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| author | Roger Frank <rfrank@pglaf.org> | 2025-10-15 02:32:46 -0700 |
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| committer | Roger Frank <rfrank@pglaf.org> | 2025-10-15 02:32:46 -0700 |
| commit | 3c4fcf5c65e1458b6a385d55a4346a7a707fa271 (patch) | |
| tree | e08f8405625901398651550df1f7fbdce8b51cfe | |
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diff --git a/.gitattributes b/.gitattributes new file mode 100644 index 0000000..6833f05 --- /dev/null +++ b/.gitattributes @@ -0,0 +1,3 @@ +* text=auto +*.txt text +*.md text diff --git a/26752-h.zip b/26752-h.zip Binary files differnew file mode 100644 index 0000000..3348dde --- /dev/null +++ b/26752-h.zip diff --git a/26752-h/26752-h.htm b/26752-h/26752-h.htm new file mode 100644 index 0000000..f0f8435 --- /dev/null +++ b/26752-h/26752-h.htm @@ -0,0 +1,12760 @@ +<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> +<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> +<head> + <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> + <title> + The Way to Geometry. + </title> + + <style type="text/css"> + +<!-- + p { margin-top: .75em; + margin-bottom: .75em; + } + H1,H2,H3,H4,H5,H6 { + text-align: center; /* all headings centered */ + } + hr {text-align: center; width: 50%;} + hr.full {width: 100%;} + hr.short {text-align: center; 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text-align: left; text-indent: 0;} + .figcenter {margin: auto;} + .figright {float: right;} + .figleft {float: left;} + img.middle { border: none; vertical-align: middle } + + // --> + </style> + </head> +<body> + + +<pre> + +The Project Gutenberg EBook of The Way To Geometry, by Peter Ramus + +This eBook is for the use of anyone anywhere at no cost and with +almost no restrictions whatsoever. You may copy it, give it away or +re-use it under the terms of the Project Gutenberg License included +with this eBook or online at www.gutenberg.org + + +Title: The Way To Geometry + +Author: Peter Ramus + +Translator: William Bedwell + +Release Date: October 2, 2008 [EBook #26752] + +Language: English + +Character set encoding: ISO-8859-1 + +*** START OF THIS PROJECT GUTENBERG EBOOK THE WAY TO GEOMETRY *** + + + + +Produced by Jonathan Ingram, Keith Edkins and the Online +Distributed Proofreading Team at https://www.pgdp.net + + + + + + +</pre> + + +<table border="0" cellpadding="10" style="background-color: #ccccff;"> +<tr> +<td style="width:25%; vertical-align:top"> +Transcriber's note: +</td> +<td> +<p>Several few typographical errors have been corrected. They +appear in the text <span class="correction" title="explanation will pop up">like this</span>, and the +explanation will appear when the mouse pointer is moved over the marked +passage. Cases which could conceivably be genuine variable orthography have been retained as printed. +Many corrections are actually part of the arguments: no guarantee is given that all such errors +in the text have been found and corrected. +</p><p> +In the original, 20 pages were printed with out-of-sequence page numbers, the numbers as printed being repeated in the index. These +have been retained as printed but marked with an asterisk to distinguish them from the in-sequence pages which +have the same number, thus 249* +</p><p> +Mixed fractions have been consistently transcribed as e.g. 5.5/96 although the period is not always present in the printed text (this +avoids possible confusion of a hyphen, as 5-5/96, with a minus sign). The plus and minus signs in the printed text are apparently +indistinguishable dashes - they have been transcribed as '+' and '-' as the context requires. +</p></td> +</tr> +</table> + +<h3><i>VIA REGIA</i></h3> + +<p class="cenhead"><span class="sc">Ad</span></p> + +<h3>GEOMETRIAM.</h3> + +<hr class="full" /> + +<h3>THE WAY</h3> + +<p class="cenhead">TO</p> + +<h1>GEOMETRY.</h1> + +<h2>Being necessary and usefull,</h2> + +<p class="cenhead">For</p> + +<p class="cenhead"><i>Astronomers. +Engineres. +Geographers. +Architecks. +Land-meaters. +Carpenters. +Sea-men. +Paynters. +Carvers, &c.</i></p> + +<hr class="full" /> + +<p class="cenhead">Written in Latine by <span class="sc">Peter Ramvs</span>, and now +Translated and much enlarged by the Learned +M<sup>r</sup>. <span class="sc">William Bedwell.</span></p> + +<hr class="full" /> + +<p class="cenhead"><i>LONDON</i>,<br /> +Printed by <i>Thomas Cotes</i>, And are to be sold by<br /> +<i>Michael Sparke</i>; at the blew Bible in<br /> +Greene Arbour, 1636.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/156.png"><img style="width:100%" src="images/156.png" + alt="Surveying." title="Surveying." /></a> + </div> + <div class="figcenter" style="width:30%;"> + <a href="images/149.png"><img style="width:100%" src="images/149.png" + alt="Surveying." title="Surveying." /></a> + </div> +<h2>TO THE</h2> + +<h1>WORSHIPFVL</h1> + +<h2><span class="sc">M. Iohn Greaves</span>, <i>Professor</i> of</h2> + +<h3><i>Geometry</i> in <i>Gresham Colledge</i> London;</h3> + +<p class="cenhead"><i>All happinesse</i>.</p> + + <p><i>SIR</i>,</p> + + <p><i>Your acquaintance with the Author before his death was not long, + which I have oft heard you say, you counted your great unhappinesse, but + within a short time after, you knew not well whether to count your selfe + more happie in that you once knew him, or unhappy in that upon your + acquaintance you so suddenly lost him. This his worke then being to come + forth to the censorious eye of the world, and as the manner usually is to + have some Patronage, I have thought good to dedicate it to your selfe; + and that for these two reasons especially</i>.</p> + + <p><i>First, in respect of the sympathy betwixt it, and your studies; + Laboures of this nature being usually offered to such persons whose + profession is that way setled</i>.</p> + + <p><i>Secondly, for the great love and respect you alwayes shewed to the + Author, being indeed a man that would deserve no lesse, humble, void of + pride, ever ready to impart his knowledge to others in what kind soever, + loving and affecting those that affected learning</i>.</p> + + <p><i>For these respects then, I offer to you this Worke of your so much + honoured friend. I my selfe also (as it is no lesse my duty) for his sake + striving to make you hereby some part of a requitall, least I should be + found guilty of ingratitude, which is a solecisme in manners, if having + so fit an opportunity, I should not expresse to the world some Testimonie + of love to you, who so much loved him. I desire then (good Sir) your kind + acceptance of it, you knowing so well the ability of the Author, and + being also able to judge of a Worke of this nature, and in that respect + the better able to defend it from the furie of envious Detractours, of + which there are not few. Thus with my best wishes to you, as to my much + respected friend, I rest</i>.</p> + + <div class="contents"> + <div class="stanza"> + <p>Yours to be commanded in</p> + <p>any thing that he is able.</p> + </div> + + <div class="stanza"> + <p><span class="sc">Iohn Clerke.</span></p> + </div> + </div> +<h3><i>To the Reader.</i></h3> + + <p>Friendly Reader, that which is here set forth to thy view, is a + Translation out of <i>Ramus</i>. Formerly indeed Translated by one + M<sup>r</sup>. <i>Thomas Hood</i>, but never before set forth with the + Demonstrations and Diagrammes, which being cut before the Authors death, + and the Worke it selfe finished, the Coppie I having in mine hands, never + had thought for the promulgation of it, but that it should have died with + its Author, considering no small prejudice usually attends the printing + of dead mens Workes, and wee see the times, the world is now all eare and + tongue, the most given with the <i>Athenians</i>, to little else than to + heare and tell newes: And if <i>Apelles</i> that skilfull Artist alwayes + found somewhat to be amended in those Pictures which he had most + curiously drawne; surely much in this Worke might have beene amended if + the Authour had lived to refine it, but in that it was onely the first + draught, and that he was prevented by death of a second view, though + perused by others before the Presse; I was ever unwilling to the + publication, but that I was often and much solicited with iteration of + strong importunity, and so in the end over-ruled: perswading me from time + to time unto it, and that it being finished by the Authour, it was farre + better to be published, though with some errours and escapes, than to be + onely moths-meat, and so utterly lost. I would have thee, Courteous + Reader know, that it is no conceit of the worth of the thing that I + should expose the name and credit of the Authour to a publike censure; + yet I durst be bold to say, had he lived to have fitted it, and corrected + the Presse, the worke would have pointed out the workeman. For I may say, + without vaine ostentation, he was a man of worth and note, and there was + not that kinde of learning in which he had not some knowledge, but + especially for the Easterne tongues, those deepe and profound Studies, in + the judgement of the learned, which knew him well, he hath not left his + fellow behind him; as his Workes also in Manuscript now extant in the + publike Library of the famous Vniversity of Cambridge; do testifie no + lesse; for him then being so grave and learned a Divine to meddle with a + worke of this nature, he gives thee a reason in his owne following + Preface for his principall end and intent of taking this Worke in hand, + was not for the deepe and Iudiciall, but for the shallowest skull, the + good and profit of the simpler sort, who as it was in the Latine, were + able to get little or no benifite from it. Therefore considering the + worth of the Authour, and his intent in the Worke. Reade it favourably, + and if the faults be not too great, cover them with the mantle of love, + and judge charitably offences unwillingly committed, and doe according to + the termes of equitie, as thou wouldest be done unto, but it is a common + saying, as <i>Printers</i> get Copies for their profit, so Readers often + buy and reade for their pleasure; and there is no worke so exactly done + that can escape the malevolous disposition of some detracting spirits, to + whom I say, as one well, <i>Facilius est unicuivis nostrum aliena curiosè + observare: quam proproia negotia rectè agere</i>. It is a great deale + more easie to carpe at other mens doings, than to give better of his + owne. And as <i>Arist</i>. <span title="to pasin aresai duscherestaton esti" class="grk" + >τό πάσιν + ἀρέσαι + δυσχερέστατόν + ἐστι</span>; <i>omnibus placere difficilimum + est</i>. But wherefore, Gentle Reader, should I make any doubt of thy + curtesie, and favourable acceptance; for surely there can be nothing more + contrary to equitie, than to speake evill of those that have taken paines + to doe good, a Pagan would hardly doe this, much lesse I hope any good + Christian. Read then, and if by reading, thou reapest any profit, I have + my desire, if not, the fault shall be thine owne, reading haply more to + judge and censure, than for any good and benefit which otherwise may be + received from it; let but the same mind towards thine owne good possesse + thee in reading it, as did the Author in writing it, and there shall be + no neede to doubt of thy profit by it.</p> + + <div class="contents"> + <div class="stanza"> + <p><i>Thine in the common</i></p> + <p><i>bond of love</i>,</p> + </div> + + <div class="stanza"> + <p><span class="sc">Iohn Clerke</span>.</p> + </div> + </div> +<hr class="full" /> + +<h2>The Authors Preface.</h2> + + <p><i>Two things, I feare me, will here be objected against me: The one + concerneth my selfe, directly: The other mine Author, and the worke I + have taken in hand the translating of him. Concerning my selfe, I + suppose, some will aske, Why I being a Divine; should meddle or busie my + selfe with these prophane studies? </i>Geometry<i> may no way further + Divinity, and therefore is no fit study for a Divine? This objection + seemeth to smell of Brownisme, that is, of a ranke peevish humour + overflowing the stomach of some, whereby they are caused to loath all + manner of solid learning, yea of true Divinity it selfe, and therefore it + doth not deserve an answer: And this we in our Title before signified. + For we have not taken this paines for Turkes and others, who by the lawes + of their profession are bound to abandon all manner of learning. But if + any man shall propose it, as a question, with a desire of satisfaction, + we are ready to answer him to the best of our abilitie. First, that + </i>Theologia vera est ars artium & scientia scientiarum<i>, Divinity + is the Art of Arts, and Science of Sciences; or Divinity is the Mistresse + upon which all Arts and Sciences are to attend as servants and + handmaides. And why then not </i>Geometry?<i> But in what place she + should follow her, I dare not say: For I am no herald, and therefore I + meddle not with precedencie: But if I were, she should be none of the + hindermost of her traine</i>.</p> + + <p><i>The Oratour saith, and very truly doubtlesse, That, </i>Omnes + artes, quæ ad humanitatē pertinent, habent commune quoddam + vinculum, & cognatione quadam inter se continentur<i>. All Arts which + pertaine unto humanity, they have a certaine common bond, and are knit + together by a kinde of affinity. If then any Arts and Sciences may be + thought necessary attendants upon this great Lady; Then surely + </i>Geometry<i> amongst the rest must needes be one: For otherwise her + traine will be but loose and shattered</i>.</p> + + <p>Plato <i>saith</i> <span title="ton theon akei geômetrein" class="grk" + >τὸν θεὸν + ἀκεὶ + γεωμετρεῖν</span>, + <i>That God doth alwayes worke by</i> Geometry, <i>that is, as the + wiseman doth interprete it,</i> <span class="sc">Sap. XI. 21.</span> + Omnia in mensura & numero & pondere disponere. <i>Dispose all + things by measure, and number, and weight: Or, as the learned + </i>Plutarch<i> speaketh; He adorneth and layeth out all the parts of the + world according to rate, proportion, and similitude. Now who, I pray you, + understandeth what these termes meane, but he which hath some meane skill + in </i>Geometry?<i> Therefore none but such an one, may be able to + declare and teach these things unto others</i>.</p> + + <p><i>How many things are there in holy Scripture which may not well be + understood without some meane skill in</i> Geometry? <i>The Fabricke and + bignesse of</i> Noah's <i>Arke: The Sciagraphy of the Temple set out + by</i> Ezechiel, <i>Who may understand, but he that is skilfull in these + Arts? I speake not of many and sundry words both in the New and Old + Testaments, whose genuine and proper signification is merely + Geometricall: And cannot well be conceived but of a Geometer</i>.</p> + + <p><i>And here, that I may speake it without offence, I would have it + observed, how many men, much magnified for learning, not onely in their + speeches, which alwayes are not premeditated, but even in their writings, + exposed to the view and censure of all men, doe often + </i>paralogizein<i>, speake much, and little to the purpose. This they + could not so easily and often doe, if they had beene but meanely + practised in these kinde of studies. Wherefore that Epigramme which was + used to be written over their Philosophy Schoole doores,</i> <span + title="oudeis ageômetrêtos eisitô" class="grk" + >οὐδῆις + ἀγεωμέτρητος + εἴσιτω</span>, <i>No man ignorant + of</i> Geometry <i>come within these doores: Now written over our + Divinitie Schooles. And if any man shall thinke this an hard sentence, + let him heare what Saint </i>Augustine<i> saith in the same case,</i> + Nemo ad divinarum humanarumq; rerum cognitionem accedat, nisi prius + annumerandi artem addiscat: <i>Let no man come neither within the + Divinity nor Philosophy Schooles, except he have first learned + Arithmeticke. Now that the one of these Arts cannot be learned without + the other;</i> Euclide <i>our great Master, who made but one of both, + hath sufficiently demonstrated</i>.</p> + + <p><i>If I should alledge the like practise of famous Divines, greatly + admired for their great skill in this profession, as</i> T. Peckham + <i>Arch-Bishop of Canterbury,</i> Maurolycus <i>Bishop of</i> Messana + <i>in</i> Sicilia, Cusanus <i>Cardinall of</i> Rome, <i>and many others, + before indifferent judges, I am sure I should not be condemned. Who doth + not greatly magnifie the grave</i> Seb. Munster, <i>the nimble</i> Ph. + Melanchthon, <i>and the noble</i> Bernardino Baldo <i>Abbot of</i> + Guastill, <i>and the painefull</i> Barth. Pitiscus <i>of</i> Grunberg, + <i>for their knowledge and paines in these Arts and Sciences? And thus + much shall at this time suffice, to have spoken unto the first Question: + If any shall require further satisfaction, those I referre unto the + forenamed Authors, whose authority peradventure may more prevaile with + them, then my reasons may</i>.</p> + + <p><i>The next is concerning mine Author, and the worke in hand</i> + Geometry, <i>it must needs be confest we are beholden to</i> Euclides + <i>Elements for: And he that would be rich in that profession, may have, + if he be not covetous, his fill there, if he will labour hard, and take + paines for it, it is true. But in what time thinke yau, may a man learne + all</i> Euclide, <i>and so by him be made skilfull in this Art? By + himselfe I know not whether ever or never: And with the helpe of another, + although very expert, I will not promise him that hee shall attaine to + perfection in many yeares</i>.</p> + + <p>Hippocrates <i>the Prince of Physicians hath, as they say, in his + workes laid out the whole Art of Physicke; but I marvell how long a man + should study him alone, and read him over and over, before he should be a + good Physician? I feare mee all the friends that he hath, and neighbours + round about him, yea, and himselfe too, would all die before he should be + able to hele them, or per adventure ere he should be able to know what + they ail'd; and after 30, or 40. yeeres of such his study, I would be + very loath to commit my selfe unto him. How much therefore are the + students of this noble Science beholding unto those men, who by their + industry, practise, and painefull travells, have shewed them a ready and + certaine way through this wildernesse?</i></p> + + <p><i>The Elements of</i> Euclide <i>they do containe generally the whole + art of</i> Geometry: <i>But if you will offer to travell thorow them + alone, you shall finde them, I will warrant you, Elements indeed: for + there you may walke through the spacious Aire, and over the great and + wide sea, and in and about the vaste and arid wildernesse many a day and + night, before you shall know where you are. This</i> Ramus, <i>my Authour + in reading him found to be true; and confesseth himselfe often to have + beene at a stand: Often to have lost himselfe: Often to have hitte upon a + rocke, when he had thought he had touch'd land</i>.</p> + + <p><i>Least therefore other men, in this journey doe not likewise loose + themselves, for the benefit and safety, I meane, of others he hath + prick'd them out a charde or chack'd out a way, which if thou shalt + please to follow, it shall lead thee to thy wayes end, as directly, and + in as short time, as conveniently may be. Yet in what time I cannot + warrant thee: For all mens capacity, especially in these Arts, is not + alike: All are not a like painefull, industrious, or diligent: All are + not of the same ability of body, to be able to continue or sit at it: Or + all not so free from other imployments or businesse calling them from + their study, as some others are. For know this for certaine, Thou shalt + here make no great progresse, except thou doe make it as it were a + continued labour, Here you must observe that rule of the great + Painter</i>, Nulla dies sine linea, <i>Let no day passe over your head, + in which you draw not some diagram or figure or other</i>.</p> + + <p><i>One other thing let me also advise thee of, how capable soever thou + art, refuse not, if thou maist have it, the helpe of a teacher; For + except thou be another</i> Hippocrates <i>or</i> Forcatelus, <i>whō + our Authour mentioneth, thou canst not in these Arts and Sciences attaine + unto any great perfection without infinite patience and great losse of + most precious time, For they are therefore called <span + title="Mathêmatikoi" class="grk" + >Μαθηματικόι</span>, + Mathematicks, that is, doctrinal or disciplinary Arts, because they are + not to be attained unto by our owne information and industry; but by the + helpe and instruction of others</i>.</p> + + <p><i>This Worke gentle Reader, was in part above 30. yeares since + published by M.</i> Thomas Hood, <i>a learned man, and loving friend of + mine, who teaching these Arts, in the Staplers Chappell in Leadenhall + London, for the benefit of his Schollers and Auditory, did set out the + Elements apart by themselves. The whole at large, with the Diagrammes, + and Demonstrations, hee promised, as appeareth in the Preface to that his + Worke, at his convenient leysure to send out shortly, after them. This + for ought we know or can learne, is not by him or any other performed: + And yet are those alone, without these of small use or none to a learner, + where a teacher is not alwayes at hand. Wherefore we are bold being + (encouraged thereunto by some private friends, and especially by the + learned M.</i> H. Brigges, <i>professour of</i> Geometry <i>in the famous + Vniversity of</i> Oxford) <i>to publish this of ours long since finished + and ended</i>.</p> + + <p><i>The usuall termes, whether Latine or Greeke, commonly used by + the</i> Geometers, <i>we have set downe and expressed in English, as well + as we could, as others, writing of this argument in our language, have + done before us. These termes, I doubt not, may by some in English + otherwise be expressed, but how harsh those termes, may unto + Mathematicall eares, at the first appeare, I will not say; and use in + short time will make these familiar, and as pleasing to the eare as those + possibly may be</i>.</p> + + <p><i>Our Authour, in the declaration of the Elements hath many passages, + which in our judgement doe not make so much for the understanding of the + matter in hand, as for the defence of the method here used, against</i> + Aristotle, Euclide, Proclus, <i>and others, which we have therfore wholly + omitted. Some other things, which in our opinion, might in some respect + illustrate any particular in this businesse, we have here and there + inserted. Out of the learned</i> Finkius's Geometria Rotundi, <i>Wee have + added to the fifth Booke certaine Propositions with their Consectaries + out of</i> Ptolomi's <i>Almagest. The painfull and diligent</i> Rod. + Snellius <i>out of the Lectures and Annotations of B.</i> Salignacus, I. + Tho. Freigius, <i>and others, hath illustrated and altered here and there + some few things</i>.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/018.png"><img style="width:100%" src="images/018.png" + alt="Decorative spacer." title="Decorative spacer." /></a> + </div> + <div class="figcenter" style="width:40%;"> + <a href="images/019.png"><img style="width:100%" src="images/019.png" + alt="Decorative spacer." title="Decorative spacer." /></a> + </div> +<h3>The Contents.</h3> + + <div class="contents"> + <div class="stanza"> + <p>Booke I. <i>Of a Magnitude.</i> Page <a href="#page1">1</a></p> + </div> + + <div class="stanza"> + <p>Booke II. <i>Of a Line.</i> p. <a href="#page13">13</a></p> + </div> + + <div class="stanza"> + <p>Book III. <i>Of an Angle.</i> p. <a href="#page21">21</a></p> + </div> + + <div class="stanza"> + <p>Book IV. <i>Of a Figure</i>. p. <a href="#page32">32</a></p> + </div> + + <div class="stanza"> + <p>Book V. <i>Of Lines and Angles in a plaine Surface.</i> p. <a href="#page51">51</a></p> + </div> + + <div class="stanza"> + <p>Book VI. <i>Of a Triangle.</i> p. <a href="#page83">83</a></p> + </div> + + <div class="stanza"> + <p>Book VII. <i>The comparison of Triangles.</i> p. <a href="#page94">94</a></p> + </div> + + <div class="stanza"> + <p>Book VIII. <i>Of the diverse kinds of Triangles.</i> p. <a href="#page106">106</a></p> + </div> + + <div class="stanza"> + <p>Book IX. <i>Of the measuring of right lines by like right-angled Triangles.</i> p. <a href="#page113">113</a></p> + </div> + + <div class="stanza"> + <p>Book X. <i>Of a Triangulate and Parallelogramme.</i> p. <a href="#page136">136</a></p> + </div> + + <div class="stanza"> + <p>Book XI. <i>Of a Right-angle.</i> p. <a href="#page148">148</a></p> + </div> + + <div class="stanza"> + <p>Book XII. <i>Of a Quadrate.</i> p. <a href="#page152">152</a></p> + </div> + + <div class="stanza"> + <p>Book XIII. <i>Of an Oblong.</i> p. <a href="#page167">167</a></p> + </div> + + <div class="stanza"> + <p>Book XIV. <i>Of a right line proportionally cut: And of other Quadrangles, and Multangles.</i> p. <a href="#page174">174</a></p> + </div> + + <div class="stanza"> + <p>Book XV. <i>Of the Lines in a Circle.</i> p. <a href="#pageastx201">201</a>*</p> + </div> + + <div class="stanza"> + <p>Book XVI. <i>Of the Segments of a Circle.</i> p. <a href="#page201">201</a></p> + </div> + + <div class="stanza"> + <p>Book XVII. <i>Of the Adscription of a Circle and Triangle.</i> p. <a href="#page215">215</a></p> + </div> + + <div class="stanza"> + <p>Book XVIII. <i>Of the adscription of a Triangulate.</i> p. <a href="#page221">221</a></p> + </div> + + <div class="stanza"> + <p>Book XIX. <i>Of the measuring of ordinate Multangle, and of a Circle.</i> p. <a href="#pageastx252">252</a>*</p> + </div> + + <div class="stanza"> + <p>Book XX. <i>Of a Bossed surface.</i> p. <a href="#pageastx257">257</a>*</p> + </div> + + <div class="stanza"> + <p>Book XXI. <i>Of Lines and Surfaces in solids.</i> p. <a href="#page242">242</a></p> + </div> + + <div class="stanza"> + <p>Book XXII. <i>Of a Pyramis.</i> p. <a href="#page249">249</a></p> + </div> + + <div class="stanza"> + <p>Book XXIII. <i>Of a Prisma.</i> p. <a href="#page256">256</a></p> + </div> + + <div class="stanza"> + <p>Book XXIV. <i>Of a Cube.</i> p. <a href="#page264">264</a></p> + </div> + + <div class="stanza"> + <p>Book XXV. <i>Of mingled ordinate Polyedra's.</i> p. <a href="#page271">271</a></p> + </div> + + <div class="stanza"> + <p>Book XXVI. <i>Of a Spheare.</i> p. <a href="#page284">284</a></p> + </div> + + <div class="stanza"> + <p>Book XXVII. <i>Of the Cone and Cylinder.</i> p. <a href="#page290">290</a></p> + </div> + </div> +<hr class="full" /> + +<p><!-- Page 1 --><span class="pagenum"><a name="page1"></a>[1]</span></p> + + <div class="figcenter" style="width:40%;"> + <a href="images/021.png"><img style="width:100%" src="images/021.png" + alt="Decorative spacer." title="Decorative spacer." /></a> + </div> +<h1><i>VIA REGIA AD +GEOMETRIAM.</i></h1> + +<h2>THE FIRST BOOKE OF +<i>Peter Ramus's</i> Geometry, +<i>Which is of a Magnitude.</i></h2> + +<hr class="full" /> + + <p><a name="1_e_j"></a> 1. <i>Geometry is the Art of measuring + well</i>.</p> + + <p>The end or scope of Geometry is to measure well: Therefore it is + defined of the end, as generally all other Arts are. <i>To measure + well</i> therefore is to consider the nature and affections of every + thing that is to be measured: To compare such like things one with + another: And to understand their reason and proportion and similitude. + For all that is to measure well, whether it bee that by Congruency and + application of some assigned measure: Or by Multiplication of the termes + or bounds: Or by Division of the product made by multiplication: Or by + any other way whatsoever the affection of the thing to be measured be + considered.</p> + + <p>But this end of Geometry will appeare much more beautifull and + glorious in the use and geometricall workes and <!-- Page 2 --><span + class="pagenum"><a name="page2"></a>[2]</span>practise then by precepts, + when thou shalt observe Astronomers, Geographers, Land-meaters, Sea-men, + Enginers, Architects, Carpenters, Painters, and Carvers, in the + description and measuring of the Starres, Countries, Lands, Engins, Seas, + Buildings, Pictures, and Statues or Images to use the helpe of no other + art but of Geometry. Wherefore here the name of this art commeth farre + short of the thing meant by it. (For <i>Geometria</i>, made of <i>Gè</i>, + which in the Greeke language signifieth the Earth; and <i>Métron</i>, a + measure, importeth no more, but as one would say <i>Land-measuring</i>. + And <i>Geometra</i>, is but <i>Agrimensor</i>, A land-meter: or as + <i>Tully</i> calleth him <i>Decempedator</i>, a Pole-man: or as + <i>Plautus</i>, <i>Finitor</i>, a Marke-man.) when as this Art teacheth + not only how to measure the Land or the Earth, but the Water, and the + Aire, yea and the whole World too, and in it all Bodies, Surfaces, Lines, + and whatsoever else is to bee measured.</p> + + <p>Now <i>a Measure</i>, as <i>Aristotle</i> doth determine it, in every + thing to be measured, is some small thing conceived and set out by the + measurer; and of the Geometers it is called <i>Mensura famosa</i>, a + knowne measure. Which kinde of measures, were at first, as + <i>Vitruvius</i> and <i>Herodo</i> teache us, taken from mans body: + whereupon <i>Protagoras</i> sayd, <i>That man was the measure of all + things</i>, which speech of his, Saint <i>Iohn</i>, <i>Apoc.</i> 21. 17. + doth seeme to approve. True it is, that beside those, there are some + other sorts of measures, especially greater ones, taken from other + things, yet all of them generally made and defined by those. And because + the stature and bignesse of men is greater in some places, then it is + ordinarily in others, therefore the measures taken from them are greater + in some countries, then they are in others. Behold here a catalogue, and + description of such as are commonly either used amongst us, or some times + mentioned in our stories and other bookes translated into our English + tongue.</p> + + <p><i>Granum hordei</i>, a Barley corne, like as a wheat corne in + weights, is no kinde of measure, but is <i>quiddam minimum <!-- Page 3 + --><span class="pagenum"><a name="page3"></a>[3]</span>in mensura</i>, + some least thing in a measure, whereof it is, as it were, made, and + whereby it is rectified.</p> + + <p><i>Digitus</i>, a Finger breadth, conteineth 2. barly cornes length, + or foure layd side to side:</p> + + <p><i>Pollex</i>, a Thumbe breadth; called otherwise <i>Vncia</i>, an + ynch, 3. barley cornes in length:</p> + + <p><i>Palmus</i>, or <i>Palmus minor</i>, an Handbreadth, 4. fingers, or + 3. ynches.</p> + + <p><i>Spithama</i>, or <i>Palmus major</i>, a Span, 3. hands breadth, or + 9. ynches.</p> + + <p><i>Cubitus</i>, a Cubit, halfe a yard, from the elbow to the top of + the middle finger, 6. hands breadth, or two spannes.</p> + + <p><i>Ulna</i>, from the top of the shoulder or arme-hole, to the top of + the middle finger. It is two folde; A yard and an Elne. <i>A yard</i>, + containeth 2. cubites, or 3. foote: <i>An Elne</i>, one yard and a + quarter, or 2. cubites and ½.</p> + + <p><i>Pes</i>, a Foot, 4. hands breadth, or twelve ynches.</p> + + <p><i>Gradus</i>, or <i>Passus minor</i>, a Steppe, two foote and an + halfe.</p> + + <p><i>Passus</i>, or <i>Passus major</i>, a Stride, two steppes, or five + foote.</p> + + <p><i>Pertica</i>, a Pertch, Pole, Rod or Lugge, 5. yardes and an + halfe.</p> + + <p><i>Stadium</i>, a Furlong; after the Romans, 125. pases: the English, + 40. rod.</p> + + <p><i>Milliare</i>, or <i>Milliarium</i>, that is <i>mille passus</i>, + 1000. passes, or 8. furlongs.</p> + + <p><i>Leuca</i>, a League, 2. miles: used by the French, spaniards, and + seamen.</p> + + <p><i>Parasanga</i>, about 4. miles: a Persian, & common Dutch mile; + 30. furlongs.</p> + + <p><i>Schœnos</i>, 40. furlongs: an Egyptian, or swedland mile.</p> + + <p>Now for a confirmation of that which hath beene saide, heare the words + of the Statute.</p> + + <p><i>It is ordained, That 3. graines of Barley, dry and round, do make + an</i> Ynch: 12. <i>ynches do make a</i> Foote: 3. <i>foote do make a</i> + <!-- Page 4 --><span class="pagenum"><a name="page4"></a>[4]</span>Yard: + <i>5. yardes and ½ doe make a Perch: And 40. perches in length, and 4. in + breadth, doe make an Aker: 33. Edwar. 1. De terris mensurandis: & De + compositione ulnarum & Perticarum</i>.</p> + + <p>Item, <i>Bee it enacted by the authority aforesaid; That a</i> Mile + <i>shall be taken and reckoned in this manner, and no otherwise; That is + to say,</i> a Mile <i>to containe 8. furlongs: And every</i> Furlong + <i>to containe 40. lugges or poles: And every</i> Lugge <i>or</i> Pole + <i>to containe 16. foote and ½. 25. Eliza.</i> An Act for restraint of + new building, &c.</p> + + <p>These, as I said, are according to diverse countries, where they are + used, much different one from another: which difference, in my judgment; + ariseth especially out of the difference of the Foote, by which generally + they are all made, whether they be greater of lesser. For the Hand being + as before hath beene taught, the fourth part of the foot whether greater + or lesser: And the Ynch, the third part of the hand, whether greater or + lesser.</p> + + <p><i>Item</i>, the Yard, containing 3. foote, whether greater or lesser: + And the Rodde 5. yardes and ½, whether greater or lesser, and so forth of + the rest; It must needes follow, that the Foote beeing in some places + greater then it is in other some, these measures, the Hand, I meane, the + Ynch, the Yard, the Rod, must needes be greater or lesser in some places + then they are in other. Of this diversity therefore, and difference of + the foot, in forreine countries, as farre as mine intelligence will + informe me, because the place doth invite me, I will here adde these few + lines following. For of the rest, because they are of more speciall use, + I will God willing, as just occasion shall be administred, speake more + plentifully hereafter.</p> + + <p>Of this argument divers men have written somewhat, more or lesse: But + none to my knowledge, more copiously and curiously, then <i>Iames + Capell</i>, a Frenchman, and the learned <i>Willebrand</i>, + <i>Snellius</i>, of <i>Leiden</i> in Holland, for they have compared, and + that very diligently, many and sundry kinds of these measures one with + another. The first as you may <!-- Page 5 --><span class="pagenum"><a + name="page5"></a>[5]</span>see in his treatise <i>De mensuris + intervallorum</i> describeth these eleven following: of which the + greatest is <i>Pes Babylonius</i>, the Babylonian foote; the least, + <i>Pes Toletanus</i>, the foote used about <i>Toledo</i> in Spaine: And + the meane betweene both, <i>Pes Atticus</i>, that used about + <i>Athens</i> in Greece. For they are one unto another as 20. 15. and 12. + are one unto another. Therefore if the Spanish foote, being the least, be + devided into 12. ynches, and every inch againe into 10. partes, and so + the whole foote into 120. the <i>Atticke</i> foote shall containe of + those parts 150. and the <i>Babylonian</i>, 200. To this <i>Atticke</i> + foote, of all other, doth ours come the neerest: For our <i>English</i> + foote comprehendeth almost 152. such parts.</p> + + <p>The other, to witt the learned <i>Snellius</i>, in his <i>Eratosthenes + Batavus</i>, a booke which hee hath written of the true quantity of the + compasse of the Earth, describeth many more, and that after a farre more + exact and curious manner.</p> + + <p>Here observe, that besides those by us here set downe, there are + certaine others by him mentioned, which as hee writeth are found wholly + to agree with some one or other of these. For <i>Rheinlandicus</i>, that + of <i>Rheinland</i> or <i>Leiden</i>, which hee maketh his base, is all + one with <i>Romanus</i>, the <i>Italian</i> or <i>Roman</i> foote. + <i>Lovaniensis</i>, that of <i>Lovane</i>, with that of <i>Antwerpe</i>: + <i>Bremensis</i>, that of <i>Breme</i> in <i>Germany</i>, with that of + <i>Hafnia</i>, in <i>Denmarke</i>. Onely his <i>Pes Arabicus</i>, the + <i>Arabian</i> foote, or that mentioned in <i>Abulfada</i>, and + <i>Nubiensis</i>: the Geographers I have overpassed, because hee dareth + not, for certeine, affirme what it was.</p> + + <div class="figcenter" style="width:60%;"> + <a href="images/025.png"><img style="width:100%" src="images/025.png" + alt="Scale marked Digitus and Palmus." title="Scale marked Digitus and Palmus." /></a> + </div> +<p><!-- Page 6 --><span class="pagenum"><a name="page6"></a>[6]</span></p> + + <p>Looke of what parts <i>Pes Tolitanus</i>, the spanish foote, or that + of <i>Toledo</i> in Spaine, conteineth 120. of such is the + <i>Pes</i>.</p> + + <div class="contents"> + <div class="stanza"> + <p><i>Heidelbergicus</i>, that of Heidelberg, 137.</p> + <p><i>Hetruscus</i>, that of Tuscan, in Italie, 138.</p> + <p><i>Sedanensis</i>, of Sedan in France, 139.</p> + <p><i>Romanus</i>, that of Rome in Italy, 144.</p> + <p><i>Atticus</i>, of Athens in Greece, 150.</p> + <p><i>Anglicus</i>, of England, 152.</p> + <p><i>Parisinus</i>, of Paris in France, 160.</p> + <p><i>Syriacus</i>, of Syria, 166.</p> + <p><i>Ægyptiacus</i>, of Egypt, 171.</p> + <p><i>Hebraicus</i>, that of Iudæa, 180.</p> + <p><i>Babylonius</i>, that of Babylon, 200.</p> + </div> + </div> + <p>Looke of what parts <i>Pes Romanus</i>, the foote of Rome, (which is + all one with the foote of <i>Rheinland</i>) is 1000. of such parts is the + foote of</p> + + <div class="contents"> + <div class="stanza"> + <p><i>Toledo</i>, in Spaine, 864.</p> + <p><i>Mechlin</i>, in Brabant, 890.</p> + <p><i>Strausburgh</i>, in Germany, 891.</p> + <p><i>Amsterdam</i>, in Holland, 904.</p> + <p><i>Antwerpe</i>, in Brabant, 909.</p> + <p><i>Bavaria</i>, in Germany, 924.</p> + <p><i>Coppen-haun</i>, in Denmarke, 934.</p> + <p><i>Goes</i>, in Zeland, 954.</p> + <p><i>Middleburge</i>, in Zeland, 960.</p> + <p><i>London</i>, in England, 968.</p> + <p><i>Noremberge</i>, in Germany, 974.</p> + <p><i>Ziriczee</i>, in Zeland, 980.</p> + <p>The ancient <i>Greeke</i>, 1042.</p> + <p><i>Dort</i>, in Holland, 1050.</p> + <p><i>Paris</i>, in France, 1055.</p> + <p><i>Briel</i>, in Holland, 1060.</p> + <p><i>Venice</i>, in Italy, 1101.</p> + <p><i>Babylon</i>, in Chaldæa, 1172.</p> + <p><i>Alexandria</i>, in Egypt, 1200.</p> + <p><i>Antioch</i>, in Syria, 1360.</p> + </div> + </div> + <p>Of all other therefore our English foote commeth neerest unto that + used by the Greekes: And the learned Master <i>Ro. Hues</i>, was not much + amisse, who in his booke or Treatise <i>De Globis</i>, thus writeth of it + <i>Pedem nostrum Angli cum Græcorum pedi æqualem invenimus, comparatione + facta <!-- Page 7 --><span class="pagenum"><a + name="page7"></a>[7]</span>cum Græcorum pede, quem Agricola & alij ex + antiquis monumentis tradiderunt</i>.</p> + + <p>Now by any one of these knowne and compared with ours, to all English + men well knowne the rest may easily be proportioned out.</p> + + <p><a name="2_e_j"></a> 2. <i>The thing proposed to bee measured is a + Magnitude</i>.</p> + + <p><i>Magnitudo</i>, a Magnitude or Bignesse is the subject about which + Geometry is busied. For every Art hath a proper subject about which it + doth employ al his rules and precepts: And by this especially they doe + differ one from another. So the subject of Grammar was speech; of + Logicke, reason; of Arithmeticke, numbers; and so now of Geometry it is a + magnitude, all whose kindes, differences and affections, are hereafter to + be declared.</p> + + <p><a name="3_e_j"></a> 3. <i>A Magnitude is a continuall + quantity</i>.</p> + + <p>A Magnitude is <i>quantitas continua</i>, a continued, or continuall + quantity. A number is <i>quantitas discreta</i>, a disjoined quantity: As + one, two, three, foure; doe consist of one, two, three, foure unities, + which are disjoyned and severed parts: whereas the parts of a Line, + Surface, and Body are contained and continued without any manner of + disjunction, separation, or distinction at all, as by and by shall better + and more plainely appeare. Therefore a Magnitude is here understood to be + that whereby every thing to be measured is said to bee great: As a Line + from hence is said to be long, a Surface broade, a Body solid: Wherefore + Length, Breadth, and solidity are Magnitudes.</p> + + <p><a name="4_e_j"></a> 4. <i>That is</i> continuum, <i>continuall, whose + parts are contained or held together by some common bound</i>.</p> + + <p>This definition of it selfe is somewhat obscure, and to be <!-- Page 8 + --><span class="pagenum"><a name="page8"></a>[8]</span>understand onely + in a geometricall sense: And it dependeth especially of the common + bounde. For the parts (which here are so called) are nothing in the + whole, but in a <i>potentia</i> or powre: Neither indeede may the whole + magnitude bee conceived, but as it is compact of his parts, which + notwithstanding wee may in all places assume or take as conteined and + continued with a common bound, which Aristotle nameth a <i>Common + limit</i>; but <i>Euclide</i> a <i>Common section</i>, as in a line, is a + Point, in a surface, a Line: in a body, a Surface.</p> + + <p><a name="5_e_j"></a> 5. <i>A bound is the outmost of a + Magnitude</i>.</p> + + <p><i>Terminus</i>, a Terme, or Bound is here understood to bee that + which doth either bound, limite, or end <i>actu</i>, in deede; as in the + beginning and end of a magnitude: Or <i>potentia</i>, in powre or + ability, as when it is the common bound of the continuall magnitude. + Neither is the Bound a parte of the bounded magnitude: For the thing + bounding is one thing, and the thing bounded is another: For the Bound is + one distance, dimension, or degree, inferiour to the thing bounded: A + Point is the bound of a line, and it is lesse then a line by one degree, + because it cannot bee divided, which a line may. A Line is the bound of a + surface, and it is also lesse then a surface by one distance or + dimension, because it is only length, wheras a surface hath both length + and breadth. A Surface is the bound of a body, and it is lesse likewise + then it is by one dimension, because it is onely length and breadth, + whereas as a body hath both length, breadth, and thickenesse.</p> + + <p>Now every Magnitude <i>actu</i>, in deede, is terminate, bounded and + finite, yet the geometer doth desire some time to have an infinite line + granted him, but no otherwise infinite or farther to bee drawane out then + may serve his turne. <!-- Page 9 --><span class="pagenum"><a + name="page9"></a>[9]</span></p> + + <p><a name="6_e_j"></a> 6. <i>A Magnitude is both infinitely made, and + continued, and cut or divided by those things wherewith it is + bounded</i>.</p> + + <p>A line, a surface, and a body are made gemetrically by the motion of a + point, line, and surface: Item, they are conteined, continued, and cut or + divided by a point, line, and surface. But a Line is bounded by a point: + a surface, by a line: And a Body by a surface, as afterward by their + severall kindes shall be understood.</p> + + <p>Now that all magnitudes are cut or divided by the same wherewith they + are bounded, is conceived out of the definition of <i>Continuum</i>, e. + 4. For if the common band to containe and couple together the parts of a + Line, surface, & Body, be a Point, Line, and Surface, it must needes + bee that a section or division shall be made by those common bandes: And + that to bee dissolved which they did containe and knitt together.</p> + + <p><a name="7_e_j"></a> 7. <i>A point is an undivisible signe in a + magnitude</i>.</p> + + <p>A Point, as here it is defined, is not naturall and to bee perceived + by sense; Because sense onely perceiveth that which is a body; And if + there be any thing lesse then other to be perceived by sense, that is + called a Point. Wherefore a Point is no Magnitude: But it is onely that + which in a Magnitude is conceived and imagined to bee undivisible. And + although it be voide of all bignesse or Magnitude, yet is it the + beginning of all magnitudes, the beginning I meane <i>potentiâ</i>, in + powre.</p> + + <p><a name="8_e_j"></a> 8. <i>Magnitudes commensurable, are those which + one and the same measure doth measure: Contrariwise, Magnitudes + incommensurable are those, which the same measure cannot measure.</i> 1, + 2. d. X.</p> + + <p>Magnitudes compared betweene themselves in respect of numbers have + Symmetry or commensurability, and <!-- Page 10 --><span + class="pagenum"><a name="page10"></a>[10]</span>Reason or rationality: Of + themselves, Congruity and Adscription. But the measure of a magnitude is + onely by supposition, and at the discretion of the Geometer, to take as + pleaseth him, whether an ynch, an hand breadth, foote, or any other thing + whatsoever, for a measure. Therefore two magnitudes, the one a foote + long, the other two foote long, are commensurable; because the magnitude + of one foote doth measure them both, the first once, the second twice. + But some magnitudes there are which have no common measure, as the + Diagony of a quadrate and his side, 116. p. X. <i>actu</i>, in deede, are + <i>Asymmetra</i>, incommensurable: And yet they are <i>potentiâ</i>, by + power, <i>symmetra</i>, commensurable, to witt by their quadrates: For + the quadrate of the diagony is double to the quadrate of the side.</p> + + <p><a name="9_e_j"></a> 9. <i>Rationall Magnitudes are those whose reason + may bee expressed by a number of the measure given. Contrariwise they are + irrationalls.</i> 5. d. X.</p> + + <p><i>Ratio</i>, Reason, Rate, or Rationality, what it is our Authour + (and likewise <i>Salignacus</i>) have taught us in the first Chapter of + the second booke of their Arithmetickes: Thither therefore I referre + thee.</p> + + <p><i>Data mensura</i>, a Measure given or assigned, is of <i>Euclide</i> + called <i>Rhetè</i>, that is spoken, (or which may be uttered) definite, + certaine, to witt which may bee expressed by some number, which is no + other then that, which as we said, was called <i>mensura famosa</i>, a + knowne or famous measure.</p> + + <p>Therefore Irrationall magnitudes, on the contrary, are understood to + be such whose reason or rate may not bee expressed by a number or a + measure assigned: As the side of the side of a quadrate of 20. foote unto + a magnitude of two foote; of which kinde of magnitudes, thirteene sorts + are mentioned in the tenth booke of <i>Euclides Elements</i>: such are + the segments of a right line proportionally cutte, unto the whole line. + The Diameter in a circle is rationall: <!-- Page 11 --><span + class="pagenum"><a name="page11"></a>[11]</span>But it is irrationall + unto the side of an inscribed quinquangle: The Diagony of an Icosahedron + and Dodecahedron is irrationall unto the side.</p> + + <p><a name="10_e_j"></a> 10. <i>Congruall or agreeable magnitudes are + those, whose parts beeing applyed or laid one upon another doe fill an + equall place</i>.</p> + + <p><i>Symmetria</i>, Symmetry or Commensurability and Rate were from + numbers: The next affections of Magnitudes are altogether + geometricall.</p> + + <p><i>Congruentia</i>, Congruency, Agreeablenesse is of two magnitudes, + when the first parts of the one doe agree to the first parts of the + other, the meane to the meane, the extreames or ends to the ends, and + lastly the parts of the one, in all respects to the parts, of the other: + so Lines are congruall or agreeable, when the bounding, points of the + one, applyed to the bounding points of the other, and the whole lengths + to the whole lengthes, doe occupie or fill the same place. So Surfaces + doe agree, when the bounding lines, with the bounding lines: And the + plots bounded, with the plots bounded doe occupie the same place. Now + bodies if they do agree, they do seeme only to agree by their surfaces. + And by this kind of congruency do we measure the bodies of all both + liquid and dry things, to witt, by filling an equall place. Thus also doe + the moniers judge the monies and coines to be equall, by the equall + weight of the plates in filling up of an equall place. But here note, + that there is nothing that is onely a line, or a surface onely, that is + naturall and sensible to the touch, but whatsoever is naturall, and thus + to be discerned is corporeall.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="11_e_j"></a> 11. <i>Congruall or agreeable Magnitudes are + equall.</i> 8. <i>ax. j</i>.</p> + + <p>A lesser right line may agree to a part of a greater, but to so much + of it, it is equall, with how much it doth agree: <!-- Page 12 --><span + class="pagenum"><a name="page12"></a>[12]</span>Neither is that axiome + reciprocall or to be converted: For neither in deede are Congruity and + Equality reciprocall or convertible. For a Triangle may bee equall to a + Parallelogramme, yet it cannot in all points agree to it: And so to a + Circle there is sometimes sought an equall quadrate, <span + class="correction" title="text reads `althoughin congruall'">although + incongruall</span> or not agreeing with it: Because those things which + are of the like kinde doe onely agree.</p> + + <p><a name="12_e_j"></a> 12. <i>Magnitudes are described betweene + themselves, one with another, when the bounds of the one are bounded + within the boundes of the other: That which is within, is called the + inscript: and that which is without, the Circumscript</i>.</p> + + <p>Now followeth Adscription, whose kindes are Inscription and + Circumscription; That is when one figure is written or made within + another: This when it is written or made about another figure.</p> + + <p><i>Homogenea</i>, Homogenealls or figures of the same kinde onely + betweene themselves <i>rectitermina</i>, or right bounded, are properly + adscribed betweene themselves, and with a round. Notwithstanding, at the + 15. booke of <i>Euclides Elements</i> Heterogenea, Heterogenealls or + figures of divers kindes are also adscribed, to witt the five ordinate + plaine bodies betweene themselves: And a right line is inscribed within a + periphery and a triangle.</p> + + <p>But the use of adscription of a rectilineall and circle, shall + hereafter manifest singular and notable mysteries by the reason and + meanes of adscripts; which adscription shall be the key whereby a way is + opened unto that most excellent doctrine taught by the subtenses or + inscripts of a circle as <i>Ptolomey</i> speakes, or Sines, as the latter + writers call them.</p> + +<hr class="full" /> + +<p><!-- Page 13 --><span class="pagenum"><a name="page13"></a>[13]</span></p> + +<h2>The second Booke of <i>Geometry</i>. +<i>Of a Line.</i></h2> + + <p><a name="1_e_ij"></a> 1. <i>A Magnitude is either a Line or a + Lineate</i>.</p> + + <p>The Common affections of a magnitude are hitherto declared: The + <i>Species</i> or kindes doe follow: for other then this division our + authour could not then meete withall.</p> + + <div class="figright" style="width:25%;"> + <a href="images/033.png"><img style="width:100%" src="images/033.png" + alt="Lines." title="Lines." /></a> + </div> + <p><a name="2_e_ij"></a> 2. <i>A Line is a Magnitude onely long</i>.</p> + + <p>As are <i>ae.</i> <i>io.</i> and <i>uy.</i> such a like Magnitude is + conceived in the measuring of waies, or distance of one place from + another: And by the difference of a lightsome place from a darke: + <i>Euclide</i> at the 2 <i>d j.</i> defineth a line to be a length void + of breadth: And indeede length is the proper difference of a line, as + breadth is of a face, and solidity of a body.</p> + + <p><a name="3_e_ij"></a> 3. <i>The bound of a line is a point</i>.</p> + + <p><i>Euclide</i> at the 3. <i>d j.</i> saith that the extremities or + ends of a line are points. Now seeing that a Periphery or an hoope line + hath neither beginning nor ending, it seemeth not to bee bounded with + points: But when it is described or made it beginneth at a point, and it + endeth at a pointe. Wherefore a Point is the bound of a line, sometime + <i>actu</i>, in deed, as in a right line: sometime <i>potentiâ</i>, in a + possibility, as in a perfect periphery. Yea in very deede, as before was + taught in the definition of <i>continuum</i>, 4 <i>e.</i> all lines, + whether they bee right lines, or crooked, are contained or continued with + points. But a line is made by the <!-- Page 14 --><span + class="pagenum"><a name="page14"></a>[14]</span>motion of a point. For + every magnitude generally is made by a geometricall motion, as was even + now taught, and it shall afterward by the severall kindes appeare, how by + one motion whole figures are made: How by a conversion, a Circle, + Spheare, Cone, and Cylinder: How by multiplication of the base and + heighth, rightangled parallelogrammes are made.</p> + + <p><a name="4_e_ij"></a> 4. <i>A Line is either Right or Crooked</i>.</p> + + <p>This division is taken out of the 4 d j. of <i>Euclide</i>, where + rectitude or straightnes is attributed to a line, as if from it both + surfaces and bodies were to have it. And even so the rectitude of a solid + figure, here-after shall be understood by a right line perpendicular from + the toppe unto the center of the base. Wherefore rectitude is propper + unto a line: And therefore also obliquity or crookednesse, from whence a + surface is judged to be right or oblique, and a body right or + oblique.</p> + + <p><a name="5_e_ij"></a> 5. <i>A right line is that which lyeth equally + betweene his owne bounds: A crooked line lieth contrariwise.</i> 4. <i>d. + j</i>.</p> + + <p>Now a line lyeth equally betweene his owne bounds, when it is not here + lower, nor there higher: But is equall to the space comprehended betweene + the two bounds or ends: As here <i>ae.</i> is, so hee that maketh + <i>rectum iter</i>, a journey in a straight line, commonly he is said to + treade so much ground, as he needes must, and no more: He goeth + <i>obliquum iter</i>, a crooked way, which goeth more then he needeth, as + <i>Proclus</i> saith.</p> + + <div class="figcenter" style="width:25%;"> + <a href="images/034.png"><img style="width:100%" src="images/034.png" + alt="Straight Line." title="Straight Line." /></a> + </div> +<p><!-- Page 15 --><span class="pagenum"><a name="page15"></a>[15]</span></p> + + <p><a name="6_e_ij"></a> 6. <i>A right line is the shortest betweene the + same bounds</i>.</p> + + <p><i>Linea recta</i>, a straight or right line is that, as <i>Plato</i> + defineth it, whose middle points do hinder us from seeing both the + extremes at once; As in the eclipse of the Sunne, if a right line should + be drawne from the Sunne, by the Moone, unto our eye, the body of the + Moone beeing in the midst, would hinder our sight, and would take away + the sight of the Sunne from us: which is taken from the Opticks, in which + we are taught, that we see by straight beames or rayes. Therfore to lye + equally betweene the boundes, that is by an equall distance: to bee the + shortest betweene the same bounds; And that the middest doth hinder the + sight of the extremes, is all one.</p> + + <p><a name="7_e_ij"></a> 7. <i>A crooked line is touch'd of a right or + crooked line, when they both doe so meete, that being continued or drawne + out farther they doe not cut one another</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/035.png"><img style="width:100%" src="images/035.png" + alt="Crooked Lines." title="Crooked Lines." /></a> + </div> + <p><i>Tactus</i>, Touching is propper to a crooked line, compared either + with a right line or crooked, as is manifest out of the 2. and 3. + <i>d</i> 3. A right line is said to touch a circle, which touching the + circle and drawne out farther, doth not cut the circle, 2 <i>d</i> 3. as + here <i>ae</i>, the right line toucheth the periphery <i>iou</i>. And + <i>ae</i>. doth touch the helix or spirall. <!-- Page 16 --><span + class="pagenum"><a name="page16"></a>[16]</span>Circles are said to touch + one another, when touching they doe not cutte one another, 3. <i>d</i> 3. + as here the periphery doth <i>aej.</i> doth touch the periphery + <i>ouy</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="8_e_ij"></a> 8. <i>Touching is but in one point onely. è 13. + p</i> 3.</p> + + <p>This Consectary is immediatly conceived out of the definition; for + otherwise it were a cutting, not touching. So <i>Aristotle</i> in his + <i>Mechanickes</i> saith; That a round is easiliest mou'd and most swift; + Because it is least touch't of the plaine underneath it.</p> + + <p><a name="9_e_ij"></a> 9. <i>A crooked line is either a Periphery or an + Helix.</i> This also is such a division, as our Authour could then hitte + on.</p> + + <div class="figright" style="width:15%;"> + <a href="images/036a.png"><img style="width:100%" src="images/036a.png" + alt="Periphery." title="Periphery." /></a> + </div> + <p><a name="10_e_ij"></a> 10. <i>A Periphery is a crooked line, which is + equally distant from the middest of the space comprehended</i>.</p> + + <p><i>Peripheria</i>, a Periphery, or Circumference, as <i>eio.</i> doth + stand equally distant from <i>a</i>, the middest of the space enclosed or + conteined within it.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="11_e_ij"></a> 11. <i>A Periphery is made by the turning about + of a line, the one end thereof standing still, and the other drawing the + line</i>.</p> + + <div class="figleft" style="width:15%;"> + <a href="images/036b.png"><img style="width:100%" src="images/036b.png" + alt="Generation of Periphery." title="Generation of Periphery." /></a> + </div> + <p>As in <i>eio.</i> let the point <i>a</i> stand still: And let the line + <i>ao</i>, be turned about, so that the point <i>o</i> doe make a race, + and it shall make the periphery <i>eoi</i>. Out of this fabricke doth + <i>Euclide</i>, at the 15. d. j. frame the definition of a Periphery: And + so doth hee afterwarde define a Cone, a Spheare, and a Cylinder. <!-- + Page 17 --><span class="pagenum"><a name="page17"></a>[17]</span></p> + + <p>Now the line that is turned about, may in a plaine, bee either a right + line or a crooked line: In a sphericall it is onely a crooked line; But + in a conicall or Cylindraceall it may bee a right line, as is the side of + a Cone and Cylinder. Therefore in the conversion or turning about of a + line making a periphery, there is considered onely the distance; yea two + points, one in the center, the other in the toppe, which therefore + Aristotle nameth <i>Rotundi principia</i>, the principles or beginnings + of a round.</p> + + <p><a name="12_e_ij"></a> 12. <i>An Helix is a crooked line which is + unequally distant from the middest of the space, howsoever + inclosed</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/037.png"><img style="width:100%" src="images/037.png" + alt="Examples of Helix." title="Examples of Helix." /></a> + </div> + <p><i>Hæc tortuosa linea</i>, This crankled line is of <i>Proclus</i> + called <i>Helicoides</i>. But it may also be called <i>Helix</i>, a twist + or wreath: The <i>Greekes</i> by this word do commonly either understand + one of the kindes of Ivie which windeth it selfe about trees & other + plants; or the strings of the vine, whereby it catcheth hold and twisteth + it selfe about such things as are set for it to clime or run upon. + Therfore it should properly signifie the spirall line. But as it is here + taken it hath divers kindes; As is the <i>Arithmetica</i> which is + Archimede'es Helix, as the <i>Conchois</i>, Cockleshell-like: as is the + <i>Cittois</i>, Iuylike: The <i>Tetragonisousa</i>, the Circle squaring + line, to witt that by whose meanes a circle may be brought into a square: + The Admirable line, found out by <i>Menelaus</i>: The Conicall + <i>Ellipsis</i>, the <i>Hyperbole</i>, the <i>Parabole</i>, such as these + are, they attribute to <!-- Page 18 --><span class="pagenum"><a + name="page18"></a>[18]</span><i>Menechmus</i>: All these + <i>Apollonius</i> hath comprised in eight Bookes; but being mingled + lines, and so not easie to bee all reckoned up and expressed, + <i>Euclide</i> hath wholly omitted them, saith <i>Proclus</i>, at the 9. + <i>p. j</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/038a.png"><img style="width:100%" src="images/038a.png" + alt="Mingled Lines." title="Mingled Lines." /></a> + </div> + <div class="figright" style="width:15%;"> + <a href="images/038b.png"><img style="width:100%" src="images/038b.png" + alt="Perpendicular Lines." title="Perpendicular Lines." /></a> + </div> + <p><a name="13_e_ij"></a> 13. <i>Lines are right one unto another, + whereof the one falling upon the other, lyeth equally: Contrariwise they + are oblique. è 10. d j</i>.</p> + + <p>Hitherto straightnesse and crookednesse have beene the affections of + one sole line onely: The affections of two lines compared one with + another are <i>Perpendiculum</i>, Perpendicularity and + <i>Parallelismus</i>, Parallell equality; Which affections are common + both to right and crooked lines. Perpendicularity is first generally + defined thus:</p> + + <p>Lines are right betweene themselves, that is, perpendicular one unto + another, when the one of them lighting upon the other, standeth upright + and inclineth or leaneth neither way. So two right lines in a plaine may + bee perpendicular; as are <i>ae.</i> and <i>io.</i> so two peripheries + upon a sphearicall may be perpendiculars, when the one of them falling + upon the other, standeth indifferently betweene, and doth not incline or + leane either way. So a right line may be <!-- Page 19 --><span + class="pagenum"><a name="page19"></a>[19]</span>perpendicular unto a + periphery, if falling upon it, it doe reele neither way, but doe ly + indifferently betweene either side. And in deede in all respects lines + right betweene themselves, and perpendicular lines are one and the same. + And from the perpendicularity of lines, the perpendicularity of surfaces + is taken, as hereafter shall appeare. Of the perpendicularity of bodies, + <i>Euclide</i> speaketh not one word in his <i>Elements</i>, & yet a + body is judged to be right, that is, plumme or perpendicular unto another + body, by a perpendicular line.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <div class="figright" style="width:15%;"> + <a href="images/039.png"><img style="width:100%" src="images/039.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p><a name="14_e_ij"></a> 14. <i>If a right line be perpendicular unto a + right line, it is from the same bound, and on the same side, one onely. ê + 13. p. xj</i>.</p> + + <p>Or, there can no more fall from the same point, and on the same side + but that one. This consectary followeth immediately upon the former: For + if there should any more fall unto the same point and on the same side, + one must needes reele, and would not ly indifferently betweene the parts + cut: as here thou seest in the right line <i>ae. io. eu</i>.</p> + + <p><a name="15_e_ij"></a> 15. <i>Parallell lines they are, which are + everywhere equally distant. è 35. d j</i>.</p> + + <p><i>Parallelismus</i>, Parallell-equality doth now follow: And this + also is common to crooked lines and right lines: As <!-- Page 20 --><span + class="pagenum"><a name="page20"></a>[20]</span>heere thou seest in these + examples following.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:30%;"> + <a href="images/040a.png"><img style="width:100%" src="images/040a.png" + alt="Parallel Lines." title="Parallel Lines." /></a> + </div> + <p>Parallell-equality is derived from perpendicularity, and is of neere + affinity to it. Therefore Posidonius did define it by a common + perpendicle or plum-line: yea and in deed our definition intimateth + asmuch. Parallell-equality of bodies is no where mentioned in <i>Euclides + Elements</i>: and yet they may also bee parallells, and are often used in + the Optickes, Mechanickes, Painting and Architecture.</p> + + <div class="figright" style="width:10%;"> + <a href="images/040b.png"><img style="width:100%" src="images/040b.png" + alt="Three Parallel Lines." title="Three Parallel Lines." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="16_e_ij"></a> 16. <i>Lines which are parallell to one and the + same line, are also parallell one to another</i>.</p> + + <p>This element is specially propounded and spoken of right lines onely, + and is demonstrated at the 30. <i>p. j.</i> But by an addition of equall + distances, an equall distance is knowne, as here.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<p><!-- Page 21 --><span class="pagenum"><a name="page21"></a>[21]</span></p> + +<h2>The third Booke of <i>Geometry</i>. +Of an Angle.</h2> + + <p><a name="1_e_iij"></a> 1. <i>A lineate is a Magnitude more then + long</i>.</p> + + <p>A New forme of doctrine hath forced our Authour to use oft times new + words, especially in dividing, that the logicall lawes and rules of more + perfect division by a dichotomy, that is into two kindes, might bee held + and observed. Therefore a Magnitude was divided into two kindes, to witt + into a Line and a Lineate: And a Lineate is made the <i>genus</i> of a + surface and a Body. Hitherto a Line, which of all bignesses is the first + and most simple, hath been described: Now followeth a Lineate, the other + kinde of magnitude opposed as you see to a line, followeth next in order. + <i>Lineatum</i> therefore a Lineate, or <i>Lineamentum</i>, a Lineament, + (as by the authority of our Authour himselfe, the learned <i>Bernhard + Salignacus</i>, who was his Scholler, hath corrected it) is that + Magnitude in which there are lines: Or which is made of lines, or as our + Authour here, which is more then long: Therefore lines may be drawne in a + surface, which is the proper soile or plots of lines; They may also be + drawne in a body, as the Diameter in a Prisma: the axis in a spheare; and + generally all lines falling from aloft: And therfore <i>Proclus</i> + maketh some plaine, other solid lines. So Conicall lines, as the + Ellipsis, Hyperbole, and Parabole, are called solid lines because they do + arise from the cutting of a body.</p> + + <p><a name="2_e_iij"></a> 2. <i>To a Lineate belongeth an Angle and a + Figure</i>.</p> + + <p>The common affections of a Magnitude were to be bounded, cutt, jointly + measured, and adscribed: Then of a line to be right, crooked, touch'd, + turn'd about, and <!-- Page 22 --><span class="pagenum"><a + name="page22"></a>[22]</span>wreathed: All which are in a lineate by + meanes of a line. Now the common affections of a Lineate are to bee + Angled and Figured. And surely an Angle and a figure in all Geometricall + businesses doe fill almost both sides of the leafe. And therefore both of + them are diligently to be considered.</p> + + <p><a name="3_e_iij"></a> 3. <i>An Angle is a lineate in the common + section of the bounds</i>.</p> + + <p>So <i>Angulus Superficiarius</i>, a superficiall Angle, is a surface + consisting in the common section of two lines: So <i>angulus solidus</i>, + a solid angle, in the common section of three surfaces at the least.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/042.png"><img style="width:100%" src="images/042.png" + alt="Angles." title="Angles." /></a> + </div> + <p>[But the learned B. <i>Salignacus</i> hath observed, that all angles + doe not consist in the common section of the bounds, Because the touching + of circles, either one another, or a rectilineal surface doth make an + angle without any cutting of the bounds: And therefore he defineth it + thus: <i>Angulus est terminorum inter se invicem inclinantium concursus: + An angle is the meeting of bounds, one leaning towards another.</i>] So + is <i>aei.</i> a superficiall angle: [And such also are the angles + <i>ouy.</i> and <i>bcd.</i>] so is the angle <i>o.</i> a solid angle, to + witt comprehended of the three surfaces <i><span class="correction" + title="text reads `aei.'">aoi.</span></i> <i>ioe.</i> and <i>aoe.</i> + Neither may a surface, of 2. dimensions, be bounded with <!-- Page 23 + --><span class="pagenum"><a name="page23"></a>[23]</span>one right line: + Nor a body, of three dimensions, bee bounded with two, at lest beeing + plaine surfaces.</p> + + <p><a name="4_e_iij"></a> 4. <i>The shankes of an angle are the bounds + compreding the angle</i>.</p> + + <p><i>Scèle</i> or <i>Crura</i>, the Shankes, Legges, H. are the bounds + insisting or standing upon the base of the angle, which in the Isosceles + only or Equicrurall triangle are so named of <i>Euclide</i>, otherwise he + nameth them <i>Latera</i>, sides. So in the examples aforesaid, + <i>ea.</i> and <i>ei.</i> are the shankes of the superficiary angle + <i>e</i>; And so are the three surfaces <i><span class="correction" + title="text reads `aei.'">aoi.</span></i> <i>ieo.</i> and <i>aeo.</i> the + shankes of the said angle <i>o</i>. Therefore the shankes making the + angle are either Lines or Surfaces: And the lineates formed or made into + Angles, are either Surfaces or Bodies.</p> + + <div class="figright" style="width:15%;"> + <a href="images/044.png"><img style="width:100%" src="images/044.png" + alt="Lunular Angles, etc." title="Lunular Angles, etc." /></a> + </div> + <p><a name="5_e_iij"></a> 5. <i>Angles homogeneall, are angles of the + same kinde, both in respect of their shankes, as also in the maner of + meeting of the same:</i> [<i>Heterogeneall, are those which differ one + from another in one, or both these conditions.</i>]</p> + + <p>Therefore this <i>Homogenia</i>, or similitude of angles is twofolde, + the first is of shanks; the other is of the manner of meeting of the + shankes: so rectilineall right angles, are angles homogeneall betweene + themselves. But right-lined right angles, and oblique-lined right angles + between themselves, are heterogenealls. So are neither all obtusangles + compared to all obtusangles: Nor all acutangles, to all acutangles, + homogenealls, except both these conditions doe concurre, to witt the + similitude both of shanke and manner of meeting. <i>Lunularis</i>, a + Lunular, or Moonlike corner angle is homogeneall to a <i>Systroides</i> + and <i>Pelecoides</i>, Hatchet formelike, in shankes: For each of these + are comprehended of <!-- Page 24 --><span class="pagenum"><a + name="page24"></a>[24]</span>peripheries: The Lunular of one convexe; the + other concave; as <i><span class="correction" title="there was no letter u on the printed diagram, inserted in place which fits the text" + >iue</span></i>. The Systroides of both convex, as <i>iao</i>. The + Pelecoides of both concave, as <i>eau</i>. And yet a lunular, in respect + of the meeting of the shankes is both to the Systroides and Pelecoides + heterogeneall: And therefore it is absolutely heterogeneall to it.</p> + + <p><a name="6_e_iij"></a> 6. <i>Angels congruall in shankes are + equall</i>.</p> + + <p>This is drawne out of the <a href="#10_e_j">10. e j</a>. For if twice + two shanks doe agree, they are not foure, but two shankes, neither are + they two equall angles, but one angle. And this is that which + <i>Proclus</i> speaketh of, at the 4. p j. when hee saith, that a right + lined angle is equall to a right lined angle, when one of the shankes of + the one put upon one of the shankes of the other, the other two doe + agree: when that other shanke fall without, the angle of the out-falling + shanke is the greater: when it falleth within, it is lesser: For there is + comprehendeth; here it is comprehended.</p> + + <p>Notwithstanding although congruall or agreeable angles be equall: yet + are not congruity and equality reciprocall or convertible: For a Lunular + may bee equall to a right <!-- Page 25 --><span class="pagenum"><a + name="page25"></a>[25]</span>lined right angle, as here thou seest: For + the angles of equall semicircles <i>ieo.</i> and <i>aeu.</i> are equall, + as application doth shew. The angle <i>aeo.</i> is common both to the + right angle <i>aei.</i> and to the lunar <i>aueo.</i> Let therefore the + equall angle <i>aeo.</i> bee added to both: the right angle <i>aei.</i> + shall be equall to the Lunular <i>aueo</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/045.png"><img style="width:100%" src="images/045.png" + alt="Lunulars equal to right lined angles." title="Lunulars equal to right lined angles." /></a> + </div> + <p>The same Lunular also may bee equall to an obtusangle and Acutangle, + as the same argument will demonstrate.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="7_e_iij"></a> 7. <i>If an angle being equicrurall to an other + angle, be also equall to it in base, it is equall: And if an angle having + equall shankes with another, bee equall to it in the angle, it is also + equall to it in the base. è</i> 8. & 4. <i>p j</i>.</p> + + <p>For such angles shall be congruall or agreeable in shanks, and also + congruall in bases. <i>Angulus isosceles</i>, or <i>Angulus + æquicrurus</i>, is a triangle having equall shankes unto another. <!-- + Page 26 --><span class="pagenum"><a name="page26"></a>[26]</span></p> + + <div class="figright" style="width:10%;"> + <a href="images/046a.png"><img style="width:100%" src="images/046a.png" + alt="Angles." title="Angles." /></a> + </div> + <p><a name="8_e_iij"></a> 8. <i>And if an angle equall in base to + another, be also equall to it in shankes, it is equall to it</i>.</p> + + <p>For the congruency is the same: And yet if equall angles bee equall in + base, they are not by and by equicrurall, as in the angles of the same + section will appeare, as here. And so of two equalities, the first is + reciprocall: The second is not. [And therefore is this Consectary, by the + learned B. <i>Salignacus</i>, justly, according to the judgement of the + worthy Rud. <i>Snellius</i>, here cancelled; or quite put out: For angles + may be equall, although they bee unequall in shankes or in bases, as + here, the angle <i>a.</i> is not greater then the angle <i>o</i>, + although the angle <i>o</i> have both greater shankes and greater base + then the angle <i>a</i>.]</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_iij"></a> 9. <i>If an angle equicrurall to another angle, + be greater then it in base, it is greater: And if it be greater, it is + greater in base: è</i> 52 & 24. <i>p j</i>.</p> + + <p>As here thou seest; [The angles <i><span class="correction" + title="there was no letter e on the printed diagram, inserted in place which fits the text" + >eai.</span></i> and <i>uoy.</i> are equicrurall, that is their shankes + are equall one to another; But the base <i>ei</i> is greater then the + base <i>uy</i>: Therefore the angle <i>eai</i>, is greater then the angle + <i>uoy</i>. And contrary wise, they being equicrurall, and the angle + <i>eai.</i> being greater then the angle <i>uoy.</i> The base <i>ei.</i> + must needes be greater then the base <i>uy</i>.]</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/046b.png"><img style="width:100%" src="images/046b.png" + alt="Equicrurall Angles." title="Equicrurall Angles." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 27 --><span class="pagenum"><a name="page27"></a>[27]</span></p> + + <div class="figright" style="width:10%;"> + <a href="images/047.png"><img style="width:100%" src="images/047.png" + alt="Inscribed Angle." title="Inscribed Angle." /></a> + </div> + <p><a name="10_e_iij"></a> 10. <i>If an angle equall in base, be lesse in + the inner shankes, it is greater</i>.</p> + + <p>Or as the learned Master <i>T. Hood</i> doth paraphrastically + translate it. <i>If being equall in the base, it bee lesser in the feete + (the feete being conteined within the feete of the other angle) it is the + greater angle.