + +\Subsection{Flat Conductors.} +\index{Alternating currents, in flat conductors@\subdashtwo in flat conductors}% +\index{Impedance, for flat conductors@\subdashone for flat conductors}% +\index{Induction, self, for flat conductors@\subdashtwo for flat conductors}% +\index{Self-induction, expression for, for xflat conductors@\subdashtwo for flat conductors}% + +\Article{275} In many experiments flat strips of metal in parallel +planes are used instead of wires, with the view of diminishing +the self-induction; these are generally arranged so that the +direct and return currents flow along adjacent and parallel +strips. When the frequency of the vibrations is very large, the +positive and negative currents endeavour to get as near together +as possible, they will thus flow on the surfaces of the strips +which are nearest each other. If the distance between the +planes of the strips is small in comparison with their breadth we +may consider them as a limiting case of the cable, when the +specific resistance of the wire is the same as that of the outer +conductor, and when the values of $\smallbold{a}$~and~$\smallbold{b}$ are indefinitely +great, their difference however remaining finite and equal to the +distance between the strips. If $I'$~is the current flowing across +unit width of the strip, then, since with our previous notation $I$ +is the current flowing over the circumference of the cable, +\[ +I' = I / 2 \pi \smallbold{a}. +\] +Since $\smallbold{b} = \smallbold{a} + d$, where $d$~is very small compared with~$\smallbold{a}$, +\[ +\log \frac{\smallbold{b}}{\smallbold{a}} = \frac{d}{\smallbold{a}} \text{ approximately.} +\] + +Making these substitutions, equation~(\eqnref{274}{41}) becomes +\[ +\smallbold{E} = 2 \iota p \left\{d + \sqrt{\frac{\mu \sigma}{2 \pi p}} (1 - \iota) \right \} 2 \pi I'. +\] +Thus, in this case the self-induction per unit length is +\[ +4 \pi \left\{d + \sqrt{\frac{\mu \sigma}{2 \pi p}} \right\}, +\] +and the impedance +\[ +4\pi \sqrt{\frac{\mu \sigma p}{2 \pi}}. +\] + +\Article{276} Though, as we have just seen, it is possible to regard the +case of two parallel metal slabs as a particular case of the cable, +yet inasmuch as the geometry of the particular case is much +simpler than that of the cable, the case is one where points of +theory are most conveniently discussed; it is therefore advisable +\index{Induction, self@\subdashone self, expressions for|)}% +%% -----File: 311.png---Folio 297------- +to treat it independently. We shall suppose that we have two +slabs of the same metal, the adjacent faces of the slabs being +parallel and separated by the distance~$2h$; we shall take the +plane parallel to these faces and midway between them as the +plane of~$yz$, the axis of~$x$ being normal to the faces. We shall +suppose that all the variable quantities vary as $\epsilon^{\iota(mz+pt)}$ and are +independent of~$y$. The slabs are supposed also to extend to infinity +in directions parallel to~$y$ and~$z$ and to be infinitely thick. + +Let $\sigma$ be the specific resistance of the slabs, $V$~the velocity of +propagation of electrodynamic action through the dielectric +which separates them. Then, using the same notation as before, +since all the quantities are independent of~$y$, the differential +equations satisfied by the components of the electromotive +intensity are by \artref{262}{Art.~262} +\begin{DPgather*} +\frac{d^2R}{dx^2} = k^2 R \text{ in the dielectric}, \\ +\lintertext{and} +\frac{d^2R}{dx^2} = n^2 R +\end{DPgather*} +in either of the slabs. + +Thus, in the dielectric we may put +\begin{align*} +R &= (A \epsilon^{kx} + B \epsilon^{-kx}) \epsilon^{\iota(mz+pt)}, \\ +P &= - \frac{\iota m}{k} (A \epsilon^{kx} - B \epsilon^{-kx}) \epsilon^{\iota(mz+pt)}, +\end{align*} +in the slab for which $x$~is positive +\begin{align*} +R &= C \epsilon^{-nx} \epsilon^{\iota(mz+pt)}, \\ +P &= \frac{\iota m}{n} C \epsilon^{-nx} \epsilon^{\iota(mz+pt)}, +\end{align*} +and in that for which $x$~is negative +\begin{align*} +R &= D \epsilon^{nx} \epsilon^{\iota(mz+pt)}, \\ +P &= -\frac{\iota m}{n} D \epsilon^{nx} \epsilon^{\iota(mz+pt)}, +\end{align*} +the real part of~$n$ being taken positive in both cases. + +Since $R$ is continuous when $x = ±h$, we have +\[ +\left.\begin{aligned} +A \epsilon^{kh} + B \epsilon^{-kh} & = C \epsilon^{-nh}, \\ +A \epsilon^{-kh} + B \epsilon^{kh} & = D \epsilon^{-nh}. +\end{aligned}\right\}\Tag{44} +\] +%% -----File: 312.png---Folio 298------- + +Since the magnetic force parallel to the surface is continuous, +we have, if $\mu$ is the magnetic permeability of the slab, +\begin{gather*} +\frac{k^2-m^2}{k} (A\epsilon^{kh} - B\epsilon^{-kh}) = \frac{m^2-n^2}{\mu n} C\epsilon^{-nh}, \\ +\frac{k^2-m^2}{k} (A\epsilon^{-kh} - B\epsilon^{kh}) = -\frac{m^2-n^2}{\mu n} D\epsilon^{-nh}. +\end{gather*} + +Eliminating $C$~and~$D$ by the aid of equations~(\eqnref{276}{44}), we have +\[ +\left.\begin{aligned} +A\left(\frac{k^2-m^2}{k} - \frac{m^2-n^2}{\mu n}\right)\epsilon^{kh} & = B\left(\frac{k^2-m^2}{k} + \frac{m^2-n^2}{\mu n}\right)\epsilon^{-kh}, \\ +A\left(\frac{k^2-m^2}{k} + \frac{m^2-n^2}{\mu n}\right)\epsilon^{-kh} & = B\left(\frac{k^2-m^2}{k} - \frac{m^2-n^2}{\mu n}\right)\epsilon^{kh}. +\end{aligned}\right\} \Tag{45} +\] +From these equations we get +\[ +A^2 = B^2. +\] + +The solution $A = B$ corresponds to the current flowing in the +same direction in the two slabs, the other solution corresponds +to the case when the current flows in one direction in one slab +and in the opposite direction in the other; it is this case we shall +proceed to investigate. Putting $A = -B$, equation~(\eqnref{276}{45}) becomes +\begin{DPgather*} +\frac{k^2-m^2}{k}(\epsilon^{kh} + \epsilon^{-kh}) + +\frac{n^2-m^2}{\mu n}(\epsilon^{kh}-\epsilon^{-kh})=0; \Tag{46} \\ +\lintertext{but} +k^2-m^2 = -p^2/V^2, \\ +n^2-m^2 = 4\pi \mu \iota p/\sigma, +\end{DPgather*} +and $kh$ is very small, thus (\eqnref{276}{46})~becomes approximately +\begin{DPgather*} +\frac{p^2}{V^2 k} = \frac{4\pi \iota p}{\sigma n}\, kh, \\ +\lintertext{or} +k^2 = -\frac{p^2}{V^2}\, \frac{\iota n\sigma}{4\pi hp}, \\ +\lintertext{so that} +m^2 = \frac{p^2}{V^2} \left\{1 - \frac{\iota n\sigma}{4\pi hp} \right\}. \Tag{47} +\end{DPgather*} + +As we have remarked before, $4\pi \mu p/\sigma$ is in the case of metals +very large compared with~$m^2$, so that we have approximately +\[ +n^2 = 4\pi \mu \iota p/\sigma, +\] +%% -----File: 313.png---Folio 299------- +and therefore approximately by equation~(\eqnref{276}{47}) +\[ +m^2 = \frac{p^2}{V^2} \left\{1 + \left( \frac{\sigma \mu}{8 \pi h^2 p} \right)^{\frac{1}{2}} (1 - \iota) \right\}. \Tag{48} +\] + +Thus, if $m = \xi + \iota \eta$, we have +\begin{gather*} +\xi^2 - \eta^2 = \frac{p^2}{V^2} \left\{1 + \left( \frac{\sigma \mu}{8 \pi h^2 p} \right)^{\frac{1}{2}} \right\},\\ +2 \xi \eta = - \frac{p^2}{V^2} \left( \frac{\sigma \mu}{8 \pi h^2 p} \right)^{\frac{1}{2}}. +\end{gather*} + +But if $\omega$~is the velocity with which the phases are propagated +along the slab, $\omega^2 = p^2 / \xi^2$, so that we have +\[ +\frac{1}{\omega^2} = \frac{\eta^2}{p^2} + + \frac{1}{V^2} \left\{1 + \left( \frac{\sigma \mu}{8 \pi h^2 p} \right)^{\frac{1}{2}} \right\}, +\] +thus $1 / \omega^2$ is never less than~$1/V^2$, or $\omega$~is never greater than~$V$, +so that the velocity of propagation of the phases along the slab +can never exceed the rate at which electrodynamic action travels +through the dielectric. + +If the frequency is so high that $\sigma \mu / 8 \pi h^2 p$ is small, then we +have by equation~(\eqnref{276}{48}) +\[ +m = - \frac{p}{V} \left\{1 - \frac{\iota}{2} \left( \frac{\sigma \mu}{8 \pi h^2 p} \right)^{\frac{1}{2}} \right\} \text{ approximately}. +\] + +This equation represents a disturbance propagated with the +velocity~$V$, whose amplitude fades away to $1/\epsilon$~of its original +value after traversing a distance +\[ +2Vh \left\{\frac{8 \pi p}{\sigma \mu} \right\}^{\frac{1}{2}}. +\] + +If the frequency is so low that $\sigma \mu / 8 \pi h^2 p$ is large, then we +have approximately by equation~(\eqnref{276}{48}) +\begin{DPgather*} +m = -\frac{p}{V} \left\{\frac{\sigma \mu}{4 \pi h^2 p} \right\}^{\frac{1}{4}} + \left( \cos{\frac{\pi}{8}} - \iota \sin{\frac{\pi}{8}} \right), \\ +\lintertext{or} +m = -\frac{p}{V} \left\{\frac{\sigma \mu}{4 \pi h^2 p} \right\}^{\frac{1}{4}} + \left( .92-\iota .38 \right). +\end{DPgather*} +This corresponds to a vibration propagated with the velocity +\[ +1.08 V \{4 \pi h^2 p / \sigma \mu \}^{\frac{1}{4}}, +\] +%% -----File: 314.png---Folio 300------- +and fading away to $1/\epsilon$~of its original amplitude after traversing +a distance +\[ +2.6V \{4 \pi h^2 / \mu \sigma p^3 \}^{\frac{1}{4}}. +\] + +If the total current through a slab per unit width is represented +by the real part of $I_0 \epsilon^{\iota (mz+pt)}$, then, when the frequency +is so great that $\sigma \mu / 8 \pi h^2 p$ is a small quantity and therefore the +real part of~$m$ large compared with the imaginary part, we +have since +\begin{DPgather*} +I_0 \epsilon^{\iota (mz+pt)} + = \int_h^\infty \frac{R}{\sigma}\,dx + = \frac{C}{\sigma n} \epsilon^{-nh} \epsilon^{\iota (mz+pt)}, \\ +C = \sigma n \epsilon^{nh} I_0; \\ +\lintertext{hence by~(\eqnref{276}{44})} +A = -B = \frac{\sigma n I_0}{2kh}. +\end{DPgather*} +We have therefore in the dielectric +\begin{DPgather*} +\begin{aligned} +R &= \sigma I_0 \sqrt{2} n' (x/h) \cos \left( mz + pt + \frac{\pi}{4} \right),\\ +P &= 4 \pi m I_0 (V^2/p) \cos(mz + pt),\\ +b &= -4 \pi I_0 \cos(mz + pt), +\end{aligned} \\ +\lintertext{where} +n' = \{2 \pi \mu p/ \sigma \}^{\frac{1}{2}}. +\end{DPgather*} + +In the metal slab we have on the side where $x$~is positive, +\begin{align*} +R &= \sigma I_0 \DPtypo{\surd{2}}{\sqrt{2}} n' \epsilon^{-n'(x-h)} \cos \left( mz+pt-n'(x-h) + \frac{\pi}{4} \right),\\ +P &= -\sigma I_0 m \epsilon^{-n'(x-h)} \sin(mz+pt-n'(x-h)),\\ +b &= -4 \pi \mu I_0 \epsilon^{-n'(x-h)} \cos(mz+pt-n'(x-h)). +\end{align*} + +We see from these equations that $P/R$ is very large in the +dielectric and very small in the metal slab, thus the Faraday +tubes are at right angles to the conductor in the dielectric and +parallel to it in the metal slab. + + +\Subsection{Mechanical Force between the Slabs.} +\index{Attraction between flat conductors conveying variable currents}% +\index{Force between flat conductors conveying alternating currents@\subdashone between flat conductors conveying alternating currents}% +\index{Mechanical force xbetween flat conductors conveying alternating currents@\subdashtwo between flat conductors conveying alternating currents}% + +\Article{277} This may be regarded as consisting of two parts, (1)~an +attractive force, due to the attraction of the positive electricity +of one slab on the negative of the other, (2)~a repulsive force, +due to the repulsion between the positive currents in one slab +and the negative in the other. To calculate the first force we +notice that since $V^2 / p \sigma$ is very large, the value of~$P$ in the conductor +%% -----File: 315.png---Folio 301------- +is very small compared with the value in the dielectric, +and may without appreciable error be neglected; hence if~$e$ is the +surface density of the electricity on the slab and $K$~the specific +inductive capacity of the dielectric, +\[ +4 \pi e = -K 4 \pi m (V^2/p) I_0 \cos(mz + pt). +\] +The force on the slab per unit area is equal to~$Pe/2$; substituting +the values of $P$~and~$e$ this becomes +\[ +2 \pi K m^2 (V^4 / p^2) I_0^2 \cos^2 (mz + pt). +\] + +The force due to the repulsion between the currents in the +slabs per unit volume is equal to the product of the magnetic +induction~$b$ into~$w$, the intensity of the current parallel to~$z$. +Since +\[ +4 \pi \mu w = - \frac{db}{dx}, +\] +the force per unit volume is equal to +\[ +-\frac{1}{8 \pi \mu}\, \frac{db^2}{dx}, +\] +hence the repulsive force per unit area of the surface of the slab +\begin{align*} +&= - \int_h^\infty \frac{1}{8 \pi \mu}\, \frac{db^2}{dx}\,dx \\ +&= \frac{1}{8 \pi \mu} \left( b^2 \right)_{x = h} = 2 \pi \mu I_0^2 \cos^2 (mz + pt). +\end{align*} +When the alternations are so rapid that the vibrations travel +with the velocity of light +\[ +V^2 m^2 = p^2, +\] +and since $K = 1/V^2$, the attraction between the slabs is equal to +\[ +2 \pi I_0^2 \cos^2 (mz + pt), +\] +while the repulsion is +\[ +2 \pi \mu I_0^2 \cos^2 (mz + pt), +\] +hence the resultant repulsion is equal to +\[ +2 \pi (\mu - 1) I_0^2 \cos^2 (mz + pt). +\] + +If the slabs are non-magnetic $\mu = 1$, so that for these very +rapid vibrations the electrostatic attraction just counterbalances +the electromagnetic repulsion. Mr.~Boys (\textit{Phil.\ Mag.}\ [5],~31, p.~44, +1891) found that the mechanical forces between two conductors +carrying very rapidly alternating currents was too small to be +%% -----File: 316.png---Folio 302------- +detected, even by the marvellously sensitive methods for measuring +small forces which he has perfected, and which would have +enabled him to detect forces comparable in magnitude with +those due to the electrostatic charges or to the repulsion between +the currents. + + +\Subsection{Propagation of Longitudinal Waves of Magnetic +Induction along Wires.} +\index{Longitudinal waves of magnetic induction along wires}% +\index{Magnetic yinduction@\subdashone induction, longitudinal waves of, along wires}% + +\Article{278} In the preceding investigations the current has been +along the wire and the lines of magnetic force have formed a +series of co-axial circles, the axis of these circles being that of +the wire. Another case, however, of considerable practical importance +is when these relations of the magnetic force and current +are interchanged, the current flowing in circles round the axis of +the wire while the magnetic force is mainly along it. This +condition might be realized by surrounding a portion of the wire +by a short co-axial solenoid, then if alternating currents are sent +through this solenoid periodic magnetic forces parallel to the +wire will be started. We shall in this article investigate the +laws which govern the transmission of such forces along the wire. +The problem has important applications to the construction of +transformers; in some of these the primary coil is wound round +one part of a closed magnetic circuit, the secondary round +another. This arrangement will not be efficient if there is any +considerable leakage of the lines of magnetic force between the +primary and the secondary. We should infer from general considerations +that the magnetic leakage would increase with the +rate of alternation of the current through the primary. For let us +suppose that an alternating current passes through an insulated +ring imbedded in a cylinder of soft iron surrounded by air, the +straight axis of the ring coinciding with the axis of the cylinder. +The variations in the intensity of the current through this ring +will induce other currents in the iron in its neighbourhood; the +magnetic action of these currents will, on the whole, cause the component +of the magnetic force along the axis of the cylinder to be +less and the radial component greater than if the current through +the ring were steady; in which case there are no currents in the +iron. Thus the effect of the changes in the intensity of the current +through the primary will be to squeeze as it were the lines of +%% -----File: 317.png---Folio 303------- +magnetic force out of the iron and make them complete their circuit +through the air. Thus when the field is changing quickly, the +lines of magnetic force, instead of taking a long path through the +medium of high permeability, will take a short path, even though +the greater part of it is through a medium of low permeability +such as air. The case is quite analogous to the difference between +the path of a steady current and that of a rapidly alternating +one. A steady current flows along the path of least resistance, +a rapidly alternating one along the path with least self-induction. +Thus, for example, if we have two wires in parallel, one very +long but made of such highly conducting material that the +total resistance is small, the other wire short but of such a nature +that the resistance is large, then when the current is steady +by far the greater part of it will travel along the long wire; +if however the current is a rapidly alternating one, the greater +part of it will travel along the short wire because the self-induction +is smaller than for the long wire, and for these +rapidly alternating currents the resistance is a secondary consideration. + +In the magnetic problem the iron corresponds to the good +conductor, the air to the bad one. When the field is steady +the lines of force prefer to take a long path through the iron +rather than a short one through the air; they will thus tend to +keep within the iron; when however the magnetic field is a very +rapidly alternating one, the paths of the lines of force will tend +to be as short as possible, whatever the material through which +they pass. The lines of force will thus in this case leave the +iron and complete their circuit through the air. + +We shall consider the case of a right circular soft iron cylinder +where the lines of magnetic force are in planes through the axis +taken as that of $z$, the corresponding system of currents flowing +round circles whose axis is that of the cylinder. The cylinder +is surrounded by a dielectric which extends to infinity. Let $a$,~$b$,~$c$ +be the components of the magnetic induction parallel to the axes +of $x$,~$y$,~$z$ respectively; then, since the component of the magnetic +induction in the $xy$~plane is at right angles to the axis of the +cylinder, we may put +\[ +a = \frac{d \chi}{dx}, \quad b = \frac{d \chi}{dy}. +\] + +Let us suppose that $a$,~$b$,~$c$ all vary as $\epsilon^{\iota (mz + pt)}$. +%% -----File: 318.png---Folio 304------- + +Now in the iron cylinder $a$,~$b$,~$c$ all satisfy differential equations +of the form +\begin{DPgather*} +\frac{d^2c}{dx^2} + \frac{d^2c}{dy^2} = n^2c, \\ +\lintertext{where} n^2 = m^2 + 4\pi \mu \iota p/\sigma, +\end{DPgather*} +$\mu$ being the magnetic permeability and~$\sigma$ the specific resistance of +the cylinder. + +In the dielectric outside the cylinder the differential equation +satisfied by the components of the magnetic induction is of the +form +\begin{DPgather*} +\frac{d^2c}{dx^2} + \frac{d^2c}{dy^2} = k^2c, \\ +\lintertext{where} k^2 = m^2 - \frac{p^2}{V^2}, +\end{DPgather*} +and $V$ is the velocity with which electromagnetic disturbances +are propagated through the dielectric. + +We have also +\[ +\frac{da}{dx} + \frac{db}{dy} + \frac{dc}{dz} = 0. +\] + +The solution of these equations is easily seen to be, in the +iron cylinder, +\begin{align*} +c & = AJ_0(\iota nr)\epsilon^{\iota (mz+pt)}, \\ +a & = -\frac{\iota m}{n^2} A \frac{d}{dx} J_0(\iota nr)\epsilon^{\iota (mz+pt)}, \\ +b & = -\frac{\iota m}{n^2} A \frac{d}{dy} J_0(\iota nr)\epsilon^{\iota (mz+pt)}, +\end{align*} +while in the dielectric, since $r$~can become infinite, +\begin{align*} +c & = CK_0(\iota kr)\epsilon^{\iota (mz+pt)}, \\ +a & = -\frac{\iota m}{k^2} C \frac{d}{dx} K_0(\iota kr)\epsilon^{\iota (mz+pt)}, \\ +b & = -\frac{\iota m}{k^2} C \frac{d}{dy} K_0(\iota kr)\epsilon^{\iota (mz+pt)}. +\end{align*} + +Let $\smallbold{a}$ be the radius of the cylinder, then when $r = \smallbold{a}$ the +tangential magnetic force in the cylinder is equal to that in the +dielectric, hence +\[ +\frac{A}{\mu} J_0(\iota n\smallbold{a}) = CK_0(\iota k\smallbold{a}); +\] +%% -----File: 319.png---Folio 305------- +since the radial magnetic induction is continuous, we have +\[ +\frac{m}{n} AJ_0'(\iota n\smallbold{a}) = \frac{m}{k} CK_0'(\iota k\smallbold{a}). +\] +Eliminating $A$ and~$C$ from these equations, we get +\[ +\frac{\iota n\smallbold{a}}{\mu}\, \frac{J_0(\iota n\smallbold{a})}{J_0'(\iota n\smallbold{a})} + = \iota k\smallbold{a} \frac{K_0(\iota k\smallbold{a})}{K_0'(\iota k\smallbold{a})}, \Tag{49} +\] +an equation which will enable us to find~$m$ when $p$~is known. + +Let us begin with the case when the frequency of the alternations +is small enough to allow of the currents being nearly +uniformly distributed over the cross-section of the cylinder. In +this case we have approximately +\[ +J_0(\iota n\smallbold{a})= 1, \quad +J_0'(\iota n\smallbold{a}) = -\tfrac{1}{2} \iota n\smallbold{a}, +\] +so that equation~(\eqnref{278}{49}) becomes +\[ +-\frac{2}{\mu} = \iota k\smallbold{a} \frac{K_0(\iota k\smallbold{a})}{K_0'(\iota k\smallbold{a})}. \Tag{50} +\] + +Since for soft iron $2/\mu$ is a small quantity, the right-hand side +of this equation and therefore $k\smallbold{a}$ must be small; but in this case +we have approximately +\begin{align*} +K_0(\iota k\smallbold{a}) & = \log(2\gamma/\iota k\smallbold{a}), \\ +K_0'(\iota k\smallbold{a}) & = -\frac{1}{\iota k\smallbold{a}}, +\end{align*} +so that~(\eqnref{278}{50}) becomes +\[ +-\frac{2}{\mu} = k^2 \smallbold{a}^2 \log(2\gamma/\iota k\smallbold{a}). \Tag{51} +\] +To solve this equation consider the solution of +\[ +x \log x = -y, +\] +when $y$~is small. If $x= -y/\log y$, then +\[ +x \log x = -y \left\{1 + \frac{\log \log(1/y)}{\log(1/y)} \right\}, +\] +but when $y$~is small $\log \log(1/y)$ is small compared with~$\log(1/y)$, +so that an approximate solution of the equation is +\[ +x = -y/\log y. +\] +%% -----File: 320.png---Folio 306------- + +If we apply this result to equation~(\eqnref{278}{51}), we find that the +approximate solution of that equation is +\[ +k^2 = - \frac{4}{\smallbold{a}^{2} \mu}\, \frac{1}{\log(\mu\gamma^2)}. +\] +\begin{DPgather*} +\lintertext{\indent Now} k^2 = m^2 - \frac{p^2}{V^2}, +\end{DPgather*} +and since the value we have just found for~$k$ is in any practicable +case very large compared with~$p^2/V^2$, we see that $k^2=m^2$ approximately, +so that +\[ +m = \frac{\iota 2}{\smallbold{a}} \left\{\frac{1}{\mu} \frac{1}{\log(\mu\gamma^2)}\right\}^{\frac{1}{2}}. +\] + +Thus since in the expression for~$c$ there is the factor +\[ +\epsilon^{\iota mz} \text{ or } +\epsilon^{-\frac{2}{\smallbold{a}} z + \left\{\frac{1}{\mu \log(\mu\gamma^2)} \right\}^{\frac{1}{2} }}, +\] +we see that the magnetic force will die away to $1/\epsilon$~of its value +at a distance +\[ +\tfrac{1}{2} \smallbold{a} \{\mu \log(\mu\gamma^2)\}^{\frac{1}{2}} +\] +from its origin. + +\Article{279} In the last case the current was uniformly distributed +over the cross-section. We can investigate the effect +of the concentration of the current at the boundary of the +cylinder by supposing that~$n\smallbold{a}$ is large compared with unity +though small compared with~$\mu$. In this case, since approximately +\[ +J_0' (\iota n \smallbold{a}) = -\iota J_0(\iota n \smallbold{a}), +\] +equation~(\eqnref{278}{49}) becomes +\[ +-\frac{n \smallbold{a}}{\mu} + = \iota k \smallbold{a} \frac{K_0(\iota k \smallbold{a})}{K_0'(\iota k \smallbold{a})}. +\] +Since the left-hand side of this equation is small, $\iota k \smallbold{a}$~is also small, +so that by \artref{261}{Art.~261} we may write this equation as +\[ +-\frac{n \smallbold{a}}{\mu} = k^2 \smallbold{a}^2 \log(2\gamma/\iota k \smallbold{a}). \Tag{52} +\] +This equation gives a value for~$k^2$ which is very large compared +with~$p^2/V^2$, so that approximately $m = k$. We also see that $k$ or +$m$ is small compared with~$n$, we may therefore put +\[ +n = \{4\pi\mu\iota p/ \sigma\}^{\frac{1}{2}}. +\] +%% -----File: 321.png---Folio 307------- +Thus equation~(\eqnref{279}{52}) becomes +\[ +k^2 \smallbold{a}^2 \log \frac{\iota k\smallbold{a}}{2\gamma} + = \left\{\frac{4\pi p\smallbold{a}^2}{\mu \sigma}\right\}^{\tfrac{1}{2}}\, + \epsilon^{\tfrac{\iota \pi}{4}}, +\] +or putting $\iota k\smallbold{a} / 2\gamma = q$, +\[ +q^2 \log q^2 + = -\frac{1}{2\gamma^{2}} \left\{\frac{4\pi p\smallbold{a}^2}{\mu \sigma}\right\}^{\frac{1}{2}}\, + \epsilon^{\tfrac{\iota \pi}{4} }. +\] + +To solve this equation put $q^2 = w\epsilon^{\iota \psi }$; equating real and imaginary +parts, we get +\begin{align*} +w \log w \cos \psi - w \psi \sin \psi &= -\frac{1}{\gamma^2} \left\{\frac{\pi p\smallbold{a}^2}{2\mu \sigma} \right\}^{\frac{1}{2}},\\ +w \log w \sin \psi + w \psi \cos \psi &= -\frac{1}{\gamma^2} \left\{\dfrac{\pi p\smallbold{a}^2}{2\mu \sigma} \right\}^{\frac{1}{2}}. +\end{align*} +Since $w$~is very small, the terms in~$\log w$ are much the most +important; an approximate solution of these equations is, therefore, +since the solution of $x \log x = -y$, is $x = -y/\log y$, +\begin{align*} +w &= - \frac{\dfrac{1}{\gamma^2} + \left\{\dfrac{\pi p \smallbold{a}^2}{\mu \sigma} \right\}^{\frac{1}{2}}} + {\log \dfrac{1}{\gamma^2} + \left\{\dfrac{\pi p \smallbold{a}^2}{\mu \sigma} \right\}^{\frac{1}{2}}},\\ +\psi &= \frac{\pi}{4}. +\end{align*} +Hence, since $k = m$ and $k^2\smallbold{a}^2 = -4\gamma^2 w \epsilon^{\dfrac{\iota \pi}{4}}$, we find +\begin{align*} +m\smallbold{a} + &= 2\gamma \sqrt{-w} \left\{\cos\frac{\pi}{8} + \iota \sin\frac{\pi}{8}\right\}\\ + &= 2\gamma w^{\frac{1}{2}} \left(\cos \frac{5\pi}{8} + \iota \sin \frac{5\pi}{8}\right). +\end{align*} + +Thus, since in the expression for~$c$ there is the factor~$\epsilon^{\iota mz}$, we +see that $c$~will fade away to $1/\epsilon$~of its initial value at a distance +from the origin equal to +\[ +\frac{\smallbold{a}}{2\gamma w^{\frac{1}{2}}} \cosec \frac{5\pi}{8}, +\] +or substituting the value of~$w$ just found, +\[ +\frac{\smallbold{a}}{2} \cosec \frac{5\pi}{8} + \biggl\{\frac{\mu \sigma}{\pi p\smallbold{a}^2} \biggr\} + \biggl\{\log \gamma^2 \Bigl(\frac{\mu \sigma}{\pi p\smallbold{a}^2}\Bigr)^{\tfrac{1}{2}} \biggr\}^{\tfrac{1}{2}}. +\] + +This distance is much shorter than the corresponding one +%% -----File: 322.png---Folio 308------- +when the current was uniformly distributed over the cross-section +of the wire, and the important factor varies as~$\mu^{\frac{1}{4}}$ +instead of~$\mu^{\frac{1}{2}}$. Thus the leakage of the lines of magnetic force +out of the iron cylinder is much greater when the alternations +are rapid than when they are slow. This is in accordance with +the conclusion we came to from general reasoning at the +beginning of \artref{278}{Art.~278}. + +The result of this investigation points strongly to the advisability +of very fine lamination of the core of a transformer, +so as to get a uniform distribution of magnetic force over +the iron and thus avoid magnetic leakage. There are many +other advantages gained by fine lamination, of which one, more +important than the effect we are considering, is the diminution +in the quantity of heat dissipated by eddy currents. We shall +proceed to consider in the next \artref{280}{article} the dissipation of energy +by the currents in the wire. + + +\Subsection{Dissipation of Energy by the Heat produced by +Alternating Currents.} +\index{Energy, transfer of}% + +\Article{280} A great deal of light is thrown on the laws which govern +the decay of currents in conductors by the consideration of the +circumstances which affect the amount of heat produced in unit +time by these currents. As we have obtained the expressions +for these currents we could determine their heating effect by +direct integration; we shall however proceed by a different +method for the sake of introducing a very important theorem +\index{Poynting's theorem}% +due to Professor Poynting, and given by him in his paper `On +the Transfer of Energy in the Electromagnetic Field,' \textit{Phil.\ +\index{Transfer of energy}% +Trans.}\ 1884, Part~II, p.~343. The theorem is that +\begin{multline*} +\frac{K}{4 \pi} \iiint \left( + P\, \frac{dP}{dt} + Q\, \frac{dQ}{dt} + R\, \frac{dR}{dt} +\right) dx\,dy\,dz\\ + \shoveleft{\qquad + \frac{\mu}{4 \pi} \iiint \left( + \alpha\, \frac{d\alpha}{dt} + \beta\, \frac{d\beta}{dt} + \gamma\, \frac{d\gamma}{dt} +\right) dx\,dy\,dz}\\ + \shoveleft{\qquad + \iiint ( X \dot{x} + Y \dot{y} + Z \dot{z} )\,dx\,dy\,dz + + \iiint ( Pp + Qq + Rr )\,dx\,dy\,dz}\\ + = \frac{1}{4 \pi} \iint + \{l ( R' \beta - Q' \gamma ) + + m ( P' \gamma - R' \alpha ) + + n ( Q' \alpha - P' \beta ) \}\,dS, +\end{multline*} +%% -----File: 323.png---Folio 309------- +where the volume integrals on the left-hand side are taken +throughout the volume contained by the closed surface~$S$, of +which $dS$~is an element and $l$,~$m$,~$n$ the direction cosines of the +normal drawn outwards. + +$P$,~$Q$,~$R$ are the components of the electromotive intensity. + +$\alpha$,~$\beta$,~$\gamma$ those of the magnetic force. + +$X$,~$Y$,~$Z$ those of the mechanical force acting on the body in +consequence of the passage of currents through it. + +$\dot{x}$,~$\dot{y}$,~$\dot{z}$ the components of the velocity of a point in the +body. + +$p$,~$q$,~$r$ the components of the conduction currents. + +$P'$,~$Q'$,~$R'$ the parts of the components of the electromotive +intensity which do not depend upon the motion of the +body. + +$K$~the specific inductive capacity and $\mu$~the magnetic permeability. + +The following proof of this theorem is taken almost verbatim +from Professor Poynting's paper. Let $u$,~$v$,~$w$ be the components +of the total current, which is the sum of the polarization and +conduction currents; we have, since the components of the former +are respectively +\begin{gather*} +\frac{K}{4 \pi}\, \frac{dP}{dt}, \quad +\frac{K}{4 \pi}\, \frac{dQ}{dt}, \quad +\frac{K}{4 \pi}\, \frac{dR}{dt},\\ +\frac{K}{4 \pi}\, \frac{dP}{dt} = u - p,\\ +\frac{K}{4 \pi}\, \frac{dQ}{dt} = v - q,\\ +\frac{K}{4 \pi}\, \frac{dR}{dt} = w - r. +\end{gather*} +Hence +\begin{multline*} +\frac{K}{4 \pi} \iiint \left( + P\, \frac{dP}{dt} + Q\, \frac{dQ}{dt} + R\, \frac{dR}{dt} +\right) dx\,dy\,dz\\ + = \iiint \{P(u - p) + Q(v - q) + R(w - r) \}\,dx\,dy\,dz\\ + = \iiint ( Pu + Qv + Rw )\, dx\,dy\,dz + - \iiint ( Pp + Qq + Rr )\, dx\,dy\,dz. \Tag{53} +\end{multline*} +%% -----File: 324.png---Folio 310------- + +Now (Maxwell's \textit{Electricity and Magnetism}, Vol.~II, Art.~598), +\begin{align*} +P & = c\dot{y} - b\dot{z} - \frac{dF}{dt} - \frac{d\psi}{dx} + = c\dot{y} - b\dot{z} + P',\\ +Q & = a\dot{z} - c\dot{x} - \frac{dG}{dt} - \frac{d\psi}{dy} + = a\dot{z} - c\dot{x} + Q',\\ +R & = b\dot{x} - a\dot{y} - \frac{dH}{dt} - \frac{d\psi}{dz} + = b\dot{x} - a\dot{y} + R', +\end{align*} +where $P'$,~$Q'$,~$R'$ are the parts of $P$,~$Q$,~$R$ which do not contain +the velocities. + +Thus +\begin{align*} +Pu&+Qv+Rw\\ +&= (c\dot{y}-b\dot{z})u + (a\dot{z}-c\dot{x})v + (b\dot{x}-a\dot{y})w + P'u + Q'v + R'w,\\ +&= -\{(vc-wb)\dot{x} + (wa-uc)\dot{y} + (ub-va)\dot{z} \} + P'u + Q'v + R'w,\\ +&= -\{X\dot{x} + Y\dot{y} + Z\dot{z} \} + P'u + Q'v + R'w; +\end{align*} +where $X$,~$Y$,~$Z$ are the components of the mechanical force per +unit volume (Maxwell, Vol.~II, Art.~603). + +Substituting this value for $Pu + Qv + Rw$ in~(\eqnref{280}{53}) and transposing, +we obtain +\begin{multline*} +\frac{K}{4 \pi} \iiint \left( + P\, \frac{dP}{dt} + Q\, \frac{dQ}{dt} + R\, \frac{dR}{dt} + \right)\,dx\,dy\,dz\\ + + \iiint ( X\dot{x} + Y\dot{y} + Z\dot{z} )\, dx\,dy\,dz + + \iiint ( Pp + Qq + Rr )\, dx\,dy\,dz\\ + = \iiint (P'u + Q'v + R'w ) \, dx\,dy\,dz. \Tag{54} +\end{multline*} +\begin{DPalign*} +\lintertext{\indent Now} +4\pi u & = \frac{d\gamma}{dy} - \frac{d\beta}{dz},\\ +4\pi v & = \frac{d\alpha}{dz} - \frac{d\gamma}{dx},\\ +4\pi w & = \frac{d\beta}{dx} - \frac{d\alpha}{dy}. +\end{DPalign*} +Substituting these values for $u$,~$v$,~$w$ in the right-hand side of +equation~(\eqnref{280}{54}), that side of the equation becomes +{\setlength{\multlinegap}{0pt} +\begin{multline*} +\frac{1}{4 \pi} \iiint \left\{ + P' \left( \frac{d\gamma}{dy} - \frac{d\beta}{dz} \right) + + Q' \left( \frac{d\alpha}{dz} - \frac{d\gamma}{dx} \right) + + R' \left( \frac{d\beta}{dx} - \frac{d\alpha}{dy} \right) \right\} dx\,dy\,dz\\ + \shoveleft{\qquad = \frac{1}{4 \pi} \iiint \left[ + \left\{R'\frac{d\beta}{dx} - Q'\frac{d\gamma}{dx} \right\} + + \left\{P'\frac{d\gamma}{dy} - R'\frac{d\alpha}{dy} \right\}\right.}\\ + + \left.\left\{Q'\frac{d\alpha}{dz} - P'\frac{d\beta}{dz} \right\} \right] dx\,dy\,dz. +\end{multline*} +} +%% -----File: 325.png---Folio 311------- +Integrating by parts, we find that the expression is equal +to +{\setlength{\multlinegap}{0pt} +\begin{multline*} + \frac{1}{4 \pi} \iint ( R'\beta - Q'\gamma ) \, dy\,dz ++ \frac{1}{4 \pi} \iint ( P'\gamma - R'\alpha )\, dx\,dz\\ +\shoveleft{\qquad + \frac{1}{4 \pi} \iint ( Q'\alpha - P'\beta ) \, dx\,dy}\\ +- \frac{1}{4 \pi} \iiint \left( + \beta\frac{dR'}{dx} - \gamma\frac{dQ'}{dx} + + \gamma\frac{dP'}{dy} - \alpha\frac{dR'}{dy} + + \alpha\frac{dQ'}{dz} - \beta\frac{dP'}{dz} + \right) dx\,dy\,dz, +\end{multline*} +} +the double integrals being taken over the closed surface. This +expression may be written as +{\setlength{\multlinegap}{0pt} +\begin{multline*} +\frac{1}{4 \pi} \iint \{ + l(R'\beta - Q'\gamma) + + m(P'\gamma - R'\alpha) + + n(Q'\alpha - P'\beta) \}\, dS\\ + - \frac{1}{4 \pi} \iiint \left\{ + \alpha \left( \frac{dQ'}{dz} - \frac{dR'}{dy} \right) + + \beta \left( \frac{dR'}{dx} - \frac{dP'}{dz} \right) \right.\\ + + \gamma \left. \left( \frac{dP'}{dy} - \frac{dQ'}{dx} \right) \right\} dx\,dy\,dz, +\end{multline*} +} +where $dS$~is an element of the surface and $l$,~$m$,~$n$ are the +direction cosines of the normal to the surface drawn outwards.\nbpagebreak[1] +\begin{DPalign*} +\lintertext{\indent But} +\frac{dQ'}{dz} - \frac{dR'}{dy} + &= \frac{d}{dt} \left( \frac{dH}{dy} - \frac{dG}{dz} \right)\\ + &= \frac{da}{dt} = \mu\, \frac{d\alpha}{dt}. +\end{DPalign*} +\begin{DPalign*} +\lintertext{Similarly} +\frac{dR'}{dx} - \frac{dP'}{dz} + & = \frac{db}{dt} = \mu\, \frac{d\beta}{dt},\\ +\frac{dP'}{dy} - \frac{dQ'}{dx} + & = \frac{dc}{dt} = \mu\, \frac{d\gamma}{dt}. +\end{DPalign*} + +Hence we see that the right-hand side of~(\eqnref{280}{54}) is equal +to +\begin{multline*} +\frac{1}{4 \pi} \iint \{ + l( R'\beta - Q'\gamma ) + m( P'\gamma - R'\alpha ) + n( Q'\alpha - P'\beta ) \}\,dS\\ + - \frac{\mu}{4 \pi} \iiint \left( + \alpha\frac{d\alpha}{dt} + + \beta\frac{d\beta}{dt} + + \gamma\frac{d\gamma}{dt} \right) dx\,dy\,dz. +\end{multline*} +%% -----File: 326.png---Folio 312------- + +Transposing the last term to the other side of the equation, +we get +\begin{multline*} +\frac{K}{4\pi} \iiint \left( + P\, \frac{dP}{dt} + Q\, \frac{dQ}{dt} + R\, \frac{dR}{dt} + \right) dx\,dy\,dz\\ + + \frac{\mu}{4 \pi} \iiint \left( + \alpha\, \frac{d\alpha}{dt} + \beta\, \frac{d\beta}{dt} + \gamma\, \frac{d\gamma}{dt} + \right) dx\,dy\,dz \\ + + \iiint ( X\dot{x} + Y\dot{y} + Z\dot{z} )\, dx\, dy\, dz + + \iiint ( Pp + Qq + Rr )\,\DPtypo{dz}{dx}\,dy\,dz\\ + = \frac{1}{4 \pi} \iiint \{ + l ( R' \beta - Q' \gamma ) + + m ( P' \gamma - R' \alpha ) + + n ( Q' \alpha - P' \beta ) \}\,dS, \Tag{55} +\end{multline*} +which is the theorem we set out to prove. + +Now the electrostatic energy inside the closed surface is +(Maxwell, Art.~631) +\begin{DPgather*} +\frac{1}{2} \iiint ( Pf + Qg + Rh )\,dx\,dy\,dz,\\ +\lintertext{or since} +f = \frac {K}{4 \pi} P, \qquad +g = \frac {K}{4 \pi} Q, \qquad +h = \frac {K}{4 \pi} R, \\ +\frac{K}{8 \pi} \iiint ( P^2 + Q^2 + R^2 )\,dx\,dy\,dz. +\end{DPgather*} +The electromagnetic energy inside the same surface is (Maxwell, +Art.~635) +\begin{DPalign*} +& \frac{1}{8 \pi} \iiint ( a \alpha + b \beta + c \gamma )\,dx\,dy\,dz,\\ +& \lintertext{or} + \frac{\mu}{8 \pi} \iiint ( \alpha^2 + \beta^2 + \gamma^2 )\,dx\,dy\,dz. +\end{DPalign*} + +Thus the first two integrals on the left-hand side of equation~(\eqnref{280}{55}) +express the gain per second in electric and magnetic energy. +The third integral expresses the work done per second by the +mechanical forces. The fourth integral expresses the energy +transformed per second in the conductor into heat, chemical +energy, and so on. Thus the left-hand side expresses the total +gain in energy per second within the closed surface, and equation~(\eqnref{280}{55}) +expresses that this gain in energy may be regarded as +coming across the bounding surface, the amount crossing that +surface per second being expressed by the right-hand side of +that equation. +%% -----File: 327.png---Folio 313------- + +Thus we may regard the change in the energy inside the +closed surface as due to the transference of energy across that +surface; the energy moving at right angles both to~$\smallbold{H}$, the +resultant magnetic force, and to~$\smallbold{E}$, the resultant of $P'$,~$Q'$,~$R'$. The +amount of energy which in unit time crosses unit area at right +angles to the direction of the energy flow is $\smallbold{H}\smallbold{E} \sin \theta/4\pi$, +where~$\theta$ is the angle between $\smallbold{H}$~and~$\smallbold{E}$. The direction of the +energy flow is related to those of $\smallbold{H}$~and~$\smallbold{E}$ in such a way +that the rotation of a positive screw from~$\smallbold{E}$ to~$\smallbold{H}$ would be +accompanied by a translation in the direction of the flow of +energy. + +Equation~(\eqnref{280}{55}) justifies us in asserting that we shall arrive at +correct results as to the changes in the distribution of energy in +the field if we regard the energy as flowing in accordance with +the laws just enunciated: it does not however justify us in +asserting that the flow of energy at any point \emph{must} be that given +by these laws, for we can find an indefinite number of quantities +$u_s$,~$v_s$,~$w_s$ of the dimensions of flow of energy which satisfy the +condition +\[ +\iint (l u_s + mv_s + nw_s)\,dS = 0, +\] +where the integration is extended over any closed surface. +Hence, we see that if the components of the flow of energy were +\begin{align*} +R'\beta - Q'\gamma + \tsum u_s & \text{ instead of } R'\beta - Q'\gamma,\\ +P'\gamma - R'\alpha + \tsum v_s & \text{ instead of } P'\gamma- R'\alpha,\\ +Q'\alpha - P'\beta + \tsum w_s & \text{ instead of } Q'\alpha- P'\beta, +\end{align*} +the changes in the distribution of energy would still be those +which actually take place. + +Though Professor Poynting's investigation does not give a +unique solution of the problem of finding the flow of energy at +any point in the electromagnetic field, it is yet of great value, as +the solution which it does give is simple and one that readily +enables us to form a consistent and vivid representation of the +changes in the distribution of energy which are going on in any +actual case that we may have under consideration. Several applications +of this theorem are given by Professor Poynting in the +paper already quoted, to which we refer the reader. We shall +now proceed to apply it to the determination of the rate of heat +production in wires at rest traversed by alternating currents. +%% -----File: 328.png---Folio 314------- + +\Article{281} Since the currents are periodic, $P^2$,~$Q^2$,~$R^2$, $\alpha^2$,~$\beta^2$,~$\gamma^2$ will +be of the form +\[ +A + B \cos(2pt + \theta), +\] +where $A$~and~$B$ do not involve the time; hence the first two +integrals on the left-hand side of equation~(\eqnref{280}{55}) will be multiplied +by factors which, as far as they involve~$t$, will be of the form +$\sin (2pt + \theta)$; hence, if we consider the mean value of these terms +over a time involving a great many oscillations of the currents, +they may be neglected: the gain or loss of energy represented +by these terms is periodic, and at the end of a period the energy +is the same as at the beginning. The third term on the left-hand +side vanishes in our case because the wires are at rest, and +since $\dot{x}$,~$\dot{y}$,~$\dot{z}$ vanish $P'$,~$Q'$,~$R'$ become identical with $P$,~$Q$,~$R$. + +Thus when the effects are periodic we see that equation~(\eqnref{280}{55}) +leads to the result that the mean value with respect to the +time of +\[ +\iiint (Pp + Qq + Rr)\,dx\,dy\,dz +\] +is equal to that of +\[ +\frac{1}{4 \pi} \iint \{l(R\beta-Q\gamma)+m(P\gamma-R\alpha)+n(Q\alpha-P\beta)\}\,dS. +\] +The first of these expressions is, however, the mean rate of heat +production, and in the case of a wire whose electrical state is +symmetrical with respect to its axis, the value of the quantity +under the sign of integration is the same at each point of the +circumference of a circle whose plane is at right angles to the +axis of the wire; hence in this case we have the result: + +The mean rate of heat production per unit length of the wire +is equal to the mean value of +\[ +\tfrac{1}{2}\smallbold{a}\ \text{(tangential electromotive intensity)} × +\text{(tangential magnetic force)},\eqnlabel{\eqnart.56}\nbtag{56} +\] +$\smallbold{a}$, as before, being the radius of the wire. + +\Article{282} Let us apply this result to find the rate of heat production +\index{Heat produced by electric discharge, in wires carrying alternating currents@\subdashtwo in wires carrying alternating currents}% +in the wire and in the outer conductor of a cable when +the current is parallel to the axis of the wire. By the methods +of \artref{268}{Art.~268}, we see that if the total current through the wire at +the point~$z$ is equal to the real part of +\[ +I_0\epsilon^{\iota(mz+pt)}, +\] +%% -----File: 329.png---Folio 315------- +or if $m = -\alpha + \iota \beta$, to +\[ +I_0 \epsilon^{-\beta z} \cos (-\alpha z + pt), +\] +then, \artref{268}{Art.~268}, equation~(\eqnref{268}{24}), the electromotive intensity~$R$ in +the wire parallel to the axis of~$z$ is equal to the real part of +\[ +- \frac{\iota \sigma n}{2 \pi \smallbold{a}}\, + \frac{J_0 (\iota n r)}{J_0' (\iota n \smallbold{a})}\, + I_0 \epsilon^{-\beta z} \epsilon^{\iota (-\alpha z + pt)}. \Tag{57} +\] +If we neglect the polarization currents in the dielectric in +comparison with the conduction currents through the wire, then +the line integral of the magnetic force round the inner surface +of the outer conductor must equal $4 \pi I_0 \epsilon^{\iota (mz + pt)}$; using this +principle we see that~$E$ in equation~(\eqnref{262}{11}), \artref{262}{Art.~262}, equals +$ -\iota n' \sigma' I_0/2 \pi \smallbold{b} K_0' (\iota n' \smallbold{b})$, and hence the electromotive intensity +parallel to~$z$ in the outer conductor is equal to the real part of +\[ +- \frac{\iota \sigma' n'}{2 \pi \smallbold{b}}\, + \frac{K_0 (\iota n' r)}{K_0' (\iota n' \smallbold{b})}\, + I_0 \epsilon^{-\beta z} \epsilon^{\iota(-\alpha z + pt)}, \Tag{58} +\] +the notation being the same as in \artref{262}{Art.~262}. + +The tangential magnetic force at the surface of the wire is +(\artref{262}{Art.~262}) +\[ +\frac{2 I_0}{\smallbold{a}} \epsilon^{-\beta z} \cos (-\alpha z + pt), \Tag{59} +\] +while that at the surface of the outer conductor is, if we neglect +the polarization currents in the dielectric in comparison with +the conduction currents through the wire, +\[ +\frac{2 I_0}{\smallbold{b}} \epsilon^{-\beta z} \cos (-\alpha z + pt). \Tag{60} +\] + +Let us now consider the case when the rate of alternation of +the current is so slow that both $n\smallbold{a}$~and~$n'\smallbold{b}$ are small quantities. +When $n\smallbold{a}$~is small $J_0'(\iota n\smallbold{a}) = -\iota n\smallbold{a}/2$, while $J_0(\iota n \smallbold{a}) = 1$ approximately; +hence, putting $r = \smallbold{a}$ in~(\eqnref{282}{57}), we find that the +tangential electromotive intensity is +\[ +\frac{\sigma}{\pi \smallbold{a}^2}\, I_0 \epsilon^{-\beta z} \cos (-\alpha z + pt). +\] +Hence by (\eqnref{281}{56})~and~(\eqnref{282}{59}) the rate of heat production in the wire is +equal to the mean value of +\[ +\frac{\sigma}{\pi \smallbold{a}^2}\, I_0^2 \epsilon^{-2\beta z} \cos^2 (-\alpha z + pt). +\] +%% -----File: 330.png---Folio 316------- +\begin{DPgather*} +\lintertext{that is to} \frac{\sigma}{2 \pi \smallbold{a}^2}\, I_0^2 \epsilon^{-2 \beta z}. +\end{DPgather*} + +Let us now consider the rate of heat production in the outer +conductor; since $n'\smallbold{b}$~is very small, we have approximately +\[ +K_0 (\iota n' \smallbold{b}) = \log (2 \gamma/\iota n' \smallbold{b}), \quad +K_0' (\iota n' \smallbold{b}) = -1/\iota n' \smallbold{b}. +\] +Making these substitutions in~(\eqnref{282}{58}), we see that the tangential +electromotive intensity at the surface of the outer conductor is +equal to the real part of +\[ +- \frac{\sigma' n'^2}{2 \pi} \log ( 2 \gamma / \iota n' \smallbold{b})\, + I_0 \epsilon^{-\beta z} \epsilon^{\iota(-\alpha z + pt)}, +\] +and since $n'^2 = 4 \pi \mu' \iota p / \sigma'$, the real part of this expression is +\begin{multline*} +2 \mu' p \log (\gamma \sqrt{\sigma' / \pi \mu' p \smallbold{b}^2}) + I_0 \epsilon^{-\beta z} \sin (-\alpha z + pt) \\ + -\tfrac{3}{2} \pi \mu' p I_0 \epsilon^{-\beta z} \cos(-\alpha z + pt). +\end{multline*} + +Hence by (\eqnref{281}{56})~and~(\eqnref{282}{60}) the rate of heat production in the +outer conductor is equal to +\[ +\tfrac{3}{4} \pi \mu' p I_0^2 \epsilon^{-2 \beta z}, +\] +since the mean value with respect to the time of +\[ +\sin (-\alpha z + pt) \cos (-\alpha z + pt) +\] +is zero. Thus, when $n'\smallbold{b}$~is small, the rate of heat production in +the outer conductor is independent both of the radius and specific +resistance of that conductor. The ratio of the heat produced in +unit time in the wire to that produced in the outer conductor is +thus $2 \sigma / 3 \pi^2 \smallbold{a}^2 \mu' p$, which is very large since we have assumed that +$n^2 \smallbold{a}^2$, i.e.~$4 \pi \mu p \smallbold{a}^2 / \sigma$, is a small quantity; in this case, therefore, by +far the larger proportion of the heat is produced in the wire. +This explains the result found in \artref{263}{Art.~263} that the rate of decay +of the vibrations is nearly independent of the resistance of the +outer conductor and depends almost wholly upon that of the +wire. + +\Article{283} When the frequency is so great that $n\smallbold{a}$~is large though +$n'\smallbold{b}$~is still small, then $J_0(\iota n\smallbold{a}) = \iota J_0'(\iota n\smallbold{a})$, so that by~(\eqnref{282}{57}) the +tangential electromotive intensity at the surface of the wire is +equal to the real part of +\[ +\frac{\sigma}{2 \pi \smallbold{a}} \{4 \pi \mu \iota p / \sigma \}^\frac{1}{2}\, + I_0 \epsilon^{-\beta z} \epsilon^{\iota (-\alpha z + pt)}, +\] +%% -----File: 331.png---Folio 317------- +\index{Heat produced by electric discharge, in wires carrying alternating currents@\subdashtwo in wires carrying alternating currents}% +which is equal to +\[ +\frac{\sigma}{2 \pi \smallbold{a}} \{2 \pi \mu p / \sigma\}^{\frac{1}{2}} + I_0 \epsilon^{-\beta z} \{\cos (-\alpha z+pt)-\sin(-\alpha z+pt)\}. +\] +Hence by (\eqnref{281}{56})~and~(\eqnref{282}{59}) the mean rate of heat production in the +wire is equal to +\[ +\frac{\sigma}{4 \pi \smallbold{a}} ( 2 \pi \mu p/ \sigma)^{\frac{1}{2}} + I_0^{2} \epsilon^{-2 \beta z.} +\] +Since $n'\smallbold{b}$~is supposed to be small the rate of heat production +in the outer conductor is as before +\[ +\frac{3 \pi}{4} \mu' p I_0^{2} \epsilon^{-2 \beta z}, +\] +hence the ratio of the amount of heat produced in unit time in +the wire to that produced in the outer conductor is +\[ +\frac{\mu}{\mu'} + \left\{\frac{2 \sigma}{9 \pi^3 p \mu \smallbold{a}^2} \right\}^{\frac{1}{2}}. +\] +Thus, since $n^2 \smallbold{a}^2$ and so~$4 \pi p \mu \smallbold{a}^2 / \sigma$ is very large by hypothesis, we +see that unless $\mu / \mu'$~is very large this ratio will be very small; in +other words the greater part of the heat is produced in the +outer conductor; this is in accordance with the result obtained +in \artref{266}{Art.~266}, which showed that the rate of decay of the vibrations +was independent of the resistance of the wire. + +\Article{284} When the frequency is so high that both $n \smallbold{a}$~and~$n' \smallbold{b}$ +are large, then the expression for the heat produced in the wire +is that just found. To find the heat produced in the outer conductor +we have, when $n' \smallbold{b}$~is very large, +\[ +K_0 ( \iota n' \smallbold{b})=-\iota K_0' ( \iota n' \smallbold{b} ); +\] +hence by~(\eqnref{282}{58}) the tangential electromotive intensity in the outer +conductor is equal to the real part of +\[ +-\frac{\sigma'}{2 \pi \smallbold{b}} ( 4 \pi \mu' \iota p / \sigma')^{\frac{1}{2}} + I_0 \epsilon^{-\beta z} \epsilon^{\iota (-\alpha z+pt)}, +\] +which is equal to +\[ +-\frac{\sigma'}{2 \pi \smallbold{b}} ( 2 \pi \mu' p / \sigma' )^{\frac{1}{2}} + I_0 \epsilon^{-\beta z} \{\cos ( -\alpha z+pt) - \sin ( - \alpha z+pt)\}. +\] +Hence by (\eqnref{281}{56})~and~(\eqnref{282}{60}) the mean rate of heat production in the +outer conductor is +\[ +\frac{\sigma'}{4 \pi \smallbold{b}} \{2 \pi \mu' p / \sigma' \}^{\frac{1}{2}} + I_0^{2} \epsilon^{-2 \beta z}. +\] +%% -----File: 332.png---Folio 318------- +\index{Alternating currents, heat produced in wire traversed by@\subdashtwo heat produced in wire traversed by}% +\index{Heat produced by electric discharge, in wires carrying alternating currents@\subdashtwo in wires carrying alternating currents}% + +Thus the ratio of the heat produced in unit time in the wire +to that produced in the same time in the outer conductor is +\[ +\Bigl\{\frac{\mu \sigma}{\smallbold{a}^2} \Bigr\}^{\frac{1}{2}} \bigg/ +\Bigl\{\frac{\mu' \sigma'}{\smallbold{b}^2} \Bigr\}^{\frac{1}{2}}, +\] +so that if, as is generally the case in cables, $\sigma'$~is very much +greater than~$\sigma$, by far the larger part of the heat will be produced +in the outer conductor. + +\Subsection{Heat produced by Foucault Currents in a Transformer.} +\index{Foucault currents, heat produced by, in a transformer}% +\index{Heat produced by electric discharge, by Foucault currents in a transformer@\subdashtwo by Foucault currents in a transformer}% +\index{Transformer, heat produced in}% + +\Article{285} We shall now proceed to consider the case discussed +in \artref{278}{Art.~278}, where the lines of magnetic force are in planes +through the axis of the wire, the currents flowing in circles in +planes at right angles to this axis. This case is one which is of +great practical importance, as the conditions approximate to +those which obtain in the soft iron cylindrical core of an induction +coil or a transformer; in this case the windings of the +primary coil are in planes at right angles to the axis of the iron +cylinder, while the lines of magnetic force due to the primary +coil are in planes passing through this axis. When a variable +current is passing through the primary coil, currents are induced +which heat the core and the heat thus produced is wasted as +far as the production of useful work is concerned; it is thus a +matter of importance to investigate the laws which govern its +development, so that the apparatus may be designed in such a +way as to reduce this waste to a minimum. We shall suppose +that the magnetic force parallel to the axis at the surface of the +wire is represented by the real part of +\[ +H \epsilon^{\iota (mz + pt)}, +\] +or if $m = \alpha + \iota \beta$, by +\[ +H \epsilon^{-\beta z} \cos (\alpha z + pt). +\] +The magnetic force at the surface of the cylinder is the most +convenient quantity in which to express the rate of heat production, +for it is due entirely to the external field and is +not, when the field is uniform, affected by the currents in the +wire itself. + +Using the notation of \artref{278}{Art.~278} we see by the results of that +article that in the wire +\[ +c = A J_0 (\iota n r) \epsilon^{\iota (mz + pt)}. +\] +%% -----File: 333.png---Folio 319------- + +The tangential electromotive intensity~$\Theta$ is given by the +equation +\begin{DPgather*} +\frac{dc}{dt} = -\frac{1}{r} \frac{d}{dr} (r \Theta); \\ +\lintertext{hence} \Theta = \frac{p}{n} A J_0' (\iota n r) \epsilon^{\iota (mz+pt)}; +\end{DPgather*} +but since at the surface of the wire, $c$~is equal to the real part of +\[ +\mu H \epsilon^{-\beta z} \epsilon^{\iota (\alpha z + pt)} , +\] +we see that at the surface $\Theta ={}$real part of +\[ +\frac{p}{n}\, \frac{J_0' (\iota n \smallbold{a})}{J_0 (\iota n \smallbold{a})} + \mu H \epsilon^{-\beta z} \epsilon^{\iota (\alpha z + pt)}.\Tag{61} +\] + +Let us first take the case when the radius of the wire is +so small that $n \smallbold{a}$~is small; in this case we have, since approximately +\begin{DPalign*} +J_0(x) & = 1 - \frac{x^2}{2^2} + \frac{x^4}{2^{2} 4^2},\\ +J_0'(x) & = -\tfrac{1}{2} x \left\{1 - \frac{x^2}{8} \right\}, \\ +\lintertext{and} n^2 & = 4 \pi \mu \iota p / \sigma, +\end{DPalign*} +\begin{multline*} +\Theta = \text{real part of} \\ +\shoveleft{-\tfrac{1}{2} \iota \smallbold{a} p + \left\{1 - \frac{\pi \mu \iota p \smallbold{a}^2}{2 \sigma} \right\} + \mu H \epsilon^{-\beta z} \epsilon^{\iota (\alpha z + pt)}}\\ + = \tfrac{1}{2} \mu \smallbold{a} p H \epsilon^{-\beta z} \sin(\alpha z + pt) + - \frac{1}{4 \sigma} \pi \mu^2 p^2 \smallbold{a}^3 H \epsilon^{-\beta z} \cos (\alpha z + pt). +\end{multline*} + +But by equation~(\eqnref{281}{56}) the rate of heat production in the +wire per unit length is equal to the mean value +\[ +-\tfrac{1}{2} \smallbold{a} \Theta H \epsilon^{-\beta z} \cos (\alpha z + pt); +\] +where the minus sign has been taken because (\artref{280}{Art.~280}) $\Theta H$~is +proportional to the rate of flow of energy in the direction of +translation of a right-handed screw twisting from~$\Theta$ to~$H$; in +this case this direction is radially \emph{outwards}. + +Thus the rate of heat production in the wire is +\[ +\frac{1}{16 \sigma} \pi \mu^2 p^2 \smallbold{a}^4 H^2 \epsilon^{-2 \beta z}, +\] +and is thus proportional to the conductivity, so that good +conductors will in this case absorb more energy than bad ones. +%% -----File: 334.png---Folio 320------- + +Let us now apply this result to find the energy absorbed +in the core of a transformer or induction coil. We shall +suppose that the core consists of iron wire of circular section, +the wires being insulated from each other by the coating of +rust with which they are covered. We shall consider the case +when the magnetic force due to the primary coil is uniform both +along the axis of the coil and over its cross-section. When the +external magnetic force is uniform along~$z$, the axis of a wire, the +currents induced in the wire by the variation of the magnetic +force flow in circles whose planes are at right angles to~$z$, and +the intensities of the currents are independent of the value of~$z$. +Under these circumstances the currents in the wire do not give +rise to any magnetic force outside it. The magnetic force +outside the wires will thus be due entirely to the primary coil, +and as this magnetic force is uniform over the cross-section +it will be the same for each of the wires, so that we can +apply the preceding investigation to the wires separately. +In order to use the whole of the iron, the magnetic force must +be approximately uniformly distributed over the cross-section +of the wires; for this to be the case $n \smallbold{a}$~must be small, as we +have seen that when $n \smallbold{a}$~is large the magnetic force is confined +to a thin skin round each wire. For soft iron, for which +we may put $\mu = 10^3$, $\sigma = 10^4$, the condition that $n \smallbold{a}$~is small +implies that when the primary current makes one hundred +alternations per second, the radius of the wire should not be +more than half a millimetre. If now the total cross-section of +the iron is kept constant so as to keep the magnetic induction +through the core constant, we have, if $\smallbold{N}$~is the number of wires, +$\smallbold{A}$~the total cross-section of the iron, +\[ +\smallbold{N} \pi \smallbold{a}^2 = \smallbold{A}. +\] + +The heat produced in all the wires per unit length of core in +one second is, if $H$~is the maximum magnetic force due to the coil, +\begin{DPgather*} +\frac{\smallbold{N}}{16 \sigma} \pi \mu^2 p^2 \smallbold{a}^4 H^2, \\ +\lintertext{or} \frac{\smallbold{A}^2}{16 \pi \sigma \smallbold{N}} \mu^2 p^2 H^2, +\end{DPgather*} +and is thus \emph{inversely proportional to the number of wires}. We +may therefore diminish the waste of energy due to the heat +%% -----File: 335.png---Folio 321------- +produced by the induced currents in the wires by increasing the +number of wires in the core. We thus arrive at the practical rule +that to diminish the waste of work by eddy currents the core +should be made up of as fine wire as possible. In many transformers +the iron core is built up of thin plates instead of wires; +when this is the case the advantage of a fine sub-division of the +core is even more striking than for wires, for we can easily +prove that the work wasted by eddy currents is inversely proportional +to the square of the number of plates (see J.~J. Thomson, +\textit{Electrician}, 28, p.~599, 1892). + +If $\gamma$~is the current flowing through the primary coil and $N$~the +number of turns of this coil per centimetre, then +\begin{DPgather*} +H \cos p t= 4 \pi N \gamma, \\ +\lintertext{and} \tfrac{1}{2} H^2 = 16 \pi^2 N^2\, (\text{mean value of~$\gamma^2$}), +\end{DPgather*} +thus in the case of a cylindrical core of radius~$\smallbold{a}$ the heat produced +in one second in a length~$l$ of the core will be +\[ +2 \pi^3 \mu^2 p^2 \smallbold{a}^4 N^2 l\, (\text{mean value of~$\gamma^2$}) / \sigma. +\] + +If $\smallbold{Q}$ is the \emph{impedance} of a circuit (\artref{272}{Art.~272}) the heat produced +in unit time is equal to +\[ +\smallbold{Q}\,(\text{mean value of~$\gamma^2$}); +\] +thus the core will increase the impedance of the primary coil by +\[ +2 \pi^3 \mu^2 p^2 \smallbold{a}^4 N^2l / \sigma. +\] + +\Article{286} Let us now consider the case when $n \smallbold{a}$~is large; here we +have +\begin{DPgather*} +J_0'(\iota n \smallbold{a}) = -\iota J_0(\iota n \smallbold{a}), \\ +\lintertext{and since} n^2 = 4 \pi \mu \iota p / \sigma, +\end{DPgather*} +we see by~(\eqnref{285}{61}), putting $\alpha$~and~$\beta$ equal to zero, that +\begin{gather*} +\Theta = \text{real part of}\\ +- \sqrt{\frac{p \mu \sigma}{4 \pi}}\, + \epsilon^{\frac{\iota \pi}{4}} H \epsilon^{\iota pt}\\ + = - \sqrt{\frac{p \mu \sigma}{8 \pi}}\, H \{\cos pt - \sin pt\}. +\end{gather*} + +But by equation~(\eqnref{281}{56}) the rate of heat production per unit +length is equal to the mean value of +\[ +- \tfrac{1}{2} \smallbold{a} \Theta H \cos pt, +\] +and is thus equal to +\[ +\frac{1}{8} \sqrt{\frac{p \mu \sigma}{\pi 2}}\, \smallbold{a} H^2. +\] +%% -----File: 336.png---Folio 322------- + +We can show, as before, that this corresponds to an increase +in the impedance of the primary circuit equal to +\[ +4 \pi^2 l N^2 \{p\mu\sigma/2\pi\}^{\frac{1}{2}} \smallbold{a}. +\] + +In this case the heat produced is proportional to the square +root of the specific resistance of the core, so the worse the conductivity +of the core the greater the amount of heat produced by +eddy currents, whereas in the case when $n\smallbold{a}$~was small, the +greater the conductivity of the core the greater was the loss due +to heating. + +When $n\smallbold{a}$~is large, the heat produced varies as the circumference +of the core instead of, as in the previous case, as the square +of the area; it also varies much more slowly with the frequency +and magnetic permeability. This is due to the fact that when +$n\smallbold{a}$~is large the currents are not uniformly distributed over the +core but confined to a thin layer on the outside, the thickness of +this layer diminishing as the magnetic permeability or the frequency +increases; thus, though an increase in $\mu$~or~$p$ may be +accompanied by an increase in the intensity of the currents, it +will also be attended by a diminution in the area over which +the currents are spread, and thus the effect on the heat produced +of the increase in $p$~or~$\mu$ will not be so great as in the previous +case when $n\smallbold{a}$~was small, and when no limitation in the area +over which the current was spread accompanied an increase in +the frequency or magnetic permeability. + +If we compare the absorption of energy when $n\smallbold{a}$~is large by +\index{Alternating magnetic force, behaviour of iron under@\subdashone magnetic force, behaviour of iron under}% +\index{Magnetic yproperties of iron in rapidly alternating fields@\subdashone properties of iron in rapidly alternating fields}% +\index{Iron, magnetic properties of@\subdashone magnetic properties of, under rapidly alternating currents}% +cores of iron and copper of the same size subject to alternating +currents of the same frequency, we find---since for iron $\mu$~may +be taken as~$10^3$ and~$\sigma$ as~$10^4$, while for copper $\mu = 1$, $\sigma = 1600$,---that +the absorption of energy by the iron core is between~$70$ and +$80$~times that by the copper. The greater absorption by the iron +can be very easily shown by an experiment of the kind figured +in \artref{85}{Art.~85}, in which two coils are placed in the circuit connecting +the outer coatings of two Leyden Jars; in one of these coils +an exhausted bulb is placed, while the core in which the heat +produced is to be measured is placed in the other. When the +oscillating current produced by the discharge of the jars passes +through the coils a brilliant discharge passes through the exhausted +bulb in~$\smallbold{A}$, if the coil~$\smallbold{B}$ is empty or if it contains a +copper cylinder; if however an iron cylinder of the same size +%% -----File: 337.png---Folio 323------- +replaces the copper one, the discharge in the bulb is at once +extinguished, showing that the iron cylinder has absorbed a +great deal more energy than the copper one. This experiment +also shows that iron retains its magnetic properties even when +the forces to which it is exposed are reversed, as in this experiment, +millions of times in a second. + +\Article{287} Another remarkable result is that though a cylinder or +\index{Heat produced by electric discharge, by currents induced in a tube@\subdashtwo by currents induced in a tube}% +\index{Tube, heat produced in under variable magnetic field}% +tube of a non-magnetic metal does not stop the discharge in the +bulb in~$\smallbold{A}$, yet if a piece of glass tubing of the same size is +coated with thin tinfoil or Dutch metal, or if it has a film of +silver deposited upon it, it will check the discharge very decidedly. +We are thus led to the somewhat unexpected result that a +thin layer of metal when exposed to very rapidly alternating +currents may absorb more energy than a thick layer. The +following investigation affords the explanation of this, and shows +that there is a certain thickness for which the heat produced is +a maximum. This result can easily be verified by the arrangement +just described, for if an excessively thin film of silver is +deposited on a beaker very little effect is produced on the discharge +in the bulb placed in~$\smallbold{A}$, but if successive layers +of very thin tinfoil are wrapped round the beaker over the +silver film the brightness of the discharge in~$\smallbold{A}$ at first rapidly +diminishes, it however soon increases again, and when a few +layers of tinfoil have been wrapped round the beaker the +discharge becomes almost as bright as if the beaker were +away. + +To investigate the theory of this effect we shall calculate the +energy absorbed by a metal tube of circular cross-section, when +placed inside a primary coil whose windings are in planes at +right angles to the axis of the tube; this coil is supposed to be +long, and uniformly wound, so that the distribution of magnetic +force and current is the same in all planes at right angles to +its axis. We shall use the same notation as before; the only +symbols which it is necessary to define again are $\smallbold{a}$~and~$\smallbold{b}$, +which are respectively the internal and external radius of the +tube, and $V$~the velocity with which electromagnetic action +is propagated through the dielectric inside the tube. The +magnetic force outside the tube is represented by the real part +of~$H \epsilon^{\iota pt}$, and this force is due entirely to the currents in the +primary coil. +%% -----File: 338.png---Folio 324------- + +Then $\gamma$, the magnetic force parallel to the axis of the tube, +may be (\artref{262}{Art.~262}) expressed by the following equations, +\begin{align*} +\gamma = AJ_0 (\iota kr)\epsilon^{\iota pt} \text{ in the dielectric inside the tube}, \\ +\gamma = \{BJ_0 (\iota nr) + + CK_0 (\iota nr)\}\epsilon^{\iota pt} \text{ in the tube itself}. +\end{align*} + +Here $k^2 = -p^2 /V^2$, $n^2 = 4\pi\mu\iota p/\sigma$, thus they represent the quantities +represented by the same symbols in previous investigations, +if in these we put~$m = 0$. + +Let $\smallbold{I}$~denote the tangential current at right angle to~$r$ and the +axis of the cylinder, then +\[ +4\pi \smallbold{I} = -\frac{d\gamma}{dr}, +\] +if $\Theta$~is the tangential electromotive intensity in the same direction, +then in the dielectric +\begin{DPalign*} +\smallbold{I} & = \frac{K}{4\pi}\, \frac{d\Theta}{dt} \\ +& = \frac{K}{4\pi}\, \iota p\Theta, \\ +\lintertext{so that} \Theta & = -\frac{V^2}{\iota p}\, \frac{d\gamma}{dr}, +\end{DPalign*} +since $1/K = V^2$. + +\begin{DPalign*} +\lintertext{\indent In the tube} \Theta & = \sigma \smallbold{I} \\ +& = -\frac{\sigma}{4\pi}\, \frac{d\gamma}{dr}. +\end{DPalign*} + +Since $\gamma$~is continuous, we have +\[ +AJ_0 (\iota k\smallbold{a}) = BJ_0 (\iota n\smallbold{a}) + CK_0 (\iota n\smallbold{a}), +\] +and since $\Theta$~is continuous, we have +\[ +\frac{V^2k}{p} AJ_0'(\iota k\smallbold{a}) + = \frac{\sigma\iota n}{4\pi} \{BJ_0'(\iota n\smallbold{a}) + CK_0'(\iota n\smallbold{a})\}. +\] + +Since $\iota k = p/V$, $\iota k\smallbold{a}$~will be very small, hence we may put +\[ +J_0 (\iota k\smallbold{a}) = 1, \quad +J_0' (\iota k\smallbold{a}) = -\tfrac{1}{2} \iota k\smallbold{a}. +\] +Making these substitutions and remembering that +\[ +J_0 (\iota n\smallbold{a})K_0' (\iota n\smallbold{a}) + - J_0' (\iota n\smallbold{a})K_0 (\iota n\smallbold{a}) = -\frac{1}{\iota n\smallbold{a}}, +\] +we find +\begin{align*} +B & = -A \{K_0'(\iota n\smallbold{a}) + \frac{\iota n\smallbold{a}}{2\mu} K_0(\iota n\smallbold{a})\}\iota n\smallbold{a}, \\ +C & = A \{J_0'(\iota n\smallbold{a}) + \frac{\iota n\smallbold{a}}{2\mu} J_0(\iota n\smallbold{a})\}\iota n\smallbold{a}. +\end{align*} +%% -----File: 339.png---Folio 325------- + +To determine~$A$ we have the condition that when +\begin{DPgather*} +r = \smallbold{b}, \quad \gamma = H \epsilon^{\iota p t}, \\ +\lintertext{hence} +H \epsilon^{\iota p t} + = \{BJ_0(\iota n\smallbold{b}) + CK_0(\iota n\smallbold{b})\} \epsilon^{\iota p t}. +\end{DPgather*} +In order to find the heat produced in the tube we require the +value of~$\Theta$ when~$r=\smallbold{b}$; but here +\[ +\Theta = -\frac{\sigma \iota n}{4 \pi} + \{BJ_0'(\iota n \smallbold{b}) + CK_0'(\iota n \smallbold{b})\} \epsilon^{\iota p t}. +\] + +{Eliminating $B$~and~$C$ from these equations, we find +\begin{multline*} +-\Theta = \text{real part of } H \epsilon^{\iota pt} \frac{\sigma \iota n}{4 \pi} × \\ +\text{\footnotesize$\frac{\left\{J_0'(\iota n\smallbold{a}) K_0'(\iota n\smallbold{b}) + - J_0'(\iota n\smallbold{b}) K_0'(\iota n\smallbold{a}) + + \frac{\iota n\smallbold{a} }{2\mu} + [J_0(\iota n\smallbold{a}) K_0'(\iota n\smallbold{b}) + - J_0'(\iota n\smallbold{b}) K_0(\iota n\smallbold{a})]\right\}} + {J_0'(\iota n\smallbold{a}) K_0 (\iota n\smallbold{b}) + - J_0 (\iota n\smallbold{b}) K_0'(\iota n\smallbold{a}) + + \frac{\iota n\smallbold{a} }{2\mu} + [J_0 (\iota n\smallbold{a}) K_0 (\iota n\smallbold{b}) + - J_0 (\iota n\smallbold{b}) K_0 (\iota n\smallbold{a})]}$}. +\end{multline*} +} + +The effect we are considering is one which is observed when +the rate of alternation of the current is very high, so that both +$n\smallbold{a}$~and~$n\smallbold{b}$ are very large; but when this is the case +\begin{align*} +J_0(\iota n\smallbold{a}) & = \frac{\epsilon^{n\smallbold{a}}}{\sqrt{2 \pi n \smallbold{a}}}, & +J_0'(\iota n\smallbold{a}) & = -\frac{\iota \epsilon^{n\smallbold{a}}}{\sqrt{2 \pi n \smallbold{a}}},\\ +% +K_0(\iota n\smallbold{a}) & = \epsilon^{-n\smallbold{a}} \sqrt{\frac{\pi}{2 n \smallbold{a}}}, & +K_0'(\iota n \smallbold{a}) & = \iota \epsilon^{-n\smallbold{a}} \sqrt{\frac{\pi}{2 n \smallbold{a}}},\\ +% +J_0(\iota n\smallbold{b}) & = \frac{\epsilon^{n\smallbold{b}}}{\sqrt{2 \pi n \smallbold{b}}}, & +J_0'(\iota n \smallbold{b}) & = -\frac{\iota \epsilon^{n\smallbold{b}}}{\sqrt{2 \pi n \smallbold{b}}},\\ +% +K_0(\iota n\smallbold{b}) & = \epsilon^{-n\smallbold{b}} \sqrt{\frac{\pi}{2 n \smallbold{b}}}, & +K_0'(\iota n \smallbold{b}) & = \iota \epsilon^{-n\smallbold{b}} \sqrt{\frac{\pi}{2 n \smallbold{b}}}; +\end{align*} +making these substitutions and writing~$h$ for $\smallbold{b}-\smallbold{a}$, we find +\[ +-\Theta = \text{real part of} \quad +\frac{\sigma n}{4 \pi}\, + \frac{\epsilon^{nh} - \epsilon^{-nh} + \dfrac{n\smallbold{a}}{2\mu}\left(\epsilon^{nh} + \epsilon^{-nh}\right)} + {\epsilon^{nh} + \epsilon^{-nh} + \dfrac{n\smallbold{a}}{2\mu}\left(\epsilon^{nh} - \epsilon^{-nh}\right)}\, + H \epsilon^{\iota p t}. \Tag{62} +\] + +Now since $n \smallbold{a}$~is very large, $n\smallbold{a}/\mu$~is also very large for the +non-magnetic metals, and even for the magnetic metals if the +frequency of the currents in the primary is exceedingly large; +%% -----File: 340.png---Folio 326------- +but when this is the case, then, unless $h$~is so small that $n^2 \smallbold{a} h / \mu$~is +no longer large, we may write equation~(\eqnref{287}{62}) as +\[ +-\Theta = \text{real part of} \quad +\frac{\sigma n}{4 \pi}\, + \frac{\epsilon^{nh} + \epsilon^{-nh}} + {\epsilon^{nh} - \epsilon^{-nh}}\, H \epsilon^{\iota pt}. \Tag{63} +\] + +Since $n=\{4 \pi \mu \iota p / \sigma \}^{\frac{1}{2}}$, we may write +$n=n_1(1+\iota)$, where $n_1=\{2 \pi \mu p / \sigma\}^{\frac{1}{2}}$, and equation~(\eqnref{287}{63}) becomes +\begin{multline*} +\Theta = -\frac{\sigma n_1}{4 \pi}\, + \frac{\epsilon^{2n_1h} - \epsilon^{-2n_1h} + 2\sin 2n_1h} + {\epsilon^{2n_1h} + \epsilon^{-2n_1h} - 2\cos 2n_1h}\, H \cos pt \\ + + \frac{\sigma n_1}{4 \pi}\, + \frac{\epsilon^{2n_1h} - \epsilon^{-2n_1h} - 2\sin 2n_1h} + {\epsilon^{2n_1h} + \epsilon^{-2n_1h} - 2\cos 2n_1h}\, H \sin pt. \Tag{64} +\end{multline*} + +In calculating the part of the energy flowing into the tube +which is converted into heat, we need only consider the part +which flows across the outer surface of the tube, because the +energy flowing across the inner surface is equal to that which +flows into the dielectric inside the tube, and since there is no +dissipation of energy in this region the average of the flow of +energy across the inner surface of the tube must vanish. Hence +the amount of heat produced in unit time in the tube is by equation~(\eqnref{271}{36}) +equal to the mean value of +\[ +-\tfrac{1}{2} \smallbold{b} \Theta H \cos pt, +\] +where the $-$~sign has been taken because the translatory motion +of a right-handed screw twisting from~$\Theta$ to~$H$ is radially outwards; +this by~(\eqnref{287}{64}) is equal to +\[ +\frac{\sigma n_1 \smallbold{b}}{16 \pi}\, + \frac{(\epsilon^{2n_1h} - \epsilon^{-2n_1h} + 2\sin 2n_1h)} + {\epsilon^{2n_1h} + \epsilon^{-2n_1h} - 2\cos 2n_1h}\, H^2; +\] +when $n_1h$~is very large this is equal to +\[ +\frac{\sigma n_1 \smallbold{b}}{16 \pi}\, H^2, +\] +which is (\artref{286}{Art.~286}), as it ought to be, the same as for a solid +cylinder of radius~$\smallbold{b}$. + +When $h$~is small and $n^2 \smallbold{a} h / \mu$ not large we must take into +account terms which we have neglected in arriving at the +preceding expression. +%% -----File: 341.png---Folio 327------- + +In this case, we find from~(\eqnref{287}{62}) that +\[ +\Theta + = -\frac{(\pi p^2 \smallbold{a}^2 h / \sigma)H\cos pt} + {1 + 4 \pi^2 p^2 \smallbold{a}^2 h^2/ \sigma^2} + + \tfrac{1}{2} + \frac{p \smallbold{a} H \sin pt} + {1 + 4 \pi^2 p^2 \smallbold{a}^2 h^2/ \sigma^2}, \Tag{65} +\] +so that the rate of heat production is +\[ +\tfrac{1}{4} + \frac{(\pi p^2 \smallbold{a}^2 \smallbold{b} h/ \sigma) H^2} + {1 + 4 \pi^2 p^2 \smallbold{a}^2 h^2/\sigma^2}. +\] +Thus it vanishes when $h=0$, and is a maximum when +\[ +h = \frac{\sigma}{2\pi \smallbold{a} p}; +\] +the rate of heat production is then +\[ +\tfrac{1}{16} p \smallbold{b} \smallbold{a} H^2, +\] +and bears to the rate when the tube is solid the ratio +\[ +\frac{\pi p \smallbold{a}}{n_1 \sigma} : 1, +\] +which is equal to~$n_1 \smallbold{a} / 2 \mu$. + +Since $n_1 \smallbold{a} / \mu$~is very large the heat produced in a tube of this +thickness is very much greater than that produced in a solid +cylinder. + +Let us take the case of a tin tube whose internal radius is +$3$~cm.\ surrounded by a primary coil conveying a current making +a hundred thousand vibrations per second, then since in this +case +\[ +\sigma = 1.3 × 10^4, \quad \smallbold{a}=3, \quad p = 2 \pi × 10^5, \quad \mu=1, +\] +the thickness which gives the maximum heat production is +about $1/90$~of a millimetre, and the heat produced is about $26$~times +as much as would be produced in a solid tin cylinder of +the same radius as the tube. + +We see from equation~(\eqnref{287}{65}) that the amplitude of~$\Theta$ diminishes +as the thickness of the plate increases, but that when the plate +is indefinitely thin the phases of the tangential electromotive +intensity and of the tangential magnetic force differ by a quarter-period; +the product of these quantities will thus be proportional +to~$\sin 2 pt$, and as the mean value of this vanishes there is no +energy converted into heat in the tube. As the thickness of +the tube increases the amplitude of~$\Theta$ diminishes, but the phase +of~$\Theta$ gets more nearly into unison with that of~$H$. We may +regard~$\Theta$ as made up of two oscillations, one being in the same +phase as~$H$ while the phase of the other differs from that of~$H$ by +%% -----File: 342.png---Folio 328------- +a quarter-period. The amplitude of the second component +diminishes as the thickness of the tube increases, while that of +the first reaches a maximum when $h = \sigma/2\pi \smallbold{a}p$. + +In the investigation of the heat produced when $h$~is small, +$n \smallbold{a} /\mu$~has been assumed large. We can however easily show +that unless this is the case the heat produced in a thin tube +will not exceed that produced in a solid cylinder. + + +\Subsection{Vibrations of Electrical Systems.} +\index{Electrical vibrations|indexetseq}% +\index{Vibrations of electrical systems|indexetseq}% + +\Article{288} If the distribution of electricity on a system in electrical +equilibrium is suddenly disturbed, the electricity will redistribute +itself so as to tend to go back to the distribution it +had when in electrical equilibrium; to effect this redistribution +electric currents will be started. The currents possess kinetic +energy which is obtained at the expense of the potential energy +of the original distribution of electricity; this kinetic energy +will go on increasing until the distribution of electricity is the +same as it was in the state from which it was displaced. As this +state is one of equilibrium its potential energy is a minimum. +The kinetic energy which the system has acquired will carry it +through this state, and the system will go on losing kinetic and +reacquiring potential energy until the kinetic energy has all +disappeared. The system will then retrace its steps, and if there +is no dissipation of energy will again regain the distribution +of electricity from which it started. The distribution of electricity +on the system will thus oscillate backwards and forwards; +we shall in the following articles endeavour to calculate +the time taken by such oscillations for some of the simpler +electrical systems. + + +\Subsection{Electrical Oscillations when Two Equal Spheres are connected +by a Wire\protect\footnotemark.} +\footnotetext{See J.~J. Thomson, \textit{Proc.\ Lond.\ Math.\ Soc.}~19, p.~542, 1888.} +\index{Time of vibration of two spheres connected by a wire@\subdashtwo vibration of two spheres connected by a wire}% + +\Article{289} The first case we shall consider is that of two equal +spheres, or any two bodies possessing equal electric capacities, +connected by a straight wire. This case can be solved at once +by means of the analysis given at the beginning of this chapter. + +Let us take the point on the wire midway between the +spheres as the origin of coordinates, and the axis of the wire as +%% -----File: 343.png---Folio 329------- +the axis of~$z$. We shall suppose that the electrostatic potential +has equal and opposite values at points on the wire equidistant +from the origin and on opposite sides of it. Then using the +same notation as in \artref{271}{Art.~271}, we may put +\begin{gather*} +\phi = L(\epsilon^{\iota mz} - \epsilon^{-\iota mz})\, + J_0(\iota mr)\epsilon^{\iota pt}, \text{ in the wire}, \\ + = L(\epsilon^{\iota mz} - \epsilon^{-\iota mz}) \epsilon^{\iota pt} +\end{gather*} +approximately, since $mr$~will be very small. Thus~$\smallbold{E}$, the external +electromotive intensity parallel to the wire, is equal to +\[ +-\iota mL(\epsilon^{\iota mz} + \epsilon^{-\iota mz})\epsilon^{\iota pt}. +\] + +If $2l$~is the length of the wire, then the potential of the sphere +at the end~$z=l$, will be +\[ +2\iota L\sin ml \epsilon^{\iota pt}. +\] + +If $C$~is the capacity of the sphere at one end of the wire, the +quantity of electricity on the sphere is +\[ +2\iota CL\sin ml \epsilon^{\iota pt}, +\] +and this increases at the rate +\[ +-2CpL\sin ml \epsilon^{\iota pt}. +\] +Now the increase in the charge of the sphere must equal the +current flowing through the wire at the point~$z=l$, hence if $I$~denotes +this current, we have +\[ +I = -2CpL\sin ml\epsilon^{\iota pt}, +\] +but by equation~(\eqnref{272}{39}) of \artref{272}{Art.~272} we have +\[ +\smallbold{E} = (\iota p \smallbold{P} + \smallbold{Q})I, +\] +whence substituting the values for~$\smallbold{E}$ and~$I$ when~$z=l$, we get +\begin{DPalign*} +-2 \iota mL\cos ml\epsilon^{\iota pt} + & = -(\iota p \smallbold{P} + \smallbold{Q})2CpL\sin ml\epsilon^{\iota pt}, \\ +\lintertext{or} m\cot ml + & = -\iota p(\iota p \smallbold{P} + \smallbold{Q})C. \Tag{66} +\end{DPalign*} + +\Article{290} Let us first consider the case when the wave length of +electrical vibrations is very much longer than the wire; here $ml$~is +very small, so that equation~(\eqnref{289}{66}) becomes +\[ +\frac{1}{l} = -\iota p(\iota p \smallbold{P} + \smallbold{Q})C. \Tag{67} +\] + +The values of $\smallbold{P}$~and~$\smallbold{Q}$, the self-induction and impedance of +the wire, are given in equation~(\eqnref{272}{40}) of \artref{272}{Art.~272}; they depend upon +the frequency of the electrical vibrations. When this is so +%% -----File: 344.png---Folio 330------- +slow that $n \smallbold{a}$~is a small quantity, $\smallbold{a}$~being the radius of the wire, +then approximately +\begin{align*} +\smallbold{P} & = \frac{L}{2l}, \\ +\smallbold{Q} & = \frac{R}{2l}, +\end{align*} +where $L$~is the coefficient of self-induction and $R$~the resistance +of the whole wire for steady currents. + +Substituting these values in~(\eqnref{290}{67}), we get +\begin{DPgather*} +(\iota p)^2 L + \iota pR + \frac{2}{C} = 0, \\ +\lintertext{or} \iota p = -\frac{R}{2L} ± \iota \sqrt{\frac{2}{CL} - \frac{R^2}{4L^2}}. \Tag{68} +\end{DPgather*} + +Since the various quantities which fix the state of the electric +field contain $\epsilon^{\iota pt}$ as a factor, we see that when $8L>CR^2$ these +quantities will be proportional to +\[ +\epsilon^{-\frac{R}{2L} t} + \cos \left\{\left(\frac{2}{CL} - \frac{R^2}{4L^2}\right)^{\frac{1}{2}} t + \alpha \right\}, +\] +where $\alpha$~is a constant. + +This represents an oscillation whose period is +\[ +2\pi \bigg/ \left\{\frac{2}{CL} - \frac{R^2}{4L^2} \right\}^{\frac{1}{2}}, +\] +and whose amplitude dies away to $1/\epsilon$~of its original value after +the time $2L/R$. + +Thus, if $2/CL$ is greater than~$R^2/4L^2$, that is if $R^2$~is less than~$8 L/C$, +the charges on the spheres will undergo oscillations like +those performed by a pendulum in a resisting medium. + +\sloppy +Suppose, for example, that the electrical connection between +\index{Oscillatory discharge}% +the spheres is broken, and let one sphere~$A$ be charged with +positive, the other sphere~$B$ with an equal quantity of negative +electricity; if now the electrical connection between the spheres +is restored, the positive charge on~$A$ and the negative on~$B$ will +diminish until after a time both spheres are free from electrification. +They will not however remain in this state, for negative +electricity will begin to appear on~$A$, positive on~$B$, and these +charges will increase in amount until (neglecting the resistance of +the circuit connecting the spheres) the charges on $A$~and~$B$ appear +to be interchanged, there being now on~$A$ the same quantity of +%% -----File: 345.png---Folio 331------- +negative electricity as there was initially on~$B$, while the charge +on~$B$ is the same as that originally on~$A$. When the negative +charge on~$A$ has reached this value it begins to decrease, and after +a time both spheres are again free from electrification. After this +positive electricity begins to reappear on~$A$, and increases until the +charge on~$A$ is the same as it was to begin with; this positive +charge then decreases, vanishes, and is replaced by a negative +one as before. The system thus behaves as if the charges +vibrated backwards and forwards between the spheres. The +changes which take place in the electrical charges on the spheres +are of course accompanied by currents in the wire, these currents +flowing sometimes in one direction, sometimes in the opposite. + +\fussy +When the circuit has a finite resistance the amplitude of the +\index{Condenser, discharge of}% +\index{Discharge, of a condenser@\subdashone of a condenser}% +\index{Leyden jar, oscillatory discharge of@\subdashtwo oscillatory discharge of|indexetseq}% +oscillations gradually diminishes, while if the resistance is greater +than~$(8 L/C)^{\frac{1}{2}}$ there will not be any vibrations at all, but the +charges will subside to zero without ever changing sign; in this +case the current in the connecting wire is always in one direction. + +\Article{291} If we assume that the wave length of the electrical +vibrations is so great that the current may be regarded as uniform +all along the wire, and that the vibrations are so slow that the +current is uniformly distributed across the wire, the discharge of +a condenser can easily be investigated by the following method, +which is due to Lord Kelvin (\textit{Phil.