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| author | Roger Frank <rfrank@pglaf.org> | 2025-10-15 01:19:54 -0700 |
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| committer | Roger Frank <rfrank@pglaf.org> | 2025-10-15 01:19:54 -0700 |
| commit | 355e0032620ad931e7edba139564f1d51858f79a (patch) | |
| tree | df9ce171ce677112284d7cfd1253345980c25733 /20214-h | |
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diff --git a/20214-h/20214-h.htm b/20214-h/20214-h.htm new file mode 100644 index 0000000..30e90e2 --- /dev/null +++ b/20214-h/20214-h.htm @@ -0,0 +1,1367 @@ +<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> +<html> +<head> + <meta content="text/html; charset=utf-8" + http-equiv="content-type"> + <title>Instructions for using a Slide Rule</title> +</head> +<body> + +<div style='text-align:center; font-size:1.2em; font-weight:bold'>The Project Gutenberg eBook of Instruction for Using a Slide Rule, by W. Stanley</div> +<div style='display:block; margin:1em 0'> +This eBook is for the use of anyone anywhere in the United States and +most other parts of the world at no cost and with almost no restrictions +whatsoever. You may copy it, give it away or re-use it under the terms +of the Project Gutenberg License included with this eBook or online +at <a href="https://www.gutenberg.org">www.gutenberg.org</a>. If you +are not located in the United States, you will have to check the laws of the +country where you are located before using this eBook. +</div> +<div style='display:block; margin-top:1em; margin-bottom:1em; margin-left:2em; text-indent:-2em'>Title: Instruction for Using a Slide Rule</div> +<div style='display:block; margin-top:1em; margin-bottom:1em; margin-left:2em; text-indent:-2em'>Author: W. Stanley</div> +<div style='display:block; margin:1em 0'>Release Date: December 29, 2006 [eBook #20214]<br /> +[Most recently updated: June 1, 2021]</div> +<div style='display:block; margin:1em 0'>Language: English</div> +<div style='display:block; margin:1em 0'>Character set encoding: UTF-8</div> +<div style='display:block; margin-left:2em; text-indent:-2em'>Produced by: Don Kostuch</div> +<div style='margin-top:2em; margin-bottom:4em'>*** START OF THE PROJECT GUTENBERG EBOOK INSTRUCTION FOR USING A SLIDE RULE ***</div> + + +<big>[Transcriber's Notes]<br> +<br> +Conventional mathematical notation requires specialized fonts and<br> +typesetting conventions. I have adopted modern computer programming<br> +notation using only ASCII characters. The square root of 9 is thus<br> +rendered as square_root(9) and the square of 9 is square(9).<br> +10 divided by 5 is (10/5) and 10 multiplied by 5 is (10 * 5 ).<br> +<br> +By the time I finished engineering school in 1963, the slide rule was a<br> +well worn tool of my trade. I did not use an electronic calculator for<br> +another ten years. Consider that my predecessors had little else to<br> +use--think Boulder Dam (with all its electrical, mechanical and<br> +construction calculations).<br> +<br> +Rather than dealing with elaborate rules for positioning the decimal <br> +point, I was taught to first "scale" the factors and deal with the <br> +decimal position separately. For example:<br> +<br> +1230 * .000093 =<br> +1.23E3 * 9.3E-5 <br> +1.23E3 means multiply 1.23 by 10 to the power 3.<br> +9.3E-5 means multiply 9.3 by 0.1 to the power 5 or 10 to the power -5.<br> +The computation is thus<br> +1.23 * 9.3 * 1E3 * 1E-5<br> +The exponents are simply added.<br> +1.23 * 9.3 * 1E-2 =<br> +11.4 * 1E-2 =<br> +.114<br> +<br> +When taking roots, divide the exponent by the root. <br> +The square root of 1E6 is 1E3<br> +The cube root of 1E12 is 1E4.<br> +<br> +When taking powers, multiply the exponent by the power.<br> +The cube of 1E5 is 1E15.<br> +<br> +[End Transcriber's Notes]<br> +<br> +<br> +INSTRUCTIONS<br> +for using a<br> +SLIDE<br> +RULE<br> +SAVE TIME!<br> +DO THE FOLLOWING INSTANTLY WITHOUT PAPER AND PENCIL<br> +MULTIPLICATION<br> +DIVISION<br> +RECIPROCAL VALUES<br> +SQUARES & CUBES<br> +EXTRACTION OF SQUARE ROOT<br> +EXTRACTION OF CUBE ROOT<br> +DIAMETER OR AREA OF CIRCLE<br> +<br> +<img style="width: 701px; height: 420px;" alt="" src="images/01Pic.jpg"><br> +<br> +<br> +<br> +INSTRUCTIONS FOR USING A SLIDE RULE<br> +<br> +The slide rule is a device for easily and quickly multiplying, dividing<br> +and extracting square root and cube root. It will also perform any<br> +combination of these processes. On this account, it is found extremely<br> +useful by students and teachers in schools and colleges, by engineers,<br> +architects, draftsmen, surveyors, chemists, and many others. Accountants<br> +and clerks find it very helpful when approximate calculations must be<br> +made rapidly. The operation of a slide rule is extremely easy, and it is<br> +well worth while for anyone who is called upon to do much numerical<br> +calculation to learn to use one. It is the purpose of this manual to<br> +explain the operation in such a way that a person who has never before<br> +used a slide rule may teach himself to do so.