</i> [That is, if one angle enscribed within another angle, + be equall in base, the angle of the inscribed shall be greater then the + angle of the circumscribed.]</p> + + <p>As here the angle <i><span class="correction" title="text interchanges aei and aoi." + >aoi.</span></i> within the angle <i>aei.</i> And the bases are equall, + to witt one and the same; Therefore <i>aoi.</i> the inner angle is + greater then <i>aei.</i> the outter angle. <i>Inner</i> is added of + necessity: For otherwise there will, in the section or cutting one of + another, appeare a manifest errour. All these consectaries are drawne out + of that same axiome of congruity, to witt out of the <a + href="#10_e_j">10. e j</a>. as <i>Proclus</i> doth plainely affirme and + teach: It seemeth saith hee, that the equalities of shankes and bases, + doth cause the equality of the verticall angles. For neither, if the + bases be equall, doth the equality of the shankes leave the same or + equall angles: But if the base bee lesser, the angle decreaseth: If + greater, it increaseth. Neither if the bases bee equall, and the shankes + unequall, doth the angle remaine the same: But when they are made lesse, + it is increased: when they are made greater, it is diminished: For the + contrary falleth out to the angles and shankes of the angles. For if thou + shalt imagine the shankes to be in the same base thrust downeward, thou + makest them lesse, but their angle greater: but if thou do againe + conceive them to be pul'd up higher, thou makest them greater, but their + angle lesser. For looke how much more neere they come one to another, so + much farther off is the toppe removed from the base: wherefore you may + boldly affirme, that the same <!-- Page 28 --><span class="pagenum"><a + name="page28"></a>[28]</span>base and equall shankes, doe define the + equality of Angels. This <i>Poclus</i>,</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="11_e_iij"></a> 11. <i>If unto the shankes of an angle given, + homogeneall shankes, from a point assigned, bee made equall upon an + equall base, they shall comprehend an angle equall to the angle given. è + 23. p j.</i> & 26. <i>p xj</i>.</p> + + <p>[This consectary teacheth how unto a point given, to make an angle + equall to an Angle given. To the effecting and doing of each three things + are required; First, that the shankes be homogeneall, that is in each + place, either straight or crooked: Secondly, that the shankes bee made + equall, that is of like or equall bignesse: Thirdly, that the bases be + equall: which three conditions if they doe meete, it must needes be that + both the angles shall bee equall: but if one of them be wanting, of + necessity againe they must be unequall.]</p> + + <p>This shall hereafter be declared and made plaine by many and sundry + practises: and therefore here we bring no example of it.</p> + + <p><a name="12_e_iij"></a> 12. <i>An angle is either right or + oblique</i>.</p> + + <p>Thus much of the Affections of an angle; the division into his kindes + followeth. An angle is either Right or Oblique: as afore, at the 4 <i>e + ij.</i> a line was right or straight, and oblique or crooked. <!-- Page + 29 --><span class="pagenum"><a name="page29"></a>[29]</span></p> + + <div class="figright" style="width:10%;"> + <a href="images/049a.png"><img style="width:100%" src="images/049a.png" + alt="Right Angle." title="Right Angle." /></a> + </div> + <p><a name="13_e_iij"></a> 13. <i>A right angle is an angle whose shankes + are right (that is perpendicular) one unto another: An Oblique angle is + contrary to this</i>.</p> + + <p>As here the angle <i>aio.</i> is a right angle, as is also <i>oie.</i> + because the shanke <i>oi.</i> is right, that is, perpendicular to + <i>ae.</i> [The instrument wherby they doe make triall which is a right + angle, and which is oblique, that is greater or lesser then a right + angle, is the square which carpenters and joyners do ordinarily use: For + lengthes are tried, saith <i>Vitruvius</i>, by the Rular and Line: + Heighths, by the Perpendicular or Plumbe: And Angles, by the <span + class="correction" title="text reads `spuare'">square</span>.] + Contrariwise, an Oblique angle it is, when the one shanke standeth so + upon another, that it inclineth, or leaneth more to one side, then it + doth to the other: And one angle on the one side, is greater then that on + the other.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="14_e_iij"></a> 14. <i>All straight-shanked right angles are + equall</i>.</p> + + <p>[That is, they are alike, and agreeable, or they doe fill the same + place; as here are <i>aio.</i> and <i>eio.</i> And yet againe on the + contrary: All straight shanked equall angles, are not right-angles.]</p> + + <p>The axiomes of the equality of angles were three, as even now wee + heard, one generall, and two Consectaries: Here moreover is there one + speciall one of the equality of Right angles.</p> + + <div class="figright" style="width:15%;"> + <a href="images/049b.png"><img style="width:100%" src="images/049b.png" + alt="Semicircular Right Angles." title="Semicircular Right Angles." /></a> + </div> + <p>Angles therfore homogeneall and recticrurall, that is whose shankes + are right, as are right lines, as plaine surfaces (For let us so take the + word) are equall right <!-- Page 30 --><span class="pagenum"><a + name="page30"></a>[30]</span>angles. So are the above written + rectilineall right angles equall: so are plaine solid right angles, as in + a cube, equall. The axiome may therefore generally be spoken of solid + angles, so they be recticruralls: Because all semicircular right angles + are not equall to all semicircular right angles: As here, when the + diameter is continued it is perpendicular, and maketh twice two angles, + within and without, the outter equall betweene themselves, and inner + equall betweene themselves: But the outer unequall to the inner: And the + angle of a greater semicircle is greater, then the angle of a lesser. + Neither is this affection any way reciprocall, That all equall angles + should bee right angles. For oblique angles may bee equall betweene + themselves: And an oblique angle may bee made equall to a right angle, as + a Lunular to a rectilineall right angle, as was manifest, at the <a + href="#6_e_iij">6 e</a>.</p> + + <p>The definition of an oblique is understood by the obliquity of the + shankes: whereupon also it appeareth; That an oblique angle is unequall + to an homogeneall right angle: Neither indeed may oblique angles be made + equall by any lawe or rule: Because obliquity may infinitly bee both + increased and diminished.</p> + + <p><a name="15_e_iij"></a> 15. <i>An oblique angle is either Obtuse or + Acute</i>.</p> + + <p>One difference of Obliquity wee had before at the <a href="#9_e_ij">9 + e ij</a>. in a line, to witt of a periphery and an helix; Here there is + another dichotomy of it into obtuse and acute: which difference is proper + to angles, from whence it is translated or conferred upon other things + and metaphorically used, as <i>Ingenium obtusum, acutum</i>; A dull, and + quicke witte, and such like. <!-- Page 31 --><span class="pagenum"><a + name="page31"></a>[31]</span></p> + + <div class="figright" style="width:10%;"> + <a href="images/051b.png"><img style="width:100%" src="images/051b.png" + alt="Acute Angle." title="Acute Angle." /></a> + </div> + <div class="figright" style="width:15%;"> + <a href="images/051a.png"><img style="width:100%" src="images/051a.png" + alt="Obtuse Angle." title="Obtuse Angle." /></a> + </div> + <p><a name="16_e_iij"></a> 16. <i>An obtuse angle is an oblique angle + greater then a right angle. 11. d j</i>.</p> + + <p><i>Obtusus</i>, Blunt or Dull; As here <i>aei.</i> In the definition + the <i>genus</i> of both <i>Species</i> or kinds is to bee understood: + For a right lined right angle is greater then a sphearicall right angle, + and yet it is not an obtuse or blunt angle: And this greater inequality + may infinitely be increased.</p> + + <p><a name="17_e_iij"></a> 17. <i>An acutangle is an oblique angle lesser + then a right angle. 12. d j</i>.</p> + + <p><i>Acutus</i>, Sharpe, Keene, as here <i>aei.</i> is. Here againe the + same <i>genus</i> is to bee understood: because every angle which is + lesse then any right angle is not an acute or sharp angle. For a + semicircle and sphericall right angle, is lesse then a rectilineall right + angle, and yet it is not an acute angle.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<p><!-- Page 32 --><span class="pagenum"><a name="page32"></a>[32]</span></p> + +<h2>The fourth Booke, which is +of a Figure.</h2> + + <p><a name="1_e_iiij"></a> 1. <i>A figure is a lineate bounded on all + parts</i>.</p> + + <p>So the triangle <i>aei.</i> is a figure; Because it is a plaine + bounded on all parts with three sides. So a circle is a figure: Because + it is a plaine every way bounded with one periphery.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/052a.png"><img style="width:100%" src="images/052a.png" + alt="Figures." title="Figures." /></a> + </div> + <p><a name="2_e_iiij"></a> 2. <i>The center is the middle point in a + figure</i>.</p> + + <p>In some part of a figure the Center, Perimeter, Radius, Diameter and + Altitude are to be considered. The Center therefore is a point in the + midst of the figure; so in the triangle, quadrate, and circle, the center + is, <i>aei</i>.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/052b.png"><img style="width:100%" src="images/052b.png" + alt="Centers of Triangle, Quadrate, And Circle." title="Centers of Triangle, Quadrate, And Circle." /></a> + </div> +<p><!-- Page 33 --><span class="pagenum"><a name="page33"></a>[33]</span></p> + + <p><i>Centrum gravitatis</i>, the center of weight, in every plaine + magnitude is said to bee that, by the which it is handled or held up + parallell to the horizon: Or it is that point whereby the weight being + suspended doth rest, when it is caried. Therefore if any plate should in + all places be alike heavie, the center of magnitude and weight would be + one and the same.</p> + + <p><a name="3_e_iiij"></a> 3. <i>The perimeter is the compasse of the + figure</i>.</p> + + <p>Or, the perimeter is that which incloseth the figure. This definition + is nothing else but the interpretation of the Greeke word. Therefore the + perimeter of a Triangle is one line made or compounded of three lines. So + the perimeter of the triangle <i>a</i>, is <i>eio.</i> So the perimeter + of the circle <i>a</i> is a periphery, as in <i>eio.</i> So the perimeter + of a Cube is a surface, compounded of sixe surfaces: And the perimeter of + a spheare is one whole sphæricall surface, as hereafter shall + appeare.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/053.png"><img style="width:100%" src="images/053.png" + alt="Perimeters." title="Perimeters." /></a> + </div> + <p><a name="4_e_iiij"></a> 4. <i>The Radius is a right line drawne from + the center to the perimeter</i>.</p> + + <p><i>Radius</i>, the Ray, Beame, or Spoake, as of the sunne, and <!-- + Page 34 --><span class="pagenum"><a name="page34"></a>[34]</span>cart + wheele: As in the figures under written are <i>ae</i>, <i>ai</i>, + <i>ao</i>. It is here taken for any distance from the center, whether + they be equall or unequall.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/054a.png"><img style="width:100%" src="images/054a.png" + alt="Examples of Radius." title="Examples of Radius." /></a> + </div> + <p><a name="5_e_iiij"></a> 5. <i>The Diameter is a right line inscribed + within the figure by his center</i>.</p> + + <p>As in the figure underwritten are <i>ae</i>, <i>ai</i>, <i>ao</i>. It + is called the <i>Diagonius</i>, when it passeth from corner to corner. In + solids it is called the <i>Axis</i>, as hereafter we shall heare.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/054b.png"><img style="width:100%" src="images/054b.png" + alt="Examples of Diameter." title="Examples of Diameter." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="6_e_iiij"></a> 6. <i>The diameters in the same figure are + infinite</i>.</p> + + <p>Although of an infinite number of unequall lines that be only the + diameter, which passeth by or through the center <!-- Page 35 --><span + class="pagenum"><a name="page35"></a>[35]</span>notwithstanding by the + center there may be divers and sundry. In a circle the thing is most + apparent: as in the Astrolabe the index may be put up and downe by all + the points of the periphery. So in a speare and all rounds the thing is + more easie to be conceived, where the diameters are equall: yet + notwithstanding in other figures the thing is the same. Because the + diameter is a right line inscribed by the center, whether from corner to + corner, or side to side, the matter skilleth not. Therefore that there + are in the same figure infinite diameters, it issueth out of the + difinition of a diameter.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="7_e_iiij"></a> 7. <i>The center of the figure is in the + diameter</i>.</p> + + <p>As here thou seest <i>a, e, i</i> this ariseth out of the definition + of the diameter. For because the diameter is inscribed into the figure by + the center: Therefore the Center of the figure must needes be in the + diameter thereof: This is by <i>Archimedes</i> assumed especially at the + 9, 10, 11, and 13 <i>Theoreme</i> of his <i>Isorropicks</i>, or + <i>Æquiponderants</i>.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/055.png"><img style="width:100%" src="images/055.png" + alt="Centers in Diameters." title="Centers in Diameters." /></a> + </div> + <p>This consectary, saith the learned Rod. Snellius, is as it were a + kinde of invention of the center. For where the diameters doe meete and + cutt one another, there must the center needes bee. The cause of this is + for that in every figure <!-- Page 36 --><span class="pagenum"><a + name="page36"></a>[36]</span>there is but one center only: And all the + diameters, as before was said, must needes passe by that center.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="8_e_iiij"></a> 8. <i>It is in the meeting of the + diameters</i>.</p> + + <p>As in the examples following. This also followeth out of the same + definition of the diameter. For seeing that every diameter passeth by the + center: The center must needes be common to all the diameters: and + therefore it must also needs be in the meeting of them: Otherwise there + should be divers centers of one and the same figure. This also doth the + same <i>Archimedes</i> propound in the same words in the 8. and 12 + theoremes of the same booke, speaking of Parallelogrammes and + Triangles.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/056.png"><img style="width:100%" src="images/056.png" + alt="Meeting of Diameters." title="Meeting of Diameters." /></a> + </div> + <p><a name="9_e_iiij"></a> 9. <i>The Altitude is a perpendicular line + falling from the toppe of the figure to the base</i>.</p> + + <p><i>Altitudo</i>, the altitude, or heigth, or the depth: [For that, as + hereafter shall bee taught, is but <i>Altitudo versa</i>, an heighth <!-- + Page 37 --><span class="pagenum"><a name="page37"></a>[37]</span>with the + heeles upward.] As in the figures following are <i>ae</i>, <i>io</i>, + <i>uy</i>, or <i>sr</i>. Neither is it any matter whether the base be the + same with the figure, or be continued or drawne out longer, as in a blunt + angled triangle, when the base is at the blunt corner, as here in the + triangle, <i>aei</i>, is <i>ao</i>.</p> + + <div class="figcenter" style="width:65%;"> + <a href="images/057.png"><img style="width:100%" src="images/057.png" + alt="Altitudes." title="Altitudes." /></a> + </div> + <p><a name="10_e_iiij"></a> 10. <i>An ordinate figure, is a figure whose + bounds are equall and angles equall</i>.</p> + + <p>In plaines the Equilater triangle is onely an ordinate figure, the + rest are all inordinate: In quadrangles, the Quadrate is ordinate, all + other of that sort are inordinate: In every sort of Multangles, or many + cornered figures one may be an ordinate. In crooked lined figures the + Circle is ordinate, because it is conteined with equall bounds, (one + bound alwaies equall to it selfe being taken for infinite many,) because + it is equiangled, seeing (although in deede there be in it no angle) the + inclination notwithstanding is every where alike and equall, and as it + were the angle of the perphery be alwaies alike unto it selfe: whereupon + of Plato and Plutarch a circle is said to be <i>Polygonia</i>, a + multangle; and of Aristotle <i>Holegonia</i>, a totangle, nothing else + but one whole angle. In mingled-lined figures there is nothing that is + ordinate: In <!-- Page 38 --><span class="pagenum"><a + name="page38"></a>[38]</span>solid bodies, and pyramids the Tetrahedrum + is ordinate: Of Prismas, the Cube: of Polyhedrum's, three onely are + ordinate, the octahedrum, the Dodecahedrum, and the Icosahedrum. In + oblique-lined bodies, the spheare is concluded to be ordinate, by the + same argument that a circle was made to bee ordinate.</p> + + <p><a name="11_e_iiij"></a> 11. <i>A prime or first figure, is a figure + which cannot be divided into any other figures more simple then it + selfe</i>.</p> + + <p>So in plaines the triangle is a prime figure, because it cannot be + divided into any other more simple figure although it may be cut many + waies: And in solids, the Pyramis is a first figure: Because it cannot be + divided into a more simple solid figure, although it may be divided into + an infinite sort of other figures: Of the Triangle all plaines are made; + as of a Pyramis all bodies or solids are compounded; such are <i>aei.</i> + and <i>aeio</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/058.png"><img style="width:100%" src="images/058.png" + alt="Prime Figures." title="Prime Figures." /></a> + </div> + <p><a name="12_e_iiij"></a> 12. <i>A rationall figure is that which is + comprehended of a base and height rationall betweene themselves</i>.</p> + + <p>So <i>Euclide</i>, at the 1. d. ij. saith, that a rightangled + parallelogramme is comprehended of two right lines perpendicular one to + another, videlicet one multiplied by the other. For Geometricall + comprehension is sometimes as it were in numbers a multiplication: + Therefore if yee shall grant the base and height to bee rationalls + betweene themselves, <!-- Page 39 --><span class="pagenum"><a + name="page39"></a>[39]</span>that their reason I meane may be expressed + by a number of the assigned measure, then the numbers of their sides + being multiplyed one by another, the bignesse of the figure shall be + expressed. Therefore a Rationall figure is made by the multiplying of two + rationall sides betweene themselves.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="13_e_iiij"></a> 13. <i>The number of a rationall figure, is + called a Figurate number: And the numbers of which it is made, the Sides + of the figurate</i>.</p> + + <p>As if a Right angled parallelogramme be comprehended of the base + foure, and the height three, the Rationall made shall be 12. which wee + here call the figurate: and 4. and 3. of which it was made, we name + sides.</p> + + <p><a name="14_e_iiij"></a> 14. <i>Isoperimetrall figures, are figures of + equall perimeter</i>.</p> + + <p>This is nothing else but an interpretation of the Greeke word; So a + triangle of 16. foote about, is a isoperimeter to a triangle 16. foote + about, to a quadrate 16. foote about, and to a circle 16. foote + about.</p> + + <p><a name="15_e_iiij"></a> 15. <i>Of isoperimetralls homogenealls that + which is most ordinate, is greatest: Of ordinate isoperimetralls + heterogenealls, that is greatest, which hath most bounds</i>.</p> + + <p>So an equilater triangle shall bee greater then an isoperimeter + inequilater triangle; and an equicrurall, greater then an unequicrurall: + so in quadrangles, the quadrate is greater then that which is not a + quadrate: so an oblong more ordinate, is greater then an oblong lesse + ordinate. So of those figures which are heterogeneall ordinates, the + quadrate is greater then the Triangle: And the Circle, then the Quadrate. + <!-- Page 40 --><span class="pagenum"><a + name="page40"></a>[40]</span></p> + + <p><a name="16_e_iiij"></a> 16. <i>If prime figures be of equall height, + they are in reason one unto another, as their bases are: And + contrariwise</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/060.png"><img style="width:100%" src="images/060.png" + alt="Areas." title="Areas." /></a> + </div> + <p>The proportion of first figures is here twofold; the first is direct + in those which are of equall height. In Arithmeticke we learned; That if + one number doe multiply many numbers, the products shall be proportionall + unto the numbers, multiplyed. From hence in rationall figures the content + of those which are of equall height is to bee expressed by a number. As + in two right angled parallelogrammes, let 4. the same height, multiply 2. + and 3. the bases: The products 8. and 12. the parallelogrammes made, are + directly proportionall unto the bases 2. and 3. Therefore as 2. is unto + 3. so is 8. unto 12. The same shall afterward appeare in right Prismes + and Cylinders. In plaines, Parallelogramms are the doubles of triangles: + In solids, Prismes are the triples of pyramides: Cylinders, the triples + of Cones. The converse of this element is plaine out of the former also: + First figures if they be in reason one to another as their bases are, + then are they of equall height, to witt when their products are + proportionall unto the multiplyed, the same number did multiply them.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="17_e_iiij"></a> 17. <i>If prime figures of equall heighth + have also equall bases, they are equall</i>.</p> + + <p>[The reason is, because then those two figures compared, have equall + sides, which doe make them equall betweene themselves; For the parts of + the one applyed or laid unto the parts of the other, doe fill an equall + place, as was taught at the <a href="#10_e_j">10. e. j</a>. <i>Sn.</i>] + So Triangles, so Parallelogrammes, and so other figures proposed are + equalled upon an equall base. <!-- Page 41 --><span class="pagenum"><a + name="page41"></a>[41]</span></p> + + <p><a name="18_e_iiij"></a> 18. <i>If prime figures be reciprocall in + base and height, they are equall: And contrariwise</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/061a.png"><img style="width:100%" src="images/061a.png" + alt="Equal Parallelogrammes." title="Equal Parallelogrammes." /></a> + </div> + <p>The second kind of proportion of first figures is reciprocall. This + kinde of proportion rationall and expressible by a number, is not to be + had in first figures themselves: but in those that are equally manifold + to them, as was taught even now in direct proportion: As for example, Let + these two right angled parallelogrammes, unequall in bases and heighths + 3, 8, 4, 6, be as heere thou seest: The proportion reciprocall is thus, + As 3 the base of the one, is unto 4, the base of the other: so is 6. the + height of the one is to 8. the height of the other: And the + parallelogrammes are equall, viz. 24. and 24. Againe, let two solids of + unequall bases & heights (for here also the base is taken for the + length and heighth) be 12, 2, 3, <span class="correction" title="text reads `0', cf. the diagram" + >6</span>, 3, 4. The solids themselves shall be 72. and 72, as here thou + seest; and the proportion of the bases and heights likewise is + reciprocall: For as 24, is unto 18, so is 4, unto 3. The cause is out of + the golden rule of proportion in Arithmeticke: Because twice two sides + are <!-- Page 42 --><span class="pagenum"><a + name="page42"></a>[42]</span>proportionall: Therefore the plots made of + them shall be equall. And againe, by the same rule, because the plots are + equall: Therefore the bounds are proportionall; which is the converse of + this present element.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/061b.png"><img style="width:100%" src="images/061b.png" + alt="Equal Solids." title="Equal Solids." /></a> + </div> + <p><a name="19_e_iiij"></a> 19. <i>Like figures are equiangled figures, + and proportionall in the shankes of the equall angles</i>.</p> + + <p>First like figures are defined, then are they compared one with + another, similitude of figures is not onely of prime figures, and of such + as are compounded of prime figures, but generally of all other + whatsoever. This similitude consisteth in two things, to witt in the + equality of their angles, and proportion of their shankes.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="20_e_iiij"></a> 20. <i>Like figures have answerable bounds + subtended against their equall angles: and equall if they themselves be + equall</i>.</p> + + <p>Or thus, They have their termes subtended to the equall angles + correspondently proportionall: And equall if the figures themselves be + equall; H. This is a consectary out of the former definition.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="21_e_iiij"></a> 21. <i>Like figures are situate alike, when + the proportionall bounds doe answer one another in like + situation</i>.</p> + + <p>The second consectary is of situation and place. And this like + situation is then said to be when the upper parts of the one figure doe + agree with the upper parts of the other, the lower, with the lower, and + so the other differences of places. <i>Sn</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 43 --><span class="pagenum"><a name="page43"></a>[43]</span></p> + + <p><a name="22_e_iiij"></a> 22. <i>Those figures that are like unto the + same, are like betweene themselves</i>.</p> + + <p>This third consectary is manifest out of the definition of like + figures. For the similitude of two figures doth conclude both the same + equality in angles and proportion of sides betweene themselves.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="23_e_iiij"></a> 23. <i>If unto the parts of a figure given, + like parts and alike situate, be placed upon a bound given, a like figure + and likely situate unto the figure given, shall bee made + accordingly</i>.</p> + + <p>This fourth consectary teacheth out of the said definition, the + fabricke and manner of making of a figure alike and likely situate unto a + figure given. <i>Sn</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/063.png"><img style="width:100%" src="images/063.png" + alt="Like Figures." title="Like Figures." /></a> + </div> + <p><a name="24_e_iiij"></a> 24. <i>Like figures have a reason of their + homologallor correspondent sides equally manifold unto their dimensions: + and a meane proportionall lesse by one</i>.</p> + + <p>Plaine figures have but two dimensions, to witt Length, and Breadth: + And therefore they have but a doubled reason of their homologall sides. + Solids have three dimensions, videl. Length, Breadth, & thicknesse: + therefore they shall have a treabled reason of their homologall or + correspondent sides. In 8. and 18. the two plaines given, first the + angles are equall: secondly, their homolegall side 2. and 4. and 3. and + 6. are proportionall. Therefore the reason of 8. the first figure, unto + 18. the <!-- Page 44 --><span class="pagenum"><a + name="page44"></a>[44]</span>second, is as the reason is of 2. unto 3. + doubled. But the reason of 2. unto 3. doubled, by the 3. chap. ij. of + Arithmeticke, is of 4. to 9. (for 2/3 2/3 is 4/9.) Therefore the reason + of 8. unto 18, that is, of the first figure unto the second, is of 4. + unto 9. In Triangles, which are the halfes of rightangled + parallelogrammes, there is the same truth, and yet by it selfe not + rationall and to be expressed by numbers.</p> + + <p>Said numbers are alike in the trebled reason of their homologall + sides; As for example, 60. and 480. are like solids; and the solids also + comprehended in those numbers are like-solids, as here thou seest: + Because their sides, 4. 3. 5. and 8. 6. 10. are proportionall betweene + themselves. But the reason of 60. to 480. is the reason of 4. to 8. + trebled, thus 4/8 4/8 4/8 = 64/512; that is of 1. unto 8. or + <i>octupla</i>, which you shall finde in the dividing of 480. by 60.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:30%;"> + <a href="images/064.png"><img style="width:100%" src="images/064.png" + alt="Like Solids." title="Like Solids." /></a> + </div> + <p>Thus farre of the first part of this element: The second, that like + figurs have a meane, proportional lesse by one, then are their + dimensions, shall be declared by few words. For plaines having but two + dimensions, have but one meane proportionall, solids having three + dimensions, have two meane proportionalls. The cause is onely + Arithmeticall, as afore. For where the bounds are but 4. as they are in + two plaines, there can be found no more but one meane proportionall, as + in the former example of 8. and 18. where the homologall or correspondent + sides are 2. 3. and 4. 6.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> +<table class="nobctr"> +<tr><td class="spac">2</td><td class="spac">3</td><td class="spac">4</td><td class="spac">6</td></tr> +<tr><td class="spac"> </td><td class="spac">3</td><td class="spac">4</td><td class="spac"> </td></tr> +<tr><td class="spac">8</td><td class="spac" colspan="2" align="center">12</td><td class="spac">18</td></tr> +</table> + +<p><!-- Page 45 --><span class="pagenum"><a name="page45"></a>[45]</span></p> + + <p>Againe by the same rule, where the bounds are 6. as they are in two + solids, there may bee found no more but two meane proportionalls: as in + the former solids 30. and 240. where the homologall or correspondent + sides are 2. 4. 3. 6. 5. 10.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> +<table class="nobctr"> +<tr><td class="spac">2</td><td class="spac">4</td><td class="spac">3</td><td class="spac">6</td><td class="spac">5</td><td class="spac">10</td></tr> +<tr><td class="spac"> </td><td class="spac">4</td><td class="spac">3</td><td class="spac"> </td></tr> +<tr><td class="spac">6</td><td class="spac" colspan="2" align="center">12</td><td class="spac">24</td></tr> +<tr><td class="spac" colspan="3"> </td><td class="spac">24</td><td class="spac">5</td></tr> +<tr><td class="spac"> </td><td class="spac">30</td><td class="spac">60</td><td class="spac">120</td><td class="spac" colspan="2" align="center">240</td></tr> +</table> + + <div class="figcenter" style="width:50%;"> + <a href="images/065a.png"><img style="width:100%" src="images/065a.png" + alt="Creation of Like Figures." title="Creation of Like Figures." /></a> + </div> + <div class="figcenter" style="width:45%;"> + <a href="images/065b.png"><img style="width:100%" src="images/065b.png" + alt="Creation of Like Solids." title="Creation of Like Solids." /></a> + </div> +<p><!-- Page 46 --><span class="pagenum"><a name="page46"></a>[46]</span></p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="25_e_iiij"></a> 25. <i>If right lines be continually + proportionall, more by one then are the dimensions of like figures + likelily situate unto the first and second, it shall be as the first + right line is unto the last, so the first figure shall be unto the + second: And contrariwise</i>.</p> + + <p>Out of the similitude of figures two consectaries doe arise, in part + only, as is their axiome, rationall and expressable by numbers. If three + right lines be continually proportionall, it shall be as the first is + unto the third: So the <span class="correction" title="text reads `rectineall'" + >rectilineall</span> figure made upon the first, shall be unto the + rectilineall figure made upon the second, alike and likelily situate. + This may in some part be conceived and understood by numbers. As for + example, Let the lines given, be 2. foot, 4. foote, and 8 foote. And upon + the first and second, let there be made like figures, of 6. foote and 24. + foote; So I meane, that 2. and 4. be the bases of them. Here as 2. the + first line, is unto 8. the third line: So is 6. the first figure, unto + 24. the second figure, as here thou seest.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/066.png"><img style="width:100%" src="images/066.png" + alt="Proportionall Lines and Figures." title="Proportionall Lines and Figures." /></a> + </div> + <p>Againe, let foure lines continually proportionall, be 1. 2. 4. 8. And + let there bee two like solids made upon the first and second: upon the + first, of the sides 1. 3. and 2. <span class="correction" title="text reads `lee'" + >let</span> it be 6. Upon the second, of the sides 2. 6. and 4. let it be + 48. As the first right line 1. is unto the fourth 8. So is the figure 6. + unto the second 48. as is manifest by division. The examples are thus. + <!-- Page 47 --><span class="pagenum"><a + name="page47"></a>[47]</span></p> + + <div class="figcenter" style="width:50%;"> + <a href="images/067a.png"><img style="width:100%" src="images/067a.png" + alt="Proportionall Lines and Solids." title="Proportionall Lines and Solids." /></a> + </div> + <p>Moreover by this Consectary a way is laid open leading unto the reason + of doubling, treabling, or after any manner way whatsoever assigned + increasing of a figure given. For as the first right line shall be unto + the last: so shall the first figure be unto the second.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="26_e_iiij"></a> 26. <i>If foure right lines bee proportionall + betweene themselves: Like figures likelily situate upon them, shall be + also proportionall betweene themselves: And contrariwise, out of the 22. + p vj. and 37. p xj</i>.</p> + + <p>The proportion may also here in part bee expressed by numbers: And yet + a continuall is not required, as it was in the former.</p> + +<p><!-- Page 48 --><span class="pagenum"><a name="page48"></a>[48]</span></p> + + <p>In Plaines let the first example be, as followeth.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/067b.png"><img style="width:100%" src="images/067b.png" + alt="Two Pairs of Figures." title="Two Pairs of Figures." /></a> + </div> + <p>The cause of proportionall figures, for that twice two figures have + the same reason doubled.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/068.png"><img style="width:100%" src="images/068.png" + alt="Two Pairs of Solids." title="Two Pairs of Solids." /></a> + </div> + <p>In Solids let this bee the second example. And yet here the figures + are not proportionall unto the right lines, as before figures of equall + heighth were unto their bases, but they themselves are proportionall one + to another. And yet are they not proportionall in the same kinde of + proportion.</p> + + <p>The cause also is here the same, that was before: To witt, because + twice two figures have the same reason trebled.</p> + + <p><a name="27_e_iiij"></a> 27. <i>Figures filling a place, are those + which being any way set about the same point, doe leave no voide + roome</i>.</p> + + <p>This was the definition of the ancient Geometers, as appeareth out of + <i>Simplicius</i>, in his commentaries upon the 8. chapter of + <i>Aristotle's</i> iij. booke of Heaven: which kinde of figures + <i>Aristotle</i> in the same place deemeth to bee onely ordinate, and yet + not all of that kind. But only three among the Plaines, to witt a + Triangle, a Quadrate, and a Sexangle: amongst Solids, two; the Pyramis, + and the Cube. But if the filling of a place bee judged by right angles, + 4. in a Plaine, and 8. in a Solid, the Oblong of plaines, and the <!-- + Page 49 --><span class="pagenum"><a + name="page49"></a>[49]</span>Octahedrum of Solids shall (as shall appeare + in their places) fill a place; And yet is not this Geometrie of + <i>Aristotle</i> accurate enough. But right angles doe determine this + sentence, and so doth <i>Euclide</i> out of the angles demonstrate, That + there are onely five ordinate solids; And so doth <i>Potamon</i> the + Geometer, as <i>Simplicus</i> testifieth, demonstrate the question of + figures filling a place. Lastly, if figures, by laying of their corners + together, doe make in a Plaine 4. right angles, or in a Solid 8. they doe + fill a place.</p> + + <p>Of this probleme the ancient geometers have written, as we heard even + now: And of the latter writers, <i>Regiomontanus</i> is said to have + written accurately; And of this argument <i>Maucolycus</i> hath promised + a treatise, neither of which as yet it hath beene our good hap to + see.</p> + + <p><i>Neither of these are figures of this nature, as in their due places + shall be proved and demonstrated</i>.</p> + + <p><a name="28_e_iiij"></a> 28. <i>A round figure is that, all whose + raies are equall</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/069.png"><img style="width:100%" src="images/069.png" + alt="Round Objects." title="Round Objects." /></a> + </div> + <p>Such in plaines shall the Circle be, in Solids the Globe or Spheare. + Now this figure, the Round, I meane, of all Isoperimeters is the + greatest, as appeared before at the <a href="#15_e_iiij">15. e</a>. For + which cause <i>Plato</i>, in his <i>Timæus</i> or his Dialogue of the + World said; That this figure is of all other the greatest. And therefore + God, saith he, did make the world of a <!-- Page 50 --><span + class="pagenum"><a name="page50"></a>[50]</span>sphearicall forme, that + within his compasse it might the better containe all things: And + <i>Aristotle</i>, in his Mechanicall problems, saith; That this figure is + the beginning, principle, and cause of all miracles. But those miracles + shall in their time God willing, be manifested and showne.</p> + + <p><i>Rotundum</i>, a Roundle, let it be here used for <i>Rotunda + figura</i>, a round figure. And in deede <i>Thomas Finkius</i> or + <i>Finche</i>, as we would call him, a learned <i>Dane</i>, sequestring + this argument from the rest of the body of Geometry, hath intituled that + his worke <i>De Geometria rotundi</i>, Of the Geometry of the Round or + roundle.</p> + + <p><a name="29_e_iiij"></a> 29. <i>The diameters of a roundle are cut in + two by equall raies</i>.</p> + + <p>The reason is, because the halfes of the diameters, are the raies. Or + because the diameter is nothing else but a doubled ray: Therefore if thou + shalt cut off from the diameter so much, as is the radius or ray, it + followeth that so much shall still remaine, as thou hast cutte of, to + witt one ray, which is the other halfe of the diameter. <i>Sn</i>.</p> + + <p>And here observe, That <i>Bisecare</i>, doth here, and in other places + following, signifie to cutte a thing into two equall parts or portions; + And so <i>Bisegmentum</i>, to be one such portion; And <i>Bisectio</i>, + such a like cutting or division.</p> + + <p><a name="30_e_iiij"></a> 30. <i>Rounds of equall diameters are equall. + Out of the 1. d. iij</i>.</p> + + <p>Circles and Spheares are equall, which have equall diameters. For the + raies, which doe measure the space betweene the Center and Perimeter, are + equall, of which, being doubled, the Diameter doth consist. + <i>Sn</i>.</p> + +<hr class="full" /> + +<p><!-- Page 51 --><span class="pagenum"><a name="page51"></a>[51]</span></p> + +<h2>The fifth Booke, of <i>Ramus</i> his +Geometry, +which is of Lines and +Angles in a plaine Surface.</h2> + + <p><a name="1_e_v"></a> 1. <i>A lineate is either a Surface or a + Body</i>.</p> + + <p><i>Lineatum</i>, (or <i>Lineamentum</i>) a magnitude made of lines, as + was defined at <a href="#1_e_iij">1. e. iij</a>. is here divided into two + kindes: which is easily conceived out of the said definition there, in + which a line is excluded, and a Surface & a body are comprehended. + And from hence arose the division of the arte Metriall into Geometry, of + a surface, and Stereometry, of a body, after which maner <i>Plato</i> in + his vij. booke of his Common-wealth, and <i>Aristotle</i> in the 7. + chapter of the first booke of his <i>Posteriorums</i>, doe distinguish + betweene Geometry and Stereometry: And yet the name of Geometry is used + to signifie the whole arte of measuring in generall.</p> + + <p><a name="2_e_v"></a> 2. <i>A Surface is a lineate only broade. 5. d + j</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/071.png"><img style="width:100%" src="images/071.png" + alt="Surfaces." title="Surfaces." /></a> + </div> + <p>As here <i>aeio.</i> and <i>uysr.</i> The definition of a Surface doth + comprehend the distance or dimension of a line, to <!-- Page 52 --><span + class="pagenum"><a name="page52"></a>[52]</span>witt Length: But it + addeth another distance, that is Breadth. <span class="correction" + title="text reads `Therefoce'">Therefore</span> a Surface is defined by + some, as <i>Proclus</i> saith, to be a magnitude of two dimensions. But + two doe not so specially and so properly define it. Therefore a Surface + is better defined, to bee a magnitude onely long and broad. Such, saith + <i>Apollonius</i>, are the shadowes upon the earth, which doe farre and + wide cover the ground and champion fields, and doe not enter into the + earth, nor have any manner of thicknesse at all.</p> + + <p><i>Epiphania</i>, the Greeke word, which importeth onely the outter + appearance of a thing, is here more significant, because of a Magnitude + there is nothing visible or to bee seene, but the surface.</p> + + <p><a name="3_e_v"></a> 3. <i>The bound of a surface is a line. 6. d + j</i>.</p> + + <p>The matter in Plaines is manifest. For a three cornered surface is + bounded with 3. lines: A foure cornered surface, with foure lines, and so + forth: A Circle is bounded with one line. But in a Sphearicall surface + the matter is not so plaine: For it being whole, seemeth not to be + bounded with a line. Yet if the manner of making of a Sphearicall + surface, by the conversiō or turning about of a semiperiphery, the + beginning of it, as also the end, shalbe a line, to wit a semiperiphery: + And as a point doth not only <i>actu</i>, or indeede bound and end a + line: But is <i>potentia</i>, or in power, the middest of it: So also a + line boundeth a Surface <i>actu</i>, and an innumerable company of lines + may be taken or supposed to be throughout the whole surface. A Surface + therefore is made by the motion of a line, as a Line was made by the + motion of a point.</p> + + <p><a name="4_e_v"></a> 4. <i>A Surface is either Plaine or + Bowed</i>.</p> + + <p>The difference of a Surface, doth answer to the difference of a Line, + in straightnesse and obliquity or crookednesse.</p> + + <p><i>Obliquum</i>, oblique, there signified crooked; Not right or + straight: Here, uneven or bowed, either upward or downeward. <i>Sn.</i> + <!-- Page 53 --><span class="pagenum"><a + name="page53"></a>[53]</span></p> + + <div class="figright" style="width:16%;"> + <a href="images/073a.png"><img style="width:100%" src="images/073a.png" + alt="Plaine Surface." title="Plaine Surface." /></a> + </div> + <p><a name="5_e_v"></a> 5. <i>A plaine surface is a surface, which lyeth + equally betweene his bounds, out of the 7. d j</i>.</p> + + <p>As here thou seest in <i>aeio.</i> That therefore a Right line doth + looke two contrary waies, a Plaine surface doth looke all about every + way, that a plaine surface should, of all surfaces within the same + bounds, be the shortest: And that the middest thereof should hinder the + sight of the extreames. Lastly, it is equall to the dimension betweene + the lines: It may also by one right line every way applyed be tryed, as + <i>Proclus</i> at this place doth intimate.</p> + + <p><i>Planum</i>, a Plaine, is taken and used for a plaine surface: as + before <i>Rotundum</i>, a Round, was used for a round figure.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="6_e_v"></a> 6. <i>From a point unto a point we may, in a + plaine surface, draw a right line, 1 and 2. post. j</i>.</p> + + <p>Three things are from the former ground begg'd: The first is of a + Right line. A right line and a periphery were in the ij. booke defined: + But the fabricke or making of them both, is here said to bee properly in + a plaine.</p> + + <div class="figcenter" style="width:20%;"> + <a href="images/073b.png"><img style="width:100%" src="images/073b.png" + alt="Right Line." title="Right Line." /></a> + </div> + <p>The fabricke or construction of a right line is the 1. petition. And + justly is it required that it may bee done onely upon a plaine: For in + any other surface it were in vaine to aske it. For neither may wee + possibly in a sphericall betweene two points draw a right line: Neither + may wee possibly in a Conicall and Cylindraceall betweene any two points + assigned draw a right line. For from the toppe <!-- Page 54 --><span + class="pagenum"><a name="page54"></a>[54]</span>unto the base that in + these is only possible: And then is it the bounde of the plaine which + cutteth the Cone and Cylinder. Therefore, as I said, of a right plaine it + may onely justly bee demanded: That from any point assigned, unto any + point assigned, a right line may be drawne, as here from <i>a</i> unto + <i>e</i>.</p> + + <p>Now the Geometricall instrument for the drawing of a right plaine is + called <i>Amussis</i>, & by <i>Petolemey</i>, in the 2. chapter of + his first booke of his Musicke, <i>Regula</i>, a Rular, such as heere + thou seest.</p> + + <div class="figcenter" style="width:60%;"> + <a href="images/074.png"><img style="width:100%" src="images/074.png" + alt="Rular." title="Rular." /></a> + </div> + <p>And from a point unto a point is this justly demanded to be done, not + unto points; For neither doe all points fall in a right line: But many + doe fall out to be in a crooked line. And in a Spheare, a Cone & + Cylinder, a Ruler may be applyed, but it must be a sphearicall, Conicall, + or Cylindraceall. But by the example of a right line doth + <i>Vitellio</i>, 2 <i>p j.</i> demaund that betweene two lines a surface + may be extended: And so may it seeme in the Elements, of many figures + both plaine and solids, by <i>Euclide</i> to be demanded; That a figure + may be described, at the 7. and 8. e ij. Item that a figure may be made + vp, at the 8. 14. 16. 23. 28. p. vj. which are of Plaines. Item at the + 25. 31. 33. 34. 36. 49. p. xj. which are of Solids. Yet notwithstanding a + plaine surface, and a plaine body doe measure their rectitude by a right + line, so that <i>jus postulandi</i>, this right of begging to have a + thing granted may seeme primarily to bee in a right plaine line.</p> + + <p>Now the <i>Continuation</i> of a right line is nothing else, but the + drawing out farther of a line now drawne, and that from a point unto a + point, as we may continue the right line <i>ae.</i> unto <i>i.</i> + wherefore the first and second Petitions of <i><span class="correction" + title="text reads `Euclde'">Euclide</span></i> do agree in one.</p> + +<p><!-- Page 55 --><span class="pagenum"><a name="page55"></a>[55]</span></p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/075.png"><img style="width:100%" src="images/075.png" + alt="Operations with Lines." title="Operations with Lines." /></a> + </div> + <p><a name="7_e_v"></a> 7. <i>To set at a point assigned a Right line + equall to another right line given: And from a greater, to cut off a part + equall to a lesser. 2. and 3. p j</i>.</p> + + <p>As let the Right line given be <i>ae.</i> And to <i>i.</i> a point + assigned, grant that <i>io.</i> equall to the same <i>ae.</i> may bee + set. Item, in the second example, let <i>ae.</i> bee greater then + <i>io.</i> And let there <span class="correction" title="text reads `he'" + >be</span> cut off from the same <i>ae.</i> by applying of a rular made + equall to <i>io.</i> <span class="correction" title="text reads `the the' over two lines" + >the</span> lesser, portion <i>au.</i> as here. For if any man shall + thinke that this ought only to be don in the minde, hee also, as it were, + beares a ruler in his minde, that he may doe it by the helpe of the + ruler. Neither is the fabricke in deede, or making of one right equal to + another: And the cutting off from greater Right line, a portion equall to + a lesser, any whit harder, then it was, having a point and a distance + given, to describe a circle: Then having a Triangle, Parallelogramme, and + semicircle given, to describe or make a Cone, Cylinder, and spheare, all + which notwithstanding <i>Euclide</i> did account as principles.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="8_e_v"></a> 8. <i>One right line, or two cutting one another, + are in the same plaine, out of the 1. and 2. p xj</i>.</p> + + <p>One Right line may bee the common section of two plaines: yet all or + the whole in the same plaine is one: And all the whole is in the same + other: And so the whole is the same plaine. Two Right lines cutting one + another, may bee in two plaines cutting one of another; But then a plaine + may be drawne by them: Therefore both <!-- Page 56 --><span + class="pagenum"><a name="page56"></a>[56]</span>of them shall be in the + same plaine. And this plaine is geometrically to be conceived: Because + the same plaine is not alwaies made the ground whereupon one oblique + line, or two cutting one another are drawne, when a periphery is in a + sphearicall: Neither may all peripheries cutting one another be possibly + in one plaine.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_v"></a> 9. <i>With a right line given to describe a + peripherie</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/076.png"><img style="width:100%" src="images/076.png" + alt="To Describe a Peripherie." title="To Describe a Peripherie." /></a> + </div> + <p>This fabricke or construction is taken out of the 3. Petition which is + thus. Having a center and a distance given to describe, make, or draw a + circle. But here the terme or end of a circle is onely sought, which is + better drawne out of the definition of a periphery, at the <a + href="#10_e_ij">10. e ij</a>. And in a plaine onely may that conversion + or turning about of a right line bee made: Not in a sphearicall, not in a + Conicall, not in a Cylindraceall, except it be in top, where + notwithstanding a periphery may bee described. Therefore before (to witt + at the said <a href="#10_e_ij">10. e ij</a>.) was taught the generall + fabricke or making of a Periphery: Here we are informed how to discribe a + Plaine periphery, as here.</p> + + <p>Now as the Rular was the instrument invented and used for the drawing + of a right line: so also may the same <i>Rular</i>, used after another + manner, be the instrument to describe or draw a periphery withall. And + indeed such is that instrument used by the Coopers (and other like + artists) for the rounding of their bottomes of their tubs, heads of + barrells and otherlike vessells: But the <i>Compasses</i>, whether + straight shanked or bow-legg'd, such as here thou seest, it skilleth not, + are for al purposes and practises, in this case the best and readiest. + And in deed the Compasses, of all <!-- Page 57 --><span + class="pagenum"><a name="page57"></a>[57]</span>geometricall instruments, + are the most excellent, and by whose help famous Geometers have taught: + That all the problems of geometry may bee wrought and performed: And + there is a booke extant, set out by <i>John Baptist</i>, an Italian, + teaching, How by one opening of the Compasses all the problems of + <i>Euclide</i> may be resolved: And <i>Jeronymus Cardanus</i>, a famous + Mathematician, in the 15. booke of his Subtilties, writeth, that there + was by the helpe of the Compasses a demonstration of all things + demonstrated by <i>Euclide</i>, found out by him and one + <i>Ferrarius</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/077.png"><img style="width:100%" src="images/077.png" + alt="Types of Compasses." title="Types of Compasses." /></a> + </div> + <p><i>Talus</i>, the nephew of <i>Dædalus</i> by his sister, is said in + the viij. booke of <i>Ovids Metamorphosis</i>, to have beene the + inventour of this instrument: For there he thus writeth of him and this + matter:—<i>Et ex uno duo ferrea brachia nodo: Iunxit, ut æquali + spatio distantibus ipsis: Altera pars staret, pars altera duceret + orbem</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therfore</p> + </div> + </div> + <p><a name="10_e_v"></a> 10. <i>The raies of the same, or of an equall + periphery, are equall</i>.</p> + + <p>The reason is, because the same right line is every where converted or + turned about. But here by the Ray of the periphery, must bee understood + the Ray the figure contained within the periphery. <!-- Page 58 --><span + class="pagenum"><a name="page58"></a>[58]</span></p> + + <div class="figright" style="width:15%;"> + <a href="images/078.png"><img style="width:100%" src="images/078.png" + alt="Bisecting an Angle." title="Bisecting an Angle." /></a> + </div> + <p><a name="11_e_v"></a> 11. <i>If two equall peripheries, from the ends + of equall shankes of an assigned rectilineall angle, doe meete before it, + a right line drawne from the meeting of them unto the toppe or point of + the angle, shall cut it into two equall parts. 9. p j</i>.</p> + + <p>Hitherto we have spoken of plaine lines: Their affection followeth, + and first in the Bisection or dividing of an Angle into two equall + parts.</p> + + <p>Let the right lined Angle to bee divided into two equall parts bee + <i>eai.</i> whose equall shankes let them be <i>ae.</i> and <i>ai.</i> + (or if they be unequall, let them be made equall, by the <a + href="#7_e_v">7 e</a>.) Then two equall peripheries from the ends + <i>e</i> and <i>i.</i> meet before the Angle in <i>o</i>. Lastly, draw a + line from <i>o.</i> unto <i>a</i>. I say the angle given is divided into + two equall parts. For by drawing the right lines <i>oe.</i> and + <i>oi.</i> the angles <i>oae.</i> and <i>oai.</i> equicrurall, by the + grant, and by their common side <i>ao.</i> are equall in base <i>eo.</i> + and <i>io.</i> by the <a href="#10_e_v">10 e</a> (Because they are the + raies of equall peripheries.) Therefore by the <a href="#7_e_iij">7. e + iij</a>. the angles <i>oae.</i> and <i>oai.</i> are equall: And therefore + the Angle <i>eai.</i> is equally divided into two parts.</p> + + <p><a name="12_e_v"></a> 12. <i>If two equall peripheries from the ends + of a right line given, doe meete on each side of the same, a right line + drawne from those meetings, shall divide the right line given into two + equall parts. 10. p j</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/079a.png"><img style="width:100%" src="images/079a.png" + alt="Bisecting a Line." title="Bisecting a Line." /></a> + </div> + <p>Let the right line given bee <i>ae.</i> And let two equall peripheries + from the ends <i>a.</i> and <i>e.</i> meete in <i>i.</i> and <i>o.</i> + Then from those meetings let the right line <i>io.</i> be drawne. I say, + That <i>ae.</i> is divided into two equall parts, by the said line thus + <!-- Page 59 --><span class="pagenum"><a + name="page59"></a>[59]</span>drawne. For by drawing the raies of the + equall peripheries <i>ia.</i> and <i>ie.</i> the said <i>io.</i> doth cut + the angle <i>aie.</i> into two equall parts, by the <a href="#11_e_v">11. + e</a>. Therefore the angles <i>aiu.</i> and <i>uie.</i> being equall and + equicrurall (seeing the shankes are the raies of equall peripheries, by + the grant.) have equall bases <i>au.</i> and <i>ue.</i> by the <a + href="#7_e_iij">7. e iij</a>. Wherefore seeing the parts <i>au.</i> and + <i>ue.</i> are equall, <i>ae.</i> the assigned right line is divided into + two equall portions.</p> + + <div class="figright" style="width:8%;"> + <a href="images/080b.png"><img style="width:100%" src="images/080b.png" + alt="Plumbe-rule." title="Plumbe-rule." /></a> + </div> + <div class="figright" style="width:15%;"> + <a href="images/079b.png"><img style="width:100%" src="images/079b.png" + alt="Perpendicular Lines." title="Perpendicular Lines." /></a> + </div> + <p><a name="13_e_v"></a> 13. <i>If a right line doe stand perpendicular + upon another right line, it maketh on each side right angles: And + contrary wise</i>.</p> + + <p>A right line standeth upon a right line, which cutteth, and is not cut + againe. And the <i>Angles on each side</i>, are they which the falling + line maketh with that underneath it, as is manifest out of + <i>Proclus</i>, at the 15. pj. of <i>Euclide</i>; As here <i>ae.</i> the + line cut: and <i>io.</i> the insisting line, let them be perpendicular; + The angles on each side, to witt <i>aio.</i> and <i>eio.</i> shall bee + right angles, by the <a href="#13_e_iij">13. e iij</a>.</p> + + <p>The <i>Rular</i>, for the making of straight lines on a plaine, was + the first Geometricall instrument: The <i>Compasses</i>, for the + describing of a Circle, was the second: The <i>Norma</i> or <i>Square</i> + for the true erecting of a right line in the same plaine upon another + right line, and then of a surface and body, upon a surface or body, is + the third. The figure therefore is thus.</p> + + <p>Now <i>Perpendiculū</i>, an instrument with a line & a + plummet of leade appendant upon it, used of Architects, Carpenters, and + Masons, is meerely physicall: because heavie things <!-- Page 60 --><span + class="pagenum"><a name="page60"></a>[60]</span>naturally by their weight + are in straight lines carried perpendicularly downeward. This instrument + is of two sorts: The first, which they call a Plumbe-rule, is for the + trying of an erect perpendicular, as whether a columne, pillar, or any + other kinde of building bee right, that is plumbe unto the plaine of the + horizont & doth not leane or reele any way. The second is for the + trying or examining of a plaine or floore, whether it doe lye parallell + to the horizont or not. Therefore when the line from the right angle, + doth fall upon the middle of the base; it shall shew that the length is + equally poysed. The Latines call it <i>Libra</i>, or <i>Libella</i>, a + ballance: of the <i>Italians Livello</i>, and vel <i>Archipendolo</i>, + <i>Achildulo</i>: of the <i>French</i>, <i>Nivelle</i>, or <i>Niueau</i>: + of us a <i>Levill</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/080a.png"><img style="width:100%" src="images/080a.png" + alt="Square and Level." title="Square and Level." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/081b.png"><img style="width:100%" src="images/081b.png" + alt="Figure for demonstration 14 converse." title="Figure for demonstration 14 converse." /></a> + </div> + <div class="figright" style="width:20%;"> + <a href="images/081a.png"><img style="width:100%" src="images/081a.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p><a name="14_e_v"></a> 14. <i>If a right line do stand upon a right + line, it maketh the angles on each side equall to two right angles: and + contrariwise out of the 13. and</i> 14. <i>p j</i>.</p> + + <p>For two such angles doe occupy or fill the same place that two right + angles doe: Therefore <!-- Page 61 --><span class="pagenum"><a + name="page61"></a>[61]</span>they are equall to them by the 11. e j. If + the insisting line be perpendicular unto that underneath it, it then + shall make 2. right angles, by the <a href="#13_e_v">13. e</a>. If it bee + not perpendicular, & do make two oblique angles, as here <i>aio.</i> + and <i>oie.</i> are yet shall they occupy the same place that two right + angles doe: And therefore they are equall to two right angles, by the + same.</p> + + <p>The converse is forced by an argument <i>ab impossibli</i>, or <i>ab + absurdo</i>, from the absurdity which otherwise would follow of it: For + the part must otherwise needes bee equall to the whole. Let therefore the + insisting or standing line which maketh two angles <i>aeo.</i> and + <i>aeu.</i> on each side equall to two right angles, be <i>ae.</i> I say + that <i>oe.</i> and <i>ei.</i> are but one right line. Otherwise let + <i>oe.</i> bee continued unto <i>u.</i> by the <a href="#6_e_v">6. e</a>. + Now by the <a href="#14_e_v">14. e.</a> or next former element, + <i>aeo.</i> & <i>aeu.</i> are equall to two right angles; To which + also <i>oea.</i> & <i>aei.</i> are equall by the grant: Let + <i>aeo.</i> the common angle be taken away: then shall there be left + <i>aeu.</i> equall to <i>aei.</i> the part to the whole, which is absurd + and impossible. Herehence is it certaine that the two right lines + <i>oe,</i> and <i>ei,</i> are in deede but one continuall right line.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/082a.png"><img style="width:100%" src="images/082a.png" + alt="Right Lines Cutting." title="Right Lines Cutting." /></a> + </div> + <p><a name="15_e_v"></a> 15. <i>If two right lines doe cut one another, + they doe make the angles at the top equall and all equall to foure right + angles. 15. p j</i>.</p> + + <p><i>Anguli ad verticem</i>, Angles at the top or head, are called + Verticall angles which have their toppes meeting in the same point. The + Demonstration is: Because the lines cutting one another, are either + perpendiculars, and then all <!-- Page 62 --><span class="pagenum"><a + name="page62"></a>[62]</span>right angles are equall as heere: Or else + they are oblique, and then also are the verticalls equall, as are + <i>aui</i>, and <i>oue</i>: And againe, <i>auo</i>, and <i>iue</i>. Now + <i>aui</i>, and <i>oue</i>, are equall, because by the <a + href="#14_e_v">14. e.</a> with <i>auo</i>, the common angle, they are + equall to two right angles: And therefore they are equall betweene + themselves. Wherefore <i>auo</i>, the said common angle beeing taken + away, they are equall one to another.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="16_e_v"></a> 16. <i>If two right lines cut with one right + line, doe make the inner angles on the same side greater then two right + angles, those on the other side against them shall be lesser then two + right angles</i>.</p> + + <p><span class="correction" title="text reads `A'">As</span> here, if + <i>auy</i>, and <i>uyi</i>, bee greater then two right angles <i>euy</i>, + and <i>uyo</i>, shall bee lesser then two right angles.</p> + + <div class="figcenter" style="width:20%;"> + <a href="images/082b.png"><img style="width:100%" src="images/082b.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p><a name="17_e_v"></a> 17. <i>If from a point assigned of an infinite + right line given, two equall parts be on each side cut off: and then from + the points of those sections two equall circles doe meete, a right line + drawne from their meeting unto the point assigned, shall bee + perpendicular unto the line given. 11. p j</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/083a.png"><img style="width:100%" src="images/083a.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> + <p>As let <i>a</i>, be the point assigned of the infinite line given: and + from that on each side, by the <a href="#7_e_v">7. e.</a> cut off equall + <!-- Page 63 --><span class="pagenum"><a + name="page63"></a>[63]</span>portions <i>ae</i>, and <i>ai</i>, Then let + two equall peripheries from the points <i>e</i>, and <i>i</i>, meete, as + in <i>o</i>, I say that a right line drawne from <i>o</i>, the point of + the meeting of the peripheries. unto <i>a.</i> the point given, shalbe + perpendicular upon the line given. For drawing the right lines <i>oe</i>, + & <i>oi</i>, the two angles <i>eao</i>, and <i>iao</i>, on each side, + equicrurall by the construction of equall segments on each side, and + <i>oa</i>, the common side, are equall in base by the <a href="#9_e_v">9. + e</a>. And therefore the angles themselves shall be equall, by the <a + href="#7_e_iij">7. e iij</a>. and therefore againe, seeing that + <i>ao</i>, doth lie equall betweene the parts <i>ea</i>, and <i>ia</i>, + it is by the <a href="#13_e_ij">13. e ij</a>. perpendicular upon it.</p> + + <p><a name="18_e_v"></a> 18. <i>If a part of an infinite right line, bee + by a periphery for a point given without, cut off a right line from the + said point, cutting in two the said part, shall bee perpendicular upon + the line given. 12. p j</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/083b.png"><img style="width:100%" src="images/083b.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p>Of an infinite right line given, let the part cut off by a periphery + of an externall center be <i>ae</i>: And then let <i>io</i>, cut the said + part into two parts by the <a href="#12_e_v">12. e</a>. I say that + <i>io</i> is perpendicular unto the said infinite right line. For it + standeth upright, and maketh <i>aoi</i>, and <i>eoi</i>, equall angles, + for the same cause, whereby the next former perpendicular was + demonstrated.</p> + + <p><a name="19_e_v"></a> 19. <i>If two right lines drawne at length in + the same plaine doe never meete, they are parallells. è 35. d j.</i></p> + + <div class="figleft" style="width:13%;"> + <a href="images/084a.png"><img style="width:100%" src="images/084a.png" + alt="Parallel lines." title="Parallel lines." /></a> + </div> + <p>Thus much of the Perpendicularity of plaine right lines: + <i>Parallelissmus</i>, or their parallell equality doth follow. <!-- Page + 64 --><span class="pagenum"><a name="page64"></a>[64]</span><i>Euclid</i> + did justly require these lines so drawne to be granted paralels: for then + shall they be alwayes equally distant, as here <i>ae.</i> and + <i>io</i>.</p> + + <p> Therefore</p> + + <p><a name="20_e_v"></a> 20. <i>If an infinite right line doe cut one of + the infinite right parallell lines, it shall also cut the other</i>.</p> + + <p>As in the same example <i>uy.</i> cutting <i>ae.</i> it shall also cut + <i>io.</i> Otherwise, if it should not cut it, it should be parallell + unto it, by the <a href="#18_e_v">18 e</a>. And that against the + grant.</p> + + <p><a name="21_e_v"></a> 21. <i>If right lines cut with a right line be + pararellells, they doe make the inner angles on the same side equall to + two right angles: And also the alterne angles equall betweene themselves: + And the outter, to the inner opposite to it: And contrariwise,</i> 29, + 28, 27. p 1.</p> + + <div class="figright" style="width:15%;"> + <a href="images/084b.png"><img style="width:100%" src="images/084b.png" + alt="Perpendicular to Parallel lines." title="Perpendicular to Parallel lines." /></a> + </div> + <p>The paralillesme, or parallell-equality of right lines cut with a + right line, concludeth a threefold equality of angles: And the same is + againe of each of them concluded. Therefore in this one element there are + sixe things taught; all which are manifest if a perpendicular, doe fall + <!-- Page 65 --><span class="pagenum"><a + name="page65"></a>[65]</span>upon two parallell lines. The first sort of + angles are in their owne words plainely enough expressed. But the word + <i>Alternum</i>, alterne [or <i>alternate</i>, <i>H.</i>] here, as + <i>Proclus</i> saith, signifieth situation, which in Arithmeticke + signified proportion, when the antecedent was compared to the consequent; + notwithstanding the metaphor answereth fitly. For as an acute angle is + unto his successively following obtuse; So on the other part is the acute + unto his successively following obtuse: Therefore alternly, As the acute + unto the acute: so is the obtuse, unto the obtuse. But the outter and + inner are opposite, of the which the one is without the parallels; the + other is within on the same part not successively; but upon the same + right line the third from the outer.</p> + + <p>The cause of this threefold propriety is from the perpendicular or + plumb-line, which falling upon the parallells breedeth and discovereth + all this variety: As here they are right angles which are the inner on + the same part or side: Item, the alterne angles: Item the inner and the + outter: And therefore they are equall, both, I meane, the two inner to + two right angles: and the alterne angles between themselvs: And the + outter to the inner opposite to it.</p> + + <p>If so be that the cutting line be oblique, that is, fall not upon them + plumbe or perpendicularly, the same shall on the contrary befall the + parallels. For by that same obliquation or slanting, the right lines + remaining and the angles unaltered, in like manner both one of the inner, + to wit, <i>euy</i>, is made obtuse, the other, to wit, <i>uyo</i>, is + made acute: And the alterne angles are made acute and obtuse: As also the + outter and inner opposite are likewise made acute and obtuse.</p> + + <p>If any man shall notwithstanding say, That the inner angles are + unequall to two right angles: By the same argument may he say (saith + <i>Ptolome</i> in <i>Proclus</i>) That on each side they be both greater + than two right angles, and also lesser: As in the parallel right lines + <i>ae</i> and <i>io</i>, cut with <!-- Page 66 --><span + class="pagenum"><a name="page66"></a>[66]</span>the right line <i>uy</i>, + if thou shalt say that <i>auy</i> and <i>iyu</i>, are greater then two + right angles, the angles on the other side, by the <a href="#16_e_v">16 + e</a>, shall be lesser then two right angles, which selfesame + notwithstanding are also, by the gainesayers graunt, greater then two + right angles, which is impossible.</p> + + <div class="figright" style="width:20%;"> + <a href="images/086a.png"><img style="width:100%" src="images/086a.png" + alt="Line crossing Parallel lines." title="Line crossing Parallel lines." /></a> + </div> + <p>The same impossibility shall be concluded, if they shall be sayd, to + be lesser than two right angles.</p> + + <p>The second and third parts may be concluded out of the first. The + second is thus: Twise two angles are equall to two right angles + <i>oyu</i>, and <i>euy</i>, by the former part: Item, <i>auy</i>, and + <i>euy</i>, by the <a href="#14_e_v">14 e</a>. Therefore they are equall + betweene themselves. Now from the equall, Take away <i>euy</i>, the + common angle, And the remainders, the alterne angles, at <i>u</i>, and + <i>y</i> shall be least equall.</p> + + <p>The third is thus: The angles <i>euy</i>, and <i>oys</i>, are equall + to the same <i>uyi</i>, by the second propriety, and by the <a + href="#15_e_v">15 e</a>. Therefore they are equall betweene + themselves.</p> + + <p>The converse of the first is here also the more manifest by that light + of the common perpendicular, And if any man shall thinke, That although + the two inner angles be equall to two right angles, yet the right may + meete, as if those equall angles were right angles, as here; it must + needes be that two right lines divided by a common perpendicular, should + both leane, the one this way, the other that way, or at least one of + them, contrary to the <a href="#13_e_ij">13 e ij</a>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/086b.png"><img style="width:100%" src="images/086b.png" + alt="Converse cases." title="Converse cases." /></a> + </div> + <p>If they be oblique angles, as here, the lines one slanting or <!-- + Page 67 --><span class="pagenum"><a + name="page67"></a>[67]</span>obliquely crossing one another, the angles + on one side will grow lesse, on the other side greater. Therefore they + would not be equall to two right angles, against the graunt.</p> + + <p>From hence the second and third parts may be concluded. The second is + thus: The alterne angles at <i>u</i> and <i>y</i>, are equall to the + foresayd inner angles, by the 14 e: Because both of them are equall to + the two right angles: And so by the first part the second is + concluded.</p> + + <p>The third is therefore by the second demonstrated, because the outter + <i>oys</i>, is equall to the verticall or opposite angle at the top, by + the <a href="#15_e_v">15 e</a>. Therefore seeing the outter and inner + opposite are equall, the alterne also are equall.</p> + + <p>Wherefore as <i>Parallelismus</i>, parallell-equality argueth a + three-fold equality of angles: So the threefold equality of angles doth + argue the same parallel-equality.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <p><a name="22_e_v"></a> 22. <i>If right lines knit together with a right + line, doe make the inner angles on the same side lesser than two right + Angles, they being on that side drawne out at length, will meete</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/087.png"><img style="width:100%" src="images/087.png" + alt="Lines that will meet." title="Lines that will meet." /></a> + </div> + <p>As here <i>ae</i>, and <i>io</i>, knit together with <i>eo</i>, doe + make two angles <i>aeo</i>, and <i>ioe</i>, lesser than two right angles: + They shall therefore, I say, meete if they be continued out that wayward. + The assumption and complexion is out of the <a href="#21_e_v">21 e</a>, + of right lines in the same plaine. If right lines cut with a right line + be parallels, they doe make the inner angles on the same part equall to + two right-angles. Therefore if they doe not make them equall, but lesser, + they shall not be parallel, but shall meete.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 68 --><span class="pagenum"><a name="page68"></a>[68]</span></p> + + <p><a name="23_e_v"></a> 23. <i>A right line knitting together parallell + right lines, is in the same plaine with them.</i> 7 <i>p xj</i>.</p> + + <div class="figcenter" style="width:20%;"> + <a href="images/088a.png"><img style="width:100%" src="images/088a.png" + alt="Line knitting together parallell right lines." title="Line knitting together parallell right lines." /></a> + </div> + <p>As here <i>uy</i>, knitting or joyning together the two parallels + <i>ae</i>, and <i>io</i>, is in the same plaine with them as is manifest + by the <a href="#8_e_v">8 e</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/088b.png"><img style="width:100%" src="images/088b.png" + alt="Alternate angles." title="Alternate angles." /></a> + </div> + <p><a name="24_e_v"></a> 24. <i>If a right line from a point given doe + with a right line given make an angle, the other shanke of the angle + equalled and alterne to the angle made, shall be parallell unto the + assigned right line.</i> 31 <i>p j</i>.</p> + + <p>As let the assigned right line be <i>ae</i>: And the point given, let + it be <i>i</i>. From which the right line, making with the assigned + <i>ae</i>, the angle, <i>ioe</i>, let it be <i>io</i>: To the which at + <i>i</i>, let the alterne angle <i>oiu,</i> be made equall: The right + line <i>ui</i>, which is the other shanke, is parallel to the assigned + <i>ae</i>.</p> + + <p>An angle, I confesse, may bee made equall by the first propriety: And + so indeed commonly the Architects and Carpenters doe make it, by erecting + of a perpendicular. It may also againe in like manner be made by the + outter angle: Any man may at his pleasure use which hee shall thinke + good: But that here taught we take to be the best.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:15%;"> + <a href="images/089a.png"><img style="width:100%" src="images/089a.png" + alt="Parallel shanks." title="Parallel shanks." /></a> + </div> + <p><a name="25_e_v"></a> 25. <i>The angles of shanks alternly parallell, + are equall.</i> Or Thus, <i>The angles whose alternate feete are + parallells, are equall. H</i>.</p> + + <p>This consectary is drawne out of the third property of <!-- Page 69 + --><span class="pagenum"><a name="page69"></a>[69]</span>the <a + href="#21_e_v">21 e</a>. The thing manifest in the example following, by + drawing out, or continuing the other shanke of the inner angle. But + <i>Lazarus Schonerus</i> it seemeth doth thinke the adverbe + <i>alterne</i>, (<i>alternely</i> or <i>alternately</i>) to be more then + needeth: And therefore he delivereth it thus: The angles of parallel + shankes are equall.