\ Mag.}~[4], 5, p.~393, 1853). +\index{Kelvin, Lord, xoscillatory discharge@\subdashtwo oscillatory discharge}% +Let $Q$~be the quantity of electricity on one of the plates of a +condenser whose capacity is~$C'$ and whose plates, like those of a +Leyden Jar, are supposed to be close together; also let $R$~be +the resistance and $L$~the coefficient of self-induction for steady +currents of the wire connecting the plates. The electromotive +force tending to increase~$Q$ is~$-Q/C'$; of this $R\,dQ/dt$ is required +to overcome the resistance and $L\,d^2Q/dt^2$ to overcome the inertia +of the circuit; hence we have +\[ +L\, \frac{d^2Q}{dt^2} + R\, \frac{dQ}{dt} + \frac{Q}{C'} = 0. \Tag{69} +\] + +The solution of this equation is, if +\begin{gather*} +\frac{1}{C'L} > \frac{R^2}{4L^2}, \\ +Q = A \epsilon^{-\frac{R}{2L} t} + \cos \left\{\left( \frac{1}{C'L} - \frac{R^2}{4L^2}\right)^{\frac{1}{2}} t + \beta \right\}, +\end{gather*} +where $A$~and~$\beta$ are arbitrary constants. +%% -----File: 346.png---Folio 332------- + +In this case we have an oscillatory discharge whose frequency +is equal to +\begin{DPgather*} +\left( \frac{1}{C'L} - \frac{R^2}{4L^2} \right)^{\frac{1}{2}}. \\ +\lintertext{When} \frac{1}{C'L} < \frac{R^2}{4L^2}, +\end{DPgather*} +the solution of equation~(\eqnref{291}{69}) is +\[ +Q = \epsilon^{-\frac{R}{2L} t} + \left\{A \epsilon^{\left(\frac{R^2}{4L^2} - \frac{1}{C'L}\right)^{\frac{1}{2}} t} + + B \epsilon^{-\left(\frac{R^2}{4L^2} - \frac{1}{C'L}\right)^{\frac{1}{2}} t} \right\}, +\] +where $A$~and~$B$ are arbitrary constants. In this case the discharge +is not oscillatory. + +To compare the results of this investigation with those of the +previous one, we must remember that the capacities which occur +in the two investigations are measured in somewhat different +ways. The capacity~$C$ in the first investigation is the ratio of +the charge on the condenser to~$\phi$ its potential; in the second +investigation $C'$~is the ratio of the charge to~$2\phi$, the difference +between the potentials of the plates, so that to compare the +results we must put $C' = C/2$; if we do this the results given +by the two investigations are identical. + +\Article{292} The existence of electrical vibrations seems to have +\index{Henry, on electrical vibrations}% +been first suspected by Dr.~Joseph Henry in 1842 from some experiments +he made on the magnetization of needles placed in a +coil in circuit with a wire which connected the inside to the +outside coating of a Leyden Jar. He says (\textit{Scientific Writings} +of Joseph Henry, Vol.~I, p.~201, Washington, 1886): `This +anomaly which has remained so long unexplained, and which at +first sight appears at variance with all our theoretical ideas of +the connection of electricity and magnetism, was after considerable +study satisfactorily referred by the author to an action of the +discharge of the Leyden jar which had never before been recognised. +The discharge, whatever may be its nature, is not correctly +represented (employing for simplicity the theory of Franklin) +by the simple transfer of an imponderable fluid from one side of +the jar to the other, the phenomenon requires us to admit the +existence of a principal discharge in one direction, and then +several reflex actions backward and forward, each more feeble +than the preceding, until the equilibrium is obtained. All the +facts are shown to be in accordance with this hypothesis, and a +ready explanation is afforded by it of a number of phenomena +%% -----File: 347.png---Folio 333------- +which are to be found in the older works on electricity but +which have until this time remained unexplained.' + +In 1853, Lord Kelvin published (\textit{Phil.\ Mag.}\ [4],~5, p.~393, +\index{Kelvin, Lord, xoscillatory discharge@\subdashtwo oscillatory discharge}% +\index{Electrical vibrations, Lord Kelvin on@\subdashtwo Lord Kelvin on}% +\index{Vibrations of electrical systems, Lord Kelvin on@\subdashtwo electrical systems, Lord Kelvin on}% +1853) the results we have just given in \artref{291}{Art.~291}, thus proving +by the laws of electrical action that electrical vibrations must +be produced when a Leyden Jar is short circuited by a wire of +not too great resistance. + +From 1857 to 1862, Feddersen (\textit{Pogg.\ Ann.}\ 103, p.~69, 1858; +\index{Feddersen, electrical vibrations@\subdashone electrical vibrations}% +\index{Electrical vibrations, Feddersen on@\subdashtwo Feddersen on}% +\index{Vibrations of electrical systems, Feddersen on@\subdashtwo electrical systems, Feddersen on}% +108, p.~497, 1859; 112, p.~452, 1861; 113, p.~437, 1861; 116, +p.~132, 1862) published accounts of some beautiful experiments +by which he demonstrated the oscillatory character of the jar +discharge. His method consisted in putting an air break in the +wire circuit joining the two coatings of the jar. When the current +through this wire is near its maximum intensity a spark passes +across the circuit, but when the current is near its minimum +value the electromotive force is not sufficient to spark across the +air break, which at these periods therefore is not luminous. +Thus the image of the air space formed by reflection from a +rotating mirror will be drawn out into a series of bright and +dark spaces, the interval between two dark spaces depending of +course on the speed of the mirror and the frequency of the +electrical vibrations. Feddersen observed this appearance of the +image of the air space, and he proved that the oscillatory +character of the discharge was destroyed by putting a large resistance +in circuit with the air space, by showing that in this case +the image of the air space was a broad band of light gradually +fading away in intensity instead of a series of bright and dark +spaces. This experiment, which is a very beautiful one, can be +repeated without difficulty. To excite the vibrations the coatings +of the jar should be connected to the terminals of an induction +coil or an electric machine. It is advisable to use a large jar +with its coatings connected by as long a wire as possible. By +connecting the coatings of the jar by a circuit with very large +\index{Electrical vibrations, Lodge on@\subdashtwo Lodge on}% +\index{Lodge, electrical vibration}% +\index{Vibrations of electrical systems, Lodge on@\subdashtwo electrical systems, Lodge on}% +self-induction, Dr.~Oliver Lodge (\textit{Modern Views of Electricity}, +p.~377) has produced such slow electrical vibrations that the +sounds generated by the successive discharges form a musical +note. + +\Article{293} In the course of the investigation in \artref{290}{Art.~290} we have +made two assumptions, (1)~that $ml$~is small, (2)~that $n \smallbold{a}$~is also +small, which implies that the currents are uniformly distributed +%% -----File: 348.png---Folio 334------- +across the section of the discharging circuit. This condition is +however very rarely fulfilled, as the electrical oscillations which +are produced by the discharge of a condenser are in general so +rapid that the currents in the discharging circuit fly to the +outside of the wire instead of distributing themselves uniformly +across it; when the currents do this, however, the resistance of +the circuit depends on the frequency of the electrical vibrations, +and the investigation of \artref{290}{Art.~290} has to be modified. Before +proceeding to the discussion of this case we shall write down the +conditions which must hold when the preceding investigation is +applicable. + +In the first place, $ml$~is to be small; now by \artref{263}{Art.~263} we +have when $n \smallbold{a}$~is small, +\begin{multline*} +m^2 = -\iota p\, \text{(resistance of unit length of the wire)} ×\\ +\text{(capacity of unit length of wire)}, +\end{multline*} +\begin{DPgather*} +\lintertext{hence} m^2 l^2 = - \tfrac{1}{2} \iota p R l \Gamma, +\end{DPgather*} +where, as before, $R$~is the resistance of the whole of the discharging +circuit, while $\Gamma$~is the capacity of unit length of the wire. + +But by equation~(\eqnref{290}{68}) when the discharge is oscillatory, we +have +\[ +\iota p = -\frac{R}{2 L} + ± \iota \left\{\frac{2}{LC} - \frac{R^2}{4 L^2} \right\}^{\frac{1}{2}}; +\] +thus the modulus of~$\iota p$ is equal to +\[ +\left\{\frac{2}{LC} \right\}^{\frac{1}{2}}, +\] +hence, when $ml$~is small, +\[ +\frac{R \Gamma l}{\sqrt{CL}} +\] +must be small. + +The other condition is that $n \smallbold{a}$~is small, which since +\[ +n^2 = m^2 + \frac{4 \pi \mu \iota p}{\sigma}, +\] +and $ml$~is also small, is equivalent to the condition that +\[ +4 \pi \mu \iota p \smallbold{a}^2 / \sigma +\] +should be small. Since the modulus of~$\iota p$ is equal to~$\{2/LC \}^{\frac{1}{2}}$, +we see that if $n^2 \smallbold{a}^2$~is small, +\[ +4 \pi \mu \smallbold{a}^2 \{2 / LC \}^{\frac{1}{2}} / \sigma +\] +%% -----File: 349.png---Folio 335------- +\index{Condenser, discharge of}% +must be small. The capacity~$C$ which occurs in this expression +is measured in electromagnetic units, its value in such measure is +only~$1/V^2$ (where `$V$'~is the ratio of the units and $V^2 = 9 × 10^{20}$) +of its value in electrostatic measure. Thus the expression which +has to be small to ensure the condition we are considering, +contains the large factor $3 × 10^{10}$, so that to fulfil this condition +the capacity and self-induction of the circuit must be very large +when the discharging circuit consists of metal wire of customary +dimensions. Thus, to take an example, suppose two spheres +each one metre in radius are connected by a copper wire +$1$~millimetre in diameter. In this case +\[ +C = 1/9 × 10^{18}, \quad \sigma = 1600, \quad \smallbold{a} = .05, \quad \mu = 1, +\] +substituting these values we find that to ensure $n \smallbold{a}$~being small, +the self-induction of the circuit must be comparable with the +enormously large value~$10^{11}$, which is comparable with the self-induction +of a coil with $10,000$ turns of wire, the coil being +about half a metre in diameter. + +The result of this example is sufficient to show that it is only +when the self-induction of the circuit or the capacity of the +condenser is exceptionally large that a theory based on the +assumption that $n \smallbold{a}$~is a small quantity is applicable, it is therefore +important to consider the case where $n \smallbold{a}$~is large and the +currents in the discharging circuit are on the surface of the +wire. + +\Article{294} The theory of this case is given in \artref{274}{Art.~274}, and we +see from equations (\eqnref{274}{42})~and~(\eqnref{274}{43}) of that Article that when the +frequency of the vibrations is so great that $n \smallbold{a}$~and~$n' \smallbold{b}$ (using +the notation of \artref{274}{Art.~274}, and supposing that the wire connecting +the spheres is a cable whose external radius is~$\smallbold{b}$) are large +quantities, equation~(\eqnref{289}{66}) of \artref{289}{Art.~289} becomes +\[ +m \cot ml = -2\iota p \left\{ + \iota p \log{\smallbold{b} / \smallbold{a}} + + (\iota p)^{\frac{1}{2}} (\mu \sigma / 4 \pi \smallbold{a}^2)^{\frac{1}{2}}\right. + \left. + (\iota p)^{\frac{1}{2}} (\mu'\sigma'/ 4 \pi \smallbold{b}^2)^{\frac{1}{2}} \right\} C. +\] + +Retaining the condition that $ml$~is small, which will be the case +when the wave length of the electrical vibrations is very much +greater than the length of the discharging circuit, this equation +becomes +\[ +\frac{1}{Cl} = -\iota p \left[ \iota p 2 \log( \smallbold{b} / \smallbold{a}) + + (\iota p)^{\frac{1}{2}} 2 \left\{( \mu \sigma / 4 \pi \smallbold{a}^2 )^{\frac{1}{2}} + + ( \DPtypo{\mu'/sigma'}{\mu' \sigma'/} 4 \pi \smallbold{b}^2 )^{\frac{1}{2}} \right\} \right], +\] +%% -----File: 350.png---Folio 336------- +which we shall write as +\[ +\frac{2}{C} = -\iota p \left\{\iota pL' + 2(\iota p)^{\frac{1}{2}} S \right\}, \Tag{70} +\] +where $L'$ is the coefficient of self-induction of the discharging +circuit for infinitely rapid alternating currents, and $S$~is written +for +\begin{DPgather*} +\left\{(\sigma \mu /4\pi \smallbold{a}^2)^{\frac{1}{2}} + + (\sigma'\mu'/4\pi \smallbold{b}^2)^{\frac{1}{2}} \right\} 2l. \\ +\lintertext{By \artref{274}{Art.~274},} L' = L - \mu l, +\end{DPgather*} +where $L$~is the self-induction of the circuit for steady currents. + +If we write~$x$ for~$\iota p$, equation~(\eqnref{294}{70}) becomes +\begin{DPgather*} +x^2 L'+ 2x^{\frac{3}{2}} S + \frac{2}{C} = 0, \\ +% +\lintertext{hence} +\left(x^2 L' + \frac{2}{C}\right)^2 = 4x^3 S^2, \\ +% +\lintertext{or} +L'^2 x^4 - 4S^2 x^3 + 4 \frac{L'}{C} x^2 + \frac{4}{C^2} = 0, \Tag{71} +\end{DPgather*} +a biquadratic equation to determine~$x$. + +If electrical oscillations take place the roots of this equation +must be imaginary. + +From the theory of the biquadratic equation (Burnside and +Panton, \textit{Theory of Equations}, §~68) +\[ +ax^4 + 4bx^3 + 6cx^2 + 4dx + e = 0, +\] +we know that if +\begin{gather*} +H = ac - b^2, \qquad I = ae - 4bd + 3c^2, \qquad G = a^2 d - 3abc + 2b^3, \\ +J = ace + 2bcd - ad^2 - eb^2 - c^3, \qquad \Delta = I^3 - 27J^2; +\end{gather*} +the condition that the roots of the biquadratic are all imaginary +is that $\Delta$~should be positive as well as one of the two following +quantities $H$~and $a^2I - 12H^2$. + +Dividing equation~(\eqnref{294}{71}) by~$L'^2$, we see that for equation~(\eqnref{294}{71}) +\begin{gather*} +H = \frac{2}{3}\, \frac{1}{L'C} - \frac{S}{L'^4}, \qquad I = \frac{16}{3}\, \frac{1}{L'^2 C^2}, \\ +G = 2 \frac{S^2}{L'^3 C} \left\{1 - \frac{CS^4}{L'^3} \right\}, \qquad +J = \frac{64}{27}\, \frac{1}{L'^3 C^3} \left\{1 - \frac{27}{16}\, \frac{CS^4}{L'^3} \right\}. +\end{gather*} +Hence we see that $a^2 I - 12H^2$ and~$\Delta$ are both positive, if +\[ +S^4 < 32L'^3/27C, +\] +that is if +\[ +16l^4 \left\{(\sigma \mu /4\pi \smallbold{a}^2)^{\frac{1}{2}} + + (\sigma'\mu'/4\pi \smallbold{b}^2)^{\frac{1}{2}} \right\}^4 < 32L'^3/27C, +\] +%% -----File: 351.png---Folio 337------- +which is the condition that the system should execute electrical +vibrations. + +When the spheres are connected by a free wire and not by a +cable $\sigma'/ \smallbold{b}^2$ vanishes, and the condition that the system should +oscillate reduces to +\[ +l^2 ( \sigma \mu / \pi \smallbold{a}^2)^2 < 32 L'^{3} / 27 l^2 C. +\] + +The results given by Ferrari's method for solving biquadratic +equations are too complicated to be of much practical value in +determining the roots of equation~(\eqnref{294}{71}), neither, since the roots +are imaginary, can we apply the very convenient method known +as Horner's method to determine the numerical value of these +roots to any required accuracy. + +\Article{295} For the purpose of analysing the nature of the electrical +oscillations it is convenient to consider separately the real and +imaginary parts of~$\iota p$, the~$x$ of equation~(\eqnref{294}{71}). The real part, +supposed negative, determines the rate at which the electrical +vibrations die away, while the imaginary part gives the period +of these vibrations. We shall now proceed to show how equation~(\eqnref{294}{71}) +can be treated so as to admit of the real and imaginary +parts of~$x$ being separately determined by Horner's method. + +If we put +\[ +\xi = x - \frac{S^2}{L'^{2}}, +\] +equation~(\eqnref{294}{71}) becomes +\[ +\xi^4 + 6 H \xi^2 + 4 G \xi + I - 3 H^2 = 0, \Tag{72} +\] +where $H$,~$G$,~$I$ are the quantities whose values we have just +written down. Since the coefficient of~$\xi^3$ in this equation +vanishes and since its roots are by hypothesis complex, we see +that the real part of one pair of roots will be positive, that of the +other pair negative: the pair of roots whose real parts are +negative are those which correspond to the solution of the +electrical problem. For if the real part of~$\xi$ were positive the +real part of~$\iota p$ would also be positive, so that such a root would +correspond to an electrical vibration whose amplitude increased +indefinitely with the time. + +The roots of equation~(\eqnref{295}{72}) will be of the form +\[ +x_1 + \iota y_1, \quad +x_1 - \iota y_1, \quad +-x_1 + \iota y_2, \quad +-x_1 - \iota y_2. +\] +We shall now proceed to show how~$x_1$ may be uniquely determined. +Since $6H$,~$-4G$,~$I - 3H^2$ are respectively the sums of +%% -----File: 352.png---Folio 338------- +the products of the roots of equation~(\eqnref{295}{72}) two and two, three +and three, and all together, we have +\begin{DPalign*} +y_1^2 + y_2^2 - 2x_1^2 &= 6H, \Tag{73} \\ +x_1 (y_1^2 - y_2^2) &= 2G, \Tag{74} \\ +(x_1^2 + y_1^2)(x_1^2 + y_2^2) &= I - 3H^2,\\ +\lintertext{or} x_1^4 + x_1^2(y_1^2 + y_2^2) + + \tfrac{1}{4} \{(y_1^2 + y_2^2)^2 + &- (y_1^2 - y_2^2)^2 \DPtypo{}{\}} = I - 3H^2. +\end{DPalign*} +Eliminating $y_1^2 + y_2^2$ and $y_1^2 - y_2^2$ by equations (\eqnref{295}{73})~and~(\eqnref{295}{74}), +we get +\begin{align*} +4x_1^4 + 12Hx_1^2 + (12H^2 - I)- \frac{G^2}{x_1^2} &= 0,\\ +\intertext{or putting $x_1^2 = \eta$,} +4\eta^3 + 12H\eta^2 +(12H^2 - I)\eta - G^2 &= 0. \Tag{75} +\end{align*} + +Since the last term of this expression is negative there is at +least one positive real root of this equation, and since the values +given for $H$~and~$I$ show that when $\Delta$~is positive $12H^2 - I$ is essentially +negative, we see by Fourier's rule that there is only one +such root. But since $x_1$~is real the value of~$\eta$ will be positive, so +that the root we are seeking will be the unique positive real root +of equation~(\eqnref{295}{75}), which can easily be determined by Horner's +method. The value of~$x_1$ is equal to minus the square root of +this root, and knowing~$x_1$ we can find~$y_1^2 / 4\pi^2$, the square of the +corresponding frequency uniquely from equations (\eqnref{295}{73})~and~(\eqnref{295}{74}). +We can in this way in any special case determine with ease +the logarithmic decrement and the frequency of the vibrations. + +\Article{296} If in equation~(\eqnref{295}{75}) we substitute the values of $G$,~$H$, and~$I$, +and write +\[ +L' C \eta = \zeta, \qquad C S^4 / L'^3 = q, +\] +that equation becomes +\[ +\zeta^3 + 2 \zeta^2(1 - \tfrac{3}{2} q) - \zeta(3q^2 - 4q) - q(1 - q)^2 = 0. +\] +We can by successive approximations expand~$\zeta$ in terms of~$q$, +and thus when $CS^4 / L'^3$ is small approximate to the value of~$\zeta$. +The first term in this expansion is +\begin{DPgather*} +\zeta = (q / 2)^{\frac{1}{2}},\\ +\lintertext{or since} L'Cx_1^2 = \zeta,\\ +x_1 = -\frac{S}{2^{\frac{1}{4}} C^{\frac{1}{4}} L'^{\frac{5}{4}}}. +\end{DPgather*} +%% -----File: 353.png---Folio 339------- + +The corresponding value of~$y_{1}^{2}$ determined by equations (\eqnref{295}{73})~and~(\eqnref{295}{74}) +is, retaining only the lowest power of~$q$, approximately, +\begin{DPgather*} +y_{1}^{2} = \frac{2}{L'C} + \left\{1 - \frac{2^{\frac{1}{4}} SC^{\frac{1}{4}}}{L'^{\frac{3}{4}}} \right\}. \\ +\lintertext{Now} +S = \left\{\DPtypo{}{(} + \mu \sigma / 4 \pi \smallbold{a}^{2})^{\frac{1}{2}} + + ( \mu'\sigma'/ 4 \pi \smallbold{b}^{2})^{\frac{1}{2}} \right\} 2l, \\ +\lintertext{\rlap{and, approximately,}} y_{1}^{2} = \frac{2}{L' C}, \\ +\lintertext{and} x_{1} = - \frac{S y^{\frac{1}{2}}}{2^{\frac{1}{2}} L}, +\end{DPgather*} +hence we see, +\[ +x_{1} = - \frac{l}{L'} + \left\{( \mu \sigma y_{1} / 2 \pi \smallbold{a}^{2} )^{\frac{1}{2}} + + ( \mu'\sigma'y_{1} / 2 \pi \smallbold{b}^{2} )^{\frac{1}{2}}\right\}. +\] + +But by \artref{274}{Art.~274}, the quantity enclosed in brackets is equal to~$\smallbold{Q}$, +the impedance of unit length of the circuit when the frequency +of vibration is~$y_{1} / 2 \pi$; thus we have +\[ +x_{1} = - \frac{Q}{2 L'}, +\] +where $Q$~is the impedance of the whole circuit. + +\begin{DPalign*} +\lintertext{\indent Since} +\iota p &= x_{1} + \iota y_{1} + \frac{S^{2}}{L'^{2}}\\ + &= x_{1} \left\{1 - (2q)^{\frac{1}{4}} \right\} + \iota y_{1} , +\end{DPalign*} +the real part of~$\iota p$ differs from~$x_{1}$ by a quantity involving~$q$. +Neglecting this term, we see that the expression for the amplitude +of the vibrations contains the factor~$\epsilon^{-\frac{Q}{2L'} t}$. Comparing this +with the factor~$\epsilon^{-\frac{R}{2L} t}$, which occurs when the oscillations are so +slow that the current is uniformly distributed over the cross-section +of the discharging wire, we find that to our order of approximation +we may for quick vibrations use a similar formula +for the decay of the amplitude to that which holds for slow +vibrations, provided we use the impedance instead of the resistance, +and the coefficient of self-induction for infinitely rapid +vibrations instead of that for infinitely slow ones. This result is, +however, only true when~$CS^{4}/L'^{3}$ is a small quantity. Now if +the external conductor is so far away that $\mu' \sigma' / \smallbold{b}^{2}$ is small compared +with~$\mu \sigma / \smallbold{a}^{2} $, then +\[ +S^{4} = \left\{2 l ( \mu \sigma / 4 \pi \smallbold{a}^{2} )^{\frac{1}{2}}\right\}^4 + = \tfrac{1}{4} l^{2} \mu^{2} R^{2}, +\] +%% -----File: 354.png---Folio 340------- +where $R$~is the resistance of the whole circuit to steady currents. +Substituting this value for~$S^{4}$ we see that the condition that +$CS^4/L'^3$ is a small quantity is that $C l^2 \mu^2 R^2 / 4 L'^3$ should be small. +When this is the case we see that, neglecting the effect of the +external conductor, +\[ +x_1 = -\frac{l}{L'} ( \mu \sigma y_1 / 2 \pi \smallbold{a}^2 )^{\frac{1}{2}}~. +\] + +Since $x_1$~is proportional to~$\mu^{\frac{1}{2}}$, the rate of decay of the vibrations +\index{Iron, xdecay of electromagnetic waves in@\subdashone decay of electromagnetic waves in}% +\index{Trowbridge, decay of vibrations along iron wires}% +will be greater when the discharging wire is made of +iron than when it is made of a non-magnetic metal of the same +resistance. This has been observed by Trowbridge (\textit{Phil.\ Mag.}\ +[5],~32, p.~504, 1891). + +\Article{297} We have assumed in the preceding work that the +length of the electrical wave is great compared with that of the +wire; we have by equation~(\eqnref{289}{66}) +\[ +m \cot {ml} = -\iota p \{\iota p \smallbold{P} + \smallbold{Q} \} C. +\] +When the frequency is very high, $\iota p \smallbold{P}$~will be very large compared +with~$\smallbold{Q}$, hence this equation may be written as +\[ +m \cot {ml} = p^2 \smallbold{P} C. +\] +Now if $V$~is the velocity of light in the dielectric, $p = Vm$, hence +we have +\[ +\frac{\cot{ml}}{ml} = \frac{V^{2} 2 \smallbold{P} l C}{2 l^2}. +\] +Now $2 \smallbold{P} l$ is equal to~$L'$, the self-induction of the discharging +circuit for infinitely rapid vibrations, and $V^2 C$~is equal to the +electrostatic measure of the capacity of the sphere which we +shall denote by~$[C]$, hence the preceding equation may be +written as +\[ +\frac{\cot {ml}}{ml} = \frac{L'[C]}{2l^2}. +\] + +Thus, if $L'[C]/ 2 l^2$~is very large, $ml$~will be very small; if, on +the other hand, $L'[C]/ 2 l^2$~is very small, $\cot{ml}$~will be very small, +or $ml = (2j + 1) \dfrac{\pi}{2}$ approximately, where $j$~is an integer. Since +$2 \pi / m$~is the length of the electrical wave the latter will equal +$4l,~4l/3, 4l/5\ldots$, or the half-wave length will be an odd submultiple +of the length of the discharging wire. We are limited +by our investigation to the odd submultiple because we have +assumed that the current in the discharging wire is symmetrical +%% -----File: 355.png---Folio 341------- +about the middle point of that wire. If we abandon +this assumption we find that the half-wave length may be any +submultiple of the length of the wire. The frequencies of the +vibrations are thus independent of the capacity at the end of the +wire provided this is small enough to make $L[C]/2l^2$ small. In +this case the vibrations are determined merely by the condition +that the current in the discharging wire should vanish at its +extremities. + + +\Subsection{Vibrations along Wires in Multiple Arc.} +\index{Vibrations along wires in multiple arc}% +\index{Multiple arc, electrical vibrations along wires in}% + +\Article{298} When the capacities of the conductors at the ends of a +single wire are very small, we have seen that the gravest +electrical vibration has for its wave length twice the length of +the wire and that the other vibrations are harmonics of this. +We shall now investigate the periods of vibration of the system +when the two conductors of small capacity are connected by two +or more wires in parallel. The first case we shall consider is +the one represented by \figureref{fig109}{Fig.~109}, where in the connection between +the points $A$~and~$F$ we have the loop~$BCED$. + +\includegraphicsmid{fig109}{Fig.~109.} + +We proved in \artref{272}{Art.~272} that the relation between the current~$I$ +and the external electromotive intensity~$\smallbold{E}$ is expressed by the +equation +\[ +\smallbold{E} = \{\iota p \smallbold{P} + \smallbold{Q} \} I. +\] +Where, when as in this case the vibrations are rapid enough to +make $n \smallbold{a}$~large, the term~$\iota p \smallbold{P}$ is much larger than~$\smallbold{Q}$, we may +therefore for our purpose write this equation as +\[ +\smallbold{E} = \iota p \smallbold{P} I, \Tag{76} +\] +where $\smallbold{P}$~is the coefficient of self-induction of unit length of +the wire for infinitely rapid vibrations. + +Let the position of a point on~$AB$ be fixed by the length~$s_1$ +measured along~$AB$ from~$A$, that of one on~$BCE$ by the length~$s_2$ +measured from~$B$, that of one on~$BDE$ by~$s_3$ measured also +from~$B$, and of one on~$EF$ by~$s_4$ measured from~$E$. Let $l_1$,~$l_2$, $l_3$,~$l_4$ +%% -----File: 356.png---Folio 342------- +denote the lengths~$AB$, $BCE$,~$BDE$, and~$EF$ respectively, and +let $P_1$,~$P_2$, $P_3$,~$P_4$ denote the self-induction per unit length of +these wires. Let $\phi$~denote the electrostatic potential, then the +external electromotive intensity along a wire is~$-d \phi / ds$, and +as this is proportional to the current it must vanish at the +ends $A$,~$F$ of the wire if the capacity there is, as we suppose, +very small. + +Hence along~$AB$ we may write, if $p / 2 \pi$ is the frequency, +\begin{DPgather*} +\phi = a \cos {m s_1} \cos {pt}, \\ +\lintertext{along $BCE$} +\phi = (a \cos{ms_2} \cos{m l_1} + b \sin{ms_2}) \cos{pt}, \\ +\lintertext{along $BDE$} +\phi = (a \cos{ms_3} \cos{m l_1} + c \sin{ms_3}) \cos{pt}, \\ +\lintertext{and along $EF$} +\phi = d \cos{m} (s_4- l_4) \cos{pt}. +\end{DPgather*} + +Equating the expressions for the potential at~$E$, we have +\[ +\left.\begin{aligned} +a \cos{ml_2} \cos{ml_1} + b \sin{ml_2} &= d \cos{ml_4},\\ +a \cos{ml_3} \cos{ml_1} + c \sin{ml_3} &= d \cos{ml_4}. +\end{aligned}\right\} \Tag{77} +\] + +The current flowing along~$AB$ at~$B$ must equal the sum of the +currents flowing along $BCE$,~$BDE$, hence by~(\eqnref{298}{76}) we have +\[ +\frac{a \sin{ml_1}}{P_1} = -\frac{b}{P_2} - \frac{c}{P_3}. \Tag{78} +\] + +Again, the current along~$EF$ at~$E$ must equal the sum of the +currents flowing along $BCE$,~$BDE$, hence we have +\begin{multline*} +\frac{d \sin{ml_4}}{P_4} + = \frac{b \cos{ml_2}}{P_2} - \frac{a \sin{ml_2} \cos{ml_1}}{P_2} + + \frac{c \cos{ml_3}}{P_3} \\ + - \frac{a \sin{ml_3} \cos{ml_1}}{P_3}. \Tag{79} +\end{multline*} + +We get from equations (\eqnref{298}{77})~and~(\eqnref{298}{78}) +\begin{multline*} +a \left\{\frac{\sin{ml_1}}{P_1} + - \frac{\cot{ml_2} \cos{ml_1}}{P_2} + - \frac{\cot{ml_3} \cos{ml_4}}{P_3} \right\}\\ + = -d \cos{ml_4} \left\{\frac{\operatorname{cosec}{ml_2}}{P_2} + + \frac{\operatorname{cosec}{ml_3}}{P_3} \right\}. +\end{multline*} + +From equations (\eqnref{298}{77})~and~(\eqnref{298}{79}) we get +\begin{multline*} +d \left\{\frac{\sin{ml_4}}{P_4} + - \frac{\cot{ml_2} \cos{ml_4}}{P_2} + - \frac{\cot{ml_3} \cos{ml_4}}{P_3} \right\}\\ + = -a \cos{ml_1} \left\{\frac{\operatorname{cosec}{ml_2}}{P_2} + + \frac{\operatorname{cosec}{ml_3}}{P_3} \right\}. +\end{multline*} +%% -----File: 357.png---Folio 343------- + +Eliminating $a$~and~$d$ from these equations, we get +\begin{multline*} +\left\{\frac{\tan{ml_1}}{P_1} - \frac{\cot{ml_2}}{P_2} - \frac{\cot{ml_3}}{P_3} \right\} +\left\{\frac{\tan{ml_4}}{P_4} - \frac{\cot{ml_2}}{P_2} - \frac{\cot{ml_3}}{P_3} \right\} \\ + = \left\{\frac{\operatorname{cosec}{ml_2}}{P_2} + + \frac{\operatorname{cosec}{ml_3}}{P_3} \right\}^2. \Tag{80} +\end{multline*} + +If $AB$~and~$EF$ are equal lengths of the same kind of wire, +$l_1 = l_4$, and $P_1 = P_4$, and~(\eqnref{298}{80}) reduces to the simple form +\[ +\frac{\tan{ml_1}}{P_1} - \frac{\cot{ml_2}}{P_2} - \frac{\cot{ml_3}}{P_3} + = ± \left\{\frac{\operatorname{cosec}{ml_2}}{P_2} + + \frac{\operatorname{cosec}{ml_3}}{P_3} \right\}; +\] +taking the upper sign, we have +\[ +\frac{\tan{ml_1}}{P_1} + = \frac{\cot{\frac{1}{2} ml_2}}{P_2} + + \frac{\cot{\frac{1}{2} ml_3}}{P_3}, \Tag{81} +\] +if we take the lower sign, we have +\[ +\frac{\tan{ml_1}}{P_1} + = - \left\{\frac{\tan{\frac{1}{2} ml_2}}{P_2} + + \frac{\tan{\frac{1}{2} ml_3}}{P_3} \right\}. \Tag{82} +\] + +Since $m = 2 \pi / \lambda$, where $\lambda$~is the wave length, these equations +determine the wave lengths of the electrical vibrations. + +If all the wires have the same radius, $P_1 = P_2 = P_3$, and equations +(\eqnref{298}{81})~and~(\eqnref{298}{82}) become respectively +\begin{DPgather*} +\tan{2 \pi \frac{l_1}{\lambda}} + = \cot{\left( \pi \frac{l_2}{\lambda} \right)} + + \cot{\left( \pi \frac{l_3}{\lambda} \right)}, \Tag{81*} \\ +\lintertext{and} +\tan{2 \pi \frac{l_1}{\lambda}} + + \tan{\pi \frac{l_2}{\lambda}} + + \tan{\pi \frac{l_3}{\lambda}} = 0. \Tag{82*} +\end{DPgather*} + +From these equations we can determine the effect on the +period of an alteration in the length of one of the wires. +Suppose that the length of~$BDE$ is increased by~$\delta l_3$, and let~$\delta \lambda$ +be the corresponding increase in~$\lambda$, then from~(81*) +\[ +\frac{\delta \lambda}{\lambda} + \left\{l_1 \sec^2{\frac{2 \pi l_1}{\lambda}} + + \tfrac{1}{2} l_2 \operatorname{cosec}^2{\frac{\pi l_2}{\lambda}} + + \tfrac{1}{2} l_3 \operatorname{cosec}^2{\frac{\pi l_3}{\lambda}} \right\} + = \tfrac{1}{2} \delta l_3 \operatorname{cosec}^2{\frac{\pi l_3}{\lambda}}. +\] +We see from this equation that $\delta \lambda$~and~$\delta l_3$ are of the same sign, +so that an increase in~$l_3$ increases the wave length. + +If we take equation~(\eqnref{298}{82*}), we have +\[ +\frac{\delta \lambda}{\lambda} + \left\{l_1 \sec^2{\frac{2 \pi l_1}{\lambda}} + + \tfrac{1}{2} l_2 \sec^2{\frac{\pi l_2}{\lambda}} + + \tfrac{1}{2} l_3 \sec^2{\frac{\pi l_3}{\lambda}} \right\} + = \tfrac{1}{2} \delta l_3 \sec^2{\frac{\pi l_3}{\lambda}}, +\] +hence, in this case also, an increase in~$l_3$ increases~$\lambda$. If~$l_3$ is +%% -----File: 358.png---Folio 344------- +infinite the wave length is $4 l_1 + 2 l_2$ and its submultiples, as we +diminish~$l_3$ the wave length shortens, hence we see that the +effect of introducing an alternative path is to shorten the wave +lengths of all the vibrations. The shortening of the wave length +goes on until $l_3$~vanishes, when the wave length of the gravest +vibration is~$4 l_1$. + +\Article{299} The currents through the wires $BCE$~and~$BDE$ are at~$B$ +in the proportion of +\[ +\frac{\cot{\frac{1}{2}ml_2}}{P_2} \text{ to } \frac{\cot{\frac{1}{2}ml_3}}{P_3}, +\] +if we take the vibrations corresponding to equation~(\eqnref{298}{81}), and in +the proportion of +\[ +\frac{\tan{\frac{1}{2}ml_2}}{P_2} \text{ to } \frac{\tan{\frac{1}{2}ml_3}}{P_3}, +\] +for the vibration given by~(\eqnref{298}{82}). + +We can prove by the method of \artref{298}{Art.~298} that if we have +$n$~wires between $B$~and~$F$, and if $AB = EF$, +\begin{multline*} +\frac{\tan{m l_1}}{P_1} - \frac{\cot{m l_2}}{P_2} - \frac{\cot{m l_3}}{P_3} - \ldots \\ + = ± \left\{\frac{\operatorname{cosec}{m l_2}}{P_2} + + \frac{\operatorname{cosec}{m l_3}}{P_3} + + \frac{\operatorname{cosec}{m l_4}}{P_4} + \ldots \right\}. +\end{multline*} +It follows from this equation that if any of the wires are +shortened the wave lengths of the vibrations are also shortened. + + +\Section{Electrical Oscillations on Cylinders.} +\index{Cylinder, electrical oscillations on}% +\index{Electrical vibrations, on cylinders@\subdashtwo on cylinders}% +\index{Oscillations, electrical, on cylinders}% +\index{Time of vibration of electricity on a cylinder@\subdashtwo vibration of electricity on a cylinder}% + +\Subsection{Periods of Vibration of Electricity on the Cylindrical Cavity +inside a Conductor.} + +\Article{300} If on the surface of a cylindrical cavity inside a +conductor an irregular distribution of electricity is produced, +then on the removal of the cause producing this irregularity, +currents of electricity will flow from one part of the cylinder to +another to restore the electrical equilibrium, electrical vibrations +will thus be started whose periods we now proceed to +investigate. + +Take the axis of the cylinder as the axis of~$z$, and suppose +that initially the distribution of electricity is the same on all +sections at right angles to the axis of the cylinder; it will +evidently remain so, and the currents which restore the electrical +%% -----File: 359.png---Folio 345------- +distribution to equilibrium will be at right angles to the axis +of~$z$. + +If $c$~is the magnetic induction parallel to~$z$, then in the cavity +filled with the dielectric $c$~satisfies the differential equation +\[ +\frac{d^2 c}{dx^2} + \frac{d^2 c}{dy^2} = \frac{1}{V^2}\, \frac{d^2 c}{dt^2}, +\] +where $V$~is the velocity of propagation of electrodynamic action +through the dielectric. + +In the conductor $c$~satisfies the equation +\[ +\frac{d^2 c}{dx^2} + \frac{d^2 c}{dy^2} = \frac{4 \pi \mu}{\sigma}\, \frac{dc}{dt}, +\] +where $\sigma$~is the specific resistance and $\mu$~the magnetic permeability +of the substance. + +Transform these equations to polar coordinates $r$~and~$\theta$, and +suppose that $c$~varies as $\cos{s \theta \epsilon^{\iota p t}}$; making these assumptions, the +differential equation satisfied by~$c$ in the dielectric is +\[ +\frac{d^2 c}{dr^2} + \frac{1}{r}\, \frac{dc}{dr} + + c \left( \frac{p^2}{V^2} - \frac{s^2}{r^2} \right) = 0, +\] +the solution of which is +\[ +c = A \cos s \theta J_s \left( \frac{p}{V} r \right) \epsilon^{\iota p t}, +\] +where $J_s$~denotes the internal Bessel's function of the $s$\textsuperscript{th}~order. + +The differential equation satisfied by~$c$ in the conductor is +\[ +\frac{d^2 c}{dr^2} + \frac{1}{r}\, \frac{dc}{dr} + + \left\{- \frac{4 \pi \mu \iota p}{\sigma} - \frac{s^2}{r^2} \right\} c = 0. +\] +Let $n^2 = 4 \pi \mu \iota p / \sigma$, then the solution of this equation is +\[ +c = B \cos s \theta K_s ( \iota n r ) \epsilon^{\iota p t}, +\] +where $K_s$ denotes the external Bessel's function of the $s$\textsuperscript{th}~order. + +Since the magnetic force parallel to the surface of the cylinder +is continuous, we have if $\smallbold{a}$~denotes the radius of the cylindrical +cavity +\[ +A J_s \left( \frac{p}{V} \smallbold{a} \right) = \frac{B}{\mu} K_s ( \iota n \smallbold{a} ). \Tag{83} +\] + +The electromotive intensity at right angles to~$r$ is also continuous. +Now the current at right angles to $r$~and~$z$ is +\[ +- dc / 4 \pi \mu\, dr, +\] +%% -----File: 360.png---Folio 346------- +hence in the conductor the electromotive intensity perpendicular +to $r$~and~$z$ is $-\sigma dc/4 \pi \mu\, dr$. In the dielectric the current is equal +to the rate of increase of the electric displacement, i.e.~to $\iota p$~times +the electric displacement or to $\iota p K / 4 \pi$ times the electromotive +intensity; we see that in the dielectric the electromotive +intensity perpendicular to~$r$ is $-\dfrac{1}{K \iota p}\, \dfrac{dc}{dr}$, hence we have +\[ +A \frac{4 \pi}{K \iota p}\, \frac{p}{V} J'_s \left( \frac{p}{V} \smallbold{a} \right) + = \frac{B}{\mu} \iota n \sigma K'_s ( \iota n \smallbold{a} ). \Tag{84} +\] + +Eliminating $A$~and~$B$ from (\eqnref{300}{83})~and~(\eqnref{300}{84}), we get +\[ +\frac{4 \pi}{K V}\, + \frac{J'_s \left( \dfrac{p}{V} \smallbold{a} \right)} + {J_s \left( \dfrac{p}{V} \smallbold{a} \right)} + = - \sigma n \frac{K'_s(\iota n \smallbold{a})}{K_s(\iota n \smallbold{a})}. \Tag{85} +\] +Now $K = \dfrac{1}{V^2}$ and $\sigma = \dfrac{4 \pi \mu \iota p}{n^2}$, so that~(\eqnref{300}{85}) may be written +\[ +\frac{V}{p \smallbold{a}}\, + \frac{J'_s \left( \dfrac{p}{V} \smallbold{a} \right)} + {J_s \left( \dfrac{p}{V} \smallbold{a} \right)} + = \frac{\mu}{\iota n \smallbold{a}}\, + \frac{K'_s(\iota n \smallbold{a})}{K_s(\iota n \smallbold{a})}. \Tag{86} +\] + +Now the wave length of the electrical vibrations will be comparable +with the diameter of the cylinder, and the value of~$p$ +corresponding to this will be sufficient to make~$n\smallbold{a}$ exceedingly +large, but when $n \smallbold{a}$~is very large we have (Heine, \textit{Kugelfunctionen}, +vol.~i.\ p.~248) +\[ +K_s (\iota n \smallbold{a}) + = (-\iota)^{s} \epsilon^{-n \smallbold{a}} + \sqrt{\frac{\pi}{2 n \smallbold{a}}}\quad \text{approximately}, +\] +hence $K'_s (\iota n \smallbold{a}) = \iota K_s(\iota n \smallbold{a})$; thus the right-hand side of~(\eqnref{300}{86}) +will be exceedingly small, and an approximate solution of this +equation will be +\[ +J_s' \left( \frac{V}{p} \smallbold{a} \right) = 0. +\] +This signifies that the tangential electromotive intensity vanishes +at the surface of the cylinder, or that the tubes of electrostatic +induction cut its surface at right angles. The roots of the +equation +\[ +J_s'(x) = 0, +\] +%% -----File: 361.png---Folio 347------- +for~$s = 1$, $2$,~$3$, are given in the following table taken from Lord +Rayleigh's \textit{Theory of Sound}, Vol.~II, p.~266:--- +\begin{center} +\tabletextsize +\begin{tabular}{|*{3}{c|}} +\hline +\tablespaceup s = 1 & s = 2 & s = 3 \tablespacedown\\ +\hline +\tablespaceup\Z1.841 & 3.054 & \Z4.201 \\ +\Z5.332 & 6.705 & \Z8.015 \\ +\Z8.536 & 9.965 & 11.344 \\ +11.706 & & \\ +14.864 & & \\ +18.016 & & \tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\index{Cylinder, electrical oscillations on}% +\index{Time of vibration of electricity on a cylinder@\subdashtwo vibration of electricity on a cylinder}% +Thus, when $s = 1$, the gravest period of the electrical vibrations +is given by the equation +\[ +\frac{p}{V} \smallbold{a} = 1.841, +\] +or the wave length of the vibration $2 \pi V/p = .543 × 2 \pi \smallbold{a}$, and is +thus more than half the circumference of the cylinder. In this +case, as far as our approximations go, there is no decay of the +vibrations, though if we took into account the right-hand side +of~(\eqnref{300}{86}) we should find there was a small imaginary term in the +expression for~$p$, which would indicate a gradual fading away of +the vibrations. If it were not for the resistance of the conductor +the oscillations would last for ever, as there is no radiation of +energy away from the cylinder. The magnetic force vanishes in +the conductor except just in the neighbourhood of the cavity, +and the magnetic waves emitted by one portion of the walls of +the cavity will be reflected from another portion, so that no +energy escapes. + + +\Subsection{Metal Cylinder surrounded by a Dielectric.} + +\Article{301} In this case the waves starting from one portion of the +cylinder travel away through the dielectric and carry energy +with them, so that the vibrations will die away independently +of the resistance of the conductor. + +Using the same notation as before, we have in the conducting +cylinder +\[ +c = A \cos{s \theta J_s (\iota n r) \epsilon^{\iota pt}}, +\] +and in the surrounding dielectric +\[ +c = B \cos{s \theta K_s \left( \frac{p}{V} r \right) \epsilon^{\iota pt}}. +\] +%% -----File: 362.png---Folio 348------- + +\index{Functions, Bessel's}% +Since the magnetic force parallel to~$z$ is continuous, we have +\[ +\frac{A}{\mu} J_s (\iota n \smallbold{a}) = B K_s \left( \frac{p}{V} \smallbold{a} \right). +\] +Since the electromotive intensity perpendicular to~$r$ is continuous, +we have +\[ +\frac{A}{\mu} \iota n \sigma J'_s(\iota n \smallbold{a}) + = B \frac{4 \pi}{K \iota p}\, \frac{p}{V} K_s' \left( \frac{p}{V} \smallbold{a} \right). +\] + +Eliminating $A$~and~$B$ from these equations, we get +\begin{DPgather*} +\iota n \sigma \frac{J'_s(\iota n \smallbold{a})}{J_s(\iota n \smallbold{a})} + = \frac{4 \pi}{K \iota V}\, + \frac{K'_s \left( \dfrac{p}{V} \smallbold{a} \right) } + {K_s \left( \dfrac{p}{V} \smallbold{a} \right) }, \\ +\lintertext{or} +\frac{1}{\iota n \smallbold{a}}\, \frac{J'_s(\iota n \smallbold{a})}{J_s(\iota n \smallbold{a})} + = \frac{V}{\mu p \smallbold{a}}\, + \frac{K'_s \left( \dfrac{p}{V} \smallbold{a} \right) } + {K_s \left( \dfrac{p}{V} \smallbold{a} \right) }. \Tag{87} +\end{DPgather*} + +Now, as before, $n \smallbold{a}$~will be large, and therefore +\[ +J_s(\iota n \smallbold{a}) + = \frac{\iota^s \epsilon^{n \smallbold{a}}}{\sqrt{2 \pi n \smallbold{a}}}\quad \text{approximately}, +\] +hence $J_s'(\iota n \smallbold{a}) = - \iota J_s(\iota n \smallbold{a})$, and the left-hand side of equation~(\eqnref{301}{87}) +is very small, so that the approximate form of~(\eqnref{301}{87}) will be +\[ +K'_s \left( \frac{p}{V} \smallbold{a} \right) = 0, \Tag{88} +\] +which again signifies that the electromotive intensity tangential +to the cylinder vanishes at its surface. + +In order to calculate the approximate values of the roots of +the equation $K'_s(x) = 0$, it is most convenient to use the expression +for~$K_s(x)$ which proceeds by powers of~$1/x$. This +series is expressed by the equation +\begin{multline*} +K_s(x) = C \frac{\epsilon^{-\iota x}}{(\iota x)^{\frac{1}{2}}} + \left\{1 - \frac{(1^2 - 4s^2)}{8 \iota x} + + \frac{(1^2-4s^2)(3^2 - 4s^2)}{1\centerdot2(8 \iota x)^2} \right.\\ + - \left. \frac{(1^2 - 4s^2)(3^2 - 4s^2)(5^2 - 4s^2)}{1\centerdot2\centerdot3 (8 \iota x)^3} + \ldots\right\}, +\end{multline*} +where $C$~is a constant (see Lord Rayleigh, \textit{Theory of Sound}, +Vol.~II, p.~271). +%% -----File: 363.png---Folio 349------- + +When $s = 1$, +\[ +K_1(x) = C \frac{\epsilon^{-\iota x}}{(\iota x)^{\frac{1}{2}}} + \left\{1 + \frac{3}{8 \iota x} - \frac{15}{2(8 \iota x)^2} + \frac{105}{2(8 \iota x)^3} - \ldots \right\}. +\] +Thus +\[ +K_1'(x) = - \iota C \frac{\epsilon^{-\iota x}}{(\iota x)^{\frac{1}{2}}} + \left\{1 + \frac{7}{8 \iota x} + \frac{57}{128 (\iota x)^2} - \frac{195}{1024 (\iota x)^3}\ldots \right\}. +\] + +\index{Decay, xof electrical oscillations on cylinders@\subdashone of electrical oscillations on cylinders}% +\index{Rate of decay of yoscillation on cylinders@\subdashtwo of oscillation on cylinders}% +\index{Vibrations d, decay of, on cylinders@\subdashtwo on cylinders}% +To approximate to the roots of the equation $K_1'(x) = 0$, put +$\iota x = y$, and equate the first four terms inside the bracket to zero; +we get +\[ +y^3 + \frac{7}{8} y^2 + \frac{57}{128} y - \frac{195}{1024} = 0, +\] +a cubic equation to determine~$y$. One root of this equation is +real and positive, the other two are imaginary; if~$\alpha$ is the +positive root, $\beta ± \iota \gamma$~the two imaginary roots, then we have +\begin{align*} +\alpha + 2 \beta & = -\frac{7}{8}, \\ +2 \beta \alpha + \beta^2 + \gamma^2 & = \frac{57}{128}, \\ +\alpha(\beta^2 + \gamma^2) & = \frac{195}{1024}. +\end{align*} + +We find by the rules for the solution of numerical equations +that $\alpha = .26$ approximately, hence +\[ +\beta = - .56, \qquad \gamma = ± .64. +\] + +These roots are however not large enough for the approximation +to be close to the accurate values. + +Hence from equation~(\eqnref{301}{88}), we see that when $s = 1$, +\begin{DPgather*} +\frac{\iota p}{V} \smallbold{a} = - .56 ± \iota .64, \\ +\lintertext{or} \iota p = (- .56 ± \iota .64) \frac{V}{\smallbold{a}}. +\end{DPgather*} +This represents a vibration whose period is $3.1 \pi \smallbold{a} / V$, and whose +amplitude fades away to $1 / \epsilon$~of its original value after a time +$1.8 \smallbold{a} / V$. + +The radiation of energy away from the \DPtypo{sphere}{cylinder} in this case is +so rapid that the vibrations are practically dead beat; thus after +one complete vibration the amplitude is only~$\epsilon^{-1.74 \pi}$, or about +one two hundred and fiftieth part of its value at the beginning +of the oscillation. +%% -----File: 364.png---Folio 350------- + +\Article{302} If we consider the state of the field at a considerable +\index{Cylinder, field of force round oscillating@\subdashone field of force round oscillating}% +\index{Faradayx tubes, disposition of round vibrating cylinder@\subdashtwo disposition of round vibrating cylinder}% +distance from the cylinder and only retain in each expression +the lowest power of~$1/r$, we find that the magnetic induction~$c$, +the tangential and radial components $\Theta$~and~$R$ of the electric +polarization in the dielectric, may be consistently represented by +the following equations: +\begin{DPgather*} +c = \cos{\theta} \frac{1}{r^{\frac{1}{2}}} + \epsilon^{- .56 \left( \frac{Vt - r}{\smallbold{a}} \right)} + \cos .64 \left( \frac{Vt - r}{\smallbold{a}} \right), \\ +\lintertext{since} K\, \frac{d \Theta}{dt} = - \frac{1}{\mu}\, \frac{dc}{dr}, \\ +\intertext{we have} +\Theta = \frac{\cos {\theta}}{K \mu V}\, \frac{1}{r^{\frac{1}{2}}} + \epsilon^{- .56 \left( \frac{Vt - r}{\smallbold{a}} \right)} + \cos .64 \left( \frac{Vt - r}{\smallbold{a}} \right), \\ +\lintertext{and since} +K\, \frac{dR}{dt} = \frac{1}{\mu r}\, \frac{dc}{d \theta}, +\end{DPgather*} +we have +\begin{multline*} +R = \frac{\sin \theta}{K \mu V}\, \frac{\smallbold{a}}{r^{\frac{3}{2}}}\, + 1.34 \epsilon^{- .56 \left( \frac{Vt - r}{\smallbold{a}} \right)} \\ + \left\{.56 \cos .64 \left( \frac{Vt - r}{\smallbold{a}} \right) + - .64 \sin .64 \left( \frac{Vt - r}{\smallbold{a}} \right) \right\}. +\end{multline*} + +Thus $R$~vanishes at all points on a series of cylinders concentric +with the original one whose radii satisfy the equation +\[ +\cot{.64} \left( \frac{Vt - r}{\smallbold{a}} \right) = 1.13, +\] +the distance between the consecutive cylinders in this series is +\[ +1.57 \pi \smallbold{a}. +\] +The Faraday tubes between two such cylinders form closed +curves, all cutting at right angles the cylinder for which +\[ +\Theta = 0, \quad \text{or} \quad +\cos{.64} \left( \frac{Vt - r}{\smallbold{a}} \right) = 0. +\] +The closed Faraday tubes move away from the cylinder and +are the vehicles by which the energy of the cylinder radiates +into space. The axes of the Faraday tubes, i.e.~the lines of +electromotive intensity between two cylinders at which $R = 0$, +are represented in \figureref{fig110}{Fig.~110}. + +\includegraphicsmid{fig110}{Fig.~110.} + +The genesis of these closed endless tubes from the unclosed +ones, which originally stretched from one point to another of the +%% -----File: 365.png---Folio 351------- +cylinder, which we may suppose to have been electrified initially +so that the surface density was proportional to~$\sin \theta$, is shown in +\figureref{fig111}{Fig.~111}. + +\includegraphicsmid[!t]{fig111}{Fig.~111.} + +The lines represent the changes in shape in a Faraday tube +which originally stretched from a positively to a negatively electrified +place on the cylinder. The outer line~\smallsanscap{A} represents the original +position of the tube; when the equilibrium is disturbed some of +the tubes inside this one will soon run into the cylinder, and the +lateral repulsion they exerted on the tube under consideration +will be removed; the outside lateral pressure on this tube will +%% -----File: 366.png---Folio 352------- +\index{Decay, xof currents and magnetic force in cylinders@\subdashone of currents and magnetic force in cylinders}% +\index{Electric currents, decay of, in cylinders}% +\index{Magnetic zforce@\subdashone force, decay of in cylinders}% +\index{Rate of decay of xcurrents in cylinders@\subdashtwo of currents in cylinders}% +now overpower the inside pressure and will produce the indentation +shown in the second position~\smallsanscap{B} of the tube; this indentation +increases until the two sides of the tube meet as in the third +position~\smallsanscap{C} of the tube; when this takes place the tube breaks up, +the outer part~\smallsanscap{D} travelling out into space and forming one of the +closed tubes shown in \figureref{fig111}{Fig.~111}, while the inner part~\smallsanscap{E} runs into +the cylinder. + + +\Subsection{Decay of Magnetic Force in a Metal Cylinder.} + +\Article{303} In addition to the very rapid oscillations we have just +investigated there are other and slower changes which may +occur in the electrical state of the cylinder. Thus, for example, +a uniform magnetic field parallel to the axis of the cylinder +might suddenly be removed; the alteration in the magnetic force +would then induce currents in the cylinder whose magnetic action +would tend to maintain the original state of the magnetic field, +so that the field instead of sinking abruptly to zero would die +away gradually. The rate at which the state of the system +changes with the time in cases like this is exceedingly slow +compared with the rate of change we have just investigated. +Using the same notation as in the preceding investigation, it +will be slow enough to make $p \smallbold{a}/V$ an exceedingly small quantity; +when however $p \smallbold{a}/V$ is very small, $K'_s (p \smallbold{a}/V)$ is exceedingly +large compared with $K_s(p \smallbold{a}/V)$, since (Heine, \textit{Kugelfunctionen}, +vol.~i.\ p.~237) $K_s(\theta)$ is equal to +\[ +(-2\theta )^s \frac{d^s K_0(\theta)}{(d\theta^2)^s}; +\] +thus since when $\theta$ is small $K_0(\theta)$~is proportional to~$\log \theta_1$, +$K_s(p \smallbold{a}/V)$~is proportional to~$(V/p \smallbold{a})^s$, and $K'_s (p \smallbold{a}/V)$ to~$(V/p \smallbold{a})^{s+1}$; +hence the right-hand side of equation~(\eqnref{301}{87}) is exceedingly +large, so that an approximate solution of that equation +will be +\[ +J_s(\iota n \smallbold{a}) = 0. +\] + +We notice that this condition makes the normal electromotive +intensity at the surface of the cylinder vanish, while it will be +remembered that for the very rapid oscillations the tangential +electromotive intensity vanished. As the normal intensity +vanishes there is no electrification on the surface of the cylinder +in this case. + +The equation $J_s(x) = 0$ has an infinite number of roots all +%% -----File: 367.png---Folio 353------- +\index{Rayleigh@Rayleigh, Lord, \textit{Theory of Sound}}% +real, the smaller values of which from $s = 0$ to $s = 5$ are given +in the following table, taken from Lord Rayleigh's \textit{Theory of +Sound}, Vol.~I, p.~274. +\begin{center} +\tabletextsize +\begin{tabular}{|*{6}{c|}} +\hline +\tablespaceup$s = 0 $ & $s = 1 $ & $s = 2 $ & $s = 3 $ & $s = 4 $ & $s = 5$\tablespacedown \\ +\hline +\tablespaceup$\Z2.404$ & $\Z3.832$ & $\Z5.135$ & $\Z6.379$ & $\Z7.586$ & $\Z8.780$ \\ +$\Z5.520$ & $\Z7.016$ & $\Z8.417$ & $\Z9.760$ & $11.064 $ & $12.339 $ \\ +$\Z8.654$ & $10.173 $ & $11.620 $ & $13.017 $ & $14.373 $ & $15.700 $ \\ +$11.792 $ & $13.323 $ & $14.796 $ & $16.224 $ & $17.616 $ & $18.982 $ \\ +$14.931 $ & $16.470 $ & $17.960 $ & $19.410 $ & $20.827 $ & $22.220 $ \\ +$18.071 $ & $19.616 $ & $21.117 $ & $22.583 $ & $24.018 $ & $25.431 $ \\ +$21.212 $ & $22.760 $ & $24.270 $ & $25.749 $ & $27.200 $ & $28.628 $ \\ +$24.353 $ & $25.903 $ & $27.421 $ & $28.909 $ & $30.371 $ & $31.813 $ \\ +$37.494 $ & $29.047 $ & $30.571 $ & $32.050 $ & $33.512 $ & $34.983 $\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +This table may be supplemented by the aid of the theorem that +\index{Bessel's functions, xroots of@\subdashtwo roots of}% +\index{Functions, Bessel's}% +the large roots of the equation got by equating a Bessel's function +to zero form approximately an arithmetical progression whose +common difference is~$\pi$. + +If $x_q$~denotes a root of the equation +\[ +J_s(x) = 0, +\] +then since $p$~is given by the equation +\begin{DPgather*} +J_s(\iota n \smallbold{a}) = 0, \\ +\lintertext{where} n^2 = \frac{4 \pi \mu \iota p}{\sigma}, +\end{DPgather*} +we see that~$p_q$, the corresponding value of~$p$, is given by the +equation +\[ +-\iota p_q = \frac{\sigma}{4\pi \smallbold{a}^2 \mu}\, x_q^2. +\] + +Thus, since $\iota p_q$~is real and negative, the system simply fades +away to its position of equilibrium and does not oscillate about it. + +The term in~$c$ which was initially expressed by +\[ +A \cos s \theta J_s \left( x_q \frac{r}{\smallbold{a}} \right), +\] +will after the lapse of a time~$t$ have diminished to +\[ +A \cos s \theta J_s \left( x_q \frac{r}{\smallbold{a}} \right) + \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2 \mu} x_q^2 t}. +\] +If we call $T$ the time which must elapse before the term sinks +to $1/\epsilon$~of its original value, the `time modulus' of the term, then, +since +\[ +T = \frac{4 \pi \smallbold{a}^2 \mu}{\sigma x_q^2}, +\] +%% -----File: 368.png---Folio 354------- +we see that the time modulus is inversely proportional to the +resistance of unit length of the cylinder and directly proportional +to the magnetic permeability. Since $\mu / \sigma$ for iron is larger +than it is for copper, the magnetic force will fade away more +slowly in an iron cylinder than in a copper one. + +\Article{304} A case of great interest, which can be solved without +difficulty by the preceding equations, is the one where a cylinder +is placed in a uniform magnetic field which is suddenly +annihilated, the lines of magnetic force being originally parallel +to the axis of the cylinder. We may imagine, for example, that +the cylinder is placed inside a long straight solenoid, the current +through which is suddenly broken. + +Since in this case everything is symmetrical about the axis +of the cylinder, $s = 0$, and the values of~$\iota p$ are therefore +\[ +-(2.404)^2 \frac{\sigma}{4 \pi \smallbold{a}^2 \mu}, \qquad +-(5.520)^2 \frac{\sigma}{4 \pi \smallbold{a}^2 \mu}, \text{ \&c.} +\] + +Now we know from the theory of Bessel's functions that any +function of~$r$ can for values of~$r$ between $0$~and~$\smallbold{a}$ be expanded +in the form +\[ +A_1 J_0 \left( x_1 \frac{r}{\smallbold{a}} \right) + +A_2 J_0 \left( x_2 \frac{r}{\smallbold{a}} \right) + +A_3 J_0 \left( x_3 \frac{r}{\smallbold{a}} \right) + \ldots, +\] +where $x_1, x_2, x_3 \ldots$ are the roots of the equation +\[ +J_0(x) = 0. +\] + +Thus, initially +\[ +c = A_1 J_0 \left( x_1 \frac{r}{\smallbold{a}} \right) + + A_2 J_0 \left( x_2 \frac{r}{\smallbold{a}} \right) + + A_3 J_0 \left( x_3 \frac{r}{\smallbold{a}} \right) + \ldots, +\] +hence the value of~$c$ after a time~$t$ will be given by the equation +\[ +c = A_1 J_0 \left( x_1 \frac{r}{\smallbold{a}} \right) + \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2 \mu} x_1^2 t} + + A_2 J_0 \left( x_2 \frac{r}{\smallbold{a}} \right) + \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2 \mu} x_2^2 t} + \ldots, +\] +so that all we have to do is to find the coefficients $A_1, A_2, +A_3\ldots$. + +We shall suppose that initially $c$~was uniform over the section +of the cylinder and equal to~$c_0$. + +Then, since +\[ +\int_0^{\smallbold{a}} r + J_0 \left( x_p \frac{r}{\smallbold{a}} \right) + J_0 \left( x_q \frac{r}{\smallbold{a}} \right) dr = 0 +\] +%% -----File: 369.png---Folio 355------- +when $p$~and~$q$ are different, we see that +\[ +c_0 \int_0^{\smallbold{a}} rJ_0 \left( x_q \frac{r}{\smallbold{a}} \right) dr + = A_q \int_0^{\smallbold{a}} rJ_0^2 \left( x_q \frac{r}{\smallbold{a}} \right) dr. +\] + +Now, since +\begin{gather*} +J_0''(x) + \frac{1}{x} J_0'(x) + J_0(x) = 0,\\ +xJ_0(x) = -\frac{d}{dx} (x J_0'(x)), +\end{gather*} +\begin{DPalign*} +\lintertext{hence} \int_0^{\smallbold{a}} r J_0 \left( x_q \frac{r}{\smallbold{a}} \right) dr + &= -\frac{\smallbold{a}^2}{x_q} J_0'(x_q) \\ + &= \frac{\smallbold{a}^2}{x_q} J_1(x_q). +\end{DPalign*} + +Again, since +\[ +J_0''(x) + \frac{1}{x} J_0'(x) + J_0(x) = 0, +\] +we have, multiplying by~$2x^2 J_0'(x)$, +\begin{DPgather*} +\frac{d}{dx} \{x^2 J_0'^2 (x) + x^2 J_0^2(x) \} = 2 x J_0^2 (x), \\ +\lintertext{hence} x^2 \{J_0'^2 (x) + J_0^2(x) \} = 2 \int_0^x x J_0^2(x)\,dx. +\end{DPgather*} + +\begin{DPalign*} +\lintertext{\indent Thus, since} J_0(x_q) &= 0,\\ +\int_0^{\smallbold{a}} r J_0^2 \left( x_q \frac{r}{\smallbold{a}} \right) dr + &= \frac{1}{2} \smallbold{a}^2 J_0'^2(x_q)\\ + &= \frac{1}{2} x^2 J_1^2 (x_q). +\end{DPalign*} + +Hence, we see that +\[ +A_q = \frac{2c_0}{x_q J_1(x_q)}, +\] +and therefore +\[ +c = 2 c_0 \tsum \frac{1}{x_q}\, + \frac{J_0 \left( x_q \dfrac{r}{\smallbold{a}} \right)}{J_1(x_q)}\, + \epsilon^{- \frac{\sigma}{4\pi \smallbold{a}^2 \mu} x_q^2 t}. +\] + +We see from this equation that immediately after the magnetic +force is removed $c$~vanishes at the surface of the cylinder; also, +since the terms in the expression for~$c$ corresponding to the +large roots of the equation $J_0(x) = 0$ die away more quickly +than those corresponding to the smaller roots, $c$~will ultimately +%% -----File: 370.png---Folio 356------- +be very approximately represented by the first term in the +preceding expression; hence we have, since +\begin{gather*} +J_1(2.404) = .519, \\ +c = 1.6c_0J_0 \left (2.404 \frac{r}{\smallbold{a}}\right ) + \epsilon^{-\frac{\sigma} {4\pi \smallbold{a}^2\mu} 5.78t}. +\end{gather*} + +This expression is a maximum when $r = 0$ and gradually dies +away to zero when~$r = \smallbold{a}$, thus the lines of magnetic force fade +away most quickly at the surface of the cylinder and linger +longest at the centre. + +The time modulus for the first term is $4\pi \smallbold{a}^2\mu / 5.78\sigma$. For a +copper rod $1$~cm.\ in radius for which $\sigma = 1600$, this is about +$1/736$~of a second; for an iron rod of the same radius for which +$\mu = 1000$, $\sigma = 10^4$, it is about $2/9$~of a second. + +\Article{305} The intensity of the current is $-\dfrac{1}{4\pi \mu}\, \dfrac{dc}{dr}$, hence at a distance~$r$ +from the axis of the cylinder the intensity is +\[ +\frac{c_0}{2\pi \mu \smallbold{a}} + \tsum \frac{J_1 \left (x_q\dfrac{r}{\smallbold{a}} \right ) }{J_1(x_q)}\, + \epsilon^{-\frac{\sigma }{4\pi \smallbold{a}^2\mu} {x_q}^2t}. +\] + +Since at the instant the magnetic force is destroyed, $c$~is +constant over the cross-section of the cylinder, the intensity of +the current when~$t = 0$ will vanish except at the surface of the +cylinder, where, as the above equation shows, it is infinite. After +some time has elapsed the intensity of the current will be +adequately represented by the first term of the series, i.e.~by +\[ +\frac{c_0}{2\pi \mu \smallbold{a}}\, + \frac{J_1\left(2.404 \dfrac{r}{\smallbold{a}}\right)}{.52}\, + \epsilon^{-\frac{\sigma }{4\pi \smallbold{a}^2\mu} 5.78t}. +\] +This vanishes at the axis of the cylinder and, as we see from +tables for~$J_1(x)$ (Lord Rayleigh, \textit{Theory of Sound}, vol.~I, p.~265), +\index{Rayleigh@Rayleigh, Lord, \textit{Theory of Sound}}% +attains a maximum when $2.404 \dfrac{r}{\smallbold{a}} = 1.841$, or at a distance from +the axis about $3/4$~the radius of the cylinder. + +The following table, taken from the paper by Prof.\ Lamb on +\index{Lamb, decay of currents in cylinders}% +this subject (\textit{Proc.\ Lond.\ Math.\ Soc.}~XV, p.~143), gives the value +of the total induction through the cylinder, and the electromotive +force round a circuit embracing the cylinder for a series +of values of~$t/\tau$, where $\tau = 4\pi \mu \smallbold{a}^2/\sigma$:--- +%% -----File: 371.png---Folio 357------- +\begin{center} +\tabletextsize +\begin{tabular}{|@{\qquad}c@{\qquad}|c|c|} +\hline +$t/\tau$ & +\settowidth{\TmpLen}{Total Induction}% +\parbox[c]{\TmpLen}{\centering Total Induction} & +\settowidth{\TmpLen}{Electromotive}% +\parbox[c]{\TmpLen}{\tablespaceup\centering Electromotive\\ force$/\sigma c_0$\tablespacedown} \\ +\hline +\tablespaceup $.00$ & \llap{$1$}$.0000$ & infinite \\ + $.02$ & $.7014$ & $1.7332$\\ + $.04$ & $.5904$ & $1.1430$\\ + $.06$ & $.5105$ & $\Z.8789$\\ + $.08$ & $.4470$ & $\Z.7195$\\ + $.10$ & $.3941$ & $\Z.6089$\\ + $.20$ & $.2178$ & $\Z.3168$\\ + $.30$ & $.1220$ & $\Z.1765$\\ + $.40$ & $.0684$ & $\Z.0989$\\ + $.50$ & $.0384$ & $\Z.0555$\\ + $.60$ & $.0215$ & $\Z.0311$\\ + $.70$ & $.0121$ & $\Z.0174$\\ + $.80$ & $.0068$ & $\Z.0098$\\ + $.90$ & $.0038$ & $\Z.0055$\\ +\llap{$1$}.00 & $.0021$ & $\Z.0031$\tablespacedown\\ +\hline +\end{tabular} +\end{center} + + +\Subsection{Rate of Decay of Currents and Magnetic Force in infinite +Cylinders when the Currents are Longitudinal and the Magnetic +Force Transversal.} + +\Article{306} We have already considered this problem in the special +case when the currents are symmetrically distributed through +the cylinder in \artref{262}{Art.~262}; we shall now consider the case when the +currents are not the same in all planes through the axis. + +Let $w$~be the intensity of the current parallel to the axis of +the cylinder, then (\artref{256}{Art.~256}) in the cylinder~$w$ satisfies the +differential equation +\[ +\frac{d^2w}{dx^2} + \frac{d^2w}{dy^2} = \frac{4 \pi \mu}{\sigma}\, \frac{dw}{dt}. +\] +If $w'$~denotes the rate of increase in the electric displacement +parallel to~$z$ in the dielectric surrounding the cylinder, then, +since $w'$~is equal to $\dfrac{K}{4 \pi}\, \dfrac{dZ}{dt}$, where $Z$~is the electromotive intensity +parallel to~$z$ the axis of the cylinder, $w'$~satisfies the equation +\[ +\frac{d^2w'}{dx^2} + \frac{d^2w'}{dy^2} = \frac{1}{V^2}\, \frac{d^2w'}{dt^2}. +\] + +Let us suppose that $w$~varies as $\cos s \theta \epsilon^{\iota p t}$, then transforming to +cylindrical coordinates $r$,~$\theta$, the equation satisfied by~$w$ in the +cylinder becomes +\[ +\frac{d^2w}{dr^2} + \frac{1}{r}\, \frac{dw}{dr} + + \left\{- \frac{4 \pi \mu \iota p}{\sigma} - \frac{s^2}{r^2} \right\} w = 0, +\] +the solution of which is +\[ +w = A \cos s \theta \epsilon^{\iota p t} J_s(\iota n r), +\] +%% -----File: 372.png---Folio 358------- +\begin{DPgather*} +\lintertext{where} n^2 = \frac{4 \pi \mu \iota p}{\sigma}; +\end{DPgather*} +while in the dielectric we have +\[ +\frac{d^2w'}{dr^2} + \frac{1}{r}\, \frac{dw'}{dr} + + \left( \frac{p^2}{V^2} - \frac{s^2}{r^2} \right) w' = 0, +\] +the solution of which is +\[ +w' = B \cos s \theta \epsilon^{\iota p t} K_s \left( \frac{p}{V} r \right). +\] + +The electromotive intensity~$Z$, parallel to the axis of the +cylinder, is equal to~$\sigma w$ in the cylinder and to $4 \pi w' / K \iota p$ in the +dielectric. At the surface of the cylinder $r = \smallbold{a}$ these must be +equal, hence we have +\[ +\sigma A J_s(\iota n \smallbold{a}) + = \frac{4 \pi}{K \iota p} B K_s \left( \frac{p}{V} \smallbold{a} \right). \Tag{89} +\] + +If $\Theta$~is the magnetic induction at right angles to~$r$, then +\[ +\frac{d \Theta}{dt} = \frac{dZ}{dr}, +\] +or, since $\Theta$~varies as~$\epsilon^{\iota p t}$, +\[ +\Theta = \frac{1}{\iota p}\, \frac{dZ}{dr}. +\] + +Thus, in the cylinder +\begin{align*} +\Theta &= \frac{\sigma}{\iota p}\, \frac{dw}{dr} \\ + &= \frac{\sigma}{\iota p}\, \iota n A J_s'(\iota n \smallbold{a}), \text{ at the surface}. +\end{align*} + +In the dielectric +\[ +\Theta = \frac{1}{\iota p}\, \frac{4 \pi}{K \iota p}\, \frac{p}{V}\, + B K_s' \left( \frac{p}{V} \smallbold{a} \right), \text{ at the surface}. +\] + +Since the magnetic force parallel to the surface is continuous, +we have +\begin{DPgather*} +\left( \frac{1}{\mu} \Theta \right) \text{ in the cylinder} + = \Theta \text{ in the dielectric}, \\ +\lintertext{hence} +\frac{\sigma}{\mu} \iota n A J_s' ( \iota n \smallbold{a} ) + = \frac{4 \pi}{K \iota p}\, \frac{p}{V} BK_s'\left( \frac{p}{V} \smallbold{a} \right). \Tag{90} +\end{DPgather*} + +Eliminating $A$~and~$B$ from (\eqnref{306}{89})~and~(\eqnref{306}{90}), we have +\[ +\frac{\iota n \smallbold{a} J_s'(\iota n \smallbold{a})}{\mu J_s (\iota n \smallbold{a})} + = \frac{p \smallbold{a}}{V}\, + \frac{K_s' \left( \dfrac{p}{V} \smallbold{a} \right)} + {K_s \left( \dfrac{p}{V} \smallbold{a} \right)}. \Tag{91} +\] +%% -----File: 373.png---Folio 359------- + +In this case $p \smallbold{a} / V$ is very small, so that (\artref{303}{Art.~303}) $K_s \left( \dfrac{p}{V} \smallbold{a} \right)$ is +approximately proportional to $\left( \dfrac{p}{V} \smallbold{a} \right)^{-s}$, and thus +\[ +\frac{p}{V}\, \frac{K_s' \left( \dfrac{p}{V} \smallbold{a} \right)} + {K_s \left( \dfrac{p}{V} \smallbold{a} \right)} + = -\frac{s}{\smallbold{a}}, \text{ approximately}; +\] +hence equation~(\eqnref{306}{91}) becomes +\[ +\iota n \smallbold{a} J_s'(\iota n \smallbold{a}) + s \mu J_s(\iota n \smallbold{a}) = 0. \Tag{92} +\] + +Bessel's functions, however, satisfy the relation +\[ +J_s'(\iota n \smallbold{a}) + \frac{s}{\iota n \smallbold{a}} J_s(\iota n \smallbold{a}) + = J_{s-1}(\iota n \smallbold{a}), +\] +so that (\eqnref{306}{92})~may be written +\[ +s(\mu-1)J_s(\iota n \smallbold{a}) + \iota n \smallbold{a} J_{s-1}(\iota n \smallbold{a}) = 0. +\] + +For non-magnetic substances $\mu = 1$, so that this equation +reduces to +\[ +J_{s-1}(\iota n \smallbold{a}) = 0. +\] +The magnetic induction along the radius is equal to +\[ +-\frac{\sigma}{\iota p}\, \frac{1}{r}\, \frac{dw}{d \theta}; +\] +at right angles to the radius it is equal to +\[ +\frac{\sigma}{\iota p}\, \frac{dw}{dr}. +\] + +\Article{307} Let us consider the case when $s = 1$. For a non-magnetic +cylinder $n$~will be given by the equation +\[ +J_0(\iota n \smallbold{a}) = 0; +\] +thus the values of~$\iota p$ will be the same as those in \artref{304}{Art.~304}, and +we may put +\[ +w = \cos{\theta} + \left\{A_1 J_1 \left( x_1 \frac{r}{\smallbold{a}} \right) \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2} x_1^2 t} \right. + \left. + A_2 J_1 \left( x_2 \frac{r}{\smallbold{a}} \right) \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2} x_2^2 t} + \ldots \right\}, \Tag{93} +\] +where $x_1$,~$x_2$ are the values $2.404, 5.520\ldots$, which are the roots +of the equation +\[ +J_0(x) = 0. +\] +%% -----File: 374.png---Folio 360------- +The magnetic force along the radius is therefore +\begin{multline*} +-\frac{4 \pi \smallbold{a}^2 \sin{\theta}}{r} + \left\{\frac{1}{x_1^2} A_1 J_1 \left( x_1 \frac{r}{\smallbold{a}} \right) \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2} x_1^2 t} \right. \\ +\left. + \frac{1}{x_2^2} A_2 J_1 \left( x_2 \frac{r}{\smallbold{a}} \right) \epsilon^{-\frac{\sigma}{4 \pi \smallbold{a}^2} x_2^2 t} + \ldots \right\}. \Tag{94} +\end{multline*} + +If originally the magnetic force is parallel to~$y$ and equal +to~$H$, the radial component of the magnetic force is~$H \sin{\theta}$; +hence, if we determine $A_1$,~$A_2$ so that when $t = 0$ the expression~(\eqnref{307}{94}) +is equal to~$H \sin{\theta}$, then equation~(\eqnref{307}{93}) will give the currents +generated by the annihilation of a uniform magnetic field +parallel to~$y$. + +\begin{DPgather*} +\lintertext{\indent Since} J_1(x) = - J_0'(x), \\ +\int_0^{\smallbold{a}} r^2 J_1 \left( x_p \frac{r}{\smallbold{a}} \right) dr + = - \int_0^{\smallbold{a}} r^2 J_0' \left( x_p \frac{r}{\smallbold{a}} \right) dr. +\end{DPgather*} +Integrating by parts and remembering that $J_0(x_p) = 0$, we see +that each of these integrals equals +\[ +\frac{2 \smallbold{a}}{x_p} \int_0^{\smallbold{a}} r J_0 \left( x_p \frac{r}{\smallbold{a}} \right) dr, +\] +which is equal to +\begin{DPgather*} +\frac{2 \smallbold{a}^3}{x_p^2} J_1(x_p), \Tag{95} \\ +\lintertext{since} \frac{d}{dx} \{x J_0'(x) \} = - x J_0(x). +\end{DPgather*} +Again, since +\[ +\frac{d^2 J_1(x)}{dx^2} + \frac{1}{x}\, \frac{d J_1(x)}{dx} + + \left(1 - \frac{1}{x^2} \right) J_1(x) = 0, +\] +multiplying by +\[ +2 x^2 \frac{d J_1}{dx}, +\] +we get +\[ +\frac{d}{dx} \left\{x^2 J_1'^2(x) + + x^2 \left( 1 - \frac{1}{x^2} \right) J_1^2(x) \right\} = 2 x J_1^2(x). +\] + +Hence +\[ +\int_0^{\xi} x J_1^2(x)\,dx + = \frac{1}{2} \xi^2 \left\{J_1'^2(\xi) + \left( 1 - \frac{1}{\xi^2} \right) J_1^2(\xi) \right\}. +\] + +\begin{DPalign*} +\lintertext{\indent Thus, since} \xi J_1'(\xi) + J_1(\xi) & = \xi J_0(\xi), \\ +\lintertext{we have if} J_0(\xi) & = 0, \\ +\int_0^{\xi} x J_1^2(x)\,dx & = \frac{1}{2} \xi^2 J_1^2(\xi). +\end{DPalign*} +%% -----File: 375.png---Folio 361------- +Hence, when $x_p$~is a root of +\begin{gather*} +J_{0}(x) = 0, \\ +\int_0^\smallbold{a} r J_1^2 \left(x_p \frac{r}{\smallbold{a}}\right)\,dr = \frac{1}{2} \smallbold{a}^2 J_1^2(x_p). \Tag{96} +\end{gather*} + +Now by~(\eqnref{307}{94}) +\[ +H = - \; \frac{4\pi \smallbold{a}^2}{r} \left\{\frac{A_1}{x_1^2} J_1 \left(x_1 \frac{r}{\smallbold{a}}\right) + \frac{A_2}{x_2^2} J_1 \left(x_2 \frac{r}{\smallbold{a}}\right) + \ldots\right\}, +\] +so that +\[ +H \int_0^\smallbold{a} r^2 J_1 \left(x_p \frac{r}{\smallbold{a}}\right)\,dr = - \frac{4\pi \smallbold{a}^2}{x_p^2} A_p \int_0^\smallbold{a} r J_1^2 \left(x_p \frac{r}{\smallbold{a}}\right)\,dr. +\] +Hence by~(\eqnref{307}{95}) and~(\eqnref{307}{96}) +\[ +A_p=-\frac{H}{\pi \smallbold{a} J_1(x_p)}. +\] + +Thus by~(\eqnref{307}{93}), the currents produced by the annihilation of +a magnetic field~$H$ parallel to~$y$ are given by the equation +\[ +w = - \frac{H \cos \theta}{\pi \smallbold{a}} \tsum \frac{J_1 \left(x_p \dfrac{r}{\smallbold{a}}\right)}{J_1 (x_p)} \, \epsilon^{- \frac{\sigma x_p^2}{4\pi \smallbold{a}^2} t}. +\] +Thus the currents vanish at the axis of the cylinder; when +$t = 0$ they are infinite at the surface and zero elsewhere. + +When, as in the case of iron, $\mu$~is very large, the equation~(\eqnref{306}{92}) +becomes approximately +\[ +J_s(\iota n \smallbold{a}) = 0. +\] + +The solution in this case can be worked out on the same lines +as the preceding one; for the results of this investigation we +\index{Lamb, decay of currents in cylinders}% +refer the reader to a paper by Prof.\ H.~Lamb (\textit{Proc.\ Lond.\ Math.\ +Soc.}\ XV, p.~270). + + +\Subsection{Electrical Oscillations on a Spherical Conductor.} +\index{Electrical vibrations, on spheres@\subdashtwo on spheres}% +\index{Oscillations, electrical, on spheres@\subdashtwo on spheres}% +\index{Sphere, xelectrical oscillations on@\subdashone electrical oscillations on}% + +\Article{308} The equations satisfied in the electromagnetic field by +the components of the magnetic induction, or of the electromotive +intensity, when these quantities vary as $\epsilon^{\iota p t}$, are, denoting +any one of them by F, of the form +\[ +\frac{d^2 F}{dx^2} + \frac{d^2 F}{dy^2} + \frac{d^2 F}{dz^2} = - \lambda^2 F, \Tag{97} +\] +where in an insulator $\lambda^2 = p^2 / V^2$, $V$~being the velocity of propagation +of electrodynamic action through the dielectric, and +in a conductor, whose specific resistance is~$\sigma$ and magnetic +permeability~$\mu$, +\[ +\lambda^2 = - 4 \pi \mu \iota p / \sigma. +\] +%% -----File: 376.png---Folio 362------- + +In treating problems about spheres and spherical waves it is +convenient to express~$F$ as the sum of terms of the form +\[ +f(r) Y_n, +\] +where $f(r)$ is a function of the distance from the centre, and +$Y_n$~a surface spherical harmonic function of the $n$\textsuperscript{th}~order. +Transforming~(\eqnref{308}{97}) to polar coordinates, we find that~$f(r)$ satisfies +the differential equation +\[ +\frac{d^2f}{dr^2} + \frac{2}{r} \frac{df}{dr} + \left(\lambda^2 - \frac{n(n + 1)}{r^2}\right)f = 0. +\] + +We can easily verify by substitution that the solution of this +equation is, writing~$\rho$ for~$\lambda r$, +\[ +f(r) = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \left(\frac{A\epsilon^{\iota\rho} + B\epsilon^{-\iota\rho}}{\rho}\right), +\] +where $A$ and $B$ are arbitrary constants; particular solutions of +this equation are thus +\begin{align*} +f(r) & = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \frac{\sin \rho}{\rho}, \Tag[alpha]{$\alpha$} \\ +f(r) & = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \frac{\cos \rho}{\rho}, \Tag[beta]{$\beta$} \\ +f(r) & = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \left\{\frac{\epsilon^{-\iota \rho}}{\rho} \right\}, \Tag[gamma]{$\gamma$} \\ +f(r) & = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \left\{\frac{\epsilon^{\iota \rho}}{\rho}\right\}. \Tag[delta]{$\delta$} +\end{align*} + +The first of these solutions is the only one which does not +become infinite when~$\rho$ vanishes, so that it is the solution we must +choose in any region where~$\rho$ can vanish; in the case of the +sphere it is the function which must be used inside the sphere; +we shall denote it by~$S_n(\rho)$. + +Outside the sphere, where~$\rho$ cannot vanish, the choice of the +function must be governed by other considerations. If we are +considering wave motions, then, since the solution~($\gamma$) will contain +the factor $\epsilon^{\iota(pt - \rho)}$, it will correspond to a wave diverging from +the sphere; the solution~($\delta$), which contains the factor $\epsilon^{\iota(pt + \rho)}$, +corresponds to waves converging on the sphere; the solutions~($\alpha$) +and~($\beta$) correspond to a combination of convergent and divergent +waves; thus, where there is no reflection we must take~($\gamma$) +if the waves are divergent, ($\delta$)~if they are convergent. In other +%% -----File: 377.png---Folio 363------- +cases we find that~$\lambda$ is complex and of the form $p + \iota q$; in this +case~($\alpha$) and~($\beta$) will be infinite at an infinite distance from the +origin, while of the two solutions~\DPtypo{$f$}{($\gamma$)} and~\DPtypo{$\delta$}{($\delta$)} one will be infinite, +the other zero, we must take the solution which vanishes when +$\rho$~is infinite. We shall denote~($\gamma$) by $E_n^-(\rho)$, ($\delta$)~by $E_n^+(\rho)$, and +when, as we shall sometimes do, we leave the question as to +which of the two we shall take unsettled until we have determined~$\lambda$, +we shall use the expression $E_n(\rho)$, which thus denotes +one or other of~($\gamma$) and~($\delta$). + +When there is no reflection, the solution of~(\eqnref{308}{97}) is thus expressed +by +\begin{align*} +& S_n(\rho) Y_n\; \epsilon^{\iota pt}\ \text{inside the sphere}, \\ +& E_n(\rho) Y_n\; \epsilon^{\iota pt}\ \text{outside the sphere}. +\end{align*} + +In particular when $Y_n$ is the zonal harmonic~$Q_n$, the solutions +are +\[ +S_n(\rho) Q_n \epsilon^{\iota pt}, \quad E_n(\rho) Q_n \epsilon^{\iota pt}. +\] + +When $Y_n$ is the first tesseral harmonic, the solutions are +\begin{gather*} +\frac{x}{r} S_n(\rho) \frac{dQ_n}{d\mu} \epsilon^{\iota pt}, \quad \frac{x}{r} E_n(\rho) \frac{dQ_n}{d\mu} \epsilon^{\iota pt}, \\ +\frac{y}{r} S_n(\rho) \frac{dQ_n}{d\mu} \epsilon^{\iota pt}, \quad \frac{y}{r} E_n(\rho) \frac{dQ_n}{d\mu} \epsilon^{\iota pt}, +\end{gather*} +where $\mu = \cos \theta$, $\theta$~being the colatitude of the intersection of the +radius with the surface of the sphere. + +\Article{309} We shall now proceed to prove those properties of the +functions~$S_n$ and~$E_n$ which we shall require for the subsequent +investigations. The reader who desires further information +about these interesting functions can derive it from the following +sources:--- + +\index{Stokes, zon the functions `S' and `E'@\subdashone on the functions `S' and `E'}% +Stokes, `On the Communication of Vibration from a Vibrating +Body to the Surrounding Gas,' \textit{Phil.\ Trans.}\ 1868, p.~447. + +\index{Rayleigh@Rayleigh, Lord, \textit{Theory of Sound}}% +Rayleigh, `Theory of Sound,' Vol.~II, Chap.~XVII. + +C.~Niven, `On the Conduction of Heat in Ellipsoids of Revolution,' +\textit{Phil.\ Trans.}\ Part~I, 1880, p.~117. + +\index{Niven, C., on the functions `S' and `E'}% +C.~Niven, `On the Induction of Electric Currents in Infinite +Plates and Spherical Shells,' \textit{Phil.\ Trans.}\ Part~II, 1881, p.~307. + +\index{Lamb, on the functions `S' and `E'@\subdashone on the functions `S' and `E'}% +H.~Lamb, `On the Vibrations of an Elastic Sphere,' and `On +the Oscillations of a Viscous Spheroid,' \textit{Proc.\ Lond.\ Math.\ Soc.}, +13, pp.~51, 189. + +H.~Lamb, `On Electrical Motions in a Spherical Conductor,' +\textit{Phil.\ Trans.}\ Part~II, 1883, p.~519. +%% -----File: 378.png---Folio 364------- + +\index{Helmholtz vb@\subdashtwo on the functions `S' and `E'}% +V.~Helmholtz, `Wissenschaftliche Abhandlungen,' Vol.~I, p.~320. + +\index{Heine@Heine, \textit{Kügelfunctionen}}% +Heine, `Kugelfunctionen,' Vol.~I, p.~140. + +The following propositions are for brevity expressed only for +the~$S_n$ functions, since, however, their proof only depends upon +the differential equations satisfied by these functions they are +equally true for the functions~$\beta$, $\gamma$, $\delta$. + +Since +\index{Functions, z `S' and `E'@\subdashone `S' and `E'}% +\begin{DPgather*} +S_n(\rho) = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \frac{\sin \rho}{\rho}, \\ +\frac{1}{\rho} \frac{d}{d\rho} \left\{\frac{S_{n-1}}{\rho^{n-1}} \right\} = \frac{S_n}{\rho^n}, \\ +\lintertext{or} \rho \frac{dS_{n-1}}{d\rho} - (n-1) S_{n-1} = \rho S_n, \Tag{98} +\end{DPgather*} +and therefore +\[ +\rho \frac{dS_n}{d\rho} - nS_n = \rho S_{n+1}. \Tag{99} +\] + +Multiply~(\eqnref{309}{98}) by $\rho^n$ and differentiate with respect to~$\rho$, and +we get +\[ +\frac{d^2}{d\rho^2} S_{n-1} + \frac{2}{\rho} \frac{dS_{n-1}}{d\rho} - \frac{n(n-1) S_{n-1}}{\rho^2} = (n+1) \frac{S_n}{\rho} + \frac{dS_n}{d\rho}. +\] + +But +\[ +\frac{d^2 S_{n-1}}{d\rho^2} + \frac{2}{\rho} \frac{dS_{n-1}}{d\rho} + \left(1 - \frac{n(n-1)}{\rho^2}\right) S_{n-1} = 0, +\] +hence +\[ +-\rho S_{n-1} = (n+1) S_n + \rho \frac{dS_n}{d\rho}. \Tag{100} +\] + +From~(\eqnref{309}{99}) and~(\eqnref{309}{100}), we get +\begin{DPalign*} +(2n + 1) S_n + \rho (S_{n-1} + S_{n+1}) = 0, & \Tag{101} \\ +\lintertext{and} (2n + 1) \frac{dS_n}{d\rho} = (n+1)S_{n+1} - nS_{n-1}. & +\end{DPalign*} + +Again, since +\begin{align*} +& \frac{d^2}{dr^2} S_n(\lambda r) + \frac{2}{r} \frac{d}{dr} S_n(\lambda r) +\left(\lambda^2 - \frac{n(n+1)}{r^2}\right) S_n(\lambda r) = 0, \\ +\intertext{and} +& \frac{d^2}{dr^2} S_n(\lambda' r) + \frac{2}{r} \frac{d}{dr} S_n(\lambda' r) +\left(\lambda'^2 - \frac{n(n+1)}{r^2}\right) S_n(\lambda' r) = 0, +\end{align*} +we have +\begin{multline*} +r^2 \left\{S_n(\lambda' r) \frac{d^2}{dr^2} S_n(\lambda r) - S_n(\lambda r) \frac{d^2}{dr^2} S_n(\lambda' r) \right\} \\ ++ 2r \left\{S_n(\lambda' r) \frac{d}{dr} S_n(\lambda r) - S_n(\lambda r) \frac{d}{dr} S_n(\lambda' r) \right\} \\ += (\lambda'^2 - \lambda^2) r^2 S_n(\lambda r) S_n(\lambda' r), +\end{multline*} +%% -----File: 379.png---Folio 365------- +and hence +\begin{multline*} +\int_a^b r^2 S_n(\lambda r) S_n (\lambda'r)\, dr \\ += \frac{1}{\lambda'^2 - \lambda^2} \left\{r^2 S_n (\lambda'r) \frac{d}{dr} S_n (\lambda r) - r^2 S_n(\lambda r) \frac{d}{dr} S_n (\lambda'r) \right\}_a^b, \Tag{102} +\end{multline*} +so that if $\lambda$, $\lambda'$ satisfy the equations +\begin{DPgather*} +a^2 \left\{S_n (\lambda'a) \frac{d}{da} S_n (\lambda a) - S_n (\lambda a) \frac{d}{da} S_n (\lambda'a) \right\} = 0,\\ +b^2 \left\{S_n (\lambda'b) \frac{d}{db} S_n (\lambda b) - S_n (\lambda b) \frac{d}{db} S_n (\lambda'b) \right\} = 0,\\ +\lintertext{then} +\int_a^b r^2 S_n (\lambda r) S_n (\lambda'r)\, dr = 0. +\end{DPgather*} + +Proceeding to the limit $\lambda' = \lambda$, we get from (\eqnref{309}{102}) +\[ +\int_a^b r^2 S_n^2 (\lambda r)\, dr = -\frac{1}{2 \lambda^2} \left[ r^2 S_n (\lambda r) \frac{d}{dr} \left\{r \frac{d S_n(\lambda r)}{dr} \right\} \right. \\ +- \left. r^3 \left\{\frac{d S_n (\lambda r)}{dr} \right\}^2 \right]_a^b. +\] + +{\allowdisplaybreaks +The following table of the values of the first four of the $S$ and +$E$ functions will be found useful for the subsequent work:--- +\begin{align*} +S_0(x) =& \frac{\sin x}{x},\\ +S_1(x) =& \frac{\cos x}{x} - \frac{\sin x}{x^2},\\ +S_2(x) =& -\frac{\sin x}{x} - \frac{3 \cos x}{x^2} + \frac{3 \sin x}{x^3},\\ +S_3(x) =& - \frac{\cos x}{x} + \frac{6 \sin x}{x^2} + \frac{15 \cos x}{x^3} - \frac{15 \sin x}{x^4}.