<br> +<br> +</big><big> +DESCRIPTION OF SLIDE RULE<br> +<br> +</big><big><img style="width: 894px; height: 199px;" alt="" + src="images/rule.jpg"><br> +<br> +The slide rule consists of three parts (see figure 1). B is the body of<br> +the rule and carries three scales marked A, D and K. S is the slider<br> +which moves relative to the body and also carries three scales marked B,<br> +CI and C. R is the runner or indicator and is marked in the center with<br> +a hair-line. The scales A and B are identical and are used in problems<br> +involving square root. Scales C and D are also identical and are used<br> +for multiplication and division. Scale K is for finding cube root. Scale<br> +CI, or C-inverse, is like scale C except that it is laid off from right<br> +to left instead of from left to right. It is useful in problems<br> +involving reciprocals.<br> +<br> +<br> +MULTIPLICATION<br> +<br> +We will start with a very simple example:<br> +<br> +Example 1: 2 * 3 = 6<br> +<br> +<img style="width: 1166px; height: 388px;" alt="" + src="images/example01.jpg"><br> +<br> +To prove this on the slide rule, move the slider so that the 1 at the<br> +left-hand end of the C scale is directly over the large 2 on the D scale<br> +(see figure 1). Then move the runner till the hair-line is over 3 on the<br> +C scale. Read the answer, 6, on the D scale under the hair-line. Now,<br> +let us consider a more complicated example:<br> +<br> +Example 2: 2.12 * 3.16 = 6.70<br> +<br> +<img style="width: 1148px; height: 394px;" alt="" + src="images/example02.jpg"><br> +<br> +As before, set the 1 at the left-hand end of the C scale, which we will<br> +call the left-hand index of the C scale, over 2.12 on the D scale (See<br> +figure 2). The hair-line of the runner is now placed over 3.16 on the C<br> +scale and the answer, 6.70, read on the D scale.<br> +<br> +<br> +METHOD OF MAKING SETTINGS<br> +<br> +<img style="width: 380px; height: 362px;" alt="" + src="images/example02B.jpg"><br> +[This 6 inch rule uses fewer minor divisions.]<br> +<br> +In order to understand just why 2.12 is set where it is (figure 2),<br> +notice that the interval from 2 to 3 is divided into 10 large or major<br> +divisions, each of which is, of course, equal to one-tenth (0.1) of the<br> +amount represented by the whole interval. The major divisions are in<br> +turn divided into 5 small or minor divisions, each of which is one-fifth<br> +or two-tenths (0.2) of the major division, that is 0.02 of the<br> +whole interval. Therefore, the index is set above<br> +<br> + 2 + 1 major division + 1 minor division = 2 + 0.1 + 0.02 = 2.12.<br> +<br> +<img style="width: 568px; height: 368px;" alt="" + src="images/example02C.jpg"><br> +<br> +In the same way we find 3.16 on the C scale. While we are on this<br> +subject, notice that in the interval from 1 to 2 the major divisions are<br> +marked with the small figures 1 to 9 and the minor divisions are 0.1 of<br> +the major divisions. In the intervals from 2 to 3 and 3 to 4 the minor<br> +divisions are 0.2 of the major divisions, and for the rest of the D (or<br> +C) scale, the minor divisions are 0.5 of the major divisions.<br> +<br> +Reading the setting from a slide rule is very much like reading<br> +measurements from a ruler. Imagine that the divisions between 2 and 3 on<br> +the D scale (figure 2) are those of a ruler divided into tenths of a<br> +foot, and each tenth of a foot divided in 5 parts 0.02 of a foot long.<br> +Then the distance from one on the left-hand end of the D scale (not<br> +shown in figure 2) to one on the left-hand end of the C scale would he<br> +2.12 feet. Of course, a foot rule is divided into parts of uniform<br> +length, while those on a slide rule get smaller toward the right-hand<br> +end, but this example may help to give an idea of the method of making<br> +and reading settings. Now consider another example.<br> +<br> +Example 3a: 2.12 * 7.35 = 15.6<br> +<br> +<img style="width: 970px; height: 408px;" alt="" + src="images/example03A.jpg"><br> +<br> +If we set the left-hand index of the C scale over 2.12 as in the last<br> +example, we find that 7.35 on the C scale falls out beyond the body of<br> +the rule. In a case like this, simply use the right-hand index of the C<br> +scale. If we set this over 2.12 on the D scale and move the runner to<br> +7.35 on the C scale we read the result 15.6 on the D scale under the<br> +hair-line.