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="26_e_v"></a> 26. <i>If parallels doe bound parallels, the + opposite lines are equall è</i> 34 <i>p. j.</i> Or thus: <i>If parallels + doe inclose parallels, the opposite parallels are equall. H</i>.</p> + + <div class="figcenter" style="width:20%;"> + <a href="images/089b.png"><img style="width:100%" src="images/089b.png" + alt="Parallels bounding parallels." title="Parallels bounding parallels." /></a> + </div> + <p>Otherwise they should not be parallell. This is understood by the + perpendiculars, knitting them together, which by the definition are + equall betweene two parallells: And if of perpendiculars they bee made + oblique, they shall notwithstanding remaine equall, onely the corners + will be changed.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="27_e_v"></a> 27. <i>If right lines doe joyntly bound on the + same side equall and parallell lines, they are also equall and + parallell</i>.</p> + + <div class="figright" style="width:15%;"> + <a href="images/090b.png"><img style="width:100%" src="images/090b.png" + alt="Not parallel bounds." title="Not parallel bounds." /></a> + </div> + <div class="figright" style="width:20%;"> + <a href="images/090a.png"><img style="width:100%" src="images/090a.png" + alt="Parallel bounds." title="Parallel bounds." /></a> + </div> + <p>This element might have beene concluded out of the next precedent: But + it may also be learned out of those <!-- Page 70 --><span + class="pagenum"><a name="page70"></a>[70]</span>which went before. As let + <i>ae</i>, and <i>io</i>, equall parallels be bounded joyntly of + <i>ai</i>, and <i>eo</i>: and let <i>ei</i> be drawn. Here because the + right line <i>ei</i> falleth upon the parallels <i>ae</i>, and <i>io</i>, + the alterne angles <i>aei</i> and <i>eio</i>, are equall, by the <a + href="#21_e_v">21 e</a>. And they are equall in shankes <i>ae</i>, and + <i>io</i>, by the grants, and <i>ei</i>, is the common shanke: Therefore + they are also equall in base <i>ai</i>, and <i>eo</i>, by the <a + href="#7_e_iij">7 e iij</a>. This is the first: Then by <a + href="#21_e_v">21 e</a>, the alterne angles <i>eia</i>, and <i>ieo</i>, + are equall betweene themselves: And those are made by <i>ai</i> and + <i>eo</i>, cut by the right line <i>ei</i>: Therefore they are parallell; + which was the second.</p> + + <p>On the same part or side it is sayd, least any man might understand + right lines knit together by opposite bounds as here.</p> + + <p><a name="28_e_v"></a> 28. <i>If right lines be cut joyntly by many + parallell right lines, the segments betweene those lines shall bee + proportionall one to another, out of the</i> 2 <i>p vj and</i> 17 <i>p + xj</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/090c.png"><img style="width:100%" src="images/090c.png" + alt="First case: perpendiculars." title="First case: perpendiculars." /></a> + </div> + <p>Thus much of the Perpendicle, and parallell equality of plaine right + lines: Their Proportion is the last thing to be considered of them.</p> + + <p>The truth of this element dependeth upon the nature of the parallells: + And that throughout all kindes of equality and inequality, both greater + and lesser. For if the lines thus cut be perpendiculars, the portions + <!-- Page 71 --><span class="pagenum"><a + name="page71"></a>[71]</span>intercepted betweene the two parallels shall + be equall: for common perpendiculars doe make parallell equality, as + before hath beene taught, and here thou seest.</p> + + <p>If the lines cut be not parallels, but doe leane one toward another, + the portions cut or intercepted betweene them will not be equall, yet + shall they be proportionall one to another. And looke how much greater + the line thus cut is: so much greater shall the intersegments or portions + intercepted be. And contrariwise, Looke how much lesse: so much lesser + shall they be.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/091.png"><img style="width:100%" src="images/091.png" + alt="Cases of non-perpendiculars." title="Cases of non-perpendiculars." /></a> + </div> + <p>The third parallell in the toppe is not expressed, yet must it be + understood.</p> + + <p>This element is very fruitfull: For from hence doe arise and issue, + First the manner of cutting a line according to any rate or proportion + assigned: And then the invention or way to finde out both the third and + fourth proportionalls.</p> + + <p><a name="29_e_v"></a> 29. <i>If a right line making an angle with + another right line, be cut according to any reason [or proportion] + assigned, parallels drawne from the ends of the segments, unto the end of + the sayd right line given and unto some contingent point in the same, + shall cut the line given according to the reason given</i>.</p> + + <p><i>Schoner</i> hath altered this Consectary, and delivereth it <!-- + Page 72 --><span class="pagenum"><a name="page72"></a>[72]</span>thus: + <i>If a right <span class="correction" title="word missing in text" + >line</span> making an angle with a right line given, and knit unto it + with a base, be cut according to any rate assigned, a parallell to the + base from the ends of the segments, shall cut the line given according to + the rate assigned.</i> 9 and 10 p vj.</p> + + <div class="figright" style="width:15%;"> + <a href="images/092a.png"><img style="width:100%" src="images/092a.png" + alt="Division into two parts." title="Division into two parts." /></a> + </div> + <p><i>Punctum contingens</i>, A contingent point, that is falling or + lighting in some place at al adventurs, not given or assigned.</p> + + <p>This is a marvelous generall consectary, serving indifferently for any + manner of section of a right line, whether it be to be cut into two + parts, or three parts, or into as many <span class="correction" + title="text reads `patts'">parts</span>, as you shall thinke good, or + generally after what manner of way soever thou shalt command or desire a + line to be cut or divided.</p> + + <p>Let the assigned Right line to be cut into two equall parts be + <i>ae</i>. And the right line making an angle with it, let it be the + infinite right line <i>ai.</i> Let <i>ao</i>, one portion thereof be cut + off. And then by the <a href="#7_e_v">7 e</a>, let <i>oi</i>, another + part thereof be taken equall to it. And lastly, by the <a + href="#24_e_v">24 e</a>, draw parallels from the points <i>i</i>, and + <i>o</i>, unto <i>e</i>, the end of the line given, and to <i>u</i>; a + contingent point therein. Now the third parallell is understood by the + point <i>a</i>, neither is it necessary that it should be expressed. + Therefore the line <i>ae</i>, by the <a href="#28_e_v">28</a>, is cut + into two equall portions: And as <i>ao</i>, is to <i>oi</i>: So is + <i>au</i>, to <i>ue</i>. But <i>ao</i>, and <i>oi</i>, are halfe parts. + Therefore <i>au</i>, and <i>ue</i>, are also halfe parts.</p> + + <p>And here also is the <a href="#12_e_v">12 e</a> comprehended, although + not in the same kinde of argument, yet in effect the same. But that + argument was indeed shorter, although this be more generall.</p> + + <div class="figright" style="width:15%;"> + <a href="images/092b.png"><img style="width:100%" src="images/092b.png" + alt="Division into three parts." title="Division into three parts." /></a> + </div> + <p>Now let <i>ae</i> be cut into three parts, of which the first let it + bee <!-- Page 73 --><span class="pagenum"><a + name="page73"></a>[73]</span>the halfe of the second: And the second, the + halfe of the third: And the conterminall or right line making an angle + with the sayd assigned line, let it be cut one part <i>ao</i>: Then + double this in <i>ou</i>: Lastly let <i>ui</i> be taken double to + <i>ou</i>, and let the whole diagramme be made up with three parallels + <i>ie</i>, <i>uy</i>, and <i>os</i>, The fourth parallell in the toppe, + as afore-sayd, shall be understood. Therefore that section which was made + in the conterminall line, by the <a href="#28_e_v">28 e</a>, shall be in + the assigned line: Because the segments or portions intercepted are + betweene the parallels.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="30_e_v"></a> 30. <i>If two right lines given, making an + angle, be continued, the first equally to the second, the second + infinitly, parallels drawne from the ends of the first continuation, unto + the beginning of the second, and some contingent point in the same, shall + intercept betweene them the third proportionall. 11. p vj</i>.</p> + + <div class="figleft" style="width:15%;"> + <a href="images/093.png"><img style="width:100%" src="images/093.png" + alt="Third proportional." title="Third proportional." /></a> + </div> + <p>Let the right lines given, making an angle, be <i>ae</i>, and + <i>ai</i>: and <i>ae</i>, the first, let it be continued equally to the + same <i>ai</i>, and the same <i>ai</i>, let it be drawne out infinitly: + Then the parallels <i>ei</i>, and <i>ou</i>, drawne from the ends of the + first continuation, unto <i>i</i>, the beginning of the second: and + <i>u</i>, a contingent point in the second, doe cut off <i>iu</i>, the + third proportionall sought. For by the <a href="#28_e_v">28 e</a>, as + <i>ae</i>, is unto <i>eo</i>, so is <i>ai</i>, unto <i>iu</i>.</p> + + <p> And</p> + + <p><a name="31_e_v"></a> 31. <i>If of three right lines given, the first + and the third making an angle be continued, the first equally to the + second, and the third infinitly; parallels drawne <!-- Page 74 --><span + class="pagenum"><a name="page74"></a>[74]</span>from the ends of the + first continuation, unto the beginning of the second, and some contingent + point, the same shall intercept betweene them the fourth proportionall. + 12. p vj</i>.</p> + + <p>Let the lines given be these: The first <i>ae</i>, the second + <i>ei</i>, the third <i>ao</i>, and let the whole diagramme be made up + according to the prescript of the consectary. Here by <a + href="#28_e_v">28. e</a>, as <i>ae</i>, is to <i>ei</i> so is <i>ao</i>, + to <i>ou</i>. Thus farre <i>Ramus</i>.</p> + + <p><i>Lazarus Schonerus</i>, who, about some 25. yeares since, did revise + and augment this worke of our Authour, hath not onely altered the forme + of these two next precedent consectaries: but he hath also changed their + order, and that which is here the second, is in his edition the third: + and the third here, is in him the second. And to the former declaration + of them, hee addeth these words: From hence, having three lines given, is + the invention of the fourth proportionall; and out of that, having two + lines given, ariseth the invention of the third proportionall.</p> + + <p>2 <i>Having three right lines given, if the first and the third making + an angle, and knit together with a base, be continued, the first equally + to the second; the third infinitly; a parallel from the end of the + second, unto the continuation of the third, shall intercept the fourth + proportionall. 12. p vj</i>.</p> + + <p>The Diagramme, and demonstration is the same with our <a + href="#31_e_v">31. e</a> or 3 c of <i>Ramus</i>.</p> + + <p>3 <i>If two right lines given making an angle, and knit together with + a base, be continued, the first equally to the second, the second + infinitly; a parallell to the base from the end of the first continuation + unto the second, shall intercept the third proportionall. 11. p + vj</i>.</p> + + <p>The Diagramme here also, and demonstration is in all <!-- Page 75 + --><span class="pagenum"><a name="page75"></a>[75]</span>respects the + same with our <a href="#30_e_v">30 e</a>, or 2 c of <i>Ramus</i>.</p> + + <p>Thus farre <i>Ramus</i>: And here by the judgement of the learned + <i>Finkius</i>, two elements of <i>Ptolomey</i> are to be adjoyned.</p> + + <div class="figright" style="width:15%;"> + <a href="images/095.png"><img style="width:100%" src="images/095.png" + alt="Parallels proportional to segments." title="Parallels proportional to segments." /></a> + </div> + <p><a name="32_e_v"></a> 32 <i>If two right lines cutting one another, be + againe cut with many parallels, the parallels are proportionall unto + their next segments</i>.</p> + + <p>It is a consectary out of the <a href="#28_e_v">28 e</a>. For let the + right lines <i>ae.</i> and <i>ai</i>, cut one another at <i>a</i>, and + let two parallell lines <i>uo</i>, and <i>ei</i>, cut them; I say, as + <i>au</i>, is to <i>uo</i>, so <i>ae</i>, is to <i>ei</i>. For from the + end <i>i</i>, let <i>is</i>, be erected parallell to <i>ae</i>, and let + <i>uo</i>, be drawne out untill it doe meete with it. Then from the end + <i>s</i>, let <i>sy</i>, be made parallell to <i>ai</i>: and lastly, let + <i>ea</i>, be drawne out, untill it doe meete with it. Here now + <i>ay</i>, shall be equall to the right line <i>is</i>, that is, by the + <a href="#26_e_v">26. e</a>, to <i>ue</i>: and at length, by the <a + href="#28_e_v">28. e</a>, as <i>ua</i>, is to <i>uo</i>; so is <i>ay</i>, + that is, <i>ue</i>, to <i>os</i>. Therefore, by composition or addition + of <span class="correction" title="text reads `ptoportions'" + >proportions</span>, as <i>ua</i>, is unto <i>uo</i>, so <i>ua</i>, and + <i>ue</i>, shall be unto <i>uo</i>, and <i>os</i>, that is, <i>ei</i>, by + the <a href="#27_e_v">27. e</a>.</p> + + <p>The same <span class="correction" title="text reads `demonstation'" + >demonstration</span> shall serve, if the lines do crosse one another, or + doe vertically cut one another, as in the same diagramme appeareth. For + if the assigned <i>ai</i>, and <i>us</i>, doe cut one another vertically + in <i>o</i>, let them be cut with the parallels <i>au</i>, and <i>si</i>: + the precedent fabricke or figure being made up, it shall be by <a + href="#28_e_v">28. e.</a> as <i>au</i>, is unto <i>ao</i>, the segment + next unto it: so <i>ay</i>, that is, <i>is</i>, shall be unto <i>oi</i>, + his next segment.</p> + + <p>The <a href="#28_e_v">28. e</a> teacheth how to finde out the third + and fourth proportionall: This affordeth us a meanes how to find out <!-- + Page 76 --><span class="pagenum"><a name="page76"></a>[76]</span>the + continually meane proportionall single or double.</p> + + <div class="poem"> + <div class="stanza"> + <p><span class="correction" title="text reads `Thefore'">Therefore</span></p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/096.png"><img style="width:100%" src="images/096.png" + alt="Squire." title="Squire." /></a> + </div> + <p><a name="33_e_v"></a> 33. <i>If two right lines given be continued + into one, a perpendicular from the point of continuation unto the angle + of the squire, including the continued line with the continuation, is the + meane proportionall betweene the two right lines given</i>.</p> + + <p>A squire (<i>Norma</i>, <i>Gnomon</i>, or <i>Canon</i>) is an + instrument consisting of two shankes, including a right angle. Of this we + heard before at the <a href="#13_e_v">13. e</a>. By the meanes of this a + meane proportionall unto two lines given is easily found: whereupon it + may also be called a <i>Mesolabium</i>, or <i>Mesographus simplex</i>, or + single meane finder.</p> + + <p>Let the two right lines given, be <i>ae</i>, and <i>ei</i>. The meane + proportional between these two is desired. For the finding of which, let + it be granted that as <i>ae</i>, is to <i>eo</i>, so <i>eo</i>, is to + <i>ei</i>: therefore let <i>ae</i>, be continued or drawne out unto + <i>i</i>, so that <i>ei</i>, be equall to the other given. Then from + <i>e</i>, the point of the continuation, let <i>eo</i>, an infinite + perpendicular be erected. Now about this perpendicular, up and downe, + this way and that way, let the squire <i>ao</i>, be moved, so that with + his angle it may comprehend at <i>eo</i>, and with his shanks it may + include the whole right line <i>ai</i>. I say that <i>eo</i>, the segment + of the perpendicular, is the meane proportionall between <!-- Page 77 + --><span class="pagenum"><a name="page77"></a>[77]</span><i>ae</i>, and + <i>ei</i>, the two lines given. For let <i>ea</i>, be continued or drawne + out into <i>u</i>, so that the continuation <i>au</i>, be equall unto + <i>eo</i>: and unto <i>a</i>, the point of the continuation, let the + angle <i>uas</i>, be made equall, and equicrurall to the angle + <i>oei</i>, that is, let the shanke <i>as</i>, be made equall to the + shanke <i>ei</i>. Wherefore knitting <i>u</i>, and <i>s</i>, together, + the right lines <i>us</i>, and <i>oi</i>, shall be equall; and the angles + <i>eoi</i>, <i>aus</i>, by the <a href="#7_e_iij">7. e iij</a>. And by + the <a href="#21_e_v">21. e</a>, the lines <i>sa</i>, and <i>oe</i>, are + parallell: and the angle <i>sao</i>, is equall to the angle <i>aoe</i>. + But the angles <i>sae</i>, and <i>aoi</i>, are right angles by the + Fabricke and by the grant; and therefore they are equall, by the <a + href="#14_e_iij">14. e iij</a>. Wherefore the other angles <i>oae</i>, + and <i>eoi</i>, that is, <i>sua</i>, are equall. And therefore by the <a + href="#21_e_v">21. e.</a> <i>us</i>, and <i>ao</i> are parallell; and + <i>us</i>, and <i>eo</i>, continued shall meete, as here in <i>y</i>: and + by the <a href="#26_e_v">26. e.</a> <i>oy</i>, and <i>as</i> are equall. + Now, by the <a href="#32_e_v">32. e.</a> as <i>ue</i>, is to <i>ua</i>, + so is <i>ey</i>, to <i>as</i>. Therefore by subduction or subtraction of + proportions, as <i>ea</i>, is to <i>ua</i>, so is <i>eo</i>, that is, + <i>ua</i>, to <i>oy</i>, that is <i>as</i>.</p> + + <div class="figcenter" style="width:20%;"> + <a href="images/097.png"><img style="width:100%" src="images/097.png" + alt="Figure for demonstration 33." title="Figure for demonstration 33." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:25%;"> + <a href="images/098.png"><img style="width:100%" src="images/098.png" + alt="Plato's Mesographus in use." title="Plato's Mesographus in use." /></a> + </div> + <p><a name="34_e_v"></a> 34 <i>If two assigned right lines joyned + together by their ends rightanglewise, be continued vertically; a square + falling with one of his shankes, and another to it parallell and moveable + upon the ends of the assigned, with the angles upon the continued lines, + shall cut betweene them from the continued two meanes continually + proportionall to the assigned</i>.</p> + + <p>The former consectary was of a single mesolabium; this is of a double, + whose use in making of solids, to this or that bignesse desired is + notable.</p> + + <p>Let the two lines assigned be <i>ae</i>, and <i>ei</i>; and let there + be two meane right lines, continually proportionall betweene them sought, + to wit, that may be as <i>ae</i>, is unto <!-- Page 78 --><span + class="pagenum"><a name="page78"></a>[78]</span>one of the lines found; + so the same may be unto the second line found. And as that is unto this, + so this may be unto <i>ei</i>. Let therefore <i>ae</i>, and <i>ei</i>, be + joyned rightanglewise by their ends at <i>e</i>; and let them be infinite + continued, but vertically, that is, from that their meeting from the + lines ward, from <i>ei</i>, towards <i>u</i>, but <i>ae</i>, towards + <i>o</i>. Now for the rest, the construction; it was <i>Plato's + Mesographus</i>; to wit, a squire with the opposits parallell. One of his + sides <i>au</i>, moueable, or to be done up and downe, by an hollow + riglet in the side adjoyning. Therefore thou shalt make thee a + Mesographus, if unto the squire thou doe adde one moveable side, but so + that how so ever it be moved, it be still parallell unto the opposite + side [which is nothing else, but as it were a double squire, if this + squire be applied unto it; and indeed what is done by this instrument, + may also be done by two squires, as hereafter shall be shewed.] And so + long and oft must the moveable side be moved up and downe, untill with + the opposite side it containe or touch the ends of the assigned, but the + angles must fall precisely upon the continued lines: The right lines from + the point of the continuation, unto the corners of the squire, are the + two meane proportionals sought.</p> + + <p>As if of the Mesographus <i>auoi</i>, the moveable side be <i>au</i>; + <!-- Page 79 --><span class="pagenum"><a + name="page79"></a>[79]</span>thus thou shalt move up and downe, untill + the angles <i>u</i>, and <i>o</i>, doe hit just upon the infinite lines; + and joyntly at the same instant <i>ua</i>, and <i>oi</i>, may touch the + ends of the assigned <i>a</i>, and <i>i</i>. By the former consectary it + shall be as <i>ei</i>, is to <i>eo</i>, so <i>eo</i>, shall be unto + <i>eu</i>: and as <i>eo</i>, is to <i>eu</i>, so shall <i>eu</i>, be unto + <i>ea</i>.</p> + + <div class="figcenter" style="width:25%;"> + <a href="images/099a.png"><img style="width:100%" src="images/099a.png" + alt="Plato's Mesographus." title="Plato's Mesographus." /></a> + </div> + <p>And thus wee have the composition and use, both of the single and + double Mesolabium.</p> + + <p><a name="35_e_v"></a> 35. <i>If of foure right lines, two doe make an + angle, the other reflected or turned backe upon themselves, from the ends + of these, doe cut the former; the reason of the one unto his owne + segment, or of the segments betweene themselves, is made of the reason of + the so joyntly bounded, that the first of the makers be joyntly bounded + with the beginning of the antecedent made; the second of this consequent + joyntly bounded with the end; doe end in the end of the consequent + made</i>.</p> + + <p><i>Ptolomey</i> hath two speciall examples of this <i>Theorem</i>: to + those <i>Theon</i> addeth other foure.</p> + + <div class="figright" style="width:20%;"> + <a href="images/099b.png"><img style="width:100%" src="images/099b.png" + alt="Figure for demonstration 35." title="Figure for demonstration 35." /></a> + </div> + <p>Let therefore the two right lines be <i>ae</i>, and <i>ai</i>: and + from the ends of these other two reflected, be <i>iu</i>, and <i>eo</i>, + cutting themselves in <i>y</i>; and the two former in <i>u</i>, and + <i>o</i>. The reason of the particular right lines made shall be as <!-- + Page 80 --><span class="pagenum"><a name="page80"></a>[80]</span>the + draught following doth manifest. In which the antecedents of the makers + are in the upper place: the consequents are set under neathe their owne + antecedents.</p> + +<table class="nobctr"> +<tr><td colspan="4" align="center">The I. is <i>Ptolemeys</i> and <i>Theons</i> I.</td></tr> + +<tr><td colspan="2" align="center"><i>The makers:</i></td><td colspan="2" align="center"><i>The reason made.</i></td></tr> +<tr><td align="center"><i>iu</i>,</td><td align="center"><i>ye</i>.</td></tr> +<tr><td align="center"><i>uy</i>,</td><td align="center"><i>eo</i>,</td><td align="center"><i>ia</i>,</td><td align="center"><i>ao</i>.</td></tr> + +<tr><td colspan="4" align="center" class="tpb">The II. is <i>Theons</i> VI.</td></tr> + +<tr><td align="center"><i>au</i>,</td><td align="center"><i>ey</i>.</td></tr> +<tr><td align="center"><i>ue</i>,</td><td align="center"><i>yo</i>,</td><td align="center"><i>ai</i>,</td><td align="center"><i>io</i>.</td></tr> + +<tr><td colspan="4" align="center" class="tpb">The III. is <i>Theons</i> III.</td></tr> + +<tr><td align="center"><i>ea</i>,</td><td align="center"><i>ui</i>.</td></tr> +<tr><td align="center"><i>au</i>,</td><td align="center"><i>iy</i>,</td><td align="center"><i>eo</i>,</td><td align="center"><i>oy</i>.</td></tr> + +<tr><td colspan="4" align="center" class="tpb">The IIII. is <i>Theons</i> II.</td></tr> + +<tr><td align="center"><i>oa</i>,</td><td align="center"><i>iu</i>.</td></tr> +<tr><td align="center"><i>ai</i>,</td><td align="center"><i>uy</i>,</td><td align="center"><i>oe</i>,</td><td align="center"><i>ey</i>.</td></tr> + +<tr><td colspan="4" align="center" class="tpb">The V. is <i>Ptolemys</i>, II. <i>Theons</i> IIII.</td></tr> + +<tr><td align="center"><i>iy</i>,</td><td align="center"><i>ue</i>.</td></tr> +<tr><td align="center"><i>yu</i>,</td><td align="center"><i>ea</i>,</td><td align="center"><i>io</i>,</td><td align="center"><i>ao</i>.</td></tr> + +<tr><td colspan="4" align="center" class="tpb">The VI. is <i>Theons</i> V.</td></tr> + +<tr><td align="center"><i>eu</i>,</td><td align="center"><i>ai</i>.</td></tr> +<tr><td align="center"><i>ua</i>,</td><td align="center"><i>io</i>,</td><td align="center"><i>ey</i>,</td><td align="center"><i>yo</i>.</td></tr> + +</table> + + <p>The businesse is the same in the two other, whether you doe crosse the + bounds or invert them.</p> + + <p>Here for demonstrations sake we crave no more, but that from the + beginning of an antecedent made a parallell be drawne to the second + consequent of the makers, unto one of the assigned infinitely continued: + then the multiplied proportions shall be,</p> + + <p>The Antecedent, the Consequent; the Antecedent, the <!-- Page 81 + --><span class="pagenum"><a name="page81"></a>[81]</span>Consequent of + the second of the makers; every way the reason or rate is of + Equallity.</p> + + <p>The Antecedent; the Consequent of the first of the makers; the + Parallell; the Antecedent of the second of the makers, by the <a + href="#32_e_v">32. e</a>. Therefore by multiplication of proportions, the + reason of the Parallell, unto the Consequent of the second of the makers, + that is, by the fabricke or construction, and the <a href="#32_e_v">32. + e.</a> the reason of the Antecedent of the Product, unto the Consequent, + is made of the reason, &c. after the manner above written.</p> + + <div class="figright" style="width:25%;"> + <a href="images/101.png"><img style="width:100%" src="images/101.png" + alt="Figure for several demonstrations in 35." title="Figure for several demonstrations in 35." /></a> + </div> + <p>For examples sake, let the first speciall example be demonstrated. I + say therefore, that the reason of <i>ia</i>, unto <i>ao</i>, is made of + the reason of <i>iu</i>, unto <i>uy</i>, multiplied by the reason of + <i>ye</i>, unto <i>eo</i>. For from the beginning of the Antecedent of + the product, to wit, from the point <i>i</i>, let a line be drawne + parallell to the right line <i>ey</i>, which shall meete with <i>ae</i>, + continued or drawne out infinitely in <i>n</i>. Therefore, by the <a + href="#32_e_v">32. e</a>, as <i>ia</i>, is to <i>ao</i>: so is the + parallell drawne to <i>eo</i>, the Consequent of the second of the + makers. Therefore now the multiplied proportions are thus <i>iu</i>, + <i>uy</i>, <i>in</i>, <i>ey</i>, by the 32. e: <i>ye</i>, <i>eo</i>, + <i>ey</i>, <i>eo</i>. Therefore as the product of <i>iu</i>, by + <i>ye</i>, is unto the product of <i>uy</i>, by <i>eo</i>: So <i>in</i>, + is to <i>eo</i>, that is, <i>ia</i>, to <i>ao</i>.</p> + + <p>So let the second of <i>Ptolemy</i> to be taught, which in our <!-- + Page 82 --><span class="pagenum"><a name="page82"></a>[82]</span>Table + aforegoing is the fifth. I say therefore that the reason of <i>io</i>, + unto <i>oa</i>; is made of the reason of <i>iy</i>, unto <i>yu</i>, and + the reason of <i>ue</i>, unto <i>ea</i>. For now againe, from the + beginning of the Antecedent of the Product <i>i</i>, let a line be drawne + parallell unto <i>ea</i>, the Consequent of the second of the Makers, + which shall meete with <i>eo</i>, drawne out at length, in <i>n</i>: + therefore, by the <a href="#32_e_v">32. e.</a> as <i>io</i>, is to + <i>ao</i>; so is <i><span class="correction" title="text reads `in'" + >en</span></i>, unto <i>ea</i>. Therefore now again the multiplied + proportions are thus:</p> + +<table class="nobctr"> +<tr><td class="spac"><i>ue</i>,</td><td class="spac"><i>ea</i>,</td><td class="spac"><i>ue</i>,</td><td class="spac"><i>ea</i>.</td></tr> +<tr><td class="spac"><i>iy</i>,</td><td class="spac"><i>yu</i>,</td><td class="spac"><i><span class="correction" title="text reads `in'">en</span></i>,</td><td class="spac"><i>ue</i>;</td></tr> +</table> + + <p>by the <a href="#32_e_v">32. e</a>. Therefore, by multiplication of + proportions, the reason of <i><span class="correction" title="text reads `in'" + >en</span></i>, unto <i>ea</i>, that is, of <i>io</i>, unto <i>oa</i>, is + made of the reason of <i>iy</i>, unto <i>yu</i>, by the reason of + <i>ue</i>, unto <i>ea</i>.</p> + + <p>It shall not be amisse to teach the same in the examples of + <i>Theon</i>. Let us take therefore the reason of the Reflex, unto the + Segment; And of the segments betweene themselves; to wit, the 4. and 6. + examples of our foresaid draught: I say therefore, that the reason of + <i>oe</i>, unto <i>ey</i>, is made of the reason <i>oa</i>, unto + <i>ai</i>, by the reason of <i>iu</i>, unto <i>uy</i>. For from the end + <i>o</i>, to wit, from the beginning of the Antecedent of the product, + let the right line <i>no</i>, be drawne parallell to <i>uy</i>. It shall + be by the <a href="#32_e_v">32. e.</a> as <i>oe</i>, is to <i>ey</i>: so + the parallell <i>no</i>, shall be to <i>uy</i>: but the reason of + <i>no</i>, unto <i>uy</i>, is made of the reason of <i>oa</i>, unto + <i>ai</i>, and of <i>iu</i>, unto <i>uy</i>: for the multiplied + proportions are,</p> + +<table class="nobctr"> +<tr><td class="spac"><i>iu</i>,</td><td class="spac"><i>uy</i>,</td><td class="spac"><i>iu</i>,</td><td class="spac"><i>uy</i>.</td></tr> +<tr><td class="spac"><i>oa</i>,</td><td class="spac"><i>ai</i>,</td><td class="spac"><i><span class="correction" title="text reads `oe'">on</span></i>,</td><td class="spac"><i>iu</i>.</td></tr> +</table> + + <p>by the <a href="#32_e_v">32. e.</a></p> + + <p>Againe, I say, that the reason of <i>ey</i>, unto <i>yo</i>, is + compounded of the reason of <i>eu</i>, unto <i>ua</i>, and of <i>ai</i>, + unto <i>io</i>.</p> + + <p><i>Theon</i> here draweth a parallell from <i>o</i>, unto <i>ui</i>. + By the generall fabricke it may be drawne out of <i>e</i>, unto <i><span + class="correction" title="text reads `oi'">ui</span></i>.</p> + + <p>It shall be therefore as <i>ey</i>, is unto <i>yo</i>, so <i>en</i>, + shall be unto <i>oi</i>. Now the proportions multiplied are,</p> + +<table class="nobctr"> +<tr><td class="spac"><i>ai</i>,</td><td class="spac"><i>io</i>,</td><td class="spac"><i>ai</i>,</td><td class="spac"><i>io</i>.</td></tr> +<tr><td class="spac"><i>eu</i>,</td><td class="spac"><i>ua</i>,</td><td class="spac"><i>en</i>,</td><td class="spac"><i><span class="correction" title="text reads `ay'">ai</span></i>.</td></tr> +</table> + + <p>by the <a href="#32_e_v">32. e.</a></p> + + <p>Therefore the reason of <i>en</i>, unto <i>io </i>, that is of + <i>ey</i>, unto <!-- Page 83 --><span class="pagenum"><a + name="page83"></a>[83]</span><i>yo</i>, shall be made of the foresaid + reasons.</p> + + <p>Of the segments of divers right lines, the <i>Arabians</i> have much + under the name of <i>The rule of sixe quantities.</i> And the + <i>Theoremes</i> of <i>Althindus</i>, concerning this matter, are in many + mens hands. And <i>Regiomontanus</i> in his <i>Algorithmus</i>: and + <i>Maurolycus</i> upon the 1 p iij. of <i>Menelaus</i>, doe make mention + of them; but they containe nothing, which may not, by any man skillfull + in Arithmeticke, be performed by the multiplication of proportions. For + all those wayes of theirs are no more but speciall examples of that kinde + of multiplication.</p> + +<hr class="full" /> + +<h2>Of <i>Geometry</i>, the sixt Booke, of +a Triangle.</h2> + + <p><a name="1_e_vj"></a> 1. <i>Like plaines have a double reason of their + homologall sides, and one proportionall meane, out of 20 p vj. and xj. + and 18. p viij</i>.</p> + + <p>Or thus; Like plaines have the proportion of their correspondent + proportionall sides doubled, & one meane proportionall: Hitherto wee + have spoken of plaine lines and their affections: Plaine figures and + their kindes doe follow in the next place. And first, there is premised a + common corollary drawne out of the <a href="#24_e_iiij">24. e. iiij</a>. + because in plaines there are but two dimensions.</p> + + <p><a name="2_e_vj"></a> 2. <i>A plaine surface is either rectilineall or + obliquelineall,</i> [<i>or rightlined, or crookedlined. H.</i>]</p> + + <p>Straightnesse, and crookednesse, was the difference of lines at the <a + href="#4_e_ij">4. e. ij</a>. From thence is it here repeated and + attributed to a surface, which is geometrically made of lines. That made + of right lines, is rectileniall: that which is made of crooked lines, is + Obliquilineall. <!-- Page 84 --><span class="pagenum"><a + name="page84"></a>[84]</span></p> + + <p><a name="3_e_vj"></a> 3. <i>A rectilineall surface, is that which is + comprehended of right lines</i>.</p> + + <p>A plaine rightlined surface is that which is on all sides inclosed and + comprehended with right lines. And yet they are not alwayes right + betweene themselves, but such lines as doe lie equally betweene their + owne bounds, and without comparison are all and every one of them right + lines.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/106.png"><img style="width:100%" src="images/106.png" + alt="Polygons on rectilineall surface." title="Polygons on rectilineall surface." /></a> + </div> + <p><a name="4_e_vj"></a> 4. <i>A rightilineall doth make all his angles + equall to right angles; the inner ones generally to paires from two + forward: the outter always to foure</i>.</p> + + <p>Or thus: A right lined plaine maketh his angles equall unto right + angles: Namely the inward angles generally, are equall unto the even + numbers from two forward, but the outward angles are equall but to 4. + right angles. <i>H</i>.</p> + + <p>The first kinde I meane of rectilineals, that is a triangle doth make + all his inner angles equall to two right angles, that is, to a binary, + the first even number of right angles: the second, that is a quadrangle, + to the second even number, that is, to a quaternary or foure: The third, + that is, a Pentangle, of quinqueangle to the third, that is a senary of + right angles, or 6. and so farre forth as thou seest in this + Arithmeticall progression of even numbers,</p> + +<table class="nobctr"> +<tr><td class="spac">2.</td><td class="spac">4.</td><td class="spac">6.</td><td class="spac">8.</td><td class="spac">10.</td><td class="spac">12.</td></tr> +<tr><td class="spac">3.</td><td class="spac">4.</td><td class="spac">5.</td><td class="spac">6.</td><td class="spac">7.</td><td class="spac">8.</td></tr> +</table> + +<p><!-- Page 85 --><span class="pagenum"><a name="page85"></a>[85]</span></p> + + <p>Notwithstanding the outter angles, every side continued and drawne + out, are alwayes equall to a quaternary of right angles, that is to + foure. The former part being granted (for that is not yet demonstrated) + the latter is from thence concluded: For of the inner angles, that of the + outter, is easily proved. For the three angles of a triangle are equall + to two right angles. The foure of a quadrangle to foure: of a + quinquangle, to sixe: of a sexe angle, to eight: Of septangle, to tenne, + and so forth, <span class="correction" title="text reads `from'" + >form</span> a binarie by even numbers: Whereupon, by the <a + href="#14_e_v">14. e. V</a>. a perpetuall quaternary of the outer angles + is concluded.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/107.png"><img style="width:100%" src="images/107.png" + alt="Outer angles." title="Outer angles." /></a> + </div> + <p><a name="5_e_vj"></a> 5. <i>A rectilineall is either a Triangle or a + Triangulate</i>.</p> + + <p>As before of a line was made a lineate: so here in like manner of a + triangle is made a triangulate.</p> + + <div class="figright" style="width:15%;"> + <a href="images/108a.png"><img style="width:100%" src="images/108a.png" + alt="Triangle." title="Triangle." /></a> + </div> + <p><a name="6_e_vj"></a> 6. <i>A triangle is a rectilineall figure + comprehended of three rightlines. 21. d j</i>.</p> + + <p>As here <i>aei.</i> A triangular figure is of <i>Euclide</i> defined + from the three sides; whereupon also it might be called + <i>Trilaterum</i>, that is three sided, of the cause: rather than + <i>Trianglum</i>, three cornered, of the effect; especially seeing that + three angles, and three sides <!-- Page 86 --><span class="pagenum"><a + name="page86"></a>[86]</span>are not reciprocall or to be converted. For + a triangle may have foure sides, as is <i>Acidoides</i>, or + <i>Cuspidatum</i>, the barbed forme, which <i>Zonodorus</i> called + <i>Cœlogonion</i>, or <i>Cavangulum</i>, an hollow cornered figure. + It may also have both five, and sixe sides, as here thou seest. The name + therefore of <i>Trilaterum</i> would more fully and fitly expresse the + thing named: But use hath received and entertained the name of a triangle + for a trilater: And therefore let it be still retained, but in that same + sense:</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/108b.png"><img style="width:100%" src="images/108b.png" + alt="Not triangles." title="Not triangles." /></a> + </div> + <p><a name="7_e_vj"></a> 7. <i>A triangle is the prime figure of + rectilineals</i>.</p> + + <p>A triangle or threesided figure is the prime or most simple figure of + all rectilineals. For amongst rectilineall figures there is none of two + sides: For two right lines cannot inclose a figure. What is meant by a + prime figure, was taught at the <a href="#7_e_iiij"><span + class="correction" title="text reads `7. e. iiij'">11. e. + iiij</span></a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:15%;"> + <a href="images/109a.png"><img style="width:100%" src="images/109a.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p><a name="8_e_vj"></a> 8. <i>If an infinite right line doe cut the + angle of a triangle, it doth also cut the base of the same: Vitell.</i> + 29. <i>t j</i>.</p> + + <p><a name="9_e_vj"></a> 9. <i>Any two sides of a triangle are greater + than the other</i>.</p> + + <p>Thus much of the difinition of a triangle; the reason or <!-- Page 87 + --><span class="pagenum"><a name="page87"></a>[87]</span>rate in the + sides and angles of a triangle doth follow. The reason of the sides is + first.</p> + + <p>Let the triangle be <i>aei</i>; I say, the side <i>ai</i>, is shorter, + than the two sides <i>ae</i>, and <i>ei</i>, because by the <a + href="#6_e_ij">6. e ij</a>, a right line is betweene the same bounds the + shortest.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><br style="clear : both" /></p> + <div class="figright" style="width:25%;"> + <a href="images/109b.png"><img style="width:100%" src="images/109b.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p><a name="10_e_vj"></a> 10. <i>If of three right lines given, any two + of them be greater than the other, and peripheries described upon the + ends of the one, at the distances of the other two, shall meete, the + rayes from that meeting unto the said ends, shall make a triangle of the + lines given</i>.</p> + + <p>Let it be desired that a triangle be made of these three lines, + <i>aei</i>, given, any two of them being greater than the other: First + let there be drawne an infinite right; From this let there be cut off + continually three portions, to wit, <i>ou</i>, <i>uy</i>, and <i>ys</i>, + equall to <i>ae</i>, and <i>i</i>, the three lines given. Then upon the + ends <i>y</i>, and <i>u</i>, at the distances <i>ou</i>, and <i>ys</i>; + let two peripheries meet in the point <i>r</i>. The rayes from that + meeting unto the said ends, <i>u</i>, and <i>y</i>, shall make the + triangle <i>ury</i>: for those rayes shall be equall to the right lines + given, by the <a href="#10_e_v">10. e v</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="11_e_vj"></a> 11. <i>If two equall peripheries, from the ends + of a right line given, and at his distance, doe meete, lines <!-- Page 88 + --><span class="pagenum"><a name="page88"></a>[88]</span>drawne from the + meeting, unto the said ends, shall make an equilater triangle upon the + line given. 1 p. j</i>.</p> + + <div class="figcenter" style="width:50%;"> + <a href="images/110a.png"><img style="width:100%" src="images/110a.png" + alt="Figure for demonstration 11." title="Figure for demonstration 11." /></a> + </div> + <p>As here upon <i><span class="correction" title="text reads `ue'" + >ae</span></i>, there is made the equilater triangle, <i>aei</i>; And in + like manner may be framed the construction of an equicrurall triangle, by + a common ray, unequall unto the line given; and of a scalen or various + triangle, by three diverse raies; all which are set out here in this one + figure. But these specialls are contained in the generall probleme: + neither doe they declare or manifest unto us any new point of + Geometry.</p> + + <div class="figright" style="width:15%;"> + <a href="images/110b.png"><img style="width:100%" src="images/110b.png" + alt="Proportions in a triangle." title="Proportions in a triangle." /></a> + </div> + <p><a name="12_e_vj"></a> 12. <i>If a right line in a triangle be + parallell to the base, it doth cut the shankes proportionally: And + contrariwise. 2 p vj</i>.</p> + + <p>Such therefore was the reason or rate of the sides in one triangle; + the proportion of the sides followeth.</p> + + <p>As here in the triangle <i>aei</i>, let <i>ou</i>, be parallell to the + base; and let a third parallel be understood to be in the toppe <i>a</i>; + therefore, by the <a href="#28_e_v">28. e. v</a>. the intersegments are + proportionall.</p> + + <p>The converse is forced out of <!-- Page 89 --><span class="pagenum"><a + name="page89"></a>[89]</span>the antecedent: because otherwise the whole + should be lesse than the part. For if <i>ou</i>, be not parallell to the + base <i>ei</i>, then <i>yu</i>, is: Here by the grant, and by the + antecedent, seeing <i>ao</i>, <i>oe</i>, <i>ay</i>, <i>ye</i>, are + proportionall: and the first <i>ao</i>, is lesser than <i>ay</i>, the + third: <i>oe</i>, the second must be lesser than <i>ye</i>, the fourth, + that is the whole then the part.</p> + + <p><br style="clear : both" /></p> + <div class="figright" style="width:20%;"> + <a href="images/111b.png"><img style="width:100%" src="images/111b.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <div class="figright" style="width:20%;"> + <a href="images/111a.png"><img style="width:100%" src="images/111a.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><a name="13_e_vj"></a> 13. <i>The three angles of a triangle, are + equall to two right angles. 32. p j.</i></p> + + <p>Hitherto therefore is declared the comparison in the sides of a + triangle. Now is declared the reason or rate in the angles, which joyntly + taken are equall to two right angles.</p> + + <p>The truth of this proposition, saith <i>Proclus</i>, according to + common notions, appeareth by two perpendiculars erected upon the ends of + the base: for looke how much by the leaning of the inclination, is taken + from two right angles at the base, so much is assumed or taken in at the + toppe, and so by that requitall the equality of two right angles is made; + as in the triangle <i>aei</i>, let, by the <a href="#24_e_v">24. e v</a>, + <i>ou</i>, be parallell against <i>ie</i>. Here three particular angles, + <i>iao</i>, <i>iae</i>, <i>eau</i>, are equall to two right lines; by the + <a href="#14_e_v">14. e v</a>. But the inner angles are equall to the + same three: For first, <i>eai</i>, is equall to it selfe: Then the other + two are equall to their alterne angles, by the <a href="#24_e_v">24. e + v</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="14_e_vj"></a> 14. <i>Any two angles of a triangle are lesse + than two right angles</i>.</p> + + <p>For if three angles be equall to two right angles, then <!-- Page 90 + --><span class="pagenum"><a name="page90"></a>[90]</span>are two lesser + than two right angles.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:18%;"> + <a href="images/112a.png"><img style="width:100%" src="images/112a.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p><a name="15_e_vj"></a> 15. <i>The one side of any triangle being + continued or drawne out, the outter angle shall be equal to the two inner + opposite angles</i>.</p> + + <p>This is the rate of the inner angles in one and the same triangle: The + rate of the outter with the inner opposite angles doth followe. As in the + triangle <i>aei</i>, let the side <i>ei</i>, be continued or drawne out + unto <i>o</i>; the two angles on each side <i>aio</i> and <i>aie</i>, are + by the <a href="#14_e_v">14 e v</a>. equall to two right angles: and the + three inner angles, are by the <a href="#13_e_vj">13. e.</a> equall also + to two right angles; take away <i>aie</i>, the common angle, and the + outter angle <i>aio</i>, shall be left equall to the other two inner and + opposite angles.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="16_e_vj"></a> 16. <i>The said outter angle is greater than + either of the inner opposite angles. 16. p j</i>.</p> + + <p>This is a consectary following necessarily upon the next former + consectary.</p> + + <div class="figright" style="width:18%;"> + <a href="images/112b.png"><img style="width:100%" src="images/112b.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> + <p><a name="17_e_vj"></a> 17. <i>If a triangle be equicrurall, the angles + at the base are equall: and contrariwise, 5. and 6. p. j</i>.</p> + + <p>The antecedent is apparent by the <a href="#7_e_iij">7. e iij</a>. The + converse is apparent by an impossibilitie, which otherwise must needs + follow. For if any one shanke be greater than the other, as <i>ae</i>: + Then by the <a href="#7_e_v">7. e v</a>. let <i>oe</i>, be cut off <span + class="correction" title="unclear grammar, he means `equall to the other (ai)'" + >equall to it</span>: and let <i>oi</i>, be drawne: then by <a + href="#7_e_iij">7. e iij</a>. the base <i>oi</i>, must <!-- Page 91 + --><span class="pagenum"><a name="page91"></a>[91]</span>be equal to the + base <i>ae</i>; but the base <i>oi</i>, is lesser than <i>ae</i>. For by + the <a href="#9_e_vj">9. e</a>, <i>ia</i>; and <i>ao</i>, (to which + <i>ae</i>, is equall, seeing that <i>oe</i>, is supposed to be equall to + the same <i>ai</i>: and <i><span class="correction" title="text reads `ae'" + >ao</span></i>, is common to both) are greater than the said <i>oi</i>; + therefore the same, <i>oi</i>, must be equall to the same <i>ae</i>, and + lesser than the same, which is impossible. This was first found out by + <i>Thales Milesius</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="18_e_vj"></a> 18. <i>If the equall shankes of a triangle be + continued or drawne out, the angles under the base shall be equall + betweene themselves</i>.</p> + + <p>For the angles <i>aei</i>, and <i>ieo</i>: Item <i>aie</i>, and + <i>eiu</i>, are equall to two right angles, by the <a href="#14_e_v">14. + e v</a>. Therefore they are equall betweene themselves: wherefore if you + shall take away the inner angles, equall betweene themselves, you shall + leave the outter equall one to another.</p> + + <div class="figcenter" style="width:18%;"> + <a href="images/113a.png"><img style="width:100%" src="images/113a.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:18%;"> + <a href="images/113b.png"><img style="width:100%" src="images/113b.png" + alt="Equilater." title="Equilater." /></a> + </div> + <p><a name="19_e_vj"></a> 19. <i>If a triangle be an equilater, it is + also an equiangle: And contrariwise</i>.</p> + + <p>It is a consectary out of the condition of an equicrurall triangle of + two, both shankes and angles, as in the example <i>aei</i>, shall be + demonstrated.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="20_e_vj"></a> 20. <i>The angle of an equilater triangle doth + <!-- Page 92 --><span class="pagenum"><a + name="page92"></a>[92]</span>countervaile two third parts of a right + angle. Regio. 23. p j</i>.</p> + + <p>For seeing that 3. angles are equall to 2. 1. must needs be equall to + 2/3.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="21_e_vj"></a> 21. <i>Sixe equilater triangles doe fill a + place</i>.</p> + + <p>As here. For 2/3. of a right angle sixe lines added together doe make + 12/3. that is foure right angles; but foure right angles doe fill a place + by the <a href="#27_e_iiij">27. e. iiij</a>.</p> + + <div class="figcenter" style="width:18%;"> + <a href="images/114a.png"><img style="width:100%" src="images/114a.png" + alt="Figure for demonstration 21." title="Figure for demonstration 21." /></a> + </div> + <p><a name="22_e_vj"></a> 22. <i>The greatest side of a triangle + subtendeth the greatest angle; and the greatest angle is subtended of the + greatest side. 19. and 18. p j</i>.</p> + + <div class="figright" style="width:12%;"> + <a href="images/114b.png"><img style="width:100%" src="images/114b.png" + alt="Figure for demonstration 22." title="Figure for demonstration 22." /></a> + </div> + <p><i>Subtendere</i>, to draw or straine out something under another; and + in this place it signifieth nothing else but to make a line or such like, + the base of an angle, arch, or such like. And <i>subtendi</i>, is to + become or made the base of an angle, arch, of a circle, or such like: As + here, let <i>ai</i>, be a greater side than <i>ae</i>, I say the angle at + <i>e</i>, shall be greater than that at <i>i</i>. For let there be cut + off from <i>ai</i>, a portion equall to <i>ae</i>,; and let that be + <i>io</i>: then the angle <i>aei</i>, equicrurall to the angle + <i>oie</i>, shall be greater in base, by the grant. Therefore the angle + shall be greater, by the <a href="#9_e_iij">9 e iij</a>.</p> + + <p>The converse is manifest by the same figure: As let the angle + <i>aei</i>, be greater than the angle <i>aie</i>. Therefore by the same, + <a href="#9_e_iij">9 e iij</a>. it is greater in base. For what is there + spoken <!-- Page 93 --><span class="pagenum"><a + name="page93"></a>[93]</span>of angles in generall, are here assumed + specially of the angles in a triangle.</p> + + <p><a name="23_e_vj"></a> 23. <i>If a right line in a triangle, doe cut + the angle in two equall parts, it shall cut the base according to the + reason of the shankes; and contrariwise. 3. p vj</i>.</p> + + <p>The mingled proportion of the sides and angles doth now remaine to be + handled in the last place.</p> + + <p>Let the triangle be <i>aei</i>; and let the angle <i><span + class="correction" title="text reads `aei'">eai</span></i>, be cut into + two equall parts, by the right line <i>ao</i>: I say, as <i>ea</i>, is + unto <i>ai</i>, so <i>eo</i>, is unto <i>oi</i>. For at the angle + <i>i</i>, let the parallell <i>iu</i>, by the <a href="#24_e_v">24. e + v</a>. be erected against <i>ao</i>; and continue or draw out <i>ea</i>, + infinitly; and it shall by the <a href="#20_e_v">20. e v</a>. cut the + same <i>iu</i>, in some place or other. Let it therefore cut it in + <i>u</i>. Here, by the <a href="#28_e_v">28. e v</a>. as <i>ea</i>, is to + <i>au</i>, so is <i>eo</i>, to <i>oi</i>. But <i>au</i>, is equall to + <i>ai</i>, by the <a href="#17_e_vj">17. e</a>. For the angle <i>uia</i>, + is equall to the alterne angle <i>oai</i>, by the <a href="#21_e_v">21. e + v</a>. And by the grant it is equall to <i>oae</i>, his equall: And by + the <a href="#21_e_v">21. e v</a>. it is equall to the inner angle + <i>aui</i>; and by that which is concluded it is equall to <i>uia</i>, + his equall. Therefore by the <a href="#17_e_vj">17. e</a>, <i>au</i>, and + <i>ai</i>, are equall. Therefore as <i>ea</i>, is unto <i>ai</i>, so is + <i>eo</i>, unto <i>oi</i>.</p> + + <div class="figcenter" style="width:25%;"> + <a href="images/115.png"><img style="width:100%" src="images/115.png" + alt="Figure for demonstration 23." title="Figure for demonstration 23." /></a> + </div> + <p>The Converse likewise is demonstrated in the same figure. For as + <i>ea</i>, is to <i>ai</i>; so is <i>eo</i>, to <i>oi</i>: And so is + <i>ea</i>, to <i>au</i>, by the 12 e: therefore <i>ai</i>, and <i>au</i>, + are equall, Item the angles <i>eao</i>, and <i>oai</i>, are equall to the + angles at <i>u</i>, and <i>i</i>, by the <a href="#21_e_v">21. e v</a>. + which are equall betweene themselves by the <a href="#17_e_vj">17. + e</a>.</p> + +<hr class="full" /> + +<p><!-- Page 94 --><span class="pagenum"><a name="page94"></a>[94]</span></p> + +<h2>Of Geometry, the seventh Booke, +Of the comparison of Triangles.</h2> + + <p><a name="1_e_vij"></a> 1. <i>Equilater triangles are equiangles. 8. p. + j</i>.</p> + + <p>Thus forre of the Geometry, or affections and reason of one triangle; + the comparison of two triangles one with another doth follow. And first + of their rate or reason, out of their sides and angles: Whereupon + triangles betweene themselves are said to be equilaters and equiangles. + First out of the equality of the sides, is drawne also the equalitie of + the angles.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/116a.png"><img style="width:100%" src="images/116a.png" + alt="Equilater triangles." title="Equilater triangles." /></a> + </div> + <p>Triangles therefore are here jointly called equilaters, whose sides + are severally equall, the first to the first, the second, to the second, + the third to the third; although every severall triangle be + inequilaterall. Therefore the equality of the sides doth argue the + equality of the angles, by the <a href="#7_e_iij">7. e iij</a>. As + here.</p> + + <p><a name="2_e_vij"></a> 2. <i>If two triangles be equall in angles, + either the two equicrurals, or two of equall either shanke, or base of + two angles, they are equilaters, 4. and 26. p j</i>.</p> + + <p><span class="correction" title="text reads `Oh'">Or</span> thus; If + two triangles be equall in their angles, either <!-- Page 95 --><span + class="pagenum"><a name="page95"></a>[95]</span>in two angles contained + under equall feet, or in two angles, whose side or base of both is + equall, those angles are equilater. <i>H</i>.</p> + + <p>This element hath three parts, or it doth conclude two triangles to be + equilaters three wayes. 1. The first part is apparent thus: Let the two + triangles be <i>aei</i>, and <i>ouy</i>; because the equall angles at + <i>a</i>, and <i>o</i>, are equicrurall, therefore they are equall in + base, by the <a href="#7_e_iij">7. e iij</a>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/116b.png"><img style="width:100%" src="images/116b.png" + alt="Equilater triangles: equicrural equal angles." title="Equilater triangles: equicrural equal angles." /></a> + </div> + <p>2 The second thus: Let the said two triangles <i>aei</i>, and + <i>ouy</i>, be equall in two angles a peece, at <i>e</i>, and <i>i</i>, + and at <i>u</i>, and <i>y</i>. And let them be equall in the shanke + <i>ei</i>, to <i>uy</i>. I say, they are equilaters. For if the side + <i>ae</i>, (for examples sake) be greater than the side <i>ou</i>, let + <i>es</i>, be cut off equall unto it; and draw the right line <i>is</i>. + Here by the antecedent, the triangles <i>sei</i>, and <i>ouy</i>, shall + be equiangles, and the angles <i>sie</i>, shall be equall to the angle + <i>oyu</i>, to which <!-- Page 96 --><span class="pagenum"><a + name="page96"></a>[96]</span>also the whole angle <i>aie</i>, is equall, + by the grant. Therefore the whole and the part are equall, which is + impossible. Wherefore the side <i>ae</i>, is not unequall but equall to + the side <i>ou</i>: And by the antecedent or former part, the triangles + <i>aei</i>, and <i>ouy</i>, being equicrurall, are equall, at the angle + of the shanks: Therefore also they are equall in their bases <i>ai</i>, + and <i>oy</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/117.png"><img style="width:100%" src="images/117.png" + alt="Equilater triangles: two equal angles and equal shank." title="Equilater triangles: two equal angles and equal shank." /></a> + </div> + <p>3 The third part is thus forced: In the triangles <i>aei</i>, and + <i>ouy</i>, let the angles at <i>e</i>, and <i>i</i>, and <i>u</i>, and + <i>y</i>, be equall, as afore: And <i>ae</i>, the base of the angle at + <i>i</i>, be equall to <i>ou</i>, the base of angle at <i>y</i>: I say + that the two triangles given are equilaters. For if the side <i>ei</i>, + be greater than the side <i>uy</i>, let <i>es</i>, be cut off equall to + it, and draw the right line <i>as</i>. Therefore by the antecedent, the + two triangles, <i>aes</i>, and <i>ouy</i>, equall in the angle of their + equall shankes are equiangle: And the angle <i>ase</i>, is equall to the + angle <i>oyu</i>, which is equall by the grant unto the angle <i>aie</i>. + Therefore <i>ase</i>, is equall to <i>aie</i>, the outter to the inner, + contrary to the <a href="#15_e_vj">15. e. vj</a>. Therefore the base + <i>ei</i>, is not unequall to the base <i>uy</i>, but equall. And + therefore as above was said, the two triangles <i>aei</i>, and + <i>ouy</i>, equall in the angle of their equall shankes, are + equilaters.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/116c.png"><img style="width:100%" src="images/116c.png" + alt="Equilater triangles: two equal angles and equal base (diagram moved to correct position: it was printed on the previous page)." title="Equilater triangles: two equal angles and equal base (diagram moved to correct position: it was printed on the previous page)." /></a> + </div> + <div class="figright" style="width:22%;"> + <a href="images/118a.png"><img style="width:100%" src="images/118a.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p><a name="3_e_vij"></a> 3. <i>Triangles are equall in their three + angles</i>.</p> + + <p>The reason is, because the three angles in any triangle are <!-- Page + 97 --><span class="pagenum"><a name="page97"></a>[97]</span>equall to two + right angles, by the <a href="#13_e_vj">13. e vj</a>. As here, the + greatest triangle, all his corners joyntly taken, is equall to the + least.</p> + + <p>And yet notwithstanding it is not therefore to be thought to be + equiangle to it: For Triangles are then equiangles, when the severall + angles of the one, are equall to the severall angles of the other: Not + when all joyntly are equall to all.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="4_e_vij"></a> 4. <i>If two angles of two triangles given be + equall, the other also are equall</i>.</p> + + <p>All the three angles, are equall betweene themselves, by the <a + href="#3_e_vij">3 e</a>. Therefore if from equall you take away equall, + those which shall remaine shall be equall.</p> + + <p><a name="5_e_vij"></a> 5. <i>If a right triangle equicrurall to a + triangle be greater in base, it is greater in angle: And contrariwise. + 25. and 24. p j</i>.</p> + + <p>Thus farre of the reason or rate of equality, in the sides and angles + of triangles: The reason of inequality, taken out of the common and + generall inequality of angles, doth <!-- Page 98 --><span + class="pagenum"><a name="page98"></a>[98]</span>follow. The first is + manifest, by the <a href="#9_e_iij">9. e iij</a>. as here thou seest in + <i>aei</i> and <i>ouy</i>.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/118b.png"><img style="width:100%" src="images/118b.png" + alt="Figure for demonstrations 5 and 6." title="Figure for demonstrations 5 and 6." /></a> + </div> + <p><a name="6_e_vij"></a> 6. <i>If a triangle placed upon the same base, + with another triangle, be lesser in the inner shankes, it is greater in + the angle of the shankes</i>.</p> + + <p>This is a consectary drawne also out of the <a href="#10_e_iij">10 e + iij</a>. As here in the triangle <i>aei</i>, and <i>aoi</i>, within it + and upon the same base. Or thus: If a triangle placed upon the same base + with another triangle, be lesse then the other triangle, in regard of his + feet, (those feete being conteined within the feete of the other + triangle) in regard of the angle conteined under those feete, it is + greater: <i>H</i>.</p> + + <div class="figright" style="width:26%;"> + <a href="images/119.png"><img style="width:100%" src="images/119.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p><a name="7_e_vij"></a> 7. <i>Triangles of equall heighth, are one to + another as their bases are one to another</i>.</p> + + <p>Thus farre of the Reason or rate of triangles: The proportion of + triangles doth follow; And first of a right line with the bases. It is a + consectary out of the <a href="#16_e_iiij">16 e iiij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="8_e_vij"></a> 8. <i>Upon an equall base, they are + equall</i>.</p> + + <p>This was a generall consectary at the <a href="#16_e_iiij">16. e + iiij</a>: From whence <i>Archimedes</i> concluded, If a triangle of + equall heighth with many other triangles, have his base equall to the + bases of them all, it is equall to them all: as here thou seest + <i>aei</i> to be equall to the triangles <i>aeo</i>, <i>uoy</i>, + <i>syr</i>, <i>lrm</i>, <i>nmi</i>. Here hence also thou mayst conclude, + that <i>Equilater</i> triangles are equall: Because they are of equall + heighth, and upon the same base.</p> + +<p><!-- Page 99 --><span class="pagenum"><a name="page99"></a>[99]</span></p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:23%;"> + <a href="images/120a.png"><img style="width:100%" src="images/120a.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p><a name="9_e_vij"></a> 9. <i>If a right line drawne from the toppe of + a triangle, doe cut the base into two equall parts, it doth also cut the + triangle into two equall parts: and it is the diameter of the + triangle</i>.</p> + + <p>As here thou seest: For the bisegments, or two equall portions thus + cut are two triangles of equall heighth <span class="correction" + title="text reads `that that'">that</span> is to say, they have one toppe + common to both, within the same parallels) and upon equall bases: + Therefore they are equall: And that right line shall be the diameter of + the triangle, by the <a href="#5_e_iiij">5 e iiij</a>, because it passeth + by the center.</p> + + <p><a name="10_e_vij"></a> 10. <i>If a right line be drawne from the + toppe of a triangle, unto a point given in the base (so it be not in the + middest of it) and a parallell be drawne from the middest of the base + unto the side, a right line drawne from the toppe of the sayd parallell + unto the sayd point, shall cut the triangle into two equall + parts</i>.</p> + + <p>Let the triangle given be <i>aei</i>: And let <i>ao</i>, cut the base + <i>ei</i>, in <i>o</i> unequally: And let <i>uy</i> be parallell from + <i>u</i>, the middest of <span class="correction" title="text reads `y' in italics" + >the</span> base, unto the sayd <span class="correction" title="text reads `ei' in italics" + ><i>ao</i></span>. I say that <i>yo</i> shall divide the triangle into + two equall portions. For let <i>au</i> be knit together with a right + line: That line, by the <a href="#9_e_vij">9 e</a>, shall divide the + triangle into two equall parts. Now the two triangles <i>ayu</i>, and + <i>you</i>, are equall by the 8 e; because they are of equall height, and + upon the same base.</p> + + <div class="figcenter" style="width:23%;"> + <a href="images/120b.png"><img style="width:100%" src="images/120b.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> +<p><!-- Page 100 --><span class="pagenum"><a name="page100"></a>[100]</span></p> + + <p>Take away <i>ysu</i>, the common triangle; And you shall leave + <i>asy</i>, and <i>osu</i>, equall betweene themselves: The common right + lined figure <i>ysui</i>, let it be added to both the sayd equall + triangles: And then <i>oyi</i>, shall be equall to <i>aui</i>, the halfe + part; And therefore <i>aeoy</i>, the other right lined figure, shall be + the halfe of the triangle given.</p> + + <p><a name="11_e_vij"></a> 11. <i>If equiangled triangles be reciprocall + in the shankes of the equall angle, they are equall: And + contrariwise.</i> 15. <i>p. vj.</i> Or thus, <i>as the learned Mr.</i> + Brigges <i>hath conceived it: If two triangles, having one angle, are + reciprocall, &c</i>.</p> + + <div class="figcenter" style="width:48%;"> + <a href="images/121.png"><img style="width:100%" src="images/121.png" + alt="Figure for demonstration 11. Labels u and i have been interchanged to match the text." title="Figure for demonstration 11. Labels u and i have been interchanged to match the text." /></a> + </div> + <p>Direct proportion in triangles, is such as hath in the former beene + taught: Reciprocall proportion followeth. It is a consectary drawne out + of the <a href="#18_e_iiij">18 e iiij</a>; which is manifest, as oft as + the equall angle is a right angle: For then those shankes, [comprehending + the equall angles,] are the heights and the bases; As here thou seest in + the severed triangles. Notwithstanding in obliquangle triangles, although + the shankes are not the heights, the cause of the truth hereof is the + same. Yet if any man shall desire a demonstration of it, it is thus: Let + therefore the diagramme or figure bee in the triangles <i>aei</i>, and + <i>aou</i>: And the angles <i>oau</i>, and <i>eai</i>, let them be + equall: And as <i>ua</i> is to <i>ae</i>, so let <i>ia</i> be unto + <i>ao</i>: I say that the triangles <i>aou</i>, and <i>eai</i>, are + equall. For <i>eo</i> being knit together with a right line, <i>uao</i> + is unto <i>oae</i>, as <i>ua</i> is unto <i>ae</i>, by the 7 e: <!-- Page + 101 --><span class="pagenum"><a name="page101"></a>[101]</span>And + <i>ia</i>, unto <i>ao</i>, by the grant, is as <i>eai</i> is unto + <i>eao</i>. Therefore <i>uao</i>, and <i>eai</i>, are unto <i>eao</i> + proportionall: And therefore they are equall one to another.</p> + + <p>The converse, is concluded by the same sorites, but by saying all + backward. For <i>ua</i> unto <i>ae</i> is, as <i>uao</i> is unto + <i>oae</i>, by the 7 e: And as <i>eai</i>, by the grant: Because they are + equall: And as <i>ia</i> is unto <i>ao</i>, by the same, Wherefore + <i>ua</i> is unto <i>ae</i>, as <i>ia</i> is unto <i>ao</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/122.png"><img style="width:100%" src="images/122.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p><a name="12_e_vij"></a> 12. <i>If two triangles be equiangles, they + are proportionall in shankes: And contrariwise: 4 and 5.</i> <i>p. + vj</i>.</p> + + <p>The comparison both of the rate and proportion of triangles hath in + the former beene taught: Their similitude remaineth for the last place. + Which similitude of theirs consisteth indeed of the reason, or rate of + their angles and proportion of the shankes. Therefore for just cause was + the reason of the angles set first: Because from thence not onely their + reason, but also their latter proportion is gathered. Let <i>aei</i> and + <i>iou</i>, be two triangles equiangled: And let them be set upon the + same line <i>eiu</i>, meeting or touching one another in the common point + <i>i</i>. Then, seeing that the angles at <i>e</i> and <i>i</i>, are + granted to bee equall, the lines <i>oi</i>, and <i>ae</i>, are parallel, + by the <a href="#21_e_v">21 e v</a>. Therefore by the <a + href="#22_e_v">22 e v</a> <i>uo</i> and <i>ea</i>, being continued, shall + meete. Item, The right lines <i>ai</i>, and <i>yu</i>, by the <a + href="#21_e_v">21 e v</a>, are parallel, because the angle <i>aie</i> is + equall to <i>oui</i>, the inner opposite to it. Therefore seeing that + <i>ai</i> is parallell to the base <i>yu</i>, by the <a href="#21_e_v">21 + e v</a>, <i>ea</i> shall be to <i>ay</i>, that is, by the <a + href="#26_e_v">26 e v</a>, to <i>io</i>, as <i>ei</i> is to <i>iu</i>: + And alternly, or crosse wayes, <i>ea</i> shall be to <i>ei</i>, as + <i>io</i> is to <i>iu</i>. This is the first proportion. Item, <!-- Page + 102 --><span class="pagenum"><a name="page102"></a>[102]</span>seeing + that <i>io</i> is parallell to the base <i>ye</i>; <i>yo</i>, that is, by + the <a href="#26_e_v">26 e v</a>, <i>ai</i> shall bee unto <i>ou</i>, as + <i>ei</i>, is unto <i>iu</i>: And crosse wise, as <i>ai</i> is unto + <i>ie</i>, so is <i>ou</i> unto <i>ui</i>. This is the second + proposition. Lastly, equiordinately: <i>ae</i> is to <i>ai</i>, as + <i>oi</i> is to <i>ou</i>: wherefore if triangles be equiangled, they are + proportional in shankes.</p> + + <div class="figright" style="width:20%;"> + <a href="images/123.png"><img style="width:100%" src="images/123.png" + alt="Figure for the converse." title="Figure for the converse." /></a> + </div> + <p>This converse is thus demonstrated. Let there be two triangles + <i>aei</i>, and <i>ouy</i>, proportionall in shankes: And as <i>ae</i> is + to <i>ei</i>; so let <i>ou</i>, be to <i>uy</i>: And as <i>ai</i> is to + <i>ie</i>; so let <i>oy</i> bee to <i>yu</i>. Then at the points <i>u</i> + and <i>y</i>, let angles be made by the <a href="#11_e_iij">11 e iij</a>. + equall to the angles at <i>e</i> and <i>i</i>, and let the triangle + <i>uys</i>, be made: for the other angles at <i>a</i> and <i>s</i>, shall + be equall by the <a href="#4_e_vij">4 e</a>. And the triangle <i>yus</i>, + shall be equiangled to the assigned <i>aei</i>. And by the antecedent, it + shall be proportionall to it in shankes. Thus are two triangles + <i>ouy</i>, by the grant; and <i>uys</i>, by the construction, + proportionall in shanks to the same triangle <i>aei</i>: And as + <i>ae</i>, is to <i>ei</i>, so is <i>ou</i>, to <i>uy</i>; so is + <i>su</i>, to <i>uy</i>. Therefore seeing <i>ou</i> and <i>su</i>, are + proportionall to the same <i>yu</i>, they are equall; Item, as <i>ai</i> + is to <i>ie</i>: so is <i>oy</i> unto <i>yu</i>: so also is <i>sy</i> + unto <i>yu</i>. Therefore <i>oy</i> and <i>sy</i>, seeing they are + proportionall to the same <i>yu</i>, are equall. (<i>yu</i> is the common + side.) The triangle therefore <i>ouy</i>, is equilater unto the triangle + <i>syu</i>. And by the <a href="#1_e_vij">1 e</a>, it is to it equiangle: + And therefore it is equiangled to the triangle <i>aei</i>, which was to + be prooved. This was generally before taught at the <a + href="#20_e_iiij">20 e iiij</a>, of homologall sides subtending equall + angles.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore,</p> + </div> + </div> + <div class="figleft" style="width:18%;"> + <a href="images/124a.png"><img style="width:100%" src="images/124a.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><a name="13_e_vij"></a> 13. <i>If a right line in a triangle be + parallell to the base, it doth cut off from it a triangle equiangle to + the whole, but lesse in base.</i> <!-- Page 103 --><span + class="pagenum"><a name="page103"></a>[103]</span></p> + + <p>As in the triangle <i>aei</i>, the right line <i>ou</i>, doth cut off + the triangle <i>aou</i>, equiangle, by the <a href="#21_e_v">21 e v</a>, + to the whole <i>aei</i>; But the base <i>ou</i>, is lesse than the base + <i>ei</i>, as appeareth by the <a href="#21_e_v">21 e</a>, and by the + alternation of the sides.</p> + + <div class="figright" style="width:28%;"> + <a href="images/124b.png"><img style="width:100%" src="images/124b.png" + alt="Equiangles." title="Equiangles." /></a> + </div> + <p><a name="14_e_vij"></a> 14. <i>If two trangles be proportionall in the + shankes of the equall angle, they are equiangles: 6 p vj</i>.</p> + + <p>Let therefore the triangles given be <i>aei</i>, and <i>ouy</i>, + equall in their angles <i>a</i> and <i>o</i>: And in their shankes let + <i>ea</i>, be unto <i>ai</i>, as <i>ou</i> is to <i>oy</i>: And by the <a + href="#11_e_iij">11 e iij</a>, let the angles <i>soy</i>, and <i>oys</i>, + be equall to the angles <i>eai</i>, and <i>eia</i>: The other at <i>s</i> + and <i>e</i>, shall be equall, by the <a href="#4_e_vij">4 e</a>. Here + thou seest that the triangle <i>aei</i>, is equiangle unto <i>oys</i>. + Now, by the <a href="#12_e_vij">12 e.</a> as <i>ea</i> is to <i>ai</i>: + so is <i>so</i> to <i>oy</i>: and therefore, by the grant, so is + <i>uo</i> to <i>oy</i>. Therefore seeing that <i>uo</i>, and <i>os</i>, + are proportionall to <i>oy</i>, they are both equall. Lastly, if the + common shanke <i>oy</i> bee added to both the shankes <i>ou</i>, and + <i>oy</i>, are equall to the shankes <i>so</i> and <i>oy</i>. [But by the + construction the angles <i>oys</i> and <i>aie</i> are equall. And, by the + <a href="#4_e_vij">4 e</a>, the other at <i>s</i> and <i>e</i> are + equall. Therefore the first triangle <i>aei</i>, is made equiangled to + the third. Now seeing the second triangle <i>uoy</i> is to the third + <i>soy</i>, equall in the shanks of the equall angle, it is to the same + equilater, and by the <a href="#1_e_vij">1 e</a>, equiangled: + <i>Shon.</i>] Wherefore the second triangle <i>ouy</i> shall likewise be + equiangled to <i>osy</i>, the third: And therefore if <!-- Page 104 + --><span class="pagenum"><a name="page104"></a>[104]</span>two triangles + proportionall in shankes be equall in the angle of their shankes, they + are equiangles.</p> + + <p><a name="15_e_vij"></a> 15. <i>If triangles proportionall in shankes, + and alternly parallell, doe make an angle betweene them, their bases are + but one right line continued. 32 p. vj</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/125.png"><img style="width:100%" src="images/125.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>Or thus: If being proportionall in their feet, and alternately + parallels, they make an angle in the midst betweene them, they have their + bases continued in a right line: <i>H</i>.</p> + + <p>The cause is out of the <a href="#14_e_v">14 e v</a>. For they shall + make on each side, with the falling line <i>ai</i>, two angles equall to + two right angles.</p> + + <p>Let the triangles <i>aei</i> and <i>oiu</i>, be proportionall in + shanks: As <i>ae</i> is to <i>ai</i>, so let <i>io</i> be to <i>ou</i>: + And let <i>ea</i> bee parallel to <i>io</i>: And <i>ai</i> to <i>ou</i>: + Item, let them make the angle <i>aio</i>, betweene them, to wit, betweene + their middle shankes <i>ai</i>, and <i>oi</i>, I say their bases + <i>ei</i>, and <i>iu</i>, are but one right line continued. For seeing + that by the grant <i>ae</i>, and <i>oi</i>, are parallels: Item <i>ai</i> + and <i>uo</i>, the right line <i>ai</i> and <i>oi</i>, shall make, by the + <a href="#21_e_v">21 e v</a>, the angles at <i>a</i>, and <i>o</i>, + equall to the alterne angle <i>aio</i>: And therefore they are equall + betweene themselves: And then, by the <a href="#14_e_vij">14 e</a>, the + triangles given are equiangles: Therefore the angle <i>oui</i>, is equall + to the angle <i>aie</i>: Wherfore the three angles <i>oiu</i>, + <i>oia</i>, and <i>aie</i>, by the <a href="#3_e_vij">3 e</a>, are equall + to the three angles of the triangle <i>eai</i>, which are equall by the + <a href="#13_e_vj">13 e vj</a>. Unto two right angles: And therefore they + themselves also are equall to two right angles. Wherefore, by the <a + href="#14_e_v">14 e v</a>, <i>ei</i>, and <i>iu</i>, are one right line + continued. <!-- Page 105 --><span class="pagenum"><a + name="page105"></a>[105]</span></p> + + <p><a name="16_e_vij"></a> 16. <i>If two triangles have one angle equall, + another proportionall in shankes, the third homogeneall, they are + equiangles. 7. p. vj</i>.</p> + + <div class="figright" style="width:24%;"> + <a href="images/126.png"><img style="width:100%" src="images/126.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p>Let <i>aei</i>, and <i>ouy</i>, the triangles given be equall in their + angles <i>a</i>, and <i>o</i>: and proportionall in the shankes of the + angles <i>e</i>, and <i>u</i>: and their other angles, at <i>i</i>, and + <i>y</i>, homogeneall, that is, let them be both, either acute, or + obtuse, or right angles. But first let them be acute, I say, the other at + <i>e</i>, & <i>u</i>, are equall. Otherwise let <i>aes</i>, by the <a + href="#11_e_iij">11 e iij.