\\ +. \qquad &. \qquad . \qquad . \qquad . \qquad . \qquad . \qquad . \qquad . \\ +&E_0^-(x) = \frac{\epsilon^{-\iota x}}{x},\\ +&E_1^-(x) = - \frac{\epsilon^{-\iota x}}{x} \left(\iota + \frac{1}{x} \right),\\ +&E_2^-(x) = - \frac{\epsilon^{-\iota x}}{x} \left( 1 - \frac{3 \iota}{x} - \frac{3}{x^2} \right),\\ +&E_3^-(x) = \frac{\epsilon^{-\iota x}}{x} \left( \iota + \frac{6}{x} - \frac{15 \iota}{x^2} - \frac{15}{x^3} \right).\\ + &\quad . \qquad . \qquad . \qquad . \qquad . \qquad . \qquad . +\end{align*} +The values of $E^+$ can be got from those of $E^-$ by changing the +sign of $\iota$. +}%end \allowdisplaybreaks +%% -----File: 380.png---Folio 366------- + +\Article{310} We shall now proceed to the study of the oscillations +of a distribution of electricity over the surface of a sphere. Let +us suppose that a distribution of electricity whose surface +density is proportional to a \emph{zonal} harmonic of the $n^{\text{th}}$ order is +produced over the surface of the sphere, and that the cause producing +this distribution is suddenly removed; then, since this +distribution cannot be in equilibrium unless under the influence +of external forces, electric currents will start off to equalize it, +and electrical vibrations will be started whose period it is the +object of the following investigation to determine. + +Since the currents obviously flow in planes through the axis +of the zonal harmonic, which we shall take for the axis of $z$, +there is no electromotive force round a circuit in a plane at +right angles to this axis; and since the electromotive force +round a circuit is equal to the rate of diminution in the number +of lines of magnetic force passing through it, we see that in this +case, since the motion is periodic, there can be no lines of +magnetic force at right angles to such a circuit; in other words, +the magnetic force parallel to the axis of $z$ vanishes. Again, +taking a small closed circuit at right angles to a radius of the +sphere, we see that the electromotive force round this circuit, +and therefore the magnetic force at right angles to it, vanish; +hence the magnetic force has no component along the radius, +and is thus at right angles to both the axis of $z$ and the radius, +so that the lines of magnetic force are a series of small circles +with the axis of the harmonic for axis. + +Hence, if $a$, $b$, $c$ denote the components of magnetic induction +parallel to the axes of $x$, $y$, $z$ respectively, we may put +\begin{align*} +a &= y\chi(r, \mu),\\ +b &= -x\chi(r, \mu),\\ +c &= 0, +\end{align*} +where $\chi(r, \mu)$ denotes some function of $r$ and $\mu$. Comparing +this with the results of \artref{308}{Art.~308}, we see that inside the sphere +\begin{equation} +\left. +\begin{aligned} +a &= A \frac{y}{r} S_n (\lambda'r) \frac{dQ_n}{d\mu} \epsilon^{\iota p t},\\ +b &= -A \frac{x}{r} S_n (\lambda'r) \frac{dQ_n}{d\mu} \epsilon^{\iota p t},\\ +c &= 0, +\end{aligned} \right\} \Tag{103} +\end{equation} +where $\lambda'^2 = - 4\pi\mu\iota p/\sigma$, and $A$ is a constant. +%% -----File: 381.png---Folio 367------- + +Outside the sphere, +\[ +\left. +\begin{aligned} +a &= B \frac{y}{r} E_n (\lambda r) \frac{dQ_n}{d \mu} \epsilon^{\iota pt},\\ +b &= -B \frac{x}{r} E_n (\lambda r) \frac{dQ_n}{d \mu} \epsilon^{\iota pt},\\ +c &= 0, +\end{aligned} +\right\} \Tag{104} +\] +where $\lambda = p/V$, and $B$ is a constant. + +Since the tangential magnetic force is continuous, we have if +$\smallbold{a}$ is the radius of the sphere, +\[ +\frac{A}{\mu} S_n (\lambda' \smallbold{a}) = B E_n (\lambda \smallbold{a}). \Tag{105} +\] +To get another surface condition we notice that the electromotive +intensity parallel to the surface of the sphere is continuous. +Now the total current through any area is equal to +$1 / 4 \pi$ times the line integral of the magnetic force round that +area, hence, taking as the area under consideration an elementary +one $dr \; r \,\sin \theta\, d\phi$, whose sides are respectively parallel to an +element of radius and to an element of a parallel of latitude, we +find, if $q$ is the current in a meridian plane at right angles to the +radius, +\[ +4 \pi q = \frac{1}{r} \frac{d}{dr} (\gamma r), +\] +where $\gamma$ is the resultant magnetic force which acts tangentially +to a parallel of latitude. + +The electromotive intensity parallel to $q$ is, in the conductor +\[ +\sigma q, +\] +and in the dielectric +\[ +\frac{4 \pi}{\iota pK} q. +\] +Hence, since this is continuous, we have +\[ +\frac{A \sigma}{\mu} \frac{d}{d \smallbold{a}} (\smallbold{a}S_n(\lambda'\smallbold{a})) += \frac{B 4 \pi}{\iota pK} \frac{d}{d\smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a}) \}. \Tag{106} +\] +Eliminating $A$ and $B$ from equations (\eqnref{310}{105}) and (\eqnref{310}{106}), we get +\[ +\frac{\sigma \dfrac{d}{d\smallbold{a}} \{\smallbold{a}S_n(\lambda'\smallbold{a})\}}{S_n(\lambda'\smallbold{a})} += \frac{4\pi}{\iota pK} \frac{\dfrac{d}{d\smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a})\}}{E_n(\lambda \smallbold{a})}. \Tag{107} +\] +\Article{311} The oscillations of the surface electrification about the +%% -----File: 382.png---Folio 368------- +state of uniform distribution are extremely rapid as the wave +length must be comparable with the radius of the sphere. For +such rapid vibrations as these however $\lambda'\smallbold{a}$, or +$\{-4 \pi \mu \iota p / \sigma \}^{\frac{1}{2}} \smallbold{a}$, +is very large, but when this is the case, we see from the equation +\[ +S_n(\rho) = \rho^n \left\{\frac{1}{\rho} \frac{d}{d\rho} \right\}^n \frac{\sin \rho}{\rho}, +\] +that $S_n' (\lambda'\smallbold{a})$ is approximately equal to $\pm \iota S_n(\lambda'\smallbold{a})$, so that the +left-hand side of equation (\eqnref{310}{107}) is of the order +\[ +\sigma \smallbold{a} \sqrt{-\frac{4 \pi \mu \iota p}{\sigma}}, +\] +and thus, since $1/K = V^2$, +\[ +\frac{\dfrac{d}{d\smallbold{a}} \{\smallbold{a} E_n(\lambda \smallbold{a}) \}}{E_n(\lambda \smallbold{a})} +\] +is of the order +\[ +\frac{1}{4 \pi V^2} p\sigma \smallbold{a}\; \sqrt{-\frac{4 \pi \mu \iota p}{\sigma}}, \quad +\text{or} \quad \sqrt{\frac{\sigma}{\smallbold{a}V}}, +\] +since $p$ is comparable with $V/\smallbold{a}$. + +This, when the sphere conducts as well as iron or copper, is +extremely small unless $\smallbold{a}$ is less than the wave length of sodium +light, while for a perfect conductor it absolutely vanishes, hence +equation (\eqnref{310}{107}) is very approximately equivalent to +\[ +\frac{d}{d \smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a}) \} = 0. \Tag{108} +\] +This, by the relation (\eqnref{309}{101}), may be written +\[ +E_{n+1}(\lambda \smallbold{a}) - \frac{n+1}{n} E_{n-1}(\lambda \smallbold{a}) = 0, +\] +which is the form given in my paper on `Electrical Oscillations,' +\textit{Proc. Lond. Math. Soc}.~XV, p.~197. + +This condition makes the tangential electromotive intensity +vanish, so that the lines of electrostatic induction are always at +right angles to the surface of the sphere. + +\Article{312} In order to show that the equations (\eqnref{310}{103}) and (\eqnref{310}{104}) in +\index{Sphere, yperiod of these oscillations@\subdashone period of these oscillations}% +\index{Time of vibration of electricity on a sphere@\subdashtwo vibration of electricity on a sphere}% +the preceding \artref{310}{article} correspond to a distribution of electricity +over the surface of the sphere represented by a zonal harmonic +$Q_n$ of the $n^{\text{th}}$ order, we only need to show that the current along +the radius vector varies as $Q_n$, for the difference between the +%% -----File: 383.png---Folio 369------- +radial currents in the sphere and in the dielectric is proportional +to the rate of variation of the surface density of the electricity +on the sphere, and therefore, since the surface density varies as +$\epsilon^{\iota p t}$, it will be proportional to the radial current. + +Consider a small area at right angles to the radius, and apply +the principle that $4\pi$ times the current through this area is +equal to the line integral of the magnetic force round it, we get, +if $\mathtt{P}$ is the current along the radius and $\mu = \cos \theta$, +\[ +4\pi \mathtt{P} = \frac{1}{r} \frac{d}{d\mu} (\gamma \sin{\theta}), \Tag{109} +\] +where $\gamma$, as before, is the resultant magnetic force which acts +along a tangent to a parallel of latitude. + +By equation (\eqnref{310}{103}), $\gamma$ is proportional to +\[ +\sin{\theta} \frac{d Q_n}{d \mu}, +\] +so that $\mathtt{P}$ is proportional to +\begin{DPgather*} +\frac{d}{d\mu} \left\{\sin^2{\theta}\; \frac{dQ_n}{d\mu} \right\};\\ +\lintertext{but} +\frac{d}{d\mu} \left\{\sin^2{\theta}\; \frac{dQ_n}{d\mu} \right\} + n(n+1)Q_n = 0, +\end{DPgather*} +hence $\mathtt{P}$, and therefore the surface density, is proportional to $Q_n$. + +We shall now consider in more detail the case $n = 1$.\\ +We have +\[ +\frac{p^2}{V^2} = \lambda^2. +\] + +We shall take as the solution of the equation $p^2/V^2 = \lambda^2$ +\[ +\frac{p}{V} = \lambda, +\] +and we shall take $E_n^- (\lambda r)$ as our solution, as this corresponds to +a wave diverging from the sphere. Thus, equation (\eqnref{311}{108}) becomes +\[ +\frac{d}{d \smallbold{a}} \{\smallbold{a} E_1^-(\lambda \smallbold{a}) \} = 0, +\] +or substituting for $E_1^- (\lambda \smallbold{a})$ the value given in \artref{309}{Art.~309}, +\begin{DPgather*} +\epsilon^{-\iota\lambda \smallbold{a}} \left\{\frac{1}{(\lambda \smallbold{a})^2} + \frac{\iota}{\lambda \smallbold{a}} - 1 \right\} = 0,\\ +\lintertext{or} +(\lambda \smallbold{a})^2 - \iota \lambda \smallbold{a} = 1,\\ +\lambda \smallbold{a} = \frac{\iota}{2} \pm \frac{\sqrt{3}}{2}. +\end{DPgather*} +%% -----File: 384.png---Folio 370------- +\begin{DPgather*} +\lintertext{Hence} p = \frac{V}{\smallbold{a}} \left\{\frac{\iota}{2} + \frac{\sqrt{3}}{2} \right\}, +\end{DPgather*} +taking the positive sign since the wave is divergent. + +\index{Rate of decay of yoscillation on spheres@\subdashtwo of oscillation on spheres}% +\index{Decay, xof electrical oscillations on spheres@\subdashone of electrical oscillations on spheres}% +\index{Vibrations d, decay of, on spheres@\subdashtwo on spheres}% +\index{Faradayx tubes, disposition of round vibrating sphere@\subdashtwo disposition of round vibrating sphere}% +\index{Sphere, zfield of force round vibrating@\subdashone field of force round vibrating}% +Hence, the time of vibration is $4 \pi \smallbold{a} / \sqrt{3}V$, and the wave +length $4 \pi \smallbold{a} / \sqrt{3}$. The amplitude of the vibration falls to $1 / \epsilon$ of +its original value after a time $2 \smallbold{a} / V$, that is after the time taken +by light to pass across a diameter of the sphere. In the time +occupied by one complete vibration the amplitude falls to $\epsilon^{-\dfrac{2 \pi}{\sqrt{3}}}$, +or about $1/35$ of its original value, thus the vibrations will +hardly make a complete oscillation before they become practically +extinguished. This very rapid extinction of the vibrations is +independent of the resistance of the conductor and is due to the +emission of radiant energy by the sphere. Whenever these +electrical vibrations can radiate freely they die away with +immense rapidity and are practically dead beat. + +If we substitute this value of $\lambda$ in the expressions for the +magnetic force and electromotive intensity in the dielectric, we +shall find that the following values satisfy the conditions of the +problem. If $\gamma$ is the resultant magnetic force, acting at right +angle to the meridional plane, +\[ +\gamma = \frac{\sin \theta \smallbold{a}}{r} \left\{1 - \frac{\smallbold{a}}{r} + \frac{\smallbold{a}^2}{r^2} \right\}^{\frac{1}{2}} \epsilon^{-\dfrac{(Vt-r)}{2 \smallbold{a}}} \cos(\phi + \delta), +\] +\begin{DPalign*} +\lintertext{where} \phi &= \frac{\sqrt{3}}{2 \smallbold{a}} (Vt - r),\\ +\tan \delta &= \frac{r - \smallbold{a}}{r + \smallbold{a}} \tan{\frac{\pi}{3}}. +\end{DPalign*} + +If $\Theta$ is the electromotive intensity at right angles to $r$ in the +meridional plane, $K$ the specific inductive capacity of the dielectric +surrounding the sphere, then by \artref{310}{Art.~310} +\begin{DPgather*} +K \Theta = \frac{\sin \theta}{V r} \smallbold{a} \left( 1 - \frac{\smallbold{a}}{r} \right) \left\{1 + \frac{\smallbold{a}}{r} + \frac{\smallbold{a}^2}{r^2} \right\}^{\frac{1}{2}} \epsilon^{-\dfrac{(Vt-r)}{2 \smallbold{a}}} \cos(\phi + \delta'),\\ +\lintertext{\rlap{where}} \tan \delta' = \frac{\sin{\dfrac{\pi}{3}}}{\cos{\dfrac{\pi}{3}} + \dfrac{\smallbold{a}}{r}}, +\end{DPgather*} +and $V$ is the velocity of propagation of electromagnetic action +%% -----File: 385.png---Folio 371------- +through the dielectric. Close to the surface of the sphere $\delta = 0$, +$\delta'= \pi / 6$, thus $\gamma$ and $\Theta$ differ in phase by $\pi / 6$. At a large +distance from the sphere +\[ +\delta = \delta' +\] +so that $\Theta$ and $\gamma$ are in the same phase, and we have +\[ +V K \Theta = \gamma = \frac{\sin \theta \smallbold{a}}{r} \epsilon^{-\dfrac{1}{2 \smallbold{a}} (V t-r)} \cos \left( \phi + \frac{\pi}{3} \right). +\] + +The radial electromotive intensity $P$ is, by equation \DPtypo{\eqnref{312}{109}}{(\eqnref{312}{109})}, given +by the equation +\[ +K P = \frac{2 \cos \theta \smallbold{a}^2}{V r^2} \left\{1 - \frac{\smallbold{a}}{r} + \frac{\smallbold{a}^2}{r^2} \right\}^{\frac{1}{2}} \epsilon^{-\dfrac{(Vt-r)}{2 \smallbold{a}}} \sin{\left( \phi + \delta - \frac{\pi}{6} \right)}. +\] + +Thus at a great distance from the sphere $P$ varies as $\smallbold{a}^2/r^2$, +while $\Theta$ only varies as $\smallbold{a}/r$, thus the electromotive intensity is +very approximately tangential. The general character of the +lines of electrostatic induction is similar to that in the case of +the cylinder shown in \figureref{fig110}{Fig.~110}. + +\Article{313} The time of vibration of the electricity about the distribution +represented by the second zonal harmonic is given by +a cubic equation, whose imaginary roots I find to be +\[ +\iota \lambda \smallbold{a} = -.7 \pm 1.8 \iota. +\] + +The rate of these vibrations is more than twice as fast as +those about the first harmonic distribution; the rate of decay of +these vibrations, though absolutely greater than in that case, is +not increased in so great a ratio as the frequency, so that the +system will make more vibrations before falling to a given +fraction of its original value than before. + +The time of vibration of the electricity about the distribution +represented by the third zonal harmonic is given by a biquadratic +equation whose roots are imaginary, and given by +\begin{align*} +\iota \lambda \smallbold{a} &= -.85 \pm 2.76 \iota,\\ +\iota \lambda \smallbold{a} &= -2.15 \pm .8 \iota. +\end{align*} + +The quicker of these vibrations is more than three times +faster than that about the first zonal harmonic, and there will be +many more vibrations before the disturbance sinks to a given +fraction of its original value. The slower vibration is of nearly +the same period as that about the first harmonic, but it fades +away much more rapidly than even that vibration. +%% -----File: 386.png---Folio 372------- + +The vibrations about distributions of electricity represented +by the higher harmonics thus tend to get quicker as the degree +of the harmonic increases, and more vibrations are made before +the disturbance sinks into insignificance. + +\Article{314} We have seen in \artref{16}{Art.~16} that a charged sphere when +moving uniformly produces the same magnetic field as an +element of current at its centre. If the sphere is oscillating +instead of moving uniformly, we may prove (J.~J. Thomson, +\textit{Phil.\ Mag.}~[5], 28, p.~1, 1889) that if the period of its oscillations +is large compared with that of a distribution of electricity over +the surface of the sphere, the vibrating sphere produces the +same magnetic field as an alternating current of the same period. +Waves of electromotive intensity carrying energy with them +travel through the dielectric, so that in this case the energy of +the sphere travels into space far away from the sphere. When, +however, the period of vibration of the sphere is less than +that of the electricity over its surface, the electromotive intensity +and the magnetic force diminish very rapidly as we +recede from the sphere, the magnetic field being practically +confined to the inside of the sphere, so that in this case the +energy of the moving sphere remains in its immediate neighbourhood. + +We may compare the behaviour of the electrified sphere with +that of a string of particles of equal mass placed at equal +intervals along a tightly stretched string; if one of the particles, +say one of the end ones, is agitated and made to vibrate more +slowly than the natural period of the system, the disturbance +will travel as a wave motion along the string of particles, and +the energy given to the particle at the end will be carried far +away from that particle; if however the particle which is +agitated is made to vibrate more quickly than the natural +period of vibration of the system, the disturbance of the adjacent +particles will diminish in geometrical progression, and +the energy will practically be confined to within a short +distance of the disturbed particle. This case possesses additional +interest since it was used by Sir G.~G. Stokes to explain +fluorescence. + +\Article{315} To consider more closely the effect of reflection let us +\index{Sphere, zvibrations of concentric spheres@\subdashone vibrations of concentric spheres}% +take the case of two concentric spherical conductors of radius +$\smallbold{a}$~and~$\smallbold{b}$ respectively. Then in the dielectric between the +%% -----File: 387.png---Folio 373------- +spheres, the components of magnetic induction are given by +\begin{align*} +a &= \frac{y}{r} \left\{BE_n^+(\lambda r) + CE_n^-(\lambda r) \right\} \frac{dQ_n}{d\mu},\\ +b &= -\frac{x}{r} \left\{BE_n^+(\lambda r) + CE_n^-(\lambda r) \right\} \frac{dQ_n}{d\mu},\\ +c &= 0. +\end{align*} + +We may show, as in \artref{311}{Art.~311}, that if the spheres are metallic +and not excessively small the electromotive intensity parallel to +the surface of the spheres vanishes when $r = \smallbold{a}$ and when $r = \smallbold{b}$; +thus we have\nblabel{eqnp:373} +\begin{align*} +0 &= B \frac{d}{d\smallbold{a}} \{\smallbold{a}E_n^+(\lambda \smallbold{a})\} + + C \frac{d}{d\smallbold{a}} \{\smallbold{a}E_n^{\DPtypo{-1}{-}}(\lambda \smallbold{a})\},\\ +0 &= B \frac{d}{d\smallbold{b}} \{\smallbold{b}E_n\DPtypo{}{^+}(\lambda \smallbold{b})\} + + C \frac{d}{d\smallbold{b}} \{\smallbold{b}E_n^-(\lambda \smallbold{b})\}. +\end{align*} + +Eliminating \DPtypo{$A$~and~$B$}{$B$~and~$C$}, we have +\[ +\frac{d}{d\smallbold{a}} \{\smallbold{a}E_n^+(\lambda \smallbold{a})\} \, +\frac{d}{d\smallbold{b}} \{\smallbold{b}E_n^-(\lambda \smallbold{b})\} = +\frac{d}{d\smallbold{a}} \{\smallbold{a}E_n^-(\lambda \smallbold{a})\} \, +\frac{d}{d\smallbold{b}} \{\smallbold{b}E_n^+(\lambda \smallbold{b})\}. +\] +When $n = 1$, this becomes +\[ +\tan \lambda \{\smallbold{b} - \smallbold{a} \} + = \lambda \frac{\left\{\dfrac{1}{\smallbold{a}} - \dfrac{1}{\smallbold{b}} \right\} + \left\{\lambda^2 + \dfrac{1}{\smallbold{ab}} \right\}} + {\left( \dfrac{1}{\smallbold{a}^2} - \lambda^2 \right) + \left( \dfrac{1}{\smallbold{b}^2} - \lambda^2 \right) + + \dfrac{\lambda^2}{\smallbold{ab}}}. +\Tag{110} +\] +The roots of this equation are real, so that in this case there is +no decay of the vibrations apart from that arising from the +resistance of the conductors. + +If $\smallbold{a}$ is very small compared with~$\smallbold{b}$, this equation reduces to +\[ +\tan \lambda \smallbold{b} = \frac{\lambda \smallbold{b}}{1-\lambda^2 \smallbold{b}^2}. +\] +The least root of this equation other than $\lambda = 0$, I find by the +method of trial and error to be $\lambda \smallbold{b} = 2.744$. + +This case is that of the vibration of a spherical shell excited +by some cause inside, here there is no radiation of the energy +into space, the electrical waves keep passing backwards and +forwards from one part of the surface of the sphere to another. + +The wave length in this case is $2\pi \smallbold{b}/2.744$ or~$2.29\smallbold{b}$, and is +therefore less than the wave length, $4\pi \smallbold{b}/\sqrt{3}$, of the oscillations +which would occur if the vibrations radiated off into space: this +is an example of the general principle in the theory of vibrations +that when dissipation of energy takes place either from friction, +%% -----File: 388.png---Folio 374------- +electrical resistance, or radiation, the time of vibration is increased. + +In this case, since the radius of the inner sphere is made to +vanish in the limit, the magnetic force inside the sphere whose +radius is~$\smallbold{b}$ must be expressed by that function of~$r$ which does +not become infinite when $r$~is zero, i.e.\ by $S_n (\lambda r)$. In the case +when $n = 1$, the components $a$,~$b$,~$c$ of the magnetic induction +are given by +\begin{align*} +a &= \tsum B \frac{y}{r} S_1 (\lambda r) \epsilon^{\iota pt},\\ +b &= -\tsum B \frac{x}{r} S_1 (\lambda r) \epsilon^{\iota pt},\\ +c &= 0; +\end{align*} +where the summation extends over all values of~$\lambda$ which satisfy +the equation +\[ +\tan \lambda \smallbold{b} = \frac{\lambda \smallbold{b}}{1 - \lambda^2 \smallbold{b}^2}. +\] + +Let us consider the case when only the gravest vibration is +excited. Let $e$~be the surface density of the electricity, then it +will be given by an equation of the form +\[ +e = C \cos \theta \cos pt; +\] +where $p = V\lambda_1$, $\lambda_1$~being equal to~$2.744 / \smallbold{b}$. + +By equation~(\eqnref{312}{109}) the normal displacement current~$\smallbold{P}$ is given +by the equation +\[ +4 \pi \smallbold{P} + = \frac{1}{r}\, \frac{d}{d\centerdot\cos \theta} \{\sin\theta \{a^2 + b^2 \}^{\frac{1}{2}} \}. +\] +In this case +\begin{DPgather*} +\left. +\begin{aligned} +a &= \frac{y}{r} BS_1(\lambda_1 r)\epsilon^{\iota pt},\\ +b &= -\frac{x}{r} BS_1(\lambda_1 r)\epsilon^{\iota pt}, +\end{aligned} +\right\} +\Tag{111} \\ +\lintertext{so that} +4 \pi \smallbold{P} = - \frac{2}{r} B \cos \theta S_1 (\lambda_1 r) \epsilon^{\iota pt}. +\end{DPgather*} +When $r = \smallbold{b}$ the normal displacement current $= de / dt$, hence +\[ +-4 \pi C \cos \theta p \sin pt + = - \frac{2}{\smallbold{b}} B \cos \theta S_1 (\lambda_1 \smallbold{b}) \epsilon^{\iota pt}. +\] + +Substituting this value of $B \epsilon^{\iota pt}$ in~(\eqnref{315}{111}), we have +\begin{align*} +a &= \frac{y}{r} 2 \pi \smallbold{b} p \sin pt C \frac{S_1(\lambda_1r)}{S_1(\lambda_1 \smallbold{b})},\\ +b &= -\frac{x}{r} 2 \pi \smallbold{b} p \sin pt C \frac{S_1(\lambda_1r)}{S_1(\lambda_1 \smallbold{b})},\\ +c &= 0. +\end{align*} +%% -----File: 389.png---Folio 375------- + +At the surface of the sphere the maximum intensity of the +magnetic force is +\begin{DPgather*} +2 \pi \smallbold{b} p C \sin \theta,\\ +\lintertext{or since} +\smallbold{b} p = V \lambda_1 \smallbold{b},\\ +\lintertext{and} +\lambda_1 \smallbold{b} = 2.744, +\end{DPgather*} +the maximum magnetic force is +\[ +2 \pi × 2.744 V C \sin \theta. +\] + +For air at atmospheric pressure~$VC$ may be as large as~$25$ +without the electricity escaping; taking this value of~$VC$, the +maximum value of the magnetic force will be +\[ +431 \sin \theta; +\] +this indicates a very intense magnetic field, which however +would be difficult to detect on account of its very rapid rate of +reversal. + + +\Subsection{Electrical Oscillations on Two Concentric Spheres of +nearly equal radius.} + +\Article{316} When $d$, the difference between the radii $\smallbold{a}$~and~$\smallbold{b}$, is very +small compared with $\smallbold{a}$~or~$\smallbold{b}$, equation~(\eqnref{315}{110}) becomes +\[ +\tan \lambda d + = \frac{\lambda d ( 1 + \lambda^2 \smallbold{a}^2)} + {\lambda^4 \smallbold{a}^4 - \lambda^2 \smallbold{a}^2 + 1}. +\Tag{112} +\] + +There will be one root of this equation corresponding to a +vibration whose wave length is comparable with~$\smallbold{a}$, and other +roots corresponding to wave lengths comparable with~$d$. + +When the wave length is comparable with~$\smallbold{a}$, $\lambda$~is comparable +with~$1 / \smallbold{a}$, so that in this case $\lambda d$~is very small; when this is the +case $( \tan \lambda d ) / \lambda d = 1$, and equation~(\eqnref{316}{112}) becomes approximately +\begin{DPgather*} +1 = \frac{1 + \lambda^2 \smallbold{a}^2} + {\lambda^4 \smallbold{a}^4 - \lambda^2 \smallbold{a}^2 + 1},\\ +\lintertext{or} +\lambda \smallbold{a} = \sqrt{2}. +\end{DPgather*} +The wave length $2 \pi / \lambda$ is thus equal to $\pi \sqrt{2}$~times the radius of +the sphere. + +In this case, since the distance between the spheres is very +small compared with the wave length, the tangential electromotive +intensity, since it vanishes at the surface of both spheres, +will remain very small throughout the space between them; the +electromotive intensity will thus be very nearly radial between +the spheres, and the places nearest each other on the two spheres +%% -----File: 390.png---Folio 376------- +will have opposite electrical charges. The tubes of electrostatic +induction are radial, and moving at right angles to themselves +traverse during a complete oscillation a distance comparable +with the circumference of one of the spheres. + +When the wave length is comparable with the distance +between the spheres, $\lambda$~is comparable with~$1/d$, and $\lambda \smallbold{a}$~is therefore +very large. The denominator of the right-hand side of +equation~(\eqnref{316}{112}), since it involves~$(\lambda \smallbold{a})^4$, will be exceedingly large +compared with the numerator, and this side of the equation will +be exceedingly small, so that an approximate solution of it is +\begin{DPgather*} +\tan \lambda d = 0, \\ +\lintertext{or} +\lambda d = n \pi, +\end{DPgather*} +where $n$~is an integer. + +The wave length $2 \pi / \lambda = 2 d / n$. Hence, the length of the +longest wave is~$2 d$, and there are harmonics whose wave lengths +are $d$,~$2d/3$, $2d/4, \ldots$. + +When $\lambda \smallbold{a}$ is very large, the equation on p.~\pageref{eqnp:373} +\[ +\frac{d}{dr} \{B r E_1^+(\lambda r) + C r E_1^-(\lambda r) \}_{r=\smallbold{a}} = 0, +\] +is equivalent to +\[ +B \epsilon^{\iota \lambda \smallbold{a}} + C \epsilon^{-\iota \lambda \smallbold{a}} = 0. +\] +Hence we may put, introducing a new constant~$A$, +\begin{align*} +B &= A \epsilon^{-\iota \lambda \smallbold{a}},\\ +C &= -A \epsilon^{\iota \lambda \smallbold{a}}. +\end{align*} + +The resultant magnetic force in the dielectric is equal to +\[ +\{B E_1^+ ( \lambda r ) + C E_1^- ( \lambda r ) \} \sin \theta \epsilon^{\iota p t}, +\] +or substituting the preceding values of $B$~and~$C$ and retaining +only the lowest powers of~$1 / \lambda r$, +\begin{DPgather*} +\frac{A \iota}{\lambda r} + \left\{\epsilon^{\iota \lambda (r-\smallbold{a})} + + \epsilon^{-\iota \lambda (r-\smallbold{a})} \right\} + \sin \theta \epsilon^{\iota p t}, \\ +\lintertext{or} +2 \frac{A\iota}{\lambda r} \cos \lambda (r - \smallbold{a}) + \sin \theta \epsilon^{\iota p t}. +\end{DPgather*} + +The tangential electromotive intensity is therefore, by \artref{310}{Art.~310}, +\[ +2 A \frac{V}{\lambda r} \sin \lambda (r-\smallbold{a}) \sin \theta \epsilon^{\iota p t}, +\] +while the normal intensity is +\[ +4 \frac{AV}{\lambda^2 r^2} \cos \lambda (r-\smallbold{a}) \cos \theta \epsilon^{\iota p t}, +\] +%% -----File: 391.png---Folio 377------- +and is thus, except just at the surface of the spheres, very small +compared with the tangential electromotive intensity. The +normal intensity changes sign as we go from~$r = \smallbold{a}$ to~$r = \smallbold{b}$, so +that the electrification on the portions of the spheres opposite to +each other is of the same sign. In this case the lines of electromotive +intensity are approximately tangential; during the +vibrations they move backwards and forwards across the short +space between the spheres. The case of two parallel planes can +be regarded as the limit of that of the two spheres, and the +preceding work shows that the wave length of the vibrations +will either be a sub-multiple of twice the distance between the +planes, or else a length comparable with the dimensions of the +plane at right angles to their common normal. + +If we arrange two metal surfaces, say two silvered glass +plates, so that, as in the experiment for showing Newton's rings, +the distance between the plates is comparable with the wave +length of the luminous rays, care being taken to insulate one +plate from the other, then one of the possible modes of electrical +vibration will have a wave length comparable with that of the +luminous rays, and so might be expected to affect a photographic +plate. These vibrations would doubtless be exceedingly difficult +to excite, on account of the difficulty of getting any lines of +induction to run down between the plates before discharge took +place, but this would to some extent be counterbalanced by the +fact that the photographic method would enable us to detect +vibrations of exceedingly small intensity. + + +\Subsection{On the Decay of Electric Currents in Conducting Spheres.} +\index{Decay, xof currents and magnetic force in spheres@\subdashone of currents and magnetic force in spheres}% +\index{Electric currents, xdecay of@\subdashtwo decay of, in spheres}% +\index{Magnetic zforce, decay of in spheres@\subdashtwo of in spheres}% +\index{Rate of decay of xcurrents in spheres@\subdashtwo of currents in spheres}% +\index{Sphere, zzdecay of electric currents in@\subdashone decay of electric currents in}% + +\Article{317} The analysis we have used to determine the electrical +oscillations on spheres will also enable us to determine the rate +at which a system of currents started in the sphere will decay if +left to themselves. Let us first consider the case when, as in +the preceding investigation, the lines of magnetic force are +circles with a diameter of the sphere for their common axis. +Using the same notation as before, when there is only a single +sphere of radius~$\smallbold{a}$ in the field, we have by equation~(\eqnref{310}{107}) +\[ +\frac{\sigma \dfrac{d}{d \smallbold{a}} \{\smallbold{a} S_n(\lambda' \smallbold{a})\}} + {S_n(\lambda' \smallbold{a})} + = \frac{4\pi}{K\iota p}\, + \frac{\dfrac{d}{d \smallbold{a}} \{\smallbold{a} E_n(\lambda \smallbold{a})\}} + {E_n(\lambda \smallbold{a})}. +\Tag{113} +\] +%% -----File: 392.png---Folio 378------- + +The rate at which the system of currents decay is infinitesimal +in comparison with the rate at which a distribution of electricity +over the surface changes, so that~$\lambda \smallbold{a}$ or~$p \smallbold{a}/V$ will in this +case be exceedingly small: but when $\lambda \smallbold{a}$~is very small +\begin{gather*} +E_n(\lambda \smallbold{a}) + = (-1)^n 1\centerdot3\centerdot5 \ldots (2n-1)\centerdot + \frac{\epsilon^{±\lambda \smallbold{a}}}{\smallbold{a}^{n+1}}, \\ +\frac{d}{d \smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a}) \} + = (-1)^{n+1} 1\centerdot3\centerdot5 \ldots (2n-1)\centerdot n + \frac{\epsilon^{±\lambda \smallbold{a}}}{\smallbold{a}^{n+1}}, +\end{gather*} +so that the right-hand side of~(\eqnref{317}{113}) is equal to +\begin{DPgather*} +-\frac{4 \pi n}{K \iota p}, \\ +\lintertext{or} +-\frac{4 \pi n V^2}{\iota p}. \\ +\lintertext{Thus} +\frac{S_n(\lambda' \smallbold{a})} + {\dfrac{d}{d \smallbold{a}} \{\smallbold{a}S_n(\lambda' \smallbold{a}) \}} + = -\frac{\iota p \sigma}{4 \pi n V^2}. +\end{DPgather*} + +Now, since $V^2 = 9 × 10^{20}$ and $\sigma$~for copper is about~$1600$, the +right-hand side of this equation is excessively small, so that it +reduces to +\[ +S_n (\lambda' \smallbold{a}) = 0. +\] + +When $n = 1$, since +\[ +S_1(\lambda' \smallbold{a}) + = \frac{\cos \lambda' \smallbold{a}}{\lambda'\smallbold{a}} + - \frac{\sin \lambda' \smallbold{a}}{\lambda'^2 \smallbold{a}^2}, +\] +$\lambda'$~is given by the equation +\[ +\tan \lambda' \smallbold{a} = \lambda' \smallbold{a}; +\] +the roots of which are approximately +\[ +\lambda' \smallbold{a} = 1.4303 \pi,\quad 2.4590\pi, \quad 3.4709\pi \dots. +\] + +The roots of the equation +\[ +S_2(\lambda' \smallbold{a})= 0 +\] +are approximately +\[ +\lambda' \smallbold{a} = 1.8346 \pi, \quad 2.8950 \pi, \quad 3.9225 \pi. +\] +(See Prof.\ H.~Lamb, `Electrical Motions on Spherical Conductors,' +\index{Lamb, decay of currents in spheres@\subdashone decay of currents in spheres}% +\textit{Phil.\ Trans.}\ Pt.~II, p.~530.\ 1883.) + +The value of~$\iota p$ corresponding to any value of~$\lambda'$ is given by +the equation +\[ +\iota p = -\frac{\sigma \lambda'^2}{4 \pi \mu}. +\] + +The time factors in the expressions for the currents will be of +%% -----File: 393.png---Folio 379------- +the form $\epsilon^{-\frac{\sigma\lambda'^2}{4\pi\mu} t}$. The most persistent type of current will be +that corresponding to the smallest value of~$\lambda'$, i.e.\ +\[ +\lambda' = 1.4303 \pi / \smallbold{a}. +\] +The time required for a current of this type to sink to $1/\epsilon$~of its +original value in a copper sphere when $\sigma = 1600$ is $.000379 \smallbold{a}^2$ +seconds; for an iron sphere when $\mu = 1000$, $\sigma = 10^4$, it is $.0622 \smallbold{a}^2$ +seconds, thus the currents will be much more persistent in the +iron sphere than in the copper one. The persistence of the +vibrations is proportional to the square of the radius of the +sphere, thus for very large spheres the rate of decay will be exceedingly +slow; for example, it would take nearly $5$~million years +for currents of this type to sink to $1/\epsilon$~of their original value in +a copper sphere as large as the earth. + +Since $S_n(\lambda' \smallbold{a}) = 0$, we see from~(\eqnref{310}{105}) that $B = 0$, and therefore +that the magnetic force is zero everywhere outside the +sphere. Hence, since these currents produce no magnetic effect +outside the sphere they cannot be excited by any external +magnetic influence. The current at right angles to the radius +inside the sphere is by \artref{310}{Art.~310} +\[ +\frac{\sin \theta}{4 \pi \mu r}\, + \frac{d}{dr} \{A r S_n ( \lambda' r ) \} + \frac{dQ_n}{d\mu}\, \epsilon^{\iota p t}, +\] +or in particular, when $n = 1$ +\[ +\frac{\sin \theta}{4 \pi \mu r}\, + \frac{d}{dr} \{r S_1 ( \lambda' r) \}\, \epsilon^{\iota p t}. +\] + +Now $\dfrac{d}{dr} \{r S_1 ( \lambda' r ) \}$ vanishes when $\lambda' r = 2.744$, hence the +tangential current will vanish when +\begin{align*} +r &= \frac{2.744}{1.4303 \pi} \smallbold{a}\\ + &= .601 \smallbold{a}; +\end{align*} +thus there is a concentric spherical surface over which the +current of this type is entirely radial. + +The magnetic force vanishes at the surface and at the centre, +and as we travel along a radius attains, when $n = 1$, a maximum +when $r$~satisfies the equation +\[ +\frac{d}{dr} S_1 (\lambda' r) = 0. +\] +%% -----File: 394.png---Folio 380------- + +The smallest root of this equation is +\begin{DPgather*} +\lambda' r = .662 \pi, \\ +\lintertext{where} +r = \frac{.662}{1.4303} \smallbold{a} = .462 \smallbold{a}. +\end{DPgather*} + +\includegraphicsmid{fig112}{Fig.~112.} + +This is nearer the centre of the sphere than the place where +the tangential current vanishes. The lines of flow of the current +in a meridional section of the sphere when $\lambda' \smallbold{a} = 2.4590 \pi$ are +given in \figureref{fig112}{Fig.~112}, which is taken from the paper by Professor +Lamb already quoted (p.~378). + + +\Subsection{Rate of Decay of Currents flowing in Circles which have a +Diameter of the Sphere as a Common Axis.} +\index{Decay, xof currents and magnetic force in spheres@\subdashone of currents and magnetic force in spheres}% +\index{Electric currents, xdecay of@\subdashtwo decay of, in spheres}% +\index{Magnetic zforce, decay of in spheres@\subdashtwo of in spheres}% +\index{Rate of decay of xcurrents in spheres@\subdashtwo of currents in spheres}% +\index{Sphere, zzdecay of electric currents in@\subdashone decay of electric currents in}% + +\Article{318} In this case the lines of flow of the current are coincident +with the lines of magnetic force of the last example and \textit{vice versa}. + +Let $P$,~$Q$,~$R$ denote the components of electromotive intensity, +then in the sphere we have +\[ +\left.\begin{aligned} +P & = A \frac{y}{r}\, S_n(\lambda'r) \frac{d Q_n}{d \mu}\, \epsilon^{\iota p t},\\ +Q & = -A \frac{x}{r}\, S_n(\lambda'r) \frac{d Q_n}{d \mu}\, \epsilon^{\iota p t},\\ +R & = 0; +\end{aligned}\right\} +\Tag{114} +\] +%% -----File: 395.png---Folio 381------- +while in the dielectric surrounding the sphere, we have +\[ +\left. +\begin{aligned} +P & = B \frac{y}{r}\, E_n(\lambda r) \frac{dQ_n}{d\mu}\, \epsilon^{\iota pt},\\ +Q & = -B \frac{x}{r}\, E_n(\lambda r) \frac{dQ_n}{d\mu}\, \epsilon^{\iota pt},\\ +R & = 0. +\end{aligned} +\right\} +\Tag{115} +\] + +Since the electromotive intensity tangential to the sphere is +continuous, we have, if $\smallbold{a}$~is the radius of the sphere, +\[ +A S_n(\lambda' \smallbold{a}) = B E_n(\lambda \smallbold{a}). +\Tag{116} +\] + +If $\omega$~is the magnetic induction tangentially to a meridian, then, +since the line integral of the electromotive intensity round a +circuit is equal to the rate of diminution of the number of lines +of magnetic induction passing through it, +\[ +\frac{d\omega}{dt} + = \frac{1}{r}\, \frac{d}{dr} \left\{r \{P^2 + Q^2 \}^{\frac{1}{2}} \right\}. +\] +Since the tangential magnetic force is continuous, we have at the +surface +\[ +\left( \frac{\omega}{\mu} \right) \text{ in the sphere} + = \omega \text{ in the dielectric}. +\] +Hence +\[ +\frac{A}{\mu}\, \frac{d}{d \smallbold{a}} \{\smallbold{a} S_n(\lambda' \smallbold{a} ) \} + = B\, \frac{d}{d \smallbold{a}} \{\smallbold{a} E_n(\lambda \smallbold{a}) \}. +\Tag{117} +\] + +Eliminating $A$ and~$B$ from equations (\eqnref{318}{116})~and~(\eqnref{318}{117}), we get +\[ +\mu \frac{S_n(\lambda' \smallbold{a})} + {\dfrac{d}{d \smallbold{a}} \{\smallbold{a}S_n(\lambda' \smallbold{a}) \}} + = \frac{E_n(\lambda \smallbold{a})} + {\dfrac{d}{d \smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a})\}}. +\Tag{118} +\] + +In this case the currents and magnetic forces change so slowly +that $\lambda \smallbold{a}$ or~$p \smallbold{a}/V$ is an exceedingly small quantity, but when this +is the case we have proved \artref{317}{Art.~317}, that approximately +\[ +\frac{E_n(\lambda \smallbold{a})} + {\dfrac{d}{d \smallbold{a}} \{\smallbold{a}E_n(\lambda \smallbold{a}) \}} = -\frac{1}{n}, +\] +so that equation~(\eqnref{318}{118}) becomes +\[ +n \mu S_n(\lambda' \smallbold{a}) + + \frac{d}{d \smallbold{a}} \{\smallbold{a}S_n(\lambda' \smallbold{a}) \} = 0. +\Tag{119} +\] +But by equation~(\eqnref{309}{100}), \artref{309}{Art.~309}, +\[ +\smallbold{a} \frac{d}{d \smallbold{a}} S_n(\lambda' \smallbold{a}) + + (n+1)S_n(\lambda' \smallbold{a}) + = - \lambda' \smallbold{a} S_{n-1}(\lambda' \smallbold{a}), +\] +%% -----File: 396.png---Folio 382------- +hence (\eqnref{318}{119}) may be written +\[ +n(\mu-1)S_n(\lambda' \smallbold{a})-\lambda' \smallbold{a} S_{n-1}(\lambda' \smallbold{a}) = 0. +\Tag{120} +\] + +For non-magnetic metals for which $\mu = 1$ this reduces to +\[ +S_{n-1} (\lambda' \smallbold{a}) = 0, +\] +while for iron, for which $\mu$~is very great, the equation approximates +very closely to +\[ +S_n (\lambda' \smallbold{a}) = 0. +\] + +The smaller roots of the equation +\[ +S_n (x) = 0, +\] +when $n = 0$, $1$,~$2$, are given below; +\begin{align*} +n =& 0, \quad x = \pi, \quad 2\pi, \quad 3\pi, \dotso;\\ +n =& 1, \quad x = 1.4303\pi,\quad 2.4590\pi, \quad 3.4709\pi;\\ +n =& 2, \quad x = 1.8346\pi, \quad 2.8950\pi, \quad 3.9225\pi. +\end{align*} + +Thus for a copper sphere for which $\sigma = 1600$, the time the +currents of the most permanent type, i.e.~those corresponding to +the root $\lambda' \smallbold{a} = \pi$, take to fall to $1 / \epsilon$~of their original value is +$.000775 \smallbold{a}^2$ seconds, which for a copper sphere as large as the +earth is ten million years. These numbers are given by Prof.\ +\index{Lamb, decay of currents in spheres@\subdashone decay of currents in spheres}% +Horace Lamb in the paper on `Electrical Motion on a Spherical +Conductor,' \textit{Phil.\ Trans.}\ 1883, Part~II. + +\Article{319} As the magnetic force outside the sphere does not +vanish in this case, this distribution of currents produces an +external magnetic field, and conversely, such a distribution +could be induced by changes in such a field. We have supposed +that the currents are symmetrical about an axis, but +by superposing distributions symmetrical about different axes +we could get the most general distribution of this type of +current. The most general distribution of this type would +however be such that the lines of current flow are on concentric +spherical surfaces, it is only distributions of this kind +which can be excited in a sphere by variations in the external +magnetic field. + +We can prove without difficulty that whenever radial currents +exist in a sphere the magnetic force outside vanishes, provided +displacement currents in the dielectric are neglected. + +Let $u$,~$v$,~$w$ be the components of the current inside the sphere, +they will, omitting the time factor, be given by equations of the +%% -----File: 397.png---Folio 383------- +form +\begin{align*} +u & = S_n (\lambda'r) Y', \\ +v & = S_n (\lambda'r) Y'', \\ +w & = S_n (\lambda'r) Y''', +\end{align*} +where $Y'$, $Y''$, $Y'''$ are surface harmonics of the $n$\textsuperscript{th}~order. + +The radial current is +\[ +S_n(\lambda'r)\left(\frac{x}{r}\, Y' + \frac{y}{r}\, Y'' + \frac{z}{r}\, Y'''\right), +\] +at the surface of the sphere the radial current must vanish, i.e.\ +\[ +S_n (\lambda'\smallbold{a}) + \left\{\frac{x}{\smallbold{a}}\, Y' + \frac{y}{\smallbold{a}}\, Y'' + \frac{z}{\smallbold{a}}\, Y'''\right\}. +\] +Now the second factor is a function merely of the angular +coordinates, and if it vanished there would not be any radial +currents at any point in the sphere, hence, on the hypothesis that +there are radial currents in the sphere, we must have +\[ +S_n (\lambda'\smallbold{a}) = 0, +\] +i.e.~$u$, $v$,~$w$ all vanish on the surface of the sphere. But if there +are no currents on the surface the electromotive intensity must +vanish over the surface, and hence also the radial magnetic induction; +for the rate of change of the radial induction through a small +area on the surface of the sphere is equal to the electromotive +force round that area. But neglecting the displacement current +in the dielectric the magnetic force outside the sphere will be +derived from a potential; hence, since the radial magnetic force +vanishes over the sphere $r = \smallbold{a}$, and over $r = \infty$, and since the +space between the two is acyclic, the magnetic force must +vanish everywhere in the region between them. Thus the +presence of radial currents in the sphere requires the magnetic +force due to the currents to be entirely confined to the inside +of the sphere. + +\Article{320} Returning to the case where the system is symmetrical +about an axis, we see from equation~(\eqnref{318}{120}) that if the sphere is an +iron one, $\lambda'$~is given approximately by the equation +\[ +S_n (\lambda'\smallbold{a}) = 0. +\] + +Hence, by equation~(\eqnref{318}{114}) the electromotive intensity, and +therefore the currents, vanish over the surface of the sphere. +Since the currents also vanish at the centre, they must attain a +maximum at some intermediate position; the distance~$r$ of this +%% -----File: 398.png---Folio 384------- +position from the centre of the sphere is given by the equation +\[ +\frac{d}{dr} S_n(\lambda'r) = 0; +\] +if $n = 1$, a root of this equation is +\begin{DPalign*} +\lambda'r &= .663\pi, \\ +\lintertext{and since} +\lambda'\smallbold{a} &= 1.4303\pi, \\ +\lintertext{we have} +r &= .463\smallbold{a}. +\end{DPalign*} + + +\Subsection{Currents induced in a Uniform Sphere by the sudden +destruction of a Uniform Magnetic Field.} + +\Article{321} We shall now apply the results we have just obtained to +find the currents produced in a sphere placed in a uniform +magnetic field which is suddenly destroyed; this problem was +\index{Lamb, decay of currents in spheres@\subdashone decay of currents in spheres}% +solved by Lamb (\textit{Proc.\ Lond.\ Math.\ Soc.}~15, p.~139, 1884). The +currents will evidently flow in circles having the diameter of the +sphere which is parallel to the magnetic force for axis. + +If $H$ is the intensity of the original field at a great distance +from the sphere, the lines of force being parallel to~$z$, then inside +the sphere the magnetic induction will be parallel to~$z$, and will +be equal to $3\mu H/(\mu + 2)$. The radial component will thus be proportional +to $\cos \theta$. If $\rho$~be the normal component of magnetic +induction, $a$,~$b$,~$c$ the components parallel to the axes of $x$,~$y$,~$z$ +respectively, then +\begin{align*} +r\rho & = xa + yb + zc, \\ +\nabla^2(r\rho) + & = x\nabla^2a + y\nabla^2b + z\nabla^2c + + 2\left\{\frac{da}{dx} + \frac{db}{dy} + \frac{dc}{dz}\right\} \\ + & = -\lambda'^2r\rho, +\end{align*} +\begin{DPgather*} +\lintertext{since} +\nabla^2a = -\lambda'^2a, \\ +\lintertext{and} +\frac{da}{dx} + \frac{db}{dy} + \frac{dc}{dz} = 0. \\ +\lintertext{Hence, by~(\eqnref{308}{97}),} +r\rho = C \cos \theta S_1 (\lambda'r)\epsilon^{\iota pt} +\Tag{121} +\end{DPgather*} +where, by~(\eqnref{318}{119}), $\lambda'$~is given by the equation +\begin{DPalign*} +(\mu + 1) S_1 (\lambda'\smallbold{a}) + + \smallbold{a} \frac{dS_1 (\lambda'\smallbold{a})}{d\smallbold{a}} & = 0, \\ +\lintertext{or by~(\eqnref{318}{120})} +(\mu - 1) S_1 (\lambda'\smallbold{a}) + - \lambda'\smallbold{a} S_0 (\lambda'\smallbold{a}) = 0. +\Tag{122} +\end{DPalign*} + +When the sphere is non-magnetic $\mu = 1$, and the values of~$\lambda'$ +are given by +\[ +S_0 (\lambda'\smallbold{a}) = 0, +\] +%% -----File: 399.png---Folio 385------- +\begin{DPgather*} +\lintertext{or} +\frac{\sin \lambda' \smallbold{a}}{\lambda' \smallbold{a}} = 0, \\ +\lintertext{hence} +\lambda' = \frac{p \pi}{\smallbold{a}}, \text{ where $p$~is an integer}. +\end{DPgather*} + +When $\mu$~is very large, $\lambda'$~is given approximately by the equation +\begin{DPgather*} +S_1 (\lambda' \smallbold{a}) = 0, \\ +\lintertext{or} +\tan\lambda' \smallbold{a} = \lambda' \smallbold{a}. +\end{DPgather*} +The roots of this equation are given in \artref{317}{Art.~317}. + +We shall for the present not make any assumption as to the +magnitude of~$\mu$, but suppose that $\lambda_1, \lambda_2 \ldots$ are the values of~$\lambda'$ +which satisfy~(\eqnref{321}{122}). The value of~$\iota p$ corresponding to~$\lambda_s$ is +$-\sigma \lambda_s^2 / 4 \pi \mu$, hence by~(\eqnref{321}{121}) we have +\[ +r \rho = \cos \theta \Bigl\{ + C_1 S_1(\lambda_1 r)\, \epsilon^{-\frac{\sigma \lambda_1^2}{4 \pi \mu} t} + + C_2 S_1(\lambda_2 r)\, \epsilon^{-\frac{\sigma \lambda_2^2}{4 \pi \mu} t} + + \ldots \Bigr\}. +\] +To determine $C_1, C_2 \ldots$ we have the condition that when $t = 0$, +\[ +r \rho = 3 r \cos \theta \frac{\mu H}{\mu + 2}, +\] +hence, for all values of~$r$ between~$0$ and~$\smallbold{a}$, we have +\[ +\frac{3 \mu H r}{\mu+2} = C_1 S_1(\lambda_1 r) + C_2 S_1(\lambda_2 r) +\ldots. +\Tag{123} +\] + +Now by \artref{309}{Art.~309}, if $\lambda_p$,~$\lambda_q$ are different roots of~(\eqnref{321}{122}) +\[ +\int_0^{\smallbold{a}} r^2 S_1(\lambda_p r)S_1(\lambda_q r)\,dr = 0, +\] +while +\begin{multline*} +\int_0^{\smallbold{a}} r^2 S_1^2(\lambda_p r)\,dr + = -\frac{1}{2}\, \frac{\smallbold{a}^2}{\lambda_p^2} + \left\{S_1(\lambda_p \smallbold{a}) \frac{d}{d \smallbold{a}} + \left\{\smallbold{a}\, \frac{dS_1(\lambda_p \smallbold{a})}{d \smallbold{a}} \right\} \right.\\ + \left. - \smallbold{a} \left( \frac{d S_1(\lambda_p \smallbold{a})}{d \smallbold{a}} \right)^2 \right\}. +\Tag{124} +\end{multline*} + +But +\begin{DPgather*} +\frac{d^2}{d \smallbold{a}^2} S_1(\lambda_p \smallbold{a}) + + \frac{2}{\smallbold{a}}\, \frac{d}{d \smallbold{a}} S_1(\lambda_p \smallbold{a}) + + \left( \lambda_p^2 - \frac{2}{\smallbold{a}^2} \right) S_1(\lambda_p \smallbold{a}) = 0, \\ +\lintertext{and} +(\mu+1)S_1(\lambda_p \smallbold{a}) + + \smallbold{a}\, \frac{d}{d \smallbold{a}} S_1(\lambda_p \smallbold{a}) = 0. +\end{DPgather*} + +Substituting in~(\eqnref{321}{124}) the values of $\dfrac{d^2}{d \smallbold{a}^2} S_1 (\lambda_p \smallbold{a})$ and $\dfrac{d}{d \smallbold{a}} S_1 (\lambda_p \smallbold{a})$ +given by these equations, we get +\[ +\int_0^{\smallbold{a}} r^2 S_1^2(\lambda_p r)\,dr + = \frac{\smallbold{a}}{2\lambda_p^2}\, S_1^2(\lambda_p \smallbold{a}) + \{\lambda_p^2 \smallbold{a}^2 + (\mu+2)(\mu-1) \}. +\] +%% -----File: 400.png---Folio 386------- + +Hence, multiplying both sides of~(\eqnref{321}{123}) by $r^2 S_1 (\lambda_p r)$ and integrating +from~$0$ to~$\smallbold{a}$, we get +\begin{multline*} +\frac{3 \mu H}{\mu+2} \int_0^{\smallbold{a}} r^3 S_1(\lambda_p r)\,dr \\ + = \frac{1}{2}\, \frac{\smallbold{a}C_p}{\lambda_p^2}\, S_1^2(\lambda_p \smallbold{a}) + \{\lambda_p^2 \smallbold{a}^2 + (\mu+2)(\mu-1) \}. +\Tag{125} +\end{multline*} + +To find the integral on the left-hand side, we notice +\[ +r^3\, \frac{d^2 S_1(\lambda_p r)}{dr^2} + + 2 r^2\, \frac{d}{dr} S_1(\lambda_p r) + - 2 r S_1(\lambda_p r) + \lambda_p^2 r^3 S_1(\lambda_p r) = 0, +\] +or +\[ +\frac{d}{dr} \left\{r^3\, \frac{d}{dr} S_1(\lambda_p r) \right\} + - \frac{d}{dr} \{r^2 S_1(\lambda_p r) \} + \lambda_p^2 r^3 S_1(\lambda_p r) = 0; +\] +hence, integrating from~$0$ to~$\smallbold{a}$ +\[ +\smallbold{a}^3\, \frac{d}{d \smallbold{a}} S_1(\lambda_p \smallbold{a}) + - \smallbold{a}^2 S_1(\lambda_p \smallbold{a}) + + \lambda_p^2 \int_0^{\smallbold{a}} r^3 S_1(\lambda_p r)\,dr = 0, +\] +which by the use of~(\eqnref{321}{122}) reduces to +\[ +\int_0^{\smallbold{a}} r^3 S_1(\lambda_p r)\,dr + = \frac{\smallbold{a}^2(\mu+2)}{\lambda_p^2}\, S_1(\lambda_p \smallbold{a}). +\] + +Hence, from~(\eqnref{321}{125}) we get +\[ +C_p = \frac{6\mu H \smallbold{a}}{S_1(\lambda_p \smallbold{a})} + ÷ \{\lambda_p^2 \smallbold{a}^2 + (\mu+2)(\mu-1) \}. +\] + +\Article{322} When the sphere is non-magnetic $\mu = 1$, and therefore +\[ +C_p = \frac{6H}{\smallbold{a} S_1(\lambda_p \smallbold{a})\lambda_p^2}. +\] + +In this case $\lambda_p = \dfrac{p \pi}{\smallbold{a}}$, and therefore +\begin{align*} +\lambda_p^2 S_1(\lambda_p \smallbold{a}) + & = \lambda_p\, \frac{\cos \lambda_p \smallbold{a}}{\smallbold{a}} + - \frac{\sin \lambda_p \smallbold{a}}{\smallbold{a}^2} \\ + & = (-1)^p\, \frac{p \pi}{\smallbold{a}^2}. +\end{align*} + +Thus the normal magnetic induction +\[ += \frac{6H\cos \theta \centerdot \smallbold{a}^3}{r\pi^3} + \tsum_{p=1}^{p=\infty} (-1)^p\, \frac{1}{p^3} + \left\{\frac{p \pi}{\smallbold{a} r} \cos p \frac{\pi r}{\smallbold{a}} + - \frac{1}{r^2} \sin p \frac{\pi r}{\smallbold{a}} \right\} + \epsilon^{-\frac{p^2 \pi\sigma}{4 \smallbold{a}^2} t}. +\] +When $r = \smallbold{a}$, this equals +\[ +\frac{6H\cos \theta}{\pi^2} + \tsum_{p=1}^{p=\infty} \frac{1}{p^2}\, \epsilon^{-\frac{p^2\pi\sigma}{4 \smallbold{a}^2} t}. +\] + +This summation could be expressed as a theta function, but as +%% -----File: 401.png---Folio 387------- +the series converges very rapidly it is more convenient to leave +it in its present form. + +Since we neglect the polarization currents outside the sphere, +the magnetic force in that region is derivable from a potential, +hence we find that the radial magnetic force is +\[ +\frac{6 H \cos \theta}{\pi^2}\, \frac{\smallbold{a}^3}{r^3} + \tsum_{p=1}^{p=\infty} \frac{1}{p^2}\, \epsilon^{-\frac{p^2 \pi\sigma}{4 \smallbold{a}^2} t}. +\] + +The magnetic force at right angles to the radius is +\[ +\frac{3H \sin \theta \smallbold{a}^3}{\pi^2r^3} + \tsum_{p=1}^{p=\infty} \frac{1}{p^2}\, \epsilon^{-\frac{p^2 \pi \sigma}{4 \smallbold{a}^2} t}. +\] + +The sphere produces the same effect at an external point as a +small magnet whose moment is +\[ +\frac{3 H \smallbold{a}^3}{\pi^2} + \tsum_{p=1}^{p=\infty} \frac{1}{p^2}\, \epsilon^{-\frac{p^2 \pi \sigma}{4 \smallbold{a}^2} t}. +\] + +\Article{323} When $\mu$ is very great +\[ +C_p = \frac{6 H \smallbold{a}}{\mu S_1(\lambda_p \smallbold{a})}. +\] + +Hence, the normal magnetic force at the surface of the sphere is +\[ +\frac{6H}{\mu^2} \cos \theta \tsum \epsilon^{-\frac{\lambda p^2 \sigma}{4 \pi \mu} t}. +\] +Outside the sphere the magnetic force is the same as that due to +a magnet whose moment is +\[ +\frac{3 H \smallbold{a}^3}{\mu} \tsum \epsilon^{-\frac{\lambda p^2 \sigma}{4 \pi \mu} t}, +\] +placed at its centre. These results are given by Lamb (\textit{l.c.}). + +Thus the magnetic effects of the currents induced in a soft +iron sphere are less than those which would be produced by a +copper sphere of the same size placed in the same field. This is +due to the changes of magnetic force proceeding more slowly in +the iron sphere on account of its greater self-induction; as the +changes in magnetic force are slower, the electromotive forces, +and therefore the currents, will be smaller. + +Since $S_1 (\lambda_p \smallbold{a}) = 0$ when $\mu$~is large, the currents on the surface +of the sphere vanish, and the currents congregate towards the +middle of the sphere. +%% -----File: 402.png---Folio 388------- + +\Chapter{Chapter V.}{Experiments on Electromagnetic Waves.} +\index{Electromagnetic waves@\subdashone waves}% +\index{Hertz, zelectromagnetic waves@\subdashone electromagnetic waves|indexetseq}% +\index{Vibrator, Electrical}% +\index{Waves, electromagnetic}% +\index{Waves, electromagnetic, production of@\subdashtwo production of}% + +\Article{324} \Firstsc{Professor Hertz} has recently described a series of experiments +which show that waves of electromotive and magnetic force +are present in the dielectric medium surrounding an electrical +system which is executing very rapid electrical vibrations. A +complete account of these will be found in his book \textit{Ausbreitung +der elektrischen Kraft}, Leipzig, 1892. The vibrations which +Hertz used in his investigations are of the type of those which +occur when the inner and outer coatings of a charged Leyden +jar are put in electrical connection. The time of vibration of +such a system when the resistance of the discharging circuit +may be neglected is, as we saw in \artref{296}{Art.~296}, approximately +equal to $2 \pi \sqrt{LC}$, where $L$~is the coefficient of self-induction of +the discharging circuit for infinitely rapid vibrations and $C$~is +the capacity of the jar in electromagnetic measure. If $\smallbold{C}$~is the +capacity of the jar in electrostatic measure, then, since $C = \smallbold{C}/V^2$, +where $V$~is the ratio of the electromagnetic unit of electricity +to the electrostatic unit, the time of vibration is equal to +$2 \pi \sqrt{L \smallbold{C}} / V$. But since $V$~is equal to the velocity of propagation +of electrodynamic action through air, the distance the disturbance +will travel in the time occupied by a complete oscillation, +in other words the wave length in air of these vibrations, +will be~$2 \pi \sqrt{L \smallbold{C}}$. By using electrical systems which had very +small capacities and coefficients of self-induction Hertz succeeded +in bringing the wave length down to a few metres. + +\includegraphicsouter{fig113}{Fig.~113.} + +\Article{325} The electrical vibrator which Hertz used in his earlier +experiments (\textit{Wied.\ Ann}.~34, pp.~155, 551,~609, 1888) is represented +in \figureref{fig113}{Figure~113}. + +\smallsanscap{A}~and~\smallsanscap{B} are square zinc plates whose sides are $40$~cm.\ long, +copper wires \smallsanscap{C}~and~\smallsanscap{D} each about $30$~cm.\ long are soldered to +the plates, these wires terminate in brass balls \smallsanscap{E}~and~\smallsanscap{F}. To +%% -----File: 403.png---Folio 389------- +ensure the success of the experiments it is necessary that these +balls should be exceedingly brightly and smoothly polished, +and inasmuch as the passage of the sparks from one ball to the +other across the air space~\smallsanscap{EF} roughens the balls by tearing +particles of metal from them, it is necessary to keep repolishing +the balls at short intervals during the course of the experiment. +It is also advisable to keep the air space~\smallsanscap{EF} shaded from the +light from any sparks that +may be passing in the neighbourhood. +In order to excite +electrical vibrations in +this system the extremities +of an induction coil are connected +with \smallsanscap{C}~and~\smallsanscap{D} respectively. When the coil is in action +it produces so great a difference of potential between the balls +\smallsanscap{E}~and~\smallsanscap{F} that the electric strength of the air is overcome, sparks +pass across the air gap which thus becomes a conductor; the two +plates \smallsanscap{A}~and~\smallsanscap{B} are now connected by a conducting circuit, and +the charges on the plates oscillate backwards and forwards from +one plate to another just as in the case of the Leyden jar. + +\Article{326} As these oscillations are exceedingly rapid they will +not be excited unless the electric strength of the air gap breaks +down suddenly; if it breaks down so gradually that instead of +a spark suddenly rushing across the gap we have an almost +continuous glow or brush discharge, hardly any vibrations will +be excited. A parallel case to this is that of the vibrations of a +simple pendulum, if the bob of such a pendulum is pulled out +from the vertical by a string and the string is suddenly cut the +pendulum will oscillate; if however the string instead of breaking +suddenly gives way gradually, the bob of the pendulum will +merely sink to its position of equilibrium and no vibrations will +be excited. It is this which makes it necessary to keep the balls +\smallsanscap{E}~and~\smallsanscap{F} well polished, if they are rough there will in all likelihood +be sharp points upon them from which the electricity will +gradually escape, the constraint of the system will then give way +gradually instead of suddenly and no vibrations will be excited. + +The necessity of shielding the air gap from light coming from +other sparks is due to a similar reason. Ultra-violet light in which +these sparks abound possesses, as we saw in \artref{39}{Art.~39}, the property +of producing a gradual discharge of electricity from the negative +%% -----File: 404.png---Folio 390------- +terminal, so that unless this light is shielded off there will be a +tendency to produce a gradual and therefore non-effective discharge +instead of an abrupt and therefore effective one. + +\Article{327} The presence of the coil does not, as the following calculation +of the period of the compound system shows, affect the +time of vibration to more than an infinitesimal extent, if, as is +practically always the case, the coefficient of self-induction of the +secondary of the coil is almost infinite in comparison with that +of the vibrator. + +Let $L$~be the coefficient of self-induction of the vibrator~$AB$, +$C$~its capacity, $L'$~the coefficient of self-induction of the secondary +of the coil, $M$~the coefficient of mutual induction between this +coil and the vibrator, $x$~the quantity of electricity at any time on +either plate of the condenser, $\dot{y}$~the current in the vibrator, $\dot{z}$~that +through the secondary of the coil. +\begin{DPalign*} +\lintertext{Then we have} +\dot{x} & = \dot{y} + \dot{z} \\ +\lintertext{or} +x & = y + z. +\end{DPalign*} + +The Kinetic energy of the currents is +\[ +\tfrac{1}{2} L \dot{y}^2 + \tfrac{1}{2} L' \dot{z}^2 + M \dot{y} \dot{z}. +\] + +The potential energy is +\[ +\tfrac{1}{2}\, \frac{x^2}{C} \quad \text{or} \quad \tfrac{1}{2}\, \frac{(y+z)^2}{C}. +\] + +Hence, if we neglect the resistance of the circuit, we have by +Lagrange's equations +\begin{align*} +L y'' + M z'' + \frac{y+z}{C} &= 0, \\ +L' z'' + M y'' + \frac{y+z}{C} &= 0. +\end{align*} + +Thus if $x$~and~$y$ each vary as~$\epsilon^{\iota p t}$, we have +\begin{align*} +y \left( \frac{1}{C} - L p^2 \right) + z \left( \frac{1}{C} - M p^2 \right) &= 0, \\ +z \left( \frac{1}{C} - L'p^2 \right) + y \left( \frac{1}{C} - M p^2 \right) &= 0. +\end{align*} + +Eliminating $y$~and~$z$ we get +\begin{DPgather*} +\left( \frac{1}{C} - L p^2 \right) \left( \frac{1}{C} - L' p^2 \right) + = \left( \frac{1}{C} - M p^2 \right)^2, \\ +\lintertext{or} +p^2 = \frac{1}{CL} \left\{1 + \frac{L}{L'} - \frac{2M}{L'} \right\} \bigg/ \left( 1 - \frac{M^2}{LL'} \right). +\end{DPgather*} +%% -----File: 405.png---Folio 391------- + +But for a circuit as short as a Hertzian vibrator $L/L'$ and +$M/L'$ will be exceedingly small, so that we have as before +\[ +p^2 = \frac{1}{CL}. +\] + + +\Subsection{The Resonator.} +\index{Resonator}% + +\includegraphicsouter{fig114}{Fig.~114.} + +\Article{328} When the electrical oscillations are taking place in the +vibrator the space around it will be the seat of electric and +magnetic intensities. Hertz found that he could detect these +by means of an instrument which is called the Resonator. It +consists of a piece of copper wire bent into a circle; the ends of +the wire, which are placed very near together, are furnished with +two balls or a ball and a point, these are connected by an insulating +screw, so that the distance between them admits of very +fine adjustment. A resonator without the +screw adjustment is shown in \figureref{fig114}{Fig.~114}. +With a vibrator having the dimensions of +the one in \artref{325}{Art.~325}, Hertz used a resonator +$35$~cm.\ in radius. + +\Article{329} When the resonator was held near +the vibrator Hertz found that sparks passed +across the air space in the resonator and +that the length of the air space across which +the sparks would pass varied with the position +of the resonator. This variation was found by Hertz to +be of the following kind: + +Let the vibrator be placed so that its axis, the line~\smallsanscap{EF}, \figureref{fig113}{Fig.~113}, +is horizontal; let the horizontal line which bisects this axis at +right angles, i.e.~which passes through the middle point of the air +space~\smallsanscap{EF}, be called the base line. Then, when the resonator is +placed so that its centre is on the base line and its plane at right +angles to that line, Hertz found that sparks pass readily in the +resonator when its air space is either vertically above or +vertically below its centre, but that they cease entirely when +the resonator is turned in its own plane round its centre until +the air space is in the horizontal plane through that point. Thus +the sparks are bright when the line joining the ends of the +resonator is parallel to the axis of the vibrator and vanish when +it is at right angles to this axis. In intermediate positions of the +air gap faint sparks pass between the terminals of the resonator. +%% -----File: 406.png---Folio 392------- + +When the centre of the resonator is in the base line and its +plane at right angles to the axis of the vibrator no sparks pass, +whatever may be the position of the air space. + +When the centre of the resonator is in the base line and its +plane horizontal the sparks are strongest when the air space +is nearest to the vibrator, and as the resonator turns about its +centre in its own plane the length of the sparks diminishes as +the air space recedes from the vibrator and is a minimum when +the air gap is at its maximum distance from the axis of the +vibrator. They do not however vanish in this case for any +position of the air space. + +\Article{330} In the preceding experiments the length of the sparks +changes as the resonator rotates in its own plane about its +centre. Since rotation is not accompanied by any change in the +number of lines of magnetic force passing through the resonator +circuit, it follows that we cannot estimate the tendency to spark +across the air gap by calculating by Faraday's rule the electromotive +force round the circuit from the diminution in the +number of lines of magnetic force passing through it. + +\Article{331} The effects on the spark length are, however, easily +explained if we consider the arrangement of the Faraday tubes +radiating from the vibrator. The tendency to spark will be +proportional to the number of tubes which stretch across the +air gap; these tubes may fall directly on the air gap or they +may be collected by the wire of the resonator and thrown on the +air gap, the resonator acting as a kind of trap for Faraday tubes. + +\includegraphicsmid{fig115}{Fig.~115.} + +Let us first consider the case when the centre of the resonator +is on, and its plane at right angles to, the base line, then in the +neighbourhood of the base line the Faraday tubes are approximately +parallel to the axis of the vibrator, and their direction of +motion is parallel to the base line; thus the Faraday tubes are +parallel to the plane of the resonator and are moving at right +angles to it. When they strike against the wire of the resonator +they will split up into separate pieces as in \figureref{fig115}{Fig.~115}, which +represents a tube moving up to and across the resonator, and after +passing the cross-section of the wire of the resonator will join +again and go on as if they had not been interrupted. The +resonator will thus not catch Faraday tubes and throw them in +the air gap, and therefore the tendency to spark across the gap +will be due only to those tubes which fall directly upon it. When +%% -----File: 407.png---Folio 393------- +the air gap is parallel to the tubes, i.e.~when it is at the +highest or lowest point of the resonator, some of the tubes will +be caught and will stretch across the gap and thus tend to +produce a spark. When, however, the gap is at right angles to +the tubes, i.e.~when it is in the horizontal plane through the +centre of the resonator, the tubes will pass right through it. +None of them will stretch across the gap and there will be consequently +no tendency to spark. + +When the plane of the resonator is at right angles to the +axis of the vibrator, the tubes when they meet the wire of +the resonator are, as in the last case, travelling at right angles +to it, so that the wire of the resonator will not collect the +tubes and throw them into the air gap. In this case the air +gap is always at right angles to the tubes, which will therefore +pass right through it, and none of them will stretch across the +gap. Thus in this case there is no tendency to spark whatever +may be the position of the air space. + +Let us now consider the case when the centre of the resonator +is on the base line and its plane horizontal. In this case, as we +see by the figures \figureref{fig116}{Fig.~116}, Faraday tubes will be caught by the +wire of the resonator and thrown into the air gap wherever that +may be; thus, whatever the position of the gap, Faraday tubes +will stretch across it, and there will be a tendency to spark. +When the gap is as near as possible to the vibrator the Faraday +tubes which strike against the resonator will break and a portion +%% -----File: 408.png---Folio 394------- +of them will stretch right across the gap. When however the +gap is a considerable distance from this position the tubes which +stretch across it are due to the bending together of two portions +of the tubes broken by previously striking against the resonator, +the end of one of the portions having travelled along one side +of the resonator while the end of the other has travelled along +the other side,~(\textit{a}); these portions bend together across the gap, +(\textit{b})~and~(\textit{c}); then break up again, one long straight tube travelling +outwards, the other shorter one running into the gap, as in~(\textit{d}) +\figureref{fig116}{Fig.~116}. The portion connecting the two sides of the gap +diverges more from the shortest distance between the terminals +than in the case where the air gap is as near to the vibrator as +possible, the field in \figureref{fig116}{Fig.~116} will not therefore be so concentrated +%% -----File: 409.png---Folio 395------- +round the gap, so that there will be less tendency to spark, +though this tendency will still remain finite. + +\includegraphicsmid{fig116}{Fig.~116.} + +\Subsection{Resonance.} +\index{Resonance}% + +\Article{332} Hitherto we have said nothing as to the effect produced +by the size of the resonator on the brightness of the sparks, +this effect is however often very great, especially when we are +using condensers with fairly large capacities which can execute +several vibrations before the radiation of their energy reduces +the amplitude of the vibration to insignificance. + +The cause of this effect is that the resonator is itself an +electrical system with a definite period of vibration of its own, +hence if we use a resonator the period of whose free vibration +is equal to that of the vibrator, the efforts of the vibrator to +produce a spark in the resonator will accumulate, and we may +be able as the result of this accumulation to get a spark which +would not have been produced if the resonator had not been in +tune with the vibrator. The case is analogous to the one in +which a vibrating tuning fork sets another of the same pitch +in vibration, though it does not produce any appreciable effect +on another of slightly different pitch. + +\includegraphicsmid{fig117}{Fig.~117.} + +\Article{333} Professor Oliver Lodge (\textit{Nature}, Feb.~20, 1890, vol.~41, +\index{Lodge, xelectrical resonance@\subdashone electrical resonance}% +p.~368) has described an experiment which shows very beautifully +the effect of electric resonance. \smallsanscap{A}~and~\smallsanscap{B}, \figureref{fig117}{Fig.~117}, represent two +Leyden jars whose inner and outer coatings are connected by +a wire bent so as to include a considerable area. The circuit +connecting the coatings of one of these jars,~\smallsanscap{A}, contains an air +break. Electrical oscillations are started in this jar by connecting +the two coatings with the poles of an electrical machine. +%% -----File: 410.png---Folio 396------- +The circuit connecting the coatings of the other jar,~\smallsanscap{B}, is provided +with a sliding piece by means of which the self-induction +of the discharging circuit, and therefore the time of an electrical +oscillation of the jar, can be adjusted. The inner and outer +coatings of this jar are put almost but not quite into electrical +contact by means of a piece of tin-foil bent over the lip of the +jar. The jars are placed face to face so that the circuits connecting +their coatings are parallel to each other, and approximately +at right angles to the line joining the centre of the +circuits. When the electrical machine is in action sparks pass +across the air break in the circuit in~\smallsanscap{A}, and by moving the +slider in~\smallsanscap{B} about it is possible to find a position for it in which +sparks pass by means of the tin-foil from one coating of the jar +to the other; as soon however as the slider is moved from this +position the sparks cease. + +Resonance effects are most clearly marked in cases of this +kind, where the system which is vibrating electrically has considerable +capacity, since in such cases several complete oscillations +have to take place before the radiation of energy from +the system has greatly diminished the amplitude of the vibrations. +When the capacity is small, the energy radiates so +quickly that only a small number of vibrations have any appreciable +amplitude; there are thus only a small number of impulses +acting on the resonator, and even if the effects of these +few conspire, the resonance cannot be expected to be very +marked. In the case of the vibrating sphere we saw (\artref{312}{Art.~312}) +that for vibrations about the distribution represented by the +first harmonic the amplitude of the second vibration is only about +$1/35$~of that of the first, in such a case as this the system is +practically dead-beat, and there can be no appreciable resonance +or interference effects. + +The Hertzian vibrator is one in which, as we can see by +considering the disposition of the Faraday tubes just before +the spark passes across the air, there will be very considerable +radiation of energy. Many of the tubes stretch from one plate +of the vibrator to the other, and when the insulation of the air +space breaks down, closed Faraday tubes will break off from +these in the same way as they did from the cylinder; see \figureref{fig14}{Fig.~14}. +These closed tubes will move off from the vibrator with the +velocity of light, and will carry the energy of the vibrator away +%% -----File: 411.png---Folio 397------- +\index{Decay, xof vibrations in Hertz's vibrator@\subdashone of vibrations in Hertz's vibrator}% +\index{Rate of decay of yoscillation in xHertz's vibrator@\subdashtwo of oscillation in Hertz's vibrator}% +\index{Vibrations d@Vibrations, decay of, in Hertz's vibrator}% +with them. In consequence of this radiation the decay of the +oscillations in the vibrator will be very rapid, indeed we should +expect the rate of decay to be comparable with its value in the +case of the vibrations of electricity over the surfaces of spheres +or cylinders, where the Faraday tubes which originally stretched +from one part to another of the electrified conductor emit closed +tubes which radiate into space in the same way as the similar +tubes in the case of the Hertzian vibrator: we have seen, however, +that for spheres and cylinders the decay of vibration is so +rapid that they may almost be regarded as dead-beat. We +should expect a somewhat similar result for the oscillations of +the Hertzian vibrator. + +\Article{334} On the other hand, the disposition of the Faraday tubes +shows us that the electrical vibrations of the resonator will +be much more persistent. In this case +the Faraday tubes will stretch from +side to side across the inside of the +resonator as in \figureref{fig118}{Fig.~118}, and these tubes +will oscillate backwards and forwards +inside the resonator; they will have +no tendency to form closed +\includegraphicsouter{fig118}{Fig.~118.} +curves, and +consequently there will be little or no +radiation of energy. In this case the +decay of the vibrations will be chiefly +due to the resistance of the resonator, +as in the corresponding cases of oscillations +in the electrical distribution over spherical or cylindrical +cavities in a mass of metal, which are discussed in Arts.\ \artref{315}{315}~and~\artref{300}{300}. + +\Article{335} The rate at which the vibrations die away for a +vibrator and resonator of dimensions not very different from +those used by Hertz has been measured by Bjerknes (\textit{Wied.\ Ann.}~44, +\index{Bjerknes, decay of vibrations}% +p.~74, 1891), who found that in the vibrator the oscillations +died away to $1/\epsilon$~of their original value after a time~$T/.26$, where +$T$~is the time of oscillation of the vibrator. This rate of decay, +though not so rapid as for spheres and cylinders, is still very +rapid, as the amplitude of the tenth swing is about $1/14$~of +that of the first. The amplitudes of the successive vibrations are +represented graphically in \figureref{fig119}{Fig.~119}, which is taken from Bjerknes' +paper. +%% -----File: 412.png---Folio 398------- + +\includegraphicsmid{fig119}{Fig.~119.} + +The time taken by the vibrations in the resonator to fade +away to $1/\epsilon$~of their original value was found by Bjerknes to be +$T'/.002$ or~$500 T'$, where $T'$~is the time of the electrical oscillation +of the resonator; thus the resonator will make more than +$1000$ complete oscillations before the amplitude of the vibration +falls to $1/10$~of its original value. The very slow rate of decay +of these oscillations confirms the conclusion we arrived at from +the consideration of the Faraday tubes, that there was little +or no radiation of energy in this case. The rate of decay of the +vibrations in the resonator compares favourably with that of +pendulums or tuning-forks, and is in striking contrast to the +very rapid fading away of the oscillations of the vibrator. +These experiments show that, as the theory led us to expect, we +must regard the vibrator as a system having a remarkably large +logarithmic decrement, the resonator as one having a remarkably +small one. + + +\Subsection{Reflection of Electromagnetic Waves from a Metal Plate.} +\index{Electromagnetic waves, reflection of@\subdashtwo reflection of}% +\index{Waves, electromagnetic, reflection of@\subdashtwo reflection of}% +\index{Reflection of electromagnetic waves}% + +\Article{336} We shall now proceed to describe the experiments by +which Hertz succeeded in demonstrating, by means of the +vibrator and resonator described in Arts.\ \artref{325}{325}~and~\artref{328}{328}, the +existence in the dielectric of waves of electromotive intensity +and magnetic force (\textit{Wied.\ Ann.}~34, p.~610, 1888). + +The experiments were made in a large room about $15$~metres +long, $14$~broad, and $6$~high. The vibrator was placed $2$~m.\ from +one of the main walls, in such a position that its axis was +vertical and its base line at right angles to the wall. At all +points along the base line the electromotive intensity is vertical, +being parallel to the axis of the vibrator. At the further end +of the room a piece of sheet zinc $4$~metres by~$2$ was placed +%% -----File: 413.png---Folio 399------- +vertically against the wall, its plane being thus at right angles +to the base line of the vibrator. The zinc plate was connected +to earth by means of the gas and water pipes. In one set of +experiments the centre of the resonator was on and its plane at +right angles to the base line. When it is in this position the +Faraday tubes from the vibrator strike the wire of the resonator +at right angles; the resonator therefore does not catch the +tubes and throw them into the air gap, and the spark will be +due to the tubes which fall directly upon the air gap. Thus, as +might be expected, the sparks vanish when the gap is at the +highest or lowest point of the resonator, when the tubes are at +right angles to the direction in which the sparks would pass, and +the sparks are brightest when the air gap is in the horizontal +plane through the base line, when the incident tubes are parallel +to the sparks. + +\Article{337} Let the air gap be kept in this plane, and the resonator +moved about, its centre remaining on the base line, and its plane +at right angles to it. When the resonator is quite close to the +zinc plate no sparks pass across the air space; feeble sparks, +however, begin to pass as soon as the resonator is moved a short +distance away from the plate. They increase rapidly in brightness +as the resonator is moved away from the plate until the distance +between the two is about $1.8$~m., when the brightness of the +sparks is a maximum. When the distance is still further increased +the brightness of the sparks diminishes, and vanishes +again at a distance of about $4$~metres from the zinc plate, after +which it begins to increase, and attains another maximum, +and so on. Thus the sparks exhibit a remarkable periodic +character, similar to that which occurs when stationary vibrations +are produced by the reflection of wave motion from a +surface at right angles to the direction of propagation of the +motion. + +\Article{338} Let the resonator now be placed so that its plane is the +vertical one through the base line, the air gap being at the +highest or lowest point; in this position the Faraday tubes +which fall directly on the air gap are at right angles to the +sparks, so that the latter are due entirely to the Faraday tubes +collected by the resonator and thrown into the air gap. + +When the resonator is in this position and close to the reflecting +plate sparks pass freely. As the resonator recedes from the +%% -----File: 414.png---Folio 400------- +plate the sparks diminish and vanish when its distance from +the plate is about $1.8$~metres, the place at which they were a +maximum when the resonator was at right angles to the base +line; after the resonator passes through this position the sparks +increase and attain a maximum $4$~metres from the plate, the +place where, with the other position of the resonator, they were +a minimum; when the resonator is removed still further from +the plate the sparks diminish, then vanish, and so on. The +sparks in this case show a periodicity of the same wave length +as when the resonator was in its former position, the places of +minimum intensity for the sparks in one position of the +resonator corresponding to those of maximum intensity in the +other. + +\Article{339} If the zinc reflecting plate is mounted on a movable +frame work so that it can be placed behind the resonator and +removed at will, its effect can be very clearly shown by the +following experiments:--- + +Hold the resonator in the position it had in the last experiment +at some distance from the vibrator and observe the sparks, +the zinc plate being placed on one side out of action: then place +the reflector immediately behind the resonator, the sparks will +increase in brightness; now push the reflector back, and at +about $2$~metres from the resonator the sparks will stop. On +pushing it still further back the sparks will increase again, and +when the reflector is about $4$~metres away they will be a little +brighter than when it was absent altogether. + +\Article{340} Hertz only used one size of resonator, which was +selected so as to be in tune with the vibrator. Sarasin and +\index{De la Rive and Sarasin, experiments on electromagnetic waves}% +\index{Sarasin and De la Rive, reflection of electromagnetic waves}% +\index{Waves, electromagnetic, Sarasin's and de la Rive's experiments on@\subdashtwo Sarasin's and de la Rive's experiments on}% +De~la~Rive (\textit{Comptes Rendus}, March~31, 1891), who repeated this +experiment with vibrators and resonators of various sizes, found +however that the apparent wave length of the vibrations, that +is twice the distance between two adjacent places where the +sparks vanish, depended entirely upon the size of the resonator, +and not at all upon that of the vibrator. The following table +contains the results of their experiments; $\lambda$~denotes the wave +length, a `loop' means a place where the sparks are at their +maximum brightness when the resonator is held in the first +position, a `node' a place where the brightness is a minimum. +The line beginning `$1/4\;\lambda$~wire' relates to another series of experiments +which we shall consider subsequently. It is included here +%% -----File: 415.png---Folio 401------- +to avoid the repetition of the table. The distances of the loops +and nodes are measured in metres from the reflecting surface. +\begin{center} +\tabletextsize +\setlength\tabcolsep{4pt} +\begin{tabular}{|c|c|c|c|c|c|} +\hline +\settowidth{\TmpLen}{resonator circle ($D$).