<br> +<br> +Now, the question immediately arises, why did we call the result 15.6<br> +and not 1.56? The answer is that the slide rule takes no account of<br> +decimal points. Thus, the settings would be identical for all of the<br> +following products:<br> +<br> +Example 3:<br> +<code style="font-weight: bold;">a: 2.12 * + 7.35 = 15.6<br> +b: 21.2 * 7.35 += 156.0<br> +c: 212 * 73.5 = +15600.<br> +d: 2.12 * .0735 += .156<br> +e: .00212 * 735 += .0156</code><br> +<br> +The most convenient way to locate the decimal point is to make a mental<br> +multiplication using only the first digits in the given factors. Then<br> +place the decimal point in the slide rule result so that its value is<br> +nearest that of the mental multiplication. Thus, in example 3a above, we<br> +can multiply 2 by 7 in our heads and see immediately that the decimal<br> +point must be placed in the slide rule result 156 so that it becomes<br> +15.6 which is nearest to 14. In example 3b (20 * 7 = 140), so we must<br> +place the decimal point to give 156. The reader can readily verify the<br> +other examples in the same way.<br> +<br> +<img style="width: 1076px; height: 392px;" alt="" + src="images/example02D.jpg"><br> +<br> +Since the product of a number by a second number is the same as the<br> +product of the second by the first, it makes no difference which of the<br> +two numbers is set first on the slide rule. Thus, an alternative way of<br> +working example 2 would be to set the left-hand index of the C scale<br> +over 3.16 on the D scale and move the runner to 2.12 on the C scale and<br> +read the answer under the hair-line on the D scale.<br> +<br> +The A and B scales are made up of two identical halves each of which is<br> +very similar to the C and D scales. Multiplication can also be carried<br> +out on either half of the A and B scales exactly as it is done on the C<br> +and D scales. However, since the A and B scales are only half as long as<br> +the C and D scales, the accuracy is not as good. It is sometimes<br> +convenient to multiply on the A and B scales in more complicated<br> +problems as we shall see later on.<br> +<br> +A group of examples follow which cover all the possible combination of<br> +settings which can arise in the multiplication of two numbers.<br> +<br> +Example<br> +<br> +4: 20 * 3 = 60<br> +<img style="width: 1038px; height: 390px;" alt="" + src="images/example04.jpg"><br> +<br> +5: 85 * 2 = 170<br> +<img style="width: 806px; height: 404px;" alt="" + src="images/example05.jpg"><br> +<br> +6: 45 * 35 = 1575<br> +<img style="width: 1002px; height: 400px;" alt="" + src="images/example06.jpg"><br> +<br> +7: 151 * 42 = 6342<br> +<img style="width: 1166px; height: 388px;" alt="" + src="images/example07.jpg"><br> +<br> +8: 6.5 * 15 = 97.5<br> +<img style="width: 1085px; height: 288px;" alt="" + src="images/example08.jpg"><br> +<br> +9: .34 * .08 = .0272<br> +<img style="width: 1092px; height: 398px;" alt="" + src="images/example09.jpg"><br> +<br> +10: 75 * 26 = 1950<br> +<img style="width: 1082px; height: 384px;" alt="" + src="images/example10.jpg"><br> +<br> +11: .00054 * 1.4 = .000756<br> +<img style="width: 1067px; height: 296px;" alt="" + src="images/example11.jpg"><br> +<br> +12: 11.1 * 2.7 = 29.97<br> +<img style="width: 1002px; height: 380px;" alt="" + src="images/example12.jpg"><br> +<br> +13: 1.01 * 54 = 54.5<br> +<img style="width: 1051px; height: 312px;" alt="" + src="images/example13.jpg"><br> +<br> +14: 3.14 * 25 = 78.5<br> +<img style="width: 932px; height: 386px;" alt="" + src="images/example14.jpg"><br> +<br> +<br> +DIVISION<br> +<br> +Since multiplication and division are inverse processes, division on a<br> +slide rule is done by making the same settings as for multiplication,<br> +but in reverse order. Suppose we have the example:<br> +<br> +Example 15: (6.70 / 2.12) = 3.16<br> +<img style="width: 946px; height: 394px;" alt="" + src="images/example15.jpg"><br> +<br> +Set indicator over the dividend 6.70 on the D scale. Move the slider<br> +until the divisor 2.12 on the C scale is under the hair-line. Then read<br> +the result on the D scale under the left-hand index of the C scale. As<br> +in multiplication, the decimal point must be placed by a separate<br> +process. Make all the digits except the first in both dividend and<br> +divisor equal zero and mentally divide the resulting numbers. Place the<br> +decimal point in the slide rule result so that it is nearest to the<br> +mental result. In example 15, we mentally divide 6 by 2. Then we place<br> +the decimal point in the slide rule result 316 so that it is 3.16 which<br> +is nearest to 3.