</a> be made equall to the same <i>ouy</i>; + Then have you them by the <a href="#4_e_vij">4 e</a>, equiangles; and the + angles <i>ase</i>, shall be equall to the angle <i>oyu</i>; and both are + acute angles: and by the <a href="#12_e_vij">12. e</a>, <i>aes</i>, and + <i>ouy</i>, are proportionall in sides: and as <i>ae</i>, is to + <i>es</i>; so shall <i>ou</i>, be to <i>uy</i>, that is, by the grant, so + shall <i>ae</i>, be to <i>ei</i>. Therefore because the same <i>ea</i>, + hath unto two, to wit, <i>es</i>, and <i>ei</i>, the same reason, the + said <i>es</i>, and <i>ei</i>, are equall one to another: And therefore, + by the <a href="#17_e_vj">17. e. vj.</a> the angles at the base in + <i>s</i> and <i>i</i>, are equall. Therefore both of them are acute + angles: And in like manner <i>ase</i>, is an acute angle, contrary to the + <a href="#14_e_v">14. e v</a>. The same will fall out altogether like to + both the other, being either obtuse or right angles. The last part of a + right angle is manifest by the <a href="#4_e_vij">4 e</a> of this + Booke.</p> + +<hr class="full" /> + +<p><!-- Page 106 --><span class="pagenum"><a name="page106"></a>[106]</span></p> + +<h2>Of Geometry the eight Booke, +of the diverse kindes of Triangles.</h2> + + <p><a name="1_e_viij"></a> 1. <i>A triangle is either right angled, or + obliquangled</i>.</p> + + <p>The division of a triangle, taken from the angles, out of their common + differences, I meane, doth now follow. But here first a speciall + division, and that of great moment, as hereafter shall be in quadrangles + and prismes.</p> + + <p><a name="2_e_viij"></a> 2. <i>A right angled triangle is that which + hath one right angle: An obliquangled is that which hath none. 27. d + j</i>.</p> + + <p>A right angled triangle in Geometry is of speciall use and force; and + of the best Mathematicians it is called <i>Magister matheseos</i>, the + master of the Mathematickes.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:15%;"> + <a href="images/127.png"><img style="width:100%" src="images/127.png" + alt="Right angled triangle." title="Right angled triangle." /></a> + </div> + <p><a name="3_e_viij"></a> 3. <i>If two perpendicular lines be knit + together, they shall make a right angled triangle</i>.</p> + + <p>As here in <i>aei</i>. This construction and manner of making of a + right angled triangle, is drawne out of the definition of a right angle. + For right lines perpendicular are the makers of a right angle, as is + manifest by the <a href="#13_e_iij">13. e iij</a>.</p> + + <p><a name="4_e_viij"></a> 4. <i>If the angle of a triangle at the + base</i>, <i>be a right <!-- Page 107 --><span class="pagenum"><a + name="page107"></a>[107]</span>angle, a perpendicular from the toppe + shall be the other shanke:</i> [<i>and contrariwise Schon.</i>]</p> + + <p>As is manifest in the same example.</p> + + <p><a name="5_e_viij"></a> 5. <i>If a right angled triangle be + equicrurall, each of the angles at the base is the halfe of a right + angle: And contrariwise</i>.</p> + + <div class="figright" style="width:15%;"> + <a href="images/128a.png"><img style="width:100%" src="images/128a.png" + alt="Equicrurall right angled triangle." title="Equicrurall right angled triangle." /></a> + </div> + <p>As in the triangle <i>aei</i>: For they are both equall to one right + angle, by the <a href="#13_e_vj">13. e. vj</a>. And betweene themselves, + by the <a href="#17_e_vj">17. e. vj</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="6_e_viij"></a> 6. <i>If one angle of a triangle be equall to + the other two, it is a right angle</i> [<i>And contrariwise + Schon.</i>]</p> + + <p>Because it is equall to the halfe of two right angles, by the <a + href="#13_e_vj">13. e vj</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="7_e_viij"></a> 7. <i>If a right line from the toppe of a + triangle cutting the base into two equall parts be equall to the + bisegment, or halfe of the base, the angle at the toppe is a right + angle:</i> [<i>And contrariwise Schon.</i>]</p> + + <div class="figright" style="width:21%;"> + <a href="images/128b.png"><img style="width:100%" src="images/128b.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>As in the triangle <i>aei</i>, the right line <i>ao</i>, cutting the + base <i>ei</i>, in <i>o</i>, into two equall parts, is equall to + <i>eo</i>, or <i>oi</i>, the halfe of the base maketh two equicrural + triangles; and the severall angles at the top equall to the angles at the + ends, <i>viz.</i> <i>e</i>, and <i>i</i>, by the <a href="#17_e_vj">17. + e. vj</a>. Therefore the angle at the toppe <!-- Page 108 --><span + class="pagenum"><a name="page108"></a>[108]</span>is equall to the other + two: wherefore by the <a href="#6_e_viij">6 e</a>, it is a right + angle.</p> + + <p><a name="8_e_viij"></a> 8. <i>A perpendicular in a triangle from the + right angle to the base, doth cut it into two triangles, like unto the + whole and betweene themselves, 8. p vj.</i> [<i>And contrariwise + Schon.</i>]</p> + + <p>As in the triangle <i>aei</i>, the perpendicular <i>ao</i>, doth cut + the triangles <i>aoe</i>, and <i>aoi</i>, like unto the whole <i>aei</i>, + because they are equiangles to it; seeing that the right angle on each + side is one, and another common in <i>i</i>, and <i>e</i>: Therefore the + other is equall to the remainder, by <a href="#4_e_vij">4. e vij</a>. + Wherefore the particular triangles are equiangles to the whole: As + proportionall in the shankes of the equall angles, by the <a + href="#12_e_vij">12. e vij</a>. But that they are like betweene + themselves it is manifest by the <a href="#22_e_iiij">22. e iiij</a>.</p> + + <div class="figcenter" style="width:28%;"> + <a href="images/129.png"><img style="width:100%" src="images/129.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="9_e_viij"></a> 9. <i>The perpendicular is the meane + proportionall betweene the segments or portions of the base</i>.</p> + + <p>As in the said example, as <i>io</i>, is to <i>oa</i>: so is + <i>oa</i>, to <i>oe</i>, because the shankes of equall angles are + proportionall, by the <a href="#8_e_viij">8. e</a>. From hence was + <i>Platoes</i> Mesographus invented.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="10_e_viij"></a> 10. <i>Either of the shankes is proportionall + betweene the base, and the segment of the base next adjoyning</i>.</p> + + <p>For as <i>ei</i>, is unto <i>ia</i>, in the whole triangle, so is + <i>ai</i>, to <i>io</i>, in the greater. For so they are homologall + sides, which <!-- Page 109 --><span class="pagenum"><a + name="page109"></a>[109]</span>doe subtend equall angles, by the <a + href="#23_e_iiij">23. e. iiij</a>. Item, as <i>ie</i>, is to <i>ea</i>; + in the whole triangle, so is <i>ae</i>, to <i>eo</i>, in the lesser + triangle.</p> + + <p>Either of the shankes is proportionall betweene the summe, and the + difference of the base and the other shanke. And contrariwise. If one + side be proportionall betweene the summe and the difference of the + others, the triangle given is a rectangle. M. <i>H.</i> + <i>Brigges</i>.</p> + + <p>This is a consectary arising likewise out of the <a href="#4_e_viij">4 + e.</a> of very great use.</p> + + <p>In the triangle <i>ead</i>, the shanke <i>ad</i>, 12. is the meane + proportionall betweene <i>bd</i>, 18. (the summe of the base <i>ae</i>, + 13. and the shanke <i>ed</i>, 5.) and 8. the difference of the said base + and shanke: For if thou shalt draw the right lines <i>ba</i>, and + <i>ac</i>, the angle <i>bac</i>, shall be by the <a href="#6_e_viij">6. + e</a>, a rectangle; (because it is equall to the angles at <i>b</i>, and + <i>c</i>, seeing that the triangles <i>bea</i>, and <i>eac</i>, are + equicrurall.) And by the <a href="#9_e_viij">9 e</a>, <i>bd</i>, + <i>da</i>, and <i>dc</i>, are continually proportionall.</p> + + <p><i>If a quadrate of a number, given for the first shanke, be divided + of another, the halfe of the difference of the divisour, and quotient + shall be the other shanke, and the halfe of the summe shall be the + base.</i> Or thus, <i>The side of divided number doubled, and the + difference of the divisour and quotient, shall be the two shankes, and + the summe of them shall be the base</i>.</p> + + <p>Let the number given for the first shanke be 4. And let 8. divide 16. + the quadrate of 4. by 2. The halfe of 8 - 2, that is 3. shall be the + other shanke: And the halfe of 8 <span class="correction" title="Note: modern + and - signs have been substituted as required for the printed symbols, - - - or - - with no apparent distinction." + >+</span> 2, that is 5. shall be the base.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><i>If any one number shall divide the quadrate of another, the side of + the divided, and the halfe of the difference of the divisour and the + quotient, shall be the two shankes of a rectangled triangle, and the + halfe of the summe of them shall be the base thereof</i>.</p> + + <p>Let the two numbers given be 4. and 6. The square of <!-- Page 110 + --><span class="pagenum"><a name="page110"></a>[110]</span>6. let it be + 36. and the quotient of 36. by 4. be 9: And the side <span + class="correction" title="text reads `it'">is</span> 6. for the one + shanke. Now 9 - 4. that is, 5. is the difference of the divisour and + quotient, whose halfe 2.½, is the other shanke. And 9 + 4. that is 13. is + the summe the said devisour and quotient, whose halfe 6.½, is the + base.</p> + + <p>Againe let 4. and 8. be given. The quadrate of 8. is 64. And the <span + class="correction" title="text reads `quient'. It is the quotient of 64. by 4." + >quotient</span> of 64 is 16. and the side of 64. is 8. for the one + shanke. The halfe 16 - 4. that is 6. is the other shanke. And the halfe + of 16 + 4. that is 10, is the base.</p> + + <p><a name="11_e_viij"></a> 11. <i>If the base of a triangle doe subtend + a right-angle, the rectilineall fitted to it, shall be equall to the like + rectilinealls in like manner fitted to the shankes thereof: And + contrariwise, out of the 31. p. vj</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/131.png"><img style="width:100%" src="images/131.png" + alt="Figure for demonstration 11. (Transcriber: should s be the rightangle in eis?)" title="Figure for demonstration 11. (Transcriber: should s be the rightangle in eis?)" /></a> + </div> + <p>Or thus: If the base of a triangle doe subtend a right angle, the + right lined figure made upon the base, is equall to the right lined + figures like, and in like manner situate upon the feete: <i>H</i>.</p> + + <p>Let the right angled triangle be <i>aei</i>: and let there be also the + triangles <i>eau</i>, and <i>aiy</i>, and to them upon the base of the + said right angle, by the <a href="#23_e_iiij">23 e iiij</a>. let the + triangle <i>ies</i>, be made like, and in like manner situate. I say, + that <i>eis</i>, is equall joyntly to <i>eau</i>, and <i>aiy</i>. Let + <i>ao</i>, a perpendicular fall from the right angle <i>a</i>, to the + base <i>ei</i>: This by the <i>ioe</i>, doth yeeld us twise three + proportionals, to wit, <i>ie</i>, <i>ea</i>, <i>eo</i>: Item, <i>ei</i>, + <i>ia</i>, <i>io</i>: Therefore, by the <a href="#25_e_iiij">25. e. + iiij</a>, as <i>ie</i>, is to <i>eo</i>: so is the triangle <i>ies</i>, + to the triangle <i>eau</i>; And as <i>ei</i>, is to <i>oi</i>, so is the + triangle <i>eis</i>, to the triangle <i>aiy</i>: But <i>ei</i>, is equall + to <i>eo</i>, and <i>oi</i>, the whole, to wit, to his parts. Wherefore + by the second composition in <!-- Page 111 --><span class="pagenum"><a + name="page111"></a>[111]</span>Arithmeticke (9. c. ij.) the triangle + <i>eis</i>, is equall to the triangles <i>eau</i>, and <i>iay</i>.</p> + + <p>The Converse is thus proved: Let the triangle be <i>aei</i>: And let + the perpendicular <i>eo</i>, be erected upon <i>ae</i>, equall to + <i>ei</i>: And draw a right line from <i>o</i> to <i>a</i>: Here by the + former, the rectilinealls situate at <i>oe</i>, and <i>ea</i>, that is by + the construction, at <i>ae</i>, and <i>ie</i>, are equall to the + rightilineall at <i>ao</i>, made alike and situate alike: And by the + graunt they are equall, to the rectilineall at <i>ai</i>, made alike and + situated alike. Therefore seeing the like rectilineals at <i>ao</i>, and + <i>ai</i>, are equall; they have by the <a href="#20_e_iiij">20 e + iiij</a>, their homologall sides equall: And the two triangles are + equiliters: And by the <a href="#1_e_vij">1 e vij</a>, equiangles. But + <i>aeo</i>, is a right angle, by the construction: And <i>aei</i>, is + proved to be equall to the same <i>aeo</i>: Therefore, by the <a + href="#13_e_v">13 e v</a>. <i>aei</i>, also is a right angle.</p> + + <p><a name="12_e_viij"></a> 12. <i>An obliquangled triangle is either + Obtusangled or Acutangled</i>.</p> + + <p>The division of an obliquangled triangle is taken from the speciall + differences of an oblique angle. For at the 15 e iij, we were taught that + an oblique angle was either obtuse or acute: Therefore an obliquangled + triangle is an obtuseangle, and an Acutangle.</p> + + <p><a name="13_e_viij"></a> 13. <i>An obtusangle is that triangle which + hath one blunt corner.</i> 28.<i>d i</i>.</p> + + <p>There can be but one right angle in a triangle, by the <a + href="#2_e_viij">2 e</a>. Therefore also in it there can be but one blunt + angle.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="14_e_viij"></a> 14. <i>If the obtuse or blunt angle be at the + base of the triangle given, a perpendicular drawne from the toppe <!-- + Page 112 --><span class="pagenum"><a name="page112"></a>[112]</span>of + the triangle, shall fall without the figure: And contrarywise</i>.</p> + + <p>As here in <i>aei</i>, the perpendicular <i>io</i>, falleth without: + This is manifest by the <a href="#4_e_viij">4 e</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="15_e_viij"></a> 15. <i>If one angle of a triangle be greater + than both the other two, it is an obtuse angle: And contrariwise</i>.</p> + + <p>This is plaine by the <a href="#6_e_viij">6 e</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:22%;"> + <a href="images/133.png"><img style="width:100%" src="images/133.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p><a name="16_e_viij"></a> 16. <i>If a right line drawne from the toppe + of the triangle cutting the base into two equall parts, be lesse than one + of those halfes, the angle at the toppe is a blunt-angle. And + contrariwise</i>.</p> + + <p>As in <i>aei</i>, the perpendicular <i>eo</i>, cutting the base + <i>ai</i> into two equall parts <i>ao</i>, and <i>oi</i>: And the said + <i>eo</i> is lesse than either <i>ao</i>, or <i>oi</i>: Therefore the + angle <i>aei</i>, is a blunt angle by the <a href="#7_e_viij">7 + e</a>.</p> + + <p><a name="17_e_viij"></a> 17. <i>An acutangled triangle is that which + hath all the angles acute. 29 d j</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="18_e_viij"></a> 18. <i>A perpendicular drawne from the top + falleth <span class="correction" title="text reads `without'" + >within</span> the figure: And contrariwise</i>.</p> + + <p>As in <i>aei</i>, the perpendicular <i>ao</i> falleth <span + class="correction" title="text reads `without'">within</span> as is + plaine by the <a href="#4_e_viij">4 e</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 113 --><span class="pagenum"><a name="page113"></a>[113]</span></p> + + <div class="figright" style="width:18%;"> + <a href="images/134.png"><img style="width:100%" src="images/134.png" + alt="Figure for demonstration 20." title="Figure for demonstration 20." /></a> + </div> + <p><a name="19_e_viij"></a> 19. <i>If any one angle of triangle be lesse + then the other two, it is acute: And contrariwise</i>.</p> + + <p>As is manifest by the <a href="#6_e_viij">6 e</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="20_e_viij"></a> 20. <i>If a right line drawne from the toppe + of the triangle; cutting the base into two equall parts, be <span + class="correction" title="text reads `lesse'">greater</span> than either + of those portions, the angle at the toppe is an acute angle: And + contrariwise</i>.</p> + + <p>As in <i>aei</i>, let <i>ao</i> cutting the base <i>ei</i> into two + equall parts, be <span class="correction" title="text reads `lesse'" + >greater</span> than any one of those parts, the angle at the toppe is an + acuteangle, as <span class="correction" title="text reads `apreareth'" + >appeareth</span> by the <a href="#7_e_viij">7 e</a>.</p> + + <p><br style="clear :both" /></p> +<hr class="full" /> + +<h2>The ninth Booke, of <i>P. Ramus</i> +Geometry, which intreateth of +the measuring of right lines +by like right-angled +<i>triangles</i>.</h2> + + <p>The Geometry of like right-angled triangles, amongst many other uses + that it hath, it doth especially afford us the geodæsy or measuring of + right lines: And that mastery, which before (at the <a href="#2_e_viij">2 + e viij</a>) attributed the right angled triangles, shall here be found to + be a true mastery indeed. <!-- Page 114 --><span class="pagenum"><a + name="page114"></a>[114]</span>For it shall containe the geodesy of right + lines; and afterward the geodesy of plaines and solides, by the measuring + of their sides, which are right lines.</p> + + <p><a name="1_e_ix"></a> 1. <i>For the measuring of right lines; we will + use the</i> Iacobs <i>staffe, which is a squire of unequall + shankes</i>.</p> + + <p><i>Radius</i>, commonly called <i>Baculus Iacob</i>, <i>Iacobs</i> + staffe, as if it had been long since invented and practised by that holy + Patriarke, is a very auncient instrument, and of all other Geometricall + instruments, commonly used, the best and fittest for this use. + <i>Archimedes</i> in his book of the Number of the sand, seemeth to + mention some such thing: And <i>Hipparchus</i>, with an instrument not + much unlike this, boldly attempted an haynous matter in the sight of God, + as <i>Pliny</i> thinketh, namely to deliver unto posterity the number of + the starres, and to assigne or fixe them in their true places by the + <i>Norma</i>, the squire or <i>Iacobs</i> staffe. And indeed true it is + that the Radius is not onely used for the measuring of the earth and + land: But especially for the defining or limiting of the starres in their + places and order: And for the describing and setting out of all the + regions and waies of the heavenly city. Yea and <i>Virgill</i> the famous + Poet, in his 3 <i>Ecloge</i>, <i>Ecquis fuit alter</i>, <i>Descripsit + radio totum</i>, <i>qui gentibus orbem?</i> and againe afterward in the 6 + of his <i>Eneiades</i>, hath noted both these uses. <i>Cœliquè + meatus.</i> <i>Describent radio & surgentia sidera dicent.</i> Long + after this the <i>Iewes</i> and <i>Arabians</i>, as <i>Rabbi Levi</i>; + But in these latter daies, the <i>Germaines</i> especially, as + <i>Regiomontanus</i>; <i>Werner</i>, <i>Schoner</i>, and <i>Appian</i> + have grac'd it: But above all other the learned <i>Gemma Phrisius</i> in + a severall worke of that argument onely, hath illustrated and taught the + use of it plainely and fully.</p> + + <p>The <i>Iacobs</i> staffe therefore according to his owne, and those + Geometricall parts, shall here be described (The <!-- Page 115 --><span + class="pagenum"><a name="page115"></a>[115]</span>astronomicall + distribution wee reserve to his time and place.) And that done, the use + of it shall be shewed in the measuring of lines.</p> + + <p>This instrument, at the discretion of the measurer may be greater or + lesser. For the quantity of the same can no otherwayes be determined.</p> + + <p><a name="2_e_ix"></a> 2. <i>The shankes of the staffe are the Index + and the Transome</i>.</p> + + <div class="figcenter" style="width:80%;"> + <a href="images/136a.png"><img style="width:100%" src="images/136a.png" + alt="Iacobs staffe: Index." title="Iacobs staffe: Index." /></a> + </div> + <div class="figcenter" style="width:40%;"> + <a href="images/136b.png"><img style="width:100%" src="images/136b.png" + alt="Iacobs staffe: Transome." title="Iacobs staffe: Transome." /></a> + </div> + <p>The principall parts of this instrument are two, the <i>Index</i>, or + <i>Staffe</i>, which is the greater or longer part: and the + <i>Transversarium</i>, or Transome, and is the lesser and shorter.</p> + + <p><a name="3_e_ix"></a> 3. <i>The Index is the double and one tenth part + of the transome</i>.</p> + + <p>Or thus: The Index is to the transversary double and 1/10 part + thereof. <i>H.</i> As here thou seest.</p> + + <p><a name="4_e_ix"></a> 4. <i>The Transome is that which rideth upon the + Index, and is to be slid higher or lower at pleasure</i>.</p> + + <p>Or, The transversary is to be moved upon the Index, sometimes higher, + sometimes lower: <i>H.</i> This proportion in defining and making of the + shankes of the instrument is perpetually to be observed: as if the + transome be 10. parts, the <!-- Page 116 --><span class="pagenum"><a + name="page116"></a>[116]</span>Index must be 21. If that be 189. this + shall be 90. or if it be 2000. this shall be 4200. Neither doth it skill + what the numbers be, so this be their proportion. More than this, That + the greater the numbers be, that is the lesser that the divisions be, the + better will it be in the use. And because the Index must beare, and the + transome is to be borne; let the index be thicker, and the transome the + thinner.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/137.png"><img style="width:100%" src="images/137.png" + alt="Parts of Iacobs staffe." title="Parts of Iacobs staffe." /></a> + </div> + <p>But of what matter each part of the staffe be made, whether of brasse + or wood it skilleth not, so it be firme, and will not cast or warpe. + Notwithstanding, the transome will more conveniently be moved up and + downe by brasen pipes, both by it selfe, and upon the Index higher or + lower right angle wise, so touching one another, that the alterne mouth + of the one may touch the side of the other. The thrid pipe is to be moved + or slid up and downe, from one end of the transome to the other; and + therefore it may be called the <i>Cursor</i>. The fourth and fifth pipes, + fixed and immoveable, are set upon the ends of the transome, are <!-- + Page 117 --><span class="pagenum"><a name="page117"></a>[117]</span>unto + the third and second of equall height with finnes, to restraine when + neede is, the opticke line, and as it were, with certaine points to + define it in the transome.</p> + + <p>The three first pipes may, as occasion shall require, be fastened or + staied with brasen scrues. With these pipes therefore the transome may be + made as great, as need shall require, as here thou seest.</p> + + <p>The fabricke or manner of making the instrument hath hitherto beene + taught, the use thereof followeth: unto which in generall is required: + First, a just distance. For the sight is not infinite. Secondly, that one + eye be closed: For the optick faculty conveighed from both the eyes into + one, doth aime more certainely; and the instrument is more fitly applied + and set to the cheeke bone, then to any other place. For here the eye is + as it were the center of the circle, into which the transome is + inscribed. Thirdly, the hands must be steady; for if they shake, the + proportion of the Geodesy must needes be troubled and uncertaine. Lastly, + the place of the station is from the midst of the foote.</p> + + <p><a name="5_e_ix"></a> 5. <i>If the sight doe passe from the beginning + of one shanke, it passeth by the end of the other: And the one shanke is + perpendicular unto the magnitude to be measured, the other + parallell</i>.</p> + + <p>These common and generall things are premised. That the sight is from + the beginning of the Index by the end of the transome; Or contrariwise, + From the beginning of the transome, unto the end of the Index. And that + the Index is right, that is, perpendicular to the line to be measured, + the transome parallell. Or contrariwise. Now the perpendicularity of the + Index, in measurings of lengthts, may be tried by a plummet of lead + appendent; But in heights and breadths, the eye must be trusted; although + a little varying of the plummet can make no sensible errour. <!-- Page + 118 --><span class="pagenum"><a name="page118"></a>[118]</span>By the end + of the transome, understand that which is made by the line visuall, + whether it be the outmost finne, or the Cursour in any other place + whatsoever.</p> + + <p><a name="6_e_ix"></a> 6. <i>Length and Altitude have a threefold + measure; The first and second kinde of measure require but one distance, + and that by granting a dimension of one of them, for the third + proportionall: The third two distances, and such onely is the dimension + of Latitude</i>.</p> + + <p>Geodesy of right lines is two fold; of one distance, or of two. + Geodesy of one distance is when the measurer for the finding of the + desired dimension doth not change his place of standing. Geodesy of two + distances is when the measurer by reason of some impediment lying in the + way betweene him and the magnitude to be measured, is constrained to + change his place, and make a double standing.</p> + + <p>Here observe, That length and heighth, may be joyntly measured both + with one, and with a double station: But breadth may not be measured + otherwise than with two.</p> + + <p><a name="7_e_ix"></a> 7. <i>If the sight be from the beginning of the + Index right or plumbe unto the length, and unto the farther end of the + same, as the segment of the Index is, unto the segment of the transome, + so is the heighth of the measurer unto the length</i>.</p> + + <p>Let therefore the segment of the Index, from the toppe, I meane, unto + the transome be 6. parts. The segment of the transome, to wit, from the + Index unto the opticke line be 18. The Index, which here is the heighth + of the measurer, 4. foote: The length, by the rule of three, shall be 12. + foote. The figure is thus, for as <i>ae</i>, is to <i>ei</i>, so is + <i>ao</i>, <!-- Page 119 --><span class="pagenum"><a + name="page119"></a>[119]</span>unto <i>ou</i>, by the <a + href="#12_e_vij">12. e vij</a>. For they are like triangles. For + <i>aei</i>, and <i>aou</i>, are right angles: And that which is at + <i>a</i> is common to them both: Wherefore the remainder is equall to the + remainder, by the <a href="#4_e_vij">4. e vij</a>.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/140a.png"><img style="width:100%" src="images/140a.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> +<p><!-- Page 120 --><span class="pagenum"><a name="page120"></a>[120]</span></p> + + <p>The same manner of measuring shall be used from an higher place; as + out of <i>y</i>, the segment of the Index is 5. parts; the segment of the + transome 6: and then the height be 10 foote: the same Length shall be + found to bee 12 foote.</p> + + <p>Neither is it any matter at all, whether the length in a plaine or + levell underneath: Or in an ascent or descent of a mountaine, as in the + figure under written.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/140b.png"><img style="width:100%" src="images/140b.png" + alt="Using Iacobs staffe on an ascent." title="Using Iacobs staffe on an ascent." /></a> + </div> + <p>Thus mayest thou measure the breadths of Rivers, Valleys, and Ditches. + For the Length is alwayes after this manner, so that one may measure the + distance of shippes on the Sea, as also <i>Thales Milesius</i>, in + <i>Proclus</i> at the 26 p j, did measure them. An example thou hast + here.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/141.png"><img style="width:100%" src="images/141.png" + alt="Using Iacobs staffe on a ship." title="Using Iacobs staffe on a ship." /></a> + </div> + <p>Hereafter in the measuring of Longitude and Altitude, sight is unto + the toppe of the heighth. Which here I doe now forewarne thee of, least + afterward it should in vaine be reitered often.</p> + + <p>The second manner of measuring a Length is thus: <!-- Page 121 + --><span class="pagenum"><a name="page121"></a>[121]</span></p> + + <p><a name="8_e_ix"></a> 8. <i>If the sight be from the beginning of the + index parallell to the length to be measured, as the segment of the + transome is, unto the segment of the index, so shall the heighth given be + to the length</i>.</p> + + <p>As if the segment of the Transome be 120 parts: the height given 400 + foote: The segment of the Index 210 parts: The length, by the golden rule + shall be 700 foote. The figure is thus. And the demonstration is like + unto the former; or indeed more easier. For the triangles are equiangles, + as afore. Therefore as <i>ou</i> is to <i>ua</i>: so is <i>ei</i> to + <i>ia</i>.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/142.png"><img style="width:100%" src="images/142.png" + alt="Using Iacobs staffe in the second kinde." title="Using Iacobs staffe in the second kinde." /></a> + </div> + <p>This is the first and second kinde of measuring of a Longitude, by one + single distance or station: The third which is by a double distance doth + now follow. Here the transome, if there be roome enough for the measurer + to goe farre enough backe, must be put lower, in the second distance.</p> + + <p><a name="9_e_ix"></a> 9. <i>If the sight be from the beginning of the + <!-- Page 122 --><span class="pagenum"><a + name="page122"></a>[122]</span>transverie parallell to the length to be + measured, as in the index the difference of the greater segment is unto + the lesser; so is the difference of the second station unto the + length</i>.</p> + + <p>This kinde of Geodæsy is somewhat more subtile than the former were. + The figure is thus; in which let the first ayming be from <i>a</i>, the + beginning of the transome, and out of <i>ai</i> the length sought by + <i>o</i>, the end of the Index, unto <i>e</i>, the toppe of the heighth: + And let the segment of the Index be <i>ou</i>: The second ayming let it + be from <i>y</i>, the beginning of the transome, out of a greater + distance by <i>s</i>, the end of the Index, unto <i>e</i>, the same note + of the heighth: And let the segment of the Index be <i>sr</i>.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/143.png"><img style="width:100%" src="images/143.png" + alt="Using Iacobs staffe at two distances." title="Using Iacobs staffe at two distances." /></a> + </div> + <p>Here the measuring performed, is the taking of the difference betweene + <i>ou</i> and <i>sr</i>. The rest are faigned onely for demonstrations + sake. Therefore in the first station let <i>aml</i>, be from the + beginning of the transome, be parallell to <i>ye</i>. Here first + <i>mu</i>, is equall to <i>sr</i>. For the triangles <!-- Page 123 + --><span class="pagenum"><a name="page123"></a>[123]</span><i>mua</i>, + and <i>sry</i>, are equall in their shankes <i>ua</i>, and <i>ry</i>, by + the grant (Because the transome standeth still in his owne place:) And + the angles at <i>mua</i>, <i>uam</i>, are equall to the angles: And all + right angles are equall, by the <a href="#14_e_iij">14 e iij</a>. These + are the outter and inner opposite one to another: And such are equall by + the <span class="correction" title="wrong reference but I cannot deduce the correction." + >1 e v</span>. Therefore they are equilaters, by the <a href="#2_e_vij">2 + e vij</a>; And <i>om</i>, is the difference of the segments of the Index. + Then as <i>om</i> is to <i>mu</i>, so is <i>el</i>, to <i>li</i>; as the + equation of three degrees doth shew. For, by the <a href="#12_e_vij">12 e + vij</a>, as <i>om</i> is to <i>ma</i>: so is <i>el</i> to <i>la</i>: And + as <i>ma</i> is to <i>mu</i>; so is <i>la</i>, to <i>li</i>. Therefore by + right, as <i>om</i>, is to <i>mu</i>: so is <i>el</i>, to <i>li</i>: And + by the <a href="#12_e_vj">12 e vj</a>, so is <i>ya</i>, to <i>ai</i>: As + if the difference of the first segment be 36 parts: The second segment be + 72 parts: The difference of the second station 40 foote. The length + sought shall be 80 foote. And here indeed is no heighth definitely given, + that may make any bound of the principall proportion. Notwithstanding the + Heighth, although it be of an unknowne measure, is the bound of the + length sought: And therefore it is an helpe and meanes to argue the + question. Because it is conceived to stand plumbe upon the outmost end of + the length.</p> + + <p>Therefore that third kinde of measuring of length is oftentimes + necessary, when by neither of the former wayes the length may possibly be + taken, by reason of some impediment in the way, to wit of a wall, or + tree, or house, or mountaine, whereby the end of the length may not be + seene, which was the first way: Nor an height next adjoyning to the end + of the length is given, which is the second way.</p> + + <p>Hitherto we have spoken of the threefold measure of longitude, the + first and second out of an heighth given the third cut of a double + distance: The measuring of heighth followeth next, and that is also + threefold. Now heighth is a perpendicular line falling from the toppe of + the magnitude, unto the ground or plaine whereon the measurer doth stand, + after which manner Altitude or <!-- Page 124 --><span class="pagenum"><a + name="page124"></a>[124]</span>heighth was defined at the <a + href="#9_e_iiij">9 e iiij</a>. The first geodesy or manner of measuring + of heighths is thus.</p> + + <p><a name="10_e_ix"></a> 10. <i>If the sight be from the beginning of + the transome perpendicular unto the height to be measured, as the segment + of the transome, is unto the segment of the Index, so shall the length + given be to the height</i>.</p> + + <p>Let the segment of the transome be 60 parts: the segment of the Index + 36: the Length given 120 foote: the height sought shall be, by the golden + rule, 72 foote.</p> + + <div class="figcenter" style="width:55%;"> + <a href="images/145.png"><img style="width:100%" src="images/145.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>The Figure is thus: And the demonstration is by the <a + href="#12_e_vij">12 e vij</a>, as afore: but here is to be added the + height of the measurer; which if it be 4 foot, the whole height shall be + 76 foote.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore in an eversed altitude</p> + </div> + </div> + <p><a name="11_e_ix"></a> 11. <i>If the sight be from the beginning of + the Index parallell to the height, as the segment of the transome <!-- + Page 125 --><span class="pagenum"><a name="page125"></a>[125]</span>is, + unto the segment of the index, so shall the length given be, unto the + height sought</i>.</p> + + <p><i>Eversa altitudo</i>, An eversed altitude (Reversed, <i>H</i>:) is + that which we call depth, which indeed is nothing else, in the Geometers + sense, but heighth turned topsie turvie, as we say, or with the heeles + upward. For out of the heighth concluded by subducting that which is + above ground, the heighth or depth of a Well shall remaine.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/146.png"><img style="width:100%" src="images/146.png" + alt="Using Iacobs staffe in an eversed altitude." title="Using Iacobs staffe in an eversed altitude." /></a> + </div> + <p>Let the segment of the transome <i>ae</i>, be 5 parts: the segment of + the Index <i>ei</i>, be 13: the diameter of the Well (which now standeth + for the length:) be 10 foote, which at toppe is supposed to be equall to + that at bottome: the opposite height, by the <a href="#12_e_vij"><span + class="correction" title="text reads `21 e vij'">12 e vij</span></a>, and + the golden rule shall <!-- Page 126 --><span class="pagenum"><a + name="page126"></a>[126]</span>be 26 foote: From whence you must take the + segment of the Index reaching over the mouth of the Well: And the true + height (or depth) shall remaine; as if that segment of 13 parts be as + much as 2 foote, the height sought shall be 24 foote. The second manner + of measuring of heights followeth.</p> + + <p><a name="12_e_ix"></a> 12. <i>If the sight be from the beginning of + the Index perpendicular to the heighth to be measured, as the segment of + the Index is unto the segment of the Transome, so shall the length given + be to the heighth</i>.</p> + + <p>As if the segment of the Index be 60 parts: and the segment also of + the transome be 60: And the Length given be 250 foote: By the Rule of + three, the height also shall be 250 foote: as thou seest in the example + underneath: For as <i>ae</i> is to <i>ei</i>; so is <i>aeo</i> to + <i>ou</i>, by the <a href="#12_e_vij">12 e vij</a>. But here unto the + height found, you must adde the height of the measurer: Which if it be 4 + foot, the whole height shall be 254 foote.</p> + + <div class="figcenter" style="width:53%;"> + <a href="images/147.png"><img style="width:100%" src="images/147.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> +<p><!-- Page 127 --><span class="pagenum"><a name="page127"></a>[127]</span></p> + + <p><a name="13_e_ix"></a> 13. <i>If the sight be from the beginning of + the Index (perpendicular to the magnitude to be measured) by the names of + the transome, unto the ends of some known part of the height, as the + distance of the Names is, unto the rest of the transome above them, so + shall the known part be unto the part sought</i>.</p> + + <p>Or thus: If the sight passe from the beginning of the Index being + right, by the vanes of the transversary, to the tearmes of some parts; as + the distance of the vanes is unto the rest of the transversary above the + index, so is the part knowne unto the remainder: <i>H</i>.</p> + + <p>This is a consectary of a knowne part of an height, from whence the + rest may be knowne, as in the figure.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/148.png"><img style="width:100%" src="images/148.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>As <i>ou</i> is unto <i>uy</i>, so is <i>ei</i> to <i>is</i>. For as + <i>ou</i>, is unto <i>ua</i>: so is <i>ei</i> unto <i>ia</i>, by the <a + href="#12_e_vij">12 e vij</a>. And as <i>ua</i>, is to <i>uy</i>, so is + <i>ia</i> unto <i>is</i>; and by right, as <i>ou</i>, is to <i>uy</i>, so + is <i>ei</i>, to <i>is</i>. Here thou hast three bounds of the + proportion. Let therefore <i>ou</i>, be 20 parts: <i>uy</i> 30: And + <i>ei</i>, the knowne part, let it be <!-- Page 128 --><span + class="pagenum"><a name="page128"></a>[128]</span>15 foote: Therefore + thou shalt conclude <i>is</i>, the rest to be 22½.</p> + + <p>The first and second kinde of measuring of heights is thus: The third + followeth.</p> + + <p><a name="14_e_ix"></a> 14 <i>If the sight be from the beginning of the + Index perpendicular to the heighth, as in the Index the difference of the + <span class="correction" title="text reads `segmeut'">segment</span>, is + unto the difference of the distance or station; so is the segment of the + transome unto the heighth</i>.</p> + + <p>Hitherto you must recall that subtilty, which was used in the third + manner of measuring of lengths.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/149.png"><img style="width:100%" src="images/149.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>Let the first aime be taken from <i>a</i>, the beginning of the Index + perpendicular unto the height to be measured: And from an unknowne length + <i>ai</i>, by <i>o</i>, the end of the transome, unto <i>e</i>, the toppe + of the height <i>ei</i>: And let the segment of the Index be <i>ua</i>. + The second ayme, let it be taken from <i>y</i>, the beginning of the same + Index; and out of a <!-- Page 129 --><span class="pagenum"><a + name="page129"></a>[129]</span>greater distance, by <i>s</i>, the end of + the transome, unto the same toppe <i>e</i>. And the segment of the Index + let it be <i><span class="correction" title="text reads `rl'" + >ry</span></i>.</p> + + <p>Here, as afore, the measuring is performed and done, by the taking of + the difference of the said <i>yr</i>, above <i>au</i>: Now the + demonstration is concluded, as in the former was taught. Let the + parallell <i>lsm</i>, be erected against <i>aoe</i>.</p> + + <p>Here first the triangles <i>oua</i>, & <i>srl</i>, are equilaters, + by the <a href="#2_e_vij">2 e vij</a>.; (seeing that the angles at + <i>a</i>, and <i>l</i>, the externall and internall, are equall in bases + <i>ou</i>, and <i>sr</i>, for the segment in each distance is the same + still:) Therefore <i>ua</i>, is equall to <i>rl</i>. Now the rest is + concluded by a sorites of foure degrees: As <i>yr</i>, is unto <i><span + class="correction" title="text reads `yu'">yi</span></i>: so by the <a + href="#12_e_vij">12. e vij</a>. is <i>sr</i>, that is, <i>ou</i>, unto + <i>ei</i>: And as <i>ou</i>, is unto <i>ei</i>, so is <i>au</i>, that is, + <i>lr</i>, unto <i>ai</i>. Therefore the remainder <i>yl</i>, unto the + remainder <i>ya</i>; shall be as <i>yr</i>, is unto the whole <i>yi</i>, + and therefore from the first unto the last, as <i>sr</i>, is to + <i>ei</i>.</p> + + <p>Therefore let the difference of the Index be 23. parts: The difference + of the distance 30. foote: The segment of the transome <span + class="correction" title="text reads `23.'">44.</span> parts: The height + shall be 57.9/23. or foote.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="15_e_ix"></a> 15 <i>Out of the Geodesy of heights, the + difference of two heights is manifest</i>.</p> + + <p>Or thus: By the measure of one altitude, we may know the difference of + two altitudes: <i>H</i>.</p> + + <p>For when thou hast taken or found both of them, by some one of the + former wayes, take the lesser out of the greater; and the remaine shall + be the heighth desired. From hence therefore by one of the towers of + unequall heighth, you may measure the heighth of the other. First out of + the lesser, let the length be taken by the first way: Because the height + of the lesser, wherein thou art, is easie to be taken, either by a + plumbe-line, let fall from the toppe to the bottom, or by some one of the + former waies. Then measure <!-- Page 130 --><span class="pagenum"><a + name="page130"></a>[130]</span>the heighth, which is above the lesser: + And adde that to the lesser, and thou shalt have the whole heighth, by + the first or second way. The figure is thus, and the demonstration is out + of the <a href="#12_e_vij">12. e vij</a>. For as <i>ae</i>, is to + <i>ei</i>, so is <i>ao</i>, to <i>ou</i>. Contrariwise out of an higher + Tower, one may measure a lesser.</p> + + <p><a name="16_e_ix"></a> 16 <i>If the sight be first from the toppe, + then againe from the base or middle place of the greater, by the vanes of + the transome unto the toppe of the lesser heighth; as the said parts of + the yards are unto the part of the first yard; so the heighth betweene + the stations shall be unto his excesse above the heighth desired</i>.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/151.png"><img style="width:100%" src="images/151.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>Let the unequall heights be these, <i>as</i>, the lesser, and + <i>uy</i>, the greater: And out of the assigned greater <i>uy</i>, let + the lesser, <i>as</i>, be sought. And let the sight be first from + <i>u</i>, the toppe of the greater, unto <i>a</i>, the toppe of the + lesser, <!-- Page 131 --><span class="pagenum"><a + name="page131"></a>[131]</span>making at the shankes of the staffe the + triangle <i>urm</i>. Then againe let the same sight be from the base, or + from the lower end of <i>uy</i>, the heighth given, unto <i>a</i>, the + same toppe of the lesser, making by the shankes of the staffe the + triangle <i>yln</i>, so that the segments of the yard be, the upper one, + I meane, <i>ur</i>, the neather one <i>ul</i>: I say the whole of + <i>ur</i>, and <i>nl</i>, is unto <i>ur</i>: so is the <i>uy</i>, greater + heighth assigned, unto <i>as</i>, the lesser sought.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/152.png"><img style="width:100%" src="images/152.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>The Demonstration, by drawing of <i>ao</i>, a perpendicular unto + <i>uy</i>, is a proportion out of two triangles of equall heighth. For + the forth of the totall equally heighted triangles <i>uao</i>, and + <i>yas</i>, although they be reciprocall in situation, they have their + bases <i>uo</i>, and <i>as</i>, as if their were <i>oy</i>. Then they + have the same with the whole triangles; as also the subducted triangles + <i>urm</i>, and <i>ynl</i>, of equal heighth; to wit whose common heighth + is the segment of the transome remained still in the same place, there + <i>rm</i>, here <i>yl</i>. And therefore the bases of these, namely, the + segments of the yards <i>ur</i>, and <i>nl</i>, have the same rate with + <i>uo</i>, unto <i>oy</i>. <!-- Page 132 --><span class="pagenum"><a + name="page132"></a>[132]</span>As therefore <i>uo</i>, is unto <i>oy</i>: + so is, <i>ur</i>, unto <i>nl</i>. And backward, as <i>nl</i>, is to + <i>ur</i>; so is, <i>yo</i>, unto <i>ou</i>, as here thou seest:</p> + +<table class="nobctr"> +<tr><td><i>nl</i>,————<i>ur</i>:</td><td> </td><td><i>yo</i>,————<i>ou</i>.</td></tr> +</table> + + <p>Therefore furthermore by composition of the Antecedent with the + Consequent unto the Consequent, by the 5 c 9 ij. Arith. As <i>nl</i>, and + <i>ur</i>, are unto <i>ur</i>: so are <i>yo</i>, and <i>ou</i>, unto + <i>ou</i>, that is <i>yu</i>, unto <i>ou</i>, on this manner.</p> + +<table class="nobctr"> +<tr><td><i>nl</i>,————<i>ur</i>,</td><td> </td><td><i>yo</i>,————<i>ou</i>,</td></tr> +<tr><td><i>nr</i>,</td><td> </td><td><i>ou</i>,</td></tr> +<tr><td colspan="3">———————————————</td></tr> +<tr><td>... <i>ur</i>,</td><td> </td><td><i>yu</i>, <i>ou</i>,</td></tr> +</table> + + <p>there is given <i>nl</i>, and <i>ur</i>, for the first proportionall: + <i>ur</i>, for the second: and <i>yu</i>, for the third: Therefore there + is also given <i>ou</i>, for the fourth: Which <i>ou</i>, subducted out + of <i>uy</i>, there remaineth <i>oy</i>, that is, <i>as</i>, the lesser + altitude sought.</p> + + <p>For let the parts of the yard be 12. and 6. and the summe of them 18. + Now as 18. is <span class="correction" title="omitted in text" + >unto</span> 12. so is the whole altitude <i>uy</i>, 190. foote, unto the + excesse 126⅔ foote. The remainder therefore 63⅓ foote, + shall be <i>as</i>, the lesser heighth sought.</p> + + <p>But thou maist more fitly dispose and order this proportion thus: As + <i>ur</i>, is unto <i>nl</i>: so is <i>uo</i> unto <i>oy</i>. Therefore + by Arithmeticall composition, as <i>ur</i>, and <i>nl</i>, are unto + <i>nl</i>: so <i>uo</i>, and <i>oy</i>, that is, the whole <i>uy</i>, is + unto <i>oy</i>, that is, unto <i>as</i>. For here a subduction of the + proportion, after the composition is no way necessary, by the crosse rule + of societia, thus:</p> + + <div class="figcenter" style="width:45%;"> + <a href="images/153.png"><img style="width:100%" src="images/153.png" + alt="Crosse rule." title="Crosse rule." /></a> + </div> + <p>The second station might have beene in <i>o</i>, the end of the + perpendicular from <i>a</i>. But by taking the ayme out of the toppe of + the lesser altitude, the demonstration shall be yet againe more easie and + short, by the two triangles at the yard <i>aei</i>, and <i>aef</i>, + resembling the two whole triangles <i>aou</i>, and <i>aoy</i>, in like + situation, the parts of the <!-- Page 133 --><span class="pagenum"><a + name="page133"></a>[133]</span>shanke cut, are on each side the segments + of the transome.</p> + + <p>One may againe also out of the toppe of a Turret measure the distance + of two turrets one from another: For it is the first manner of measuring + of longitudes, neither doth it here differ any whit from it, more than + the yard is hang'd without the heighth given. The figure is thus: And the + Demonstration is by the <a href="#12_e_vij">12. e vij</a>. For as + <i>ae</i>, the segment of the yard, is unto <i>ei</i> the segment of the + transome: so is the assigned altitude <i>ao</i>, unto the length + <i>ou</i>.</p> + + <p>The geodesy or measuring of altitude is thus, where either the length, + or some part of the length is given, as in the first and second way: Or + where the distance is double, as in the third.</p> + + <p><a name="17_e_ix"></a> 17 <i>If the sight be from the beginning of the + yard being right or perpendicular, by the vanes of the transome, unto the + ends of the breadth; as in the yard the difference of the segment is unto + the differēce of the distance, so is the distance of the vanes unto + the breadth</i>.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/154.png"><img style="width:100%" src="images/154.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>The measuring of breadth, that is of a thwart or crosse <!-- Page 134 + --><span class="pagenum"><a name="page134"></a>[134]</span>line, + remaineth. The Figure and Demonstration is thus: The first ayming, let it + be <i>aei</i>, by <i>o</i>, and <i>u</i>, the vanes of the transome + <i>ou</i>. The second, let it be <i>yei</i>, by <i>s</i>, and <i>r</i>, + the vanes of the transome <i>sr</i>. Then by the point <i>s</i>, let the + parallell <i>lsm</i>, be drawne against <i>aoe</i>. Here first, the + triangles <i>oua</i>, and <i>sil</i>, are equilaters, by the <a + href="#2_e_vij">2 e vij</a>. Because the angles at <i>n</i> and <i>j</i>, + are right angles: And <i>uao</i>, and <i>jls</i>, the outter and inner, + are equall in their bases <i>ou</i>, and <i>sj</i>, by the grant: Because + here the segment of the transome remaineth the same: Therefore <i>ua</i>, + is equall to <i>jl</i>. These grounds thus laid, the demonstration of the + third altitude here taken place. For as <i>yl</i>, is unto <i>ya</i>: so + is <i>sj</i>, unto <i>er</i>: And, because parts are proportionall unto + their multiplicants, so is <i>sr</i>, unto <i>ei</i>: for the rest doe + agree.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/155.png"><img style="width:100%" src="images/155.png" + alt="Using Iacobs staffe." title="Using Iacobs staffe." /></a> + </div> + <p>The same shall be the geodesy or manner of measuring, if thou wouldest + from some higher place, measure the breadth that is beneath thee, as in + the last example. But from the distance of two places, that is, from + latitude or breadth, as of Trees, Mountaines, Cities, Geographers and + Chorographers do gaine great advantages and helpes. <!-- Page 135 + --><span class="pagenum"><a name="page135"></a>[135]</span></p> + + <div class="figcenter" style="width:54%;"> + <a href="images/156.png"><img style="width:100%" src="images/156.png" + alt="Geodesy." title="Geodesy." /></a> + </div> + <p>Wherefore the geodesy or measuring of right lines is thus in length, + heighth, and breadth, from whence the Painter, the Architect, and + Cosmographer, may view and gather of many famous place the windowes, the + statues or imagery, pyramides, signes, and lastly, the length and + heighth, either by a single or double: the breadth by a double dimension + onely, that is, they may thus behold and take of all places the nature + and symmetry; as in the example next following thou mayst make triall + when thou pleasest.</p> + +<hr class="full" /> + +<p><!-- Page 136 --><span class="pagenum"><a name="page136"></a>[136]</span></p> + +<h2>The tenth Booke of <i>Geometry</i>, +of a Triangulate and Parallelogramme.</h2> + + <p>And thus much of the geodesy of right lines, by the meanes of + rectangled triangles: It followeth now of the triangulate.</p> + + <p><a name="1_e_x"></a> 1. <i>A triangulate is a rectilineall figure + compounded of triangles</i>.</p> + + <p>As before (for the dichotomies sake) of a line was made a Lineate, to + signifie the <i>genus</i> of surface and a Body: so now is for the same + cause of a triangle made a Triangulate, to declare and expresse the + <i>genus</i> of a Quadrilater and Multilater, and indeed more justly, + then before in a Lineate. For triangles doe compound and make the + triangulate, but lines doe not make the lineate.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="2_e_x"></a> 2. <i>The sides of a triangulate are two more + than are the triangles of which it is made</i>.</p> + + <div class="figcenter" style="width:60%;"> + <a href="images/157.png"><img style="width:100%" src="images/157.png" + alt="Quadrangle and Quinquangles." title="Quadrangle and Quinquangles." /></a> + </div> + <p>As the sides of a Quadrangle are 4. Therefore the triangles which doe + make the same foure-sided figure are but 2. The sides of a Quinquangle + are 5, Therefore the triangles are 3, and so forth of the rest, as here + thou seest. And <!-- Page 137 --><span class="pagenum"><a + name="page137"></a>[137]</span>that indeed is the least: For even a + triangle it selfe, may be cut into as many triangles as one please.</p> + + <p>That both the inner and outter are equall to right angles, in every + kinde of right line figure, it was manifest at the <a href="#4_e_vj">4 e + vj</a>. The inner <span class="correction" title="text reads `is'" + >in</span> a Quadrangle, are equall to 4. In a Quinquangle, to 6: In an + Hexangle, to 8; and so forth.</p> + + <div class="figcenter" style="width:40%;"> + <a href="images/158.png"><img style="width:100%" src="images/158.png" + alt="Hexangles." title="Hexangles." /></a> + </div> + <p>But the outter, in every right-lined figure, are equall to 4 right + angles: as here may be demonstrated, by the <a href="#14_e_v">14 e v</a> + and <a href="#13_e_vj">13 e vj</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="3_e_x"></a> 3. <i>Homgeneall Triangulates are cut into an + equall number of triangles, è 20 p vj</i>.</p> + + <p>For if they be Quadrangles, they be cut into two triangles: If + Quinquangles, into 3. If Hexangles, into 4, and so forth.</p> + + <p><a name="4_e_x"></a> 4. <i>Like triangulates are cut into triangles + alike one to another and homologall to the whole è 20 p vj</i>.</p> + + <p>Or thus: Like Triangulates are divided into triangles like one unto + another, and in porportion correspondent unto the whole: <i>H</i>.</p> + + <p>As in these two <span class="correction" title="text reads `quinqualges'" + >quinquangles</span>. First the particular triangles are like betweene + themselves. For the shankes of <i>aeu</i> and <i>ysm</i>, equall angles + are proportionall, by the grant. Therefore the triangles themselves are + equiangles, by <a href="#14_e_vij">14 e vij</a>. And therefore alike, by + the <a href="#12_e_vij">12 e vij</a>, and so forth of the rest. <!-- Page + 138 --><span class="pagenum"><a name="page138"></a>[138]</span></p> + + <div class="figcenter" style="width:50%;"> + <a href="images/159.png"><img style="width:100%" src="images/159.png" + alt="Like quinquangles." title="Like quinquangles." /></a> + </div> + <p>The middle triangles, the equall angles being substracted shall have + their other angles equall: And therefore they also shall be equiangles + and alike, by the same.</p> + + <p>Secondarily, the triangles <i>aeu</i>. and <i>ysm</i>: <i>eio</i> and + <i>srl</i>; <i>eou</i>, and <i>slm</i>, to wit, alike betweene + themselves, are by the <a href="#1_e_vj">1 e vj</a>, in a double reason + of their homologall sides <i>eu</i>, <i>sm</i>, <i>eo</i>, <i>sl</i>, + which reason is the same, by meanes of the common sides. Therefore three + triangles are in the same reason: And therefore they are proportionall: + And, by the third composition, as one of the antecedents is, unto one of + the consequents; so is the whole quinquangle to the whole.</p> + + <p><a name="5_e_x"></a> 5. <i>A triangulate is a Quadrangle or a + Multangle</i>.</p> + + <p>The parts of this partition are in Euclide, and yet without any shew + of a division. And here also, as before, the species or severall kinds + have their denomination their angles, although it had beene better and + truer to have beene taken from their sides; as to have beene called a + Quadrilater, or a Multilater. But in words use must bee followed as a + master.</p> + + <p><a name="6_e_x"></a> 6. <i>A <span class="correction" title="text reads `Quandrangle'" + >Quadrangle</span> is that which is comprehended of foure right lines. 22 + d j</i>.</p> + + <p>As here thou seest. But a Quadrangle may also bee a sphearicall, and a + conicall, and a cylindraceall, and that <!-- Page 139 --><span + class="pagenum"><a name="page139"></a>[139]</span>those differences are + common, we doe foretell at the <a href="#3_e_v">3 e v</a>. And a + Quadrangle may be a plaine, which is not a quadrilater, as here.</p> + + <div class="figcenter" style="width:39%;"> + <a href="images/160a.png"><img style="width:100%" src="images/160a.png" + alt="Quadrangles." title="Quadrangles." /></a> + </div> + <p><a name="7_e_x"></a> 7. <i>A quadrangle is <span class="correction" + title="text reads `a a'"></span>a Parallelogramme, or a + Trapezium.</i></p> + + <p>This division also in his parts is in the Elements of Euclide, but + without any forme or shew of a division. But the difference of the parts + shall more fitly be distinguished thus: Because in generall there are + many common parallels.</p> + + <div class="figright" style="width:19%;"> + <a href="images/160b.png"><img style="width:100%" src="images/160b.png" + alt="Parallelogramme." title="Parallelogramme." /></a> + </div> + <p><a name="8_e_x"></a> 8. <i>A Parallelogramme is a quadrangle whose + opposite sides are parallell</i>.</p> + + <p>As in the example, the side <i>ae</i>, is parallell to the side + <i>io</i>: And the side <i>ei</i>, is parallell to opposite side + <i>ao</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="9_e_x"></a> 9. <i>If right lines on one and the same side, + doe joyntly bound equall and parallall lines, they shall make a + parallelogramme.</i> <!-- Page 140 --><span class="pagenum"><a + name="page140"></a>[140]</span></p> + + <p>The reason is, because they shall be equall and parallell betweene + themselves, by the <a href="#26_e_v">26. e v</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="10_e_x"></a> 10 <i>A parallelogramme is equall both in his + opposite sides, and angles, and segments cut by the diameter</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/161a.png"><img style="width:100%" src="images/161a.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p>Or thus: The opposite, both sides, and angles, and segments cut by the + diameter are equall. Three things are here concluded: The first is, that + the opposite sides are equall: This manifest by the <a href="#26_e_v">26 + e v</a>. Because two right lines doe jointly bound equall parallells.</p> + + <p>The second, that the opposite angles are equall, the Diagonall + <i>ai</i>, doth shew. For it maketh the triangles <i>aei</i>, and + <i>ioa</i>, equilaters: And therefore also equiangles: And seeing that + the particular angles at <i>a</i>, and <i>i</i>, are equall, the whole is + equall to the whole. This part is the 34. p j;</p> + + <div class="figcenter" style="width:62%;"> + <a href="images/161b.png"><img style="width:100%" src="images/161b.png" + alt="Figure for demonstration 10 the third." title="Figure for demonstration 10 the third." /></a> + </div> + <p>The third: The segments cut by the diameter are alwayes equall, + whether they be triangles, or any manner of quadrangles, as in the + figures. For the Diameter doth cut into two equall parts, the + parallelogramme by the Angles, or by the opposite sides, or by the <span + class="correction" title="text reads `alernall'">alternall</span> equall + segments of the sides.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 141 --><span class="pagenum"><a name="page141"></a>[141]</span></p> + + <p><a name="11_e_x"></a> 11. <i>The Diameter of a parallelogramme is cut + into two by equall raies</i>.</p> + + <p>As in the three figures <i>aei</i>, next before: This a + parallelogramme hath common with a circle, as was manifest at the <a + href="#28_e_iiij">28. e iiij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:18%;"> + <a href="images/162a.png"><img style="width:100%" src="images/162a.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p><a name="12_e_x"></a> 12 <i>A parallelogramme is the double of a + triangle of a trinangle of equall base and heighth, 41. p j</i>.</p> + + <p>The comparison first in rate of inequality of a parallelogramme with a + triangle, doth follow: As here thou seest in this diagramme. For a + parallelogramme is cut into two equall triangles, by the antecedent. + Therefore it is the double of the halfe.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="13_e_x"></a> 13 <i>A parallelogramme is equall to a triangle + of equall heighth and double base unto it: è 42. p j.</i></p> + + <p>As to <i>aei</i>, the triangle, the parallelogramme <i>aoiu</i>, is + equall: because halfe of the parallelogramme is equall to the triangle: + Therefore the halfes being equall, whole also shall be equall.</p> + + <div class="figright" style="width:19%;"> + <a href="images/162b.png"><img style="width:100%" src="images/162b.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>From whence one may</p> + </div> + </div> + <p><a name="14_e_x"></a> 14 <i>To a triangle given, in a rectilineall + angle given, make an equall parallelogramme</i>.</p> + + <div class="figleft" style="width:27%;"> + <a href="images/162c.png"><img style="width:100%" src="images/162c.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>As here to the triangle, <i>aei</i>, given in <i>s</i>, the right + lined angle given, you may equall the parallelogramme <i>ouyi</i>. <!-- + Page 142 --><span class="pagenum"><a name="page142"></a>[142]</span></p> + + <p><a name="15_e_x"></a> 15 <i>A parallelogramme doth consist both of two + diagonals, and complements, and gnomons</i>.</p> + + <p>For these three parts of a parallelogramme are much used in + Geometricall workes and businesses, and therefore they are to be + defined.</p> + + <p><a name="16_e_x"></a> 16 <i>The Diagonall is a particular + parallelogramme having both an angle and diagonall diameter common with + the whole parallelogramme</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/163.png"><img style="width:100%" src="images/163.png" + alt="Diagonall." title="Diagonall." /></a> + </div> + <p>First the Diagonall is defined: As in the whole parallelogramme + <i>aeio</i>, the diagonals are <i>auys</i>, and <i>ylir</i>; Because they + are parts of the whole, having both the same common angles at <i>a</i>, + and <i>i</i>: and diagonall diameter <i>ai</i>, with the whole + parallelogramme: Not that the whole diagonie is common to both: But + because the particular diagonies are the parts of the whole diagony. + Therefore the diagonalls are two.</p> + + <p><a name="17_e_x"></a> 17 <i>The Diagonall is like, and alike situate + to the whole parallelogramme: è 24. p vj</i>.</p> + + <p>There is not any, either rate or proportion of the diagonall + propounded, onely similitude is attributed to it, as in the same figure, + the Diagonall <i>auys</i>, is like unto the whole parallelogramme + <i>aeio</i>. For first it is equianglar to it. For the angle at <i>a</i>, + is common to them both: And that is equall to that which is at <i>y</i>, + (by the <a href="#10_e_x">10. e x</a>:) And therefore also it is equall + to that at <i>i</i> by the <a href="#10_e_x">10. e x</a>. Then the angles + <i>auy</i>, and <i>asy</i>, are equall, by the <a href="#21_e_v">21. e + v</a>. to the opposite inner angles at <i>e</i>, and <i>o</i>. Therefore + it is equiangular unto it.</p> + + <p>Againe, it is proportionall to it in the shankes of the <!-- Page 143 + --><span class="pagenum"><a name="page143"></a>[143]</span>equall angles. + For the triangles <i>auy</i>, and <i>aei</i>, are alike, by the <a + href="#12_e_vij">12 e vij</a>, because <i>uy</i> is parallell to the + base. Therefore as <i>au</i> is <i>uy</i>; so is <i>ai</i> to <i>ei</i>: + Then as <i>uy</i> is to <i>ya</i>; so is <i>ei</i> to <i>ia</i>. Againe + by the <a href="#21_e_v">21 e v</a>, because <i>sy</i> is parallell to + the base <i>io</i>, as <i>ay</i> is to <i>ys</i>: so is <i>ai</i>, to + <i>io</i>: Therefore equiordinately, as <i>uy</i> is to <i>ys</i>: so is + <i>ei</i> to <i>io</i>: Item as <i>sy</i> is to <i>ya</i>, so is + <i>io</i> to <i>ia</i>: And as <i>ya</i> is to <i>as</i>: so is <i>ia</i> + to <i>ao</i>. Therefore equiordinately, as <i>ys</i> is to <i>sa</i>: so + is <i>io</i> to <i>oa</i>. Lastly as <i>sa</i> is unto <i>ay</i>; so is + <i>oa</i> unto <i>ai</i>: And as <i>ay</i> is to <i>au</i>; so is + <i>ai</i> unto <i>ae</i>. Therefore equiordinately, as <i>sa</i> is to + <i>au</i>: so is <i>ao</i>, to <i>ae</i>. Wherefore the Diagonall + <i>su</i> is proportionall in the shankes of equall angles to the + parallelogramme <i>oe</i>.</p> + + <p>The demonstration shall be the same of the Diagonall <i>rl</i>. The + like situation is manifest, by the <a href="#21_e_iiij">21 e iiij</a>. + And from hence also is manifest, That the diagonall of a Quadrate, is a + Quadrate: Of an Oblong, an Oblong: Of a Rhombe, a Rhombe: Of a + Rhomboides, a Rhomboides: because it is like unto the whole, and a like + situate.</p> + + <p>Now the Diagonalls seeing they are like unto the whole and a like + situate, they shall also be like betweene themselves and alike situate + one to another, by the <a href="#21_e_iiij">21</a> and <a + href="#22_e_iiij">22 e iiij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figleft" style="width:18%;"> + <a href="images/164.png"><img style="width:100%" src="images/164.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p><a name="18_e_x"></a> 18. <i>If the particular parallelogramme have + one and the same angle with the whole, be like and alike situate unto it, + it is the Diagonall. 26 p vj</i>.</p> + + <p>This might have beene drawn, as a consectary, out of the former: But + it may also as it is by Euclide be forced, by an argument <i>ab + impossibili</i>. For otherwise the whole should be equall to the part, + which is impossible.</p> + + <p>As for example, Let the particular parallelogramme <i>auys</i>, be + <!-- Page 144 --><span class="pagenum"><a + name="page144"></a>[144]</span>coangular to the whole parallelogramme + <i>aeio</i>; And let it have the same angle with it at <i>a</i>; like + unto the whole and alike situate unto it; I say it is the Diagonall.</p> + + <p>Otherwise, let the diverse Diagony be <i>aro</i>: And let <i>lr</i> be + parallell against <i>ae</i>: Therefore <i>alrs</i>, shall bee the + Diagonall, by the 6 e [<a href="#16_e_x"><span class="correction" + title="text reads `15'">16</span></a>.] Now therefore it shall be, by 8 e + [<a href="#17_e_x"><span class="correction" title="text reads `16 e'">17 + e,</span></a>] as <i>ea</i> is to <i>ai</i>: so is <i>sa</i> unto + <i>al</i>: Againe,by the grant, as <i>ea</i> is unto <i>ai</i>: so is + <i>sa</i> to <i>au</i>: Therefore the same <i>sa</i> is proportionall to + <i>al</i>, and to <i>au</i>: And <i>al</i> is equall to <i>au</i>, the + part to the whole, which is impossible.</p> + + <div class="figright" style="width:19%;"> + <a href="images/165a.png"><img style="width:100%" src="images/165a.png" + alt="Complements." title="Complements." /></a> + </div> + <p><a name="19_e_x"></a> 19. <i>The Complement is a particular + parallelogramme, comprehended of the conterminall sides of the + diagonals</i>.</p> + + <p>Or thus: It is a particular parallelogramme conteined under the next + adjoyning sides of the diagonals.</p> + + <p>As in this figure, are <i>ur</i>, and <i>sy</i>: For each of them is + comprehended of the continued sides of the two diagonals. And therefore + are they called Complements, because they doe with the Diagonals + <i>complere</i>, that is, fill or make up the whole parallelogramme. + Neither in deed may the two diagonals be described, but withall the + complements must needes be described.</p> + + <div class="figleft" style="width:18%;"> + <a href="images/165b.png"><img style="width:100%" src="images/165b.png" + alt="Figure for demonstration 20." title="Figure for demonstration 20." /></a> + </div> + <p><a name="20_e_x"></a> 20. <i>The complements are equall. 43 p + j</i>.</p> + + <p>As in the same figure, are the sayd <i>ur</i>, and <i>sr</i>: For the + triangles <i>aei</i>, and <i>aoi</i>, are equall, by the <a + href="#12_e_x">12 e</a>. Item, so are <i>asl</i>, and <i>aul</i>: Item, + so are <i>lui</i>, and <i>lri</i>. Therefore if you shall on each side + take away equall triangles from those which are <!-- Page 145 --><span + class="pagenum"><a name="page145"></a>[145]</span>equall, you shall leave + the Complements equall betweene themselves.</p> + + <p> Therefore</p> + + <p><a name="21_e_x"></a> 21. <i>If one of the Complements be made equall + to a triangle given, in a right-lined angle given, the other made upon a + right line given shall be in like manner equall to the same triangle. 44 + p j</i>.</p> + + <div class="figright" style="width:25%;"> + <a href="images/166.png"><img style="width:100%" src="images/166.png" + alt="Figure for demonstration 21." title="Figure for demonstration 21." /></a> + </div> + <p>As if thou shouldest desire to have a parallelogramme upon a right + line given, and in a right lined angle given, to be made equall to a + triangle given, this proposition shall give satisfaction.</p> + + <p>Let <i>aei</i> be the Triangle given: The Angle be <i>o</i>: And the + right line given be <i>iu</i>: And the Parallelogramme <i>ay</i> is + equall to <i>aei</i>, triangle given in the angle assigned, by the <a + href="#13_e_x">13 e</a>. Then let the side <i>ay</i>, bee continued to + <i>r</i>, equally to <i>iu</i>, the line given: And let <i>ru</i> be knit + by a right line: And from <i>r</i> drawne out a diagony untill it doe + meete with <i>as</i>, infinitely continued; which shall meete with it, by + the <a href="#19_e_v">19 e v</a>, in <i>l</i>. And the sides <i>yi</i>, + and <i>ru</i>, let them be continued equally to <i>sl</i>. in <i>m</i> + and <i>n</i>. And knit <i>ln</i> together with a right line. This + complement <i>mu</i>, is equall to the complement <i>ys</i>, which is + equall to the Triangle assigned, by the former, and that in a right lined + angle given.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="22_e_x"></a> 22 <i>If parallelogrammes be continually made + equall to all the triangles of an assigned triangulate, in a right lined + angle given, the whole parallelogramme shall in like manner be equall to + the whole triangulate. 45 p j</i>.</p> + + <p>This is a corollary of the former, of the Reason or rate of a + Parallelogramme with a Triangulate; and it needeth no <!-- Page 146 + --><span class="pagenum"><a name="page146"></a>[146]</span>farther + demonstration; but a ready and steddy hand in describing and working of + it.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/167a.png"><img style="width:100%" src="images/167a.png" + alt="Triangulate." title="Triangulate." /></a> + </div> + <p>Take therefore an infinite right line; upon the continue the + particular parallelogrammes, As if the Triangulate <i>aeiou</i>, were + given to be brought into a parallelogramme: Let it be resolved into three + triangles, <i>aei</i>, <i>aio</i>, and <i>aou</i>: And let the Angle be + <i>y</i>: First in the assigned Angle, upon the Infinite right line, make + by the former the Parallelogramme <i>ae</i>, in the angle assigned, + equall to <i>aei</i>, the first triangle. Then the second triangle, thou + shalt so make upon the said Infinite line, that one of the shankes may + fall upon the side of the equall complement; The other be cast on + forward, and so forth in more, if neede be.</p> + + <div class="figright" style="width:22%;"> + <a href="images/167b.png"><img style="width:100%" src="images/167b.png" + alt="Complements." title="Complements." /></a> + </div> + <p>Here thou hast 3 complements continued, and continuing the + Parallelogramme: But it is best in making and working of them, to put out + the former, and one of the sides of the inferiour or latter Diagonall, + least the confusion of lines doe hinder or trouble thee.</p> + + <p> Therefore</p> + + <p><a name="23_e_x"></a> 23. <i>A Parallelogramme is equall to his + diagonals and complements</i>.</p> + + <p>For a Parallelogramme doth consist of two diagonals, and as many + complements: Wherefore a Parallelogramme is equall to his parts: And + againe the parts are equall to their whole.</p> + + <p><a name="24_e_x"></a> 24. <i>The Gnomon is any one of the Diagonall + with the two complements</i>.</p> + + <p>There is therefore in every Parallelogramme a double Gnomon; as in + these two examples. Of all the space of a <!-- Page 147 --><span + class="pagenum"><a name="page147"></a>[147]</span>parallelogramme about + his diameter, any parallelogramme with the two complements, let it be + called the Gnomon. Therefore the gnomon is compounded, or made of both + the kindes of diagonall and complements.</p> + + <div class="figleft" style="width:26%;"> + <a href="images/168a.png"><img style="width:100%" src="images/168a.png" + alt="Gnomons." title="Gnomons." /></a> + </div> + <p>In the Elements of Geometry there is no other use, as it seemeth of + the gnomons than that in one word three parts of a parallelogramme might + be signified and called by three letters <i>aei</i>. Otherwise gnomon is + a perpendicular.</p> + + <p><a name="25_e_x"></a> 25. <i>Parallelogrames of equall height are one + to another as their bases are. 1 p vj</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/168b.png"><img style="width:100%" src="images/168b.png" + alt="Figure for demonstration 25." title="Figure for demonstration 25." /></a> + </div> + <p>As is apparent, by the <a href="#16_e_iiij">16 e iiij</a>. Because + they be the double of Triangles, by the <a href="#12_e_x"><span + class="correction" title="text reads `10 e'">12 e</span></a>, of first + figures: As <i>ae</i>, and <i>ei</i>.</p> + + <p> Therefore</p> + + <p><a name="26_e_x"></a> 26 <i>Parallelogrammes of equall height upon + equall bases are equall. 35. 36 pj</i>.</p> + + <p>As is manifest in the same example.</p> + + <p><a name="27_e_x"></a> 27 <i>If equiangle parallelogrammes be + reciprocall in the shankes of the equall angle, they are equall: And + contrariwise. 15 p vj</i>.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/168c.png"><img style="width:100%" src="images/168c.png" + alt="Figure for demonstration 27." title="Figure for demonstration 27." /></a> + </div> + <p>It is a consectary drawne out of the <a href="#11_e_vij">11 e vij</a>: + As here thou seest: And yet indeed both that (as there was sayd) and this + is rather a consectary of the <a href="#18_e_iiij">18 e iiij</a>, which + here also is more manifest.</p> + + <p> Therefore</p> + +<p><!-- Page 148 --><span class="pagenum"><a name="page148"></a>[148]</span></p> + + <p><a name="28_e_x"></a> 28 <i>If foure right lines be proportionall, the + parallelogramme made of the two middle ones, is equall to the equiangled + parallelogramme made of the first and last: And contrariwise, e 16 p + vj</i>.</p> + + <p>For they shall be equiangled parallelogrammes reciprocall in the + shankes of the equall angle.</p> + + <p> And</p> + + <p><a name="29_e_x"></a> 29 <i>If three right lines be proportionall, the + parallelogramme of the middle one is equall to the equiangled + parallelogramme of the extremes: And contrariwise</i>.</p> + + <p>It is a consectary drawne out of the former.</p> + +<hr class="full" /> + +<h2>Of <i>Geometry</i>, the eleventh Booke, +of a Right angle.</h2> + + <p><a name="1_e_xj"></a> 1. <i>A Parallelogramme is a Right angle or an + Obliquangle</i>.