}% +\parbox[c]{\TmpLen}{\centering% + Diameter of\\ resonator circle ($D$).} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering\tablespaceup% + $1$ metre,\\ stout wire\\$1$ cm.\ in\\ diameter.\tablespacedown} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.75$ m.\\stout wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.50$ m.\\stout wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.35$ m.\\stout wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.35$ m.\\ fine wire\\ $2$~mm.\ in \\ diameter.} \\ +\hline +1st Loop\mdotfill & $2.11$ & $1.60$ & $1.11$ & $\Z.76$ & $\Z.75$\\ +\hline +1st Node\mdotfill & $4.14$ & $3.01$ & & $1.49$ & $1.51$\\ +\hline +2nd Loop\mdotfill & & & & $2.30$ & $2.37$\\ +\hline +2nd Node\mdotfill & & & & $3.04$ & $3.10$\\ +\hline +3rd Loop\mdotfill & & & & & \\ +\hline +3rd Node\mdotfill & & & & & \\ +\hline +\tablespaceup$\frac{1}{4} \lambda$ air\mdotfill + & $2.03$ & $1.41$ & $1.11$ & $\Z.76$ & $\Z.80$ \\ +\tablespaceup$\frac{1}{4} \lambda$ wire\mdotfill + & $1.92$ & $1.48$ & $\Z.98$ & $\Z.73$ & \\ +\tablespaceup$2D$\mdotfill & $2.00$ & $1.50$ & $1.00$ & $\Z.70$ & $\Z.70$ \\ +\hline +\hline +\settowidth{\TmpLen}{resonator circle ($D$).}% +\parbox[c]{\TmpLen}{\centering\tablespaceup% + Diameter of\\ resonator circle ($D$).\tablespacedown} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.25$~m.\\ stout wire} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.25$ m.\\ fine wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.20$~m.\\ stout wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.20$ m.\\ fine wire.} & +\settowidth{\TmpLen}{stout wire.}% +\parbox[c]{\TmpLen}{\centering% + $.10$ m.\\ stout wire.} \\ +\hline +1st Loop\mdotfill & $\Z.46$ & $\Z.54$ & $\Z.39$ & $\Z.42$ & $\Z.21$\\ +\hline +1st Node\mdotfill & $\Z.94$ & $1.17$ & $\Z.80$ & $\Z.93$ & $\Z.41$\\ +\hline +2nd Loop\mdotfill & $1.63$ & $1.89$ & $1.24$ & $1.55$ & $\Z.59$\\ +\hline +2nd Node\mdotfill & $2.15$ & $2.40$ & $1.69$ & $2.05$ & $.79$ \\ +\hline +3rd Loop\mdotfill & $2.71$ & & & $2.46$ & $\Z.96$\\ +\hline +3rd Node\mdotfill & $3.14$ & & & & \\ +\hline +\tablespaceup$\frac{1}{4} \lambda$ air\mdotfill + & & $\Z.60$ & $\Z.43$ & $\Z.51$ & $\Z.19$\\ +\tablespaceup$\frac{1}{4} \lambda$ wire\mdotfill + & & $\Z.56$ & & $\Z.45$ & \\ +\tablespaceup$2D$\mdotfill & & $\Z.50$ & $\Z.40$ & $\Z.40$ & $\Z.20$\\ +\hline +\end{tabular} +\end{center} + +The most natural interpretation of Hertz's original experiment +was to suppose that the vibrator emitted waves of electromotive +intensity which, by interference with the waves reflected from the +zinc plate, produced standing waves in the region between the +vibrator and the reflector, the places in these waves where the +electromotive intensity was a maximum being where the sparks +were brightest when the resonator was held in the first position. +%% -----File: 416.png---Folio 402------- + +Sarasin's and De~la~Rive's discovery of the influence of the +size of the resonator on the positions of maximum sparking, and +the independence of these positions on the period of the vibrator, +compels us, if we retain this explanation, to suppose that any +electrical vibrator gives out vibrations of all periods, emitting as +it were a continuous electric spectrum. + +\Article{340*} This hypothesis appears most improbable, and a more +satisfactory explanation seems to be afforded by means of the +fact that the oscillations of the vibrator die away with great +rapidity, while those of the resonator are extremely persistent. +Let us consider what would happen in the extreme case when +the oscillations in the vibrator are absolutely dead-beat. Here +an electric impulse starts from the vibrator; on its way to the +reflector it strikes against the resonator and sets it in electrical +vibration; the impulse then travels up to the plate and is +reflected, the electromotive intensity in the impulse being reversed +by reflection; after reflection the impulse again strikes +the resonator, which has maintained the vibrations started by +the first impact. If when the reflected impulse reaches the resonator +the phase of the vibrations of the latter is opposite to the +phase when the impulse passed it on its way to the reflector, the +electromotive intensity across the air gap due to the direct and +reflected impulses will conspire, so that if the resonator is held +in the first position a bright spark will be produced. Now the +reflected impulse will strike the resonator the second time when +its vibration is in the opposite phase to that which it had just +after the first impact if the time which has elapsed between the +two impacts is equal to half the time of a complete electrical +oscillation of the resonator. The impulse travels at the rate at +which electromagnetic action is propagated; hence, if the distance +travelled by the impulse between the two impacts is equal +to half the wave length of the free electrical vibrations of the +resonator, that is, if the distance of the resonator from the reflecting +plane is equal to one quarter of the wave length of this +vibration, the direct and reflected waves will conspire. If the +path travelled by the impulse between the two impacts is equal +to a wave length, the electromotive intensity at the air gap +due to the incident impulse will be equal and opposite to +that due to the reflected one; so that there will in this case, +in which the resonator is half a wave length away from the +%% -----File: 417.png---Folio 403------- +reflector, be no tendency to spark when the resonator is held +in this position. + +Thus we see that on this view the distances from the reflecting +plane of the places where the sparks have their maximum +brightness will depend entirely upon the size of the resonator, +and not upon that of the vibrator. This, as we have seen, was +found by Sarasin and De~la~Rive to be a very marked feature in +their experiments. We have assumed in this explanation that +the vibrator does not vibrate. Bjerknes' experiments (l.c.)\ show +that though the vibrations die away very rapidly they are not +absolutely dead-beat. The existence of a small number of oscillations +in the vibrator will cause the effects to be more vivid with +a resonator in tune with it than with any other resonator. Since, +however, the rate of decay of the vibrator is infinitely rapid +compared with that of the resonator, the positions in which the +sparks are brightest will depend much more upon the time of +oscillation of the resonator than upon that of the vibrator. + +\Article{341} We have still to explain why the places at which the +sparks were a maximum when the resonator was in the first +position (i.e.~with its plane at right angles to the base line) were the +places where the sparks vanished when the vibrator was in the +second position (i.e.~with its plane containing the base line and +the axis of the vibrator). When the resonator is in the first +position the sparks are wholly due to the Faraday tubes which +fall directly upon the air gap, hence the sparks will be a +maximum when the state of the resonator corresponds to the +incidence upon it of Faraday tubes from the vibrator of the +same kind as those which reach it after reflection from the zinc +plate. When the resonator is in the second position, having +the line joining the terminals of the air gap at right angles to +the axis of the vibrator, the sparks are due entirely to the +Faraday tubes collected by the resonator and thrown into the +air gap, and there would be no tendency to spark in the case +just mentioned. For when two Faraday tubes of the same +kind moving in opposite directions strike against opposite +sides of the resonator, the tubes thrown into the air gap are +of opposite signs, and thus do not produce any tendency to +spark. When the resonator is in this position the maximum +sparks will be produced when the positive tubes strike against +one side of the resonator, the negative tubes against the other; +%% -----File: 418.png---Folio 404------- +the tubes thrown into the air gap will then be of the same sign +and their efforts to produce a spark will conspire: if however +the resonator had been held in the first position the positive +tubes would have counterbalanced the negative ones, and there +would not have been any tendency to spark. + +\Article{342} There is one result of Sarasin's and De~la~Rive's +experiments which it is difficult to reconcile with theory. As +will be seen from the table they found that the wave length of +the vibration was equal to $8$~times the diameter of the resonator; +theory would lead us to expect that the circumference of the +resonator should be half a wave length, since, until the sparks +pass, the current in the resonator will vanish at each end of the +resonator, as we may neglect the capacity of the knobs. Thus +there will be a node at each end of the resonator, and we should +expect the wave length to be $2 \pi$~times the diameter instead of +$8$~times, as found by Sarasin and De~la~Rive. + + +\Subsection{Parabolic Mirrors.} +\index{Mirrors, parabolic, for electromagnetic waves}% +\index{Parabolic mirrors for electromagnetic waves}% + +\Article{343} If the vibrator is placed in the focal line of a parabolic +cylinder, and if it is of such a kind that the Faraday tubes it +emits are parallel to the focal line, then the waves emitted by +the vibrator will, if the laws of reflection of these waves are the +same as for light, after reflection from the cylinder emerge as +a parallel beam and will therefore not diminish in intensity as +they recede from the mirror; if such a beam falls on another +parabolic mirror whose axis (i.e.~the axis of its cross-section) is +parallel to the beam, it will be brought to a focus on the focal +line of the second mirror. For these reasons the use of parabolic +mirrors facilitates very much many experiments on electromagnetic +waves. + +\includegraphicsmid{fig120}{Fig.~120.} + +The parabolic mirrors used by Hertz were made of sheet zinc, +and their focal length was about $12.5$~cm. The vibrator which +was placed in the focal line of one of the mirrors consisted of two +equal brass cylinders placed so that their axes were coincident +with each other and with the focal line; the length of each of +the cylinders was $12$~cm.\ and the diameter $3$~cm., their sparking +ends being rounded and well polished. The resonator, which was +placed in the focal line of an equal parabolic mirror, consisted of +two pieces of wire, each had a straight piece $50$~cm.\ long, and was +then bent round at right angles so as to pass through the back +%% -----File: 419.png---Folio 405------- +of the mirror, the length of this bent piece being $15$~cm. The +ends which came through the mirror were connected with a +spark micrometer and the sparks were observed from behind the +mirror. The mirrors are represented in \figureref{fig120}{Fig.~120}. + + +\Subsection{Electric Screening.} +\index{Electric screening@\subdashone screening}% +\index{Screening, electric}% + +\Article{344} If the mirrors are placed about $6$~or $7$~feet apart in such +a way that they face each other and have their axes coincident, +then when the vibrator is in action vigorous sparks will be +observed in the resonator. If a screen of sheet zinc about $2$~m.\ +high by $1$~broad is placed between the mirrors the sparks in the +resonator will immediately cease; they will also cease if a paste-board +screen covered with gold-leaf or tin-foil is placed between +the mirrors; the interposition of a non-conductor, such as a +wooden door, will not however produce any effect. We thus see +that a very thin metallic plate acts as a perfect screen and is +absolutely opaque to electrical oscillations, while on the other +hand a non-conductor allows these radiations to pass through +quite freely. The human body is a sufficiently good conductor +to produce considerable screening when interposed between the +vibrator and resonator. + +\Article{345} If wire be wound round a large rectangular framework +in such a way that the turns of wire are parallel to one pair of +sides of the frame, and if this is interposed between the mirrors, +it will stop the sparks when the wires are vertical and thus +parallel to the Faraday tubes emitted from the resonator; the +sparks however will begin again if the framework is turned +through a right angle so that the wires are at right angles to the +Faraday tubes. +%% -----File: 420.png---Folio 406------- + +\Subsection{Reflection of Electric Waves.} +\index{Electromagnetic waves, reflection of from grating@\subdashtwo reflection of from grating}% +\index{Grating, reflection of electromagnetic waves from}% +\index{Reflection of electromagnetic waves from a grating@\subdashtwo electromagnetic waves from a grating}% +\index{Waves, electromagnetic, reflection of from grating@\subdashtwo reflection of from grating}% + +\Article{346} To show the reflection of these waves place the mirrors +side by side, so that their openings look in the same directions +and their axes converge at a point distant about $3$~m.\ from the +mirrors. No sparks can be detected at the resonator when the +vibrator is in action. If, however, we place at the point of +intersection of the axes of the mirrors a metal plate about $2$~m.\ +square at right angles to the line which bisects the angle between +the axes of the mirrors, sparks will appear at the resonator; +they will however disappear if the metal plate is twisted through +about~$15°$ on either side. This experiment shows that these waves +are reflected and that, approximately at any rate, the angle of +incidence is equal to the angle of reflection. + +If the framework wound with wire is substituted for the +metal plate sparks will appear when the wires are vertical and +so parallel to the Faraday tubes, while the sparks will disappear +if the framework is turned round until the wires are horizontal. +Thus this framework reflects but does not transmit Faraday +tubes parallel to the wires, while it transmits but does not +reflect Faraday tubes at right angles to them. It behaves in +fact towards the electrical waves very much as a plate of tourmaline +does to light waves. + +\Subsection{Refraction of Electric Waves.} +\index{Electromagnetic waves, refraction of@\subdashtwo refraction of}% +\index{Refraction of electromagnetic waves}% +\index{Waves, electromagnetic, refraction of from grating@\subdashtwo refraction of from grating}% + +\Article{347} To show the refraction of these waves Hertz used a large +prism made of pitch; it was about $1.5$~metres in height, had a +refracting angle of~$30°$, and a slant side of $1.2$~metres. When +the electric waves from the vibrator passed through this prism +the sparks in the resonator were not excited when the axes of +the two mirrors were parallel, but they were produced when +the axis of the mirror of the resonator made a suitable angle +with that of the vibrator. When the system was adjusted for +minimum deviation the sparks were most vigorous in the resonator +when the axis of its mirror made an angle of~$22°$ with +that of the vibrator. This shows that the refractive index for +pitch is~$1.69$ for these long electrical waves. + + +\Subsection{Angle of Polarization.} +\index{Electromagnetic waves, xangle of polarization of@\subdashtwo angle of polarization of}% +\index{Polarization angle of for electromagnetic waves,@\subdashone angle of for electromagnetic waves}% + +\Article{348} When light polarized in a plane at right angles to that +of incidence falls upon a plate of refracting substance and the +%% -----File: 421.png---Folio 407------- +normal to the wave front makes with the normal to the surface +an angle $\tan^{-1} \mu$ where $\mu$~is the refractive index, all the light is +refracted and none reflected. + +Trouton (\textit{Nature}, February\DPtypo{,}{} 21, 1889) has observed a similar +\index{Trouton, angle of polarization for electromagnetic waves}% +effect with these electrical vibrations. From a wall $3$~feet thick +reflections were obtained when the vibrator, and therefore the +Faraday tubes, were perpendicular to the plane of incidence, +while there was no reflection when the vibrator was turned +through a right angle so that the Faraday tubes were in +the plane of incidence. This experiment proves that in the +Electromagnetic Theory of Light the Faraday tubes and the +electric polarization are at right angles to the plane of polarization. + +\index{Electromagnetic waves, xtheory of reflection of from insulators@\subdashtwo theory of reflection of from insulators}% +\index{Waves, electromagnetic, theory of reflection of from insulators@\subdashtwo theory of reflection of from insulators}% +Before proceeding to describe some other interesting experiments +of Mr.~Trouton's on the reflection of these waves from +slabs of dielectrics, we shall investigate the theory of these +phenomena on Maxwell's Theory. + +\Article{349} Let us suppose that plane waves are incident on a plate +of dielectric bounded by parallel planes, let the plane of the +paper be taken as that of incidence and of~$xy$, let the plate be +bounded by the parallel planes $x = 0$, $x = -h$, the wave being incident +on the plane $x = 0$. We shall first take the case when the +polarization and Faraday tubes are at right angles to the plane +of incidence. Let the electromotive intensity in the incident +wave be represented by the real part of +\[ +A\, \epsilon^{\iota(ax+by+pt)}; +\] +if $i$~is the angle of incidence, $\lambda$~the wave length of the vibrations, +$V$~their velocity of propagation, +\[ +a = \frac{2 \pi}{\lambda} \cos i,\quad +b = \frac{2 \pi}{\lambda} \sin i,\quad +p = \frac{2 \pi}{\lambda} V. +\] + +Let the intensity in the reflected wave be represented by the +real part of +\[ +A'\,\epsilon^{\iota(-ax+by+pt)}. +\] + +The coefficient of~$y$ in the exponential in the reflected wave +must be the same as that in the incident wave, otherwise the +ratio of the reflected to the incident light would depend upon +the portion of the plate on which the light fell. The coefficient +of~$x$ in the expression for the reflected wave can only differ in +sign from that in the incident wave: for if $E$~is the electromotive +%% -----File: 422.png---Folio 408------- +intensity in either the incident or reflected wave, we +have +\[ +\frac{d^{2} E}{dx^{2}} + \frac{d^{2} E}{dy^{2}} = \frac{1}{V^{2}}\, \frac{d^{2} E}{dt^{2}}, +\] +hence the sum of the squares of the coefficients of $x$~and~$y$ must +be the same for the incident and reflected waves, and since the +\DPtypo{cofficients}{coefficients} of~$y$ are the same the coefficients of~$x$ can only differ in +sign. If $E_1$,~$E_2$,~$E_3$ are the total electromotive intensities at +right angles to the plane of incidence in the air, in the plate, and +in the air on the further side of the plate, we may put +\begin{align*} +E_1 &= A\, \epsilon^{\iota(ax+by+pt)} + A'\, \epsilon^{\iota(-ax+by+pt)},\\ +E_2 &= B\, \epsilon^{\iota(a'x+by+pt)} + B'\, \epsilon^{\iota(-a'x+by+pt)},\\ +E_3 &= C\, \epsilon^{\iota(ax+by+pt)}, +\end{align*} +\begin{DPgather*} +\lintertext{where} +a'^{2} + b^{2} = \frac{p^{2}}{V'^{2}}, +\end{DPgather*} +$V'$ being the velocity with which electromagnetic action travels +through the plate. The real parts of the preceding expressions +only are to be taken. + +Since the electromotive intensity is continuous when $x = 0$ +and when $x = -h$, we have +\begin{align*} +A + A' &= B + B', \Tag{1}\\ +C\, \epsilon^{-\iota a h} + &= B\, \epsilon^{-\iota a'h} + B'\, \epsilon^{\iota a' h}. \Tag{2} +\end{align*} + +Since there is no accumulation of Faraday tubes on the surface +of the plate the normal flow of these tubes in the air must equal +that in the dielectric. Let $K$ be the specific inductive capacity of +the plate, that of air being taken as unity, then in the air just +above the plate the normal flow of tubes towards the plate is +\[ +\frac{1}{4 \pi} (A-A')V \cos{i} \epsilon^{\iota(by+pt)}, +\] +the normal flow of tubes in the plate away from the surface +$x = 0$ is +\[ +\frac{K}{4 \pi} (B-B')V' \cos{r} \epsilon^{\iota(by+pt)}, +\] +where $r$~is the angle of refraction. Since these must be equal we +have +\[ +(A - A')V \cos i = K(B - B')V' \cos r. +\Tag{3} +\] +The corresponding condition when $x = -h$ gives +\[ +C\, \epsilon^{-\iota ah}\, V \cos i + = K \left(B\, \epsilon^{-\iota a'h} + - B'\, \epsilon^{\iota a'h}\right)\, V' \cos r. +\Tag{4} +\] +%% -----File: 423.png---Folio 409------- + +Equations (\eqnref{349}{3})~and~(\eqnref{349}{4}) are equivalent to the condition that the +tangential magnetic force is continuous. + +Solving equations (\eqnref{349}{1}),~(\eqnref{349}{2}),~(\eqnref{349}{3}),~(\eqnref{349}{4}), we get +\[ +\left. +\begin{aligned} +A' &= -A(K^{2} V'^{2} \cos^{2}r - V^{2} \cos^{2}i)(\epsilon^{\iota a'h} - \epsilon^{-\iota a'h}) ÷ \Delta,\\ +B &= 2AV \cos i (KV' \cos r + V \cos i)\epsilon^{\iota a'h} ÷ \Delta,\\ +B' &= 2AV \cos i (KV' \cos r - V \cos i)\epsilon^{-\iota ah} ÷ \Delta,\\ +C &= 4AKVV' \cos i \cos r \epsilon^{\iota ah} ÷ \Delta, +\end{aligned} +\right\} +\Tag{5} +\] +where +\begin{multline*} +\Delta = (K^{2}V'^{2} \cos^{2}r + V^{2} cos^{2}i) + (\epsilon^{\iota a'h} - \epsilon^{-\iota a'h})\\ + + 2KVV' \cos i \cos r (\epsilon^{\iota a'h} + \epsilon^{-\iota a'h}). +\end{multline*} + +Thus, corresponding to the incident wave of electromotive +intensity +\[ +\cos \frac{2 \pi}{\lambda} (x \cos i + y \sin i + Vt), +\] +there will be a reflected wave represented by +\begin{multline*} +-(K^{2} V'^{2} \cos^{2}r - V^{2} \cos^{2}i) + \sin \left( \frac{2 \pi}{\lambda'} h \cos r \right) × \\ + \cos \left[ \frac{2 \pi}{\lambda} (-x \cos i + y \sin i + Vt) + + \frac{\pi}{2} - \vartheta \right] ÷ D, +\end{multline*} +where $\lambda'$ is the wave length in the plate. +\begin{multline*} +D^{2} = (K^{2} V'^{2} \cos^{2}r + V^{2} \cos^{2}i)^2 + \sin^{2} \left( \frac{2 \pi}{\lambda'} h \cos r \right) \\ + + 4K^{2} V'^{2} V^{2} \cos^{2}i \cos^{2}r + \cos^{2} \left( \frac{2 \pi}{\lambda'} h \cos r \right), +\end{multline*} +\begin{DPgather*} +\lintertext{and} +\tan \vartheta = \frac{K^{2} V'^{2} \cos^{2}r + V^{2} \cos^{2}i}{2KVV' \cos i \cos r} + \tan \left( \frac{2 \pi}{\lambda'} h \cos r \right). +\end{DPgather*} +The waves in the plate will be +\begin{multline*} +V \cos i(KV' \cos r + V \cos i) × \\ + \cos \left[ \frac{2 \pi}{\lambda'} \bigl((x + h) \cos r + y \sin r + V't\bigr) - \vartheta \right] ÷ D, +\end{multline*} +and +\begin{multline*} +V \cos i(KV' \cos r - V \cos i) × \\ + \cos \left[ \frac{2 \pi}{\lambda'} \bigl(-(x + h) \cos r + y \sin r + V't\bigr) - \vartheta \right] ÷ D; +\end{multline*} +while the wave emerging from the plate will be +\[ +2KVV' \cos i \cos r \cos \left[ \frac{2 \pi}{\lambda} \bigl((x + h) \cos i + y \sin i + Vt\bigr) - \vartheta \right] ÷ D. +\] +%% -----File: 424.png---Folio 410------- + +Thus we see that when $2\pi h \cos r/\lambda'$ is very small the reflected +wave vanishes; this is what we should have expected, as it must +require a slab whose thickness is at least comparable with the +wave length in the slab to produce any appreciable reflection. +When the reflecting surface is too thin we get a result analogous +to the blackness of very thin soap films. Trouton has +verified that there is no reflection of the electrical waves from +window-glass unless this is covered with moisture. + +The expression for the amplitude for the reflected wave shows +that this will vanish not merely when $2\pi h \cos r/\lambda'$ vanishes but +also when this is a multiple of~$\pi$. Trouton used as the dielectric +plate a wall built of paraffin bricks, a method which enabled him +to try the effect of altering the thickness of the plate; he found +that after reaching the thickness at which the reflected wave +became sensible, by making the wall still thicker the reflected +wave could be diminished so that its effects were insensible. +The case is exactly analogous to that of Newton's rings, where +we have darkness whenever $2h \cos r$~is a multiple of a wave +length of the light in the plate. + +There will be a critical angle in this case if the solution of the +equation +\[ +K^{2} V'^{2} \cos^{2} r - V^{2} \cos^{2} i = 0 +\Tag{6} +\] +is real. If the plate is non-magnetic the magnetic permeability +is unity, and we have +\[ +K = \frac{V^{2}}{V'^{2}} = \frac{\sin^{2}i}{\sin^{2}r}, +\] +so equation~(\eqnref{349}{6}) becomes +\[ +\cot^{2} r - \cot^{2} i = 0, +\] +an equation which cannot be satisfied, so that there is no critical +angle in this case. This result would not however be true if it +were possible to find a magnetic substance which was transparent +to electric waves; for if $\mu'$~is the magnetic permeability +of the substance, we have +\[ +\mu' K = \frac{V^{2}}{V'^{2}}, +\] +so that equation~(\eqnref{349}{6}) becomes +\begin{DPalign*} +\frac{\cot^{2} r}{\mu'^{2}} & = \cot^{2} i, \\ +\lintertext{or} +\frac{\cot r}{\mu'} & = \cot i. +\end{DPalign*} +\begin{DPgather*} +\lintertext{\indent Since} +\sqrt{\mu'K} \sin r = \sin i +\end{DPgather*} +%% -----File: 425.png---Folio 411------- +we may transform this equation to +\[ +\sin^{2}i + = \frac{\mu'^{2} - \mu'K}{\mu'^{2}-1} + = \frac{\mu'(\mu' - K)}{\mu'^{2}-1}; +\] +hence if $i$~is real, $\mu'$~must be greater than~$K$. No substance is +known which fulfils the conditions of being transparent and +having the magnetic permeability greater than the specific +inductive capacity, which are the conditions for the existence of +a polarizing angle when the Faraday tubes are at right angles +to the plane of incidence. + +When the plane is infinitely thick, we see that +\[ +A' = - \frac{K V' \cos r - V \cos i}{K V' \cos r + V \cos i}\, A, +\] +or if the magnetic permeability is unity, +\[ +A' = - \frac{\sin(i - r)}{\sin(i + r)}\, A, +\] +which is analogous to the expression obtained by Fresnel for +the amplitude of the reflected ray when the incident light is +polarized in the plane of incidence. + +\Article{350} In the preceding investigation the Faraday tubes were at +right angles to the plane of incidence, we shall now consider the +case when they are in that plane: they are also of course in the +planes at right angles to the direction of propagation of the +several waves. + +Let the electromotive intensity at right angles to the incident +ray be +\[ +A\, \epsilon^{\iota(ax + by + pt)}, +\] +that at right angles to the reflected ray +\[ +A'\, \epsilon^{\iota(-ax + by + pt)}. +\] + +Let the electromotive intensity at right angles to the ray +which travels in the same sense as the incident one through +the plate of dielectric, i.e.~in a direction in which $x$~diminishes, be +\[ +B\, \epsilon^{\iota(a'x + by + pt)}, +\] +while that at right angles to the ray travelling in a direction in +which $x$~increases is represented by +\[ +B'\, \epsilon^{\iota(-a'x + by + pt)}. +\] +The electromotive intensity at right angles to the ray emerging +from the plate is +\[ +C\, \epsilon^{\iota(ax + by + pt)} +\] +%% -----File: 426.png---Folio 412------- + +The conditions at the boundary are (1)~that the electromotive +intensity parallel to the surface of the plate is continuous; +(2)~that the electric polarization at right angles to the plate is +also continuous. + +Hence if $i$~is the angle of incidence, $r$~that of refraction, the +boundary conditions at the surface $x = 0$ of the plate give +\[ +\left. +\begin{aligned} +(A-A') \cos i &= (B-B') \cos r,\\ +(A+A') \sin i &= K(B+B') \sin r, +\end{aligned} +\right\} +\Tag{7} +\] +where $K$~is the specific inductive capacity of the plate. + +The boundary conditions at the lower surface of the plate +give +\[ +\left. +\begin{aligned} +C\, \epsilon^{-\iota ah} \cos i &= (B\, \epsilon^{-\iota a'h} - B'\, \epsilon^{\iota a'h}) \cos r, \\ +C\, \epsilon^{-\iota ah} \sin i &= K(B\, \epsilon^{-\iota a'h} + B'\, \epsilon^{\iota a'h}) \sin r. +\end{aligned} +\right\} +\Tag{8} +\] + +Solving equations (\eqnref{350}{7})~and~(\eqnref{350}{8}) we get +\begin{align*} +A' &= A(K^{2} \tan^{2} r - tan^{2} i)(\epsilon^{\iota a'h} - \epsilon^{-\iota a'h}) ÷ \Delta',\\ +B\phantom{'} + &= 2 A(\sin i / \cos r)(K \tan r + \tan i) \epsilon^{\iota a'h} ÷ \Delta',\\ +B' &= -2 A(\sin i / \cos r)(K \tan r - \tan i) \epsilon^{-\iota a'h} ÷ \Delta',\\ +C \phantom{'} + &= 4 A K \tan i \tan r \epsilon^{\iota ah} ÷ \Delta', +\end{align*} +where +\[ +\Delta' = (K^{2} \tan^{2} r + \tan^{2} i)(\epsilon^{\iota a'h} - \epsilon^{-\iota a'h}) + + 2 K \tan i \tan r (\epsilon^{\iota a'h} + \epsilon^{-\iota a'h}). +\] +From these equations we see that if the incident wave is equal to +\[ +\cos \frac{2 \pi}{\lambda} (x \cos i + y \sin i + Vt) +\] +the reflected wave will be +\begin{multline*} +(K^{2} \tan^{2} r - \tan^{2} i) + \sin \left( \frac{2 \pi}{\lambda'} h \cos r \right) × \\ + \cos \left[ \frac{2 \pi}{\lambda} (-x \cos i + y \sin i + Vt) + \frac{\pi}{2} - \theta \right] ÷ D'; +\end{multline*} +the waves in the plate will be represented by +\begin{multline*} +(\sin i / \cos r)(K \tan r + \tan i) × \\ + \cos \left[ \frac{2 \pi}{\lambda'} \bigl((x + h) \cos r + y \sin r + V't\bigr) - \theta \right] ÷ D', +\end{multline*} +and +\begin{multline*} +-(\sin i / \cos r)(K \tan r - \tan i) × \\ + \cos \left[ \frac{2 \pi}{\lambda'} \bigl(-(x+h) \cos r + y \sin r + V't\bigr) - \theta \right] ÷ D' +\end{multline*} +%% -----File: 427.png---Folio 413------- +respectively, while the emergent wave is +\[ +2K \tan i \tan r \cos\left[\frac{2}{\pi}{\lambda} \bigl((x + h) \cos i + y \sin i + Vt\bigr) - \theta\right] ÷ D', +\] +where +\begin{multline*} +D'^2 = (K^2 \tan^2 r + \tan^2 i)^2 + \sin^2 \left(\frac{2\pi}{\lambda'} h \cos r\right) \\ + + 4K^2 \tan^2 r \tan^2 i \cos^2\left(\frac{2\pi}{\lambda'} h \cos r\right), +\end{multline*} +\begin{DPgather*} +\lintertext{and} +\tan \theta = \frac{K^2 \tan^2r + \tan^2i}{2K \tan r \tan i} + \tan\left(\frac{2\pi}{\lambda'} h \cos r\right). +\end{DPgather*} + +From these expressions we see that, as before, there is no +reflected wave when $h$~is very small compared with~$\lambda'$ and when +$h \cos r$ is a multiple of~$\lambda'/2$; these results are the same whether the +Faraday tubes are in or at right angles to the plane of incidence. +We see now, however, that in addition to this the reflected wave +vanishes, whatever the thickness of the plate, when $K \tan r = \tan i$, +or since $\sqrt{\mu'K} \sin r = \sin i$ where $\mu'$~is the magnetic permeability, +the reflected wave vanishes when +\[ +\tan^2 i = \frac{K (K-\mu')}{\mu' K - 1}; +\] +if the plate is non-magnetic $\mu'= 1$, and we have +\[ +\tan i = \sqrt{K}. +\] + +When $K \tan r = \tan i$ the reflected wave and one of the waves +in the plate vanish; the electromotive intensity in the other wave +in the plate is equal to +\[ +\sqrt{\frac{\mu'}{K}} \cos \frac{2\pi}{\lambda'} (x \cos r + y \sin r + V't), +\] +and the emergent wave is +\[ +\cos \frac{2\pi}{\lambda} \left((x + h) \cos i + y \sin i + Vt - \frac{h\lambda}{\lambda'} \cos r\right). +\] +The intensity of all these waves are independent of the thickness +of the plate. + +If the plate is infinitely thick we must put $B' = 0$ in equations~(\eqnref{350}{7}); +doing this we find from these equations that +\begin{align*} +A' & = A\, \frac{(K \tan r - \tan i)}{K \tan r + \tan i}, \\ +B\phantom{'} & = A\, \frac{\sin 2i}{\sin i \cos r + K \cos i \sin r}. +\end{align*} +%% -----File: 428.png---Folio 414------- + +If the plate is made of a non-magnetic material $K = \sin^2 i / \sin^2 r$, +and in this case we have +\begin{align*} +A' & = A\, \frac{\tan(i - r)}{\tan(i + r)}, \\ +B & = 4A\, \frac{\sin r \cos i}{\sin 2i + \sin 2r}. +\end{align*} + + +\Subsection{Reflection from a Metal Plate.} +\index{Electromagnetic waves, xtheory of reflection of from metals@\subdashtwo theory of reflection of from metals}% +\index{Waves, electromagnetic, theory of reflection of from metals@\subdashtwo theory of reflection of from metals}% + +\Article{351} The very important case when the plate is made of a metal +instead of an insulator can be solved in a similar way. The +expressions for the electromotive intensities in the various media +will be of the same type as before; in the case of metallic +reflection however the quantity~$a'$, which occurs in the expression +for the electromotive intensity in the plate, will no longer be +real. In a conductor whose specific resistance is~$\sigma$ the electromotive +intensity will satisfy a differential equation of the form +\[ +\frac{d^2 E}{dx^2} + \frac{d^2 E}{dy^2} = \frac{4\pi\mu}{\sigma}\, \frac{dE}{dt}, +\] +or, since $E$~varies as~$\epsilon^{\iota pt}$, +\[ +\frac{d^2 E}{dx^2} + \frac{d^2 E}{dy^2} = \frac{4\pi\mu\iota p}{\sigma}\, E. +\] + +Hence, since in the metal plate $E$~varies as~$\epsilon^{\iota(± a'x + by + pt)}$, we +see that +\[ +a'^2 + b^2 = -4\pi\mu\iota p / \sigma. +\Tag{9} +\] + +To compare the magnitude of the terms in this equation, let us +suppose that we are dealing with a wave whose wave length is +$10^q$~centimetres. Then since $2\pi/p$~is the time of a vibration, if +$V$~is the velocity of propagation of electromagnetic action in air, +\[ +V 2\pi / p = \lambda, +\] +but $V$~is equal to $3 × 10^{10}$, hence +\[ +p = 6\pi 10^{10-q}. +\] + +If the plate is made of zinc $\sigma$~is about~$10^4$, so that the modulus +of $4\pi\mu\iota p / \sigma$ is about $24\pi^2 10^{6-q}$. Now $b^2$~is less than $4\pi^2 / \lambda^2$, +i.e.~$4\pi^2 × 10^{-2q}$, hence the ratio of the modulus of $4\pi\mu\iota p / \sigma$ to +$b^2$ is of the order $6 × 10^{6+q}$, and is therefore exceedingly large +unless $q$~is less than~$-6$, that is, unless the wave length of the +electrical oscillation is much less than that of green light. Thus +for waves appreciably longer than this we may for a zinc plate +%% -----File: 429.png---Folio 415------- +neglect~$b^{2}$ in equation~(\eqnref{351}{9}), which then becomes +\begin{DPalign*} +a'^2 & = -4 \pi \mu \iota p / \sigma, \\ +\lintertext{or} +a'\phantom{^2} & = ± \sqrt{2 \pi \mu p / \sigma} (1-\iota), +\end{DPalign*} +thus $a'$~is exceedingly large compared with~$a$. + +We shall first consider the case when the Faraday tubes are +at right angles to the plane of incidence as in \artref{349}{Art.~349}. The +condition that the electromotive intensity parallel to the surface +of the plate is continuous will still be true, but since there is no +real angle of refraction in metals it is convenient to recognize +the second condition of that article as expressing the condition +that the tangential magnetic force is continuous. The tangential +magnetic force is parallel to~$y$ and is equal to +\[ +\frac{1}{\mu \iota p}\, \frac{dE}{dx}, +\] +where $\mu$~is the magnetic permeability. By means of this and the +previous condition we find, using the notation of \artref{349}{Art.~\DPtypo{(349)}{349}}, +\[ +\left. +\begin{aligned} +&A' = -A(a'^{2} / \mu^{2} - a^{2})(\epsilon^{\iota h a'} - \epsilon^{-\iota h a'}) ÷ D, \\ +&B\phantom{'} = 2 A a(a' / \mu + a)\epsilon^{\iota h a'} ÷ D, \\ +&B' = 2 A a(a' / \mu - a)\epsilon^{-\iota h a'} ÷ D, \\ +&C\phantom{'} = A 4 a(a' / \mu)\epsilon^{\iota h a} ÷ D, \\ +&\text{where} \\ +& D\phantom{'} = (a'^{2} / \mu^{2} + a^{2})(\epsilon^{\iota ha'} - \epsilon^{-\iota ha'}) + + 2a(a' / \mu)(\epsilon^{\iota ha'} + \epsilon^{-\iota ha'}). +\end{aligned} +\right\} +\Tag{10} +\] + +Since $\epsilon^{\iota(a'x + by + pt)}$ represents a wave travelling in the plate in +the direction of the incident wave, i.e.~so that $x$~is increasingly +negative; the real part of~$\iota a'$ must be positive, otherwise the +amplitude of the wave would continually increase as the wave +travelled onwards; hence if $ha'$~is very large, equations~(\eqnref{351}{10}) +become approximately, remembering that $a'/a$~is also very large, +\begin{align*} +A' &= -A,\\ +B\phantom{'} &= \frac{2 a \mu}{a'}\, A,\\ +C\phantom{'} &= B' = 0. +\end{align*} + +Hence in this case there is complete reflection from the metal +plate, and since $A' + A = 0$ we see that the electromotive intensity +vanishes at the surface of the plate, and since $C = 0$ +there is no electromotive intensity on the far side of the plate. +%% -----File: 430.png---Folio 416------- +The condition that the plate should act as a perfect reflector or, +which is the same thing, as a perfect screen, is that $\{4 \pi \mu p h^{2} / \sigma\}^{\frac{1}{2}}$ +should be large. In the case of zinc plates the value of this +quantity for vibrations whose wave length is $10^{q}$~centimetres is +equal to $1.5 × 10^{4-q/2} h$, so that for waves $1$~metre long it is equal +to $1500 h$; thus, if $h$~were as great as $\frac{1}{15}$~of a millimetre, $a'h$ +would be equal to~$10$, and since $\epsilon^{10}$~is very large the reflection +in this case would be practically perfect. We see from this +result the reason why gold-leaf and tin-foil are able to reflect +these very rapid oscillations almost completely. If however the +conductor is an electrolyte $\sigma$~may be of the order~$10^{10}$, so that +$a'h$~will now be only~$1.5 h$ for waves $1$~metre in length, in this case +it will require a slab of electrolyte several millimetres in thickness +to produce complete reflection. We shall consider a little +more fully the wave emergent from the metallic plate. We +have by equations~(\eqnref{351}{10}) +\[ +C = \frac{4 A a a'\, \epsilon^{\iota h a}} + {\mu \{(a'^{2} / \mu^{2} + a^{2}) (\epsilon^{\iota ha'} - \epsilon^{-\iota ha'}) + + (2 a a'/ \mu) (\epsilon^{\iota ha'} + \epsilon^{-\iota ha'}) \} }. +\Tag{11} +\] + +If $ha'$~is very small this may be written +\[ +C = \frac{2Aaa'\, \epsilon^{\iota h a}} + {\mu \{(a'^{2} / \mu^{2} + a^{2}) h a' \iota + (2 a a' / \mu) \} }, +\] +or, since $a'^{2} / \mu^{2}$ is very large compared with~$a^{2}$, +\begin{align*} +C &= \frac{A\, \epsilon^{\iota h a}}{1 + \dfrac{\iota h a'^{2}}{2 \mu a} + \frac{1}{2} \iota \mu h a} \\ + &= \frac{A\, \epsilon^{\iota h a}}{1 + (2 \pi V h / \sigma) + \frac{1}{2} \iota \mu h a}. +\end{align*} + +Thus, corresponding to the incident wave +\[ +\cos \frac{2 \pi}{\lambda} (x + V t), +\] +we have, since $h a$ is very small, an emergent wave +\begin{DPgather*} +\frac{1}{1 + (2 \pi h V / \sigma)} \cos \frac{2 \pi}{\lambda} (x + h' + V t), \\ +\lintertext{where} +h' = h \left\{1 - \tfrac{1}{2}\, \frac{\mu}{1 + 2 \pi h V / \sigma} \right\}. +\end{DPgather*} + +Since $V$~is equal to $3 × 10^{10}$ and $\sigma$~for electrolytes is rarely +greater than~$10^{9}$, we see that for very moderate thicknesses +$(2 \pi h V / \sigma)$ will be large compared with unity, so that the expression +%% -----File: 431.png---Folio 417------- +for the emergent wave becomes +\[ +\frac{1}{(2 \pi h V / \sigma)} \cos \frac{2 \pi}{\lambda} (x + h + Vt). +\] + +The thickness of the conducting material which, when interposed +in the path of the wave, produces a given diminution in +the electric intensity is thus proportional to the specific resistance +of the material; this result has been applied to measure the +specific resistance of electrolytes under very rapidly alternating +\index{Electrolytes, under rapidly alternating currents@\subdashone under rapidly alternating currents}% +currents (see J.~J. Thomson, \textit{Proc.\ Roy.\ Soc.}~45, p.~269, 1889). + +The preceding investigation applies to the case when the +Faraday tubes are at right angles to the plane of incidence, the +same results will apply when the Faraday tubes are in the plane +of incidence: the proof of these results for this case we shall +however leave as an exercise for the student. + + +\Subsection{Reflection of Light from Metals.} +\index{Light, xreflection of from metals@\subdashone reflection of from metals}% +\index{Metals, xreflection of light from@\subdashone reflection of light from}% +\index{Reflection of light from metals@\subdashtwo light from metals}% + +\Article{352} The assumption that $a'/a$~is very large is legitimate when +we are dealing with waves as long as those produced by Hertz's +apparatus, it ceases however to be so when the length of the +wave is as small as it is in the electrical vibrations we call +light. We shall therefore consider separately the theory of the +reflection of such waves from metallic surfaces. With the view +of making our equations more general we shall not in this case +neglect the effects of the polarization currents in the metal; when +we include these, the components of the magnetic force and +electromotive intensity in the metal satisfy differential equations +of the form +\[ +\mu K'\, \frac{d^{2}f}{dt^{2}} + \frac{4 \pi \mu}{\sigma}\, \frac{df}{dt} + = \frac{d^{2}f}{dx^{2}} + \frac{d^{2}f}{dy^{2}} + \frac{d^{2}f}{dz^{2}}. +\Tag{1} +\] +See Maxwell's \textit{Electricity and Magnetism}, Art.~783; here $K'$~is +the specific inductive capacity of the metal. + +\Article{353} Let us first consider the case when the incident wave is +polarized in the plane of incidence, which we take as the plane +of~$xy$, the reflecting surface being given by the equation $x = 0$. +In this case the electromotive intensity~$Z$ is parallel to the axis +of~$z$; let the incident wave be +\begin{DPgather*} +Z = \epsilon^{\iota(ax + by + pt)},\\ +\intertext{the reflected wave} +Z = A\, \epsilon^{\iota(-ax + by + pt)},\\ +%% -----File: 432.png---Folio 418------- +\lintertext{where} +a^{2} + b^{2} = Kp^{2}, +\Tag{2} +\end{DPgather*} +$K$~being the specific inductive capacity of the dielectric, and +the magnetic permeability of this dielectric being assumed to be +unity. + +Let the wave in the metal be given by the equation +\begin{DPgather*} +Z = B\, \epsilon^{\iota(a'x + by + pt)}, \\ +\lintertext{where} +a'^{2} + b^{2} = p^{2} \mu K' - \frac{4 \pi \mu \iota p}{\sigma}. +\Tag{3} +\end{DPgather*} + +Thus in the dielectric we have +\begin{DPgather*} +Z = \epsilon^{\iota(ax + by + pt)} + A\, \epsilon^{\iota(-ax + by + pt)}, \\ +\lintertext{and in the metal} +Z = B\, \epsilon^{\iota(a'x + by + pt)}. +\end{DPgather*} + +Since $Z$, the electromotive intensity, is continuous when $x = 0$, +we have +\[ +1 + A = B. +\] + +By equation~(\eqnref{256}{2}) of \artref{256}{Art.~256} the magnetic induction parallel to~$y$ +is equal to +\[ +\frac{1}{\iota p}\, \frac{dZ}{dx}, +\] +and since the magnetic force parallel to~$y$ is continuous when +$x = 0$, we have +\[ +a(1-A) = \frac{a'}{\mu} B. +\] + +From these equations we find +\[ +A = \frac{1 - \dfrac{a'}{\mu a}}{1 + \dfrac{a'}{\mu a}}. +\Tag[3s]{3*} +\] + +Let us for the present confine our attention to the non-magnetic +metals for which $\mu = 1$, in this case the preceding +equation becomes +\[ +A = \frac{1 - \dfrac{a'}{a}}{1 + \dfrac{a'}{a}}. +\] + +The expression given by Fresnel for the amplitude of the wave +reflected from a transparent substance is of exactly the same +form as this result, the only difference being that for a transparent +substance $a'$~is real, while in the case of metals it is +complex. +%% -----File: 433.png---Folio 419------- + +Now for transparent substances the relation between $a'$~and~$a$ +is +\[ +\frac{a'^{2} + b^{2}}{a^{2} + b^{2}} = \mu'^{2}, +\] +where $\mu'$~is the refractive index of the substance. + +In the case of metals however the relation between $a'$~and~$a$ is +\[ +\frac{a'^{2} + b^{2}}{a^{2} + b^{2}} + = \mu \frac{K'}{K} - \frac{4 \pi \mu \iota}{K p \sigma} + = R^{2}\, \epsilon^{2 \iota\alpha}, \text{ say}, +\Tag{4} +\] +which is of exactly the same form as the preceding, with $R\, \epsilon^{\iota \alpha}$ +written instead of~$\mu'$, the refractive index of the transparent +substance. + +Thus, if in Fresnel's formula for the reflected light we suppose +that the refractive index is complex and equal to~$R\, \epsilon^{\iota \alpha}$, where $R$ +and~$\alpha$ are defined by equation~(\eqnref{353}{4}), we shall arrive at the results +given by the preceding theory of the reflection of light by +metals. + +\Article{354} Let us now consider the case when the plane of polarization +is perpendicular to the plane of incidence; in this case the +electromotive intensity is in the plane of incidence and the +magnetic force~$\gamma$ at right angles to it. If the incident wave is +expressed by the equation +\[ +\gamma = \epsilon^{\iota(ax + by + pt)}, +\] +then in the dielectric we may put +\[ +\gamma = \epsilon^{\iota(ax + by + pt)} + A'\, \epsilon^{\iota(-ax + by + pt)}, +\] +while in the metal we have +\[ +\gamma = B'\, \epsilon^{\iota(a'x + by + pt)}. +\] + +Since the magnetic force parallel to the surface is continuous, +we have +\[ +1 + A' = B'. +\Tag{5} +\] + +The other boundary condition we shall employ is that~$Q$, the +tangential electromotive intensity parallel to the axis of~$y$, is +continuous. Now if $g$~is the electric polarization parallel to~$y$, +and $v$~the conduction current in the same direction, then in the +dielectric above the metal +\[ +4 \pi \frac{dg}{dt} = -\frac{d \gamma}{dx}, +\] +or since +\[ +g = \frac{K}{4 \pi} Q = \frac{a^{2} + b^{2}}{4 \pi p^{2}} Q +\] +%% -----File: 434.png---Folio 420------- +by equation~(\eqnref{353}{2}) we have +\[ +\frac{\iota(a^{2} + b^{2})}{p} Q = - \frac{d \gamma}{dx}. +\] + +In the metal +\begin{DPgather*} +4 \pi \frac{dg}{dt} + 4 \pi v = -\frac{d \gamma}{dx}, \\ +\lintertext{or} +\left( K' \iota p + \frac{4 \pi}{\sigma} \right) Q = -\frac{d \gamma}{dx}, +\end{DPgather*} +this by equation~(\eqnref{353}{3}) becomes +\[ +\frac{\iota}{p \mu} (a'^{2} + b^{2}) Q = -\frac{d \gamma}{dx}; +\] +hence, since $Q$~is continuous when $x = 0$, we have +\[ +\frac{a}{a^{2} + b^{2}} (1 - A') = \frac{\mu a'}{(a'^{2} + b^{2})} B'. +\Tag{6} +\] + +Equations (\eqnref{354}{5})~and~(\eqnref{354}{6}) give +\[ +A' = \frac{1 - \mu \dfrac{a'}{a}\, \dfrac{a^{2} + b^{2}}{a'^{2} + b^{2}}} + {1 + \mu \dfrac{a'}{a}\, \dfrac{a^{2} + b^{2}}{a'^{2} + b^{2}}}, +\] +which is again, for non-magnetic metals for which $\mu = 1$, of the +same form as Fresnel's expression for the amplitude of the +reflected wave from a transparent substance. So that in this +case, as in the previous one, we see that we can get the results +of this theory of metallic reflection by substituting in Fresnel's +expression a complex quantity for the refractive index. + +\Article{355} This result leads to a difficulty similar to the one which +was pointed out by Lord Rayleigh (\textit{Phil.\ Mag.}~[4], 43, p.~321, 1872) +\index{Rayleigh, Lord, metallic reflection@\subdashtwo metallic reflection}% +in the theory of metallic reflection on the elastic solid theory of +light. The result of substituting in Fresnel's expressions a complex +quantity for the refractive index has been compared with the +\index{Eisenlohr, metallic reflection}% +result of experiments on metallic reflection by Eisenlohr (\textit{Pogg.\ +Ann.}~104, p.~368, 1858) and Drude (\textit{Wied.\ Ann.}~39, p.~481, 1890). +\index{Drude on metallic reflection}% +The latter writer finds that if the real part of $R^{2}\, \epsilon^{2 \iota \alpha}$, the +quantity which for metals replaces the square of the refractive +index for transparent substances, is written as $n^{2} (1 - k^{2})$, the +imaginary part as $-2 \iota n^{2} k$; then $n$~and~$k$ have the following +values, where the accented letters refer to the values for red +light, the unaccented to sodium light. +%% -----File: 435.png---Folio 421------- +\begin{center} +\index{Refractive@`Refractive Indices' of metals}% +\tabletextsize +\settowidth{\TmpLen}{Copper-Nickel alloy\qquad} +\begin{tabular}{| l@{}|*{4}{>{\quad}c<{\quad}|}} +\hline +\parbox{\TmpLen}{\bigskip$~$\bigskip}& $n$ & $n'$ & $k$ & $k'$ \\ +\hline +\tablespaceup Bismuth\mdotfill &$1.90\Z$ &$2.07\Z$ &$\Z1.93$ &$\Z1.90$ \\ +Lead, pure\mdotfill &$2.01\Z$ &$1.97\Z$ &$\Z1.73$ &$\Z1.74$ \\ +Lead, impure\mdotfill &$1.97\Z$ & &$\Z1.74$ & \\ +Mercury, pure\mdotfill &$1.73\Z$ &$1.87\Z$ &$\Z2.87$ &$\Z2.78$ \\ +Mercury, impure\mdotfill &$1.55\Z$ & &$\Z3.14$ & \\ +Platinum, pure\mdotfill &$2.06\Z$ &$2.16\Z$ &$\Z2.06$ &$\Z2.06$ \\ +Platinum, impure\mdotfill &$2.15\Z$ & &$\Z1.92$ & \\ +Gold, pure\mdotfill &$\Z.366$ &$\Z.306$ &$\Z7.71$ &$10.2\Z$ \\ +Gold, impure\mdotfill &$\Z.570$ & &$\Z5.31$ & \\ +Antimony\mdotfill &$3.04\Z$ &$3.17\Z$ &$\Z1.63$ &$\Z1.56$ \\ +Tin, solid\mdotfill &$1.48\Z$ &$1.66\Z$ &$\Z3.55$ &$\Z3.30$ \\ +Tin, liquid\mdotfill &$2.10\Z$ & &$\Z2.15$ & \\ +Cadmium\mdotfill &$1.13\Z$ &$1.31\Z$ &$\Z4.43$ &$\Z4.05$ \\ +Silver\mdotfill &$\Z.181$ &$\Z.203$ &$20.3\Z$ &$19.5\Z$ \\ +Zinc\mdotfill &$2.12\Z$ &$2.36\Z$ &$\Z2.60$ &$\Z2.34$ \\ +Copper, pure\mdotfill &$\Z.641$ &$\Z.580$ &$\Z4.09$ &$\Z5.24$ \\ +Copper, impure\mdotfill &$\Z.686$ & &$\Z3.85$ & \\ +Copper-Nickel alloy\mdotfill &$1.55\Z$ & &$\Z2.14$ & \\ +Nickel\mdotfill &$1.79\Z$ &$1.89\Z$ &$\Z1.86$ &$\Z1.88$ \\ +Iron\mdotfill &$2.36\Z$ & &$\Z1.36$ & \\ +Steel\mdotfill &$2.41\Z$ &$2.62\Z$ &$\Z1.38$ &$\Z1.32$ \\ +Aluminium\mdotfill &$1.44\Z$ &$1.62\Z$ &$\Z3.63$ &$\Z3.36$ \\ +Magnesium\mdotfill &$\Z.37\Z$ &$\Z.40\Z$ &$11.8\Z$ &$11.5\Z$\tablespacedown \\ +\hline +\end{tabular} +\end{center} +It will be seen that for all these metals without exception the +value of~$k$ is greater than unity, so that the real part of $R^{2}\, \epsilon^{2 \iota \alpha}$ +or $n^{2}(1-k^{2})$ is negative. Equation~(\eqnref{353}{4}), \artref{353}{Art.~353}, shows, however, +that the real part of $R^{2}\, \epsilon^{2 \iota \alpha}$ is equal to~$\mu K'/K$, an essentially +positive quantity. This shows that the electromagnetic theory +of metallic reflection is not general enough to cover the facts. +In this respect, however, it is in no worse position than any +other existing theory of light, while it possesses the advantage +over other theories of explaining why metals are opaque. + +\Article{356} The direction in which to look for an improvement of +the theory seems pretty obvious. The preceding table shows +how rapidly the effects vary with the frequency of the light +vibrations; they are in this respect analogous to the effects of +`anomalous dispersion' (see Glazebrook, \textit{Report on Optical +\index{Glazebrook@Glazebrook, \textit{Report on Optical Theories}}% +Theories, B.~A. Report}, 1885), which have been accounted for by +assuming that the molecules of the substance through which the +light passes have free periods of vibration comparable with the +frequency of the light vibrations. The energy absorbed by such +molecules is then a function of the frequency of the light +vibrations, and the optical character of the medium cannot be +fixed by one or two constants, such as the specific inductive +%% -----File: 436.png---Folio 422------- +capacity or the specific resistance; we require to know in +addition the free periods of the molecules. + +\Article{357} We now return to the case of the magnetic metals; the +question arises whether or not these substances retain their +magnetic properties under magnetic forces which oscillate as +rapidly as those in a wave of light. We have seen (\artref{286}{Art.~286}) +that iron retains its magnetic properties when the magnetic +forces make about one million vibrations per second; in the +light waves, however, the magnetic forces are vibrating more +than five hundred million times faster than this, and the only +means we have of testing whether magnetic substances retain +their properties under such circumstances is to examine the light +reflected from or transmitted through such bodies. When we +do this, however, we labour under the disadvantage that, as the +preceding investigation shows, the theory of metallic reflection +is incomplete, so that the conclusions we may come to as the +results of this theory are not conclusive. Such evidence as we +have, however, tends to show that iron does not retain its +magnetic properties under such rapidly alternating magnetic +forces. An example of such evidence is furnished by equation~(\hyperref[eqn:353.3s]{3*}), +\artref{353}{Art.~353}. We see from that equation that if $\mu$~for light waves +in iron were very large, the intensity of the light reflected from +iron would be very nearly the same as that of the incident +light, in other words iron would have a very high reflecting +power. The reverse, however, seems to be true; thus Drude +(\textit{Wied.\ Ann}.\ 39, p.~549, 1890) gives the following numbers as +representing the reflective powers of some metals for yellow +light:--- +\begin{center} +\setlength{\tabcolsep}{12pt} +\begin{tabular}{c c c c c c } +\tabletextsize Silver. & +\tabletextsize Gold. & +\tabletextsize Copper. & +\tabletextsize Iron. & +\tabletextsize Steel. & +\tabletextsize Nickel. \\ +$95.3$ &$85.1$ &$73.2$ &$56.1$ &$58.5$ &$62.0$ +\end{tabular} +\end{center} +Rubens (\textit{Wied.\ Ann.}~37, p.~265, 1889) gives for the same metals +\index{Rubens, metallic reflection}% +the following numbers:--- +\begin{center} +\setlength{\tabcolsep}{12pt} +\begin{tabular}{c c c c c } +\tabletextsize Silver. & +\tabletextsize Gold. & +\tabletextsize Copper. & +\tabletextsize Iron. & +\tabletextsize Nickel. \\ +$90.3$ &$71.1$ &$70.0$ &$56.1$ &$62.1$ +\end{tabular} +\end{center} +The near agreement of the numbers found by these two experimenters +seems to show that the smallness of the reflection observed +from iron could not be due to any accidental cause such as +want of polish. Another reason for believing that iron does +not manifest magnetic properties under the action of light +waves, is that there is nothing exceptional in the position of +%% -----File: 437.png---Folio 423------- +iron with respect to the optical constants of metals in the table +given in \artref{353}{Art.~353}. The theory of metallic reflection is however +so far from accounting for the facts that we cannot attach much +weight to considerations based on it. The only conclusion we +can come to is the negative one, that there is no evidence to +show that iron does retain its magnetic properties for the light +vibrations. + +\Subsection{The change in Phase produced by the Transmission of Light +through thin Films of Metal.} +\index{Films, transmission of light through}% +\index{Kundt, transmission of light through thin films@\subdashone transmission of light through thin films}% +\index{Light, xtransmission of through thin films@\subdashone transmission of through thin films}% +\index{Metals, xtransmissions of light through thin films of@\subdashone transmissions of light through thin films of}% +\index{Quincke, transmission of light through thin films}% + +\Article{358} Quincke (\textit{Pogg.\DPtypo{,}{}\ Ann.}\ 120, p.~599, 1863) investigated the +change in phase produced when light passed through thin silver +plates, and found that in many cases the phase was accelerated, +the effect being the same as if the velocity of light through +silver was greater than that through air. Kundt (\textit{Phil.\ Mag.}\ +[5], 26, p.~1, 1888), in a most beautiful series of experiments, +measured the deviation of a ray passing through a small metal +\emph{prism}, and found that when the prism was made of silver, +gold, or copper, the deviation was towards the thin end. With +platinum, nickel, bismuth, and iron prisms the deviation was, +on the other hand, towards the thick end. We can readily find +on the electromagnetic theory of light the change in phase produced +when the light passes through a thin film of metal. The +equation~(\eqnref{351}{11}) of \artref{351}{Art.~351} shows, that if the incident wave (supposed +for simplicity to be travelling at right angles to the film) +is represented by +\[ +\epsilon^{\iota(ax+pt)}, +\] +the emergent wave will be +\[ +\frac{4a(a'/\mu)\, \epsilon^{\iota ha}\, \epsilon^{\iota(ax+pt)}} + {(a'^2/\mu^2 + a^2)(\epsilon^{\iota ha'} - \epsilon^{-\iota ha')} + + 2a(a'/\mu)(\epsilon^{\iota ha'} + \epsilon^{-\iota ha')}}, +\] +or if the film is so thin that $ha'$ is a small quantity, the emergent +wave is equal to +\[ +\frac{\epsilon^{\iota ha}\, \epsilon^{\iota(ax+pt)}} + {1 + \frac{1}{2}\, \dfrac{\iota h\mu}{a} \left(\dfrac{a'^2}{\mu^2} + a^2\right)}. +\] + +Now, since in this case $b = 0$, we have by equation~(\eqnref{353}{4}) of \artref{353}{Art.~353} +$\dfrac{a'^2}{a^2} = R^2\, \epsilon^{2\iota\alpha}$, hence the emergent wave is equal to +\[ +\frac{\epsilon^{\iota ha}\, \epsilon^{\iota(ax+pt)}} + {1 + \frac{1}{2} \iota h\mu a \left\{\dfrac{R^2\, \epsilon^{2\iota\alpha}}{\mu^2} + 1\right\}}, +\] +%% -----File: 438.png---Folio 424------- +or, neglecting squares and higher powers of~$h$, this is equal to +\begin{multline*} +\epsilon^{\frac{1}{2} haR^2 \sin 2\alpha\mu^{-1}}\, +\epsilon^{\iota ha}\, +\epsilon^{-\frac{1}{2} \iota h\mu a (1 + R^2 \cos 2\alpha/\mu^2)}\, +\epsilon^{\iota(ax+pt)} \\ += \epsilon^{\frac{1}{2} haR^2 \sin 2\alpha\mu^{-1}}\, +\epsilon^{\iota ha \left(1 - \frac{\mu}{2} \{1 + R^2 \cos 2\alpha/\mu^2\}\right)}\, +\epsilon^{\iota(ax+pt)}, +\end{multline*} +hence the acceleration of phase expressed as a length is equal to +\[ +h\left(1 - \frac{\mu}{2} \{1 + R^2 \cos 2\alpha/\mu^2\}\right), +\] +or for non-magnetic substances to +\[ +\tfrac{1}{2} h(1 - R^2 \cos 2\alpha). +\] +In the interpretation of this result we are beset with difficulties, +whether we take $R^2 \cos 2\alpha$ as determined by the electromagnetic +theory, or whether we take it as given by Drude's experiments. +In the former case $R^2 \cos 2\alpha$ is positive, so that the acceleration +cannot be greater than~$h/2$, or the apparent speed of light +through the metal cannot be greater than twice that through +air; this is not in accordance with Kundt's experiments on silver +and gold. If, on the other hand, we take Drude's values for +$R^2 \cos 2\alpha$, since these are negative for all metals, the apparent +velocity of light through a film of any metal ought to be more +than double that through air; this again is not in accordance with +Kundt's observations, according to which the apparent velocity +of light through films of metals other than gold, silver, or +copper is less than that through air. We might have anticipated +that such a discrepancy would arise, for we have assumed in +deducing the expression for the transmitted ray that the electromotive +intensity parallel to the surface of the metal is continuous. +Now if we suppose that the light vibrations have +periods comparable with periods of the molecules of the metal, +the electromotive intensity in the metal will arise from two +causes. The first is due to magnetic induction, this will be continuous +with that due to the same cause in the air; the second is +due to the reaction of the molecules of the metal on the medium +conveying the light. Now there does not seem to be any reason +to assume that this part of the electromotive intensity should +be continuous as we pass from the air which does not exhibit +anomalous dispersion to the metal which does. The electromotive +intensity parallel to the boundary is thus probably +discontinuous, and we could not therefore expect a formula +obtained by the condition that this intensity was continuous to +be in accordance with experiment. +%% -----File: 439.png---Folio 425------- + +\Section{Reflection of Electromagnetic Waves from Wires.} + +\Subsection{Reflection from a Grating.} +\index{Grating, reflection of electromagnetic waves from}% +\index{Reflection of electromagnetic waves from a grating@\subdashtwo electromagnetic waves from a grating}% + +\Article{359} We shall now consider the reflection of electromagnetic +waves from a grating consisting of similar and parallel metallic +wires, whose cross-sections we leave for the present indeterminate, +arranged at equal intervals, the axes of all the wires being +in one plane, which we shall take as the plane of~$yz$, the axis of~$z$ +being parallel to the wires: the distance between the axes of +two adjacent wires is~$a$. We shall suppose that a wave in which +the electromotive intensity is parallel to the wires, and whose +front is parallel to the plane of the grating, falls upon the wires. +The electromotive intensity in the incident wave may be represented +by the real part of $A\, \epsilon^{\frac{\iota 2 \pi}{\lambda} (Vt+x)}$, $x$~being measured from +the plane of the grating towards the advancing wave. The +incidence of this wave will induce currents in the wires, and +these currents will themselves produce electromotive intensities +parallel to~$z$ in the region surrounding them; these intensities +will evidently be expressed by a periodic function of~$y$ of such +a character that when $y$~is increased by~$a$ the value of the +function remains unchanged. If we make the axis of~$z$ coincide +with the axis of one of the wires, the electromotive intensity +will evidently be an even function of~$y$. Thus~$E_2$, the electromotive +intensity due to the currents in the wire, will be given by +an equation of the form +\[ +E_2 =\tsum A_m \cos \frac{2 m \pi y}{a}\, \epsilon^{\iota n x}\, \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt}, +\] +where $m$~is an integer. + +Since the electromotive intensity satisfies the equation +\[ +\frac{d^{2} E}{dx^{2}} + \frac{d^{2} E}{dy^{2}} + = \frac{1}{V^{2}}\, \frac{d^{2} E}{dt^{2}}, +\] +we have +\[ +n^{2} = - \frac{4 \pi^{2} m^{2}}{a^{2}} + \frac{4 \pi^{2}}{\lambda^{2}}. +\] + +We shall assume that the distance between the wires of the +grating is very small compared with the length of the wave; +thus, unless $m$~is zero, the first term on the right-hand side of the +above equation will be very large compared with the second, so +%% -----File: 440.png---Folio 426------- +that when $m$~is not zero we may put +\[ +n = ± \frac{\iota 2 \pi m}{a}, +\] +while when $m$ is zero +\[ +n = -\frac{2 \pi}{\lambda}, +\] +the minus sign being taken so as to represent a wave diverging +from the wires. Substituting these values we find that when +$x$~is positive, +\[ +E_2 = A_0\, \epsilon^{\frac{\iota 2 \pi}{\lambda}\bigl(Vt-(x+\alpha)\bigr)} + + \tsum_{m=1}^{m=\infty} A_m\, \epsilon^{-\frac{2\pi m}{a} x} + \cos{\frac{2 \pi m y}{a}}\, \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt}, +\] +where $\alpha$~is a constant. + +When the rate of alternation is so rapid that the waves are +only a few metres in length the electromotive intensity at the surface +of the metal wire must vanish, see Arts.\ \artref{300}{300}~and~\artref{301}{301}; hence +if $E_1$~is the electromotive intensity in the incident wave, $E_1 + E_2$ +must vanish at the surface of the wire. Near the grating however +$x/\lambda$~will be small; hence we may put, writing +\[ +A_m' \cos\frac{2 \pi}{\lambda} Vt + B_m' \sin\frac{2 \pi}{\lambda} Vt +\quad \text{for} \quad +A_m\, \epsilon^{\iota 2 \pi Vt/\lambda}, +\] +\begin{multline*} +E_1 + E_2 = (A +A_0) \cos{\frac{2 \pi}{\lambda} Vt} + + \bigl(A_0(x + \alpha) - Ax\bigr) \frac{2 \pi}{\lambda} \sin{\frac{2 \pi}{\lambda}} Vt \\ + + \tsum \epsilon^{-\frac{2 \pi m x}{a}} \cos{\frac{2\pi m y}{a}} + \left( A_m' \cos{\frac{2 \pi}{\lambda}} Vt + + B_m' \sin{\frac{2 \pi}{\lambda}} Vt \right). +\end{multline*} + +Now in Maxwell's \textit{Electricity and Magnetism}, Vol.~i. Art.~203, +it is shown that the expression +\[ +C \log \left\{1 - 2\epsilon^{-\frac{2 \pi x}{a}} \cos{\frac{2 \pi y}{a}} + \epsilon^{-\frac{4 \pi x}{a}} \right\} + Dx, +\] +where $C$~and~$D$ are constants, is constant over a series of equidistant +parallel wires, whose axes are at a distance~$a$ apart and +whose cross-section is approximately circular. The logarithm +can be expanded in the form +\[ +-2 C \tsum \frac{1}{m}\, \epsilon^{-\frac{2 m \pi x}{a}} \cos{\frac{2 m \pi y}{a}}. +\] + +Now in the expression for $E_1 + E_2$ put +\[ +A + A_0 = 0,\quad A_m = 0,\quad B_m = -\frac{2 C}{m}, +\] +%% -----File: 441.png---Folio 427------- +then +\begin{multline*} +E_1 + E_2 = A \cos{\frac{2 \pi}{\lambda}} (Vt + x) + - A \cos{\frac{2 \pi}{\lambda}} \bigl(Vt - (x+\alpha)\bigr)\\ + + C \log \left( 1 - 2 \epsilon^{-\frac{2 \pi x}{a}} \cos{\frac{2 \pi y}{a}} + \epsilon^{-\frac{4 \pi x}{a}} \right) \sin{\frac{2 \pi}{\lambda}} Vt, +\end{multline*} +hence near the grating where $x/\lambda$~is small +\begin{multline*} +E_1 + E_2 = \sin{\frac{2 \pi}{\lambda}} Vt + \left\{-A \frac{2 \pi x}{\lambda} - A \frac{2 \pi}{\lambda} (x+\alpha) \right.\\ + \left. + C \log \left( 1 - 2 \epsilon^{-\frac{2 \pi x}{a}} \cos{\frac{2 \pi y}{a}} + \epsilon^{-\frac{4 \pi x}{a}} \right) \right\}, +\end{multline*} +and we see by Maxwell's result that the quantity inside the +bracket has a constant value over the surface of the wires; +hence, if we make this value zero, we shall have satisfied the +conditions of the problem. Let $2c$~be the diameter of any one +of the wires in the plane of the grating, then when $x = 0$ and +$y = c$ the expression inside the bracket must vanish, hence +\[ +-A \frac{2 \pi}{\lambda} \alpha + C \log 4 \sin^{2} \frac{\pi c}{a} = 0. +\] + +To find another relation between $A$,~$C$, and~$\alpha$ we must consider +the equation to the cross-section of the wire at the origin, viz., +\[ +-A \frac{2 \pi}{\lambda} (2x + \alpha) + + C \log \left( 1 - 2\epsilon^{-\frac{2 \pi x}{a}} \cos{\frac{2 \pi y}{a}} + \epsilon^{-\frac{4 \pi x}{a}} \right) = 0, +\] +or substituting for~$C$ its value in terms of~$A$, +\[ +\left( \frac{2 x}{\alpha} + 1 \right) \log \left\{4 \sin^{2} \frac{\pi c}{a} \right\} + = \log \left( 1 - 2 \epsilon^{-\frac{2 \pi x}{a}} \cos \frac{2 \pi y}{a} + \epsilon^{-\frac{4 \pi x}{a}} \right). +\Tag{1} +\] + +If $d$~is the value of~$x$ when $y = 0$, +\[ +\alpha = 2 d \frac{\log 2 \sin \dfrac{\pi c}{a}}{\log\left\{\dfrac{1-\epsilon^{-\frac{2 \pi d}{a}}}{2 \sin \dfrac{\pi c}{a}} \right\} }. +\Tag{2} +\] + +When $c = d$, this equation becomes, since $c/a$~is small, +\[ +\alpha = -\frac{2 a}{\pi} \log 2 \sin \frac{\pi c}{a}. +\] + +The expression for~$E_2$ consists of two parts, one of which is +\[ +-A\, \epsilon^{\frac{\iota 2 \pi}{\lambda}(Vt - (x+\alpha))}, +\] +%% -----File: 442.png---Folio 428------- +which represents a reflected wave equal in intensity to the incident +one, but whose phase is changed by reflection by $\left(\frac{1}{2} \lambda -\alpha\right)$, +where~$\alpha$ is given by~(\eqnref{359}{2}) and depends upon the size of the wires +and their distance apart. The other part of the expression for~$E_2$ +is +\[ +C \log \left( 1 - 2 \epsilon^{-\frac{2 \pi x}{a}} \cos \frac{2 \pi y}{a} + \epsilon^{-\frac{4 \pi x}{a}} \right). +\] +This is inappreciable at a distance from the grating $4$~or $5$~times +the distance between the wires, hence the reflection, at some +distance from the grating, is the same, except for the alteration +in phase as from a continuous metallic surface. + +\Article{360} If the electromotive intensity had been at right angles to +the wires the reflection would have been very small; thus a +grating of this kind will act like a polariscope, changing either +by reflection or transmission an \DPtypo{unpolarised}{unpolarized} set of electrical +vibrations into a \DPtypo{polarised}{polarized} one. When used to produce \DPtypo{polarisation}{polarization} +by transmission we may regard it as the electrical analogue +of a plate of tourmaline crystal. + +\Subsection{Scattering of Electromagnetic Waves by a Metallic Wire.} +\index{Waves, electromagnetic, scattering of from cylinders@\subdashtwo scattering of from cylinders}% +\index{Cylinder, scattering of electromagnetic waves by@\subdashone scattering of electromagnetic waves by}% +\index{Electromagnetic waves, xscattering of by a cylinder@\subdashtwo scattering of by a cylinder}% +\index{Light, zscattering of by cylinders@\subdashone scattering of by cylinders}% +\index{Scattering of electromagnetic waves by a cylinder}% + +\Article{361} The scattering produced when a train of plane electromagnetic +waves impinges on an infinitely long metal cylinder, +whose axis is at right angles to the direction of propagation of +the waves and whose diameter is small compared with the wave +length, can easily be found as follows:--- + +We shall begin with the case where the electromotive intensity +in the incident wave is parallel to the axis of the cylinder, which +we take as the axis of~$z$; the axis of~$x$ being at right angles to +the fronts of the incident waves. + +Let $\lambda$~be the wave length, then $E_1$, the electromotive intensity +in the incident waves, may be represented by the equation +\[ +E_1 = \epsilon^{\frac{\iota 2 \pi}{\lambda}(Vt+x)}, +\] +where the real part of the right-hand side is to be taken. The +positive direction of~$x$ is opposite to that in which the waves are +travelling. In the neighbourhood of the cylinder $x/\lambda$~is small, +so that we may put +\[ +E_1 = \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt} \left( 1+\iota x \frac{2 \pi}{\lambda} \right) +\] +%% -----File: 443.png---Folio 429------- +approximately, or if $r$~and~$\theta$ are the polar coordinates of the point +where the intensity is~$E_1$, +\[ +E_1 = \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt} \left( 1+\iota \frac{2 \pi}{\lambda} r \cos \theta \right). +\] + +Let $E_2$~be the electromotive intensity due to the currents +induced in the cylinder, then $E_2$~satisfies the differential equation +\begin{align*} +\frac{d^{2}E_2}{dr^{2}} + + \frac{1}{r}\, \frac{d E_2}{dr} + + \frac{1}{r^{2}}\, \frac{d^{2} E_2}{d\theta^{2}} + &= \frac{1}{V^{2}}\, \frac{d^{2} E_2}{dt^{2}} \\ + &= -\frac{4 \pi^{2}}{\lambda^{2}}\, E_2, +\end{align*} +or if $E_2$~varies as~$\cos n\theta$, +\[ +\frac{d^{2} E_2}{dr^{2}} + + \frac{1}{r}\, \frac{d E_2}{dr} + + \left( \frac{4 \pi^{2}}{\lambda^{2}} - \frac{n^{2}}{r^{2}} \right) E_2 = 0. +\] + +The solution of which outside the cylinder is +\[ +E_2 = A_n \cos{n\theta} K_n \left( \frac{2 \pi}{\lambda} r \right) \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt}, +\] +where $K_n$~represents the `external' Bessel's function of the $n$\textsuperscript{th}~order. + +Thus +\begin{multline*} +E_2 = \left\{A_0 K_0 \left( \frac{2 \pi}{\lambda} r \right) + + A_1 \cos \theta K_1 \left( \frac{2 \pi}{\lambda} r \right) \right. \\ + \left. + A_2 \cos 2 \theta K_2 \left( \frac{2 \pi}{\lambda} r \right) + \ldots \right\} \epsilon^{\frac{\iota 2\pi}{\lambda} Vt}. +\end{multline*} + +Now since the cylinder is a good conductor, the total tangential +electromotive intensity must vanish over its surface, see Arts.\ \artref{300}{300}~and~\artref{301}{301}. +Hence if $c$~is the radius of the cylinder, $E_1 + E_2 = 0$ +when $r = c$; from this condition we get +\[ +A_0 = -\frac{1}{K_0 \left( \dfrac{2 \pi}{\lambda} c \right) }, \quad +A_1 = -\frac{\iota 2 \pi c}{\lambda K_1 \left( \dfrac{2 \pi}{\lambda} c \right) }, \quad +A_2 = A_3 = \ldots = 0. +\] + +Thus +\[ +E_2 = \left\{-\frac{K_0 \left( \dfrac{2 \pi}{\lambda} r \right)} + {K_0 \left( \dfrac{2 \pi}{\lambda} c \right)} + - \frac{\iota 2 \pi c}{\lambda} \cos \theta + \frac{K_1 \left( \dfrac{2 \pi}{\lambda} r \right)} + {K_1 \left( \dfrac{2 \pi}{\lambda} c \right)} \right\} + \epsilon^{\frac{\iota 2 \pi}{\lambda} Vt}. +\] + +\Article{362} Let us first consider the effect of the cylinder on the +lines of magnetic force in its neighbourhood. If $\alpha$,~$\beta$ are the +%% -----File: 444.png---Folio 430------- +components of the magnetic force parallel to the axes of $x$~and~$y$ +respectively, $E$~the total electromotive intensity, then +\begin{align*} +\frac{dE}{dx} &= \frac{d\beta}{dt} = \iota \frac{2\pi}{\lambda} V \beta, \\ +\frac{dE}{dy} &= -\frac{d\alpha}{dt} = - \iota \frac{2\pi}{\lambda} V \alpha. +\end{align*} + +Thus the direction of the magnetic force will be tangential to +the curves over which $E$~is constant, the equations to the lines of +magnetic force in the neighbourhood of the cylinder are therefore +\[ +\left\{\left( + 1 - \frac{K_0 \left(\dfrac{2\pi}{\lambda} r\right)} + {K_0 \left(\dfrac{2\pi}{\lambda} c\right)}\right) + + \iota \frac{2\pi}{\lambda} \cos{\theta} + \left( r - c \frac{K_1 \left(\dfrac{2\pi}{\lambda} r\right)} + {K_1 \left(\dfrac{2\pi}{\lambda} c\right)}\right) \right\} + \epsilon^{\frac{\iota 2 \pi}{\lambda}Vt} = C, +\] +where $C$~is independent of $r$~and~$\theta$. + +Now $2\pi c/\lambda$~is by hypothesis very small, and when $x$~is small +then, by \artref{261}{Art.~261}, the values of $K_0$~and~$K_1$ are given approximately +by the equations +\begin{align*} +K_0(x) &= \log (2\gamma/x), \\ +K_1(x) &= - K_0'(x) = \frac{1}{x}, +\end{align*} +where $\gamma$~is Euler's constant and $\log \gamma$ is equal to~$.5772157$. + +In the neighbourhood of the cylinder $r/\lambda$~is small as well as~$c/\lambda$, +so that in this region the equations to the lines of magnetic +force are, approximately, +\[ +\frac{\log{(r/c)}}{\log{(\gamma\lambda/\pi c)} } \cos{\frac{2\pi}{\lambda} Vt} + + \frac{2\pi}{\lambda} \cos{\theta \frac{(c^2 - r^2)}{r}} \sin{\frac{2\pi}{\lambda} Vt} = C. +\] + +In this expression the coefficient of $\cos (2\pi Vt/\lambda)$ is very large +compared with that of $\sin (2\pi Vt/\lambda)$, so that unless $2\pi Vt / \lambda$ is an +odd multiple of~$\pi/2$, that is, unless the intensity in the incident +wave at the axis of the cylinder vanishes, the equations to the +lines of magnetic force are +\[ +\log{(c/r)} = \text{a constant}, +\] +so that these lines are circles concentric with the cylinders. + +When $2\pi Vt/\lambda$~is an odd multiple of~$\pi/2$, the lines of magnetic +force are given by the equation +\[ +\cos \theta \frac{(c^2 - r^2)}{r} = C, +\] +%% -----File: 445.png---Folio 431------- +or in Cartesian coordinates +\[ +x \left\{c^2 - (x^2 + y^2) \right\} = C (x^2 + y^2); +\] +these curves are shown in \figureref{fig121}{Fig.~121}. + +\includegraphicsmid{fig121}{Fig.~121.} + +\Article{363} Since the direction of motion of the Faraday tubes is at +right angles to themselves and to the magnetic force, when the +lines of magnetic force near the cylinder are circles, these tubes +will, in the neighbourhood of the cylinder, move radially, the +positive tubes (i.e.~those parallel to the tubes in the incident +wave) moving inwards, the negative ones outwards. In the +special case where the electromotive intensity vanishes at the +axis of the cylinder, the incident wave throws tubes of one sign +into the half of the cylinder in front, where $x$~is positive, and +tubes of opposite sign into the half in the rear, where $x$~is +negative; in this case, if the positive tubes in the neighbourhood +of the cylinder are moving radially inwards in front, they are +moving radially outwards in the rear and \textit{vice versâ}; there are +in this case but few tubes near the equatorial plane, and the +motion of these is no longer radial. + +\Article{364} When the distance from the cylinder is large compared +with the wave length, we have +\begin{align*} +K_0 \left(\frac{2\pi}{\lambda} r \right) &= \tfrac{1}{2} \iota^{\frac{1}{2}} \frac{\epsilon^{-\iota 2 \pi r / \lambda}}{(r/\lambda)^{\frac{1}{2}}}, \\ +K_1 \left(\frac{2\pi}{\lambda} r \right) &= -\tfrac{1}{2} \iota^{\frac{3}{2}} \frac{\epsilon^{-\iota 2 \pi r / \lambda}}{(r/\lambda)^{\frac{1}{2}}}. +\end{align*} +%% -----File: 446.png---Folio 432------- + +Thus in the wave `scattered' by the cylinder +\[ +E_2 = - \frac{\epsilon^{-\iota \frac{2\pi}{\lambda} \left(r-Vt-\frac{\lambda}{8}\right)}} + {2(r/\lambda)^{\frac{1}{2}}} + \left\{\frac{1}{\log(\gamma\pi\lambda/c)} + \frac{4\pi^2c^2}{\lambda^2} \cos \theta\right\}. +\] + +Thus in this case, as we should expect, the part of the scattered +wave which is independent of the azimuth is very much larger +than the part which varies with~$\theta$, so that there is no direction in +which the intensity of the scattered light vanishes. In this respect +the metal cylinder resembles one made of a non-conductor, the +effect of which on a train of waves has been investigated by Lord +Rayleigh (\textit{Phil.\ Mag.}\ [5], 12, p.~98, 1881): there are however +\index{Rayleigh, Lord, scattering of light by fine particles@\subdashtwo scattering of light by fine particles}% +some important differences between the two cases; in the first +place we see that since $c$~occurs in the leading term only as a +logarithm, the amount of light scattered by the cylinder changes +very slowly with the dimensions of the cylinder, while in the +light scattered from a dielectric cylinder the electromotive intensity +in the scattered wave is proportional to the area of the +cross-section of the cylinder. Again, when the cylinder is a good +conductor the electromotive intensity in the scattered wave, if +we regard the logarithmic term as approximately constant, varies +as~$\lambda^{\frac{1}{2}}$ and so increases with the wave length, while when the +cylinder is an insulator the electromotive intensity varies as~$\lambda^{-\frac{3}{2}}$, +so that the scattering \emph{decreases} rapidly as the length of the wave +increases. The most interesting case of this kind is when the +wave incident on the cylinder is a wave of light; in this case the +theory indicates that the light scattered by the metallic cylinder +would be slightly reddish, while that from the insulating cylinder +would be distinctly blue; the blue in the latter case would be +much more decided than the red of the previous one, since the +variation of the intensity of the scattered light with the wave +length is much more rapid when the cylinder is an insulator +than when it is a good conductor. + +\Article{365} We shall now proceed to consider the case when the +electromotive intensity in the incident wave is at right angles to +the axis of the cylinder. This case is of more interest than the +preceding because the general features of the results obtained +will apply to the scattering of light by particles limited in every +direction; it is thus representative of the scattering by small +particles in general, while the peculiarities of the case discussed +%% -----File: 447.png---Folio 433------- +in the preceding \artref{364}{article} were due to the cylindrical shape of the +obstacle. The only case to which the results of this article would +not be applicable without further investigation is that in which +the particles are highly magnetic, and we shall find that even +this case constitutes no exception since our results do not involve +the magnetic permeability of the cylinder. + +As the electromotive intensity is at right angles to the axis of +the cylinder, the magnetic force will be parallel to the axis. + +Let the magnetic force~$H_1$ in the incident wave be expressed +by the equation +\[ +H_1 = \epsilon^{\frac{\iota 2\pi}{\lambda} (Vt+x)}. +\] +When $x$ which is equal to $r \cos \theta$ is small compared with~$\lambda$, this +is approximately +\[ +H_1 = \epsilon^{\frac{\iota 2\pi}{\lambda} Vt} + \left\{1 - \frac{\pi^2}{\lambda^2} r^2 + + \frac{\iota 2\pi}{\lambda} r \cos \theta + - \frac{\pi^2}{\lambda^2} r^2 \cos 2\theta\right\}. +\] + +Since $H$, the magnetic force, satisfies the differential equation +\[ +\frac{d^2H}{dx^2} + \frac{d^2H}{dy^2} = \frac{1}{V^2}\, \frac{d^2H}{dt^2}, +\] +the magnetic force~$H_2$ due to the currents induced in the cylinder +may be expressed by the equation +\[ +H_2 = \epsilon^{\frac{\iota 2\pi}{\lambda} Vt} + \left\{A_0K_0\left(\frac{2\pi}{\lambda} r\right) + + A_1 \cos \theta K_1\left(\frac{2\pi}{\lambda} r\right) + + A_2 \cos 2\theta K_2\left(\frac{2\pi}{\lambda} r\right)\right\}, +\] +where $A_0$,~$A_1$ and~$A_2$ are arbitrary constants. + +The condition to be satisfied at the boundary of the cylinder +is that the tangential electromotive intensity at its surface should +vanish. In this case we have, however, +\[ +\frac{d}{dr}(H_1 + H_2) = 4\pi \text{ (intensity of current at right angles to~$r$)}. +\] + +The current in the dielectric is a polarization current, and +if $E$~is the tangential electromotive intensity, the intensity of +this current at right angles to~$r$ is +\[ +\frac{K}{4\pi}\, \frac{dE}{dt}, +\] +which is equal to +\[ +\frac{K}{4\pi}\, \frac{\iota 2\pi}{\lambda}\, VE. +\] + +Thus the condition that $E$~should vanish at the surface is +%% -----File: 448.png---Folio 434------- +equivalent to the condition that +\[ +\frac{d}{dr} (H_1 + H_2) = 0 +\] +when $r = c$, $c$~being the radius of the cylinder. + +From this condition we get +\begin{align*} +-2c \frac{\pi^2}{\lambda^2} + A_0 \frac{d}{dc} K_0 \left(\frac{2\pi}{\lambda} c\right) &= 0, \\ + \frac{\iota 2\pi}{\lambda} + A_1 \frac{d}{dc} K_1 \left(\frac{2\pi}{\lambda} c\right) &= 0, \\ +-2c \frac{\pi^2}{\lambda^2} + A_2 \frac{d}{dc} K_2 \left(\frac{2\pi}{\lambda} c\right) &= 0. +\end{align*} + +Since $2\pi c/\lambda$ is very small and therefore approximately +\begin{align*} +K_0 \left(\frac{2\pi}{\lambda} c\right) &= \log\left(2\gamma\bigg{/}\frac{2\pi c}{\lambda}\right), \\ +K_1 \left(\frac{2\pi}{\lambda} c\right) &= \frac{\lambda}{2\pi c}, \\ +K_2 \left(\frac{2\pi}{\lambda} c\right) &= \frac{\lambda^2}{2\pi^2c^2}, +\end{align*} +we get +\begin{align*} +A_0 &= -2\pi^2 \frac{c^2}{\lambda^2}, \\ +A_1 &= \iota 4\pi^2 \frac{c^2}{\lambda^2}, \\ +A_2 &= -2\pi^4 \frac{c^4}{\lambda^4}. +\end{align*} + +Thus the magnetic force due to the currents induced in the +cylinder is given by the equation +\begin{multline*} +H_2 = 2\pi^2 \frac{c^2}{\lambda^2}\, \epsilon^{\frac{\iota 2\pi}{\lambda} Vt} + \biggl\{-K_0\Bigl(\frac{2\pi}{\lambda} r\Bigr) + + 2\iota \cos \theta K_1\Bigl(\frac{2\pi}{\lambda} r\Bigr)\\ + - \frac{\pi^2c^2}{\lambda^2} \cos 2\theta K_2 \Bigl(\frac{2\pi}{\lambda} r\Bigr)\biggr\}. +\end{multline*} + +\Article{366} To draw the lines of electromotive intensity, we notice +that if $ds$~is an element of a curve in the dielectric, $d(H_1 + H_2)/ds$ +is proportional to the electromotive intensity at right angles +to~$ds$, so that the lines of electromotive intensity will be the +lines +\[ +H_1 + H_2 = \text{a constant}. +\] +%% -----File: 449.png---Folio 435------- + +When $r/\lambda$ is small, this condition leads to the equation +\begin{multline*} +\epsilon^{\frac{\iota 2\pi}{\lambda} Vt} + \left[1 - \frac{\pi^2}{\lambda^2} r^2 + - \frac{2\pi^2c^2}{\lambda^2} K_0\left(\frac{2\pi}{\lambda} r\right) + + \frac{2\iota\pi}{\lambda} \cos \theta + \left\{r + \frac{2\pi}{\lambda} c^2 K_1 \left(\frac{2\pi}{\lambda} r\right)\right\} \right. \\ + \left. - \frac{\pi^2}{\lambda^2} \cos 2\theta + \left\{r^2 + \frac{2\pi^2c^4}{\lambda^2} K_2 \left(\frac{2\pi}{\lambda} r\right)\right\}\right] = C, +\end{multline*} +where $C$~is a constant. + +Substituting the approximate values of $K_0$,~$K_1$ and~$K_2$ this +becomes +\begin{multline*} +\epsilon^{\frac{\iota 2\pi}{\lambda} Vt} + \left[1 - \frac{\pi^2}{\lambda^2} r^2 + + \frac{2\pi^2c^2}{\lambda^2} \log(\pi r/\gamma\lambda) + + \frac{2\iota\pi}{\lambda} \cos \theta \frac{(r^2+c^2)}{r} \right. \\ + \left. - \frac{\pi^2}{\lambda^2} \cos 2\theta \left(r^2 + \frac{c^4}{r^2}\right)\right] = C. +\end{multline*} +Except when $\epsilon^{\frac{\iota 2\pi}{\lambda} Vt/\lambda}$ is wholly real, i.e.