<br> +<br> +A group of examples for practice in division follow:<br> +<br> +Example<br> +16: 34 / 2 = 17<br> +<img style="width: 778px; height: 396px;" alt="" + src="images/example16.jpg"><br> +<br> +17: 49 / 7 = 7<br> +<img style="width: 638px; height: 388px;" alt="" + src="images/example17.jpg"><br> +<br> +18: 132 / 12 = 11<br> +<img style="width: 496px; height: 376px;" alt="" + src="images/example18.jpg"><br> +<br> +19: 480 / 16 = 30<br> +<img style="width: 636px; height: 390px;" alt="" + src="images/example19.jpg"><br> +<br> +20: 1.05 / 35 = .03<br> +<img style="width: 922px; height: 384px;" alt="" + src="images/example20.jpg"><br> +<br> +21: 4.32 / 12 = .36<br> +<img style="width: 648px; height: 388px;" alt="" + src="images/example21.jpg"><br> +<br> +22: 5.23 / 6.15 = .85<br> +<img style="width: 744px; height: 396px;" alt="" + src="images/example22.jpg"><br> +<br> +23: 17.1 / 4.5 = 3.8<br> +<img style="width: 730px; height: 390px;" alt="" + src="images/example23.jpg"><br> +<br> +24: 1895 / 6.06 = 313<br> +<img style="width: 598px; height: 382px;" alt="" + src="images/example24.jpg"><br> +<br> +25: 45 /.017 = 2647<br> +<img style="width: 710px; height: 396px;" alt="" + src="images/example25.jpg"><br> +<br> +<br> +THE CI SCALE<br> +<br> +If we divide one (1) by any number the answer is called the reciprocal<br> +of the number. Thus, one-half is the reciprocal of two, one-quarter is<br> +the reciprocal of four. If we take any number, say 14, and multiply it<br> +by the reciprocal of another number, say 2, we get:<br> +<br> +Example 26: 14 * (1/2) = 7<br> +<img style="width: 1013px; height: 323px;" alt="" + src="images/example26.jpg"><br> +<br> +which is the same as 14 divided by two. This process can be carried out<br> +directly on the slide rule by use of the CI scale. Numbers on the CI<br> +scale are reciprocals of those on the C scale. Thus we see that 2 on the<br> +CI scale comes directly over 0.5 or 1/2 on the C scale. Similarly 4 on<br> +the CI scale comes over 0.25 or 1/4 on the C scale, and so on. To do<br> +example 26 by use of the CI scale, proceed exactly as if you were going<br> +to multiply in the usual manner except that you use the CI scale instead<br> +of the C scale. First set the left-hand index of the C scale over 14 on<br> +the D scale. Then move the indicator to 2 on the CI scale. Read the<br> +result, 7, on the D scale under the hair-line. This is really another<br> +way of dividing. THE READER IS ADVISED TO WORK EXAMPLES 16 TO 25 OVER<br> +AGAIN BY USE OF THE CI SCALE.<br> +<br> +<br> +SQUARING AND SQUARE ROOT<br> +<br> +If we take a number and multiply it by itself we call the result the<br> +square of the number. The process is called squaring the number. If we<br> +find the number which, when multiplied by itself is equal to a given<br> +number, the former number is called the square root of the given number.<br> +The process is called extracting the square root of the number. Both<br> +these processes may be carried out on the A and D scales of a slide<br> +rule. For example:<br> +<br> +Example 27: 4 * 4 = square( 4 ) = 16<br> +<img style="width: 1160px; height: 374px;" alt="" + src="images/example27.jpg"><br> +<br> +Set indicator over 4 on D scale. Read 16 on A scale under hair-line.<br> +<br> +Example 28: square( 25.4 ) = 646.0<br> +<img style="width: 398px; height: 394px;" alt="" + src="images/example28.jpg"><br> +<br> +The decimal point must be placed by mental survey. We know that <br> +square( 25.4 ) must be a little larger than square( 25 ) = 625 so that <br> +it +must be 646.0.<br> +<br> +To extract a square root, we set the indicator over the number on the A<br> +scale and read the result under the hair-line on the D scale. When we<br> +examine the A scale we see that there are two places where any given<br> +number may be set, so we must have some way of deciding in a given case<br> +which half of the A scale to use. The rule is as follows:<br> +<br> +(a) If the number is greater than one. For an odd number of digits to<br> +the left of the decimal point, use the left-hand half of the A scale.<br> +For an even number of digits to the left of the decimal point, use the<br> +right-hand half of the A scale.<br> +<br> +(b) If the number is less than one. For an odd number of zeros to the<br> +right of the decimal point before the first digit not a zero, use the<br> +left-hand half of the A scale. For none or any even number of zeros to<br> +the right of the decimal point before the first digit not a zero, use<br> +the right-hand half of the A scale.<br> +<br> +Example 29: square_root( 157 ) = 12.5<br> +<img style="width: 496px; height: 378px;" alt="" + src="images/example29.jpg"><br> +<br> +Since we have an odd number of digits set indicator over 157 on<br> +left-hand half of A scale. Read 12.5 on the D scale under hair-line. To<br> +check the decimal point think of the perfect square nearest to 157. It<br> +is 12 * 12 = 144, so that square_root(157) must be a little more than +12 or<br> +12.5.