</p> + + <p>Hitherto we have spoken of certaine common and generall matters + belonging unto parallelogrammes: specials doe follow in Rectangles and + Obliquangles, which difference, as is aforesaid, is common to triangles + and triangulates. But at this time we finde no fitter words whereby to + distinguish the generals.</p> + + <p><a name="2_e_xj"></a> 2. <i>A Right angle is a parallelogramme that + hath all his angles right angles</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/169.png"><img style="width:100%" src="images/169.png" + alt="A Right angle." title="A Right angle." /></a> + </div> + <p>As in <i>aeio</i>. And here hence you must understand by one right + angle that all are right angles. For the right angle at <i>a</i>, is + equall to the opposite angle at <i>i</i>, by the <a href="#10_e_x">10 e + x</a>.</p> + + <p>And therefore they are both right angles, by the <a + href="#14_e_iij">14 e iij</a>. The other angle at <i>e</i>, and <i>o</i>, + by the <a href="#4_e_vj">4 e vj</a>, are equall to two right angles: And + they are equall betweene themselves, by the <a href="#10_e_x">10 e x</a>. + Therefore all of them are right angles. Neither <!-- Page 149 --><span + class="pagenum"><a name="page149"></a>[149]</span>may it indeed possible + be, that in a parallelogramme there should be one right angle, but by and + by they must be all right angles.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="3_e_xj"></a> 3 <i>A rightangle is comprehended of two right + lines comprehending the right angle 1. d ij</i>.</p> + + <p><i>Comprehension</i>, in this place doth signifie a certaine kind of + Geometricall multiplication. For as of two numbers multiplied betweene + themselves there is made a number: so of two sides (<i>ductis</i>) driven + together, a right angle is made: And yet every right angle is not + rationall, as before was manifest, at the <a href="#12_e_iiij">12. e + iiij</a>, and shall after appeare at the <a href="#9_e_xj"><span + class="correction" title="text reads `8 e'">9 e</span></a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="4_e_xj"></a> 4 <i>Foure right angles doe fill a + place</i>.</p> + + <p>Neither is it any matter at all whether the foure rectangles be + equall, or unequall; equilaters, or unequilaters; homogeneals, or + heterogenealls. For which way so ever they be turned, the angles shall be + right angles: And therefore they shall fill a place.</p> + + <div class="figright" style="width:17%;"> + <a href="images/170.png"><img style="width:100%" src="images/170.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p><a name="5_e_xj"></a> 5 <i>If the diameter doe cut the side of a right + angle into two aquall parts, it doth cut it perpendicularly: And + contrariwise</i>.</p> + + <p>As here appeareth by the <a href="#1_e_vij">1 e vij</a>. by drawing of + the diagonies of the bisegments. The converse is manifest, by the <a + href="#2_e_vij">2 e vij</a>. and <span class="correction" title="wrong reference but I cannot deduce the correction." + >17. e vij</span>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="6_e_xj"></a> 6 <i>If an inscribed right line doe + perpendicularly cut the side of the right angle into two equall parts, it + is the diameter</i>.</p> + + <p>The reason is, because it doth cut the parallelogramme into two equall + portions.</p> + + <p><a name="7_e_xj"></a> 7 <i>A right angle is equall to the rightangles + <!-- Page 150 --><span class="pagenum"><a + name="page150"></a>[150]</span>made of one of his sides and the segments + of the other</i>.</p> + + <p>As here the foure particular right angles are equall to the whole, + which are made of <i>ae</i>, one of his sides, and of <i>ei</i>, + <i>io</i>, <i>ou</i>, <i>uy</i>, the segments of the other.</p> + + <div class="figcenter" style="width:26%;"> + <a href="images/171a.png"><img style="width:100%" src="images/171a.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>The Demonstration of this is from the rule of congruency: Because the + whole agreeth to all his parts. But the same reason in numbers is more + apparent by an induction of the parts: as foure times eight are 32. I + breake or divide 8. into 5. and 3. Now foure times 5. are 20. And foure + times 3. are 12. And 20. and 12. are 32. And 32. and 32. are equall. + Therefore 20. and 12. are also equall to 32.</p> + + <p>Lastly, every arithmeticall multiplication of the whole numbers doth + make the same product, that the multiplication of the one of the whole + numbers given, by the parts of the other shall make: yea, that the + multiplication of the parts by the parts shall make. This proportion is + cited by <i>Ptolomey</i> in the 9. Chapter of the 1 booke of his + Almagest.</p> + + <p><a name="8_e_xj"></a> 8 <i>If foure right lines be proportionall, the + rectangle of the two middle ones, is equall to the rectangle of the two + extremes. 16. p vj</i>.</p> + + <div class="figcenter" style="width:28%;"> + <a href="images/171b.png"><img style="width:100%" src="images/171b.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>It is a speciall consectary out of the <a href="#28_e_x">28 e x</a>. + As here are foure right lines proportionall betweene themselves: And the + rectangle of the extremes, or first and last let it be <i>ay</i>: Of the + middle ones, let it be <i>se</i>.</p> + + <p><a name="9_e_xj"></a> 9 <i>The figurate of a rationall rectangle is + called a rectinall plaine. 16. d vij</i>.</p> + + <p>A rationall figure was defined at the <a href="#12_e_iiij">12. e + iiij</a>. of which <!-- Page 151 --><span class="pagenum"><a + name="page151"></a>[151]</span>sort amongst all the rectilineals hitherto + spoken of, we have not had one: The first is a Right angled + parallelogramme; And yet not every one indifferently: But that onely + whose base is rationall to the highest: And that reason of the base and + heighth is expressable by a number, where also the Figurate is defined. A + rectangle or irrational sides, such as were mentioned at the <a + href="#9_e_j">9 e j</a>. is irrationall. Therefore a rectangled rationall + of rationall sides, is here understood: And the figurate thereof, is + called, by the generall name, A <i>Plaine:</i> Because of all the kindes + of <i>Plaines</i>, this kinde onely is rationall.</p> + + <div class="figright" style="width:18%;"> + <a href="images/172b.png"><img style="width:100%" src="images/172b.png" + alt="Rectangled parallellogramme of 40. square foote." title="Rectangled parallellogramme of 40. square foote." /></a> + </div> + <div class="figright" style="width:13%;"> + <a href="images/172a.png"><img style="width:100%" src="images/172a.png" + alt="Rectinall plaine." title="Rectinall plaine." /></a> + </div> + <p>If therefore the Base of a Rectangle be 6. And the height 4. The plot + or content shall be 24. And if it be certaine that the rectangles content + be 24. And the base be 6. It shall also be certaine that the heighth is + 4. The example is thus.</p> + + <p>And this multiplication, as appeared at the <a href="#13_e_iiij">13. e + iiij</a>. is geometricall: As if thou dost multiply 5. by 8. thou makest + 40. for the Plaine: And the sides of this Plaine, are 5. and 8. it is all + one as if thou hadst made a rectangled parallellogramme of 40. square + foote content, whose base should be 5. foote, and the heigth 8. after + this manner.</p> + + <p>This manner of multiplication, say I, is Geometricall: Neither are + there here, of lines made lines, as there of unities were made unities; + but a magnitude one degree higher, to wit, a surface, is here made.</p> + + <p>Here hence is the <i>Geodesy</i> or manner of measuring of a + rectangled triangle made knowne unto us. For when thou shalt multiply the + shankes of a right angle, the one by the other, thou dost make the whole + rectangled parallelogramme, whose halfe is a triangle, by the <a + href="#12_e_x">12. e x</a>.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<p><!-- Page 152 --><span class="pagenum"><a name="page152"></a>[152]</span></p> + +<h2>Of Geometry the twelfth Booke, +Of a Quadrate.</h2> + + <p><a name="1_e_xij"></a> 1 <i>A Rectangle is a Quadrate or an + Oblong</i>.</p> + + <p>This division is made in the proper termes: but the thing it selfe and + the subject difference is common out of the angles and sides.</p> + + <p><a name="2_e_xij"></a> 2 <i>A Quadrate is a rectangle equilater 30. d + j</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/173.png"><img style="width:100%" src="images/173.png" + alt="Quadrate." title="Quadrate." /></a> + </div> + <p><i>Quadratum</i>, a Quadrate, or square, is a rectangled + parallellogramme of equall sides: as here thou seest <i><span + class="correction" title="text reads `aeao'">aeio</span></i>, to be.</p> + + <p>Plaines are with us, according to their diverse natures and qualities, + measured with divers and sundry kindes of measures. Boord, Glasse, and + Paving-stone are measured by the foote: Cloth, Wainscote, Painting, + Paving, and such like, by the yard: Land, and Wood, by the Perch or + Rodde.</p> + + <p>Of Measures and sundry sorts thereof commonly used and mentioned in + histories we have in the former spoken at large: Yet for the farther + confirmation of some thing then spoken, and here againe now upon this + particular occasion repeated, it shall not be amisse to heare what our + Statutes speake of these three sorts here mentioned.</p> + + <p>It is ordained, saith the Statute, That three Barley-cornes dry and + round, doe make an <i>Ynch</i>: twelve ynches doe make a <i>Foote</i>: + three foote doe make a <i>Yard</i>: Five yards and an halfe doe make a + <i>Perch</i>: Fortie perches in length, and foure in breadth doe make an + <i>Aker</i>. <i>33. Edwardi 1. De Terris mensurandis.</i> Item, <i>De + compositione Ulnarum & Perticarum</i>.</p> + + <p>Moreover observe, that all those measures there spoken <!-- Page 153 + --><span class="pagenum"><a name="page153"></a>[153]</span>of were onely + lengths: These here now last repeated, are such as the magnitudes by + <span class="correction" title="text reads `the'">them</span> measured + are, in Planimetry, I meane, they are Plaines: In Stereometry they are + solids, as hereafter we shall make manifest. Therefore in that which + followeth, An <i>ynch</i> is not onely a length three barley-cornes long: + but a plaine three barley-cornes long, and three broad. A <i>Foote</i> is + not onely a length of 12. ynches: But a plaine also of 12. ynches square, + or containing 144. square ynches: A <i>yard</i> is not onely the length + of three foote: But it is also a plaine 3. foote square every way. A + <i>Perch</i> is not onely a length of 5½. yards: But it is a plot of + ground 5½. yards square every way.</p> + + <p>A Quadrate therefore or square, seeing that it is equilater that is of + equall sides: And equiangle by meanes of the equall right angles, of + <span class="correction" title="text reads `quandrangles'" + >quadrangles</span> that onely is ordinate.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="3_e_xij"></a> 3 <i>The sides of equall quadrates, are + equall</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p>The sides of equall quadrates are equally compared: If therefore two + or more quadrates be equall, it must needs follow that their sides are + equall one to another.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="4_e_xij"></a> 4 <i>The power of a right line is a + quadrate</i>.</p> + + <p>Or thus: The possibility of a right line is a square <i>H</i>. A right + line is said <i>posse quadratum</i>, to be in power a square; because + being multiplied in it selfe, it doth make a square.</p> + + <div class="figright" style="width:19%;"> + <a href="images/175.png"><img style="width:100%" src="images/175.png" + alt="Figure for demonstration 4." title="Figure for demonstration 4." /></a> + </div> + <p><a name="5_e_xij"></a> 5 <i>If two conterminall perpendicular equall + right lines be closed with parallells, they shall make a quadrate. 46. p. + j</i>.</p> + + <p>Or thus: If two equall perpendicular lines, ioyning one with another, + be inclosed together by parallell lines they will make a square. + <i>H</i>. As in <i>aeio</i>, let the perpendiculars <i>ae</i>, and + <i>ei</i>, equall betweene themselves, be closed with two parallells, + <i>ao</i>, against <i>ei</i>: And <i>oi</i>, against <i>ae</i>; they <!-- + Page 154 --><span class="pagenum"><a name="page154"></a>[154]</span>shall + make the quadrate or square <i>aeio</i>. For it is a parallelogramme, by + the grant: Because the opposite sides are parallell: And it is + rectangled: because seeing the angle <i>aei</i>, of the perpendicular + lines, is a right angle, they shall be all right angles by the <a + href="#2_e_xj">2 e xj</a>. Then one side <i>ei</i>, is equall to all the + rest. First to <i>ao</i>, that over against it, by the <a href="#8_e_x">8 + e x</a>. And then to <i>ea</i>, by the grant: And therefore to <i>oi</i>, + to that over against it, by the <a href="#8_e_x">8 e x</a>.</p> + + <p><a name="6_e_xij"></a> 6 <i>The plaine of a quadrate is an equilater + plaine</i>.</p> + + <p>Or thus: The plaine number of a square, is a plaine number of equall + sides, <i>H</i>.</p> + + <p>A quadrate or square number, is that which is equally equall: Or that + which is comprehended of two equall numbers, A quadrate of all plaines is + especially rationall; and yet not alwayes: But that onely is rationall + whose number is a quadrate. Therefore the quadrates of numbers not + quadrates, are not rationalls.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="7_e_xij"></a> 7 <i>A quadrate is made of a number multiplied + by it self</i>.</p> + + <p>Such quadrates are the first nine. 1, 4, 9, 16, 25, 36, 49, 64, 81, + made of once one, twice two, thrise three, foure times foure, five times + five, sixe times sixe, seven times seven, eight times eight, and nine + times nine. And this is the summe of the making and invention of a + quadrate number of multiplication of the side given by it selfe.</p> + +<table class="nobctr"> +<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td><td>8</td><td>9.</td><td>The sides given.</td></tr> +<tr><td>1 </td><td>4 </td><td>9 </td><td>16</td><td>25</td><td>36</td><td>49</td><td>64</td><td>81.</td><td>The quadrates found.</td></tr> +</table> + + <p>Hereafter diverse comparisons of a quadrate or square, with a + rectangle, with a quadrate, <span class="correction" title="text reads `aud'" + >and</span> with a rectangle and a quadrate iointly. The comparison or + rate of a quadrate with a rectangle is first.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> +<p><!-- Page 155 --><span class="pagenum"><a name="page155"></a>[155]</span></p> + + <div class="figright" style="width:19%;"> + <a href="images/176a.png"><img style="width:100%" src="images/176a.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p><a name="8_e_xij"></a> 8 <i>If three right lines be proportionall, the + quadrate of the middle one, shall be equall to the rectangle of the + extremes: And contrariwise: 17. p vj. and 20. p vij</i>.</p> + + <p>Or thus: If three lines be proportionall, the square made of the + middle line is equall to the right angled parallelogramme made of the two + outmost lines: <i>H</i>.</p> + + <p>It is a corallary out of the <a href="#28_e_x">28. e x</a>. As in + <i>ae</i>, <i>ei</i>, <i>io</i>.</p> + + <p><a name="9_e_xij"></a> 9 <i>If the base of a triangle doe subtend a + right angle, the powre of it is as much as of both the shankes: And + contrariwise 47, 48. p j</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/176b.png"><img style="width:100%" src="images/176b.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p>It is a consectary out of the <a href="#11_e_viij">11. e viij</a>. But + it is sometime rationall, and to be expressed by a number: yet but in a + scalene triangle onely. For the sides of an equicrurall right-angled + triangle are irrationall; Whereas the sides of a scalene are sometime + rationall; and that after two manners, the one of <i>Pythagoras</i>, the + other of <i>Plato</i>, as <i>Proclus</i> teacheth, at the 47. p j. + <i>Pythagora's</i> way is thus, by an odde number.</p> + + <div class="figright" style="width:13%;"> + <a href="images/177a.png"><img style="width:100%" src="images/177a.png" + alt="Pythagora's way." title="Pythagora's way." /></a> + </div> + <p><a name="10_e_xij"></a> 10 <i>If the quadrate of an odde number, given + for the first shanke, be made lesse by an unity; the halfe of the + remainder shall be the other shanke; increased by an unity it shall be + the base</i>.</p> + + <p>Or thus: If the square of an odde number given for the first <!-- Page + 156 --><span class="pagenum"><a name="page156"></a>[156]</span>foote, + have an unity taken from it, the halfe of the remainder shall be the + other foote, and the same halfe increased by an unitie, shall be the + base: <i>H</i>.</p> + + <p>As in the example: The sides are 3, 4, and 5. And 25. the square of 5. + the base, is equall to 16. and 9. the squares of the shanks 4. and 3.</p> + + <p>Againe, the quadrate or square of 3. the first shanke is 9. and 9 - 1. + is 8, whose halfe 4, is the other shanke. And 9 + 1, is 10. whose halfe + 5. is the base. <i>Plato's</i> way is thus by an even number.</p> + + <p><a name="11_e_xij"></a> 11 <i>If the halfe of an even number given for + the first shanke be squared, the square number diminished by an unity + shall be the other shanke, and increased by an unitie it shall be the + base</i>.</p> + + <div class="figcenter" style="width:23%;"> + <a href="images/177b.png"><img style="width:100%" src="images/177b.png" + alt="Plato's way." title="Plato's way." /></a> + </div> + <p>As in this example where the sides are 6, 8. and 10. For 100. the + square of 10. the base is equall to 36. and 64. the squares of the + shankes 6. and 8.</p> + + <p>Againe, the quadrate or square of 3. the halfe of 6, the first shanke, + is 9. and 9 - 1, is 8, for the second shanke. And out of this rate of + rationall powers (as <i>Vitruvius</i>, in the 2. Chapter of his IX. + booke) saith <i>Pythagoras</i> taught how to make a most exact and true + squire, by joyning of three rulers together in the forme of a triangle, + which are one unto another as 3, 4. and 5. are one to another.</p> + + <p>From hence Architecture learned an Arithmeticall proportion in the + parts of ladders and stayres. For that rate or proportion, as in many + businesses and measures is very commodious; so also in buildings, and + making of ladders or staires, that they may have moderate rises of the + steps, it is very speedy. For 9 + 1. is, 10, base. <!-- Page 157 --><span + class="pagenum"><a name="page157"></a>[157]</span></p> + + <p><a name="12_e_xij"></a> 12. <i>The power of the diagony is twise + asmuch, as is the power of the side, and it is unto it also + incommensurable</i>.</p> + + <div class="figright" style="width:26%;"> + <a href="images/178.png"><img style="width:100%" src="images/178.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>Or thus: The diagonall line is in power double to the side, and is + incommensurable unto it, <i>H</i>.</p> + + <p>As here thou seest, let the first quadrate bee <i>aeio:</i> Of whose + diagony <i>ai</i>, let there be made the quadrate <i>aiuy:</i> This, I + say, shall be the double of that: seeing that the diagonies power is + equall to the power of both the equall shankes. Therefore it is double to + the power of one of them.</p> + + <p>This is the way of doubling of a square taught by <i>Plato</i>, as + <i>Vitruvius</i> telleth us: Which notwithstanding may be also doubled, + trebled, or according to any reason assigned increased, by the <a + href="#25_e_iiij">25 e iiij</a>, as there was foretold.</p> + + <p>But that the Diagony is incommensurable unto the side it is the 116 p + x. The reason is, because otherwise there might be given one quadrate + number, double to another quadrate number: Which as <i>Theon</i> and + <i>Campanus</i> teach us, is impossible to be found. But that reason + which <i>Aristotle</i> bringeth is more cleare which is this; Because + otherwise an even number should be odde. For if the Diagony be 4, and the + side 3: The square of the Diagony 16, shall be double to the square of + the side: And so the square of the side shall be 8. and the same square + shall be 9, to wit, the square of 3. And so even shall be odde, which is + most absurd.</p> + + <p>Hither may be added that at the 42 p x. That the segments of a right + line diversly cut; the more unequall they are the greater is their + power.</p> + + <p><a name="13_e_xij"></a> 13. <i>If the base of a right angled triangle + be cut by a <!-- Page 158 --><span class="pagenum"><a + name="page158"></a>[158]</span>perpendicular from the right angle in a + doubled reason, the power of it shall be halfe as much more, as is the + power of the greater shanke: But thrise so much as is the power of the + lesser. If in a quadrupled reason, it shall be foure times and one fourth + so much as is the greater: But five times so much as is the lesser, At + the 13, 15, 16 p xiij</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/179a.png"><img style="width:100%" src="images/179a.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p>Or thus: If the base of a right angled triangle be cut in double + proportion, by a perpendicular comming from the right angle, it is in + power sesquialter to the greater foote; and treble to the lesser: But if + the base be cut in quadruple proportion, it is sesquiarta to the greater + side, and quintuple to the lesser.</p> + + <p>As in <i>aei</i>, let the base <i>ae</i>, be so cut that the segment + <i>ao</i>, be double to the segment <i>oe</i>, to wit, as 2 is to 1. The + whole <i>ae</i>, shall be unto <i>ao sesquialtera</i>, that is, as 2 is + to 3. And therefore by the <a href="#10_e_viij">10 e viij</a>, and <a + href="#25_e_iiij">25 e iiij</a>, the square of <i>ae</i>, shall be + <i>sesquialterum</i> unto the square of <i>ai</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/179b.png"><img style="width:100%" src="images/179b.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p>And by the same argument it shall be treble unto the quadrate or + square of <i>ei</i>.</p> + + <p>The other, of the fourefold or quadruple section, are manifest in the + figure following, by the like argument.</p> + + <p><a name="14_e_xij"></a> 14 <i>If a right line be cut into how many + parts so ever, the power of it is manifold unto the power of segment, + denominated of the square of the number of the section</i>.</p> + + <p>Or thus: if a right <span class="correction" title="omitted in text" + >line</span> be cut into how many parts soever it is in power the + multiplex of the segment, the square of the number of the section, being + denominated thereof: <i>H</i>. <!-- Page 159 --><span class="pagenum"><a + name="page159"></a>[159]</span></p> + + <div class="figcenter" style="width:55%;"> + <a href="images/180a.png"><img style="width:100%" src="images/180a.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>So if it be cut into two equall parts, the power of it shall be foure + times so much, as is the power of the halfe, taking demonstration from 4, + which is the square of 2, according to which the division was made: If it + be cut into three equall parts, the power of it shall be nine fold the + power of the third part. If into foure equall parts, it shall be 16 times + so much as is the power of the quarter: As here thou seest in these + examples.</p> + + <div class="figright" style="width:18%;"> + <a href="images/180b.png"><img style="width:100%" src="images/180b.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p><a name="15_e_xij"></a> 15. <i>If a right line be cut into two + segments, the quadrate of the whole is equall to the quadrats of the + segments, and a double rectanguled figure, made of them both. 4 p + ij</i>.</p> + + <p>The third rate of a quadrate is hereafter with two rectangles, and two + quadrates, and first of equality.</p> + + <p>This is a consectary out of the <a href="#22_e_x">22 e x</a>: Because + a parallelogramme is equall to his two diagonals and complements. If the + right <i>ae</i>, be cut in <i>i</i>, it maketh the quadrate <i>aeuo</i>, + greater than <i>eyi</i>, and <i>yus</i>, the quadrates of the segments, + by the two rectangles <i>ay</i> and <i>yo</i>. This is the rate of a + quadrate with a rectangle and a quadrate. But the side of a quadrate + proposed in a number is oft times sought. Therefore by the <!-- Page 160 + --><span class="pagenum"><a name="page160"></a>[160]</span>next precedent + element and his consectaries, the analysis or finding of the side of a + quadrate is made and taught.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="16_e_xij"></a> 16. <i>The side of the first diagonall, is the + side of one of the complements; And being doubled, it is the side of them + both together: Now the other side of the same complements both together, + is the side of the other diagonall</i>.</p> + + <p>The side of a quadrate given is many times in numbers sought. + Therefore by the former element and his consectaries the resolution of a + quadrates side is framed and performed.</p> + + <p>Let therefore the side now of the quadrate number given be sought: And + first let the Genesis or making be considered, such as you see here by + the multiplication of numbers in the numbers themselves:</p> + +<table class="nobctr"> +<tr><td align="right">10 2</td><td align="right">10 2</td><td><i> The number or</i></td></tr> +<tr><td align="right">10 2</td><td align="right">10 2</td><td><i> side divided.</i></td></tr> +<tr><td align="right">———</td><td align="right">———</td></tr> +<tr><td align="right">2 4</td><td align="right">4</td><td><i> The lesser diagonall.</i></td></tr> +<tr><td align="right">2 0</td><td align="right"> Or thus 2 0</td><td><i> One Complement.</i></td></tr> +<tr><td align="right">1 0 0</td><td align="right">2 0</td><td><i> Th'other Complement</i></td></tr> +<tr><td align="right">———</td><td align="right">1 0 0</td><td><i> The greater diagonall.</i></td></tr> +<tr><td align="right">1 4 4</td><td align="right">———</td></tr> +<tr><td align="right"> </td><td align="right">1 4 4</td><td><i> The quadrate.</i></td></tr> +</table> + + <p>This is the rate of a quadrate with a rectangle & a quadrate, from + whence is had the analisis or resolution of the side of a quadrate + expressable by a number. For it is the same way fro <i>Cambridge</i> to + <i>London</i>, that is from <i>London</i> to <i>Cambridge</i>. And this + use of geometricall analysis remaineth, as afterward in a Cube, when as + otherwise through the whole booke of <i>Euclides</i> Elements there is no + other use at all of that.</p> + + <p>Here therefore thou shalt note or marke out the severall quadrates, + beginning at the right hand and so proceeding towards the left; after + this manner, 144. These notes doe signifie that so many severall sides to + be found, to make up <!-- Page 161 --><span class="pagenum"><a + name="page161"></a>[161]</span>the whole side of the quadrate given. And + here first, it shall not be amisse to warne thee, before thou commest to + practice, that for helpe of memory and speed in working, thou know the + Quadrats of the nine single numbers of figures; which are these</p> + +<table class="nobctr"> +<tr><td align="right">1.</td><td align="right">2.</td><td align="right">3.</td><td align="right">4.</td><td align="right">5.</td><td align="right">6.</td><td align="right">7.</td><td align="right">8.</td><td align="right">9.</td><td><i> Sides.</i></td></tr> +<tr><td align="right">1.</td><td align="right"> 4.</td><td align="right"> 9.</td><td> 16.</td><td> 25.</td><td> 36.</td><td> 49.</td><td> 64.</td><td> 81.</td><td><i> Qu.</i></td></tr> +</table> + +<table><tr><td valign="top"> + + <p>Then beginning at the left hand, as in Division, that is where we left + in multiplication, and I seeke amongst the squares the greatest conteined + in the first periode, which here is 1; And the side of it, which is also + 1, I place with my quotient: Then I square this quotient, that is I + multiply it by it selfe, and the product 1, I sect under the same first + periode: Lastly, I subtract it from the same periode, and there remaineth + not any thing. Then as in division I set up the figures of the next + periode one degree higher.</p> + + <p>Secondly double the side now found, and it shall be 2, which I place + in manner of a Divisor, on the left hand, within the semicircle: By this + I divide the 40, the two complements or Plaines, and I finde the quotient + or second side 2; which I place in the quotient by 1, This side I + multiply first quadrate like, that is by it selfe; and I make 4, the + lesser Diagonall: And therefore I place under the last 4: Then I multiply + the said Divisor 2, by the same 2 the quotient, and I make in like + manner, 4 which I place under the dividend, or the first 4. Lastly I + subtract these products from the numbers above them, and remaineth + nothing. Therefore I say first, That 144, the number given is a quadrate: + And more-over, That 12 is the true side of it.</p> + +</td><td> </td><td valign="top" style="width:15%;"> + +<table> +<tr><td align="right"> </td><td><del>44</del></td></tr> +<tr><td align="right"><del>1</del>,</td><td><del>44</del></td><td>(12</td></tr> +<tr><td align="right">2) <del>1</del> </td></tr> +<tr><td align="right"> </td><td><del>44</del></td></tr> +</table> + + <p> Or thus:</p> + +<table> +<tr><td align="right"> </td><td align="right"><del>44</del></td></tr> +<tr><td align="right"><del>1</del>,</td><td align="right"><del>44</del></td><td>(12</td></tr> +<tr><td align="right">20) <del>1</del> </td></tr> +<tr><td align="right"> </td><td align="right"><del>40</del></td></tr> +<tr><td align="right"> </td><td align="right"><del>4</del></td></tr> +</table> +</td></tr></table> + +<table><tr><td valign="top"> + + <p>Againe, let the side of 15129 be sought. First divide it into + imperfect periods as before was taught; in this manner: 15129. Then I + seeke amongst the former quadrates, for the side of 1, the quadrate of + the first periode; and I finde it to be 1: This side I place within the + quotient or lunular on the right side: Lastly I subtract 1 from 1, and + nothing remaineth. Then I double the said side found; and I make 2: This + 2, I place for my divisor within the lunular or semicircle on the left + hand: By which I divide 5; and I finde the <!-- Page 162 --><span + class="pagenum"><a name="page162"></a>[162]</span>quotient 2, which I + place by the former quotient: Then I multiply the same 2, first + quadratelike by it selfe, and I make 4. Then I multiply the sayd divisour + by 2, the quotient, and I make likewise 4: which I place underneath 51. + Lastly, I subtract the same 44, from 51, and there remaine 7, over the + head of 1; By which I place 29, the last periode remaining.</p> + + <p>Againe I double 12, my whole quotient, and I make 24. By this double I + divide 72, the double Complement remaining, and I finde 3 for the side or + quotient: First this side I multiply quadratelike by it selfe, and I make + 9, which I place underneath 9, the last figure of my dividende. Then + againe, by the same quotient, or side 3, I multiply 24: my divisour, and + I make 72; which I place under 72, the two figures of my Dividende: + Lastly I subtract the under figures, from the upper, and there is + likewise nothing remaining: Wherefore I say, as afore; that the figurate + 15129 given, is a square: And the side thereof is 123.</p> + +</td><td> </td><td valign="top" style="width:15%;"> + +<table> +<tr><td align="right" colspan="3"><del>7</del> </td><td align="right"><del>29</del></td></tr> +<tr><td align="right" colspan="3"><del>51</del> </td></tr> +<tr><td align="right" colspan="2"><del>1</del>,</td><td align="right"><del>51</del>,</td><td align="right"><del>29</del></td><td>(123</td></tr> +<tr><td align="right"> 2)</td><td align="right"><del>1</del> </td></tr> +<tr><td align="right">24)</td><td align="right" colspan="2"><del>44</del> </td></tr> +<tr><td align="right" colspan="3"><del>7</del> </td><td align="right"><del>29</del></td></tr> +</table> + + <p> Or thus:</p> + +<table> +<tr><td align="right" colspan="3"><del>7</del> </td><td align="right"><del>29</del></td></tr> +<tr><td align="right" colspan="3"><del>51</del> </td></tr> +<tr><td align="right" colspan="2"><del>1</del>,</td><td align="right"><del>51</del>,</td><td align="right"><del>29</del></td><td>(123</td></tr> +<tr><td align="right"> 20)</td><td align="right"><del>1</del> </td></tr> +<tr><td align="right" colspan="3"><del>40</del> </td></tr> +<tr><td align="right" colspan="3"><del>4</del> </td></tr> +<tr><td align="right" colspan="3">240) <del>7</del> </td><td align="right"><del>20</del></td></tr> +<tr><td align="right" colspan="4"><del>9</del></td></tr> +</table> +</td></tr></table> + + <p>Sometime after the quadrate now found, in the next places, there is + neither any plaine nor square to bee found: Therefore the single side + thereof shall be <i>O</i>. As in the quadrate 366025, the whole side is + 605, consisting of three severall sides, of which the middle one is + <i>o</i>.</p> + +<table><tr><td valign="top"> +Sometime also the middle plaine doth containe a part of +the quadrate next following: Therfore if the other side remaining +be greater than the side of the quadrate following, +it is to be made equall unto it: As for example, Let the side +of the quadrate 784, be sought; The side of the first quadrate +shall be 2, and there shall remaine 3, thus: Then the same +side doubled is 4 for the quotient; Which is found in 38, the +double plaine remaining 9 times, for the other side: But this +side is greater than the side of the next following quadrate: +Take therefore 1 out of it: And for nine take 8, and place +it in your quotient; Which 8 multiplyed by it selfe maketh +64, for the Lesser quadrate: And againe the same multiplyed +by 4 the divisour maketh 32; the summe of which two +products 384, subtracted from the remaine 384, leave nothing: +Therefore 784 is a Quadrate: And the side is 28. + +</td><td> </td><td valign="top" style="width:15%;"> + +<table> +<tr><td> </td><td><del>384</del></td></tr> +<tr><td align="right">4)</td><td><del>784</del></td><td> (28</td></tr> +<tr><td> </td><td><del>4</del></td></tr> +</table> + + <p>Or thus:</p> + +<table> +<tr><td> </td><td><del>384</del></td></tr> +<tr><td align="right">40)</td><td><del>784</del></td><td> (28</td></tr> +<tr><td> </td><td><del>4</del></td></tr> +<tr><td> </td><td><del>320</del></td></tr> +<tr><td> </td><td align="right"><del>64</del></td></tr> +</table> +</td></tr></table> + +<p><!-- Page 163 --><span class="pagenum"><a name="page163"></a>[163]</span></p> + + <p><i>And from hence the invention of a meane <span class="correction" + title="text reads `proportionll'">proportionall</span>, betweene two + numbers given, (if there be any such to be found) is manifest.</i> For if + the product of two numbers given be a quadrate, the side of the quadrate + shall be the meane proportionall, betweene the numbers given; as is + apparent by the golden rule: As for example, Betweene 4. and 9. two + numbers given, I desire to know what is the meane proportion. I multiply + therefore 4 and 9. betweene themselves, and the product is 36: which is a + quadrate number; as you see in the former; And the side is 6. Therefore I + say, the meane proportionall betweene 4. and 9. is 6, that is, As 4. is + to 6. so is 6. to 9.</p> + + <p>If the number given be not a quadrate, there shall no arithmeticall + side, and to be expressed by a number be found: And this figurate number + is but the shadow of a Geometricall figure, and doth not indeede expresse + it fully, neither is such a quadrate rationall: Yet notwithstanding the + numerall side of the greatest square in such like number may be found: As + in 148. The greatest quadrate continued is 144 and the side is 12. And + there doe remaine 4. Therefore of such kinde of number, which is not a + quadrate, there is no true or exact side: Neither shall there ever be + found any so neare unto the true one; but there may still be one found + more neare the truth. Therefore the side is not to be expressed by a + number.</p> + + <p>Of the invention of this there are two wayes: The one is by the + <i>Addition of the gnomon</i>; The other is by the Reduction of the + number assigned unto parts of some greater denomination. The first is + thus:</p> + + <p><a name="17_e_xij"></a> 17 <i>If the side found be doubled, and to the + double a unity be added, the whole shall be the gnomon of the next + greater quadrate</i>.</p> + + <p>For the sides is one of the complements, and being doubled it is the + side of both together. And an unity is the latter diagonall. So the side + of 148 is 12.4/25.</p> + + <p>The reason of this dependeth on the same proposition, <!-- Page 164 + --><span class="pagenum"><a name="page164"></a>[164]</span>from whence + also the whole side, is found. For seeing that the side of every quadrate + lesser than the next follower differeth onely from the side of the + quadrate next above greater than it but by an 1. the same unity, both + twice multiplied by the side of the former quadrate, and also once by it + selfe, doth make the <i>Gnomon</i> of the greater to be added to the + quadrate. For it doth make the quadrate 169. Whereby is understood, that + looke how much the numerator 4. is short of the denominatour 25. so much + is the quadrate 148. short of the next greater quadrate. For <span + class="correction" title="text reads `it'">if</span> thou doe adde 21. + which is the difference whereby 4 is short of 25. thou shalt make the + quadrate 169. whose side is 13. The second is by the reduction, as I + said, of the number given unto parts assigned of some great denomination, + as 100. or 1000. or some smaller than those, and those quadrates, that + their true and certaine may be knowne: Now looke how much the smaller + they are, so much nearer to the truth shall the side found be.</p> + + <div class="figright" style="width:18%;"> + <a href="images/185.png"><img style="width:100%" src="images/185.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> + <p>Let the same example be reduced unto hundreds squared parts, thus: + 1480000/10000. The side of 10000. by grant is 100. But the side of + 1480000. the numerator by the former is 1216. and beside there doe + remaine 1344: thus, 1216/100. that is, 12.16/100, or 4/25 which was + discovered by the former way. But in the side of the numerator there + remained 1344. By which little this second way is more accurate and + precise than the first. Yet notwithstanding those remaines are not + regarded, because they cannot adde so much as 1/100 part unto the side, + found: For neither in deed doe 1344/2426. make one hundred part.</p> + + <p>Moreover in lesser parts, the second way beside the other, doth shew + the side to be somewhat greater than the side, by the first way found: as + in 7. the side by the first way is 3/25. But by the second way the side + of 7. reduced unto thousands quadrates, that is unto 7000000/1000000, + that is, 2645/1000, and beside there doe remaine 3975. But 645/1000 are + greater than 3/5. <!-- Page 165 --><span class="pagenum"><a + name="page165"></a>[165]</span>For 3/5. reduced unto 1000. are but + 600/1000. Therefore the second way, in this example, doth exceed the + first by 45/1000. those remaines 3975. being also neglected.</p> + + <p>Therefore this is the Analysis or manner of finding the side of a + quadrate, by the first rate of a quadrate, equall to a double rectangle + and quadrate.</p> + +<p class="cenhead"><i>The Geodesy or measuring of a Triangle</i>.</p> + + <p>There is one generall Geodesy or way of measuring any manner of + triangle whatsoever in <i>Hero</i>, by addition of the sides, halving of + the summe, subduction, multiplication, and invention of the quadrates + side, after this manner.</p> + + <div class="figleft" style="width:18%;"> + <a href="images/186.png"><img style="width:100%" src="images/186.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p><a name="18_e_xij"></a> 18 <i>If from the halfe of the summe of the + sides, the sides be severally subducted, the side of the quadrate + continually made of the halfe, and the remaines shall be the content of + the triangle</i>.</p> + + <p>As for example, Let the sides of the triangle <i>aei</i>, be 6. 8. 10: + The summe 24. the halfe of the summe 12. From which halfe subduct the + sides 6. 8. <span class="correction" title="text reads `18'">10</span>. + and let the remaines be 6. 4. 2. Now multiply continually these foure + numbers 12. 6. 4. 2. and thou shalt make first of 12. and 6. 72. Of 72. + and 4. 288. Lastly, of 288. and 2. 576. And the side of 576. by the <a + href="#16_e_xij">16. e.</a> shall be found to be 24. for the content of + the triangle: which also here will be found to be true, by multiplying + the sides <i>ae</i> and <i>ei</i>, containing the right angle, the one by + the other; and then taking the halfe of the product.</p> + + <p>This generall way of measuring a triangle is most easie and speedy, + where the sides are expressed by whole numbers.</p> + + <p>The speciall geodesy of rectangle triangle was before taught (at the + <a href="#9_e_xj">9 e xj</a>.) But of an oblique angle it shall hereafter + be spoken. But the generall way is farre more <!-- Page 166 --><span + class="pagenum"><a name="page166"></a>[166]</span>excellent than the + speciall; For by the reduction of an obliquangle many fraudes and errours + doe fall out, which caused the learned <i>Cardine</i> merrily to wish, + that hee had but as much land as was lost by that false kinde of + measuring.</p> + + <div class="figright" style="width:18%;"> + <a href="images/187.png"><img style="width:100%" src="images/187.png" + alt="Figure for demonstration 19." title="Figure for demonstration 19." /></a> + </div> + <p><a name="19_e_xij"></a> 19 <i>If the base of a triangle doe subtend an + obtuse angle, the power of it is more than the power of the shankes, by a + double right angle of the one, and of the continuation from the said + obtusangle unto the perpendicular of the toppe. 12. p ij</i>.</p> + + <p>Or thus: If the base of a triangle doe subtend an obtuse angle, it is + in power more than the feete, by the right angled figure twise taken, + which is contained under one of the feete and the line continued from the + said foote unto the perpendicular drawne from the toppe of the triangle. + <i>H</i>.</p> + + <p>There is a comparison of a quadrate with two in like manner triangles, + and as many quadrates, but of unequality.</p> + + <p>As in the triangle <i>aei</i>, the quadrate of the base <i>ai</i>, is + greater in power, than the quadrates of the shankes <i>ae</i>, and + <i>ei</i>, by double of the rectangle <i>ar</i>, which is made of + <i>ae</i>, one of the shankes, and of <i>eo</i>, the continuation of the + same <i>ae</i>, unto <i>o</i>, the perpendicular of the toppe + <i>i</i>.</p> + + <p>For by <a href="#9_e_xij">9. e</a>, the quadrate of <i>ai</i>, is + equall to the quadrates of <i>ao</i>, and <i>oi</i>, that is, to three + quadrates, of <i>io</i>, <i>oe</i>, <i>ea</i>, and the double rectangle + aforesaid. But the quadrates of the shankes <i>ae</i>, <i>ei</i>, are + equall to those three quadrates, to wit, of <i>ai</i>, his owne quadrate, + and of <i>ei</i>, two, the first <i>io</i>, the second <i>oe</i>, by the + <a href="#9_e_xij">9. e.</a> Therefore the excesse remaineth of a double + rectangle.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<p><!-- Page 167 --><span class="pagenum"><a name="page167"></a>[167]</span></p> + +<h2>Of Geometry, the thirteenth Booke, +Of an Oblong.</h2> + + <div class="figright" style="width:15%;"> + <a href="images/188a.png"><img style="width:100%" src="images/188a.png" + alt="Oblong." title="Oblong." /></a> + </div> + <p><a name="1_e_xiij"></a> 1 <i>An Oblong is a rectangle of inequall + sides, 31. d j</i>.</p> + + <p>Or thus: An Oblong is a rectangled parallelogramme, being not + equilater: <i>H</i>. As here is <i>ae</i>, <i>io</i>.</p> + + <p>This second kinde of rectangle is of Euclide in his elements properly + named for a definitions sake onely.</p> + + <p>The rate of Oblongs is very copious, out of a threefold section of a + right line given, sometime rationall and expresable by a number: The + first section is as you please, that is, into two segments, equall or + unequall: From whence a five-fold rate ariseth.</p> + + <p><a name="2_e_xiij"></a> 2 <i>An oblong made of an whole line given, + and of one segment of the same, is equall to a rectangle made of both the + segments, and the square of the said segment. 3. p ij</i>.</p> + + <div class="figleft" style="width:24%;"> + <a href="images/188b.png"><img style="width:100%" src="images/188b.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p>It is a consectary out of the <a href="#7_e_xj">7 e xj</a>. For the + rectangle of the segments, and the quadrate, are made of one side, and of + the segments of the other.</p> + + <p>As let the right line <i>ae</i>, be 6. And let it be cut into two + parts <i>ai</i>, 2. and <i>ie</i>, 4. The rectangle 12. made of + <i>ae</i>, 6. the whole, and of <i>ai</i>, 2. the one segment, shall be + equall to <i>iu</i>, 8. the rectangle made <!-- Page 168 --><span + class="pagenum"><a name="page168"></a>[168]</span>of the same <i>ai</i>, + 2. and of <i>ie</i>, 4. And also to <i>ao</i>, 4. the quadrate of the + said segment <i>ai</i>, 2.</p> + + <p>Now a rectangle is here therefore proposed, because it may be also a + quadrate, to wit, if the line be cut into to equall parts.</p> + + <div class="poem"> + <div class="stanza"> + <p>Secondarily,</p> + </div> + </div> + <div class="figright" style="width:24%;"> + <a href="images/189a.png"><img style="width:100%" src="images/189a.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p><a name="3_e_xiij"></a> 3 <i>Oblongs made of the whole line given, and + of the segments, are equall to the quadrate of the whole 2 p ij</i>.</p> + + <p>This is also a Consectary out of the <a href="#4_e_xj"><span + class="correction" title="text reads `4. e xj'">7. e xj</span></a>.</p> + + <p>As let the line <i>ae</i>, 6. be cut into <i>ai</i>, 2. <span + class="correction" title="text reads `10'"><i>io</i></span>. 2. and + <i>oe</i>, 2. The Oblongs <i>as</i>, 12. <i>ir</i>, 12. and <i>oy</i>, + 12. made of the whole <i>ae</i>, and of those segments, are equall to + <i>ay</i>, the quadrates of the whole.</p> + + <p>Here the segments are more than two, and yet notwithstanding from the + first the rest may be taken for one, seeing that the particular rectangle + in like manner is equall to them. This proposition is used in the + demonstration of the <a href="#9_e_xviij">9. e xviij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Thirdly,</p> + </div> + </div> + <p><a name="4_e_xiij"></a> 4 <i>Two Oblongs made of the whole line given, + and of the one segment, with the third quadrate of the other segment, are + equall to the quadrates of the whole, and of the said segment. 7 p + ij</i>.</p> + + <div class="figleft" style="width:25%;"> + <a href="images/189b.png"><img style="width:100%" src="images/189b.png" + alt="Figure for demonstration 4." title="Figure for demonstration 4." /></a> + </div> + <p>As for example, let the right line <i>ae</i>, 8. be cut into + <i>ai</i>, 6. and <i>ie</i>, 2. The oblongs <i>ao</i>, and <i>iu</i>, of + the whole, and 2. the segments, are 32. The quadrate of 6. the other + segment 36. And the whole 68. Now the quadrate, of the whole <i>ae</i>. + 8. is 64. And the quadrate of the said segment 2, is 4. And the summe of + these is 68. <!-- Page 169 --><span class="pagenum"><a + name="page169"></a>[169]</span></p> + + <p><a name="5_e_xiij"></a> 5. <i>The base of an acute triangle is of + lesse power than the shankes are, by a double oblong made of one of the + shankes, and the one segment of the same, from the said angle, unto the + perpendicular of the toppe. 13 p. ij</i>.</p> + + <div class="figright" style="width:14%;"> + <a href="images/190.png"><img style="width:100%" src="images/190.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p>As in the triangle <i>aei</i>, let the angle at <i>i</i>, be taken for + an acute angle. Here by the <a href="#4_e_xiij">4. e</a>, two obongs of + <i>ei</i>, and <i>oi</i>, with the quadrate of <i>eo</i>, are equall to + the quadrates of <i>ei</i>, and <i>oi</i>. Let the quadrate of <i>ao</i>, + be added to both in common. Here the quadrate of <i>ei</i>, with the + quadrates of <i>io</i>, and <i>oa</i>, that is the <a href="#9_e_xij">9 e + xij</a>, with the quadrate of <i>ia</i>, is equall to two oblongs of + <i>ei</i>, and <i>oi</i>, with two quadrates of <i>eo</i> & + <i>oa</i>, that is by the <a href="#9_e_xij">9 e xij</a>, with the + quadrate of <i>ea</i>. Therefore two oblongs with the quadrate of the + base, are equall to the quadrates of the shankes: And the base is + exceeded of the shankes by two oblongs.</p> + + <p>And from hence is had the segment of the shanke toward the angle, and + by that the perpendicular in a triangle.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="6_e_xiij"></a> 6. <i>If the square of the base of an acute + angle be taken out of the squares of the shankes, the quotient of the + halfe of the remaine, divided by the shanke, shall be the segment of the + dividing shanke from the said angle unto the perpendicular of the + toppe</i>.</p> + + <div class="figleft" style="width:28%;"> + <a href="images/191.png"><img style="width:100%" src="images/191.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>As in the acute angled triangle <i>aei</i>, let the sides be 13, 20, + 21. And let <i>ae</i> be the base of the acute angle. Now the quadrate or + square of 13 the said base is 169: And the quadrate of 20, or <i>ai</i>, + is 400: And of 21, or <i>ei</i>, is 441. The summe of which is 841. And + 841, 169, are 672: <!-- Page 170 --><span class="pagenum"><a + name="page170"></a>[170]</span>Whose halfe is 336. And the quotient of + 336, divided by 21, is 16, the segment of the dividing shanke <i>ei</i>, + from the angle <i>aei</i>, unto <i>ao</i>, the perpendicular of the + toppe. Now 21, 16, are 5. Therefore the other segment or portion of the + said <i>ei</i>, is 5.</p> + + <p>Now againe from 169, the quadrate of the base 13, take 25, the + quadrate of 5, the said segment: And the remaine shall be 144, for the + quadrate of the perpendicular <i>ao</i>, by the <a href="#9_e_xij">9 e + xij</a>.</p> + + <p>Here the perpendicular now found, and the sides cut, are the sides of + the rectangle, whose halfe shall be the content of the Triangle: As here + the Rectangle of 21 and 12 is 252; whose halfe 126, is the content of the + triangle.</p> + + <p>The second section followeth from whence ariseth the fourth rate or + comparison.</p> + + <p><a name="7_e_xiij"></a> 7. <i>If a right line be cut into two equall + parts, and otherwise; the oblong of the unequall segments, with the + quadrate of the segment betweene them, is equall to the quadrate of the + bisegment. 5 p ij</i>.</p> + + <div class="figright" style="width:26%;"> + <a href="images/192a.png"><img style="width:100%" src="images/192a.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>As for example, Let the right line <i>ae</i> 8, be cut into two equall + portions, <i>ai</i> 4, and <i>ie</i> 4. And otherwise that is into two + unequall portions, <i>ao</i> 7, and <i>oe</i> 1: The oblong of 7 and 1, + with 9, the quadrate of 3, the intersegment, (or portion cut betweene + them) that is 16; shall bee equall to the quadrate of <i>ie</i> 4, which + is also 16. Which is also manifest by making up the diagramme as here + thou seest. For as the parallelogramme <i><span class="correction" + title="text reads `missing in text'">as</span></i> is by the <a + href="#24_e_x"><span class="correction" title="text reads `24 e x'">26 e + x</span></a>, equall to the <!-- Page 171 --><span class="pagenum"><a + name="page171"></a>[171]</span>parallelogramme <i>iu</i>; And therefore + by the <a href="#19_e_x">19 e x</a>, it is equall to <i>oy</i>. For + <i>ou</i>, is common to both the equall complements, Therefore if + <i>so</i> be added in common to both; the <i>ar</i>, shall be equall to + the gnomon <i>mni</i>: Now the quadrate of the segment betweene them is + <i>sl</i>. Wherefore <i>ar</i>, the oblong of the unequall segments, with + <i>s</i> the quadrate of the intersegment, is equall to <i>iy</i> the + quadrate of the said bisegment.</p> + + <p>The third section doth follow, from whence the fifth reason + ariseth.</p> + + <p><a name="8_e_xiij"></a> 8. <i>If a right line be cut into equall + parts; and continued; the oblong made of the continued and the + continuation, with the quadrate of the bisegment or halfe, is equall to + the quadrate of the line compounded of the bisegment and continuation. 6 + p ij</i>.</p> + + <div class="figleft" style="width:26%;"> + <a href="images/192b.png"><img style="width:100%" src="images/192b.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>As for example, let the line <i>ae</i> 6, be cut into two equall + portions, <i>ai</i> 3, and <i>ie</i> 3: And let it be continued unto + <i>eo</i> 2: The oblong 16, made of 8 the continued line, and of 2, the + continuation; with 9 the quadrate of 3, the halfe, (that is 25.) shall be + equall to 25, the quadrate of 3, the halfe and 2, the continuation, that + is 5. This as the former, may geometrically, with the helpe of numbers be + expressed. For by the <a href="#26_e_x"><span class="correction" + title="text reads `24 e x'">26 e x</span></a>, <i>as</i> is equall to + <i>iy</i>: And by the <a href="#19_e_x">19 e x</a>, it is equall to + <i>yr</i>, the complement. To these equalls adde <i>so</i>. Now the + oblong <i>au</i>, shall be equall to the gnomon <i>nju</i>. Lastly, to + the equalls adde the quadrate of the bisegment or halfe. The Oblong of + the continued line and of the <!-- Page 172 --><span class="pagenum"><a + name="page172"></a>[172]</span>continuation, with the quadrate of the + bisegment, shall be equall to the quadrate of the line compounded of the + bisegment and continuation. These were the rates of an oblong with a + rectangle.</p> + + <p>From hence ariseth the Mesographus or Mesolabus of <i>Heron</i> the + mechanicke; so named of the invention of two lines continually + proportionall betweene two lines given. Whereupon arose the Deliacke + probleme, which troubled <i>Apollo</i> himselfe. Now the Mesographus of + <i>Hero</i> is an infinite right line, which is stayed with a + scrue-pinne, which is to be moved up and downe in riglet. And it is as + <i>Pappus</i> saith, in the beginning of his <span + class="scac">III</span> booke, for architects most fit, and more ready + than the Plato's mesographus. The mechanicall handling of this + mesographus, is described by <i>Eutocius</i> at the 1 Theoreme of the + <span class="scac">II</span> booke of the spheare; But it is somewhat + more plainely and easily thus layd downe by us.</p> + + <p><a name="9_e_xiij"></a> 9. <i>If the Mesographus, touching the angle + opposite to the angle made of the two lines given, doe cut the said two + lines given, comprehending a right angled parallelogramme, and infinitely + continued, equally distant from the center, the intersegments shall be + the meanes continually proportionally, betweene and two lines + given</i>.</p> + + <p>Or thus: If a Mesographus, touching the angle opposite to the angle + made of the lines given, doe cut the equall distance from the center, the + two right lines given, conteining a right angled parallelogramme, and + continued out infinitely, the segments shall be meane in continuall + proportion with the line given: <i>H</i>.</p> + + <div class="figright" style="width:24%;"> + <a href="images/194.png"><img style="width:100%" src="images/194.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p>As let the two right-lines given be <i>ae</i>, and <i>ai</i>: And let + them comprehend the rectangled parallelogramme <i>ao</i>: And let the + said right lines given be continued infinitely, <i>ae</i> toward + <i>u</i>; and <i>ai</i> toward <i>y</i>. Now let the Mesographus + <i>uy</i>, touch <i>o</i>, the angle opposite to <i>a</i>: And let it cut + the sayd continued lines equally distant from the Center. <!-- Page 173 + --><span class="pagenum"><a name="page173"></a>[173]</span></p> + + <p>(The center is found by the <a href="#8_e_iiij">8 e iiij</a>, to wit, + by the meeting of the diagonies: For the equidistance from the center the + Mesographus is to be moved up or downe, untill by the Compasses, it be + found.)</p> + + <p>Now suppose the points of equidistancy thus found to be <i>u</i>, and + <i>y</i>. I say, That the portions of the continued lines thus are the + meane proportionalls sought: And as <i>ae</i> is to <i>iy</i>: so is + <i>iy</i> to <i>eu</i>, so is <i>eu</i>, to <i>ai</i>.</p> + + <p>First let from <i>s</i>, the center, <i>sr</i> be perpendicular to the + side <i>ae</i>: It shall therefore cut the said <i>ae</i>, into two + parts, by the <a href="#5_e_xj">5 e xj</a>: And therefore againe, by the + <a href="#7_e_xiij">7 e</a>, the oblong made of <i>au</i>, and <i>ue</i>, + with the quadrate of <i>re</i>, is equall to the quadrate of <i>ru</i>: + And taking to them in common <i>rs</i>, the oblong with two quadrates + <i>er</i>, and <i>rs</i>, that is, by the <a href="#9_e_xij">9 e xij</a>, + with the quadrate <i>se</i> is equall to the quadrates <i>ru</i> and + <i>rs</i>, that is by the <a href="#9_e_xij">9 e xij</a>, to the quadrate + <i>su</i>. The like is to be said of the oblong of <i>ay</i>, and + <i>yi</i>, by drawing the perpendicular <i>sl</i>, as afore. For this + oblong with the quadrates <i>li</i>, and <i>sl</i>, that is, by the <a + href="#9_e_xij">9 e xij</a>, with the quadrate <i>is</i>, is equall to + the quadrates <i>yl</i>, and <i>ls</i>, that is, by the <a + href="#9_e_xij">9 e 12</a>, to <i>ys</i>. Therefore the oblongs equall to + equalls, are equall betweene themselves: And taking from each side of + equall rayes, by the <a href="#11_e_x">11 e x</a>, equall quadrates + <i>se</i> and <i>si</i>, there shall remaine equalls. Wherefore by the <a + href="#26_e_x"><span class="correction" title="text reads `26 e x'">27 e + x</span></a>, the sides of equall rectangles are reciprocall: And as + <i>au</i> is to <i>ay</i>: so by the <a href="#13_e_vij">13 e vij</a>, + <i>oi</i>, that is, by the <a href="#8_e_x">8 e x</a>, <i>ea</i>, to + <i>iy</i>: And so therefore by the concluded, <i>yi</i> is to <i>ue</i>; + And so by the <a href="#13_e_vij">13 e vij</a>, is <i>ue</i> to + <i>eo</i>, that is, by the <a href="#8_e_x">8 e x</a>, unto <i>ai</i>. + Therefore as <i>ea</i> is to <i>yi</i>: so is <i>yi</i> to <i>ue</i>; and + so is <i>ue</i>, to <i>ai</i>. Wherefore <i>eu</i>, <i>iy</i>, the + intersegments or portions cut, are the two meane proportionals betweene + the two lines given.</p> + +<hr class="full" /> + +<p><!-- Page 174 --><span class="pagenum"><a name="page174"></a>[174]</span></p> + +<h2>The fourteenth Booke, of <i>P. Ramus</i> Geometry: +Of a right line proportionally +cut: And of other Quadrangles, +and Multangels.</h2> + + <p>Thus farre of the threefold section, from whence we have the five + rationall rates of equality: There followeth of the third section another + section, into two segments proportionall to the whole. The section it + selfe is first to be defined.</p> + + <p><a name="1_e_xiiij"></a> 1. <i>A right line is cut according to a + meane and extreame rate, when as the whole shall be to the greater + segment; so the greater shall be unto the lesser. 3 d vj</i>.</p> + + <p>This line is cut so, that the whole line it selfe, with the two + segments, doth make the three bounds of the proportion: And the whole it + selfe is first bound: The greater segment is the middle bound: The lesser + the third bound.</p> + + <p><a name="2_e_xiiij"></a> 2. <i>If a right line cut proportionally be + rationall unto the measure given, the segments are unto the same, and + betweene themselves irrationall è 6 p xiij</i>.</p> + + <div class="figcenter" style="width:22%;"> + <a href="images/195.png"><img style="width:100%" src="images/195.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p><i>Euclide</i> calleth each of these segments <span title="Apotomê" class="grk" + >Ἀποτομὴ</span> that is, + <i>Residuum</i>, a Residuall or remaine: And surely these cannot + otherwise be expressed, then by the name <i>Residuum</i>; As if a line of + 7 foote should thus be given or put downe: The greater segment shall be + called a line of 7 foote, from whence the lesser is substracted: Neither + may the lesser otherwise be expressed, but by saying, It is the part + residuall or remnant of the line of 7 foote, from which the greater + segment was subtracted or taken.</p> + + <p>A Triangle, and all Triangulates, that is figures made of <!-- Page + 175 --><span class="pagenum"><a name="page175"></a>[175]</span>triangles, + except a Rightangled-parallelogramme, are in Geometry held to be + irrationalls. This is therefore the definition of a proportionall + section: The section it selfe followeth, which is by the rate of an + oblong with a quadrate.</p> + + <p><a name="3_e_xiiij"></a> 3. <i>If a quadrate be made of a right line + given, the difference of the right line from the middest of the + conterminall side of the said quadrate made, above the same halfe, shall + be the greater segment of the line given proportionally cut: 11 p + ij</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/196.png"><img style="width:100%" src="images/196.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p>Or thus: If a square be made of a right line given, the difference of + a right line drawne from the angle of the square made unto the middest of + the next side, above the halfe of the side, shall be the greater segment + of the line given, being proportionally cut: <i>H</i>.</p> + + <p>Let the right line gived be <i>ae</i>. The quadrate of the same let it + be <i>aeio</i>: And from the angle <i>e</i>, unto <i>u</i>, the middest + of the conterminal side, let the right line <i>eu</i>, be drawne; Then + compare or lay it to the halfe <i>ua</i>; The difference of it above the + said halfe shall be <i>ay</i>, This <i>ay</i>, say 1, is the greater + segment of <i>ae</i>, the line given, proportionally cut.</p> + + <p>For of <i>ya</i>, let the quadrate <i>aysr</i>, be made: And let + <i>sr</i>, be continued unto <i>l</i>. Now by the <a href="#8_e_xiij">8 + e, xiij</a>. the <span class="correction" title="text reads `obloug'" + >oblong</span> of <i>oy</i>, and <i>ay</i>, with the quadrate of + <i>ua</i>, is equall to the quadrate of <i>uy</i>, that is by the + construction of <i>ue</i>: And therefore, by the <a href="#9_e_xij">9 e + xij</a>. it is equall to the quadrates <i>ea</i>, and <i>au</i>: Take + away from each side the common oblong <i>al</i>, and the quadrate + <i>yr</i>, shall be equall to the oblong <i>ri</i>. Therefore the three + right lines, <i>ea</i>, <i>ar</i>, and <i>re</i>, by the <a + href="#8_e_xij">8 e xij</a>. are continuall proportionall. And the right + line <i>ae</i>, is cut proportionally.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> +<p><!-- Page 176 --><span class="pagenum"><a name="page176"></a>[176]</span></p> + + <p><a name="4_e_xiiij"></a> 4. <i>If a right line cut proportionally, be + continued with the greater segment, the whole shall be cut + proportionally, and the greater segment shall be the line given. 5 p + xiij</i>.</p> + + <p>As in the same example, the right line <i>oy</i>, is continued with + the greater segment, and the oblong of the whole and the lesser segment + is equall to the quadrate of the greater. And thus one may by infinitely + proportionally cutting increase a right line; and againe decrease it. The + lesser segment of a right line proportionally cut, is the greater + segment, of the greater proportionally cut. And from hence a decreasing + may be made infinitely.</p> + + <p><a name="5_e_xiiij"></a> 5. <i>The greater segment continued to the + halfe of the whole, is of power quintuple unto the said halfe, that is, + five times so great as it is: and if the power of a right line be + quintuple to his segment, the remainder made the double of the former is + cut proportionally, and the greater segment, is the same remainder. 1. + and 2. p xiij</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/197.png"><img style="width:100%" src="images/197.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p>This is the fabricke or manner of making a proportionall section. A + threefold rate followeth: The first is of the greater segment.</p> + + <p>Let therefore the right line <i>ae</i>, be cut proportionally in + <i>i</i>: And let the greater segment be <i>ia</i>: and let the line cut + be continued unto <i>io</i>, so that <i>oa</i>, be the halfe of the line + cut. I say, the quadrate of <i>io</i>, is in power five times so great, + as <i>ys</i>, the power of the quadrate of <i>ao</i>. Let therefore of + <i>ao</i>, be made the quadrate <i>iosr</i>: We doe see the quadrate + <i>ua</i>, to be once contained in the quadrate <i>si</i>. Let us now + <!-- Page 177 --><span class="pagenum"><a + name="page177"></a>[177]</span>teach that it is moreover foure times + comprehended in <i>lmn</i>, the gnomon remaining: Let therefore the + quadrate <i>aeiu</i>, be made of the line given: And let <i>ri</i>, be + continued unto <i>f</i>. Here the quadrate <i>ae</i>, is (<a + href="#14_e_xij">14. e xij</a>.) foure times so much as is that + <i>au</i>, made of the halfe: and it is also equall to the gnomon + <i>lmn</i>: For the part <i>iu</i>, is equall to <i>ry</i>; first by the + grant, seeing that <i>ai</i>, is the greater segment, from whence + <i>ry</i>, is made the quadrate, because the other Diagonall is also a + quadrate: Secondarily the complements <i>sy</i>, and <i>yi</i>, by the <a + href="#19_e_x">19. e x</a>, are equall: And to them is equall <i>af</i>. + For by the <a href="#23_e_x">23. e x</a>. and by the grant, it is the + double of the complement <i>yi</i>. Therefore it is equall to them both. + Wherefore the gnomon <i>lmn</i>, is equall to the quadruple quadrate of + the said little quadrate: And the greater segment continued to the halfe + of the right line given is of power five fold to the power of + <i>ao</i>.</p> + + <p>The converse is apparent in the same example: For seeing that + <i>io</i>, is of power five times so much as is <i>ao</i>; the gnomon + <i>lmn</i>, shall be foure times so much as is <i>ua</i>: Whose quadruple + also, by the <a href="#14_e_xij">14. e xij</a>, is <i>av</i>. Therefore + it is equall to the gnomon. Now <i>aj</i>, is equall to <i>ae</i>: + Therefore it is the double also of <i>ao</i>, that is of <i>ay</i>: And + therefore by the <a href="#24_e_x">24. e x</a>. it is the double of + <i>at</i>: And therefore it is equall to the complements <i>iy</i>, and + <i>ys</i>: Therefore the other diagonall <i>yr</i>, is equall to the + other rectangle <i>iv</i>. Wherefore, by the <a href="#8_e_xij">8 e + xij</a>. as <i>ev</i>, that is, <i>ae</i>, is to <i>yt</i>, that is + <i>ai</i>: so is <i>ai</i>, unto <i>ie</i>; Wherefore by the <a + href="#1_e_xiiij">1 e</a>, <i>ae</i>, is proportionall cut: And the + greater segment is <i>ai</i>, the same remaine.</p> + + <p>The other propriety of the quintuple doth follow.</p> + + <p><a name="6_e_xiiij"></a> 6 <i>The lesser segment continued to the + halfe of the greater, is of power quintuple to the same halfe è 3 p + xiij</i>.</p> + + <div class="figright" style="width:24%;"> + <a href="images/199a.png"><img style="width:100%" src="images/199a.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>As here, the right line <i>ae</i>, let it be cut proportionally in + <i>i</i>: And the lesser <i>ie</i>, let it be continued even unto + <i>o</i>, the halfe of the greater <i>ai</i>. I say, that the power of + <i>oe</i>, shall be five times as much as is the power of <i>io</i>. Let + a quadrate <!-- Page 178 --><span class="pagenum"><a + name="page178"></a>[178]</span>therefore be made of <i>ae</i>: And let + the figure be made up (as you see:) And let the quadrate of the halfe be + noted with <i>su</i>: And the gnomon <i>rlm</i>. Here the first quadrate + <i>oy</i>, is five times as great, as the second <i>su</i>. For it doe + containe it once: And the gnomon <i>rlm</i>, remaining containeth it + foure times. For it is equall to the Oblong <i>in</i>; because <i>os</i>, + the complement is equall to <i>sy</i>, by the <a href="#19_e_x">19 e + x</a>; And therefore also it is equall to <i>in</i>; seeing the whole + complement <i>as</i>, is equall to the whole complement <i>sn</i>: And + <i>av</i>, is equall to <i>os</i>, by the construction, and <a + href="#23_e_x">23. e x</a>: And adding to both the common oblong + <i>iy</i>, the whole gnomon is equal to the whole oblong. But the oblong + <i>in</i>, is equall to the quadrate <i>ai</i>, by the grant, & <a + href="#8_e_xij">8 e xij</a>. which by the <a href="#14_e_xij">14. e + xij</a>. is foure times as great, as the quadrate <i>su</i>. Wherefore + the lesser segment <i>ie</i>, continued to <i>io</i>, the halfe of the + greater segment, is of power five times as much as is the halfe of the + same.</p> + + <div class="poem"> + <div class="stanza"> + <p><i>The rate of the triple followeth</i>.</p> + </div> + </div> + <div class="figleft" style="width:18%;"> + <a href="images/199b.png"><img style="width:100%" src="images/199b.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p><a name="7_e_xiiij"></a> 7 <i>The whole line and the lesser segment + are in power treble unto the greater. è 4 p xiij</i>.</p> + + <p>Let the right line <i>ae</i> be proportionally cut in <i>i</i>, and + let the figure be made up: The oblong <i>ay</i>, and <i>io</i>, with the + quadrate <i>su</i>, by the <a href="#4_e_xiij">4 e xiij</a>, are equall + to the quadrates of <i>ae</i>, and <i>ie</i>, whose power is treble to + that of <i>ai</i>. For they doe once containe the quadrate <i>su</i>; And + each of the oblongs is equall to the same quadrate <i>su</i>, by the + grant, and <a href="#8_e_xij">8 e xij</a>. Therefore they doe containe it + thrise.</p> + +<p><!-- Page 191 --><span class="pagenum"><a name="pageastx191"></a>[191*]</span></p> + + <p><br style="clear : both" /></p> + <p><a name="8_e_xiiij"></a> 8 <i>An obliquangled parallelogramme is + either a Rhombus, or a Rhomboides</i>.</p> + + <p><a name="9_e_xiiij"></a> 9 <i>A Rhombus is an obliquangled equilater + parallelogramme 32 d j</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/200a.png"><img style="width:100%" src="images/200a.png" + alt="Rhombi." title="Rhombi." /></a> + </div> + <p>Whereupon it is apparant that a Rhombus is a square having the angles + as it were pressed, or thrust nearer together, by which name, both the + Byrt or Turbot, a Fish; and a Wheele or Reele, which Spinners doe use; + and the quarrels in glasse windowes, because they are cut commonly of + this forme, are by the Greekes and Latines so called.</p> + + <p>It is otherwise of some called a Diamond.</p> + + <p><a name="10_e_xiiij"></a> 10 <i>A Rhomboides is an obliquangled + parallelogramme not equilater 33. d j</i>.</p> + + <div class="figcenter" style="width:44%;"> + <a href="images/200b.png"><img style="width:100%" src="images/200b.png" + alt="Rhomboides." title="Rhomboides." /></a> + </div> + <p>And a Rhomboides is so opposed to an oblong, as a Rhombus is to a + quadrate.</p> + + <div class="figright" style="width:28%;"> + <a href="images/201a.png"><img style="width:100%" src="images/201a.png" + alt="Angles of Rhomboides." title="Angles of Rhomboides." /></a> + </div> + <p>So also looke how much the straightening or pressing <!-- Page 180 + --><span class="pagenum"><a name="pageastx180"></a>[180*]</span>together + is greater, so much is the inequality of the obtuse and acute angles the + greater. As here.</p> + + <p>And the Rhomboides is so called as one would say Rhombuslike, although + beside the inequality of the angles it hath nothing like to a Rhombus. An + example of measuring of a <span class="correction" title="text reads `Rhombus' but diagram shows a Rhomboides" + >Rhomboides</span> is thus.</p> + + <p><br style="clear : both" /></p> + <p><a name="11_e_xiiij"></a> 11 <i>A Trapezium is a quadrangle not + parallelogramme. 34. d j</i>.</p> + + <div class="figcenter" style="width:57%;"> + <a href="images/201b.png"><img style="width:100%" src="images/201b.png" + alt="Trapezia." title="Trapezia." /></a> + </div> + <p>Of the quadrangles the Trapezium remaineth for the last place: + <i>Euclide</i> intreateth this fabricke to be granted him, that a + Trapezium may be called as it were a little table: And surely Geometry + can yeeld no reason of that name.</p> + + <p>The examples both of the figure and of the measure of the same let + these be.</p> + + <p>Therefore triangulate quadrangles are of this sort. <!-- Page 190 + --><span class="pagenum"><a name="pageastx190"></a>[190*]</span></p> + + <p><a name="12_e_xiiij"></a> 12 <i>A multangle is a figure that is + comprehended of more than foure right lines. 23. d j</i>.</p> + + <p>By this generall name, all other sorts of right lined figures + hereafter following, are by Euclide comprehended, as are the quinquangle, + sexangle, septangle, and such like inumerable taking their names of the + number of their angles.</p> + + <p>In every kinde of multangle, there is one ordinate, as we have in the + former signified, of which in this place we will say nothing, but this + one thing of the quinquangle. The rest shall be reserved untill we come + to Adscription.</p> + + <div class="figright" style="width:22%;"> + <a href="images/202.png"><img style="width:100%" src="images/202.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><a name="13_e_xiiij"></a> 13 <i>Multangled triangulates doe take their + measure also from their triangles</i>.</p> + + <p>As here, this quinquangle is measured by his three triangles. The + first triangle, whose sides are 9. 10. and 17. by the <a + href="#18_e_xij">18. e xij</a>. is 36. The second, whose sides are 6, 17, + and 17. by the same e, is 50.20/101. The third, whose sides are 17, 15. + and 8. by the same, is 60. And the summe of 36. 50.20/101. and 60. is + 146.20/101, for the whole content of the Quinquangle given.</p> + + <p><a name="14_e_xiiij"></a> 14 <i>If an equilater quinquangle have three + sides equall, it is equiangled. 7 p 13</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/203a.png"><img style="width:100%" src="images/203a.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>This of some, from the Greeke is called Pentagon; of others a + Pentangle, by a name partly Greeke partly Latine.</p> + + <p>As in the Quinquangle <i>aeiou</i>, the three angles at <i>a</i>, + <i>e</i>, and <i>i</i>, are equall: Therefore the other two are equall: + And they are equall unto these. For let <i>eu</i>, <i>ai</i>, <i>ia</i>, + be knit together with right lines. Here the triangles <i>aei</i>, and + <i>eau</i>. by the grant, and by the <a href="#2_e_vij">2</a> and <a + href="#1_e_vij">1 e vij</a>. are equilaters and equiangles: And the Bases + <i>ai</i>, and <i>eu</i>, are <!-- Page 200 --><span class="pagenum"><a + name="pageastx200"></a>[200*]</span>equall: And the Angles, <i>eai</i>, + and <i>aue</i>, are equall: Item <i>aeu</i>, and <i>eia</i>. Therefore + <i>ay</i>, and <i>ye</i>, are equall, by the <a href="#17_e_vj">17 e + vj</a>. Item the remainder <i>uy</i>, is equall to the remainder + <i>yi</i>, when from equals equals be subtracted. Moreover by the grant, + and by the <a href="#17_e_vj">17 e vj</a>, <i>oui</i>, and <i>oiu</i>, + are equall. Wherefore three are equall; And therefore the whole angle is + equall at <i>u</i>, to the whole <span class="correction" title="text reads `anlge'" + >angle</span> at <i>i</i>. And therefore it is equall to those which are + equall to it.