~except when the rate +of variation of the magnetic force in the incident wave at the axis +of the cylinder vanishes, by far the most important term is that +which contains $\cos \theta$, so that the equations to the lines of electromotive +intensity are +\[ +\frac{c^2 + r^2}{r} \cos \theta = \text{a constant} = C', \text{ say.} +\] + +\includegraphicsmid{fig122}{Fig.~122.} + +The lines of electromotive intensity are represented in \figureref{fig122}{Fig.~122}. + +At the times when $\epsilon^{\iota 2\pi Vt/\lambda}$ is wholly real, the lines are approximately +circles concentric with the cross-section of the +cylinder, since in this case the term involving the logarithm is +the most important of the variable terms. +%% -----File: 450.png---Folio 436------- + +\Article{367} When $r$~is large compared with~$\lambda$, we find by introducing +the values of the $K$~functions when the argument is very +large, viz.\ +\begin{gather*} +\begin{aligned} +K_0(x) & = \iota^{\frac{1}{2}} \left( \frac{\pi}{2 x} \right)^{\frac{1}{2}} \epsilon^{-\iota x},\\ +K_1(x) & = -\iota^{\frac{3}{2}} \left( \frac{\pi}{2 x} \right)^{\frac{1}{2}} \epsilon^{-\iota x}, +\end{aligned} \\ +H_2 = -\frac{\pi^{2} c^{2}}{r^{\frac{1}{2}}\lambda^{\frac{3}{2}}}\, + \epsilon^{\frac{\iota 2 \pi}{\lambda}\left( Vt-r+ \frac{\lambda}{8} \right) } + (1 + 2 \cos \theta), +\end{gather*} +retaining only the lowest powers of~$c/\lambda$. + +Thus the magnetic force in the scattered wave vanishes when +$2 \cos \theta = -1$, or in a direction making an angle of~$120°$ with the +incident ray. When the wave is scattered by an insulating +cylinder Lord Rayleigh (l.c.)\ found that the magnetic intensity +in the scattered ray was expressed by a similar formula \emph{with the +exception that the factor $(1 + 2 \cos \theta)$ was replaced by $\cos \theta$}. Thus, +if we take the case where the incident wave is a luminous one, +the scattered light will vanish in the direction of the electric +displacement when the particles are insulators, while it will +vanish in a direction making an angle of~$30°$ with this direction +if the particles are metallic. If the incident light is not +polarized, then with metallic particles the scattered light will +be completely polarized in a direction making~$120°$ with the +direction of propagation of the incident light, while if the particles +are insulators the direction in which the polarization is +complete is at right angles to the direction of the incident light. +The observations of Tyndall, Brücke, Stokes, and Lord Rayleigh +afford abundant proof of the truth of the last statement: but no +experiments seem to have been published on the results of the +reflection of light from small metallic particles. + +\Article{368} The preceding results have also an important application +to the consideration of the influence of the size of the reflector on +the intensity of reflected electromagnetic waves. When the +electromotive intensity is parallel to the axis of the cylinder, the +most important term in the expression for the reflected wave +only involves the radius of the cylinder as a logarithm, it will +thus only vary slowly with the radius, so that in this case the +size of the cylinder is of comparatively little importance: hence +we may conclude that we shall get good reflection if the length +%% -----File: 451.png---Folio 437------- +of the reflector measured in the direction of the electromotive +intensity is considerable, whatever may be the breadth of the +reflector at right angles to the electromotive intensity. On the +other hand, when the electromotive intensity is at right angles +to the axis of the cylinder, the electromotive intensity in the +scattered wave increases as the square of the radius of the +cylinder, so that in this case the size of the reflector is all important. +These results are confirmed by Trouton's experiments +\index{Trouton, influence of size of reflector on Hertz's experiments@\subdashone influence of size of reflector on Hertz's experiments}% +on `The Influence the Size of the Reflector exerts in Hertz's +Experiment,' \textit{Phil.\ Mag.}~[5], 32, p.~80, 1891. + +\Subsection{On the Scattering of Electric Waves by Metallic Spheres.} +\index{Electromagnetic waves, xscattering of by a metal sphere@\subdashtwo scattering of by a metal sphere}% +\index{Light, zscattering of by metallic spheres@\subdashtwo of by metallic spheres}% +\index{Scattering of electromagnetic waves by a sphere@\subdashone of electromagnetic waves by a sphere}% +\index{Sphere, zzscattering of light by@\subdashone scattering of light by}% +\index{Waves, electromagnetic, scattering of from spheres@\subdashtwo scattering of from spheres}% + +\Article{369} We shall proceed to discuss in some detail the problem +of the incidence of a plane electric wave upon a metal sphere\footnotemark. +\index{Michell, plane electromagnetic waves}% + \footnotetext{The scattering by an insulating sphere is discussed by Lord Rayleigh (\textit{Phil.\ Mag.}~12, + p.~98, 1881). The incidence of a plane wave on a sphere was the subject of a dissertation + sent in to Trinity College, Cambridge, by Professor Michell in 1890. I do not know + of any papers which discuss the special problem of the scattering by \emph{metal} spheres.} + +If $\alpha$,~$\beta$,~$\gamma$; $f$,~$g$,~$h$ are respectively the components of the +magnetic force and of the polarization in the dielectric which +are radiated from the sphere, then if $\psi$~stands for any one of +these quantities it satisfies a differential equation of the form +\[ +\frac{d^{2} \psi}{dx^{2}} + \frac{d^{2} \psi}{dy^{2}} + \frac{d^{2} \psi}{dz^{2}} + = \frac{1}{V^{2}}\, \frac{d^{2} \psi}{dt^{2}}, +\Tag{1} +\] +where $V$~is the velocity with which electric action is propagated +through the dielectric surrounding the sphere. If $\lambda$~is the wave +length of the disturbance incident upon the sphere, then the +components of magnetic induction and of electric polarization +will all vary as $\epsilon^{\frac{\iota 2 \pi}{\lambda} Vt}$; thus $V^{-2} d^{2} \psi / dt^{2}$ may be replaced by +$-4 \pi^{2} \psi / \lambda^{2}$, so that writing~$k$ for~$2 \pi / \lambda$, equation~(\eqnref{369}{1}) may be +written +\[ +\frac{d^{2} \psi}{dx^{2}} + \frac{d^{2} \psi}{dy^{2}} + \frac{d^{2} \psi}{dz^{2}} + k^{2} \psi = 0, +\] +a solution of which is by \artref{308}{Art.~308}, +\[ +\psi = \epsilon^{\iota kVt} \tsum f_n(kr)S_n, +\] +where $r$~is the distance from the centre of the sphere. Since the +waves of magnetic force and dielectric polarization are radiating +outwards from the sphere +\[ +f_n(kr) = \left( \frac{1}{kr}\, \frac{d}{d(kr)} \right)^{n} + \frac{\epsilon^{-\iota kr}}{kr}, +\] +%% -----File: 452.png---Folio 438------- +$S_n$~is a solid spherical harmonic of degree~$n$. It should be noted +that $f_n (kr)$ of this article is $(kr)^{-n} f(kr)$ of \artref{308}{\DPtypo{article}{Article}~308}. + +\Article{370} We shall now prove a theorem due to Professor Lamb +\index{Lambx@Lamb's theorem}% +(\textit{Proc.\ Lond.\ Math.\ Soc.}~13, p.~189, 1881), that if $\alpha$,~$\beta$,~$\gamma$ satisfy +equations of the form~(\eqnref{369}{1}), and if +\[ +\frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} = 0; +\] +then the most general solution of these equations is given by +\[ +\left. + \begin{aligned} + \alpha = \tsum \left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dx} - nk^2r^{2n+3} f_{n+1} (kr) \frac{d}{dx}\, \frac{\omega_n}{r^{2n+1}}\right\}\qquad \\ + + \tsum f_n (kr)\left(y \frac{d}{dz} - z \frac{d}{dy}\right)\omega'_n,\\ + \beta = \tsum \left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dy} - nk^2r^{2n+3} f_{n+1} (kr) \frac{d}{dy}\, \frac{\omega_n}{r^{2n+1}}\right\}\qquad \\ + + \tsum f_n (kr)\left(z \frac{d}{dx} - x \frac{d}{dz}\right)\omega'_n,\\ + \gamma = \tsum \left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dz} - nk^2r^{2n+3} f_{n+1} (kr) \frac{d}{dz}\, \frac{\omega_n}{r^{2n+1}}\right\}\qquad \\ + + \tsum f_n (kr)\left(x \frac{d}{dy} - y \frac{d}{dx}\right)\omega'_n.\\ + \end{aligned} +\right\} +\Tag{2} +\] +where $\omega_n$,~$\omega'_n$ represent arbitrary solid spherical harmonics of +degree~$n$. + +Since +\[ +\frac{d\omega_n}{dx}, \qquad +\frac{d}{dx}\, \frac{\omega_n}{r^{2n+1}}, \qquad +\left(y \frac{d}{dz} - z \frac{d}{dy}\right)\omega'_n +\] +are solid spherical harmonics of degrees $(n - 1)$,~$-(n + 1)$,~$n$ respectively, +we see that the expression given for~$\alpha$ satisfies the +differential equation~(\eqnref{369}{1}); similarly this equation is satisfied by +the values of $\beta$~and~$\gamma$. + +Let us now find the value of $d\alpha/dx + d\beta/dy + d\gamma/dz$; we notice +that the terms involving~$\omega'_n$ vanish identically, and since +\[ +\nabla^2(\omega_n) = 0, \quad +\nabla^2 \frac{\omega_n}{r^{2n+1}} = 0, +\] +we have +\begin{multline*} +\frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} + = \tsum (n+1) \frac{k}{r} f'_{n-1} (kr)\left\{x \frac{d}{dx} + y \frac{d}{dy} + z \frac{d}{dz}\right\}\omega_n \\ + - \tsum [nk^3r^{2n+2} f'_{n+1} (kr) + n(2n+3)k^2r^{2n+1} f_{n+1} (kr)] × \\ + \left\{x \frac{d}{dx} + y \frac{d}{dy} + z \frac{d}{dz}\right\} \frac{\omega_n}{r^{2n+1}} \\ + = \tsum n \centerdot n+1 \centerdot \frac{k}{r} + \{f'_{n-1} (kr) + k^2r^2f'_{n+1} (kr) + (2n+3)krf_{n+1} (kr)\} \omega_n. +\end{multline*} +%% -----File: 453.png---Folio 439------- + +Now +\[ +f_n (kr) = \left( \frac{1}{kr}\, \frac{d}{d(kr)} \right)^{n} \frac{\epsilon^{-\iota kr}}{kr}, +\] +hence +\[ +f'_{n-1} (kr) = kr\, f_n (kr). +\Tag{3} +\] +We have also +\[ +f''_n (kr) + \frac{2(n+1)}{kr}\, f'_n (kr) + f_n (kr) = 0, +\] +which may be written as +\begin{align*} +\frac{d}{d(kr)} \{kr\, f'_n (kr) + (2n+1) f_n (kr) \} + &= -kr\, f_n (kr)\\ + &= -f'_{n-1} (kr) \text{ by (\eqnref{370}{3})}; +\end{align*} +hence, since the constant of integration must vanish since all the~$f$'s +involve~$\epsilon^{-\iota kr}$, +\[ +kr\, f'_n (kr) + (2n+1) f_n (kr) = - f_{n-1} (kr), +\Tag{4} +\] +and by~(\eqnref{309}{101}), \artref{308}{Art.~\DPtypo{308}{309}}, +\[ +(2n+1) f_n (kr) = -\{f_{n-1} (kr) + k^{2} r^{2}\, f_{n+1} (kr) \}. +\Tag{5} +\] +Writing $(n+1)$ for~$n$ in~(\eqnref{370}{4}), we have +\begin{align*} +kr\, f'_{n+1} (kr) + (2n+3) f_{n+1} (kr) &= -f_n (kr)\\ + &= -\frac{f'_{n-1} (kr)}{kr}. +\Tag{6} +\end{align*} +From this equation we see that +\[ +\frac{d \alpha}{dx} + \frac{d \beta}{dy} + \frac{d \gamma}{dz} = 0. +\] + +To prove that equation~(\eqnref{370}{2}) gives the most general expressions +for $\alpha$,~$\beta$,~$\gamma$, we notice that the values of $\alpha$,~$\beta$ may be written +\[ +\left.\begin{aligned} +\alpha = \tsum f_{n} (kr) \left[ \left\{(n+2) \frac{d \omega_{n+1}}{dx} + - (n-1) k^{2} r^{2n+1} \frac{d}{dx}\, \frac{\omega_{n-1}}{r^{2n-1}} \right\} \right. \\ + + \left. \left( y \frac{d}{dz} - z \frac{d}{dy} \right) \omega'_{n} \right], \\ +\beta = \tsum f_n (kr) \left[ \left\{(n+2) \frac{d \omega_{n+1}}{dy} + - (n-1) k^{2} r^{2n+1} \frac{d}{dy}\, \frac{\omega_{n-1}}{r^{2n-1}} \right\} \right. \\ + + \left. \left( z \frac{d}{dx} - x \frac{d}{dz} \right) \omega'_{n} \right]. +\end{aligned}\right\} +\Tag{7} +\] + +The most general expressions for $\alpha$,~$\beta$, when they represent +radiation outwards from the sphere, may however, \artref{308}{Art.~308}, be +expressed in the form +\[ +\left.\begin{aligned} +\alpha & = \tsum f_{n} (kr) U_{n},\\ +\beta & = \tsum f_{n} (kr) V_{n}, +\end{aligned} \right\} +\Tag{8} +\] +where $U_{n}$,~$V_{n}$ are solid spherical harmonics of degree~$n$. Since +%% -----File: 454.png---Folio 440------- +$\omega_n$~and~$\omega'_n$ are arbitrary, we may determine them so as to make +the values of $\alpha$~and~$\beta$ given by~(\eqnref{370}{7}) agree with those given by~(\eqnref{370}{8}). +Thus (\eqnref{370}{7})~are sufficiently general expressions for $\alpha$,~$\beta$, and +when $\alpha$~and~$\beta$ are given $\gamma$~follows from the equation +\[ +\frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} = 0. +\] + +\Article{371} If $\alpha$,~$\beta$,~$\gamma$ represent the components of the magnetic +force, $f$,~$g$,~$h$ the components of the electric polarization are, in a +dielectric, given by the equations +\begin{align*} +4\pi \frac{df}{dt} & = \frac{d\gamma}{dy} - \frac{d\beta}{dz}, \\ +4\pi \frac{dg}{dt} & = \frac{d\alpha}{dz} - \frac{d\gamma}{dx}, \\ +4\pi \frac{dh}{dt} & = \frac{d\beta}{dx} - \frac{d\alpha}{dy}. +\end{align*} + +Taking the values of $\beta$~and~$\gamma$ given in~(\eqnref{370}{2}), we see that the +term in $4\pi df/dt$ involving~$\omega_n$ is equal to +\begin{multline*} +\left\{(n+1) \frac{k}{r} f'_{n-1}(kr) - nk^3 rf'_{n+1}(kr) - n(2n+3) k^2 f_{n+1}(kr) \right\} × \\ + \left\{y \frac{d\omega_n}{dz} - z \frac{d\omega_n}{dy} \right\}, +\end{multline*} +and this by equations (\eqnref{370}{4})~and~(\eqnref{370}{6}) is equal to +\[ +(2n+1)k^2 f_n(kr) \left\{y \frac{d\omega_n}{dz} - z \frac{d\omega_n}{dy} \right\}. +\] + +Let us now consider the term in~$4\pi df/dt$ involving~$\omega_n'$; this +equals +\begin{multline*} +f_n(kr) \left\{-2 \frac{d}{dx} - \left(x \frac{d}{dx} + y \frac{d}{dy} + z \frac{d}{dz}\right) \frac{d}{dx}\right\} \omega'_n \\ + + f'_n(kr)k \left( x \frac{d}{dr} - r \frac{d}{dx} \right) \omega'_n \\ + = -(n+1) f_n(kr) \frac{d\omega'_n}{dx} + rk\, f'_n(kr) \frac{nx}{r^2} \omega'_n - kr\, f'_n(kr) \frac{d\omega'_n}{dx}, +\end{multline*} +this by equations (\eqnref{370}{4})~and~(\eqnref{370}{6}) equals +\begin{multline*} +- \frac{n+1}{2n+1} \left\{\bigl(k^2 r^2 f_{n+1}(kr) + f_{n-1}(kr)\bigr) - k^2 r^2 f_{n+1}(kr) \right\} \frac{d\omega'_n}{dx} \\ + + rk\, f'_n(kr) \frac{nx}{r^2} \omega'_n \\ + = \frac{1}{(2n+1)} \left\{(n+1) f_{n-1}(kr) \frac{d\omega'_n}{dx} - nk^2 r^{2n+3} f_{n+1}(kr) \frac{d}{dx}\, \frac{\omega'_n}{r^{2n+1}} \right\}. +\end{multline*} +%% -----File: 455.png---Folio 441------- + +Thus if $\alpha$,~$\beta$,~$\gamma$ are given by~(\eqnref{370}{2}), then we have +\begin{multline*} +4\pi \frac{df}{dt} = \tsum \frac{1}{2n+1} \left\{(n+1) f_{n-1} (kr) \frac{d\omega'_n}{dx} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dx}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum (2n+1) k^2 f_n (kr) \left(y \frac{d\omega_n}{dz} - z \frac{d\omega_n}{dy}\right), +\end{multline*} +\begin{multline*} +4\pi \frac{dg}{dt} = \tsum \frac{1}{2n+1} \left\{(n+1) f_{n-1} (kr) \frac{d\omega'_n}{dy} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dy}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum (2n+1) k^2 f_n (kr) \left(z \frac{d\omega_n}{dx} - x \frac{d\omega_n}{dz}\right), +\end{multline*} +\begin{multline*} +4\pi \frac{dh}{dt} = \tsum \frac{1}{2n+1} \left\{(n+1) f_{n-1} (kr) \frac{d\omega'_n}{dz} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dz}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum (2n+1) k^2 f_n (kr) \left(x \frac{d\omega_n}{dy} - y \frac{d\omega_n}{dx}\right). +\end{multline*} + +\Article{372} In the plane electrical wave incident on the sphere, let +us suppose that the electric polarization~$h_0$ in the wave front +is parallel to~$z$ and expressed by the equation +\[ +h_0 = \epsilon^{\frac{\iota 2\pi}{\lambda} (Vt+x)} = \epsilon^{\iota k(Vt+x)}, +\] +where the axis of~$x$ is at right angles to the wave front. + +We have to expand~$h_0$ in the form +\[ +\epsilon^{\iota kVt} \tsum A_n Q_n, +\] +where $Q_n$~is a zonal harmonic of degree~$n$ whose axis is the axis +of~$x$ and $A_n$~is a function of~$r$ which we have to determine. + +Since +\[ +\epsilon^{\iota kx} = \tsum A_n Q_n, +\] +and since it satisfies the equation +\[ +\frac{d^2\psi}{dx^2} + \frac{d^2\psi}{dy^2} + \frac{d^2\psi}{dz^2} + k^2\psi = 0, +\] +and is finite when $r = 0$, we see by \artref{308}{Art.~308} that +\[ +A_n = A_n' S_n (kr) + = A_n' (kr)^n \left\{\frac{1}{kr}\, \frac{d}{d(kr)}\right\}^n \frac{\sin kr}{kr}, +\] +where $A_n'$~is independent of~$r$. + +\begin{DPgather*} +\lintertext{\indent Since} +\frac{\sin kr}{kr} = 1 - \frac{k^2 r^2}{3!} + \frac{k^4 r^4}{5!} - \ldots, +\end{DPgather*} +we see that when $kr$~is very small +\[ +A_n = (-1)^n A_n'\, \frac{(kr)^n}{(2n+1)(2n-1) \ldots 1}. +\Tag{9} +\] +%% -----File: 456.png---Folio 442------- + +But if $x/r = \mu$, we have +\begin{gather*} +\epsilon^{\iota k r \mu} = \tsum A_n Q_n, \\ +\therefore \int_{-1}^{+1} \epsilon^{\iota k r \mu} Q_n\,d\mu + = A_n \int_{-1}^{+1} Q_n^2\,d\mu = \frac{2 A_n}{2n + 1}. +\end{gather*} + +The lowest power of~$kr$ on the left-hand side of this equation +is the~$n$\textsuperscript{th}, the coefficient of this is equal to +\[ +\frac{\iota^n}{\nbfactorial{n}} \int_{-1}^{+1} \mu^n Q_n\,d\mu + = \frac{2 \iota^n}{(2n + 1)(2n - 1)(2n - 3) \ldots 1}; +\] +hence when $kr$~is small we have +\[ +\frac{2 \iota^n (kr)^n}{(2n + 1)(2n - 1) \ldots 1} = \frac{2 A_n}{2n + 1} +\] +Comparing this equation with~(\eqnref{372}{9}) we see that +\begin{DPalign*} +A_n' & = \frac{(2n + 1)}{\iota^n}, \\ +A_n & = \frac{2n + 1}{\iota^n} S_n(kr), \\ +\lintertext{so that} +\epsilon^{\iota k r \mu} &= \tsum \frac{2n + 1}{\iota^n} S_n(kr) Q_n. +\end{DPalign*} +This expression is given by Lord Rayleigh (\textit{Theory of Sound}, +\index{Rayleigh@Rayleigh, Lord, \textit{Theory of Sound}}% +ii.\ p.~239). + +By equation~(\eqnref{309}{101}) of \DPtypo{\artref{308}{Art.~308}}{\artref{309}{Art.~309}} we have +\[ +\frac{A_{n-1}}{2n - 1} - \frac{A_{n+1}}{2n + 3} = \frac{1}{\iota k r} A_n. +\Tag{10} +\] +This can also be proved directly thus, +\begin{align*} +\frac{A_{n-1}}{2n - 1} + & = \tfrac{1}{2} \int_{-1}^{+1} \epsilon^{\iota k r \mu} Q_{n-1}\,d\mu, \\ +\frac{A_{n+1}}{2n + 3} + & = \tfrac{1}{2} \int_{-1}^{+1} \epsilon^{\iota k r \mu} Q_{n+1}\,d\mu, +\end{align*} +\begin{multline*} +\frac{A_{n-1}}{2n - 1} - \frac{A_{n+1}}{2n + 3} + = \left[\tfrac{1}{2} \frac{\epsilon^{\iota k r \mu}}{\iota k r}(Q_{n-1} - Q_{n+1})\right]_{-1}^{+1} \\ + - \tfrac{1}{2} \frac{1}{\iota k r} \int_{-1}^{+1} \epsilon^{\iota k r \mu} \left(\frac{dQ_{n-1}}{d\mu} - \frac{dQ_{n+1}}{d\mu}\right) d\mu. +\end{multline*} +The terms within square brackets vanish, and since +\[ +\frac{dQ_{n-1}}{d\mu} - \frac{dQ_{n+1}}{d\mu} = -(2n + 1) Q_n, +\] +%% -----File: 457.png---Folio 443------- +we have +\begin{align*} +\frac{A_{n-1}}{2n-1} - \frac{A_{n+1}}{2n+3} + &= \frac{1}{2\iota kr} \int_{-1}^{+1} (2n+1)\epsilon^{\iota kr\mu} Q_n\,d\mu \\ + &= \frac{A_n}{\iota kr}. +\end{align*} + +\Article{373} It will be convenient to collect together the results we +have obtained. + +In the incident wave, +\[ +f_0 = 0, \qquad g_0 = 0, \qquad +h_0 = \epsilon^{\iota kVt} \tsum \frac{2n+1}{\iota^n} Q_n S_n (kr), +\] +and therefore by \artref{9}{Art.~9}, +\[ +\alpha_0 = 0, \qquad \gamma_0 = 0, \qquad +\beta_0 = 4\pi h_0 V = 4\pi V\, \epsilon^{\iota kVt} \tsum \frac{2n+1}{\iota^n} Q_n S_n (kr). +\] +For the wave scattered by the sphere, omitting the time factor, +we have since $d/dt = \iota kV$ +{\setlength{\multlinegap}{0pt} +\begin{multline*} +4\pi\iota kVf = \tsum \frac{1}{2n+1} + \left\{(n+1)f_{n-1} (kr) \frac{d\omega'_n}{dx} - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dx}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum(2n+1)k^2 f_n (kr)\left(y \frac{d\omega_n}{dz} - z \frac{d\omega_n}{dy}\right), +\end{multline*} +\begin{multline*} +4\pi\iota kVf = \tsum \frac{1}{2n+1} + \left\{(n+1)f_{n-1} (kr) \frac{d\omega'_n}{dy} - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dy}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum(2n+1)k^2 f_n (kr)\left(z \frac{d\omega_n}{dx} - x \frac{d\omega_n}{dz}\right), +\end{multline*} +\begin{multline*} +4\pi\iota kVf = \tsum \frac{1}{2n+1} + \left\{(n+1)f_{n-1} (kr) \frac{d\omega'_n}{dz} - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dz}\, \frac{\omega'_n}{r^{2n+1}}\right\} \\ + + \tsum(2n+1)k^2 f_n (kr)\left(x \frac{d\omega_n}{dy} - y \frac{d\omega_n}{dx}\right). +\end{multline*} +\begin{multline*} +\alpha = \tsum\left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dx} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dx}\, \frac{\omega_n}{r^{2n+1}}\right\} \\ + + \tsum f_n (kr)\left(y \frac{d\omega'_n}{dz} - z \frac{d\omega'_n}{dy}\right), +\end{multline*} +\begin{multline*} +\beta = \tsum\left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dy} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dy}\, \frac{\omega_n}{r^{2n+1}}\right\} \\ + + \tsum f_n (kr)\left(z \frac{d\omega'_n}{dx} - x \frac{d\omega'_n}{dz}\right), +\end{multline*} +\begin{multline*} +\gamma = \tsum\left\{(n+1)f_{n-1} (kr) \frac{d\omega_n}{dz} + - nk^2 r^{2n+3} f_{n+1} (kr) \frac{d}{dz}\, \frac{\omega_n}{r^{2n+1}}\right\} \\ + + \tsum f_n (kr)\left(x \frac{d\omega'_n}{dy} - y \frac{d\omega'_n}{dx}\right). +\end{multline*} +} +%% -----File: 458.png---Folio 444------- + +\Article{374} To determine $\omega_n$,~$\omega_n'$, we shall assume that the sphere is +a perfect conductor and therefore that the electromotive intensity, +and therefore the electric polarization, is at right angles to the +sphere. This condition is satisfied whatever the resistance of +the sphere if the frequency is so great that $kV\mu a^2 /\sigma$ is large; +$a$~being the radius of the sphere, $\sigma$~its specific resistance, and $\mu$~its +magnetic permeability. If $R$~is the normal electromotive +polarization, $\Theta$~that along a tangent to a meridian, $\Phi$~that along +a parallel of latitude, then the condition +\[ +\frac{df}{dx} + \frac{dg}{dy} + \frac{dh}{dz} = 0 +\] +is equivalent to +\[ +\frac{d}{dr} (r^2 R) + + \frac{1}{\sin \theta}\, \frac{d}{d\theta} (r \sin \theta\Theta) + + \frac{1}{\sin \theta}\, \frac{d}{d\phi} (r\Phi) = 0; +\] +but since $\Theta$~and~$\Phi$ vanish all over the sphere, this, if $a$~is the +radius of the sphere, gives the condition +\[ +\frac{d}{dr} (r^2 R) = 0 \text{ when } r = a. +\] + +\begin{DPgather*} +\lintertext{\indent Now} rR = x(f + f_0) + y(g + g_0) + z(h + h_0); +\end{DPgather*} +but +\begin{align*} +4\pi\iota kV(xf + yg + zh) + &= \tsum \frac{n\centerdot(n+1)}{2n+1} \bigl(f_{n-1} (kr) + k^2r^2f_{n+1}(kr)\bigr)\omega_n \\ + &= - \tsum n \centerdot n+1 \centerdot f_n(kr)\omega_n', \text{ by equation~(\eqnref{370}{6})}, \\ +xf_0 + yg_0 + zh_0 + &= z\tsum A_n Q_n, \text{ omitting the time factor}. +\end{align*} + +But if $r$,~$\theta$,~$\phi$ are the polar coordinates of the point whose +Cartesian coordinates are $x$,~$y$,~$z$, +\begin{DPalign*} +z & = r \sin \theta \sin \phi, \\ +\lintertext{and} +Q_n & = \frac{1}{2n+1} \left\{\frac{dQ_{n+1}}{d\mu} - \frac{dQ_{n-1}}{d\mu}\right\}; +\end{DPalign*} +hence, if $\omega_n' = r^n Y_n'$ where $Y_n'$~is a surface harmonic of degree~$n$, +the condition +\[ +\frac{d}{dr} (r^2 R) = 0 \text{ when } r = a +\] +becomes +\begin{multline*} +\frac{1}{4\pi\iota KV} \tsum n \centerdot (n+1)Y_n'\, \frac{d}{da} (a^{n+1} f_n(ka)) + = \sin \theta \sin \phi \tsum Q_n\, \frac{d}{da} (a^2A_n) \\ + = \sin \theta \sin \phi \tsum \frac{dQ_n}{d\mu}\, + \frac{d}{da} \left\{\frac{a^2A_{n-1}}{2n-1} - \frac{a^2 A_{n+1}}{2n+3}\right\}; +\end{multline*} +%% -----File: 459.png---Folio 445------- +but $\sin \theta \sin \phi \dfrac{dQ_n}{d\mu}$ is a surface harmonic of \DPtypo{degrees}{degree}~$n$, hence +\[ +Y_n' = \frac{\sin \theta \sin \phi \dfrac{dQ_n}{d\mu}\, + \dfrac{d}{da} \left\{\dfrac{a^2 A_{n-1}}{2n-1} + - \dfrac{a^2 A_{n+1}}{2n+3}\right\} } + {\dfrac{n\centerdot n+1}{4\pi\iota kV} \centerdot + \dfrac{d}{da} \bigl(a^{n+1} f_n (ka)\bigr) } , +\] +or by~(\eqnref{372}{10}) +\[ +Y_n' = 4\pi V \sin \theta \sin \phi \frac{dQ_n}{d\mu}\, + \frac{\dfrac{d(aA_n)}{da} } + {n \centerdot n+1 \centerdot \dfrac{d}{da} \bigl(a^{n+1} f_n (ka)\bigr) }, +\] +and $\omega_n' = r^n Y_n'$. + +\Article{375} We now proceed to find~$\omega_n$. The line integral of the +electromotive intensity taken round any closed curve is equal to +the rate of diminution of the number of lines of magnetic induction +passing through it: if we take as our closed curve one +drawn on the surface of the sphere, we see, since the tangential +electromotive intensity over the surface of the sphere vanishes, +that the rate of diminution of the normal magnetic induction +also vanishes; this condition, since the induction varies harmonically, +is equivalent to the condition that the normal magnetic +induction vanishes over the surface of the surface; hence when +$r = a$, we have +\[ +x(\alpha + \alpha_0) + y(\beta+\beta_0) + z(\gamma+\gamma_0) = 0. +\Tag{1} +\] +But when $r = a$, +\begin{align*} +x\alpha + y\beta + z\gamma + &= \tsum n \centerdot (n+1)(2n+1)f_n (ka) \omega_n, \\ +x\alpha_0 + y\beta_0 + z\gamma_0 + &= 4\pi Vy \tsum A_n Q_n \\ + &= 4\pi Va \sin \theta \cos \phi + \tsum\left(\frac{A_{n-1}}{2n-1} - \frac{A_{n+1}}{2n+3}\right) \frac{dQ_n}{d\mu} \\ + &= \frac{4\pi V}{\iota k} \sin \theta \cos \phi \tsum A_n \frac{dQ_n}{d\mu}. +\end{align*} + +Let $\omega_n = r^n Y_n$, where $Y_n$~is a surface harmonic of degree~$n$. +Then we have +\[ +Y_n = \frac{4\pi Va^{-n}}{n \centerdot n + 1 \centerdot 2n + 1 \centerdot \iota k} + \sin \theta \cos \phi \frac{dQ_n}{d\mu}\, \frac{A_n}{f_n(ka)}. +\] + +\Article{376} Substituting the values just found for $\omega_n$,~$\omega_n'$, we find +that the values of $f$,~$g$,~$h$, $\alpha$,~$\beta$,~$\gamma$ in the wave scattered by the +%% -----File: 460.png---Folio 446------- +sphere are, omitting the time factor, given by the equations +{\setlength{\multlinegap}{0pt}\footnotesize +\begin{multline*} +f = \tsum \frac{1}{n \centerdot n+1 \centerdot} + \frac{1}{\iota^n}\, \frac{1}{\iota k} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dx} \left( r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu} \right) \\ + - nk^2 r^{2n+3} f_{n+1}(kr)\, + \frac{d}{dx} \Biggl(\frac{\sin \theta \sin \phi \dfrac{dQ_n}{d\mu}} {r^{n+1}}\Biggr) \biggr\} + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n (ka)\bigr)} \\ + - \tsum \frac{2n+1}{\iota^n a^n \centerdot n \centerdot n+1 \centerdot} + \cdot \frac{S_n(ka)}{f_n(ka)}\, f_n(kr) \left(y \frac{d}{dz} - z \frac{d}{dy}\right) + \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right), +\end{multline*} +\begin{multline*} +g = \tsum \frac{1}{n \centerdot n+1} \cdot \frac{1}{\iota^n}\, \frac{1}{\iota k} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dy} \left( r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu} \right) \\ + - nk^2 r^{2n+3} f_{n+1}(kr)\, + \frac{d}{dy} \Biggl(\frac{\sin \theta \sin \phi \dfrac{dQ_n}{d\mu}}{r^{n+1}}\Biggr) \biggr\} + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n (ka)\bigr)} \\ + - \tsum \frac{2n+1}{\iota^n a^n \centerdot n \centerdot n+1 \centerdot} + \cdot \frac{S_n(ka)}{f_n(ka)}\, f_n(kr) \left(z \frac{d}{dx} - x \frac{d}{dz}\right) + \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right), +\end{multline*} +\begin{multline*} +h = \tsum \frac{1}{n \centerdot n+1 \centerdot} + \frac{1}{\iota^n}\, \frac{1}{\iota k} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dz} \left( r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu} \right) \\ + - nk^2 r^{2n+3} f_{n+1}(kr)\, \frac{d}{dz} \Biggl(\frac{\sin \theta \sin \phi \dfrac{dQ_n}{d\mu}}{r^{n+1}}\Biggr) \biggr\} + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n (ka)\bigr)} \\ + - \tsum \frac{2n+1}{\iota^n a^n \centerdot n \centerdot n+1 \centerdot} + \cdot \frac{S_n(ka)}{f_n(ka)}\, f_n(kr) \left(x \frac{d}{dy} - y \frac{d}{dz}\right) + \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right); +\end{multline*} +\begin{multline*} +\alpha = 4\pi V \tsum \frac{a^{-n}}{n \centerdot n+1 \centerdot} + \frac{1}{\iota^n \iota k}\, \frac{S_n(ka)}{f_n(ka)} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dx} \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right) \\ + - nk^2 f_{n+1}(kr) r^{2n+3}\, \frac{d}{dx} \Biggl(\frac{\sin \theta \cos \phi \dfrac{dQ_n}{d\mu}} {r^{n+1}}\Biggr) \biggr\} \\ + + 4\pi V \tsum \cdot \frac{2n+1}{n \centerdot n+1 \centerdot} + \cdot \frac{1}{\iota^n}\, + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n(ka)\bigr) } + f_n(kr) \left(y \frac{d}{dz} - z \frac{d}{dy}\right) + \left(r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu}\right) +\end{multline*} +%% -----File: 461.png---Folio 447------- +\begin{multline*} +\beta = 4\pi V \tsum \frac{a^{-n}}{n \centerdot n+1 \centerdot} + \frac{1}{\iota^n \centerdot \iota k}\, + \frac{S_n(ka)}{f_n(ka)} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dy} \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right) \\ + - nk^2 f_{n+1}(kr) r^{2n+3}\, + \frac{d}{dy} \Biggl(\frac{\sin \theta \cos \phi \dfrac{dQ_n}{d\mu}} {r^{n+1}}\Biggr) \biggr\} \\ + + 4\pi V \tsum \cdot \frac{2n+1}{n \centerdot n+1 \centerdot} + \cdot \frac{1}{\iota^n}\, + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n(ka)\bigr) } f_n(kr) \left(z \frac{d}{dx} - x \frac{d}{dz}\right) + \left(r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu}\right), +\end{multline*} +\begin{multline*} +\gamma = 4\pi V \tsum \frac{a^{-n}}{n \centerdot n+1} + \frac{1}{\iota^n \iota k}\, \frac{S_n(ka)}{f_n(ka)} + \biggl\{(n+1)f_{n-1}(kr)\, \frac{d}{dz} \left(r^n \sin \theta \cos \phi \frac{dQ_n}{d\mu}\right) \\ + - nk^2 f_{n+1}(kr) r^{2n+3}\, \frac{d}{dz} \Biggl(\frac{\sin \theta \cos \phi \dfrac{dQ_n}{d\mu}}{r^{n+1}}\Biggr) \biggr\} \\ + + 4\pi V \tsum \frac{2n+1}{n \centerdot n+1} \cdot \frac{1}{\iota^n}\, + \frac{\dfrac{d}{da} \bigl(aS_n(ka)\bigr) } + {\dfrac{d}{da} \bigl(a^{n+1} f_n(ka)\bigr) }\DPtypo{}{f_n(kr)} \left(x \frac{d}{dy} - y \frac{d}{dx}\right) + \left(r^n \sin \theta \sin \phi \frac{dQ_n}{d\mu}\right). +\end{multline*} +} + +\Article{377} These expressions give the solution of the problem of +the scattering of a plane wave by a sphere of any size. The +particular case when the radius of the sphere is very small compared +with the wave length of the incident wave is of great +importance. In this case $ka$~is very small, and the approximate +values of $S_n (ka)$, $f_n (ka)$ are, \artref{308}{Art.~308}, expressed by the equations +\begin{align*} +S_n(ka) &= \frac{(-1)^n (ka)^n}{2n+1 \centerdot 2n-1 \ldots 1}, \\ +f_n(ka) &= (-1)^n 2n-1 \centerdot 2n-3 \ldots 1 \frac{\epsilon^{-\iota ka}} {(ka)^{2n+1}}. +\end{align*} + +Substituting these values in the preceding equations and retaining +only the lowest powers of~$ka$, we find, omitting the +time factor, +\begin{align*} +&\left. +\begin{aligned} +f &= k^5 a^3\, \epsilon^{\iota ka} f_2 (kr)xz + \frac{1}{2\iota}\, k^4 a^3\, \epsilon^{\iota ka} f_1 (kr)z, \\ +g &= k^5 a^3\, \epsilon^{\iota ka} f_2 (kr)yz, \\ +h &= \tfrac{1}{3} k^3 a^3\, \epsilon^{\iota ka} + \{2f_0(kr) + k^2(3z^2-r^2)f_2 (kr)\} + - \frac{1}{2\iota}\, k^4 a^3\, \epsilon^{\iota ka} f_1 (kr)x; +\end{aligned} +\right.\\ +%% -----File: 462.png---Folio 448------- +&\left.\begin{aligned} +\alpha & = -4\pi V \tfrac{1}{2} k^5 a^3\, \epsilon^{\iota ka} f_2 (kr)xy + + 4\pi V \iota k^4 a^3\, \epsilon^{\iota ka} f_1(kr)y. \\ +\beta & = + \begin{aligned}[t] + -4 \pi V \frac{1}{6} k^3a^3\, \epsilon^{\iota ka} \{2f_0(kr) + + k^2(3y^2 - r^2)f_2(kr)\} \\ + -4 \pi V \iota k^4 a^3\, \epsilon^{\iota ka} f_1(kr)x, + \end{aligned} \\ +\gamma & = -4 \pi V \frac{1}{2} k^5 a^3\, \epsilon^{\iota ka} f_2(kr)yz. +\end{aligned} +\right\} +\end{align*} +At a distance from the sphere, which is large compared with the +wave length, $kr$~is very large; we then have approximately +\[ +f_2(kr) = - \frac{\epsilon^{-\iota kr}}{k^3 r^3}, \qquad +f_1(kr) = - \frac{\iota\, \epsilon^{-\iota kr}}{k^2 r^2}, \qquad +f_0(kr) = \frac{\epsilon^{-\iota kr}}{kr}. +\] + +Substituting their value and introducing the time factor, we get +\[ +\left.\begin{aligned} +f &= -\epsilon^{\iota k \bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r} \left(\frac{xz}{r^2} + \tfrac{1}{2}\frac{z}{r}\right), \\ +g &= -\epsilon^{\iota k \bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r}\, \frac{yz}{r^2}, \\ +h &= \epsilon^{\iota k \bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r} \left(1 - \frac{z^2}{r^2} + \tfrac{1}{2} \frac{x}{r}\right); +\end{aligned} \right\} +\] +\[ +\left.\begin{aligned} +\alpha &= 4 \pi V\, \epsilon^{\iota k\bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r} \left\{\tfrac{1}{2} \frac{xy}{r^2} + \frac{y}{r}\right\}, \\ +\beta &= 4 \pi V\, \epsilon^{\iota k\bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r} \left\{\frac{y^2-r^2}{2r^2} - \frac{x}{r}\right\}, \\ +\gamma &= 4 \pi V\, \epsilon^{\iota k\bigl(Vt-(r-a)\bigr)} \frac{k^2a^3}{r}\, \tfrac{1}{2} yz. +\end{aligned} \right\} +\] +From these expressions we see that +\[ +xf + yg + zh = 0, \qquad x\alpha + x\beta + z\gamma = 0; +\] +so that both the electric polarization and the magnetic induction +are at right angles to the radius. We have also +\[ +f\alpha + g\beta + h\gamma = 0, +\] +so that the electric polarization is at right angles to the magnetic +induction. Taking the real part of the preceding expressions, +we find +\begin{gather*} +f^2 + g^2 + h^2 = \cos^2 k\bigl(Vt-(r-a)\bigr) + \frac{k^4a^6}{r^2} \left\{\left(\frac{x}{r} + \tfrac{1}{2}\right)^2 + \tfrac{3}{4} \frac{y^2}{r^2} \right\}, \\ +\alpha^2 + \beta^2 + \gamma^2 = (4 \pi V)^2 \cos^2 k \bigl(Vt-(r-a)\bigr) + \frac{k^4a^6}{r^2} \left\{\left(\frac{x}{r} + \tfrac{1}{2}\right)^2 + \tfrac{3}{4} \frac{y^2}{r^2} \right\}. +\end{gather*} + +Thus we see that the resultant magnetic induction is equal to +$4 \pi V$~times the resultant electric displacement. We could have +%% -----File: 463.png---Folio 449------- +deduced this result directly from \artref{9}{Art.~9}, since the Faraday +tubes are moving outwards at right angles to themselves with +the velocity~$V$. + +\Article{378} We see from the expressions for the resultant electric +polarization and the magnetic force that at the places where the +scattered wave vanishes +\[ +x/r = -\tfrac{1}{2}, \qquad y = 0. +\] +Thus the scattered light produced by the incidence of a plane +polarized wave vanishes in the plane through the centre at right +angles to the magnetic induction in the incident wave along +a line, making an angle of~$120°$ with the radius to the point +at which the wave first strikes the sphere, and it does not +vanish in any direction other than this. Thus if non-polarized +waves of light or of electric displacement are incident upon a +sphere, whose radius is small compared with the wave length of +the incident vibration, the direction in which the scattered light +is plane polarized will be inclined at an angle of~$120°$ to the +direction of the incident light. The scattering of light by small +metallic spheres thus follows laws which are quite different from +those which hold when the scattering is produced by non-conducting +particles. In the latter case (see Lord Rayleigh, \textit{Phil.\ Mag.}\ +[5], 12, p.~81, 1881), when a ray of plane polarized light falls +\index{Rayleigh, Lord, scattering of light by fine particles@\subdashtwo scattering of light by fine particles}% +upon a small sphere, the scattered light vanishes at all points +in the plane normal to the magnetic induction, where the radius +vector makes an angle of~$90°$, and not~$120°$, with the direction +of the incident light. Thus, when non-polarized light falls upon +a small non-conducting sphere, the scattered light will be completely +polarized at any point in a plane through the centre of +the sphere at right angles to the direction of the incident light. +When the light is scattered by a conducting sphere, the points at +which the light is completely polarized are on the surface of +a cone whose axis is the direction of propagation of the incident +light and whose semi-vertical angle is~$120°$. The Faraday tubes +given off by the conducting sphere form two sets of closed +curves, which are separated by the surface of this cone. The +momentum of these tubes being at right angles both to the +magnetic induction and the electric polarization is radial, so +that the energy emitted by the conducting sphere is, when we +are considering a point whose distance from the centre is a large +%% -----File: 464.png---Folio 450------- +number of wave lengths, travelling radially outwards from the +sphere. + +At a point close to the sphere $kr$~is very small, so that we +have approximately +\[ +f_0(kr) = \frac{\epsilon^{-\iota kr}}{kr}, \qquad +f_1(kr) = -\frac{\epsilon^{-\iota kr}}{k^3r^3}, \qquad +f_2(kr) = \frac{3\epsilon^{-\iota kr}}{k^5r^5}. +\] + +Substituting these values in the expressions in \artref{377}{Art.~377}, we find +that the components of the total electric polarization and magnetic +induction, i.e.~the polarization and induction scattered from the +sphere plus that due to the incident wave, are given approximately +by the equations +\begin{align*} +f &= \frac{3a^3}{r^5}\, xz \cos kVt, \\ +g &= \frac{3a^3}{r^5}\, yz \cos kVt, \\ +h &= \left\{\frac{a^3}{r^5} (3z^2 - r^2) + 1\right\} \cos kVt; +\end{align*} +\begin{align*} +\alpha &= -6\pi V \frac{a^3}{r^5}\, xy \cos kVt, \\ +\beta &= -2\pi V \left\{\frac{a^3}{r^5} (3y^2 - r^2) - 2 \right\} \cos kVt, \\ +\gamma &= -6\pi V \frac{a^3}{r^5}\, yz \cos kVt. +\end{align*} +Thus when $r = a$, +\begin{gather*} +f = \frac{3xz}{a^2} \cos kVt, \qquad +g = \frac{3yz}{a^2} \cos kVt, \qquad +h = \frac{3z^2}{a^2} \cos kVt; \\ +% +\alpha = -6\pi V \frac{xy}{a^2} \cos kVt, \qquad +\beta = 6\pi V \frac{(x^2 + z^2)}{a^2} \cos kVt, \\ +\gamma = -6\pi V \frac{yz}{a^2} \cos kVt. +\end{gather*} +Thus at the surface of the sphere the resultant electric polarization +is radial and proportional to~$z$; there is thus a distribution +of electricity over the sphere whose surface density varies as the +distance of the point on the sphere from a plane through its +centre parallel to the plane of polarization of the incident wave,---the +plane of polarization being the plane at right angles to +the electric polarization. +%% -----File: 465.png---Folio 451------- + +The magnetic induction at the surface of the sphere is tangential +to the sphere and equal to +\[ +6\pi V \frac{1}{a} \{x^2 + z^2\}^\frac{1}{2} \cos kVt; +\] +it is thus proportional to the distance of a point on the surface +of the sphere from the diameter of the sphere parallel to the +magnetic force in the incident wave. The lines of magnetic force +on the sphere are great circles all passing through this diameter. + +Since the electric polarization is radial and the magnetic +induction is tangential, the momentum due to the Faraday tubes +which is at right angles to each of these quantities is tangential. +The direction of the momentum is tangential to a series of small +circles on the sphere whose planes are at right angles to the +diameter of the sphere parallel to the magnetic induction in the +incident wave. + + +\Subsection{Waves along Wires.} +\index{Electromagnetic waves, yalong wires@\subdashtwo along wires}% +\index{Propagation velocity of zelectromagnetic waves along a wire@\subdashtwo of electromagnetic waves along a wire}% +\index{Velocity of xelectromagnetic waves along wires@\subdashtwo electromagnetic waves along wires}% +\index{Waves, electromagnetic, along wires@\subdashtwo along wires}% +\index{Wires, electromagnetic waves along}% + +\Article{379} If the electric potential at one end of a wire be made to +vary harmonically so as at any time to be represented by $\cos pt$, +the electromotive intensity, as we proceed along the wire, will be +a harmonic function of the distance from the end of the wire; if +the wave length of this harmonic distribution is~$\lambda$, the velocity of +propagation of the disturbance along the wire is defined to be +$\lambda p/2\pi$. This velocity ought, if Maxwell's theory is true, to +be equal to~$V$, the velocity with which electrodynamic disturbances +are propagated through air (see \artref{267}{Art.~267}). Indeed on this +theory the effects observed do in reality travel through the air +even though the wire is present, so that the introduction of the +wire does not materially alter the physical conditions. The +electrical vibrations considered in this chapter are all of very +high frequency, being produced by the discharge of condensers +through short discharging circuits. In this case (see \artref{269}{Art.~269}) +the electromotive intensity in the region around the wire is at +right angles to it, and we may suppose that the phenomena near +the wire are due to radial Faraday tubes, with their ends on the +wire travelling along it with the velocity of light. + +\Article{380} Considerable interest attaches to some experiments +made by Hertz, which seemed to indicate that the velocity along +the wire was considerably less than that through the air; and +though later experiments have shown that this conclusion is +%% -----File: 466.png---Folio 452------- +erroneous, and that, as Maxwell's theory indicates, the two +velocities are identical, Hertz's experiments are of great interest +both from the methods used and the points they illustrate. + +\includegraphicsmid{fig123}{Fig.~123.} + +In these experiments Hertz (\textit{Wied.\ Ann.}\ 34, p.~551, 1888) +used the vibrator described in \artref{325}{Art.~325}. This was placed in a +vertical plane; behind and parallel to one of the metal plates~$A$, +and insulated from it, was a metal plate~$B$ of equal area (see +\figureref{fig123}{Fig.~123}). A long wire was soldered to~$B$ and bent round so +as to come in front of the vibrator and lie in the vertical plane of +symmetry of the vibrator about a foot above the base line. The +wire, which was above sixty metres long, was taken through +a window, and was kept as far as possible from walls,~\&c., so as +to avoid disturbances arising from reflected waves. In the first +set of experiments the free end of the wire was insulated. The +resonator used was the circular coil of wire $35$~cm.\ in radius previously +described. When the plane of the resonator was at right +angles to the axis of the vibrator, the electromotive intensity due +to the vibrator (apart from the action of the wire) did not (\artref{331}{Art.~331}) +produce any tendency to spark in the resonator, so that the +sparks in this position of the resonator must have been entirely +due to the disturbance produced by the wire. To observe the +effects due to the wire, the resonator was turned round in its own +plane until the air gap was at the highest point, and therefore +parallel to the wire. When the resonator was moved along the +wire the following effects were observed. At the free end of +the wire (which was insulated) the sparks in the resonator were +extremely small, as the resonator was moved towards the +vibrator the sparks increased and attained a maximum; they then +%% -----File: 467.png---Folio 453------- +decreased again until they almost vanished. If we call such a +place a node, then, as the resonator moved along the wire, such +nodes were found to occur at approximately equal intervals. + +\Article{381} Similar periodic effects were observed when the plane of +the resonator was at right angles to the wire, the air gap being +vertical; in such a position there would have been no sparks +unless the wire had been present. On moving the resonator +along the wire the brightness of the sparks changed in a periodic +way: the positions however in which the sparks were brightest +with the resonator in this position were those in which they had +been dullest when the resonator was in its previous position. + +This result is what we should expect from theoretical considerations. +For when the resonator is in the first position, with +its plane passing through the wire, the air gap is placed +parallel to the wire. Now the Faraday tubes travelling along the +wire are, as we saw \artref{269}{Art.~269}, at right angles to it and therefore to +the air gap: thus the tubes which fall directly on the air gap +do not tend to produce a spark; the sparks must be due to the +tubes collected by the resonator and thrown by it into the air +gap. The tubes which travel with their ends on the wire will +be reflected from the insulated extremity of it, so that there will +be tubes travelling in opposite directions along the wire; incident +tubes travelling from the vibrator to the free end of the wire, and +reflected tubes travelling back from the free end to the vibrator. + +Let us now consider what will happen when the vibrator is +in such a position as that represented in \figureref{fig124}{Fig.~124}. The tube +thrown into the air gap by a positive tube, such as~$CD$ +proceeding from the vibrator, will be of opposite sign to that +thrown by a positive tube, such as~$AB$ proceeding from the free +end: thus in this position of the vibrator the positive tubes +%% -----File: 468.png---Folio 454------- +moving in opposite directions will neutralize each other's effects +in producing sparks, though they increase the resultant electromotive +intensity: thus, in this case, at the places where the +electromotive intensity is greatest there will be no sparks in the +resonator, for this maximum intensity will be due to two sets of +tubes of the same sign, one set moving in one direction, the other +in the opposite. + +\includegraphicsmid{fig124}{Fig.~124.} + +Since the free end of the wire has little or no capacity, no +electricity can accumulate there, so that when one set of positive +tubes arrives at the free end from the vibrator an equal number of +positive tubes must start from the free end and move towards the +vibrator; thus at the free end we have equal numbers of positive +(or negative) tubes travelling in opposite directions. We should +expect therefore that no sparks would be produced when the +resonator was placed close to the free end; this, as we have seen, +was found by Hertz to be the case. + +When however the resonator is placed in the second position, +with its plane at right angles to the wire, the conditions are very +different; for the tubes which though they strike the resonator yet +miss the air gap, are not hampered by the resonator in their +passage through it; thus the resonator does not in this case collect +tubes and throw them into the air gap. The sparks are now entirely +due to the tubes which strike the air gap itself, and thus will +be brightest at those points on the wire where the electromotive +intensity is a maximum, while at such places, as we have seen, +the sparks vanish when the resonator is in the former position. + +\Article{382} Hertz found that when the wire was cut at a node the +nodes in the portion of the wire which remained were not +altered in position, but that they were displaced when the wire +was cut at any place other than a node. + +Hertz also found that the distance between the nodes was independent +of the diameter of the wire and of the material of +which it was made, and that in particular the positions of the nodes +were not affected by substituting an iron wire for a copper one. + +The distance between the nodes is half the wave length along +the wire; thus, if we know the period of the electrical vibrations +of the system we can determine the velocity of propagation along +the wire. Hertz, by using the formula $2\pi \sqrt{LC}$ for the wave +length of the vibrations emitted by a condenser of capacity~$C$, +whose plates are connected by a discharging circuit whose coefficient +%% -----File: 469.png---Folio 455------- +of self-induction is~$L$, came to the conclusion that the +velocity of propagation along the wire was only about $2/3$~of +that through the dielectric; there are however many difficulties +and doubtful points in the theoretical calculation of the period of +vibration of such a system as Hertz's. + +\Article{383} Before discussing these we shall consider another method +which Hertz used to compare directly the velocity of propagation +along a wire with that through the air. + +In this method interference was produced in the following way +between the waves travelling out from the vibrator through +the air and those travelling along the wire. The free end of +the wire was put to earth so as to get rid of reflected waves along +the wire, and as there were no metallic reflectors in the way of +the waves proceeding directly through the air from the vibrator, +the only reflected waves of this kind must have come from the +floors or walls of the room; we shall assume for the present that +there were no reflected air waves. The resonator was placed so +that the air gap was at the highest point and vertically under +the wire, and the plane of the resonator could rotate about a +vertical axis passing through the middle of the air gap. When +the plane of the resonator was at right angles to the wire, +the waves proceeding along the latter had no tendency to produce +a spark; any sparks that passed across the resonator must +have been entirely due to the waves travelling from the vibrator +through the air independently of the wire. In Hertz's experiments +when the resonator was in this position the sparks were +about $2$~mm.\ long. On the other hand, when the resonator was +twisted about the axis so that its plane passed through the wire +and was at right angles to the axis of the vibrator, the direct waves +through the air from the vibrator would have no tendency to produce +sparks; which in this case must have been entirely due to the +waves travelling along the wire. In Hertz's experiments when +the resonator was in this position the sparks were again about +$2$~mm.\ long. When the resonator was in a position intermediate +between these two, the sparks were due to the combined action of +the waves travelling along the wire and those coming directly +through the air. In such a case the brightness of the sparks +would, in general, change when the plane of the vibrator was +twisted through a considerable angle. If now the fronts of the two +sets of waves were parallel and moving forward with the same +%% -----File: 470.png---Folio 456------- +velocity, then the effect of turning the plane of the vibrator +through a definite angle in a definite direction would be the +same at all points on the wire: if however the two waves were +travelling at different rates the effect of turning the resonator +would vary as it is moved from place to place along the wire. + +\Article{384} To prove this, let the electromotive intensity in the air +gap due to the wave travelling along the wire be +\[ +A \cos \frac{2\pi}{\lambda} (Vt - z), +\] +when the plane of the resonator passes through the wire; here +the wire is taken as the axis of~$z$, and $\lambda$~is the wave length of the +waves travelling along it. Then, when the plane of the resonator +is twisted through an angle~$\phi$ from this position, the electromotive +intensity in the air gap due to the wire waves will be +\[ +A \cos\phi \cos \frac{2\pi}{\lambda} (Vt - z), +\] +since the electromotive intensity is approximately proportional +to the projection of the resonator on the plane through the wire +and the base line of the vibrator. + +Let the electromotive intensity in the air gap due to the +waves coming from the vibrator independently of the wire be, +when the plane of the resonator is at right angles to the wire, +\[ +B \cos \frac{2\pi}{\lambda'} \bigl(V't - (z - \alpha)\bigr), +\] +where $\lambda'$~is the wave length and $V'$~the velocity of the air waves; +then, if the plane of the resonator is turned until it makes an +angle~$\phi$ with the plane through the wire and the base line, the +electromotive intensity resolved parallel to the air gap is +equal to +\[ +B \sin\phi \cos \frac{2\pi}{\lambda'} \bigl(V't - (z - \alpha)\bigr). +\] +Thus, considering both the air waves and those along the wire, +the electromotive intensity when the resonator is in this position +is equal to +\[ +A \cos\phi \cos \frac{2\pi}{\lambda} (Vt - z) + +B \sin\phi \cos \frac{2\pi}{\lambda'} \bigl(V't - (z - \alpha)\bigr), +\] +which may, since $V/\lambda$~is equal to~$V'/\lambda'$, be written as +\[ +R \cos \left\{\frac{2\pi}{\lambda} V(t + \epsilon) \right\}, +\] +%% -----File: 471.png---Folio 457------- +where +\begin{multline*} +R^2 = A^2 \cos^2 \phi + B^2 \sin^2 \phi \\ + + 2AB \cos\phi \sin\phi + \cos \left\{\left( \frac{2\pi}{\lambda} - \frac{2\pi}{\lambda'} \right) z + \frac{2\pi}{\lambda'} \alpha \right\}. +\end{multline*} + +Now $R$~is the maximum electromotive intensity acting on the +air gap, and will be measured by the brightness of the spark. +We see from the preceding expression that if $\lambda = \lambda'$, that is, if the +velocity of the waves along the wire is the same as that of the +air waves which are not affected by the wire, the last term in +the expression for~$R^2$ will cease to be a periodic function of~$z$, +so that in this case there will be no periodic change in the +effect produced by a given rotation as we move the resonator +along the wire. When however $\lambda$~is not equal to~$\lambda'$, the effect on +the spark length of a given rotation of the resonator will vary +harmonically along the wire. Since in Hertz's experiments the +sparks were about equally long in the two extreme positions, +$\phi = 0$ and $\phi = \pi/2$, we may in discussing these experiments put +$A = B$, and therefore +\[ +R^2 = A^2 \left( 1 + 2 \cos\phi \sin\phi + \cos \left\{\left( \frac{2\pi}{\lambda} - \frac{2\pi}{\lambda'} \right) z + \frac{2\pi}{\lambda'} \alpha \right\} \right); +\] +thus, if the resonator is rotated so that $\phi$~changes from $+\beta$ to~$-\beta$, +$R^2$~is diminished by +\[ +2A^2 \sin 2\beta + \cos \left\{\left( \frac{2\pi}{\lambda} - \frac{2\pi}{\lambda'} \right) z + \frac{2\pi}{\lambda'} \alpha \right\}. +\] +Thus when +\[ +\left( \frac{2\pi}{\lambda} - \frac{2\pi}{\lambda'} \right) z + \frac{2\pi}{\lambda'} \alpha + = (2n + 1) \frac{\pi}{2}, +\] +that is, at places separated by the intervals +\[ +\tfrac{1}{2} \bigg/ \left\{\frac{1}{\lambda} - \frac{1}{\lambda'} \right\} +\] +along the wire the rotation of the resonator will produce no +effect upon the sparks, while on one side of one of these positions +it will increase, on the other side diminish the brightness +of the sparks. If $\lambda'$~were very large compared with~$\lambda$, that is, +if the velocity of the waves travelling freely through the air +were very much greater than that of those travelling along the +wire, the distance between the places where rotation produces +no effect would be~$\frac{1}{2} \lambda$, which is the distance between the nodes +observed in the experiments described in \artref{380}{Art.~380}. Hertz, however, +%% -----File: 472.png---Folio 458------- +came to the conclusion that the places where rotation produced +no effect were separated by a much greater interval than +the nodes. These he had determined to be about $2.8$~metres apart, +whereas the places where rotation produced no effect seemed to +be separated by about $7.5$~metres. Assuming these numbers we +have +\begin{gather*} +\lambda = 5.6, \\ + \tfrac{1}{2} \bigg{/} \left(\frac{1}{\lambda} - \frac{1}{\lambda'}\right) = 7.5; +\end{gather*} +hence $\lambda' = 8.94$. Thus from these experiments the velocity of +the free air waves would appear to be greater than those along +the wire in the proportion of $8.94$~to~$5.6$ or $1.6$~to~$1$; or the +velocity of the air waves is about half as large again as that of +the wire waves. + +We have, however, in the preceding investigations made +several assumptions which it would be difficult to realise in +practice; we have assumed, for example, that in the neighbourhood +of the resonator the front of the air waves was at right +angles to the wire. Since the resonator was close to the axis of +the vibrator this assumption would be justifiable if there had +been no reflection of the air waves from the walls or floors of +the room. Since the thickness of the walls was small compared +with the wave length it is not likely, unless they were very +damp, that there would be much reflection from them; the case +of the floor is however very different, and it is difficult to see +how reflection from it could have been entirely avoided. Reflection +from the floor would however introduce waves, the +normals to whose fronts would make a finite angle with the +wire. The electromotive intensity in the spark gap due to such +waves would no longer be represented by a term of the form +\[ +\cos \bigl(2\pi(V't - z)/\lambda'\bigr), +\] +but by one of the form +\[ +\cos \bigl(2\pi(V't - z \cos\theta)/\lambda'\bigr), +\] +where $\theta$~is the angle between the normal to the wave front and +the wire. Thus in the preceding investigation we must, for such +waves, replace~$\lambda'$ by~$\lambda'\sec\theta$, and their apparent wave length +along the wire would be $\lambda'\sec\theta$ and not~$\lambda'$, so that the reflection +would have the effect of increasing the apparent wave +length of the air waves. The result then of Hertz's experiments +that the wave length of the air waves, measured parallel to the +%% -----File: 473.png---Folio 459------- +wire, was greater than that of the wire waves, may perhaps be +explained by the reflection of the waves from the floor of the +room, without supposing that the velocity of the free air waves +is different from that of those guided by the wire. + +\includegraphicsmid{fig125}{Fig.~125.} + +\index{Sarasin and De la Rive, reflection of electromagnetic waves along wires@\subdashtwo electromagnetic waves along wires}% +\index{Wires, Sarasin's and de la Rive's experiments on@\subdashone Sarasin's and de la Rive's experiments on}% +\Article{385} The experiments of Sarasin and De~la~Rive (\textit{Archives des +Sciences Physiques et Naturelles Genève}, 1890, t.~xxiii, p.~113) on +the distance between the nodes (1)~along a wire, (2)~when produced +by interference between direct air waves and waves reflected +from a large metallic plate, seem to prove conclusively +that the velocity of the waves guided by a wire is the same as +that of free air waves. The experiments on the air waves have +already been described in \artref{339}{Art.~339}; those on the wire waves +were made in a slightly different way from Hertz's experiments. + +\includegraphicsmid{fig126}{Fig.~126.} + +The method used by Sarasin and De~la~Rive is indicated in +\figureref{fig125}{Fig.~125}. Two metallic plates placed in front of the plates of +the vibrator have parallel wires $F$,~$F$ soldered to them, the wires +being of equal length and insulated. The plane of the resonator +is at right angles to the wires, and the air gap is at the highest +point, so that the air gap is parallel to the shortest distance +between the wires. The resonator is mounted on a wagon by +means of which it can be moved to and fro along the wires, +while a scale on the bench along which the wagon slides enables +the position of the latter to be determined. The resonator with +its mounting is shown in \figureref{fig126}{Fig.~126}. Sarasin and De~la~Rive +found that as long as the same resonator was used the distance +between the nodes as determined by this apparatus was the +%% -----File: 474.png---Folio 460------- +same as when the nodes were produced by the interference of +direct air waves and those reflected from a metallic plate. The +relative distances are given in the table in \artref{340}{Art.~340}, where `$\lambda$~for +wire' indicates twice the distance between the nodes measured +along the wire. They found with the wires, as later on they +found for the air waves, that the distance between the nodes +depended entirely upon the size of the resonator and not upon +that of the vibrator; in fact the distance between the nodes +was directly proportional to the diameter of the resonator; +while it did not seem to depend to any appreciable extent +upon the size of the vibrator. These peculiarities can be explained +in the same way as the corresponding ones for the air +waves, see \artref{341}{Art.~341}. + +When the extremities of the wires remote from the vibrator +are attached to large metallic plates, instead of being free, the +electromotive intensity parallel to the plates at the ends must +vanish; hence, whenever a bundle of positive Faraday tubes +from the vibrator arrives at a plate an equal number of negative +tubes must start from the plate and travel towards the +vibrator, while, when the end of the wire is free, the tubes starting +from the end of the wire in response to those coming from +%% -----File: 475.png---Folio 461------- +the vibrator are of the same sign as those arriving. Thus, when +the end is free, the current vanishes and the electromotive intensity +is a maximum, while when the end is attached to a large +plate the electromotive intensity vanishes and the current is a +maximum. Since the sparks in the resonator, when used as in +Sarasin and De~la~Rive's experiments, are due to the tubes +falling directly on the air gap, the sparks will be brightest when +the electromotive intensity is a maximum, and will vanish when +it vanishes; thus the loops when the ends are free will coincide +with the nodes when the wires are attached to large plates. +This was found by Sarasin and De~la~Rive to be the case. + +A similar point arises in connection with the experiments +with wires to that which was mentioned in \artref{342}{Art.~342} in connection +with the experiments on the air waves. The distance +between the nodes, which is half the wave length of the vibration +of the resonator, is, as is seen from the table in \artref{340}{Art.~340}, +very approximately four times the diameter; if the resonator +were a straight wire the half wave length would be equal to the +length of the wire, and we should expect that bending the wire +into a circle would tend to shorten the period, we should therefore +have expected the distance between the nodes to have been +a little less than the circumference of the resonator. Sarasin +and De~la~Rive's experiments show however that it was $80$~per +cent.\ greater than this: it is remarkable however that the distance +of the first node from the end of the wire, which is a loop, +was always equal to half the circumference of the resonator, +which is the value it would have had if the wave length of the +vibration emitted by the resonator had been equal to twice its +circumference. + +\Article{386} The experiments of Sarasin and De~la~Rive show that +when vibrators of the kind shown in \figureref{fig113}{Fig.~113} are used, the +oscillations which are detected by a circular resonator are those +in the resonator rather than the vibrator. + +\index{Arons@Arons, electromagnetic waves}% +\index{Paalzow, electromagnetic waves}% +\index{Ritter, electromagnetic waves}% +\index{Rubens, zelectromagnetic waves@\subdashone electromagnetic waves}% +Rubens, Paalzow, Ritter, and Arons (\textit{Wied.\ Ann.}\ 37, p.~529, +1889; 40, p.~55, 1890; 42, pp.~154, 581, 1891) have used another +method of measuring wave lengths, which though it certainly +requires great care and labour, yet when used in a particular +way would seem to give very accurate results. The method +depends upon the change which takes place in the resistance of +a wire when it is heated by the passage of a current through +%% -----File: 476.png---Folio 462------- +it. Rubens finds that the rapidly alternating currents induced +by the vibrator can produce heat sufficient to increase the resistance +of a fine wire by an amount which can be made to +cause a considerable deflection in a delicate galvanometer. + +\includegraphicsmid{fig127}{Fig.~127.} + +\Article{387} Rubens' apparatus, which is really a bolometer, is arranged +as follows. Rapidly alternating currents pass through a very +fine iron wire~$L$. This wire forms one of the arms of a Wheatstone's +Bridge provided with a battery and a galvanometer. +When the rapidly alternating currents do not pass through~$L$ +this bridge is balanced, and there is no deflection of the galvanometer. +When however a rapidly alternating discharge passes +through the fine wire it heats it and so alters its resistance, and +as the Bridge is no longer balanced the galvanometer is deflected. +This arrangement is so sensitive that it is not necessary +to place~$L$ in series with the wires connected with the +plates of the vibrating system. Rubens found if a wire in +series with~$L$ encircled, without touching, one of the wires +$EJ$, $DH$ in the experiment figured in \figureref{fig127}{Fig.~127} (Rubens, \textit{Wied.\ +Ann.}\ 42, p.~154, 1871), the deflection of the galvanometer was +large enough to be +easily measured. The apparatus was so +delicate that a rise in temperature of $1/10,000$ of a degree +in the wire produced a deflection of a millimetre on the galvanometer +scale. In one of his experiments the wire joined +%% -----File: 477.png---Folio 463------- +in series with~$L$ was bent round two pieces of glass tubing +through which the wires~$EJ$, $DH$ passed, the plane of the turns +round the glass tube being at right angles to the wires. In this +case each turn of the wire and the wire it surrounds acted like a +little Leyden jar, and the electricity which flowed through the +wire~$L$ and disturbed the balance in the Bridge was due to the +charging and discharging of these jars. + +\includegraphicsmid{fig128}{Fig.~128.} + +The pieces of glass tube were attached to a frame work, see +\figureref{fig128}{Fig.~128}, which was moved along the wire, and the deflection of +the galvanometer observed as it moved along the wire. The +relation between the galvanometer deflection and the position of +the tubes is shown in \figureref{fig129}{Fig.~129}, where the ordinates represent the +deflection of the galvanometer and the abscissae, the distance +of the turns in the bolometer circuit from the point~$F$ in the +wire. The curve shows very clearly the harmonic character of +the disturbance along the wire. + +\Article{388} The results however of experiments of this kind were +not very accordant, and in the majority of his experiments +Rubens used another method which had previously been used +by Lecher, who instead of a bolometer employed the brightness of +\index{Lecher, xon electromagnetic waves@\subdashone on electromagnetic waves}% +the discharge through an exhausted tube as a measure of the +intensity of the waves. +%% -----File: 478.png---Folio 464------- + +In these experiments the turns~$l$, $m$ (\figureref{fig128}{Fig.~128}) in the bolometer +circuit were kept at the ends~$J$ and~$H$ of the main wire (\figureref{fig127}{Fig.~127}), +while a metallic wire forming a bridge between the two parallel +wires was moved along from one end of the wires to the other. +The deflection of the bolometer depended on the position of the +bridge, in the manner represented in \figureref{fig130}{Fig.~130}, where the ordinates +represent the deflection of the galvanometer, the abscissae the +position of the bridge. + +\includegraphicsmid{fig129}{Fig.~129.} + +Rubens found that the positions of the bridge, in which the +deflection of the galvanometer was a maximum, were independent +of the length of the wire connecting the plates of the vibrator to +the balls between which the sparks passed, and therefore of +the period of vibration of the vibrator. This result shows that +the vibrations in the wires which are detected by the bolometer +cannot be `forced' by the vibrator; for though, if this were the +case, the deflection of the bolometer would vary with the position +of the bridge, the places where the bridge produced a maximum +deflection would depend upon the period of the vibrator. We +can see this in the following way, if the bridge was at a place +where the electromotive intensity at right angles to the wire +%% -----File: 479.png---Folio 465------- +vanished---which, if there were no capacity at the ends~$J$, $H$, +would be an odd number of quarter wave lengths from these +ends---the introduction of the bridge would, since no current +would flow through it, produce no diminution in the electromotive +intensity at the ends~$J$, $H$; in other positions of the +bridge some of the current, which in its absence would go to the +ends, would be diverted by the bridge, so that the electromotive +intensity at the ends would be weakened. Thus, when the +deflection of the bolometer was a maximum, the distances of +the bridge from the ends~$J$, $H$ would be an odd multiple of a +quarter of the wave length of the vibration travelling along the +wire; thus, if these vibrations were `forced' by the vibrator, +the positions of the bridge which give a maximum deflection in +the bolometer would depend upon the period of the vibrator. +Rubens' experiments show that this was not the case. + +\includegraphicsmid{fig130}{Fig.~130.} + +We may therefore, as the result of these experiments, assume +that the effect of the sparks in the vibrator is to give an electrical +impulse to the wires and start the `free' vibrations proper to +them. The capacity of the plates at the ends of the wire makes +the investigation of the free periods troublesome; we may however +avail ourselves of the results of some experiments of Lecher's +\index{Lecher, xon electromagnetic waves@\subdashone on electromagnetic waves}% +(\textit{Wied.\ Ann.}\ 41, p.~850, 1890), who found that the addition of +capacity to the ends might be represented by supposing the wires +prolonged to an extent depending upon this additional capacity. + +\Article{389} Let $AB$, $CD$, \figureref{fig131}{Fig.~131}, be the original wires, $A\alpha$, $B\beta$, $C\gamma$, +$D\delta$~the amount by which they have to be prolonged to represent +the capacity at the ends, we shall call the wires~$\alpha\beta$, $\gamma\delta$ the +`equivalent' wires. Let~$PQ$ represent the position of the +bridge. + +\includegraphicsmid{fig131}{Fig.~131.} + +The electrical disturbance produced by the coil may start +several systems of currents in the wires~$\alpha\beta$, $\gamma\delta$. Then there may +be a system of longitudinal currents along~$\alpha\beta$, $\gamma\delta$ determined by +the condition that the currents must vanish at~$\alpha$, $\beta$, and at~$\gamma$, $\delta$. +Another system might flow round $\alpha PQ\gamma$, their wave length being +determined by the condition that the currents along the wire +must vanish at~$\alpha$ and~$\gamma$, and that by symmetry the electrification +%% -----File: 480.png---Folio 466------- +at these points must be equal and opposite. A third system of +currents might flow round $\beta PQ \delta$, the flow vanishing at $\beta$~and~$\delta$. +If the bridge~$PQ$ were near the ends $\alpha$,~$\gamma$, we might expect, +\textit{a~priori}, that the current in the circuit $\alpha PQ \gamma$ would be the most +intense. Since the currents induced in the wires by the coil +would tend to distribute themselves so that their self-induction +should be as small as possible they would therefore tend to take +the shortest course, i.e.~that round the circuit~$\alpha PQ \gamma$: these currents +would induce currents round the circuit~$\beta PQ \delta$. Lecher's +experiments (\textit{Wied.\ Ann.}~41, p.~850, 1890) show that the currents +circulating round $\alpha PQ \gamma$, $\beta PQ \delta$ are much more efficacious in +producing the electrical disturbance at the ends than the +longitudinal ones along $\alpha \beta$,~$\gamma \delta$. As a test of the magnitude of +the disturbance at the ends, Lecher used an exhausted tube +containing nitrogen and a little turpentine vapour; this was +placed across the wires at the ends, and the brilliancy of the +luminosity in the tube served as an indication of the magnitude +of the electromotive intensity across~$\beta \delta$. In one of his +experiments Lecher used a bridge formed of two wires, $PQ$,~$P'Q'$ +in parallel, and moved this about until the luminosity in the +tube was a maximum; he then cut the wires $\alpha \beta$,~$\gamma \delta$ between +$PQ$~and~$P'Q'$, so that the two circuits $\alpha PQ \gamma$, $\beta P'Q' \delta$ were no +longer in metallic connection. Lecher found that this division +of the circuit produced very little diminution in the brilliancy +of the luminosity in the tube, though the longitudinal flow +of the currents from $\alpha$ to~$\beta$ and from $\gamma$ to~$\delta$ must have been +almost entirely destroyed by it. Lecher also found that the +position of the bridge in which the luminosity of the tube was a +maximum depended upon the length of the bridge; if the bridge +were lengthened it had to be pushed towards, and if shortened +away from the coil, to maintain the luminosity of the tube at +its maximum value. He also found that, as might be expected, +if the bridge were very short the tube at the end remained dark +wherever the bridge was placed, while if the bridge were very +long the tube was always bright whatever the position of the +bridge. These experiments show that it is the currents round +the circuits $\alpha PQ \gamma$, $\beta PQ \delta$ which chiefly cause the luminosity +in the tube. Since the currents in the circuit $\beta PQ \delta$ are induced +by those in the circuit~$\alpha PQ \gamma$, they will be greatest when +the time of the electrical vibration of the system $\alpha PQ \gamma$ is +%% -----File: 481.png---Folio 467------- +the same as that of~$\beta PQ \delta$. The periods of vibration of these +circuits are determined by the conditions that the current must +vanish at their extremities and that these must be in opposite +electrical conditions; these conditions entail that the wave +lengths must be odd submultiples of the lengths of the circuit. +If the two circuits are in unison the wave lengths must be the +same, hence the ratio of the lengths of the two circuits must +be of the form $(2n - 1)/(2m - 1)$, where $n$~and~$m$ are integers. + +This conclusion is verified in a remarkable way by Rubens' +experiments with the bolometer. The relation between the +deflections of the bolometer (the ordinates) and the distances +of the bridge from~$G$ in \figureref{fig127}{Fig.~127} (the abscissae) is represented +in \figureref{fig130}{Fig.~130}. The length of the bridge in these experiments +was $14$~cm., that of the curved piece of the wire~$EG$ was $83$~cm., +and that of the straight portion~$GJ$ was $570$~cm. The lengths +$A \alpha$,~$B \beta$ which had to be added to the wires to represent the +effects of the capacity at the ends were assumed to be $55$~cm.\ for +the end of the wire next the coil, and $60$~cm.\ for the end next +the bolometer. These two lengths were chosen so as best to fit +in with the observations, and were thus really determined by +the measurements given in the following table; in spite of this, +so many maxima were observed that the observations furnish +satisfactory evidence of the truth of the theory just described. +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{4pt} +\settowidth{\TmpLen}{$2m-1$.} +\begin{tabular}{|c|c|c|c|c|c|c|} +\hline +\parbox[c]{\TmpLen}{\bigskip\centering$m$.} & +\parbox[c]{\TmpLen}{\bigskip\centering$n$.} & +\parbox[c]{\TmpLen}{\bigskip\centering$2m-1$.} & +\parbox[c]{\TmpLen}{\bigskip\centering$2n-1$.} & +\multicolumn{2}{c|}{\settowidth{\TmpLen}{\itshape maximum deflection}% +\parbox[c]{\TmpLen}{\centering\itshape\tablespaceup Distance of point of\\ maximum deflection\\ from~$G$.\tablespacedown}} & +\settowidth{\TmpLen}{Corresponding point}% +\parbox[t]{\TmpLen}{\centering\itshape Corresponding point\\ in \figureref{fig130}{Fig.~130}.}\\ \cline{5-6} + & & & & \tablespaceup\textit{Calculated.} & \tablespaceup\textit{Observed.} & \\ +\hline +\tablespaceup$2$ & $1$ & $3$ & $1$ & $\Z51$ & $\Z50$ & $A$\\ +$4$ & $2$ & $7$ & $3$ & $\Z89$ & $\Z86$ & $B$\\ +$3$ & $2$ & $5$ & $3$ & $148$ & $143$ & $C$\\ +$4$ & $3$ & $7$ & $5$ & $181$ & $182$ & $D$\\ +$2$ & $2$ & $3$ & $3$ & $246$ & $245$ & $E$\\ +$3$ & $4$ & $5$ & $7$ & $311$ & $305$ & $F$\\ +$2$ & $3$ & $3$ & $5$ & $343$ & $334$ & $G$\\ +$2$ & $4$ & $3$ & $7$ & $402$ & $386$ & $H$\\ +$1$ & $2$ & $1$ & $3$ & $441$ & $443$ & $J$\\ +$1$ & $3$ & $1$ & $5$ & $506$ & $503$ & $K$\\ +$1$ & $4$ & $1$ & $7$ & $529$ & $523$ & $L$\tablespacedown\\ +\hline +\end{tabular} +\end{center} +%% -----File: 482.png---Folio 468------- + +\bigskip + +\Subsection{Specific Inductive Capacity of Dielectrics in rapidly +alternating Electric Fields.} +\index{Specific inductive capacity}% +\index{Capacity xspecific inductive@\subdashone specific inductive|indexetseq}% +\index{Inductive capacity, specific}% + +\Article{390} Methods analogous to those we have just described +have been applied to determine the specific inductive capacities +of dielectrics when transmitting electrical waves a few metres +long. + +One of the most striking results of Maxwell's \textit{Electromagnetic +Theory of Light} is the connection which it entails between the +specific inductive capacity and the refractive index of a transparent +body. On this theory the refractive index for infinitely +long waves is (Maxwell's \textit{Electricity and Magnetism}, vol.~ii, Art.~786) +equal to the square root of the specific inductive capacity +of the dielectric under a steady electric field. + +\Article{391} Some determinations of~$K$, the specific inductive capacity +of various dielectrics in slowly varying fields, are given in the +following table, which also contains the value of~$\mu^2$, the square of +the refractive index for such dielectrics as are transparent. The +letter following the value of~$\mu^2$ denotes the \DPtypo{Frauenhofer}{Fraunhofer} line for +which the refractive index is measured; when $\infty$~is affixed to +the value of~$\mu^2$ the number denotes the square of the refractive +index for infinitely long waves deduced from Cauchy's formula. + +When $\mu$ is given by the observer of the specific inductive +capacity this value has been used, in other cases $\mu$~has been taken +from Landolt's and Börnstein's `Physicalisch-Chemische Tabellen.' + +\renewcommand\thefootnote{\arabic{footnote}} +{ +\tabletextsize +\setlength{\tabcolsep}{4pt} +\begin{longtable}{|l|c|l|c||l|} +\hline +\multicolumn{1}{|c|}{Substance.} & +Observer. & +\multicolumn{1}{c|}{$K$.} & +\settowidth{\TmpLen}{Tempera-}% +\parbox[c]{\TmpLen}{\tablespaceup\centering Tempera-\\ture.\tablespacedown} & +\multicolumn{1}{c|}{$\mu^2$.