<br> +<br> +Example 30: square_root( .0037 ) = .0608<br> +<img style="width: 904px; height: 398px;" alt="" + src="images/example30.jpg"><br> +<br> +In this number we have an even number of zeros to the right of the<br> +decimal point, so we must set the indicator over 37 on the right-hand<br> +half of the A scale. Read 608 under the hair-line on D scale. To place<br> +the decimal point write:<br> +<br> +square_root( .0037 ) = square_root( 37/10000 )<br> + += 1/100 square_root( 37 )<br> +<br> +The nearest perfect square to 37 is 6 * 6 = 36, so the answer should be<br> +a little more than 0.06 or .0608. All of what has been said about use of<br> +the A and D scales for squaring and extracting square root applies<br> +equally well to the B and C scales since they are identical to the A and<br> +D scales respectively.<br> +<br> +A number of examples follow for squaring and the extraction of square<br> +root.<br> +<br> +Example<br> +31: square( 2 ) = 4<br> +<img style="width: 688px; height: 380px;" alt="" + src="images/example31.jpg"><br> +<br> +32: square( 15 ) = 225<br> +<img style="width: 588px; height: 384px;" alt="" + src="images/example32.jpg"><br> +<br> +33: square( 26 ) = 676<br> +<img style="width: 844px; height: 374px;" alt="" + src="images/example33.jpg"><br> +<br> +34: square( 19.65 ) = 386<br> +<img style="width: 742px; height: 380px;" alt="" + src="images/example34.jpg"><br> +<br> +35: square_root( 64 ) = 8<br> +<img style="width: 552px; height: 366px;" alt="" + src="images/example35.jpg"><br> +<br> +36: square_root( 6.4 ) = 2.53<br> +<img style="width: 824px; height: 386px;" alt="" + src="images/example36.jpg"><br> +<br> +37: square_root( 498 ) = 22.5<br> +<img style="width: 746px; height: 388px;" alt="" + src="images/example37.jpg"><br> +<br> +38: square_root( 2500 ) = 50<br> +<img style="width: 698px; height: 380px;" alt="" + src="images/example38.jpg"><br> +<br> +39: square_root( .16 ) = .04<br> +<img style="width: 834px; height: 392px;" alt="" + src="images/example39.jpg"><br> +<br> +40: square_root( .03 ) = .173<br> +<img style="width: 658px; height: 398px;" alt="" + src="images/example40.jpg"><br> +<br> +<br> +CUBING AND CUBE ROOT<br> +<br> +If we take a number and multiply it by itself, and then multiply the<br> +result by the original number we get what is called the cube of the<br> +original number. This process is called cubing the number. The reverse<br> +process of finding the number which, when multiplied by itself and then<br> +by itself again, is equal to the given number, is called extracting the<br> +cube root of the given number. Thus, since 5 * 5 * 5 = 125, 125 is the<br> +cube of 5 and 5 is the cube root of 125.<br> +<br> +To find the cube of any number on the slide rule set the indicator over<br> +the number on the D scale and read the answer on the K scale under the<br> +hair-line. To find the cube root of any number set the indicator over<br> +the number on the K scale and read the answer on the D scale under the<br> +hair-line. Just as on the A scale, where there were two places where you<br> +could set a given number, on the K scale there are three places where a<br> +number may be set. To tell which of the three to use, we must make use<br> +of the following rule.<br> +<br> +(a) If the number is greater than one. For 1, 4, 7, 10, etc., digits to<br> +the left of the decimal point, use the left-hand third of the K scale.<br> +For 2, 5, 8, 11, etc., digits to the left of the decimal point, use the<br> +middle third of the K scale. For 3, 6, 9, 12, etc., digits to the left<br> +of the decimal point use the right-hand third of the K scale.<br> +<br> +(b) If the number is less than one. We now tell which scale to use by<br> +counting the number of zeros to the right of the decimal point before<br> +the first digit not zero. If there are 2, 5, 8, 11, etc., zeros, use the<br> +left-hand third of the K scale. If there are 1, 4, 7, 10, etc., zeros,<br> +then use the middle third of the K scale. If there are no zeros or 3, 6,<br> +9, 12, etc., zeros, then use the right-hand third of the K scale. For<br> +example:<br> +<br> +Example 41: cube_root( 185 ) = 5.70<br> +<img style="width: 602px; height: 384px;" alt="" + src="images/example41.jpg"><br> +<br> +Since there are 3 digits in the given number, we set the indicator on<br> +185 in the right-hand third of the K scale, and read the result 570 on<br> +the D scale. We can place the decimal point by thinking of the nearest<br> +perfect cube, which is 125. Therefore, the decimal point must be placed<br> +so as to give 5.70, which is nearest to 5, the cube root of 125.