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/203b.png"><img style="width:100%" src="images/203b.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>I say moreover that the angle at <i>o</i>, is likewise equall, if + <i>ao</i>, and <i>oe</i>, be knit together with a right line, as here: + For three in like manner do come to be equall.</p> + + <div class="figcenter" style="width:53%;"> + <a href="images/203c.png"><img style="width:100%" src="images/203c.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>But if the three angles <i>non deinceps</i> not successively following + be equall, as <i>aio</i>, the businesse will yet be more easie, as here: + For the angles <i>eua</i>, and <i>eoi</i>, are equall by the grant: And + the inner also <i>eou</i>, and <i>euo</i>. Therefore the wholes of two + are equall. Of the other at <i>e</i>, the same will fall out, if + <i>iu</i>, be knit together with <span class="correction" title="text reads `e' in italics" + >a</span> right line <i>iu</i>, as here: For the wholes of two shall be + equall.</p> + +<hr class="full" /> + +<p><!-- Page 201 --><span class="pagenum"><a name="pageastx201"></a>[201*]</span></p> + +<h2>The fifteenth Booke of <i>Geometry</i>, +Of the Lines in a Circle.</h2> + + <p>As yet we have had the Geometry of rectilineals: The Geometry of + Curvilineals, of which the Circle is the chiefe, doth follow.</p> + + <p><a name="1_e_xv"></a> 1. <i>A Circle is a round plaine. è 15 d + j</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/204.png"><img style="width:100%" src="images/204.png" + alt="Circle." title="Circle." /></a> + </div> + <p>As here thou seest. A Rectilineall plaine was at the <a + href="#3_e_vj">3 e vj</a>, defined to be a plaine comprehended of right + lines. And so also might a circle have beene defined to be a plaine + comprehended of a periphery or bought-line, but this is better.</p> + + <p>The meanes to describe a Circle, is the same, which was to make a + Periphery: But with some difference: For there was considered no more but + the motion, the point in the end of the ray describing the periphery: + Here is considered the motion of the whole ray, making the whole plot + conteined within the periphery.</p> + + <p>A Circle of all plaines is the most ordinate figure, as was before + taught at the <a href="#10_e_iiij">10 e iiij</a>.</p> + + <p><a name="2_e_xv"></a> 2 <i>Circles are as the quadrates or squares + made of their diameters 2 p. xij</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/205a.png"><img style="width:100%" src="images/205a.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p>For Circles are like plaines. And their homologall sides are their + diameters, as was foretold at the <a href="#24_e_iiij">24 e iiij</a>. And + therefore by the <a href="#1_e_vj">1 e vj</a>, they are one to another, + as the quadrates of their diameters are one to another, which indeed is + the double reason of their homologall sides. As here the Circle + <i>aei</i>, is unto the Circle <i>ouy</i> as 25, is unto 16, which are + <!-- Page 202 --><span class="pagenum"><a + name="pageastx202"></a>[202*]</span>the quadrates of their Dieameters, 5 + and 4.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="3_e_xv"></a> 3. <i>The Diameters are, as their peripheries + Pappus, 5 l. xj, and 26th. 18</i>.</p> + + <p>As here thou seest in <i>ae</i>, and <i>io</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/205b.png"><img style="width:100%" src="images/205b.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p><a name="4_e_xv"></a> 4. <i>Circular Geometry is either in Lines, or + in the segments of a Circle</i>.</p> + + <p>This partition of the subject matters howsoever is taken for the + distinguishing and severing with some light a matter somewhat confused; + And indeed concerning lines, the consideration of secants is here the + foremost, and first of Inscripts.</p> + + <div class="figright" style="width:19%;"> + <a href="images/206a.png"><img style="width:100%" src="images/206a.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p><a name="5_e_xv"></a> 5. <i>If a right line be bounded by two points + in the periphery, it shall fall within the Circle. 2 p iij.</i> <!-- Page + 203 --><span class="pagenum"><a name="pageastx203"></a>[203*]</span></p> + + <p>As here <i>ae</i>, because the right within the same points is + shorter, than the periphery is, by the <a href="#5_e_ij">5 e ij</a>.</p> + + <p>From hence doth follow the Infinite section, of which we spake at the + <a href="#6_e_j">6 e j</a>.</p> + + <p>This proposition teacheth how a Rightline is to be inscribed in a + circle, to wit, by taking of two points in the periphery.</p> + + <p><a name="6_e_xv"></a> 6. <i>If from the end of the diameter, and with + a ray of it equal to the right line given, a periphery be described, a + right line drawne from the said end, unto the meeting of the peripheries, + shall be inscribed into the circle, equall to the right line given. 1 p + iiij</i>.</p> + + <div class="figleft" style="width:25%;"> + <a href="images/206b.png"><img style="width:100%" src="images/206b.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>As let the right line given be <i>a</i>: And from <i>e</i>, the end of + the diameter <i>ei</i>: And with <i>eo</i>, a part of it equall to + <i>a</i>, the line given, describe the circle <i>eu</i>: A right line + <i>eu</i>, drawne from the end <i>e</i>, unto <i>u</i>, the meeting of + the two peripheries, shall be inscribed in the circle given, by the <a + href="#5_e_xv">5 e</a>, equall to the line given; because it is equall to + <i>eo</i>, by the <a href="#10_e_v">10 e v</a>, seeing it is a ray of the + same Circle.</p> + + <p>And this proposition teacheth, How a right line given is to be + inscribed into a Circle, equall to a line given.</p> + + <p>Moreover of all inscripts the diameter is the chiefe: For it sheweth + the center, and also the reason or proportion of all other inscripts. + Therefore the invention and making of the diameter of a Circle is first + to be taught.</p> + + <p><a name="7_e_xv"></a> 7. <i>If an inscript do cut into two equall + parts, another <!-- Page 174 --><span class="pagenum"><a + name="pageastx174"></a>[174*]</span>inscript perpendicularly, it is the + diamiter of the Circle, and the middest of it is the center. 1 p + iij</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/207.png"><img style="width:100%" src="images/207.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>As let the Inscript <i>ae</i>, cut the inscript <i>iu</i> + perpendicularly: dividing it into two equall parts in <i>o</i>. I say + that the <span class="correction" title="text reads `once'">one</span> + inscript thus halfing the other, is the diameter of the Circle: And that + the middest of it is the center thereof: As in the circle, let the + Inscript <i>is</i>, cut the inscript <i>ae</i>, and that perpendicularly + dividing into two equall parts in <i>o</i>. I say that <i>iu</i>, thus + dividing <i>ae</i>, is the Diameter of the Circle: And <i>y</i>, the + middest of the said <i>iu</i>, is the Center of the same.</p> + + <p>The cause is the same, which was of the <a href="#5_e_xj">5 e xj</a>. + Because the inscript cut into halfes <span class="correction" title="text reads `if'" + >is</span> for the side of the inscribed rectangle, and it doth subtend + the periphery cut also into two parts; By the which both the Inscript and + Periphery also were in like manner cut into two equall parts: Therefore + the right line thus halfing in the diameter of the rectangle: But that + the middle of the circle is the center, is manifest out of the <a + href="#7_e_v">7 e v</a>, and <a href="#29_e_iiij">29 e iiij</a>.</p> + + <p><i>Euclide</i>, thought better of <i>Impossibile</i>, than he did of + the cause: And thus he forceth it. For if <i>y</i> be not the Center, but + <i>s</i>, the part must be equall to the whole: For the Triangle + <i>aos</i>, shall be equilater to the triangle <i>eos</i>. For <i>ao</i>, + <i>oe</i>, are equall by the grant: Item <i>sa</i>, and <i>se</i>, are + the rayes of the circle: And <i>so</i>, is common to both the triangles. + Therefore by the <a href="#1_e_vij">1 e vij</a>, the angles <span + class="correction" title="text reads `no'">on</span> each side at + <i>o</i> are equall; And by the <a href="#13_e_v">13 e v</a>, they are + both right angles. Therefore <i>soe</i> is a right angle; It is therefore + equall by the grant, to the right angle <i>yoe</i>, that is, the part is + equall to the whole, which is impossible. Wherefore <span + class="correction" title="text reads `y'"><i>s</i></span> is not the + Center. The same will fall out of any other points whatsoever out of + <i>y</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="8_e_xv"></a> 8. <i>If two right lines doe perpendicularly + halfe two <!-- Page 175 --><span class="pagenum"><a + name="pageastx175"></a>[175*]</span>inscripts, the meeting of these two + bisecants shall be the Center of the circle è 25 p iij.</i></p> + + <div class="figright" style="width:20%;"> + <a href="images/208a.png"><img style="width:100%" src="images/208a.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>As here <i>ae</i>, and <i>io</i>, let them cut into halfes the right + lines <i>uy</i>, and <i>ys</i>. And let them meete, that they cut one + another in <i>r</i>. I say <i>r</i> is the center of the circle + <i>ayoseiu</i>. For before, at the <a href="#6_e_xv">6</a>, and <a + href="#7_e_xv"><span class="correction" title="text reads `7 e v'">7 + e</span></a>, it was manifest that the Center was in the Diameter. And in + the meeting of the diameters. [Therefore two manner of wayes is the + Center found; First by the middle of the diameter: And then againe by the + concourse, or meeting of the diameters, in the middest of the lines + halfed or cut into two equall portions.] Here is no neede of the meeting + of many diameters, one will serve well enough.</p> + + <div class="poem"> + <div class="stanza"> + <p>And one may</p> + </div> + </div> + <p><a name="9_e_xv"></a> 9. <i>Draw a periphery by three points, which + doe not fall in a right line</i>.</p> + + <div class="figleft" style="width:19%;"> + <a href="images/208b.png"><img style="width:100%" src="images/208b.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p>As here, by <i>aei</i>, (First from <i>a</i>, to <i>e</i>, let a right + line be drawne; And likewise from <i>e</i> to <i>i</i>. Then, by the <a + href="#12_e_v">12 e v</a>, let both these lines be cut into equall parts, + by two infinite right lines: These halfing lines also shall meete: And in + their meeting shall be the Center, by the <a href="#8_e_xv">8 e</a>. And + therefore from that meeting unto any of the sayd points given is the ray + of the periphery desired.)</p> + + <p><a name="10_e_xv"></a> 10. <i>If a diameter doe halfe an inscript, + that is, not a diameter, it doth cut it perpendicularly: And + contrariwise: 3 p iij.</i> <!-- Page 206 --><span class="pagenum"><a + name="pageastx206"></a>[206*]</span></p> + + <div class="figright" style="width:19%;"> + <a href="images/209a.png"><img style="width:100%" src="images/209a.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p>As let the diameter <i>ae</i>, halfe the inscript <i>io</i>, which is + not a diameter: And let the raies of the circle bee <i>ui</i>, and + <i>uo</i>. The cause in all is the same, which was of the <a + href="#5_e_xj">5 e xj</a>.</p> + + <p><a name="11_e_xv"></a> 11. <i>If inscripts which are not diameters doe + cut one another, the segments shall be unequall. 4 p iij</i>.</p> + + <div class="figleft" style="width:19%;"> + <a href="images/209b.png"><img style="width:100%" src="images/209b.png" + alt="Figure for demonstration 11." title="Figure for demonstration 11." /></a> + </div> + <p>This is a consectary drawne out of the <a href="#28_e_iiij">28 e + iiij</a>. For if the inscripts were halfed, they should be diameters, + against the grant.</p> + + <p>But rate hath beene hitherto in the parts of inscripts: Proportion in + the same parts followeth.</p> + + <p><a name="12_e_xv"></a> 12 <i>If two inscripts doe cut one another, the + rectangle of the segments of the one is equall to the rectangle of the + segments of the other. 35 p iij</i>.</p> + + <p>If the inscripts thus cut be diameters, the proportion is manifest, as + in the first figure. For the Rectangle of the segments, of the one is + equall to the rectangle of the segments of the other, seeing they be both + quadrates of equall sides. If they be not diameters let them otherwise as + <i>ae</i>, and <i>io</i>: I say the Oblong of <i>au</i>, and <i>ue</i>, + is equall to the Oblong of <i>ou</i>, and <i>ui</i>. For let the raies + from the Center <i>y</i>, be <i>ye</i>, and <i>yi</i>. To the quadrate of + each of these both the rectangles of the segments shall be equall. For by + the <a href="#7_e_xv">7 e</a>, let the diameter <i>yu</i>, fall upon the + point of the common section <i>u</i>; And let <i>ys</i>, and <i>sr</i>, + be perpendiculars. Here by the <a href="#5_e_xj">5 e xj</a>. the + inscripts are cut equally in the points <i>r</i> and <i>s</i>: And + unequally in the point <i>u</i>: Therefore by the <a href="#7_e_xiij">7 e + xiij</a>, the <!-- Page 189 --><span class="pagenum"><a + name="page189"></a>[189]</span>oblong, of <i>ou</i>, and <i>ui</i>, with + the quadrate <i>su</i>, is equall to the quadrates <i>si</i>; And adding + <i>ys</i>, the same oblong, with the quadrates <i>us</i> and <i>sy</i>, + that is, by the <a href="#9_e_xij">9 e xij</a>, with the quadrate + <i>yu</i>, is equall to the quadrates <i>is</i> and <i>sy</i>, that is, + by the <a href="#9_e_xij">9 e xij</a>, to the quadrate <i>iy</i>, that + is, by the <a href="#5_e_xij">5 e xij</a>, to <i>ye</i>, to the which by + the same cause it is manifest the other oblong with the quadrate + <i>yu</i> is equall. Let the quadrate <i>yu</i>, bee taken from each of + them: And then the oblongs shall be equall to the same: And therefore + betweene themselves.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/210a.png"><img style="width:100%" src="images/210a.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>And this is the comparison of the parts inscripts. The rate of whole + inscripts doth follow, the which whole one diameter doth make:</p> + + <div class="figright" style="width:19%;"> + <a href="images/210b.png"><img style="width:100%" src="images/210b.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><a name="13_e_xv"></a> 13 <i>Inscripts are equall distant from the + center, unto which the perpendiculars from the center are equall 4 d + iij</i>.</p> + + <p>As it appeareth in the next figure, of the lines <i>ae</i> and + <i>io</i>, unto which the perpendiculars <i>uy</i> and <i>us</i>, from + the Center <i>u</i>, are equall.</p> + + <p><a name="14_e_xv"></a> 14. <i>If inscripts be equall, they be equally + distant from the center: And contrariwise. 13 p iij.</i> <!-- Page 190 + --><span class="pagenum"><a name="page190"></a>[190]</span></p> + + <p>The diameters in the same circle, by the <a href="#28_e_iiij">28 e + iiij</a>, are equall: And they are equally distant from the center, + seeing they are by the center, or rather are no whit at all distant from + it: Other inscripts are judged to be equall, greater, or lesser one than + another, by the diameter, or by the diameters center.</p> + + <p><i>Euclide</i> doth demonstrate this proposition thus: Let first + <i>ae</i> and <i>io</i> be equall; I say they are equidistant from the + center. For let <i>uy</i>, and <span class="correction" title="text reads `uy'" + ><i>us</i></span>, be perpendiculars: They shall cut the assigned + <i>ae</i>, & <i>io</i>, into halfes, by the <a href="#5_e_xj">5 e + xj</a>: And <i>ya</i> and <i>si</i> are equall, because they are the + halfes of equals. Now let the raies of the circle be <i>ua</i>, <span + class="correction" title="text reads `aund'">and</span> <i>ui</i>: Their + quadrates by the <a href="#9_e_xij">9 e xij</a>, are equall to the paire + of quadrates of the shankes, which paires are therefore equall betweene + themselves. Take from equalls the quadrates <i>ya</i>, and <i>si</i>, + there shall remaine <i>yu</i>, and <i>us</i>, equalls: and therefore the + sides are equall, by the <a href="#4_e_xij">4 e 12</a>.</p> + + <p>The converse likewise is manifest: For the perpendiculars given do + halfe them: And the halfes as before are equall.</p> + + <p><a name="15_e_xv"></a> 15 <i>Of unequall inscripts the diameter is the + greatest: And that which is next to the diameter, is greater than that + which is farther off from it: That which is farthest off from it, is the + least: And that which is next to the least, is lesser than that which is + farther off: And those two onely which are on each side of the diameter + are equall è 15 e iij</i>.</p> + + <p>This proposition consisteth of five members: The first is, The + diameter is the greatest <span class="correction" title="text reads `iuscript'" + >inscript</span>: The second, That which is next to the diameter is + greater than that which is farther off: The third, That which is farthest + off from the diameter is the least: The fourth, That next to the least is + lesser, than that farther off: The fifth, That two onely on each side of + the diameter are equall betweene themselves. All which are manifest, out + of that same argument of equalitie, that is the center the beginning of + decreasing, and the <!-- Page 191 --><span class="pagenum"><a + name="page191"></a>[191]</span>end of increasing. For looke how much + farther off you goe from the center, or how much nearer you come unto it, + so much lesser or greater doe you make the inscript.</p> + + <div class="figright" style="width:18%;"> + <a href="images/212.png"><img style="width:100%" src="images/212.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>Let there be in a circle; many inscripts, of which one, to wit, + <i>ae</i>, let it be the diameter: I say, that it is of them all the + greatest or longest. But let <i>io</i>, be nearer to the diameter, (or as + in the former Elements was said) nearer to the center, than <i>uy</i>. I + say that <i>io</i>, is longer than <i>uy</i>. Moreover, let <i>uy</i>, be + the farthest off from the same diameter or center; I say the same + <i>uy</i>, is the shortest of them all. Now to this shortest <i>uy</i>, + let <i>io</i>, be nearer than <i>ae</i>; I say therefore that <i>io</i>, + also is lesser than <i>ae</i>. Let at length <i>io</i>, be not the + diameter: I say that beyond the diameter <i>ae</i>, there may onely a + line be inscribed equall unto it, such as is <i>sr</i>. And those equal + betweene themselves on each side of the diametry may only be given, not + three, nor more. And after the same manner also, onely one beyond the + diameter, may possibly be equall to <i>uy</i>, to wit, that which is as + farre off from the diameter as it is; and so in others.</p> + + <p>But Euclides conclusion is by triangles of two sides greater than the + other; and of the greater angle.</p> + + <p>The first part is plaine thus: Because the diameter <i>ae</i>, is + equall to <i>il</i>, and <i>lo</i>, <i>viz</i>. to the raies; And to + those which are greater than <i>io</i>, the base by the <a + href="#9_e_vj">9. e vj</a> &c.</p> + + <p>The second part of the nearer, is manifest by the <a href="#5_e_vij">5 + e vij</a>. because of the triangle <i>ilo</i>, equicrurall to the + triangle <i>uly</i>, is greater in angle: And therefore it is also + greater in base.</p> + + <p>The third and fourth are consectaries of the first.</p> + + <p>The fifth part is manifest by the second: For if beside <i>io</i>, and + <i>sr</i>, there be supposed a third equall, the same also shall be + unequall, because it shall be both nearer and farther off from the + diameter. <!-- Page 192 --><span class="pagenum"><a + name="page192"></a>[192]</span></p> + + <div class="figright" style="width:19%;"> + <a href="images/213.png"><img style="width:100%" src="images/213.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p><a name="16_e_xv"></a> 16 <i>Of right lines drawne from a point in the + diameter which is not the center unto the periphery, that which passeth + by the center is the greatest: And that which is nearer to the greatest, + is greater than that which is farther off: The other part of the greatest + is the left. And that which is nearest to the least, is lesser than that + which is farther off: And two on each side of the greater or least are + only equall. 7 p iij</i>.</p> + + <p>The first part of <i>ae</i>, and <i>ai</i>, is manifest, as before, by + the <a href="#9_e_vj">9 e vj</a>. The second of <i>ai</i>, and <i>ao</i>; + Item of <i>ao</i>, and <i>au</i>, is plaine by the <a href="#5_e_vij">5 e + vij</a>.</p> + + <p>The third, that <i>ay</i>, is lesser than <i>au</i>, because + <i>sy</i>, which is equall to <i>su</i>, is lesser than the right lines + <i>sa</i>, and <i>au</i>, by the <a href="#9_e_vj">9 e vj</a>: And the + common <i>sa</i>, being taken away, <i>ay</i> shall be left, lesser than + <i>au</i>.</p> + + <p>The fourth part followeth of the third.</p> + + <p>The fifth let it be thus: <i>sr</i>, making the angle <i>asr</i>, + equall to the angle <i>asu</i>, the bases <i>au</i>, and <i>ar</i>, shall + be equall by the <a href="#2_e_vij">2 e vij</a>. To these if the third be + supposed to be equall, as <i>al</i>, it would follow by the <a + href="#1_e_vij">1 e vij</a>. that the whole angle <i>sa</i>, should be + equall to <i>rsa</i>, the particular angle, which is impossible. And out + of this fifth part issueth this Consectary.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figleft" style="width:19%;"> + <a href="images/214a.png"><img style="width:100%" src="images/214a.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> + <p><a name="17_e_xv"></a> 17 <i>If a point in a circle be the bound of + three equall right lines determined in the periphery, it is the center of + the circle. 9 p iij</i>.</p> + + <p>Let the point <i>a</i>, in a circle be the common bound of three right + lines, ending in the periphery and equall betweene themselves, be + <i>ae</i>, <i>ai</i>, <i>au</i>. I say this point is the center of the + Circle. <!-- Page 193 --><span class="pagenum"><a + name="page193"></a>[193]</span></p> + + <div class="figright" style="width:16%;"> + <a href="images/214b.png"><img style="width:100%" src="images/214b.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p>Otherwise from a point of the diameter which is not the center, not + onely two right lines on each side should be equall. For by any point + whatsoever the diameter may be drawne. Such was before observed in a + quinquangle; If three angles be equall, all are equall; so in a Circle: + If three right lines falling from the same point unto the perephery be + equall, all are equall.</p> + + <p><a name="18_e_xv"></a> 18 <i>Of right lines drawne from a point + assigned without the periphery, unto the concavity or hollow of the same, + that which is by the center is the greatest; And that next to the + greatest, is greater than that which is farther off: But of those which + fall upon the convexitie of the circumference, the segment of the + greatest is least. And that which is next unto the least is lesser than + that is farther off: And two on each side of the greatest or least are + onely equall. 8 p iij</i>.</p> + + <p>The demonstration of this is very like unto the above mentioned, of + five parts. And thus much of the secants, the Tangents doe follow.</p> + + <div class="figleft" style="width:19%;"> + <a href="images/215a.png"><img style="width:100%" src="images/215a.png" + alt="Figure for demonstration 19." title="Figure for demonstration 19." /></a> + </div> + <p><a name="19_e_xv"></a> 19 <i>If a right line be perpendicular unto the + end of the diameter, it doth touch the periphery: And contrariwise è 16 p + iij</i>.</p> + +<p><!-- Page 194 --><span class="pagenum"><a name="page194"></a>[194]</span></p> + + <p>As for example, Let the circle given <i>ae</i>, be perpendicular to + the end of the diameter, or the end of the ray, in the end <i>a</i>, as + suppose the ray be <i>ia</i>: I say, that <i>ea</i>, doth touch, not cut + the periphery in the common bound <i>a</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/215b.png"><img style="width:100%" src="images/215b.png" + alt="Figure for demonstration 19 converse." title="Figure for demonstration 19 converse." /></a> + </div> + <p>This was to have beene made a <i>postulatum</i> out of the definition + of a perpendicle: Because if this should leane never so little, it should + cut the periphery, and should not be perpendicular: Notwithstanding + <i>Euclide</i> doth force it thus: Otherwise let the right line + <i>ae</i>, be perpendicular to the diameter <i>ai</i>. And a right line + from <i>o</i>, with the center <i>i</i>, let it fall within the circle at + <i>o</i>, and let <i>oi</i>, joyned together. Here in the triangle + <i>aoi</i>, two angles, contrary to the <a href="#13_e_vj">13 e vj</a>, + should be right angles at <i>a</i>, by the grant: And at <i>o</i>, by the + <a href="#17_e_vj">17 e vj</a>.</p> + + <p>The demonstration of the converse is like unto the former. For if the + tangent, or touch-line <i>ae</i>, be not perpendicular to the diameter + <i>iou</i>, let <i>oe</i>, from the center <i>o</i>, be drawne + perpendicular; Then shall the angle <i>oei</i>, be right angle: And + <i>oie</i> an acutangle: And therefore by the <a href="#22_e_vj">22 e + vj</a>, <i>oi</i>, that is <i>oy</i>, shall be greater then <i>oye</i>, + that is the part, then the whole.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="20_e_xv"></a> 20 <i>If a right line doe passe by the center + and touch-point, it is perpendicular to the tangent or touch-line. 18 p + iij</i>.</p> + + <p>Or thus, as <i>Schoner</i> amendeth it: If a right line be the + diameter by the touch point, it is perpendicular to the tangent. <!-- + Page 195 --><span class="pagenum"><a name="page195"></a>[195]</span></p> + + <p><a name="21_e_xv"></a> 21 <i>If a right line be perpendicular unto the + tangent, it doth passe by the center and touch-point. 19. p iij.</i></p> + + <p>Or thus: if it be perpendicular to the tangent, it is a diameter by + the touch point: <i>Schoner</i>.</p> + + <p>For a right line either from the center unto the touch-point; or from + the touch point unto the center is radius or semidiameter.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="22_e_xv"></a> 22 <i>The touch-point is that, into which the + perpendicular from the center doth fall upon the touch line</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/216.png"><img style="width:100%" src="images/216.png" + alt="Figure for demonstration 23." title="Figure for demonstration 23." /></a> + </div> + <p><a name="23_e_xv"></a> 23 <i>A tangent on the same side is onely + one</i>.</p> + + <p>Or touch line is but one upon one, and the same side: <i>H</i>. Or. A + tangent is but one onely in that point of the periphery + <i>Schoner</i>.</p> + + <p>It is a consectary drawne out of the <a href="#13_e_ij">xiij. e + ij</a>. Because a tangent is a very perpendicular.</p> + + <p><i>Euclide</i> propoundeth this more specially thus; that no other + right line may possibly fall betweene the periphery and the tangent.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="24_e_xv"></a> 24 <i>A touch-angle is lesser than any + rectilineall acute angle, è 16 p ij</i>.</p> + + <p><i>Angulus contractus,</i> A touch angle is an angle of a straight + touch-line and a periphery. It is commonly called <i>Angulus + contingentiæ</i>: Of <i>Proclus</i> it is named <i>Cornicularis</i>, an + horne-like corner; because it is made of a right line and periphery like + unto a horne. It is lesse therefore than any acute or sharpe right-lined + angle: Because if it were not lesser, a <!-- Page 196 --><span + class="pagenum"><a name="page196"></a>[196]</span>right line might fall + between the periphery and the perpendicular.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="25_e_xv"></a> 25 <i>All touch-angles in equall peripheries + are equall</i>.</p> + + <p>But in unequall peripheries, the cornicular angle of a lesser + periphery, is greater than the Cornicular of a greater.</p> + + <div class="figright" style="width:19%;"> + <a href="images/217.png"><img style="width:100%" src="images/217.png" + alt="Figure for demonstration 26." title="Figure for demonstration 26." /></a> + </div> + <p><a name="26_e_xv"></a> 26 <i>If from a ray out of the center of a + periphery given, a periphery be described unto a point assigned without, + and from the meeting of the assigned and the ray, a perpendicular falling + upon the said ray unto the now described periphery, be tied by a right + line with the said center, a right line drawne from the point given unto + the meeting of the periphery given, and the knitting line shall touch the + assigned periphery 17 p iij</i>.</p> + + <p>As with the ray <i>ae</i>, from the center <i>a</i>, of the periphery + assigned, unto the point assigned <i>e</i>, let the periphery <i>eo</i>, + be described: And let <i>io</i>, be perpendicular to the ray unto the + described periphery. This knit by a right line unto the center <i>a</i>, + let <i>eu</i>, be drawne. I say, that <i>eu</i>, doth touch the periphery + <i>iu</i>, assigned: Because it shall be perpendicular unto the end of + the diameter. For the triangles <i>eau</i>, and <i>oai</i>, by the <a + href="#2_e_vij">2 e vij</a>, seeing they are equicrurall; And equall in + shankes of the common angle; they are equall in the angles at the base. + But the angle <i>aio</i>, is a right angle: Therefore the angle + <i>eua</i>, shall be a right angle. And therefore the right line + <i>eu</i>, by the <a href="#13_e_ij">13 e ij</a>, is perpendicular to + <i>ao</i>.</p> + + <p>Thus much of the Secants and Tangents severally: It followeth of both + kindes joyntly together.</p> + + <div class="figright" style="width:16%;"> + <a href="images/218a.png"><img style="width:100%" src="images/218a.png" + alt="Figure for demonstration 27 first case." title="Figure for demonstration 27 first case." /></a> + </div> + <p><a name="27_e_xv"></a> 27 <i>If of two right lines, from an assigned + point without, the first doe cut a periphery unto the concave, <!-- Page + 197 --><span class="pagenum"><a name="page197"></a>[197]</span>the other + do touch the same; the oblong of the secant, and of the outter segment of + the secant, is equall to the quadrate of the tangent: and if such a like + oblong be equall to the quadrate of the other, that same other doth touch + the periphery: 36, and 37. p iij</i>.</p> + + <p>If the secant or cutting line do passe by the center, the matter is + more easie and as here, Let <span class="correction" title="text reads `a'" + ><i>ae</i></span>, cut; And <i>ai</i>, touch: The outter segment is + <i>ao</i>, and the center <i>u</i>, Now <i>ui</i>, shall be perpendicular + to the tangent <i>ai</i>, by the 20. e: Then by <a href="#8_e_xiij">8 e + xiij</a>, the oblong of <i>ea</i>, and <i>ao</i>, with the quadrate of + <i>au</i>, that is, of <i>iu</i>, is equall to the quadrate of <i>au</i>, + that is, by the <a href="#9_e_xij">9 e xij</a>. to the quadrates of + <i>ai</i>, and <i>iu</i>. Take <i>iu</i>, the common quadrate: The + Rectangle shall be equall to the quadrate of the tangent.</p> + + <div class="figleft" style="width:16%;"> + <a href="images/218b.png"><img style="width:100%" src="images/218b.png" + alt="Figure for demonstration 27 second case." title="Figure for demonstration 27 second case." /></a> + </div> + <p>If the secant doe not passe by the center, as in this figure, the + center <i>u</i>, found by the <a href="#7_e_xv">7 e</a>, <i>iu</i>, shall + be by the <a href="#20_e_xv">20 e</a> perpendicular unto the tangent + <i>ai</i>; then draw <i>ua</i>, and <i>uo</i>, and the perpendicular + halving <i>oe</i>, by the <a href="#10_e_xv">10 e</a>. Here by the <a + href="#8_e_xiij">8 e xiij</a>, the oblong of <i>ae</i>, and <i>ao</i>, + with the quadrate <i>oy</i>, is equal to the quadrate <i>ay</i>: + Therefore <i>yu</i>, the common quadrate added, the same oblong, with the + quadrates <i>oy</i>, and <i>yu</i>, that is by the <a href="#9_e_xij">9 e + xij</a>. with the quadrate <i>ou</i>, is equall to the quadrates + <i>ay</i>, and <i>uy</i>, that is, by the <a href="#9_e_xij">9 e xij</a>, + to <i>au</i>, that is, againe, to <i>ai</i>, and <i>iu</i>. Lastly, let + <i>ur</i>, and <i>iu</i>, two equall quadrates be taken from each, and + there wil remaine the oblong equall to the quadrate of the tangent.</p> + + <div class="figright" style="width:16%;"> + <a href="images/219.png"><img style="width:100%" src="images/219.png" + alt="Figure for demonstration 27 converse." title="Figure for demonstration 27 converse." /></a> + </div> + <p>The converse is likewise demonstrated in this figure. Let the + Rectangle of <i>ae</i>, and <i>ay</i>, be equall to the quadrate of + <i>ai</i>. <!-- Page 198 --><span class="pagenum"><a + name="page198"></a>[198]</span>I say, that <i>ai</i> doth touch the + circle. For let, by the <a href="#26_e_xv">26 e</a>, <i>ao</i> the + tangent be drawne: Item let <i>au</i>, <i>ui</i>, and <i>uo</i> bee + drawne. Here the oblong of <i>ea</i>, and <i>ay</i>, is equall to the + quadrate of <i>ao</i>, by the <a href="#27_e_xv">27 e</a>: And to the + quadrate of <i>ai</i>, by the grant. Therefore <i>ai</i>, and <i>ao</i>, + are equall. Then is <i>uo</i>, by the <a href="#20_e_xv">20 e</a>, + perpendicular to the tangent. Here the triangles <i>auo</i>, and + <i>aui</i>, are equilaters: And by the <a href="#1_e_vij">1 e vij</a>, + equiangles. But the angle at <i>o</i> is a right angle: Therefore also a + right angle and equall to it is that at <i>i</i>, by the <a + href="#13_e_iij">13 e iij</a>, wherefore <i>ai</i> is perpendicular to + the end of the diameter: And, by the <a href="#19_e_xv">19 e</a>, it + toucheth the periphery.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="28_e_xv"></a> 28. <i>All tangents falling from the same point + are equall</i>.</p> + + <p>Or, Touch lines drawne from one and the same point are equall: + <i>H</i>.</p> + + <p>Because their quadrates are equall to the same oblong.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="29_e_xv"></a> 29. <i>The oblongs made of any secant from the + same point, and of the outter segment of the secant are equall betweene + themselves. Camp. 36 p iij</i>.</p> + + <p>The reason is because to the same <i>thing</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="30_e_xv"></a> 30. <i>To two right lines given one may so + continue or joyne the third, that the oblong of the continued and the + continuation may be equall to the quadrate remaining. Vitellio 127 p + j</i>.</p> + + <p>As in the first figure, if the first of the lines given be <i>eo</i>, + the second <i>ia</i>, the third <i>oa</i>.</p> + + <p>Now are we come to Circular Geometry, that is to the Geometry of + Circles or Peripheries cut and touching one another: And of Right lines + and Peripheries. <!-- Page 199 --><span class="pagenum"><a + name="page199"></a>[199]</span></p> + + <div class="figright" style="width:23%;"> + <a href="images/220a.png"><img style="width:100%" src="images/220a.png" + alt="Figure for demonstration 31 first part." title="Figure for demonstration 31 first part." /></a> + </div> + <p><a name="31_e_xv"></a> 31. <i>If peripheries doe either cut or touch + one another, they are eccentrickes: And they doe cut one another in two + points onely, and these by the touch point doe continue their diameters, + 5. 6. 10, 11, 12 p iij</i>.</p> + + <p>All these might well have beene asked: But they have also their + demonstrations, <i>ex impossibili</i>, not very difficult.</p> + + <div class="figleft" style="width:17%;"> + <a href="images/220b.png"><img style="width:100%" src="images/220b.png" + alt="Figure for demonstration 31 second part." title="Figure for demonstration 31 second part." /></a> + </div> + <p>The first part is manifest, because the part should be equall to the + whole, if the Center were the same to both, as <i>a</i>. For two raies + are equall to the common raie <i>ao</i>: And therefore <i>ae</i> and + <i>ai</i>, that is, the part and the whole, are equall one to + another.</p> + + <p>The second part is demonstrated as the first: For otherwise the part + must be equall to the whole, as here <i>ae</i> and <i>ai</i>, the raies + of the lesser periphery; And <i>ae</i>, and <i>ao</i>, the raies of the + greater are equall. Wherefore <i>ai</i>, should be equall to <i>ao</i> + the Part to the whole.</p> + + <div class="figright" style="width:23%;"> + <a href="images/220c.png"><img style="width:100%" src="images/220c.png" + alt="Figure for demonstration 31 outwardly contiguall." title="Figure for demonstration 31 outwardly contiguall." /></a> + </div> + <p>If the Peripheries be outwardly contiguall, the matter is more easie, + and by the judgement of <i>Euclide</i> it deserved not a demonstration, + as here.</p> + + <p><br style="clear :left" /></p> + <div class="figleft" style="width:22%;"> + <a href="images/220d.png"><img style="width:100%" src="images/220d.png" + alt="Figure for demonstration 31 third part." title="Figure for demonstration 31 third part." /></a> + </div> + <p>The third part is apparent out of the first: Otherwise those which cut + one another should be concentrickes. For, by the <a href="#7_e_xv">7 + e</a>, the center being found: And by the <a href="#9_e_xv">9 e</a>, + three right lines being drawne from the center unto three points of <!-- + Page 200 --><span class="pagenum"><a name="page200"></a>[200]</span>the + sections, the three raies must be equall, as here.</p> + + <div class="figright" style="width:18%;"> + <a href="images/221a.png"><img style="width:100%" src="images/221a.png" + alt="Figure for demonstration 31 fourth part." title="Figure for demonstration 31 fourth part." /></a> + </div> + <p>The fourth part is demonstrated after the same manner: Because + otherwise the Part must be greater then the whole. For let the right line + <i>aeio</i>, be drawne by the centers <i>a</i> and <i>e</i>: And let the + particular raies be <i>eu</i>, and <i>au</i>. Here two sides <i>ue</i>, + and <i>ea</i>, of the triangle <i>uea</i>, by the <a href="#9_e_vj">9 e + vj</a>, are greater than <i>ua</i>: And therefore also then <i>ao</i>; + Take away <i>ae</i>, the remainder <i>ue</i>, shall be greater than + <i>eo</i>. But <i>ei</i> is equall to <i>eu</i>. Wherefore <i>ei</i> is + greater than <i>eo</i>, the part, than the whole.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/221b.png"><img style="width:100%" src="images/221b.png" + alt="Figure for demonstration 31 touching without." title="Figure for demonstration 31 touching without." /></a> + </div> + <p>The same will fall out, if the touch be without, as here: For, by the + <a href="#9_e_vj">9 e vj</a>, <i>ea</i> and <i>ia</i>, are greater than + <i>ie</i>. But <i>eo</i> and <i>iu</i>, are equall to <i>ea</i>, and + <i>ia</i>. Wherefore <i>eo</i>, and <i>iu</i>, are greater than + <i>ie</i>, the parts than the whole.</p> + + <p>Of right lines and Peripheries joyntly the rate is but one.</p> + + <p><a name="32_e_xv"></a> 32. <i>If inscripts be equall, they doe cut + equall peripheries: And contrariwise, 28, 29 p iij</i>.</p> + + <p>Or thus: If the inscripts of the same circle or of equall circles be + equall, they doe cut equall peripheries: And contrariwise <i>B</i>.</p> + + <p>Or thus: If lines inscribed into equall circles or to the same be + equall, they cut equall peripheries: And contrariwise, if they doe cut + equall peripheries, they shall themselves be equall: <i>Schoner</i>. <!-- + Page 201 --><span class="pagenum"><a name="page201"></a>[201]</span></p> + + <div class="figcenter" style="width:42%;"> + <a href="images/222.png"><img style="width:100%" src="images/222.png" + alt="Figure for demonstration 32." title="Figure for demonstration 32." /></a> + </div> + <p>The matter is apparent by congruency or application: as here in this + example. For let the circles agree, and then shall equall inscripts and + peripheries agree.</p> + + <p>Except with the learned <i>Rodulphus Snellius</i>, you doe understand + aswell two equall peripheries to be given, as two equall right lines, you + shall not conclude two equall sections, and therefore we have justly + inserted <i>of the same, or of equall Circles</i>; which we doe now see + was in like manner by <i>Lazarus Schonerus</i>.</p> + +<hr class="full" /> + +<h2>The sixteenth Booke of <i>Geometry</i>, +Of the Segments of a Circle.</h2> + + <p><a name="1_e_xvj"></a> 1. <i>A Segment of a Circle is that which is + comprehended outterly of a periphery, and innerly of a right + line</i>.</p> + + <p>The Geometry of Segments is common also to the spheare: But now this + same generall is hard to be declared and taught: And the segment may be + comprehended within of an oblique line either single or manifold. But + here we follow those things that are usuall and commonly received. First + therefore the generall definition is set formost, <!-- Page 202 --><span + class="pagenum"><a name="page202"></a>[202]</span>for the more easie + distinguishing of the species and severall kindes.</p> + + <div class="figright" style="width:18%;"> + <a href="images/223a.png"><img style="width:100%" src="images/223a.png" + alt="Sector." title="Sector." /></a> + </div> + <p><a name="2_e_xvj"></a> 2. <i>A segment of a Circle is either a + sectour, or a section</i>.</p> + + <p><i>Segmentum</i> a segment, and <i>Sectio</i> a section, and + <i>Sector</i> a sectour, are almost the same in common acceptation, but + they shall be distinguished by their definitions.</p> + + <p><a name="3_e_xvj"></a> 3. <i>A Sectour is a segment innerly + comprehended of two right lines, making an angle in the center; which is + called an angle in the center: As the periphery is, the base of the + sectour, 9 d iij</i>.</p> + + <p>As <i>aei</i> is a sectour. Here a sectour is defined, and his right + lined angle, is absolutely called <i>The greater Sectour</i> which + notwithstanding may be cut into two sectours by drawing of a + semidiameter, as after shall be seene in the measuring of a section.</p> + + <p><a name="4_e_xvj"></a> 4. <i>An angle in the Periphery is an angle + comprehended of two right lines inscribed, and jointly bounded or meeting + in the periphery. 8 d iij</i>.</p> + + <div class="figleft" style="width:18%;"> + <a href="images/223b.png"><img style="width:100%" src="images/223b.png" + alt="Angle in the Periphery." title="Angle in the Periphery." /></a> + </div> + <p>This might have beene called <i>The Sectour in the Periphery</i>, to + wit, comprehended innerly of two right lines joyntly bounded in the + periphery; as here <i>aei</i>.</p> + + <p><a name="5_e_xvj"></a> 5. <i>The angle in the center, is double to the + angle of the periphery standing upon the same base, 20 p iij</i>.</p> + + <p>The variety or the example in <i>Euclide</i> is threefold, and yet + <!-- Page 203 --><span class="pagenum"><a + name="page203"></a>[203]</span>the demonstration is but one and the same: + As here <i>eai</i>, the angle in the center, shall be prooved to be + double to <i>eoi</i>, the angle in the periphery, the right line + <i>ou</i> cutting it into two triangles on each side equicrurall; And, by + the <a href="#17_e_vj">17 e vj</a>, at the base equiangles: Whose doubles + severally are the angles, <i>eau</i>, of <i>eoa</i>: And <i>iau</i>, of + <i>ioa</i>, For seeing it is equall to the two inner equall betweene + themselves by the <a href="#15_e_vj">15 e vj</a>; it shall be the double + of one of them. Therefore the whole <i>eai</i>, is the double of the + whole <i>eoi</i>.</p> + + <p>The second example is thus of the angle in the center <i>aei</i>: And + in the periphery <i>aoi</i>. Here the shankes <i>eo</i>, and <i>ei</i>, + by the <a href="#28_e_iiij">28 e iiij</a>, are equall: And by the <a + href="#17_e_vj">17 e vj</a>, the angles at <i>o</i> and <i>i</i> are + equall: To both which the angle in the center is equall, by the <a + href="#15_e_vj">15 e vj</a>. Therefore it is double of the one.</p> + + <div class="figcenter" style="width:73%;"> + <a href="images/224.png"><img style="width:100%" src="images/224.png" + alt="Figures for demonstration 5." title="Figures for demonstration 5." /></a> + </div> + <p>The third example is of the angle in the center, <i>aei</i>, And in + the periphery <i>aoi</i>, Let the diameter be <i>oeu</i>. Here the whole + angle <i>ieu</i>, by the <a href="#15_e_vj">15 e vj</a>, is equall to the + two inner angles <i>eoi</i>, and <i>eio</i>, which are equall one to + another, by the <a href="#17_e_vj">17 e vj</a>: And therefore it is + double of the one. Item the particular angle <i>aeu</i>, is equall by the + <a href="#15_e_vj">15 e vj</a>, to the angles <i>eoa</i>, and <i>eao</i>, + equall also one to another, by the <a href="#17_e_vj">17 e vj</a>. + Therefore the remainder <i>aei</i>, is the double of the other + <i>aoi</i>, in the periphery.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="6_e_xvj"></a> 6. <i>If the angle in the periphery be equall + to the <!-- Page 204 --><span class="pagenum"><a + name="page204"></a>[204]</span>angle in the center, it is double to it in + base. And contrariwise</i>.</p> + + <p>This followeth out of the former element: For the angle in the center + is double to the angle in the periphery standing upon the same base: + Wherefore if the angle in the periphery be to be made equall to the angle + in the center, his base is to be doubled, and thence shall follow the + equality of them both: <i>S</i>.</p> + + <p><a name="7_e_xvj"></a> 7. <i>The angles in the center or periphery of + equall circles, are as the Peripheries are upon which they doe insist: + And contrariwise. è 33 p vj, and 26, 27 p iij</i>.</p> + + <div class="figcenter" style="width:41%;"> + <a href="images/225.png"><img style="width:100%" src="images/225.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>Here is a double proportion with the periphery underneath, of the + angles in the center: And of angles in the periphery. But it shall + suffice to declare it in the angles in the center.</p> + + <p>First therefore let the Angles in the center <i>aei</i>, and + <i>ouy</i> be equall: The bases <i>ai</i>, and <i>oy</i>, shall be + equall, by the <a href="#11_e_vij">11 e vij</a>: And the peripheries, + <i>ai</i>, and <i>oy</i>, by the <a href="#32_e_xv">32 e xv</a>, shall + likewise be equall. Therefore if the angles be unequall, the peripheries + likewise shall be <span class="correction" title="text reads `equall'" + >unequall</span>.</p> + + <p>The same shall also be true of the Angles in the Periphery. The + Converse in like manner is true: From whence followeth this + consectary:</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> +<p><!-- Page 205 --><span class="pagenum"><a name="page205"></a>[205]</span></p> + + <p><a name="8_e_xvj"></a> 8. <i>As the sectour is unto the sectour, so is + the angle unto the angle: And Contrariwise</i>.</p> + + <p>And thus much of the Sectour.</p> + + <p><a name="9_e_xvj"></a> 9. <i>A section is a segment of a circle within + cōprehended of one right line, which is termed the base of the + section</i>.</p> + + <div class="figcenter" style="width:53%;"> + <a href="images/226a.png"><img style="width:100%" src="images/226a.png" + alt="Sections." title="Sections." /></a> + </div> + <p>As here, <i>aei</i>, and <i>ouy</i>, and <i>srl</i>, are sections.</p> + + <div class="figright" style="width:18%;"> + <a href="images/226b.png"><img style="width:100%" src="images/226b.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p><a name="10_e_xvj"></a> 10. <i>A section is made up by finding of the + center</i>.</p> + + <p>The Invention of the center was manifest at the <a href="#7_e_xv">7 e + xv</a>: And so here thou seest a way to make up a Circle, by the <a + href="#8_e_xv">8 e xv</a>.</p> + + <p><a name="11_e_xvj"></a> 11 <i>The periphery of a section is divided + into two equall parts by a perpendicular dividing the base into two + equall parts. 20. p iij</i>.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/226c.png"><img style="width:100%" src="images/226c.png" + alt="Figure for demonstration 11." title="Figure for demonstration 11." /></a> + </div> + <p>Let the periphery of the section <i>aoe</i>, to be halfed or cut into + two equall parts. Let the base <i>ae</i>, be cut into two equall parts by + the pendicular <i>io</i>, which shall cut the periphery in <i>o</i>, I + say, that <i>ao</i>, and <i>oe</i>, are bisegments. For draw two right + lines <i>ao</i>, and <i>oe</i>, and thou shalt have two triangles + <i>aio</i>, and <i>eio</i>, equilaters by the <a href="#2_e_vij">2 e + vij</a>. Therefore the bases <i>ao</i>, and <i>oe</i>, are <!-- Page 206 + --><span class="pagenum"><a name="page206"></a>[206]</span>equall: And by + the <a href="#32_e_xv">32. e xv</a>. equall peripheries to the + subtenses.</p> + + <p>Here <i>Euclide</i> doth by congruency comprehende two peripheries in + one, and so doe we comprehend them.</p> + + <p><a name="12_e_xvj"></a> 12 <i>An angle in a section is an angle + comprehended of two right lines joyntly bounded in the base and in the + periphery joyntly bounded 7 d iij</i>.</p> + + <p>Or thus: An angle in the section, is an angle comprehended under two + right lines, having the same tearmes with the bases, and the termes with + the circumference: <i>H</i>. As <i>aoe</i>, in the former example.</p> + + <div class="figright" style="width:18%;"> + <a href="images/227a.png"><img style="width:100%" src="images/227a.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><a name="13_e_xvj"></a> 13 <i>The angles in the same section are + equall. 21. p iij</i>.</p> + + <p>Let the section be <i>eauo</i>, And in it the angles at <i>a</i>, + & <i>u</i>: These are equall, because, by the <a href="#5_e_xvj">5 + e</a>, they are the halfes of the angle <i>eyo</i>, in the center: Or + else they are equall, by the <a href="#7_e_xvj">7 e</a>, because they + insist upon the same periphery.</p> + + <p>Here it is certaine that angles in a section are indeed angles in a + periphery, and doe differ onely in base.</p> + + <p><a name="14_e_xvj"></a> 14 <i>The angles in opposite sections are + equall to two right angles. 22. p iij</i>.</p> + + <div class="figleft" style="width:19%;"> + <a href="images/227b.png"><img style="width:100%" src="images/227b.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>For here the opposite angles at <i>a</i>, and <i>i</i>, are equall to + the three angles of the triangle <i>eoi</i>, which are equall to two + right angles, by the <a href="#13_e_vj">13 e vj</a>. For first <i>i</i>, + is equall to it selfe: Then <i>a</i>, by parts is equall to the two + other. For <i>eai</i>, is equall to <i>eoi</i>, and <i>iao</i>, to + <i>oei</i>, by the <a href="#13_e_xvj">13 e</a>. Therefore the opposite + angles are equall to two right angles. <!-- Page 207 --><span + class="pagenum"><a name="page207"></a>[207]</span></p> + + <p>The reason or rate of a section is thus: The similitude doth + follow.</p> + + <p><a name="15_e_xvj"></a> 15 <i>If sections doe receive [or containe] + equall angles, they are alike è 10. d iij</i>.</p> + + <div class="figcenter" style="width:41%;"> + <a href="images/228a.png"><img style="width:100%" src="images/228a.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>As here <i>aei</i>, and <i>ouy</i>. The triangle here inscribed, + seeing they are equiangles, by the grant; they shall also be alike, by + the <a href="#12_e_vij">12 e vij</a>.</p> + + <p><a name="16_e_xvj"></a> 16 <i>If like sections be upon an equall base, + they are equall: and contrariwise. 23, 24. p iij</i>.</p> + + <div class="figcenter" style="width:47%;"> + <a href="images/228b.png"><img style="width:100%" src="images/228b.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p>In the first figure, let the base be the same. And if they shall be + said to unequall sections; and one of them greater than another, the + angle in that <i>aoe</i>, shall be lesse than the angle <i>aie</i>, in + the lesser section, by the <a href="#16_e_vj">16 e vj</a>. which + notwithstanding, by the grant, is equall.</p> + + <p>In the second figure, if one section be put upon another, it will + agree with it: Otherwise against the first part, like sections upon the + same base, should not be equall. But congruency is here sufficient.</p> + + <p>By the former two propositions, and by the <a href="#9_e_xv">9 e + xv</a>. one may finde a section like unto another assigned, or else from + a circle given to cut off one like unto it. <!-- Page 208 --><span + class="pagenum"><a name="page208"></a>[208]</span></p> + + <div class="figright" style="width:23%;"> + <a href="images/229a.png"><img style="width:100%" src="images/229a.png" + alt="Angle of a section." title="Angle of a section." /></a> + </div> + <p><a name="17_e_xvj"></a> 17 <i>Angle of a section is that which is + comprehended of the bounds of a section</i>.</p> + + <p>As here <i>eai</i>: And <i>eia</i>.</p> + + <p><a name="18_e_xvj"></a> 18 <i>A section is either a semicircle: or + that which is unequall to a semicircle</i>.</p> + + <p>A section is two fold, a semicircle, to wit, when it is cut by the + diameter: or unequall to a semicircle, when it is cut by a line lesser + than the diameter.</p> + + <p><a name="19_e_xvj"></a> 19 <i>A semicircle is the half section of a + circle</i>.</p> + + <p>Or it is that which is made the diameter.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/229b.png"><img style="width:100%" src="images/229b.png" + alt="Semicircle and sections." title="Semicircle and sections." /></a> + </div> + <p><a name="20_e_xvj"></a> 20 <i>A semicircle is comprehended of a + periphery and the diameter 18 d j</i>.</p> + + <p>As <i>aei</i>, is a semicircle: The other sections, as <i>oyu</i>, and + <i>oeu</i>, are unequall sections: that greater; this lesser.</p> + + <p><a name="21_e_xvj"></a> 21 <i>The angle in a semicircle is a right + angle: The angle of a semicircle is lesser than a rectilineall right + angle: But greater than any acute angle: The angle in a greater section + is lesser than a right angle: Of a greater, it is a greater. In a lesser + it is greater: Of a lesser, it is lesser, è 31. and 16. p iij</i>.</p> + + <p>Or thus: The angle in a semicircle is a right angle, the angle of a + semicircle is lesse than a right rightlined angle, but <!-- Page 209 + --><span class="pagenum"><a name="page209"></a>[209]</span>greater than + any acute angle: The angle in the greater section is lesse than a right + angle: the angle of the greater section is greater than a right angle: + the angle in the lesser section is greater than a right angle, the angle + of the lesser section, is lesser than a right angle: <i>H</i>.</p> + + <div class="figleft" style="width:21%;"> + <a href="images/230a.png"><img style="width:100%" src="images/230a.png" + alt="Figure for demonstration 21." title="Figure for demonstration 21." /></a> + </div> + <p>There are seven parts of this Element: The first is that <i>The angle + in a semicircle is a right angle</i>: as in <i>aei</i>: For if the ray + <i>oe</i>, be drawne, the angle <i>aei</i>, shall be divided into two + angles <i>aeo</i>, and <i>oei</i>, equall to the angles <i>eao</i>, and + <i>eio</i>, by the <a href="#17_e_vj">17 e vj</a>. Therefore seeing that + one angle is equall to the other two, it is a right angle, by the <a + href="#6_e_viij">6 e viij</a>. <i>Aristotle</i> saith that the angle in a + semicircle is a right angle, because it is the halfe of two right angles, + which is all one in effect.</p> + + <p>The second part, <i>That the angle of a semicircle is lesser than a + right angle</i>; is manifest out of that, because it is the part of a + right angle. For the angle of <span class="correction" title="text reads `these micircle'" + >the semicircle</span> <i>aie</i>, is part of the rectilineall right + angle <i>aiu</i>.</p> + + <div class="figright" style="width:21%;"> + <a href="images/230b.png"><img style="width:100%" src="images/230b.png" + alt="Figure for demonstration 21, fourth to seventh." title="Figure for demonstration 21, fourth to seventh." /></a> + </div> + <p>The third part, That it is greater than any acute angle; is manifest + out of the <a href="#23_e_xv">23. e xv</a>. For otherwise a tangent were + not on the same part one onely and no more.</p> + + <p>The fourth part is thus made manifest: The angle at <i>i</i>, in the + greater section <i>aei</i>, is lesser than a right angle; because it is + in the same triangle <i>aei</i>, which at <i>a</i>, is a right angle. And + if neither of the shankes be by the center, not withstanding an angle may + be made equall to the assigned in the same section.</p> + + <p>The fifth is thus: The angle of the greater section <i>eai</i>, is + greater than a right angle: because it containeth a right-angle. <!-- + Page 210 --><span class="pagenum"><a name="page210"></a>[210]</span></p> + + <p>The sixth is thus, the angle <i>aoe</i>, in a lesser section, is + greater than a right angle, by the <a href="#14_e_xvj">14 e xvj</a>. + Because that which is in the opposite section, is lesser than a right + angle.</p> + + <p>The seventh is thus. The angle <i>eao</i>, is lesser than a + right-angle: Because it is part of a right angle, to wit of the outter + angle, if <i>ia</i>, be drawne out at length.</p> + + <p>And thus much of the angles of a circle, of all which the most + effectuall and of greater power and use is the angle in a semicircle, and + therefore it is not without cause so often mentioned of <i>Aristotle</i>. + This Geometry therefore of <i>Aristotle</i>, let us somewhat more fully + open and declare. For from hence doe arise many things.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="22_e_xvj"></a> 22 <i>If two right lines jointly bounded with + the diameter of a circle, be jointly bounded in the periphery, they doe + make a right angle</i>.</p> + + <p>Or thus; If two right lines, having the same termes with the diameter, + be joyned together in one point, of the circomference, they make a right + angle. <i>H</i>.</p> + + <p>This corollary is drawne out of the first part of the former Element, + where it was said, that an angle in a semicircle is a right angle.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="23_e_xvj"></a> 23 <i>If an infinite right line be cut of a + periphery of an externall center, in a point assigned and contingent, and + the diameter be drawne from the contingent point, a right line from the + point assigned knitting it with the diameter, shall be perpendicular unto + the infinite line given</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/232a.png"><img style="width:100%" src="images/232a.png" + alt="Figure for demonstration 23." title="Figure for demonstration 23." /></a> + </div> + <p>Let the infinite right line be <i>ae</i>, from whose point <i>a</i>, a + perpendicular is to be raised.</p> + + <p>The right line <i>ae</i>, let it be cut by the periphery <i>aei</i>, + (whose center <i>o</i>, is out of the assigned <i>ae</i>,) and that in + the point <i>a</i>, and a contingent point, as in <i>e</i>: And from + <i>e</i>, let the <!-- Page 211 --><span class="pagenum"><a + name="page211"></a>[211]</span>diamiter be <i>eoi</i>: The right line + <i>ai</i>, from <i>a</i>, the point given, knitting it with the diameter + <i>ioe</i>, shall be perpendicular upon the infinite line <i>ae</i>; + Because with the said infinite, it maketh an angle in a semicircle.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="24_e_xvj"></a> 24 <i>If a right line from a point given, + making an acute angle with an infinite line, be made the diameter of a + periphery cutting the infinite, a right line from the point assigned + knitting the segment, shall be perpendicular upon the infinite + line</i>.</p> + + <p>As in the same example, having an externall point given, let a + perpendicular unto the infinite right line <i>ae</i> be sought: Let the + right line <i>ioe</i>, be made the diameter of the peripherie; and + withall let it make with the infinite right line given an acute angle in + <i>e</i>, from whose bisection for the center, let a periphery cut the + infinite, &c.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:22%;"> + <a href="images/232b.png"><img style="width:100%" src="images/232b.png" + alt="Figure for demonstration 25." title="Figure for demonstration 25." /></a> + </div> + <p><a name="25_e_xvj"></a> 25 <i>If of two right lines, the greater be + made the diameter of a circle, and the lesser jointly bounded with the + greater and inscribed, be knit together, the power of the greater shall + be more than the power of the lesser by the quadrate of that which + knitteth them both together. ad 13 p. x</i>.</p> + + <p>As in this example; The power of the diameter <i>ae</i>, is greater + than the power of <i>ei</i>, by the quadrate of <i>ai</i>. For the + triangle <i>aei</i>, shall be a rectangle; And by the <a + href="#9_e_xij">9 e xij.</a> <i>ae</i>, the greater shall be of <!-- Page + 212 --><span class="pagenum"><a name="page212"></a>[212]</span>power + equall to the shankes. Out of an angle in a semicircle Euclide raiseth + two notable fabrickes; to wit, the invention of a meane proportionall + betweene two lines given: And the Reason or rate in opposite sections. + The <i>genesis</i> or invention of the meane proportionall, of which we + heard at the <a href="#9_e_viij">9 e viij</a>. is thus:</p> + + <p><a name="26_e_xvj"></a> 26 <i>If a right line continued or continually + made of two right lines given, be made the diameter of a circle, the + perpendicular from the point of their continuation unto the periphery, + shall be the meane proportionall betweene the two lines given. 13 p + vj</i>.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/233.png"><img style="width:100%" src="images/233.png" + alt="Figure for demonstration 26." title="Figure for demonstration 26." /></a> + </div> + <p>As for example, let the assigned right lines be <i>ae</i>, and + <i>ei</i>, of the which <i>aei</i>, is continued. And let <i>eo</i>, be + perpendicular from the periphery <i>aoi</i>, unto <i>e</i>, the point of + continuation or joyning together of the lines given. This <i>eo</i>, say + I, shall be the meane proportionall: Because drawing the right lines + <i>ao</i>, and <i>io</i>, you shall make a rectangled triangle, seeing + that <i>aoi</i>, is an angle in a semicircle: And, by the <a + href="#9_e_viij">9 e viij</a>. <i>oe</i>, shall be proportionall betweene + <i>ae</i>, and <i>ei</i>.</p> + + <p>So if the side of a quadrate of 10. foote content, were sought; let + the sides 1. foote and 10. foote an oblong equall to that same quadrate, + be continued; the meane proportionall shall be the side of the quadrate, + that is, the power of it shall be 10. foote. The reason of the angles in + opposite sections doth follow.</p> + + <div class="figright" style="width:26%;"> + <a href="images/234a.png"><img style="width:100%" src="images/234a.png" + alt="Figure for demonstration 27." title="Figure for demonstration 27." /></a> + </div> + <p><a name="27_e_xvj"></a> 27 <i>The angles in opposite sections are + equall in the alterne angles made of the secant and touch line. 32. p + iij</i>.</p> + + <p>If the sections be equall or alike, then are they the sections of a + semicircle, and the matter is plaine by the <a href="#21_e_xvj">21 e</a>. + But if they be unequall or unlike the argument of demonstration <!-- Page + 213 --><span class="pagenum"><a name="page213"></a>[213]</span>is indeed + fetch'd from the angle in a semicircle, but by the equall or like angle + of the tangent and end of the diameter.</p> + + <p>As let the unequall sections be <i>eio</i>, and <i>eao</i>: the + tangent let it be <i>uey</i>: And the angles in the opposite sections, + <i>eao</i>, and <i>eio</i>. I say they are equall in the alterne angles + of the secant and touch line <i>oey</i>, and <i>oeu</i>. First that which + is at <i>a</i>, is equall to the alterne <i>oey</i>: Because also three + angles <i>oey</i>, <i>oea</i>, and <i>aeu</i>, are equall to two right + angles, by the <a href="#14_e_v">14 e v</a>. Unto which also are equall + the three angles in the triangle <i>aeo</i>, by the <a href="#13_e_vj">13 + e vj</a>. From three equals take away the two right angles <i>aue</i>, + and <i>aoe</i>: (For <i>aoe</i>, is a right angle, by the <a + href="#21_e_xvj">21 e</a>; because it is in a semicircle:) Take away also + the common angle <i>aeo</i>: And the remainders <i>eao</i>, and + <i>oey</i>, alterne angles, shall be equall.</p> + + <div class="figright" style="width:19%;"> + <a href="images/234b.png"><img style="width:100%" src="images/234b.png" + alt="Figure for demonstration 27." title="Figure for demonstration 27." /></a> + </div> + <p>Secondarily, the angles at <i>a</i>, and <i>i</i>, are equall to two + right angles, by the <a href="#14_e_xvj">14, e</a>: To these are equall + both <i>oey</i>, and <i>oeu</i>. But <i>eao</i>, is equall to the alterne + <i>oey</i>. Therefore that which is at <i>i</i>, is equall to, the other + alterne <i>oeu</i>. Neither is it any matter, whether the angle at + <i>a</i>, be at the diameter or not: For that is onely assumed for + demonstrations sake: For wheresoever it is, it is equall, to wit, in the + same section. And from hence is the making of a like section, by giving a + right line to be subtended.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="28_e_xvj"></a> 28 <i>If at the end of a right line given a + right lined angle be made equall to an angle given, and from the <!-- + Page 214 --><span class="pagenum"><a name="page214"></a>[214]</span>toppe + of the angle now made, a perpendicular unto the other side do meete with + a perpendicular drawn from the middest of the line given, the meeting + shall be the center of the circle described by the equalled angle, in + whose opposite section the angle upon the line given shall be made equall + to the assigned è 33 p iij</i>.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:64%;"> + <a href="images/235.png"><img style="width:100%" src="images/235.png" + alt="Figure for demonstration 28." title="Figure for demonstration 28." /></a> + </div> + <p>This you may make triall of in the three kindes of angles, all wayes + by the same argument: as here the angle given is <i>a</i>: The right line + given <i>ei</i>: at the end <i>e</i>, the equalled angle, <i>ieo</i>: The + perpendicular to the side <i>eo</i>, let it be <i>eu</i>: But from the + middest of the line given let it be <i>yu</i>. Here <i>u</i>, shall be + the center desired. And from hence one may make a section upon a right + line given, which shall receive a rectilineall angle equall to an angle + assigned.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="29_e_xvj"></a> 29 <i>If the angle of the secant and touch + line be equall to an assigned rectilineall angle, the angle in the + opposite section shall likewise be equall to the same. 34. p iij</i>.</p> + + <p>As in this figure underneath. And from hence one may from a circle + given cut off a section, in which there is an <!-- Page 215 --><span + class="pagenum"><a name="page215"></a>[215]</span>angle equall to the + assigned. As let the angle given be <i>a</i>: And the circle <i>eio</i>. + Thou must make at the point <i>e</i>, of the secant <i>eo</i>, and the + tangent <i>yu</i>, an angle equall to the assigned, by the <a + href="#11_e_iij">11 e iij</a>. such as here is <i>oeu</i>: Then the + section <i>oei</i>, shall containe an angle equall to the assigned.</p> + + <div class="figcenter" style="width:19%;"> + <a href="images/236.png"><img style="width:100%" src="images/236.png" + alt="Figure for demonstration 29." title="Figure for demonstration 29." /></a> + </div> +<hr class="full" /> + +<h2>Of <i>Geometry</i> the seventeenth Booke, +Of the Adscription of a Circle +and Triangle.</h2> + + <p>Hitherto we have spoken of the Geometry of Rectilineall plaines, and + of a circle: Now followeth the Adscription of both: This was generally + defined in the first book <a href="#12_e_j">12 e</a>. Now the periphery + of a circle is the bound therof. Therefore a rectilineall is inscribed + into a circle, when the periphery doth touch the angles of it 3 d iiij. + It is circumscribed when it is touched of every side by the periphery; 4 + d iij.</p> + + <div class="figright" style="width:22%;"> + <a href="images/237a.png"><img style="width:100%" src="images/237a.png" + alt="Figure for demonstration 1." title="Figure for demonstration 1." /></a> + </div> + <p><a name="1_e_xvij"></a> 1. <i>If rectilineall ascribed unto a circle + be an equilater, it is equiangle</i>.</p> + + <p>Of the inscript it is manifest; And that of a Triangle by it selfe: + Because if it be equilater, it is equiangle, by the <a href="#19_e_vj">19 + e vj</a>. But in a Triangulate the matter is to be prooved by + demonstration. As here, if the inscripts <i>ou</i>, and <i>sy</i>, be + equall, then doe they subtend equall peripheries, by the 32 <!-- Page 216 + --><span class="pagenum"><a name="page216"></a>[216]</span>e xv. Then if + you doe omit the periphery in the middest betweene them both, as here + <i>uy</i>, and shalt adde <i>oies</i> the remainder to each of them, the + whole <i>oiesy</i>, subtended to the angle at <i>u</i>: And <i>uoies</i>, + subtended to the angle at <i>y</i>, shall be equall. Therefore the angles + in the periphery, insisting upon equall peripheries are equall.</p> + + <p>Of the circumscript it is likewise true, if the circumscript be + understood to be a circle. For the perpendiculars from the center + <i>a</i>, unto the sides of the circumscript, by the <a href="#9_e_xij">9 + e xij</a>, shal make triangles on each side equilaters, & equiangls, + by drawing the semidiameters unto the corners, as in the same + exāple.</p> + + <p><a name="2_e_xvij"></a> 2. <i>It is equall to a triangle of equall + base to the perimeter, but of heighth to the perpendicular from the + center to the side</i>.</p> + +<p><!-- Page 217 --><span class="pagenum"><a name="page217"></a>[217]</span></p> + + <p>As here is manifest, by the <a href="#8_e_vij">8 e vij</a>. For there + are in one triangle, three triangles of equall heighth.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:59%;"> + <a href="images/237b.png"><img style="width:100%" src="images/237b.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p>The same will fall out in a Triangulate, as here in a quadrate: For + here shal be made foure triangles of equall height.</p> + + <p>Lastly every equilater rectilineall ascribed to a circle, shall be + equall to a triangle, of base equall to the perimeter of the adscript. + Because the perimeter conteineth the bases of the triangles, into the + which the rectilineall is resolved.</p> + + <p><a name="3_e_xvij"></a> 3. <i>Like rectilinealls inscribed into + circles, are one to another as the quadrates of their diameters, 1 p. + xij</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/238.png"><img style="width:100%" src="images/238.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p>Because by the <a href="#1_e_vj">1 e vj</a>, like plains have a + doubled reasó of their homologall sides. But in rectilineals inscribed + the diameters are the homologall sides, or they are proportionall to + their homologall sides. As let the like rectangled triangles be + <i>aei</i>, and <i>ouy</i>; Here because <i>ae</i> and <i>ou</i>, are the + diameters, the matter appeareth to be plaine at the first sight. But in + the Obliquangled triangles, <i>sei</i>, and <i>ruy</i>, alike also, the + diameters are proportionall to their homologall sides, to wit, <i>ei</i> + and <i>uy</i>. For by the grant, as <i>se</i> is to <i>ru</i>: so is + <i>ei</i> to <i>uy</i>, And therefore, by the former, <span + class="correction" title="text is in italics, wrongly">as</span> the + diameter <i>ea</i> and <i>uo</i>.</p> + + <p>In like Triangulates, seeing by the <a href="#4_e_x">4 e x</a>, they + may be resolved into like triangles, the same will fall out.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> +<p><!-- Page 218 --><span class="pagenum"><a name="page218"></a>[218]</span></p> + + <p><a name="4_e_xvij"></a> 4. <i>If it be as the diameter of the circle + is unto the side of rectilineall inscribed, so the diameter of the second + circle be unto the side of the second rectilineall inscribed, and the + severall triangles of the inscripts be alike and likely situate, the + rectilinealls inscribed shall be alike and likely situate</i>.</p> + + <p>This <i>Euclide</i> did thus assume at the 2 p xij, and indeed as it + seemeth out of the 18 p vj. Both which are conteined in the <a + href="#23_e_iiij">23 e iiij</a>. And therefore we also have assumed + it.</p> + + <p>Adscription of a Circle is with any triangle: But with a triangulate + it is with that onely which is ordinate: And indeed adscription of a + Circle is common <i>to all</i>.</p> + + <p><a name="5_e_xvij"></a> 5. <i>If two right lines doe cut into two + equall parts two angles of an assigned rectilineall, the circle of the + ray from their meeting perpendicular unto the side, shall be inscribed + unto the assigned rectilineall. 4 and 8. p. iiij</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/239.png"><img style="width:100%" src="images/239.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p>As in the Triangle <i>aei</i>, let the right lines <i>ao</i>, and + <i>eu</i>, halfe the angles <i>a</i> and <i>e</i>: And from <i>y</i>, + their meeting, let the perpendiculars unto the sides be <i>yo</i>, + <i>yu</i>, <i>ys</i>; I say that the center <i>y</i>, with the ray + <i>yo</i>, or <i>ya</i>, or <i>ys</i>, is the circle inscribed, by the <a + href="#17_e_xv">17 e xv</a>. Because the halfing lines with the + perpendiculars shall make equilater triangles, by the <a + href="#2_e_vij">2 e vij</a>. And therefore the three perpendiculars, + which are the bases of the equilaters, shall be equall. <!-- Page 219 + --><span class="pagenum"><a name="page219"></a>[219]</span></p> + + <p>The same argument shall serve in a Triangulate.</p> + + <p><a name="6_e_xvij"></a> 6. <i>If two right lines do right anglewise + cut into two equall parts two sides of an assigned rectilineall, the + circle of the ray from their meeting unto the angle, shall be + circumscribed unto the assigned rectilineall. 5 p iiij</i>.</p> + + <p>As in former figures. The demonstration is the same with the former. + For the three rayes, by the <a href="#2_e_vij">2 e vij</a>, are equall: + And the meeting of them, by the <a href="#17_e_x">17 e x</a>, is the + center.</p> + + <p>And thus is the common adscription of a circle: The adscription of a + rectilineall followeth, and first of a Triangle.</p> + + <div class="figright" style="width:26%;"> + <a href="images/240.png"><img style="width:100%" src="images/240.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p><a name="7_e_xvij"></a> 7. <i>If two inscripts, from the touch point + of a right line and a periphery, doe make two angles on each side equall + to two angles of the triangle assigned be knit together, they shall + inscribe a triangle into the circle given, equiangular to the triangle + given è 2 p iiij</i>.