}\\ +\hline +\endhead +\hline +\endfoot +\tablespaceup Glass, very light flint\mdotfill & Hopkinson\tabfootmark[0] & + $\Z6.57$ & \dots & $2.375~D$\\ +\PadTo{\text{Glass,}}{\Ditto} light flint\mdotfill & \Ditto & + $\Z6.85$ & \dots & $2.478~D$\\ +\PadTo{\text{Glass,}}{\Ditto} dense flint\mdotfill & \Ditto & + $\Z7.4$ & \dots & $2.631~D$\\ +\PadTo{\text{Glass,}}{\Ditto} extra dense flint\mdotfill & \Ditto & + $10.1$ & \dots & $2.924~D$\\ +\PadTo{\text{Glass,}}{\Ditto} hard crown\mdotfill & \Ditto & + $\Z6.96$ & & \\ +\PadTo{\text{Glass,}}{\Ditto} plate\mdotfill & \Ditto & + $\Z8.45$ & & \\ +Paraffin\mdotfill & \Ditto & + $\Z2.29$ & \dots & $2.022~\infty$\\ +Sulphur, along greatest axis\mdotfill & Boltzmann\tabfootmark & + $\Z4.73$ & \dots & $4.89~B$\\ +\PadTo{\text{Sulphur, }}{\Ditto}\PadTo{\text{ along}}{\Ditto} mean axis\mdotfill & \Ditto & + $\Z3.970$ & \dots & $4.154~B$\\ +\PadTo{\text{Sulphur, }}{\Ditto}\PadTo{\text{ along}}{\Ditto} least axis\mdotfill& \Ditto & + $\Z3.811$ & \dots & $3.748~B$\\ +\PadTo{\text{Sulphur, }}{\Ditto} non-crystalline\mdotfill & \Ditto & + $\Z3.84$ & & \\ +Calcite, perpendicular to axis\mdotfill & Romich \& Nowak\tabfootmark & + $\Z7.7$ & \dots & $2.734~A$\\ +\PadTo{\text{Calcite, }}{\Ditto} along axis\mdotfill & \PadTo{\text{Romich}}{\Ditto}\ \PadTo{\text{Nowak}}{\Ditto} & + $\Z7.5$ & \dots & $2.197~A$\\ +%% -----File: 483.png---Folio 469------- +\index{Arons and Cohn, specific inductive capacity of water}% +\index{Cohn and Arons, specific inductive capacity}% +\index{Curie, specific inductive capacity}% +\index{Klemencic@Klemen\v{c}i\v{c}, specific inductive capacity}% +\index{Negreano, specific inductive capacity}% +\index{Nowak and Romich, specific inductive capacity}% +\index{Romich and Nowak, specific inductive capacity}% +\index{Rosa, specific inductive capacity}% +Fluor Spar\mdotfill & \PadTo{\text{Romich}}{\Ditto}\ \PadTo{\text{Nowak}}{\Ditto} & + $\Z6.7$ & \ldots & $2.050\ B$ \\ +Mica\mdotfill & Klemen\v{c}i\v{c}\tabfootmark & + $\Z6.64$ & \ldots & $2.526\ D$ \\ +Ebonite\mdotfill & Boltzmann\tabfootmark[-2] & + $\Z3.15$ & & \\ +Resin\mdotfill & \Ditto & + $\Z2.55$ & & \\ +Quartz along optic axis\mdotfill & Curie\tabfootmark[3] & + $\Z4.55$ & \ldots & $2.41\ D$ \\ +\PadTo{\text{Quartz}}{\Ditto} perpendicular to axis\mdotfill & \Ditto & + $\Z4.49$ & \ldots & $2.38\ D$ \\ +Tourmaline along axis\mdotfill & \Ditto & + $\Z6.05$ & \ldots & $2.63\ D$ \\ +\settowidth{\TmpLen}{Tourmaline perpendicular to} +\parbox[b]{\TmpLen}{\PadTo{\text{Tourmaline}}{\Ditto}perpendicular to\\ + \phantom{Tourmaline pe} axis\mdotfill} & \Ditto & + $\Z7.10$ & \ldots & $2.70\ D$ \\ +Beryl along axis\mdotfill & \Ditto & + $\Z6.24$ & \ldots & $2.48\ D$ \\ +\PadTo{\text{Beryl}}{\Ditto} perpendicular to axis\mdotfill & \Ditto & + $\Z7.58$ & \ldots & $2.50\ D$ \\ +Topaz\mdotfill & \Ditto & + $\Z6.56$ & \ldots & $2.61\ D$ \\ +Gypsum\mdotfill & \Ditto & + $\Z6.33$ & \ldots & $2.32\ D$ \\ +Alum\mdotfill & \Ditto & + $\Z6.4$ & \ldots & $2.2\ D$ \\ +Rock Salt\mdotfill & \Ditto & + $\Z5.85$ & \ldots & $2.36\ D$\tablespacedown \\ +\hline +\tablespaceup Petroleum Spirit\mdotfill & Hopkinson\tabfootmark[-4] & + $\Z1.92$ & \ldots & $1.922\ \infty$ \\ +Petroleum Oil, Field's\mdotfill & \Ditto & + $\Z2.07$ & \ldots & $2.075\ \infty$ \\ +\PadTo{\text{Petroleum}}{\Ditto} \PadTo{\text{Oil,}}{\Ditto} Common\mdotfill & \Ditto & + $\Z2.10$ & \ldots & $2.078\ \infty$ \\ +Ozokerite\mdotfill & \Ditto & + $\Z2.13$ & \ldots & $2.086\ \infty$ \\ +Turpentine, commercial\mdotfill + & \Ditto & + $\Z2.23$ & \ldots & $2.128\ \infty$ \\ +Castor Oil\mdotfill & \Ditto & + $\Z4.78$ & \ldots & $2.153\ \infty$ \\ +Sperm Oil\mdotfill & \Ditto & + $\Z3.02$ & \ldots & $2.135\ \infty$ \\ +Olive Oil\mdotfill & \Ditto & + $\Z3.16$ & \ldots & $2.131\ \infty$ \\ +Neat's-foot Oil\mdotfill + & \Ditto & + $\Z3.07$ & \ldots & $2.125\ \infty$ \\ +Benzene \ce{C6H6}\mdotfill & Hopkinson\tabfootmark[5] & + $\Z2.38$ & \ldots & $2.2614\ D$ \\ +\PadTo{\text{Benzene}}{\Ditto}\PadTo{\ce{C6H6}}{\Ditto} & Negreano\tabfootmark & + $\Z2.2988$ & $25$ & $2.2434\ D$ \\ +\PadTo{\text{Benzene}}{\Ditto}\PadTo{\ce{C6H6}}{\Ditto} & \Ditto & + $\Z2.2921$ & $14$ & $2.2686\ D$ \\ +Toluene \ce{C7H8}\mdotfill & \Ditto & + $\Z2.242$ & $27$ & $2.224\ D$ \\ +\PadTo{\text{Toluene}}{\Ditto}\PadTo{\ce{C7H8}}{\Ditto} & \Ditto & + $\Z2.3013$ & $14$ & $2.245\ D$ \tablespacedown\\ +\tablespaceup Toluene\mdotfill & Hopkinson\tabfootmark[-1] & + $\Z2.42$ & \ldots & $2.2470\ D$ \\ +Xylene \ce{C8H10}\mdotfill & \Ditto & + $\Z2.39$ & \ldots & $2.2238\ D$ \\ +\PadTo{\text{Xylene}}{\Ditto}\PadTo{\ce{C8H10}}{\Ditto} & Negreano\tabfootmark & + $\Z2.2679$ & $27$ & $2.219\ D$ \\ +Metaxylene \ce{C8H10}\mdotfill & \Ditto & + $\Z2.3781$ & $12$ & $2.243\ D$ \\ +Pseudocumene \ce{C9H12}\mdotfill & \Ditto & + $\Z2.4310$ & $14$ & $2.201\ D$ \\ +Cymene \ce{C10H14}\mdotfill & \Ditto & + $\Z2.4706$ & $19$ & $2.201\ D$ \\ +\PadTo{\text{Cymene}}{\Ditto}\PadTo{\ce{C10H14}}{\Ditto} & Hopkinson\tabfootmark[-1] & + $\Z2.25$ & \ldots & $2.2254\ D$ \\ +Terebenthine \ce{C10H16}\mdotfill & Negreano\tabfootmark & + $\Z2.2618$ & $20$ & $2.168\ D$ \\ +Carbon bisulphide\mdotfill & Hopkinson\tabfootmark[-1] & + $\Z2.67$ & \ldots & $2.673\ D$ \\ + & & + & & (at $10°$) \\ +Ether\mdotfill & \Ditto & + $\Z4.75$ & \ldots & $1.8055\ \infty$ \\ +Amylene\mdotfill & \Ditto & + $\Z2.05$ & \ldots & $1.9044\ D$ \\ +Distilled Water\mdotfill & Cohn and Arons\tabfootmark[2] & + $76.$ & $15$\rlap{°?} & $1.779\ D$ \\ +\PadTo{\text{Distilled}}{\Ditto}\PadTo{\text{Water}}{\Ditto} & Rosa\tabfootmark & + $75.7$ & $25\rlap{°}$ & \\ +Ethyl alcohol ($98$\%)\mdotfill & Cohn and Arons\tabfootmark[-1] & + $26.5$ & \ldots & $1.831\ \infty$ \\ +Amyl alcohol\mdotfill & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $15.$ & \ldots & $1.951\ \infty$ \\ +\settowidth{\TmpLen}{Mixture of Xylene and Ethyl}% +\parbox[b]{\TmpLen}{\tabhang Mixture of Xylene and Ethyl\\ alcohol containing $x$~parts \\ of alcohol in unit volume} & & + & & \\ + \qquad$x =\Z.00$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $\Z2.36$&& \\ +\qquad$\phantom{x} = \Z.09$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $\Z3.08$&& \\ +\qquad$\phantom{x} = \Z.17$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $\Z3.98$&& \\ +\qquad$\phantom{x} = \Z.30$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $\Z7.08$&& \\ +\qquad$\phantom{x} = \Z.40$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $\Z9.53$&& \\ +\qquad$\phantom{x} = \Z.50$ & \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $13.0\Z$&& \\ +\qquad$\phantom{x} = 1.\Z\Z$& \PadTo{\text{Cohn and Arons}}{\Ditto\qquad\qquad\Ditto} & + $26.5\Z$&&\tablespacedown \\ +\end{longtable} +} + + \addtocounter{footnote}{-7}% +\footnotetext{Hopkinson, \textit{Phil.\ Trans.}\ 1878, Part~I, p.~17, and \textit{Phil.\ Trans.}\ 1881, Part~II, p.~355.% +\index{Hopkinson, specific inductive capacity}} + \addtocounter{footnote}{1}% +\footnotetext{Boltzmann, \textit{Wien.\ Berichte}~70, 2nd~abth.\ p.~342, 1874.\index{Boltzmann, specific inductive capacity}} + \addtocounter{footnote}{1}% +\footnotetext{Romich and Nowak, \textit{Wien.\ Berichte}~70, 2nd~abth.\ p.~380, 1874.} + \addtocounter{footnote}{1}% +\footnotetext{Klemen\v{c}i\v{c}, \textit{Wien.\ Berichte} 96, 2nd~abth.\ p.~807, 1887.} + \addtocounter{footnote}{1}% +\footnotetext{Curie, \textit{Annales de Chimie et de Physique}, 6, 17, p.~385, 1889.} + \addtocounter{footnote}{1}% +\footnotetext{Hopkinson, \textit{Proc.\ Roy.\ Soc.}\ 43, p.~161, 1887.} + \addtocounter{footnote}{1}% +\footnotetext{Negreano, \textit{Compt.\ rend.}\ 104, p.~425, 1887.} + \addtocounter{footnote}{1}% +\footnotetext{Cohn and Arons, \textit{Wied.\ Ann.}\ 33, p.~13, 1888.} + \addtocounter{footnote}{1}% +\footnotetext{Rosa, \textit{Phil.\ Mag.}\ [5], 31, p.~188, 1891.} +%% -----File: 484.png---Folio 470------- + +The values of $K$ for the following gases at the pressure of +$760$~mm.\ of mercury are expressed in terms of that for a +vacuum. In deducing them it has been assumed that for air +at different pressures the changes in~$K$ are proportional to the +changes in the pressure. +\begin{center} +\tabletextsize +\begin{tabular}{|l|c|l|c||l|} +\hline +\multicolumn{1}{|c|}{Gas.} & Observer. & \multicolumn{1}{c|}{$K$.} & +\multicolumn{1}{c||}{\settowidth{\TmpLen}{Tempera-}% +\parbox[c]{\TmpLen}{\centering\medskip Tempera-\\ture.\medskip}} & \multicolumn{1}{c|}{$\mu^2$.}\\ +\hline +\tablespaceup Air\mdotfill & Boltzmann\tabfootmark[-8] & $1.000590$ & $\Z\Z0°$ & $1.000588\ D$ \\ +\PadTo{\text{Air}}{\Ditto} + & Klemen\v{c}i\v{c}\tabfootmark & $1.000586$ & $\Z\Z0°$ & \\ +Hydrogen\mdotfill & Boltzmann\tabfootmark[-1] & $1.000264$ & $\Z\Z0°$ & $1.000278\ D$ \\ +\PadTo{\text{Hydrogen}}{\Ditto} + & Klemen\v{c}i\v{c}\tabfootmark & $1.000264$ & $\Z\Z0°$ & \\ +Carbonic acid\mdotfill & Boltzmann\tabfootmark[-1] & $1.000946$ & $\Z\Z0°$ & $1.000908\ D$ \\ +\PadTo{\text{Carbonic}}{\Ditto} \PadTo{\text{Acid}}{\Ditto} + & Klemen\v{c}i\v{c}\tabfootmark & $1.000984$ & $\Z\Z0°$ & \\ +Carbonic oxide\mdotfill & Boltzmann\tabfootmark[-1] & $1.00069$ & $\Z\Z0°$ & $1.00067\ D$ \\ +\PadTo{\text{Carbonic}}{\Ditto} \PadTo{\text{Oxide}}{\Ditto} + & Klemen\v{c}i\v{c}\tabfootmark & $1.000694$ & $\Z\Z0°$ & \\ +Nitrous oxide\mdotfill & Boltzmann\tabfootmark[-1] & $1.000994$ & $\Z\Z0°$ & $1.001032\ D$ \\ +\PadTo{\text{Nitric}}{\Ditto} \PadTo{\text{Oxide}}{\Ditto} + & Klemen\v{c}i\v{c}\tabfootmark & $1.001158$ & $\Z\Z0°$ & \\ +Olefiant gas\mdotfill & Boltzmann\tabfootmark[-1] & $1.001312$ & $\Z\Z0°$ & $1.001356\ D$ \\ +Marsh gas\mdotfill & Boltzmann\tabfootmark[0] & $1.000944$ & $\Z\Z0°$ & $1.000886$ \\ +Methyl alcohol\mdotfill & Lebedew\tabfootmark[2] & $1.0057$ & $100°$ & \\ +Ethyl alcohol\mdotfill & \Ditto & & & $1.001745\ D$ \\ + & & $1.0065$ & $100°$ & \multicolumn{1}{c|}{(at~$0°$)} \\ +Methyl formate\mdotfill & \Ditto & $1.0069$ & $100°$ & \\ +Ethyl formate\mdotfill & \Ditto & $1.0083$ & $100°$ & \\ +Methyl acetate\mdotfill & \Ditto & $1.0073$ & $100°$ & \\ +Ethyl ether\mdotfill & \Ditto & $1.0045$ & $100°$ & \\ +\PadTo{\text{Ethyl}}{\Ditto} \PadTo{\text{Ether}}{\Ditto} & Klemen\v{c}i\v{c}\tabfootmark[-1] + & $1.0074$ & $\Z\Z0°$ & $1.003048\ D$ \\ +Carbon bisulphide\mdotfill & \Ditto & $1.0029$ & $\Z\Z0°$ & $1.00296\ D$ \\ +Toluene\mdotfill & Lebedew\tabfootmark & $1.0043$ & $126°$ & \\ +Benzene\mdotfill & \Ditto & $1.0027$ & $100°$ & \tablespacedown \\ +\hline +\end{tabular} +\end{center} + \addtocounter{footnote}{-2}% +\footnotetext{Boltzmann, \textit{Pogg.\ Ann.}~155, p.~403, 1875.}% + \addtocounter{footnote}{1}% +\footnotetext{Klemen\v{c}i\v{c}, \textit{Wien.\ Berichte}~91, 2nd~abth.\ p.~712, 1885.}% + \addtocounter{footnote}{1}% +\footnotetext{Lebedew, \textit{Wied.\ Ann.}~44, p.~288, 1891.\index{Lebedew, specific inductive capacity}}% +%% -----File: 485.png---Folio 471------- + +Ayrton and Perry (\textit{Practical Electricity}, p.~310) found that +\index{Ayrton and Perry, specific inductive capacity of a `vacuum'}% +the specific inductive capacity of a vacuum in which they +estimated the pressure to be $.001$~mm.\ was about~$.994$. This +would make $K$~for air referred to this vacuum as the unit about +$1.006$, while $\mu^2$~from a vacuum to air is about $1.000588$, there is +thus a serious discrepancy between these values. + +\Article{392} We see from the above table that for some substances, +such as sulphur, paraffin, liquid hydrocarbons, and the permanent +gases, the relation $K = \mu^2$ is very approximately fulfilled; while +for most other substances the divergence between $K$~and~$\mu^2$ is considerable. +When, however, we remember (1)~that even when $\mu$~is +estimated for infinitely long waves this is done by Cauchy's +formula, and that the values so deduced would be completely +invalidated if there were any anomalous dispersion below the +visible rays, (2)~that Maxwell's equations do not profess to contain +any terms which would account for dispersion, the marvel is +not that there should be substances for which the relation $K = \mu^2$ +does not hold, but that there should be any for which it does. +To give the theory a fair trial we ought to measure the specific +inductive capacity for electrical waves whose wave length is the +same as the luminous waves we use to determine the refractive +index. + +\Article{393} Though we are as yet unable to construct an electrical +\index{Inductive capacity, specific in rapidly varying fields@\subdashtwo specific in rapidly varying fields}% +system which emits electrical waves whose lengths approach +those of the luminous rays, it is still interesting to measure the +values of the specific inductive capacity for the shortest electrical +waves we can produce. + +We can do this by a method used by von~Bezold (\textit{Pogg.\ Ann.}\ +140, p.~541, 1870) twenty years ago to prove that the velocity +\index{Bezold@v.~Bezold, velocity of electromagnetic waves}% +with which an electric pulse travels along a wire is independent +of the material of wire, it was also used by Hertz in his experiments +on electric waves. + +\includegraphicsouter{fig132}{Fig.~132.} + +This method is as follows. Let $ABCD$~be a rectangle of wires +with an air space at~$EF$ in the middle of~$CD$; this rectangle is +connected to one of the poles of an induction coil by a wire +attached to a point~$K$ in~$AB$, then if $K$~is at the middle of~$AB$ +the pulse coming along the wire from the induction coil will +divide at~$K$ and will travel to $E$~and~$F$, reaching these points +simultaneously; thus $E$~and~$F$ will be in similar electric states +and there will be no tendency to spark across the air gap~$EF$. +%% -----File: 486.png---Folio 472------- +If now we move~$K$ to a position which is not symmetrical with +respect to $E$~and~$F$, then, when a pulse travels along the rectangle, +it will reach one of these points before the other; their +electric states will therefore be different +and there will be a tendency to spark. + +Suppose that with $K$~at the middle +point of~$AB$, we insert~$BC$ into a dielectric +through which electromagnetic +disturbances travel more slowly than +they do through air, then the pulse +which goes round~$AD$ will arrive at~$E$ +before the pulse which goes round~$BC$ +arrives at~$F$; thus $E$~and~$F$ will not be +in the same electrical state and sparks +will therefore pass across the air space. +To get rid of the sparks we must either +move~$K$ towards~$B$ or else keep~$K$ fixed +and, as the waves travel more slowly +through the dielectric than through air, +lengthen the side~$AD$ of the figure. If +we do this until the sparks disappear we may conclude that +$E$~and~$F$ are in similar electric states, and therefore that the +time taken by the pulse to travel round one arm of the circuit +is the same as that round the other. By seeing how much the +length of the one arm exceeds that of the other we can compare +the velocity of electromagnetic action through the dielectric +in which $BC$~is immersed with that through air. + +\Article{394} I have used (\textit{Phil.\ Mag.}\ [5], 30, p.~129, 1890) this method +to determine the velocity of propagation of electromagnetic action +through paraffin and sulphur. This was done by leading one of +the wires, say~$BC$, through a long metal tube filled with either +paraffin or sulphur, the wire being insulated from the tube +which was connected to earth. By measuring the length of wire +it was necessary to insert in~$AD$ to stop the sparks, I found that +the velocities with which electromagnetic action travels through +sulphur and paraffin are respectively $1/1.7$ and $1/1.35$~of the +velocity through air. The corresponding values of the specific +inductive capacities would be about $2.9$~and~$1.8$. + +\includegraphicsmid{fig133}{Fig.~133.} + +\Article{395} Rubens and Arons (\textit{Wied.\ Ann.}\ 42, p.~581; 44, p.~206), +\index{Arons and Rubens, velocity of electromagnetic waves}% +\index{Rubensx and Arons, velocity of electromagnetic waves}% +while employing a method based on the same principles, have +%% -----File: 487.png---Folio 473------- +made it very much more sensitive by using a bolometer instead +of observing the sparks and by using two quadrilaterals +instead of one. The arrangement they used is represented in +\figureref{fig133}{Fig.~133} (\textit{Wied.\ Ann.}\ 42, p.~584). + +The poles $P$~and~$Q$ of an induction coil are connected to +the balls of a spark gap~$S$, to each of these balls a metal plate, +$40$~cm.\ square, was attached by vertical brass rods $15$~cm.\ +long. + +Two small tin plates $x$,~$y$, $8$~cm.\ square, were placed at a distance +of between $3$~and~$4$~cm.\ from the large plates. Then wires +connected to these plates made sliding contacts at $u$~and~$v$ with the +wire rectangles $ABCD$, $EFGH$ $.230$~cm.\ by $35$~cm. One of these rectangles +was placed vertically over the other, the distance between +them being $8$~cm. The points $u$,~$v$ were connected with each other +by a vertical wooden rod, ending in a pointer which moved over +a millimetre scale. The direct action of the coil on the rectangles +was screened off by interposing a wire grating through which the +%% -----File: 488.png---Folio 474------- +wires $u$~$x$, $v$~$y$ were led. The wires $CD$,~$GH$ were cut in the +middle and the free ends were attached to small metal plates +$5.5$~cm.\ square; metal pieces attached to these plates went between +the plates of the little condensers~$J$, $K$,~$L$,~$M$, the plates of these +condensers were attached cross-wise to each other as in the figure. +The two wires connecting the plates were attached to a bolometer +circuit similar to that described in \artref{387}{Art.~387}. By means of a +sliding coil attached to the bolometer circuit, Arons and Rubens +investigated the electrical condition of the circuits $uADJ$, +$uBCK$,~\&c., and found that approximately there was a node in +the middle and a loop at each end; these circuits then may be +regarded as executing electrical vibrations whose wave lengths +are twice the lengths of the circuits. If the times of vibrations of +the circuits on the left of~$u$,~$v$ are the same as those on the right, +the plates $J$~and~$K$ will be in similar electrical states, as will also +$L$~and~$M$, and there will be no deflection of the galvanometer in +the bolometer circuit. When the wires are surrounded by air +this will be when $u$,~$v$ are at the middle points of $AB$,~$EF$. In +practice Arons and Rubens found that the deflection of the +galvanometer never actually vanished, but attained a very +decided minimum when~$u$,~$v$ were in the middle, and that the +effect produced by sliding $u$,~$v$ through $1$~cm.\ could easily be +detected. + +To determine the velocity of propagation of electromagnetic +action through different dielectrics, one of the short sides of the +rectangles was made so that the wires passed through a zinc box, +$18$~cm.\ long, $13$~cm.\ broad, and $14$~cm.\ high; the wires were carefully +insulated from the box; the wires outside the box were +straight, but the part inside was sometimes straight and sometimes +zigzag. This box could be filled with the dielectric under +observation, and the velocity of propagation of the electromagnetic +action through the dielectric was deduced from the +alteration made in the null position (i.e.~the position in which +the deflection of the galvanometer in the bolometer circuit was a +minimum) of~$uv$ by filling the box with the dielectric. + +Let $p_1$~and~$p_2$ be the readings of the pointer attached to~$uv$ +when a straight wire of length~$D_g$ and a zigzag of length~$D_k$ are +respectively inserted in the box, the box in this case being +empty. Then since in each case the lengths of the circuits on the +right and left of~$uv$ must be the same, the difference in the +%% -----File: 489.png---Folio 475------- +lengths of the circuits on the left, when the straight wire and +the zigzag respectively are inserted, must be equal to the difference +in the lengths of the circuits on the right. The length of +the circuit on the left when the zigzag is in exceeds that when +the straight wire is in by +\[ +(D_k - p_2) - (D_g - p_1), +\] +while the difference in the length of the circuits on the right is +\begin{DPgather*} +p_2 - p_1; \\ +\lintertext{hence} +D_k - D_g - (p_2 - p_1) = p_2 - p_1, \\ +\lintertext{or} +D_k - D_g = 2(p_2 - P_1). +\end{DPgather*} + +When the wires are surrounded by the dielectric, Arons and +Rubens regard them as equivalent to wires in air, whose lengths +are $n D_g$~and~$n D_k$, where $n$~is the ratio of the velocity of transmission +of electromagnetic action through air to that through the +dielectric; for the time taken by a pulse to travel over a wire of +length~$n D_g$ in air, is the same as that required for the pulse to +travel over the length~$D_g$ in the dielectric. We shall return to +this point after describing the results of these experiments. If +$p_3$~and~$p_4$ are the readings for the null positions of~$uv$ when the +box is filled with the dielectric, then we have, on Arons and +Rubens' hypothesis, +\[ +n(D_k - D_g) = 2(p_4 - p_3); +\] +or, eliminating $D_k - D_g$, +\[ +n = \frac{p_4 - p_3} {p_2 - p_1} ; +\] +hence, if $p_1$,~$p_2$, $p_3$,~$p_4$ are determined, the value of~$n$ follows +immediately. + +In this way Arons and Rubens found as the values of~$n$ for +the following substances:--- +\begin{center} +\settowidth{\TmpLen}{Castor Oil Castor Oil} +\begin{tabular}{p{\TmpLen} @{} c @{\quad\qquad} c} + & $n$. & $\sqrt{K}$. \\ +Castor Oil\mdotfill & $2.05$ & $2.16$ \\ +Olive Oil\mdotfill & $1.71$ & $1.75$ \\ +Xylol\mdotfill & $1.50$ & $1.53$ \\ +Petroleum\mdotfill & $1.40$ & $1.44$ +\end{tabular} +\end{center} +The values of~$K$, the specific inductive capacity in a slowly +varying field, were determined by Arons and Rubens for the +same samples as they used in their bolometer experiments. + +\Article{396} The method used by Arons and Rubens to reduce their +observations leads to values of the specific inductive capacity +%% -----File: 490.png---Folio 476------- +which are in accordance with those found by other methods. +It is however very difficult to see, using any theory of the +action of the divided rectangle that has been suggested, why the +values of the specific inductive capacity should be accurately +deduced from the observations by this method, except in the +particular case when the wires outside the box are very short +compared with the wave length of the electrical vibrations. + +Considering the case of the single divided rectangle, there +seem to be three ways in which it might be supposed to act. +We may suppose that a single electrical impulse comes to~$K$ (\figureref{fig132}{Fig.~132}), +and there splits up into two equal parts, one travelling +round~$AD$ to~$E$, the other round~$BC$ to~$F$. If these impulses +arrived at $E$~and~$F$ simultaneously they would, if they were of +equal intensity, cause the electric states of $E$~and~$F$ to be similar, +so that there would be no tendency to spark across the gap~$EF$. +Thus, if the pulses arrived at $E$~and~$F$ undiminished in intensity, +the condition for there to be no spark would be that the time +taken by a pulse to travel from~$K$ to~$E$ should be equal to that from~$K$ +to~$F$. This reasoning is not applicable however when the pulse +in its way round one side of the circuit passes through regions in +which its velocity is not the same as when passing through air, +because in this case the pulse will be partly reflected as it passes +from one medium to another, and will therefore proceed with +diminished intensity. Thus, though this pulse may arrive at the +air gap at the same time as the pulse which has travelled round +the other side of the rectangle, it will not have the same intensity +as that pulse; the electrical conditions of the knobs will therefore +be different, and there will therefore be a tendency to spark. +When the pulse has to travel through media of high specific +inductive capacity the reflection must be very considerable, and +the inequality in the pulses on the two sides of the air gap +so great that we should not expect to get under any circumstances +such a diminution in the intensity of the sparks as we +know from experience actually takes place. We conclude therefore +that this method of regarding the action of the rectangle is +not tenable. + +\Article{397} Another method of regarding the action is to look on +the rectangle as the seat of vibrations, whose period is determined +by the electrical system with which it is connected. Thus +we may regard the potential at~$K$ as expressed by $\phi_0 \cos pt$; +%% -----File: 491.png---Folio 477------- +then the condition that there should be no sparks is that the +potentials at $E$~and~$F$ should be the same. We can deduce the +expressions for the potentials at $E$~and~$F$ from that at~$K$ when~$E$ +and~$F$ are nodes or loops. Let us consider the case when the capacity +of the knobs $E$~and~$F$ is so small that the current at $E$~and~$F$ +vanishes. Then we can easily show by the method of \artref{298}{Art.~298} +that if there is no discontinuity in the current along the wire, +and if the self-induction per unit length of the wire is the same +at all points in~$KADE$, and if the portions $AK$,~$DF$ are in air +while $AD$~is immersed in a dielectric in which the velocity of +propagation of electromagnetic action is~$V'$, that through air +being~$V$, then if the potential at~$K$ is $\phi_0 \cos pt$, that at~$F$ is +equal to +{\setlength{\multlinegap}{0pt}% +\begin{multline*} +\hfill\frac{\phi_0 \cos pt} {\Delta},\hfill\\ +\shoveleft{\text{where } +\Delta = \cos\left(\frac{p}{V'} AD\right) \cos \frac{p}{V} (KA + DF) + - \sin\left(\frac{p}{V'} AD\right) ×} \\ + \left\{\mu \sin\left(\frac{p}{V} DF\right) \cos\left(\frac{p}{V} KA\right) + + \frac{1}{\mu} \sin\left(\frac{p}{V} KA\right) \cos\left(\frac{p}{V} DF\right) \right\}, +\end{multline*}% +}% +and $\mu = V/V'$. + +The potential at~$E$ is +\[ +\frac{\phi_0 \cos pt} {\cos \dfrac{p}{V} KE} +\] +if $KE$~represents the total length $KB + BC + CE$, the whole of +which is supposed to be surrounded by air. Hence, if the +potentials at $E$~and~$F$ are the same, we have +\begin{multline*} +\cos\left(\frac{p}{V'} AD\right) \cos \frac{p}{V} (KA + DF) + - \sin\left(\frac{p}{V'} AD\right) × \\ + \left\{\mu \sin\left(\frac{p}{V} DF\right) \cos\left(\frac{p}{V} KA\right) + + \frac{1}{\mu} \sin\left(\frac{p}{V} KA\right) \cos\left(\frac{p}{V} DF\right) \right\} \\ + = \cos \frac{p}{V} KE. +\Tag{1} +\end{multline*} + +To make the interpretation of this equation as simple as +possible, suppose $KA = DF$, equation~(\eqnref{397}{1}) then becomes +\begin{multline*} +\cos\left(\frac{p}{V'} AD\right) \cos\left(\frac{2p}{V} KA\right) + - \left(\mu+\frac{1}{\mu}\right) + \tfrac{1}{2} \sin\left(\frac{p}{V'} AD\right) \sin\left(\frac{2p}{V} KA\right) \\ + = \cos \left(\frac{p}{V} KE\right). +\Tag{2} +\end{multline*} +%% -----File: 492.png---Folio 478------- + +Let us now consider one or two special cases of this equation. +Let us suppose that~$AD$ is so small that $\left(\mu + \dfrac{1}{\mu}\right) \sin \left(\dfrac{p}{V'} AD\right)$ is a +small quantity, then equation~(\eqnref{397}{2}) may be written approximately +\begin{DPgather*} +\cos \left\{\frac{2p}{V} KA + \tfrac{1}{2}\left(\mu+\frac{1}{\mu}\right) \frac{p}{V'} AD \right\} + = \cos \left(\frac{p}{V} KE\right); \\ +\lintertext{hence} +2KA + \tfrac{1}{2} (\mu^2 + 1)AD = KE, \\ +\lintertext{therefore} +\frac{\delta KE}{\delta AD} = \tfrac{1}{2} (\mu^2 + 1), +\end{DPgather*} +so that in this case the process which Arons and Rubens applied +to their measurements would give $(\mu^2+ 1)/2$ and not~$\mu$. + +If, on the other hand, $KA$~is so small that $\left(\mu + \dfrac{1}{\mu}\right) \sin \dfrac{2p}{V} KA$ +is small, equation~(\eqnref{397}{2}) may be written approximately +{\allowdisplaybreaks +\begin{DPgather*} +\cos \left\{\frac{p}{V'} AD + \left(\mu + \frac{1}{\mu}\right) \frac{p}{V} KA \right\} + = \cos \left(\frac{p}{V} KE\right), \\ +\lintertext{or} +\mu AD + \left(\mu + \frac{1}{\mu}\right) KA = KE, \\ +\lintertext{so that} +\frac{\delta KE}{\delta AD} = \mu, +\end{DPgather*} +} +and in this case Arons and Rubens' process gives the correct result. + +\Article{398} A third view of the action of the rectangle, which seems +to be that taken by Arons and Rubens, is that the vibrations are +not forced, but that each side of the rectangle executes its natural +vibrations independently of the other. If the extremities are to +keep in the same electrical states, then the times of vibration of +the two sides must be equal. + +Arons and Rubens' measurements with the bolometer show +that there is a loop at~$K$ and nodes at $E$~and~$F$. + +Now if $2 \pi/p$ is the time of vibration of a wire such as~$KADF$ +with a node at~$F$ and a loop at~$K$, surrounded by air along~$KA$, +$DF$, and along~$AD$ by a medium through which electromagnetic +action travels with the velocity~$V'$, then we can show by a +process similar to that in \artref{298}{Art.~298} that $p$~is given by the equation +\begin{multline*} +\frac{1}{\mu} \cot \left(\frac{p}{V'} AD\right) + - \frac{1}{\mu} \cot \left(\frac{p}{V'} AD\right) + \cot \left(\frac{p}{V} KA\right) + \cot \left(\frac{p}{V} DF\right) \\ + + \frac{1}{\mu^2}\cot\left(\frac{p}{V} KA\right) + \cot \left(\frac{p}{V} DF\right) = 0. +\Tag{3} +\end{multline*} +%% -----File: 493.png---Folio 479------- + +Let us take the case when $KA = DF$, then this equation +becomes +\begin{align*} +\cot \left(\frac{p}{V'} AD\right) + &= \left(\mu + \frac{1}{\mu}\right) + \frac{\cot\left(\dfrac{p}{V} KA\right) } + {\cot^2\left(\dfrac{p}{V} KA\right) - 1 } \\ + &= \tfrac{1}{2} \left(\mu + \frac{1}{\mu}\right) \tan\left(\frac{2p}{V} KA\right), +\end{align*} +\begin{DPgather*} +\lintertext{or} +\cot \left(\frac{2p}{V} KA\right) + = \tfrac{1}{2} \left(\mu + \frac{1}{\mu}\right) \tan \frac{p}{V'} AD. +\Tag{4} +\end{DPgather*} + +Let us consider the special case when $p \centerdot AD/V'$ is small, the +solution of~(\eqnref{398}{4}) is then +{\allowdisplaybreaks +\begin{DPgather*} +\frac{2p}{V} KA = \frac{\pi}{2} + - \tfrac{1}{2} \left(\mu + \frac{1}{\mu}\right) \frac{p}{V'} AD, \\ +\lintertext{or} +\frac{p}{V} \left\{2KA + \frac{\mu^2 + 1}{2} AD \right\} = \frac{\pi}{2}. +\end{DPgather*} +} + +If $p'$ is the time of vibration of $KBCE$ with a loop at~$K$ and +a node at~$E$, this wire being entirely surrounded by air, then +\[ +\frac{p'}{V} (KE) = \frac{\pi}{2}; +\] +hence if $p' = p$, +\begin{DPgather*} +2KA + \frac{\mu^2 + 1}{2} AD = KE, \\ +\lintertext{so that} +\frac{\delta KE}{\delta AD} = \frac{\mu^2 + 1}{2}. +\end{DPgather*} + +Arons and Rubens when reducing their observations took the +ratio $\delta KE / \delta AD$ to be always equal to~$\mu$. The above investigation +shows that this is not the case when $pAD/V'$ is small. We +might show that $\delta KE / \delta AD$ is equal to~$\mu$ when $KA/AD$ is +small. + +The results given on the third view of the electrical vibrations +of the compound wire seem parallel to those which +hold for vibrating strings and bars. Thus if we have three +strings of different materials stretched in series between two +points, the time of longitudinal vibration of this system is not +proportional to the sum of the times a pulse would take to travel +over the strings separately (see Routh's \textit{Advanced Rigid Dynamics}, +\index{Routh@Routh's \textit{Rigid Dynamics}}% +p.~397), but is given by an equation somewhat resembling~(\eqnref{398}{3}). +%% -----File: 494.png---Folio 480------- + +\Article{399} The discrepancy between the results of the preceding +theory of the action of the divided rectangle and the method +employed by Arons and Rubens to reduce their observations, may +perhaps explain to some extent the difference between the values +of the specific inductive capacity of glass in rapidly alternating +electric fields obtained by these observers and those obtained by +\index{Blondlot, velocity of electromagnetic waves@\subdashone velocity of electromagnetic waves}% +M.~Blondlot and myself for the same quantity. + +Arons and Rubens (\textit{Wied.\ Ann.}\ 44, p.~206, 1891) determined +the ratio of the velocity of electromagnetic action through air to +that through glass by filling with glass blocks a box through which +the wires on one side of their rectangle passed. Employing the +same method of reduction as for liquid dielectrics, they found~$\mu$ (the +ratio of the velocities) to be~$2.33$, whence $K = \mu^{2}$ is~$5.43$; while the +value of~$K$ for the same glass, in slowly varying fields, was~$5.37$, +which is practically identical with the preceding value. If, however, +we adopted the method of reduction indicated by the preceding +theory we should get a considerably smaller value of~$K$. +In order to see what kind of diminution we might expect, let +us suppose that the circuit through the glass is so short that +the relation expressed by~(\eqnref{398}{4}) holds. This gives the same value +for $(K+1)/2$ as Arons and Rubens get for~$\mu$; hence we find +$K = 3.66$, a value considerably less than under steady fields. + +\includegraphicsouter{fig134}{Fig.~134.} + +\Article{400} Arons and Rubens checked their method by finding by +means of it the specific inductive capacity of paraffin. This +substance happens to be one for which either method of reduction +leads to very much the same result. For example, for fluid +paraffin their method of reduction gave $\mu = \sqrt{K} = 1.47$, $K = 2.16$; +if we suppose that we ought to have $(K + 1)/2$ instead of~$\mu$ we +get $K = 1.94$, while the value in slowly varying fields is~$1.98$; +so that the result for this substance is not decisive between the +methods of reduction. + +Both M.~Blondlot and myself found that the specific inductive +capacity of glass was smaller under rapidly changing fields than +in steady ones. The following is the method used by M.~Blondlot +(\textit{Comptes Rendus}, May~11, 1891, p.~1058; \textit{Phil.\ Mag.}\ [5], 32, +p.~230, 1891). A large rectangular plate of copper~$AA'$, \figureref{fig134}{Fig.~134}, +is fixed vertically, and a second parallel and smaller plate~$BB'$ +forms a condenser with the first. This condenser discharges +itself by means of the knobs $a$,~$b$; $a$~is connected with the gas +pipes, $b$~with one pole of an induction-coil, the other pole of +%% -----File: 495.png---Folio 481------- +which is connected to the gas pipes. When the coil is working, +electrical oscillations take place in the condenser, the period +of which is of the order $1/25,000,000$ of a second. There is thus +on the side of~$AA'$ a periodic electric field which has~$xx$ as the +plane of symmetry. Two square plates, $CD$,~$C'D'$, are placed in +this field parallel to~$AA'$ and symmetrical +with respect to~$xx$; two +wires terminating in~$EE'$ are +soldered at~$DD'$ to the middle +points of the sides of these plates. +The wires are connected at~$EE'$ to +two carbon points kept facing each +other at a very small distance apart. + +When the coil is working no +sparks are observed between~$E$ +and~$E'$, this is due to the symmetry +of the apparatus. When, +however, a glass plate is placed +between~$AA'$ and~$CD$ sparks immediately +pass between~$E$ and~$E'$; +these are caused by the induction +received by~$CD$ differing from +that received by~$C'D'$. By interposing +between~$AA'$ and~$C'D'$ a +sheet of sulphur of suitable thickness +the sparks can be made to +disappear again. We can thus +find the relative thicknesses of +plates of glass and sulphur which +produce the same effect on the electromagnetic waves passing +through them, and we can therefore compare the specific inductive +capacity of glass and sulphur under similar electrical conditions. +M.~Blondlot found the specific inductive capacity of the sulphur +he employed by Curie's method (\textit{Annales de Chimie et de Physique}, +[6], 17, p.~385, 1889), and assuming that its inductive +capacity was the same in rapidly alternating fields as in steady +ones, he found the specific inductive capacity of the glass to be~$2.84$, +which is considerably less than its value in steady fields. + +\Article{401} I had previously (\textit{Proc.\ Roy.\ Soc.}\ 46, p.~292) arrived at +the same conclusion by measuring the lengths of the electrical +%% -----File: 496.png---Folio 482------- +waves emitted by a parallel plate condenser, (1)~when the +plates were separated by air, (2)~when they were separated by +glass. The period of vibration of the condenser depends upon +its capacity, and this again upon the dielectric between the +plates, so that the determination of the periods gives us the +means of determining the specific inductive capacity of the glass. +The parallel plate condenser loses its energy by radiation slowly, +and will thus force the vibration of its own period upon any +electrical system under its influence. It differs in this respect +from the condenser in \figureref{fig113}{Fig.~113}, which radiates its energy away +so rapidly that its action on neighbouring electrical conductors +approximates to an impulse which starts the free vibrations of +such systems. + +The wave lengths in those observations were determined by +observations on sparks. This is not comparable in delicacy +with the bolometric method of Arons and Rubens; the method +was however sufficiently sensitive to show a considerable falling +off in the specific inductive capacity of the glass, for which +I obtained the value~$2.7$, almost coincident with that obtained +by M.~Blondlot. Sulphur and ebonite on the other hand, when +tested in the same way, showed no appreciable change in their +specific inductive capacity. + + +\Subsection{The Effects produced by a Magnetic Field on Light.} +\index{Light, yeffect of magnetic field on@\subdashone effect of magnetic field on|indexetseq}% +\index{Magnetic zzfield@\subdashone field, effect of on light|indexetseq}% + +\Article{402} The connection between optical and electromagnetic +\index{Faraday, rotation of plane of polarization of light@\subdashone rotation of plane of polarization of light}% +\index{Rotation of plane of polarization of light}% +phenomena is illustrated by the effects produced by a magnetic +field on light passing through it. Faraday was the first to discover +the action of magnetism on light; he found (\textit{Experimental +Researches}, vol.~3, p.~1) that when plane polarized light passes +through certain substances, such as bisulphide of carbon or +heavy glass, placed in a magnetic field where the lines of force +are parallel to the direction of propagation of the light, the +plane of polarization is twisted round the direction of the +magnetic force. The laws of this phenomenon are described in +Maxwell's \textit{Electricity and Magnetism}, Chapter~XXI\@. + +\Article{403} Subsequent investigations have shown that a magnetic +field produces other effects upon light, which, though they +probably have their origin in the same cause as that which produces +the rotation of the plane of polarization in the magnetic +field, manifest themselves in a different way. +%% -----File: 497.png---Folio 483------- + +\index{Magnets, reflection of light from@\subdashone reflection of light from|indexetseq}% +\index{Reflection of light from a magnet@\subdashtwo light from a magnet}% +\index{Kerr, reflection of light from the pole of a magnet}% +\index{Righi, reflection from a magnet@\subdashone reflection from a magnet}% +\index{Kundt, reflection of light from a magnet@\subdashone reflection of light from a magnet}% +\index{Du Bois, reflection of light from a magnet}% +\index{Sissingh, reflection of light from a magnet}% +Thus Kerr (\textit{Phil.\ Mag.}\ [5], 3, p.~321, 1877), whose experiments +have been verified and extended by Righi (\textit{Annales de Chimie et +de Physique}, [6], 4, p.~433, 1885; 9, p.~65, 1886; 10, p.~200, +1887), Kundt (\textit{Wied.\ Ann.}\ 23, p.~228, 1884), Du~Bois (\textit{Wied.\ +Ann.}\ 39, p.~25, 1890), and Sissingh (\textit{Wied.\ Ann.}\ 42, p.~115, 1891) +found that when plane polarized light is incident on the pole of +an electromagnet, polished so as to act like a mirror, the plane +of polarization of the reflected light is not the same when the +magnet is `on' as when it is `off.' + +The simplest case is when the incident plane polarized light +falls normally on the pole of an electromagnet. In this case, +when the magnet is not excited, the reflected ray is plane +polarized, and can be completely stopped by an analyser placed +in a suitable position. If the analyser is kept in this position +and the electromagnet excited, the field, as seen through the +analyser, is no longer quite dark, but becomes so, or very nearly +so, when the analyser is turned through a small angle, showing +that the plane of polarization has been twisted through a small +angle by reflection from the magnetized iron. Righi~(l.c.)\ has +shown that the reflected light is not quite plane polarized, but +that it is elliptically polarized, the axes of the ellipse being of +very unequal magnitude. These axes are not respectively in and +at right angles to the plane of incidence. If we regard for +a moment the reflected elliptically \DPtypo{polarised}{polarized} light as approximately +plane polarized, the plane of polarization being that through +the major axis of the ellipse, the direction of rotation of the plane +of polarization depends upon whether the pole from which the +light is reflected is a north or south pole. Kerr found that the +direction of rotation was opposite to that of the currents exciting +the pole from which the light was reflected. + +The rotation produced is small. Kerr, who used a small +electromagnet, had to concentrate the lines of magnetic force in +the neighbourhood of the mirror by placing near to this a large +mass of soft iron, before he could get any appreciable effects. +\index{Gordon, reflection of light from a magnet}% +By the use of more powerful magnets Gordon and Righi have +succeeded in getting a difference of about half a degree between +the positions of the analyser for maximum darkness with the +magnetizing current flowing first in one direction and then in the +opposite. + +A piece of gold-leaf placed over the pole entirely stops the +%% -----File: 498.png---Folio 484------- +magnetic rotation, thus proving that the rotation of the plane +of polarization is not produced in the air. + +Hall (\textit{Phil.\ Mag.}\ [5], 12, p.~157, 1881) found that the rotation +takes place when the light is reflected from nickel or cobalt, +instead of from iron, and is in the same direction as for iron. + +Righi~(l.c.)\ showed that the amount of rotation depends on the +nature of the light; the longer the wave length the greater (at +least within the limits of the luminous spectrum) the rotation. + + +\Subsection{Oblique Incidence on a Magnetic Pole.} + +\Article{404} When the light is incident obliquely and not normally +on the polished pole of an electromagnet it is necessary, in +order to be able to measure the rotation, that the incident light +should be polarized either in or at right angles to the plane of +incidence, since it is only in these two cases that plane polarized +light remains plane polarized after reflection from a metallic +surface, even though this is not in a magnetic field. When light +polarized in either of these planes is incident on the polished pole +of an electromagnet, the light, when the magnet is on, is elliptically +polarized after reflection, and the major and minor axes +of the ellipse are not respectively in and at right angles to the +plane of incidence. The ellipticity of the reflected light is very +small. If we regard the light as consisting of two plane polarized +waves of unequal amplitudes and complementary phases, then +the rotation from the plane of polarization of the incident wave +to that of the plane in which the amplitude of the reflected wave +is greatest is in the direction opposite to that of the currents +which circulate round the poles of the electromagnet. + +According to Righi the amount of this rotation when the +incident light is polarized in a plane perpendicular to that of +incidence reaches a maximum when the angle of incidence is +between~$44°$ and~$68°$; while when the light is polarized in the +plane of incidence the rotation steadily decreases as the angle of +incidence is increased. The rotation when the light is polarized +in the plane of incidence is always less than when it is polarized +at right angles to that plane, except when the incidence is normal, +when of course the two rotations are equal. + +These results of Righi's differ in some respects from those of +some preceding investigations by Kundt, who, when the light +%% -----File: 499.png---Folio 485------- +was polarized at right angles to the plane of incidence, obtained +a reversal of the sign of the rotation of the plane of polarization +near grazing incidence. + + +\Subsection{Reflection from Tangentially Magnetized Iron.} + +\Article{405} In the preceding experiments the lines of magnetic force +were at right angles to the reflecting surface; somewhat similar +effects are however produced when the mirror is magnetized +tangentially. In this case Kerr (\textit{Phil.\ Mag.}\ [5], 5, p.~161, 1878) +found:--- + +1. That when the plane of incidence is perpendicular to the +lines of magnetic force no change is produced by the magnetization +on the reflected light. + +2. No change is produced at normal incidence. + +3. When the incidence is oblique, the lines of magnetic force +being in the plane of incidence, the reflected light is elliptically +polarized after reflection from the magnetized surface, and the +axes of the ellipse are not in and at right angles to the plane of +incidence. When the light is polarized in the plane of incidence, +the rotation of the plane of polarization (that is the rotation from +the original plane to the plane through the major axis of the +ellipse) is for all angles of incidence in the opposite direction to +that of currents which would produce a magnetic field of the +same sign as the magnet. When the light is polarized at right +angles to the plane of incidence, the rotation is in the same +direction as these currents when the angle of incidence is between +$0°$~and~$75°$ according to Kerr, between $0°$~and~$80°$ according to +Kundt, and between $0°$~and~$78°\,54'$ according to Righi. When the +incidence is more oblique than this, the rotation of the plane of +polarization is in the opposite direction to the electric currents +which would produce a magnetic field of the same sign. + +\Article{406} Kerr's experiments were confined to the case of light +reflected from metallic surfaces. Kundt (\textit{Phil.\ Mag.}\ [5], 18, +p.~308, 1884) has made a most interesting series of observations +of the effect of thin plates of the magnetic metals iron, nickel +and cobalt, on the plane of polarization of light passing through +these plates in a strong magnetic field where the lines of force are +at right angles to the surface of the plates. + +Kundt found that in these circumstances the magnetic metals +possess to an extraordinary degree the power of rotating the +%% -----File: 500.png---Folio 486------- +plane of polarization of the light. The rotation due to an iron +plate is for the mean rays of the spectrum more than $30,000$ +times that of a glass plate of the same thickness in the same +magnetic field, and nearly $1,500$ times the natural rotation +(i.e.~the rotation independent of magnetic force) due to a plate +of quartz of the same thickness. The rotation of the plane +of polarization is with all three substances in the direction +of the currents which would produce a magnetic field of the +same sign as the one producing the rotation. The rotation +under similar circumstances is nearly the same for iron and +cobalt, while for nickel it is decidedly weaker. The rotation is +greater for the red rays than for the blue. + +\Article{407} The phenomena discovered by Kerr show that when the +rapidly alternating currents which accompany light waves are +flowing through iron, nickel, or cobalt in a magnetic field, +electromotive intensities are produced which are at right angles +both to the current and the magnetic force. Let us take, for +example, the simple case when light is incident normally on the +pole of an electromagnet. Let us suppose that the incident +light is polarized in the plane of~$zx$, where $z=0$ is the equation to +the reflecting surface, so that in the incident wave the electromotive +intensities and the currents are at right angles to this +plane; Kerr found, however, that the reflected wave had a component +polarized in the plane of~$yz$; thus after reflection there +are electromotive intensities and currents parallel to~$x$, that is at +right angles to both the direction of the external magnetic field +which is parallel to~$z$ and to the intensities in the incident wave +which are parallel to~$y$. + + +\Subsection{The Hall Effect.} +\index{Hall@`Hall effect'}% + +\Article{408} In the \textit{Philosophical Magazine} for November, 1880, Hall +published an account of some experiments, which show that when +a steady current is flowing in a steady magnetic field electromotive +intensities are developed which are at right angles both to +the magnetic force and to the current, and are proportional to the +product of the intensity of the current, the magnetic force and the +sine of the angle between the directions of these quantities. +\includegraphicsouter{fig135}{Fig.~135.} +The nature of the experiments by which this effect was demonstrated +was as follows: A thin film of metal was deposited on a glass +plate; this plate was placed over the pole of an electromagnet +%% -----File: 501.png---Folio 487------- +and a steady current sent through the film from two electrodes. +The distribution of the current was indicated by finding two +places in the film which were at the same potential; this was +done by finding two points such that if they were placed in +electrical connection with +the terminals of a delicate +galvanometer~($G$) they produced +no current through it +when the electromagnet was +`off.' If now the current +was sent through an electromagnet +a deflection of the +galvanometer~($G$) was produced, +and this continued as +long as the electromagnet was `on,' showing that the distribution +of current in the film was altered by the magnetic field. The +method used by Hall to measure this effect is described in the +following extract taken from one of his papers on this subject +(\textit{Phil.\ Mag.}\ [5], 19, p.~419, 1885). `In most cases, when possible, +the metal was used in the form of a thin strip about $1.1$~centim.\ +wide and about $3$~centim.\ long between the two pieces of brass +$B$,~$B$ (\figureref{fig135}{Fig.~135}), which, soldered to the ends of the strip, served +as electrodes for the entrance +and escape of the main current. +To the arms $a$,~$a$, about +$2$~millim.\ wide and perhaps $7$~millim.\ +long, were soldered the +wires $w$,~$w$, which led to a +Thomson galvanometer. The +notches $c$,~$c$ show how adjustment +was secured. The strip +thus prepared was fastened to +a plate of glass by means of a +cement of beeswax and rosin, +all the parts shown in the +figure being imbedded in and +covered by this cement, which was so hard and stiff as to be +quite brittle at the ordinary temperature of the air. + +\includegraphicsouter{fig136}{Fig.~136.} + +`The plate of glass bearing the strip of metal so embedded was, +when about to be tested, placed with $B$,~$B$ vertical in the narrow +%% -----File: 502.png---Folio 488------- +part of a tank whose horizontal section is shown in \figureref{fig136}{Fig.~136}. +This tank,~$TT$, containing the plate of glass with the metal strip +was placed between the poles~$PP$ of the electromagnet. The +tank was filled with water which was sometimes at rest and +sometimes flowing. By this means the temperature of the strip +of metal was under tolerable control, and the inconvenience +from thermoelectric effects at $a$~and~$a$ considerably lessened. The +diameter of the plane circular ends of the pole pieces~$PP$ were +about $3.7$~centim.' + +By means of experiments of this kind Hall arrived at the conclusion +that if $\alpha$,~$\beta$,~$\gamma$; $u$,~$v$,~$w$ denote respectively the components +of the magnetic force and the intensity of the current, +electromotive intensities are set up whose components parallel +to the axes of $x$,~$y$,~$z$ are respectively +\[ +C(\beta w - \gamma v), \quad +C(\gamma u - \alpha w), \quad +C(\alpha v - \beta u). +\] +The values of~$C$ in electromagnetic units for some metals at +$20°$\,C, as determined by Hall (\textit{Phil.\ Mag.}\ [5], 19, p.~419, 1885), +are given in the following table (l.c.\ p.~436):--- +\begin{center} +\begin{tabular}{p{3in}} +\quad\small Metal.\hfill $C × 10^{15}.\Z$\\ +Copper\mdotfill$- 520$ \\ +Zinc\mdotfill$+ 820$ \\ +Iron\mdotfill$+ 7850$ \\ +Steel, soft\mdotfill$+ 12060$ \\ +\PadTo{\text{Steel,}}{\Ditto} tempered\mdotfill$+ 33000$ \\ +Cobalt\mdotfill$+ 2460$ \\ +Nickel\mdotfill$- 14740$ \\ +Bismuth\mdotfill$- 8580000$ \\ +Antimony\mdotfill$+ 114000$ \\ +Gold\mdotfill$- 660$ +\end{tabular} +\end{center} + +With regard to the magnetic metals, it is not certain that the +quantity primarily involved in the Hall effect is the magnetic +force rather than the magnetic induction, or the intensity of +magnetization. Hall's experiments with nickel seem to point +to its being the last of these three, as he found, using strong +magnetic fields, that the effect ceased to be proportional to +the external magnetic field, and fell off in a way similar to +that in which the magnetization falls off when the field is increased. +We must remember, if we use Hall's value of~$C$ for +iron and the other magnetic metals, to use in the expression for +%% -----File: 503.png---Folio 489------- +the electromotive intensities the magnetic induction instead of +the magnetic force. For in Hall's experiments the magnetic +force measured was the normal magnetic force outside the iron. +Since the plate was very thin the normal magnetic force outside +the iron would be large compared with that inside; the normal +magnetic induction inside would however be equal to the normal +magnetic force outside, so that Hall in this case measured the +relation between the electromotive intensity produced and the +magnetic induction producing it. + +Hall has thus established for steady currents the existence of +an effect of the same nature as that which Kerr's experiments +proved (assuming the electromagnetic theory of light) to exist +for the rapidly alternating currents which constitute light. Here +however the resemblance ends; the values of the coefficient~$C$ +deduced by Hall from his experiments on steady currents do not +apply to rapidly alternating light currents. Thus Hall found +that for steady currents the sign of~$C$ was positive for iron, +negative for nickel; the magneto-optical properties of these +bodies are however quite similar. Again, both Hall and Righi +found that the~$C$ for bismuth was enormously larger than that +for iron or nickel. Righi, however, was unable to find any +traces of magneto-optical effects in bismuth. + +The optical experiments previously described show that there +is an electromotive intensity at right angles both to the magnetic +force and to the electromotive intensity; they do not however +show without further investigation on what function of the +electromotive intensity the magnitude of the transverse intensity +depends. Thus, for example, the complete current in the metal is +the sum of the polarization and conduction currents. Thus, if +the electromotive intensity is~$X$, the total current~$u$ is given by +the equation +\[ +u = \left(\frac{K'}{4\pi}\, \frac{d}{dt} + \frac{1}{\sigma}\right)X, +\] +or if the effects are periodic and proportional to~$\epsilon^{\iota pt}$, +\[ +u = \left(\frac{K'}{4\pi}\, \iota p + \frac{1}{\sigma}\right)X, +\] +where $K'$~is the specific inductive capacity of the metal and~$\sigma$ +its specific resistance. + +We do not know from the experiments, without further discussion, +%% -----File: 504.png---Folio 490------- +whether the transverse electromotive intensity is proportional +to~$u$, the total current, or only to $K'\iota pX/4\pi$, the polarization +part of it, or to~$X/\sigma$, the conduction current. + +We shall assume that the components of the transverse electromotive +intensity are given by the expressions +\begin{gather*} +k(bw - cv), \\ +k(cu - aw), \\ +k(av - bu); +\end{gather*} +where $a$,~$b$,~$c$ are the components of the magnetic induction, +$u$,~$v$,~$w$ those of the total current. + +This form, if $k$~is a real constant, makes the transverse intensity +proportional to the total current; the form is however sufficiently +general analytically to cover the cases where the transverse +intensity is proportional to the polarization current alone or to +the conduction one. Thus, if we put +\[ +k = \left(\frac{K'\iota p/4\pi}{K'\iota p/4\pi + 1/\sigma}\right)k', +\] +where $k'$~is a real constant, the transverse intensity will be proportional +to the displacement current; while if we put +\[ +k = \frac{k''}{K'\iota p/4\pi + 1/\sigma}, +\] +where $k''$~is a real constant, the transverse intensity will be proportional +to the conduction current. We shall now proceed to investigate +which, if any, of these hypotheses will explain the +results observed by Kerr. + +\Article{409} Let $P$,~$Q$,~$R$ be the components of the electromotive +intensity in a conductor, $P'$,~$Q'$,~$R'$ the parts of these which arise +from electromagnetic induction, $a$,~$b$,~$c$ the components of the +magnetic induction, $\alpha$,~$\beta$,~$\gamma$ those of the magnetic force, $u$,~$v$,~$w$ the +components of the current. $K'$,~$\mu'$,~$\sigma$ are respectively the specific +inductive capacity, the magnetic permeability, and the specific +resistance of the metal. + +Then we have in the metal +\begin{align*} +P & = P' + k(bw - cv), \\ +Q & = Q' + k(cu - aw), \\ +R & = R' + k(av - bu), +\end{align*} +where $k$~is a coefficient which bears the same relation to rapidly +alternating currents as~$C$ (\artref{408}{Art.~408}) does to steady currents. If the +%% -----File: 505.png---Folio 491------- +external field is very strong, we may without appreciable error +substitute for $a$,~$b$,~$c$, in the terms multiplied by~$k$, $a_0$,~$b_0$,~$c_0$, the +components of the external field. We shall suppose that this +field is uniform, so that $a_0$,~$b_0$,~$c_0$ are independent of~$x$,~$y$,~$z$. + +By equation~(\eqnref{256}{2}) of \artref{256}{Art.~256} +\begin{align*} +\frac{da}{dt} & = \frac{dQ'}{dz} - \frac{dR'}{dy} \\ + & = \frac{dQ}{dz} - \frac{dR}{dy} + - k\left(a_0\, \frac{d}{dx} + b_0\, \frac{d}{dy} + c_0\, \frac{d}{dz}\right) u, +\Tag{1} +\end{align*} +since $\dfrac{du}{dx} + \dfrac{dv}{dy} + \dfrac{dw}{dz} = 0$ on Maxwell's hypothesis that all the +currents are closed. Now since~$u$ is the component of the total +current parallel to~$x$, it is equal to the sum of the components of +the polarization and conduction currents in that direction. The +polarization current is equal to +\[ +\frac{K'}{4\pi}\, \frac{dP}{dt}, +\] +the conduction current to~$P/\sigma$, hence +\[ +4\pi u = K'\, \frac{dP}{dt} + \frac{4\pi}{\sigma}\, P. +\] +We shall confine our attention to periodic currents and suppose +that the variables are proportional to~$\epsilon^{\iota pt}$; in this case the preceding +equation becomes +\begin{DPalign*} +4\pi u & = (K'\iota p + 4\pi /\sigma) P, \\ +\lintertext{but} +4\pi u & = \frac{d\gamma}{dy} - \frac{d\beta}{dz}; +\end{DPalign*} +hence we have +\begin{DPalign*} +(K'\iota p + 4\pi/\sigma) P & = \frac{d\gamma}{dy} - \frac{d\beta}{dz}; \\ +\lintertext{similarly} +(K'\iota p + 4\pi/\sigma) Q & = \frac{d\alpha}{dz} - \frac{d\gamma}{dx}, \\ +(K'\iota p + 4\pi/\sigma) R & = \frac{d\beta}{dx} - \frac{d\alpha}{dy}; +\end{DPalign*} +and therefore since +\begin{gather*} +\frac{d\alpha}{dx} + \frac{d\beta}{dy} + \frac{d\gamma}{dz} = 0, \\ +(K'\iota p + 4\pi/\sigma) \left(\frac{dQ}{dz} - \frac{dR}{dy}\right) + = \frac{d^2\alpha}{dx^2} + \frac{d^2\alpha}{dy^2} + \frac{d^2\alpha}{dz^2}; +\end{gather*} +%% -----File: 506.png---Folio 492------- +and hence equation~(\eqnref{409}{1}) becomes +\begin{multline*} +(K' \iota p + 4 \pi / \sigma) \mu'\, \frac{d \alpha}{dt} + = \frac{d^{2} \alpha}{dx^{2}} + \frac{d^{2} \alpha}{dy^{2}} + \frac{d^{2} \alpha}{dz^{2}} \\ + - \frac{k}{4 \pi} (K' \iota p + 4 \pi / \sigma) + \left( a_0\, \frac{d}{dx} + b_0\, \frac{d}{dy} + c_0\, \frac{d}{dz} \right) + \left( \frac{d \gamma}{dy} - \frac{d \beta}{dz} \right). +\end{multline*} +Similarly we have +\[ +\left.\begin{aligned} +&(K' \iota p + 4 \pi / \sigma) \mu'\, \frac{d \beta}{dt} + = \frac{d^{2} \beta}{dx^{2}} + \frac{d^{2} \beta}{dy^{2}} + \frac{d^{2} \beta}{dz^{2}} \\ +&\quad - \frac{k}{4 \pi} (K' \iota p + 4 \pi / \sigma) + \left( a_0\, \frac{d}{dx} + b_0\, \frac{d}{dy} + c_0\, \frac{d}{dz} \right) + \left( \frac{d \alpha}{dz} - \frac{d \gamma}{dx} \right), \\ +&(K' \iota p + 4 \pi / \sigma) \mu'\, \frac{d \gamma}{dt} + = \frac{d^{2} \gamma}{dx^{2}} + \frac{d^{2} \gamma}{dy^{2}} + \frac{d^{2} \gamma}{dz^{2}} \\ +& \quad - \frac{k}{4 \pi} (K' \iota p + 4 \pi / \sigma) + \left( a_0\, \frac{d}{dx} + b_0\, \frac{d}{dy} + c_0\, \frac{d}{dz} \right) + \left( \frac{d \beta}{dx} - \frac{d \alpha}{dy} \right). +\end{aligned}\right\} +\Tag{2} +\] +We are now in a position to discuss the reflection of waves of +light from a plane metallic surface. Let us take the plane +separating the metal from the air as the plane of~$xy$, the plane of +incidence as the plane of~$xz$; the positive direction along~$z$ is +from the metal to the air. + +Let us suppose that waves of magnetic force are incidence on +the metal, these incident waves may be expressed by equations +of the form\nbpagebreak[0] +\begin{DPgather*} +\alpha = A_0\, \epsilon^{\iota(lx + mz + pt)},\\ +\beta = B_0\, \epsilon^{\iota(lx + mz + pt)}; \\ +\lintertext{and since} +\frac{d \alpha}{dx} + \frac{d \beta}{dy} + \frac{d \gamma}{dz} = 0,\\ +\gamma = - \frac{l}{m} A_0\, \epsilon^{\iota(lx + mz + pt)}, \\ +\lintertext{where} +l^{2} + m^{2} = \frac{p^{2}}{V^{2}}, +\end{DPgather*} +and $A_0$~and~$B_0$ are constants. + +$V$~is the velocity of propagation of electromagnetic action +through the air and so is equal to~$1/K$, where $K$~is the electromagnetic +measure of the specific inductive capacity of the air, +whose magnetic permeability is taken as unity. Waves will be +reflected from the surface of the metal, and the amplitudes of +these waves will be proportional to $\epsilon^{\iota(lx - mz + pt)}$ , so that $\alpha$,~$\beta$,~$\gamma$, +the components of the total magnetic force in the air, will, since +%% -----File: 507.png---Folio 493------- +it is due to both the incident and reflected waves, be represented +by the equations +\begin{align*} +\alpha & = A_0\, \epsilon^{\iota(lx + mz + pt)} + A\, \epsilon^{\iota(lx - mz + pt)}, \\ +\beta & = B_0\, \epsilon^{\iota(lx + mz + pt)} + B\, \epsilon^{\iota(lx - mz + pt)}, \\ +\gamma & = - \frac{l}{m} A_0\, \epsilon^{\iota(lx + mz + pt)} + + \frac{l}{m} A\, \epsilon^{\iota(lx - mz + pt)}, +\end{align*} +where $A$~and~$B$ are constants. + +We shall suppose that the metal is so thick that there is no +reflection except from the face $z = 0$; in this case the waves in +the metal will travel in the negative direction of~$z$. + +Thus in the metal we may put +\begin{align*} +\alpha & = A'\, \epsilon^{\iota(lx + m'z + pt)}, \\ +\beta & = B'\, \epsilon^{\iota(lx + m'z + pt)}, \\ +\gamma & = - \frac{l}{m'} A'\, \epsilon^{\iota(lx + m'z + pt)}, +\end{align*} +where if $m'$~is complex the real part must be positive in order +that the equations should represent a wave travelling in the +negative direction of~$z$; the imaginary part of~$m'$ must be +negative, otherwise the amplitude of the wave of magnetic force +would increase indefinitely as the wave travelled along.\nbpagebreak[1] + +Substituting these values of $\alpha$,~$\beta$,~$\gamma$ in equations~(\eqnref{409}{2}), we get +\begin{multline*} +A'(-p^{2} \mu' K' + 4 \pi \mu' \iota p / \sigma + l^{2} + m'^{2}) \\ + = - \frac{k}{4 \pi} (K' \iota p + 4 \pi / \sigma) m' (l a_0 + m' c_0) B', +\Tag{3} +\end{multline*} +\begin{multline*} +B'(-p^{2} \mu' K' + 4 \pi \mu' \iota p / \sigma + l^{2} + m'^{2}) \\ + = \frac{k}{4 \pi} (K'\iota p + 4 \pi / \sigma) + \frac{l^{2} + m'^{2}}{m'} (l a_0 + m' c_0) A'. +\Tag{4} +\end{multline*} +Eliminating $A'$~and~$B'$ from these equations, we get +\begin{multline*} +-p^{2} \mu' K' + 4 \pi \mu' \iota p / \sigma + l^{2} + m'^{2} \\ + = ± \frac{\iota k}{4 \pi} (K' \iota p + 4 \pi / \sigma) + (l^{2} + m'^{2})^{\frac{1}{2}} (l a_0 + m' c_0). +\Tag{5} +\end{multline*} + +There are only two values of~$m'$ which satisfy this equation and +which have their real parts positive and their imaginary parts +negative. We shall denote these two roots by~$m_1$,~$m_2$; $m_1$~being +the root when the plus sign is taken in the ambiguity in sign +in equation~(\eqnref{409}{4}), $m_2$~the root when the minus sign is taken. +%% -----File: 508.png---Folio 494------- + +We have from equation~(\eqnref{409}{3}), if $A_1$~and~$B_1$ are the values of~$A'$ +and~$B'$ corresponding to the root~$m_1$, +\begin{DPgather*} +A_1 \iota (l^{2} + m_1^{2})^{\frac{1}{2}} = -B_1 m_1; \\ +\lintertext{or if} +l^{2} + m_1^{2} = \omega_1 ^{2}, \\ +A_1 \iota \omega_1 = -B_1 m_1. +\end{DPgather*} +If $A_2$~and~$B_2$ are the values of $A'$~and~$B'$ corresponding to the +root~$m_2$, we have +\begin{DPgather*} +A_2 \iota \omega_2 = B_2 m_2, \\ +\lintertext{where} +l^{2} + m_2^{2} = \omega_2^{2}. +\end{DPgather*} +Thus in the metal we have +\begin{align*} +\alpha & = A_1\, \epsilon^{\iota(lx + m_1 z + pt)} + + A_2\, \epsilon^{\iota(lx + m_2 z + pt)}, \\ +\beta & = - \frac{\iota \omega_1}{m_1} A_1\, \epsilon^{\iota(lx + m_1 z + pt)} + + \frac{\iota \omega_2}{m_2} A_2\, \epsilon^{\iota(lx + m_2 z + pt)}, \\ +\gamma & = - \frac{l}{m_1} A_1\, \epsilon^{\iota(lx + m_1 z + pt)} + - \frac{l}{m_2} A_2\, \epsilon^{\iota(lx + m_2 z + pt)}. +\end{align*} +We thus see that the original plane wave is in the metal split +up into two plane waves travelling with the velocities $p / \omega_1$, +$p / \omega_2$ respectively. We also see from the equations for $\alpha$,~$\beta$,~$\gamma$ +that the waves are two circularly polarized ones travelling with +different velocities. Starting from this result Prof.\ G.~F. Fitzgerald +\index{Fitzgerald, rotation of plane of polarization of light@\subdashone rotation of plane of polarization of light}% +(\textit{Phil.\ Trans.}\ 1880, p.~691) has calculated the rotation of the +plane of polarization produced by reflection from the surface of a +\emph{transparent} medium which under the action of magnetic force +splits up a plane wave into two circularly polarized ones; some +of the results which he has arrived at are not in accordance +with the results of Kerr's and Righi's experiments on the reflection +from metallic surfaces placed in a magnetic field, proving +that in them we must take into account the opacity of the +medium if we wish to completely explain the results of these +experiments. + +\Article{410} In order to determine the reflected and transmitted waves +we must introduce the boundary conditions. We assume (1)~that +$\alpha$~and~$\beta$, the tangential components of the magnetic force, +are continuous; (2)~that the normal magnetic induction is continuous; +and (3)~that the part of the tangential electromotive +intensity which is due to magnetic induction is continuous. It +should be noticed that condition~(3) makes the total tangential +%% -----File: 509.png---Folio 495------- +electromotive intensity discontinuous, for the total electromotive +intensity is made up of two parts, one due to electromagnetic +induction, the other due to the causes which produce the Hall +effect; it is only the first of these parts which we assume to be +continuous. + +If $P$~is the component parallel to~$x$ of the total electromotive +intensity, $P'$~the part of it due to electromagnetic induction, +then +\[ +P = P' + k(b_0 w - c_0 v); +\] +\begin{DPalign*} +\lintertext{but} +P &= \frac{1}{K'\iota p + 4\pi/\sigma} \Bigl(\frac{d\gamma}{dy} - \frac{d\beta}{dz}\Bigr) \\ + &= - \frac{1}{K'\iota p + 4\pi/\sigma}\, \frac{d\beta}{dz}, +\end{DPalign*} +since in the present case $\gamma$~does not depend upon~$y$. + +Hence, substituting the values of $w$~and~$v$ in terms of the +magnetic force, the condition that $P'$~is continuous is equivalent +to that of +\[ +- \frac{1}{K'\iota p + 4\pi/\sigma}\, \frac{d\beta}{dz} + - \frac{k}{4\pi} \left( b_0\, \frac{d\beta}{dx} - c_0\, \Bigl( \frac{d\alpha}{dz} - \frac{d\gamma}{dx} \Bigr) \right) +\] +being continuous. + +We shall suppose that in the air $k = 0$. + +The condition that $\alpha$~is continuous gives +\[ +A_0 + A = A_1 + A_2; +\Tag{6} +\] +the condition that $\beta$~is continuous gives +\[ +B_0 + B = - \frac{\iota\omega_1}{m_1} A_1 + \frac{\iota\omega_2}{m_2} A_2; +\Tag{7} +\] +the condition that the normal magnetic induction is continuous +gives +\begin{align*} +-\frac{l}{m} (A_0 - A) &= -\mu' \left( \frac{l}{m_1} A_1 + \frac{l}{m_2} A_2 \right), \\ +\intertext{or dividing by~$l$,} +-\frac{1}{m} (A_0 - A) &= -\mu' \left( \frac{1}{m_1} A_1 + \frac{1}{m_2} A_2 \right). +\Tag{8} +\end{align*} + +We can easily prove independently that this equation is true +when $l = 0$, though in that case it cannot be legitimately deduced +from the preceding equation. +%% -----File: 510.png---Folio 496------- + +The condition that $P'$~is continuous gives, since $k = 0$ and $\sigma = \infty$ +for air, +\begin{multline*} +- \frac{m}{K\iota p} (B_0 - B) + = \frac{\iota(\omega_1 A_1 - \omega_2 A_2) }{K'\iota p + 4\pi/\sigma } \\ + - \frac{k}{4\pi} \left\{ + b_0 l \left(- \frac{\iota\omega_1}{m_1} A_1 + \frac{\iota\omega_2}{m_2} A_2\right) + - c_0 \left(\frac{\omega_1^2}{m_1} A_1 + \frac{\omega_2^2}{m_2} A_2\right) \right\}. +\Tag{9} +\end{multline*} + +The equations (\eqnref{410}{6}),~(\eqnref{410}{7}),~(\eqnref{410}{8}), and~(\eqnref{410}{9}) are sufficient to determine +the four quantities~$A$, $A_1$, $A_2$, $B$, and thus to determine the +amplitudes and phases of the reflected and transmitted waves. + +\Article{411} We shall now proceed to apply these equations to the case +of reflection from a tangentially magnetized reflecting surface, as +the peculiar reversal of the direction of rotation of the plane +of polarization which (\artref{405}{Art.~405}) Kerr found to take place when +the angle of incidence passes through~$75°$ seems to indicate that +this case is the one which is best fitted to distinguish between +rival hypotheses. + +Since in this case the magnetic force is tangential $c_0 = 0$; hence, +referring to equation~(\eqnref{409}{5}), we see that there will only be one +value of~$m'$ if $la_0$~vanishes, i.e.~if $l = 0$, in which case the incidence +is normal, or if $a_0 = 0$, in which case the magnetic force is at +right angles to the plane of incidence; hence, since there is only +one value of~$m'$, there will not be any rotation of the plane of +polarization in either of these cases; this agrees with Kerr's +experiments (see \artref{405}{Art.~405}). + +Let us suppose that the light is polarized perpendicularly to +the plane of incidence and that the mirror is magnetized in that +plane. In the incident wave the magnetic force is at right +angles to the plane of incidence, so that the~$A_0$ of equations (\eqnref{410}{6}),~(\eqnref{410}{7}),~(\eqnref{410}{8}), +and~(\eqnref{410}{9}) vanishes. Putting +\[ +A_0 = 0, \quad b_0 = 0, \quad c_0 = 0, +\] +we get from these equations +\begin{gather*} +A = A_1 + A_2, \\ +B_0 + B = -\iota \left( \frac{\omega_1}{m_1} A_1 - \frac{\omega_2}{m_2} A_2\right), \\ +A = -\mu' m \left(\frac{1}{m_1} A_1 + \frac{1}{m_2} A_2\right) \\ +- \frac{m}{K\iota p} (B_0 - B) + = \frac{\iota(\omega_1 A_1 - \omega_2 A_2)} {K'\iota p + 4\pi/\sigma}. +\end{gather*} +%% -----File: 511.png---Folio 497------- + +Since $(K'\iota p + 4\pi/\sigma) / K\iota p + = \dfrac{1}{\mu'} R^2 \epsilon^{2\iota\alpha}$, see \artref{353}{Art.~353}, the last +equation may be written +\[ +-(B_0 - B) = \frac{\iota\mu'} {R^2 \epsilon^{2\iota\alpha} m} (\omega_1 A_1 - \omega_2 A_2). +\] + +The rotation observed is small, we shall therefore neglect the +squares and higher powers of $(m_1 - m_2)$; doing this we find from +the preceding equations that +\[ +\frac{A}{B} + = \frac{\iota\mu'm \left(\dfrac{1}{m_1} - \dfrac{1}{m_2}\right) } + {\omega\left( \dfrac{\mu'}{R^2 \epsilon^{2\iota\alpha} m} - \dfrac{1}{M}\right) + \left(1 + \mu' \dfrac{m}{M}\right) }, +\Tag{10} +\] +where $M$~is the value of~$m_1$ or~$m_2$, when $k = 0$, and $\omega^2 = l^2 + M^2$. + +From equation~(\eqnref{409}{5}) we have, when $c_0 = 0$, +\begin{align*} +-p^2\mu'K' + 4\pi\mu'\iota p/\sigma + l^2 + m_1^2 & = \frac{\iota k}{4\pi} (K'\iota p + 4\pi/\sigma)(l^2 + m_1^2)^{\frac{1}{2}} la_0, \\ +-p^2\mu'K' + 4\pi\mu'\iota p/\sigma + l^2 + m_2^2 & = - \frac{\iota k}{4\pi} (K'\iota p + 4\pi/\sigma)(l^2 + m_2^2)^{\frac{1}{2}} la_0. +\end{align*} + +Hence, when $m_1 - m_2$ is small, we have approximately +\begin{align*} +(m_1 - m_2)M &= \frac{\iota k}{4\pi} (K'\iota p + 4\pi/\sigma)\omega la_0 \\ + &= \frac{\iota k}{4\pi\mu'} R^2 \epsilon^{2\iota\alpha} \iota p V_0^{-2} \omega la_0, +\end{align*} +where $V_0$~denotes the velocity of propagation of electromagnetic +action through air. Substituting this value of $m_1 - m_2$ in +equation~(\eqnref{411}{10}) we get +\[ +\frac{A}{B} = \frac{\iota kp}{4\pi}\, + \frac{R^2 \epsilon^{2\iota\alpha} lmV_0^{-2} a_0\omega } + {M \left( \dfrac{\mu'M}{R^2 \epsilon^{2\iota\alpha} m} - 1 \right) (M + \mu'm) }. +\Tag{11} +\] + +\begin{DPgather*} +\lintertext{\indent If} +\frac{A}{B} = \theta + \iota\phi, +\end{DPgather*} +where $\theta$~and~$\phi$ are real quantities, then if the reflected light +polarized perpendicularly to the plane of incidence is represented +by +\[ +\beta = \cos(pt + lx - mz), +\] +the reflected light polarized in the plane of incidence will be +represented by +\[ +\alpha = \theta \cos(pt + lx - mz) - \phi \sin(pt + lx - mz); +\] +%% -----File: 512.png---Folio 498------- +thus, unless $\phi$~vanishes, the reflected light will be elliptically +polarized. If however $\theta$~and~$\phi$ are small, then the angle between +the major axis of the ellipse for the reflected light and that of +the incident light (regarding this which is plane polarized as the +limit of elliptically polarized light when the minor axis of the +ellipse vanishes) will be approximately~$\theta$. Hence if the analysing +prism is set so as to extinguish the light reflected from +the mirror when it is not magnetized, the field after magnetization +will be darkest when the analyser is turned through an +angle~$\theta$, though even in this case it will not be absolutely dark. +We proceed now to find~$\theta$ from equation~(\eqnref{411}{11}). + +We have by \artref{353}{Art.~\DPtypo{(353)}{353}} +\begin{DPalign*} +l^{2} + M^{2} &= R^{2} \epsilon^{2 \iota \alpha} (l^{2} + m^{2}),\\ +\lintertext{or} +M^{2} &= (R^{2} \epsilon^{2 \iota \alpha} - 1) l^{2} + + R^{2} \epsilon^{2 \iota \alpha} m^{2}. +\end{DPalign*} + +Now for metals the modulus of $R^{2} \epsilon^{2 \iota \alpha}$ is large, the table in +\artref{355}{Art.~355} showing that for steel it is about~$17$; hence we have +approximately +\begin{align*} +M^{2} &= R^{2} \epsilon^{2 \iota \alpha} (l^{2} + m^{2}) \\ + &= R^{2} \epsilon^{2 \iota \alpha} \frac{p^2}{V_0^{2}}. +\end{align*} + +We shall put $\mu' = 1$ in the denominator of the right-hand side +of equation~(\eqnref{411}{11}), since there is no evidence that iron and steel +retain their magnetic properties for magnetic forces alternating +as rapidly as those in the light waves. Making this substitution +and putting $m = (p / V_0) \cos i$, where $i$~is the angle of incidence, +we find +\begin{gather*} +\left( \frac{M}{R^{2} \epsilon^{2 \iota \alpha} m} - 1 \right) (M + m) + = \frac{p}{V_0} \left( \frac{1}{\cos i} - R \epsilon^{\iota \alpha} + \frac{1}{R \epsilon^{\iota \alpha}} - \cos i \right) \\ + = \frac{p}{V_0 \cos i} (1 - \cos^{2} i - R \epsilon^{\iota \alpha} \cos i) +\end{gather*} +approximately, since the modulus of $R \epsilon^{\iota \alpha}$ is large. + +Hence we see +\[ +\frac{A}{B} = \frac{\iota k}{4 \pi}\, + \frac{p a_0 V_0^{-2} R \epsilon^{\iota \alpha} \sin i \cos^{2} i} + {\sin^{2} i - R\epsilon^{\iota \alpha} \cos i}, +\] +so that if $k$~is real, +\[ +\theta = - \frac{k}{4 \pi}\, + \frac{p a_0 V_0^{-2} \sin^{3} i \cos^{2}{i} R \sin \alpha} + {\sin^{4} i - 2 \sin^{2} i \cos{i} R \cos \alpha + R^{2} \cos^{2} i}. +\] +%% -----File: 513.png---Folio 499------- + +This does not change sign for any value of~$i$ between~$0$ and~$\pi/2$; +this result is therefore inconsistent with Kerr's and Kundt's +experiments, and we may conclude that the hypothesis on which +it is founded---that the transverse intensity is proportional to +the \emph{total} current---is erroneous. + +As Kerr's and Kundt's experiments were made with magnetic +metals it seems desirable to consider the results of supposing +these metals to retain their magnetic properties. When $\mu'$~is not +put equal to unity, $\theta$~is proportional to +\[ +\cos^2 i \sin i \sin \alpha + \left(\mu' \sin^2 i + \frac{2\mu'^2}{R} - \cos \alpha \cos i\right); +\] +this does not change sign for any value of~$i$ between~$0$ and~$\pi/2$, +so that the preceding hypothesis cannot be made to agree with +the facts by supposing the metals to retain their magnetic +properties. + +\Article{412} Let us now consider the consequence of supposing that +the transverse electromotive intensity is proportional not to the +total current but to the polarization current; we can do this by +putting +\[ +k = \frac{K'\iota p/4\pi}{K'\iota p/4\pi + 1/\sigma}\, k', +\] +where $k'$~is a real quantity. + +This equation may be written +\[ +k = \frac{K'V_0^2}{R^2 \epsilon^{2\iota\alpha}}\, k'. +\] + +Substituting this value of~$k$ in equation~(\eqnref{411}{11}) we find +\[ +\frac{A}{B} = \frac{\iota k'K'pa_0}{4\pi R\epsilon^{\iota\alpha}}\, + \frac{\sin i \cos^2 i }{\sin^2 i - R\epsilon^{\iota\alpha} \cos i}. +\] + +If we write this in the form +\[ +\frac{A}{B} = \theta' + \iota\phi', +\] +where $\theta'$~and~$\phi'$ are real, we find +\[ +\theta' = \frac{k'K'pa_0}{4\pi R}\, + \frac{\sin i \cos^2 i (\sin \alpha \sin^2 i - R \sin 2 \alpha \cos i)} + {\sin^4 i - 2R\sin^2 i \cos i \cos \alpha + R^2 \cos^2 i}. +\Tag{12} +\] + +The angle through which the analyser has to be twisted in +order to produce the greatest darkness is, as we have seen, equal +to~$\theta'$ the real part of~$A/B$. Equation~(\eqnref{412}{12}) shows that this +%% -----File: 514.png---Folio 500------- +changes sign when $i$~passes through the value given by the +equation +\begin{DPgather*} +\sin \alpha \sin^2 i - R \sin 2\alpha \cos i = 0, \\ +\lintertext{or} +\sin^2 i = 2R \cos \alpha \cos i; +\end{DPgather*} +with the notation of the table in \artref{355}{Art.~355} this is +\[ +\sin^2 i = 2n \cos i. +\] + +If $\mu'$~is not equal to unity the corresponding equation may +easily be shown to be +\[ +\mu' \sin^2 i = 2n \cos i. +\] + +From the table in \artref{355}{Art.~355} we see that for steel $n = 2.41$, the +corresponding value of~$i$ when $\mu' = 1$ is about~$78°$, which agrees +well with the results of Kerr's experiments. Hence we see that +the consequences of the hypotheses, that the transverse electromotive +intensity is proportional to the polarization current, and +that $\mu' = 1$, agree with the results of experiments. + +We shall now consider the consequences of supposing that the +transverse electromotive intensity is proportional to the conduction +current. We can do this by putting +\[ +k = \frac{k''}{K'\iota p/4\pi + 1/\sigma}, +\] +where $k''$~is a constant real quantity. + +This equation may be written +\[ +k = \frac{4\pi k''V_0^2}{\iota pR^2 \epsilon^{2\iota\alpha}}. +\] + +Substituting this value of~$k$ in equation~(\eqnref{411}{11}) we find +\[ +\frac{A}{B} = \frac{k'' \sin i \cos^2 i}{R\, \epsilon^{\iota\alpha} (\sin^2 i - R\, \epsilon^{\iota\alpha} \cos i)}, +\] +the real part of which is +\[ +\frac{k'' \sin i \cos^2 i}{R}\, + \frac{(\cos \alpha \sin^2 i - R \cos 2\alpha \cos i)} + {\sin^4 i - 2\sin^2 i \cos i R \cos\alpha + R^2 \cos^2 i}. +\] + +This is the angle through which the analyser must be twisted +in order to quench the reflected light as much as possible. The +rotation of the analyser will change sign when $i$~passes through +the value given by the equation +\begin{DPalign*} +\cos\alpha \sin^2 i &= R \cos 2\alpha \cos i, \\ +\lintertext{or} +R \cos\alpha \sin^2 i &= R^2 \cos 2\alpha \cos i. +\end{DPalign*} +%% -----File: 515.png---Folio 501------- +With the notation of \artref{355}{Art.~355} this may be written +\[ +n \sin^{2}\iota = n^{2}(1-k^{2}) \cos \iota. +\] +From the table in \artref{355}{Art.