<br> +<br> +Example 42: cube_root( .034 ) = .324<br> +<img style="width: 978px; height: 384px;" alt="" + src="images/example42.jpg"><br> +<br> +Since there is one zero between the decimal point and the first digit<br> +not zero, we must set the indicator over 34 on the middle third of the K<br> +scale. We read the result 324 on the D scale. The decimal point may be<br> +placed as follows:<br> +<br> +cube_root( .034 ) = cube_root( 34/1000 )<br> + += 1/10 cube_root( 34 )<br> +<br> +The nearest perfect cube to 34 is 27, so our answer must be close to<br> +one-tenth of the cube root of 27 or nearly 0.3. Therefore, we must place<br> +the decimal point to give 0.324. A group of examples for practice in<br> +extraction of cube root follows:<br> +<br> +Example<br> +43: cube_root( 64 ) = 4<br> +<img style="width: 842px; height: 396px;" alt="" + src="images/example43.jpg"><br> +<br> +44: cube_root( 8 ) = 2<br> +<img style="width: 672px; height: 384px;" alt="" + src="images/example44.jpg"><br> +<br> +45: cube_root( 343 ) = 7<br> +<img style="width: 582px; height: 382px;" alt="" + src="images/example45.jpg"><br> +<br> +46: cube_root( .000715 ) = .0894<br> +<img style="width: 504px; height: 380px;" alt="" + src="images/example46.jpg"><br> +<br> +47: cube_root( .00715 ) = .193<br> +<img style="width: 664px; height: 400px;" alt="" + src="images/example47.jpg"><br> +<br> +48: cube_root( .0715 ) = .415<br> +<img style="width: 752px; height: 388px;" alt="" + src="images/example48.jpg"><br> +<br> +49: cube_root( .516 ) = .803<br> +<img style="width: 500px; height: 384px;" alt="" + src="images/example49.jpg"><br> +<br> +50: cube_root( 27.8 ) = 3.03<br> +<img style="width: 944px; height: 390px;" alt="" + src="images/example50.jpg"><br> +<br> +51: cube_root( 5.49 ) = 1.76<br> +<img style="width: 596px; height: 374px;" alt="" + src="images/example51.jpg"><br> +<br> +52: cube_root( 87.1 ) = 4.43<br> +<img style="width: 766px; height: 376px;" alt="" + src="images/example52.jpg"><br> +<br> +<br> +THE 1.5 AND 2/3 POWER<br> +<br> +If the indicator is set over a given number on the A scale, the number<br> +under the hair-line on the K scale is the 1.5 power of the given<br> +number. If the indicator is set over a given number on the K scale, the<br> +number under the hair-line on the A scale is the 2/3 power of the given<br> +number.<br> +<br> +4 to the 3/2 power is 8<br> +8 to the 2/3 power is 4.<br> +<img style="width: 694px; height: 380px;" alt="" + src="images/example52B.jpg"><br> +<br> +<br> +COMBINATIONS OF PROCESSES<br> +<br> +A slide rule is especially useful where some combination of processes is<br> +necessary, like multiplying 3 numbers together and dividing by a third.<br> +Operations of this sort may be performed in such a way that the final<br> +answer is obtained immediately without finding intermediate results.<br> +<br> +1. Multiplying several numbers together. For example, suppose it is<br> +desired to multiply 4 * 8 * 6. Place the right-hand index of the C scale<br> +over 4 on the D scale and set the indicator over 8 on the C scale. Now,<br> +leaving the indicator where it is, move the slider till the right-hand<br> +index is under the hairline. Now, leaving the slider where it is, move<br> +the indicator until it is over 6 on the C scale, and read the result,<br> +192, on the D scale. This may be continued indefinitely, and so as many<br> +numbers as desired may be multiplied together.<br> +<br> +Example 53: 2.32 * 154 * .0375 * .56 = 7.54<br> +<img style="width: 934px; height: 162px;" alt="" + src="images/example53A.jpg"><br> +<img style="width: 968px; height: 158px;" alt="" + src="images/example53B.jpg"><br> +<img style="width: 786px; height: 163px;" alt="" + src="images/example53C.jpg"><br> +<br> +2. Multiplication and division.<br> +Suppose we wish to do the following example:<br> +<br> +Example 54: (4 * 15) / 2.5 = 24<br> +<br> +First divide 4 by 2.5. Set indicator over 4 on the D scale and move the<br> +slider until 2.5 is under the hair-line. The result of this division,<br> +1.6, appears under the left-hand index of the C scale. We do not need to<br> +write it down, however, but we can immediately move the indicator to 15<br> +on the C scale and read the final result 24 on the D scale under the<br> +hair-line. Let us consider a more complicated problem of the same type:<br> +<br> +Example 55: (30/7.5) * (2/4) * (4.5/5) * (1.5/3) = .9<br> +<br> +First set indicator over 30 on the D scale and move slider until 7.5 on<br> +the C scale comes under the hairline. The intermediate result, 4,<br> +appears under the right-hand index of the C scale. We do not need to<br> +write it down but merely note it by moving the indicator until the<br> +hair-line is over the right-hand index of the C scale. Now we want to<br> +multiply this result by 2, the next factor in the numerator. Since two<br> +is out beyond the body of the rule, transfer the slider till the other<br> +(left-hand) index of the C scale is under the hair-line, and then move<br> +the indicator to 2 on the C scale. Thus, successive division and<br> +multiplication is continued until all the factors have been used. The<br> +order in which the factors are taken does not affect the result. With a<br> +little practice you will learn to take them in the order which will<br> +require the fewest settings. The following examples are for practice:<br> +<br> +Example 56: (6/3.5) * (4/5) * (3.5/2.4) * (2.8/7) = .8<br> +<br> +Example 57: 352 * (273/254) * (760/768) = 374<br> +<br> +An alternative method of doing these examples is to proceed exactly as<br> +though you were multiplying all the factors together, except that<br> +whenever you come to a number in the denominator you use the CI scale<br> +instead of the C scale. The reader is advised to practice both methods<br> +and use whichever one he likes best.