</p> + + <p>Let the Triangle <i>aei</i> be given: And the circle, <i>o</i>, into + which a Triangle equiangular to the triangle given, is to be inscribed. + Therefore let the right line <i>uys</i>, touch the periphery <i>yrl</i>: + And from the touch <i>y</i>, let the inscripts <i>yr</i>, and <i>yl</i>, + make with the tangent two angles <i>uyr</i>, and <i>syl</i>, equall to + the assigned angles <i>aei</i>, and <i>aie</i>: And let them be knit + together with the right line <i>rl</i>: They shall by the <a + href="#27_e_xvj"><span class="correction" title="text reads `19 e xvj'" + >27 e xvj</span></a>, make the angle of the alterne segments equall to + the angles <span class="correction" title="text reads `url, and yrl'" + ><i>uyr</i>, and <i>syl</i></span>. Therefore by the <a href="#4_e_vij">4 + e vij</a> seeing that two are equall, the other must needs be equall to + the remainder.</p> + + <p>The circumscription here is also speciall. <!-- Page 220 --><span + class="pagenum"><a name="page220"></a>[220]</span></p> + + <p><a name="8_e_xvij"></a> 8 <i>If two angles in the center of a circle + given, be equall at a common ray to the outter angles of a triangle + given, right lines touching a periphery in the shankes of the angles, + shall circumscribe a triangle about the circle given like to the triangle + given. 3 p iiij</i>.</p> + + <div class="figright" style="width:26%;"> + <a href="images/241.png"><img style="width:100%" src="images/241.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>Let there be a Triangle, and in it the outter angles <i>aei</i>, and + <i>aou</i>: The Circle let it be <i>ysr</i>; And in the center <i>l</i>, + let the angles <i>ylr</i>, and <i>slr</i>; at the common side <i>lr</i>, + bee made equall to the said outter angles <i>aei</i>, and <i>aou</i>. I + say the angles of the circumscribed triangle, are equall to the angles of + the triangle given. For the foure inner angles of the quadrangle + <i>ylrm</i>, are equall to the foure right angles, by the <a + href="#6_e_x">6 e x</a>: And two of them, to wit, at <i>y</i> and + <i>r</i>, are right angles, by the construction: For they are made by the + secant and touch line, from the touch point by the center, by the <a + href="#20_e_xv">20 e xv</a>. Therefore the remainders at <i>l</i> and + <i>m</i>, are equall to two right angles: To which two <i>aei</i> and + <i>aeo</i> are equall. But the angle at <i>l</i>, is equall to the + outter: Therefore the remainder <i>m</i>, is equall to <i>aeo</i>. The + same shall be sayd of the angles <i>aoe</i>, and <i>aou</i>. Therefore + two being equall, the rest at <i>a</i> and <i>i</i>, shall be equall.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="9_e_xvij"></a> 9. <i>If a triangle be a rectangle, an + obtusangle, an acute angle, the center of the circumscribed triangle is + in the side, out of the sides, and within the sides: And contrariwise. 5 + e iiij.</i> <!-- Page 221 --><span class="pagenum"><a + name="page221"></a>[221]</span></p> + + <div class="figcenter" style="width:60%;"> + <a href="images/242.png"><img style="width:100%" src="images/242.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p>As, thou seest in these three figures, underneath, the center + <i>a</i>.</p> + +<hr class="full" /> + +<h2>Of <i>Geometry</i>, the eighteenth Booke, +Of the adscription of a +Triangulate.</h2> + + <p>Such is the Adscription of a triangle: The adscription of an ordinate + triangulate is now to be taught. And first the common adscription, and + yet out of the former adscription, after this manner.</p> + + <p><a name="1_e_xviij"></a> 1. <i>If right lines doe touch a periphery in + the angles of the inscript ordinate triangulate, they shall onto a circle + cirumscribe a triangulate homogeneall to the inscribed + triangulate</i>.</p> + + <p>The examples shall be laid downe according as the species or severall + kindes doe come in order. The speciall inscription therefore shall first + be taught, and that by one side, which reiterated, as oft as need shall + require, may fill up the whole periphery. For that <i>Euclide</i> did in + the quindecangle <!-- Page 222 --><span class="pagenum"><a + name="page222"></a>[222]</span>one of the kindes, we will doe it in all + the rest.</p> + + <div class="figright" style="width:19%;"> + <a href="images/243.png"><img style="width:100%" src="images/243.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p><a name="2_e_xviij"></a> 2. <i>If the diameters doe cut one another + right-angle-wise, a right line subtended or drawne against the right + angle, shall be the side of the quadrate. è 6 p iiij</i>.</p> + + <p>As here. For the shankes of the angle are the raies whose diameters + knit together shall make foure rectangled triangles, equall in shankes: + And by the <a href="#2_e_vij">2 e vij</a>, equall in bases. Therefore + they they shall inscribe a quadrate.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="3_e_xviij"></a> 3. <i>A quadrate inscribed is the halfe of + that which is circumscribed</i>.</p> + + <p>Because the side of the circumscribed (which here is equall to the + diameter of the circle) is of power double, to the side of the inscript, + by the <a href="#9_e_xij">9 e xij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="4_e_xviij"></a> 4. <i>It is greater than the halfe of the + circumscribed Circle</i>.</p> + + <p>Because the circumscribed quadrate, which is his double, is greater + than the whole circle.</p> + + <p>For the inscribing or other multangled odde-sided figures we must + needes use the helpe of a triangle, each of whose angles at the base is + manifold to the other: In a <span class="correction" title="text reads `Quinguangle'" + >Quinquangle</span> first, that which is double unto the remainder, which + is thus found.</p> + + <div class="figright" style="width:21%;"> + <a href="images/244.png"><img style="width:100%" src="images/244.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p><a name="5_e_xviij"></a> 5. <i>If a right line be cut proportionally, + the base of that triangle whose shankes shall be equall to the whole line + cut, and the base to the greater segment of the same, shall have each of + the angles at base double to the <!-- Page 223 --><span + class="pagenum"><a name="page223"></a>[223]</span>remainder: And the base + shall be the side of the quinquangle inscribed with the triangle into a + circle. 10, and 11. p iiij</i>.</p> + + <p>Here first thou shalt take for the fabricke or making of the Triangle, + for the ray the right line <i>ae</i> by the <a href="#3_e_xiiij">3 e + xiiij</a>, cut proportionally in <i>o</i>: A circle also shalt thou make + upon the center <i>a</i>, with the ray <i>ae</i>: And then shalt thou by + the <a href="#6_e_xv">6 e xv</a>, inscribe a right line equall to the + greater segment: And shalt knit the same inscript with the whole line cut + with another right line. This triangle shall be your desire. For by the + <a href="#17_e_vj">17 e vj</a>, the angles at the base <i>ei</i> are + equall, so that looke whatsoever is prooved of the one, is by and by also + prooved of the other. Then let <i>oi</i> be drawne; And a Circle, by the + <a href="#8_e_xvij">8 e xvij</a>, circumscribed about the triangle + <i>aoi</i>. This circle the right line <i>ei</i>, shall touch, by the <a + href="#27_e_xv">27 e xv</a>. Because, by the grant, the right line + <i>ae</i>, is cut proportionally, therefore the Oblong of the secant and + outter segment, is equall to the quadrate of the greater segment, to + which by the grant, the base <i>ei</i>, is equall. Here therefore the + angle <i>aie</i> is the double of the angle at <i>a</i>: because it is + equall to the angles <i>aio</i>, and <i>oai</i>, which are equall + betweene themselves. For by the <a href="#27_e_xvj">27 e xvj</a> it is + equall to the angle <i>oai</i> in the alterne segment. And the remainder + <i>aio</i>, is equall to it selfe. Therefore also the angle <i>aei</i>, + is equall to the same two angles, because it is equall to the angle + <i>aie</i>. But the outter angle <i>eoi</i>, is equall to the same two, + by the <a href="#15_e_vj">15 e vj</a>. Therefore the angles <i>ioe</i> + and <i>oei</i> (because they are equall to the same) they are equall + betweene themselves. Wherefore by the <a href="#17_e_vj">17 e vj</a>, the + sides <i>oi</i> and <i>ei</i> are equall. And there also <i>ao</i> and + <i>oi</i>: And the angles <i>oai</i> & <span class="correction" + title="text reads `oai'"><i>oia</i></span> are equall by the <a + href="#17_e_vj">17 e vj</a>. Wherefore seeing <!-- Page 224 --><span + class="pagenum"><a name="page224"></a>[224]</span>that to both the angle + <i>aie</i> is equall, it shall be the double of <span class="correction" + title="text reads `ther'">either</span> of the equalls.</p> + + <div class="figright" style="width:24%;"> + <a href="images/245.png"><img style="width:100%" src="images/245.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p>But the base <i>ei</i>, is the side of the equilater quinquangle. For + if two right lines halfing both the angles of a triangle which is the + double of the remainder, be knit together with a right line, both one to + another, and with the angles, shall inscribe unto a circle an equilater + triangle, whose one side shall be the base it selfe: As here seeing the + angles <i>eoa</i>, <i>eoi</i>, <i>uio</i>, <i>uia</i>, <i>iao</i>, are + equal in the periphery, the peripheries, by the <a href="#7_e_xvj">7 e, + xvj</a>. subtending them are equall: And therefore, by the <a + href="#32_e_xv">32 e, xv</a>. the subtenses <i>ae</i>, <i>ei</i>, + <i>io</i>, <i>ou</i>, <i>ua</i>, are also equall. Now of those five, one + is <i>ae</i>. Therefore a right line proportionall cut, doth thus make + the adscription of a quinquangle: And from thence againe is afforded a + line proportionally cut.</p> + + <p><a name="6_e_xviij"></a> 6 <i>If two right lines doe subtend on each + side two angles of an inscript quinquangle, they are cut proportionally, + and the greater segments are the sides of the said inscript è 8, p + xiij</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/246a.png"><img style="width:100%" src="images/246a.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>As here, Let <i>ai</i>, and <i>eu</i>, subtending the angles on each + side <i>aei</i>, and <i>eau</i>: I say, That they are proportionally cut + in the point <i>s</i>: And the greater segments <i>si</i>, and <i>su</i>, + are equall to <i>ae</i>, the side of the quinquangle. For here two + triangles are equiangles: First <i>aei</i>, and <i>uae</i>, are equall by + the grant, and by the <a href="#2_e_vij">2 e, vij</a>. Therefore the + angles <i>aie</i>, and <i>aes</i>, are equall. Then <i>aei</i>, and + <i>ase</i>, are equall: Because the <!-- Page 225 --><span + class="pagenum"><a name="page225"></a>[225]</span>angle at <i>a</i>, is + common to both: Therefore the other is equall to the remainder, by the <a + href="#4_e_vij">4 e, 7</a>. Now, by the <a href="#12_e_vij">12. e, + vij.</a> as <i>ia</i>, is unto <i>ae</i>, that is, as by and by shall + appeare, unto <i>is</i>: so is <i>ea</i>, unto <i>as</i>: Therefore, by + the <a href="#1_e_xiiij">1 e, xiiij</a>. <i>ia</i>, is cut proportionally + in <i>s</i>. But the side <i>ea</i>, is equall to <i>is</i>: Because both + of them is equall to the side <i>ei</i>, that by the grant, this by the + <a href="#17_e_vj">17. e, vj</a>. For the angles at the base, <i>ise</i>, + and <i>ies</i>, are equall, as being indeed the doubles of the same. For + <i>ise</i>, by the <a href="#16_e_vj">16. e vj</a>. is equall to the two + inner, which are equall to the angle at <i>u</i>, by the <a + href="#17_e_vj">17 e vj</a>. and by the former conclusion. Therefore it + is the double of the angles <i>aes</i>: Whose double also is the angle + <i>uei</i>, by the <a href="#7_e_xvj">7 e. xvj</a>. insisting indeede + upon a double periphery.</p> + + <p>And from hence the fabricke or construction of an ordinate quinquangle + upon a right line given, is manifest.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:26%;"> + <a href="images/246b.png"><img style="width:100%" src="images/246b.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p><a name="7_e_xviij"></a> 7 <i>If a right line given, cut + proportionall, be continued at each end with the greater segment, and + sixe peripheries at the distance of the line given shall meete, two on + each side from the ends of the line given and the continued, two others + from their meetings, right lines drawne from their meetings, & the + ends of the assigned shall make an ordinate quinquangle upon the + assigned</i>.</p> + + <p>The example is thus.</p> + + <p><a name="8_e_xviij"></a> 8 <i>If the diameter of a circle + circumscribed about a quinquangle be rationall, it is irrationall unto + the side of the inscribed quinquangle, è 11. p xiij.</i> <!-- Page 226 + --><span class="pagenum"><a name="page226"></a>[226]</span></p> + + <p>So before the segments of a right line proportionally cut were + irrationall.</p> + + <p>The other triangulates hereafter multiplied from the ternary, + quaternary, or quinary of the sides, may be inscribed into a circle by an + inscript triangle, quadrate, or quinquangle. Therefore by a triangle + there may be inscribed a triangulate of 6. 12, 24, <span + class="correction" title="text reads `46'">48</span>, angles: By a + quadrate, a triangulate of 8. 16, 32, 64, angles. By a quinquangle, a + triangulate of 10, 20, 40, 80. angles, &c.</p> + + <p><a name="9_e_xviij"></a> 9 <i>The ray of a circle is the side of the + inscript sexangle. è 15 p iiij</i>.</p> + + <div class="figright" style="width:25%;"> + <a href="images/247.png"><img style="width:100%" src="images/247.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>A sexangle is inscribed by an inscript equilaterall triangle, by + halfing of the three angles of the said triangle: But it is done more + speedily by the ray or semidiameter of the circle, sixe times continually + inscribed. As in the circle given, let the diameter be <i>ae</i>; And + upon the center <i>o</i>, with the ray <i>ie</i>, let the periphery + <i>uio</i>, be described: And from the points <i>o</i> and <i>u</i>, let + the diameters be <i>oy</i>, and <i>us</i>; These knit both one with + another, and also with the diameter <i>ae</i> shall inscribe an + equilaterall sexangle into the circle given, whose side shal be equal to + the ray of the same circle. As <i>eu</i>, is equal to <i>ui</i>, because + they both equall to the same <i>ie</i>, by the <a href="#29_e_iiij">29 e, + iiij</a>. There fore <i>eiu</i>, is an equilater triangle: And likewise + <i>eio</i>, is an equilater. The angles also in the center are ⅔ + of one rightangle: And therefore they are equall. And by the <a + href="#14_e_v">14. e v</a>, the angle <i>sio</i>, is ⅓. of two + rightangles: And by the <a href="#15_e_v">15. e v</a>. the angles at the + toppe are also equall. Wherefore sixe are equall: And therefore, by the + <a href="#7_e_xvj">7 e xvj</a>. and <a href="#32_e_xv">32. e, xv</a>, all + the bases are equall, both betweene themselves, and as was even now made + manifest, to the ray of the circle given. Therefore the sexangle inscript + by the ray of a circle is an <!-- Page 227 --><span class="pagenum"><a + name="page227"></a>[227]</span>equilater; And by the <a + href="#1_e_xvij">1 e xvij</a>. equiangled.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="10_e_xviij"></a> 10 <i>Three ordinate sexangles doe fill up a + place</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/248a.png"><img style="width:100%" src="images/248a.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p>As here. For they are sixe equilater triangles, if you shal resolve + the sexangles into sixe triangls: Or els because the angle of an ordinate + sexangle is as much as one right angle and ⅓. of a right + angle.</p> + + <p>Furthermore also no one figure amongst the plaines doth fill up a + place. A Quinquangle doth not: For three angles a quinquangle may make + only 3.3/5 angles which is too little. And foure would make 4.4/5 which + is as much too great. The angles of a septangle would make onely two + rightangles, and 6/7 of one: Three would make 3, and 9/7, that is in the + whole 4.2/7, which is too much, &c. to him that by induction shall + thus make triall, it will appeare, That a plaine place may be filled up + by three sorts of ordinate plaines onely.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="11_e_xviij"></a> 11 <i>If right lines from one angle of an + inscript sexangle unto the third angle on each side be knit together, + they shall inscribe an equilater triangle into the circle given</i>.</p> + + <div class="figleft" style="width:19%;"> + <a href="images/248b.png"><img style="width:100%" src="images/248b.png" + alt="Figure for demonstration 11." title="Figure for demonstration 11." /></a> + </div> + <p>As here; Because the sides shall be subtended to equall peripheries: + Therefore by the <a href="#32_e_xv">32 e xv</a>. they shall be equall + betweene themselves: And againe, on the contrary, by such a like + triangle, by halfing the angles, a sexangle is inscribed.</p> + + <p><a name="12_e_xviij"></a> 12 <i>The side of an inscribed equilater + triangle hath a <!-- Page 228 --><span class="pagenum"><a + name="page228"></a>[228]</span>treble power, unto the ray of the circle + 12. p xiij</i>.</p> + + <div class="figright" style="width:19%;"> + <a href="images/249a.png"><img style="width:100%" src="images/249a.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>As here, with <i>ae</i>, one side of the triangle <i>aei</i>, two + third parts of the halfe periphery are imployed: For with one side one + third of the whole <i>eu</i>, is imployed: Therefore <i>eu</i>, is the + other third part, that is, the sixth part of the whole periphery. + Therefore the inscript <i>eu</i>, is the ray of the circle, by the <a + href="#9_e_xviij">9 e</a>. Now the power of the diameter <i>aou</i>, by + the <a href="#14_e_xij">14 e xij</a>. is foure times so much as is the + power of the ray, that is, of <i>eu</i>: And by <a href="#21_e_xvj">21. e + xvj</a>, and <a href="#9_e_xij">9 e xij</a>, <i>ae</i>, and <i>eu</i>, + are of the same power; take away <i>eu</i>, and the side <i>ae</i>, shall + be of treble power unto the ray.</p> + + <p><a name="13_e_xviij"></a> 13 <i>If the side of a sexangle be cut + proportionally, the greater segment shall be the side of the + decangle</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/249b.png"><img style="width:100%" src="images/249b.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p><i>Pappus lib. 5. ca. 24.</i> & <i>Campanus ad 3 p xiiij.</i> Let + the ray <i>ao</i>, or side of the sexangle be cut proportionally, by the + <a href="#3_e_xiiij">3 e xiiij</a>: And let <i>ae</i>, be equall to the + greater segment. I say that <i>ae</i>, is the side of the decangle. For + if it be moreover continued with the whole ray unto <i>i</i>, the whole + <i>aei</i>, shall <span class="correction" title="text reads `be by' (duplicated be)" + >by</span> the <a href="#4_e_xiiij">4 e xiiij</a>. be cut proportionally: + and the greater segment <i>ei</i>, shal be the same ray. For the if the + right line <i>iea</i>, be cut proportionally, it shall be as <i>ia</i>, + is unto <i>ie</i>, that is to <i>oa</i>, to wit, unto the ray: so + <i>ao</i>, shal be unto <i>ae</i>. Therefore, by the <a + href="#15_e_vij">15. e vij</a>. the triangles <i>iao</i>, and <i>oae</i>, + are equiangles: And the angle <i>aoe</i>, is equall to the angle + <i>oia</i>. But the angle <i>uoe</i>, is foure times as great as the + angle <i>aoe</i>: for it is equall to the two inner at <i>a</i>, and + <i>e</i>, by the <a href="#15_e_vj">15 e vj</a>: which are equall between + themselves, by the <a href="#10_e_v"><span class="correction" title="text reads `9 e v'" + >10 e v</span></a>. and by the <a href="#17_e_vj">17 e vj</a>. And + therefore it is the double of <!-- Page 249 --><span class="pagenum"><a + name="pageastx249"></a>[249*]</span><i>aeo</i>, which is the double, for + the same cause, of <i>aio</i>, equall to the same <i>aoe</i>. Therefore + <i>uoe</i>, is the quadruple of the said <i>aoe</i>. Therefore <span + class="correction" title="text reads `ae'"><i>ue</i></span>, is the + quadruple of the periphery <i>ea</i>. Therefore the whole <i>uea</i>, is + the quintuple of the same <i>ea</i>: And the whole periphery is decuple + unto it. And the subtense <i>ae</i>, is the side of the decangle.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="14_e_xviij"></a> 14 <i>If a decangle and a sexangle be + inscribed in the same circle, a right line continued and made of both + sides, shall be cut proportionally, and the greater segment shall be the + side of a sexangle; and if the greater segment of a right line cut + proportionally be the side of an hexagon, the rest shall be the side of a + decagon. 9. p xiij</i>.</p> + + <p>The comparison of the decangle and the sexangle with the quinangle + followeth.</p> + + <p><a name="15_e_xviij"></a> 15 <i>If a decangle, a sexangle, and a + pentangle be inscribed into the same circle the side of the pentangle + shall in power countervaile the sides of the others. And if a right line + inscribed do countervaile the sides of the sexangle and decangle, it is + the side of the pentangle. 10. p xiiij</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/250.png"><img style="width:100%" src="images/250.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>Let the side of the inscribed quinquangle be <i>ae</i>: of the + sexangle, <i>ei</i>: Of the decangle <i>ao</i>. I say, the side + <i>ae</i>, doth in power countervaile the rest. For let there be two + perpēdiculars: The first <i>io</i>, the second <i>iu</i>, cutting + the sides of the quinquangle and decangle into halves: And the meeting of + the second perpendicular with the side of the quinquangle let it be + <i>y</i>. The syllogisme of the demonstration is this: The oblongs of the + side of the quinquangle, and the segments of the same, are equall to the + quadrates of the other sides. But the quadrate of the same whole side, is + equall to the oblongs of the whole, and the segments, by the <a + href="#3_e_xiij">3 e, xiij</a>. Therefore it is equall to the quadrates + of the other sides. <!-- Page 230 --><span class="pagenum"><a + name="page230"></a>[230]</span></p> + + <p>Let the proportion of this syllogisme be demonstrated: For this part + onely remaineth doubtfull. Therefore two triangles, <i>aei</i>, and + <i>yei</i>, are equiangles, having one common angle at <i>e</i>: And also + two equall ones <i>aei</i>, and <i>eiy</i>, the halfes, to wit, of the + same <i>eis</i>: Because that is, by the <a href="#17_e_vj">17 e, vj</a>: + one of the two equalls, unto the which <i>eis</i>, the out angle, is + equall, by the <a href="#15_e_vj">15 e. vj</a>. And this doth insist upon + a halfe periphery. For the halfe periphery <i>als</i>, is equall to the + halfe periphery <i>ars</i>: and also <i>al</i>, is equall to <i>ar</i>. + Therefore the remnant <i>ls</i>, is equall to the remnant <i>rs</i>: And + the whole <i>rl</i>, is the double of the same <i>rs</i>: And therefore + <i>er</i>, is the double of <i>eo</i>: And <i>rs</i>, the double of + <i>ou</i>. For the bisegments are manifest by the <a href="#10_e_xv">10 + e, xv</a>. and the <a href="#11_e_xvj">11 e, xvj</a>. Therefore the + periphery <i>ers</i>, is the double of the periphery <i>eou</i>: And + therefore the angle <i>eiu</i>, is the halfe of the angle <i>eis</i>, by + the <a href="#7_e_xvj">7 e, xvj</a>. Therefore two angles of two + triangles are equall: Wherefore the remainder, by the <a + href="#4_e_vij">4 e vij</a>, is equall to the remainder. Wherefore by the + <a href="#12_e_vij">12 e, vij</a>, as the side <i>ae</i>, is to + <i>ei</i>: so is <i>ei</i>, to <i>ey</i>. Therefore by the <a + href="#8_e_xij">8 e xij</a>, the oblong of the extreames is equall to the + quadrate of the meane.</p> + + <p>Now let <i>oy</i>, be knit together with a straight: Here againe the + two triangles <i>aoe</i>, and <i>aoy</i>, are equiangles, having one + common angle at <i>a</i>: And <i>aoy</i>, and <i>oea</i>, therefore also + equall: Because both are equall to the angle at <i>a</i>: That by the <a + href="#17_e_vj">17 e, vj</a>: This by the <a href="#2_e_vij">2 e, + vij</a>: Because the perpendicular halfing the side of the decangle, doth + make two triangles, equicrurall, and equall by the right angle of their + shankes: And therefore they are equiangles. Therefore as <i>ea</i>, is to + <i>ao</i>: so is <i>ea</i>, to <i>ay</i>. Wherefore by the <a + href="#8_e_xij">8 e, xij</a>. the oblong of the two extremes is equall to + the quadrate of the meane: And the proposition of the syllogisme, which + was to be demonstrated. The converse from hence as manifest + <i>Euclide</i> doth use at the 16 p xiij.</p> + + <div class="figright" style="width:19%;"> + <a href="images/252a.png"><img style="width:100%" src="images/252a.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p><a name="16_e_xviij"></a> 16. <i>If a triangle and a quinquangle be + inscribed into the same Circle at the same point, the right line + inscribed betweene the bases of the both opposite to the said <!-- Page + 231 --><span class="pagenum"><a name="page231"></a>[231]</span>point, + shall be the side of the inscribed quindecangle. 16. p. iiij</i>.</p> + + <p>For the side of the equilaterall triangle doth subtend 1/3 of the + whole pheriphery. And two sides of the ordinate quinquangle doe subtend + 2/5 of the same. Now 2/5 - 1/3 is 1/15: Therefore the space betweene the + triangle, and the quinquangle shall be the 1/15 of the whole + periphery.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="17_e_xviij"></a> 17. <i>If a quinquangle and a sexangle be + inscribed into the same circle at the same point, the periphery + intercepted beweene both their sides, shall be the thirtieth part of the + whole periphery</i>.</p> + + <p>As here. Therefore the inscription of ordinate triangulates, of a + Quadrate, Quinquangle, Sexangle, Decangle, Quindecangle is easie to bee + performed by one side given or found, which reiterated as oft as need + shall require, shal subtend the whole periphery. <i>Jun. 4.</i> A. C. <a + href="images/252c.png"><img src="images/252c.png" class="middle" + style="height:2ex" alt="MDCXXII in apostrophus form" /></a> <i>Campana + pulsante pro</i>. H. W.</p> + + <div class="figcenter" style="width:24%;"> + <a href="images/252b.png"><img style="width:100%" src="images/252b.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> +<hr class="full" /> + +<p><!-- Page 252 --><span class="pagenum"><a name="pageastx252"></a>[252*]</span></p> + +<h2>Of <i>Geometry</i> the ninteenth Booke; +Of the Measuring of ordinate +Multangle and of a +<i>Circle</i>.</h2> + + <p>Out of the Adscription of a Circle and a Rectilineall is drawne the + Geodesy of ordinate Multangles, and first of the Circle it selfe. For the + meeting of two right lines equally, dividing two angles is the center of + the circumscribed Circle: From the center unto the angle is the ray: And + then if the quadrate of halfe the side be taken out of the quadrate of + the ray, the side of the remainder shall be the perpendicular, by the <a + href="#9_e_xij">9 e xij</a>. Therefore a speciall theoreme is here thus + made:</p> + + <div class="figright" style="width:24%;"> + <a href="images/253.png"><img style="width:100%" src="images/253.png" + alt="Figure for demonstration 1 in a quinquangle." title="Figure for demonstration 1 in a quinquangle." /></a> + </div> + <p><a name="1_e_xix"></a> 1. <i>A plaine made of the perpendicular from + the center unto the side, and of halfe the perimeter, is the content of + an ordinate multangle</i>.</p> + + <p>As here; The quadrate of 10, the ray is 100. The quadrate of 6, the + halfe of the side 12, is 36: And 100. 36 is 64, the quadrate of the + Perpendicular, whose side 8, is the Perpendicular it selfe. Now the whole + periphery of the Quinquangle, is 60. The halfe thereof therefore is 30. + And the product of 30, by 8, is 240, for the content of the sayd + quinquangle.</p> + + <p>The Demonstration here also is of the certaine antecedent cause + thereof. For of five triangles in a quinquangle, the plaine of the + perpendicular, and of halfe the base is one of them, as in the former + hath beene taught: Therefore five <!-- Page 253 --><span + class="pagenum"><a name="pageastx253"></a>[253*]</span>such doe make the + whole quinquangle. But that multiplication, is a multiplication of the + Perpendicular by the Perimeter or bout-line.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/254a.png"><img style="width:100%" src="images/254a.png" + alt="Figure for demonstration 1 in a sexangle." title="Figure for demonstration 1 in a sexangle." /></a> + </div> + <p>In an ordinate Sexangle also the ray, by the <a href="#9_e_xviij">9 e + xviij</a>, is knowne by the side of the sexangle. As here, the quadrate + of 6, the ray is 36. The quadrate of 3, the halfe of the side, is 9: And + 36 - 9. are 27, for the quadrate of the Perpendicular, whose side 5.2/11 + is the perpendicular it selfe. Now the whole perimeter, as you see, is + 36. Therefore the halfe is 18. And the product of 18 by 5.2/11 is 93.3/11 + for the content of the sexangle given.</p> + + <p>Lastly in all ordinate Multangles this theoreme shall satisfie + thee.</p> + + <p><a name="2_e_xix"></a> 2 <i>The periphery is the triple of the + diameter and almost one seaventh part of it</i>.</p> + + <div class="figright" style="width:17%;"> + <a href="images/254b.png"><img style="width:100%" src="images/254b.png" + alt="Figure for demonstration 2." title="Figure for demonstration 2." /></a> + </div> + <p>Or the Periphery conteineth the diameter three times and almost one + seventh of the same diameter. That it is triple of it, sixe raies, (that + is three diameters) about which the periphery, the <a href="#9_e_xviij">9 + e xviij</a>, is circumscribed doth plainely shew: And therefore the + continent is the greater: But the excesse is not altogether so much as + one seventh part. For there doth want an unity of one seventh: And yet is + the same excesse farre greater than one eighth part. Therefore because + the difference was neerer to one seventh, than it was to one eighth, + therefore one seventh was taken, as neerest unto the truth, for the truth + it selfe.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> +<p><!-- Page 254 --><span class="pagenum"><a name="pageastx254"></a>[254*]</span></p> + + <p><a name="3_e_xix"></a> 3. <i>The plaine of the ray, and of halfe the + periphery is the content of the circle</i>.</p> + + <div class="figright" style="width:24%;"> + <a href="images/255.png"><img style="width:100%" src="images/255.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p>For here 7, the ray, of halfe the diameter 14, Multiplying 22, the + halfe of the periphery 44, maketh the oblong 154, for the content of the + circle. In the diameter two opposite sides, and likewise in the perimeter + the two other opposite sides of the rectangle are conteined. Therefore + the halfes of those two are taken, of the which the rectangle is + comprehended.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="4_e_xix"></a> 4. <i>As 14 is unto 11, so is the quadrate of + the diameter unto the Circle</i>.</p> + + <p>For here 3 bounds of the proportion are given in <i>potentia</i>: The + fourth is found by the multiplication of the third by the second, and by + the Division of the product by the first: As here the Quadrate of the + diameter 14, is 196. The product of 196 by 11 is 2156. Lastly 2156 + divided by 14, the first bound, giveth in the Quotient 154, for the + content of the circle sought. This ariseth by an analysis out of the + quadrate and Circle measured. For the reason of 196, unto a 154; is the + reason of 14 unto 11, as will appeare by the reduction of the bounds.</p> + + <p>This is the second manner of squaring of a circle taught by + <i>Euclide</i> as <i>Hero</i> telleth us, but otherwise layd downe, + namely after this manner. <i>If from the quadrate of the diameter you + shall take away 3/14 parts of the same, the remainder shall be the + content of the Circle.</i> As if 196, the quadrate be divided by 14, the + quotient likewise shall be 14. Now thrise 14, are 42: And 196 - 42, are + 154, the quadrate equall to the circle.</p> + + <p>Out of that same reason or rate of the pheriphery and <!-- Page 255 + --><span class="pagenum"><a name="pageastx255"></a>[255*]</span>diameter + ariseth the manner of measuring of the Parts of a circle, as of a + Semicircle, a Sector, a Section, both greater and lesser.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="5_e_xix"></a> 5. <i>The plaine of the ray and one quarter of + the periphery, is the content of the semicircle</i>.</p> + + <div class="figright" style="width:26%;"> + <a href="images/256a.png"><img style="width:100%" src="images/256a.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p>As here thou seest: For the product of 7, the halfe of the diameter, + multiplyed by 11, the quarter of the periphery, doth make 77, for the + content of the semicircle.</p> + + <p>This may also be done by taking of the halfe of the circle now + measured.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="6_e_xix"></a> 6. <i>The plaine made of the ray and halfe the + base, is the content of the Sector</i>.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/256b.png"><img style="width:100%" src="images/256b.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>Here are three sectours, <i>ae</i> the base of 12 foote: And <i>ei</i> + in like manner of 12 foote. The other or remainder <i>ia</i> of 7 + <i>f</i>. and 3/7 of one foote. The diameter is 10 foote. Multiply + therefore 5, halfe of the diameter, by 6 halfe of the base, and the + product 30, shall be the content of the first sector. The same shall also + be for the second sectour. Againe multiply the same ray or semidiameters + 5, by 3.5/7, the halfe of 7.3/7, the product of 18.4/7 shall be the + content of the third sector. Lastly, 30 + 30 + 18.4/7 are 78.4/7, the + content of the whole circle.</p> + + <p> And</p> + +<p><!-- Page 256 --><span class="pagenum"><a name="pageastx256"></a>[256*]</span></p> + + <p><a name="7_e_xix"></a> 7. <i>If a triangle, made of two raies and the + base of the greater section, be added unto the two sectors in it, the + whole shall be the content of the greater section: If the same be taken + from his owne sector, the remainder shall be the content of the + lesser</i>.</p> + + <p>In the former figure the greater section is <i>aei</i>: The lesser is + <i>ai</i>. The base of them both is as you see, 6. The perpendicular from + the toppe of the triangle, or his heighth is 4. Therefore the content of + the triangle is 12. Wherefore 30 + 30 + 12, that is 72, is the content of + the greater section <i>aei</i>. And the lesser sectour, as in the former + was taught, is 18.4/7. Therefore 18.4/7 - 12, that is, 6.4/7, is the + content of <i>ai</i>, the lesser section.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="8_e_xix"></a> 8. <i>A circle of unequall isoperimetrall + plaines is the greatest</i>.</p> + + <div class="figcenter" style="width:70%;"> + <a href="images/257.png"><img style="width:100%" src="images/257.png" + alt="Figures for demonstration 8." title="Figures for demonstration 8." /></a> + </div> + <p>The reason is because it is the most ordinate, and <!-- Page 257 + --><span class="pagenum"><a + name="pageastx257"></a>[257*]</span>comprehended of most bounds; see the + <a href="#7_e_iiij">7</a>, and <a href="#15_e_iiij"><span + class="correction" title="text reads `11 e iiij'">15 e iiij</span></a>. + As the Circle <i>a</i>, of 24 perimeter, is greater then any rectilineall + figure, of equall perimeter to it, as the Quadrate <i>e</i>, or the + Triangle <i>i</i>.</p> + + <div class="figcenter" style="width:57%;"> + <a href="images/258.png"><img style="width:100%" src="images/258.png" + alt="Figures for demonstration 8." title="Figures for demonstration 8." /></a> + </div> +<hr class="full" /> + +<h2>Of <i>Geometry</i> the twentieth Booke, +Of a Bossed surface.</h2> + + <p><a name="1_e_xx"></a> 1. <i>A bossed surface is a surface which lyeth + unequally betweene his bounds</i>.</p> + + <p>It is contrary unto a Plaine surface, as wee heard at the <a + href="#4_e_v">4 e v</a>. <!-- Page 258 --><span class="pagenum"><a + name="pageastx258"></a>[258*]</span></p> + + <div class="figright" style="width:24%;"> + <a href="images/259a.png"><img style="width:100%" src="images/259a.png" + alt="Sphericall surface." title="Sphericall surface." /></a> + </div> + <p><a name="2_e_xx"></a> 2. <i>A bossed surface is either a sphericall, + or varium</i>.</p> + + <p><a name="3_e_xx"></a> 3. <i>A sphericall surface is a bossed surface + equally distant from the center of the space inclosed</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="4_e_xx"></a> 4. <i>It is made by the turning about of an + halfe circumference the diameter standeth still. è 14 d xj</i>.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/259b.png"><img style="width:100%" src="images/259b.png" + alt="Figure for demonstration 4." title="Figure for demonstration 4." /></a> + </div> + <p>As here if thou shalt conceive the space betweene the periphery and + the diameter to be empty.</p> + + <p><a name="5_e_xx"></a> 5. <i>The greatest periphery in a sphericall + surface is that which cutteth it into two equall parts</i>.</p> + + <p>Those things which were before spoken of a circle, the same almost are + hither to bee referred. The greatest periphery of a sphericall doth + answere unto the Diameter of a Circle.</p> + + <p> Therefore</p> + + <div class="figright" style="width:24%;"> + <a href="images/260a.png"><img style="width:100%" src="images/260a.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p><a name="6_e_xx"></a> 6. <i>That periphery that is neerer to the + greatest, is greater than that which is farther off: And on each <!-- + Page 259 --><span class="pagenum"><a + name="pageastx259"></a>[259*]</span>side those two which are equally + distant from the greatest, are equall</i>.</p> + + <p>The very like unto those which are taught at the <a + href="#15_e_xv">15</a>, <a href="#16_e_xv">16</a>, <a + href="#17_e_xv">17</a>, <a href="#18_e_xv">18. e. xv</a>. may here againe + be repeated: As here.</p> + + <p><a name="7_e_xx"></a> 7 <i>The plaine made of the greatest periphery + and his diameter is the sphericall</i>.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/260b.png"><img style="width:100%" src="images/260b.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>So the plaine made of the diameter 14. and of 44. the greatest + periphery, which is 616. is the sphericall surface. So before the content + of a circle was measured by a rectangle both of the halfe diameter, and + periphery. But here, by the whole periphery and whole diameter, there is + made a rectangle for the measure of the sphericall, foure times so great + as was that other: Because by the <a href="#1_e_vj">1 e vj</a>. like + plaines (such as here are conceived to be made of both halfe the + diameter, and halfe the periphery, and both of the whole diameter and + whole periphery) are in a doubled reason of their homologall sides.</p> + + <p> Therefore</p> + + <p><a name="8_e_xx"></a> 8 <i>A plaine of the greatest circle and 4, is + the sphericall</i>.</p> + + <p>This consectarium is manifest out of the former element.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_xx"></a> 9 <i>As 7 is to 22. so is the quadrate of the + diameter unto the sphericall.</i></p> + +<p><!-- Page 260 --><span class="pagenum"><a name="pageastx260"></a>[260*]</span></p> + + <p>For 7, and 22, are the two least bounds in the reason of the diameter + unto the periphery: But in a circle, as 14, is to 11, so is the quadrate + of the diameter unto the circle. The analogie doth answer fitly: Because + here thou multipliest by the double, and dividest by the halfe: There + contrariwise thou multipliest by the halfe, and dividest by the double. + Therefore there one single circle is made, here the quadruple of that. + This is, therefore the analogy of a circle and sphericall; from whence + ariseth the hemispherical, the greater and the lesser section.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="10_e_xx"></a> 10 <i>The plaine of the greatest periphery and + the ray, is the hemisphericall</i>.</p> + + <p>As here, the greatest periphery is 44. the ray 7. The product + therefore of 44. by 7. that is, 308. is the hemisphericall.</p> + + <div class="figright" style="width:22%;"> + <a href="images/261.png"><img style="width:100%" src="images/261.png" + alt="Figure for demonstration 11." title="Figure for demonstration 11." /></a> + </div> + <p><a name="11_e_xx"></a> 11 <i>If looke what the part be of the ray + perpendicular from the center unto the base of the greater section, so + much the hemisphericall be increased, the whole shall be the greater + section of the sphericall: But if it be so much decreased, the remainder + shall be the lesser</i>.</p> + + <p>As in the example, the part of the third ray, that is, of 3/7, is from + the center: such like part of the hemispherical 308, is 132. (For the 7, + part of 308. is 44. And three times 44. is 132.) Therefore 132. added to + 308. do make 440. for the greater section of the sphericall. And 132. + taken from 308. doe leave 176. for the lesser section of the same.</p> + + <p><a name="12_e_xx"></a> 12 <i>The varium is a bossed surface, whose + base is a <!-- Page 241 --><span class="pagenum"><a + name="page241"></a>[241]</span>periphery, the side a right line from the + bound of the toppe, unto the bound of the base</i>.</p> + + <p><a name="13_e_xx"></a> 13 <i>A varium is a conicall or a cylinderlike + forme</i>.</p> + + <p><a name="14_e_xx"></a> 14 <i>A conicall surface is that which from the + periphery beneath doth equally waxe lesse and lesse unto the very + toppe</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figleft" style="width:21%;"> + <a href="images/262a.png"><img style="width:100%" src="images/262a.png" + alt="Conicall surface." title="Conicall surface." /></a> + </div> + <p><a name="15_e_xx"></a> 15. <i>It is made by turning about of the side + about the periphery beneath</i>.</p> + + <p><a name="16_e_xx"></a> 16 <i>The plaine of the side and halfe the base + is the conicall surface</i>.</p> + + <p>As in the example next aforegoing, the side is 13. The halfe periphery + is 15.5/7: And the product of 15.5/7 by 13. is 204.2/7. for the conicall + surface. To which if you shall adde the circle underneath, you shall have + the whole surface.</p> + + <div class="figright" style="width:16%;"> + <a href="images/262b.png"><img style="width:100%" src="images/262b.png" + alt="Cylinderlike forme." title="Cylinderlike forme." /></a> + </div> + <p><a name="17_e_xx"></a> 17 <i>A cylinderlike forme is that which from + the periphery underneath unto the the upper one, equall and parallell + unto it, is equally raised</i>.</p> + + <p> Therefore</p> + + <p><a name="18_e_xx"></a> 18 <i>It is made by the turning of the side + about two equall and parallell peripheries</i>.</p> + + <p><a name="19_e_xx"></a> 19 <i>The plaine of his side and heighth is the + cylinderlike surface.</i> <!-- Page 242 --><span class="pagenum"><a + name="page242"></a>[242]</span></p> + + <p>As here the periphery is 22. as is gathered by the Diameter, which is + 7. The heighth is 12. The base therefore is 38.1/2. And 38.1/2 by 12. are + 462. for the cylinderlike surface. To which if you shall adde both the + bases on each side, to wit, 38.1/2. twise, or 77. once, the whole surface + shall be 539.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<h2><i>Geometry</i>, the one and twentieth Book, +Of Lines and Surfaces in solids.</h2> + + <div class="figright" style="width:20%;"> + <a href="images/263.png"><img style="width:100%" src="images/263.png" + alt="Body or solid." title="Body or solid." /></a> + </div> + <p><a name="1_e_xxj"></a> 1 <i>A body or solid is a lineate broad and + high 1 d xj</i>.</p> + + <p>For length onely is proper to a line: Length and breadth, to a + surface: Length breath, and heighth joyntly, belong unto a body: This + threefold perfection of a magnitude, is proper to a body: Whereby wee doe + understand that are in a body, not onely lines of length, and surfaces of + breadth, (for so a body should consist of lines and surfaces.) But we do + conceive a solidity in length, breadth and heighth. For every part of a + body is also a body. And therefore a solid we doe understand the body it + selfe. As in the body <i>aeio</i>, the length is <i>ae</i>; the breadth, + <i>ai</i>, And the heighth, <i>ao</i>.</p> + + <p><a name="2_e_xxj"></a> 2 <i>The bound of a solid is a surface 2 d + xj</i>.</p> + + <p>The bound of a line is a point: and yet neither is a point a line, or + any part of a line. The bound of a surface is a line: And yet a line is + not a surface, or any part of a surface. So now the bound of a body is a + surface: And yet a surface is not a body, or any part of a body. A + magnitude is one thing; <!-- Page 243 --><span class="pagenum"><a + name="page243"></a>[243]</span>a bound of a magnitude is another thing, + as appeared at the <a href="#5_e_j">5 e j</a>.</p> + + <p>As they were called plaine lines, which are conceived to be in a + plaine, so those are named solid both lines and surfaces which are + considered in a solid; And their perpendicle and parallelisme are hither + to be recalled from simple lines.</p> + + <div class="figright" style="width:23%;"> + <a href="images/264.png"><img style="width:100%" src="images/264.png" + alt="Figure for demonstration 3." title="Figure for demonstration 3." /></a> + </div> + <p><a name="3_e_xxj"></a> 3 <i>If a right line be unto right lines cut in + a plaine underneath, perpendicular in the common intersection, it is + perpendicular to the plaine beneath: And if it be perpendicular, it is + unto right lines, cut in the same plaine, perpendicular in the common + intersection è 3 d and 4 p xj</i>.</p> + + <p>Perpendicularity was in the former attributed to lines considered in a + surface. Therefore from thence is repeated this consectary of the + perpendicle of a line with the surface it selfe.</p> + + <p>If thou shalt conceive the right lines, <i>ae</i>, <i>io</i>, + <i>uy</i>, to cut one another in the plaine beneath, in the common + intersections: And the line <i>rs</i>, falling from above, to be to every + one of them perpendicular in the common point <i>s</i>, thou hast an + example of this consectary.</p> + + <p><a name="4_e_xxj"></a> 4 <i>If three right lines cutting one another, + be unto the same right line perpendicular in the common section, they are + in the same plaine 5. p xj</i>.</p> + + <p>For by the perpendicle and common section is understood an equall + state on all parts, and therefore the same plaine: as in the former + example, <i>as</i>, <i>ys</i>, <i>os</i>, suppose them to be to + <i>sr</i>, the same loftie line, perpendicular, they shall be in the same + nearer plaine <i>aiueoy</i>.</p> + + <div class="figright" style="width:20%;"> + <a href="images/265a.png"><img style="width:100%" src="images/265a.png" + alt="Figure for demonstration 5." title="Figure for demonstration 5." /></a> + </div> + <p><a name="5_e_xxj"></a> 5 <i>If two right lines be perpendicular to the + under-plaine, they are parallells: And if the one two <!-- Page 244 + --><span class="pagenum"><a name="page244"></a>[244]</span>parallells be + perpendicular to the under plaine, the other is also perpendicular to the + same. 6. 8 p xj</i>.</p> + + <p>The cause is out of the first law or rule parallells. For if two right + lines be perpendicular to the same under plaine, being joyned together by + a right line, they shall make their inner corners equall to two right + angles: And therefore they shall be parallells, by the <a + href="#21_e_v">21. e v</a>. And if in two parallells knit together with a + right line, one of the inner angles, be a right angle: the other also + shall be a right angle. Because they are divided by a common + perpendicular; As in the example. If the angles at <i>a</i>, and + <i>e</i>, be right angles, <i>ai</i>, and <i>eo</i>, are parallells, and + contrariwise, if <i>ai</i>, and <i>eo</i> be parallells, and the angle at + <i>a</i>, be a right angle, the angle at <i>e</i>, also shall be a right + angle.</p> + + <p><a name="6_e_xxj"></a> 6 <i>If right lines in diverse plaines be unto + the same right line parallel, they are also parallell betweene + themselves. 9 p xj</i>.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/265b.png"><img style="width:100%" src="images/265b.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p>As here <i>ae</i>, and <i>uy</i>, right lines in diverse plaines + suppose them to be parallell to <i>io</i>: I say, they are parallell one + to another. For from the point <i>i</i>, let <i>ia</i>, and <i>iu</i>, be + <span class="correction" title="text reads `these words, or similar, are omitted in the text'" + >erected at right angles to <i>io</i> to cut the</span> parallells, by + the <a href="#17_e_v">17. e v</a>. Therefore, by the <a href="#3_e_xxj">3 + e</a>, <i>oi</i>, seeing that it is perpedicular to <i>ia</i>, and + <i>iu</i>, two lines cutting one another, it is perpendicular to the + plaine beneath. Therefore by the the <a href="#6_e_xxj">6 e</a>, + <i>yu</i>, and <i>ea</i>, are perpendicular to the same plaine: And + therefore, by the same, they are parallell.</p> + + <div class="figright" style="width:18%;"> + <a href="images/266a.png"><img style="width:100%" src="images/266a.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p><a name="7_e_xxj"></a> 7 <i>If two right lines be perpendiculars, the + first from a point above, unto a right line underneath, the second <!-- + Page 245 --><span class="pagenum"><a name="page245"></a>[245]</span>from + the common section in the plaine underneath, a third, from the sayd point + perpendicular to the second, shall be perpendicular to the plaine + beneath. è 11 p xj</i>.</p> + + <p>It is a consectary out of the <a href="#3_e_xxj">3 e</a>. As for + example, if from a lofty point <i>a</i>, <i>ae</i>, be by the <a + href="#18_e_v">18 e v</a>, perpendicular to <i>e</i>, a point of the + right line <i>io</i> underneath: And from <i>e</i> the common section, by + the <a href="#17_e_v">17 e v</a>, there be <i>eu</i>, another + perpendicular: Lastly <i>ay</i>, a lofty right line, be by the <a + href="#18_e_v">18 e v</a>, perpendicular unto <i>eu</i>, at the point + <i>y</i>, <i>ay</i> shall be perpendicular unto the plaine underneath. + For that <i>ae</i> is perpendicular to <i>io</i>, the same <i>ae</i> + declineth neither to the right hand, nor to the left, by the <a + href="#13_e_ij">13 e ij</a>. And in that againe <i>ay</i> is + perpendicular to <i>eu</i>, it leaneth neither forward nor backeward. + Therefore it lyeth equally or indifferently, betweene the foure quarters + of the world.</p> + + <p>If the right line <i>io</i>, doe with equall angles agree to <i>r</i>, + the third element.</p> + + <p><a name="8_e_xxj"></a> 8. <i>If a right line from a point assigned of + a plaine underneath, be parallell to a right line perpendicular to the + same plaine, it shall also be perpendicular to the plaine underneath. ex + 12 p xj</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/266b.png"><img style="width:100%" src="images/266b.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>As for example let the plaine be <i>aeio</i>: And the assigned point + in it <i>u</i>: From this point a lofty perpendicular is to be erected. + Let there be made from the point <i>y</i>, the perpendicular <i>ys</i>, + unto the plaine underneath, by the <a href="#7_e_xxj">7 e</a>. And to it + let <i>ur</i>, be made parallell by the <a href="#24_e_v">24 e v</a>. Now + <i>ur</i>, seeing it is parallell to a perpendicular upon the plaine + underneath, it shall be perpendicular to the same, by the <a + href="#6_e_xxj"><span class="correction" title="text reads `6 e'">5 + e</span></a>.</p> + +<p><!-- Page 246 --><span class="pagenum"><a name="page246"></a>[246]</span></p> + + <div class="figright" style="width:22%;"> + <a href="images/267.png"><img style="width:100%" src="images/267.png" + alt="Plaines perceived in a Booke." title="Plaines perceived in a Booke." /></a> + </div> + <p><a name="9_e_xxj"></a> 9. <i>If a right line in one of the plaines + cut, perpendicular to the common section, be perpendicular to the other, + the plaines are perpendicular: And if the plaines be perpendicular, a + right line in the one perpendicular to the common section is + perpendicular to the other è 4 d, and 38 p xj</i>.</p> + + <p>The perpendicularity of plaines, is drawne out of the former condition + of the perpendicle: And the state of plaines on each side equall betweene + themselves, is fetch'd from a perpendicularity of a right line falling + upon a plaine. Because from hence it is understood that the plaine it + selfe doth lye indifferently betweene all parts signified by right lines: + Which in a Booke with the pages each way opened, is perceived by the + verses or lines of the pages, both to the section and plaine underneath, + perpendicular as here thou seest.</p> + + <p><a name="10_e_xxj"></a> 10. <i>If a right line be perpendicular to a + plaine, all plaines by it, are perpendicular to the same: And if two + plaines be unto any other plaine perpendiculars, the common section is + perpendicular to the same. e 15, and 19 p. xj</i>.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/268a.png"><img style="width:100%" src="images/268a.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p>The first is a consectary drawne out of the <a href="#9_e_xxj">9 + e</a>. And the latter is from hence manifest, because that same common + section is a right line, in any manner of lofty plaines intersected, + perpendicular both to the common section and plaine underneath. For if + the common section, were not perpendicular to the plaine underneath, + neither should the plaines <!-- Page 247 --><span class="pagenum"><a + name="page247"></a>[247]</span>cutting one another be perpendicular to + the plaine underneath, but some one should be oblique, against the grant, + as here thou seest.</p> + + <div class="figright" style="width:21%;"> + <a href="images/268b.png"><img style="width:100%" src="images/268b.png" + alt="Parallell plaines." title="Parallell plaines." /></a> + </div> + <p><a name="11_e_xxj"></a> 11. <i>Plaines are parallell which doe leane + no way. 8 d xj</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="12_e_xxj"></a> 12. <i>Those which divided by a common + perpendicle. 14 p xj</i>.</p> + + <p>It is a consectary out of the <a href="#3_e_xxj">3</a>, and <a + href="#6_e_xxj">6 e</a>. For if the middle right line be perpendicular to + both the plaines, it is also to the right lines on either side cut, + perpendicular in the common intersection: And the <span + class="correction" title="text reads `innner'">inner</span> angles on + each side, being right angles, will evince them to be parallels.</p> + + <p>It is also out of the definition of parallels, at the <a + href="#15_e_ij"><span class="correction" title="text reads `17 e ij' (no such section)" + >15 e ij</span></a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="13_e_xxj"></a> 13. <i>If two paires of right in them be + joyntly bounded, they are parallell. 15 p xj</i>.</p> + + <div class="figright" style="width:17%;"> + <a href="images/269a.png"><img style="width:100%" src="images/269a.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p>Such are the opposite walls in the toppe or ridge of houses. As let + <i>aei</i>, and <i>uoy</i>, be plaine which have two payres of <!-- Page + 248 --><span class="pagenum"><a name="page248"></a>[248]</span>right + lines, <i>ea</i>, and <i>ia</i>: Item <i>uo</i>, and <i>yo</i>, joyntly + bounded in <i>a</i>, and <i>o</i>: And parallels, to wit <i>ea</i>, + against <i>uo</i>: and <i>ia</i>, against <i>yo</i>. I say that the + plaines themselves are parallels: For the right lines <i>ue</i>, and + <i>oa</i>: item <i>yi</i>, and <i>oa</i>, doe knit together equall + parallels, they shal by the <a href="#27_e_v">27 e v</a>, be equall and + parallels: And so they shall prove the equidistancie.</p> + + <p>The same will fall out if thou shalt imagine the joyntly bounded to + infinitely drawn out; for the plaines also infinitely extended shall be + parallell.</p> + + <p><a name="14_e_xxj"></a> 14. <i>If two parallell plaines are cut with + another plaine, the common sections are parallels, 16 p xj</i>.</p> + + <div class="figleft" style="width:17%;"> + <a href="images/269b.png"><img style="width:100%" src="images/269b.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>As here thou seest the parallell plaines <i>aeio</i>, and <i>uysr</i>, + cut by the plaine <i>ljvf</i>, the common sections <i>lj</i>, and + <i>fv</i>, shall also be parallell: Otherwise they themselves, and + therefore also the plaines in which they are, shall meete, as in the + point <i>t</i>, which is against the grant.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<p><!-- Page 249 --><span class="pagenum"><a name="page249"></a>[249]</span></p> + +<h2>The twenty second Booke, of P. +<i>Ramus</i> Geometry, +Of a +<i>Pyramis</i>.</h2> + + <div class="figright" style="width:24%;"> + <a href="images/270.png"><img style="width:100%" src="images/270.png" + alt="Axis." title="Axis." /></a> + </div> + <p><a name="1_e_xxij"></a> 1. <i>The axis of a solid is the diameter + about which it is turned, e 15, 19, 22 d xj</i>.</p> + + <p>The Axis or Axeltree is commonly thought to be proper to the sphere or + globe, as here <i>ae</i>: But it is attributed to other kindes of solids, + as well as to that.</p> + + <p><a name="2_e_xxij"></a> 2. <i>A right solid is that whose axis is + perpendicular to the center of the base</i>.</p> + + <p>Thus <i>Serenus</i> and <i>Apllonius</i> doe define a Cone and a + Cylinder: And these onely <i>Euclide</i> considered: Yea and indeed + stereometry entertaineth no other kinde of solid but that which is right + or perpendicular.</p> + + <p><a name="3_e_xxij"></a> 3. <i>If solids be comprehended of homogeneall + surfaces, equall in multitude and magnitude, they are equall. 10 d + xj</i>.</p> + + <p>Equality of lines and surfaces was not informed by any peculiar rule; + farther than out of reason and common sense, and in most places + congruency and application was enough and did satisfie to the full: But + here the congruency of Bodies is judged by their surfaces. Two cubes are + equall, whose sixe sides or plaine surfaces, are equall, &c.</p> + + <p><a name="4_e_xxij"></a> 4. <i>If solids be comprehended of surfaces in + multitude equall and like, they are equall, 9 d xj.</i> <!-- Page 250 + --><span class="pagenum"><a name="page250"></a>[250]</span></p> + + <p>This is a consectary drawne out of the general difinition of like + figures, at the <a href="#19_e_iiij">19 e. iiij</a>. For there like + figures were defined to be equiangled and proportionall in the shankes of + the equall angles: But in like plaine solids the angles are esteemed to + be equall out of the similitude of their like plaines: And the equall + shankes are the same plaine surfaces, and therefore they are + proportionall, equall and alike.</p> + + <p><a name="5_e_xxij"></a> 5 <i>Like solids have a treble reason of their + homologall sides, and two meane proportionalls. 33. p xj. 8 p + xij</i>.</p> + + <div class="figcenter" style="width:62%;"> + <a href="images/271.png"><img style="width:100%" src="images/271.png" + alt="Like solids." title="Like solids." /></a> + </div> + <p>It is a consectary drawne out of the <a href="#24_e_iiij">24 e. + iiij</a>. as the example from thence repeated shall make manifest.</p> + + <p><a name="6_e_xxij"></a> 6 <i>A solid is plaine or embosed</i>.</p> + + <p><a name="7_e_xxij"></a> 7 <i>A plaine solid is that which is + comprehended of plaine surfaces</i>.</p> + + <p><a name="8_e_xxij"></a> 8 <i>The plaine angles comprehending a solid + angle, are lesse than foure right angles. 21. p xj</i>.</p> + + <p>For if they should be equall to foure right angles, they would fill up + a place by the <a href="#27_e_iiij"><span class="correction" title="text reads `22 e, vj'" + ></span>27 e, iiij</a>. neither would they at all make an angle, much + lesse therefore would they doe it if they were greater.</p> + + <div class="figright" style="width:24%;"> + <a href="images/272.png"><img style="width:100%" src="images/272.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p><a name="9_e_xxij"></a> 9 <i>If three plaine angles lesse than foure + right angles, do comprehend a solid angle, any two of them are greater + <!-- Page 251 --><span class="pagenum"><a + name="page251"></a>[251]</span>than the other: And if any two of them be + greater than the other, then may comprehend a solid angle, 21. and 23. p + xj</i>.</p> + + <p>It is an analogy unto the <a href="#10_e_vj">10 e vj</a>. and the + cause is in a readinesse. For if two plaine angles be equall to the + remainder, they shall with that third include no space betweene them: But + if thou shalt conceit to fit the plaine to the shankes, with the + congruity they should of two make one: but much lesse if they be + lesser.</p> + + <p>The converse from hence also is manifest.</p> + + <p><i>Euclide</i> doth thus demonstrate it: First if three angles are + equall, then by and by two are conceived to be greater than the + remainder. But if they be unequall, let the angle <i>aei</i>, be greater + than the angle <i>aeo</i>: And let <i>aeu</i>, equall to <i>aeo</i>, be + cut off from the greater <i>aei</i>: And let <i>eu</i>, be equall to + <i>eo</i>. Now by the <a href="#2_e_vij">2 e, vij</a>. two triangles + <i>aeu</i>, and <i>aeo</i>, are equall in their bases <i>au</i>, and + <i>ao</i>. Item <i>ao</i>, and <i>ei</i>, are greater than <i>ai</i>, and + <i>ao</i>: And <i>ao</i>, is equall to <i>au</i>. Therefore <i>oi</i>, is + greater than <i>iu</i>. Here two triangles, <i>uei</i>, and <i>ieo</i>, + equall in two shankes; and the base <i>oi</i>, greater than the base + <i>iu</i>. Therefore, by the <a href="#5_e_vij">5 e vij</a>. the angle + <i>oei</i>, is greater than the angle <i>ieu</i>. Therefore two angles + <i>aeo</i>, and <i>oei</i>, are greater than <i>aei</i>.</p> + + <div class="figright" style="width:35%;"> + <a href="images/273a.png"><img style="width:100%" src="images/273a.png" + alt="Pyramides." title="Pyramides." /></a> + </div> + <p><a name="10_e_xxij"></a> 10 <i>A plaine solid is a Pyramis or a + Pyramidate</i>.</p> + + <p><a name="11_e_xxij"></a> 11 <i>A Pyramis is a plaine solid from a + rectilineall base equally decreasing</i>.</p> + + <p>As here thou conceivest from the triangular base <i>aei</i>, unto the + toppe <i>o</i>, the triangles <i>aoe</i>, <i>aoi</i>, and <i>eoi</i>, to + be <!-- Page 252 --><span class="pagenum"><a + name="page252"></a>[252]</span>reared up.</p> + + <p>In the pyramis <i>aeiou</i>, thou seest from the quadrangular base + <i>aeio</i>, unto the toppe <i>u</i>, foure triangles in like manner to + be raised.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="12_e_xxij"></a> 12 <i>The sides of a pyramis are one more + than are the base</i>.</p> + + <p>The sides are here named <i>Hedræ</i>.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:56%;"> + <a href="images/273b.png"><img style="width:100%" src="images/273b.png" + alt="Sides of Pyramides." title="Sides of Pyramides." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="13_e_xxij"></a> 13 <i>A pyramis is the first figure of + solids</i>.</p> + + <p>For a pyramis in solids, is as a triangle is in plaines. For a pyramis + may be resolved into other solid figures, but it cannot be resolved into + any one more simple than it selfe, and which consists of fewer sides than + it doth.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="14_e_xxij"></a> 14 <i>Pyramides of equall heighth, are as + their bases are <!-- Page 253 --><span class="pagenum"><a + name="page253"></a>[253]</span>5 e, and 6. p xij</i>.</p> + + <div class="figcenter" style="width:32%;"> + <a href="images/274a.png"><img style="width:100%" src="images/274a.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="15_e_xxij"></a> 15 <i>Those which are reciprocall in base and + heighth are equall 9 p xij</i>.</p> + + <div class="figcenter" style="width:35%;"> + <a href="images/274b.png"><img style="width:100%" src="images/274b.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>These consectaries are drawne out of the <a href="#16_e_iiij">16</a>, + <a href="#18_e_iiij">18 e. iiij</a>.</p> + + <div class="figright" style="width:27%;"> + <a href="images/275.png"><img style="width:100%" src="images/275.png" + alt="tetraedrum." title="tetraedrum." /></a> + </div> + <p><a name="16_e_xxij"></a> 16 <i>A tetraedrum is an ordinate pyramis + comprehended of foure triangles 26. d xj</i>.</p> + + <p>As here thou seest. In rectilineall plaines we have in the former + signified, in every kinde there is but one ordinate figure: Amongst the + triangles the equilater: Amongst the <!-- Page 254 --><span + class="pagenum"><a name="page254"></a>[254]</span>quadrangles, the + Quadrate: so now of all kinde of Pyramides, there is one kinde ordinate + onely, and that is the Tetraedrum. And yet not every Tetraedrum is such, + but that only which is comprehended of triangles, not onely severally + ordinate, but equall one to another altogether alike.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="17_e_xxij"></a> 17 <i>The edges of a tetraedrum are sixe, the + plaine angles twelve, the solide angles foure</i>.</p> + + <p>For a Tetraedrum is comprehended of foure triangles, each of them + having three sides, and three corners a peece: And every side is twise + taken: Therefore the number of edges is but halfe so many.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="18_e_xxij"></a> 18 <i>Twelve tetraedra's doe fill up a solid + place</i>.</p> + + <p>Because 8. solid right angles <span class="correction" title="text reads `fillling'" + >filling</span> a place, and 12. angles of the tetraedrum are equall + betweene themselves, seeing that both of them are comprehended of 24 + plaine right-angles. For a solid right angle is comprehended of three + plaine right angles: And therefore 8. are comprehended of 24. In like + manner the angle of a Tetraedrum is comprehended of three plaine + equilaters, that is of sixe third of one right angle: and therefore of + two right angles: Therefore 12 are comprehended of 24.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="19_e_xxij"></a> 19. <i>If foure ordinate and equall triangles + be joyned together in solid angles, they shall comprehend a + tetraedrum.</i> <!-- Page 255 --><span class="pagenum"><a + name="page255"></a>[255]</span></p> + + <div class="figcenter" style="width:75%;"> + <a href="images/276.png"><img style="width:100%" src="images/276.png" + alt="Foure triangles comprehend a tetraedrum." title="Foure triangles comprehend a tetraedrum." /></a> + </div> + <p>This fabricke or construction is very easie, as you may see in these + examples: For if thou shalt joyne or fold together these triangles here + thus expressed, thou shalt make a tetraedrum.</p> + + <p><a name="20_e_xxij"></a> 20. <i>If a right line whose power is + sesquialter unto the side of an equilater triangle, be cut after a double + reason, the double segment perpendicular to the center of the triangle, + knit together with the angles thereof shall comprehend a tetraedrum. 13 p + xiij</i>.</p> + + <p>For a solid to be comprehended of right lines understand plaines + comprehended of right lines, as in other places following.</p> + + <div class="figcenter" style="width:75%;"> + <a href="images/277.png"><img style="width:100%" src="images/277.png" + alt="Figures for demonstration 20." title="Figures for demonstration 20." /></a> + </div> + <p>As here, Let first <i>ae</i> be the right line whose power is + sesquialter unto <i>ai</i> the side of the equilater triangle, as in the + forme was manifest at the <a href="#13_e_xij">13 e xij</a>. And let it be + by the <a href="#29_e_v">29 e v</a>, be cut in a double reason in + <i>o</i>: And let the double segment <i>ao</i>, be perpendicular to the + equilater triangle <i>uys</i>, unto the center <i>r</i>, by the <a + href="#7_e_xxj">7 e xxj</a>. And let <i>lr</i> be knit with the angles, + by <i>lu</i>, <i>ls</i>, <i>ly</i>. I say that the triangles <i>uys</i>, + <i>usl</i>, <i>uyl</i>, are equilater and equall, because all the sides + are equall. First the three lower ones are equall by the grant: And the + three higher ones are equall by the <a href="#9_e_xij">9 e xij</a>. And + every one of the higher ones are equall to the under one. For if a Circle + bee supposed to bee circumscribed about the triangle, the side <!-- Page + 256 --><span class="pagenum"><a name="page256"></a>[256]</span>shall be + of treble power to the ray <i>ur</i>, by the <a href="#12_e_xviij">12 e + xviij</a>. But the higher one also is of treble power to the same ray, as + is manifest in the first figure of the ray <i>oi</i>, which is for the + ray of the second figure <i>ur</i>. For as <i>ao</i>, is to <i>oi</i>, so + by the <a href="#9_e_viij">9 e viij</a>, is <i>oi</i>, unto <i>oe</i>: + And by the <a href="#25_e_iiij">25 e iiij</a>, as the first rect line + <i>ao</i>, is unto the third <i>oe</i>: so is the quadrate <i>ao</i>, + unto the quadrate <i>oi</i>. And by compounding <i>ao</i> with <i>oe</i>; + As <i>ae</i> is to <i>oe</i>; so are the quadrates <i>ao</i>; and + <i>oi</i>, that is, by the <a href="#9_e_xij">9 e xij</a>, the quadrate + <i>ai</i>, unto the quadrate <i>oi</i>, But <i>ae</i> is the triple of + <i>oe</i>. Therefore the quadrate <i>ai</i>, is the triple of the + quadrate <i>oi</i>. Wherefore the higher side equall to <i>ai</i>, is of + treble power to the ray: And therefore also all the sides are equall: And + therefore againe the triangles themselves are equall.</p> + +<hr class="full" /> + +<h2>The twenty third Booke of <i>Geometry</i>, +of a <i>Prisma</i>.</h2> + + <div class="figright" style="width:33%;"> + <a href="images/278a.png"><img style="width:100%" src="images/278a.png" + alt="Prisma's." title="Prisma's." /></a> + </div> + <p><a name="1_e_xxiij"></a> 1 <i>A Pyramidate is a plaine solid + comprehended of pyramides</i>.</p> + + <p><a name="2_e_xxiij"></a> 2. <i>A pyramidate is a Prisma, or a mingled + polyedrum</i>.</p> + + <p><a name="3_e_xxiij"></a> 3. <i>A prisma is a pyramidate whose opposite + plaines are equall, alike, and parallell, the rest parallelogramme. 13 d + xj.</i> <!-- Page 257 --><span class="pagenum"><a + name="page257"></a>[257]</span></p> + + <p>As here thou seest. The base of a pyramis was but one: Of a Prisma, + they are two, and they opposite one against another, First equall; Then + like: Next parallell. The other are parallelogramme.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="4_e_xxiij"></a> 4. <i>The flattes of a prisma are two more + than are the angles in the base</i>.</p> + + <p>And indeed as the augmentation of a Pyramis from a quaternary is + infinite: so is it of a Prisma from a quinary: As if it be from a + triangular, quadrangular, or quinquangular base; you shal have a + Pentraedrum, Hexaedrum, Heptaedrum, and so in infinite.</p> + + <p><a name="5_e_xxiij"></a> 5. <i>The plaine of the base and heighth is + the solidity of a right prisma</i>.</p> + + <div class="figright" style="width:16%;"> + <a href="images/278b.png"><img style="width:100%" src="images/278b.png" + alt="Figure for demonstration 6." title="Figure for demonstration 6." /></a> + </div> + <p><a name="6_e_xxiij"></a> 6. <i>A prisma is the triple of a pyramis of + equall base and heighth. è 7 p. xij</i>.</p> + + <p>As in the example a prisma pentaedrum is cut into three equall + pyramides. For the first consisting of the plaines <i>aei</i>, + <i>aeo</i>, <i>aoi</i>, <i>eio</i>; is equall to the second consisting of + the plaines <i>aoi</i>, <i>aou</i>, <i>aiu</i>, <span class="correction" + title="text reads `auy'"><i>iou</i></span>, by the <a + href="#10_e_vij"><span class="correction" title="wrong reference">10 e + vij</span></a>. Because it is equall to it both in common base and + heighth. Therefore the first and second are equall. And the same second + is equall to it selfe, seeing the base is <i>iou</i>, and the toppe + <i>a</i>. Then also it is equall to the third consisting of the plaines + <i>aiu</i>, <i>aiy</i>, <i>uiy</i>, <i>auy</i>. Therefore three are + equall. <!-- Page 258 --><span class="pagenum"><a + name="page258"></a>[258]</span></p> + + <p>If the base be triangular, the Prisma may be resolved into prisma's of + triangular bases, and the theoreme shall be concluded as afore.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="7_e_xxiij"></a> 7. <i>The plaine made of the base and the + third part of the heighth is the solidity of a pyramis of equall base and + heighth</i>.</p> + + <p>The heighth of a pyramis shall be found, if you shall take the square + of the ray of the base out of the quadrate of the side: for the side of + the remainder, by the <a href="#9_e_xij">9 e xij</a>, shall be the + altitude or heighth, as in the example following.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/279a.png"><img style="width:100%" src="images/279a.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>Here the content of the triangle by the <a href="#18_e_xij">18 e + xij</a>, is found to be 62.44/125 for the base of the pyramis. The + altitude is 9.15/19: Because by the <a href="#12_e_xviij"><span + class="correction" title="text reads `6 e xviij'">12 e xviij</span></a>, + the side is of treble power to the ray. But if from 144, the quadrate of + 12 the side, you take the subtriple <i>i</i>. 48, the remainder 96, by + the <a href="#9_e_xij">9 e xij</a>, shall be the square of the heighth. + And the side of the quadrate shall be 9.15/19. Now the third part of + 9.15/19 is 3.5/19. And the plaine of 62.44/125 and 3.5/19, shall be + 203.1103/2375 for the solidity of the pyramis.</p> + + <div class="figright" style="width:17%;"> + <a href="images/280a.png"><img style="width:100%" src="images/280a.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <div class="figright" style="width:17%;"> + <a href="images/279b.png"><img style="width:100%" src="images/279b.png" + alt="Figure for demonstration 7." title="Figure for demonstration 7." /></a> + </div> + <p>So in the example following, Let 36, the quadrate of 6 the ray, be + taken out of 292.9/1156 the quadrate of the side 17.3/34 the side <span + class="correction" title="This value is wrong, it should be approx. 16.1/4110. It follows that the rest of this section is wrong." + >16.3/34</span> of 256.9/1156 the remainder shall be the height, whose + third part is 5.37/102; the plaine of which by the base 72.1/4 shall be + 387.11/24 for the solidity of the pyramis given.</p> + + <p>If the pyramis be unperfit, first measure the whole, and then that + part which is wanting: Lastly from the whole <!