~355} we see that $1-k^{2}$ is negative, hence, +since $n$~is positive there is no real value of~$i$ less than~$\pi / 2$ which +satisfies this equation, so that if this hypothesis were correct +there would be no reversal of the direction of rotation of the +analyser. + +Hence of the three hypotheses, (1)~that the transverse electromotive +intensity concerned in these magnetic optical effects +is proportional to the total current, (2)~that it is proportional +to the polarization current, (3)~that it is proportional to the +conduction current, we see that (1)~and~(3) are inconsistent +with Kerr's experiments on the reflection from tangentially +magnetized mirrors, while (2)~is completely in accordance with +them. + +\Article{413} The transverse electromotive intensity indicated by +hypothesis~(2) is of a totally different character from that +discovered by Hall. In Hall's experiments the electromotive +intensities, and therefore the currents through the metallic plates, +were constant; when however this is the case the `polarization' +current vanishes. Thus in Hall's experiments there could have +been no electromotive intensity of the kind assumed in hypothesis~(2); +there is therefore no reason to expect that the order +of the metals with respect to Kerr's effect should be the same as +that with respect to Hall's. + +It is worth noting that reflection from a transparent body +placed in a magnetic field can be deduced from the preceding +equations by putting $\alpha = 0$, since this makes the refractive index +real. In this case we see, by equation~(\eqnref{412}{12}), that the real part of~$A / B$ +vanishes, so that the reflected light is elliptically polarized, +with the major axis of the ellipse in the plane of incidence; +any small rotation of the analyser would therefore in this case +increase the brightness of the field. + +\Article{414} We now proceed to consider the case of reflection from +a normally magnetized mirror. We shall confine ourselves to +the case of normal incidence. + +If the incident light is plane polarized we may (using the +notation of \artref{409}{Art.~409}) put $B_0=0$; we have also $l=0$, $\omega_1 = m_1$, +$\omega_{2} = m_{2}$, and since the mirror is magnetized normally, $a_0 = 0$, +%% -----File: 516.png---Folio 502------- +$b_0 = 0$. Making these substitutions, equations (\eqnref{410}{6}),~(\eqnref{410}{7}),~(\eqnref{410}{8}); and~(\eqnref{410}{9}) +of \artref{410}{Art.~410} become, putting $\mu'= 1$, +\begin{gather*} +A_0 + A = A_1 + A_2, \Tag{13}\\ +B = -\iota(A_1 - A_2), \Tag{14}\\ +A_0 - A = m \left( \frac{A_1}{m_1} + \frac{A_2}{m_2} \right), \Tag{15}\\ +\frac{m}{K \iota p}\, B + = \frac{\iota(m_1 A_1 - m_2 A_2)}{K' \iota p + 4 \pi / \sigma} + + \frac{k}{4 \pi}\, c_0 (m_1 A_1 + m_2 A_2), \Tag{16} +\end{gather*} +where $K$~is the specific inductive capacity of air. The last equation +by means of~(\eqnref{409}{5}) reduces to +{\allowdisplaybreaks +\begin{DPgather*} +\frac{m}{K \iota p}\, B = p \left( \frac{A_1}{m_1} - \frac{A_2}{m_2} \right), \\ +\lintertext{or since} +K p^{2} = m^{2},\\* +B = \iota m \left( \frac{A_1}{m_1} - \frac{A_2}{m_2} \right). +\Tag{17} +\end{DPgather*} +} + +Solving these equations we find +\[ +\frac{B}{A} = - \frac{\iota m (m_1 - m_2)}{m_1 m_2 - m^{2}}. +\] +Now $m_1 - m_2$ is small, and we may therefore, if we neglect +the squares of small quantities, in the denominator of the +expression for~$B/A$, put~$M$ for either $m_1$~or~$m_2$, where $M$~is the +value of these quantities when the magnetic field vanishes. + +We have by equation~(\eqnref{409}{5}) +\begin{align*} +-p^{2} \mu' K' + 4 \pi \mu' \iota p / \sigma + m_1^{2} & = \frac{\iota k}{4 \pi} (K' \iota p + 4 \pi / \sigma) m_1^{2} c_0,\\ +-p^{2} \mu' K' + 4 \pi \mu' \iota p / \sigma + m_2^{2} & = - \frac{\iota k}{4 \pi} (K' \iota p + 4 \pi / \sigma) m_2^{2} c_0; +\end{align*} +\begin{DPgather*} +\lintertext{hence} +m_1 - m_2 = \frac{\iota k}{4 \pi} (K' \iota p + 4 \pi / \sigma) M c_0 +\end{DPgather*} +approximately. + +Since the transverse electromotive intensity is proportional to +the polarization current we have +\[ +k = \frac{K' \iota p / 4 \pi}{K'\iota p / 4 \pi + 1 / \sigma}\, k', +\] +where $k'$~is a real quantity. Substituting this value of~$k$ in the +expression for $m_1 - m_2$ , we get +\[ +m_1 - m_2 = - \frac{p K' k' M c_0}{4 \pi}; +\] +%% -----File: 517.png---Folio 503------- +but $M = R \epsilon^{\iota \alpha} m$, so that +\[ +\frac{B}{A} = \frac{\iota p K' k' R \epsilon^{\iota \alpha} c_0}{4 \pi (R^{2} \epsilon^{2\iota \alpha} - 1)}, +\] +or, since the modulus of $R^{2} \epsilon^{2 \iota \alpha}$ is large compared with unity, +\begin{align*} +\frac{B}{A} &= \frac{\iota p K' k' \epsilon^{-\iota\alpha}}{4\pi R} c_0 \\ +&= \frac{p K' k'}{4 \pi R}\, c_0 (\sin \alpha + \iota \cos \alpha) +\end{align*} +approximately. + +Hence, if the magnetic force in the reflected wave, which is +polarized in the same plane as the incident wave, is represented by +\[ +\cos(pt + mz), +\] +the magnetic force in the reflected wave polarized in the plane +at right angles to this will be represented by +\[ +\frac{p K' k'}{4 \pi R}\, c_0 \sin \alpha \cos(pt+mz) - +\frac{p K' k'}{4 \pi R}\, c_0 \cos \alpha \sin(pt+mz). +\] + +Thus in the expression for the light polarized in this plane one +term represents a component in the same phase as the constituent +in the original plane, while the phase of the component represented +by the other term differs from this by quarter of a wave +length. The resultant reflected light will thus be slightly +elliptically polarized. As in \artref{411}{Art.~\DPtypo{(411)}{411}} however, we may show +that the field can be darkened by twisting the analyser through +a small angle from the position in which it completely quenched +the light when the mirror was not magnetized. The angle for +which the darkening is as great as possible is equal to the real +term in the expression for~$B/A$, i.e.~to +\[ +\frac{p K' k'}{4 \pi R}\, c_0 \sin \alpha. +\] + +Thus though the reflected light cannot be completely quenched +by rotating the analyser, its intensity can be very considerably +reduced; this agrees with the results of Righi's experiments, see +\artref{403}{Art.~403}. + +We can deduce from this case that of reflection from a transparent +substance by putting $\alpha = 0$, as this assumption makes the +refractive index wholly real; in this case the reflected light is elliptically +polarized, but as the axes of the ellipse are respectively +in and at right angles to the plane of the original polarization +%% -----File: 518.png---Folio 504------- +any small rotation of the analyser will increase the brightness +of the field. + +We can solve by similar means the case of oblique reflection +from a normally magnetized mirror; the results agree with Kerr's +experiments; want of space compels us however to pass on to +apply the same principles to the case where light, as in Kundt's +experiments \artref{406}{Art.~406}, passes through thin metallic films placed +in a magnetic field. + + +\Subsection{On the Effect produced by a thin Magnetized Plate on Light +passing through it.} +\index{Films, transmission of light through when in magnetic field@\subdashone transmission of light through when in magnetic field}% +\index{Light, zaction of magnet on light through thin films@\subdashone action of magnet on light through thin films}% +\index{Magnets, zaction of light passing through thin films@\subdashone action of light passing through thin films}% +\index{Rotation of plane of polarization xby a thin film@\subdashtwo of polarization by a thin film}% + +\Article{415} We shall assume that the plate is bounded by the planes +$z = 0$, $z = -h$, the incident light falling normally on the plane +$z = 0$. The external magnetic field is supposed to be parallel to +the axis of~$z$. + +Let the incident light be plane polarized, the magnetic force in +it being parallel to the axis of~$x$. The reflected light will consist +of two portions, one polarized in the same plane as the incident +light, the other polarized in the plane at right angles to this: the +magnetic force in the latter part of the light will therefore be +parallel to the axis of~$y$. + +If $\alpha$,~$\beta$ are the components of the magnetic force parallel to the +axes of $x$~and~$y$ respectively, then in the region for which $z$~is +positive we have +\begin{align*} +\alpha & = A_0 \epsilon^{\iota (mz+pt)} + A \epsilon^{\iota (-mz+pt)},\\ +\beta & = B \epsilon^{\iota (-mz+pt)}, +\end{align*} +where $A_0 \epsilon^{\iota(mz+pt)}$ represents the magnetic force in the incident +wave and $A$~and~$B$ are constants. + +In the plate we have +\[ +\alpha + = A_1 \epsilon^{\iota (m_1 z + pt)} + A_1' \epsilon^{\iota (-m_1 z + pt)} + + A_2 \epsilon^{\iota (m_2 z + pt)} + A_2' \epsilon^{\iota (-m_2 z + pt)}, +\] +and therefore, as in \artref{409}{Art.~409}, as $l=0$, +\[ +\beta + = -\iota A_1 \epsilon^{\iota(m_1 z + pt)} - \iota A_1' \epsilon^{\iota (-m_1 z + pt)} + + \iota A_2 \epsilon^{\iota(m_2 z + pt)} + \iota A_2' \epsilon^{\iota (-m_2 z + pt)}, +\] +where $m_1$,~$m_2$ are the roots of equation~(\eqnref{409}{5}) and $A_1$,~$A_1'$, $A_2$,~$A_2'$ +are constants. + +After the light has passed through the plate, the components +of the magnetic force will be given by equations of the form +\begin{align*} +\alpha & = C \epsilon^{\iota (mz+pt)},\\ +\beta & = D \epsilon^{\iota (mz+pt)}. +\end{align*} +%% -----File: 519.png---Folio 505------- + +The four boundary conditions at the surface $z = 0$ give, if $\mu' = 1$, +\begin{align*} +&\left.\begin{aligned} +A_0 + A &= A_1 + A_1' + A_2 + A_2', \\ +A_0 - A &= m\left(\frac{A_1}{m_1} - \frac{A_1'}{m_1} + \frac{A_2}{m_2} - \frac{A_2'}{m_2}\right); +\end{aligned} \right\} \Tag{18} \\ +&\left.\begin{aligned} +B &= -\iota(A_1 + A_1' - A_2 - A_2'), \\ +B &= \iota m \left(\frac{A_1}{m_1} - \frac{A_1'}{m_1} - \frac{A_2}{m_2} + \frac{A_2'}{m_2}\right). +\end{aligned} \right\} \Tag{19} +\end{align*} + +The boundary conditions when $z = -h$ give, writing $\theta$~and~$\phi$ +for $-\iota m_1 h$, $-\iota m_2 h$ respectively, +\begin{align*} +&\left.\begin{aligned} +C\epsilon^{-\iota mh} + &= A_1 \epsilon^\theta + A_1' \epsilon^{-\theta} + + A_2 \epsilon^\phi + A_2' \epsilon^{-\phi}, \\ +C\epsilon^{-\iota mh} + &= m \left(\frac{A_1 \epsilon^\theta}{m_1} - \frac{A_1' \epsilon^{-\theta}}{m_1} + + \frac{A_2 \epsilon^\phi }{m_2} - \frac{A_2' \epsilon^{-\phi }}{m_2} \right); +\end{aligned} \right\} \Tag{20} \\ +&\left.\begin{aligned} +D\epsilon^{-\iota mh} + &= -\iota (A_1 \epsilon^\theta + A_1' \epsilon^{-\theta} + - A_2 \epsilon^\phi - A_2' \epsilon^{-\phi}), \\ +D\epsilon^{-\iota mh} + &= \iota m \left(\frac{A_1 \epsilon^\theta}{m_1} - \frac{A_1' \epsilon^{-\theta}}{m_1} + - \frac{A_2 \epsilon^\phi }{m_2} + \frac{A_2' \epsilon^{-\phi}}{m_2} \right). +\end{aligned} \right\} \Tag{21} +\end{align*} + +From equations (\eqnref{415}{19}),~(\eqnref{415}{20}), and~(\eqnref{415}{21}) we get +\begin{align*} + &A_1 \epsilon^\theta \bigl(1 - \frac{m}{m_1}\bigr) + A_1' \epsilon^{-\theta} \bigl(1 + \frac{m}{m_1}\bigr) + + A_2 \epsilon^\phi \bigl(1 - \frac{m}{m_2}\bigr) + A_2' \epsilon^{-\phi} \bigl(1 + \frac{m}{m_2}\bigr) = 0,\\ + &A_1 \epsilon^\theta \bigl(1 + \frac{m}{m_1}\bigr) + A_1' \epsilon^{-\theta} \bigl(1 - \frac{m}{m_1}\bigr) + - A_2 \epsilon^\phi \bigl(1 + \frac{m}{m_2}\bigr) - A_2' \epsilon^{-\phi} \bigl(1 - \frac{m}{m_2}\bigr) = 0,\\ + &A_1 \bigl(1 + \frac{m}{m_1}\bigr) + A_1' \bigl(1 - \frac{m}{m_1}\bigr) + - A_2 \bigl(1 + \frac{m}{m_2}\bigr) - A_2' \bigl(1 - \frac{m}{m_2}\bigr) = 0, +\end{align*} + +The solution of these equations may be expressed in the form +{\footnotesize +\begin{align*} +\Delta &= \frac{A_1 \epsilon^{\theta} } + {\epsilon^\phi \Bigl(1 - \dfrac{m}{m_2}\Bigr) \Bigl(1 + \dfrac{m^2}{m_1m_2}\Bigr) - + \epsilon^{-\phi} \Bigl(1 + \dfrac{m}{m_2}\Bigr) \Bigl(1 - \dfrac{m^2}{m_1m_2}\Bigr) + + 2\epsilon^{\theta} \Bigl(1 - \dfrac{m}{m_1}\Bigr) \dfrac{m}{m_2} }, \\ + &= \frac{-A_1' \epsilon^{-\theta} }{\epsilon^\phi \Bigl(1 - \dfrac{m}{m_2}\Bigr) \Bigl(1 - \dfrac{m^2}{m_1m_2}\Bigr) - \epsilon^{-\phi} \Bigl(1 + \dfrac{m}{m_2}\Bigr) \Bigl(1 + \dfrac{m^2}{m_1m_2}\Bigr) + 2\epsilon^{-\theta} \Bigl(1 + \dfrac{m}{m_1}\Bigr) \dfrac{m}{m_2} }, \\ + &= \frac{A_2 \epsilon^{\phi } }{\epsilon^\theta \Bigl(1 - \dfrac{m}{m_1}\Bigr) \Bigl(1 + \dfrac{m^2}{m_1m_2}\Bigr) - \epsilon^{-\theta} \Bigl(1 + \dfrac{m}{m_1}\Bigr) \Bigl(1 - \dfrac{m^2}{m_1m_2}\Bigr) + 2\epsilon^{\phi} \Bigl(1 - \dfrac{m}{m_2}\Bigr) \dfrac{m}{m_1} }, \\ + &= \frac{-A_2' \epsilon^{-\phi } }{\epsilon^\theta \Bigl(1 - \dfrac{m}{m_1}\Bigr) \Bigl(1 - \dfrac{m^2}{m_1m_2}\Bigr) - \epsilon^{-\theta} \Bigl(1 + \dfrac{m}{m_1}\Bigr) \Bigl(1 + \dfrac{m^2}{m_1m_2}\Bigr) + 2\epsilon^{-\phi} \Bigl(1 + \dfrac{m}{m_2}\Bigr) \dfrac{m}{m_1} }. +\end{align*} +} +%% -----File: 520.png---Folio 506------- + +Now by equations (\eqnref{415}{20})~and~(\eqnref{415}{21}) we have +\[ +\frac{D}{C} + = - \frac{\iota ( A_1 \epsilon^{\theta} + A_1' \epsilon^{-\theta} + - A_2 \epsilon^{\phi} - A_2' \epsilon^{-\phi} ) } + {A_1 \epsilon^{\theta} + A_1' \epsilon^{-\theta} + + A_2 \epsilon^{\phi} + A_2' \epsilon^{-\phi}}. +\] + +Substituting the ratios of $A_1$,~$A_1'$, $A_2$,~$A_2'$ just found, we get +{\footnotesize +\begin{gather*} +\text{\normalsize$-\dfrac{D}{C} =$} \\[6pt] + \frac{\iota \left\{\dfrac{1}{m_2} \Bigl( 1 + \dfrac{m^{2}}{m_1^{2}} \Bigr) (\epsilon^{\theta} - \epsilon^{-\theta}) + - \dfrac{1}{m_1} \Bigl( 1 + \dfrac{m^{2}}{m_2^{2}} \Bigr) (\epsilon^{\phi} - \epsilon^{-\phi}) + + \dfrac{2m}{m_1 m_2} (\epsilon^{\phi} + \epsilon^{-\phi} - \epsilon^{\theta} - \epsilon^{-\theta}) \right\} } + { \dfrac{1}{m_2} \Bigl( 1 - \dfrac{m^{2}}{m_1^{2}} \Bigr) (\epsilon^{\theta} - \epsilon^{-\theta}) + + \dfrac{1}{m_1} \Bigl( 1 - \dfrac{m^{2}}{m_2^{2}} \Bigr) (\epsilon^{\phi} - \epsilon^{-\phi})} +\end{gather*} +} + +We notice that the numerator vanishes when $m_1 = m_2$, in +which case $\theta = \phi$: it therefore contains the factor $m_1 - m_2$; hence, +if we neglect the squares and higher powers of $(m_1 - m_2)$, we may +in the denominator put $m_1 = m_2 = M$ and $\phi = \theta$. + +If the thickness of the film is so small that $\theta$~and~$\phi$ are small +quantities, then neglecting powers of~$h$ higher than the second, +we find +\[ +\frac{D}{C} = \tfrac{1}{2}\, \frac{m_2^{2} - m_1^{2}}{M^{2} - m^{2}} (\iota - m h). +\] + +\nbpagebreak[1] +Substituting the value of $m_2^{2} - m_1^{2}$ from equation~(\eqnref{409}{5}), and +putting $M = R \epsilon^{\iota \alpha} m$, we see that +\[ +\frac{D}{C} + = \frac{p K' k' c_0}{4 \pi}\, + \frac{(\iota - m h)}{1 - \dfrac{\epsilon^{- 2 \iota \alpha}}{R^{2}}}. +\] + +Since $R^{2}$~is large for metals we may, as a first approximation, +put +\[ +\frac{D}{C} = \frac{p K' k' c_0}{4 \pi} (\iota - m h). +\] + +The angle through which the plane of polarization is twisted +is equal to the real part of~$D / C$, and is therefore equal to +\[ +- p K' k' c_0 mh / 4 \pi; +\] +it is thus to our order of approximation independent of the +opacity of the plate. We see from \artref{414}{Art.~414} that when light is +incident normally on a magnetized mirror the rotation of the +plane of polarization of the reflected light is proportional to~$\sin\alpha$, +and thus depends primarily on the opacity of the mirror, vanishing +when the mirror is transparent. + +The imaginary part of~$D / C$ remains finite though $h$~is made +%% -----File: 521.png---Folio 507------- +indefinitely small, we therefore infer that the transmitted light is +elliptically polarized, and that the ratio of the axes of the ellipse +is approximately independent of the thickness of the plate. + +Let us now consider the light reflected from the plate. We +have by equations (\eqnref{415}{18})~and~(\eqnref{415}{19}) +\[ +\frac{B}{2A} + = - \frac{\iota(A_1 + A_1' - A_2 - A_2')} + {A_1 \left( 1 - \dfrac{m}{m_1} \right) + A_1' \left( 1 + \dfrac{m}{m_1} \right) + + A_2 \left( 1 - \dfrac{m}{m_2} \right) + A_2' \left( 1 + \dfrac{m}{m_2} \right) }. +\] +Substituting the values of $A_1$,~$A_1'$, $A_2$,~$A_2'$ previously given, +we find, neglecting squares and higher powers of $m_1 - m_2$, +{\footnotesize +\begin{gather*} +\text{\normalsize$-\dfrac{B}{2A} =$} \\[6pt] +\iota \frac{\left\{(\epsilon^{\theta - \phi} - \epsilon^{-(\theta - \phi)}) \dfrac{2 m}{M} \Bigl( 1 + \dfrac{m^2}{M^2} \Bigr) + + \Bigl( \epsilon^{-(\theta + \phi)} - \epsilon^{\theta + \phi} \Bigr) m \Bigl( \dfrac{1}{m_1} - \dfrac{1}{m_2} \Bigr) \Bigl( 1 - \dfrac{m^2}{M^2} \Bigr) \right\} } + {2 \Bigl( 1 - \dfrac{m^2}{M^2} \Bigr)^{2} \{2 - ( \epsilon^{2 \theta} + \epsilon^{-2 \theta} ) \} }. +\end{gather*} +} +If the plate is so thin that $\theta$~and~$\phi$ are small, we have approximately +\begin{align*} +\frac{B}{A} + &= \frac{(m_1 - m_2) \dfrac{m}{M} \left\{1 + \dfrac{m^2}{M^2} + \left( 1 - \dfrac{m^2}{M^2} \right) \right\} } + {\left( 1 - \dfrac{m^2}{M^2} \right)^2 M^2 h } \\ + &= (m_1 - m_2)\, \frac{2m}{M^3 h \left( 1 - \dfrac{m^2}{M^2} \right)^2} \\ + &= \frac{2(m_1 - m_2)m}{M^3 h}, +\end{align*} +since $m/M$~is small for metals. + +Substituting the value of $m_1 - m_2$ from equation~(\eqnref{409}{5}) we get, +putting $M = R \epsilon^{\iota \alpha} m$, +\[ +\frac{B}{A} = - \frac{pK'k'c_0}{2\pi}\, \frac{1}{m R^{2} \epsilon^{2 \iota \alpha} h}; +\] +the rotation of the plane of polarization is equal to the real part +of~$B / A$, and hence to +\[ +- \frac{K' k' c_0}{2 \pi}\, \frac{p}{m h}\, \frac{\cos 2 \alpha}{R^{2}}. +\] + +Since this is proportional to~$1 / h$ we see that the rotation +increases as the thickness of the plate diminishes. The explanation +%% -----File: 522.png---Folio 508------- +of this is that while the intensities of the two components +reflected light, viz.~the component polarized in the same plane as +the incident wave and the component polarized in the plane at +right angles to this, both diminish as the thickness of the plate +diminishes; the first component diminishes much more rapidly +than the second; thus the ratio of the second component to the +first and therefore the angle of rotation of the plane of polarization +increases as the thickness of the plate diminishes. + +\Article{416} The effect of a magnetic field in producing rotation of +the plane of polarization thus seems to afford strong evidence of +the existence of a transverse electromotive intensity in a conductor +placed in a magnetic field, this intensity being quite +distinct from that discovered by Hall, inasmuch as the former +is proportional to the rate of variation of the electromotive intensity, +whereas the Hall effect is proportional to the electromotive +intensity itself. We shall now endeavour to form some estimate +of the magnitude of this transverse intensity revealed to us by +optical phenomena. + +Kundt (\textit{Wied.\ Ann.}~23, p.~238, 1884) found from his experiments +\index{Kundt, transmission of light through thin films@\subdashone transmission of light through thin films}% +that if~$\phi$, the rotation of the plane of polarization +produced by the passage of light of wave length~$\lambda$ through a +magnetized plate of thickness~$h$, is given by an equation of the +form +\[ +\phi = \frac{\pi h}{\lambda} (n - n'), +\] +then $\phi = 1°.48'$ when +\begin{DPgather*} +\lambda = 5.8 × 10^{-5}, \quad \text{and} \quad h = 5.5 × 10^{-6}, \\ +\lintertext{thus} +n - n' = .1. +\end{DPgather*} + +But we have seen that the rotation in this case is equal to +\[ +\frac{pK'k'c_0}{2\pi}\, \frac{\pi h}{\lambda}; +\] +hence, comparing this with Kundt's result, we find +\[ +\frac{pK'k'c_0}{2\pi} = .1, +\] +but if $\lambda = 5.8 × 10^{-5}$, $p = 2\pi × 3 × 10^{10} × 10^5 /5.8 = 3.2 × 10^{15}$. + +Substituting these values, we find +\[ +\frac{K'k'}{2\pi}\, c_0 = 3.1 × 10^{-17}. +\] +%% -----File: 523.png---Folio 509------- + +Now if $f$~is the electric polarization parallel to~$x$, the transverse +electromotive intensity is equal to +\begin{align*} +k'c_0 \frac{df}{dt} + &= k' \iota pc_0 f \\ + &= k' \frac{K'}{4\pi} \iota pc_0 X, +\end{align*} +where $X$~is the electromotive intensity parallel to~$x$. Hence +$k'K'pc_0 /4\pi$ the ratio of the magnitude of the transverse intensity +to that producing the current; this ratio is for iron therefore +equal to +\[ +1.6 × 10^{-17} p +\] +for magnetic fields of the strength used by Kundt. The factor +multiplying~$p$ is so small as to make it probable that the effects +of this transverse force are insensible except when the electromotive +intensity is changing with a rapidity comparable with +the rate of change in light waves, in other words, that it is +only in optical phenomena that this transverse electromotive +intensity produces any measurable effect. +%% -----File: 524.png---Folio 510------- + +\Chapter{Chapter VI.}{The Distribution of Rapidly Alternating Currents.} +\index{Alternating currents, distribution among a net-work of conductors}% +\index{Rayleigh, Lord, distribution of alternating currents@\subdashtwo distribution of alternating currents|indexetseq}% + +\Article{417} \Firstsc{Problems} concerning alternating currents have become +in recent years of much greater importance than they were at +the time when Maxwell's Treatise was published; this is due to +the extensive use of such currents for electric lighting, and to the +important part which the much more rapidly oscillating currents +produced by the discharge of Leyden jars now play in electrical +researches. It is therefore desirable to consider more +fully than is done in the \textit{Electricity and Magnetism} the application +of Maxwell's principles to such currents. In doing this +we shall follow the methods used by Lord Rayleigh in his papers +on `The Reaction upon the Driving-Point of a System executing +Forced Harmonic Oscillations of various Periods, with Applications +to Electricity,' \textit{Phil.\ Mag.}~[5], 21, p.~369, 1886, and on +`The Sensitiveness of the Bridge Method in its Application to +Periodic Electric Currents,' \textit{Proc.\ Roy.\ Soc.}~49, p.~203, 1891. + +\Article{418} When the currents are steady their distribution among a +net-work of conductors is determined by the condition that the +rate of heat production must be a minimum, see Maxwell's +\textit{Electricity and Magnetism}, vol.~i.\ p.~408. Thus, if $F$~is the +Dissipation Function (\textit{Electricity and Magnetism}, vol.~i.\ p.~408), +$\dot{x}_1$,~$\dot{x}_2$, $\dot{x}_3 \ldots$ the currents flowing through the circuits, these +variables being chosen so that they are sufficient but not more +than sufficient to determine the currents flowing through each +branch of the net-work, then $\dot{x}_1$,~$\dot{x}_2$,~\&c.\ are determined by the +equations +\[ +\frac{dF}{d\dot{x}_1} = \frac{dF}{d\dot{x}_2} = \frac{dF}{d\dot{x}_3} = \ldots = 0. +\] +%% -----File: 525.png---Folio 511------- +When, however, the currents are variable these equations are no +longer true; we have instead of them the equations +\begin{gather*} +\frac{d}{dt}\, \frac{dT}{d\dot{x}_1} + \frac{dF}{d\dot{x}_1} - \frac{dV}{dx_1} = 0,\\ +.\quad .\quad .\quad .\quad .\quad .\quad .\quad .\quad . +\end{gather*} +where $T$~is the Kinetic Energy due to the Self and Mutual induction +of the circuits, $F$~as before is the Dissipation Function, +and $V$~is the Potential Energy arising from the charges that +may be in any condensers in the system. + +If the currents are periodic and proportional to~$\epsilon^{\iota pt}$, the preceding +equation may be written as +\[ +\iota p\, \frac{dT}{d\dot{x}_1} + \frac{dF}{d\dot{x}_1} - \frac{dV}{dx_1} = 0 +\] +and thus when $p$~increases indefinitely the preceding equation +approximates to +\[ +\frac{dT}{d\dot{x}_1} = 0; +\] +we have similarly +\[ +\frac{dT}{d\dot{x}_2} = \frac{dT}{d\dot{x}_3} = \ldots = 0. +\] +Thus in this case the distribution of currents is independent +of the resistances, and is determined by the condition that +the Kinetic Energy and not the Dissipation Function is a +minimum. + +\index{Kinetic energy, xa minimum for rapidly alternating currents@\subdashtwo a minimum for rapidly alternating currents}% +\Article{419} We have already considered several instances of this +effect. Thus, when a rapidly alternating current travels along a +wire, the currents fly to the outside of the wire, since by doing +this the mean distance between the parts of the current is a +maximum and the Kinetic Energy therefore a minimum. Again, +when two currents in opposite directions flow through two +parallel plates the currents congregate on the adjacent surfaces +of the plates, since by so doing the average distance between +the opposite currents, and therefore the Kinetic Energy, is a +minimum. + +\includegraphicsmid[b]{fig137}{Fig.~137.} + +\includegraphicsmid[t]{fig138}{Fig.~138.} + +Mr.\ G.~F.~C. Searle has devised an experiment which shows +\index{Searle, experiment on alternating currents}% +this tendency of the currents in a very striking way. $AB$,~\figureref{fig123}{Fig.~123}, +is an exhausted tube through which the periodic currents +produced by the discharge of a Leyden jar are sent. When none +of the wires leading from the jar to the tube passes parallel to it +%% -----File: 526.png---Folio 512------- +in its neighbourhood, the glow produced by the currents fills the +tube uniformly. When however one of the leads is bent, as in +\figureref{fig137}{Fig.~137}, so as to pass near the tube in such a way that the current +through the lead is in the opposite direction to that through the +tube, the glow no longer fills the tube but concentrates itself on +the side of the tube next the wire, thus getting as near as possible +to the current in the opposite direction through the wire. When +however the wire is bent, as in \figureref{fig138}{Fig.~138}, so that the current +through the lead is in the same direction as that through the +tube, the glow flies to the part of the tube most remote from the +wire. + +\includegraphicsmid{fig139}{Fig.~139.} + +\Article{420} We shall now proceed to consider the distribution of +\index{Alternating currents, distribution of between two circuits in parallel@\subdashtwo distribution of between two circuits in parallel}% +alternating currents among various systems of conductors. The +first case we shall consider is the distribution of an alternating +current between two conductors $ACB$,~$ADB$ in parallel. Let the +resistance and self-induction in the arm~$ACB$ be respectively +$R$,~$L$, the corresponding quantities in the arm~$ADB$ being denoted +by $S$,~$N$, and let~$M$ be the coefficient of mutual induction between +the circuits $ACB$,~$ADB$. We shall suppose that the rate of +alternation of the current is not so rapid as to produce any +%% -----File: 527.png---Folio 513------- +appreciable variation in the intensity of the current from one +end of~$ACB$ or~$ADB$ to the other, in other words, that the wave +length corresponding to the rate of alternation of the current +is large compared with the length~$ACB$ or~$ADB$; the case +when this wave length is comparable with the length of the +circuit is considered separately in \artref{298}{Art.~298}. Let the current +flowing in along~$OA$ and out along~$BP$ be denoted by~$\dot{x}$; we +shall assume that $\dot{x}$~varies as~$\epsilon^{\iota pt}$. Let the current in~$ACB$ be~$\dot{y}$, +that in~$ADB$ will be $\dot{x} - \dot{y}$. Then~$T$, the Kinetic Energy in +the branch $ACDB$ of the circuit, is expressed by the equation +\[ +T = \tfrac{1}{2} \{L \dot{y}^{2} + 2 M ( \dot{x} - \dot{y} ) \dot{y} + N ( \dot{x} - \dot{y} )^{2} \}. +\] +The dissipation function~$F$ is given by +\[ +F = \tfrac{1}{2} \{R \dot{y}^{2} + S ( \dot{x} - \dot{y} )^{2} \}, +\] +and we have +\begin{gather*} +\frac{d}{dt}\, \frac{dT}{d \dot{y}} + \frac{dF}{d \dot{y}} = 0, \\ +\intertext{or} +( L + N - 2 M ) \frac{d \dot{y}}{dt} + ( R + S ) \dot{y} - ( N - M ) \frac{d \dot{x}}{dt} - S \dot{x} = 0. +\end{gather*} + +Let $\dot{x} = \epsilon^{\iota pt}$, then from this equation we have +\[ +\dot{y} = \frac{(N - M) \iota p + S}{( L + N - 2M ) \iota p + ( R + S ) }\, \epsilon^{\iota pt}, +\] +or, taking the real part of this, corresponding to the current $\cos pt$ +along $OA$, we find +{\footnotesize +\setlength{\multlinegap}{0pt} +\eqnlabel{\eqnart.1} +\begin{multline*} +\dot{y} =\\ + \frac{\{S(R + S) + (L + N - 2M)(N - M)p^{2} \} \cos pt - p \{R(N - M) - S(L - M)\} \sin pt} + {(L + N - 2M)^{2} p^{2} + (R + S)^{2}},\nbtag{1} +\end{multline*} +\eqnlabel{\eqnart.2} +\begin{multline*} +\dot{x} - \dot{y} =\\ + \frac{\{R(S + R) + (L + N - 2M)(L - M)p^{2} \} \cos pt + p \{R(N - M) - S(L - M) \} \sin pt} + {(L + N - 2M)^{2} p^{2} + (R + S)^{2}}.\nbtag{2} +\end{multline*} +} +These expressions may be written in the forms +\begin{gather*} +\dot{y} + = \Bigl\{\frac{S^{2} + (N - M)^{2} p^{2}}{(L + N - 2M)^{2} p^{2} + (R + S)^{2}} \Bigr\}^{\frac{1}{2}} \cos(pt + \epsilon) = A \cos(pt+\epsilon), \text{ say},\\ +\dot{x} - \dot{y} + = \left\{\frac{R^{2} + (L - M)^{2} p^{2}}{(L + N - 2M)^{2} p^{2} + (R + S)^{2}} \right\}^{\frac{1}{2}} \cos(pt + \epsilon') = B \cos(pt+\epsilon'), +\end{gather*} +\begin{DPalign*} +\lintertext{where} +\tan \epsilon & = \frac{p \{R(N - M) - S(L - M) \}}{S(R + S) + (L + N - 2M)(N - M)p^{2}}, \\ +\lintertext{and} +\tan \epsilon' & = - \frac{p \{R(N - M) - S(L - M) \}}{R(R + S) + (L + N - 2M)(L - M)p^{2}}. +\end{DPalign*} +%% -----File: 528.png---Folio 514------- + +The maximum currents through $ACB$,~$ADB$ are proportional +to $A$~and $B$, and we see from the preceding equations that +\[ +\frac{A}{\{S^{2} + (N - M)^{2} p^{2} \}^{\frac{1}{2}}} = +\frac{B}{\{R^{2} + (L - M)^{2} p^{2} \}^{\frac{1}{2}}}. +\] +When $p$~is very large, this equation becomes +\[ +\frac{A}{N - M} = \frac{B}{L - M}, +\] +so that in this case the distribution of the currents is governed +entirely by the induction in the circuits, and not at all by their +resistances. Referring to equations (\eqnref{420}{1})~and~(\eqnref{420}{2}) we see that when +$p$~is infinite +\begin{align*} +\dot{y} &= \frac{N - M}{L + N - 2M} \cos pt, \Tag{3} \\ +\dot{x} - \dot{y} &= \frac{L-M}{L + N - 2M} \cos pt. \Tag{4} +\end{align*} + +An inspection of these equations leads to the interesting result +that when the alternations are very rapid the maximum current +in one or both of the branches may be greater than that in the +leads. Consider the case when the two circuits $ACB$,~$ADB$ are +wound close together. Suppose, for example, that they are parts +of a circular coil, and that there are $m$~turns in the circuit~$ACB$, +and $n$~turns in~$ADB$, then if the coils are close together we may +put +\[ +L = Km^{2},\quad M = Knm,\quad N = Kn^{2}, +\] +where $K$~is a constant. + +Substituting these values for $L$,~$M$,~$N$ in equations (\eqnref{420}{3})~and~(\eqnref{420}{4}) +we find +\begin{align*} +\dot{y} + &= \frac{n^{2} - nm}{(n - m)^{2}} \cos pt + = \frac{n}{n - m} \cos pt, \Tag{5} \\ +\dot{x} - \dot{y} + &= \frac{m^{2} - nm}{(n - m)^{2}} + = - \frac{m}{n - m} \cos pt. \Tag{6} +\end{align*} + +Thus the currents are of opposite signs in the two coils, the +current in the coil with the smallest number of turns flows in +the same direction as the current in the leads. When $n - m$ is +very small both currents become large, being now much greater +than the current in the leads whose maximum value was taken +%% -----File: 529.png---Folio 515------- +as unity; thus by introducing an alternating current of small +intensity into a divided circuit, we can produce in the arms of +this circuit currents of very much greater intensity. The reason +of this becomes clear when we consider the energy in the loop, +when the rate of alternation is exceedingly rapid. The effects +of the inertia of the system become all important, and the distribution +of currents is that which would result if we considered +merely the Kinetic Energy of the system. In this case, in +accordance with dynamical principles, the actual solution is that +which makes the Kinetic Energy as small as possible consistent +with the condition that the algebraical sum of the currents in +$ACB$,~$ADB$ shall be equal to~$\dot{x}$. + +Thus, as the Kinetic Energy is to be as small as possible, and +this energy is in the field around the loop and proportional at each +place to the square of the magnetic force, the currents will +distribute themselves in the wires so as to neutralize as much as +possible each other's magnetic effect. Thus if the wires are wound +close together the currents will flow in opposite directions, the +branch having the smallest number of turns having the largest +current, so as to be on equal terms as far as magnetic force is +concerned with the branch with the larger number of turns. In +fact we see from equations (\eqnref{420}{5})~and~(\eqnref{420}{6}) that the current in each +branch is inversely proportional to the number of turns. If the +two branches are exactly equal in all respects the current in +each will be in the same direction, but this distribution will be +unstable, the slightest difference of the coefficients of induction in +the two branches being sufficient to make the current in the +branch of least inductance flow in the direction of that in the +leads, and the current in the other branch in the opposite direction, +the intensity in either branch at the same time increasing +largely. + +When the currents are distributed in accordance with equations +(\eqnref{420}{3})~and (\eqnref{420}{4}), the Kinetic Energy in the loop is +\[ +\tfrac{1}{2}\, \frac{LN-M^2}{L+N-2M}\, p^2 \cos^2 pt. +\] + +We notice that $(LN - M^2)/(L + N - 2M)$ is always less than +$L$~or~$N$. $L + N - 2M$~is always positive, since it is proportional +to the Kinetic Energy in the loop when the currents are equal +and opposite. +%% -----File: 530.png---Folio 516------- + +We see from equations (\eqnref{420}{1})~and~(\eqnref{420}{2}) that when +\begin{gather*} +R(N - M) = S(L - M), \\ +\dot{y} = \frac{S}{R+S} \cos pt, \\ +\dot{x} - \dot{y} = \frac{R}{R+S} \cos pt. +\end{gather*} +So that in this case the distribution of alternating currents of +any frequency is the same as when the currents are steady. + +\Article{421} We shall now consider the self-induction and resistance +\index{Induction, self, for two wires in parallel@\subdashtwo for two wires in parallel}% +\index{Self-induction, expression for, of two wires in parallel@\subdashtwo of two wires in parallel}% +\index{Multiple arc, xself-induction of wires in@\subdashtwo self-induction of wires in}% +of the two wires in parallel. Let $L_0$ and~$r$ be respectively the +self-induction and resistance of the leads, and suppose that +there is no mutual induction between the leads and the branches +$ACB$,~$ADB$. + +Then we have +\begin{multline*} +(L_0 + N)\frac{d\dot{x}}{dt} - (N - M)\frac{d\dot{y}}{dt} + (r + S)\dot{x} - S\dot{y} \\ += \text{external electromotive force tending to increase~$x$}. +\end{multline*} + +Substituting in this expression the value of~$\dot{y}$ in terms of~$\dot{x}$ +previously obtained in \artref{420}{Art.~420}, we find +\begin{multline*} +(L_0 + N) \frac{d\dot{x}}{dt} + - \frac{{(N-M)\iota p + S}^2}{(L+N-2M)\iota p+R+S} \dot{x} + (r+S)\dot{x} \\ + = \text{external electromotive force tending to increase~$x$}. +\end{multline*} + +Remembering that $\iota p\dot{x} = d\dot{x}/dt$, we see that the left-hand side +of this equation may be written +\begin{multline*} +\left\{L_0 + \frac{NR^2 + LS^2 + 2MRS + p^2(LN-M^2)(L+N-2M)} + {(R+S)^2 + p^2(L+N-2M)^2}\right\} \frac{d\dot{x}}{dt} \\ + + \left\{r + \frac{RS(R+S) + p^2{R(N-M)^2 + S(L-M)^2}} + {(R+S)^2 + p^2(L+N-2M)^2}\right\} \dot{x}. +\end{multline*} + +From the form of this equation we see that the self-induction +of the two wires in parallel is +\[ +\frac{NR^2 + LS^2 + 2MRS + p^2(LN-M^2)(L+N-2M)} + {(R+S)^2 + p^2(L+N-2M)^2}, +\] +which may be written as +\begin{multline*} +\frac{NR^2 + LS^2 + 2MRS}{(R+S)^2} \\ +- \frac{p^2(L+N-2M)}{(R+S)^2+p^2(L+N-2M)^2}\, \{R(N-M)-S(L-M)\}^2. +\end{multline*} +%% -----File: 531.png---Folio 517------- + +The impedance of the loop is +\[ +\frac{RS(R+S) + p^2\{R(N-M)^2 + S(L-M)^2\}} + {(R+S)^2 + p^2(L+N-2M)^2}, +\] +which is equal to +\[ +\frac{RS}{R+S} + + \frac{p^2\{R(N-M) - S(L-M)\}^2} + {(R+S)\{(R+S)^2 + p^2(L+N-2M)^2\}}. +\] + +We see from the expression for the self-induction of the loop +that it is greatest when $p = 0$, when its value is +\[ +\frac{NR^2 + 2MRS + LS^2}{(R+S)^2}, +\] +and least when $p$~is infinite when it is equal to +\begin{DPgather*} +\frac{LN-M^2}{L+N-2M}.\\ +\lintertext{\indent If} +R(N - M) = S(L - M), +\end{DPgather*} +the self-induction of the loop is independent of the period. + +From the expression for the impedance of the loop we see that +it is least when $p = 0$ when its value is +\[ +\frac{RS}{R+S} +\] +and greatest when $p$~is infinite when it is equal to +\begin{DPgather*} +\frac{R(N-M)^2 + S(L-M)^2}{(L+N-2M)^2}; \\ +\lintertext{and if} +R(N - M) = S(L - M), +\end{DPgather*} +the impedance is independent of the period. Thus in this case +the self-induction and the impedance are unaltered, whatever the +frequency of the currents. In all other cases the self-induction +diminishes and the impedance increases as the frequency of the +currents increases. + +\Article{422} We shall now proceed to investigate the general case +\index{Alternating currents, expression for self-induction of systems of wires@\subdashtwo expression for self-induction of systems of wires}% +\index{Alternating currents, expression for `impedance' of systems of wire@\subdashtwo expression for `impedance' of systems of wire}% +\index{Impedance, for two wires in parallel@\subdashone for two wires in parallel}% +\index{Multiple arc, ximpedance of wires in@\subdashtwo impedance of wires in}% +when there are any number of wires in parallel. Let~$\dot{x}_0$ be the +current in the leads, $\dot{x}_1, \dot{x}_2, \ldots \dot{x}_n$ the currents in the $n$~wires in +parallel; we shall assume, as before, that there is no induction +between these wires and the leads. Let $a_{rr}$~be the self-induction +and $r_r$~the resistance of the wire through which the current is~$\dot{x}_r$, +$a_{rs}$~the coefficient of mutual induction between this wire and the +wire through which the current is~$\dot{x}_s$. Let $a_0$~be the self-induction, +$r_0$~the resistance of the leads, $E_0$~the electromotive +force in the external circuit; we shall suppose that this varies as~$\epsilon^{\iota pt}$. +%% -----File: 532.png---Folio 518------- +The current through the leads and those through the +wires in parallel are connected by the relation +\[ +\dot{x}_0 - (\dot{x}_1 + \dot{x}_2 + \ldots \dot{x}_n) = 0; +\] +we shall denote this by +\[ +\phi = 0. +\] + +Then $T$~being the Kinetic Energy, $F$~the Dissipation function, +and $\lambda$~an arbitrary multiplier, the equations determining the +currents are of the form +\begin{multline*} +\frac{d}{dt}\, \frac{dT}{d \dot{x}_s} + \frac{dF}{d \dot{x}_s} + \lambda \frac{d\phi}{d \dot{x}_s}\\ + = \text{external electromotive force tending to increase~$\dot{x}_s$}. +\end{multline*} + +From these equations we get +\begin{gather*} +(a_0 \iota p + r_0) \dot{x}_0 + \lambda = E_0, +\Tag{7} \\ +\left. +\begin{aligned} +(a_{11} \iota p + r_1) \dot{x}_1 + a_{12} \iota p \dot{x}_2 + \ldots -\lambda = 0,&\\ +a_{12} \iota p \dot{x}_1 + (a_{22} \iota p + r_2) \dot{x}_2 + \ldots -\lambda = 0,&\\ +.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\;\;&\\%[TN:manual spacing of dots] +a_{1n} \iota p \dot{x}_1 + \PadTo[l]{(a_{22} \iota p + r_2) \dot{x}_2 + \ldots}{a_{2n} \iota p \dot{x}_2 + \ldots} -\lambda = 0.& +\end{aligned} +\right\} +\Tag{8} +\end{gather*} + +Solving equations~(\eqnref{422}{8}) we find +\begin{multline*} +\frac{\dot{x}_1}{A_{11} + A_{12} + \ldots A_{1n}} + = \frac{\dot{x}_2}{A_{12} + A_{22} + \ldots A_{2n}} \\ + = \frac{\dot{x}_n}{A_{1n} + A_{2n} + \ldots A_{nn}} + = \frac{\lambda}{\Delta}, \Tag{9} +\end{multline*} +where +\[ +\Delta= +\begin{vmatrix} +a_{11} \iota p + r_1, &a_{12} \iota p\hfill, &\ldots &a_{1n} \iota p\\ +a_{12} \iota p\hfill, &a_{22} \iota p + r_2, &\ldots &a_{2n} \iota p\\ +\hdotsfor[6]{4}\\ +a_{1n} \iota p\hfill, &a_{2n} \iota p\hfill, &\ldots &a_{nn} \iota p + r_n +\end{vmatrix}, +\] +and $A_{pq}$~denotes the minor of~$\Delta$ corresponding to the constituent +$a_{pq} \iota p$. +\begin{DPgather*} +\lintertext{\indent Since} +\dot{x}_0 = \dot{x}_1 + \dot{x}_2 + \ldots, +\end{DPgather*} +we have from the above equations +\[ +\frac{\dot{x}_0}{A_{11} + A_{22} + \ldots A_{nn} + 2A_{12} + 2A_{13} + 2A_{23} + \ldots} + = \frac{\lambda}{\Delta}. +\] + +Substituting this value of~$\lambda$ in equation~(\eqnref{422}{7}) we find +\[ +\left( a_0 \iota p + r_0 + \frac{\Delta}{S} \right) \dot{x}_0 = E_0, +\Tag{10} +\] +where $S$~is written for +\[ +A_{11} + A_{22} + \ldots A_{nn} + 2A_{12} + 2A_{13} + 2A_{23} + \ldots . +\] +%% -----File: 533.png---Folio 519------- + +The self-induction and impedance of the leads can be deduced +from (\eqnref{422}{10}); the expressions for them are however in general very +complicated, but they take comparatively simple forms when +$\iota p$~is either very large or very small. + +When $\iota p$~is very large, +\[ +\frac{\Delta}{S} = \iota p \frac{D}{S'} + + \frac{r_1 ( A'_{11} + A'_{12} + \ldots A'_{1n} )^{2} + + r_2 ( A'_{12} + A'_{22} + \ldots A'_{2n} )^{2} + \ldots}{S'^{2}}, +\] +where +\[ +D = +\begin{vmatrix} +a_{11}, & a_{12}, & a_{1n} \\ +a_{12}, & a_{22}, & a_{2n} \\ +\hdotsfor[6]{3} \\ +a_{1n}, & a_{2n}, & a_{nn} +\end{vmatrix}, +\] +and $A'_{pq}$~is the minor of~$D$ corresponding to the constituent~$a_{pq}$, +while +\[ +S' = A'_{11} + A'_{22} + \ldots A'_{nn} + 2A'_{12} + 2A'_{13} + 2A'_{23} + \ldots. +\] + +Thus the self-induction of the wires in parallel is in this case +\[ +\frac{D}{S'}, +\] +while the impedance is +\[ +\{r_1 ( A'_{11} + A'_{12} + \ldots A'_{1n})^{2} + + r_2 ( A'_{12} + A'_{22} + \ldots A'_{2n})^{2} + \ldots \} / S'^{2}. +\] + +When $\iota p$~is very small, +\[ +\frac{\Delta}{S} = \iota p\, + \frac{\left( \dfrac{a_{11}}{r_1^2} + \dfrac{a_{22}}{r_2^2} + \ldots + + \dfrac{2a_{12}}{r_1r_2} + \dfrac{2a_{13}}{r_1r_3} + \ldots \right)} + {\left( \dfrac{1}{r_1} + \dfrac{1}{r_2} + \ldots \dfrac{1}{r_n} \right)^{2}} + + \frac{1}{\dfrac{1}{r_1} + \dfrac{1}{r_2} + \ldots \dfrac{1}{r_n}}. +\] + +So that in this case the self-induction of the wires in +parallel is +\[ +\frac{\dfrac{a_{11}}{r_1^2} + \dfrac{a_{22}}{r_2^2} + \ldots + + \dfrac{2a_{12}}{r_1 r_2} + \dfrac{2a_{13}}{r_1 r_3} + \ldots} + {\left( \dfrac{1}{r_1} + \dfrac{1}{r_2} + \ldots \dfrac{1}{r_n} \right)^{2}} +\] +and the resistance is +\[ +\frac{1}{\dfrac{1}{r_1} + \dfrac{1}{r_2} + \ldots \dfrac{1}{r_n}}. +\] + +When there is no induction between the wires in parallel, +%% -----File: 534.png---Folio 520------- +$a_{12}$,~$a_{13}$, $a_{23}$,~\&c.\ all vanish; hence, when $\iota p$~is infinite, the +self-induction is +\[ +\frac{1}{\dfrac{1}{a_{11}} + \dfrac{1}{a_{22}} + \ldots \dfrac{1}{a_{nn}}}, +\] +and the impedance +\[ +\frac{\dfrac{r_1}{a_{11}^{2}} + \dfrac{r_2}{a_{22}^{2}} + \ldots} + {\left( \dfrac{1}{a_{11}} + \dfrac{1}{a_{22}} + \ldots\right)^{2}}. +\] + +\Article{423} We shall now consider the case of any number of +\index{Impedance, for a network of wire@\subdashone for a network of wire}% +\index{Induction, self, for a network of wires@\subdashtwo for a network of wires}% +\index{Self-induction, expression for, of a net-work of wires@\subdashtwo of a net-work of wires}% +circuits; the investigation will apply whether the circuits are +arranged so as to form separate circuits or whether some or all +of them are metallically connected so as to form a net-work +of conductors. + +Let $\dot{x}_1, \dot{x}_2, \ldots \dot{x}_n$ be the variables required to fix the distribution +of currents through the circuits; let~$T$, the Kinetic Energy due +to these currents, be expressed by the equation +\[ +T = \tfrac{1}{2} \{a_{11} \dot{x_1^2} + a_{22} \dot{x_2^2} + \ldots + + 2a_{12} \dot{x_1} \dot{x_2} + \ldots \}, +\] +while the Dissipation Function~$F$ is given by +\[ +F = \tfrac{1}{2} \{r_{11} \dot{x_1^2} + r_{22} \dot{x_2^2} + \ldots + + 2r_{12} \dot{x_1} \dot{x_2} + \ldots\}. +\] + +Let us suppose that there are no external forces of types +$\dot{x}_2$,~$\dot{x}_3$,~\&c., and that~$X_1$, the external force of type~$x_1$, is proportional +to~$\epsilon^{\iota pt}$. + +The equations giving the currents are +\begin{align*} +(a_{11} \iota p + r_{11}) \dot{x_1} + (a_{12} \iota p + r_{12}) \dot{x_2} + \ldots &{} = X,\\ +(a_{12} \iota p + r_{12}) \dot{x_1} + (a_{22} \iota p + r_{22}) \dot{x_2} + \ldots &{} = 0,\\ +(a_{13} \iota p + r_{13}) \dot{x_1} + (a_{23} \iota p + r_{23}) \dot{x_2} + \ldots &{} = 0,\\ +.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.&\quad.%[TN:manual spacing of dots] +\end{align*} + +From the last~$(n-1)$ of these equations we have +\[ +\frac{\dot{x}_{1}}{B_{11}} + = \frac{\dot{x}_{2}}{B_{12}} + = \frac{\dot{x}_{3}}{B_{13}} = \ldots, +\Tag{11} +\] +where $B_{pq}$~denotes the minor of the determinant +\[ +\begin{vmatrix} +a_{11} \iota p + r_{11}, & a_{12} \iota p + r_{12}, \ldots \\ +a_{12} \iota p + r_{12}, & a_{22} \iota p + r_{22}, \ldots \\ +\hdotsfor[6]{2} +\end{vmatrix} +\] +corresponding to the constituent $a_{pq} \iota p + r_{pq}$; we shall denote the +determinant by~$\Delta$. +%% -----File: 535.png---Folio 521------- + +Substituting the values of~$\dot{x}_2, \dot{x}_3, \ldots$ in the first equation, we +have +\[ +(a_{11} \iota p + r_{11})\dot{x}_1 + + \frac{1}{B_{11}} \{(a_{12} \iota p + r_{12})B_{12} + + (a_{13} \iota p + r_{13})B_{13} + \dots \} \dot{x}_1 = X_1, +\] +which may be written +\[ +\frac{\Delta}{B_{11}} \dot{x}_1 = X_1. +\Tag{12} +\] + +If $\Delta / B_{11}$~be written in the form $L\iota p + R$, where $L$~and~$R$ are +real quantities, then $L$~is the effective self-induction of the circuit +and $R$~the impedance. + +By equation~(\eqnref{423}{11}) we have +\[ +\frac{\Delta}{B_{12}} \dot{x}_2 = X_1. +\] + +If an electromotive force~$X_2$ of the same period as~$X_1$ acted +on the second circuit, then the current~$\dot{x}_1$ induced in the first +circuit would be given by +\[ +\frac{\Delta}{B_{12}} \dot{x}_1 = X_2. +\] + +Comparing these results we get Lord Rayleigh's theorem, that +when a periodic electromotive force~$F$ acts on a circuit~$A$ the +current induced in another circuit~$B$ is the same in amplitude +and phase as the current induced in~$A$ when an electromotive +force equal in amplitude and phase to~$F$ acts on the circuit~$B$. + +When there are only two circuits in the field, +\[ +\frac{\Delta}{B_{11}} = a_{11} \iota p + r_{11} + - \frac{(a_{12} \iota p + r_{12})^2}{a_{22} \iota p + r_{22}}; +\] +if the circuits are not in metallic connection $r_{12}=0$, and we have +\[ +\frac{\Delta}{B_{11}} + = \left(a_{11} - \frac{p^2 a_{22} a^2_{12}}{a^2_{22} p^2 +r^2_{22}}\right) \iota p + + r_{11} + \frac{p^2 r_{22} a^2_{12}}{a^2_{22} p^2 +r^2_{22}}. +\] + +Thus the presence of the second circuit diminishes the self-induction +of the first by +\[ +\frac{p^2 a_{22} a^2_{12}}{a^2_{22} p^2 + r^2_{22}}, +\] +while it increases the impedance by +\[ +\frac{p^2 r_{22} a^2_{12}}{a^2_{22} p^2 + r^2_{22}}. +\] +%% -----File: 536.png---Folio 522------- + +These results were given by Maxwell in his paper `A Dynamical +Theory of the Electromagnetic Field' (\textit{Phil.\ Trans.}\ 155, p.~459, +1865). We see from these expressions that the diminution in the +self-induction and the increase in the impedance increase continuously +as the frequency of the electromotive force increases. + +\Article{424} Lord Rayleigh has shown that this result is true whatever +may be the number of circuits. We have by~(\eqnref{423}{12}) +\[ +\frac{\Delta}{B_{11}} \dot{x}_1 = X_1. +\] + +Now while keeping $\dot{x}_1$ the same we can choose $\dot{x}_2$,~$\dot{x}_3$,~\&c., so +that the two quadratic expressions +\begin{align*} +& a_{22} \dot{x}^2_2 + a_{33} \dot{x}_3^2 + \ldots 2a_{23} \dot{x}_2 \dot{x}_3 + \ldots, \\ +& r_{22} \dot{x}^2_2 + r_{33} \dot{x}_3^2 + \ldots 2r_{23} \dot{x}_2 \dot{x}_3 + \ldots, +\end{align*} +i.e.~the expressions got by putting $\dot{x}_1 = 0$ in~$2T$ and~$2F$ respectively, +reduce to the sums of squares of $\dot{x}_2$,~$\dot{x}_3$,~\&c.; when $\dot{x}_2$,~$\dot{x}_3$,~\&c.\ +are chosen in this way, +\[ +a_{23} = a_{24} = a_{pq} = 0, +\] +when $p$~is not equal to~$q$ and both are greater than unity. + +In this case +\begin{align*} +\Delta &= +\begin{vmatrix} +a_{11} \iota p + r_{11}, &a_{12} \iota p + r_{12}, &a_{13} \iota p + r_{13}, &\ldots &a_{1n} \iota p + r_{1n}\\ +a_{12} \iota p + r_{12}, &a_{22} \iota p + r_{22}, &0\hfill, &\ldots &0 \\ +a_{13} \iota p + r_{13}, &0\hfill, &a_{33} \iota p + r_{33}, &\ldots &0 \\ +\hdotsfor[6]{5}\\ +a_{1n} \iota p + r_{1n}, &0\hfill, &0\hfill, &\ldots &a_{nn} \iota p + r_{nn} +\end{vmatrix} \\ + &= (a_{11} \iota p +r_{11}) + (a_{22} \iota p +r_{22}) \ldots + (a_{nn} \iota p +r_{nn}) × {}\\ + &\quad\begin{aligned} + \biggl\{1 - \frac{(a_{12} \iota p + r_{12})^2}{(a_{11} \iota p +r_{11}) (a_{22}\iota p +r_{22})} + &- \frac{(a_{13} \iota p + r_{13})^2}{(a_{11} \iota p +r_{11}) (a_{33}\iota p +r_{33})} \\ + \llap{${}- \ldots$} &- \frac{(a_{1n} \iota p + r_{1n})^2}{(a_{11} \iota p + r_{11})(a_{nn}\iota p + r_{nn})} \biggr\}, +\end{aligned} \\ +B_{11} &= (a_{22} \iota p + r_{22})^2 \ldots (a_{nn} \iota p + r_{nn}). +\end{align*} + +Hence +{\setlength{\multlinegap}{0pt} +\begin{multline*} +\frac{\Delta}{B_{11}} + = a_{11} \iota p + r_{11} + - \frac{(a_{12} \iota p + r_{12})^2}{a_{22} \iota p + r_{22}} + - \frac{(a_{13} \iota p + r_{13})^2}{a_{33} \iota p + r_{33}} - \ldots + - \frac{(a_{1n} \iota p + r_{1n})^2}{a_{nn} \iota p + r_{nn}} \\ + = \Bigl\{a_{11} + + \tsum \bigl( \dfrac{a_{nn} r_{1n}^2 - 2 a_{1n} r_{1n} r_{nn}}{r_{nn}^2} \bigr) + - \tsum \bigl( \dfrac{a_{nn} p^2 (a_{1n} r_{nn} - a_{nn} r_{1n})^2}{r^2_{nn} (a^2_{nn} p^2 +r^2_{nn})} \bigr) \Bigr\} \iota p\\ + + r_{11} - \tsum \dfrac{r^2_{1n}}{r_{nn}} + + \tsum \bigl( \dfrac{p^2 (a_{1n} r_{nn} - a_{nn} r_{1n})^2}{r_{nn}(a^2_{nn} p^2 + r^2_{nn})} \bigr). +\end{multline*} +} +%% -----File: 537.png---Folio 523------- + +The coefficient of~$\iota p$ in the first line is the coefficient of self-induction +of the first circuit,---we see that it is diminished by +any increase in~$p$; the second line is the impedance, and we see +that this is increased by any increase in~$p$. + +\Article{425} We shall now return to the general case. The reduction +of~$\Delta/B_{11}$ to the form $L\iota p + R$ without any limitation as to the +value of~$p$ would usually lead to very complicated expressions; +we can, however, obtain without difficulty the values of $L$~and~$R$, +(1)~when $p$~is very large, (2)~when it is very small. + +When $\iota p$~is very large we see that +\begin{DPgather*} +L = \frac{D}{A_{11}},\\ +\lintertext{where} +D = \begin{vmatrix} + a_{11}, & a_{12} & \ldots & a_{1n} \\ + a_{12}, & a_{22} & \ldots & a_{2n} \\ + \hdotsfor{4}[6] \\ + a_{1n}, & a_{12} & \ldots & a_{nn} \end{vmatrix}, +\end{DPgather*} +and $A_{11}$~is the minor of~$D$ corresponding to the constituent~$a_{11}$. +If $A_{pq}$~denotes the minor of~$D$ corresponding to the constituent~$a_{pq}$, +then we have by~(\eqnref{423}{11}) +\[ +\frac{\dot{x}_1}{A_{11}} = +\frac{\dot{x}_2}{A_{12}} = \ldots = +\frac{\dot{x}_n}{A_{1n}}. +\Tag{13} +\] + +Substituting these values of $\dot{x}_2$,~$\dot{x}_3$,~\&c.\ in terms of~$\dot{x}_1$, in the +Dissipation Function, we find that +\[ +R = \frac{1}{A_{11}^2} + \{r_{11} A_{11}^2 + r_{22} A_{12}^2 + \dots r_{nn} A_{1n}^2 + + 2r_{12} A_{11} A_{12} + 2r_{pq} A_{1p} A_{1q} + \ldots \}; +\] +we might of course have deduced this value directly from that +of~$\Delta/B_{11}$. + +When $\iota p$~is very small, we see by putting $\iota p = 0$ in~$\Delta/B_{11}$ that +\begin{DPgather*} +R = \frac{C}{R_{11}},\\ +\lintertext{where} +C = \begin{vmatrix} + r_{11}, & r_{12} & \ldots & r_{1n} \\ + r_{12}, & r_{22} & \ldots & r_{2n} \\ + \hdotsfor{4}[6] \\%[TN:Dots added} + r_{1n}, & r_{2n} & \ldots & r_{nn} \end{vmatrix}, +\end{DPgather*} +and $R_{11}$~is the minor of~$C$ corresponding to the constituent~$r_{11}$; +if $R_{pq}$~denotes the minor of~$C$ corresponding to the constituent~$r_{pq}$, +then we have by~(\eqnref{423}{11}) +\[ +\frac{\dot{x}_1}{R_{11}} = +\frac{\dot{x}_2}{R_{12}} = \ldots = +\frac{\dot{x}_n}{R_{1n}}. +\] +%% -----File: 538.png---Folio 524------- + +Substituting these values of $\dot{x}_1, \dot{x}_2, \dot{x}_3, \ldots$ in the expression for +the Kinetic Energy, we see that +\[ +L = \frac{1}{R_{11}^2} + \{a_{11} R_{11}^2 + a_{22} R_{12}^2 + \ldots 2a_{pq} R_{1p} R_{1q} + \ldots \}. +\] + +\Article{426} Suppose we have a series of circuits arranged so that +each circuit acts by induction only on the two adjacent ones; +this is expressed by the condition that $a_{12}$~is finite but that $a_{1p}$~vanishes +when $p > 2$; again, $a_{12}$,~$a_{23}$ are finite, but $a_{2p}$~vanishes if +$p$~differs from~$2$ by more than unity. Substituting these values +of~$a_{1p}, a_{2p}, a_{3p} \ldots$, we easily find +\begin{align*} +A_{12} &= -a_{12}\, \frac{dA_{11}} {da_{22}}, \\ +A_{13} &= a_{12} a_{23}\, \frac{d^2 A_{11}} {da_{22}\, da_{33}}, \\ +A_{14} &= -a_{12} a_{23} a_{34}\, \frac{d^3 A_{11}} {da_{22}\, da_{33}\, da_{44}}, \\ +.\quad&\quad.\qquad.\qquad.\qquad.\qquad.\qquad.\\ +A_{1n} &= (-1)^{n-1} a_{12} a_{23} a_{34} \ldots a_{n-1 n}. +\end{align*} + +Now $T$, the Kinetic Energy, is always positive, but the condition +for this is (Maxwell's \textit{Electricity and Magnetism}, vol.~i.\ p.~111) that +\[ +D,\quad A_{11},\quad \frac{d A_{11}} {da_{22}},\quad +\frac{d^2 A_{11}} {da_{22}\, da_{33}}\ \ldots +\] +should all be positive; hence we see if we take $a_{12}, a_{23} \ldots$,~\&c.\ all +positive, $A_{11}$,~$A_{12}$,~$A_{13}$ will be alternately plus and minus, but +when the frequency of the electromotive force is very great, $\dot{x}_1, \dot{x}_2, \ldots$ +are by~(\eqnref{425}{13}) respectively proportional to $A_{11}, A_{12} \ldots$; hence we see +that in this case the adjacent currents are flowing in opposite +directions: a result given by Lord Rayleigh. Another way of +stating this result is to say that the direction of the currents is +such that all the terms involving the product of two currents +in the expression for the Kinetic Energy of the system of currents +are negative, and in this form we recognise it as a consequence +of the principle that the distribution of the currents must be +such as to make the Kinetic Energy a minimum. + +\Article{427} We shall now apply these results to the case when the +circuits are a series of $m$~co-axial right circular solenoids of equal +length, which act inductively on each other but which are not +%% -----File: 539.png---Folio 525------- +in metallic connection. We shall suppose that $a$~is the radius +of the first solenoid, $b$~that of the second, $c$~that of the third, and +so on, $a$,~$b$,~$c$ being in ascending order of magnitude; and that +$n_1, n_2, n_3 \ldots$ are the numbers of turns of wire per unit length +of the first, second, and third circuits. Then if $l$~is the length of +the solenoids, we have +\begin{align*} +a_{11} &= 4\pi^2 n_1^2 la^2, & a_{22} &= 4\pi^2 n_2^2 lb^2, & a_{33} &= 4\pi^2 n_3^2 lc^2, \\ +a_{12} &= 4\pi^2 n_1 n_2 la^2, & a_{23} &= 4\pi^2 n_2 n_3 lb^2, & a_{34} &= 4\pi^2 n_3 n_4 lc^2, \\ +a_{13} &= 4\pi^2 n_1 n_3 la^2, & a_{24} &= 4\pi^2 n_2 n_4 lb^2, & . \quad &. \quad . \quad . \quad . \quad . \\ +. \quad &. \quad . \quad . \quad . \quad . & . \quad &. \quad . \quad . \quad . \quad . +\end{align*} + +Hence +\begin{gather*} +D = \begin{vmatrix} +a_{11}, & a_{12}, & a_{13} & \ldots \\ +a_{12}, & a_{22}, & a_{23} & \ldots \\ +a_{13}, & a_{23}, & a_{33} & \ldots \\ +\hdotsfor[6]{4} \\ +\end{vmatrix} \\[0.5ex] += (4\pi^2 l)^m n_1^2 n_2^2 n_3^2 \ldots a^2 (b^2 - a^2)(c^2 - b^2)(d^2 - c^2) \ldots, +\end{gather*} +\begin{DPalign*} +\lintertext{and} +A_{11} &= \frac{dD} {da_{11}} \\ + &= (4\pi^2 l)^{m-1} n_2^2 n_3^2 \ldots b^2 (c^2 - b^2)(d^2 - c^2) \ldots. +\end{DPalign*} + +Now the coefficient of self-induction of the first circuit for +very rapidly alternating current is +\[ +\frac{D} {A_{11}}. +\] +Substituting the preceding expressions for $D$~and~$A_{11}$ we find that +the self-induction equals +\[ +4\pi^2 l n_1^2 a^2 \left(1 - \frac{a^2} {b^2} \right). +\] + +Thus the only one of the circuits which affects the self-induction +of the first is the one immediately adjacent to it. We +can at once see the reason for this if we notice that +\begin{DPgather*} +\frac{a_{12}} {a_{22}} = \frac{a_{13}} {a_{23}} = \frac{a_{14}} {a_{24}} = \dots , \\ +\lintertext{and therefore} +A_{13} = A_{14} = A_{15} = \ldots = 0. +\end{DPgather*} + +Now when the rate of alternation is very rapid, $\dot{x}_3, \dot{x}_4, \dot{x}_5 \ldots$, +the currents in the third, fourth, and fifth circuits,~\&c.\ are by +equation~(\eqnref{425}{13}) \artref{425}{Art.~\DPtypo{(425)}{425}} proportional to~$A_{13}, A_{14}, A_{15} \ldots$; hence +we see that in this case these currents all vanish, in other words +%% -----File: 540.png---Folio 526------- +the second solenoid forms a perfect electric screen, and screens +off all induction from the solenoids outside it. + +\Article{428} Let us consider the case of three solenoids each of +length~$l$ when the frequency is not infinitely rapid; we shall +suppose that the primary coil is inside and has a radius~$a$, +number of turns per unit length~$n_1$, resistance~$r$; next to this +is the secondary, radius~$b$, turns per unit length~$n_2$, resistance~$s$; +and outside this is the tertiary, radius~$c$, turns per unit length +$n_3$, resistance~$t$. Since the circuits are not in metallic connection +$r_{12} = r_{13} = r_{23} = 0$. If $X_1$, the electromotive force acting on the +primary, is proportional to~$\epsilon^{\iota pt}$, then we have by equations (\eqnref{423}{11})~and~(\eqnref{423}{12}) +\[ +x_3 = - \frac{n_1 n_3 a^2 s\iota p} {n_1^2 n_2^2 n_3^2 (4\pi^2 l)^2} \, + \frac{X_1} { +\begin{vmatrix} +a^2 \iota p + \dfrac{r} {4\pi^2 ln_1^2}\hfill, & a^2 \iota p\hfill, & a^2 \iota p \\ +a^2 \iota p\hfill, & b^2 \iota p + \dfrac{s} {4\pi^2 ln_2^2}\hfill, & b^2 \iota p \\ +a^2 \iota p\hfill, & b^2 \iota p\hfill, & c^2 \iota p + \dfrac{t} {4\pi^2 ln_3^2} +\end{vmatrix} }~. +\] + +We see from this expression that as long as the radius and +length of the secondary remain the same, the effect produced by +it on the current in the tertiary circuit depends on the ratio~$s/n_2^2$, +since $s$~and~$n_2$ only enter into the expression for~$\dot{x}_3$ as +constituents of the factor~$s/n_2^2$. Thus all secondaries of radius~$b$ +and length~$l$ will produce the same effect if $s/n_2^2$~remains +constant. + +\sloppy +We can apply this result to compare resistances in the +following way: take two similar systems $A$~and~$B$ each consisting +of three co-axial solenoids, the primaries of $A$~and~$B$ being +exactly equal, as are also the two tertiaries, while the two +secondaries are of the same size but differ as to the materials of +which they are made. Let us use $A$~and~$B$ as a Hughes' Induction +\index{Balance, Induction}% +\index{Hughes, induction balance@\subdashone induction balance}% +\index{Induction balance}% +Balance, putting the two primaries in series and connecting +the tertiaries so that the currents generated in them by their +respective primaries tend to circulate in opposite directions; +then if, by altering if necessary the resistance in one of the +secondaries, we make the resultant current in the combined +tertiaries vanish, we know that $s/n_2^2$ is the same for $A$~and~$B$. +Suppose that the secondary in~$B$ is a thin tube of thickness~$\tau$ +%% -----File: 541.png---Folio 527------- +and specific resistance~$\sigma$, then considering the tube as a solenoid +wound with wire of square section~$\alpha$ packed close together, +we see that for the tube +\[ +s = 2\pi bln_2\, \frac{\sigma}{\alpha} = 2\pi bln_2^2\, \frac{\sigma}{\tau}. +\] + +\fussy +Now $s/n_2^2$ for the tube is equal to $s/n_2^2$ for the secondary +of~$A$, which may be an ordinary solenoid. We thus have +\[ +\frac{s}{n_2^2} = 2\pi bl\sigma/\tau, +\] +a relation by which we can deduce~$\sigma$. + +In order that this method should be sensitive the interposition +of the secondary ought to produce a considerable effect on the +currents induced in the tertiary. If the resistance of the +secondary is large this will not happen unless the frequency of +the electromotive force is very great; for ordinary metals a +frequency of about a thousand is sufficient, but this would be +useless if the specific resistance of the tube were comparable with +that of electrolytes. + +On the other hand, if the frequency is infinite, there will not +be any current in the tertiaries whatever the resistance of the +secondaries may be. + + +\Subsection{Wheatstone's Bridge with Self-Induction in the Arms.} +\index{Wheatstone's Bridge with alternating current}% + +\includegraphicsouter{fig140}{Fig.~140.} + +\Article{429} The preceding investigation can be applied to find the +effect of self-induction in the arms of a Wheatstone's Bridge. +Let $ABCO$ represent the bridge, let an electromotive +force~$X$ proportional to~$\epsilon^{\iota pt}$ act in +the arm~$CB$. Let $x$~be the current in~$CB$, +$y$~that in~$BA$, $z$~that in~$AO$, then the currents +along~$BO$, $AC$,~$OC$ are respectively $x-y$, +$y-z$, and~$x-y+z$. + +Let the self-induction in~$CB$, $BA$, $AC$, $AO$, +$BO$, $CO$ be respectively $A$,~$C$,~$B$, $L$,~$M$,~$N$, +while the resistance in these arms are respectively +$a$,~$c$,~$b$, $\alpha$,~$\beta$,~$\gamma$. We suppose, moreover, that there is +no mutual induction between the various arms of the Bridge. +Then the Kinetic Energy~$T$ of the system of currents is expressed +by the equation +\[ +2T = Ax^2 + Cy^2 + B(y - z)^2 + Lz^2 + M(x - y)^2 + N(x - y + z)^2. +\] +%% -----File: 542.png---Folio 528------- + +The Dissipation Function~$F$ is given by the expression +\[ +2F = ax^2 + cy^2 + b(y - z)^2 + \alpha z^2 + \beta(x - y)^2 + \gamma(x - y + z)^2. +\] + +Comparing this with our previous notation, we must put +\begin{align*} +a_{11} & = A + M + N, & a_{12} & = -(M + N), \\ +a_{22} & = B + C + M + N, & a_{13} & = N, \\ +a_{33} & = B + L + N, & a_{23} & = -(N+B); \\ +r_{11} & = \alpha + \beta + \gamma, & r_{12} & = -(\beta + \gamma), \\ +r_{22} & = b + c + \beta + \gamma, & r_{13} & = \gamma, \\ +r_{33} & = b + \alpha + \gamma, & r_{23} & = -(\gamma + b). +\end{align*} + +Now by equations (\eqnref{423}{11})~and~(\eqnref{423}{12}) +\[ +z = \frac{B_{13}}{\Delta}\, X, +\] +where $B_{13}$~is the minor of~$\Delta$ corresponding to the constituent +$a_{13} \iota p + r_{13}$, i.e.\ +\[ +B_{13} = (a_{12} \iota p + r_{12})(a_{23} \iota p + r_{23}) + - (a_{22} \iota p + r_{22})(a_{13} \iota p + r_{13}). +\] + +Substituting the preceding values for the $a$'s and the~$r$'s, we +find +\[ +B_{13} = -p^2 (MB - NC) + \iota p(Mb + B\beta - Nc - C\gamma) + b\beta - c\gamma. +\] + +Now if $z$~vanishes $B_{13}$ must vanish; hence if the Bridge is +balanced for all values of~$p$ we must have +\begin{gather*} +MB - NC = 0, \\ +Mb + B\beta - Nc - C\gamma = 0, \\ +b\beta - c\gamma = 0; +\end{gather*} +while if the Bridge is only balanced for a particular value of~$p$, +we have +\begin{gather*} +b\beta - c\gamma = p^2(MB - NC), \\ +p(Mb + B\beta - Nc - C\gamma) = 0. +\end{gather*} + +When the frequency is very great the most important term in +the expression for~$B_{13}$ is $-p^2 (MB - NC)$, so that the most important +condition to be fulfilled when the Bridge is balanced is +\[ +MB - NC = 0; +\] +thus for high frequencies the Bridge tests the self-induction +rather than the resistances of its arms. +%% -----File: 543.png---Folio 529------- + + +\Subsection{Combination of Self-Induction and Capacity.} +\index{Capacity zelectrostatic neutralizes self@\subdashone electrostatic neutralizes self-induction}% +\index{Induction, self, xand capacity@\subdashtwo and capacity}% +\index{Self-induction, expression for, xand capacity@\subdashtwo and capacity}% + +\Article{430} We have supposed in the preceding investigations that +the circuits were closed and devoid of capacity; very interesting +results, however, occur when some or all of the circuits are cut +and their free ends connected to condensers of suitable capacity. +We can by properly adjusting the capacity inserted in a circuit +in relation to the frequency of the electromotive force and the +self-induction of the circuit, make the circuit behave under the +action of an electromotive force of given frequency as if it possessed +no apparent self-induction. + +The explanation of this will, perhaps, be clear if we consider +the behaviour of a simple mechanical system under the action of +a periodic force. The system we shall take is that of the +rectilinear motion of a mass attached to a spring and resisted by +a frictional force proportional to its velocity. + +Suppose that an external periodic force~$X$ acts on the system, +then at any instant $X$~must be in equilibrium with the resultant +of (1)~minus the rate of change of momentum of the system, +(2)~the force due to the compression or extension of the spring, +(3)~the resistance. If the frequency of~$X$ is very great, then for a +given momentum (1)~will be very large, so that unless it is +counterbalanced by~(2) a finite force of infinite frequency would +produce an infinitely small momentum. Let us, however, suppose +that the frequency of the force is the same as that of the +free vibrations of the system when the friction is zero. When +the mass vibrates with this frequency (1)~and~(2) will balance +each other, thus all the external force has to do is to balance +the resistance. The system will thus behave like one without +either mass or stiffness resisted by a frictional force. + +In the corresponding electrical system, self-induction corresponds +to mass, the reciprocal of the capacity to the stiffness of +the spring, and the electric resistance to the frictional resistance. +If now we choose the capacity so that the period of the electrical +vibrations, calculated on the supposition that the resistance of +the circuit vanishes, is the same as that of the external electromotive +force, the system will behave as if it had neither self-induction +nor capacity but only resistance. Hence, if $L$~is the +self-induction of a circuit whose ends are connected to the plates +of a condenser whose capacity in electromagnetic measure is~$C$, +%% -----File: 544.png---Folio 530------- +the system will behave as if it had no self-induction under an +electromotive force whose frequency is $p / 2 \pi$ if $LCp^2 = 1$. + +\includegraphicsmid{fig141}{Fig.~141.} + +\Article{431} We shall now consider the case represented in the figure, +where we have two circuits in parallel, one of the circuits being +cut and its ends connected to the plates of a condenser. Let $\Lambda$~be +the self-induction of the leads, $r$~their resistance; $L$,~$N$ the +coefficients of self-induction of~$ACB$ and the condenser circuit +respectively, $M$~the coefficient of mutual induction between these +circuits. Let $R$,~$S$ be the resistances respectively of~$ACB$ and the +condenser circuit, $C$~the capacity of the condenser. Let $\dot{x}$~be the +current in the leads, $\dot{y}$~that in the condenser circuit, then that in +the circuit~$ACB$ will be $\dot{x} - \dot{y}$. Let $X$, the electromotive force in +the leads, be proportional to~$\epsilon^{\iota pt}$. If there is no mutual induction +between the leads and the wires in parallel, the equations +giving $\dot{x}$,~$\dot{y}$ are +\begin{gather*} +(\Lambda + L)\, \frac{d \dot{x}}{dt} - (L - M)\, \frac{d \dot{y}}{dt} + (r + R)\dot{x} - R \dot{y} = X,\\ +(L + N - 2M)\, \frac{d \dot{y}}{dt} - (L - M)\, \frac{d \dot{x}}{dt} + (S + R)\dot{y} - R \dot{x} + \frac{y}{C} = 0. +\end{gather*} + +Substituting the value of~$\dot{y}$ in terms of~$\dot{x}$ and remembering +that $d / dt = \iota p$, we get +\begin{multline*} +\left\{\Lambda + L + + \frac{\xi \{R^2 - (L - M)^2 p^2 \} - 2R(R + S)(L - M)} + {p^2 \xi^2 + (R + S)^2} \right\} \iota p \dot{x}\\ + + \left\{r + R + - \frac{(R + S) \{R^2 - (L - M)^2 p^2 \} + 2p^2 \xi R(L - M)} + {p^2 \xi^2 + (R + S)^2} \right\} \dot{x} = X, +\Tag{14} +\end{multline*} +\begin{DPgather*} +\lintertext{where} +\xi = (L + N - 2M) - \frac{1}{Cp^2}. +\end{DPgather*} + +From the form of this equation we see that the self-induction +of the two circuits in parallel is +\[ +L + \frac{\xi \{R^2 - (L - M)^2 p^2 \} - 2R(R + S)(L - M)} + {p^2 \xi^2 + (R + S)^2}, +\] +%% -----File: 545.png---Folio 531------- +this will vanish if +\begin{multline*} +Lp^2 \xi^2 + \xi \{R^2 - (L - M)^2 p^2\}\\ + + (R + S)\{L(R + S) - 2R(L - M)\} = 0. +\Tag{15} +\end{multline*} +If the roots of this quadratic are real, then it is possible to choose~$C$ +so that the self-induction of the loop vanishes. An important +special case is when $S = 0$, $M = 0$, when the quadratic reduces to +\begin{DPgather*} +Lp^2 \xi^2 + \xi(R^2 - L^2 p^2) - LR^2 = 0; \\ +\lintertext{thus} +\xi = -\frac{R^2}{Lp^2} \text{ or } L; +\end{DPgather*} +the first root gives +\[ +\frac{1}{C} = (L + N)p^2 + \frac{R^2}{L}, +\] +the second +\[ +\frac{1}{C} = Np^2; +\] +this last value of~$1/C$ makes $\dot{x} = \dot{y}$, so that none of the current +goes through~$ACB$. + +When $\xi$ satisfies~(\eqnref{431}{15}) the self-induction of the loop vanishes. +If in that equation we substitute $L + \Lambda$ for~$L$ and $M + \Lambda$ for~$M$, +the values of~$\xi$ which satisfy the new equation will make the +self-induction of the whole circuit vanish. + +\Article{432} We shall next consider the case of an induction coil or +transformer, the primary of which is cut and its free ends connected +to the plates of a condenser whose capacity is~$C$. Let +$L$,~$N$ be the self-induction of the primary and secondary respectively, +$M$~the coefficient of mutual induction between the two, $R$~the +resistance of the primary, $S$~that of the secondary, $\dot{x}$,~$\dot{y}$ the +currents in the primary and secondary respectively; then if $X$~is +the electromotive force acting on the primary, we have +\begin{gather*} +L\, \frac{d\dot{x}}{dt} + M\, \frac{d\dot{y}}{dt} + R\dot{x} + \frac{x}{C} = X,\\ +M\, \frac{d\dot{x}}{dt} + N\, \frac{d\dot{y}}{dt} + S\dot{y} = 0. +\end{gather*} + +Hence if $X$~varies as~$\epsilon^{\iota pt}$, we find +\begin{DPgather*} +\dot{y} = \frac{-M\iota pX }{-p^2(\xi N-M^2) + RS + \iota p(RN+S\xi)}, \\ +\lintertext{where} +\xi = L - \frac{1}{Cp^2}. +\end{DPgather*} +%% -----File: 546.png---Folio 532------- + +The amplitude of~$\dot{y}$ for a given amplitude of~$X$ is proportional +to +\[ +\frac{XMp}{\bigl\{\bigl(RS-p^2(\xi N-M^2)\bigr)^2 + (RN+S\xi)^2p^2 \bigr\}^{\frac{1}{2}}}. +\] + +This vanishes when $p = 0$, because in this case the current in +the primary is steady; it also vanishes in general when $p$~is +infinite, because in consequence of the self-induction of the +primary only an indefinitely small current passes through it in +this case. If however +\begin{DPgather*} +\xi N = M^2, \\ +\lintertext{or} +\frac{1}{Cp^2} = L - \frac{M^2}{N}, +\end{DPgather*} +then the amplitude of the current in the secondary is finite when +$p$~is infinite, and is equal to +\[ +\frac{MNX}{RN^2 + SM^2}; +\] +thus when the frequency of the electromotive force is very high +the amplitude of the current in the secondary may be increased +enormously by cutting the primary circuit and connecting its +ends to a condenser of suitable capacity. + +\Article{432*} We can apply a method similar to that of \artref{424}{Art.~424} to +\index{Time of vibration of adjacent electrical systems@\subdashtwo vibration of adjacent electrical systems}% +determine the effect of placing a vibrating electrical system near +a number of other such systems. + +We shall suppose that the systems are not in electrical connection, +and neglect the resistances of the circuits. Let $T$~be the +Kinetic, $V$~the Potential Energy of the system of currents; let~$\dot{x}_1$ +denote the current in the first circuit, and let $\dot{x}_2, \dot{x}_3, \ldots$, the currents +in the other circuits, be so chosen that when $x_1$~is put equal +to zero the expressions for $T$~and~$V$ reduce to the sums of +squares of $\dot{x}_2, \dot{x}_3, \ldots$; $x_2, x_3, \ldots$ respectively. + +Let $T$~be given by the same expression as in \artref{424}{Article~424}, +while +\[ +V = \tfrac{1}{2} \left\{\frac{x_1^2}{c_1} + \frac{x_2^2}{c_2} + \frac{{x_3}^2}{c_3} + \ldots \right\}. +\] + +Then the equations of the type +\[ +\frac{d}{dt}\, \frac{dT}{d \dot{x}} + \frac{dV}{dx} = 0 +\] +%% -----File: 547.png---Folio 533------- +give, if all the variables are proportional to~$\epsilon^\iota pt$, +\[ +\begin{aligned} +\left(-a_{11} p^2 + \frac{1}{c_1}\right)x_1 - a_{12} p^2 x_2 - a_{13} p^2 x_3 - \ldots &= 0 \\ +-a_{12} p^2 x_1 + \left(-a_{22} p^2+ \frac{1}{c_2} \right)x_2 &=0 \\ +-a_{13} p^2 x_1 + \left(-a_{33} p^2+ \frac{1}{c_3} \right)x_3 &=0. \\ +.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad.\quad & +\end{aligned} +\] + +Hence substituting for $x_2$,~$x_3$ in terms of~$x_1$ we get +\[ +-a_{11} p^2 + \frac{1}{c_1} + = \frac{a_{12}{^2} p^4}{\dfrac{1}{c_2} - a_{22} p^2} + + \frac{a_{13}{^2} p^4}{\dfrac{1}{c_3} - a_{33} p^2} + \ldots. +\] + +Let us suppose that the period of the first system is only +slightly changed, so that we may in the right-hand side of this +equation write~$p_1$ for~$p$, where~$p_1$ is the value of~$p$ when the first +vibrator is alone in the field. + +Let $p_2, p_3, \ldots$ be the values of~$p$ for the other vibrators when +the first one is absent, then +\begin{align*} +\frac{1}{c^2} & = p_2{^2} a_{22} \\ +\frac{1}{c^3} & = p_3{^2} a_{33}. +\end{align*} + +Thus if $\delta p_1{^2}$~denotes the increase in~$p_1{^2}$ due to the presence of +the other vibrators, we have +\[ +-a_{11}\, \delta p_1{^2} + = p_1{^4} \left\{\frac{a_{12}{^2}}{a_{22}(p_2{^2} - p_1{^2})} + + \frac{a_{13}{^2}}{a_{33}(p_3{^2} - p_1{^2})} + \ldots \right\}. +\] + +Thus we see that if~$p_2$ is greater than~$p_1$ the effect of the +proximity of the circuit whose period is~$p_2$ is to diminish~$p_1$, +while if~$p_2$ is less than~$p_1$ the proximity of this circuit increases~$p_1$. +Similar remarks apply to the other circuits. Thus the first +system, if its free period is slower than that of the second, is +made to vibrate still more slowly by the presence of the latter; +while if its free period is faster than that of the second the +presence of the latter makes it vibrate still more quickly. In +other words, the effect of putting two vibrators near together is +to make the difference between their periods greater than it is +when the vibrators are free from each other's influence; the +quicker period is accelerated, the slower one retarded. +%% -----File: 548.png---Folio 534------- + +\Chapter{Chapter VII.}{Electromotive Intensity in Moving Bodies.} + +\Article{433} \Firstsc{The} equations~$(B)$ given in Art.~598 of Maxwell's \textit{Electricity +and Magnetism}, for the components of the electromotive intensity +in a moving body involve a quantity~$\Psi$, whose physical meaning +it is desirable to consider more fully. The investigation by +which the equations themselves are deduced tells us nothing +about~$\Psi$; it is introduced after the investigation is finished, so +as to make the expressions for the electromotive intensity as +general as it is possible for them to be and yet be consistent +with Faraday's Law of the induction of currents in a variable +magnetic field. + +Let $u$,~$v$,~$w$ denote the components of the velocity of the +medium; $a$,~$b$,~$c$ the components of the magnetic induction; +$F$,~$G$,~$H$ those of the vector potential; $X$,~$Y$,~$Z$ those of the +electromotive intensity. + +In the course of Maxwell's investigation of the values of +$X$,~$Y$,~$Z$ due to induction, the terms +\begin{gather*} +-\frac{d}{dx} (Fu + Gv + Hw), \quad +-\frac{d}{dy} (Fu + Gv + Hw), \\ +-\frac{d}{dz} (Fu + Gv + Hw) +\end{gather*} +respectively in the final expressions for $X$,~$Y$,~$Z$ are included +under the $\Psi$~terms. We shall find it clearer to keep these +terms separate and write the expressions for $X$,~$Y$,~$Z$ as +\[ +\left. \begin{aligned} +X& = cv - bw - \frac{dF}{dt} - \frac{d}{dx} (Fu + Gv + Hw) - \frac{d\phi}{dx}, \\ +Y& = aw - cu - \frac{dG}{dt} - \frac{d}{dy} (Fu + Gv + Hw) - \frac{d\phi}{dy}, \\ +Z& = bu - av - \frac{dH}{dt} - \frac{d}{dz} (Fu + Gv + Hw) - \frac{d\phi}{dz}. +\end{aligned} \right\} \Tag{1} +\] +%% -----File: 549.png---Folio 535------- + +For Faraday's law to hold, the line integral of the electromotive +intensity taken round any closed curve must be independent +of~$\phi$, hence $\phi$~must be a continuous function. + +When there is no free electricity +\[ +\frac{dX}{dx} + \frac{dY}{dy} + \frac{dZ}{dz} = 0. +\] + +Substituting the values of $X$,~$Y$,~$Z$ just given, we find, using +\[ +\frac{dF}{dx} + \frac{dG}{dy} + \frac{dH}{dz} = 0, +\] +\begin{multline*} +F\nabla^2 u + G\nabla^2 v + H\nabla^2 w + + 2 \left(\frac{dF}{dx}\, \frac{du}{dx} + + \frac{dG}{dy}\, \frac{dv}{dy} + + \frac{dH}{dz}\, \frac{dw}{dz}\right) \\ + + \left(\frac{dH}{dy} + \frac{dG}{dz}\right) \left(\frac{dw}{dy} + \frac{dv}{dz}\right) + + \left(\frac{dF}{dz} + \frac{dH}{dx}\right) \left(\frac{du}{dz} + \frac{dw}{dx}\right)\\ + + \left(\frac{dG}{dx} + \frac{dF}{dy}\right) \left(\frac{dv}{dx} + \frac{du}{dy}\right) + = -\nabla^2 \phi. +\end{multline*} + +If the medium is moving like a rigid body, then +\begin{align*} +u &= p + \omega_2 z - \omega_3 y,\\ +v &= q + \omega_3 x - \omega_1 z,\\ +w &= r + \omega_1 y - \omega_2 x; +\end{align*} +where $p$,~$q$,~$r$ are the components of the velocity of the origin and +$\omega_1$,~$\omega_2$,~$\omega_3$ the rotations about the axes of $x$,~$y$,~$z$ respectively. + +Substituting these values we see that whenever the system moves +as a rigid body +\[ +\nabla^2 \phi = 0. +\] + +\Article{434} In order to see the meaning of~$\phi$ we shall take the case +\index{Rotating sphere in a symmetrical magnetic field@\subdashone sphere in a symmetrical magnetic field|indexetseq}% +\index{Sphere, rotating in a symmetrical magnetic field@\subdashone rotating in a symmetrical magnetic field|indexetseq}% +of a solid sphere rotating with uniform angular velocity~$\omega$ about +the axis of~$z$ in a uniform magnetic field where the magnetic +induction is parallel to the axis~$z$ and is equal to~$c$. We may +suppose that the magnetic induction is produced by a large +cylindrical solenoid with the axis of~$z$ for its axis; in this case +\[ +F = -\tfrac{1}{2} cy, \quad +G = \tfrac{1}{2} cx, \quad +H = 0. +\] + +In the rotating sphere +\[ +u = -\omega y, \quad +v = \omega x, \quad +w = 0. +\] + +If the system is in a steady state, $dF/dt$, $dG/dt$, $dH/dt$ all +vanish. +%% -----File: 550.png---Folio 536------- + +Thus in the sphere +\begin{alignat*}{2} +X &= c \omega x - \tfrac{1}{2} \frac{d}{dx} \{c\omega(x^2 + y^2) \} &{}- \frac{d\phi}{dx},\\ +Y &= c \omega y - \tfrac{1}{2} \frac{d}{dy} \{c\omega(x^2 + y^2) \} &{}- \frac{d\phi}{dy},\\ +Z &= &{}-\frac{d\phi}{dz}; +\end{alignat*} +these equations reduce to +\begin{align*} +X &= -\frac{d\phi}{dx}, \\ +Y &= -\frac{d\phi}{dy}, \\ +Z &= -\frac{d\phi}{dz}, +\end{align*} +and we have also $\nabla^2 \phi = 0$. + +In the space outside the sphere the medium does not move as a +rigid body. The process by which the equations~(\eqnref{433}{1}) were obtained +could not without further investigation be held to justify us in +applying them to cases where the velocity is discontinuous, for in +the investigation, see Maxwell, Art.