<br> +<br> +3. The area of a circle. The area of a circle is found by multiplying<br> +3.1416=PI by the square of the radius or by one-quarter the square of<br> +the diameter<br> +<br> +Formula: <br> +A = PI * square( R )<br> +A = PI * +(square( D ) / 4 )<br> +<br> +Example 58: The radius of a circle is 0.25 inches; find its area.<br> +<br> +Area = PI * square(0.25) = 0.196 square inches.<br> +<br> +Set left-hand index of C scale over 0.25 on D scale. square(0.25) now<br> +appears above the left-hand index of the B scale. This can be multiplied<br> +by PI by moving the indicator to PI on the B scale and reading the<br> +answer .196 on the A scale. This is an example where it is convenient to<br> +multiply with the A and B scales.<br> +<br> +Example 59: The diameter of a circle is 8.1 feet. What is its area?<br> +<br> +Area = (PI / 4) * square(8.1)<br> + = .7854 * square(8.1)<br> + = 51.7 sq. inches.<br> +<br> +Set right-hand index of the C scale over 8.1 on the D scale. Move the<br> +indicator till hair-line is over .7854 (the special long mark near 8) at<br> +the right hand of the B scale. Read the answer under the hair-line on<br> +the A scale. Another way of finding the area of a circle is to set 7854<br> +on the B scale to one of the indices of the A scale, and read the area<br> +from the B scale directly above the given diameter on the D scale.<br> +<br> +4. The circumference of a circle. Set the index of the B scale to the<br> +diameter and read the answer on the A scale opposite PI on the B scale<br> +<br> +Formula: C = PI * D<br> + C = 2 * PI * R<br> +<br> +Example 60: The diameter of a circle is 1.54 inches, what is its<br> +circumference?<br> +<br> +Set the left-hand index of the B scale to 1.54 on the A scale. Read the<br> +circumference 4.85 inches above PI on the B scale.<br> +<br> +EXAMPLES FOR PRACTICE<br> +<br> +61: What is the area of a circle 32-1/2 inches in diameter?<br> +Answer 830 sq. inches<br> +<br> +62: What is the area of a circle 24 inches in diameter?<br> +Answer 452 sq. inches<br> +<br> +63: What is the circumference of a circle whose diameter is 95 feet?<br> +Answer 298 ft.<br> +<br> +64: What is the circumference of a circle whose diameter is 3.65 inches?<br> +Answer 11.5 inches<br> +<br> +5. Ratio and Proportion.<br> +<br> +Example 65: 3 : 7 : : 4 : X<br> +or<br> +(3/7) = (4/x)<br> +Find X<br> +<br> +Set 3 on C scale over 7 on D scale. Read X on D scale under 4 on C<br> +scale. In fact, any number on the C scale is to the number directly<br> +under it on the D scale as 3 is to 7.<br> +<br> +<br> +PRACTICAL PROBLEMS SOLVED BY SLIDE RULE<br> +<br> +<br> +1. Discount.<br> +A firm buys a typewriter with a list price of $150, subject to a<br> +discount of 20% and 10%. How much does it pay?<br> +<br> +A discount of 20% means 0.8 of the list price, and 10% more means<br> +0.8 X 0.9 X 150 = 108.<br> +<br> +To do this on the slide rule, put the index of the C scale opposite 8 on<br> +the D scale and move the indicator to 9 on the C scale. Then move the<br> +slider till the right-hand index of the C scale is under the hairline.<br> +Now, move the indicator to 150 on the C scale and read the answer $108<br> +on the D scale. Notice that in this, as in many practical problems,<br> +there is no question about where the decimal point should go.<br> +<br> +<br> +2. Sales Tax.<br> +<br> +A man buys an article worth $12 and he must pay a sales tax of 1.5%. How<br> +much does he pay? A tax of 1.5% means he must pay 1.015 * 12.00.<br> +<br> +Set index of C scale at 1.015 on D scale. Move indicator to 12 on C<br> +scale and read the answer $12.18 on the D scale.<br> +<br> +A longer but more accurate way is to multiply 12 * .015 and add the<br> +result to $12.<br> +<br> +<br> +3. Unit Price.<br> +<br> +A motorist buys 17 gallons of gas at 19.5 cents per gallon. How much<br> +does he pay?<br> +<br> +Set index of C scale at 17 on D scale and move indicator to 19.5 on C<br> +scale and read the answer $3.32 on the D scale.<br> +<br> +<br> +4. Gasoline Mileage.<br> +<br> +An automobile goes 175 miles on 12 gallons of gas. What is the average<br> +gasoline consumption?