-- Page 259 --><span + class="pagenum"><a name="page259"></a>[259]</span>subtract that which was + wanting, and the remaine shall be the solidity of the unperfect pyramis + given: As here, let <i>ao</i>, the side of the whole be 16.5/12, + <i>eo</i> the side of the particular be 8.1/16. Therefore the + perpendicular of the whole <i>ou</i>, shall be <span class="correction" + title="Wrong again.He is taking sqrt(nn.pp/qq) to be n.p/q!" + >15.5/32</span>: Whose third part is 5.5/96: Of which, and the base + 93.3/11 the plaine shall be 471.134/1056 for the whole pyramis. But in + the lesser pyramis, 9 the square of the ray 3, taken out of 65.1/256 the + quadrate of the side 8.1/16 the remaine shall be 56.1/256; whose side is + almost 7-1/2 for the heighth. The third part of which is 2-1/2. The base + likewise is almost 22. The plaine of which two is 55, for the solidity of + the lesser pyramis: And 471 - 55 is 416, for the imperfect pyramis.</p> + + <p>After this manner you may measure an imperfect Prisma.</p> + + <p><a name="8_e_xxiij"></a> 8. <i>Homogeneall Prisma's of equall heighth + are one to another as their bases are one to another, 29, 30, 31, 32 p + xj</i>.</p> + + <div class="figcenter" style="width:30%;"> + <a href="images/280b.png"><img style="width:100%" src="images/280b.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>The reason is, because they consist equally of like number <!-- Page + 260 --><span class="pagenum"><a name="page260"></a>[260]</span>of + pyramides. Now it is required that they be homogeneall or of like kindes; + Because a Pentaedrum with an Hexaedrum will not so agree.</p> + + <p>This element is a consectary out of the <a href="#16_e_iiij">16 e + iiij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_xxiij"></a> 9. <i>If they be reciprocall in base and + heighth, they are equall</i>.</p> + + <div class="figcenter" style="width:34%;"> + <a href="images/281a.png"><img style="width:100%" src="images/281a.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <p>This is a Consectary out the <a href="#18_e_iiij">18 e iiij</a>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:26%;"> + <a href="images/281b.png"><img style="width:100%" src="images/281b.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p><a name="10_e_xxiij"></a> 10. <i>If a Prisma be cut by a plaine + parallell to his opposite flattes, the segments are as the bases are. 25 + p. xj</i>.</p> + + <p>The segments are homogeneall because the prismas. Therefore seeing + they are of equall heighth (by the heighth I meane of plaine dividing + them) they shall be as their bases are: And here the bases are to be + taken opposite to the heighth.</p> + + <p><a name="11_e_xxiij"></a> 11. <i>A Prisma is either a Pentaedrum, or + Compounded of pentaedra's.</i> <!-- Page 261 --><span class="pagenum"><a + name="page261"></a>[261]</span></p> + + <p>Here the resolution sheweth the composition.</p> + + <p><a name="12_e_xxiij"></a> 12 <i>If of two pentaedra's, the one of a + triangular base, the other of a parallelogramme base, double unto the + triangular, be of equall heighth, they are equall 40. p xj</i>.</p> + + <p>The <span class="correction" title="text reads `canse'">cause</span> + is manifest and briefe: Because they be the halfes of the same prisma: As + here thou maist perceive in a prisma cut into two halfes by the diagoni's + of the opposite sides.</p> + + <div class="figcenter" style="width:42%;"> + <a href="images/282.png"><img style="width:100%" src="images/282.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p><i>Euclide</i> doth demonstrate it thus: Let the Pentaedra's + <i>aeiou</i>, and <i>ysrlm,</i> be of equall heighth: the first of a + triangular base <i>eio</i>: The second of a parallelogramme base + <i>sl</i>, double unto the triangular. Now let both of them be double and + made up, so that first be <i>aeioun.</i> The second <i>ysrlvf</i>. Now + againe, by the grant, the base <i>sl</i>, is the double of the base + <i>eio</i>,: whose double is the base <i>eo</i>, by the <a + href="#12_e_x">12 e x</a>. Therefore the bases <i>sl</i>, and <i>eo</i>, + are equall: And therefore seeing the prisma's, by the grant, here are of + equall heighth, as the bases by the conclusion are equall, the prisma's + are equall; And therefore also their halfes <i>aeiou</i>, and <i><span + class="correction" title="text reads `ysnlr'">ysmlr</span></i>, are + equall.</p> + + <p>The measuring of a pentaedrall prisma was even now generally taught: + The matter in speciall may be conceived in these two examples + following.</p> + + <div class="figright" style="width:34%;"> + <a href="images/283.png"><img style="width:100%" src="images/283.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>The plaine of 18. the perimeter of the triangular base, <!-- Page 262 + --><span class="pagenum"><a name="page262"></a>[262]</span>and 12, the + heighth is 216. This added to the triangular base, 15.18/31. or 15.3/5, + almost twise taken, that is, 31.1/5, doth make 247.1/5, for the summe of + the whole surface. But the plaine of the same base 15.3/5, and the + heighth 12. is 187.1/5, for the whole solidity.</p> + + <p>So in the pentaedrum, the second prisma, which is called + <i>Cuneus</i>, (a wedge) of the sharpnesse, and which also more properly + of cutting is called a prisma, the whole surface is 150, and the solidity + 90.</p> + + <p><a name="13_e_xxiij"></a> 13 <i>A prisma compounded of pentaedra's, is + either an Hexaedrum or Polyedrum: And the Hexaedrum is either a + Parallelepipedum or a Trapezium</i>.</p> + + <p><a name="14_e_xxiij"></a> 14 <i>A parallelepipedum is that whose + opposite plaines are parallelogrammes ê 24. p xj</i>.</p> + + <p>Therefore a Parallelepipedum in solids, answereth to a Parallelogramme + in plaines. For here the opposite <i>Hedræ</i> or flattes are parallell: + There the opposite sides are parallell.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:20%;"> + <a href="images/284a.png"><img style="width:100%" src="images/284a.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p><a name="15_e_xxiij"></a> 15 <i>It is cut into two halfes with a + plaine by the diagonies of the opposite sides. 28 p xj. It answereth to + the 34. p j.</i> <!-- Page 263 --><span class="pagenum"><a + name="page263"></a>[263]</span></p> + + <p>Let the Prisma be of sixe bases <i>ai</i>, <i>yo</i>, <i>ye</i>, + <i>ui</i>, <span class="correction" title="text reads `ri'" + ><i>si</i></span>, <i>au</i>. The diagonies doe cut into halfes, by the + <a href="#10_e_x">10. e x</a>. the opposite bases: And the other opposite + bases or the two prisma's cut, are equall by the <a href="#3_e_xxiij">3 + e</a>. Wherefore two prisma's are comprehended of bases, equall both in + multitude and magnitude: therfore they are equall.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="16_e_xxiij"></a> 16 <i>If it be halfed by two plaines halfing + the opposite sides, the common bisection and diagony doe halfe one + another 39. p xj</i>.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/284b.png"><img style="width:100%" src="images/284b.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p>Because here the diameters (such as is that bisection) are halfed + betweene themselves [or doe halfe one another.] Let the parallelepipedum + <i>aeiouy</i>, be cut in to <i>y</i> the halfs by two plains, fro + <i>srlm</i>, <i><span class="correction" title="The figure is wrongly labelled but the argument is not affected." + >uivf</span></i>, halfing the opposite sides: Here the common section + <i>ts</i>, and the diagony <i>ao</i>, doe cut one another.</p> + + <p><a name="17_e_xxiij"></a> 17 <i>If three lines be proportionall, the + parallelepipedum of meane shall be equall to the equiangled + parallelepipedum of all them. è 36. p xj</i>.</p> + + <p>It is a consectary out of the <a href="#8_e_xxiij">8 e</a>.</p> + + <p><a name="18_e_xxiij"></a> 18 <i>Eight rectangled parallelepiped's doe + fill a solid place</i>.</p> + + <p><a name="19_e_xxiij"></a> 19 <i>The Figurate of a rectangled + parallelepipedum is called a solid, made of three numbers 17. d + vij.</i></p> + + <p>As if thou shalt multiply 1, 2, 3. continually, thou shalt make the + solid 6. Item if thou shalt in like manner multiply 2, 3, 4. thou shalt + make the solid 24. And the sides of that solid <!-- Page 264 --><span + class="pagenum"><a name="page264"></a>[264]</span>6 solid shall be 1, 2, + 3. Of 24, they shall be 2, 3, 4.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="20_e_xxiij"></a> 20 <i>If two solids be alike, they have + their sides proportionalls, and two meane proportionalls 21 d vij, 19. + 21. p viij.</i></p> + + <p>It is a consectary out of the <a href="#5_e_xxij">5 e xxij</a>. But + the meane proportionalls are made of the sides of the like solids, to + wit, of the second, third, and fourth: Item of the third, fourth, and + fifth, as here thou seest.</p> + +<table class="nobctr"> +<tr><td>2, </td><td>3, </td><td>5, </td><td>4, </td><td>6, </td><td>10.</td></tr> +<tr><td colspan="2">30,</td><td>60,</td><td colspan="2" align="center">120,</td><td>240.</td></tr> +</table> + +<hr class="full" /> + +<h2>Of <i>Geometry</i> the twentie fourth Book. +Of a Cube.</h2> + + <p><a name="1_e_xxiiij"></a> 1 <i>A Rightangled parallelepipedum is + either a Cube, or an Oblong</i>.</p> + + <p><a name="2_e_xxiiij"></a> 2 <i>A Cube is a right angled + parallelepipedum of equall flattes, 25. d. xj</i>.</p> + + <div class="figcenter" style="width:48%;"> + <a href="images/285.png"><img style="width:100%" src="images/285.png" + alt="Cubes." title="Cubes." /></a> + </div> + <p>As here thou seest in these two figures.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="3_e_xxiiij"></a> 3 <i>The sides of a cube are 12. the plaine + angles 24. the solid 8.</i> <!-- Page 265 --><span class="pagenum"><a + name="page265"></a>[265]</span></p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="4_e_xxiiij"></a> 4 <i>If sixe equall quadrates be joyned with + solid angles, they shall comprehend a cube</i>.</p> + + <div class="figcenter" style="width:53%;"> + <a href="images/286.png"><img style="width:100%" src="images/286.png" + alt="Nets of a cube." title="Nets of a cube." /></a> + </div> + <p>As here in these two examples.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="5_e_xxiiij"></a> 5 <i>If from the angles of a quadrate, + perpendiculars equall to the sides be tied together aloft, they shall + comprehend a Cube. è 15 p xj</i>.</p> + + <p>It is a consectary following upon the former consectary: For then + shall sixe equall quadrates be knit together:</p> + + <p><a name="6_e_xxiiij"></a> 6 <i>The diagony of a Cube is of treble + power unto the side</i>.</p> + + <p>For the Diagony of a quadrate is of double power to the side, by the + <a href="#12_e_xij">12 e, xij</a>. And the Diagony of a Cube is of as + much power as the side the diagony of the quadrate, by the same <i>e</i>. + Therefore it is of treble power to the side.</p> + + <p><a name="7_e_xxiiij"></a> 7 <i>If of foure right lines continually, + proportionally the first be the halfe of the fourth, the cube of the + first shall be the halfe of the Cube of the second è 33 p xj</i>.</p> + + <p>It is a consectary out of the <a href="#25_e_iiij">25 e, iiij</a>. + From hence <i>Hippocrates</i> first found how to answer <i>Apollo's</i> + Probleme.</p> + + <p><a name="8_e_xxiiij"></a> 8 <i>The solid plaine of a cube is called a + Cube, to wit, a solid of equall sides. 19, d vij</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="9_e_xxiiij"></a> 9 <i>It is made of a number multiplied into + his owne quadrate.</i> <!-- Page 266 --><span class="pagenum"><a + name="page266"></a>[266]</span></p> + + <p>So is a Cube made by multiplying a number by it selfe, and the product + againe by the first. Such are these nine first cubes made of the nine + first Arithmeticall figures.</p> + +<table class="nobctr"> +<tr><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td><td>8</td><td>9</td><td>Latera.</td></tr> +<tr><td>1</td><td>4</td><td>9</td><td>16</td><td>25</td><td>36</td><td>49</td><td>64</td><td>81</td><td>Quadrates.</td></tr> +<tr><td>1 </td><td>8 </td><td>27 </td><td>64 </td><td>125 </td><td>216 </td><td>343 </td><td>512 </td><td>729 </td><td>Cubes.</td></tr> +</table> + + <p>This is the generall invention of a Cube, both Geometricall and + Arithmeticall.</p> + + <p><a name="10_e_xxiiij"></a> 10 <i>If a right line be cut into two + segments, the Cube of the whole shall be equall to the Cubes of the + segments, and a double solid thrice comprehended of the quadrate of his + owne segment and the other segment</i>.</p> + + <p>As for example, the side 12, let it be cut into two segments 10 and 2. + The cube of 12. the whole, which is 1728, shall be equall to two cubes + 1000, and 8 made of the segments 10. and 2. And a double solid; of which + the first 600. is thrise comprehended of 100. the quadrate of his segment + 10. and of 2. the other segment: The second 120. is thrice comprehended + of 4, the quadrate of his owne segment, and of 10. the other segment. Now + 1000 + 600 + 120. + 8, is equall to 1728: And therefore a right. + &c.</p> + + <p>But the genesis of the whole cube will make all this whole matter more + apparant, to wit, how the extreme and meane solids are made. Let + therefore a cube be made of three equall sides, 12, 12, and 12: And first + of all let the second side be multiplied by the first, after this manner: + And not adding the severall figures of the same degree, as was taught in + multiplication, but multiply againe every one of them by the other side; + and lastly, add the figures of the same degrees severally, thus: <!-- + Page 267 --><span class="pagenum"><a name="page267"></a>[267]</span></p> + +<table class="nobctr"><tr><td align="right"> +12<br /> +12<br /> +——<br /> +24<br /> +12 <br /> +12<br /> +——<br /> +48<br /> +24 <br /> +24 <br /> +12 <br /> +——<br /> +1,6,12,8 +</td><td align="center"> + Or thus, +</td><td align="right"> +12<br /> +12<br /> +——<br /> +4<br /> +20<br /> +20<br /> +100<br /> +——<br /> +12<br /> +——<br /> +8<br /> +40<br /> +40<br /> +40<br /> +200<br /> +200<br /> +200<br /> +1000<br /> +——<br /> +1728 +</td></tr></table> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="11_e_xxiiij"></a> 11. <i>The side of the first severall cube + is the other side of the second solide: And the quadrate of the same side + is the other side of the first solide, whose other side is the side of + the second cube; and the quadrate of the same other side is the other + side of the second solid</i>.</p> + + <p>In that equation therefore of foure solids with one solid, thou shalt + consider a peculiar making and composition: First that the last cube be + made of the last segment 2: Then that the second solid of 4, the quadrate + of his owne segment, and of 10, the other segment be thrise comprehended: + Lastly that the first solid of 100, the square of his owne segment 10 and + the other segment 2, be also thrice comprehended: Lastly, that the Cube + 1000, be made of the greater segment 10. Out of this making &c.</p> + + <p>And thus much of the Cube: Of other sorts of parallelepipedes, as of + the Oblong, the Rhombe, the Rhomboides, and of the Trapezium, and many + flatted pentaedra's there is no <!-- Page 268 --><span class="pagenum"><a + name="page268"></a>[268]</span>peculiar stereometry. The measuring of a + Prisma hath in the former beene generally declared, and is now onely + farther be made more plaine by speciall examples; as here:</p> + + <div class="figcenter" style="width:44%;"> + <a href="images/289a.png"><img style="width:100%" src="images/289a.png" + alt="Figure for Demonstration 11." title="Figure for Demonstration 11." /></a> + </div> + <p>The plaine of the perimeter of the base 20, and the altitude 5 is 100. + This added to 25 and 25, both the bases that is to 50, maketh 150, for + the whole surface. Now the plaine of 25 the base, and the heighth 5 is + 125, for the whole solidity.</p> + + <p>So in the Oblong, the plaine of the base's perimeter 20, and the + heighth 11, is 220, which added to the bases 24 and 24, that is 48, + maketh 268, for the whole surface. But the plaine of the base 24, and the + height 11, is 264, for the solidity.</p> + + <div class="figcenter" style="width:35%;"> + <a href="images/289b.png"><img style="width:100%" src="images/289b.png" + alt="Figure for Demonstration 11." title="Figure for Demonstration 11." /></a> + </div> + <p>The same also Geodesie or manner of measuring is used in the measuring + of rectangled walls or gates and doores, which have either any window, or + any hollow <!-- Page 269 --><span class="pagenum"><a + name="page269"></a>[269]</span>or voyde space cut out of them, if those + voyde places be taken out of them; as here thou seest in the next + following example. The thickenesse is 3 foote; the breadth 12, the + heighth 11. Therefore the whole solidity is 396. Now the Gate way is of + thickenesse 3 foote, of breadth 4: of heighth 6. And therefore the whole + solidity of the Gate is 72 foote. But 396 - 72 are 314. Therefore the + solidity of the rest of the wall remaining is 324.</p> + + <p>In the second example, the length is 10. The breadth 8, the heighth 7. + Therefore the whole body if it were found, were 560 foote. But there is + an hollow in it, whose length is 6, breadth 5, heighth 7. Therefore the + cavity or hollow place is 168. Now 560 - 168 is 392, for the solidity of + the rest of the sound body.</p> + + <div class="figcenter" style="width:44%;"> + <a href="images/290.png"><img style="width:100%" src="images/290.png" + alt="Figure for Demonstration 11 second example." title="Figure for Demonstration 11 second example." /></a> + </div> + <p>Thus are such kinde of walls whether of mudde, bricke, or stone, of + most large houses to bee measured. The same manner of Geodesy is also to + be used in the measuring of a Rhombe, Rhomboides, Trapezium or mensall, + and any kinde of multangled body. The base is first to be measured, as in + the former: Then out of that and the heighth the solidity shall be + manifested: As in the Rhombe the base is 24, the heighth 4. Therefore the + solidity is 96.</p> + + <p>In the Rhomboides, the base is 64.35/129: The heigh <span + class="correction" title="text reads `11', result requires `16'" + >16</span>. Therefore the solidity is 1028.44/129.</p> + + <p>The same is the geodesy of a trapezium, as in these examples: The + surface of the first is 198: The solidity 192.1/2.</p> + + <p>The surface of the second is 158.3/49: The solidity is 91.29/49. <!-- + Page 270 --><span class="pagenum"><a name="page270"></a>[270]</span></p> + + <div class="figcenter" style="width:46%;"> + <a href="images/291a.png"><img style="width:100%" src="images/291a.png" + alt="Figure for Demonstration 11 - a many flatted Prisma." title="Figure for Demonstration 11 - a many flatted Prisma." /></a> + </div> + <div class="figright" style="width:22%;"> + <a href="images/291b.png"><img style="width:100%" src="images/291b.png" + alt="Figure for Demonstration 11." title="Figure for Demonstration 11." /></a> + </div> + <p>The same shall be also the geodesy of a many flatted Prisma: As here + thou seest in an Octoedrum of a sexangular base: The surface shall bee + 762.6/11: The solidity 1492.4/11.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/291c.png"><img style="width:100%" src="images/291c.png" + alt="Figure for Demonstration 11." title="Figure for Demonstration 11." /></a> + </div> + <p>And from hence also may the capacity or content of vessels or + measures, made after any manner of plaine solid bee esteemed and judged + of as here thou seest. For here the plaine of the sexangular base is + 41.1/7; (For the ray, by the <a href="#9_e_xviij">9 e xviij</a>, is the + side:) and the heighth 5, shall be 205.5/7. Therefore if a cubicall foote + doe conteine 4 quarters, as we commonly call them, then shall the vessell + conteine 822.6/7 quartes, that is almost 823 quartes.</p> + + <p><br style="clear :both" /></p> +<hr class="full" /> + +<p><!-- Page 271 --><span class="pagenum"><a name="page271"></a>[271]</span></p> + +<h2><i>Of Geometry</i> the twenty fifth Booke; +Of mingled ordinate <i>Polyedra's</i>.</h2> + + <p><a name="1_e_xxv"></a> 1. <i>A mingled ordinate polyedrum is a + pyramidate, compounded of pyramides with their toppes meeting in the + center, and their bases onely outwardly appearing</i>.</p> + + <p>Seeing therefore a Mingled ordinate pyramidate is thus made or + compounded of pyramides the geodesy of it shall be had from the Geodesy + of the pyramides compounding it: And one Base multiplyed by the number of + all the bases shall make the surface of the body. And one Pyramis by the + number of all the pyramides; shall make the solidity.</p> + + <p><a name="2_e_xxv"></a> 2 <i>The heighth of the compounding pyramis is + found by the ray of the circle circumscribed about the base, and by the + semidiagony of the polyedrum</i>.</p> + + <p>The base of the pyramis appeareth to the eye: The heighth lieth hidde + within, but it is discovered by a right angle triangle, whose base is the + semidiagony or halfe diagony, the shankes the ray of the circle, and the + perpendicular of the heighth. Therefore subtracting the quadrate of the + ray, from the quadrate of the halfe diagony the side of the remainder, by + the <a href="#9_e_xij">9 e xij</a>. shall be the heighth. But the ray of + the circle shall have a speciall invention, according to the kindes of + the base, first of a triangular, and then next of a quinquangular.</p> + + <p><a name="3_e_xxv"></a> 3 <i>A mingled ordinate polyedrum hath either a + triangular, or a quinquangular base.</i> <!-- Page 272 --><span + class="pagenum"><a name="page272"></a>[272]</span></p> + + <p>The division of a Polyhedron ariseth from the bases upon which it + standeth.</p> + + <p><a name="4_e_xxv"></a> 4 <i>If a quadrate of a triangular base be + divided into three parts, the side of the third part shall be the ray of + the circle circumscribed about the base</i>.</p> + + <p>As is manifest by the <a href="#12_e_xviij">12 e. xviij</a>. And this + is the invention or way to finde out the circular ray for an octoedrum, + and an icosoedrum.</p> + + <p><a name="5_e_xxv"></a> 5 <i>A mingled ordinate polyedrum of a + triangular base, is either an Octoedrum, or an Icosoedrum</i>.</p> + + <p>This division also ariseth from the bases of the figures.</p> + + <p><a name="6_e_xxv"></a> 6 <i>An octoedrum is a mingled ordinate + polyedrum, which is comprehended of eight triangles. 27 d xj</i>.</p> + + <div class="figcenter" style="width:52%;"> + <a href="images/293.png"><img style="width:100%" src="images/293.png" + alt="Lines and solid octahedrum." title="Lines and solid octahedrum." /></a> + </div> + <p>As here thou seest, in this Monogrammum and solidum, that is lines and + solid octahedrum.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="7_e_xxv"></a> 7 <i>The sides of an octoedrum are 12. the + plaine angles 24, and the solid 6</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="8_e_xxv"></a> 8 <i>Nine octoedra's doe fill a solid + place</i>.</p> + + <p>For foure angles of a Tetraedrum are equall to three angles of the + Octoedrum: And therefore 12. are equall to <!-- Page 273 --><span + class="pagenum"><a name="page273"></a>[273]</span>nine. Therefore nine + angles of an octaedrum doe countervaile eight solid right angles.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_xxv"></a> 9 <i>If eight triangles, equilaters and equall + be joyned together by their edges; they shall comprehend an + octaedreum</i>.</p> + + <div class="figright" style="width:21%;"> + <a href="images/294a.png"><img style="width:100%" src="images/294a.png" + alt="Net of octahedrum." title="Net of octahedrum." /></a> + </div> + <p>This construction is easie, as it is manifest in the example + following: Where thou seest as it were two equilater and equall triangles + of a double pentaedrum to cut one another.</p> + + <p><a name="10_e_xxv"></a> 10 <i>If a right line of each side + perpendicular to the center of a quadrate and equall to the halfe diagony + be tied together with the angles, it shall comprehend an octaedrum, 14. d + xiij</i>.</p> + + <div class="figleft" style="width:20%;"> + <a href="images/294b.png"><img style="width:100%" src="images/294b.png" + alt="Figure for demonstration 10." title="Figure for demonstration 10." /></a> + </div> + <p>For the perpendicular <i>yu</i>, and <i>su</i>, with the + semidiagoni's, <i>ua</i>, <i>uo</i>, <i>ui</i>, <i>ue</i>, shall be made + equall by the <a href="#2_e_vij">2 e vij</a>, the eight sides <i>ya</i>, + <i>ye</i>, <i>yo</i>, <i>yi</i>, <i>se</i>, <i>si</i>, <i>sa</i>, + <i>so</i>; And also eight triangles.</p> + + <p> Therefore</p> + + <p><a name="11_e_xxv"></a> 11 <i>The Diagony of an octaedrum is of double + power to the side</i>.</p> + + <p>As is manifest by the <a href="#9_e_xij">9 e xij</a>.</p> + + <p> And</p> + + <p><a name="12_e_xxv"></a> 12 <i>If the quadrate of the side of an + octaedrum, be <!-- Page 274 --><span class="pagenum"><a + name="page274"></a>[274]</span>doubled, the side of the double shall be + the diagony</i>.</p> + + <p>As in the figure following, the side is 6. The quadrate is 36. the + double is 72. whose side 8.8/17, is the diagony.</p> + + <div class="figright" style="width:24%;"> + <a href="images/295a.png"><img style="width:100%" src="images/295a.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>And from hence doth arise the geodesy of the octaedrum. For the + semidiagony is 4.4/17. whose quadrate is 17.171/289. And the quadrate of + 6, the side of the equilater triangle, being of treble power to the ray, + by the <a href="#12_e_xviij"><span class="correction" title="text reads `6 e, xviiij'" + >12 e, xviij</span></a>. is 36. And the side of 12. the third part 3.3/7 + is the ray of the circle. Wherefore 8.8/17. that is 5.21/289. is the + quadrate of the perpendicular, whose side 2.1/5 is the height of the same + perpendicular: whose third part againe 11/25. <span class="correction" + title="text reads `mulliplied'">multiplied</span> by 15.18/31. the + triangular base doe make 11.66/155 for one of the eight pyramides: + Therefore the same 11.66/155 multiplied by eight, shall make 91.63/155 + for the whole octoedrum.</p> + + <p><br style="clear : both" /></p> + <p><a name="13_e_xxv"></a> 13 <i>An Icosaedrum is an ordinate polyedrum + comprehended of 20 triangles 29 d xj</i>.</p> + + <div class="figcenter" style="width:54%;"> + <a href="images/295b.png"><img style="width:100%" src="images/295b.png" + alt="Line and Solid Icosaedrum." title="Line and Solid Icosaedrum." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="14_e_xxv"></a> 14 <i>The sides of an Icosaedrum are 30. + plaine angles 60. the solid 12.</i> <!-- Page 275 --><span + class="pagenum"><a name="page275"></a>[275]</span></p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="15_e_xxv"></a> 15 <i>If twentie ordinate and equall triangles + be joyned with solid angles, they shall comprehend an Icosaedrum</i>.</p> + + <div class="figcenter" style="width:28%;"> + <a href="images/296a.png"><img style="width:100%" src="images/296a.png" + alt="Net of Icosaedrum." title="Net of Icosaedrum." /></a> + </div> + <p>This fabricke is ready end easie, as is to be seene in this example + following.</p> + + <p><a name="16_e_xxv"></a> 16. <i>If ordinate figures, to wit, a double + quinquangle, and one decangle be so inscribed into the same circle, that + the side of both the quinquangle doe subtend two sides of the decangle, + sixe right lines perpendicular to the circle and equall to his ray, five + from the angles of one of the quinquangles, knit together both betweene + themselves, and with the angles of the other quinquangle; the sixth from + the center on each side continued with the side of the decangle, and knit + therewith the five perpendiculars, here with the angles of the second + quinquangle, they shall comprehend an icosaedrum. è 15 p xiij</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/296b.png"><img style="width:100%" src="images/296b.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> + <p>For there shall be made 20 triangles, both equilaters and equall. Let + there be therefore two ordinate quinquangles, the first <i>aeiou</i>; The + second <i>ysrlm</i>; each of whose sides let them subtend two sides of a + decangle; to wit, <i>utym</i>, let it subtend <i>ya</i>, and <i>am</i>. + Then let there be five perpendiculars from the angles of the second + quinquangle <i>yj</i>, <i>sy</i>, <i>rv</i>, <!-- Page 276 --><span + class="pagenum"><a name="page276"></a>[276]</span><i>lf</i>, <i>mt</i>. + And let them be knit first one with another, by the lines <i>nj</i>, + <i>jv</i>, <i>vf</i>, <i>ft</i>, <i>tn</i>. Secondarily, with the angles + of the first quinquangle, by the lines <i>ne</i>, <i>ej</i>, <i>ji</i>, + <i>iv</i>, <i>of</i>, <i>fu</i>, <i>ut</i>, <i>ta</i>, <i>an</i>. The + sixth perpendicular from the center <i>d</i>, let it be <i>bg</i>, the + ray <i>dc</i>, continued at each end with the side of the decangle, + <i>cg</i>, and <i>db</i>, tied together about with the perpendiculars, as + by the lines <i>ng</i>, <i>tg</i>: Beneath with the angles of the first + quinquangle, as by the lines <i>be</i>, <i>bi</i>, and in other places in + like manner, and let all the plaines be made up. This say I, is an + Icosaedrum; And is comprehended of 20. triangles, both equilaters and + equall. First, the tenne middle triangles, leaving out the + perpendiculars, that they are equilaters and equall, one shall + demonstrate, as <i>nat</i>. For <i>mt</i> and <i>yu</i>, because they are + perpendiculars, they are also, by the <a href="#6_e_xxj">6 e xxj</a>. + parallells: And by the grant, equall. Therefore by the <a + href="#27_e_v">27 e, v</a>, <i>nt</i>, is equall to <i>ym</i>, the side + of the quinquangle. Item <i>na</i>, by the <a href="#6_e_xij">6 e + xij</a>. is of as great power, as both the shankes <i>ny</i>, and + <i>ya</i>, that is, by the construction, as the sides of the sexangle and + decangle: And, by the converse of the <a href="#15_e_xviij">15. e + xviij</a>. it is the side of the quinquangle. The same shall fall out of + <i>ot</i>. Wherefore <i>nat</i>, is an equilater triangle. The same shall + fall out of the other nine middle triangles, <i>nae</i>, <i>nej</i>, + <i>eji</i>, <i>jiv</i>, <i>ivo</i>, <i>vof</i>, <i>fou</i>, <i>fut</i>, + <i>uta</i>, <i>tan</i>.</p> + + <p>In like manner also shall it be proved of the five upper triangles, by + drawing the right lines <i>dy</i> and <i>cn</i> which as afore (because + they knit together equall parallells, to wit, <i>dc</i>, and <i>yn</i>) + they shall be equall. But <i>dy</i>, is the side of a sexangle: Therefore + <i>cn</i>, shall be also the side of a sexangle: And <i>cg</i>, is the + side of a decangle: Therefore <i>an</i>, whose power is equall to both + theirs by the <a href="#9_e_xij">9 e xij</a>. shall by the converse of + the <a href="#15_e_xviij">15 e xviij</a>, be the side of a quinquangle: + And in like manner <i>gt</i>, shall be concluded to be the side of a + quinquangle. Wherefore <i>ngt</i>, is an equilater: And the foure other + shall likewise be equilaters.</p> + + <p>The other five triangles beneath shall after the like manner be + concluded to be equilaters. Therefore one shall be for all, to wit, + <i>ibe</i>, by drawing the raies <i>di</i>, and <i>de</i>. For <i>ib</i>, + <!-- Page 277 --><span class="pagenum"><a + name="page277"></a>[277]</span>whose power, as afore, is as much as the + sides of the sexangle, and decangle, shall be the side of the + quinquangle: And in like sort <i>be</i>, being of equall power with + <i>de</i>, and <i>do</i>, the sides of the sexangle and decangle, shall + be the side of the quinquangle. Wherefore the triangle <i>ebi</i>, is an + equilater: And the foure other in like manner may be shewed to be + equilaters. Therefore all the side of the twenty triangles, seeing they + are equall, they shall be equilater triangles: And by the <a + href="#8_e_vij">8 e, vij</a>. equall.</p> + + <p><a name="17_e_xxv"></a> 17 <i>The diagony of an icosaedrū is + irrational unto the side</i>.</p> + + <p>This is the fourth example of irrationality, or incommensurability. + The first was of the Diagony and side of a square or quadrate. The second + was of the segments of a line proportionally cut. The third of the + Diameter of a circle and the side of a quinquangle.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="18_e_xxv"></a> 18 <i>The power of the diagony of an + icosaedrum is five times as much as the ray of the circle</i>.</p> + + <div class="figright" style="width:16%;"> + <a href="images/298.png"><img style="width:100%" src="images/298.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p>For by the <a href="#13_e_xviij">13 e, xviij</a>. the line continually + made of the side of the sexangle and decangle is cut proportionally, and + the greater segment is the side of the sexangle: As here. Let the + perpendicular <i>ae</i>, be cut into two equall parts in <i>i</i>. Then + <i>eo</i>, that is the lesser segment continued with the halfe of the + greater, that is, with <i>ie</i>. it shall by the <a href="#6_e_xiiij">6 + e xiiij</a>, be of power five times so great as is the power of the same + halfe. Therefore seeing that <i>io</i>, the halfe of the diagony is of + power fivefold to the halfe: the whole diagony shall be of power fivefold + to the whole cut.</p> + + <div class="figleft" style="width:23%;"> + <a href="images/299.png"><img style="width:100%" src="images/299.png" + alt="Figure for demonstration 18." title="Figure for demonstration 18." /></a> + </div> + <p>And from hence also shall be the geodesy of the Icosaedrum. For the + finding out of the heighth of the pyramis, there is the semidiagony of + the side of the decangle and the halfe ray of the circle: But the side of + the decangle is a right line subtending the halfe periphery of the side + of the quinquangle, or else the greater segment of the ray <!-- Page 278 + --><span class="pagenum"><a name="page278"></a>[278]</span>proportionally + cut. For so it may be taken Geometrically, and reckoned for his measure. + Therefore if the quadrate of the side of the decangle, be taken out of + the quadrate of the side of the quinquangle, there shall by the <a + href="#15_e_xviij">15 e xviij</a>, remaine the quadrate of the sexangle, + that is of the ray. The side of the decangle (because the side of the + quinquangle here is 6) shall be 3.3/35 to wit a right line subtending the + halfe periphery. Now the halfe ray shall thus be had. The quadrates of + the quinquangle and decangle are 36, and 9.639/1225. And this being + subducted fro that, the remaine 26.386/1225 by the <a + href="#15_e_xviij">15 e xviij</a>, shall be the quadrate or square of the + sexangle: And the side of it, 5, and almost 5/7 shall be the ray: The + halfe ray therefore shall be 2.6/7. To the side of the decangle 3.3/35 + adde 2.6/7: the whole shal be 5.33/35 for the semi-diagony of the + Icosaedrum. The ray of the circle circumscribed about the triangle, is by + the <a href="#12_e_xviij">12 e xviij</a>, the same which was before 3.3/7 + to wit of the quadrate 12. Therefore if the quadrate of the circular ray, + be taken out of the quadrate of the halfe diagony, there shall remaine + the quadrate of the heighth and perpendicular: the quadrate of the + halfe-diagony is 35.389/1225: the quadrate of the circular ray is 12. + This taken out of that beneath 23.639/1225: whose side is almost 5, for + the perpendicular and heighth proposed: From whence now the Pyramis is + esteemed. The case of a triangular pyramis is 15.18/31. The Plaine of + this base and the third part of the heighth is 25.30/31 for the solidity + of one Pyramis. This multiplyed by 20 maketh 519.11/31 for the summe or + whole solidity of the Icosaedum. And this is the geodesy or manner of + measuring of an Icosaedrum.</p> + + <p><a name="19_e_xxv"></a> 19. <i>A mingled ordinate polyedrum of a <!-- + Page 279 --><span class="pagenum"><a + name="page279"></a>[279]</span>quinquangular base is that which is + comprehended of 12 quinquangles, and it is called a Dodecaedrum.</i></p> + + <div class="figcenter" style="width:49%;"> + <a href="images/300a.png"><img style="width:100%" src="images/300a.png" + alt="Line and Solid Dodecaedrum." title="Line and Solid Dodecaedrum." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="20_e_xxv"></a> 20. <i>The sides of a Dodecaedrum are 30, the + plaine angles 60. the solid 20</i>.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="21_e_xxv"></a> 21. <i>If 12 ordinate equall quinquangles be + joyned with solid angles, they shall comprehend a Dodecaedrum</i>.</p> + + <div class="figcenter" style="width:27%;"> + <a href="images/300b.png"><img style="width:100%" src="images/300b.png" + alt="Net of Dodecaedrum." title="Net of Dodecaedrum." /></a> + </div> + <p>As here thou seest.</p> + + <p><a name="22_e_xxv"></a> 22. <i>If the sides of a cube be with right + lines cut into two equall parts, and three bisegments of the bisecants in + the abbuting plaines, neither meeting one the other, nor parallell one + unto another, two of one, the third of that next unto the remainder, be + so proportionally cut that the lesser segments doe bound the bisecant: + three lines without the cube perpendicular unto the sayd <!-- Page 280 + --><span class="pagenum"><a name="page280"></a>[280]</span>plaines from + the points of the proportionall sections, equall to the greater segment + knit together, two of the same bisecant, betweene themselves and with the + next angles of cube; the third with the same angles, they shall + comprehend a dodecaedrum. 17 p xiij</i>.</p> + + <div class="figright" style="width:18%;"> + <a href="images/301.png"><img style="width:100%" src="images/301.png" + alt="Figure for demonstration 22." title="Figure for demonstration 22." /></a> + </div> + <p>Let there be two plaines for a cube for all, that one quinquangle for + twelve may be described, and they abutting one upon another, <i>aeio</i>, + and <i>euyi</i>, having their sides halfed by the bisecantes, <i>sr</i>, + <i>lm</i>, <i>rn</i>, <i>jv</i>: And the three bisegments or portions of + the bisegments <i>lm</i>, and <i>rn</i>, neither concurring or meeting, + nor parallell one to another; two of the said <i>lm</i>, to wit, + <i>fl</i>, and <i>fm</i>: The third next unto the remainder, that is + <i>lr</i>. And let each bisegment be cut proportionally in the points + <i>d</i>, <i>c</i>, <i>g</i>; so that the lesser segments doe bound the + bisecant, to wit, <i>dl</i>, <i>cm</i>, and <i>gr</i>. Lastly let there + be three perpendiculars from the points <i>db</i>, <i>cg</i>, to the said + <i>d</i>, <i>cp</i>, <i>gz</i>: And the two first knit one to another, by + <i>bp</i>: And againe with the angles of the cube, by <i>be</i>, and + <i>pi</i>: The third knit with the same angles, by <i>ze</i>, and + <i>zi</i>: And let all the plaines be made up. I say first, that the five + sides <i>bp</i>, <i>pi</i>, <i>iz</i>, <i>ze</i>, and <i>eb</i> are + equall; Because, every one of them severally are the doubles of the same + greater segment. For in drawing the right lines <i>de</i> and <i>eg</i>, + <i>ig</i>, it shall be plaine of two of them; And after the same manner + of the rest. First therefore <i>cd</i>, and <i>bp</i>, are equall by the + <a href="#6_e_xxj">6 e xxj</a>, and by the <a href="#27_e_v">27 e v</a>. + Therefore <i>bp</i>, is the double of the greater segment. Then the whole + <i>fl</i>, cut proportionally, and the lesser segment <i>dl</i>, they are + by the <a href="#7_e_xiiij">7 e xiiij</a>, of treble power to the greater + <i>fd</i>, that is, by the fabricke <i>db</i>. Therefore <i>le</i> wich + is equall to <i>lf</i>, the line cut, and <i>ld</i>, are of treble power + to the same <i>db</i>: But by the <a href="#9_e_xij">9 e xij</a>, + <i>de</i> is of as much power as <i>le</i>, and <i>ld</i> too. <!-- Page + 281 --><span class="pagenum"><a name="page281"></a>[281]</span>Therefore + <i>de</i> is of treble power to <i>db</i>. Therefore both <i>ed</i>, and + <i>db</i>, are of quadruple power to <i>db</i>. But <i>be</i>, by the <a + href="#9_e_xij">9 e xij</a>, is of as much power as <i>ed</i>, and + <i>db</i>. And therefore <i>be</i>, is of quadruple value to <span + class="correction" title="text reads `eb'"><i>db</i></span>: And by the + <a href="#14_e_xij">14 e xij</a>, it is the double of the said <span + class="correction" title="text reads `eb'"><i>db</i></span>. Therefore + the two sides <i>eb</i>, and <i>bp</i>, are equall: And by the same + argument <i>pi</i>, <i>iz</i>, and <i>ze</i>, are equall. Therefore the + quinquangle is equilater.</p> + + <p>I say also that it is a Plaine quinquangle: For it may be said to be + an oblique quinquangle; and to be seated in two plaines. Let therefore + <i>fh</i> be parallell to <i>db</i>, and <i>cp</i>: and be equall unto + them. And let <i>hz</i>, be drawne: This <i>hz</i> shall be cut one line, + by the <a href="#14_e_vij">14 e vij</a>. For as the whole <i>tr</i>, that + is <i>rf</i>, is unto the greater segment that is to <i>fh</i>: so + <i>fh</i>, that is <i>zg</i>, is unto <i>gr</i>. And two paire of shankes + <i>fh</i>, <i>gr</i>, <i>fc</i>, <i>gz</i>, by the <a href="#6_e_xxj">6 e + xxj</a>, are alternely or crosse-wise parallell. Therefore their bases + are continuall.</p> + + <p>Hitherto it hath beene prooved that the quinquangle made is an + equilater and plaine: It remaineth that it bee prooved to be Equiangled. + Let therefore the right lines <i>ep</i>, and <i>ec</i>, be drawne: I say + that the angles, <i>pbe</i>, and <i>ezi</i>, are equall: Because they + have by the construction, the bases of equall shankes equall, being to + wit in value the quadruple of <i>le</i>. For the right line <i>lf</i>, + cut proportionally, and increased with the greater segment <i>df</i>, + that is <i>fc</i>, is cut also proportionally, by the <a + href="#4_e_xiiij">4 e xiiij</a>, and by the <a href="#7_e_xiiij">7 e + xiiij</a>, the whole line proportionally cut, and the lesser segment, + that is <i>cp</i>, are of treble value to the greater <i>fl</i>, that is + of the sayd <i>le</i>. Therefore <i>el</i>, and <i>lc</i>, that is + <i>ec</i>, and <i>cp</i>, that is <i>ep</i>, is of quadruple power to + <i>el</i>: And therefore by the <a href="#14_e_xij">14 e xij</a>, it is + the double of it: And <i>ei</i>, it selfe in like manner, by the fabricke + or construction, is the double of the same. Therefore the bases are + equall. And after the same manner, by drawing the right lines <i>id</i>, + and <i>ib</i>, the third angle <i>bpi</i>, shall be concluded to be equal + to the angle <i>ezi</i>. Therefore by the <a href="#13_e_xiiij">13 e + xiiij</a>, five angles are equall. <!-- Page 282 --><span + class="pagenum"><a name="page282"></a>[282]</span></p> + + <p><a name="23_e_xxv"></a> 23. <i>The Diagony is irrationall unto the + side of the dodecahedrum</i>.</p> + + <p>This is the fifth example of irrationality and incommensurability. The + first was of the diagony and side of a quadrate or square. The second was + of a line proportionally cut and his segments: The third is of the + diameter of a Circle and the side of an inscribed quinquangle. The fourth + was of the diagony and side of an icosahedrum. The fifth now is of the + diagony and side of a dodecahedrum.</p> + + <p><a name="24_e_xxv"></a> 24 <i>If the side of a cube be cut + proportionally, the greater segment shall be the side of a + dodecahedrum</i>.</p> + + <p>For that hath beene told you even now.</p> + + <div class="figright" style="width:22%;"> + <a href="images/303.png"><img style="width:100%" src="images/303.png" + alt="Figure for demonstration 24." title="Figure for demonstration 24." /></a> + </div> + <p>But from hence also doth arise the geodesy or māner of measuring + of a dodecahedrum. For if the quadrate of the line subtending the angle + of a quinquangle be trebled, the half of the treble shall be the side of + the semidiagony of the dodecahedrum: Because by the <a + href="#6_e_xxiiij">6 e xxiiij</a>, the diagony of the cube, that is of + the dodecahedrum is of treble power to the side of the cube. But if the + quadrate of the side of the decangle be taken out of the quadrate of the + side of the quinquangle; The side of the remainder shall be the ray of + the circle circumscribed about a quinquangle. Lastly if the quadrate of + the ray, be taken of the quadrate of the half-diagony; the side of the + remainder shall be the heighth of perpendicular. As if the side of the + decangle be 7.3/5: The quadrate of that shall be 57.19/25: the treble of + which is 173.7/25 whose side is about 13.107/131 for the side of the + Dodecahedrum, therefore 6.119/131 the halfe shall be the semidiagony of + the dodecahedrum. The ray of the <!-- Page 283 --><span + class="pagenum"><a name="page283"></a>[283]</span>Circle shall now thus + be found. If the quadrate of the side of the decangle be taken out of the + quadrate of the side of the sexangle; the side of the remainder, shall be + the Ray of the Circle, by the <a href="#15_e_xviij">15</a> and <a + href="#9_e_xviij">9 e xviij</a>. As here the side of the Quinquangle is + 4.2/3. The side of the Decangle 2.2/5: And the quadrates therefore are + 21.7/9, and 5.19/25. This subducted from that leaveth 16.4/225 whose side + is 4.2/15 for the Ray of the Circle.</p> + + <p>The semidiagony and ray of the circle thus found, the altitude + remaineth. Take out therefore the quadrate of the ray of the circle, + 16.4/225 out of the quadrate of the semidiagony 47.12458/17161, the side + of the remainder 31.2714406/3861225 is for the altitude or heighth: whose + 1/3 is 5/3. The quinquangled base is almost 38. Which multiplied by 5/3 + doth make 63.1/3 for the solidity of one Pyramis; which multiplied by 12, + doth make 760. for the soliditie of the whole <span class="correction" + title="text reads `dodetacedrum'">dodecaedrum</span>.</p> + + <p><a name="25_e_xxv"></a> 25 <i>There are but five ordinate solid + plaines</i>.</p> + + <p>This appeareth plainely out of the nature of a solid angle, by the + kindes of plaine figures. Of two plaine angles a solid angle cannot be + comprehended. Of three angles of an ordinate triangle is the angle of a + Tetrahedrum comprehended: Of foure, an Octahedrum: Of five, an + Icosahedrum: Of sixe none can be comprehended: For sixe such like plaine + angles, are equall to 12 thirds of one right angle, that is to foure + right angles. But plaine angles making a solid angle, are lesser than + foure right angles, by the <a href="#8_e_xxij">8 e xxij</a>. Of seven + therefore, and of more it is, much lesse possible. Of three quadrate + angles the angle of a cube is comprehended: Of 4. such angles none may be + comprehended for the same cause. Of three angles of an ordinate + quinquangle, is made the angle of a Dodecahedrum. Of 4. none may possibly + be made; For every such angle: For every one of them severally doe + countervaile one right angle and 1/5 of the same, Therefore they would be + foure, and three fifths. Of more therefore much lesse may it be possible. + <!-- Page 284 --><span class="pagenum"><a + name="page284"></a>[284]</span></p> + + <p>This demonstration doth indeed very accurately and manifestly appeare, + Although there may be an innumerable sort of ordinate plaines, yet of the + kindes of angles five onely ordinate bodies may be made; From whence the + Tetrahedrum, Octahedrum, and Icosahedrum are made upon a triangular base: + the Cube upon a quadrangular: And the Dodecahedrum, upon a + quinquangular.</p> + +<hr class="full" /> + +<h2>Of <i>Geometry</i> the twenty sixth Booke; +Of a <i>Spheare</i>.</h2> + + <p><a name="1_e_xxvj"></a> 1 <i>An imbossed solid is that which is + comprehended of an imbossed surface</i>.</p> + + <p><a name="2_e_xxvj"></a> 2. <i>And it is either a spheare or a Mingled + forme</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/305.png"><img style="width:100%" src="images/305.png" + alt="Sphæra." title="Sphæra." /></a> + </div> + <p><a name="3_e_xxvj"></a> 3. <i>A speare is a round imbossement</i>.</p> + + <p>It may also be defined to be that which is comprehended of a + sphearical surface. A sphearicall body in Greeke is called <i>Sphæra</i>, + in Latine <i>Globus</i>, a Globe.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="4_e_xxvj"></a> 4. <i>A Spheare is made by the conversion of a + semicircle, the diameter standing still. 14 d xj.</i> <!-- Page 285 + --><span class="pagenum"><a name="page285"></a>[285]</span></p> + + <div class="figleft" style="width:26%;"> + <a href="images/306a.png"><img style="width:100%" src="images/306a.png" + alt="Figure for demonstration 4." title="Figure for demonstration 4." /></a> + </div> + <p>As here thou seest.</p> + + <p><a name="5_e_xxvj"></a> 5. <i>The greatest circle of a spheare, is + that which cutteth the spheare into two equall parts</i>.</p> + + <p> Therefore</p> + + <p><a name="6_e_xxvj"></a> 6. <i>That circle which is neerest to the + greatest, is greater than that which is farther off</i>.</p> + + <p> And</p> + + <p><a name="7_e_xxvj"></a> 7. <i>Those which are equally distant from the + greatest are equall</i>.</p> + + <p>As in the example above written.</p> + + <p><a name="8_e_xxvj"></a> 8. <i>The plaine of the diameter and sixth + part of the sphearicall is the solidity of the spheare</i>.</p> + + <div class="figright" style="width:22%;"> + <a href="images/306b.png"><img style="width:100%" src="images/306b.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <p>As before there was an analogy betweene a Circle and a Sphericall: so + now is there betweene a Cube and a spheare. A cubicall surface is + comprehended of sixe quadrate or square and equall bases: And a spheare + in like manner is comprehended of sixe equall sphearicall bases + compassing the <!-- Page 286 --><span class="pagenum"><a + name="page286"></a>[286]</span>cubicall bases. A cube is made by the + multiplication of the sixth part of the base, by the side: And a spheare + likewise is made by multiplying the sixth part of the sphearicall by the + diameter, as it were by the side: so the plaine of 616/6 and 14, the + diameter is 1437.1/3 for the solidity of the spheare.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="9_e_xxvj"></a> 9. <i>As 21 is unto 11, so is the cube of the + diameter unto the spheare</i>.</p> + + <p>As here the Cube of 14 is 2744. For it was an easy matter for him that + will compare the cube 2744, with the spheare, to finde that 2744 to be to + 1437.1/3 in the least boundes of the same reason, as 21 is unto 11.</p> + + <p>Thus much therefore of the Geodesy of the spheare: The geodesy of the + <span class="correction" title="text reads `Sctour'">Sectour</span> and + section of the spheare shall follow in the next place.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="10_e_xxvj"></a> 10. <i>The plaine of the ray, and of the + sixth part of the sphearicall is the hemispheare</i>.</p> + + <p>But it is more accurate and preciser cause to take the halfe of the + spheare.</p> + + <p><a name="11_e_xxvj"></a> 11. <i>Spheares have a trebled reason of + their diameters</i>.</p> + + <p>So before it was told you; That circles were one to another, as the + squares of their diameters were one to another, because they were like + plaines: And the diameters in circles were, as now they are in spheares, + the homologall sides. Therefore seeing that spheres are figures alike, + and of treble dimension, they have a trebled reason of their + diameters.</p> + + <p><a name="12_e_xxvj"></a> 12. <i>The five ordinate bodies are inscribed + into the same spheare, by the conversion of a semicicle having for the + diameter, in a tetrahedrum, a right line of value <!-- Page 287 --><span + class="pagenum"><a name="page287"></a>[287]</span>sesquialter unto the + side of the said tetrahedrum; in the other foure ordinate bodies, the + diagony of the same orginate</i>.</p> + + <p>The Adscription of ordinate plaine bodies is unto a spheare, as before + the Adscription plaine surfaces was into a circle; of a triangle, I + meane, and ordinate triangulate, as Quadrangle, Quinquangle, Sexangle, + Decangle, and Quindecangle. But indeed the Geometer hath both inscribed + and circumscribed those plaine figures within a circle. But these five + ordinate bodies, and over and above the Polyhedrum the Stereometer hath + onely inscribed within the spheare. The Polyhedrum we have passed over, + and we purpose onely to touch the other ordinate bodies.</p> + + <p><a name="13_e_xxvj"></a> 13 <i>Out of the reason of the axeltree of + the sphearicall the sides of the tetraedrum, cube, octahedrum and + dodecahedrum are found out</i>.</p> + + <div class="figright" style="width:24%;"> + <a href="images/308.png"><img style="width:100%" src="images/308.png" + alt="Figure for demonstration 13." title="Figure for demonstration 13." /></a> + </div> + <p>The axeltree in the three first bodies is rationall unto the side, as + was manifested in the former. For it is of the sesquialter valew unto the + side of the tetrahedrum; of treble, to the side of the cube: Of double, + to the side of the Octahedrum. Therefore if the axis <i>ae</i>, be cut by + a double reason in <i>i</i>: And the perpendicular <i>io</i>, be knit to + <i>a</i>, and <i>e</i>, shall be the side of the tetrahedrum; and + <i>oe</i>, of the cube, as was manifest by the <a href="#10_e_viij">10 e + viij</a>, and <a href="#25_e_iiij">25 iiij</a>: And the greater segment + of the side of the cube proportionally cut, is by the <a + href="#24_e_xxv">24 e, xxv</a>.</p> + + <p>If the same axis be cut into two halfes, as in <i>u</i>: And the + perpendicular <i>uy</i>, be erected: And <i>y</i>, and <i>a</i>, be knit + together, the same <i>ya</i>, thus knitting them, shall be the side of + the Octahedrum, as is manifest in like manner, by the said <a + href="#10_e_viij">10 e, viij</a>, and <a href="#25_e_iiij">25 e + iiij</a>.</p> + + <p>The side of the Icosahedrum is had by this meanes.</p> + + <p><a name="14_e_xxvj"></a> 14. <i>If a right line equall to the axis of + the sphearicall, and to it from the end of the perpendicular be knit unto + the center, a right line drawne from the cutting of the <!-- Page 288 + --><span class="pagenum"><a name="page288"></a>[288]</span>periphery unto + the said end shall be the side of the Icosahedrum</i>.</p> + + <div class="figright" style="width:21%;"> + <a href="images/309.png"><img style="width:100%" src="images/309.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p>As here let the Axis <i>ae</i>; be the diameter of the circle + <i>aue</i>, and <i>ai</i>, equall to the same axis, and perpendicular + from the end, be knit unto the center, by the right line <i>io</i>: A + right drawne from the section <i>u</i>, unto <i>a</i>, shall be the side + of the Icosahedrum. From <i>u</i>, let the perpendicular <i>uy</i>, be + drawne: Here the two triangles <i>iao</i>, & <i>uyo</i>, are + equiangles by the <a href="#13_e_vij">13 e, vij</a>. Therfore by the <a + href="#12_e_vij">12 e, vij</a>. as <i>ia</i>, is unto <i>ao</i>: so is + <i>uy</i>, unto <i>yo</i>. But <i>ia</i>, is the double of the said + <i>ao</i>: Therefore <i>uy</i>, is the double of the same <i>yo</i>: + Therefore by the <a href="#14_e_xij">14 e, xij</a>, it is of quadruple + power unto it: And therefore also <i>uy</i>, and <i>yo</i>, that is, by + the <a href="#9_e_xij">9 e xij</a>, <i>uo</i>, that is againe by the <a + href="#28_e_iiij">28 e, iiij</a>, <i>ao</i>, is of quintuple power to + <i>yo</i>. But <i>yo</i>, is lesser than <i>ao</i>, that is, than + <i>oe</i>: Let therefore <i>os</i>, be cut off equall to it. Now as the + halfe of <i>ao</i>, is of quintuple valew to the halfe of <i>yo</i>: so + the double <i>ae</i>, is of quintuple power to the double <i>ys</i>. + Therefore, by the <a href="#18_e_xxv">18 e xxv</a>. seeing that the + diagony <i>ae</i>, is of quintuple power to <i>ys</i>; the said + <i>ys</i>, shall be the side of the sexangle inscribed into a circle, + circumscribing the quinquangle of the Icosahedrum. But the perpendicular + <i>uy</i>, is equall to <i>ys</i>; because each of them is the double of + <i>yo</i>. Wherefore <i>uy</i>, is the side of the sexangle. But + <i>ay</i>, is the side of the Decangle: For it is equall to <i>se</i>: + Because if from equall rayes <i>ao</i>, and <i>oe</i>, you take equall + portions <i>oy</i>, and <i>os</i>: There shall remaine equall, <i>ya</i>, + and <i>se</i>. And the Diagony of an Icosahedrum by the <a + href="#16_e_xxv">16 e xxv</a>, is compounded of the side of the sexangle, + continued at each end with the side of the decangle. Wherefore <i>ay</i>, + is the side of the decangle. Lastly, <i>ua</i>, whose power is as much as + the sides of the <!-- Page 289 --><span class="pagenum"><a + name="page289"></a>[289]</span>sexangle and decangle, by the <a + href="#15_e_xviij">15. e, xviij</a>, shall be the side of an + Icosahedrum.</p> + + <p><a name="15_e_xxvj"></a> 15 <i>Of the five ordinate bodies inscribed + into the same spheare, the tetrahedrum in respect of the greatnesse of + his side is first, the Octahedrum, the second; the Cube, the third; the + Icosahedrum, the fourth; and the Dodecahedrum, the fifth</i>.</p> + + <div class="figright" style="width:23%;"> + <a href="images/310.png"><img style="width:100%" src="images/310.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <p>As it will plainely appeare, if all of them be gathered into one, + thus. For <i>ai</i>, the side of the Tetrahedrum, subtendeth a greater + periphery than <i>ao</i>, the side of the Octahedrum; And <i>ao</i>, a + greater than <i>ie</i>, the side of the Cube; because it subtendeth but + the halfe: And <i>ie</i>, greater than <i>ue</i>, the side of the + Icosahedrum: And <i>ue</i>, greater than <i>ye</i>, the side of + Dodecahedrum.</p> + + <p>The latter, <i>Euclide</i> doth demonstrate with a greater + circumstance. Therefore out of the former figures and demonstrations, let + here be repeated, The sections of the axis first into a double reason in + <i>s</i>: And the side of the sexangle <i>rl</i>: And the side of the + Decangle <i>ar</i>, inscribed into the same circle, circumscribing the + quinquangle of an icosahedrum: And the perpendiculars <i>is</i>, and + <i>ul</i>.</p> + + <p>Here the two triangles <i>aie</i>, and <i>ies</i>, are by the <a + href="#8_e_viij">8 e, viij</a>. alike; And as <i>se</i>, is unto + <i>ei</i>: So is <i>ie</i>, unto <i>ea</i>: And by <a + href="#25_e_iiij">25 e, iiij</a>, as <i>se</i>, is to <i>ea</i>: so is + the quadrate of <i>se</i>, to the quadrate of <i>ei</i>: And inversly or + backward, as <i>ae</i>, is to <i>se</i>: so is the quadrate of <i>ie</i>, + to the quadrate of <i>se</i>. But <i>ae</i>, is the triple of <i>se</i>. + Therefore the quadrate of <i>ie</i>, is the triple of <i>se</i>. But the + quadrate of <i>as</i>, by the grant, and <a href="#14_e_xij">14 e + xij</a>, the quadruple of the quadrate of <i>se</i>. Therefore also it is + greater than the quadrate of <i>ie</i>: And the right line <i>as</i>, is + greater than <i>ie</i>, and <i>al</i>, therefore is much greater. But + <i>al</i>, is by the grant <!-- Page 290 --><span class="pagenum"><a + name="page290"></a>[290]</span>compounded of the sides of the sexangle + and decangle <i>rl</i>, and <i>ar</i>. Therefore by the 1 c. <a + href="#5_e_xviij">5 e, 18.</a> it is cut proportionally: And the greater + segment is the side of the sexangle, to wit, <i>rl</i>: And the greater + segment of <i>ie</i>, proportionally also cut, is <i>ye</i>. Therefore + the said <i>rl</i>, is greeter than <i>ye</i>: And even now it was shewed + <i>ul</i>, was equall to <i>rl</i>. Therefore <i>ul</i>, is greater than + <i>ye</i>: But <i>ue</i>, the side of the Icosahedrum, by <a + href="#22_e_vj">22. e vj</a>. is greater than <i>ul</i>. Therefore the + side of the Icosahedrum is much greater, then the side of the + dodecahedrum.</p> + +<hr class="full" /> + +<h2>Of <i>Geometry</i> the twenty seventh Book; +Of the Cone and Cylinder.</h2> + + <p><a name="1_e_xxvij"></a> 1 <i>A mingled solid is that which is + comprehended of a variable surface and of a base</i>.</p> + + <p>For here the base is to be added to the variable surface.</p> + + <p><a name="2_e_xxvij"></a> 2 <i>If variable solids have their axes + proportionall to their bases, they are alike. 24. d xj</i>.</p> + + <p>It is a Consectary out of the <a href="#19_e_iiij">19 e, iiij</a>. For + here the axes and diameters are, as it were, the shankes of equall + angles, to wit, of right angles in the base, and perpendicular axis.</p> + + <p><a name="3_e_xxvij"></a> 3 <i>A mingled body is a Cone or a + Cylinder</i>.</p> + + <p>The cause of this division of a varied or mingled body, is to be + conceived from the division of surfaces. <!-- Page 291 --><span + class="pagenum"><a name="page291"></a>[291]</span></p> + + <div class="figright" style="width:22%;"> + <a href="images/312a.png"><img style="width:100%" src="images/312a.png" + alt="Cone." title="Cone." /></a> + </div> + <p><a name="4_e_xxvij"></a> 4 <i>A Cone is that which is comprehended of + a conicall and a base</i>.</p> + + <p>Here the base is a circle.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="5_e_xxvij"></a> 5 <i>It is made by the turning about of a + right angled triangle, the one shanke standing still</i>.</p> + + <p>As it appeareth out of the definition of a variable body.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="6_e_xxvij"></a> 6 <i>A Cone is rightangled, if the shanke + standing still be equall to that turned about: It is Obtusangeld, if it + be lesse: and acutangled, if it be greater. ê 18 d xj</i>.</p> + + <div class="figleft" style="width:22%;"> + <a href="images/312b.png"><img style="width:100%" src="images/312b.png" + alt="Right angled and other cones." title="Right angled and other cones." /></a> + </div> + <p>Here a threefold difference of the heighth of a Cone is professed, out + of the threefold difference of the angles, whereby the toppe of the + halfed cone is distinguished: Notwithstanding this consideration + belongeth rather to the Optickes, than to Geometry. For a Cone a farre + off seeme like triangle. Therefore according to the difference of the + heighth, it <!-- Page 292 --><span class="pagenum"><a + name="page292"></a>[292]</span>appeareth with a right angled, or + obtusangled or acutangled toppe: As here the least Cone is obtusangled: + the middle one rightangled: and the highest acutangled. But the cause of + this threefold difference in the angles from of the difference of the + shankes, is out of the consectaries of the threefold triangle of a right + line cutting the base into two equall parts, as appeareth at the end of + the <a href="#20_e_viij">viij</a> Booke.</p> + + <p> And</p> + + <p><a name="7_e_xxvij"></a> 7 <i>A Cone is the first of all + variable</i>.</p> + + <p>For a Cone is so the first in variable solids, as a triangle is in + rectilineall plaines: As a Pyramis is in solid plaines: For neither may + it indeed be divided into any other variable solids more simple.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="8_e_xxvij"></a> 8 <i>Cones of equall heighth are as their + bases are 11. p xij</i>.</p> + + <p>As here you see.</p> + + <div class="figcenter" style="width:34%;"> + <a href="images/313.png"><img style="width:100%" src="images/313.png" + alt="Figure for demonstration 8." title="Figure for demonstration 8." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="9_e_xxvij"></a> 9 <i>They which are reciprocall in base and + heighth are equall, 15 p xij.</i> <!-- Page 293 --><span + class="pagenum"><a name="page293"></a>[293]</span></p> + + <p>These are consectaries drawne out of the <span class="correction" + title="text reads `12 and 13 e. iiij' - compare the same discussion for the pyramis at 14, 15 e. xxij." + ><a href="#16_e_iiij">16</a> and <a href="#18_e_iiij">18 e. + iiij</a></span>. As here you see.</p> + + <div class="figcenter" style="width:35%;"> + <a href="images/314a.png"><img style="width:100%" src="images/314a.png" + alt="Figure for demonstration 9." title="Figure for demonstration 9." /></a> + </div> + <div class="figright" style="width:19%;"> + <a href="images/315a.png"><img style="width:100%" src="images/315a.png" + alt="Geodesy of Cylinder." title="Geodesy of Cylinder." /></a> + </div> + <div class="figright" style="width:17%;"> + <a href="images/314b.png"><img style="width:100%" src="images/314b.png" + alt="Cylinder." title="Cylinder." /></a> + </div> + <p><a name="10_e_xxvij"></a> 10 <i>A Cylinder is that which is + comprehended of a <span class="correction" title="text reads `cyliudricall'" + >cylindricall</span> surface and the opposite bases</i>.</p> + + <p>For here two circles, parallell one to another are the bases of a + Cylinder.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <p><a name="11_e_xxvij"></a> 11 <i>It is made by the turning about of a + right angled parallelogramme, the one side standing still. 21. d + xj</i>.</p> + + <p>As is apparant out the same definition of a varium. <!-- Page 294 + --><span class="pagenum"><a name="page294"></a>[294]</span></p> + + <p><a name="12_e_xxvij"></a> 12. <i>A plaine made of the base and heighth + is the solidity of a Cylinder</i>.</p> + + <p>The geodesy here is fetch'd from the prisma: As if the base of the + cylinder be 38.1/2: Of it and the heighth 12, the solidity of the + cylinder is 462.</p> + + <p>This manner of measuring doth answeare, I say, to the manner of + measuring of a prisma, and in all respects to the geodesy of a right + angled parallelogramme.</p> + + <p>If the cylinder in the opposite bases be oblique, then if what thou + cuttest off from one base thou doest adde unto the other, thou shalt have + the measure of the whole; as here thou seest in these cylinders, <i>a</i> + and <i>b</i>.</p> + + <p><br style="clear : both" /></p> + <div class="figcenter" style="width:33%;"> + <a href="images/315b.png"><img style="width:100%" src="images/315b.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <div class="figright" style="width:17%;"> + <a href="images/316.png"><img style="width:100%" src="images/316.png" + alt="Figure for demonstration 12." title="Figure for demonstration 12." /></a> + </div> + <p>From hence the capacity or content of cylinder-like <!-- Page 295 + --><span class="pagenum"><a name="page295"></a>[295]</span>vessell or + measure is esteemed and judged of. For the hollow or empty place is to be + measured as if it were a solid body.</p> + + <p>As here the diameter of the inner Circle is 6 foote: The periphery is + 18.6/7: Therefore the plot or content of the circle is 28.2/7. Of which, + and the heighth 10, the plaine is 282.6/7 for the capacity of the + vessell. Thus therefore shalt thou judge, as afore, how much liquor or + any thing else conteined, a cubicall foote may hold.</p> + + <p><a name="13_e_xxvij"></a> 13. <i>A Cylinder is the triple of a cone + equall to it in base and heighth. 10 p xij</i>.</p> + + <p>The demonstration of this proposition hath much troubled the + interpreters. The reason of a Cylinder unto a Cone, may more easily be + assumed from the reason of a Prisme unto a Pyramis: For a Cylinder doth + as much resemble a Prisme, as the Cone doth a Pyramis: Yea and within the + same sides may a Prisme and a Cylinder, a Pyramis and a Cone be + conteined: And if a Prisme and a Pyramis have a very multangled base, the + Prisme and <span class="correction" title="text reads `Clinder'" + >Cylinder</span>, as also the Pyramis and Cone, do seeme to be the same + figure. Lastly within the same sides, as the Cones and Cylinders, so the + Prisma and Pyramides, from their axeltrees and diameters may have the + similitude of their bases. And with as great reason may the Geometer + demand to have it granted him, That the Cylinder is the treble of a Cone: + As it was demanded and granted him, That Cylinders and Cones are alike, + whose axletees are proportionall to the diameters of their bases.</p> + + <div class="poem"> + <div class="stanza"> + <p>Therefore</p> + </div> + </div> + <div class="figright" style="width:16%;"> + <a href="images/317b.png"><img style="width:100%" src="images/317b.png" + alt="Archimede's Rhombus." title="Archimede's Rhombus." /></a> + </div> + <div class="figright" style="width:21%;"> + <a href="images/317a.png"><img style="width:100%" src="images/317a.png" + alt="Figure for demonstration 14." title="Figure for demonstration 14." /></a> + </div> + <p><a name="14_e_xxvij"></a> 14. <i>A plaine made of the base and thid + part of the height, is the solidity of the cone of equall base & + height;</i> <!-- Page 296 --><span class="pagenum"><a + name="page296"></a>[296]</span></p> + + <p>The heighth is thus had. If the square of the ray of the base, be + taken out of the square of the side, the side of the remainder shall bee + the heighth, as is manifest by the <a href="#9_e_xij">9 e xij</a>. Here + therefore the square of the ray 5, is 25. The square of 13, the side is + 169. And 169 - 25, are 144; whose side is 12 for the heighth: The third + part of which is 4. Now the circular base is 78.4/7: And the plaine of + these is 314.2/7 for the solidity of the Cone.</p> + + <p>But the analogie of a conicall unto a Cylinder like surface doth not + answeare, that the Conicall should be the subtriple of the Cylindricall, + as the Cone is the subtriple of the Cylinder.</p> + + <p>Of two cones of one common base is made <i>Archimede's Rhombus</i>, as + here, whose geodæsy shall be cut of two cones.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="15_e_xxvij"></a> 15. <i>Cylinder of equall heighth are as + their bases are. 11 p xij</i>.</p> + + <p>Sackes in which they carry corne, are for the most part of <!-- Page + 297 --><span class="pagenum"><a name="page297"></a>[297]</span>a + cylinderlike forme. If an husbandman therefore shall lend unto his + neighbour a sacke full or corne, and the base of the sacke be 4 foote + over. And the neighbour afterward for that one sacke, shall pay him 4 + sacke fulls, every sacke being as long as that was, yet but one foote + over in the diameter, he may be thought peradventure to have repayed that + which he borrowed in equall measure, to wit in heighth and base. But it + shall be indeed farre otherwise: For there is a great difference betweene + the quadrate of the foure severall diameters, 1. 1. 1. 1. that is 4: and + 16, the quadrate of 4, the diameter of that sacke by which it was lent. + For Circles are one unto another as the quadrates of their diameters are + one to another, by the <a href="#2_e_xv">2 e xv</a>. Therefore he payd + him but one fourth part of that which he borrowed of him.</p> + + <div class="figcenter" style="width:29%;"> + <a href="images/318a.png"><img style="width:100%" src="images/318a.png" + alt="Figure for demonstration 15." title="Figure for demonstration 15." /></a> + </div> + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <p><a name="16_e_xxvij"></a> 16 <i>Cylinders reciprocall in base and + heighth are equall. 15 p xij</i>.</p> + + <div class="figcenter" style="width:33%;"> + <a href="images/318a.png"><img style="width:100%" src="images/318a.png" + alt="Figure for demonstration 16." title="Figure for demonstration 16." /></a> + </div> +<p><!-- Page 298 --><span class="pagenum"><a name="page298"></a>[298]</span></p> + + <p>Both these affections are in common attributed to the equally manifold + of first figures.</p> + + <div class="poem"> + <div class="stanza"> + <p>And</p> + </div> + </div> + <div class="figright" style="width:15%;"> + <a href="images/319.png"><img style="width:100%" src="images/319.png" + alt="Figure for demonstration 17." title="Figure for demonstration 17." /></a> + </div> + <p><a name="17_e_xxvij"></a> 17. <i>If a cylinder be cut with a plaine + surface parallell to his opposite bases, the segments are, as their axes + are 13 p xij</i>.</p> + + <p>As here thou seest. For the axes are the altitudes or heights. It is + likwise a consectary following upon that generall theoreme of first + figure, but somewhat varyed from it. It doth answere unto the <a + href="#10_e_xxiij">10 e 23</a>.</p> + + <p>The unequall sections of a spheare we have reserved for this place: + Because they are comprehended of a surface both sphearicall and conicall, + as is the sectour. As also of a plaine and sphearicall, as is the + section: And in both like as in a Circle, there is but a greater and + lesser segment. And the sectour, as before, is considered in the + center.</p> + + <p><a name="18_e_xxvij"></a> 18. <i>The sectour of a spheare is a segment + of a spheare, which without is comprehended of a sphearicall within of a + conicall bounded in the center, the greater of a concave, the lesser of a + convex</i>.</p> + + <p><i>Archimedes</i>, maketh mention of such kinde of Sectours, in his 1 + booke of the Spheare. From hence also is the geodesy following drawne. + And here also is there a certaine analogy with a circular sectour.</p> + + <p><a name="19_e_xxvij"></a> 19. <i>A plaine made of the diameter, and + sixth part of the greater, or lesser sphearicall, is the greater or + lesser sector.</i> <!-- Page 299 --><span class="pagenum"><a + name="page299"></a>[299]</span></p> + + <div class="figleft" style="width:22%;"> + <a href="images/320.png"><img style="width:100%" src="images/320.png" + alt="Figure for demonstration 19." title="Figure for demonstration 19." /></a> + </div> + <p>As here of the Diameter 14, and of 73.1/3 and 4.2/3 (which is the one + sixth part of the greater sphearicall) the plaine is 1026.2/3 for the + solidity of the greater sectour, so of the same diameter 14, and 29.1/3 + which is the 1/6 part of 176, the lesser sphæricall, the plaine is + 410.2/3 for the solidity of the lesser sectour.</p> + + <p>And from hence lastly doth arise the solidity of the section, by + addition and subduction.</p> + + <p><a name="20_e_xxvij"></a> 20. <i>If the greater sectour be increased + with the internall cone, the whole shall be the greater section: If the + lesser be diminished by it, the remaine shall be the lesser + section</i>.</p> + + <p>As here the inner cone measured is 126.4/63. The greater sectour, by + the former was 1026.2/3. And <span class="correction" title="text reads `126'" + >1026</span>.2/3 + 126.4/63 doe make 1152.46/63.</p> + + <p>Againe the lesser sectour, by the next precedent, was 410.2/3: And + here the inner cone is 126.4/63 And therefore 410.2/3 - 126.4/63 that is + 284.38/63 is the lesser section.</p> + + <p><br style="clear : both" /></p> +<hr class="full" /> + +<h3><i>FINIS.</i></h3> + +<hr class="full" /> + +<p><!-- Page 300 --><span class="pagenum"><a name="page300"></a>[300]</span></p> + + <div class="figcenter" style="width:55%;"> + <a href="images/141.png"><img style="width:100%" src="images/141.png" + alt="Use of Jacob's Staffe at Sea (p. 120)." title="Use of Jacob's Staffe at Sea (p. 120)." /></a> + </div> + <div class="figcenter" style="width:43%;"> + <a href="images/146.png"><img style="width:100%" src="images/146.png" + alt="Use of Jacob's Staffe in a Well (p. 125)." title="Use of Jacob's Staffe in a Well (p. 125)." /></a> + </div> + + + + + + + +<pre> + + + + + +End of the Project Gutenberg EBook of The Way To Geometry, by Peter Ramus + +*** END OF THIS PROJECT GUTENBERG EBOOK THE WAY TO GEOMETRY *** + +***** This file should be named 26752-h.htm or 26752-h.zip ***** +This and all associated files of various formats will be found in: + https://www.gutenberg.org/2/6/7/5/26752/ + +Produced by Jonathan Ingram, Keith Edkins and the Online +Distributed Proofreading Team at https://www.pgdp.net + + +Updated editions will replace the previous one--the old editions +will be renamed. + +Creating the works from public domain print editions means that no +one owns a United States copyright in these works, so the Foundation +(and you!) can copy and distribute it in the United States without +permission and without paying copyright royalties. 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