~598, it is assumed that the +variations $\delta x$,~$\delta y$,~$\delta z$ are continuous, and that these are proportional +to the components of the velocity. To avoid any +discontinuity in the velocity at the surface of the sphere we +shall suppose that the medium in contact with the sphere moves +at the same rate as the sphere, but that as we recede from the +surface of the sphere the velocity diminishes in the same way +as it does in a viscous fluid surrounding a rotating sphere. Thus +we shall suppose that the rotating sphere whose radius is~$\smallbold{a}$ is +surrounded by a fixed sphere whose radius is~$\smallbold{b}$, and that between +the spheres the components of the velocity are given by the +expressions +\[ +u = -(A\, \frac{d}{dy}\, \frac{1}{r} + By),\quad +v = (A\, \frac{d}{dx}\, \frac{1}{r} + Bx),\quad +w = 0, +\] +where $r$~is the distance from the centre of the rotating sphere. + +When $r = \smallbold{b}$,\quad $u = 0$,\quad $v = 0$, hence +\[ +-\frac{A}{\smallbold{b}^3} + B = 0; +\] +%% -----File: 551.png---Folio 537------- +when $r = \smallbold{a}$, $u = -\omega y$, $v = \omega x$, hence +\[ +-\frac{A}{\smallbold{a}^3} + B = \omega, +\] +hence +\[ +A = -\frac{\omega \smallbold{a}^3 \smallbold{b}^3}{\smallbold{b}^3 - \smallbold{a}^3}. +\] + +Substituting these values of $u$,~$v$ in equation~(\eqnref{433}{1}), we find that +when $\smallbold{a} < r < \smallbold{b}$, +\begin{align*} +X & = \tfrac{1}{2} cA(x^2 + y^2)\,\frac{d}{dx}\, \frac{1}{r^3} - \frac{d\phi}{dx}, \\ +Y & = \tfrac{1}{2} cA(x^2 + y^2)\,\frac{d}{dy}\, \frac{1}{r^3} - \frac{d\phi}{dy}, \\ +Z & = \tfrac{1}{2} cA(x^2 + y^2)\,\frac{d}{dz}\, \frac{1}{r^3} - \frac{d\phi}{dz}; +\end{align*} +\begin{DPgather*} +\lintertext{hence, since} +\frac{dX}{dx} + \frac{dY}{dy} + \frac{dZ}{dz} = 0, \\ +\lintertext{we have} +\nabla^2 \phi = 0. +\end{DPgather*} + +Again, when $r > \smallbold{b}$ the medium is at rest, here we have +\begin{align*} +X & = -\frac{d\phi}{dx},\\ +Y & = -\frac{d\phi}{dy},\\ +Z & = -\frac{d\phi}{dz}, +\end{align*} +and $\nabla^2 \phi = 0$. + +The boundary conditions satisfied by~$\phi$ and its differential +coefficients will depend upon whether the sphere is a conductor +or an insulator. We shall first consider the case when it is an +insulated conductor. In this case, when the system is in a +steady state, the radial currents in the sphere must vanish, otherwise +the electrical condition of the surface of the sphere could +not be constant. + +Thus at any point on the surface of the sphere +\[ +xX + yY + zZ = 0, +\] +this is equivalent to +\[ +\frac{d\phi_1}{dr} = 0, +\] +where $\phi_1$~is the value of~$\phi$ inside the rotating sphere; hence we +have +\[ +\phi_1 = K, +\] +where $K$~is a constant. +%% -----File: 552.png---Folio 538------- + +If $\phi_{2}$,~$\phi_{3}$ are the values of~$\phi$ in the region between the fixed +and moving spheres, and in the fixed sphere respectively, then +we may put +\begin{align*} +\phi_2 &= L + \frac{M}{r} + NQ_{2} \left( \frac{r^{2}}{\smallbold{a}^{2}} - \frac{\smallbold{a}^{3}}{r^{3}} \right), \\ +\phi_{3} &= \frac{PQ_{2}}{r^{3}}, +\end{align*} +where $L$,~$M$, $N$,~$P$ are constants, and $Q_{2}$~is the second zonal +harmonic with~$z$ for its axis. + +The continuity of~$\phi$ gives +\begin{align*} +K &= L + \frac{M}{\smallbold{a}},\quad 0 = L + \frac{M}{\smallbold{b}}, \\ +P &= \frac{N(\smallbold{b}^{5} - \smallbold{a}^{5} )}{\smallbold{a}^{2}}. +\end{align*} + +If $K_{1}$~is the specific inductive capacity of the medium between +the two spheres, $K_{2}$~that of the medium beyond the outer sphere; +then, since the normal electric polarization must be continuous +when $r = \smallbold{b}$, we have +\[ +3 K_{2}P \frac{Q_{2}}{\smallbold{b}^{4}} + = K_{1} \left\{cA \frac{(Q_{2}-1)}{\smallbold{b}^{2}} + + \frac{M}{\smallbold{b}^{2}} + - NQ_{2} \left( \frac{2 \smallbold{b}}{\smallbold{a}^{2}} + \frac{3 \smallbold{a}^{3}}{\smallbold{b}^{4}} \right) \right\}. +\] + +Solving these equations we find +\begin{DPgather*} +\left. +\begin{aligned} +P &= \frac{cAK_{1} \smallbold{b}^{2}(\smallbold{b}^{5} - \smallbold{a}^{5})} + {3K_{2}( \smallbold{b}^{5} - \smallbold{a}^{5}) + K_{1} (2 \smallbold{b}^{5} + 3 \smallbold{a}^{5})},\\ +N &= \frac{cAK_{1} \smallbold{a}^{2} \smallbold{b}^{2}} + {3K_{2}( \smallbold{b}^{5} - \smallbold{a}^{5}) + K_{1} (2 \smallbold{b}^{5} + 3 \smallbold{a}^{5})},\\ +M &= cA,\quad +L = -cA/\smallbold{b},\quad +K= cA(\smallbold{b} - \smallbold{a})/ \smallbold{a} \smallbold{b}, +\end{aligned} +\right\} +\Tag{2} \\ +\lintertext{where} +A = -\omega \smallbold{a}^{3} \smallbold{b}^{3} / ( \smallbold{b}^{3} - \smallbold{a}^{3}). +\end{DPgather*} + +The surface density of the electricity on the moving sphere is +\[ +\frac{K_{1} cA}{4 \pi \smallbold{a}^{2}} + \left\{\frac{K_1(2 \smallbold{b}^{5}+3 \smallbold{a}^{5} - 5 \smallbold{a}^{3} \smallbold{b}^{2}) + 3K_{2}( \smallbold{b}^{5} - \smallbold{a}^{5})} + {3K_{2}( \smallbold{b}^{5} - \smallbold{a}^{5}) + K_{1}(2 \smallbold{b}^{5} + 3 \smallbold{a}^{5})} \right\} Q_2. +\] + +The preceding formulæ are general; we shall now consider +some particular cases. + +\Article{435} The first we shall consider is when $\smallbold{b} - \smallbold{a} = \delta$ is small +compared with either~$\smallbold{b}$ or~$\smallbold{a}$. In this case we have approximately, +when $K_{2}$~is not infinite, +\begin{gather*} +P = -\tfrac{1}{3} c \omega \smallbold{a}^{5},\quad +N = -\tfrac{1}{15}\, \frac{c \omega \smallbold{a}^{3}}{\delta}, \quad +M = -\tfrac{1}{3}\, \frac{c \omega \smallbold{a}^{4}}{\delta},\\ +% +L = \tfrac{1}{3}\, \frac{c \omega \smallbold{a}^{3}}{\delta},\quad +K = -\tfrac{1}{3} c \omega \smallbold{a}^{2}. +\end{gather*} +%% -----File: 553.png---Folio 539------- + +Thus in the outer fixed sphere the components of the electromotive +intensity are equal to the differential coefficients with +respect to $x$,~$y$,~$z$ of the function +\[ +\tfrac{1}{3} c\omega \smallbold{a}^5 \frac{Q_2}{r^3}. +\] + +Thus the radial electromotive intensity close to the surface of +the rotating sphere is +\[ +-c\omega \smallbold{a} Q_2, +\] +while the tangential intensity is +\[ +-c\omega \smallbold{a} \sin\theta \cos\theta. +\] + +These results show that the effects produced by rotating +uncharged spheres in a strong magnetic field ought to be quite +large enough to be measurable. Thus if the sphere is rotating so +fast that a point on its equator moves with the velocity $3 × 10^3$, +which is about $100$~feet per second, and if $c = 10^3$, then the +maximum radial intensity is about $1/33$~of a volt per centimetre, +and the maximum tangential intensity about $1/2$~of this: these +are quite measurable quantities, and if it were necessary to increase +the effect both $c$~and~$\omega$ might be made considerably greater +than the values we have assumed. + +The surface density of the electricity on the rotating sphere +when $(\smallbold{b}-\smallbold{a})/\smallbold{a}$ is small is +\[ +-\frac{1}{4\pi}\, K_2 c\omega \smallbold{a} Q_2. +\] + +\Article{436} If the outer fixed sphere is a conductor, the electromotive +intensity must vanish when $r > \smallbold{b}$, hence $P = 0$, so that $N = 0$, +while $M$,~$L$,~$K$ have the same values as before. In this case the +surface density of the electricity on the surface of the rotating +sphere is +\[ +\frac{K_1}{4\pi \smallbold{a}^2}\, cAQ_2, +\] +and when $\smallbold{b} - \smallbold{a}$ is small, this is equal to +\[ +-\frac{K_1}{12\pi\delta}\, c\omega \smallbold{a}^2 Q_2. +\] + +Since this expression is proportional to~$1/\delta$, the surface density +can be increased to any extent by diminishing the distance +between the rotating and fixed surfaces. + +In the general case, when $\smallbold{b}-\smallbold{a}$ is not necessarily small, the +%% -----File: 554.png---Folio 540------- +surface density of the electricity on the rotating sphere is +\[ +\frac{K_{1}}{4 \pi \smallbold{a}^{2}}\, cAQ_{2}, +\] +the surface density on the fixed sphere is +\[ +- \frac{K_1}{4 \pi \smallbold{b}^{2}}\, cAQ_{2}. +\] +The electrostatic potential due to this distribution of electricity +at a distance~$r$ from the centre of the rotating sphere is, when +$r > \smallbold{b}$, +\[ +- \frac{cA}{5} ( \smallbold{b}^{2} - \smallbold{a}^{2} )\, \frac{Q_{2}}{r^{3}}, +\] +while when $r < \smallbold{a}$ it is +\[ +- \frac{cA}{5} \left( \frac{1}{\smallbold{b}^{3}} - \frac{1}{\smallbold{a}^{3}} \right) r^{2} Q_{2}. +\] + +The values of~$\phi$ in these regions are respectively zero and a +constant. Hence this example is sufficient to show us that $\phi$~is +not equal to the electrostatic potential due to the free electricity +on the surface of the conductors. + +\Article{437} We may (though there does not seem to be any advantage +gained by so doing) regard~$\phi$ as the sum of two parts, +one of which,~$\phi_{e}$, is the electrostatic potential due to the distribution +of free electricity over the surfaces separating the different +media; the other,~$\phi_{m}$, being regarded as peculiarly due to electromagnetic +induction. + +Let us consider the case of a body moving in any manner, +then we must have, since there is no volume distribution of +electricity, +\[ +\nabla^{2} \phi_{e} = 0. +\] + +If $\sigma$~is the surface density of the electricity over any surface of +separation at a point where the direction cosines of the outward +drawn normal are $l$,~$m$,~$n$, then if $K$~is the specific inductive +capacity +\[ +4 \pi \sigma = \bigl[K(lX + mY + nZ)\bigr]_{1}^{2}, +\] +where the expression on the right-hand side of this equation +denotes the excess of the value of $K(lX + mY + nZ)$ in the +outer medium over its value in the inner. But if $\phi_{e}$~is the +electrostatic potential, then +\[ +4 \pi \sigma + = - \left[ K \left( l\, \frac{d \phi_{e}}{dx} + m\, \frac{d \phi_{e}}{dy} + n\, \frac{d \phi_{e}}{dz} \right) \right]_{1}^{2}. +\] +%% -----File: 555.png---Folio 541------- + +From these conditions we see from equations~(\eqnref{433}{1}) that +{\setlength{\multlinegap}{0pt} +\begin{multline*} +\nabla^2 (\phi_m + Fu + Gv + Hw) = \frac{d}{dx} (cv - bw) + + \frac{d}{dy} (aw - cu) + + \frac{d}{dz} (bu - av),\\ +\shoveleft{\text{and\quad} +\left[ K ( l\, \frac{d}{dx} + m\, \frac{d}{dy} + n\, \frac{d}{dz} ) + ( \phi_m + Fu + Gv + Hw) \right]_{1}^{2}} \\ += \bigl[ K \{l(cv-bw) + m(aw-cu) + n(bu-av) \} \bigr]_{1}^{2}.\quad +\end{multline*} +} +From these equations $\phi_m$~is uniquely determined, for we see that +$\phi_m + Fu + Gv + Hw$ is the potential due to a distribution of +electricity whose volume density is +\[ +- \frac{1}{4 \pi} \left\{\frac{d}{dx} (cv - bw) + \frac{d}{dy} (aw - cu) + \frac{d}{dz} (bu - av) \right\}, +\] +together with a distribution whose surface density is +\[ +- \frac{1}{4 \pi} \bigl[ K \{l(cv-bw) + m(aw-cu) + n(bu-av) \} \bigr]_{1}^{2}. +\] + +Having thus determined~$\phi_m$ and deducing~$\phi$ by the process +exemplified in the preceding examples we can determine~$\phi_e$. + +\Article{438} The question as to whether or not the equations~(\eqnref{433}{1}) are +true for moving insulators as well as for moving conductors, +$u$,~$v$,~$w$ being the components of the velocity of the insulator, is +a very important one. The truth of these equations for conductors +has been firmly established by experiment, but we have, +so far as I am aware, no experimental verification of them for +insulators. The following considerations suggest, I think, that +some further evidence is required before we can feel assured of +the validity of the application of these equations to insulators. +We may regard a steady magnetic field as one in which Faraday +tubes are moving about according to definite laws, the positive +tubes moving in one direction, the negative ones in the opposite, +the tubes being arranged so that as many positive as negative +tubes pass through any area. When a conductor is moved +about in such a magnetic field it disturbs the motion of the +tubes, so that at some parts of the field the positive tubes no +longer balance the negative and an electromotive intensity is +produced in such regions. To assume the truth of equations~(\eqnref{433}{1}), +whatever the nature of the moving body may be, is, from this +point of view, to assume that the effect on these tubes is the +same whether the moving body be a conductor or an insulator of +%% -----File: 556.png---Folio 542------- +large or small specific inductive capacity. Now it is quite conceivable +that though a conductor, or a dielectric with a considerable +inductive capacity, might when in motion produce a considerable +disturbance of the Faraday tubes in the ether in and +around it, yet little or no effect might be produced by the +motion of a substance of small specific inductive capacity such +as a gas, and thus it might be expected that the electromotive +intensity due to the motion of a conductor in a magnetic field +would be much greater than that due to the motion of a gas +moving with the same speed. + +\Article{439} As one of the most obvious methods of determining +whether or not equations~(\eqnref{433}{1}) are true for dielectrics is to investigate +the effect of rotating an insulating sphere in a magnetic +field: we give the solution of the case similar to the one discussed +in \artref{434}{Art.~434}, with the exception that the metallic rotating sphere +of that article is replaced by an insulating one, specific inductive +capacity~$K_0$, of the same radius. Using the notation of that +article, we easily find that in this case +\begin{multline*} +P \left\{\frac{3K_2}{\smallbold{b}^4} + + \frac{2 \smallbold{b} ( 3K_1 + 2K_0 ) K_1 - 6K_1 ( K_1 - K_0 ) \smallbold{a}^5 / \smallbold{b}^4} + {2(K_1-K_0) \smallbold{a}^5 + (3K_1 + 2K_0) \smallbold{b}^5} \right\} \\ + = cK_1 A \left\{\frac{1}{\smallbold{b}^2} + - \frac{5 \smallbold{a}^2 \smallbold{b} K_1} + {2(K_1 - K_0) \smallbold{a}^5 + (3K_1 + 2K_0)\smallbold{b}^5} \right\}. +\end{multline*} +When $\smallbold{b} - \smallbold{a}$ is small, this becomes +\[ +P = - \tfrac{1}{3}\, \frac{2K_0}{3K_2 + 2K_0}\, c \omega \smallbold{a}^5. +\] +So that in this case the components of electromotive intensities +in the region at rest are equal to the differential coefficients +with respect to $x$,~$y$,~$z$ of the function +\[ +\tfrac{1}{3}\, \frac{2K_0}{3K_2 + 2K_0}\, \frac{c \omega \smallbold{a}^5}{r^3}\, Q_2, +\] +and thus, by \artref{435}{Art.~435}, bear to the intensities produced by the +rotating conductor the ratio of~$2K_0$ to $3K_2 + 2K_0$. + +Thus, if equations~(\eqnref{433}{1}) are true for insulators, a rotating sphere +made of an insulating material ought to produce an electric field +comparable with that due to a rotating metallic sphere of the +same size. + +\sloppy +The greatest difficulty in experimenting with the insulating +sphere would be that it would probably get electrified by +friction, but unless this completely overpowered the effect due +%% -----File: 557.png---Folio 543------- +to the rotation we ought to be able to distinguish between the +two effects, since the rotational one is reversed when the direction +of rotation is reversed as well as when the magnetic field is +reversed. + +\fussy +In deducing equations~(\eqnref{434}{2}) of \artref{434}{Art.~434}, we assumed that equations~(\eqnref{433}{1}) +held in the medium between the fixed and moving +surfaces, the general equations will therefore only be true on +this assumption. In the special case, however, when the layer of +this medium is indefinitely thin, the results will be the same +whether this medium is an insulator or conductor, so that the +results in this special case would not throw any light on whether +equations~(\eqnref{433}{1}) do or do not hold for a moving dielectric. + + +\Subsection{Propagation of Light through a Moving Dielectric.} + +\Article{440} We might expect that some light would be thrown on +the electromotive intensity developed in a dielectric moving in a +magnetic field by the consideration of the effect which the motion +of the dielectric would have on the velocity of light passing +through it. We shall therefore investigate the laws of propagation +of light through a dielectric moving uniformly with the +velocity components $u$,~$v$,~$w$. + +In this case, since we have only to deal with insulators, all +the currents in the field are polarization currents due to alterations +in the intensity of the polarization. When the dielectric +is moving we are confronted with a question which we have not +had to consider previously, and that is whether the equivalent +current is to be taken as equal to the time rate of variation of +the polarization at a point fixed in space or at a point fixed in +the dielectric and moving with it; i.e.~if $f$~is the dielectric +polarization parallel to~$x$, is the current parallel to~$x$ +\begin{DPgather*} +\frac{df}{dt}, \\ +\lintertext{or} +\frac{df}{dt} + u\, \frac{df}{dx} + v\, \frac{df}{dy} + w\, \frac{df}{dz}? +\end{DPgather*} + +In the first case we should have, if $\alpha$,~$\beta$,~$\gamma$ are the components of +the magnetic force, +\[ +4 \pi\, \frac{df}{dt} = \frac{d \gamma}{dy} - \frac{d \beta}{dz}; +\Tag{3} +\] +in the second, +\[ +4 \pi \left( \frac{df}{dt} + u\, \frac{df}{dx} + v\, \frac{df}{dy} + w\, \frac{df}{dz} \right) + = \frac{d \gamma}{dy} - \frac{d \beta}{dz}. +\Tag{4} +\] +%% -----File: 558.png---Folio 544------- + +This point seems one which can only be settled by experiment. +It seems desirable, however, to look at the question from +as many points of view as possible; the equation connecting the +current with the magnetic force is the expression of the fact that +the line integral of the magnetic force round any closed curve is +equal to $4 \pi$~times the rate of increase of the number of Faraday +tubes passing through the curve. We saw in \chapref{Chapter I.}{Chapter~I.} that this +was equivalent to saying that a Faraday tube when in motion +gave rise to a magnetic force at right angles to itself, and to the +direction in which it is moving and proportional to its velocity +at right angles to itself. + +\index{Dielectric, electromotive forces in a moving}% +\index{Equations for a moving dielectric}% +\index{Moving dielectrics, electromotive intensity in}% +\index{Propagation of light through moving dielectrics}% +When the medium is moving, the question then arises whether +this velocity to which the magnetic force is proportional is the +velocity of the tube relative (1)~to a fixed point in the region +under consideration, or (2)~relative to the moving dielectric, or +(3)~relative to the ether in this region. If the first supposition +is true we have equation~(\eqnref{440}{3}), if the second equation~(\eqnref{440}{4}), if the +third an equation similar to~(\eqnref{440}{4}) with the components of the +velocity of the ether written for $u$,~$v$,~$w$. I am not aware of any +experiments which would enable us to decide absolutely which, +if any, of the assumptions (1),~(2),~(3) is correct; \textit{a~priori} (3)~appears +the most probable. + +If $X$,~$Y$,~$Z$ are the components of the electromotive intensity; +$a$,~$b$,~$c$ those of magnetic induction; $f$,~$g$,~$h$ those of electric +polarization, and $F$,~$G$,~$H$ those of the vector potential, then we +have +\[ +\left. +\begin{aligned} +X & = \frac{4 \pi}{K}\, f = cv - bw - \frac{dF}{dt} - \frac{d \psi}{dx},\\ +Y & = \frac{4 \pi}{K}\, g = aw - cu - \frac{dG}{dt} - \frac{d \psi}{dy},\\ +Z & = \frac{4 \pi}{K}\, h = bu - av - \frac{dH}{dt} - \frac{d \psi}{dz}. +\end{aligned} +\right\} +\Tag{5} +\] + +Then, since the dielectric is moving uniformly, we have +\begin{align*} +\frac{4 \pi}{K} \left( \frac{df}{dy} - \frac{dg}{dx} \right) + &= u\, \frac{dc}{dx} + v\, \frac{dc}{dy} + w\, \frac{dc}{dz} + \frac{dc}{dt} +\Tag{6}\\ +% + &= \left( \frac{d}{dt} + u\, \frac{d}{dx} + v\, \frac{d}{dy} + w\, \frac{d}{dz} \right) c. +\end{align*} + +Now if equation~(\eqnref{440}{3}) is true +\[ +\frac{df}{dt} = \frac{1}{4 \pi \mu} \left( \frac{dc}{dy} - \frac{db}{dz} \right), +\] +%% -----File: 559.png---Folio 545------- +with similar equations for $dg/dt$,~$dh/dt$; hence from~(\eqnref{440}{6}) we +have +\[ +\frac{1}{K \mu}\, \nabla^2 c + = \frac{d}{dt} \left( \frac{d}{dt} + u\, \frac{d}{dx} + v\, \frac{d}{dy} + w\, \frac{d}{dz} \right) c. +\Tag{7} +\] + +If, on the other hand, equation~(\eqnref{440}{4}) is true, we get +\[ +\frac{1}{K \mu}\, \nabla^2 c + = \left( \frac{d}{dt} + u\, \frac{d}{dx} + v\, \frac{d}{dy} + w\, \frac{d}{dz} \right)^{2} c, +\Tag{8} +\] +with similar equations for $a$~and~$b$. + +\index{Dielectric, velocity of light through a moving@\subdashone velocity of light through a moving}% +\index{Light, zvelocity of through moving dielectric@\subdashone velocity of through moving dielectric}% +\index{Moving dielectrics, velocity of light through@\subdashtwo velocity of light through}% +\index{Velocity of ylight through moving dielectrics@\subdashtwo light through moving dielectrics}% +Let us apply these equations to a wave of plane polarized +light travelling along the axis of~$x$, the dielectric moving with +velocity~$u$ in that direction. In this case equation~(\eqnref{440}{7}) becomes +\[ +\frac{1}{K \mu}\, \frac{d^2 c}{dx^2} = \frac{d^2 c}{dt^2} + u\, \frac{d^2 c}{dx\,dt}. +\Tag{9} +\] + +Let $c = \cos(pt - mx)$; then if $V$~is the velocity of light through +the dielectric when at rest, equation~(\eqnref{440}{9}) gives +\begin{DPgather*} +V^2 m^2 = p^2 - upm, \\ +\lintertext{or} +\frac{p^2}{m^2} - \frac{up}{m} = V^2. +\end{DPgather*} + +Since $u$~is small compared with~$V$, we have approximately +\[ +\frac{p}{m} = \tfrac{1}{2} u + V. +\] + +Thus the velocity of light through the moving dielectric is +increased by half the velocity of the dielectric. + +If we take equation~(\eqnref{440}{8}), then +\[ +V^2\, \frac{d^2 c}{dx^2} = \left( \frac{d}{dt} + u\, \frac{d}{dx} \right)^{2} c, +\] +or putting as before, +\begin{DPgather*} +c = \cos(pt - mx),\\ +V^2 m^2 = (p - mu)^2, \\ +\lintertext{hence} +\frac{p}{m} = V + u; +\end{DPgather*} +so that in this case the velocity of the light is increased by that +of the dielectric. + +If we suppose that the condition~(\eqnref{440}{3}) is the true one, viz., that +\[ +4 \pi \mu \left( \frac{df}{dt} + u_0\, \frac{df}{dx} + v_0\, \frac{df}{dy} + w_0\, \frac{df}{dz} \right) + = \frac{dc}{dy} - \frac{db}{dz}, +\] +where $u_0$,~$v_0$,~$w_0$ are the components of the velocity of the ether, +%% -----File: 560.png---Folio 546------- +then, when equations~(\eqnref{433}{1}) are supposed to hold, the relation +between $p$~and~$m$ for the plane polarized wave is easily found to be +\[ +V^2 m^2 = (p - mu)(p - mu_0), +\] +or if $u$ and~$u_0$ are small compared with~$V$, +\[ +\frac{p}{m} = V + \tfrac{1}{2} (u + u_0), +\] +so that in this case the velocity of the light is increased by the +mean of the velocities of the dielectric and the ether. + +Fizeau's result that the increase in the velocity of light passing +through a current of air is a very small fraction of the velocity +of the air, shows that all of the preceding suppositions are +incorrect. + +Thus, if we retain the Electromagnetic Theory of Light, we +must admit that equations~(\eqnref{433}{1}) do not represent the electromotive +intensities in a dielectric in motion if $u$,~$v$,~$w$ are the velocities +of the \emph{dielectric itself}. + +If we suppose that in these equations $u$,~$v$,~$w$ ought to refer to +the velocity of the \emph{ether and not of the dielectric}, then the preceding +work shows that if supposition~(1) is true, the velocity +of light passing through moving ether is increased by one half +the velocity of the ether, while if supposition~(3) is true it is +increased by the velocity of the ether. + +As we could not suppose that the motion of the dielectric +makes the ether move faster than itself, the discovery of a case +in which the velocity of light was increased by more than half +the velocity of the dielectric would be sufficient to disprove +supposition~(1). + + +\Subsection{Currents induced in a Rotating conducting Sphere.} +\index{Himstedt, xcurrents induced in rotating sphere@\subdashone currents induced in rotating sphere}% +\index{Rotating sphere in an unsymmetrical field@\subdashtwo in an unsymmetrical field|indexetseq}% +\index{Sphere, rotating in an unsymmetrical field@\subdashone rotating in an unsymmetrical field|indexetseq}% + +\Article{441} When the external magnetic field is not symmetrical +about the axis of rotation electric currents will be produced in +the sphere. These have been discussed by Himstedt (\textit{Wied.\ Ann.}\ +11, p.~812, 1880), and Larmor (\textit{Phil.\ Mag.}\ [5], 17, p.~1, 1884). We +\index{Larmor, currents in a rotating sphere}% +can find these currents by the methods given in \chapref{Chapter IV.}{Chapters IV}~and~\chapref{Chapter V.}{V} +for dealing with spherical conductors. + +From equations~(\eqnref{433}{1}) we have, since +\[ +\frac{da}{dz} + \frac{db}{dy} + \frac{dc}{dz} = 0, +\] +%% -----File: 561.png---Folio 547------- +\begin{multline*} +\frac{dX}{dy} - \frac{dY}{dx} + = u \frac{dc}{dx} + v \frac{dc}{dy} + w \frac{dc}{dz} + + c\left(\frac{du}{dx} + \frac{dv}{dy} + \frac{dw}{dz}\right) \\ + - \left(a \frac{dw}{dx} + b \frac{dw}{dy} + c \frac{dw}{dz}\right), +\Tag{10} +\end{multline*} +with similar equations for +\[ +\frac{dZ}{dx} - \frac{dX}{dz}, \quad +\frac{dY}{dz} - \frac{dZ}{dy}. +\] + +If the sphere is rotating with angular velocity~$\omega$ about the +axis of~$z$, +\[ +u = -\omega y, \quad v = \omega x, \quad w = 0; +\] +so that equation~(\eqnref{441}{10}) becomes +\[ +\frac{dX}{dy} - \frac{dY}{dx} + = \omega\left(x \frac{dc}{dy} - y \frac{dc}{dx}\right). +\Tag{11} +\] + +If $\sigma$~is the specific resistance of the sphere, $\mu$~its magnetic +permeability, $\smallbold{p}$,~$\smallbold{q}$,~$\smallbold{r}$ the components of the current, +\[ +\left.\begin{aligned} +X & = \sigma \smallbold{p} = \frac{\sigma}{4\pi\mu} \left(\frac{dc}{dy} - \frac{db}{dz}\right), \\ +Y & = \sigma \smallbold{q} = \frac{\sigma}{4\pi\mu} \left(\frac{da}{dz} - \frac{dc}{dx}\right), \\ +Z & = \sigma \smallbold{r} = \frac{\sigma}{4\pi\mu} \left(\frac{db}{dx} - \frac{da}{dy}\right). +\end{aligned}\right\} +\Tag{12} +\] + +If we substitute these values for $X$~and~$Y$, equation~(\eqnref{441}{11}) +becomes +\begin{DPgather*} +\lintertext{\raisebox{\baselineskip}{similarly}} +\left.\begin{aligned} +\frac{\sigma}{4\pi\mu} \nabla^2 c & = \omega\left(x \frac{dc}{dy} - y \frac{dc}{dx}\right), \\ +\frac{\sigma}{4\pi\mu} \nabla^2 b & = \omega\left(x \frac{db}{dy} - y \frac{db}{dx}\right) - \omega a, \\ +\frac{\sigma}{4\pi\mu} \nabla^2 a & = \omega\left(x \frac{da}{dy} - y \frac{da}{dx}\right) + \omega b. +\end{aligned}\right\} +\Tag{13} +\end{DPgather*} + +From these equations we find by the aid of~(\eqnref{441}{12}) +\begin{align*} +\frac{\sigma}{4\pi\mu} \nabla^2 \smallbold{p} & = \omega\left(x \frac{d\smallbold{p}}{dy} - y \frac{d\smallbold{p}}{dx}\right) + \omega \smallbold{q}, \\ +\frac{\sigma}{4\pi\mu} \nabla^2 \smallbold{q} & = \omega\left(x \frac{d\smallbold{q}}{dy} - y \frac{d\smallbold{q}}{dx}\right) + \omega \smallbold{p}, \\ +\frac{\sigma}{4\pi\mu} \nabla^2 \smallbold{r} & = \omega\left(x \frac{d\smallbold{r}}{dy} - y \frac{d\smallbold{r}}{dx}\right). +\end{align*} +%% -----File: 562.png---Folio 548------- + +Hence +\[ +\frac{\sigma}{4\pi\mu} \nabla^2 (x\smallbold{p} + y\smallbold{q} + z\smallbold{r}) + = \omega\left(x \frac{d}{dy} - y \frac{d}{dx}\right)(x\smallbold{p} + y\smallbold{q} + z\smallbold{r}). +\Tag{14} +\] + +\begin{DPgather*} +\lintertext{\indent Let} +x\smallbold{p} + y\smallbold{q} + z\smallbold{r} = F(r)Y_n^s\, \epsilon^{\iota s\phi}, +\end{DPgather*} +where $r$,~$\theta$,~$\phi$ are the polar coordinates of a point, $\theta$~being +measured from the axis of~$z$. $Y_n^s\, \epsilon^{\iota s\phi}$ is a surface harmonic of +degree~$n$. Substituting this value in~(\eqnref{441}{14}), we find +\[ +\frac{d^2F}{dr^2} + \frac{2}{r}\, \frac{dF}{dr} + - \left(\frac{n(n + 1)}{r^2} + \frac{4\pi\iota\mu s\omega}{\sigma}\right)F = 0. +\] + +The solution of this is, \artref{308}{Art.~308}, +\begin{DPgather*} +F(r) = S_n (kr), \\ +\lintertext{where} +k^2 = -4\pi\mu\iota s\omega/\sigma. \\ +\lintertext{\indent Thus} +x\smallbold{p} + y\smallbold{q} + z\smallbold{r} = AS_n (kr)Y_n^s\, \epsilon^{\iota s\phi}, +\end{DPgather*} +where $A$~is a constant. + +Now $x\smallbold{p} + y\smallbold{q} + z\smallbold{r}$ is proportional to the current along the +radius, and this vanishes at the surface of the sphere where +$r = \smallbold{a}$; hence we have $AS_n (k\smallbold{a}) = 0$, but since the roots of +$S_n (x) = 0$ are real, and $k$~is partly imaginary, $S_n (k\smallbold{a})$ cannot +vanish, thus $A$~must vanish. In other words, the radial currents +must vanish throughout the sphere; the currents thus flow along +the surfaces of spheres concentric with the rotating one. +\begin{DPgather*} +\lintertext{\indent Since} +x\smallbold{p} + y\smallbold{q} + z\smallbold{r} = 0, \\ +\intertext{we may by \artref{370}{Art.~370} put} +\left.\begin{aligned} +\smallbold{p} = f_n (kr) \left(y \frac{d}{dz} - z \frac{d}{dy}\right)\omega_n, \\ +\smallbold{q} = f_n (kr) \left(z \frac{d}{dx} - x \frac{d}{dz}\right)\omega_n, \\ +\smallbold{r} = f_n (kr) \left(x \frac{d}{dy} - y \frac{d}{dx}\right)\omega_n; +\end{aligned}\right\} +\Tag{15} \\ +\lintertext{where} +f_n (kr) = \frac{S_n (kr)}{(kr)^n}, \\ +k^2 = -4\pi\mu\iota \DPtypo{S}{s}\omega/\sigma, +\end{DPgather*} +and $\omega_n$~is a solid spherical harmonic of degree~$n$. + +By \artref{372}{Art.~372}, $\alpha$,~$\beta$,~$\gamma$, the components of magnetic force, will be +given by +\[ +\alpha = \frac{4\pi}{(2n+1)k^2} + \left\{(n+1)f_{n-1} (kr)\, \frac{d\omega_n}{dx} + - nk^2 r^{2n+3} f_{n+1} (kr)\, \frac{d}{dx} \left(\frac{\omega_n}{r^{2n+1}}\right)\right\}, +\Tag{16} +\] +with similar expressions for $\beta$~and~$\gamma$. +%% -----File: 563.png---Folio 549------- + +Now the magnetic force may be regarded as made up of two +parts, one due to the currents induced in the sphere, the other to +the external magnetic field; the latter part will be derived from +a potential. Let~$\Omega_n$ be the value of this potential in the sphere; +we may regard~$\Omega_n$ as a solid spherical harmonic of degree~$n$, +since the most general expression for the potential is the sum +of terms of this type. If $\alpha_1$,~$\beta_1$,~$\gamma_1$ are the components of the +magnetic force due to the currents, $\alpha_0$,~$\beta_0$,~$\gamma_0$ those due to the +magnetic field, then +\[ +a = a_1 + a_0 = a_1 - \frac{d}{dx} \Omega_n. +\] + +Hence in the sphere +\begin{multline*} +a_1 = \frac{d\Omega_n}{dx} + + \frac{4\pi}{(2n+1)k^2} \left\{(n+1)f_{n-1} (kr)\, \frac{d\omega_n}{dx} \right. \\ + \left. -nk^2 r^{2n+3} f_{n+1} (kr)\, \frac{d}{dx} \left(\frac{\omega_n}{r^{2n+1}}\right)\right\}, +\Tag{17} +\end{multline*} +with similar expressions for $\beta_1$~and~$\gamma_1$. + +Outside the sphere the magnetic force due to the currents will +(neglecting the displacement currents in the dielectric) be derivable +from a potential which satisfies Laplace's equation; hence +outside the sphere we may put, if $\omega_n'$~represents a solid harmonic, +\[ +a_1 = -\smallbold{a}^{2n+1}\, \frac{d}{dx}\, \frac{\omega_n'}{r^{2n+1}}, +\] +with similar expressions for $\beta_1$~and~$\gamma_1$, where $\smallbold{a}$~is the radius of +the sphere. The magnetic force tangential to the sphere due +to these currents is continuous, as is also the normal magnetic +induction; hence, $\mu$~being the magnetic permeability of the +sphere, we have +\begin{gather*} +\Omega_n + \frac{4\pi}{(2n+1)k^2} \left\{(n+1) f_{n-1} (k\smallbold{a}) \omega_n - nk^2 \smallbold{a}^2 f_{n+1} (k\smallbold{a}) \omega_n \right\} \\ + = - \omega_n', \\ +\mu (n\Omega_n) + \frac{\mu n(n+1) 4\pi}{(2n+1)k^2} \left\{f_{n-1} (k\smallbold{a}) \omega_n + k^2 \smallbold{a}^2 f_{n+1} (k\smallbold{a}) \omega_n \right\} \\ + = (n+1) \omega_n'. +\end{gather*} + +Solving these equations, we find at the surface of the sphere +\begin{align*} +4\pi\omega_n + & = -\frac{(2n+1)(\mu n + n + 1) k^2 \Omega_n} + {(n+1)\{(\mu n + n + 1) f_{n-1} (k\smallbold{a}) + n(\mu-1) k^2 \smallbold{a}^2 f_{n+1} (k\smallbold{a})\}}, +\Tag{18} \\ +% +\omega_n' + & = -\frac{n(2n+1)\mu k^2 \smallbold{a}^2 f_{n+1} (k\smallbold{a})\Omega_n} + {(n+1)\{(\mu n + n + 1) f_{n-1} (k\smallbold{a}) + n(\mu-1) k^2 \smallbold{a}^2 f_{n+1} (k\smallbold{a})\}}. +\Tag{19} +\end{align*} +%% -----File: 564.png---Folio 550------- + +If we substitute these values of $\omega_n$,~$\omega_n'$ in equations (\eqnref{441}{15})~and~(\eqnref{441}{17}), +we get the currents induced in the sphere and the magnetic +force produced by those currents. + +\Article{442} We shall consider in detail the case when $n = 1$, i.e.~when +the sphere is rotating in a uniform magnetic field. Let +the magnetic potential of the external field be equal to the real +part of +\[ +Cr \cos \theta + Br \sin \theta\, \epsilon^{\iota \phi}, +\] +where $C$~is the force parallel to~$z$ and $B$~that parallel to~$x$. + +Then in the sphere +\[ +\Omega_1 = \frac{3}{\mu+ 2} (Cr \cos \theta + Br \sin \theta\, \epsilon^{\iota \phi}). +\] + +We shall first consider the case when $kr$~is very small, so +that approximately by \artref{309}{Art.~309} +\[ +f_0 (kr) = 1 - \tfrac{1}{6} k^2 r^2, \quad +f_1 (kr) = -\tfrac{1}{3}, \quad +f_2 (kr) = \tfrac{1}{15}. +\] + +Substituting these values in (\eqnref{441}{18})~and~(\eqnref{441}{19}) and retaining only +the lowest powers of~$k$, we find +\begin{gather*} +4\pi\omega_1 + = - \tfrac{9}{2}\, \frac{k^2}{\mu+2} \left(1+ \frac{\mu+4}{10(\mu+2)} k^2 \smallbold{a}^2\right) + Br \sin \theta\, \epsilon^{\iota \phi}, \\ +\omega_1' = - \frac{3k^2 \smallbold{a}^2}{10(\mu+2)^2} + Br \sin \theta\, \epsilon^{\iota \phi}. +\end{gather*} + +The term $Cr \cos \theta$ in~$\Omega$ does not give rise to any terms in +$\omega_n$,~$\omega_n'$ since~$s$ and therefore~$k$ vanishes for this term. Substituting +these values we get by equations~(\eqnref{441}{15}) +\[ +\left. +\begin{aligned} +\smallbold{p} &= -\tfrac{3}{2}\, \frac{\mu \omega}{(\mu + 2)\sigma} zB, \\ +\smallbold{q} &= 0, \\ +\smallbold{r} &= \tfrac{3}{2}\, \frac{\mu \omega}{(\mu + 2)\sigma} xB. +\end{aligned} \right\} +\Tag{20} +\] + +Thus the currents flow in parallel circles, having for their +common axis the line through the centre of the sphere which +is at right angles both to the axis of rotation and to the direction +of magnetic force in the external field. The intensity of the +current at any point is proportional to the distance of the point +from this axis. + +The components of the magnetic induction in the sphere are +given by the equations +%% -----File: 565.png---Folio 551------- +\[ +\left. +\begin{aligned} +a &= - \frac{3 \mu B}{\mu + 2} \left( 1 + \frac{2 \pi \mu \omega} {5 \sigma} xy \right), \\ +b &= \frac{3 \pi \mu^2 \omega B}{(\mu + 2) \sigma} (\tfrac{4}{5} r^2 - \tfrac{2}{5} y^2 - \tfrac{2}{5}\, \frac{\mu + 4}{\mu + 2} \smallbold{a}^2), \\ +c &= - \frac{3 \mu}{\mu + 2} \left( C + \frac{2 \pi \mu \omega}{5 \sigma} Byz \right). +\end{aligned} \right\} +\Tag{21} +\] + +Thus the magnetic force due to currents consists of a radial +force proportional to~$yr$, together with a force parallel to~$y$ +proportional to $2 r^2 - (\mu+4) \smallbold{a}^2 /(\mu+2)$. + +Outside the sphere the total magnetic potential is +\[ +(Cz + Bx) \left( 1 - \frac{(\mu - 1)}{\mu + 2}\, \frac{\smallbold{a}^3}{r^3} \right) + - \frac{6 \pi B}{5 (\mu + 2)^2}\, \frac{\mu^2 \omega \smallbold{a}^5}{\sigma}\, \frac{y}{r^3}. +\] + +Thus the magnetic effect of the currents at a point outside +the sphere is the same as that of a small magnet at the centre, +with its axis at right angles to the axis of rotation and the +external magnetic field, and whose moment is +\[ +\frac{6 \pi B}{5(\mu + 2)^2}\, \frac{\mu^2 \omega \smallbold{a}^5}{\sigma}. +\] + +\Article{443} Let us now consider the case when $k \smallbold{a}$~is large, since, +when $s = 1$ +\begin{DPalign*} +k^2 &= - \frac{4 \pi \mu \omega \iota}{\sigma},\\ +\lintertext{we have} +k &= \sqrt{2} K\, \epsilon^{-\frac{\iota \pi}{4}}, \\ +\lintertext{where} +K^2 &= \frac{2 \pi \mu \omega}{\sigma}, +\end{DPalign*} +thus the real part of~$\iota k \smallbold{a}$ is positive and large; hence we have +approximately +\begin{align*} +f_0(k \smallbold{a}) &= \frac{\epsilon^{\iota k \smallbold{a}}}{2 \iota k \smallbold{a}}, \\ +f_1(k \smallbold{a}) &= \frac{\epsilon^{\iota k \smallbold{a}}}{2k^2 \smallbold{a}^2}, \\ +f_2(k \smallbold{a}) &= -\frac{\epsilon^{\iota k \smallbold{a}}}{2 \iota k^3 \smallbold{a}^3}. +\end{align*} + +Hence we find +\begin{gather*} +4 \pi \omega_1 + = - 3 \iota k^3 \smallbold{a}\, \epsilon^{-\iota k \smallbold{a}}\, Br \sin \theta\, \epsilon^{\iota \phi},\\ +\omega_1' = \tfrac{3}{2}\, \frac{\mu}{\mu + 2} Br \sin \theta\, \epsilon^{\iota \phi}, +\end{gather*} +%% -----File: 566.png---Folio 552------- +so that by~(\eqnref{441}{15}) +{\footnotesize +\[ +\left. +\begin{aligned} +\smallbold{p} &= - \frac{3 \sqrt{2} K}{8 \pi}\, \frac{z \smallbold{a}}{r^2}\, B \epsilon^{-K(\smallbold{a}-r)} \cos \left\{K(\smallbold{a}-r) + \frac{\pi}{4} \right\},\\ +\smallbold{q} &= - \frac{3 \sqrt{2} K}{8 \pi}\, \frac{z \smallbold{a}}{r^2}\, B \epsilon^{-K(\smallbold{a}-r)} \sin \left\{K(\smallbold{a}-r) + \frac{\pi}{4} \right\},\\ +\smallbold{r} &= \frac{3 \sqrt{2} K}{8 \pi}\, \frac{\smallbold{a}}{r^2}\, B \epsilon^{-K(\smallbold{a}-r)} + \left[ x \cos \left\{K(\smallbold{a}-r) + \frac{\pi}{4} \right\} + + y \sin \left\{K(\smallbold{a}-r) + \frac{\pi}{4} \right\} \right]. +\end{aligned} +\right\} +\eqnlabel{\eqnart.22}\tag*{\text{\normalsize(22)}} +\] +} + +The total components of the magnetic induction inside the +sphere are given by +{\footnotesize +\[ +\left. +\begin{aligned} +a = - \mu B \frac{\smallbold{a}}{r}\, \epsilon^{-K(\smallbold{a}-r)} \cos K (\smallbold{a}-r) + &- \tfrac{1}{2} \mu B \epsilon^{-K (\smallbold{a}-r)} \smallbold{a}r^2 \cos K (\smallbold{a}-r)\, \frac{d}{dx}\, \frac{x}{r^3} \\ + &- \tfrac{1}{2} \mu B \epsilon^{-K (\smallbold{a}-r)} \smallbold{a}r^2 \sin K (\smallbold{a}-r)\, \frac{d}{dx}\, \frac{y}{r^3},\\ +% +b = - \mu B \frac{\smallbold{a}}{r}\, \epsilon^{-K(\smallbold{a}-r)} \sin K (\smallbold{a}-r) + &- \tfrac{1}{2} \mu B \epsilon^{-K (\smallbold{a}-r)} \smallbold{a}r^2 \cos K (\smallbold{a}-r)\, \frac{d}{dy}\, \frac{x}{r^3} \\ + &- \tfrac{1}{2} \mu B \epsilon^{-K (\smallbold{a}-r)} \smallbold{a}r^2 \sin K (\smallbold{a}-r)\, \frac{d}{dy}\, \frac{y}{r^3},\\ +% +c = - \frac{3 \mu C}{\mu + 2} - \tfrac{1}{2} \mu B\, \epsilon^{-K(\smallbold{a}-r)} \smallbold{a}r^2 &\cos K (\smallbold{a}-r)\, \frac{d}{dz}\, \frac{x}{r^3} \\ + &- \tfrac{1}{2} \mu B \epsilon^{-K (\smallbold{a}-r)} \smallbold{a}r^2 \sin K (\smallbold{a}-r)\, \frac{d}{dz}\, \frac{y}{r^3}, +\end{aligned} +\right\} +\eqnlabel{\eqnart.23}\tag*{\text{\normalsize(23)}} +\] +} +while the magnetic potential outside due to the currents in +the sphere is +\[ +\frac{3}{2}\, \frac{\mu B}{\mu+2}\, \smallbold{a}^3\, \frac{x}{r^3}. +\Tag{24} +\] + +If we compare these results with those we obtained when~$k \smallbold{a}$, +was small, we see that they differ in the same way as the +distribution of rapidly varying currents in a conductor differs +from that of steady or slowly varying ones. When $k \smallbold{a}$~is small +the currents spread through the whole of the sphere, while +when $k \smallbold{a}$~is large they are, as equations~(\eqnref{443}{22}) show, confined +to a thin shell. The currents flow along the surfaces of spheres +concentric with the rotating one, and the intensity of the +currents diminishes in Geometrical Progression as the distance +from the surface of the sphere increases in Arithmetical Progression. + +The magnetic field due to these currents annuls in the interior +of the sphere, as equation~(\eqnref{443}{23}) shows, that part of the external +%% -----File: 567.png---Folio 553------- +magnetic field which is not symmetrical about the axis of +rotation. Thus the rotating sphere screens its interior from all +but symmetrical distributions of magnetic force if $\{4 \pi \mu \omega / \sigma \}^{\frac{1}{2}} \smallbold{a}$ is +large. + +A very interesting case of the rotating sphere is that of the +\index{Earth's magnetism}% +earth; in this case +\[ +\smallbold{a} = 6.37 × 10^8,\quad \omega = 2 \pi / (24 × 60 × 60), +\] +so that approximately +\[ +\{4 \pi \mu \omega / \sigma \}^{\frac{1}{2}} \smallbold{a} = 2 × 10^7 \sigma^{-\frac{1}{2}}. +\] + +Thus if $\sigma$~is comparable with~$10^8$, which is of the order of the +specific resistance of electrolytes, $k \smallbold{a}$~will be about $2000$, and this +will be large enough to keep the earth a few miles below its +surface practically free from the effects of an external unsymmetrical +magnetic field. + +Again, we have seen, \artref{84}{Art.~84}, that rarefied gases have considerable +conductivity for discharges travelling along closed +curves inside them. For gases in the normal state this conductivity +only manifests itself under large electromotive intensities, +but when the gas is in the state similar to that +produced by the passage of a previous discharge, it has considerable +conductivity even for small electromotive intensities. We +see from the preceding results that if there were a belt of gas in +this condition in the upper regions of the earth's atmosphere, +and if the part of the solar system traversed by the earth were +a magnetic field, this gas would screen off from the earth all +magnetic effects which were not symmetrical about the axis of +rotation. Thus the magnetic field at the earth's surface would, +on this hypothesis, resemble that which actually exists in being +roughly symmetrical about the earth's axis. The thickness of +a shell required to reduce the magnetic field to $1 / \epsilon$~of its value at +the outer surface of the shell is $\{4 \pi \omega / \sigma \}^{-\frac{1}{2}}$, or if $\sigma = 10^8$, about +two miles. The result mentioned in Art.~470 of Maxwell's +\textit{Electricity and Magnetism}, that by far the greater part of the +mean value of the magnetic elements arises from some cause +inside the earth, shows, however, that we cannot assign the +earth's permanent magnetic field to this cause. + +\Article{444} The total magnetic potential outside the sphere is, when +$k \smallbold{a}$~is large, by equation~(\eqnref{443}{24}), +%% -----File: 568.png---Folio 554------- +\begin{multline*} +Cz \left( 1 - \frac{\mu - 1}{\mu + 2}\, \frac{\smallbold{a}^3}{r^3} \right) + + B \left( x-\frac{\mu-1}{\mu+2}\, \frac{\smallbold{a}^3}{r^3} x + + \tfrac{3}{2}\, \frac{\mu}{\mu + 2}\, \frac{\smallbold{a}^3}{r^3} x \right) \\ += Cz \left( 1 - \frac{\mu - 1}{\mu + 2}\, \frac{\smallbold{a}^3}{r^3} \right) + + Bx \left( 1 + \tfrac{1}{2}\, \frac{\smallbold{a}^3}{r^3} \right). +\end{multline*} + +Thus the effect of the rotating sphere on the part of the +external magnetic field which is unsymmetrical about the axis +of rotation, i.e.~upon the term $Br \sin \theta\, \epsilon^{\iota \phi}$, is exactly the same +as if this sphere were replaced by a sphere of diamagnetic +substance for which $\mu = 0$; in other words, the rotating sphere +behaves like a diamagnetic body. Thus we could make a +model which would exhibit the properties of a feebly diamagnetic +body in a steady field, by having a large number of rotating +conductors arranged so that the distance between their centres +was large compared with their linear dimensions. + + +\Subsection{Couples and Forces on the Rotating Sphere.} + +\Article{445} We shall now proceed to investigate the couples and +forces on the sphere caused by the action of the magnetic field +on the currents induced in the sphere. + +If $X$,~$Y$,~$Z$ are the components of the mechanical force per +unit volume, then (Maxwell's \textit{Electricity and Magnetism}, vol.~ii. +Art.~603, equations~\textit{C}) +\begin{align*} +X & = c \smallbold{q} - b \smallbold{r},\\ +Y & = a \smallbold{r} - c \smallbold{p},\\ +Z & = b \smallbold{p} - a \smallbold{q}. +\end{align*} + +The couple on the sphere round the axis of~$z$ is +\[ +\iiint (Yx - Xy)\,dx\,dy\,dz, +\] +the integration extending throughout the sphere. + +Substituting the preceding values for $Y$~and~$X$, we see that +this may be written +\[ +\iiint ( \smallbold{r} (ax + by + cz) - c ( \smallbold{p}x + \smallbold{q}y + \smallbold{r}z))\,dx\,dy\,dz. +\] + +But since the radial current vanishes, +\[ +\smallbold{p}x + \smallbold{q}y + \smallbold{r}z = 0; +\] +thus the couple round~$z$ reduces to +\[ +\iiint \smallbold{r}Rr\,dx\,dy\,dz, +\] +where $R$~is the magnetic induction along the radius. +%% -----File: 569.png---Folio 555------- + +Similarly the couple round~$x$ is equal to +\index{Couple on a sphere rotating in a magnetic field}% +\[ +\iiint \smallbold{p}Rr\,dx\,dy\,dz, +\] +while that round~$y$ is +\[ +\iiint \smallbold{q}Rr\,dx\,dy\,dz. +\] + +From equation~(\eqnref{441}{16}) we see that +\[ +Rr = \frac{4\pi\mu}{(2n+1)k^2}\, n(n+1)\{f_{n-1} (kr)+k^2 r^2 f_{n+1} (kr)\}\omega_n. +\] + +Now by~(\eqnref{370}{4}), \artref{370}{Art.~370}, +\[ +f_{n-1} (kr)+k^2 r^2 f_{n+1} (kr) = -(2n+1)f_n (kr), +\] +so that +\[ +Rr = - \frac{4\pi\mu}{k^2}\, n(n+1)f_n (kr)\omega_n, +\Tag{25} +\] +or by~(\eqnref{441}{15}) +\[ +Rr = - \frac{\sigma}{\omega s^2}\, n(n+1)\smallbold{r}. +\] + +Thus the couple around~$z$ is +\[ +- \frac{\sigma}{\omega s^2}\, n\centerdot(n+1) \iiint \smallbold{r}^2\,dx\,dy\,dz. +\] + +When $\omega$~is small we find, by substituting the value of~$r$ given +in equation~(\eqnref{442}{20}), that when the sphere is rotating in a uniform +magnetic field the couple tending to stop it is +\[ +\frac{6\mu^2}{5(\mu+2)^2}\, B^2\, \frac{\omega}{\sigma}\, \pi \smallbold{a}^5. +\] + +\nbpagebreak[1]\Article{446} We see by equation~(\eqnref{445}{25}) that the normal component of +the magnetic force is proportional to $f_n (kr)$, while by~(\eqnref{441}{16}) the +other components contain terms proportional to $f_{n-1} (kr)$, but +when $k\smallbold{a}$~is very large we have approximately +\begin{gather*} +f_{n-1} (k\smallbold{a}) = \tfrac{1}{2}\, \iota^{n-2}\, \frac{\epsilon^{\iota k\smallbold{a}}}{(k\smallbold{a})^n}, \\ +f_n (k\smallbold{a}) = \tfrac{1}{2}\, \iota^{n-1}\, \frac{\epsilon^{\iota k\smallbold{a}}}{(k\smallbold{a})^{n+1}}. +\end{gather*} + +Thus when $k\smallbold{a}$~is very large $f_n (k\smallbold{a})$, and near the surface of the +sphere $f_n (k\smallbold{r})$, is very small compared with $f_{n-1} (k\smallbold{a})$, so that by~(\eqnref{445}{25}) +the magnetic force along the normal to the sphere vanishes in +comparison with the tangential force, in other words the magnetic +force is tangential to the surface. + +This result can be shown to be true, whatever the shape of +the body, provided it is rotating with very great velocity. If +%% -----File: 570.png---Folio 556------- +we consider the part of the magnetic field which is not symmetrical +about the axis of rotation we have the following +results:--- + +Since the magnetic potential outside the rotating bodies is +determined by the conditions (1)~that it should have at an infinite +distance from these bodies the same value as for the undisturbed +external field, and (2)~that the magnetic force at right angles to +these bodies should vanish over their surface, we see that the +magnetic force at any point will be the same as the velocity of +an incompressible fluid moving irrotationally and surrounding +these bodies supposed at rest, the velocity potential at an infinite +distance from these being equal to the magnetic potential in the +undisturbed magnetic field. + +\Article{447} If we substitute the value of~$R$, given by equation~(\eqnref{445}{25}), in +the expression for the couple round~$z$, we find that if we neglect +powers of~$1/k\smallbold{a}$ the couple vanishes. Thus the couple vanishes +when $\omega = 0$ and when $\omega = \infty$, there must therefore be some +intermediate value of~$\omega$ for which the couple is a maximum. + +Let us now consider the forces on the sphere. The force +parallel to~$x$ is equal to +\begin{gather*} +\iiint (c\smallbold{q}-b\smallbold{r})\,dx\,dy\,dz \\ +\begin{aligned} + &= \frac{1}{4\pi} \iiint + \left\{c\left(\frac{d\alpha}{dz} - \frac{d\gamma}{dx}\right) + - b\left(\frac{d\beta}{dx} - \frac{d\alpha}{dy}\right)\right\} dx\,dy\,dz \\ + &= \frac{1}{4\pi} \iint + \left\{\alpha(la + mb + nc) - \tfrac{1}{2} l(a\alpha + b\beta + c\gamma)\right\}\,dS, +\end{aligned} +\end{gather*} +where $dS$~is an element of the surface, and $l$,~$m$,~$n$ the direction +cosines of the outward drawn normal. The forces parallel to +$y$~and~$z$ are given by similar expressions. We see that the force +is equivalent to a tension parallel to the magnetic force inside +the sphere and equal to +\[ +\frac{1}{4\pi}(\alpha^2 + \beta^2 + \gamma^2 )^{\frac{1}{2}} R +\] +per unit of surface, $R$~being the magnetic induction along the +outward normal; and to a normal pressure equal to +\[ +\frac{1}{8\pi}(a\alpha + b\beta + c\gamma). +\] + +When the sphere is rotating so rapidly that $k\smallbold{a}$~is very large +%% -----File: 571.png---Folio 557------- +$R$~vanishes, and the force on the rotating sphere is that due +to a pressure +\[ +\frac{\mu}{8\pi}(\alpha^2 + \beta^2 + \gamma^2); +\] +this pressure will tend to make the sphere move from the strong +to the weak places of the field. We see, therefore, that not only +does the rotating sphere disturb the magnetic field in the same +way as a diamagnetic body, but that it tends to move as such +a body would move, i.e.~from the strong to the weak parts of +the field. + +\Article{448} If instead of a rotating sphere in a steady magnetic +field we have a fixed sphere in a variable field, varying as~$\epsilon^{\iota pt}$, +the preceding results will apply if instead of putting +$k^2 = -4\pi\mu\omega\iota s/\sigma$ we put $k^2 = -4\pi\mu\iota p/\sigma$, and neglect the polarization +currents in the dielectric. We can prove this at once by +seeing that the equations for $a$,~$b$,~$c$ in the two cases become +identical if we make this change. + +The results we have already obtained in this chapter, when +applied to the case of alternating currents, show that in a +variable field when $k\smallbold{a}$~is large the currents and magnetic force +will be confined to a thin layer near the surface, and that a conductor +will act like a diamagnetic body both in the way it +disturbs the field and the way it tends to move under the +influence of that field. The movement of currents from the +strong to the weak parts of the field has been demonstrated in +\index{Electromagnetic vrepulsion@\subdashone repulsion}% +\index{Fleming, electromagnetic repulsion@\subdashone electromagnetic repulsion}% +\index{Repulsion, electromagnetic}% +\index{Thompson, Elihu, electromagnetic repulsion}% +\index{Walker, electromagnetic repulsion}% +some very striking experiments made by Professor Elihu Thomson, +\textit{Electrical World}, 1887, p.~258 (see also Professor J.~A. +Fleming on `Electromagnetic Repulsion,' \textit{Electrician}, 1891, pp.~567 +and~601, and Mr.\ G.~T. Walker, \textit{Phil.\ Trans}.\ A. p.~279, 1892). +The correspondence of the magnetic force to the velocity of an +incompressible fluid, flowing round the conductors, is more complete +in this case than in that of the rotating sphere, inasmuch +as we have not to except any part of the magnetic potential, +whereas in the case of the rotating sphere we have to except +that part of the magnetic potential which is symmetrical about +the axis of rotation. +%% -----File: 572.png---Folio 558------- +%% -----File: 573.png---Folio 559------- + +\Chapter{Appendix.}{} + +\artlabel{App}\Firstsc{In} \artref{201}{Art.~201} of the text there is a description of Perrot's experiments +on the electrolysis of steam. As these experiments throw a great deal of +light on the way in which electrical discharges pass through gases I have, +while this work has been passing through the press, made a series of +experiments on the same subject. + +The apparatus I used was the same in principle as Perrot's. I made +some changes, however, in order to avoid some inconveniences to which +it seemed to me Perrot's form was liable. One source of doubt in +Perrot's experiments arose from the proximity of the tubes surrounding +the electrodes to the surface of the water, and their liability to get +damp in consequence. These tubes were narrow, and if they got damp +the sparks instead of passing directly through the steam might conceivably +have passed from one platinum electrode to the film of moisture +on the adjacent tube, then through the steam to the film of moisture on +the other tube and thence to the other electrode. If anything of this +kind happened it might be urged that since the discharge passed +through water in its passage from one terminal to the other, some of +the gases collected in the tubes~$gg$ (\figureref{fig84}{Fig.~84}) might have been due to +the decomposition of the water and not to that of the steam. + +To overcome this objection I (1)~removed the terminals to a very +much greater distance from the surface of the water and placed them in +a region surrounded by a ring-burner by means of which the steam was +heated to a temperature of $140°$\,C to $150°$\,C. \hspace{0.5em}(2)~I got rid of the +narrow tubes surrounding the electrodes altogether by making the tubes +through which the steam escaped partly of metal and using the metallic +part of these tubes as the electrodes. + +Instead of following Perrot's plan of removing the mixed gases from +the collecting tubes~$ee$ (\figureref{fig84}{Fig.~84}) and then exploding them in a separate +vessel, I collected the gases on their escape from the discharge tubes in +%% -----File: 574.png---Folio 560------- +graduated eudiometers provided with platinum terminals, by means of +which the mixed gases were exploded \textit{in~situ} at short intervals during +the course of the experiments. + +\Subsection{Description of Apparatus.} + +This apparatus is represented in \figureref{fig142}{Fig.~142}. \smallsanscap{H} is a glass bulb $1.5$~to +$2$~litres in volume containing the water which supplies the steam; a +%% -----File: 575.png---Folio 561------- +glass tube about $.75$~cm.\ in diameter and $35$~cm.\ in length is joined on to +this bulb, and the top of this tube is fused on to the discharge tube~\smallsanscap{CD}; +this tube is blown out into a bulb in the region where the sparks pass, +so that when long sparks are used they may not fly to the walls of the +tube. This part of the tube is encircled by the ring-burner~\smallsanscap{K} by means +of which the steam can be superheated. + +\includegraphicsmid{fig142}{Fig.~142.} + +The electrodes between which the sparks pass are shown in detail in +\figureref{fig143}{Fig.~143}; \smallsanscap{A},~\smallsanscap{B}~are metal tubes, these must be made of a metal which does +not oxidise. In the following experiment \smallsanscap{A},~\smallsanscap{B}~are either brass tubes +thickly plated with gold, or tubes made by winding thick platinum wire +into a coil. These tubes are placed in pieces of glass tubing to hold +them in position. These tubes stop short of the places \smallsanscap{F},~\smallsanscap{G} where the +delivery tubes join the discharge tube. The discharge tube is closed at +the ends by the glass tubes \smallsanscap{P}~and~\smallsanscap{Q}, and wires connected to the electrodes +\smallsanscap{A}~and~\smallsanscap{B} are fused through these tubes. + +\includegraphicsmid{fig143}{Fig.~143.} + +The delivery tubes which terminate in fine openings were fused on to +the discharge tube at \smallsanscap{F}~and~\smallsanscap{G}. + +To get rid of the air which is in the apparatus or which is absorbed +by the water, the apparatus is filled so full of water at the beginning of +the experiment that when the water is heated it expands sufficiently +to fill the discharge tube and overflow through the delivery tubes. The +water is boiled vigorously for $6$~or $7$~hours with the ends of the delivery +tubes open to the atmosphere. The eudiometer tubes filled with +mercury are then placed over the ends of the delivery tubes, so that if +any air is mixed with the steam it will be collected in these tubes. +The sparking is not commenced until after the steam has run into the +delivery tubes for about an hour without carrying with it a quantity of +air large enough to be detected. + +The sparks are produced by a large induction coil giving sparks +about $5$~cm.\ long when the current from five large storage cells is sent +through the primary. When a condenser of about $6$~or $7$~micro-farads +capacity is added to that supplied with the instrument a current was +produced which, when the distance between the electrodes \smallsanscap{A}~and~\smallsanscap{B} in +%% -----File: 576.png---Folio 562------- +the discharge tube is not more than about $4$~mm., will liberate about +$4$~c.c.\ of hydrogen per hour in a water voltameter placed in series with +the discharge tube. + + +\Subsection{Method of making the Experiments.} + +When it had been ascertained that all the air had been expelled from +the vessel and from the water, and that the rates of flow of the gases +through the delivery tubes were approximately equal, the eudiometer +tubes filled with mercury were placed over the ends of the delivery +tubes, a water voltameter was placed in series with the steam tube, and +the coil set in action. + +The steam which went up the eudiometer tubes condensed into hot +water which soon displaced the mercury; the mixture of oxygen and +hydrogen produced by the spark went up the eudiometer tubes and +was collected over this hot water and exploded at short intervals of time +by the sparks from a Wimshurst machine. The gases did not disappear +entirely when the sparks passed; a small fraction of the volume remained +over after each explosion, and the volume which remained was +greater in one tube than the other. The residual gas which had the +greatest volume was found on analysis to be hydrogen, the other was +oxygen. When a sufficient quantity of the residual gases had been +collected they were analysed. The result of the analysis was that when +the sparks were not too long the residual gas in one tube was pure +hydrogen, that in the other pure oxygen; if any other gases were present +their volume was too small to be detected by my analyses. When the +sparks were very long there was always some other gas (nitrogen?)\ +present, sometimes in considerable quantities. + + +\Subsection{Results of the Experiments.} + +The results obtained by the preceding method varied greatly in their +character with the length of the spark, I shall therefore consider them +under the heads---`short sparks,' `medium sparks,' and `long sparks.' + +The lengths at which a spark changes from `short' to `medium' and +then again to `long' depend on the intensity of the current passing +through the steam, and therefore upon the size of the induction coil and +the battery power used to drive it. The limits of `short,' `medium,' +and `long' sparks given below must therefore be understood to have +reference to the particular coil and current used in these experiments. +With a larger coil and current these limits would expand, with a smaller +one they would contract. +%% -----File: 577.png---Folio 563------- + +\Subsection{Short Sparks.} +\index{Arc discharge, connection between chemical change and quantity of electricity passing@\subdashtwo connection between chemical change and quantity of electricity passing}% + +These sparks were from $1.5$~mm.~to $4$~mm.\ long. The appearance of +the spark showed all the characteristics of an arc discharge, it was a +thickish column with ill-defined edges and was blown out by a wind to +a broad flame-like appearance. For these arcs the following laws were +found to hold:--- + +1. That within the limits of error of the experiments the volumes of +the excesses of hydrogen in one tube and of oxygen in the other which +remain after the explosion of the mixed gases are respectively equal to +the volumes of the hydrogen and oxygen liberated in the water voltameter +placed in series with the steam tube. + +2. The excess of hydrogen appears in the tube which is in connection +with the \emph{positive} electrode, the excess of oxygen in the tube which is in +connection with the \emph{negative} electrode. + +It thus appears that with these short sparks or arcs the hydrogen +appears at the \emph{positive} electrode instead of as in ordinary electrolysis at +the \emph{negative}. + +The following table contains the results of some measurements of the +relation between the excesses of hydrogen and oxygen in the eudiometer +tubes attached to the steam tube and the quantity of hydrogen liberated +in a water voltameter placed in series with the discharge tube. The +ordinary vibrating break supplied with induction coils was used unless +the contrary is specified:--- +\begin{center} +\tabletextsize +\setlength{\tabcolsep}{2pt} +\settowidth{\TmpPadLen}{Platinum} +\begin{tabular}{|*{6}{c|}} +\hline +\settowidth{\TmpLen}{Spark length}% +\parbox[c]{\TmpLen}{\medskip\centering Spark length\\in milli-\\metres.\medskip} & +\settowidth{\TmpLen}{Metal used for}% +\parbox[c]{\TmpLen}{\centering Metal used for\\electrodes.} & +\settowidth{\TmpLen}{Excess of $H$ in}% +\parbox[c]{\TmpLen}{\centering Excess of $H$ in\\tube next $+$\\electrode.} & +\settowidth{\TmpLen}{Excess of $O$ in}% +\parbox[c]{\TmpLen}{\centering Excess of $O$ in\\tube next $-$\\electrode.} & +\settowidth{\TmpLen}{$H$ liberated}% +\parbox[c]{\TmpLen}{\centering $H$ liberated\\in water\\voltameter.} & +\settowidth{\TmpLen}{Duration of}% +\parbox[c]{\TmpLen}{\centering Duration of\\experiment\\in minutes.} \\ +\hline +\tablespaceup$1.5$ & \parbox[c]{\TmpPadLen}{Gold} & $3.25$\rlap{ c.c.}& $1.5\Z$\rlap{c.c.} & $3.2\Z$\rlap{c.c.} & $40$ \\ +$1.5$ & Platinum & $2.8\Z$ & $1.6\Z$ & $3\phantom{.00}$ & $30$ \\ +$1.5$ & \parbox[c]{\TmpPadLen}{Gold} & $1.7\Z$ & $\Z.8\Z$ & $1.8\Z$ & $20$ \\ +$2\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $2\phantom{.00}$ & $1.08$ & $1.95$ & $30$ \\ +$2\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $3.25$ & $1.75$ & $3.2\Z$ & $60$ \\ +$2\phantom{.0}$ & Platinum & $1.8\Z$ & Tube broke & $2\phantom{.00}$ & Not noted \\ +$2\phantom{.0}$ & Platinum & $3\phantom{.00}$ & $1.5\Z$ & $3\phantom{.00}$ & $60$ \\ +$2\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $2.5\Z$ & $1.5\Z$ & $3\phantom{.00}$ & $60$ \\ +$3\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $1.8\Z$ & Not noted & $1.8\Z$ & Not noted \\ +$3\rlap{\tabfootmark}\phantom{.0}$% + & \parbox[c]{\TmpPadLen}{Gold} & $\Z.7\Z$ & $\Z.4\Z$ & $\Z.8\Z$ & $90$ \\ +$3\rlap{\tabfootmark}\phantom{.0}$% + & \parbox[c]{\TmpPadLen}{Gold} & $1.6\Z$ & Not noted & $1.75$ & Not noted \\ +$4\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $\Z.9\Z$ & $\Z.37$ & $\Z.7\Z$ & $20$ \\ +$4\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $2.75$ & $1.25$ & $2.7\Z$ & $60$ \\ +$4\rlap{\tabfootmark[0]}\phantom{.0}$% + & \parbox[c]{\TmpPadLen}{Gold} & $1.0\Z$ & Not noted & $1.25$ & Not noted \\ +$4\phantom{.0}$ & \parbox[c]{\TmpPadLen}{Gold} & $2.5\Z$ & $1.25$ & $2.3\Z$ & $45$\tablespacedown \\ +\hline +\end{tabular} +\end{center} + +\addtocounter{footnote}{-1}% +\footnotetext[\value{footnote}]{In this experiment a slow mercury break, making about four breaks a second, was used.} +\addtocounter{footnote}{1}% +\footnotetext[\value{footnote}]{In these experiments Leyden jars were attached to the electrodes.} +%% -----File: 578.png---Folio 564------- + +The results tabulated above show that the excesses of hydrogen and +oxygen from the steam are approximately equal to the quantities of +hydrogen and oxygen liberated in the water voltameter. + + +\Subsection{Medium Sparks.} + +When the spark length is greater than $4$~mm.\ the first of the preceding +results ceases to hold. The second, that the hydrogen comes off +at the positive electrode, remains true until the sparks are about $11$~mm.\ +long, but the hydrogen from the steam, instead of being equal to that +from the voltameter, is, when the increase in the spark length is not too +large, considerably greater. + +\noindent\begin{minipage}{\textwidth} %[TN: minipage to keep sentence with table] +The following are a few instances of this:--- +\begin{center} +\tabletextsize +\begin{tabular}{c *{2}{>{\qquad}{c}}} +Spark length & +\settowidth{\TmpLen}{Hydrogen from}% +\parbox[c]{\TmpLen}{\centering Hydrogen from\\steam in c.c.\medskip} & +\settowidth{\TmpLen}{voltameter in c.c.}% +\parbox[c]{\TmpLen}{\centering Hydrogen from\\voltameter in c.c.} \\ +$5$ mm. & $1.8\Z$ & $1.2$ \\ +$5$ mm. & $3.75$ & $3\phantom{.0}$ \\ +$5$ mm. & $4.4\Z$ & $2.1$ \\ +$6$ mm. & $4\phantom{.00}$ & $1.6$ \\ +$7$ mm. & $4.25$ & $3\phantom{.0}$ \\ +$7$ mm. & $3.75$ & $2\phantom{.0}$ \\ +$8$ mm. & $3.75$ & $2.6$ +\end{tabular} +\medskip +\end{center} +\end{minipage} + +The increase in the ratio of the hydrogen from the steam to that from +the voltameter does not continue when the spark length is still further +increased. When the spark length exceeds $8$~mm.\ this ratio begins to +fall off very rapidly as the spark length increases, and we soon reach a +critical spark length at which it seems almost a matter of chance whether +the hydrogen from the steam appears at the positive or the negative +electrode. + + +\Subsection{Long Sparks.} + +When the spark length is increased beyond the critical value, the +excess of hydrogen instead of appearing at the positive electrode as with +shorter sparks changes over to the negative, the excess of oxygen at the +same time going over from the negative to the positive electrode. Thus +the gases, when the spark length is greater than its critical value, appear +at the same terminals in the steam tube as when liberated from an +ordinary electrolyte, instead of at the opposite ones as they do when the +sparks are shorter. + +The critical length depends very largely upon the current sent through +the steam; the smaller the current the shorter this length. It also +depends upon a number of small differences, some of which are not easily +specified, and it will sometimes change suddenly without any apparent +reason. I have found, however, that this capriciousness disappears if +%% -----File: 579.png---Folio 565------- +Leyden jars are attached to the terminals of the steam tube or if an +air-break is placed in series with that tube. + +It will be seen that the results when the spark length is greater than +the critical length agree with those obtained by Perrot (\artref{201}{Art.~201}) and +Ludeking (\artref{210}{Art.~210}), as both these observers found that the hydrogen +appeared at the negative, the oxygen at the positive electrode. Ludeking +worked with long sparks, so that his results are quite in accordance +with mine. In Perrot's experiments the spark length was $6$~mm. +I have never been able to reduce the critical length quite so low as this, +though I diminished the current to the magnitude of that used by +Perrot; I have, however, got it as low as $8$~mm., and it is probable that +the critical length may not be governed entirely by the current. + +\nblabel{pag:565}I was not able to detect any decided change in the appearance of the +spark as the spark length passed through the critical value. My +observations on the connection between the appearance of the discharge +and the electrode at which the hydrogen appears may be expressed by +the statement that when the discharge is plainly an arc the hydrogen +appears at the positive electrode, and that when the hydrogen appears +at the negative electrode the discharge shows all the characteristics of +a spark. It however looks much more like a spark than an arc long +before the spark length reaches the critical value. + +With regard to the ratio of the quantities of hydrogen liberated from +the steam tube and from the water voltameter, I found that when the +spark length was a few millimetres greater than the critical length the +amount of hydrogen from the steam was the same as that from the voltameter. +The following table contains a few measurements on this +point:--- +\begin{center} +\tabletextsize +\begin{tabular}{c *{2}{>{\qquad}{c}}} +Spark length. & +\settowidth{\TmpLen}{Hydrogen from}% +\parbox[c]{\TmpLen}{\medskip\centering Hydrogen from\\steam in c.c.\medskip} & +\settowidth{\TmpLen}{voltameter in c.c.}% +\parbox[c]{\TmpLen}{\centering Hydrogen from\\voltameter in c.c.} \\ +$10$ mm. & $.7\Z$ & $\Z.8$ \\ +$12$ mm.\rlap{\tabfootmark[-1]} + & $.75$ & $\Z.9$ \\ +$14$ mm. & $.8\Z$ & $1.1$ +\end{tabular} +\footnotetext[\value{footnote}]{In this experiment there was an air break $9$~mm.~long in series with the steam +tube.} +\end{center} + +When the sparks were longer than $14$~mm.\ the amount of hydrogen +from the steam was no longer equal to that from the voltameter. The +results became irregular, and there was a further reversal of the electrode +at which the hydrogen appeared when the spark length exceeded +$22$~mm. In this case, however, the current was so small that it took +several hours to liberate $1$~c.c.\ of hydrogen in the voltameter. With these +very long sparks the proportion between the hydrogen from the steam +and that from the voltameter was too irregular to allow of any conclusions +being drawn. +%% -----File: 580.png---Folio 566------- + +\index{Arc discharge, electrification in@\subdashtwo electrification in}% +\index{Electrification xin arc discharge@\subdashone in arc discharge}% +We see from the preceding results that in the electrolysis of steam, as +in that of water, there is a very close connection between the amounts of +hydrogen and oxygen liberated at the electrodes and the quantity of +electricity which has passed through the steam, and that this relation for +certain lengths of arc is the same for steam as for water. There is, +however, this remarkable difference between the electrolysis of steam and +that of water, that whereas in water the hydrogen always comes off at the +negative, the oxygen at the positive electrode, in steam the hydrogen and +oxygen come off sometimes at one terminal, sometimes at the other, +according to the nature of the spark. + +\includegraphicsmid{fig144}{Fig.~144.} + +The results obtained when the discharge passed as an arc, i.e.~that the +oxygen appears at the negative electrode, the hydrogen at the positive, is +what would happen if the oxygen in the arc had a positive charge, the +hydrogen a negative one. With the view of seeing if I could obtain any +other evidence of this peculiarity I tried the following experiments, the +arrangement of which is represented in \figureref{fig144}{Fig.~144}. + +An arc discharge between the platinum terminals \smallsanscap{A},~\smallsanscap{B} was produced +by a large transformer, which transformed up in the ratio of $400$~to~$1$; +a current of about $40$~Ampères making $80$~alternations per second was +%% -----File: 581.png---Folio 567------- +sent through the primary. A current of the gas under examination +entered the discharge tube through a glass tube~\smallsanscap{C} and blew the gas in +the neighbourhood of the arc against the platinum electrode~\smallsanscap{E}, which was +connected to one quadrant of an electrometer, the other quadrant of +which was connected to earth. To screen~\smallsanscap{E} from external electrical influences +it was enclosed in a platinum tube~\smallsanscap{D}, which was closed in by fine +platinum wire gauze, which though it screened~\smallsanscap{E} from external electrostatic +action, yet allowed the gases in the neighbourhood of the arc to pass +through it. This tube was connected to earth. The electrode~\smallsanscap{E} after +passing out of this tube was attached to one end of gutta-percha covered +wire wound round with tin-foil connected to earth. + +The experiments were of the following kind. The quadrants of the +electrometer were charged up by a battery, the connection with the +battery was then broken and the rate of leak observed. When the arc +was not passing the insulation was practically perfect. As soon, however, +as the arc was started, and for as long as it continued, the insulation of +the gas in many cases completely gave way. There are, however, many +remarkable exceptions to this which we proceed to consider. + + +\Subsection{Oxygen.} + +We shall begin by considering the case when a well-developed arc +passed through the oxygen. + +If the electrode~\smallsanscap{E} was charged negatively, it lost its charge very +rapidly; it did not however remain uncharged, but acquired a positive +charge, this charge increasing until~\smallsanscap{E} acquired a potential~$V$; $V$~depended +greatly upon the size of the arc and the proximity to it of the +electrode~\smallsanscap{E}, in many of my experiments it was as large as $10$~or $12$~volts. + +When \smallsanscap{E}~was charged positively to a high potential the electricity +leaked from it until the potential fell to~$V$; after reaching this potential +the leak stopped and the gas seemed to insulate as well as when no discharge +passed through it. If the potential to which~\smallsanscap{E} was initially raised +was less than~$V$ (a particular case being when it was without charge to +begin with) the positive charge increased until the potential of~\smallsanscap{E} was +equal to~$V$, after which it remained constant. Thus we see (1)~that an +electrode immersed in the oxygen of the arc can insulate a small positive +charge perfectly, while it very rapidly loses a negative one; (2)~that an +uncharged electrode immersed in this gas acquires a positive charge. + +When the distance between the electrodes \smallsanscap{A},~\smallsanscap{B} was increased until the +discharge passed as a spark then the electrode~\smallsanscap{E} leaked slowly, whether +charged positively or negatively. The rate of leak in this case was however +%% -----File: 582.png---Folio 568------- +exceedingly small compared to that which existed when the discharge +passed as an arc. + + +\Subsection{Hydrogen.} + +When similar experiments were tried in hydrogen the results were +quite different. When the \emph{arc} discharge passed through the hydrogen +the electrode~\smallsanscap{E} always leaked when it was positively electrified, and it +did not merely lose its charge but acquired a negative one, its potential +falling to~$-U$, where $U$~is a quantity which depended upon the size of +the arc and on its proximity to the electrode~\smallsanscap{E}. In my experiments $5$~to +$6$~volts was a common value of~$U$. + +When the electrode~\smallsanscap{E} was initially uncharged it acquired a negative +charge, the potential falling to~$-U$; when it was initially charged negatively, +it leaked if its initial negative potential was greater than~$U$ until +its potential fell to this value, when no further leak occurred. When the +initial negative potential of~\smallsanscap{E} was less than~$U$ the negative charge +increased until the potential had fallen to~$-U$. + +It is more difficult to get a good arc in hydrogen than in oxygen, +so that the experiments with the former gas are a little more troublesome +than those with the latter. When short arcs are used the electrode~\smallsanscap{E} +must be placed close to the arc. + +The following experiment was made to see if the charging up of the +electrode was due to an electrification developed by the contact of the gas +in the arc with the electrode, or whether this gas behaved as if it had a +charge of electricity independent of its contact with the metal of the +electrode. If the electrification were due to the contact of the gas with +the electrode it would disappear if the electrode were covered with a non-conducting +layer; if however the gas in the arc behaved as if it were +charged with electricity, then even though the electrode were covered +with a non-conducting layer the electrostatic induction due to the charge +in the gas ought to produce a deflection of the electrometer in the same +direction as if the electrode were uncovered. To test this point the +electrode~\smallsanscap{E} was coated with glass, with mica, with ebonite, and with +sulphur; in all these cases the needle of the electrometer was deflected as +long as the arc was passing, and the deflection corresponded to a positive +charge on the gas when the arc passed through oxygen and to a negative +one when it passed through hydrogen; this deflection disappeared almost +entirely as soon as the arc stopped. + +In another experiment tried with the same object the arc was surrounded +by a large glass tube coated inside and out with a thin layer of +sulphur so as to prevent conduction over the surface. A ring of tin-foil +was placed outside the tube so as to surround the place where the arc +%% -----File: 583.png---Folio 569------- +passed, and this ring was connected with one of the quadrants of an +electrometer. As a further precaution against the creeping of the electricity +over the surface of the tube two thin rings of tin-foil connected to +the earth were placed round the ends of the tube. When the arc passed +through oxygen the quadrants of the electrometer connected with the +ring of tin-foil were positively electrified by induction, when the arc +passed through hydrogen they were negatively charged. + +These experiments show that the oxygen in the arc behaves as if it +had a \emph{positive} charge of electricity, while the hydrogen in the arc +behaves as if it had a \emph{negative} charge. + +In all the above experiments the electrodes were so large that they +were not heated sufficiently by the discharge to become luminous. + +\nblabel{add:2}Elster and Geitel found (\artref{43}{Art.~43}) that a metal plate placed near a red-hot +\index{Elster and Geitel, electrification produced by glowing bodies}% +platinum wire became positively electrified if the wire and the plate +were surrounded by oxygen, and negatively electrified if they were surrounded +by hydrogen. If we suppose that the effect of the hot wire is to +put the gas around it in a condition resembling the gas in the arc, Elster +and Geitel's results would be explained by the preceding experiments, for +these have shown that when this gas is oxygen it is positively electrified, +while when it is hydrogen it is negatively electrified. + +These experiments suggest the following explanation of the results of +the investigation on the electrolysis of steam. We have seen (\artref{212}{Art.~212}) +that when an electric discharge passes through a gas the properties of +the gas in the neighbourhood of the line of discharge are modified, and +(\artref{84}{Art.~84}) that this modified gas possesses very considerable conductivity. +When the discharge stops, this modified gas goes back to its original condition. +If now the discharges through the gas follow one another so +rapidly that the modified gas produced by one discharge has not time to +revert to its original condition before the next discharge passes, the successive +discharges will pass through the modified gas. If, on the other +hand, the gas has time to return to its original condition before the next +discharge passes, each discharge will have to make its way through the +unmodified gas. + +We regard the arc discharge as corresponding to the first of the +preceding cases when the discharge passes through the modified gas, the +spark discharge as corresponding to the second case when the discharge +passes through the gas in its unmodified condition. + +From this point of view the explanation of the results observed in the +electrolysis of steam are very simple. The modified gas produced by the +passage of the discharge through the steam consists of a mixture of +hydrogen and oxygen, these gases being in the same condition as when +the arc discharge passes through hydrogen and oxygen respectively, when, +%% -----File: 584.png---Folio 570------- +as we have seen, the hydrogen behaves as if it had a negative charge, the +oxygen as if it had a positive one. Thus in the case of the \emph{arc} in steam +the oxygen, since it behaves as if it had a positive charge, will move in +the direction of the current and appear at the \emph{negative} electrode; the +hydrogen will move in the opposite direction and appear at the \emph{positive} +electrode. + +The equality which we found to exist between the quantities of hydrogen +and oxygen from the electrolysis of the steam and those liberated from +the electrolysis of water by the same current, shows that the charges on +the atoms of the modified oxygen and hydrogen are the same in amount +but opposite in sign to the charges we ascribe to them in ordinary +electrolytes. + +In the case of the long sparks when the discharge goes through the +steam itself, since the molecule of steam consists of two positively +charged hydrogen atoms and one negatively charged oxygen atom, when +this splits up in the electric field the hydrogen atoms will go towards the +negative, the oxygen atom towards the positive electrode, as in ordinary +electrolysis. The experiments described on page~\pageref{pag:565} show that with these +long sparks the hydrogen appears at the negative, the oxygen at the +positive electrode. +%% -----File: 585.png---Folio 571------- + +%Include the index here +\printindex + +\begin{center} +\vspace{2ex} +THE END. +\end{center} +%% -----File: 586.png---Folio 572------- +%% -----File: 587.png---Folio 573------- +%% -----File: 588.png---Folio 574------- +%% -----File: 589.png---Folio 575------- +%% -----File: 580.png---Folio 576------- +%% -----File: 591.png---Folio 577------- +%% -----File: 592.png---Folio 578------- +%% -----File: 593.png---Folio 579------- + +\pagebreak +\fancyhf{} +\renewcommand{\headrulewidth}{0.5pt} +\thispagestyle{empty} +\fancyhead[C]{\itshape Select Works Published by the Clarendon Press} + +\begin{center} +{\huge Select Works}\\[2ex] +{PUBLISHED BY THE CLARENDON PRESS}\\[2ex] +\rule{1in}{0.5pt} +\end{center} + +\sloppy +\selectedwork{ALDIS}{A Text-Book of Algebra: {\normalfont with} Answers to the Examples} +By \selectedauthor{W.~S. Aldis, M.A\@.} Crown 8vo, \selectedprice{7}{6} + +\selectedwork{BAYNES}{Lessons on Thermodynamics} By \selectedauthor{R.~E. Baynes}, +M.A\@. Crown 8vo, \selectedprice{7}{6} + +\selectedwork{CHAMBERS}{A Handbook of Descriptive Astronomy} By +\selectedauthor{G.~F. Chambers}, F.R.A.S\@. \textit{Fourth Edition.} + +\selectedvol{Vol.~I} The Sun, Planets, and Comets. 8vo, \selectedprice{21}{} + +\selectedvol{Vol.~II} Instruments and Practical Astronomy. 8vo, \selectedprice{21}{} + +\selectedvol{Vol.~III} The Starry Heavens. 8vo, \selectedprice{14}{} + +\selectedwork{CLARKE}{Geodesy} By \selectedauthor[Col.]{A.~R. Clarke}, C.B., R.E\@. \selectedprice{12}{6} + +\selectedwork{CREMONA}{Elements of Projective Geometry} By \selectedauthor{Luigi +Cremona}. Translated by \selectedauthor{C.~Leudesdorf}, M.A\@. Demy 8vo, \selectedprice{12}{6} + +\selectedwork{}{Graphical Statics} Two Treatises on the Graphical +Calculus and Reciprocal Figures in Graphical Statics. By \selectedauthor{Luigi +Cremona}. 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