<br> +<br> +Set indicator over 175 on D scale and move slider till 12 is under<br> +hair-line. Read the answer 14.6 miles per gallon on the D scale under<br> +the left-hand index of the C scale.<br> +<br> +<br> +5. Average Speed.<br> +<br> +A motorist makes a trip of 256 miles in 7.5 hours. What is his average<br> +speed?<br> +<br> +Set indicator over 256 on D scale. Move slider till 7.5 on the C scale<br> +is under the hair-line. Read the answer 34.2 miles per hour under the<br> +right-hand index of the C scale.<br> +<br> +<br> +6. Decimal Parts of an Inch.<br> +<br> +What is 5/16 of an inch expressed as decimal fraction?<br> +<br> +Set 16 on C scale over 5 on D scale and read the result .3125 inches on<br> +the D scale under the left-hand index of the C scale.<br> +<br> +<br> +7. Physics.<br> +<br> +A certain quantity of gas occupies 1200 cubic centimeters at a<br> +temperature of 15 degrees C and 740 millimeters pressure. What volume<br> +does it occupy at 0 degrees C and 760 millimeters pressure?<br> +<br> +Volume = 1200 X (740/760) * (273/288) = 1100 cubic cm.<br> +<br> +Set 760 on C scale over 12 on D scale. Move indicator to 740 on C scale.<br> +Move slider till 288 on C scale is under hair-line. Move indicator to<br> +273 on C scale. Read answer, 1110, under hair-line on D scale.<br> +<br> +<br> +8. Chemistry.<br> +<br> +How many grams of hydrogen are formed when 80 grams of zinc react with<br> +sufficient hydrochloric acid to dissolve the metal?<br> +<br> +(80 / X ) = ( 65.4 / 2.01)<br> +<br> +Set 65.4 on C scale over 2.01 on D scale.<br> +Read X = 2.46 grams under 80 on C scale.<br> +<br> +<br> +In conclusion, we want to impress upon those to whom the slide rule is a<br> +new method of doing their mathematical calculations, and also the<br> +experienced operator of a slide rule, that if they will form a habit of,<br> +and apply themselves to, using a slide rule at work, study, or during<br> +recreations, they will be well rewarded in the saving of time and<br> +energy. ALWAYS HAVE YOUR SLIDE RULE AND INSTRUCTION <br> +BOOK WITH YOU, the same as you would a fountain pen or pencil.<br> +<br> +The present day wonders of the twentieth century prove that there is no<br> +end to what an individual can accomplish--the same applies to the slide<br> +rule.<br> +<br> +You will find after practice that you will be able to do many<br> +specialized problems that are not outlined in this instruction book. It<br> +depends entirely upon your ability to do what we advocate and to be<br> +slide-rule conscious in all your mathematical problems.<br> +<br> +<br> +CONVERSION FACTORS<br> +<br> +1. Length<br> +<br> +1 mile = 5280 feet =1760 yards<br> +<br> +1 inch = 2.54 centimeters<br> +<br> +1 meter = 39.37 inches<br> +<br> +<br> +2. Weight (or Mass)<br> +<br> +1 pound = 16 ounces = 0.4536 kilograms<br> +<br> +1 kilogram = 2.2 pounds<br> +<br> +1 long ton = 2240 pounds<br> +<br> +1 short ton = 2000 pounds<br> +<br> +<br> +3. Volume<br> +<br> +1 liquid quart = 0.945 litres<br> +<br> +1 litre = 1.06 liquid quarts<br> +<br> +1 U. S. gallon = 4 quarts = 231 cubic inches<br> +<br> +<br> +4. Angular Measure<br> +<br> +3.14 radians = PI radians = 180 degrees<br> +<br> +1 radian = 57.30 degrees<br> +<br> +<br> +5. Pressure<br> +<br> +760 millimeters of mercury = 14.7 pounds per square inch<br> +<br> +<br> +6. Power<br> +<br> +1 horse power = 550 foot pounds per second = 746 watts<br> +<br> +<br> +7. Miscellaneous<br> +<br> +60 miles per hour = 88 feet per second<br> +<br> +980 centimeters per second </big><big>per second <br> +</big><big>= 32.2 feet per second per second<br> += acceleration of gravity.<br> +<br> +1 cubic foot of water weighs 62.4 pounds<br> +<br> +1 gallon of water weighs 8.34 pounds<br> +<br> +<br> +<br> +Printed in U. S. A.<br> +INSTRUCTIONS FOR USING A SLIDE RULE<br> +COPYRIGHTED BY W. STANLEY & CO.<br> +Commercial Trust Building, Philadelphia, Pa.<br> +<br> +</big> + +<div style='display:block; margin-top:4em'>*** END OF THE PROJECT GUTENBERG EBOOK INSTRUCTION FOR USING A SLIDE RULE ***</div> +<div style='text-align:left'> + +<div style='display:block; margin:1em 0'> +Updated editions will replace the previous one—the old editions will +be renamed. +</div> + +<div style='display:block; margin:1em 0'> +Creating the works from print editions not protected by U.S. copyright +law means that no one owns a United States copyright in these works, +so the Foundation (and you!) can copy and distribute it in the United +States without permission and without paying copyright +royalties. Special rules, set forth in the General Terms of Use part +of this license, apply to copying and distributing Project +Gutenberg™ electronic works to protect the PROJECT GUTENBERG™ +concept and trademark. 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